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Research article Special Issues

Integration of Albanian nurses in Germany: Employment challenges and opportunities - A descriptive study

  • Nurse migration from low- and middle-income countries to high-income nations is a significant global phenomenon. This study aimed to examine the opportunities and challenges faced by Albanian nurses during their work integration after migrating to Germany. A descriptive cross-sectional quantitative study was conducted using convenience sampling with a snowball recruitment technique. A total of 162 Albanian nurses working in Germany, mostly female and married, participated in the survey. The findings revealed that the overall integration process was satisfactory, particularly regarding the recognition of professional qualifications, respect from colleagues, patients, and families, career opportunities, and autonomy at work. The host institutions supported integration through mentorship programs, language training, procedural training, and education on the German healthcare system. However, nurses reported challenges in medical terminologies, telephone communication, and healthcare documentation. The participants expressed the need for more comprehensive pre-departure information to facilitate smoother transitions. The study highlights the pivotal role of managers and institutions in the integration process and in creating inclusive and equitable work environments. Germany serves as a model for implementing effective integration activities for migrant nurses. Albania must adopt stronger strategies to retain nurses within the country and enhance its human capital by improving the working conditions and providing career development opportunities. Future research is recommended to explore the integration processes of Albanian nurses across other European countries. Subsequent studies should concentrate on identifying and addressing potential barriers to integration while fostering opportunities for collaboration between the origin and destination countries. Such research can contribute to academic, political, and social frameworks that enhance the migration experience for migrant nurses.

    Citation: Alketa Dervishi, Simon Jäger, Blerina Duka, Etleva Kika, Valbona Bezhani, Ardit Lena, Dhurata Ivziku. Integration of Albanian nurses in Germany: Employment challenges and opportunities - A descriptive study[J]. AIMS Public Health, 2025, 12(2): 399-417. doi: 10.3934/publichealth.2025023

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  • Nurse migration from low- and middle-income countries to high-income nations is a significant global phenomenon. This study aimed to examine the opportunities and challenges faced by Albanian nurses during their work integration after migrating to Germany. A descriptive cross-sectional quantitative study was conducted using convenience sampling with a snowball recruitment technique. A total of 162 Albanian nurses working in Germany, mostly female and married, participated in the survey. The findings revealed that the overall integration process was satisfactory, particularly regarding the recognition of professional qualifications, respect from colleagues, patients, and families, career opportunities, and autonomy at work. The host institutions supported integration through mentorship programs, language training, procedural training, and education on the German healthcare system. However, nurses reported challenges in medical terminologies, telephone communication, and healthcare documentation. The participants expressed the need for more comprehensive pre-departure information to facilitate smoother transitions. The study highlights the pivotal role of managers and institutions in the integration process and in creating inclusive and equitable work environments. Germany serves as a model for implementing effective integration activities for migrant nurses. Albania must adopt stronger strategies to retain nurses within the country and enhance its human capital by improving the working conditions and providing career development opportunities. Future research is recommended to explore the integration processes of Albanian nurses across other European countries. Subsequent studies should concentrate on identifying and addressing potential barriers to integration while fostering opportunities for collaboration between the origin and destination countries. Such research can contribute to academic, political, and social frameworks that enhance the migration experience for migrant nurses.



    Let Ω be a convex polygonal domain in R2. In this paper, we consider the following Dirichlet boundary optimal control problem,

    min{q} J(y,q)=12yˆy2L2(Ω)+α2q2L2(Γ) (1.1)

    subject to the advection-diffusion equation

    Δy(x)+β(x)y(x)+c(x)y(x)=f(x),xΩ, (1.2a)
    y(x)=q(x),xΓ. (1.2b)

    Here, y(x) denotes the state variable, ˆy(x) is the desired state, (1.2a) and (1.2b) are called the state equation, q(x) is the control, Γ=Ω.

    We assume the given functions f(x),ˆy(x)L2(Ω), β(x)[W1(Ω)]2, c(x)L(Ω) with the assumption

    c(x)12β(x)0,

    and α>0 is a given scalar.

    This problem is important in many applications, for example distribution of pollution in air [1] or water [2] and for problems in computational electro-dynamics, gas and fluid dynamics [3]. However, there are several challenges involved in solving this problem numerically. One problem arises for higher order elements and nonsmooth Dirichlet data which can cause serious problems in using standard finite element methods (see [4,5]). Another difficulty lies in the fact that Dirichlet boundary conditions do not enter the bilinear form naturally and that causes problems for analyzing the finite element method (see [6,7,8,9,10] for further discussion).

    One faces another challenge in the presence of layers which are the regions where the gradient of the solution is large. Usually, the boundary layers occur because of the fact that problem has reduced to the first order PDEs and requires boundary conditions on inflow part of the boundary only. In this case, standard Galerkin methods fail when h|β|>1, where h is mesh size, producing highly oscillatory solutions. A lot of research has been done in last 40 years to address this difficulty (see [3,4,11,12,13]).

    We have an example to illustrate this difficulty in the following simple example,

    Example 1.1.

    ϵy(x)+y(x)=1,x(0,1),y(0)=y(1)=0. (1.3)

    The Figure 1 shows nonphysical oscillations of the standard Galerkin solution for h=0.1 and ϵ=0.0025.

    Figure 1.  Standard Galerkin.

    One way to solve this problem is to use stabilized methods (see [14]). We will mention some of them. One of the first stable method of arbitrary order is SUPG (Streamline Upwind Petrov Galerkin) [11,15,16]. In this method, the space of test function is different from the space of trial function and chosen such that the method is stable and consistent. Other stabilized methods where the space of trial and test functions are the same and used upwind stabilization are HDG (Hybridizable Discontinuous Galerkin), [17,18,19,20,21], SIPG (Symmetric Interior Petrov Galerkin) [5,7,10], and LDG (Local Discontinuous Galerkin) [22,23,24]. Another popular stabilized method where the space of trial and test functions are the same is edge stabilization [25,26].

    DG methods are shown to be robust for the advection-diffusion-reaction problem (see [7,27]) even for the advection-dominated case. DG methods were not only analyzed for the advection-diffusion-reaction problem but also for the optimal control problem of the advection-diffusion-reaction equation [28], (see other stabilized methods for the optimal control problem of the advection-diffusion-reaction equation [26,29,30]). In addition to being stable, the discontinuous Galerkin methods, such as SIPG, usually treat the boundary conditions weakly. The SIPG method was also analyzed for distributed optimal control problems and optimal local and global error estimates were obtained (see [28] but not for the boundary control problems. We would like to investigate the performance of the SIPG method applied to Dirichlet boundary control problem (1.1), (1.2a) and (1.2b) and prove a priori error estimates. We would also like to perform a number of numerical experiments to confirm our theoretical result which is the main subject of the current work.

    In this paper, we analyze the SIPG solution of Dirichlet boundary control problem and the difficulties with dealing with the stability issues as well as with the difficulty of the treatment of Dirichlet boundary conditions. This method has some attractive features and offers some advantages. This method is stable and accurate, can be of arbitrary order and has been shown analytically that the boundary layers do not pollute the solution into the subdomain of smoothness [28]. Another attractive feature of the method is that Dirichlet boundary conditions are enforced weakly through the penalty term and not through the finite dimensional subspace [25]. As a result of the weak treatment of the boundary conditions, Dirichlet boundary control enters naturally into the bilinear form and makes analysis more natural [6,7,8,31]. Finally, the SIPG method has the property that two strategies optimize-then-discretize and discretize-then-optimize produce the same discrete optimality system (see [10,23]), which is not the case for other stabilized methods, for example, SUPG method (see [15]).

    Let us show some features of SIPG method with Figure 2 in the previous example. Consider the problem 1.3 in the example 1 with the much more smaller diffiusion parameter 109 instead of 0.0025. Figure 2 shows the behavior of the SIPG solution for h=0.1 and ϵ=1e9. As one can see the solution is stable. The Dirichlet boundary condition at x=1 is almost ignored by the method as a result of weak treatment.

    Figure 2.  SIPG method.

    Our choice of this particular DG method was motivated by good approximation and stabilization properties of the method. Additional attractive feature of the method is the weak treatment of the boundary conditions which allows us to set Dirichlet optimal control problem in natural the finite element frame work and to prove optimal convergence rates for on general convex polygonal domain. Moreover, we state the main result of the paper is valid for any general convex domain, there exists a positive constant C independent of h for the error between exact solution of the control function ˉq and its approximation ˉqh such that

    ˉqˉqhL2(Γ)Ch1/2(|ˉq|H1/2(Γ)+ˉyH1(Ω)+ˆyL2(Ω)),

    for h small enough. Also, we performed several numerical examples to support our theoretical results, and additionally when we investigate numerically performance of the method in the advection-dominated case.

    Throughout the paper, we will use standard notation for spaces, completeness and norms. We will use the standard notation for Lebesgue and Sobolev space, their suitable norms, and L2- inner product. Thus,

    (u,v)Ω=Ωuvdx and u,vΓ=Γuvds are the inner products on the domain Ω and its boundary Γ, respectively.

    The corresponding norms respectively are

    uL2(Ω)=(Ω|u|2dx)1/2,uL2(Γ)=(Γ|u|2)ds)1/2.

    H1/2(Γ)={uL2(Γ)|˜uH1(Ω):u=tr(˜u)}.

    uH1/2(Γ)=inf{˜uH1(Ω)|tr(˜u)=u}.

    |u|H1/2(Γ)=inf{|˜u|H1(Ω)|tr(˜u)=u}.

    First, let us consider the state equation,

    Δy+βy+cy=fin Ω,y=qon Γ. (2.1)

    We review some regularity results for various conditions on data which we will use later in the analysis. The first result is standard and found in [32].

    Theorem 2.1. Let fH1(Ω) and qH1/2(Γ). Then Eq (2.1) admits a unique solution yH1(Ω). Moreover, the following estimate holds

    yH1(Ω)C(fH1(Ω)+qH12(Γ)).

    In the case of q=0 on Γ, fL2(Ω), and convex Ω, we can obtain a higher regularity of the solution (see [33]).

    Theorem 2.2. Let fL2(Ω) and q=0 on Γ. Then, the Eq (2.1) admits a unique solution yH2(Ω) and the following estimate holds

    yH2(Ω)CfL2(Ω).

    Remark 2.1. Since the adjoint equation defined by

    Δz(βz)+cz=yˆyin Ωz=0on Γ,

    it is also an advection-diffusion equation and the results of the above theorems are valid for the adjoint equation with similar estimates as well. Also, notice that βz+(cβ)z=(βz)+cz.

    The theory in the case of qL2(Γ) is more technical and to obtain the desired regularity result, we use the transposition method [34], which we will briefly describe next.

    Suppose q is smooth enough having continuous derivatives up to the desired order, ϕL2(Ω) and let y1 and y2 be the solutions of the following equations,

    Δy1+βy1+cy1=0 in Ω,y1=qon Γ,andΔy2(βy2)+cy2=ϕin Ω,y2=0on Γ,

    respectively. Then, by the integration by parts and using the fact that y2=0 on Γ, we obtain

    0=(Δy1+βy1+cy1,y2)Ω=(y1,y2)Ωy1n,y2Γ+y1βn,y2Γ(y1,(βy2))Ω+(cy1,y2)Ω=(y1,y2)Ω(y1,(βy2))Ω+(y1,cy2)Ω=(y1,Δy2)Ω+y1,y2nΓ(y1,(βy2))Ω+(y1,cy2)Ω=(y1,Δy2(βy2)+cy2)Ω+y1,y2nΓ=(y1,ϕ)Ω+q,y2nΓ,

    where in the last step we use that Δy2(βy2)+cy2=ϕ in Ω and y1=q on Γ. Hence we obtain

    (y1,ϕ)Ω=q,y2nΓ.

    The above formula defines a mapping Λ:ϕy2n that is linear and continuous from L2(Ω) to H1/2(Γ). Since the embedding H1/2(Γ)L2(Γ) is compact, Λ is a compact operator from L2(Ω) to L2(Γ). Hence, its adjoint Λ is a compact operator from L2(Γ) to L2(Ω).

    Since (y1,ϕ)Ω=Γqy2n=q,ΛϕΓ and q,ΛϕΓ=(Λq,ϕ)Ω, we conclude that y1=Λq. Using the above, we can define an "ultra-weak" solution for the Eq (2.1) for Dirichlet data in L2(Γ) as follows.

    Definition 2.1. We say that yL2(Ω) is a unique ultra-weak solution of the Eq (2.1) if

    Ωyϕ=(f,p)(H1(Ω),H10(Ω))Γqpn,ϕL2(Ω),

    where p satisfies

    Δp(βp)+cp=ϕin Ω,p=0 on Γ.

    Now we are ready to provide the following regularity result.

    Theorem 2.3. For any fH1(Ω) and qL2(Γ), the Eq (2.1) admits a unique ultra-weak solution yL2(Ω). Moreover, the following estimate holds,

    yL2(Ω)C(fH1(Ω)+qL2(Γ)). (2.2)

    Proof. Existence follows from the Definition (2.1). For the uniqueness, we assume that y1 and y2 are distinct solutions of the Eq (2.1) and let u=y1y2, then

    Δu(βu)+cu=0in Ω,u=0on Γ.

    Since H1(Ω) is dense in L2(Ω), it is enough to consider uH1(Ω). By the Theorem (2.1), we have

    uH1(Ω)=0.

    As a result u=0, hence y1=y2 and this contradiction proves the uniqueness.

    To show the desired estimate (2.2), we use a duality argument. Let w be the solution of the problem

    Δw(βw)+cw=yin Ω,w=0on Γ.

    By using the above duality argument and using integration by parts and the fact that w=0 on Γ, we obtain

    y2L2(Ω)=(y,Δw(βw)+cw)Ω=(y,w)Ωy,wnΓy,w(βn)Γ+(βy,w)Ω+(y,cw)Ω=(Δy,w)Ω+yn,wΓy,wnΓy,w(βn)Γ+(βy,w)Ω+(y,cw)Ω=(Δy+βy+cy,w)Ωy,wnΓ=(f,w)Ωq,wnΓ,

    where in the last step we use Δy+βy+cy=f.

    By the trace and the Cauchy-Schwarz inequalities, and by using the Theorem (2.2), we have the following estimate

    y2L2(Ω)fH1(Ω)wH1(Ω)+qL2(Γ)wnL2(Γ)C(fH1(Ω)+qL2(Γ))wH2(Ω)C(fH1(Ω)+qL2(Γ))yL2(Ω).

    Canceling yL2(Ω) on both sides, we prove the desired estimate (2.2).

    Next we will provide the first order optimality conditions for the problem (1.1)

    Theorem 3.1. Assume that f,ˆyL2(Ω) and let (ˉy,ˉq) be the optimal solution of the Eq (2.1). Then, the optimal control ˉq is given by ˉzn=αˉq, where ˉz is the unique solution of the equation,

    Δˉz(βˉz)+cˉz=ˉyˆyin Ω,ˉz=0 on Γ. (3.1)

    Proof. Let (ˉy,ˉq) be an optimal solution of the Eq (1.1). We set

    F(q)=J(y(q),q),

    where y(q) is the solution of the Eq (2.1) for a given qL2(Γ). Let yq be the solution of the problem

    Δyq+βyq+cyq=f in Ω,yq=q+ˉqon Γ.

    By the optimality of (ˉy,ˉq) and convexity of Ω, we have that 1λ(F(ˉq+λq)F(ˉq))0 for all q and λ(0,1] [35]. For λ=1, yq=q+ˉq, and so F(ˉq+q)F(ˉq)0.

    Equivalently, if F(ˉq+q)F(ˉq)0 for all q in L2(Γ), then ˉq is an optimal solution of the problem. We find

    F(ˉq+q)F(ˉq)=J(yq,q+ˉq)J(ˉy,ˉq)=12Ω(yqˉy)(yq+ˉy2ˆy)+α2Γ(2qˉq+q2)=12Ω(yqˉy)2+α2Γq2+Ω(yqˉy)(ˉyˆy)+αΓqˉq.

    Let ˉz be the solution of the Eq (3.1). Then, we can estimate the third term of the right hand side by using the Green's formula and using the fact that yq=ˉq+q and ˉz=0 on Γ. Thus, we obtain

    Ω(yqˉy)(ˉyˆy)=Ω(yqˉy)(Δˉz(βˉz)+cˉz)=Γˉzn(yqˉq)+Ωˉz(yqˉy)Γ(yqˉy)ˉz(βn)+Ωˉz(β(yqˉy))+Ω(yqˉy)cˉz=Γˉzn(ˉq+qˉq)+Ωˉz(yqˉy)+Ωˉz(β(yqˉy))+Ω(yqˉy)cˉz=Γqˉzn+(yqnˉyn)ˉz|Γ+Ωˉz(Δ(yqˉy)+β(yqˉy)+c(yqˉy))=0.

    Notice that Ωˉz(yqˉy)=(yqnˉyn)ˉz|ΓΩˉzΔ(yqˉy) by using integration by parts. By setting ˉzn=αˉq, we have

    Ω(yqˉy)(ˉyˆy)=Γqˉzn=αΓqˉq.

    Putting all results together, we have

    F(ˉq+q)F(ˉq)=12Ω(yqˉy)2+α2Γq2αΓqˉq+αΓqˉq=12Ω(yqˉy)2+α2Γq20,

    i.e., (ˉy,ˉq) is the optimal solution to the Eq (2.1) with ˉq=1αˉzn where α>0 given any scalar in the problem (1.1)

    The first order optimality conditions in the strong form are as the following

    Adjoint equation{Δzβz+(cβ)z=yˆyinΩ,z=0 onΓ. (3.2)
    Gradient equation{zn=αqonΓ, (3.3)
    State equation{Δy+βy+cy=finΩ,y=qonΓ. (3.4)

    In the next theorem, we establish the regularity of the optimal solution of the problem (1.2a) and (1.2b).

    Theorem 3.2. Let (ˉy,ˉq)L2(Ω)×L2(Γ) be the optimal solution to the optimization problem (1.1) subject to the problem (1.2a) and (1.2b), and ˉz be the optimal adjoint state (3.1). Then,

    (ˉy,ˉq,ˉz)H1(Ω)×H1/2(Γ)×H2(Ω).

    Proof. For ˉqL2(Γ), from the state Eq (3.4), ˉyL2(Ω) holds by Theorem (2.3).

    Since ˉy,ˆyL2(Ω) and Ω is a convex domain, from the adjoint Eq (3.2), ˉzH2(Ω) holds by Theorem (2.2).

    Since ˉzH2(Ω), we have ˉznH1/2(Γ), from the gradient Eq (3.3), ˉzn=αq implies ˉqH1/2(Γ).

    Since ˉqH1/2(Γ), from the state Eq (3.4), ˉyH1(Ω) holds by Theorem (2.1).

    Remark 3.1. Using regularity results, we can generalize the regularity which depends on the largest interior angle of the polygonal domain in R2 [36].

    The idea of the FEM is to construct Vh and Qh defined on a finite dimensional space that is well approximate the solution spaces V and Q. The Galerkin FEM is to find yhVh and qhQh such that

    ah(yh,vh)=h(f;qh,vh),vhVh, (4.1)

    where Vh is a finite dimensional space and h is a discretization parameter. We can easily see that if ah(,) satisfies the conditions of Lax-Milgram Lemma, the Eq (4.1) has a unique solution for each h.

    To construct Vh, we consider a family of conforming quasi-uniform shape regular triangulations Th of Ω such that ˉΩ=τiThτi and τiτj=0 τi,τjTh, ij with a mesh size

    h=supτiThdiam(τi).

    We define Eh as a collection of all edges Eh=E0hEh where E0h and Eh are the collections of interior and boundary edges, respectively, and we decompose the boundary edges as

    Eh=E+hh, (4.2)

    where Eh:={eEh:e{xΓ:β(x)n(x)<0}} and E+h:=EhEh i.e. these are the collections of the edges that belong to the inflow and outflow part of the boundary, respectively. In other words, for a given elements τTh and nτ indicates the outward normal to τ, then we can decompose its boundary τ as τ={xτ:β(x)nτ(x)<0} and τ+={xτ:β(x)nτ(x)0}.

    We define the standard jumps and averages on the set of interior edges by

    {φ}=φ1+φ22,[[φ]]=φ1n1+φ2n2,{ϕ}=ϕ1+ϕ22,[[ϕ]]=ϕ1n1+ϕ2n2,

    where n1 and n2 are outward normal vectors at the common boundary edge of neighboring elements τ1 and τ2, respectively. If eEh, then {φ}=[[φ]]=φ|e [37,38]. Define the discrete state and control spaces as

    Vh:={yhL2(Ω):yh|τPk(τ)τTh}, (4.3)
    Qh:={qhL2(Γ):qh|τPl(τ)τEh}, (4.4)

    respectively. We denote by Pk, Pl the space of polynomials of degree at most k on each element and at most l on each edge, respectively. In general, the state and control variables can be approximated by polynomials of different degrees k, lN.

    Here, we use the symmetric interior penalty Galerkin (SIPG) method to approximate to the problem. In deriving the SIPG method, we use the following identity

    τTh(ϕn,φ)τ=eEh({ϕ},[[φ]])e+eE0h([[ϕ]],{φ})e=eE0h({ϕ},[[φ]])e+([[ϕ]],{φ})e+eEh(ϕn,φ)e.

    The SIPG solutions qhQh, yhVh and a constant advection field β satisfies the Eq (4.1) for all vhVh where

    ah(yh,vh)=τTh(yh,vh)τ +τTh(βyh+cyh,vh)τ+eEh[γh([[yh]],[[vh]])e({yh},[[vh]])e([[yh]],{vh})e]+eE0h(y+hyh,|nβ|v+h)e+eEh(y+h,v+h|nβ|)e, (4.5)

    where γ is the penalty parameter, which should be chosen sufficiently large to ensure the stability of the SIPG scheme [37,39,40], and yh=limζ0+yh(xζβ), y+h(x)=limζ0+yh(x+ζβ),

    h(f;qh,vh)=τTh(f,vh)τ+eEh(γh(qh,[[vh]])e(qh,{vh})e)+eEh(qh,v+h|nβ|)e. (4.6)

    Then, DG solution is defined as a solution of ah(yh,vh)=h(f;qh,vh) for al all vhVh, and mesh dependent norm

    |||vh|||2=vh2h=τThvh2τ+vh2τ+eEhγh[[vh]]2e,

    which is equivalent to the energy norm [38].

    It has been shown, for example [7], that the bilinear form (4.5) is coercive and bounded on Vh i.e., ah(vh,vh)C|||vh|||2 and ah(yh,vh)C|||yh||||||vh|||, respectively. Thus, Lax-Milgram Lemma guarantees the existence of a unique solution yhVh of the Eq (4.1) for all vhVh.

    We apply the SIPG discretization to the optimal control problem (1.1). Now, define the discrete Lagrangian as

    Lh(ˉyh,ˉqh,ˉzh)=J(ˉyh,ˉqh)+ah(ˉyh,ˉzh)h(f,ˉqh).

    Then, setting the partial Frechet derivatives with respect to yh,qh and zh to be zero, we obtain the discrete optimality system.Then, the discretized optimal control problem has a unique solution (yh,qh)VhxQh if only if there exists zhVh holds the following system:

    Lhˉyhψh=0ah(ψh,ˉzh)=h(ˆyˉyh;0,ψh)ψhVh, (4.7)
    Lhˉqhϕh=0ˉzhn,ϕhΓ=αˉqh,ϕhΓ+γhˉzh,ϕhΓ+ˉzh|nβ|,ϕhΓ  ϕhQh, (4.8)
    Lhˉzhφh=0ah(φh,ˉyh)=h(f;qh,φh)φhVh. (4.9)

    We will need some auxiliary estimates that we will use in the proof of the main result. First, we have some standard estimates which are trace and inverse inequalities and the proofs can be found in [41,42,43].

    Lemma 5.1. There exist positive constants Ctr and Cinv independent of τ and h such that for τTh,

    vτCtr(h1/2vτ+h1/2vτ),vHk+1(τ), (5.1)
    vhτCinvh1vhτ,vhVh, (5.2)

    for integer k0

    Then, we need some basic estimates for L2-Projection where Ph:L2(Ω)Vh is the orthogonal projection such that (Phv,χ)τ=(v,χ)τ for all vL2(τ) and χVh.

    Lemma 5.2. Let Ph be L2-projection. Then, we have that Ph:Hk+1Vh such that for any τTh,

    vPhvL2(τ)Chk+1vHk+1(τ),vHk+1(τ),(vPhv)L2(τ)ChkvHk+1(τ),vHk+1(τ),

    where integer k0.

    Proof. From Local Approximation used in [30], we know that there exists a local interpolant operator Ph:Hk+1Vh such that for any τTh and vHk+1(τ),

    h(vPh(v))τ+vPh(v)τChk+1vHk+1(τ).

    Since h(vPh(v))τh(vPh(v))τ+vPh(v)τChk+1vHk+1(τ), we have

    h(vPh(v))τChk+1vHk+1(τ).

    Thus,

    (vPhv)L2(τ)ChkvHk+1(τ).

    Likewise, we obtain vPhvL2(τ)Chk+1vHk+1(τ).

    Now, we are ready to show the error estimate of SIPG solution in the energy norm.

    Lemma 5.3. Let v be the unique solution of the Eq (2.1) to satisfy vHk+1(Ω) and vhVh be the SIPG solution of the discretized state equation with piecewise polynomials of degree k. Then,

    |||vvh|||ChkvHk+1(Ω),

    for integer k0.

    The proof can be easily seen by using the well-posedness of the bilinear form (4.5), Lemmas (5.1) and (5.2), and it can be also found for example in [44,45]. Next, we will need the estimate of L2-Projection on the boundary Γ where Ph:L2(Γ)Qh is defined by qPhq,ϕhe=0 for all ϕhPs(e).

    Lemma 5.4. Let Ph be L2projection defined on the boundary. Then, for any edge eEh,

    qPqL2(e)+hsqPqWs,p(e)hs|q|Ws,p(e)eEh,

    where Eh is the set of boundary edges which is described in the Eq (4.2), qWs,p(e), 0s1, and 1<p<.

    The proof can be found in [6].

    Note that Lemmas (5.1)–(5.4) state for general reqularity which depends on the polynomial degree k used in SIPG, the regularity on the solution of the optimal control problem is (ˉy,ˉq,ˉz)H1(Ω)×H1/2(Γ)×H2(Ω) by Theorem (3.2). Thus, the following estimates and the main result will be done by using the regularity on the solution of the problem in Theorem (3.2).

    Since SIPG method treats the boundary conditions weakly, SIPG solution is not zero on the boundary even if its continuous solution z is. However, the following result says that the norm of SIPG solution zh on the boundary is rather small.

    Lemma 5.5. Let us define auxiliary variable ˜z to be a solution of the Eq (3.2)

    Δ˜z(β˜z)+c˜z=ˆyyh in Ω˜z=0on Γ,

    and ˜zhVh be the SIPG approximation solution. Then,

    ˜zhL2(Γ)Ch3/2ˆyyhL2(Ω).

    Proof. Let ˜z be a solution to the Eq (3.2). Since

    ˜zhL2(Γ)=˜zh˜zL2(Γ)=[[˜zh˜z]]L2(Γ),

    we can estimated that

    [[˜zh˜z]]L2(Γ)Ch1/2|||˜zh˜z|||,

    by using the definition of the energy norm. Thus, by Theorems (2.2), (3.2) and Lemma (5.3), we have that

    ˜zhL2(Γ)Ch1/2|||˜zh˜z|||Ch1/2h˜zH2(Ω)Ch3/2ˆyyhL2(Ω).

    The estimate of |||yyh||| is more involved because (yyh) does not satisfy the Galerkin orthogonality by (yyh)Vh and ah(yyh,vh)0 for vhVh. First, we can show the following result.

    Lemma 5.6. Let y and yh satisfy

    ah(y,v)=h(f;q,v), vH1(Ω),ah(yh,χ)=h(f;qh,χ),χVh.

    Then,

    |||yyh|||C(h1/2qqhL2(Γ)+yH1(Ω)).

    Proof. By the coersivity, adding and subtracting Phy, we have

    |||yyh|||2ah(yyh,yyh)=ah(yyh,Phyyh)I+ah(yyh,yPhy)II.

    II:

    By using the boundedness of ah(.,.), Theorem (3.2) and Lemma (5.3), k=0 and we obtain

    ah(yyh,yPhy)|||yyh||||||yPhy|||C|||yyh|||yH1(Ω).

    I:

    Since(Phyyh)Vh, we have ah(yyh,Phyyh)=h(0;qqh,Phyyh). Then, we have

    h(0;qqh,Phyyh)=eEh(γh(qqh,[[Phyyh]])e(qqh,{(Phyyh)})e)+eEh(qqh,(Phyyh)+|nβ|)e.

    By the definition of h(,), we can see that eγh(qqh,[[Phyyh]])e is the dominating term by being γh large. Using the fact that [[Phyyh]]L2(Γ) is a part of the energy norm and Lemma (5.3) for k=0 since yH1(Ω), we have

    h(0;qqh,Phyyh)Ceγh(qqh,[[Phyyh]])eCh1(eqqh2L2(e))1/2(e[[Phyyh]]2L2(e))1/2Ch1qqhL2(Γ)[[Phyyh]]L2(Γ)Ch1qqhL2(Γ)h1/2|||Phyyh|||Ch1/2qqhL2(Γ)(|||Phyy|||+|||yyh|||)Ch1/2qqhL2(Γ)(yH1(Ω)+|||yyh|||).

    The other terms in h(0;qqh,Phyyh) can be estimated with the similar way. Thus,

    |||yyh|||2I+IICyH1(Ω)|||yyh|||+Ch12qqhL2(Γ)|||yyh|||+Ch12qqhL2(Γ)yH1(Ω)14|||yyh|||2+Ch1qqh2L2(Γ)+Cy2H1(Ω).

    By first taking the square root and then canceling |||yyh|||, we obtain

    |||yyh|||C(h1/2qqhL2(Γ)+yH1(Ω)).

    Using a duality, we can show better estimate in L2 norm.

    Lemma 5.7. Let y be the solution of the Eq (2.1) and yh in Vh satisfy the bilinear form (4.5). Then,

    yyhL2(Ω)C(h1/2qqhL2(Γ)+hyH1(Ω)).

    Proof. Since yh is not a Galerkin projection of y, let us define ˜yh by ah(y˜yh,χ)=0 for χVh. Then, by the triangle inequality, we have

    yyh2L2(Ω)y˜yh2L2(Ω)K1+˜yhyh2L2(Ω)K2.

    K1

    Consider the following equation,

    Δt(βt)+ct=y˜yh in Ωt=0 on Γ.

    By the boundedness of the bilinear form and using the Galerkin orthogonality,

    y˜yh2L2(Ω)=ah(y˜yh,t)=ah(y˜yh,tPht)+ah(y˜yh,Pht)=0C|||tPht|||.|||y˜yh|||ChtH2(Ω)|||y˜yh|||.

    By using Theorem (2.2) and Lemma (5.3), we obtain

    K1Chy˜yhL2(Ω)yH1(Ω)14y˜yh2L2(Ω)+Ch2y2H1(Ω).

    By canceling y˜yh2L2(Ω), we obtain that

    K1Ch2y2H1(Ω).

    K2:

    Let us define another dual equation,

    Δv(βv)+cv=˜yhyhin Ωv=0on Γ.
    ˜yhyh2L2(Ω)=ah(˜yhyh,v)=ah(~yhy,v)K21+ah(yyh,v)K22.

    K21:

    Likewise K1,

    K21=ah(˜yhy,v)=ah(˜yhy,vPhv)+ah(˜yhy,Phv)=0C|||vPhv||||||˜yhy|||ChvH2(Ω)|||˜yhy|||.

    By using Theorem (2.2) and Lemma (5.3), we obtain

    K21Ch˜yhyhL2(Ω)yH1(Ω).

    K22:

    K22=ah(yyh,v)=ah(yyh,vPhv)K221+ah(yyh,Phv)K222.

    By using the boundedness of the bilinear form, Theorem (2.2) and Lemma (5.3),

    K221=ah(yyh,vPhv)C|||vPhv||||||yyh|||ChvH2(Ω)|||yyh|||Ch˜yhyhL2(Ω)|||yyh|||.

    By using Lemma (5.6), we obtain

    K221Ch˜yhyhL2(Ω)|||yyh|||Ch˜yhyhL2(Ω)(h1/2qqhL2(Γ)+yH1(Ω))C˜yhyhL2(Ω)(h1/2qqhL2(Γ)+hyH1(Ω)).

    K222:

    Using the fact that v=0 on Γ, Theorems (2.2), (3.2) and Lemma (5.3), we have that

    K222=ah(yyh,Phv)=h(0;qqh,Phv)Ch1qqhL2(Γ)PhvL2(Γ)Ch1qqhL2(Γ)[[Phvv]]L2(Γ)Ch1qqhL2(Γ)h1/2|||Phvv|||Ch1qqhL2(Γ)h1/2hvH2(Ω)Ch1qqhL2(Γ)h3/2˜yhyhL2(Ω).

    Then, we obtain

    K222Ch1/2qqhL2(Γ)˜yhyhL2(Ω).

    Thus, we have

    ˜yhyh2L2(Ω)K21+K22K221+K222Ch2yH1(Ω)+C˜yhyhL2(Ω)(h1/2qqhL2(Γ)+hyH1(Ω))14˜yhyh2L2(Ω)+Ch2y2H1(Ω)+Chqqh2L2(Γ).

    By canceling ˜yhyh2L2(Ω), we obtain

    ˜yhyh2L2(Ω)Ch2y2H1(Ω)+Chqqh2L2(Γ).

    Finally, we obtain

    yyh2L2(Ω)y˜yh2L2(Ω)+˜yhyh2L2(Ω)C(hqqh2L2(Γ)+h2y2H1(Ω)).

    By taking the square root, we conclude

    yyhL2(Ω)C(h1/2qqhL2(Γ)+hyH1(Ω)).

    Now, we are ready to prove the main result of the paper. We will state it in the next theorem.

    Theorem 5.1. Let Ω be a convex polygonal domain, ˉq be the optimal control of the problem (1.1) and ˉqh be its optimal SIPG solution. Then, for h sufficiently small, there exists a positive constant C independent of h such that

    ˉqˉqhL2(Γ)Ch1/2(|ˉq|H1/2(Γ)+ˉyH1(Ω)+ˆyL2(Ω)), (5.3)

    where (ˉy,ˉq,ˉz)H1(Ω)×H1/2(Γ)×H2(Ω) and ˆyL2(Ω).

    Proof. Since ˉq is the optimal solution of the problem (1.1) and ˉq satisfies the Eq (3.3), we have

    αˉq,ϕhΓ+ϕh,ˉznΓ=0,ϕhQh. (5.4)

    Since ˉqh is the approximate solution of the problem (1.1) and ˉqh satisfies the Eq (4.8), we have

    αˉqh,ϕhΓ+ϕh,ˉzhnΓγhϕh,ˉzhΓˉzh|nβ|,ϕhΓ=0,ϕh Qh. (5.5)

    Subtracting the Eq (5.4) from the Eq (5.5), for any ϕhQh, we have

    αˉqˉqh,ϕhΓ+ϕh,(ˉzˉzh)nΓ+γhϕh,ˉzhΓ+ˉzh|nβ|,ϕhΓ=0. (5.6)

    Taking ϕh=Ph(ˉqˉqh)=PhˉqPhˉqh=Phˉqˉqh in the Eq (5.6) and splitting

    Phˉqˉqh=(Phˉqˉq)+(ˉqˉqh),

    we obtain

    αˉqˉqh2L2(Γ)=αˉqˉqh,ˉqˉqhαˉqˉqh,PhˉqˉqΓJ1+Phˉqˉq,(ˉzˉzh)nΓJ2+γhPhˉqˉq,ˉzhΓJ3+Phˉqˉq,ˉzh|nβ|ΓJ4+ˉqˉqh,(ˉzˉzh)nΓJ5+γhˉqˉqh,ˉzhΓJ6+ˉqˉqh,ˉzh|nβ|ΓJ7=J1+J2+J3+J4+J5+J6+J7. (5.7)

    Now, we shall estimate each term separately. Most terms can be estimated by using the estimate of the L2-projection. However, the term (ˉzˉzh) in J2 and J5 is not in the discrete space, so additional arguments are needed to treat these terms.

    Estimate for J1: By the Cauchy-Schwarz inequality and using Lemma (5.4),

    J1=αˉqˉqh,PhˉqˉqΓαˉqˉqhL2(Γ)PhˉqˉqL2(Γ)C1h1/2|ˉq|H1/2(Γ)ˉqˉqhL2(Γ),

    where C1 depends on α.

    Estimates for J3 and J6: Using Lemma (5.5) to estimate ˉzhL2(Γ), the Cauchy-Schwarz inequality, Lemma (5.7) and the regularity of ˉy, then we have

    J3=γhPhˉqˉq,ˉzhΓγhPhˉqˉqL2(Γ)ˉzhL2(Γ).C3h1h1/2|ˉq|H1/2(Γ)h3/2ˆyˉyhL2(Ω)C3h|ˉq|H1/2ˆyˉyhL2(Ω)C3h|q|H1/2(ˆyL2(Ω)+ˉyH1(Ω)+ˉyˉyhL2(Ω))C3h|q|H1/2(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Likewise,

    J6=γhˉqˉqh,ˉzhΓγhˉqˉqhL2(Γ)ˉzhL2(Γ)C6h1/2ˉqˉqhL2(Γ)ˆyˉyhL2(Ω)C6h1/2ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+ˉyˉyhL2(Ω))C6h1/2ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)),

    where C3 and C6 depend on γ.

    Estimates for J4 and J7: By using the Cauchy-Schwarz inequality, Lemmas (5.5) and (5.7), we have

    J4=Phˉqˉq,ˉzh|nβ|ΓC4h1/2|ˉq|H1/2(Γ)β1/2L(Γ)ˉzhL2(Γ)C4h2|q|H1/2(Γ)β1/2L(Γ)ˆyˉyhL2(Ω)C4h2|ˉq|H1/2(Γ)β1/2L(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+ˉyˉyhL2(Ω))C4h2|ˉq|H1/2(Γ)β1/2L(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Likewise,

    J7=ˉqˉqh,ˉzh|nβ|ΓC7β1/2L(Γ)ˉqˉqhL2(Γ)ˉzhL2(Γ)C7β1/2L(Γ)ˉqˉqhL2(Γ)h3/2ˆyˉyhL2(Ω)C7h3/2β1/2L(Γ)ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+ˉyˉyhL2(Ω))C7h3/2β1/2L(Γ)ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Estimate for J5: By the Cauchy-Schwarz inequality,

    J5=ˉqˉqh,(ˉzˉzh)nΓˉqˉqhL2(Γ)(ˉzˉzh)nL2(Γ).

    Let us define ˜zhVh to be the SIPG solution to ˉz i.e. ah(χ,˜zh)=(ˆyˉy,χ), χVh.

    In particular, ah(χ,ˉz˜zh)=0 by the Galerkin orthogonality. Thus, we continue as following,

    ˉqˉqh,(ˉzˉzh)nΓˉqˉqhL2(Γ)((ˉz˜zh)nL2(Γ)J51+(˜zhˉzh)nL2(Γ)J52).

    J51:

    By the triangle inequality, we have

    (ˉz˜zh)nL2(Γ)(ˉzPhˉz)nL2(Γ)J511+(Phˉz˜zh)nL2(Γ)J512.

    J511:

    By the trace inequality, Theorem (2.2) and Lemma (5.2), we obtain

    J511=(ˉzPhˉz)n2L2(Γ)=eΓ(ˉzPhˉz)n2L2(e)τTh(Ch1ˉzPhˉz2H1(τ)+ChˉzPhˉz2H2(τ))τThChˉz2H2(τ)=Chˉz2H2(Ω)Chˆyˉy2L2(Ω).

    Thus,

    J511=(ˉzPhˉz)nL2(Γ)Ch1/2ˆyˉyL2(Ω).

    J512:

    Since (Phˉz˜zh)Vh, we can apply the trace theorem for discrete function and by using the inverse inequality and Lemma (5.2), we obtain that

    (Phˉz˜zh)nL2(Γ)Ch1/2Phˉz˜zhH1(Ω)Ch1/2|||Phˉz˜zh|||Ch1/2(|||Phˉzˉz|||+|||ˉz˜zh|||)Ch1/2hˉzH2(Ω)Ch1/2ˆyˉyL2(Ω),

    where we have used Lemma (5.3) for k=1 by Theorem (2.2) and Lemma (5.2).

    Thus,

    (Phˉz˜zh)nL2(Γ)Ch1/2ˆyˉyL2(Ω).

    Since J51=J511+J512, we obtain

    J51=(ˉz˜zh)nL2(Γ)Ch1/2ˆyˉyL2(Ω)Ch1/2(ˆyL2(Ω)+ˉyH1(Ω)).

    J52:

    Since we have

    ah(χ,ˉzh)=(ˆyˉyh,χ),ah(χ,˜zh)=(ˆyˉy,χ),

    where χVh. We obtain

    ah(χ,˜zhˉzh)=(ˉyhˉy,χ),χVh. (5.8)

    Now, let us define the following equation

    Δw(βw)+cw=ˉyhˉyin Ωw=0on Γ.

    By using the Eq (5.8),

    ah(χ,˜zhˉzh)=ah(χ,˜zh)ah(χ,ˉzh)=(ˆyˉy,χ)(ˆyˉyh,χ)=(ˉyhˉy,χ)=ah(χ,wh).

    The above equality shows that wh=˜zhˉzh.

    Now, using the inverse inequality and the fact that w=0 on Γ, we obtain

    (˜zhˉzh)nL2(Γ)Ch1˜zhˉzhL2(Γ)=Ch1˜zhˉzhwL2(Γ)Ch1h1/2|||(˜zhˉzh)w|||Ch1/2|||whw|||Ch1/2hwH2(Ω)Ch1/2ˉyhˉyL2(Ω)Ch1/2(h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)),

    where we have used Theorem (2.2) and Lemma (5.3) for k=1 by Lemmas (5.2) and (5.7) in the last step.

    Thus,

    J52=(˜zhˉzh)nL2(Γ)Ch1/2(h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Finally, we obtain

    J5ˉqˉqhL2(Γ)(J51+J52)C5h1/2ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Estimate for J2: By using the the estimation of (ˉzˉzh)nL2(Γ) in J5, Cauchy-Schwarz inequality and Lemma (5.4), we have

    J2=Phˉqˉq,(ˉzˉzh)nΓPhˉqˉqL2(Γ)(ˉzˉzh)nL2(Γ)C2h1/2|ˉq|H1/2(Γ)(ˉzˉzh)nL2(Γ)C2h1/2|ˉq|H1/2(Γ)h1/2(ˆyL(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))=C2h|ˉq|H1/2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Thus,

    J2C2h|q|H1/2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    After using Lemma (5.7) to estimate ˉyˉyhL2(Ω) and combining J1,J2,J3,J4,J5,J6,J7 in the Eq (5.7), we obtain

    αˉqˉqh2L2(Ω)J1+J2+J3+J4+J5+J6+J7C1h12|ˉq|H1/2(Γ)ˉqˉqhL2(Γ)+C2h|ˉq|H1/2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))+C3h|ˉq|H1/2(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))+C4h2|ˉq|H1/2(Γ)β12L(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))+C5h12ˉqˉqhL2(Γ)(ˆyH1(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))+C6h12ˉqˉqhL2(Γ)(ˆyH1(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))+C7h32β12L(Γ)ˉqˉqhL2(Γ)(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω)).

    Notice that we can rewrite the above inequality as

    αˉqˉqh2L2(Γ)CIh|ˉq|2H1/2(Γ)+α4ˉqˉqh2L2(Γ)+CIIh(ˆyL2(Ω)+ˉyH1(Ω)+h1/2ˉqˉqhL2(Γ)+hˉyH1(Ω))2+α4ˉqˉqh2L2(Γ)+CIIIhˉqˉqh2L2(Γ).

    After all simplification, we obtain

    αˉqˉqh2L2(Γ)Ch(|ˉq|H1/2(Γ)+ˆyL2(Ω)+ˉyH1(Ω))2+Chˉqˉqh2L2(Γ),

    where h is sufficiently small such that Chα2 to absorb Chˉqˉqh2L2(Γ) to the left hand side. Thus, we conclude that there exists a positive constant C such that

    ˉqˉqhL2(Γ)Ch1/2(|ˉq|H1/2(Γ)+ˆyL2(Ω)+ˉyH1(Ω)),

    provided h is sufficiently small.

    In this section, we show the features of the method and some numerical examples to support our theoretical results by the method described for the main problem (1.1), (1.2a) and (1.2b). Here, we present numerical results depending on different kinds of domain as the following.

    Since the domain is one dimensional and the boundary is consisting of two points, there is no regularity limitation due to geometry restriction. Thus, we do not expect an optimal convergence rate, but we observe that the method is still stable and convergent in Tables 13 and Figures 34.

    Table 1.  1D Error rates for piecewise linear basis functions.
    h L2yrate H1yrate Leftqrate Rightqrate
    5.00e-01 1.959 1.002 2.007 1.965
    2.50e-01 1.979 1.001 2.006 1.982
    1.25e-01 1.990 1.001 2.004 1.991
    6.25e-02 1.995 1.000 2.002 1.996
    3.12e-02 1.997 1.001 2.001 1.998
    1.56e-03 1.999 1.000 2.001 1.999

     | Show Table
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    Table 2.  1D Error rates for piecewise quadratic basis functions.
    h L2yrate H1yrate Leftqrate Rightqrate
    5.00e-01 2.999 2.013 2.025 2.982
    2.50e-01 2.999 2.007 2.683 2.991
    1.25e-01 3.000 2.004 2.864 2.996
    6.25e-02 3.000 2.002 2.937 2.998
    3.12e-02 2.998 2.001 2.969 2.999
    1.56e-03 1.938 2.001 2.985 2.999

     | Show Table
    DownLoad: CSV
    Table 3.  1D Error rates for piecewise cubic basis functions.
    h L2yrate H1yrate Leftqrate Rightqrate
    5.00e-01 4.436 2.436 3.970 3.866
    2.50e-01 4.425 3.423 3.985 3.983
    1.25e-01 4.380 3.385 3.992 3.991
    6.25e-02 1.188 3.320 3.996 3.996
    3.12e-02 -0.777 3.223 3.998 3.998
    1.56e-03 -1.119 1.268 3.999 3.999

     | Show Table
    DownLoad: CSV
    Figure 3.  Computed and exact state solution.
    Figure 4.  State solution error.

    By setting Ω=[0,1], ϵ=1, α=1, β=[1], ˉq=(1x)2(x2), c=0, ˉy=x4ex1ϵe1ϵ1e1ϵ, and ˉz=αϵ(1x)2x2.

    By setting the problem as the following,

    Ω=[0,1]×[0,1], β=[1;1], c=1,α=1, ˉq=1ϵ(x(1x)+y(1y)),ˉy=1ϵ(x(1x)+y(1y)), ˉz=αϵ(xy(1x)(1y)).

    Here, we consider piecewise linear continuous functions to approximate the optimal control.

    The first order conditions allow us deduce the regularity results of the optimal control and so the expected convergence rate has agreed well with the rate in [6] as ˉqˉqhL2(Γ)Ch by the square domain with the largest interior angle wmax=π2.

    Lemma (5.7) and ˉqˉqhL2(Γ)Ch yield ˉyˉyhL2(Ω)Ch3/2. Since the power of h on the right-hand side drops for one for each derivative of the error (ˉyˉyh), ˉyˉyhH1(Ω)Ch1/2 by Lemma (5.2). Likewise, From Lemma (5.2) and zH2, ˉzˉzhL2(Ω)Ch2, and so ˉzˉzhH1(Ω)Ch as our expected convergence rates indicated in Tables 4 and 5. Also, the expected rates have agreed well with the rates for the different densities of the meshes in [6]. Also, we can see the stability of the method in Figure 5.

    Table 4.  Error for the regular case on the unit square domain.
    h ˉyˉyhL2 ˉyˉyhH1 ˉqˉqhL2 ˉzˉzhL2 ˉzˉzhH1
    5.00e-01 1.92e-01 3.91e+00 1.07e+00 4.31e-02 9.19e-01
    2.50e-01 8.44e-02 2.25e+00 4.86e-01 1.38e-02 5.06e-01
    1.25e-01 3.14e-02 1.27e+00 2.29e-01 4.21e-03 2.62e-01
    6.25e-02 1.10e-02 7.33e-01 1.09e-01 1.22e-03 1.32e-01
    3.12e-02 3.80e-03 4.49e-01 5.20e-02 3.32e-04 6.66e-02

     | Show Table
    DownLoad: CSV
    Table 5.  Error rates for the regular case on the unit square domain.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 1.19 0.80 1.13 1.64 0.86
    1.25e-01 1.43 0.83 1.08 1.72 0.95
    6.25e-02 1.51 0.79 1.08 1.79 0.98
    3.12e-02 1.53 0.71 1.06 1.87 0.99
    expected 1.50 0.50 1.00 2.00 1.00

     | Show Table
    DownLoad: CSV
    Figure 5.  Exact and computed control for the regular case on the unit square domain are shown in green and red, respectively.

    Since ϵ is too small for this case such as ϵ=105, h|β|ϵ>1 which means the advection-diffusion dominated case occurs. The norm of y depends on ϵ such that ˉyHk+1(Ω)Cϵk+1/2. Since the convergence rate of ˉq depends on data of ˉy from the main result, we do not expect any convergence rate and so this case does not contradict with our main result. Also, the feature of the method shows itself that Dirichlet boundary condition is almost ignored by the method as a result of weak treatment and it does not resolve the layers and causes oscillations on the boundary. It can be seen in Figure 6 and Tables 6 and 7 that some oscillatory solutions and non-convergent rate of q appear on the inflow boundary, caused by non-stabilized terms of boundary edges Eh represented by Eh in the bilinear form (4.6) and (4.5), whereas it is stable on both the interior edges E0h and the stabilized boundary edges Eh by the penalty term in the form.

    Figure 6.  Exact and computed control for the the advection-diffusion dominated case on the unit square domain are shown in green and red, respectively.
    Table 6.  Error for the the advection-diffusion dominated case on the unit square domain.
    h ˉyˉyhL2 ˉyˉyhH1 ˉqˉqhL2 ˉzˉzhL2 ˉzˉzhH1
    5.00e-01 4.29e+00 2.68e+01 8.15e+00 5.66e+01 9.52e+02
    2.50e-01 7.69e-01 1.32e+01 2.22e+00 1.51e+01 5.15e+02
    1.25e-01 4.72e-01 1.58e+01 9.70e-01 3.85e+00 2.63e+02
    6.25e-02 3.78e-01 2.36e+01 6.66e-01 9.64e-01 1.32e+02
    3.12e-02 2.55e-01 2.88e+01 6.37e-01 2.40e-01 6.62e+01

     | Show Table
    DownLoad: CSV
    Table 7.  Error rates for the the advection-diffusion dominated case on the unit square domain.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 2.48 1.02 1.87 1.91 0.89
    1.25e-01 0.71 -0.26 1.20 1.97 0.97
    6.25e-02 0.32 -0.58 0.54 2.00 0.99
    3.12e-02 0.57 -0.28 0.06 2.01 1.00

     | Show Table
    DownLoad: CSV

    By a transformation from the unit square domain to obtain a diamond shaped domain Ω with π4, π8 and π10 angles, while the angle of the domain is getting smaller, we expect that the error rate is getting close to the predicted optimal error rate.

    After the transformation from the unit square domain to obtain a diamond shaped domain Ω with π4, π8 and π10 angles, we can observe from tables 810 that the regularity of the state is reducing sharply close to 1 and that we will obtain the predicted rate i.e., ˉqˉqhL2(Γ)Ch1/2 yields ˉyˉyhL2(Ω)Ch1 by Theorem (5.7). There are many researches, see [6,31,46], which obtained an error estimate for the optimal control of order depends on the largest angle of the boundary polygon. Also, we can see the stable behavior of the method in Figures 79.

    Table 8.  Error rates for the regular case with angle on the diamond shape domain with angle π/4.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 1.51 0.80 0.65 1.43 1.78
    1.25e-01 1.47 0.84 0.96 1.75 1.91
    6.25e-02 1.69 0.85 1.05 1.89 1.96
    3.12e-02 1.75 0.81 1.05 1.95 1.98
    1.56e-02 1.73 0.74 1.03 1.97 1.99

     | Show Table
    DownLoad: CSV
    Table 9.  Error rates for the regular case with angle on the diamond shape domain with angle π/8.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 1.75 0.72 0.32 1.11 0.76
    1.25e-01 1.16 0.41 0.72 1.63 0.95
    6.25e-02 1.60 0.50 0.97 1.88 0.99
    3.12e-02 1.70 0.55 1.01 1.96 1.00
    1.56e-02 1.66 0.53 1.02 1.99 1.00

     | Show Table
    DownLoad: CSV
    Table 10.  Error rates for the regular case with angle on the diamond shape domain with angle π/10.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 0.85 0.17 0.17 1.03 0.61
    1.25e-01 0.92 0.17 1.59 1.60 1.04
    6.25e-02 1.32 0.26 0.90 1.89 1.14
    3.12e-02 1.50 0.42 1.00 1.98 1.10
    1.56e-02 1.55 0.50 1.02 2.00 1.05

     | Show Table
    DownLoad: CSV
    Figure 7.  Exact and computed control for the regular case with angle π/4 are shown in green and red, respectively.
    Figure 8.  Exact and computed control for the regular case with angle π/8 are shown in green and red, respectively.
    Figure 9.  Exact and computed control for the regular case with angle π/10 are shown in green and red, respectively.

    While the method still works, likewise the frame in the unit square domain, it can be seen in Figure 10 and Table 11 that some oscillatory solutions and non-convergent rate of q appear on the inflow boundary whereas it is stable on the interior edges and the stabilized boundary edges as a result of weak treatment because of not resolving the layers and causing oscillations on the boundary.

    Figure 10.  Exact and computed control for the advection-diffusion dominated case on the diamond shape domain with angle π/4 are shown in green and red, respectively.
    Table 11.  Error rates for the the advection-diffusion dominated case on the diamond shape domain with angle π/4.
    h L2yrate H1yrate L2qrate L2zrate H1zrate
    5.00e-01 0.00 0.00 0.00 0.00 0.00
    2.50e-01 3.35 2.45 3.36 2.87 1.89
    1.25e-01 0.31 0.23 1.41 2.96 1.97
    6.25e-02 -0.01 -0.64 0.81 2.97 1.99
    3.12e-02 0.01 -0.68 0.45 2.45 2.00

     | Show Table
    DownLoad: CSV

    In this paper, we consider Dirichlet boundary optimal control problem governed by the advection-diffusion equation and apply the DG methods to the problem. We show some attractive features of the method such as the stable behavior of the SIPG method into the domain of the smoothness and for the advection dominated case except on the boundary as a result of the boundary weak treatments. We have proven that the convergence rate for the SIPG method is optimal in the interior of the general convex domain. However, all convergence rates in numerical examples are higher than predicted by the main result because the predicted order exists for general convex domain, but obtaining the predicted optimal convergence rate depends on the maximal angle of the domain because of the regularity [6,36,47], which is an interesting topic for future work. Also, for general polygonal domains and Laplace equations it has been shown [6] that

    ˉqˉqhL2(Γ)Ch11p,

    where p>2 depends on the largest angle, and obtaining optimal convergence rates for the p=2 case is another interesting topic for future work.

    I would like to thank to Prof. Dmitriy Leykekhman, my thesis advisor, for helpful discussions and his advisement on my academic journey.

    The author declares no conflict of interest.


    Acknowledgments



    No funding was received for this research. The authors want to acknowledge all the Albanian nurses that contributed to this research for their insights.

    Authors' contribution



    Conceptualization, A.D., S.J.; methodology, A.D., D.I; software, D.I.; formal analysis, A.D., B.D., and D.I.; investigation, E.K., V.B.; data curation A.D., E.K., V.B.; writing—original draft preparation, B.D., A.D. and D.I.; writing—review and editing, A.D., S.J., B.D., D.I.; visualization, A.L.; project administration, A.D., S.J. All authors have read and agreed to the published version of the manuscript.

    Conflict of interest



    The authors have no conflicts of interest.

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