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Research article

Symmetry of positive solutions of a p-Laplace equation with convex nonlinearites

  • Received: 22 September 2022 Revised: 18 January 2023 Accepted: 25 January 2023 Published: 06 April 2023
  • MSC : 35A21, 35B06

  • In this paper, we consider the symmetry properties of the positive solutions of a p-Laplacian problem of the form

    {Δpu=f(x,u),       in     Ω,       u=g(x),          on    Ω,

    where Ω is an open smooth bounded domain in RN,N2, and symmetric w.r.t. the hyperplane Tν0(ν is a direction vector in RN,|ν|=1), f: Ω×R+R+ is a continuous function of class C1 w.r.t. the second variable, g0 is continuous, and both f and g are symmetric w.r.t. Tν0, respectively. Introducing some assumptions on nonlinearities, we get that the positive solutions of the problem above are symmetric w.r.t. the direction ν by a new simple idea even if Ω is not convex in the direction ν.

    Citation: Keqiang Li, Shangjiu Wang. Symmetry of positive solutions of a p-Laplace equation with convex nonlinearites[J]. AIMS Mathematics, 2023, 8(6): 13425-13431. doi: 10.3934/math.2023680

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  • In this paper, we consider the symmetry properties of the positive solutions of a p-Laplacian problem of the form

    {Δpu=f(x,u),       in     Ω,       u=g(x),          on    Ω,

    where Ω is an open smooth bounded domain in RN,N2, and symmetric w.r.t. the hyperplane Tν0(ν is a direction vector in RN,|ν|=1), f: Ω×R+R+ is a continuous function of class C1 w.r.t. the second variable, g0 is continuous, and both f and g are symmetric w.r.t. Tν0, respectively. Introducing some assumptions on nonlinearities, we get that the positive solutions of the problem above are symmetric w.r.t. the direction ν by a new simple idea even if Ω is not convex in the direction ν.



    Let ν be a direction vector in RN,N2,|ν|=1, and ΩRN be an open bounded smooth domain which is symmetric with respect to the hyperplane Tν0:={xRN|xν=0}. Let us study the symmetry of the positive solutions of the p-Laplace problem of the form

    {Δpu=f(x,u),       in     Ω,           u=g(x),          on    Ω,     (1.1)

    where Δpu=div(|u|p2u) with p>1, f: Ω×R+R+ is a continuous function of class C1 w.r.t. the second variable, g0 is continuous, and both f and g are symmetric w.r.t. Tν0.

    For the case p=2, the research of symmetry properties for solutions of differential equation was started by Serrin [1], by the method of moving planes (MMP), which was also called Alexandrov reflection method. Since the MMP is essentially a monotonicity method it usually works very well, when g0,u>0 in Ω and f has some monotonicity in x. Later, in the celebrated papers [2,3], by MMP, Gidas, Ni and Nirenberg proved that any positive solution uC2(¯Ω) of the problem Δu=f(u) in Ω with u=0 on Ω is radially symmetric when f(s) is C1 and Ω is a ball in RN or Ω=RN (assuming that u(x)=o(|x|2N) at infinity). After that, in a general bounded domain Ω (RN), which is convex in the x1 direction, Berestycki and Nirenberg in [4] proved that monotonicity and symmetry w.r.t. the x1 direction for positive solutions uW2,Nloc(Ω)C(¯Ω) of nonlinear elliptic equations.

    For the p-Laplace operator, the coefficient (|u|p2) is vanishing or singular at the critical points of u for p>2 or 1<p<2, respectively. So, many symmetry results of positive solutions for p-Laplace equations were proved under some assumptions on the critical set of u. Symmetry results for positive solutions of p-Laplace equations, without any assumptions on the critical set of u, were obtained in [5,6] for bounded domains and in [7] for RN, by MMP. In [8], the authors studied the symmetry of nonnegative C1 ground states of a class of quasilinear elliptic equations. For p>2, the monotonicity and symmetry properties for nonnegative solutions of Δpu=f(u) in B with the boundary condition u=0, where Δp is the p-Laplace-Beltrami operator and B is a geodesic ball in hyperbolic space HN, was studied in [9].

    In this paper, even if Ω is not convex in the direction ν orthogonal to Tν0, f may not have the right monotonicity in x, and u doesn't vanish on the boundary of Ω, we obtain u is symmetric w.r.t. the hyperplane Tν0, which is different from the previous results.

    To be more precise, let xν0 denote the reflection point of x w.r t. Tν0, i.e.,

    xν0=Rν0(x):=x2(xν)ν,

    and to guarantee that the p-Laplace equation is uniformly elliptic, we give an hypothesis on the positive solution u of (1.1),

    u(x)0,    x¯Ω. (1.2)

    So, by (1.2), it follows that the quasilinear second order operator in (1.1) is nondegenerate elliptic.

    Now, we state the main result of the paper as follows.

    Theorem 1.1. Assume uC1(¯Ω) is a positive solution of (1.1) and (1.2) holds. If f(x,s) and g(x)0 are symmetric w.r.t the hyperplane Tν0, f is strictly convex in s and the derivative of f with respect to the second variable s is nonpositive, i.e., fs satisfies following inequality

    fs(x,s)0,   (x,s)Ω×R+, (1.3)

    then u is symmetric with respect to Tν0, i.e., u(x)=u(xν0) for any xΩ. Furthermore, if f(x,s) is convex in s and fs(x,s)<0, for (x,s)Ω×R+, the same result holds.

    This paper is motivated by [10], where the authors studied the symmetry of the solutions of semilinear elliptic equations with convex nonlinearites for the case p=2. In [10], the author proved that nonnegativity of the first eigenvalue of the linearized operator in the caps determined by the symmetry of Ω is a sufficient condition for the symmetry of the solution, when the nonlinearities and the boundary value condition have some symmetric in x. Here, for the p-Laplace equation in (1.1), p>1, we introduce the nonpositivity of the derivative of f w.r.t. the second variable instead of the nonnegativity of the first eigenvalue of linearized operator in [10]. Under our assumptions, we prove that the positive solution u of (1.1) is symmetric w.r.t. the direction ν by a novel simple method instead of the method of moving planes.

    In this section, we give some notations. For the direction νRN, set Ω and Ω+ for the caps of the left and right of Tν0, i.e.,

    Ω={xΩ| xν<0}  and  Ω+={xΩ| xν>0}.

    Let us define the reflected functions of u in the domains Ω and Ω+ by v and v+, respectively,

    v(x)=u(x2(xν) ν),  xΩ,
    v+(x)=u(x2(xν) ν),  xΩ+.

    Hence, by definition, v and v+ are solutions of (1.1) in Ω and Ω+, respectively, and by the condition (1.2), we have

    u0  in  Ω,      v0,  in  Ω,      v+0  in  Ω+. (2.1)

    Furthermore, by (2.1) and the definitions of v and v+, we also get

    uv  in  Ω,         uv+  in  Ω+. (2.2)

    What's more, regularity theory for quasilinear elliptic equations [11] give us that any positive solution of the p-Laplacian equation in (1.1) satisfying (1.2) also satisfies uC2(BRZ)(=C2(BR)), where Z is the set of critical points of u.

    Now, by assumptions uC1(¯Ω) and (1.2), it follows that uC2(Ω)C1(¯Ω). Then, we can write Δpu=f(x,u) in the form (see also (2.5) in [8])

    Ni,jaij(x)uij=f(x,u)  in  Ω, (2.3)

    where aij(x) is a bounded continuous function in Ω, uij=2uxixj, i,j=1,...,N.

    Remark 2.1. By (1.2) and Lemma 2.1 in [8], the matrix {aij} is a positive definite  xΩ and the Eq (2.3) is uniformly elliptic in Ω.

    Next, we recall a lemma proved by Simon in [12] and Damascelli in [13], which will be used to prove the main result later.

    Lemma 2.1. Let p>1 and N(2)N. There exists a positive constant c depending on p and N such that for all η,ηRN with |η|+|η|>0,

    (|η|p2η|η|p2η)(ηη)c(|η|+|η|)p2|ηη|2. (2.4)

    In this section, we give the proof of Theorem 1.1. We adopt the notations introduced in Section 2. At last, a remark on the proof is given.

    In order to have a clear proof, we divide it in two steps.

    Firstly, we assume that f(x,s) is the strictly convex in s. In this situation, we obtain

    f(x,v(x))f(x,u(x))fu(x,u(x))(v(x)u(x)),   in Ω, (3.1)
    f(x,v+(x))f(x,u(x))fu(x,u(x))(v+(x)u(x)),   in Ω+, (3.2)

    with the strict inequality whenever v(x)u or v+(x)u. Furthermore, we set

    w=vu in Ω,  and   w+=v+u  in  Ω+.

    Then, since v (or v+) is also a solution of (1.1) in Ω (or Ω+), using the symmetry of f and g with respect to Tν0, by (1.1) and (3.1), we have,

    Δpv(Δpu)=f(x,v)f(x,u)fu(x,u)(vu),  in Ω, (3.3)
    Δpv+(Δpu)=f(x,v+)f(x,u)fu(x,u)(v+u),  in Ω+, (3.4)

    and the strict inequality holds whenever w(x)0 or w+(x)0, and

    w=0   on Ω,   w+=0   on Ω+. (3.5)

    Actually, if w+ and w are both nonnegative in domains Ω+ and Ω, respectively, then w+w0, by the definition. Then, we get u is symmetric w.r.t. Tν0 at once.

    Now, we can use two methods to prove w+ and w are nonnegative in Ω+ and Ω, respectively.

    In this proof, we argue by a contradiction. So we assume one of two functions, without loss of generality, w is negative somewhere in Ω. Then, by (3.3), it follows that

    Δpv(Δpu)fu(x,u)(vu)0     in   Ω, (3.6)

    with the strict inequality whenever w(x)0. Next, considering a connected component D in Ω of the set where w<0, multiplying w on the both sides of (3.6), integrating and by (3.5), we get

    D(|v|p2v|u|p2u)wDfu(x,u)(w)2<0. (3.7)

    But by Lemma 2.1, Eqs (1.3), (2.1) and (2.2), we have

    D(|v|p2v|u|p2u)wDfu(x,u)(w)2=D(|v|p2v|u|p2u)(vu)Dfu(x,u)(w)2Dc(|v|+|u|)p2|vu|2Dfu(x,u)(w)2>0. (3.8)

    So it contradicts to (3.7).

    In this proof, we use the weak maximum principle. Now, since f and g are symmetric with respect to the hyperplane Tν0, by (1.1), differencing the equation for v and u in Ω, v+ and u in Ω+, respectively, and applying the mean value theorem, by (2.3), for w and w+, we obtain

    Ni,jaij(x)wij+Nibi(x)wi=f(x,v)f(x,u),   in  Ω, (3.9)
    Ni,jaij(x)w+ij+Nibi(x)w+i=f(x,v+)f(x,u),   in  Ω+, (3.10)

    where wij=wxixj, wi=wxi, aij(x) and  bi(x), aij(x) and  bi(x) are bounded continuous functions in Ω and Ω+ respectively, i,j1,...,N, the matrix {aij} is positive definite for xΩ, and the matrix {aij} is positive definite for xΩ+.

    Meanwhile, by (1.2) and Remark 2.1 or Lemma 2.1 in [8], we know the Eqs (3.9) and (3.10) are uniformly elliptic in Ω and Ω+, respectively. Actually, since ¯Ω doesn't contain the set Z of critical points of u, the Eqs (3.9) and (3.10) are uniformly elliptic. This is an easy consequence of Z= and of the linearized process exposed by Serrin in [1].

    So, by (1.3), applying the weak maximum principle in the following problems, respectively,

    {Ni,jaij(x)wij+Nibi(x)wifu(x,u)w0,       in    Ω,                                                         w=0,       on   Ω, (3.11)
    {Ni,jaij(x)w+ij+Nibi(x)w+ifu(x,u)w+0,       in    Ω+,                                                         w+=0,       on   Ω+, (3.12)

    we obtain

    wminx¯Ωw=minxΩw=0,  in  Ω,
    w+minx¯Ω+w+=minxΩ+w+=0,  in  Ω+.

    Secondly, we assume that f is convex. Then, we can also get (3.3)–(3.5). To prove the symmetry of u in Ω, the fact that w0 and w+0 are both nonnegative in the respective domains Ω and Ω+ are useful. In this situation, the arguments to prove that w+ and w are both negative are similar to the situation above. On the one hand, we can argue by a contradiction. In this way, we still assume w is negative somewhere in Ω. Next, the (3.7) is changed to

    D(|v|p2v|u|p2u)wDfu(x,u)(w)20, (3.13)

    and the (3.8) still holds. Then, we get a contradiction by (3.13) and (3.8). On the other hand, we can also get w+0 and w0 in Ω+ and Ω by the weak maximum principle, respectively. So the symmetry of u w.r.t. Tν0 is proved.

    Remark 3.1. (1) Since the domain Ω can be not convex in the direction ν in our problem and the method of moving planes can't be applied to the symmetry of the solutions, we don't get the monotonicity of the solutions in Ω+ or Ω by our method.

    (2) The assumption that the critical set Z= plays an important role to guarantee the quasilinear second order operator in (1.1) is nondegenerate and the quasilinear Eqs (2.3), (3.9) and (3.10) are uniformly elliptic.

    As the critical set Z={xΩ|u(x)=0}, the authors in [5,14] considered not only the symmetry but also the monotonicity of the positive solution of the problem

    {Δpu=f(u),          in     Ω,           u=0,              on    Ω,     (3.14)

    where Ω is an open bounded smooth convex domain in RN,N2,1<p<2 or p>1.

    Exactly, in [5], for 1<p<2, the authors considered the symmetry and monotonicity for the positive solution u of Δpu=f(u) satisfying an homogenuous Dirichlet boundary condition in Ω by MMP, and in [14], for p>1, under the assumption that the critical set Z has only one point in Ω that is the origin, i.e., ZΩ={0}, the symmetry and monotonicity of the positive solution of (3.14) is gotten by MMP.

    In this paper, we get the symmetry of the positive solutions of the problem

    {Δpu=f(x,u),       in     Ω,       u=g(x),          on    Ω,

    where Δpu=div(|u|p2u) with p>1, Ω is an open smooth bounded domain in RN,N2, and symmetric w.r.t. the hyperplane Tν0(ν is a direction vector in RN,|ν|=1), both f and g are symmetric w.r.t. Tν0. Assuming some nonlinearities, we prove that the solutions are symmetric w.r.t. the direction ν by a novel simple idea even if Ω is not convex in the direction ν and there are nonzero boundary values. In this paper, the symmetry is different from that gotten by the method of moving planes. So, by our method, the monotonicity of the solutions is not gotten.

    This work is partially supported by NSFC (No. 11501178) and China Scholarship Council (No. 202108410329), Shaoguan Science and Technology Project (No. 210726224533614, 210726214533591, 220606164534145), Natural Science Foundation of Guangdong Province (No. 2021A1515010292, 2022A1515011358), Innovative team project of ordinary universities of Guangdong Province (No. 2020KCXTD024), Characteristic Innovative Project from Guangdong Provincial Department of Education (No. 2020KTSCX134), and National College Students Innovation and Entrepreneurship Training Program (No. 202210576012).

    The authors declare no conflicts of interest.



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