Stability estimates for scalar conservation laws with moving flux constraints

  • Received: 01 October 2016 Revised: 01 January 2017
  • Primary: 35L65; Secondary: 35B35

  • We study well-posedness of scalar conservation laws with moving flux constraints. In particular, we show the Lipschitz continuous dependence of BV solutions with respect to the initial data and the constraint trajectory. Applications to traffic flow theory are detailed.

    Citation: Maria Laura Delle Monache, Paola Goatin. Stability estimates for scalar conservation laws with moving flux constraints[J]. Networks and Heterogeneous Media, 2017, 12(2): 245-258. doi: 10.3934/nhm.2017010

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  • We study well-posedness of scalar conservation laws with moving flux constraints. In particular, we show the Lipschitz continuous dependence of BV solutions with respect to the initial data and the constraint trajectory. Applications to traffic flow theory are detailed.



    Motivated by the modeling of moving bottlenecks in traffic flow, which can be caused by a large, slow moving vehicle, we consider the Cauchy problem for a scalar conservation law with moving flux constraint

    tρ+xf(ρ)=0,(t,x)R+×R, (1a)
    ρ(0,x)=ρ0(x),xR, (1b)
    f(ρ(t,y(t)))˙y(t)ρ(t,y(t))˜Fα(˙y(t)),tR+, (1c)

    where ty(t) is a given trajectory, starting from y(0)=y0, and

    ˜Fα(˙y):=Fα(ρα(˙y))=fα(ρα(˙y))˙yρα(˙y), (2)

    with ρα(˙y) such that f(ρα(˙y)/α)=˙y. Systems of the form (1) arise in the modeling of moving bottlenecks in vehicular traffic [12,16]: ρ=ρ(t,x)[0,R] is the scalar conserved quantity and represents the traffic density, whose maximum attainable value is R. The flux function f:[0,R]R+ is assumed to be strictly concave, Lipschitz continuous and such that f(0)=f(R)=0. The time-dependent variable y denotes the constraint position. In the present paper we consider a weakly coupled PDE-ODE system, in the sense that we assume that the constraint trajectory is given, and it does not depend on the solution of (1a).

    Let us detail the meaning of inequality (1c). A moving flux constraint located at x=y(t) acts as an obstacle, thus hindering the flow as expressed by the unilateral constraint (1c). There, α ]0,1[ is the dimensionless reduction rate of the road capacity (the maximal allowed density) at the bottleneck position. The inequality (1c) is derived by studying the problem in the constraint reference frame, i.e., setting ˜ρ(t,x):=ρ(t,x+y(t)) and rewriting the conservation law (1a) as

    t˜ρ+xF(˜ρ)=0,F(˜ρ)=f(˜ρ)˙y˜ρ. (3)

    In fact, let fα:[0,αR]R+ be the rescaled flux function describing the reduced flow at x=y(t), defined by fα(ρ)=αf(ρ/α), and let ρα(˙y) ]0,αR[ such that

    Fα(ρα(˙y))=fα(ρα(˙y))˙y=0fα(ρα(˙y))=˙y, (4)

    with Fα(ρ)=fα(ρ)˙yρ, see Figure 1. Notice that, for (4) to have a solution in ]0,αR[, we will need to assume that ˙y(t)<f(0) for t0. Then setting ˜Fα(˙y):=Fα(ρα(˙y)) we recover (2). Imposing that in the obstacle reference frame the flux F is less than the maximum value of the flux of the reduced flow, one gets (1c). Notice that the inequality (1c) is always satisfied if

    Figure 1.  Graphical representation of the constraint action in the fixed (left) and moving (right) reference frames.
    ˙y(t)=f(ρ(t,y(t)±))ρ(t,y(t)±),

    since its left-hand side is 0. Moreover, it is well defined even if ρ has a jump at y(t), because of the Rankine-Hugoniot conditions.

    Problem (3), (1b), (1c), can therefore be recast in the framework of conservation laws with fix local constraint, first introduced in [10], then developed in [2,4] for scalar equations and extended in [3,14,13] to systems. Following [12,Definition 4.1] and [6,Definition 1 and 2], solutions of (1) are defined as follows.

    Definition 1.1. Let yW1,(R+;R) with 0˙y<f(0) and ρ0L1L(R;[0,R]) be given. A function ρC0(R+;L1(R;[0,R])) is a solution to (1) if

    1. ρ satisfies Kružkov entropy conditions [15] on (R+×R){(t,y(t)):tR+}, i.e. for every k[0,R] and for all φC1c(R2;R+) and φ(t,y(t))=0, t>0,

    R+R(|ρk|tφ+sgn(ρk)(f(ρ)f(k))xφ)dx dt+R|ρok|φ(0,x) dx0 ; (5a)

    2. for a. e. t>0 the left and right traces of ρ at x=y(t) satisfy

    (ρ(t,y(t)),ρ(t,y(t)+))Gα(˙y(t)). (5b)

    Notice that the left and right traces in (5b) do exist, see [4,Section 2].

    The set Gα(˙y) in (5b) is defined as follows, see [4,5,6].

    Definition 1.2. The admissibility germ Gα(˙y)[0,R]2 for (1a), (1c) is the union Gα(˙y):=G1(˙y)G2(˙y)G3(˙y), where

    G1(˙y):={(cL,cR)[0,R]2:cL>cR, f(cL)˙ycL=f(cR)˙ycR=Fα(˙y)},G2(˙y):={(c,c)[0,R]2:f(c)˙ycFα(˙y)},G3(˙y):={(cL,cR)[0,R]2:cL<cR, f(cL)˙ycL=f(cR)˙ycRFα(˙y)}.

    We refer the reader to Figure 2 for a graphical representation of Gα(˙y)

    Figure 2.  The set Gα(˙y) (thick lines) in the case of a flux function of the form f(ρ)=Vρ(1ρ/R), as in Section 3.

    The equivalence between Definition 1.1 and [12,Definition 4.1] can be proved as in [4,Proposition 2.6].

    Systems of the type (1) arise in the modeling of moving bottlenecks in traffic flows, see [12,16] and Section 3 below, where they are coupled with an ODE depending on the downstream traffic velocity and describing the trajectory of a slow moving vehicle (a bus or a truck) acting as a bottleneck.

    This paper is a first step towards establishing well-posedness for the strongly coupled models [12,16]. Section 2 presents the main result, stating the L1 Lipschitz continuous dependence of solutions of (1) from the initial data and the constraint trajectory. Section 3 describes in details the related traffic flow model with moving bottleneck. Technical proof details are deferred to Appendix A.

    Let us fix the constraint trajectory yW1,(R+;R) with 0˙y<f(0) and the initial datum ρ0BV(R;[0,R]), and let ρC0(R+;L1(R;[0,R])) be a solution of (1) in the sense of Definition 1.1. Applying the coordinate transformation ˜ρ(t,x):=ρ(t,x+y(t)), ˜ρ is a weak entropy solution of the problem

    t˜ρ+xF(˜ρ)=0,(t,x)R+×R, (6a)
    ˜ρ(0,x)=ρ0(x+y0),xR, (6b)
    F(˜ρ(t,0))˜Fα(˙y(t)),tR+, (6c)

    in the sense of [4,Proposition 2.6(A)] where we have set F(˜ρ):=f(˜ρ)˙y˜ρ. Existence and uniqueness for (6) are proved in [4,10]. In particular, we have that for every k[0,R] and for all φC1c(R2;R+) such that φ(t,0)=0, t>0,

    R+R(|˜ρk|tφ+Φ(˙y;˜ρ,k)xφ)dx dt+R|ρo(x+y0)k|φ(0,x) dx0 ,

    where we have set

    Φ(˙y;a,b):=sgn(ab)(f(a)f(b))˙y|ab|,for a,bR,

    and

    (˜ρ(t,0),˜ρ(t,0+))Gα(˙y(t))for a. e. t>0,

    see [4,Proposition 2.6]. Moreover, we note that, since α<1 and f is strictly concave, we have

    ˜Fα(˙y)=fα(ρα(˙y))˙yρα(˙y)<f(ρα(˙y))˙yρα(˙y)=maxρ[0,R]F(ρ). (7)

    Remark 1. Solution to (6) are not in BV in general (see [1,10]), but thanks to the strict inequality in (7) and since yW1,(R+;R) implies ˙yBVloc(R+), we can conclude that ˜ρ(t,)BV(R;[0,R]) for any t>0, as in [12].

    We compare solutions of (6) corresponding to different constraint trajectories y and z.

    Theorem 2.1. Assume y,zW1,(R+;R), with 0˙y,˙z<f(0), ˜ρ0,˜σ0L(R,[0,R]) and ˜ρ0˜σ0L1(R). Let ˜ρ,˜σC0(R+;L1(R;[0,R])) be solutions of (6) corresponding respectively to y,˜ρ0 and z,˜σ0. Moreover, let Ct=sups[0,t]TV(˜ρ(s,)) be finite. Then we have

    |˜ρ(t,)˜σ(t,)|L1(R)|˜ρ0˜σ0|L1(R)+(Ct+2R)˙y˙zL1([0,t]). (8)

    Proof. The two solutions ˜ρ, ˜σ satisfy

    t|˜ρk|+xΦ(˙y;˜ρ,k)0, (9)
    t|˜σk|+xΦ(˙z;˜σ,k)0, (10)

    in D(R+×R) (where we have noted R=R{0}). Following the proofs of [6,Lemma 15] and [7,Theorem 3.1] we observe that

    t|˜ρk|+xΦ(˙y;˜ρ,k)=t|˜ρk|+xΦ(˙z;˜ρ,k)+xΦ(˙y;˜ρ,k)xΦ(˙z;˜ρ,k)

    therefore

    t|˜ρk|+xΦ(˙z;˜ρ,k)xΦ(˙z;˜ρ,k)xΦ(˙y;˜ρ,k)|˙y˙z||x˜ρ|. (11)

    Applying the classical Kružkov doubling of variables technique [15], with a test function ψC1c(R2;R+) such that ψ(t,0)=0, we deduce the following Kato inequality

    R+R(|˜ρ˜σ|tψ+Φ(˙z;˜ρ,˜σ)xψ)dx dt+R|˜ρ0˜σ0|ψ(0,x) dx+Ct|ψ|R+|˙y˙z|dt0 ,

    We now choose the test function ψ(t,x)=θε(x)ξ(t,x), where ξC1c(R2;R+) is an approximation of the characteristic function of the trapezoid

    {(s,x):|x|M+L(ts), 0st}

    (where Lsupρ[0,R],s[0,t]|f(ρ)˙z(s)| and MR, M>0) and θε a smooth approximation of xmin{|x|/ε,1}. Following the proof of [10,Proposition 4.4] and letting ε0 we get

    MM|˜ρ(t,x)˜σ(t,x)|dxM+LtMLt|˜ρ0(x)˜σ0(x)|dx+Ct0|˙y(s)˙z(s)|ds+t0(Φ(˙z;˜ρ(t,0+),˜σ(t,0+))Φ(˙z;˜ρ(t,0),˜σ(t,0)))ds.

    By Lemma A.1, the last integrand can be bounded by

    t0(Φ(˙z;˜ρ(t,0+),˜σ(t,0+))Φ(˙z;˜ρ(t,0),˜σ(t,0)))ds2Rt0|˙y(s)˙z(s)|ds. (12)

    Letting M, we recover (8).

    We are now able to state the well-posedness of problem (1).

    Corollary 1. Assume y,zW1,(R+;R), with 0˙y,˙z<f(0), ρ0,σ0L(R,[0,R]) and ρ0σ0L1(R). Let ρ,σC0(R+;L1(R;[0,R])) be solutions of (1) corresponding respectively to y,ρ0 and z,σ0. Moreover, let Ct=sups[0,t]TV(ρ(s,)) be finite. Then we have

    |ρ(t,)σ(t,)|L1(R)|ρ0σ0|L1(R)+2Ct|y(0)z(0)|+(2Ct+2R)˙y˙zL1([0,t]). (13)

    Proof. Setting

    ˜ρ(t,x)=ρ(t,x+y(t))and˜σ(t,x)=σ(t,x+z(t)),

    for any t>0 we get

    R|ρ(t,x)σ(t,x)|dx=R|ρ(t,x+z(t))σ(t,x+z(t))|dx=R|ρ(t,x+z(t))ρ(t,x+y(t))σ(t,x+z(t))|dx|y(t)z(t)|TV(ρ(t,))+R|˜ρ(t,x)˜σ(t,x)|dx.

    Therefore, by (8), we get

    R|ρ(t,x)σ(t,x)|dx Ct|y(t)z(t)|+R|˜ρ0(x)˜σ0(x)|dx+(Ct+2R)t0|˙y(s)˙z(s)|ds R|ρ0(x)σ0(x)|dx+|y(0)z(0)|TV(ρ0)+Ct(|y(0)z(0)|+t0|˙y(s)˙z(s)|ds)+(Ct+2R)t0|˙y(s)˙z(s)|ds= R|ρ0(x)σ0(x)|dx+2Ct|y(0)z(0)|+(2Ct+2R)t0|˙y(s)˙z(s)|ds,

    where we have used the estimate |y(t)z(t)||y(0)z(0)|+t0|˙y(s)˙z(s)|ds.

    Setting

    f(ρ):=ρv(ρ),

    where v(ρ)=V(1ρ/R) is the mean traffic speed, V being the maximal velocity allowed on the road, problem (1) can be used to describe the situation of a moving bottleneck along a road, see [12]. In this case, we get fα(ρ)=Vρ(1ραR) and ρα(˙y)=αR2(1˙yV), so that

    ˜Fα(˙y)=αR4V(V˙y)2.

    Let us suppose that a slow and large vehicle, like for example a bus or a truck moves on the road. The slow vehicle, that in the following we will refer as "the bus", reduces the road capacity and moves with a trajectory given by the following ODE:

    {˙y(t)=ω(ρ(t,y(t)+)),tR+,y(0)=y0, (14)

    where the velocity of the bus is given by the following traffic density dependent function (see Figure 3)

    Figure 3.  Bus and cars speed.
    ω(ρ)={Vbif ρρR(1Vb/V),v(ρ)otherwise. (15)

    This means that if the traffic is not too congested, the bus moves at its own maximal speed Vb<V. When the surrounding traffic density becomes too high, the bus adapts its velocity accordingly. In particular, it is not possible for the bus to overtake the cars.

    Solutions of the coupled system (1), (14) for general initial data are defined as follows.

    Definition 3.1. A couple (ρ,y)C0(R+;L1(R;[0,R]))×W1,1(R+;R) is a solution to (1) if

    1. ρ satisfies Kružkov entropy conditions [15] on (R+×R){(t,y(t)):tR+}, i.e. for every k[0,R] and for all φC1c(R2;R+) and φ(t,y(t))=0, t>0,

    R+R(|ρk|tφ+sgn(ρk)(f(ρ)f(k))xφ)dx dt+R|ρok|φ(0,x) dx0 ; (16a)

    2. for a. e. t>0 the one-sided traces of ρ at x=y(t) satisfy

    (ρ(t,y(t)),ρ(t,y(t)+))Gα(˙y(t)); (16b)

    3. y is a Carathéodory solution of (14), i.e. for a.e. tR+

    y(t)=yo+t0ω(ρ(s,y(s)+)) ds . (16c)

    The proof of existence of solutions for the general Cauchy problem (1) strongly coupled with the bus trajectory (14) with BV initial data can be found in [12]. For completeness, we recall the definition of the solution of a Riemann problem, as given in [12]. Let us consider a Riemann type initial datum

    ρ0(x)={ρLif x<0,ρRif x>0,y0=0. (17)

    Denote by R the standard (i.e., without the constraint (1c)) Riemann solver for (1a)-(1b)-(17), i.e., the (right continuous) map (t,x)R(ρL,ρR)(x/t) given by the standard weak entropy solution, see for instance [8,Chapter 5]. Moreover, assume that ˙y is constant and let ˇρ=ˇρ(˙y) and ˆρ=ˆρ(˙y), with ˇρˆρ, be the intersection points of the flux function f(ρ) with the line fα(ρα)+˙y(ρρα) (see Figure 1(a)):

    ˇρ(˙y)=R2V(11α)(V˙y),ˆρ(˙y)=R2V(1+1α)(V˙y). (18)

    Definition 3.2. The constrained Riemann solver Rα:[0,R]2Lloc1(R;[0,R]) corresponding to (1), (14), (17) is defined as follows.

    1. If f(R(ρL,ρR)(Vb))>Fα+VbR(ρL,ρR)(Vb), then

    Rα(ρL,ρR)(x/t)={R(ρL,ˆρ(Vb))(x/t)if x<Vbt,R(ˇρ(Vb),ρR)(x/t)if xVbt,andy(t)=Vbt.

    2. If VbR(ρL,ρR)(Vb)f(R(ρL,ρR)(Vb))Fα+VbR(ρL,ρR)(Vb), then

    Rα(ρL,ρR)=R(ρL,ρR)andy(t)=Vbt.

    3. If f(R(ρL,ρR)(Vb))<VbR(ρL,ρR)(Vb), i.e., v(R(ρL,ρR)(Vb))<Vb then

    Rα(ρL,ρR)=R(ρL,ρR)andy(t)=v(ρR)t.

    Note that, when the constraint is enforced (point 1. in the above definition), a non-classical shock arises between ˆρ(Vb) and ˇρ(Vb), which satisfies the Rankine-Hugoniot condition but violates the Lax entropy condition, see Figure 4 for an example.

    Figure 4.  Different solutions of the Riemann problem (17). Each subfigure illustrates a point of the Definition 3.2: fundamental diagram representation (left) and space-time diagram (right).

    Remark 2. Unfortunately, no result about the Lipschitz continuous dependence of the solution y=y(t) of (14) from the solution ρ=ρ(t,x) of (1) is known at present. Related results [9,11] concerning uniqueness and continuous dependence for ODEs of the form (14) hold under hypothesis on the speed function ω that are not satisfied by (15).

    Lemma A.1 For any (ρ,ρ+)Gα(˙y) and (σ,σ+)Gα(˙z), it holds

    Φ(˙z;ρ+,σ+)Φ(˙z;ρ,σ)2R|˙y˙z|.

    Proof. First of all, let us remark that

    Φ(˙z;ρ+,σ+)Φ(˙z;ρ,σ)=sgn(ρ+σ+)(f(ρ+)˙zρ+f(σ+)+˙zσ+) (19)
    sgn(ρσ)(f(ρ)˙zρf(σ)+˙zσ)=(λ(ρ+,σ+)˙z)|ρ+σ+|(λ(ρ,σ)˙z)|ρσ|, (20)

    where

    λ(ρ,σ)=f(ρ)f(σ)ρσ.

    Without loss of generality, we can assume ˙y<˙z. Therefore we get

    Fα(˙y)Fα(˙z)ρα(˙z)(˙z˙y)>0. (21)

    We distinguish the following cases:

    1. (ρ,ρ+)G1(˙y): we observe that

    ρ=ˆρ, ρ+=ˇρandf(ρ)˙yρ=f(ρ+)˙yρ+=Fα(˙y).

    Depending on the values of σ, σ+, different situations can occur as shown in Figure 5:

    Figure 5.  Case 1.

    1.1 (σ,σ+)G1(˙z): in this case σ=ˆσ, σ+=ˇσ, as shown in Figure 5a and f(σ)˙zσ=f(σ+)˙zσ+=Fα(˙z), therefore

    (19)=(Fα(˙y)+˙yρ+˙zρ+Fα(˙z))(Fα(˙y)+˙yρ˙zρFα(˙z))=(ρρ+)(˙z˙y)R|˙y˙z|.

    1.2 (σ,σ+)G2(˙z): we set

    σ:=σ=σ+andf(σ)˙zσ=:F(σ)Fα(˙z).

    The following cases can occur:

    0σˇσ:

    (19)=(Fα(˙y)+˙yρ+˙zρ+F(σ))(Fα(˙y)+˙yρ˙zρF(σ))=(ρρ+)(˙z˙y)R|˙y˙z|.

    ˆσσˆρ, see Figure 5b:

    (19)=(Fα(˙y)+˙yρ+˙zρ+F(σ))(Fα(˙y)+˙yρ˙zρF(σ))=2F(σ)2Fα(˙y)+(ρ++ρ)(˙z˙y)2Fα(˙z)2Fα(˙y)+2R(˙z˙y)=2ρα(˙z)(˙z˙y)+2R(˙z˙y)2R|˙y˙z|.

    ˆρσR:

    (19)=(Fα(˙y)+˙yρ+˙zρ+F(σ))+(Fα(˙y)+˙yρ˙zρF(σ))=(ρ+ρ)(˙z˙y)0.

    1.3 (σ,σ+)G3(˙z): we set

    f(σ)˙zσ=f(σ+)˙zσ+=:F(σ)Fα(˙z).

    We observe that sgn(ρ+σ+)<0 and sgn(ρσ)>0, see Figure 5c. Therefore

    (19)=(Fα(˙y)+˙yρ+˙zρ+F(σ))(Fα(˙y)+˙yρ˙zρF(σ))=2F(σ)2Fα(˙y)+(ρ++ρ)(˙z˙y)2Fα(˙z)2Fα(˙y)+2R(˙z˙y)=2ρα(˙z)(˙z˙y)+2R(˙z˙y)2R|˙y˙z|.

    2. (ρ,ρ+)G2(˙y): we set

    ρ:=ρ=ρ+andf(ρ)˙yρ=:F(ρ)Fα(˙y).

    as illustrated in Figure 6.

    Figure 6.  Case 2.

    2.1 (σ,σ+)G1(˙z):

    0ρˇσ:

    (19)=(F(ρ)+˙yρ˙zρFα(˙z))+(F(ρ)+˙yρ˙zρFα(˙z))=0.

    ˇσρˇρ, this case is displayed in Figure 6a:

    (19)=(F(ρ)+˙yρ˙zρFα(˙z))+(F(ρ)+˙yρ˙zρFα(˙z))=2F(ρ)2Fα(˙z)+2ρ(˙y˙z)2(Fα(˙y)Fα(˙z))2ρα(˙y)(˙z˙y)2αR|˙y˙z|.

    ˆρρR:

    (19)=(F(ρ)+˙yρ˙zρFα(˙z))(F(ρ)+˙yρ˙zρFα(˙z))=0.

    2.2 (σ,σ+)G2(˙z), illustrated in Figure 6b:

    We observe that sgn(ρ+σ+)=sgn(ρσ)=sgn(ρσ), therefore

    (19)=sgn(ρσ)[(F(ρ)+˙yρ˙zρF(σ))(F(ρ)+˙yρ˙zρF(σ))]=0.

    2.3 (σ,σ+)G3(˙z) shown in Figure 6c: If sgn(ρσ+)=sgn(ρσ), we get

    (19)=sgn(ρσ+)[(F(ρ)+˙yρ˙zρF(σ))(F(ρ)+˙yρ˙zρF(σ))]=0.

    Otherwise, we have that σρˇρ or ˆρρσ+. In this case

    λ(ρ+,σ+)˙z=f(σ+)f(ρ)σ+ρf(σ+)f(σ)σ+σ0,λ(ρ,σ)˙z=f(σ)f(ρ)σρf(σ+)f(σ)σ+σ0,

    by the concavity of f. Therefore, (19)≤0 by (20).

    3. (ρ,ρ+)G3(˙y): we set

    f(ρ)˙yρ=f(ρ+)˙yρ+=:F(ρ)Fα(˙y).

    See Figure 7, for a graphical representation.

    Figure 7.  Case 3.

    3.1 (σ,σ+)G1(˙z), see Figure 7a.

    (19)=(F(ρ)+˙yρ+˙zρ+Fα(˙z))+(F(ρ)+˙yρ˙zρFα(˙z))=2F(ρ)2Fα(˙z)+(ρ++ρ)(˙y˙z)2(Fα(˙y)Fα(˙z))2ρα(˙y)(˙z˙y)2αR|˙y˙z|.

    3.2 (σ,σ+)G2(˙z): If sgn(ρ+σ)=sgn(ρσ), we get

    (19)=sgn(ρ+σ)[(F(ρ)+˙yρ+˙zρ+F(σ))(F(ρ)+˙yρ˙zρF(σ))](ρ+ρ)(˙z˙y)R|˙y˙z|.

    Otherwise as shown in Figure 7b, we have that ρσˇσ or ˆσσρ+. In this case

    λ(ρ+,σ+)˙zλ(ρ+,σ+)˙y=f(ρ+)f(σ)ρ+σf(ρ+)f(ρ)ρ+ρ0.

    Moreover, we observe that λ(ρ,σ)>˙y. Indeed

    λ(ρ,σ)˙y=f(ρ)f(σ)ρσf(ρ+)f(ρ)ρ+ρ0.

    Therefore, by (20)

    (19)R|˙y˙z|.

    3.3 (σ,σ+)G3(˙z):

    We observe that one of the following relations must hold

    ρσ<σ+ρ+,σρ<σ+ρ+,σρ<ρ+σ+.

    For an example see Figure 7c. Therefore

    λ(ρ+,σ+)˙z=f(ρ+)f(σ+)ρ+σ+f(σ+)f(σ)σ+σ0,λ(ρ,σ)˙z=f(ρ)f(σ)ρσf(σ+)f(σ)σ+σ0,

    again by concavity of f. Hence (19)≤0 by (20).

    The authors are grateful to Boris Andreianov for suggesting links with the results in [6]. The authors also thank the two anonymous referees for the careful revision and the insightful comments, which were of great help in improving the paper.

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