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Global existence and boundedness of chemotaxis-fluid equations to the coupled Solow-Swan model

  • In this paper, we consider the following Keller-Segel-(Navier)-Stokes system to the coupled Solow-Swan model

    {nt+un=Δnχ(nc)+μ1nμ2nk,xΩ,t>0,ct+uc=Δcc+μ3cαw1α,xΩ,t>0,wt+uw=Δww+n,xΩ,t>0,ut+κ(uu)=ΔuP+nΦ,u=0,xΩ,t>0,

    in a smooth bounded domain ΩRN(N=2,3) with no-flux boundary for n,c,w and no-slip boundary for u, where the parameters χ>0,α(0,1),μ1R,μ20,μ3>0 and κ{0,1},kN. Due to the interference of the fractional nonlinear term of the Solow-Swan model, we use the Moser-Trudinger inequality to obtain the global existence of the solution for two-dimensional case without logistic source. For three-dimensional case, we control the required estimation with the help of the negative term of logistic source to obtain the boundedness and asymptotic behavior. In the process of estimating the corresponding term, we find the order of the negative term of the logistic source is related to the spatial dimension, and we give the decay estimate of the corresponding solutions when μ1<0 or μ1=0,μ2>0.

    Citation: Jie Wu, Zheng Yang. Global existence and boundedness of chemotaxis-fluid equations to the coupled Solow-Swan model[J]. AIMS Mathematics, 2023, 8(8): 17914-17942. doi: 10.3934/math.2023912

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  • In this paper, we consider the following Keller-Segel-(Navier)-Stokes system to the coupled Solow-Swan model

    {nt+un=Δnχ(nc)+μ1nμ2nk,xΩ,t>0,ct+uc=Δcc+μ3cαw1α,xΩ,t>0,wt+uw=Δww+n,xΩ,t>0,ut+κ(uu)=ΔuP+nΦ,u=0,xΩ,t>0,

    in a smooth bounded domain ΩRN(N=2,3) with no-flux boundary for n,c,w and no-slip boundary for u, where the parameters χ>0,α(0,1),μ1R,μ20,μ3>0 and κ{0,1},kN. Due to the interference of the fractional nonlinear term of the Solow-Swan model, we use the Moser-Trudinger inequality to obtain the global existence of the solution for two-dimensional case without logistic source. For three-dimensional case, we control the required estimation with the help of the negative term of logistic source to obtain the boundedness and asymptotic behavior. In the process of estimating the corresponding term, we find the order of the negative term of the logistic source is related to the spatial dimension, and we give the decay estimate of the corresponding solutions when μ1<0 or μ1=0,μ2>0.



    The Keller and Segel model in [22] was introduced in 1970, and the mathematical study of this system has extensively developed the parabolic-parabolic equations in [13,24,28,36,39] and the parabolic-elliptic equations in [2,3,7,14,15,37]. This model is used to describe the chemotaxis-aggregation phenomena in nature.

    Cells and microorganisms usually live in fluid, so it is particularly important to consider the interaction of fluids with them. In view of this idea, Tuval et al. considered the experiment of the collective behavior of \emph{Bacillus subtilis} in [49]. Then, a large number of related results of global solvability for chemotaxis-fluid were investigated in recent years. For example, we can see the researches of introducing the Keller-Segel equations in [1,20,34,46,55,78], the Keller-Segel-Navier-Stokes equations in [5,6,9,10,21,25,27,31,41,42,43,47,51,52,53,54,56,57,58,62,63,64,66,67,68,69,70,71,73,76,77,79], the rotational flux term in [5,21,31,51,58,59,64,79], the nonlinear diffusion in [8,11,41,48,73], the logistic source in [12,47,54,62,78], the singular sensitivity in [13,14,15,24,52,65,75] etc. These papers on global existence and boundedness analysis gave a good theoretical and guiding significance for our understanding of biological growth of cells. Due to the global existence of the solution, we do not have to worry about the occurrence of sudden change and other unexpected results, and can achieve the purpose of guiding experiments with theory.

    Recently, a macroscopic model called the spatial Solow-Swan was proposed by Juchem Neto et al. in [16,17,18] for describing economic growth phenomena under capital induction and labor migration. Very recently, Li-Li [26] investigated global boundedness of the following model

    {nt=Δnχ(nc)+μ1nμ2n2,xΩ,t>0,ct=Δcc+μ3cαn1α,xΩ,t>0.

    Assuming that the dynamic behavior of microscopic particles also meets the above macroscopic model, it is necessary to consider the Keller-Segel-Solow-Swan model. For the above model, there are two difficulties: the first equation contains cross diffusion term (nc), and the second contains the Cobb-Douglas function μ3cαn1α. Therefore, it becomes very interesting to use the corresponding mathematical theory to deal with this problem. Recently, more results in [29,30,32,33,60,72,74] have turned their attention to the indirect signal production model under multi-signal, and the researches on the global solvability of this model have become very important.

    Compared with the chemical substance concentration term of the indirect signal model, we found that the system became more difficult to control after adding Cobb-Douglas term. We can explain it by Sturm's comparison theorem in [44] as follows:

    y(t)+y=μ3cαw1αL1(Ω)12y+(2μ1α3)α1αwL1(Ω)forallα(0,1),

    where y=cL1(Ω) and w are the concentrations of another chemical involved in the reaction, which is given in the following model (1.1). Let

    y(t)+12y=2α1αwL1(Ω)forallα(0,1).

    If α=0, the above system degenerates into an indirect signal model, and if α>0 increase, then the corresponding solution will be raised. When we assume that the differential equation of the indirect signal model c is

    ˜y+˜y=˜wL1(Ω)

    and assume that they have the same initial data and velocity, namely, y(0)=˜y(0),˙y(0)=˙˜y(0), as wall as suppose that y(a)=y(b)=y(0), then we have ab and

    y(s1)˜y(s1)y(s0)˜y(s0)andy(s1)˜y(s1)forall0<s0<s1<a.

    This shows that the distance between the two solutions increases gradually during the evolution. Motivated by the above works, we think that the relationship between cells and chemicals also meets the operating mechanism in the Solow-Swan model. In this paper, we let ΩRN(N=2,3) be a bounded domain smooth boundary with outer norm vector ν and investigate the following chemotaxis-fluid-Solow-Swan system:

    {nt+un=Δnχ(nc)+μ1nμ2nk,xΩ,t>0,ct+uc=Δcc+μ3cαw1α,xΩ,t>0,wt+uw=Δww+n,xΩ,t>0,ut+κ(uu)=ΔuP+nΦ,u=0,xΩ,t>0,nν=cν=wν=0,u=0,xΩ,t>0,n(x,0)=n0(x),c(x,0)=c0(x),u(x,0)=u0(x),xΩ. (1.1)

    Here, the unknowns n=n(t,x),c=c(t,x) and w=w(t,x) denote the cell density and the two concentrations of chemical substance, respectively. u=u(t,x) represents the fluid velocity field, and P=P(t,x) denotes the associated pressure. The scalar valued function Φ=Φ(x) is given and it accounts the effects of external forces such as gravity or centrifugal forces. The parameters satisfy χ>0,kN,μ1R,μ20,μ3>0,α(0,1),κ{0,1}. Moser-Trudinger inequality [4,38,50] has natural advantage as a priori estimate for dealing with two-dimensional critical cases, and Winkler [68] has promoted it and provided a better version. For the three-dimensional case, we control it with help of the order of logistic source and the estimate of heat semigroup. Based on these results, we describe the work of this paper. For the convenience of this paper, we let

    m0:=Ωn0dx>0.

    We assume that potential function Φ fulfills

    ΦW2,(Ω) (1.2)

    and that the initial data n0,c0,w0,u0 satisfies

    {n0C0(ˉΩ)isnonnegativewithn00,c0W1,(Ω)isnonnegative,w0W1,(Ω)isnonnegative,andu0W2,2(Ω;R2)W1,20,σ,N=2oru0W2,224(Ω;R3)W1,20,σ,N=3, (1.3)

    where W1,20,σ:=W1,20(Ω;RN)L2σ(Ω), with L2σ:={φL2(Ω;RN)|φ=0inD(Ω)} denoting the space of all solenoidal vector fields in L2(Ω;RN).

    Under this assumption, our main results on global boundedness and asymptotic behavior of the initial-boundary value problems (1.1) and (1.3) can be formulated as follows.

    Theorem 1.1. Let ΩRN(N=2,3) be a bounded domain with smooth boundary and Φ comply with (1.2), and suppose that n0,c0,w0, and u0 satisfy (1.3), and if N=2,μ1R,μ2>0 or μ1=0,μ20 and if N=3,μ1R,μ2>0, then there exist functions (n,c,w,u,P) satisfying

    {nC0(ˉΩ×[0,))C2,1(ˉΩ×(0,)),cC0(ˉΩ×[0,))C2,1(ˉΩ×(0,)),wC0(ˉΩ×[0,))C2,1(ˉΩ×(0,)),uC0(ˉΩ×[0,))C2,1(ˉΩ×(0,)),PC1,0(ˉΩ×[0,))

    and fulfill n>0,c>0 and w>0 in ˉΩ×[0,).

    Theorem 1.2. Let ΩRN(N=2,3) be a bounded domain with smooth boundary, and let (n,c,w,u,Φ) satisfy the conditions of Theorem 1.1.

    (I) If μ1<0,μ20, then there exist C>0, suitable small δ>0, and t>1 satisfying

    nL(Ω)Ceμ1N+1t

    and

    cW1,q(Ω)Cemax{δ1,μ1}N(N+1)qtandwW1,q(Ω)Cemax{1,μ1}N(N+1)qt

    as well as

    uW1,(Ω)Ceδtforallt>t.

    If μ1=0,μ2<0, then there exist C>0, suitable small δ>0, and t>1 fulfilling

    nL(Ω)e1N+1μ2|Ω|1k1t0n(,s)k1L1(Ω)ds

    and

    cW1,q(Ω)Cemax{δ1,μ2|Ω|1k1t0n(,s)k1L1(Ω)ds}N(N+1)qtandwW1,q(Ω)c2emax{1,μ2|Ω|1k1t0n(,s)k1L1(Ω)ds}N(N+1)qt

    as well as

    uW1,(Ω)Ceδtforallt>t.

    Remark 1.1. For notational convenience, we do not explain the constants of Ci,i=1,2,,40 and CGN in the following. Here, CGN is Gagliardo-Nirenberg constant.

    First of all, we give the local existence result. This proof is based on the Banach's fixed point theorem in a bounded closed set in L((0,T);C0(ˉΩ)×(W1,q(Ω))2×D(Aγ)) for all γ(12,1) and suitably small T, where A is the realization of the stokes operator in the solenoidal subspace. Additionally, here we omit the details of the proof, which can be found in [1,20,63]. For the positive solutions, we can obtain them using the principle of comparison. Because n_0 is a sub-solution of the first equation in (1.1) and n(x,0)0, we have n(x,t)0. Furthermore, we can obtain n(x,t)>0 due to n0(x)0. Therefore, we can get w(x,t)>0 and c(x,t)>0, respectively.

    Lemma 2.1. Let ΩRN(N=2,3) be a bounded domain with smooth boundary and Φ comply with (1.2), and suppose that n0,c0,w0, and u0 satisfy (1.3), then there exist functions

    {nC0(ˉΩ×[0,Tmax))C2,1(ˉΩ×(0,Tmax)),cC0(ˉΩ×[0,Tmax))C2,1(ˉΩ×(0,Tmax)),wC0(ˉΩ×[0,Tmax))C2,1(ˉΩ×(0,Tmax)),uC0(ˉΩ×[0,Tmax))C2,1(ˉΩ×(0,Tmax)),PC1,0(ˉΩ×[0,Tmax))

    and fulfill n>0,c>0 and w>0 in ˉΩ×[0,Tmax). Moreover, if Tmax<, then for all q>N,γ(12,1) we have

    limtTmaxsup(n(,t)L(Ω)+c(,t)W1,q(Ω)+w(,t)W1,q(Ω)+Aγu(,t)L2(Ω))=.

    For the treatment of the global existence for two-dimensional Keller-Segel-Navier-Stokes-Solow-Swan system, we adopt the following Moser-Trudinger inequalities.

    Lemma 3.1. ([68]) Suppose that ΩR2 is a bounded domain with smooth boundary. Then for all ϵ>0 there exists M=M(ϵ,Ω)>0 such that if 0ϕC0(ˉΩ) is nonnegative and ψW1,2(Ω), then for each a>0,

    Ωϕ|ψ|dx1aΩϕlnϕˉϕdx+(1+ϵ)a8π{Ωϕdx}Ω|ψ|2dx+Ma{Ωϕdx}{Ω|ψ|dx}2+MaΩϕdx, (3.1)

    where ˉϕ:=1|Ω|Ωϕdx.

    Lemma 3.2. ([68]) Suppose that ΩR2 is a bounded domain with smooth boundary, and let 0ϕC0(ˉΩ) is nonnegative. Then for any choice of ϵ>0,

    Ωϕln(ϕ+1)dx1+ϵ2π{Ωϕdx}Ω|ϕ|2(ϕ+1)2dx+4M{Ωϕdx}3+{Mlnˉϕ}Ωϕdx,

    where M=M(ϵ,Ω)>0 is as in Lemma 3.1.

    Next, we give the required a prior estimates.

    Lemma 3.3. Assume that (1.3) holds. Then we have

    Ωn(x,t)dx=m0 (3.2)

    and

    Ωc(x,t)dxΩc0(x)dx+C0(m0+{Ωw0(x)dx}et)

    as well as

    Ωw(x,t)dxm0+{Ωw0(x)dx}et. (3.3)

    Proof. Since μ1=μ2=0, we integrate the first equation of (1.1) to get (3.2) and integrate the third equation of (1.1) and use the ODE argument to obtain (3.3). Then, using the similar method for the second equation of (1.1), we can complete the proof of the Lemma 3.3.

    Lemma 3.4. Suppose that (1.3) holds. Then for all T(0,Tmax) there exists C(T)>0 such that

    Ω(c2(x,t)+w2(x,t))dxC(T) (3.4)

    and

    T0Ω(|c(x,t)|2+|w(x,t)|2+|n(x,t)|2(n+1)2)dxdtC(T) (3.5)

    as well as

    T0Ωn(x,t)lnn(x,t)ˉn0dxdtC(T). (3.6)

    Proof. We first integrate by parts in the first equation from (1.1) and use u=0 and the Young's inequality to deduce that

    ddtΩln(n+1)dx=Ωntn+1dx=Ω1n+1[Δnχ(nc)un]dx=Ω|n|2(n+1)2dx+χΩnnc(n+1)2dx12Ω|n|2(n+1)2dx+χ22Ωn2(n+1)2|c|2dx12Ω|n|2(n+1)2dx+χ22Ω|c|2dx. (3.7)

    Multiplying the second equation of (1.1) by c, we have

    12ddtΩc2dx=Ωc(Δcc+μ3cαw1αuc)=Ω|c|2dxΩc2dx+μ3Ωc1+αw1αdxΩ|c|2dxΩc2dx+μ3c1+αL21+α(Ω)w1αL21α(Ω)=Ω|c|2dxΩc2dx+μ3c1+αL2(Ω)w1αL2(Ω)Ω|c|2dx12Ωc2dx+C1w2L2(Ω). (3.8)

    Multiplying (3.8) by χ2 and then substituting it into (3.7), we have

    ddt(Ωln(n+1)dx+χ22Ωc2dx)+χ22(Ωc2dx+Ω|c|2dx)+12Ω|n|2(n+1)2dxχ2C1w2L2(Ω). (3.9)

    For the right hand side of (3.9), using the Gagliardo-Nirenberg inequality and Young's inequality, we have

    ddt(Ωln(n+1)dx+χ22Ωc2dx)+χ22(Ωc2dx+Ωc|2dx)+12Ω|n|2(n+1)2dx2χ2C1CGN(wL1(Ω)wL2(Ω)+w2L1(Ω))ϵ1w2L2(Ω)+C2, (3.10)

    where ϵ1>0 is small enough and to be determined.

    Multiplying the third equation of (1.1) by w, one has

    12ddtΩw2dx=Ωw(Δww+nuw)=Ω|w|2dxΩw2dx+Ωnwdx. (3.11)

    In order to control the last term at the right end of (3.11), using Lemma 3.1, we obtain

    Ωnwdx1aΩnlnnˉn0dx+(1+ϵ)m0a8πΩ|w|2dx+Mm0a{Ωwdx}2+Mm0aforallt>0. (3.12)

    For the first term at the right end of (3.12), using Lemma 3.2, we can get

    Ωnlnnˉn0dx(1+ϵ)m02πΩ|n|2(n+1)2dx+4Mm30+m0(Mlnm0|Ω|). (3.13)

    Multiplying (3.13) by 1a, that is

    1aΩnlnnˉn0dx(1+ϵ)m02πaΩ|n|2(n+1)2dx+4Mm30a+m0a(Mlnm0|Ω|). (3.14)

    We now substituting (3.12) and (3.14) into (3.11) to deduce that

    12ddtΩw2dx+Ωw2dx+(1(1+ϵ)m0a8π)Ω|w|2dx(1+ϵ)m02πaΩ|n|2(n+1)2dx+Mm0a{Ωwdx}2+2Mm0a+m0a(4Mm20lnm0|Ω|). (3.15)

    Let λ0:=4(1+ϵ)m0πa>0. Multiplying (3.10) by λ0 and adding it to (3.15), we can see that

    ddt{λ0Ωln(n+1)dx+λ0χ22Ωc2dx+Ωw2dx}+λ0χ22(Ωc2dx+Ω|c|2dx)+(2(1+ϵ)m0a4πϵ1λ0)Ω|w|2dx+(1+ϵ)m0πaΩ|n|2(n+1)2dx+2Ωw2dx2Mam0(m0+{Ωw0dx}et)2+4Mm0a+2m0a(4Mm20lnm0|Ω|)+C2λ0.

    Therefore, we only need to select the appropriate positive numbers ϵ,ϵ1 and a such that 2(1+ϵ)m0a4πϵ1λ0>0. If ϵ is fixed, we can take a=2π(1+ϵ)m0 and ϵ1=πa4(1+ϵ)m0, which can meet the conditions we need. Then we use the inequality Ωln(n+1)dxΩndx=m0 to get (3.4) and (3.5). Finally, we use (3.5), (3.13) and the fact that nlnne1 to arrive at (3.6).

    Lemma 3.5. Assume (1.3) is satisfied. Then, for all T(0,Tmax) there exists C(T)>0 such that

    Ω|u(x,t)|2dxC(T) (3.16)

    and

    T0Ω|u(x,t)|2dxdtC(T). (3.17)

    Proof. We test the fourth equation of (1.1) by u and use the Hölder's inequality and Moser-Trudinger inequality to get

    12ddtΩ|u|2dx+Ω|u|2dx=ΩnΦuΦL(Ω){2i=1Ω|n||ui|}ΦL(Ω)a1Ωnlnnˉn+(1+ϵ2)m0a1ΦL(Ω)8πΩ|u|2dx+ΦL(Ω)(Mm0a1{Ω|u|dx}2+Mm0a1), (3.18)

    where

    a1:=1(2Mm0κ1|Ω|+(1+ϵ2)m04π)ΦL(Ω)>0,

    and κ1>0 is to be determined, it will be given by the following Poincaré's inequality.\\ On the other hand, using Poincaré's inequality and Hölder's inequality we have

    (Ω|u|dx)2|Ω|Ωu2dxκ1|Ω|Ω|u|2dx. (3.19)

    Therefore, (3.18) together with (3.19) shows that

    ddtΩ|u|2dx+Ω|u|2dx2ΦL(Ω)a1(Ωnlnnˉn+Mm0).

    So, using Gronwall's inequality and (3.6), we have the descried results.

    Lemma 3.6. If (1.3) holds, then for all T(0,Tmax) there exists C(T)>0 such that

    Ω|c(x,t)|2dxC(T).

    Moreover, we have

    T0Ω(|Δc(x,t)|2+|c(x,t)|4)dxdtC(T). (3.20)

    Proof. We multiply the Eq (1.1)2 with Δc and use the integration by parts and Hölder's inequality to obtain

    12ddtΩ|c|2dx+Ω|c|2dx+Ω|Δc|2dx=Ω(uc)Δcdxμ3Ωcαw1αΔcdx14Ω|Δc|2dx+2u2L4(Ω)c2L4(Ω)+2μ23c2αL2(Ω)w2(1α)L2(Ω)14Ω|Δc|2dx+2u2L4(Ω)c2L4(Ω)+c2L2(Ω)+C3w2L2(Ω). (3.21)

    Applying the Gagliardo-Nirenberg inequality and Young's inequality, we have

    c2L4(Ω)CGN(cL2(Ω)D2cL2(Ω)+c2L2(Ω)) (3.22)

    and

    w2L4(Ω)CGN(wL2(Ω)D2wL2(Ω)+w2L2(Ω)). (3.23)

    We plug (3.22) into (3.21) to obtain

    12ddtΩ|c|2dx+Ω|c|2dx+Ω|Δc|2dx=Ω(uc)Δcdxμ3Ωcαw1αΔcdx14Ω|Δc|2dx+2u2L4(Ω)c2L4(Ω)+2μ23c2αL2(Ω)w2(1α)L2(Ω)14Ω|Δc|2dx+2CGNu2L4(Ω)cL2(Ω)D2cL2(Ω)+2CGNu2L4(Ω)c2L2(Ω)+c2L2(Ω)+C3w2L2(Ω)14Ω|Δc|2dx+316D2c2L2(Ω)+C41u4L4(Ω)c2L2(Ω)+2CGNu2L4(Ω)c2L2(Ω)+c2L2(Ω)+C3w2L2(Ω), (3.24)

    where C41>0 is a constant.

    On the other hand, note that the identities |Δc|2=(Δcc)cΔc and Δ|c|2=2cΔc+2|D2c|2, we deduce that

    Ω|Δc|2dx=Ω(Δcc)dxΩcΔcdx=ΩΔccνdSΩcΔcdx=ΩcΔcdx=Ω|D2c|2dx12ΩΔ|c|2dx=Ω|D2c|2dx12Ω|c|2νdS. (3.25)

    Thanks to the fact |c|2ν2κ2|c|2, where κ2:=κ2(Ω)>0 is an upper bound for the curvatures of Ω in ([35], Lemma 4.2), the trace theorem and (3.25), we can see that

    Ω|D2c|2dxΩ|Δc|2dx+κ2Ω|c|2dSΩ|Δc|2dx+κ2˜C41(Ω,s)c2H3+s2(Ω)Ω|Δc|2dx+˜C42(D2c3+s2L2(Ω)c1s2L2(Ω)+c2L2(Ω))Ω|Δc|2dx+14Ω|D2c|2dx+˜C43,

    where ˜C41,˜C42,˜C43 and s(0,1) are positive constants.

    That is

    Ω|D2c|2dx43Ω|Δc|2dx+43˜C43. (3.26)

    Similarly, we have

    Ω|D2w|2dx43Ω|Δw|2dx+43˜C43. (3.27)

    Then, we apply Gagliardo-Nirenberg inequality, Lemma 3.5 and Poincaré's inequality to get

    u4L4(Ω)CGN(u2L2(Ω)u2L2(Ω)+u4L2(Ω))12u2L2(Ω)+C42u4L2(Ω)C43u2L2(Ω), (3.28)

    where C42,C43 are two positive constants.

    Therefore, (3.24) together with (3.26) and (3.28) shows that

    ddtΩ|c|2dx+Ω|Δc|2dx2c2L2(Ω)+2C3w2L2(Ω)+C4(uL2(Ω)+u2L2(Ω))c2L2(Ω), (3.29)

    where C4=max{C41C43,2CGNC43}.

    So, we use Gronwall inequality, and use Lemmas 3.4 and 3.5 and Hölder's inequality to arrive at the Lemma 3.6.

    Lemma 3.7. Suppose that (1.3) holds and that T(0,Tmax). Then there exists C(T)>0 such that

    Ω|w(x,t)|2dxC(T)

    and

    T0Ω(|Δw(x,t)|2+|w(x,t)|4)dxdtC(T).

    Proof. Multiplying the Eq (1.1)3 with Δw and using Hölder's inequality, (3.23), (3.27) and (3.28), one has

    12ddtΩ|w|2dx+Ω|w|2dx+Ω|Δw|2dx=Ω(uw)ΔwdxΩnΔwdx14Ω|Δw|2dx+2u2L4(Ω)w2L4(Ω)+2n2L2(Ω)14Ω|Δw|2dx+2u2L4(Ω)(wL2(Ω)D2wL2(Ω)+w2L2(Ω))+2n2L2(Ω)12Ω|Δw|2dx+C5(uL2(Ω)+u2L2(Ω))wL2(Ω)+2n2L2(Ω), (3.30)

    where C5>0 is a constant.

    For the term of n2L2(Ω), we apply the Gagliardo-Nirenberg inequality and the mass conservation of nL1(Ω) to deduce that

    n2L2(Ω)=n4L4(Ω)CGN(n2L2(Ω)n2L2(Ω)+n4L2(Ω))C5(n2L2(Ω)+1). (3.31)

    Multiplying the Eq (1.1)1 with (1+lnn) and using Hölder's inequality and Young's inequality, we have

    ddtΩnlnndx=(Δnχ(nc))(1+lnn)dxΩ|n|2ndx+χΩnc=Ω|n|2ndx+χΩnnncdx12Ω|n|2ndx+χ22Ωn|c|2dx2n2L2(Ω)+1C5n2L2(Ω)+χ4C58c4L4(Ω). (3.32)

    Then, we add (3.31) into (3.32) to obtain

    ddtΩnlnndx+n2L2(Ω)1+χ4C58c4L4(Ω). (3.33)

    We integrate the two ends of (3.33) with respect to t, and use Lemma 3.6 to get

    Ωnlnndx+T0n2L2(Ω)dtT+χ4C58T0c4L4(Ω)dtC(T)forallT(0,Tmax). (3.34)

    Finally, we use Gronwall's inequality to (3.30) and note that nlnne1 and (3.34) to complete the Lemma 3.7.

    Lemma 3.8. Assume (1.3), and let T(0,Tmax). Then there exists C(T)>0 such that

    Ω|n(,t)|2dxC(T).

    Proof. Testing the first equation in (1.1) against n and integrating by parts show that

    12ddtΩn2dx+Ω|n|2dx=χΩn(nc)dx=χΩnncdx.

    Applying the identity n(nc)=nnc+n2Δc, we show that

    ddtΩn2dx+2Ω|n|2dx=χΩn2Δcdxχn2L2(Ω)ΔcL2(Ω)=χn2L4(Ω)ΔcL2(Ω). (3.35)

    Using the Gagliardo-Nirenberg inequality again, we have

    n2L4(Ω)CGN(nL2(Ω)nL2(Ω)+m20). (3.36)

    Combining (3.35) with (3.36) and using the Young' s inequality, one has

    ddtΩn2dx+2Ω|n|2dxCGNχΔcL2(Ω)nL2(Ω)nL2(Ω)+CGNχm20ΔcL2(Ω)n2L2(Ω)+C6Δc2L2(Ω)n2L2(Ω)+C6(Δc2L2(Ω)+1).

    Applying Gronwall's inequality and the Lemma 3.7, we can obtain

    Ωn2dxn02L2(Ω)eC6t0Δc(,s)2L2(Ω)ds+C6eC6t0Δc(,s)2L2(Ω)dst0(Δc(,s)2L2(Ω)+1)eC6s0Δc(,τ)2L2(Ω)dτdsC(T)forallt(0,Tmax).

    Thus, we complete the proof of the Lemma 3.8.

    Lemma 3.9. Suppose that (1.3) holds and that T(0,Tmax). Then there exists C(T)>0 such that

    Ω|u(x,t)|2dxC(T)

    and

    T0Ω|Au(x,t)|2dxdtC(T).

    Proof. Testing (1.1)4 by Au and using Hölder's inequality, Gagliardo-Nirenberg inequality, Young's inequality and (3.16), one has

    12ddtΩ|u|2dx+Ω|Au|2dx=Ω(nΦ)AudxΩ(uu)Audx12AuL2(Ω)+ΦL(Ω)n2L2(Ω)+uu2L2(Ω)12AuL2(Ω)+ΦL(Ω)n2L2(Ω)+u2L(Ω)u2L2(Ω)12AuL2(Ω)+ΦL(Ω)n2L2(Ω)+CGNuL2(Ω)uW2,2(Ω)u2L2(Ω)34AuL2(Ω)+C7+C7u4L2(Ω). (3.37)

    Applying the variation of constant formula and (3.17), we have

    Ω|u|2dxu0L2(Ω)e2C7t0u(,s)L2(Ω)ds+2C7e2C7t0u(,s)L2(Ω)dst0e2C7τ0u(,s)L2(Ω)dsdτC8 (3.38)

    for all t(0,Tmax).

    Integrating the two sides of (3.37) and applying (3.38), we complete the proof.

    Lemma 3.10. Assume that (1.3) holds and let γ0(12,γ](12,1). Then for all T(0,Tmax). there exists C(T)>0 such that

    Ω|Aγ0u(,t)|2dxC(T) (3.39)

    and

    u(,t)Cθ(Ω)C(T).

    Proof. We fix γ0 and let p>11γ0, then use the Helmholtz projection operator to the fourth equation of (1.1) and the variation of constant formula to deduce that

    Aγ0u(,t)L2(Ω)=Aγ0(etAu0+t0e(ts)AP(n(,s)Φu(,s)u(,s))ds)L2(Ω)C9+C9t0(ts)γ0u(,s)u(,s)L2(Ω)dsC9+C9(t0(ts)pγ0p1ds)p1p(t0u(,s)u(,s)pL2(Ω)ds)1p:=C9+C9Jpp11J1p2.

    Due to p>11γ0, we have pγ0p1(0,1). So, J1(0,).

    For J2, we apply the Hölder's inequality, Sobolev embedding, Poincaré's inequality and Gagliardo-Nirenberg inequality to obtain

    J2=t0u(,s)u(,s)pL2(Ω)dst0u(,s)pLq(Ω)u(,s)pL2qq2(Ω)dst0u(,s)pW1,2(Ω)u(,s)pL2qq2(Ω)dsC10t0u(,s)2p2L2(Ω)Δu(,s)2L2(Ω)C10supt(0,T)u(,s)2p2L2(Ω)T0Au(,s)2L2(Ω)ds.

    Applying Lemma 3.9, we can get (3.39). Then we apply the embedding of D(Aγ0)Cθ(Ω) for all θ(0,2γ01) to complete the proof of Lemma 3.10.

    Lemma 3.11. If (1.3) holds, there for all T(0,Tmax). there exists C(T)>0 such that

    c(,t)W1,q(Ω)C(T)forallq>1.

    Proof. Without loss of generality, we assume that q>2. Using the Duhamel principle for c and using standard semigroup estimates for the Neumann heat semigroup in ([61], Lemma 1.3) and embedding in ([19], Lemma 1.6.1) and the estimate in ([20] Lemma 2.1 or [15], Lemma 2.2), and using the Lemmas 3.4, 3.6 and 3.7, we can see that

    c(,t)W1,q(Ω)et(Δ1)c0W1,q(Ω)+t0e(ts)(Δ1)(μ3cα(,s)w1α(,s)+u(,s)c(,s))W1,q(Ω)dsC11+μ3t0e(ts)(Δ1)cα(,s)w1α(,s)W1,q(Ω)+t0e(ts)(Δ1)(u(,s)c(,s))W1,q(Ω)dsC11+C12t0(1+(ts)34+1q)eλ1(ts)cα(,s)w1α(,s)L4(Ω)ds+C12t0(Δ+1)κ3e(ts)(Δ1)(u(,s)c(,s))L2q(Ω)dsC11+C12c(,s)αL4(Ω)w(,s)1αL4(Ω)t0(1+(ts)34+1q)eλ1(ts)ds+C13t0(ts)κ312δ1eλ1(ts)u(,s)c(,s)L2q(Ω)C11+C13(cαW1,2(Ω)w1αW1,2(Ω)+u(,s)L(Ω)c(,s)W1,2(Ω)t0(ts)κ312δ1eλ1(ts)ds)C14forallκ3>1212qand0<κ3+δ1<12.

    Lemma 3.12. Suppose that (1.3) holds and that T(0,Tmax). Then there exists C(T)>0 such that

    n(,t)L(Ω)C(T).

    Proof. Let M(T):=supt(0,T)n(,t)L(Ω) for all T(0,T) and let t0=(t1)+. We use the Duhamel principle for n and use the semigroup estimate, Interpolation inequality and Young's inequality to deduce that

    n(,t)L(Ω)=e(tt0)Δn(,t0)tt0e(ts)Δ(χn(,s)c(,s)+n(,s)u(,s))dsL(Ω)C15+10(1+s56)χn(,s)c(,s)+n(,s)u(,s)L3(Ω)dsC15+C1610(1+s56)n(,s)L4(Ω)dsC15+C1610(1+s56)n(,s)14L1(Ω)n34L(Ω)dsC15+C16m140M34(T)10(1+s56)dsC17+12M(T)+C17forallt(0,T). (3.40)

    We take the supremum of time for both sides of (3.40) to obtain the Lemma 3.12.

    Lemma 3.13. Assume (1.3), and let T(0,Tmax). Then there exists C(T)>0 such that

    w(,t)W1,q(Ω)C(T).

    Proof. Since the estimate of nL(Ω) in Lemma 3.12 has been obtained, we only need to use the Duhamel principle and the processing techniques similar to Lemma 3.11.

    Proof of Theorem 1.1. For the two-dimensional Navier-Stokes case, applying the Lemmas 2.1 and 3.10–3.13, if T is finite, then using the extendability criterion, we can see that n,c,w and u are unbounded of their respective norms, which contradict the boundedness of our a prior estimates. Next, we will give the asymptotic behavior of the system (1.1) with logistic source. Finally, we give a priori estimates of the corresponding solution in the three-dimensional case.

    For μ1<0, we can obtain the decay estimates of the following.

    Since μ1<0 and μ2 are nonnegative, we can easily obtain the corresponding global boundedness results of the system (1.1) by using the previous processing ways. Next, we give the corresponding large time behavior.

    Lemma 4.1. Under the assumption of Lemma 3.10, there exist θ(0,1) and C=C(χ,μ1,μ2,μ3,α)>0, independent of t, such that

    u(,t)C2+θ,1+θ2(ˉΩ×(0,))C.

    Proof. Applying the estimates obtained by Lemmas 3.10 and 3.12, and then combining with the standard Schauder estimate in [45], we arrive the proof.

    Lemma 4.2. Under the assumption of Lemma 3.12, there is an C, independent of time t such that

    n(,t)W1,(Ω)C.

    Proof. Let p:=n,q:=c. We rewrite the first equation of (1.1) to obtain

    ddtn(x,t)=(nχncnu)+μ1nμ2nk:=a(x,t,p)+b(x,t)(x,t,p)Ω×(0,+)×RN,

    where a(x,t,p)=pn(χqu) and b=μ1nμ2nk.

    Using Lemmas 3.10–3.12 and 4.1, there exists C18>0 satisfying

    a(x,t,p)p=|p|2χnpqnup12|p|2C18|q|2C18

    and

    |a(x,t,p)|=|pχnqnu||p|+C18|q|+C18

    as well as

    |b(x,t)|=|μ1nμ2nk|C18.

    Thanks to qL(0,T;L(Ω)), it evident that 1+N2=0<1. Apply the standard result on Hölder's regularity in scalar parabolic equation in ([40], Theorem 1.3) to get nCθ,θ2(Ω×(0,T)) bounded. Then the Lemma 4.2 now follows from ([23], Theorem IV. 5.3).

    Next, we adapt the similar methods to obtain the following:

    Lemma 4.3. Under the assumption of Lemmas 3.11 and 3.13, there is an C, independent of time t such that

    c(,t)W1,(Ω)+w(,t)W1,(Ω)C.

    Lemma 4.4. Assume that (1.3) holds. If μ1<0,μ20, then there exist a constant c1, independent of time t such that

    n(,t)L(Ω)c1eμ13t.

    Proof. We integrate the first equation of (1.1) to obtain

    ddtΩn(,t)dxμ1Ωn(,t)dx0. (4.1)

    Using the Gronwall's inequality for the Eq (4.1), we can see that

    nL1(Ω)m0eμ1t. (4.2)

    Applying the Gagliardo-Nirenberg inequality, the Lemma 4.2 and the estimate (4.2), we have

    nL(Ω)CGN(n13L1(Ω)n23L(Ω)+nL1(Ω))C19eμ13t. (4.3)

    Thus, we complete the proof of the Lemma 4.4.

    Lemma 4.5. Suppose that (1.3) holds. If μ1<0,μ20, then there exist a constant c2, independent of time t such that

    c(,t)W1,q(Ω)c2emax{δ21,μ1}23qtandw(,t)W1,q(Ω)c2emax{1,μ1}23qt.

    Proof. We integrate the first equation of (1.1) and (4.2) to deduce that

    ddtΩwdx+Ωwdx=Ωndxm0eμ1t.

    Thus, using the Gronwall's inequality, we can obtain

    Ωw(,t)dxw0L1(Ω)et+mμ1+1eμ1tC20emax{1,μ1}t. (4.4)

    Similarly, using Hölder's inequality and Young's inequality, there exist a suitable small 0<δ21 such that

    ddtΩcdx+Ωcdxμ3cαL1(Ω)w1αL1(Ω)δ2cL1(Ω)+C21wL1(Ω).

    Thus, we use ODE argument to get

    cL1(Ω)C22emax{δ21,μ1}t. (4.5)

    Then, for all q>1 we apply the Gagliardo-Nirenberg inequality to see that

    cW1,q(Ω)CGN(c23qL1(Ω)c3q23qL(Ω)+cL1(Ω))

    and

    wW1,q(Ω)CGN(w23qL1(Ω)w3q23qL(Ω)+wL1(Ω)).

    Using the above two estimates and (4.4), (4.5) proves that the Lemma 4.5.

    Lemma 4.6. Suppose (1.3) and μ1<0,μ20 hold, then there exist a constant c3, independent of time t such that

    u(,t)W1,(Ω)c3eδ3t.

    Proof. Testing the Eq (1.1)4 with u and using Poincaré's inequality and Young's inequality, we have

    12ddtΩ|u|2dx+Ω|u|2dx=ΩnΦuΦL(Ω)uL2(Ω)nL2(Ω)C23uL2(Ω)nL2(Ω)12u2L2(Ω)+C2232n2L2(Ω). (4.6)

    And using Poincaré's inequality once more, there is a constant ˜C23>0 such that

    ddtu2L2(Ω)+˜C23u2L2(Ω)C223n2L2(Ω).

    Using Gronwall's inequality and the Lemma 4.4, there exists a constant C24>0 fulfilling

    uL2(Ω)C24emax{˜C23,μ13}t.

    Then, applying the Gagliardo-Nirenberg inequality, this shows that

    uW1,(Ω)CGN(u13L2(Ω)u23W2,(Ω)+uL2(Ω))C25emax{˜C233,μ19}t.

    Lemma 4.7. Assume that (1.3) holds. If μ1=0,μ2>0, then there exist a constant c4, independent of time t such that

    n(,t)L(Ω)c4e13μ2|Ω|1k1t0n(,s)k1L1(Ω)ds.

    Proof. We integrate the first equation of (1.1) to obtain

    ddtΩn(,t)dx+μ2Ωnk(,t)dx=0.

    We use Hölder's inequality to deduce that

    ddtΩn(,t)dx+μ2|Ω|1k1(Ωn(,t)dx)k0.

    We apply ODE argument to get

    n(,t)L1(Ω)n0L1(Ω)eμ2|Ω|1k1t0n(,s)k1L1(Ω)ds.

    Similarly, using the inequality (4.3), we complete the proof of the Lemma 4.5.

    Lemma 4.8. Suppose that (1.3) holds. If μ1=0,μ2>0, then there exist a constant c5, independent of time t such that

    c(,t)W1,q(Ω)c5emax{δ21,μ2|Ω|1k1t0n(,s)k1L1(Ω)ds}23qt

    and

    w(,t)W1,q(Ω)c5emax{1,μ2|Ω|1k1t0n(,s)k1L1(Ω)ds}23qt

    as well as

    u(,t)W1,(Ω)c5eδ4t.

    Proof. The proof is completely similar to Lemmas 4.5 and 4.6, so we omit the details.

    Next, we will give a priori estimates when μ1>0,μ2>0.

    Lemma 4.9. Assume that (1.3) holds. Then for all T>0 there exist C(T)>0 such that

    n(,t)L1(Ω)max{n0L1(Ω),(μ1μ2)1k1|Ω|}. (4.7)

    and

    T0n(,t)kLk(Ω)dtC(T). (4.8)

    Proof. We integrate the first equation of (1.1) to get

    ddtΩn(,t)dx=μ1Ωn(,t)dxμ2Ωnk(,t)dx. (4.9)

    Applying ODE comparison, we have

    n(,t)L1(Ω)n0L1(Ω) (4.10)

    or

    μ1Ωn(,t)dx>μ2Ωnk(,t)dxμ2|Ω|1kn(,t)kL1(Ω). (4.11)

    Combining (4.10) with (4.11), this entails (4.7). Then, we integrate the two sides of Eq (4.9) to get (4.8).

    Lemma 4.10. Suppose that (1.3) holds. Then for all T>0 there exist C(T)>0 such that

    Ω(c2(x,t)+w2(x,t))dxC(T) (4.12)

    and

    T0Ω(|c(x,t)|2+|w(x,t)|2)dxdtC(T). (4.13)

    Proof. Using the inequality (3.8) and (3.11), and using Hölder's inequality and Young's inequality we have

    ddtΩc2dx+2Ω|c|2dx+Ωc2dx2C1w2L2(Ω) (4.14)

    and

    ddtΩw2dx+2Ω|w|2dx+Ωw2dxΩn2dx|Ω|+Ωnkdx. (4.15)

    We can get (4.12) and (4.13) by integrating (4.14) and (4.15) and using Lemma 4.9.

    Lemma 4.11. If (1.3) holds, then for all T there exist C(T)>0 such that

    Ω|u(,t)|2dxC(T) (4.16)

    and

    T0Ω|u(,t)|2dxdtC(T). (4.17)

    Proof. Applying the estimate of (4.6), we have

    ddtΩ|u|2dx+Ω|u|2dxC223n2L2(Ω). (4.18)

    Integrating both sides of (4.18) and applying the estimate of (4.8), we obtain (4.16) and (4.17).

    The proof of the remaining part is completely similar to the processing of Lemmas 3.6–3.13, so we omit the details.

    Next, we can use semigroup estimation to obtain the following prior estimates for the three-dimensional case.

    Lemma 4.12. Suppose that (1.3) holds and let γ0(12,γ](12,1). Then for all T(0,Tmax) there exist C(T)>0 and θ>0 such that

    Ω|Aγ0u(,t)|225dxC(T)

    and

    u(,t)Cθ(Ω)C(T).

    Proof. Let δ0=0.1,γ0=0.501,r0=3,r1=3.7,r2=4.4. We have 2δ0>32(1r01r1) and γ1:=γ0+δ0+32(1r11r2)<23. Therefore, we use standard semigroup estimates, Hölder's inequality and (4.8) to deduce that

    Aγ0u(,t)Lr2(Ω)=Aγ0(etAu0+t0e(ts)AP(n(,s)Φ)ds)Lr2(Ω)etAAγ0u0Lr2(Ω)+t0Aγ0+δ0e(ts)AAδ0(n(,s)Φ)Lr2(Ω)dsAγ0u0Lr2(Ω)+C26t0(ts)γ0δ032×(1r11r2)eλ1(ts)Aδ0n(,s)Lr1(Ω)dsC27+C27t0(ts)γ1×eλ1(ts)n(,s)L3(Ω)dsC27+C27t0n(,s)3L3(Ω)dst0(ts)32γ1×eλ1(ts)dsC28forallt(0,T).

    Then, we apply the embedding D(Aγ0r2)Cθ,0<θ<2γ03r2 to obtain the Lemma 4.12.

    Lemma 4.13. Assume that (1.3) holds. Then for all T(0,Tmax) there exist C(T)>0 such that

    Ω|c(x,t)|2dxC(T)

    and

    T0Ω|Δc(x,t)|2dxdtC(T).

    Proof. We multiply the Eq (1.1)2 with Δc and use the integration by parts and Hölder's inequality to obtain

    12ddtΩ|c|2dx+Ω|c|2dx+Ω|Δc|2dx=Ω(uc)Δcdxμ3Ωcαw1αΔcdx12Ω|Δc|2dx+u2L(Ω)c2L2(Ω)+μ23c2αL2(Ω)w2(1α)L2(Ω)12Ω|Δc|2dx+u2L(Ω)c2L2(Ω)+μ322(c2L2(Ω)+w2L2(Ω)).

    That is

    ddtΩ|c|2dx+2Ω|c|2dx+Ω|Δc|2dx2u2L(Ω)c2L2(Ω)+μ32(c2L2(Ω)+w2L2(Ω)). (4.19)

    Integrating the two sides of the inequality (4.19) and applying the Lemmas 4.10 and 4.12, we completely the proof of the Lemma 4.13.

    Lemma 4.14. If (1.3) holds. Then for all T(0,Tmax) there exist C(T)>0 such that

    Ω|n(,t)|2dxC(T). (4.20)

    Proof. We integrate the first equation of (1.1) and use the Höder's inequality and Young's inequality to get

    ddtΩn2dx+2Ω|n|2dx=χΩn2Δcdx+μ1Ωn2dxμ2Ωnk+1dxχ24Ω|Δc|2dx+Ωn4dx+μ22Ωnk+1dx+C29μ2Ωnk+1dxχ24Ω|Δc|2dx+C30forallk>3. (4.21)

    For k=3, using the same method, we can get

    ddtΩn2dx+2Ω|n|2dxμ22Ωn4dx+χ22μ2Ω|Δc|2dx+μ22Ωn4dx+μ212μ2|Ω|μ2Ωn4dxχ22μ2Ω|Δc|2dx+C31. (4.22)

    By integrating the expressions of (4.21) or (4.22) and using the Lemma 4.13, the proof is complete.

    Lemma 4.15. Assume that (1.3) holds. Then for all T>0 there exist C(T)>0 such that

    Ω|w(,s)|2dxC(T)

    and

    t0Ω|Δw(,s)|2dxdtC(T).

    Proof. Multiplying the Eq (1.1)3 with Δw and using Hölder's inequality, one has

    12ddtΩ|w|2dx+Ω|w|2dx+Ω|Δw|2dx=Ω(uw)ΔwdxΩnΔwdx12Ω|Δw|2dx+u2L(Ω)w2L2(Ω)+n2L2(Ω). (4.23)

    Integrating the two sides of (4.23) and applying the estimates (4.12) and (4.20), we complete the proof of the Lemma 4.15.

    Lemma 4.16. If (1.3) holds. Then for all T(0,Tmax) there exist C(T)>0 such that

    c(,t)W1,q(Ω)C(T).

    Proof. Applying the variation of constant formula of n, we have

    c(,t)L(Ω)et(Δ1)c0L(Ω)+t0e(ts)(Δ1)(μ3cα(,s)w1α(,s)+(u(,s)c(,s)))L(Ω)dsC32+C32t0(1+(ts)34)cα(,s)w1α(,s)L2(Ω)ds+C32t0(1+(ts)78)c(,s)u(,s)L4(Ω)dsC32+C32(cαL2(Ω)w1αL2(Ω)+cW1,2(Ω))C33.

    Then, we use the similar method of Lemma 3.11 to deduce that

    c(,t)W1,q(Ω)et(Δ1)c0W1,q(Ω)+t0e(ts)(Δ1)(μ3cα(,s)w1α(,s)+u(,s)c(,s))W1,q(Ω)dsC34+C35t0(1+(ts)34+32q)eλ1(ts)cα(,s)w1α(,s)L6(Ω)ds+C35t0(Δ+1)κ4e(ts)(Δ1)(u(,s)c(,s))L(Ω)dsC34+C35c(,s)αL6(Ω)w(,s)1αL6(Ω)t0(1+(ts)34+32q)eλ1(ts)ds+C36t0(ts)κ412δ5eλ1(ts)u(,s)c(,s)L(Ω)dsC34+C36cαW1,2(Ω)w1αW1,2(Ω)+C36t0(ts)κ412δ5eλ1(ts)u(,s)L(Ω)c(,s)L(Ω)dsC37forallq>1,κ4>1232q,0<κ4+δ5<12.

    Next, we give the estimates of n, and then apply them to obtain the estimate of w.

    Lemma 4.17. Suppose that (1.3) holds. Then for all T(0,Tmax) there is C(T)>0 such that

    n(,t)L(Ω)C(T).

    Proof. Let M(T):=supt(0,T)n(,t)L(Ω) for all T(0,T) and let t0=(t1)+. Applying the variation of constant formula of n, we can see that

    n(,t)L(Ω)e(tt0)Δn(,t0)tt0e(ts)Δ((χn(,s)c(,s)+n(,s)u(,s))ds+μ1n)dsL(Ω)C38+10(1+s78)χn(,s)c(,s)+n(,s)u(,s)L4(Ω)ds+μ110(1+s38)nL4(Ω)dsC38+10(1+s78)(χn(,s)L20(Ω)c(,s)L5(Ω)+u(,s)L(Ω)n(,s)L4(Ω))ds+μ1t0(1+s38)n(,s)12L2(Ω)n(,s)12L(Ω)dsC38+C39(M910(T)+M12(T)).

    Thus, using the Young's inequality, we obtain the result.

    Lemma 4.18. Assume that (1.3) holds. Then for all T(0,Tmax) there exist C(T)>0 such that

    w(,t)W1,q(Ω)C(T).

    Proof. Using the variation of constant formula of w and taking δ6>0 suitable small, we have

    w(,t)W1,q(Ω)=et(Δ1)w0W1,q(Ω)+t0e(ts)(Δ1)(n+(u(,s)w(,s)))W1,q(Ω)dsC40+C40t0(1+(ts)12+32q)eλ1(ts)n(,s)L(Ω)ds+C40t0(Δ+1)κ5(u(,s)w(,s))L(Ω)+C40t0(1+(ts)1+32qδ6)eλ1(ts)u(,s)w(,s)L(Ω)ds

    for all q>1,κ5>1232q,δ6<32q.

    Similar to Lemma 4.16, we get the proof of Lemma 4.18.

    Proof of Theorem 1.1 for the three-dimensional case. Finally, we arrive at the proof of Theorem 1.1, using the estimates we obtained in Lemmas 4.16–4.18 and then using the extendability criterion.

    Proof of Theorem 1.2. Based on the estimates collected in Lemmas 4.4–4.8, and the three-dimensional case is similar. We finish the proof.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The first author was supposed by Scientific Research Funds of Chengdu University under grant No. 2081921030. The second author was supposed by the NSFC Youth Fund under grant No. 12001384.

    The authors declare that they have no known competing financial interests or personal relationships that could have appeared to influence the work reported in this paper.



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