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Research article

Global dynamics of IAV/SARS-CoV-2 coinfection model with eclipse phase and antibody immunity


  • Received: 08 October 2022 Revised: 12 November 2022 Accepted: 25 November 2022 Published: 13 December 2022
  • Coronavirus disease 2019 (COVID-19) and influenza are two respiratory infectious diseases of high importance widely studied around the world. COVID-19 is caused by the severe acute respiratory syndrome coronavirus 2 (SARS-CoV-2), while influenza is caused by one of the influenza viruses, A, B, C, and D. Influenza A virus (IAV) can infect a wide range of species. Studies have reported several cases of respiratory virus coinfection in hospitalized patients. IAV mimics the SARS-CoV-2 with respect to the seasonal occurrence, transmission routes, clinical manifestations and related immune responses. The present paper aimed to develop and investigate a mathematical model to study the within-host dynamics of IAV/SARS-CoV-2 coinfection with the eclipse (or latent) phase. The eclipse phase is the period of time that elapses between the viral entry into the target cell and the release of virions produced by that newly infected cell. The role of the immune system in controlling and clearing the coinfection is modeled. The model simulates the interaction between nine compartments, uninfected epithelial cells, latent/active SARS-CoV-2-infected cells, latent/active IAV-infected cells, free SARS-CoV-2 particles, free IAV particles, SARS-CoV-2-specific antibodies and IAV-specific antibodies. The regrowth and death of the uninfected epithelial cells are considered. We study the basic qualitative properties of the model, calculate all equilibria, and prove the global stability of all equilibria. The global stability of equilibria is established using the Lyapunov method. The theoretical findings are demonstrated via numerical simulations. The importance of considering the antibody immunity in the coinfection dynamics model is discussed. It is found that without modeling the antibody immunity, the case of IAV and SARS-CoV-2 coexistence will not occur. Further, we discuss the effect of IAV infection on the dynamics of SARS-CoV-2 single infection and vice versa.

    Citation: A. M. Elaiw, Raghad S. Alsulami, A. D. Hobiny. Global dynamics of IAV/SARS-CoV-2 coinfection model with eclipse phase and antibody immunity[J]. Mathematical Biosciences and Engineering, 2023, 20(2): 3873-3917. doi: 10.3934/mbe.2023182

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  • Coronavirus disease 2019 (COVID-19) and influenza are two respiratory infectious diseases of high importance widely studied around the world. COVID-19 is caused by the severe acute respiratory syndrome coronavirus 2 (SARS-CoV-2), while influenza is caused by one of the influenza viruses, A, B, C, and D. Influenza A virus (IAV) can infect a wide range of species. Studies have reported several cases of respiratory virus coinfection in hospitalized patients. IAV mimics the SARS-CoV-2 with respect to the seasonal occurrence, transmission routes, clinical manifestations and related immune responses. The present paper aimed to develop and investigate a mathematical model to study the within-host dynamics of IAV/SARS-CoV-2 coinfection with the eclipse (or latent) phase. The eclipse phase is the period of time that elapses between the viral entry into the target cell and the release of virions produced by that newly infected cell. The role of the immune system in controlling and clearing the coinfection is modeled. The model simulates the interaction between nine compartments, uninfected epithelial cells, latent/active SARS-CoV-2-infected cells, latent/active IAV-infected cells, free SARS-CoV-2 particles, free IAV particles, SARS-CoV-2-specific antibodies and IAV-specific antibodies. The regrowth and death of the uninfected epithelial cells are considered. We study the basic qualitative properties of the model, calculate all equilibria, and prove the global stability of all equilibria. The global stability of equilibria is established using the Lyapunov method. The theoretical findings are demonstrated via numerical simulations. The importance of considering the antibody immunity in the coinfection dynamics model is discussed. It is found that without modeling the antibody immunity, the case of IAV and SARS-CoV-2 coexistence will not occur. Further, we discuss the effect of IAV infection on the dynamics of SARS-CoV-2 single infection and vice versa.



    Severe acute respiratory syndrome coronavirus 2 (SARS-CoV-2) and influenza A virus (IAV) are two respiratory RNA viruses with high pandemic potential. SARS-CoV-2 causes the coronavirus disease 2019 (COVID-19). According to the update provided by the World Health Organization (WHO) on 2 October 2022 [1], over 593 million confirmed cases and over 6.4 million deaths were reported globally. Influenza viruses infect about 20% of the world's population in annual epidemics, resulting in 3-5 million severe illnesses and 290, 000–650, 000 deaths each year [2].

    Both SARS-CoV-2 and IAV infect the uninfected epithelial cells of the host respiratory tract [3,4], and have analogous transmission ways. Moreover, they have common clinical manifestations including dyspnea, cough, fever, headache, rhinitis, myalgia and sore throat [5]. Viral shedding usually takes place 5 to 10 days in influenza, whereas it does 2 to 5 weeks in COVID-19 [5]. Acute respiratory distress is less common in influenza than in COVID-19 [5]. Deaths in influenza cases are less than 1%, while in cases of COVID-19 it ranges from 3 to 4% [5]. The precautionary measures implemented by governments to limit the transmission of SARS-CoV-2 can play a role in reducing the transmission of the IAV [6].

    Eleven vaccines for COVID-19 were approved by WHO for emergency use. These include Novavax/Nuvaxovid, Bharat Biotech/Covaxin, CanSino/Convidecia, Pfizer/BioNTech/Comirnaty, Moderna/Spikevax, Serum Institute of India COVOVAX (Novavax formulation), Janssen (Johnson & Johnson)/Jcovden, Oxford/AstraZeneca/Vaxzevria, Serum Institute of India Covishield (Oxford/AstraZeneca formulation), Sinopharm (Beijing)/Covilo, and Sinovac/CoronaVac [7]. Currently, there are three types of influenza vaccines used worldwide: live attenuated influenza vaccine, inactivated influenza vaccine and recombinant hemagglutinin vaccine [8].

    It was reported in [9] that, 94.2% of individuals with COVID-19 were also coinfected with several other microorganisms, such as fungi, bacteria and viruses. Important viral copathogens include the respiratory syncytial virus (RSV), human enterovirus (HEV), human rhinovirus (HRV), influenza A virus (IAV), influenza B virus (IBV), human metapneumovirus (HMPV), parainfluenza virus (PIV), human immunodeficiency virus (HIV), cytomegalovirus (CMV), dengue virus (DENV), Epstein Barr virus (EBV), hepatitis B virus (HBV) and other coronaviruses (COVs), among which the HRV, HEV and IAV are the most common copathogens [10]. Several coinfection cases of COVID-19 and influenza were reported in [5,9,11,12,13] (see also the review papers [14,15,16,17,18]). Lansbury et al. [14] presented a systematic review and meta-analysis that included 30 studies for evaluating coinfections among patients infected with COVID-19. It was reported that 7% of patients had a bacterial coinfection and 3% of patients had another respiratory virus, with RSV and IAV being among the most common coinfecting viruses. Dao et al. [15] conducted a systematic review and meta-analysis that included 54 publications and found that, 7% of COVID-19 patients are co-infected with influenza viruses. Most influenza co-infections were due to the IAV [15]. A respective study in Wuhan, China showed that the coinfection rate of IAV and SARS-CoV-2 was 49.8% during the outbreak period of COVID-19 [19]. Based on two separate studies presented in [11] and [12], COVID-19-influenza coinfection did not result in worse clinical outcomes [11]. In addition, this condition reduced the mortality rate among COVID-19-influenza coinfected patients. Coinfection with influenza virus in COVID-19 patients might render them less vulnerable to morbidities associated with COVID-19, and therefore, a better prognosis overall [12]. In [18], it is found that, although patients with IAV and SARS-CoV-2 coinfection did not experience longer hospital stays compared with those SARS COV-2 single-infection, they usually presented with a more severe clinical conditions. In an animal study [20], it was found that the disease severity is increased in hamsters with SARS-CoV-2 and IAV coinfection compared with those with SARS-CoV-2 mono-infection.

    Viral interference phenomenon can appear in case of infections with multiple competitive respiratory viruses [21,22,23]. One virus may be able to suppress the growth of another virus [21,24]. In [22], it was reported that an H3N2 strain of IAV was inhibited by SARS-CoV-2 coinfection in the hamster model. Oishi et al. [23] used the golden Syrian hamster model, and found that, IAV interferes with SARS-CoV-2 replication in the lung, even more than one week after IAV clearance. Disease progression and outcome in SARS-CoV-2 infection are highly dependent on the host immune response, particularly in the elderly in whom immunosenescence may predispose to increased risk of coinfection [21].

    Over the years, mathematical models have demonstrated their ability to provide useful insight to gain a further understanding of the dynamics and mechanisms of the viruses within a host level. These models may assist in the development of viral therapies and vaccines as well as the selection of appropriate therapeutic and vaccine strategies. Moreover, these models are helpful in determining the sufficient number of factors to analyze the experimental results and explain the biological phenomena [3]. Stability analysis of the model's equilibria can help researchers to (i) expect the qualitative features of the model for a given set of values of the model's parameters, (ii) establish the conditions that ensure the persistence or deletion of this infection, and (iii) determine under what conditions the immune system is stimulated against the infection.

    Mathematical models of within-host IAV single-infection were developed in several works (see the review papers [25,26,27,28,29]). Baccam et al. [30] presented the following IAV-single-infection with limited target cells and eclipse (or latent) phase:

    {˙X=IAV infectious transmissionβPXP,˙E=IAV infectious transmissionβPXPlatent transitionδEE,˙I=latent transitionδEEnatural deathγII,˙P=IAV productionκPInatural deathπPP, (1.1)

    where X=X(t), E=E(t), I=I(t) and P=P(t) are the concentrations of uninfected epithelial cells, latent IAV-infected epithelial cells, active IAV-infected epithelial cells and free IAV particles, at time t, respectively. The model was fitted using real data from six patients infected with influenza [30].

    Several works were devoted to developing IAV single-infection dynamics models by considering the following:

    ● Innate immune response: It represents the first line of defense that recognizes the antigens and activate the adaptive immune response. In [30], the effect of interferon (IFN) response was included in the IAV infection model. The dynamics of the IFN are given as:

    ˙F=ϖFI(tτ)μFF,

    where, F is the concentration of IFN, ϖF is the IFN production rate constant, μF is the IFN decay rate constant, and τ is the time lag that occurs between the initiation of an IAV infection and the appearance of IFN. IFN can reduce viral replication in an infected cell, the rate of viral production in the presence of IFN was modeled by replacing δE by δE1+ϵEF. The rate that IAV-infected cells in the eclipse phase begin virus production (κP) may also be altered and was accounted for by replacing this parameter by κP1+ϵPF. The efficiency of these interferon effects is reflected by the parameters ϵE and ϵP [30,31]. Saenz et al. [32] presented an influenza model with interferon response. It is reported that the model with interferon response provided better fitting with real data than that without interferon response.

    ● Adaptive immune response: Cytotoxic T Lymphocytes (CTLs) and antibodies are the two major components of the adaptive immune response. CTLs destroy the viral-infected cells, while the antibodies neutralize the viruses. An influenza dynamics model with different forms of the CTL response was developed in [33]. It was shown that slight changes in the virus dynamics was observed when different choices of CTL response were implemented. Both CTL and antibody immunities were included into the IAV model in [34].

    ● Both innate and adaptive immune responses [3,35,36,37,38]. The model presented in [37] predicted that, the level and time of the viral peak are affected by the innate interferon response, while the clearance phase and duration of infection are determined by the CTL response. Handel et al. [38] showed that, both the innate and adaptive immune responses are required to give an appropriate explanation of the real data.

    ● Drug therapy: There are two approved anti-IAV drugs, adamantane antiviral drugs which block infection by reducing the rate of infection, and neuraminidase inhibitors which block the production of newly formed virions [31]. Beauchemin et al. [39] used model (1.1) to study the effect of the antiviral drug amantadine on IAV infection. Handel et al. [40] presented a mathematical model for within-host influenza infection under the effect of neuraminidase inhibitors drugs. Lee et al. [34] included the effect of a combination of neuraminidase inhibitors and anti-IAV therapies in the IAV model. The IAV model predicts that the drug therapies are more beneficial when they are administered early.

    ● Regrowth and death of the uninfected epithelial cells. In [34], the first equation of model (1.1) was modified by considering the target cell production and death as:

    ˙X=epithelial cells productionαX(0)natural deathαXIAV infectious transmissionβPXP, (1.2)

    where X(0) is the initial concentration of the uninfected epithelial cells.

    Mathematical analysis of within-host IAV infection model was studied in a few papers [33,41,42].

    Model (1.1) was utilized to characterize the dynamics of SARS-CoV-2 within a host in [43,44,45]. Li et al. [46], used Eq (1.2) for the uninfected epithelial cell dynamics in case of SARS-CoV-2 infection. The model with target-cell limited and model with regrowth and death of the uninfected epithelial cells presented, respectively, in [43,46] were extended and modified by including (i) effect of immune response [44,47,48,49,50,51], (ii) effect of different drug therapies [52,53], and (iii) effect of time delay [54].

    Stability analysis of within-host SARS-CoV-2 single-infection models was investigated in [49,50,51,55].

    Mathematical model of IAV/SARS-CoV-2 coinfection. Recently, mathematical models were developed to characterize within-host co-dynamics of COVID-19 with other diseases, such as: SARS-CoV-2-cancer [56], SARS-CoV-2/HIV coinfection [57], SARS-CoV-2/malaria coinfection [58]. Based on the target cell-limited model (1.1), and the Pinky and Dobrovolny [24] developed a model for the within-host dynamics of two respiratory viruses coinfection (SARS-CoV-2 and IAV).

    {˙X=SARS-CoV-2 infectious transmissionβVXVIAV infectious transmissionβPXP,˙L=SARS-CoV-2 infectious transmissionβVXVlatent transitionδLL,˙E=IAV infectious transmissionβPXPlatent transitionδEE,˙Y=latent transitionδLLnatural deathγYY,˙I=latent transitionδEEnatural deathγII,˙V=SARS-CoV-2 productionκVYnatural deathπVV,˙P=IAV productionκPInatural deathπPP, (1.3)

    where L=L(t), Y=Y(t) and V=V(t) are the concentrations of latent SARS-CoV-2-infected epithelial cells, active SARS-CoV-2-infected epithelial cells and free SARS-CoV-2 particles, at time t, respectively. Model (1.3) describes the competition between two respiratory viruses, SARS-CoV-2 and IAV. However, the effect of the immune response was not modeled. Further, the regrowth and death of the uninfected epithelial cells were not considered. Furthermore, mathematical analysis of the model was not studied.

    The objective of the present work is to formulate a mathematical model for within-host IAV/SARS-CoV-2 coinfection with eclipse phase. The model is a generalization of the model (1.3) by taking into account (i) the regrowth and death of the uninfected epithelial cells, (ii) the death of the latent SARS-CoV-2-infected cells and latent IAV-infected cells, (iii) the effect of SARS-CoV-2-specific antibody and IAV-specific antibody. We study the basic qualitative properties of the model, calculate all equilibria, investigate the global stability of equilibria and demonstrate the theoretical results via numerical simulations. We discuss the importance of including the antibody immunity in the IAV/SARS-CoV-2 co-infection model.

    Our proposed model can be helpful to characterize the dynamics of coinfection with SARS-CoV-2 strains (Alpha, Beta, Gamma, Delta, Lambda and Omicron), or coinfection of SARS-CoV-2 (or IAV) and other respiratory viruses. Moreover, the model may help to predict new treatment regimens for viral coinfections.

    In this section, we present an IAV/SARS-CoV-2 coinfection dynamics model with a latent phase. The dynamics of IAV/SARS-CoV-2 coinfection is presented in the diagram Figure 1. We denote Z=Z(t) and M=M(t) for the concentrations of SARS-CoV-2-specific antibodies and IAV-specific antibodies, at time t, respectively. The ODEs that describe the coinfection dynamics are:

    {˙X=epithelial cells productionλnatural deathαXSARS-CoV-2 infectious transmissionβVXVIAV infectious transmissionβPXP,˙L=SARS-CoV-2 infectious transmissionβVXVnatural deathηLLlatent transitionδLL,˙E=IAV infectious transmissionβPXVnatural deathηEElatent transitionδEE,˙Y=latent transitionδLLnatural deathγYY,˙I=latent transitionδEEnatural deathγII,˙V=SARS-CoV-2 productionκVYnatural deathπVVSARS-CoV-2 neutralizationϰVVZ,˙P=IAV productionκPInatural deathπPPIAV neutralizationϰPPM,˙Z=SARS-CoV-2-specific antibody proliferationσZVZnatural deathμZZ,˙M=IAV-specific antibody proliferationσMPMnatural deathμMM. (2.1)
    Figure 1.  The schematic diagram of the IAV/SARS-CoV-2 coinfection dynamics within-host.

    where (X,L,E,Y,I,V,P,Z,M)=(X(t),L(t),E(t),Y(t),I(t),V(t),P(t),Z(t),M(t)).

    In model (2.1) the regrowth death of the uninfected epithelial cells is considered. Further, the death of the latent SARS-CoV-2-infected and latent IAV-infected cells are included, Furthermore, the effect of SARS-CoV-2-specific and IAV-specific antibodies are modeled. First, we start our mathematical analysis of the system by examining the nonnegativity and boundedness of the system's solutions.

    Here, we study the basic qualitative properties of system (2.1).

    Lemma 1. The solutions of system (2.1) are nonnegative and bounded.

    Proof. We have that

    ˙XX=0=λ>0,˙LL=0=βVXV0 for all X,V0,˙EE=0=βPXP0 for all X,P0,˙YY=0=δLL for all L0,˙II=0=δEE for all E0,˙VV=0=κVY0 for all Y0,˙PP=0=κPI0 for all I0,˙ZZ=0=0,˙MM=0=0.

    This guarantees that, (X(t),L(t),E(t),Y(t),I(t),V(t),P(t),Z(t),M(t))R90 for all t0 when (X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))R90. Let us define

    Ψ=X+L+E+Y+I+γY2κVV+γI2κPP+γYϰV2κVσZZ+γIϰP2κPσMM.

    Then

    ˙Ψ=λαXηLLηEEγY2YγI2IγYπV2κVVγIπP2κPPγYϰVμZ2κVσZZγIϰPμM2κPσMMλϕ[X+L+E+Y+I+γY2κVV+γI2κPP+γYϰV2κVσZZ+γIϰP2κPσMM]=λϕΨ,

    where ϕ=min{α,ηL,ηE,γY2,γI2,πV,πP,μZ,μM}. Hence, 0Ψ(t)Δ1 if Ψ(0)Δ1 for t0, where Δ1=λϕ. Since X,L,E,Y,I,V,P,Z and M are all nonnegative, then 0X(t),L(t),E(t),Y(t),I(t)Δ1, 0V(t)Δ2, 0P(t)Δ3, 0Z(t)Δ4, 0M(t)Δ5 if X(0)+L(0)+E(0)+Y(0)+I(0)+γY2κVV(0)+γI2κPP(0)+γYϰV2κVσZZ(0)+γIϰP2κPσMM(0)Δ1, where Δ2=2κVγYΔ1, Δ3=2κPγIΔ1, Δ4=2σZκVϰVγYΔ1 and Δ5=2σMκPϰPγIΔ1. This proves the boundedness of the solutions.

    Here, we calculate the system's equilibria and deduce the conditions of their existence. Any equilibrium point Ξ=(X,L,E,Y,I,V,P,Z,M) satisfies:

    0=λαXβVXVβPXP, (4.1)
    0=βVXV(ηL+δL)L, (4.2)
    0=βPXP(ηE+δE)E, (4.3)
    0=δLLγYY, (4.4)
    0=δEEγII, (4.5)
    0=κVYπVVϰVVZ, (4.6)
    0=κPIπPPϰPPM, (4.7)
    0=σZVZμZZ, (4.8)
    0=σMPMμMM. (4.9)

    Solving Eqs (4.1)–(4.9), we get eight equilibria.

    (i) Infection-free equilibrium, Ξ0=(X0,0,0,0,0,0,0,0,0), where X0=λ/α.

    (ii) SARS-CoV-2 single-infection equilibrium without antibody immunity Ξ1=(X1,L1,0,Y1,0,V1,0,0,0), where

    X1=γYπV(ηL+δL)κVβVδL,                       L1=αγYπVκVβVδL[X0κVβVδLγYπV(ηL+δL)1],Y1=απVκVβV[X0κVβVδLγYπV(ηL+δL)1],  V1=αβV[X0κVβVδLγYπV(ηL+δL)1].

    Therefore, L1>0,Y1>0 and V1>0 when X0κVβVδLγYπV(ηL+δL)>1. We define the basic SARS-CoV-2 single-infection reproductive ratio as:

    1=X0κVβVδLγYπV(ηL+δL).

    The parameter 1 determines whether or not a SARS-CoV-2 single-infection can be established. Thus, we can write

    X1=X01,                    L1=αγYπVκVβVδL(11),Y1=απVκVβV(11),  V1=αβV(11).

    It follows that, Ξ1 exists if 1>1.

    (iii) IAV single-infection equilibrium without antibody immunity, Ξ2=(X2,0,E2,0,I2,0,P2,0,0), where

    X2=γIπP(ηE+δE)κPβPδE,                        E2=αγIπPκPβPδE[X0κPβPδEγIπP(ηE+δE)1],I2=απPκPβP[X0κPβPδEγIπP(ηE+δE)1],  P2=αβP[X0κPβPδEγIπP(ηE+δE)1].

    Therefore, E2>0,I2>0 and P2>0 when X0κPβPδEγIπP(ηE+δE)>1. We define the basic IAV-infection reproductive ratio as:

    2=X0κPβPδEγIπP(ηE+δE).

    The parameter 2, determines whether or not the IAV single-infection can be established. In terms of 2, we can write:

    X2=X02,                   E2=αγIπPκPβPδE(21),I2=απPκPβP(21),  P2=αβP(21).

    Therefore, Ξ2 exists if 2>1

    (iv) SARS-CoV-2 single-infection equilibrium with stimulated SARS-CoV-2-specific antibody immunity, Ξ3=(X3,L3,0,Y3,0,V3,0,Z3,0), where

    X3=λσZβVμZ+ασZ, L3=λβVμZ(ηL+δL)(βVμZ+ασZ), Y3=λβVμZδLγY(ηL+δL)(βVμZ+ασZ),V3=μZσZ,  Z3=πVϰV[λβVσZκVδLγYπV(ηL+δL)(βVμZ+ασZ)1].

    We note that Ξ3 exists when λβVσZκVδLγYπV(ηL+δL)(βVμZ+ασZ)>1. Let us define the SARS-CoV-2-specific antibody activation ratio in case of SARS-CoV-2 single-infection as:

    3=λβVσZκVδLγYπV(ηL+δL)(βVμZ+ασZ).

    Thus, Z3=πVϰV(31). The parameter 3 determines whether or not the SARS-CoV-2-specific antibody immunity is activated in the absence of IAV infection.

    (v) IAV single-infection equilibrium with stimulated of IAV-specific antibody immunity, Ξ4=(X4,0,E4,0,I4,0,P4,0,M4), where

    X4=λσMβPμM+ασM,  E4=λβPμM(ηE+δE)(βPμM+ασM), I4=λβPμMδEγI(ηE+δE)(βPμM+ασM),  P4=μMσM,  M4=πPϰP[λβPσMκPδEγIπP(ηE+δE)(βPμM+ασM)1].

    We note that Ξ4 exists when λβPσMκPδEγIπP(ηE+δE)(βPμM+ασM)>1. We define the IAV-specific antibody immunity activation ratio for IAV single-infection as:

    4=λβPσMκPδEγIπP(ηE+δE)(βPμM+ασM).

    Thus, M4=πPϰP(41). The parameter 4 determines whether or not the IAV-specific antibody immunity is activated in the absence of SARS-CoV-2 infection.

    (vi) IAV/SARS-CoV-2 coinfection equilibrium with only stimulated SARS-CoV-2-specific antibody immunity, Ξ5=(X5,L5,E5,Y5,I5,V5,P5,Z5,0), where

    X5=γIπP(ηE+δE)κPβPδE,   L5=βVμZγIπP(ηE+δE)κPβPδEσZ(ηL+δL),E5=γIπP(βVμZ+ασZ)κPβPδEσZ[λβPκPδEσZγIπP(ηE+δE)(βVμZ+ασZ)1],  Y5=βVμZγIπPδL(ηE+δE)κPβPδEσZγY(ηL+δL),I5=πP(βVμZ+ασZ)κPβPσZ[λβPκPδEσZγIπP(ηE+δE)(βVμZ+ασZ)1],  V5=μZσZ,P5=βVμZ+ασZβPσZ[λβPκPδEσZγIπP(ηE+δE)(βVμZ+ασZ)1],Z5=πVϰV[κVβVγIδLπP(ηE+δE)κPβPγYδEπV(ηL+δL)1]=πVϰV(1/21).

    We note that Ξ5 exists when,

    12>1  and  λβPκPδEσZγIπP(ηE+δE)(βVμZ+ασZ)>1.

    Now, we define the SARS-CoV-2 infection reproductive ratio in the presence of IAV infection as:

    5=λβPκPδEσZγIπP(ηE+δE)(βVμZ+ασZ).

    The parameter 5 determines whether or not SARS-CoV-2-infected patients could be coinfected with IAV. Hence,

    E5=γIπP(βVμZ+ασZ)κPβPδEσZ(51),  I5=πP(βVμZ+ασZ)βPσZκP(51),P5=βVμZ+ασZβPσZ(51).

    and then Ξ5 exists if 12>1 and 5>1.

    (vii) IAV/SARS-CoV-2 coinfection equilibrium with only stimulated IAV-specific antibody immunity, Ξ6=(X6,L6,E6,Y6,I6,V6,P6,0,M6), where

    X6=γYπV(ηL+δL)κVβVδL,          L6=γYπV(βPμM+ασM)κVβVδLσM[λβVκVδLσMγYπV(ηL+δL)(βPμM+ασM)1],E6=γYβPμMπV(ηL+δL)κVβVδLσM(ηE+δE),       Y6=πV(βPμM+ασM)κVβVσM[λβVκVδLσMγYπV(ηL+δL)(βPμM+ασM)1],I6=βPδEμMπVγY(ηL+δL)κVβVδLσMγI(ηE+δE),   V6=βPμM+ασMβVσM[λβVκVδLσMγYπV(ηL+δL)(βPμM+ασM)1],P6=μMσM,   M6=πPϰP[κPβPγYδEπV(ηL+δL)κVβVγIδLπP(ηE+δE)1]=πPϰP(2/11).

    We note that Ξ6 exists when

    21>1  and  λβVκVδLσMγYπV(ηL+δL)(βPμM+ασM)>1.

    We define the SARS-CoV-2 infection reproductive ratio in the presence of IAV infection as:

    6=λβVκVδLσMγYπV(ηL+δL)(βPμM+ασM).

    Thus,

    L6=γYπV(βPμM+ασM)κVβVδLσM(61),  Y6=πV(βPμM+ασM)βVσMκV(61),V6=βPμM+ασMβVσM(61).

    The parameter 6 determines whether or not SARS-CoV-2-infected patients could be coinfected with IAV.

    (viii) IAV/SARS-CoV-2 coinfection equilibrium with stimulated both SARS-CoV-2-specific and IAV-specific antibody immunities, Ξ7=(X7,L7,E7,Y7,I7,V7,P7,Z7,M7), where

    X7=λσZσMβPμMσZ+βVμZσM+ασZσM,  L7=βVλμZσM(ηL+δL)(βPμMσZ+βVμZσM+ασZσM),E7=βPλμMσZ(ηE+δE)(βPμMσZ+βVμZσM+ασZσM),Y7=βVδLλμZσMγY(ηL+δL)(βPμMσZ+βVμZσM+ασZσM),I7=βPδEλμMσZγI(ηE+δE)(βPμMσZ+βVμZσM+ασZσM),  V7=μZσZ,  P7=μMσM,Z7=πVϰV[λβVκVδLσMσZγYπV(ηL+δL)(βPμMσZ+βVμZσM+ασZσM)1],M7=πPϰP[λβPκPδEσMσZγIπP(ηE+δE)(βPμMσZ+βVμZσM+ασZσM)1].

    It is obvious that Ξ7 exists when

    λβVκVδLσMσZγYπV(ηL+δL)(βPμMσZ+βVμZσM+ασZσM)>1λβPκPδEσMσZγIπP(ηE+δE)(βPμMσZ+βVμZσM+ασZσM)>1.

    Now, we define

    7=λβVκVδLσMσZγYπV(ηL+δL)(βPμMσZ+βVμZσM+ασZσM),8=λβPκPδEσMσZγIπP(ηE+δE)(βPμMσZ+βVμZσM+ασZσM).

    Here, 7 is the SARS-CoV-2-specific antibody activation ratio in case of IAV/SARS-CoV-2 coinfection, 8 is the IAV-specific antibody activation ratio in case of IAV/SARS-CoV-2 coinfection. Hence, Z7=πVϰV(71) and M7=πPϰP(81). If 7>1 and 8>1, then Ξ7 exists.

    In summary, we have eight threshold parameters which determine the existence of the model's equilibria

    (4.10)

    This section is devoted to studying the global asymptotic stability of all equilibria. We configure Lyapunov functions following the way outlined in [59]. The following arithmetic-mean-geometric-mean inequality will be utilized:

    u1+u2+...+unnn(u1)(u2)...(un), ui0,  i=1,2,...,n. (5.1)

    Let a function Λj(X,L,E,Y,I,V,P,Z,M) and ˜Ωj be the largest invariant subset of

    Ωj={(X,L,E,Y,I,V,P,Z,M):dΛjdt=0},  j=0,1,...,7.

    Define a function

    ϝ(υ)=υ1lnυ,   υ>0.

    Theorem 1. If 11 and 21, then Ξ0 is globally asymptotically stable (G.A.S).

    Proof. Define

    Λ0=X0ϝ(XX0)+L+E+ηL+δLδLY+ηE+δEδEI+βVX0πVV+βPX0πPP+βVX0ϰVσZπVZ+βPX0ϰPσMπPM.

    We note that, Λ0>0 for all X,L,E,Y,I,V,P,Z,M>0 and Λ0(X0,0,0,0,0,0,0,0,0)=0. We calculate dΛ0dt along the solutions of model (2.1) as:

    dΛ0dt=(1X0X)[λαXβVXVβPXP]+βVXV(ηL+δL)L+βPXP(ηE+δE)E+ηL+δLδL[δLLγYY]+ηE+δEδE[δEEγII]+βVX0πV[κVYπVVϰVVZ]+βPX0πP[κPIπPPϰPPM]+βVX0ϰVσZπV[σZVZμZZ]+βPX0ϰPσMπP[σMPMμMM]=(1X0X)(λαX)γY(ηL+δL)δLYγI(ηE+δE)δEI+κVβVX0πVY+κPβPX0πPIβVX0ϰVμZπVσZZβPX0ϰPμMπPσMM.

    Using the equilibrium condition, λ=αX0 we get

    dΛ0dt=α(XX0)2X+γY(ηL+δL)δL(κVβVδLX0γYπV(ηL+δL)1)Y+γI(ηE+δE)δE(κPβPδEX0γIπP(ηE+δE)1)IβVX0ϰVμZπVσZZβPX0ϰPμMπPσMM=α(XX0)2X+γY(ηL+δL)δL(11)Y+γI(ηE+δE)δE(21)IβVX0ϰVμZπVσZZβPX0ϰPμMπPσMM.

    Since 11 and 21, then dΛ0dt0 for all X,Y,I,Z,M>0. In addition dΛ0dt=0, when X=X0 and Y=I=Z=M=0. The solutions of system (2.1) tend to ˜Ω0 [60] which includes elements with Y=I=0. Thus, ˙Y=˙I=0 and from the fourth and fifth equations of system (2.1) we have:

    0=˙Y=δLLL(t)=0, for all t,0=˙I=δEEE(t)=0, for all t.

    In addition, from the second and third equations of system (2.1) we have:

    0=˙L=βVX0VV(t)=0, for all t,0=˙E=βPX0PP(t)=0, for all t.

    Therefore, ˜Ω0={Ξ0} and applying Lyapunov-LaSalle Asymptotic Stability Theorem (L-LAST) [61,63], we obtain that Ξ0 is G.A.S.

    Theorem 2. Suppose that 1>1, 2/11 and 31, then Ξ1 is G.A.S.

    Proof. Let us formulate a Lyapunov function Λ1 as:

    Λ1=X1ϝ(XX1)+L1ϝ(LL1)+E+ηL+δLδLY1ϝ(YY1)+ηE+δEδEI+βVX1πVV1ϝ(VV1)+βPX1πPP+βVX1ϰVσZπVZ+βPX1ϰPσMπPM.

    We calculate dΛ1dt as:

    dΛ1dt=(1X1X)[λαXβVXVβPXP]+(1L1L)[βVXV(ηL+δL)L]+βPXP(ηE+δE)E+ηL+δLδL(1Y1Y)[δLLγYY]+ηE+δEδE[δEEγII]+βVX1πV(1V1V)[κVYπVVϰVVZ]+βPX1πP[κPIπPPϰPPM]+βVX1ϰVσZπV[σZVZμZZ]+βPX1ϰPσMπP[σMPMμMM]. (5.2)

    Simplifying Eq (5.2), we get

    dΛ1dt=(1X1X)(λαX)βVXVL1L+(ηL+δL)L1γY(ηL+δL)δLY(ηL+δL)LY1Y+γY(ηL+δL)δLY1γI(ηE+δE)δEI+βVX1κVπVYβVX1κVπVYV1V+βVX1V1+βVX1ϰVπVV1Z+βPX1κPπPIβVX1ϰVμZσZπVZβPX1ϰPμMσMπPM.

    Using the equilibrium conditions for Ξ1:

    λ=αX1+βVX1V1,  βVX1V1=(ηL+δL)L1,L1=γYδLY1,  V1=κVπVY1,

    we obtain

    dΛ1dt=(1X1X)(αX1αX)+4βVX1V1βVX1V1X1XβVX1V1L1XVLX1V1βVX1V1Y1LYL1βVX1V1V1YVY1+γI(ηE+δE)δE(βPX1κPδEγIπP(ηE+δE)1)I+βVX1ϰVμZσZπV(σZμZV11)ZβPX1ϰPμMσMπPM. (5.3)

    Then collecting terms of (5.3), we get

    dΛ1dt=α(XX1)2X+βVX1V1[4X1XL1XVLX1V1Y1LYL1V1YVY1]+γI(ηE+δE)δE(211)I+ϰVX1(ασZ+βVμZ)σZπV(31)ZβPX1ϰPμMσMπPM.

    Using inequality (5.1), we get

    4X1XL1XVLX1V1Y1LYL1V1YVY10.

    Since 2/11 and 31, then dΛ1dt0 for all X,L,Y,I,V,Z,M>0. Moreover, dΛ1dt=0 when X=X1, L=L1,Y=Y1, V=V1 and I=Z=M=0. The solutions of system (2.1) tend to ˜Ω1 where I=0. Hence, ˙I=0 and the fifth equation of system (2.1) gives

    0=˙I=δEEE(t)=0, for all t.

    In addition, from the third equation of system (2.1) we get,

    0=˙E=βPX1PP(t)=0, for all t.

    Hence, ˜Ω1={Ξ _{1} } and Ξ1 is G.A.S by using L-LAST [61,62,63].

    Theorem 3. Let 2>1, 1/21 and 41, then Ξ2 is G.A.S.

    Proof. Consider

    Λ2=X2ϝ(XX2)+L+E2ϝ(EE2)+ηL+δLδLY+ηE+δEδEI2ϝ(II2)+βVX2πVV+βPX2πPP2ϝ(PP2)+βVX2ϰVσZπVZ+βPX2ϰPσMπPM.

    We calculate dΛ2dt as:

    dΛ2dt=(1X2X)[λαXβVXVβPXP]+βVXV(ηL+δL)L+(1E2E)[βPXP(ηE+δE)E]+ηL+δLδL[δLLγYY]+ηE+δEδE(1I2I)[δEEγII]+βVX2πV[κVYπVVϰVVZ]+βPX2πP(1P2P)[κPIπPPϰPPM]+βVX2ϰVσZπV[σZVZμZZ]+βPX2ϰPσMπP[σMPMμMM]. (5.4)

    Then simplifying Eq (5.4), we get

    dΛ2dt=(1X2X)(λαX)βPXPE2E+(ηE+δE)E2γY(ηL+δL)δLYγI(ηE+δE)δEI(ηE+δE)EI2I+γI(ηE+δE)δEI2+κVπVβVX2Y+κPπPβPX2IκPπPβPX2IP2P+βPX2P2+ϰPπPβPX2P2MϰVμZσZπVβVX2ZϰPμMσMπPβPX2M.

    Using the equilibrium conditions for Ξ2:

    λ=αX2+βPX2P2,  βPX2P2=(ηE+δE)E2,E2=γIδEI2,  P2=κPπPI2,

    we obtain,

    dΛ2dt=(1X2X)(αX2αX)+4βPX2P2βPX2P2X2XβPX2P2E2XPEX2P2βPX2P2I2EIE2βPX2P2P2IPI2+γY(ηL+δL)δL(δLκVβVX2γYπV(ηL+δL)1)Y+βPX2ϰPμMσMπP(σMμMP21)MβVX2ϰVμZσZπVZ=α(XX2)2X+βPX2P2(4X2XE2XPEX2P2I2EIE2P2IPI2)+γY(ηL+δL)δL(121)Y+X2ϰP(ασM+βPμM)πPσM(41)MβVX2ϰVμZσZπVZ.

    If 1/21 and 41, then employing inequality (5.1), we get dΛ2dt0 for all X,E,Y,I,P,Z,M>0. Further, dΛ2dt=0 when X=X2,E=E2, I=I2, P=P2 and Y=Z=M=0. The solutions of system (2.1) tend to ˜Ω2 which has Y=0, and gives ˙Y=0. The fourth equation of system (2.1) gives

    0=˙Y=δLLL(t)=0, for all t.

    In addition, from the second equation of system (2.1) gives

    0=˙L=βVX2VV(t)=0, for all t.

    Therefore, ˜Ω2={Ξ _{2} }. Applying L-LAST, we get Ξ2 is G.A.S.

    Theorem 4. Let 3>1 and 51, then Ξ3 is G.A.S.

    Proof. Define

    Λ3=X3ϝ(XX3)+L3ϝ(LL3)+E+ηL+δLδLY3ϝ(YY3)+ηE+δEδEI+γY(ηL+δL)κVδLV3ϝ(VV3)+γI(ηE+δE)κPδEP+γYϰV(ηL+δL)κVδLσZZ3ϝ(ZZ3)+γIϰP(ηE+δE)κPδEσMM.

    We calculate dΛ3dt as:

    dΛ3dt=(1X3X)[λαXβVXVβPXP]+(1L3L)[βVXV(ηL+δL)L]+βPXP(ηE+δE)E+ηL+δLδL(1Y3Y)[δLLγYY]+ηE+δEδE[δEEγII]+γY(ηL+δL)κVδL(1V3V)[κVYπVVϰVVZ]+γI(ηE+δE)κPδE[κPIπPPϰPPM]+γYϰV(ηL+δL)κVδLσZ(1Z3Z)[σZVZμZZ]+γIϰP(ηE+δE)κPδEσM[σMPMμMM]. (5.5)

    Then simplifying Eq (5.5), we get

    dΛ3dt=(1X3X)(λαX)+βVX3V+βPX3PβVXVL3L+(ηL+δL)L3(ηL+δL)LY3Y+γY(ηL+δL)δLY3πVγY(ηL+δL)κVδLVγY(ηL+δL)YV3δLV+πVγY(ηL+δL)κVδLV3+ϰVγY(ηL+δL)κVδLZV3πPγI(ηE+δE)κPδEPϰVγYμZ(ηL+δL)σZκVδLZϰVγY(ηL+δL)κVδLZ3V+ϰVγYμZ(ηL+δL)σZκVδLZ3ϰPγIμM(ηE+δE)σMκPδEM.

    Using the equilibrium conditions for Ξ3:

    λ=αX3+βVX3V3,   βVX3V3=(ηL+δL)L3,L3=γYδLY3,   κVY3=πVV3+ϰVV3Z3, V3=μZσZ,

    we obtain,

    dΛ3dt=(1X3X)(αX3αX)+4βVX3V3βVX3V3X3XβVX3V3L3XVLX3V3βVX3V3Y3LYL3βVX3V3V3YVY3+πPγI(ηE+δE)κPδE(βPX3κPδEπPγI(ηE+δE)1)PϰPγIμM(ηE+δE)σMκPδEM=α(XX3)2X+βVX3V3(4X3XL3XVLX3V3Y3LYL3V3YVY3)+πPγI(ηE+δE)κPδE(51)PϰPγIμM(ηE+δE)σMκPδEM.

    Using inequality (5.1) and 51, we get dΛ3dt0 for all X,L,Y,V,P,M>0. Further, dΛ3dt=0 when X=X3, L=L3, Y=Y3,V=V3 and P=M=0. Further, the trajectories of system (2.1) tend to ˜Ω3 which has elements with V=V3 and P=0. Then ˙V=0 and ˙P=0. The sixth and seventh equations of system (2.1), provide

    0=˙V=κVY3πVV3ϰVV3ZZ(t)=Z3, for all t0=˙P=κPII(t)=0, for all t.

    In addition, from the fifth equation of system (2.1) gives

    0=˙I=δEEE(t)=0, for all t.

    Consequently, ˜Ω3={Ξ _{3} }. Applying L-LAST, we find that Ξ3 is G.A.S.

    Theorem 5. If 4>1 and 61, then Ξ4 is G.A.S.

    Proof. Define a function Λ4 as:

    Λ4=X4ϝ(XX4)+L+E4ϝ(EE4)+ηL+δLδLY+ηE+δEδEI4ϝ(II4)+γY(ηL+δL)κVδLV+γI(ηE+δE)κPδEP4ϝ(PP4)+γYϰV(ηL+δL)κVδLσZZ+γIϰP(ηE+δE)κPδEσMM4ϝ(MM4).

    Calculating dΛ4dt as:

    dΛ4dt=(1X4X)[λαXβVXVβPXP]+βVXV(ηL+δL)L+(1E4E)[βPXP(ηE+δE)E]+ηL+δLδL[δLLγYY]+ηE+δEδE(1I4I)[δEEγII]+γY(ηL+δL)κVδL[κVYπVVϰVVZ]+γI(ηE+δE)κPδE(1P4P)[κPIπPPϰPPM]+γYϰV(ηL+δL)κVδLσZ[σZVZμZZ]+γIϰP(ηE+δE)κPδEσM(1M4M)[σMPMμMM]. (5.6)

    Equation (5.6) can be written as:

    dΛ4dt=(1X4X)(λαX)+βVX4V+βPX4PβPXPE4E+(ηE+δE)E4(ηE+δE)EI4I+γI(ηE+δE)δEI4πVγY(ηL+δL)κVδLVπPγI(ηE+δE)κPδEPγI(ηE+δE)P4δEPI+πPγI(ηE+δE)κPδEP4+ϰPγI(ηE+δE)κPδEMP4ϰVγYμZ(ηL+δL)κVδLσZZϰPγIμM(ηE+δE)κPδEσMMϰPγI(ηE+δE)κPδEM4P+ϰPγIμM(ηE+δE)σMκPδEM4.

    Using the equilibrium conditions for Ξ4:

    λ=αX4+βPX4P4,   βPX4P4=(ηE+δE)E4,κPI4=πPP4+ϰPP4M4,  E4=γIδEI4,  P4=μMσM,

    we obtain,

    dΛ4dt=(1X4X)(αX4αX)+4βPX4P4βPX4P4X4XβPX4P4E4XPEX4P4βPX4P4I4EIE4βPX4P4P4IPI4ϰVγYμZ(ηL+δL)κVδLσZZ+πVγY(ηL+δL)κVδL(βVX4κVδLπVγY(ηL+δL)1)V=α(XX4)2X+βPX4P4(4X4XE4XPEX4P4I4EIE4P4IPI4)+πVγY(ηL+δL)κVδL(61)VϰVγYμZ(ηL+δL)κVδLσZZ.

    Since 61, then employing inequality (5.1), we get dΛ4dt0 for all X,E,I,V,P,Z>0. Further, dΛ4dt=0 when X=X4, E=E4,I=I4,P=P4 and V=Z=0. The solutions of system (2.1) tend to ˜Ω4 which contains elements with P=P4 and V=0, then ˙V=˙P=0. The sixth and seventh equations of system (2.1) imply

    0=˙V=κVYY(t)=0, for all t0=˙P=κPI4πPP4ϰPP4MM(t)=M4, for all t.

    In addition, since Y=0, then ˙Y=0. The fourth equation of system (2.1) gives

    0=˙Y=δLLL(t)=0, for all t.

    Therefore, ˜Ω4={Ξ4}. Applying L-LAST, we get Ξ4 is G.A.S.

    Theorem 6. If 5>1, 1/2>1 and 81, then Ξ5 is G.A.S.

    Proof. Define

    Λ5=X5ϝ(XX5)+L5ϝ(LL5)+E5ϝ(EE5)+ηL+δLδLY5ϝ(YY5)+ηE+δEδEI5ϝ(II5)+γY(ηL+δL)κVδLV5ϝ(VV5)+γI(ηE+δE)κPδEP5ϝ(PP5)+γYϰV(ηL+δL)κVδLσZZ5ϝ(ZZ5)+γIϰP(ηE+δE)κPδEσMM.

    Calculating dΛ5dt as:

    dΛ5dt=(1X5X)[λαXβVXVβPXP]+(1L5L)[βVXV(ηL+δL)L]+(1E5E)[βPXP(ηE+δE)E]+ηL+δLδL(1Y5Y)[δLLγYY]+ηE+δEδE(1I5I)[δEEγII]+γY(ηL+δL)κVδL(1V5V)[κVYπVVϰVVZ]+γI(ηE+δE)κPδE(1P5P)[κPIπPPϰPPM]+γYϰV(ηL+δL)κVδLσZ(1Z5Z)[σZVZμZZ]+γIϰP(ηE+δE)κPδEσM[σMPMμMM]. (5.7)

    Equation (5.7) can be simplified as:

    dΛ5dt=(1X5X)(λαX)+βVX5V+βPX5PβVXVL5L+(ηL+δL)L5βPXPE5E+(ηE+δE)E5(ηL+δL)LY5Y+γY(ηL+δL)δLY5(ηE+δE)EI5I+γI(ηE+δE)δEI5πVγY(ηL+δL)κVδLVγY(ηL+δL)V5δLVY+πVγY(ηL+δL)κVδLV5+ϰVγY(ηL+δL)κVδLV5ZπPγI(ηE+δE)κPδEPγI(ηE+δE)P5δEPI+πPγI(ηE+δE)κPδEP5+ϰPγI(ηE+δE)κPδEMP5ϰVγYμZ(ηL+δL)κVδLσZZϰVγY(ηL+δL)κVδLVZ5+ϰVγYμZ(ηL+δL)κVδLσZZ5ϰPγIμM(ηE+δE)κPδEσMM.

    Using the equilibrium conditions for Ξ5:

    λ=αX5+βVX5V5+βPX5P5,    βVX5V5=(ηL+δL)L5,βPX5P5=(ηE+δE)E5,    κVY5=πVV5+ϰVV5Z5,κPI5=πPP5,    V5=μZσZ,L5=γYδLY5,    E5=γIδEI5,

    we obtain,

    dΛ5dt=(1X5X)(αX5αX)+4βVX5V5+4βPX5P5βVX5V5X5XβPX5P5X5XβVX5V5L5XVLX5V5βPX5P5E5XPEX5P5βVX5V5Y5LYL5βPX5P5I5EIE5βVX5V5V5YVY5βPX5P5P5IPI5+ϰPγIμM(ηE+δE)κPδEσM(σMμMP51)M=α(XX5)2X+βVX5V5(4X5XL5XVLX5V5Y5LYL5V5YVY5)+βPX5P5(4X5XE5XPEX5P5I5EIE5P5IPI5)+ϰPγI(ηE+δE)(ασZσM+βVμZσM+βPμMσZ)κPδEβPσZσM(81)M.

    Since 81, then employing inequality (5.1), we get dΛ5dt0 for all X,L,E,Y,I,V,P,M>0. Moreover, we have dΛ5dt=0, when X=X5,L=L5,E=E5, Y=Y5, I=I5,V=V5,P=P5 and M=0. The trajectories of system (2.1) converge to ˜Ω5 which comprises elements with Y=Y5 and V=V5, then ˙V=0. The sixth equation of system (2.1) implies that

    0=˙V=κVY5πVV5ϰVV5ZZ(t)=Z5, for all t.

    Consequently, ˜Ω5={Ξ _{5} }. and by applying L-LAST, we get Ξ5 is G.A.S.

    Theorem 7. Let 6>1, 71 and 2/1>1, then Ξ6 is G.A.S.

    Proof. Consider a function Λ6 as:

    Λ6=X6ϝ(XX6)+L6ϝ(LL6)+E6ϝ(EE6)+ηL+δLδLY6ϝ(YY6)+ηE+δEδEI6ϝ(II6)+γY(ηL+δL)κVδLV6ϝ(VV6)+γI(ηE+δE)κPδEP6ϝ(PP6)+γYϰV(ηL+δL)κVδLσZZ+γIϰP(ηE+δE)κPδEσMM6ϝ(MM6).

    Calculating dΛ6dt as:

    dΛ6dt=(1X6X)[λαXβVXVβPXP]+(1L6L)[βVXV(ηL+δL)L]+(1E6E)[βPXP(ηE+δE)E]+ηL+δLδL(1Y6Y)[δLLγYY]+ηE+δEδE(1I6I)[δEEγII]+γY(ηL+δL)κVδL(1V6V)[κVYπVVϰVVZ]+γI(ηE+δE)κPδE(1P6P)[κPIπPPϰPPM]+γYϰV(ηL+δL)κVδLσZ[σZVZμZZ]+γIϰP(ηE+δE)κPδEσM(1M6M)[σMPMμMM]. (5.8)

    We collect the terms of Eq (5.8) as:

    dΛ6dt=(1X6X)(λαX)+βVX6V+βPX6PβVXVL6L+(ηL+δL)L6βPXPE6E+(ηE+δE)E6(ηL+δL)LY6Y+γY(ηL+δL)δLY6(ηE+δE)EI6I+γI(ηE+δE)δEI6πVγY(ηL+δL)κVδLVγY(ηL+δL)V6δLVY+πVγY(ηL+δL)κVδLV6+ϰVγY(ηL+δL)κVδLV6ZπPγI(ηE+δE)κPδEPγI(ηE+δE)P6δEPI+πPγI(ηE+δE)κPδEP6+ϰPγI(ηE+δE)κPδEMP6ϰVγYμZ(ηL+δL)κVδLσZZϰPγIμM(ηE+δE)κPδEσMMϰPγI(ηE+δE)κPδEPM6+ϰPγIμM(ηE+δE)κPδEσMM6.

    Using the equilibrium conditions for Ξ6:

    λ=αX6+βVX6V6+βPX6P6,   βVX6V6=(ηL+δL)L6,  βPX6P6=(ηE+δE)E6,L6=γYδLY6,  E6=γIδEI6,  Y6=πVκVV6,I6=πPκPP6+ϰPκPP6M6,  P6=μMσM,

    we obtain,

    dΛ6dt=(1X6X)(αX6αX)+4βVX6V6+4βPX6P6βVX6V6X6XβPX6P6X6XβVX6V6L6XVLX6V6βPX6P6E6XPEX6P6βVX6V6Y6LYL6βPX6P6I6EIE6βVX6V6V6YVY6βPX6P6P6IPI6+ϰVγYμZ(ηL+δL)κVδLσZ(σZμZV61)Z=α(XX6)2X+βVX6V6(4X6XL6XVLX6V6Y6LYL6V6YVY6)+βPX6P6(4X6XE6XPEX6P6I6EIE6P6IPI6)+ϰVγY(ηL+δL)(ασZσM+βVμZσM+βPμMσZ)κVδLσMβVσZ(71)Z.

    Since 71, then employing inequality (5.1), we get dΛ6dt0 for all X,L,E,Y,I,V,P,Z>0. Moreover, dΛ6dt=0 when X=X6, L=L6,E=E6,Y=Y6, I=I6,V=V6,P=P6 and Z=0. The solutions of system (2.1) tend to ˜Ω6 which contains elements with P=P6 then, ˙P=0. The seven equation of system (2.1) implies that

    0=˙P=κPI6πPP6ϰPP6MM(t)=M6, for all t.

    Consequently, ˜Ω6={Ξ6}. Using L-LAST we deduce that Ξ6 is G.A.S.

    Theorem 8. If 7>1 and 8>1, then Ξ7 is G.A.S.

    Proof. Define a function Λ7 as:

    Λ7=X7ϝ(XX7)+L7ϝ(LL7)+E7ϝ(EE7)+ηL+δLδLY7ϝ(YY7)+ηE+δEδEI7ϝ(II7)+γY(ηL+δL)κVδLV7ϝ(VV7)+γI(ηE+δE)κPδEP7ϝ(PP7)+γYϰV(ηL+δL)κVδLσZZ7ϝ(ZZ7)+γIϰP(ηE+δE)κPδEσMM7ϝ(MM7).

    Calculating dΛ7dt as:

    dΛ7dt=(1X7X)[λαXβVXVβPXP]+(1L7L)[βVXV(ηL+δL)L]+(1E7E)[βPXP(ηE+δE)E]+ηL+δLδL(1Y7Y)[δLLγYY]+ηE+δEδE(1I7I)[δEEγII]+γY(ηL+δL)κVδL(1V7V)[κVYπVVϰVVZ]+γI(ηE+δE)κPδE(1P7P)[κPIπPPϰPPM]+γYϰV(ηL+δL)κVδLσZ(1Z7Z)[σZVZμZZ]+γIϰP(ηE+δE)κPδEσM(1M7M)[σMPMμMM]. (5.9)

    We collect the terms of Eq (5.9) as:

    dΛ7dt=(1X7X)(λαX)+βVX7V+βPX7PβVXVL7L+(ηL+δL)L7βPXPE7E+(ηE+δE)E7(ηL+δL)LY7Y+γY(ηL+δL)δLY7(ηE+δE)EI7I+γI(ηE+δE)δEI7πVγY(ηL+δL)κVδLVγY(ηL+δL)V7δLVY+πVγY(ηL+δL)κVδLV7+ϰVγY(ηL+δL)κVδLV7ZπPγI(ηE+δE)κPδEPγI(ηE+δE)P7δEPI+πPγI(ηE+δE)κPδEP7+ϰPγI(ηE+δE)κPδEMP7ϰVγYμZ(ηL+δL)κVδLσZZϰVγY(ηL+δL)κVδLVZ7+ϰVγYμZ(ηL+δL)κVδLσZZ7ϰPγIμM(ηE+δE)κPδEσMMϰPγI(ηE+δE)κPδEPM7+ϰPγIμM(ηE+δE)κPδEσMM7.

    Using the equilibrium conditions for Ξ7:

    λ=αX7+βVX7V7+βPX7P7,     βVX7V7=(ηL+δL)L7,   βPX7P7=(ηE+δE)E7,   L7=γYδLY7,   E7=γIδEI7,Y7=πVκVV7+ϰVκVV7Z7,   I7=πPκPP7+ϰPκPP7M7,V7=μZσZ,   P7=μMσM,

    we obtain,

    dΛ7dt=(1X7X)(αX7αX)+4βVX7V7+4βPX7P7βVX7V7X7XβPX7P7X7XβVX7V7L7XVLX7V7βPX7P7E7XPEX7P7βVX7V7Y7LYL7βPX7P7I7EIE7βVX7V7V7YVY7βPX7P7P7IPI7=α(XX7)2X+βVX7V7(4X7XL7XVLX7V7Y7LYL7V7YVY7)+βPX7P7(4X7XE7XPEX7P7I7EIE7P7IPI7).

    Using inequality (5.1), we get dΛ7dt0 for all X,L,E,Y,I,V,P>0, where dΛ7dt=0 when X=X7, L=L7,E=E7,Y=Y7,I=I7,V=V7 and P=P7. The solutions of system (2.1) tend to ˜Ω7 which includes element with V=V7 and P=P7 which gives ˙V=˙P=0 and from the sixth and seventh equations of system (2.1) we get

    0=˙V=κVY7πVV7ϰVV7ZZ(t)=Z7, for all t,0=˙P=κPI7πPP7ϰPP7MM(t)=M7, for all t.

    Therefore, ˜Ω7={Ξ7} and by employing L-LAST, we get Ξ7 is G.A.S. Based on the above findings, we summarize the existence and global stability conditions for all equilibrium points in Table 1.

    Table 1.  Conditions of existence and global stability of the system's equilibria.
    Equilibrium point Existence conditions Global stability  conditions
    Ξ0=(X0,0,0,0,0,0,0,0,0) None 11 and 21
    Ξ1=(X1,L1,0,Y1,0,V1,0,0,0) 1>1 1>1, 2/11 and 31
    Ξ2=(X2,0,E2,0,I2,0,P2,0,0) 2>1 2>1, 1/21 and 41
    Ξ3=(X3,L3,0,Y3,0,V3,0,Z3,0) 3>1 3>1 and 51
    Ξ4=(X4,0,E4,0,I4,0,P4,0,M4) 4>1 4>1 and 61
    Ξ5=(X5,L5,E5,Y5,I5,V5,P5,Z5,0) 5>1 and 1/2>1 5>1, 81 and 1/2>1
    Ξ6=(X6,L6,E6,Y6,I6,V6,P6,0,M6) 6>1 and 2/1>1 6>1, 71 and 2/1>1
    Ξ7=(X7,L7,E7,Y7,I7,V7,P7,Z7,M7) 7>1 and 8>1 7>1 and 8>1

     | Show Table
    DownLoad: CSV

    We noted that system (2.1) has eight equilibria for which the coexistence case of IAV and SARS-CoV-2 can only be occurred if at least one type of the specific antibody immunities is active. Now, we discuss the importance of considering the antibody immune response in the IAV/SARS-CoV-2 dynamics model. If the antibody immune response is neglected then system (2.1) becomes:

    {˙X=λαXβVXVβPXP,˙L=βVXV(ηL+δL)L,˙E=βPXP(ηE+δE)E,˙Y=δLLγYY,˙I=δEEγII,˙V=κVYπVV,˙P=κPIπPP. (6.1)

    We can see that system (6.1) describes the competition between IAV and SARS-CoV-2 on one source of target cells, epithelial cells. The model admits only three equilibria:

    (i) Infection-free equilibrium, ˜Ξ0=(˜X0,0,0,0,0,0,0), where both IAV and SARS-CoV-2 are cleared,

    (ii) SARS-CoV-2 single-infection equilibrium ˜Ξ1=(˜X1,˜L1,0,˜Y1,0,˜V1,0), where the IAV is blocked,

    (iii) IAV single-infection equilibrium, ˜Ξ2=(˜X2,0,˜E2,0,˜I2,0,˜P2), where the SARS-CoV-2 is blocked, where ˜Xi=Xi, i=0,1,2, ˜L1=L1, ˜Y1=Y1, ˜V1=V1, ˜E2=E2, ˜I2=I2, and ˜P2=P2.

    We note that the case of IAV and SARS-CoV-2 coexistence does not appear. In the recent studies presented in [5,9,11,12], it was recorded that some COVID-19 patients were detected to be coinfected with IAV. Therefore, neglecting the immune response may not describe the coinfection dynamics accurately. This supports the idea of including the immune response into the IAV/SARS-CoV-2 coinfection model, where the case of IAV and SARS-CoV-2 coexistence is observed.

    The global stability of the system's equilibria will be illustrated numerically. We use the values of the parameters presented in Table 2. In addition, we make a comparison between single-infection and coinfection.

    Table 2.  Model parameters.
    Parameter Value Parameter Value Parameter Value Parameter Value
    λ 0.5 γI 0.2 ϰV 0.05 μM 0.04
    α 0.05 κV 0.2 ϰP 0.04 ηL 0.05
    βV Varied κP 0.4 σZ Varied ηE 0.06
    βP Varied πV 0.2 σM Varied δL 0.05
    γY 0.11 πP 0.1 μZ 0.05 δE 0.06

     | Show Table
    DownLoad: CSV

    Now, we solve system (2.1) with three different initial conditions (states) as:

    C1:(X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))=(8,0.5,1,1,0.5,1,0.5,1,4),C2:(X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))=(7,1,1.5,1.5,0.7,1.5,0.8,2,6),C3:(X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))=(6,1.5,2,2,1,2,1.4,3,8).

    Selecting the values of βV, βP, σZ and σM leads to the following situations:

    Situation 1 (Stability of Ξ0): βV=0.001,βP=0.001, σZ=0.01 and σM=0.02. For these values of parameters, we have 1=0.0455<1 and 2=0.1<1. Figure 2 shows that the trajectories tend to the equilibrium Ξ0=(10,0,0,0,0,0,0,0,0) for all initials C1-C3. This demonstrates that, Ξ0 is G.A.S based on Theorem 1. In this situation, both SARS-CoV-2 and IAV will be removed.

    Figure 2.  Solutions of system (2.1) when 11 and 21.

    Situation 2 (Stability of Ξ1): βV=0.05,βP=0.001,σZ=0.002 and σM=0.02. With such selection we obtain 1=2.2727>1, 3=0.0874<1 and hence 2/1=0.044<1. The equilibrium point Ξ1 exists with Ξ1=(4.4,2.8,0,1.27,0,1.27,0,0,0). It is clear from Figure 3 that, the trajectories tend to Ξ1 for all initials C1-C3. Thus, the numerical results agree with Theorem 2. This case simulates a SARS-CoV-2 single-infection without antibody immunity.

    Figure 3.  Solutions of system (2.1) when 1>1,2/11 and 31.

    Situation 3 (Stability of Ξ2): βV=0.005,βP=0.03, σZ=0.01 and σM=0.001. This gives 2=3>1, 4=0.12<1 and then 1/2=0.0758<1. The numerical results show that, Ξ2=(3.33,0,2.78,0,0.83,0,3.33,0,0) exists. We can observe from Figure 4 that, the trajectories converge to Ξ2 regardless of the initial states. This result supports the result of Theorem 3. This situation represents an IAV single-infection without antibody immunity.

    Figure 4.  Solutions of system (2.1) when 2>1,1/21 and 41.

    Situation 4 (Stability of Ξ3): βV=0.09,βP=0.002, σZ=0.05 and σM=0.05. This yields 3=1.461>1 and 5=0.0714<1. Figure 5 shows that the trajectories tend to Ξ3=(3.57,3.21,0,1.46,0,1,0,1.84,0) regardless of the initial states. Therefore, Ξ3 is G.A.S and this supports Theorem 4. Hence, a SARS-CoV-2 single-infection with stimulated SARS-CoV-2-specific antibody is attained.

    Figure 5.  Solutions of system (2.1) when 3>1 and 51.

    Situation 5 (Stability of Ξ4): βV=0.01,βP=0.1, σZ=0.01 and σM=0.02. The values of 4 and 6 are computed as 4=2>1 and 6=0.0909<1. Thus, Ξ4 exists with Ξ4=(2,0,3.33,0,1,0,2,0,2.5). In Figure 6 we see that the trajectories tend to Ξ4 regardless of the initial states. It follows that Ξ4 is G.A.S according to Theorem 5. Hence, an IAV single-infection with activated IAV-specific antibody is achieved.

    Figure 6.  Solutions of system (2.1) when 4>1 and 61.

    Situation 6 (Stability of Ξ5): βV=0.09,βP=0.02, σZ=0.095 and σM=0.009. Then, we calculate 5=1.027>1, 8=0.5369<1 and 1/2=2.0455>1 The numerical results drawn in Figure 7 show that Ξ5=(5,2.37,0.11,1.08,0.03,0.53,0.13,4.18,0) exists and it is G.A.S and this is consistent with Theorem 6. As a result, a coinfection with SARS-CoV-2 and IAV is attained where only SARS-CoV-2-specific antibody is stimulated.

    Figure 7.  Solutions of system (2.1) when 5>1,1/2>1 and 81.

    Situation 7 (Stability of Ξ6): βV=0.09,βP=0.09, σZ=0.03 and σM=0.03. We compute 6=1.2032>1, 7=0.6392<1 and 2/1=2.2>1. We find that, the equilibrium Ξ6=(2.44,0.84,2.44,0.38,0.73,0.38,1.33,0,3) exists. Further, the numerical solutions outlined in Figure 8 show that, Ξ6 is G.A.S and this boosts the result of Theorem 7. In this situation, a coinfection with SARS-CoV-2 and IAV are attained where only IAV-specific antibody is activated.

    Figure 8.  Solutions of system (2.1) when 6>1,2/1>1 and 71.

    Situation 8 (Stability of Ξ7): βV=0.09,βP=0.09, σZ=0.5 and σM=0.5. This selection yields 7=3.0898>1 and 8=6.7976>1. Figure 9 shows that Ξ7=(7.55,0.68,0.45,0.31,0.14,0.1,0.08,8.36,14.49) exists and it is G.A.S based on Theorem 8. In this situation, a coinfection with SARS-CoV-2 and IAV is established regardless of the initial states. In this case, both SARS-CoV-2-specific antibodies and IAV-specific antibodies are working against the coinfection.

    Figure 9.  Solutions of system (2.1) when 7>1 and 8>1.

    For more confirmation, we investigate the local stability of the system's equilibria. Calculating the Jacobian matrix J=J(X,L,E,Y,I,V,P,Z,M) of system (2.1) as:

    J=(J_110000β_VXβ_PX00β_VVJ22000β_VX000β_PP0J33000β_PX000δ_L0γ_Y0000000δ_E0γ_I0000000κ_V0J660ϰ_VV00000κ_P0J770ϰ_PP00000σ_ZZ0J880000000σ_MM0J99)

    where J11=(α+βVV+βPP),  J22=(ηL+δL),  J33=(ηE+δE),  J66=(πV+ϰVZ), J77=(πP+ϰPM),  J88=σZVμZ,  J99=σMPμM.

    At each equilibrium, we compute the eigenvalues λj,j=1,2,...,9 of J. If Re(λj)<0,i=1,2,...,9, then the equilibrium point is locally stable. We select the parameters βV, βP, σZ and σM as given in situations 1-8, then we compute all nonnegative equilibria and the accompanying eigenvalues. Table 3 outlined the nonnegative equilibria, the real parts of the eigenvalues and whether or not the equilibrium point is stable.

    Table 3.  Local stability of nonnegative equilibria Ξi, i=0,1,...,9.
    Situatio The equilibria Re(λj), j = 1, 2, …, 9 Stability
    1 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.18, −0.18, −0.18, −0.15, −0.08, −0.07, −0.05, −0.05, −0.04) stable
    2 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.22, −0.22, −0.18, −0.18, −0.07, −0.05, −0.05, −0.04, 0.04) unstable
    Ξ1 = (4.4, 2.8, 01.27, 0, 1.27, 0, 0, 0) (−0.22, −0.22, −0.17, −0.17, −0.08, −0.04, −0.04, −0.05, −0.04) stable
    3 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.24, −0.24, −0.18, −0.18, 0.06, −0.05, −0.05, −0.05, −0.04) unstable
    Ξ2 = (3.33, 0, 2.78, 0, 0.83, 0, 3.33, 0, 0) (−0.24, −0.24, −0.17, −0.17, −0.07, −0.05, −0.05, −0.05, −0.04) stable
    4 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.24, −0.24, −0.18, −0.18, 0.08, −0.05, −0.05, −0.05, −0.04) unstable
    Ξ1 = (2.44, 3.78, 0, 1.27, 0, 1.27, 0, 0, 0) (−0.25, −0.25, −0.17, −0.17, −0.08, −0.06, −0.06, −0.04, 0.04) unstable
    Ξ3 = (3.57, 3.21, 0, 1.46, 0, 1, 0, 1.84, 0) (−0.27, −0.27, −0.17, −0.17, −0.07, −0.04, −0.04, −0.04, −0.03) stable
    5 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.29, −0.29, −0.19, −0.19, 0.15, −0.05, −0.05, −0.04, −0.03) unstable
    Ξ2 = (1, 0, 3.75, 0, 1.13, 0, 4.5, 0, 0) (−0.47, −0.29, −0.18, −0.15, −0.08, −0.08, −0.08, −0.05, 0.05) unstable
    Ξ4 = (2, 0, 3.33, 0, 1, 0, 2, 0, 2.5) (−0.31, −0.31, −0.17, −0.17, −0.06, −0.06, −0.07, −0.05, −0.03) stable
    6 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.24, −0.24, −0.23, −0.23, 0.08, −0.05, −0.05, −0.04, 0.03) unstable
    Ξ1 = (2.44, 3.78, 0, 1.72, 0, 1.72, 0, 0, 0) (−0.25, −0.25, −0.2, −0.2, 0.11, −0.06, −0.06, −0.04, −0.03) unstable
    Ξ2 = (5, 0, 2.08, 0, 0.63, 0, 2.5, 0, 0) (−0.22, −0.22, −0.22, −0.22, −0.05, −0.04, −0.04, 0.04, −0.02) unstable
    Ξ3 = (5.14, 2.43, 0, 1.11, 0, 0.53, 0, 4.4, 0) (−0.32, −0.32, −0.21, −0.21, −0.02, −0.02, −0.04, −0.04, 0.001) unstable
    Ξ5 = (5, 2.37, 0.11, 1.08, 0.03, 0.53, 0.13, 4.18, 0) (−0.31, −0.31, −0.21, −0.21, −0.02, −0.02, −0.04, −0.03, −0.001) stable
    7 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.28, −0.28, −0.24, −0.24, 0.14, 0.07, −0.05, −0.05, −0.04) unstable
    Ξ1 = (2.44, 3.78, 0, 1.72, 0, 1.72, 0, 0, 0) (−0.25, −0.25, −0.23, −0.23, −0.06, −0.06, −0.04, 0.04, 0.002) unstable
    Ξ2 = (1.11, 0, 3.71, 0, 1.11, 0, 4.44, 0, 0) (−0.4, −0.31, −0.19, −0.19, 0.09, −0.08, −0.08, −0.05, −0.03) unstable
    Ξ3 = (2.5, 3.75, 0, 1.7, 0, 1.67, 0, 0.09, 0) (−0.25, −0.25, −0.23, −0.23, −0.06, −0.06, 0.04, −0.04, −0.001) unstable
    Ξ4 = (2.94, 0, 2.94, 0, 0.88, 0, 1.33, 0, 4.12) (−0.32, −0.32, −0.21, −0.21, −0.04, −0.04, −0.05, −0.04, 0.008) unstable
    Ξ6 = (2.44, 0.84, 2.44, 0.38, 0.73, 0.38, 1.33, 0, 3) (−0.3, −0.3, −0.21, −0.21, −0.05, −0.05, −0.04, −0.02, −0.02) stable
    8 Ξ0 = (10, 0, 0, 0, 0, 0, 0, 0, 0) (−0.28, −0.28, −0.24, −0.24, 0.14, 0.08, −0.05, −0.05, −0.04) unstable
    Ξ1 = (2.44, 3.78, 0, 1.72, 0, 1.72, 0, 0, 0) (0.81, −0.25, −0.25, −0.23, −0.23, −0.06, −0.06, −0.04, 0.04) unstable
    Ξ2 = (1.11, 0, 3.7, 0, 1.11, 0, 4.44, 0, 0) (2.18, −0.4, −0.31, −0.19, −0.19, −0.08, −0.08, −0.05, −0.03) unstable
    Ξ3 = (8.47, 0.76, 0, 0.35, 0, 0.1, 0, 9.87, 0) (−0.63, −0.27, −0.27, −0.26, 0.13, −0.05, −0.01, −0.01, −0.04) unstable
    Ξ4 = (8.74, 0, 0.52, 0, 0.16, 0, 0.08, 0, 17.17) (−0.67, −0.41, −0.24, −0.24, 0.07, −0.01, −0.01, −0.05, −0.05) unstable
    Ξ6 = (2.44, 9.27, 0.15, 1.64, 0.04, 1.64, 0.08, 0, 3) (0.77, −0.27, −0.27, −0.25, −0.25, −0.06, −0.06, −0.006, −0.006) unstable
    Ξ7 = (7.55, 0.68, 0.45, 0.31, 0.14, 0.1, 0.08, 8.36, 14.49) (−0.54, −0.49, −0.49, −0.27, −0.02, −0.02, −0.05, −0.01, −0.01) stable

     | Show Table
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    In this subsection, we present a comparison between the single-infection and coinfection.

    Here, we compare the solutions of model (2.1) and the following SARS-CoV-2 single-infection model:

    {˙X=λαXβVXV,˙L=βVXV(ηL+δL)L,˙Y=δLLγYY,˙V=κVYπVVϰVVZ,˙Z=σZVZμZZ. (7.1)

    We fix parameters βV=0.09, βP=0.05, σZ=0.5, and σM=0.9 and select the initial state as:

    C4:(X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))=(7.5,0.3,5,0.5,0.4,0.05,0.04,9,9.5).

    From Figure 10 we observe that when the SARS-CoV-2 single-infected individual is coinfected with IAV, then the concentrations of uninfected epithelial cells, latent SARS-CoV-2-infected cells, active SARS-CoV-2-infected cells and SARS-CoV-2-specific antibodies are reduced. However, the concentration of free SARS-CoV-2 particles tends to be the same value in both SARS-CoV-2 single-infection and IAV/SARS-CoV-2 coinfection. This result agrees with the observation of Ding et al. [11] which said that "IAV/SARS-CoV-2 coinfection did not result in worse clinical outcomes in comparison with SARS-CoV-2 single-infection".

    Figure 10.  Comparison between the solutions of SARS-CoV-2-single infection model and IAV/SARS-CoV-2 coinfection model.

    To examine the impact of SARS-CoV-2 infection on IAV single-infection, we compare the solutions of model (2.1) and the following IAV single-infection model:

    {˙X=λαXβPXP,˙E=βPXV(ηE+δE)E,˙I=δEEγII,˙P=κPIπPPϰPPM,˙M=σMPMμMM. (7.2)

    We fix parameters βV=0.09, βP=0.08,σZ=0.07 and σM=0.05 and consider the following initial condition:

    C5:(X(0),L(0),E(0),Y(0),I(0),V(0),P(0),Z(0),M(0))=(4,1,5,0.6,0.5,0.2,0.05,3,8).

    It can be observed from Figure 11 that, when the IAV single-infected individual is coinfected with SARS-CoV-2 then the concentrations of uninfected epithelial cells, latent IAV-infected cells, active IAV-infected cells and IAV-specific antibodies are decreased. However, the concentration of free IAV particles tend to the same value in both IAV single-infection and IAV/SARS-CoV-2 coinfection.

    Figure 11.  Comparison between the solutions of IAV-single infection model and IAV/SARS-CoV-2 coinfection model.

    IAV and SARS-CoV-2 coinfection cases were reported in some works (see [5,9,11,12]). Therefore, it is important to understand the within-host dynamics of this coinfection. In this paper, we develop and examine a within-host IAV/SARS-CoV-2 coinfection model. The model considered the interactions between uninfected epithelial cells, latent SARS-CoV-2-infected cells, latent IAV-infected cells, active SARS-CoV-2-infected cells, active IAV-infected cells, free SARS-CoV-2 particles, free IAV particles, SARS-CoV-2-specific antibodies and IAV-specific antibodies. We examined the nonnegativity and boundedness of the solutions. We found that the system has eight equilibria and we proved the following:

    (I) The infection-free equilibrium Ξ0 always exists. It is G.A.S when 11 and 21. In this case, the patient is recovered from both IAV and SARS-CoV-2.

    (II) The SARS-CoV-2 single-infection equilibrium without antibody immunity Ξ1 exists if 1>1. It is G.A.S when 1>1, 2/11 and 31. This case leads to the situation of the patient only infected by SARS-CoV-2 with an inactive immune response. As we will see below that if both SARS-CoV-2-specific antibody and IAV-specific antibody immunities are not activated against the two viruses, then according to the competition between the two viruses, SARS-CoV-2 may be able to block the IAV.

    (III)- The IAV single-infection equilibrium without antibody immunity Ξ2 exists if 2>1. It is G.A.S when 2>1, 1/21 and 41. This case leads to the situation of the patient only infected by IAV with an unstimulated immune response. Then, IAV may be able to block the SARS-CoV-2.

    (IV) The SARS-CoV-2 single-infection equilibrium with stimulated SARS-CoV-2-specific antibody immunity Ξ3 exists if 3>1. It is G.A.S when 3>1 and 51. This point represents the situation of SARS-CoV-2 single-infection patient with active SARS-CoV-2-specific antibody immunity.

    (V) The IAV single-infection equilibrium with stimulated IAV-specific antibody immunity Ξ4 exists if 4>1. It is G.A.S when 4>1 and 61. This point represents the case of IAV single-infection patient with active IAV-specific antibody immunity.

    (VI) The IAV/SARS-CoV-2 coinfection equilibrium with only stimulated SARS-CoV-2-specific antibody immunity Ξ5 exists if 5>1 and 1/2>1. It is G.A.S when 5>1, 81 and 1/2>1. Here, the IAV/SARS-CoV-2 coinfection occurs with only stimulated SARS-CoV-2-specific antibody immunity.

    (VII) The IAV/SARS-CoV-2 coinfection equilibrium with only stimulated IAV-specific antibody immunity Ξ6 exists if 6>1 and 2/1>1. It is G.A.S when 6>1, 71 and 2/1>1. It means that the IAV/SARS-CoV-2 coinfection occurs with only stimulated IAV-specific antibody immunity.

    (VIII) The IAV/SARS-CoV-2 coinfection equilibrium with stimulated both SARS-CoV-2-specific antibodies and IAV-specific antibody immunities Ξ7 exists and it is G.A.S if 7>1 and 8>1. It means that, the IAV/SARS-CoV-2 coinfection occurs with both SARS-CoV-2-specific antibodies and IAV-specific antibody immunities are activated.

    The global stability of equilibria was established using the Lyapunov method. We performed numerical simulations and demonstrated that they are in good agreement with the theoretical results. We discussed the influence of IAV infection on SARS-CoV-2 single-infection dynamics and vice versa. We found that the concentration of free IAV or SARS-CoV-2 particles cells tends to be the same value in both single-infection and coinfection. This agrees with the work of Ding et al. [11] which reported that IAV/SARS-CoV-2 coinfection did not result in worse clinical outcomes. In addition, the spread of seasonal influenza can increase the likelihood of coinfection in patients with COVID-19 [9].

    The model developed in this work can be improved by (i) utilizing real data to find a good estimation of the parameters' values, (ii) studying the effect of time delays that occur during infection or production of IAV and SARS-CoV-2 particles, (iii) considering viral mutations [64,65], (iv) considering the effect of treatments on the progression of both viruses, and (v) including the influence of CTLs in killing SARS-CoV-2-infected and IAV-infected cells. Memory is an important characteristic of viral infections and immune response. It will be important to address the effect of memory on the dynamics of IAV/SARS-CoV-2 coinfection by formulation of the model via fractional differential equations [66,67,68].

    The innate immune response is one of the major antiviral responses to explain host-pathogen interaction. Also, it is a trigger to induce adaptive immunity which is the major focus of our proposed model. Model (2.1) can be extended to include the effect of IFN response as:

    ˙X=λαXβVXVβPXP,˙L=βVXVηLLδLL1+ϵLF,˙E=βPXPηEEδEE1+ϵEF,˙Y=δLL1+ϵLFγYY,˙I=δEE1+ϵEFγII,˙V=κVY1+ϵVFπVVϰVVZ,˙P=κPI1+ϵPFπPPϰPPM,˙Z=σZVZμZZ,˙M=σMPMμMM,˙F=ϖF(Y(tτ)+I(tτ))μFF.

    where ϵL, ϵE, ϵV and ϵP are the efficiencies of the IFN effects. These research points need further investigations so we leave them to future works.

    This research work was funded by Institutional Fund Projects under grant no. (IFPIP:69-130-1443). The authors gratefully acknowledge technical and financial support provided by the Ministry of Education and King Abdulaziz University, DSR, Jeddah, Saudi Arabia.



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