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Existence of solution for a Langevin equation involving the ψ-Hilfer fractional derivative: A variational approach

  • This study examines the existence of a solution for a nonvariational Langevin equation that involves the ψ-Hilfer fractional derivative. More specifically, we apply the mountain pass theorem, and then an iterative approach to establish the existence of a solution for the problem.

    Citation: Lamya Almaghamsi, Aeshah Alghamdi, Abdeljabbar Ghanmi. Existence of solution for a Langevin equation involving the ψ-Hilfer fractional derivative: A variational approach[J]. AIMS Mathematics, 2025, 10(1): 534-550. doi: 10.3934/math.2025024

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  • This study examines the existence of a solution for a nonvariational Langevin equation that involves the ψ-Hilfer fractional derivative. More specifically, we apply the mountain pass theorem, and then an iterative approach to establish the existence of a solution for the problem.



    Fractional calculus is a field of mathematical analysis that generalizes the concepts of derivatives and integrals to non-integer orders. It has become increasingly important in numerous scientific and engineering disciplines. As a result, many researchers have investigated its applications across various domains, such as virotherapy (see [1]), quantum mechanics (see [2]), image processing (see [3]), other applications in physics and engineering can be found in the papers [4,5]. Given their significance, numerous researchers have focused on addressing problems involving various fractional derivatives. For example, the works [6] (for the ψ-Caputo derivative), the papers [7,8,9,10] (Riemann-Liouville derivative combined with fixed points theorems), the papers [11,12,13] (Riemann-Liouville derivative combined with the variational method), and the work [14] (Hadamard derivative).

    Recently, numerous papers have focused on studying problems involving the ψ-Hilfer fractional derivative, which was introduced in the work of Hilfer [15]. The ψ-Hilfer fractional derivative is based on the generalized Hilfer fractional derivative, which itself combines elements of the Riemann-Liouville and Caputo derivatives. The Hilfer fractional derivative is a more flexible formulation than other fractional derivatives because it incorporates both the memory of a function and its local behavior, thus providing more control over the fractional-order derivative. This fractional derivative type generalizes and extends several classical definitions in fractional calculus and has been applied to model complex processes in physics, biology, and engineering; see, for instance, [16,17,18,19,20].

    In this work, we continue to address a problem involving the ψ-Hilfer fractional derivatives yDν,β,ψT and 0Dν,β,ψy, which were introduced in Section 2. More precisely, we prove the existence of solutions for the following problem:

    {yDν,β,ψT(0Dν,β,ψyu(y))=g(y,u(y),0Dν,β,ψyu(y)),y(0,T),Iν(ν1);ψ0+u(0)=Iν(ν1);ψTu(T)=0, (1.1)

    where ν(12,1), ψ is a positive increasing function on [0,T] with T>0 and ψ(y)0 for all y(0,T). The function g is a measurable function on [0,T]×R×R and satisfies additional conditions that will be stated later. We note that a function uE is a solution for problem (1.1), if for every vE we have

    T00Dν,β,ψyu(y)0Dν,β,ψyv(y)dy=T0g(y,u(y),0Dν,β,ψyu(y))v(y)dy,

    where E is a functional space introduced in Section 2. We also note that, in the special case where

    g(y,u(y),0Dν,β,ψyu(y))=f(y,u(y))λ0Dν,β,ψyu(y),

    the problem (1.1) simplifies to a Langevin equation.

    It is worth mentioning that the Langevin equation is the fundamental equation in the fields of statistical mechanics and stochastic processes. It describes the time evolution of a system's state, incorporating both deterministic and random forces. Albert Einstein provided a theoretical framework for Brownian motion, which refers to the random motion of particles suspended in a fluid. His work established the foundation for understanding the stochastic behavior of particles. Paul [21] further extended the concept of Brownian motion by introducing both a deterministic force and a random force (the thermal or stochastic force). He formulated what is now known as the Langevin equation, which describes the dynamics of a particle in a fluid, accounting for both frictional drag and random thermal fluctuations.

    The Langevin equation is given by:

    md2φ(y)dx2=γdφ(y)dx+η(y),

    where m is the mass of the particle, γ is the damping coefficient, and η(y) represents the random force following a Gaussian distribution. Recently, significant attention has been given to the study of Langevin equations with various fractional derivatives. Ahmad et al. [22,23] applied a combination of the contraction mapping principle and the Krasnoselskii fixed point theorem to establish the existence of solutions for certain Langevin equations involving Caputo fractional derivatives. Almaghamsi [24] investigated weak solutions for boundary value problems with fractional Langevin inclusions, employing the Katugampola-Caputo derivative and Pettis integrability, and utilizing the Mönch fixed point theorem along with weak noncompactness. Lim et al. [25] examined a Langevin problem involving the Weyl and Riemann-Liouville fractional derivatives, focusing on Gaussian processes and their relationship with fractional Brownian motion, thereby proving several existing results. Most recently, Torres [26] studied a Langevin equation incorporating the Riemann-Liouville fractional derivative. He combined a variational method with an iterative technique to demonstrate the existence of solutions for the problem under study.

    In this paper, we further explore a Langevin problem involving the ψ-Hilfer fractional derivative by using the study of Xie et al. [27]. It is important to point out that the presence of the third variable in the function g prevents the application of variational methods to solve this problem. So, we begin by replacing the third variable of a function g with a fixed function in an appropriate function space, and in Section 3, we employ the mountain pass theorem to establish the existence of solutions for this auxiliary problem. Following this, in Section 4 we construct a sequence of solutions for related auxiliary problems and demonstrate that this sequence converges to a solution for the original problem (1.1). It is noted that our study generalizes other works in the literature; for example, if ψ(x)=x and β=1, then we obtain the result of Toress [26]. To our knowledge, no known work in the literature utilizes the theory of [27] to problems involving fractional derivatives with respect to a function.

    In this section, we present some foundational background and theoretical concepts related to the ψ-Hilfer fractional derivative, which will be applied throughout this paper. We begin by recalling the definition of the fractional integral, as introduced by Kilbas et al. [4] and Samko et al. [28]. In this section, η and β are positive real numbers, Γ represents the Euler gamma function, and for a<b, [a,b] denotes a finite or infinite interval on the real line. Moreover, ψ is assumed to be an increasing positive function on [a,b], with a continuously differentiable derivative ψ(y)0 on (a,b).

    Definition 2.1. [4,28] Let χ be an integrable function on the interval [a,b], and let ψC1([a,b],R) be a strictly increasing function with ψ(y)0 for all y[a,b]. The fractional integrals of χ with respect to ψ, on the left and right sides, are given by:

    Iβ,ψa+χ(y):=1Γ(β)yaψ(σ)(ψ(y)ψ(σ))β1χ(σ)dσ, (2.1)

    and

    Iβ,ψbχ(y):=1Γ(β)byψ(σ)(ψ(σ)ψ(y))β1χ(σ)dσ. (2.2)

    Definition 2.2. [19,29] Let χ be a function that is integrable over the interval [a,b], and let ψC1([a,b],R) be a strictly increasing function such that ψ(y)0 for all y[a,b]. Below is the definition of the left and right ψ-Hilfer fractional derivatives of type 0β1:

    HDη,β,ψa+χ(y):=Iβ(mη),ψa+(1ψ(y)ddy)mI(1β)(mη),ψa+χ(y),

    and

    HDη,β,ψbχ(y):=Iβ(mη),ψb(1ψ(y)ddy)mI(1β)(mη),ψbχ(y),

    where m is an integer satisfying m1<ηm.

    It is important to highlight that the ψ-Hilfer fractional derivatives generalize previous concepts, including the ψ-Riemann-Liouville and ψ-Caputo fractional derivatives. Specifically, the following remark holds:

    Remark 2.3. The following statements are true:

    (i) From the ψ-Hilfer fractional derivatives, as β tends to zero, we obtain the ψ-Riemann-Liouville fractional derivatives:

    Dη,ψa+χ(y)=(1ψ(y)ddy)mImη,ψa+χ(y),

    and

    Dη,ψbχ(y)=(1ψ(y)ddy)mImη,ψbχ(y).

    (ii) As β tends to 1, the ψ-Hilfer fractional derivatives become equivalent to the ψ-Caputo fractional derivatives, defined as:

    CDη,ψa+χ(y)=Imη,ψa+(1ψ(y)ddy)mχ(y),

    and

    CDη,ψbχ(y)=Imη,ψb(1ψ(y)ddy)mχ(y).

    (iii) ψ-Hilfer fractional derivatives are directly related to ψ-Riemann-Liouville fractional derivatives. Below are the specific results:

    HDη,β,ψa+χ(y)=Iξη,ψa+Dξ,ψa+χ(y),

    and

    HDη,β,ψbχ(y)=Iξη,ψbDξ,ψbχ(y),

    where ξ=η+β(mη).

    We note that we have an analogue integration by parts formula; for more details, the interested readers can consult [30, Theorem 12].

    For 1s, Ls(a,b) denotes the set of all measurable functions χ on [a,b], such that ba|χ(σ)|sdσ<. Define the norm as

    χLs(a,b)=(ba|χ(σ)|sdσ)1s,andχ=esssupaσb|χ(σ)|.

    Remark 2.4. [13,19] Let 0<η1, s1, and q=ss1. For each χLs(a,b), the following properties hold:

    (i) The operator Iη,ψa+χ is bounded in Ls(a,b), and the following inequality holds:

    Iη,ψa+χLs(a,b)(ψ(b)ψ(a))ηΓ(η+1)χLs(a,b).

    (ii) If 1s<η<1, then Iη,ψa+χ is Hölder continuous on [a,b] with an exponent of η1s.

    (iii) If 1s<η<1, then limyaIη,ψa+χ(y)=0, meaning that Iη,ψa+χ can be continuously extended to zero at y=a. Therefore, Iη,ψa+χ is continuous on [a,b], and the following bound holds:

    Iη,ψa+χ(ψ(b)ψ(a))η1sΓ(η)((η1)q+1)1qχLs(a,b).

    To establish the variational structure for problem (1.1), we introduce the fractional derivative space \(E_{\eta, \beta, \psi} \), defined as the closure of Cc([0,T],R) under the norm:

    wEη,β,ψp=(wpLp(0,T)+0Dη,β,ψtwpLp(0,T))1p.

    The space \(E_{\eta, \psi} \) can be characterized as follows:

    Eη,β,ψp={vLp([0,T],R):Dη,β,ψ0+vLp([0,T],R),Iβ(β1);ψ0+(0)=Iβ(β1);ψT(T)=0}.

    Remark 2.5. [13,19] If 0<η1 and 0β1, then for all χEη,β,ψs, the following properties hold:

    (i) The space Eη,β,ψs is a Banach space that is both reflexive and separable.

    (ii) If 1η>1s or η>1s, we have the inequality:

    χLs(0,T)(ψ(T)ψ(0))ηΓ(η+1)Dη,β,ψ0+χLs(0,T).

    (iii) If 1s<η and q=ss1, then the following holds:

    χ(ψ(T)ψ(0))η1sΓ(η)((η1)q+1)1qDη,β,ψ0+χLs(0,T).

    Let

    E:=Eη,β,ψ2,

    which defines a Hilbert space, and from the last remark, E can be equipped with the following equivalent norm:

    χ=0Dη,β,ψtχL2(0,T).

    Furthermore, based on Remark 2.5, there exists a constant c1>0, such that for each χE, we have

    χc1χ. (2.3)

    In this section, we fix a function φ in the space E and consider the following auxiliary problem:

    (Pφ){yDν,β,ψT(0Dν,β,ψyu(y))=g(y,u(y),0Dν,β,ψyφ(y)),y(0,T),Iν(ν1);ψ0+u(0)=Iν(ν1);ψTu(T)=0.

    We assume the following conditions:

    (H1) We assume that there exist q>1, 0<δ<Γ(ν+1)(ψ(T)ψ(0))ν, and Cδ>0 such that for all (y,ξ,η)[0,T]×R×R, the following inequalities hold:

    |g(y,ξ,η)|δ|ξ|+Cδ|ξ|q,

    and

    |G(y,ξ,η)|δ2|ξ|2+Cδq+1|ξ|q+1.

    (H2) There exist σ>2, and positive constants c1 and c2, such that for all real values ξ and η, and for each y[0,T], we have

    G(y,ξ,η)c1|ξ|σc2,

    where G is the antiderivative of the function g with respect to its second variable and equals zero when evaluated at zero.

    (H3) The function g satisfies the Ambrosetti-Rabinowitz condition, which means that there exists a constant C>0 such that for all (y,η)[0,T]×R, we have:

    0<σG(y,ξ,η)ξg(y,ξ,η),for all|ξ|C.

    The first main result of this work is stated in the following theorem.

    Theorem 3.1. Under the conditions (H1)(H3), problem (Pφ) has a nontrivial solution.

    To prove the existence of solutions for problem (Pφ), we will make use of the following theorem.

    Theorem 3.2. [31] Let X be a real Banach space, and let JC1(E,R) be a functional that satisfies the Palais-Smale condition. Assume the following:

    (i) J(0)=0.

    (ii) There exist constants ρ>0 and χ>0 such that J(z)χ for all zE with z=ρ.

    (iii) There exists z1E with z1ρ such that J(z1)<0.

    Then, J has a critical value cσ. Furthermore, c can be expressed as

    c=infγΓmaxz[0,1]J(γ(z)),

    where Γ={γC([0,1],X):γ(0)=0,γ(1)=z1}.

    We recall that a functional J satisfies the Palais-Smale condition if any sequence {um}X such that J(um) is bounded and J(um)0 in X, possesses a convergent subsequence.

    The energy functional associated with problem (Pφ) is defined as:

    Lφ(u)=12T0|0Dν,β,ψsu(s)|2dsT0G(s,u(s),0Dν,β,ψsφ(s))ds,

    where G(s,ξ,η)=ξ0g(s,σ,η)dσ.

    Since the function G is continuous, then we get LφC1(E,R). Moreover, for all pairs (u,v)E2, we have:

    Lφ(u),v=T00Dν,β,ψsu(s)0Dν,β,ψsv(s)dsT0g(s,u(s),0Dν,β,ψsφ(s))v(s)ds. (3.1)

    Lemma 3.3. Under assumptions (H1)(H3), the functional Lφ satisfies the Palais-Smale condition.

    Proof. Let {uk} be a sequence in E such that

    Lφ(uk)is bounded, andLφ(uk)0ask.

    We first observe that, based on this information, there exists a constant C0>0 such that

    |Lφ(uk)|C0and|Lφ(uk),uk|C0for allkN. (3.2)

    Next, we show that the sequence {uk} is bounded. To do so, let r(1σ,12). Using assumption (H3), we can derive the necessary bounds for any kN.

    C0+rC0Lφ(uk)Lφ(uk),uk=(12r)uk2+T0(ruk(s)g(s,uk(s),0Dν,β,ψsφ(s))G(s,uk(s),0Dν,β,ψsφ(s)))ds(12r)uk2+|uk|C(ruk(s)g(s,uk(s),0Dν,β,ψsφ(s))G(s,uk(s),0Dν,β,ψsφ(s)))ds+|uk|C(ruk(s)g(s,uk(s),0Dν,β,ψsφ(s))G(s,uk(s),0Dν,β,ψsφ(s)))ds(12r)uk2+C1+(rσ1)|uk|CG(s,uk(s),0Dν,β,ψsφ(s))ds(12r)uk2+C1. (3.3)

    Since r<12, it is clear that the sequence {uk} is bounded. Moreover, since E is a reflexive space, this implies that, after possibly passing to a subsequence, there exists uE such that uk converges weakly to u in E. Additionally, due to the compact embedding, uk converges strongly to u in C([0,T]). Now, we will show that {uk} converges strongly to u in E.

    From Eq (3.1), we obtain

    Lφ(uk),uku=T00Dν,β,ψsuk(s)0Dν,β,ψs(uku)(s)dsT0g(s,uk(s),0Dν,β,ψsφ(s))(uku)(s)ds,

    and

    Lφ(u),uku=T00Dν,β,ψsu(s)0Dν,β,ψs(uku)(s)dsT0g(s,u(s),0Dν,β,ψsφ(s))(uku)(s)ds.

    So, we obtain

    Lφ(uk)Lφ(u),uku≻=uku2Ik, (3.4)

    where

    Ik=T0(g(s,uk(s),0Dν,β,ψsφ(s))g(s,u(s),0Dν,β,ψsφ(s)))(uku)(s)ds.

    From hypothesis (H2) and the fact that uk converges strongly to u in C([0,T]), we obtain

    limkIk=0. (3.5)

    Next, since Lφ(uk)0 and uku is bounded, then we obtain

    limkLφ(uk),uku≻=0.

    Moreover, from the fact that uk converges strongly to u in C([0,T])

    limkLφ(u),uku≻=0.

    Hence, one has

    limkLφ(uk)Lφ(u),uku≻=0. (3.6)

    In conclusion, by utilizing Eqs (3.4)–(3.6), we can confirm that the sequence {uk} converges strongly to u in E.

    Lemma 3.4. Under assumption (H1)(H3), if q>1, then, there exist ρ>0 and ϖ>0 such that Lφ(z)ϖ for every zE with z=ρ.

    Proof. Let zE, and δ>0. Then using Remark 2.5, hypothesis (H1), and the decreasing embedding of the Lebegue spaces, we have

    Lφ(z)=12z2T0G(s,u(s),0Dν,β,ψsz(s))ds12z2δ2zL2(0,T)Cδq+1zq+1Lq+1(0,T)12z2δ(ψ(T)ψ(0))ν2Γ(ν+1)z2TCδ(ψ(T)ψ(0))ν12(q+1)Γ(ν)(ν1)12zq+1z2(12δ(ψ(T)ψ(0))ν2Γ(ν+1)TCδ(ψ(T)ψ(0))ν12(q+1)Γ(ν)(ν1)12zq1). (3.7)

    Now, if we fix δ<Γ(ν+1)(ψ(T)ψ(0))ν and

    ρ<[(12δ(ψ(T)ψ(0))ν2Γ(ν+1))(q+1)Γ(ν)(ν1)12TCδ(ψ(T)ψ(0))ν12]1q1.

    Then, we obtain

    ϖ=ρ2(12δ(ψ(T)ψ(0))ν2Γ(ν+1)TCδ(ψ(T)ψ(0))ν12(q+1)Γ(ν)(ν1)12ρq1)>0.

    So, we can see from (3.7) that if z=ρ, then Lφ(z)>0. Thus Lemma 3.4 has been proven.

    Lemma 3.5. Under assumptions (H1)(H3), there exists z1E with z1ρ such that Lφ(z1)<0.

    Proof. Let ξ>0 and zE, then from hypothesis (H2), we obtain

    Lφ(ξz)=ξ22z2T0G(s,ξz(s),0Dν,β,ψsφ)dsξ22zc1ξσzσLσ(0,T)+c3T. (3.8)

    Since we have σ>2, then

    limξLφ(ξu)=.

    So, we can choose ξ large enough and z1=ξu so that z1ρ and Lφ(z1)<0.

    Proof of Theorem 3.1. The proof of Theorem 3.1 naturally follows from the preceding lemmas in this section. Specifically, Lemma 3.3 confirms that Lφ satisfies the Palais-Smale condition, while Lemma 3.4 ensures that condition (ii) of Theorem 3.2 is met. Furthermore, Lemma 3.5 guarantees that condition (iii) of Theorem 3.2 is also fulfilled. Finally, noting that Lφ(0)=0, we infer from Theorem 3.2 that Lφ possesses a critical point, which corresponds to a weak solution of the problem (Pφ). Additionally, Lemma 3.4 confirms that this solution is nontrivial.

    For the remainder of this paper, a solution to problem (Pφ) will be referred to as S(Pφ).

    In this part, we introduce the second primary finding of this paper, which deals with the existence of solutions for the problem denoted as (1.1). The demonstration relies on the application of the outcome established in Section 3 alongside some iterative techniques. Before revealing the main conclusion of this paper, we assume that the function g adheres to the condition outlined below:

    (H4) There exists R>0 small enough, such that for every pair (η,η1) belonging to the real numbers R, the following holds true:

    |g(s,ξ,η)g(s,ξ1,η)|α1|ξξ1|,(s,ξ,ξ1)[0,T]×[R,R]×[R,R],

    and

    |g(s,ξ,η)g(s,ξ,η1)|α2|ηη1|,(s,ξ)[0,T]×[R,R],

    where α1 and α2 are positive constants satisfying the condition:

    0<θ:=α2Γ(ν+1)(ψ(T)ψ(0))ν(Γ(ν+1))2α1(ψ(T)ψ(0))2ν<1. (4.1)

    The second result of this work is the following theorem.

    Theorem 4.1. Under the Assumptions (H1)(H4), problem (1.1) admits a nontrivial solution.

    Proof. To prove Theorem 4.1, we begin by remarking that, since the hypotheses (H1)(H3) are satisfied, then, the sequence {uk}E defined by

    {u0is a fixed function in E,uk+1=S(Puk),kN,

    is well defined, moreover, for each kN, we have

    T0|sDν,β,ψT(uk(s))|2ds=T0g(s,uk(s),0Dν,β,ψsuk1(s))uk(s)ds. (4.2)

    Let 0<δ<Γ(ν+1)(ψ(T)ψ(0))ν, then from Eq (4.2) and hypothesis (H1), we obtain

    uk2δu2L2([0,T])+Cδuq+1Lq+1([0,T])δ(ψ(T)ψ(0))νΓ(ν+1)uk2+TCδ(ψ(T)ψ(0))ν12Γ(ν)(ν1)12ukq+1.

    So, we obtain

    (1δ(ψ(T)ψ(0))νΓ(ν+1))uk2TCδ(ψ(T)ψ(0))ν12Γ(ν)(ν1)12ukq+1.

    Since q>1, then it follows that

    uk(Γ(ν)(ν1)12TCδ(ψ(T)ψ(0))ν12(1δ(ψ(T)ψ(0))νΓ(ν+1)))1q1:=M0>0. (4.3)

    On the other hand, from the characterization of the mountain pass level (see [32]), we have

    |Luk1(uk)|maxs0Luk1(sz),

    for some zE with z=1.

    Now, from the last inequality, and as in Eq (3.8), we obtain

    |Luk1(uk)|s22zc1sσzσLσ(0,T)+c2T:=f(s).

    Since f is continuous on [0,), f(0)=0, and limsf(s)=. Then we can deduce that f is upper bounded, so there exists M>0 such that |Luk1(uk)|M. Therefore, as in Eq (3.3), we obtain

    (12r)uk2+C1Luk1(uk)Luk1(uk),ukMLuk1(uk),uk. (4.4)

    Now, from the fact that uk+1 is a critical point of the functional Luk, and uk is a critical point of the functional Luk1, one has

    Luk(uk+1),uk+1uk≻=0,and Luk1(uk),uk+1uk≻=0. (4.5)

    So, by combining the last information with Eq (4.4), we can deduce the existence of M1>0, such that

    ukM1. (4.6)

    Now, by combining Eq (4.6) with Eq (4.3), we get

    0<M0ukM1. (4.7)

    So, if we choose R=c1M1, where R is given by hypothesis (H4), and c1 is given in Eq (2.3), then using Eq (4.7), we obtain

    ukc1ukc1M1=R.

    Next, from Eq (4.5), we deduce that

    Luk(uk+1)Luk1(uk),uk+1uk≻=0,

    which yields to

    uk+1uk2=T0g((s,uk+1(s),0Dv,β;ψsuk(s))(uk+1uk)dsT0g(s,uk(s),0Dv,β;ψsuk1(s)))(uk+1uk)ds.

    So, from Remark 2.5, assumption (H4), and the Hölder inequality, we obtain

    uk+1uk2=T0g((s,uk+1(s),0Dν,β;ψsuk(s))g(s,uk(s),0Dν,β;ψsuk(s)))(uk+1uk)ds+T0g((s,uk(s),0Dν,β;ψsuk(s))g(s,uk(s),0Dν,β;ψsuk1(s)))(uk+1uk)dsα1uk+1un2L2(0,T)+α2T0|0Dν,β;ψs(uk(s)uk1(s))|(uk+1uk)dsα1(ψ(T)ψ(0))2ν(Γ(ν+1))2uk+1uk2+α2ukuk1uk+1ukL2(0,T)α1(ψ(T)ψ(0))2ν(Γ(ν+1))2uk+1uk2+α2(ψ(T)ψ(0))νΓ(ν+1)ukuk1uk+1uk.

    Hence, we deduce that

    uk+1ukθukuk1,

    where θ is given by Eq (4.1).

    Based on the previous inequality, we can infer that the sequence {uk} is a Cauchy sequence in the Banach space E. Consequently, there is an element uE to which the sequence {un} converges in E. To conclude the proof, it is enough to demonstrate that u solves problem (1.1). To achieve this, it is necessary to show that as k approaches infinity, we get

    T0g(s,uk+1(s),0Dν,β;ψsuk(s))v(s)dsT0g(s,u(s),0Dν,β;ψsu(s))v(s)ds. (4.8)

    Again, from Remark 2.5, assumption (H4), and the Hölder inequality, we conclude that

    T0(g(s,uk+1(s),0Dν,β;ψsuk(s))g(s,u(s),0Dν,β;ψsu(s)))v(s)ds=T0(g(s,uk+1(s),0Dν,β;ψsuk(s))g(s,u(s),0Dν,β;ψsuk(s)))v(s)ds+T0(g(s,u(s),0Dν,β;ψsuk(s))g(s,u(s),0Dν,β;ψsu(s)))v(s)dsα1uk+1uL2(0,T)vL2(0,T)+α2ukuvL2(0,T)vL2(0,T)(α1(ψ(T)ψ(0))νΓ(ν+1)uk+1u+α2uku).

    Hence, we deduce that Eq (4.8) holds, and consequently the proof of Theorem 4.1 is completed.

    In this section, we present the following illustrative example:

    (P){HD610,121(HD610,120+u(y))=g(y,u(y),HD610,120+u(y)),y(0,1),I0.24,y0+u(0)=I0.24,y1u(12)=0,

    where HD6101 and HD610,120+ are the left and right Hilfer derivatives of order 610 and type 12, that is, ψ(x)=x, ν=610,T=1, β=12, and

    g(y,ξ,η)=(c1c2sinμ)|ξ|ξ,

    with c1>c2 are positive constants that satisfy an appropriate condition fixed later.

    A simple calculation shows that, for any δ>0 small enough, we have

    |g(y,ξ,η)|(c1+c2)|ξ|2δ|ξ|+(c1+c2)|ξ|2.

    This means that the first inequality in hypothesis (H1) is satisfied with q=2>1. On the other hand, we have

    |G(y,ξ,η)|c1+c23|ξ|3δ2|ξ|2+c1+c23|ξ|3.

    So, hypothesis (H1) holds.

    Now, since 1sinμ1, then for any c>0, we obtain

    G(y,ξ,η)c1c23|ξ|3c,

    which means that hypothesis (H1) is also satisfied with σ=3>2.

    It is not difficult to see that

    ξg(y,ξ,η)=3G(y,ξ,η)3G(y,ξ,η),

    so hypothesis (H3) is satisfied.

    Next, we prove that hypothesis (H4) holds. For this, we recall from [33, Lemme 2.1] the following elementary inequality:

    ||a|p2a|b|p2b|C(|a|+|b|)p2|ab|,p>1, (5.1)

    provided that |a|+|b|0.

    Now, we applied equation for p=2, a=ξ and b=ξ1, we get

    ||ξ|ξ|ξ1|ξ1|C|ξξ1|.

    This implies that

    |g(y,ξ,η)g(y,ξ1,η)|C(c1+c2)|ξξ1|.

    on the other hand, we have

    |g(y,ξ,η)g(y,ξ,η1)|c2ξ2|sinηsinη1|c2R2|ηη1|.

    To finish, it suffices to prove that Eq (4.1) holds. From the above inequalities, we can see that α1=C(c1+c2) and α2=c2R2. Since ψ(1)=1 and ψ(0)=o, then we obtain

    θ=c2R2Γ(85)(Γ(85))2C(c1+c2).

    If we choose c1+c2<(Γ(85))2C and

    0<R<((Γ(85))2C(c1+c2)c2Γ(85))12,

    then, all hypotheses of Theorem 4.1 hold. Hence, problem (P) admits a nontrivial solution.

    In this work, we investigated the existence of solutions for a nonvariational problem involving the ψ-Hilfer fractional derivative. Precisely, we fixed a function in the functional space to transform a nonvariational problem into a variational auxiliary problem; after that, we used a mountain pass theorem to prove that the auxiliary problem admits a nontrivial solution. Later, we fix a function u0E, and we find a function u1 as a solution for the auxiliary problem associated with u0. by the same way, we determine a function u2 as a solution for the auxiliary problem associated with u1, so a sequence {uk} is constructed. Finally, we proved that this sequence is convergent and its limit is a nontrivial solution for our studied problem. This idea was first introduced by Xie et al. [27] and used later by Torres [26] for the particular case when ψ(x)=x and β=1. We hope to use this idea for a capillarity problem involving the ψ-Hilfer derivative and variable exponents, which will also be submitted to Aims Mathematics.

    Lamya Almaghamsi: Conceptualization, writing-review & editing, funding acquisition; Aeshah Alghamdi: Conceptualization, writing-review & editing; Abdeljabbar Ghanmi: Conceptualization; Abdeljabbar Ghanmi: Resources. All authors have read and approved the final version of the manuscript for publication.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors declare that they have no competing interests.



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