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Some estimates of virtual element methods for fourth order problems

  • In this paper, we employ the techniques developed for second order operators to obtain the new estimates of Virtual Element Method for fourth order operators. The analysis bases on elements with proper shape regularity. Estimates for projection and interpolation operators are derived. Also, the biharmonic problem is solved by Virtual Element Method, optimal error estimates were obtained. Our choice of the discrete form for the right hand side function relaxes the regularity requirement in previous work and the error estimates between exact solutions and the computable numerical solutions were proved.

    Citation: Qingguang Guan. Some estimates of virtual element methods for fourth order problems[J]. Electronic Research Archive, 2021, 29(6): 4099-4118. doi: 10.3934/era.2021074

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  • In this paper, we employ the techniques developed for second order operators to obtain the new estimates of Virtual Element Method for fourth order operators. The analysis bases on elements with proper shape regularity. Estimates for projection and interpolation operators are derived. Also, the biharmonic problem is solved by Virtual Element Method, optimal error estimates were obtained. Our choice of the discrete form for the right hand side function relaxes the regularity requirement in previous work and the error estimates between exact solutions and the computable numerical solutions were proved.



    Virtual Element methods are designed on polygonal/polyhedral meshes, see [2]–[5]. It gives us the flexibility to use a wide range of meshes which is a great advantage especially in computational mechanics. And the computation cost is less than weak Galerkin finite element method, which can also employ general shape elements, see [17]–[14]. Virtual Element Methods for second order problems are well studied in [2]–[5], also the stability and error analysis for these methods are obtained. New techniques based on the shape regularity and discrete norm for virtual element functions are developed in [7]. Virtual Element Methods for fourth order problems are analyzed in [10,11], however, the stability and error analysis are not completed.

    The motivations for this paper are: firstly, apply the techniques in [7] to higher order problems, getting the basic estimates; secondly, to improve the error analysis for biharmonic equation. If we modify the virtual element method slightly then the regularity requirement for right hand side function f can be relaxed; thirdly, since the numerical solutions uh of virtual element methods can't be computed directly, to overcome this drawback, we present two ways to get the approximations of uh preserving the same convergence rate, and the computation of the approximations is much more efficient.

    The paper is organized as follows: In Section 2, 2.1–2.3, the definition of two dimensional virtual element with the shape regularity is given. The projection in 2.2 is the same as in [11]. Compared with the definition of local virtual element space in [10,11], our method has the right hand side polynomial qv(=Δ2v)Pk(D) not Pk4(D) or Pk2(D). This new definition provides more degrees of freedom which is necessary to denote the L2 projection from virtual element function space to Pk(D). In Section 2.4, a semi-norm ||||||k,D similar as in [7] is presented. The local estimates for the projections ΠΔk,D and Π0k,D are obtained. In Section 2.5–2.6, a piecewise C1 polynomial w depending only on the values on D is constructed and the local interpolation error is proved. In section 3, we get the error estimates between uh, its approximations and the exact solution for biharmonic equation. In Section 4, we draw the conclusions.

    Let D be a polygon in R2 with diameter hD. For a nonnegative integer k, Pk is the space of polynomials of degree k and Pk={0}, k1. The space Pk(D) is the restriction of Pk to D.

    The index (r,s) related to the degree of k2 is defined by

    rmax{3,k}, s=k1, m=k4.

    A natural choice is r=max{3,k}, however, r can be greater. The set of edges of D is denoted by ED and Pk(e) is the restriction of Pk to eED. Then we define Pr,s(D) as

    Pr,s(D)={v|ePr(e), vn|ePs(e),eED, and v,vC(D), values of v,v at each vertex of D are given degrees of freedom}.

    Here the shape regularity assumptions are the same as in [7]. Let D be the polygon with diameter hD. Assume that

    |e|ρhDfor any edge e of D, ρ(0,1), (1)

    and

    D is star shaped with respect to a disc B with radius = ρhD. (2)

    The center of B is the star center of D.

    The polygon in Figure 1 is an example of D, we denote by TD the corresponding triangulation of D. We will use the notation AB to represent the inequality A(constant)B, where the positive constant depends only on k and the parameter ρ, and it increases with k and 1/ρ. The notation AB is equivalent to AB and AB.

    Figure 1.  A subdomain.

    Lemma 2.1. [6] Bramble-Hilbert Estimates. Conditions (1)-(2) imply that we have the following estimates:

    infqPl|ξq|Hm(D)hl+1mD|ξ|Hl+1(D), (3)

    for any ξHl+1(D), l=0,,k, and 0ml.

    Details can be found in [8], Lemma 4.3.8.

    Lemma 2.2. [1] Sobolev Imbedding Theorem 4.12. From (1)-(2), we have:

    ξCj(D)2+jl=0hl1D|ξ|Hl(D), ξH2+j(D), j=1,2. (4)

    Lemma 2.3. [16] The Generalized Poincarˊe Inequality. From (1)-(2), suppose hD=1, we have:

    ξ2H2(D)|ξ|2H2(D)+2i=1(Dξxi dx)2+(Dξ dx)2,ξH2(D). (5)

    Proof. The proof is similar as the one in [16], Section 1.1.6.

    By the generalized poincarˊe inequality from Lemma 2.3, the Sobolev space H2(D) is a Hilbert space with the inner product ((())) denoted as:

    (((ξ,v)))=((ξ,v))D+2i=1(Dξxi dx)(Dvxi dx)+(Dξ dx)(Dv dx), (6)

    where

    ((ξ,v))D=Di,j2ξxixj2vxixj dx, i=1,2;j=1,2,

    for any ξ,vH2(D).

    The discrete operator ΠΔk,D:H2(D)Pk(D) is denoted with respect to ((())) as:

    (((ΠΔk,Dξ,q)))D=(((ξ,q)))D, qPk(D), (7)

    in (7), let q=1, we have (8), let q=x then q=y, we have (9), with the help of (8) and (9), the definition of ΠΔk,D in (7) can be simplified as (10),

    DΠΔk,Dξ ds=Dξ ds. (8)
    DΠΔk,Dξ dx=Dξ ds, (9)
    ((ΠΔk,Dξ,q))D=((ξ,q))D, ξH2(D), qPk(D), (10)

    from now on we will use (8)-(10) instead of (7).

    On the domain D, with boundary D, we denote by n=(n1,n2) the outward unit normal vector to D, and by t=(t1,t2) the unit tangent vector in the counterclockwise ordering of the boundary. For uH2(D), we define

    D2u=(u11,u22,u12,u21)=(2ux21,2ux22,2ux1x2,2ux2x1).

    We then denote by Unn(D2u):=i,juijninj the normal bending moment, by Unt(D2u):=i,juijnitj the twisting moment, and by Qn(D2u):=i,juijxinj the normal shear force, and UΔ(D2u)=Δ2u.

    After applying integration by parts twice, we have

    ((u,v))D=DUΔ(D2u)v dx+DUnn(D2u)vn dsD(Qn(D2u)+Unt(D2u)t)v ds. (11)

    Then, for k2, the local VEM space Qk(D)H2(D) is defined as: vH2(D) belongs to Qk(D) if and only if (i) v|D and trace of vn on D belongs to Pr,s(D), then (ii) there exists a polynomial qv(=Δ2v)Pk(D) such that

    ((v,w))D=(qv,w),wH20(D), (12)

    and (iii)

    Π0k,DvΠΔk,DvPk4(D), (13)

    where Π0k,D is the projection from L2(D) onto Pk(D).

    Remark 1. It's obvious that Pk(D) is a subspace of Qk(D). From (13), we have Π0k,Dv=ΠΔk,Dv, k=2,3.

    The choice (ii) can be replaced by qv(=Δ2v)Pk2(D) in [11], also Lemma 2.9–Lemma 2.15, and Corollary 1–Corollary 2 are valid. The reason we chose qvPk(D) is that it helps to get the same error estimate with less smooth right hand side f. For k=2,3, we only require fL2(Ω), while in [11], fH1(Ω) for k=2, and fH2(Ω) for k=3.

    For completeness, we recall the definition for degrees of freedom in [10], employ the following notation: for i a nonnegative integer, e an edge with midpoint xe, length he, the set of i+1 normalized monomials is denoted by Mei

    Mei:={1,xxehe,(xxehe)2,,(xxehe)i}.

    And for domain D with diameter hD and barycenter xD, the set of (i+1)(i+2)/2 normalized monomials is defined by MDi

    MDi:={(xxDhD)α,|α|i},

    where α is a nonnegative multiindex α=(α1,α2), |α|=α1+α2 and xα=xα11xα22. In D the degrees of freedom are denoted as:

     The values v at each vertex of D. (14)
     The values v at each vertex of D. (15)
     For r>3, the moments 1heeq(s)v ds, qMer4, eD. (16)
     For s>1, the moments 1heeq(s)vn ds, qMes2, eD. (17)
     For m0, the moments 1|D|Dq(x)v(x) dx, qMDm. (18)

    Lemma 2.4. Given any gPr,s(D) and fPk(D), there exists a unique function vH2(D) such that (i) v=g, vn=gn on D and (ii)

    DD2vD2w dx=Dfw dx,wH20(D).

    Proof. Similar as in [7], let ˜gH2(D) be a C1, Pk piece-wise polynomial constructed in Section 2.6.1, such that v=g, vn=gn on D. Then the unique vH2(D) is given by ϕ+˜g, where ϕH20(D) is defined by

    DD2ϕD2w dx=Dfw dxDD2˜gD2w dx,wH20(D).

    The proof is completed.

    Lemma 2.5. We have (i) dim Qk(D) = dim Pr,s(D) +dim Pm(D), and (ii) vQk(D) is uniquely determined by v|D,vn|D and Π0k4,Dv.

    Proof. Following [7] and [10], let

    QkD:={vH2(D),v|D,vn|DPr,s(D) and Δ2vPk(D)}

    The linear map v(v|D,vn|D,Δ2v) from QkD to Pr,s(D)×Pk(D) is an isomorphism by Lemma 2.4.

    The linear map v(v|D,vn|D,Π0k4,Dv+(Π0k,DΠ0k4,D)(vΠΔk,Dv)) from Qk(D) to Pr,s(D)×Pk(D) is also an isomorphism. Suppose v null space, then Π0k4,Dv=0,

    v|D=0 and vn|D=0.

    With (10)-(8) and (11), we have ΠΔk,Dv=0, so that by (13),

    0=Π0k4,Dv=Π0k,DvPk4(D).

    In (12), let w=vQk(D), then we have

    |v|2H2(D)=0v=0.

    This completes the proof.

    Lemma 2.6. Discrete Estimates. From Conditions (1)-(2), and the equivalence of norms on finite dimensional vector spaces, for any uPk, we have the following estimates:

    D2uL2(D)uL2(D)andutL2(e)h1/2euL2(e),
    h2DUΔ(D2u)L2(D)+Unn(D2u)L2(D)+h3/2DQn(D2u)+Unt(D2u)tL2(D)D2uL2(D).

    The semi-norm ||||||k,D for ξH2(D) is defined by

    |||ξ|||2k,D=Π0k4,Dξ2L2(D)+hDeEDΠ0r,eξ2L2(e)+h3DeED,i=1,2Π0r1,eξxi2L2(e). (19)

    There is an obvious stability estimate from (10)

    |ΠΔk,Dξ|H2(D)|ξ|H2(D), ξH2(D). (20)

    We define the kernel of operator ΠΔk,D as:

    KerΠΔk,D:={vQk(D):ΠΔk,Dv=0}.

    And for any vQk(D), we have

    eEDΠ0r,ev2L2(e)=v2L2(D),eEDΠ0r1,evxi2L2(e)=vxi2L2(D).

    Lemma 2.7. For any vQk(D), we have the equivalence of norms:

    |||v|||k,D=Π0k4,Dξ2L2(D)+hDv2L2(D)+h3Di=1,2vxi2L2(D)Π0k4,Dξ2L2(D)+hDv2L2(D)+h3Dvn2L2(D).

    Proof. Suppose hD=1, by the discrete estimates from Lemma 2.6, we have

    vtL2(D)vL2(D),

    and

    vt2L2(D)+vn2L2(D)i=1,2vxi2L2(D),

    so that the equivalence is obtained.

    Lemma 2.8. For any pPk4, k2, there exists qPk, such that Δ2q=p and

    qL2(D)pL2(D).

    Proof. From [7], we know that Δ maps Pk to Pk2, so that Δ2=ΔΔ maps Pk to Pk4. Then there exists an operator (Δ2):Pk4Pk such that Δ2(Δ2) is the identity operator on Pk4. We define the norm of p as

    p(Δ2):=inf(Δ2)pPk(Δ2)pL2(D).

    Since we have

    q=i,j=0;i+jkcijxi1xj2  and  Δ2q=p,

    the minimization problem

    p(Δ2)=infci,jqL2(D),

    is solvable. So, there exists q=(Δ2)p such that

    qL2(D)=p(Δ2).

    By the equivalence of norms on finite dimensional vector space, we have

    p(Δ2)pL2(D),

    then the result is obtained.

    Lemma 2.9. For any vKerΠΔk,D, we have

    |||v|||2k,DhDv2L2(D)+h3Dvn2L2(D).

    Proof. Suppose hD=1. For k<4, Π0k4,Dv=0, the equivalence is trivial. For k4, let vKerΠΔk,D, by (10), (11), and using the same p, q in Lemma 2.8, we have

    Dv(Δ2q) dx=D(Qn(D2q)+Unt(D2q)t)v dsDUnn(D2q)vn ds. (21)

    By lemma 2.6, we have

    Qn(D2q)+Unt(D2q)tL2(D)D2qL2(D)qL2(D)

    and Unn(D2q)L2(D)qL2(D). Then, by Lemma 2.8,

    |Dvp dx|(vL2(D)+vnL2(D))qL2(D),

    so that

    Π0k4,DvL2(D)=maxpPk4|D(Π0k4,Dv)(p/pL2(D)) dx|vL2(D)+vnL2(D),

    which means

    Π0k4,Dv2L2(D)v2L2(D)+vn2L2(D),

    with Lemma 2.7, we get the result.

    Remark 2. Same as in [7], we have

    |||v|||2k,Dh3Dvt2L2(D)+h3Dvn2L2(D),vKerΠΔk,D,

    where /t denotes a tangential derivative along D.

    There is also a stability estimate for ΠΔk,Dξ in H1(D) norm in terms of the semi-norm ||||||k,D.

    Lemma 2.10. We have

    ΠΔk,DξL2(D)+hD|ΠΔk,Dξ|H1(D)+h2D|ΠΔk,Dξ|H2(D)|||ξ|||k,D, ξH2(D). (22)

    Proof. Suppose u=ΠΔk,Dξ and hD=1, by (10), (11), we have

    |ΠΔk,Dξ|2H2(D)=((ΠΔk,Dξ,ξ))D=DUΔ(D2(ΠΔk,Dξ))ξ dx+DUnn(D2(ΠΔk,Dξ))ξn dsD(Qn(D2u(ΠΔk,Dξ))+Unt(D2(ΠΔk,Dξ))t)ξ ds, (23)

    then, by Cauchy-Schwarz inequality, Lemma 2.6 and (19), we have

    |ΠΔk,Dξ|2H2(D)|ΠΔk,Dξ|H2(D)|||ξ|||k,D|||ξ|||2k,D. (24)

    By (8)-(9), and Lemma 2.3, we have

    ΠΔk,Dξ2H2(D)|ΠΔk,Dξ|2H2(D)+2i=1(DΠΔk,Dξxi ds)2+(DΠΔk,Dξ ds)2 (25)

    also we have

    DΠΔk,Dξxi ds=Dξxi ds
    |Dξxi ds|eED|eΠ00,eξxi ds|(eEDΠ0r1,eξxi2L2(e))1/2 (26)

    Similarly,

    (DΠΔk,Dξ ds)2eEDΠ0r,eξ2L2(e). (27)

    From (23)-(27), the following inequality is valid

    ΠΔk,DξH2(D)|||ξ|||. (28)

    The proof is completed.

    Lemma 2.11. For any ξH2(D), we have

    |||ξ|||k,DξL2(D)+hD|ξ|H1(D)+h2D|ξ|H2(D), (29)

    and there exists ˉξP1, such that

    |||ξˉξ|||k,Dh2D|ξ|H2(D), (30)

    where

    Dˉξ dx=Dξ dx,
    Dˉξ dx=Dξ dx.

    Proof. Assume hD = 1, then by trace theorem

    |||ξ|||k,DξL2(D)+ξL2(D)+i=1,2ξxiL2(D)ξL2(D)+|ξ|H1(D)+|ξ|H2(D).

    So that we have (29), and by Lemma 2.3

    |||ξˉξ|||2k,Dξˉξ2H2(D)|ξ|2H2(D)+2i=1(D(ξˉξ)xi dx)2+(Dξˉξ dx)2

    with the definition of ˉξ, we arrived at

    |||ξˉξ|||k,D|ξ|H2(D).

    The proof is completed.

    Corollary 1. We have

    ξΠΔk,DξL2(D)hl+1D|ξ|Hl+1(D),ξHl+1(D), 1lk, (31)
    |ξΠΔk,Dξ|H1(D)hlD|ξ|Hl+1(D),ξHl+1(D), 1lk, (32)
    |ξΠΔk,Dξ|H2(D)hl1D|ξ|Hl+1(D),ξHl+1(D), 1lk. (33)

    Proof. From Lemma 2.1, Lemma 2.10, and Lemma 2.11, for any qPl, ξHl+1(D) we have

    ξΠΔk,DξL2(D)ξqL2(D)+ΠΔk,D(qξ)L2(D)hl+1D|ξ|Hl+1(D),

    so as the H1 and H2 error estimates.

    For the L2 operator Π0k,D, from [7], we have

    Π0k,DξL2(D)ξL2(D),|Π0k,Dξ|H1(D)|ξ|H1(D),ξH1(D), (34)

    and

    |ξΠ0k,Dξ|H1(D)hlD|ξ|Hl+1(D),ξHl+1(D), 1lk. (35)

    Lemma 2.12. The estimates of Π0k,D satisfy

    |Π0k,Dξ|H2(D)|ξ|H2(D),ξH2(D), (36)
    |ξΠ0k,Dξ|H2(D)hl1D|ξ|Hl+1(D),ξHl+1(D), 1lk. (37)

    Proof. Here, suppose ξH2(D), then by (20), (32), (35) and the inverse inequality, we have

    |Π0k,Dξ|H2(D)|Π0k,DξΠΔk,Dξ|H2(D)+|ΠΔk,Dξ|H2(D)h1D|Π0k,Dξξ+ξΠΔk,Dξ|H1(D)+|ξ|H2(D)|ξ|H2(D)

    which completes the proof.

    Lemma 2.13. The following inequality is valid

    |v|H2(D)|ξ|H2(D), (38)

    for any vQk(D) and ξH2(D) such that ξ=v on D, ξn=vn on D, and Π0k,D(ξv)=0.

    Proof. In (11), let u be v, v be ξv, the second and third terms at right hand side can be eliminated. Also ξ satisfies Π0k,D(ξv)=0, and UΔ(D2v)Pk(D) so that ((v,ξv))D=0. Then by (10) and (11), we have

    ((v,ξv))D=((v,ξ))D|v|2H2(D)=0

    And hence,

    |ξ|2H2(D)=|ξv|2H2(D)+|v|2H2(D),

    which means

    |v|H2(D)|ξ|H2(D).

    So the proof is completed. Next, we will consider the relation between |v|H2(D) and |||v|||k,D, vQk(D).

    The degree of freedom of vQk(D) is defined in [10], from (4.7)–(4.11). For k2, we will employ the triangulation TD to define a piecewise polynomial w which has the same boundary conditions as v. On each internal triangle, we employ a Pr macroelement, which is defined in [12], Section 1. Suppose k=2,3, in Figure 2, on each internal triangle, the function is defined by P3 macroelement as in Figure 3. All degrees of freedom within D are 0.

    Figure 2.  Local d.o.f. for the lowest-order element: k=2, (r,s,m)=(3,1,2) (left), and next to the lowest element: k=3, (r,s,m)=(3,2,1) (right).
    Figure 3.  P3 macroelement.

    From the definition of w, we have

    w2L2(D)h2D|w|2H2(D)hDw2L2(D)+h3Dwn2L2(D)=hDv2L2(D)+h3Dvn2L2(D). (39)

    Lemma 2.14.

    |v|H2(D)h2D|||v|||k,D, vQk(D).

    Proof. Following [7], it suffices to prove when hD=1. Let ϕ be a smooth function supported on the disc B with radius ρ, such that

    Dϕ dx=1.

    By the equivalence of norms on finite dimensional spaces, we have

    pL2(D)Dϕp2 dx, pPk.

    Let wH2(D) be the piecewise polynomial constructed in Section 2.6.1, and let ξ=w+pϕ for pPk such that

    D(ξv)q dx=0, qPk,

    or equivalently

    Dpqϕ dx=D(vw)q dx=D(Π0k,Dvw)q dx, qPk. (40)

    Let q=p in (40), then

    pL2(D)Π0k,DvwL2(D)Π0k,DvL2(D)+wL2(D),

    and by Lemma 2.10,

    Π0k,Dv2L2(D)=Π0k4,Dv2L2(D)+(Π0k,DΠ0k4,D)v2L2(D)Π0k4,Dv2L2(D)+ΠΔk,Dv2L2(D)Π0k4,Dv2L2(D)+v2L2(D)+vn2L2(D).

    From (39), we have

    p2L2(D)Π0k4,Dv2L2(D)+v2L2(D)+vn2L2(D). (41)

    Also, by Lemma 2.13,

    |v|H2(D)|ξ|H2(D).

    By (39) and (41),

    |ξ|2H2(D)|w|2H2(D)+|pϕ|2H2(D)Π0k4,Dv2L2(D)+v2L2(D)+vn2L2(D).

    Then, vQk(D), we have

    |v|2H2(D)Π0k4,Dv2L2(D)+v2L2(D)+vn2L2(D).

    By Lemma 2.7, we arrived at the estimate.

    Corollary 2. For any vQk(D),

    vL2(D)+hD|v|H1(D)+h2D|v|H2(D)|||v|||k,D.

    Proof. From Lemma 2.10, Corollary 1 and Lemma 2.14, we have

    vL2(D)vΠΔk,DvL2(D)+ΠΔk,DvL2(D)h2D|v|H2(D)+|||v|||k,D,hD|v|H1(D)hD|vΠΔk,Dv|H1(D)+hD|ΠΔk,Dv|H1(D)h2D|v|H2(D)+|||v|||k,D.

    The proof is completed.

    The interpolation operator Ik,D:H3(D)Qk(D) is defined by the conditions that ξ and Ik,Dξ have the same value for each degree of freedom of Ik,Dξ. It is clear that

    Ik,Dξ=ξ,ξQk(D) or ξPk(D).

    Lemma 2.15. The interpolation errors are listed below, ξHl+1(D), 1lk, we have

    ξIk,DξL2(D)+ξΠΔk,DIk,DξL2(D)hl+1D|ξ|Hl+1(D), (42)
    |ξIk,Dξ|H1(D)+|ξΠΔk,DIk,Dξ|H1(D)hlD|ξ|Hl+1(D), (43)
    |ξIk,Dξ|H2(D)+|ξΠΔk,DIk,Dξ|H2(D)hl1D|ξ|Hl+1(D). (44)

    Proof. Suppose hD=1, by Trace theorem, Lemma 2.2, Lemma 2.10 and Corollary 2, we have

    Ik,DξL2(D)+ΠΔk,DIk,DξL2(D)|||Ik,Dξ|||k,DξHl+1(D),|Ik,Dξ|H1(D)+|ΠΔk,DIk,Dξ|H1(D)|||Ik,Dξ|||k,DξHl+1(D),|Ik,Dξ|H2(D)+|ΠΔk,DIk,Dξ|H2(D)|||Ik,Dξ|||k,DξHl+1(D).

    The results follow from Lemma 2.1, and Ik,Dq=q,qPl.

    Let Ω be a bounded polygonal domain in R2, fL2(Ω), the biharmonic equation is

    { Δ2u=f, u|Ω=0, un|Ω=0. (45)

    The variational formulation of (45) is finding uH20(Ω), such that

    a(u,v)=(f,v), vH20(Ω),

    where

    a(u,v)=((u,v))Ω=ΩD2uD2v dx.

    Remark 3. For u,vH20(Ω), we also have a(u,v)=ΩΔuΔv dx. However, ((u,v))D, where D is a sub-domain of Ω and DΔuΔv dx are not equivalent.

    In following sections, we will use virtual element method to solve (45).

    Let be a conforming partition of by polygonal subdomains, i.e., the intersection of two distinct subdomains is either empty, common vertices or common edges. We assume that all the polygons satisfy the shape regularity assumptions in Section 2.1.

    We take the virtual element space to be and denote by the space of (discontinuous) piecewise polynomials of degree with respect to . The operators are defined in terms of their local counterparts:

    (46)
    (47)
    (48)

    Also, the semi-norm on is defined as

    (49)

    so that for and

    The local estimates: Corollary 1, (34)-(35), Lemma 2.12 and Lemma 2.15 immediately imply the following global results, where .

    Corollary 3. The global error estimates are listed below, we have

    (50)
    (51)
    (52)

    where the norm .

    Our goal is to find , which satisfies

    (53)

    where is an operator from to , and

    (54)
    (55)
    (56)

    for . If we have

    so that can be computed explicitly with the degrees of freedom of .

    The systems of virtual element method are equivalent if the bilinear form satisfies

    From Lemma 2.9 and Remark 2, we can take

    (57)
    (58)

    for .

    We can show the well-posedness by the following Lemmas.

    Lemma 3.1. For any , we have

    Proof. By (10)-(8) and Lemma 2.11, let , we have , and

    Lemma 3.2. For any , we have

    Proof. For any we have and

    with Lemma 2.14 and Lemma 3.1, we have the equivalence.

    Remark 4. By Lemma 3.1, for any , we have

    Then by Lemma 3.2, as in [7], we have

    (59)

    which means problem (53) is uniquely solvable.

    Here, we chose as

    (60)

    The following result can be used for error analysis in norm. Define , and the indices as

    (61)

    Lemma 3.3. With (61), we have

    (62)

    Proof. For , we define so that with Corollary 3, we have

    For , with Lemma 2.1 and Corollary 3, we have

    Lemma 3.4. With (61), we have

    (63)

    for any And

    (64)

    for any

    Proof. Follow the proof in Lemma 3.3 with Lemma 2.12 and Lemma 2.15. For , , we have

    then with Corollary 3, we can get (63), so as and .

    Firstly, the error estimate in norm for is given in Theorem 3.5.

    Theorem 3.5. With (61), we have

    Suppose then

    Proof. Similar as in [7], for any given , from (59), we have

    and by (53),

    Then from (54) to (56), by (33), (44), we have

    with Lemma 3.3, Remark 4 or Lemma 3.1 and Corollary 3, the estimate is obtained.

    We suppose is also convex and start with a consistency result.

    Lemma 3.6. Suppose and is defined in (61), then

    (65)

    for any And

    (66)

    for any .

    Proof. Similar as in [7], we have

    Then by Lemma 3.4, Corollary 3, and Theorem 3.5, we get the estimate.

    From the regularity results of (45), see [13], we have

    (67)
    (68)

    Theorem 3.7. Suppose then

    (69)

    where is defined in (61).

    Proof. Using the duality arguments and (65), let and be the solution of (45), then we get

    by (67), we have , then the result is obtained.

    Theorem 3.8. Suppose then

    (70)
    (71)

    where is defined in (61).

    Proof. For by Theorem 3.7 and Poincar inequality, (70) is obtained. For , using the duality arguments and (66), let and be the solution of (45), then we get

    by (68), we have , then the result is obtained.

    We also have an error estimate for the computable .

    Corollary 4. Suppose then

    Proof. By (20), Theorem 3.5, Corollary 3, and

    the estimate is obtained.

    Corollary 5. Suppose then

    where is defined in (61).

    Proof. By Corollary 1, Corollary 3, Theorem 3.7, Lemma 2.10 and

    Suppose and is defined as in Lemma 2.11, the second term is estimated as

    so that

    sum them up then the estimate is obtained.

    Corollary 6. Suppose then

    (72)
    (73)

    where is defined in (61).

    Proof. By Corollary 1, Corollary 3, Theorem 3.7, Theorem 3.8, Lemma 2.10 and

    From Lemma 2.11, the second term is estimated as

    sum them up then, the estimate is obtained.

    Since can be computed explicitly, we can also get the similar error estimates between and .

    Corollary 7. Suppose then

    Proof. By Lemma 2.12, Theorem 3.5, and

    the estimate is obtained.

    Corollary 8. Suppose then

    where is defined in (61).

    Proof. By (34), (35), Theorem 3.7, and

    for the second term, we have

    sum them up then the estimate is obtained.

    Corollary 9. Suppose then

    (74)
    (75)

    where is defined in (61).

    Proof. By Theorem 3.8, and

    the second term is estimated as

    so the results are obtained.

    We have extended the works done in [7] to forth order problems in two dimension. Similar basic estimates for local projections , , and the improved error analysis of modified virtual element method for biharmonic equation are obtained. The computable piecewise polynomials and are more efficient to use in practice.

    We can replace (9) by (76)

    (76)

    To compute (76), we have

    (77)

    For , can replace (8) by (78)

    (78)

    And the replacements attain same estimates for projections and error analysis.

    We would like to thank anonymous reviewers for their valuable comments and suggestions. Also we are grateful for the editors' patience while handling this paper.



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