Research article

On irregularity descriptors of derived graphs

  • Received: 23 March 2020 Accepted: 20 April 2020 Published: 28 April 2020
  • MSC : 05C07, 05C09, 05C92

  • Topological indices are molecular structural descriptors which computationally and theoretically describe the natures of the underlying connectivity of nanomaterials and chemical compounds, and hence they provide quicker methods to examine their activities and properties. Irregularity indices are mainly used to characterize the topological structures of irregular graphs. Graph irregularity studies are useful not only for quantitative structure-activity relationship (QSAR) and quantitative structure-property relationship (QSPR) studies, but also for predicting their various physical and chemical properties, including toxicity, resistance, melting and boiling points, the enthalpy of evaporation and entropy. In this article, we establish the expressions for the irregularity indices named as the variance of vertex degrees, σ irregularity index, and the discrepancy index of subdivision graph, vertex-semi total graph, edge-semi total graph, total graph, line graph, paraline graph, double graph, strong double graph and extended double cover of a graph.

    Citation: Wei Gao, Zahid Iqbal, Shehnaz Akhter, Muhammad Ishaq, Adnan Aslam. On irregularity descriptors of derived graphs[J]. AIMS Mathematics, 2020, 5(5): 4085-4107. doi: 10.3934/math.2020262

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  • Topological indices are molecular structural descriptors which computationally and theoretically describe the natures of the underlying connectivity of nanomaterials and chemical compounds, and hence they provide quicker methods to examine their activities and properties. Irregularity indices are mainly used to characterize the topological structures of irregular graphs. Graph irregularity studies are useful not only for quantitative structure-activity relationship (QSAR) and quantitative structure-property relationship (QSPR) studies, but also for predicting their various physical and chemical properties, including toxicity, resistance, melting and boiling points, the enthalpy of evaporation and entropy. In this article, we establish the expressions for the irregularity indices named as the variance of vertex degrees, σ irregularity index, and the discrepancy index of subdivision graph, vertex-semi total graph, edge-semi total graph, total graph, line graph, paraline graph, double graph, strong double graph and extended double cover of a graph.


    In the last few decades, an outstanding advancement has been witnessed in nonlinear sciences and engineering fields. Many scientists showed keen interest in finding the exact and numerical solutions for the nonlinear PDEs. Numerous techniques were devised in this regard which includes the GERFM method [1], modified variational iteration algorithm-II [3], enhanced (GG)-expansion method [4], the direct algebraic method [5], the extended trial equation method [6], the generalized fractional integral conditions method [7], the modified simple equation method [8], the Monch's theorem method [9], the extended modified mapping method [10], the reductive perturbation method [11], the new probability transformation method [12] and the differential transformation method [13]. In future work for more related extensions or generalizations of the results these references may be very helpful [2,32,33,34,35,36].

    The time fractional derivatives in the fractional reaction-diffusion model describes the process relating to the physical phenomena, physically known as the historical dependence. The space fractional derivative explains the path dependence and global correlation properties of physical processes, that is, the global dependence. The reaction diffusion equation has a dynamic role in dissipative dynamical systems as studied by various biologists [38], scientists and engineers [14]. The nonlinear form of this model has found a number of applications in numerous branches of biology, physics and chemistry [14,15]. This model has also been useful for other areas of science and effectively generalized by employing the theory of fractional calculus, for instance see [15,16]. Diffusion-wave equations involving Caputo's derivative [17,18], Riemann-Liouville derivatives [19] have been discussed by various researchers. Anomalous dispersion equations can be explained by fractional derivative [20]. An extensive variety of exact methods which have been applied for exact solutions of the fractional nonlinear reaction diffusion equation, for example see [14,15,16,17,18,19,20] and references there in.

    To interpret numerous physical phenomena in some special fields of science and engineering, nonlinear evolution equations are extensively used as models especially in solid-state physics and plasma physics. Finding the exact solutions of NLEEs is a key role in the study of these physical phenomena [39]. A lot of research work has been carried out during the past decades for evaluating the exact and numerical solutions of many nonlinear evolution equations. Among them are homotopy analysis method [21], modified exp-function method [22], (GG)-expansion method [23], exp-function method [24], homotopy perturbation method [25], Jacobi elliptic function method [26], sub equation function method [27], kudryashov method [28], and so on.We can be expressed the exact solutions of FPDE via exp (φ(η)).

    (φ(η))=exp(φ(η))+μ exp(φ(η))+λ (1.1)

    The article is arranged as follows: Section 1 represents the introduction of the article. In section 2, we have explained the Caputo's fractional derivative. In section 3, we have interpreted the exp (φ(η))-expansion method. In section 4, we use this method to explore the reaction-diffusion model. In section 5 and 6, graphical representation and physical interpretation are explained. In section 7 and 8, we have interpreted the results, discussions and conclusion.

    Property 1: [29] A function f(x,t),where x>0 is considered as Cα. Here αR, if a R and (p>α), such that

    f(x)=xpf1(x) (1.2)
    f1(x)C[0,).Where f1(x)C[0,)

    Property2: [29] A function f(x,t), where x>0 is considered to be in space Cmα. Here mN{0}, if f(m)Cα.

    Iμtf(x,t)=1Γ(μ)t0(tT)μ1f(x,T)dT, t>0. (1.3)

    Property3: [29] Suppose fCα and α1, then the Riemann Liouville integral μ, where μ>0 is given by

    Property4: [29] A fractional Caputo derivative of f with respect to t, where fCm1, mN{0},is given as

    Dμtf(x,t)=mtmf(x,t), μ=m (1.4)
    =Imμtmtmf(x,t),m1μ<m (1.5)

    Note that

    IμtDμtf(x,t)=f(x,t)m1k=0k ftk(x,0)tkk!,  m1<μm, mN (1.6)
    Iμttν=Γ(ν+1)Γ(μ+ν+1)tμ+ν. (1.7)

    Consider the fractional partial differential equation,

    φ(u,Dαtu,ux,uxx,D2αtu,Dαtux,)=0,t>0,xR,0α1, (1.8)

    where Dαtu, Dαxu, Dαxxu are derivatives, u(η)=u(x,t). For solving Eq 1.8, we follow:

    Step 1: Using a transformation, we get,

    η=x±VtαΓ(1+α),u=u(η), (1.9)

    where constant V is a nonzero. By substituting Eq 1.9 in Eq 1.8 yields ODE:

    φ(u,±Vu,ku,V2u,k2u,)=0. (1.10)

    Step 2: Assuming the traveling wave solution

    u(η)=Mn=0an(eφ(η))n, (1.11)

    where φ(η) satisfies the following equation:

    φ(η)=eφ(η)+λ+μeφ(η) (1.12)
    φ(η)=λeφ(η)e2φ(η)+μλeφ(η)+μ2e2φ(η),

    where prime indicates derivative w.r.t.η. The solutions of Eq 1.12 are written in the form of different cases.

    Class1: when μ0 and λ24μ>0, we have

    φ(η)=ln{12μ(λλtanh(λ2(c1+η)))}. (1.13)

    where λ=(4μ+λ2)

    Class 2: when, μ0 and λ24μ<0, we have

    φ(η)=ln{12μ(λ+λtan(λ2(c1+η)))}. (1.14)

    where, λ=(4μ+λ2)

    Class 3: when, λ0,μ=0 and λ24μ>0, we have

    φ(η)=ln{λ1+exp(λ(k+η)) }

    φ(η)=ln{λ1+exp(λ(k+η)) }.

    Class 4: when, λ,μ0 and λ24μ=0, we have

    φ(η)=ln{2(2+λ(k+η))(λ2(η+k))}.

    Class 5: when, λ,μ=0 and λ24μ=0, we have

    φ(η)=[ln{η+k}], (1.15)

    Step 3: Using the homogeneous balancing principal, in (10), we attain M. In view of Eq (11), Eq (10) and Eq (12), we obtain a system of equations with these parameters, a_n, λ,μ. We substitute the values in Eq (11) and Eq (12) and obtained the results of Eq (8).

    Suppose the reaction-diffusion equation is,

    D2αtu+δuxx+βu+γu3=0,0<α1, (2.1)

    where δ, β and γ are parameters without zero, setting, δ=a, β=b and γ=c and changing Eq 2.1 into an ODE.

    V2u+au+bu+cu3=0, (2.2)

    where prime represents the derivative w. r. t. η.With the help of balancing principal, u and u3, we attain, M=1.

    Rewriting the solution of Eq 2.2 we get,

    u(η)=[a0+a1(exp(φ(η)))], (2.3)

    where a0, a10 are constants, while λ,μ are some constants.

    Substituting u,u and u3 in Eq 2.2, we get the solution sets as.

    Solution set 1

    λ=0, C=C,V=122μ(2aμ+b)μ,a0=0, a1=cbμc

    Substituting in Eq 2.3, we get,

    u(η)=a1(exp(φ(η))), (2.4)

    Substituting all the five classes in Eq 2.4, we get the solutions.

    Class 1: When, λ24μ>0 and μ0,

    v1=12cbμ tanh(12(122μ(2aμ+b)tαμΓ(α+1)+x)4μ)4μcμ

    Class 2: When, λ24μ<0 and μ0,

    v2=12cbμ tan(12(122μ(2aμ+b)tαμΓ(α+1)+x)4μ)4cμ (2.5)

    Solution set 2:

    {λ=0,C=C, V=122μ(2aμ+b)μ,a0=0, a1=cbμc}

    Substituting in Eq 2.3, we get,

    u(η)=a1(exp(φ(η))), (2.6)

    Substituting equations 1.13 and 1.14 in Eq 2.6, we get the solutions.

    Class 1: When, μ0 and λ24μ>0,

    v3=12cbμ tanh(12(122μ(2aμ+b)tαμΓ(α+1)+x)4μ)4μcμ (2.7)

    Class 2: When, μ0 and λ24μ<0,

    v4=12cbμ tan(12(122μ(2aμ+b)tαμΓ(α+1)+x)4μ)4cμ (2.8)

    Solution Set 3

    {λ=λ, C=C, V=(λ24μ)(aλ24aμ2b)λ24μ, a0=bλc(λ24μ)b, a1=2c(λ24μ)b μc(λ24μ)}

    Substituting in Eq 2.3, we get,

    u(η)=a1(exp(φ(η)))+a0, (2.9)

    Substituting equations 1.13 to 1.15 in Eq 2.9, we get the solutions.

    Class 1: When, μ0 and4μ+λ2>0,

    v5=bλc(λ24μ)b1c(λ24μ)(c(λ24μ)b(λtanh(12((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x)λ24μ)λ24μ)) (2.10)

    Class 2: When, μ0 and4μ+λ2<0,

    v6=bλc(λ24μ)b(c(λ24μ)b(λ+tan(12((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x)λ2+4μ)λ2+4μ)) (2.11)

    Class 3: When λ0, 4μ+λ2>0 and μ=0,

    v7=bλc(λ24μ)b2c(λ24μ)bμ(eλ((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x)1)c(λ24μ)λ (2.12)

    Class 4: When, λ0, μ=0 and 4μ+λ2=0,

    v8=bλc(λ24μ)b+2c(λ24μ)bμ(2λ((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x)+2)c(λ24μ)λ2((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x) (2.13)

    Case 5: When, λ=0, μ=0 and 4μ+λ2=0,

    v9=bλc(λ24μ)b2c(λ24μ)(c(λ24μ)b μ((λ24μ)(aλ24aμ2b)tα(λ24μ)Γ(α+1)+x)) (2.14)

    Physical interpretation

    With some free parameters the proposed technique provides solitary wave solutions. By setting the specific parameters we have explained the miscellaneous wave solutions. In this study, we would explain the physical interpretation of the solutions for reaction-diffusion equation taking solution v1 for μ=20λ=1b=11a=10a1=12c=11α=1, shows the solitary wave solution in Figure 1. Figure 2 shows Soliton wave solution with paremeters μ=910λ=1b=11a=10a1=12c=11α=.5. Figures 3, 4 and 7 interprets the singular kink solution of v3,v4, v7 for μ=.010λ=1b=.11a=10a1= 12 c=11α=.1,μ=.0010λ=991b=11a=10a1=102c=1α= .1, μ=20λ=1b=11a=10a1=12c=11α=.25. Finally kink wave results have been obtained from v5,v6, v8 by setting the parameters, μ=3.0λ=1b=11a=10a1= 12 c=11α=0.001,μ=2.0λ=1b=11a=10a1=12c= -11 α=0.001,μ=20λ=1b=11a=10a1=12c=11α=0.01, which is presented in Figures 5, 6 and 8. The solutions gained in this article have been checked by putting them back into the original equation and found correct. From the above obtained results we have many potential applications in fluid mechanics, quantum field theory, plasma physics and nonlinear optics.

    Figure 1.  Solitary wave solusion ν1(η).
    Figure 2.  Soliton wave solusion ν2(η).
    Figure 3.  Singular kink wave solusion ν3(η).
    Figure 4.  Singular kink wave solusion ν4(η).
    Figure 5.  kink wave solusion ν5(η).
    Figure 6.  kink wave solusion ν6(η).
    Figure 7.  Singular kink wave solusion ν7(η).
    Figure 8.  kink wave solusion ν8(η).

    When

    μ=20, λ=1, b=11, a=10,a1=12,c=11,α=1

    When

    μ=910, λ=1, b=11, a=10,a1=12,c=11,α=1

    When

    μ=.010, λ=1, b=.11, a=10,a1=12,c=11,α=.1

    When

    μ=.0010, λ=991, b=11, a=10,a1=102,c=11,α=.1

    When

    μ=3.0, λ=1, b=11, a=10,a1=12,c=11,α=.001

    When

    μ=2.0, λ=1, b=11, a=10,a1=12,c=11,α=.001

    When

    μ=20, λ=1, b=11, a=10,a1=12,c=11,α=.25

    When

    μ=20, λ=1, b=11, a=10,a1=12,c=11,α=.01

    If we set b=β,c=γ,μ=r and η=ξ in the obtaining solution v2 and v3 in this article is equal to u5 and u1 for case 5 respectively found in [31] see Table 1.

    Table 1.  Comparing the results of [31], with our results.
    Attained Results [31] results
    (i) If we set b=β,c=γ,μ=r and η=ξ then our solution v3 becomes v3=βγtanh(rξ) (i) The solution u1 is as u1=βγtanh(rξ)
    (ii) If we set b=β,c=γ,μ=r and η=ξ then our solution v2 becomes v2=βγtan(rξ) (ii) The solution u5 is as u5=βγtan(rξ)

     | Show Table
    DownLoad: CSV

    If we set b=β,c=γ and η=ξ, in the obtaining solution v2 and v4 in this article is equal to u and u for c10,c2=0,λ=0 and μ>0 in [23] see Table 2.

    Table 2.  Comparing the results of [23], with our results.
    Attained Results [23] results
    (i) If we set b=β,c=γ and η=ξ then our solution v2 becomes v2=βγtan(μξ) (i) The solution u is as u(ξ)=±βγtan(μξ)
    (ii) If we set b=β,c=γ and η=ξ then our solution v3 becomes v3=βγtan(μξ) (ii) The solution u is as u(ξ)=±βγtan(μξ)

     | Show Table
    DownLoad: CSV

    If we set b=β,c=γ in the obtaining solution v2 and v4 are equal to v9 and v9 for λ=0 and μ is positive in v9 found in [32] see Table 3.

    Table 3.  Comparing the results of [32], with our results.
    Attained Results [32] results
    (i) If we set b=β,c=γ then our solution v2 becomes v2=βγtan(μη) (i) The solution u is as u(ξ)=±βγtan(μη)
    (ii) If we set b=β,c=γ then our solution v4 becomes v3=βγtan(μη) (ii) The solution u is as u(ξ)=±βγtan(μη)

     | Show Table
    DownLoad: CSV

    If we set b=β,c=γ and η=ξ in the obtaining solution v2 and v4 in this article are equal to u2 and u2 for k>0,β>0 and our v1 and v3 are equal to u4 and u4 for k<0,β<0 respectively founded in [30] see Table 4.

    Table 4.  Comparing the results of [30], with our results.
    Attained Results [30] results
    (i) If we set b=β,c=γ,μ=k and η=ξ then our solution v2 becomes v2=βγtan(kξ) (i) The solution u2 is as u1=±βγtan(kξ)
    (ii) If we set b=β,c=γ,μ=k and η=ξ then our solution v4 becomes v2=βγtan(kξ) (ii) The solution u2 is as u2=±βγtan(kξ)
    (iii) If we set b=β,c=γ,μ=k and η=ξ then our solution v1 becomes v1=βγtanh(kξ) (iii) The solution u4 is as u4=±βγtanh(kξ)
    (iv) If we set b=β,c=γ,μ=k and η=ξ then our solution v4 becomes v4=βγtanh(kξ) (iv) The solution u4 is as u4=±βγtanh(kξ)

     | Show Table
    DownLoad: CSV

    In the current paper, we explore that the proposed method is effective and capable to find exact solutions of reaction-diffusion equation. The obtained solutions indicate that the suggested method is direct, constructive and simple. The proposed technique can be implemented to the other NLPDEs of fractional order to establish new reliable solutions. The exact solutions are different and new along with different values of parameters. The reduction in the magnitude of computational part and the consistency of the technique give a broader applicability to the technique. The reaction diffusion equation has a dynamic role in dissipative dynamical systems as studied by various biologists, scientists and engineers. This model has found a number of applications in biology, physics (neutron diffusi0n theory), ecology and chemistry. It has also been claimed that reaction-diffusion processes have crucial basis for procedures associated to morphogenesis in biology and may even be connected to skin pigmentation and animal coats. Other applications of this model contain spread of epidemics, ecological invasions, wound healing and tumors growth. Another aim for the consideration in reaction-diffusion systems is that although they are nonlinear partial differential equations, there are often visions for an analytical treatment. My main contribution is programming and comparisons.

    The authors declare that there is no conflict of interest regarding the publication of this paper.



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