This paper provides a multiplicity result of solutions with one node for a class of (non-degenerate) classical diffusive logistic equations. Although reminiscent of the multiplicity theorem of López-Gómez and Rabinowitz [
Citation: Pablo Cubillos, Julián López-Gómez, Andrea Tellini. Multiplicity of nodal solutions in classical non-degenerate logistic equations[J]. Electronic Research Archive, 2022, 30(3): 898-928. doi: 10.3934/era.2022047
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This paper provides a multiplicity result of solutions with one node for a class of (non-degenerate) classical diffusive logistic equations. Although reminiscent of the multiplicity theorem of López-Gómez and Rabinowitz [
Let C denote the complex plane and Cn the n-dimensional complex Euclidean space with an inner product defined as ⟨z,w⟩=∑nj=1zj¯wj. Let B(a,r)={z∈Cn:|z−a|<r} be the open ball of Cn. In particular, the open unit ball is defined as B=B(0,1).
Let H(B) denote the set of all holomorphic functions on B and S(B) the set of all holomorphic self-mappings of B. For given φ∈S(B) and u∈H(B), the weighted composition operator on or between some subspaces of H(B) is defined by
Wu,φf(z)=u(z)f(φ(z)). |
If u≡1, then Wu,φ is reduced to the composition operator usually denoted by Cφ. If φ(z)=z, then Wu,φ is reduced to the multiplication operator usually denoted by Mu. Since Wu,φ=Mu⋅Cφ, Wu,φ can be regarded as the product of Mu and Cφ.
If n=1, B becomes the open unit disk in C usually denoted by D. Let Dm be the mth differentiation operator on H(D), that is,
Dmf(z)=f(m)(z), |
where f(0)=f. D1 denotes the classical differentiation operator denoted by D. As expected, there has been some considerable interest in investigating products of differentiation and other related operators. For example, the most common products DCφ and CφD were extensively studied in [1,10,11,12,13,23,25,26], and the products
MuCφD,CφMuD,MuDCφ,CφDMu,DMuCφ,DCφMu | (1.1) |
were also extensively studied in [14,18,22,27]. Following the study of the operators in (1.1), people naturally extend to study the operators (see [5,6,30])
MuCφDm,CφMuDm,MuDmCφ,CφDmMu,DmMuCφ,DmCφMu. |
Other examples of products involving differentiation operators can be found in [7,8,19,32] and the related references.
As studying on the unit disk becomes more mature, people begin to become interested in exploring related properties on the unit ball. One method for extending the differentiation operator to Cn is the radial derivative operator
ℜf(z)=n∑j=1zj∂f∂zj(z). |
Naturally, replacing D by ℜ in (1.1), we obtain the following operators
MuCφℜ,CφMuℜ,MuℜCφ,CφℜMu,ℜMuCφ,ℜCφMu. | (1.2) |
Recently, these operators have been studied in [31]. Other operators involving radial derivative operators have been studied in [21,33,34].
Interestingly, the radial derivative operator can be defined iteratively, namely, ℜmf can be defined as ℜmf=ℜ(ℜm−1f). Similarly, using the radial derivative operator can yield the related operators
MuCφℜm,CφMuℜm,MuℜmCφ,CφℜmMu,ℜmMuCφ,ℜmCφMu. | (1.3) |
Clearly, the operators in (1.3) are more complex than those in (1.2). Since CφMuℜm=Mu∘φCφℜm, the operator MuCφℜm can be regarded as the simplest one in (1.3) which was first studied and denoted as ℜmu,φ in [24]. Recently, it has been studied again because people need to obtain more properties about spaces to characterize its properties (see [29]).
To reconsider the operator CφℜmMu, people find the fact
CφℜmMu=m∑i=0Cimℜi(ℜm−iu)∘φ,φ. | (1.4) |
Motivated by (1.4), people directly studied the sum operator (see [2,28])
Sm→u,φ=m∑i=0MuiCφℜi, |
where ui∈H(B), i=¯0,m, and φ∈S(B). Particularly, if we set u0≡⋯≡um−1≡0 and um=u, then Sm→u,φ=MuCφℜm; if we set u0≡⋯≡um−1≡0 and um=u∘φ, then Sm→u,φ=CφMuℜm. In [28], Stević et al. studied the operators Sm→u,φ from Hardy spaces to weighted-type spaces on the unit ball and obtained the following results.
Theorem A. Let m∈N, uj∈H(B), j=¯0,m, φ∈S(B), and μ a weight function on B. Then, the operator Sm→u,φ:Hp→H∞μ is bounded and
supz∈Bμ(z)|uj(φ(z))||φ(z)|<+∞,j=¯1,m, | (1.5) |
if and only if
I0=supz∈Bμ(z)|u0(z)|(1−|φ(z)|2)np<+∞ |
and
Ij=supz∈Bμ(z)|uj(z)||φ(z)|(1−|φ(z)|2)np+j<+∞,j=¯1,m. |
Theorem B. Let m∈N, uj∈H(B), j=¯0,m, φ∈S(B), and μ a weight function on B. Then, the operator Sm→u,φ:Hp→H∞μ is compact if and only if it is bounded,
lim|φ(z)|→1μ(z)|u0(z)|(1−|φ(z)|2)np=0 |
and
lim|φ(z)|→1μ(z)|uj(z)||φ(z)|(1−|φ(z)|2)np+j=0,j=¯1,m. |
It must be mentioned that we find that the necessity of Theorem A requires (1.5) to hold. Inspired by [2,28], here we use a new method and technique without (1.5) to study the sum operator Sm→u,φ from logarithmic Bergman-type space to weighted-type space on the unit ball. To this end, we need to introduce the well-known Bell polynomial (see [3])
Bm,k(x1,x2,…,xm−k+1)=∑m!∏m−k−1i=1ji!m−k−1∏i=1(xii!)ji, |
where all non-negative integer sequences j1, j2,…,jm−k+1 satisfy
m−k+1∑i=1ji=kandm−k+1∑i=1iji=m. |
In particular, when k=0, one can get B0,0=1 and Bm,0=0 for any m∈N. When k=1, one can get Bi,1=xi. When m=k=i, Bi,i=xi1 holds.
In this section, we need to introduce logarithmic Bergman-type space and weighted-type space. Here, a bounded positive continuous function on B is called a weight. For a weight μ, the weighted-type space H∞μ consists of all f∈H(B) such that
‖f‖H∞μ=supz∈Bμ(z)|f(z)|<+∞. |
With the norm ‖⋅‖H∞μ, H∞μ becomes a Banach space. In particular, if μ(z)=(1−|z|2)σ(σ>0), the space H∞μ is called classical weighted-type space usually denoted by H∞σ. If μ≡1, then space H∞μ becomes the bounded holomorphic function space usually denoted by H∞.
Next, we need to present the logarithmic Bergman-type space on B (see [4] for the unit disk case). Let dv be the standardized Lebesgue measure on B. The logarithmic Bergman-type space Apwγ,δ consists of all f∈H(B) such that
‖f‖pApwγ,δ=∫B|f(z)|pwγ,δ(z)dv(z)<+∞, |
where −1<γ<+∞, δ≤0, 0<p<+∞ and wγ,δ(z) is defined by
wγ,δ(z)=(log1|z|)γ[log(1−1log|z|)]δ. |
When p≥1, Apwγ,δ is a Banach space. While 0<p<1, it is a Fréchet space with the translation invariant metric ρ(f,g)=‖f−g‖pApωγ,δ.
Let φ∈S(B), 0≤r<1, 0≤γ<∞, δ≤0, and a∈B∖{φ(0)}. The generalized counting functions are defined as
Nφ,γ,δ(r,a)=∑zj(a)∈φ−1(a)wγ,δ(zj(a)r) |
where |zj(a)|<r, counting multiplicities, and
Nφ,γ,δ(a)=Nφ,γ,δ(1,a)=∑zj(a)∈φ−1(a)wγ,δ(zj(a)). |
If φ∈S(D), then the function Nφ,γ,δ has the integral expression: For 1≤γ<+∞ and δ≤0, there is a positive function F(t) satisfying
Nφ,γ,δ(r,u)=∫r0F(t)Nφ,1(t,u)dt,r∈(0,1),u≠φ(0). |
When φ∈S(D) and δ=0, the generalized counting functions become the common counting functions. Namely,
Nφ,γ(r,a)=∑z∈φ−1(a),|z|<r(logr|z|)γ, |
and
Nφ,γ(a)=Nφ,γ(1,a)=∑z∈φ−1(a)(log1|z|)γ. |
In [17], Shapiro used the function Nφ,γ(1,a) to characterize the compact composition operators on the weighted Bergman space.
Let X and Y be two topological spaces induced by the translation invariant metrics dX and dY, respectively. A linear operator T:X→Y is called bounded if there is a positive number K such that
dY(Tf,0)≤KdX(f,0) |
for all f∈X. The operator T:X→Y is called compact if it maps bounded sets into relatively compact sets.
In this paper, j=¯k,l is used to represent j=k,...,l, where k,l∈N0 and k≤l. Positive numbers are denoted by C, and they may vary in different situations. The notation a≲b (resp. a≳b) means that there is a positive number C such that a≤Cb (resp. a≥Cb). When a≲b and b≳a, we write a≍b.
In this section, we obtain some properties on the logarithmic Bergman-type space. First, we have the following point-evaluation estimate for the functions in the space.
Theorem 3.1. Let −1<γ<+∞, δ≤0, 0<p<+∞ and 0<r<1. Then, there exists a positive number C=C(γ,δ,p,r) independent of z∈K={z∈B:|z|>r} and f∈Apwγ,δ such that
|f(z)|≤C(1−|z|2)γ+n+1p[log(1−1log|z|)]−δp‖f‖Apwγ,δ. | (3.1) |
Proof. Let z∈B. By applying the subharmonicity of the function |f|p to Euclidean ball B(z,r) and using Lemma 1.23 in [35], we have
|f(z)|p≤1v(B(z,r))∫B(z,r)|f(w)|pdv(w)≤C1,r(1−|z|2)n+1∫B(z,r)|f(w)|pdv(w). | (3.2) |
Since r<|z|<1 and 1−|w|2≍1−|z|2, we have
log1|w|≍1−|w|≍1−|z|≍log1|z| | (3.3) |
and
log(1−log1|w|)≍log(1−log1|z|). | (3.4) |
From (3.3) and (3.4), it follows that there is a positive constant C2,r such that wγ,δ(z)≤C2,rwγ,δ(w) for all w∈B(z,r). From this and (3.2), we have
|f(z)|p≤C1,rC2,r(1−|z|2)n+1wγ,δ(z)∫B(z,r)|f(w)|pwγ,δ(w)dv(w)≤C1,rC2,r(1−|z|2)n+1wγ,δ(z)‖f‖pApwγ,δ. | (3.5) |
From (3.5) and the fact log1|z|≍1−|z|≍1−|z|2, the following inequality is right with a fixed constant C3,r
|f(z)|p≤C1,rC2,rC3,r(1−|z|2)n+1+γ[log(1−1log|z|)]−δ‖f‖pApwγ,δ. |
Let C=C1,rC2,rC3,rp. Then the proof is end.
Theorem 3.2. Let m∈N, −1<γ<+∞, δ≤0, 0<p<+∞ and 0<r<1. Then, there exists a positive constant Cm=C(γ,δ,p,r,m) independent of z∈K and f∈Apwγ,δ such that
|∂mf(z)∂zi1∂zi2…∂zim|≤Cm(1−|z|2)γ+n+1p+m[log(1−1log|z|)]−δp‖f‖Apwγ,δ. | (3.6) |
Proof. First, we prove the case of m=1. By the definition of the gradient and the Cauchy's inequality, we get
|∂f(z)∂zi|≤|∇f(z)|≤˜C1supw∈B(z,q(1−|z|))|f(w)|1−|z|, | (3.7) |
where i=¯1,n. By using the relations
1−|z|≤1−|z|2≤2(1−|z|), |
(1−q)(1−|z|)≤1−|w|≤(q+1)(1−|z|), |
and
log(1−1log|z|)≍log(1−1log|w|), |
we obtain the following formula
|f(w)|≤˘C1(1−|z|2)γ+n+1p[log(1−1log|z|)]−δp‖f‖Apwγ,δ |
for any w∈B(z,q(1−|z|)). Then,
supw∈B(z,q(1−|z|))|f(w)|≤˘C1(1−|z|2)γ+n+1p[log(1−1log|z|)]−δp‖f‖Apwγ,δ. |
From (3.1) and (3.2), it follows that
|∂f(z)∂zi|≤ˆC1(1−|z|2)γ+n+1p+1[log(1−1log|z|)]−δp‖f‖Apwγ,δ. | (3.8) |
Hence, the proof is completed for the case of m=1.
We will use the mathematical induction to complete the proof. Assume that (3.6) holds for m<a. For convenience, let g(z)=∂a−1f(z)∂zi1∂zi2…∂zia−1. By applying (3.7) to the function g, we obtain
|∂g(z)∂zi|≤˜C1supw∈B(z,q(1−|z|))|g(w)|1−|z|. | (3.9) |
According to the assumption, the function g satisfies
|g(z)|≤ˆCa−1(1−|z|2)γ+n+1p+a−1[log(1−1log|z|)]−δp‖f‖Apwγ,δ. |
By using (3.8), the following formula is also obtained
|∂g(z)∂zi|≤ˆCa(1−|z|2)γ+n+1p+a[log(1−1log|z|)]−δp‖f‖Apwγ,δ. |
This shows that (3.6) holds for m=a. The proof is end.
As an application of Theorems 3.1 and 3.2, we give the estimate in z=0 for the functions in Apωγ,δ.
Corollary 3.1. Let −1<γ<+∞, δ≤0, 0<p<+∞, and 0<r<2/3. Then, for all f∈Apwγ,δ, it follows that
|f(0)|≤C(1−r2)γ+n+1p[log(1−1logr)]−δp‖f‖Apwγ,δ, | (3.10) |
and
|∂mf(0)∂zl1…∂zlm|≤Cm(1−r2)γ+n+1p+m[log(1−1logr)]−δp‖f‖Apwγ,δ, | (3.11) |
where constants C and Cm are defined in Theorems 3.1 and 3.2, respectively.
Proof. For f∈Apwγ,δ, from Theorem 3.1 and the maximum module theorem, we have
|f(0)|≤max|z|=r|f(z)|≤C(1−r2)γ+n+1p[log(1−1logr)]−δp‖f‖Apwγ,δ, |
which implies that (3.10) holds. By using the similar method, we also have that (3.11) holds.
Next, we give an equivalent norm in Apwγ,δ, which extends Lemma 3.2 in [4] to B.
Theorem 3.3. Let r0∈[0,1). Then, for every f∈Apwγ,δ, it follows that
‖f‖pApwγ,δ≍∫B∖r0B|f(z)|pwγ,δ(z)dv(z). | (3.12) |
Proof. If r0=0, then it is obvious. So, we assume that r0∈(0,1). Integration in polar coordinates, we have
‖f‖pApwγ,δ=2n∫10wγ,δ(r)r2n−1dr∫S|f(rζ)|pdσ(ζ). |
Put
A(r)=wγ,δ(r)r2n−1andM(r,f)=∫S|f(rζ)|pdσ(ζ). |
Then it is represented that
‖f‖pApwγ,δ≍∫r00+∫1r0M(r,f)A(r)dr. | (3.13) |
Since M(r,f) is increasing, A(r) is positive and continuous in r on (0,1) and
limr→0A(r)=limx→+∞xγ[log(1+1x)]δe−(2n−1)x=limx→+∞xγ−δe(2n−1)x=0, |
that is, there is a constant ε>0(ε<r0) such that A(r)<A(ε) for r∈(0,ε). Then we have
∫r00M(r,f)A(r)dr≤2r01−r0maxε≤r≤r0A(r)∫1+r02r0M(r,f)dr≤2r01−r0maxε≤r≤r0A(r)minr0≤r≤1+r02A(r)∫1+r02r0M(r,f)A(r)dr≲∫1r0M(r,f)A(r)dr. | (3.14) |
From (3.13) and (3.14), we obtain the inequality
‖f‖pApwγ,δ≲∫1r0M(r,f)A(r)dr. |
The inequality reverse to this is obvious. The asymptotic relationship (3.12) follows, as desired.
The following integral estimate is an extension of Lemma 3.4 in [4]. The proof is similar, but we still present it for completeness.
Lemma 3.1. Let −1<γ<+∞, δ≤0, β>γ−δ and 0<r<1. Then, for each fixed w∈B with |w|>r,
∫Bωγ,δ(z)|1−⟨z,w⟩|n+β+1dv(z)≲1(1−|w|)β−γ[log(1−1log|w|)]δ. |
Proof. Fix |w| with |w|>r0 (0<r0<1). It is easy to see that
log1r≍1−rforr0≤r<1. | (3.15) |
By applying Theorem 3.3 with
fw(z)=1(1−⟨z,w⟩)n+β+1 |
and using (3.15), the formula of integration in polar coordinates gives
∫B1|1−⟨z,w⟩|n+β+1ωγ,δ(z)dv(z)≲∫1r0M(r,fw)(1−r)γ[log(1−1logr)]δr2n−1dr. | (3.16) |
By Proposition 1.4.10 in [15], we have
M(r,fw)≍1(1−r2|w|2)β+1. | (3.17) |
From (3.16) and (3.17), we have
∫B1|1−⟨z,w⟩|β+2nωγ,δ(z)dv(z)≲∫1r01(1−r2|w|2)β+1(1−r)γ[log(1−1logr)]δr2n−1dr≲∫1r01(1−r|w|)β+1(1−r)γ[log(1−1logr)]δr2n−1dr≲∫|w|r01(1−r|w|)β+1(1−r)γ[log(1−1logr)]δr2n−1dr+∫1|w|1(1−r|w|)β+1(1−r)γ[log(1−1logr)]δr2n−1dr=I1+I2. |
Since [log(1−1logr)]δ is decreasing in r on [|w|,1], we have
I2=∫1|w|1(1−r|w|)β+1(1−r)γ[log(1−1logr)]δr2n−1dr≲1(1−|w|)β+1[log(1−1log|w|)]δ∫1|w|(1−r)γdr≍1(1−|w|)β−γ[log(1−1log|w|)]δ. | (3.18) |
On the other hand, we obtain
I1=∫|w|r01(1−r|w|)β+1(1−r)γ[log(1−1logr)]δr2n−1dr≲∫|w|r0(1−r)γ−β−1(log21−r)δdr. |
If δ=0 and β>γ, then we have
I1(0)≲(1−|w|)γ−β. |
If δ≠0, then integration by parts gives
I1(δ)=−1γ−β(1−|w|)γ−β(log21−|w|)δ+1γ−β(1−r0)γ−β(log21−r0)δ+δγ−βI1(δ−1). |
Since δ<0, γ−β<0 and
(log21−r)δ−1≤(log21−r)δforr0<r<|w|<1, |
we have
I1(δ)≤−1γ−β(1−|w|)γ−β(log21−|w|)δ+δγ−βI1(δ) |
and from this follows
I1(δ)≲(1−|w|)γ−β(log21−|w|)δ≍(1−|w|)γ−β[log(1−1log|w|)]δ |
provided γ−β−δ<0. The proof is finished.
The following gives an important test function in Apwγ,δ.
Theorem 3.4. Let −1<γ<+∞, δ≤0, 0<p<+∞ and 0<r<1. Then, for each t≥0 and w∈B with |w|>r, the following function is in Apwγ,δ
fw,t(z)=[log(1−1log|w|)]−δp(1−|w|2)−δp+t+1(1−⟨z,w⟩)γ−δ+n+1p+t+1. |
Moreover,
sup{w∈B:|w|>r}‖fw,t‖Apwγ,δ≲1. |
Proof. By Lemma 3.1 and a direct calculation, we have
‖fw,t‖pApwγ,δ=∫B|[log(1−1log|w|)]−δp(1−|w|2)−δp+t+1(1−⟨z,w⟩)γ−δ+n+1p+t+1|pwγ,δ(z)dA(z)=(1−|w|2)p(t+1)−δ[log(1−1log|w|)]−δ×∫B1|1−⟨z,w⟩|γ−δ+p(t+1)+n+1wγ,δ(z)dA(z)≲1. |
The proof is finished.
In this section, for simplicity, we define
Bi,j(φ(z))=Bi,j(φ(z),φ(z),…,φ(z)). |
In order to characterize the compactness of the operator Sm→u,φ:Apwγ,δ→H∞μ, we need the following lemma. It can be proved similar to that in [16], so we omit here.
Lemma 4.1. Let −1<γ<+∞, δ≤0, 0<p<+∞, m∈N, uj∈H(B), j=¯0,m, and φ∈S(B). Then, the bounded operator Sm→u,φ:Apwγ,δ→H∞μ is compact if and only if for every bounded sequence {fk}k∈N in Apwγ,δ such that fk→0 uniformly on any compact subset of B as k→∞, it follows that
limk→∞‖Sm→u,φfk‖H∞μ=0. |
The following result was obtained in [24].
Lemma 4.2. Let s≥0, w∈B and
gw,s(z)=1(1−⟨z,w⟩)s,z∈B. |
Then,
ℜkgw,s(z)=sPk(⟨z,w⟩)(1−⟨z,w⟩)s+k, |
where Pk(w)=sk−1wk+p(k)k−1(s)wk−1+...+p(k)2(s)w2+w, and p(k)j(s), j=¯2,k−1, are nonnegative polynomials for s.
We also need the following result obtained in [20].
Lemma 4.3. Let s>0, w∈B and
gw,s(z)=1(1−⟨z,w⟩)s,z∈B. |
Then,
ℜkgw,s(z)=k∑t=1a(k)t(t−1∏j=0(s+j))⟨z,w⟩t(1−⟨z,w⟩)s+t, |
where the sequences (a(k)t)t∈¯1,k, k∈N, are defined by the relations
a(k)k=a(k)1=1 |
for k∈N and
a(k)t=ta(k−1)t+a(k−1)t−1 |
for 2≤t≤k−1,k≥3.
The final lemma of this section was obtained in [24].
Lemma 4.4. If a>0, then
Dn(a)=|11⋯1aa+1⋯a+n−1a(a+1)(a+1)(a+2)⋯(a+n−1)(a+n)⋮⋮⋯⋮n−2∏k=0(a+k)n−2∏k=0(a+k+1)⋯n−2∏k=0(a+k+n−1)|=n−1∏k=1k!. |
Theorem 4.1. Let −1<γ<+∞, δ≤0, 0<p<+∞, m∈N, uj∈H(B), j=¯0,m, and φ∈S(B). Then, the operator Sm→u,φ:Apwγ,δ→H∞μ is bounded if and only if
M0:=supz∈Bμ(z)|u0(z)|(1−|φ(z)|2)γ+n+1p[log(1−1log|φ(z)|)]−δp<+∞ | (4.1) |
and
Mj:=supz∈Bμ(z)|∑mi=jui(z)Bi,j(φ(z))|(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp<+∞ | (4.2) |
for j=¯1,m.
Moreover, if the operator Sm→u,φ:Apwγ,δ→H∞μ is bounded, then
‖Sm→u,φ‖Apwγ,δ→H∞μ≍m∑j=0Mj. | (4.3) |
Proof. Suppose that (4.1) and (4.2) hold. From Theorem 3.1, Theorem 3.2, and some easy calculations, it follows that
μ(z)|m∑i=0ui(z)ℜif(φ(z))|≤μ(z)m∑i=0|ui(z)||ℜif(φ(z))|=μ(z)|u0(z)||f(φ(z))|+μ(z)|m∑i=1i∑j=1(ui(z)n∑l1=1⋯n∑lj=1(∂jf∂zl1∂zl2⋯∂zlj(φ(z))∑k1,…,kjC(i)k1,…,kjj∏t=1φlt(z)))|=μ(z)|u0(z)f(φ(z))|+μ(z)|m∑j=1m∑i=j(ui(z)n∑l1=1⋯n∑lj=1(∂jf∂zl1∂zl2⋯∂zlj(φ(z))∑k1,…,kjC(i)k1,…,kjj∏t=1φlt(z)))|≲μ(z)|u0(z)|(1−|φ(z)|2)γ+n+1p[log(1−1log|φ(z)|)]−δp‖f‖Apwγ,δ+m∑j=1μ(z)|∑mi=jui(z)Bi,j(φ(z))|(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp‖f‖Apwγ,δ=M0‖f‖Apwγ,δ+m∑j=1Mj‖f‖Apwγ,δ. | (4.4) |
By taking the supremum in inequality (4.4) over the unit ball in the space Apwγ,δ, and using (4.1) and (4.2), we obtain that the operator Sm→u,φ:Apwγ,δ→H∞μ is bounded. Moreover, we have
‖Sm→u,φ‖Apwγ,δ→H∞μ≤Cm∑j=0Mj, | (4.5) |
where C is a positive constant.
Assume that the operator Sm→u,φ:Apwγ,δ→H∞μ is bounded. Then there exists a positive constant C such that
‖Sm→u,φf‖H∞μ≤C‖f‖Apwγ,δ | (4.6) |
for any f∈Apwγ,δ. First, we can take f(z)=1∈Apwγ,δ, then one has that
supz∈Bμ(z)|u0(z)|<+∞. | (4.7) |
Similarly, take fk(z)=zjk∈Apwγ,δ, k=¯1,n and j=¯1,m, by (4.7), then
μ(z)|u0(z)φk(z)j+m∑i=j(ui(z)Bi,j(φk(z))))|<+∞ | (4.8) |
for any j∈{1,2,…,m}. Since φ(z)∈B, we have |φ(z)|≤1. So, one can use the triangle inequality (4.7) and (4.8), the following inequality is true
supz∈Bμ(z)|m∑i=jui(z)Bi,j(φ(z))|<+∞. | (4.9) |
Let w∈B and dk=γ+n+1p+k. For any j∈{1,2,…,m} and constants ck=c(j)k, k=¯0,m, let
h(j)w(z)=m∑k=0c(j)kfw,k(z), | (4.10) |
where fw,k is defined in Theorem 3.4. Then, by Theorem 3.4, we have
Lj=supw∈B‖h(j)w‖Apwγ,δ<+∞. | (4.11) |
From (4.6), (4.11), and some easy calculations, it follows that
Lj‖Sm→u,φ‖Apwγ,δ→H∞μ≥‖Sm→u,φh(j)φ(w)‖H∞μ=supz∈Bμ(z)|m∑i=0u0(z)h(j)φ(w)(φ(z))|≥μ(w)|u0(w)h(j)φ(w)(φ(w))+m∑i=1(ui(w)ℜih(j)φ(w)(φ(w)))|=μ(w)|u0(w)h(j)φ(w)(φ(w))+m∑i=1ui(w)m∑k=0c(j)kfφ(w),k(φ(w))|=μ(w)|u0(w)c0+c1+⋯+cm(1−|φ(z)|2)γ+n+1p+⟨m∑i=1ui(w)Bi,1(φ(w)),φ(w)⟩(d0c0+⋯+dmcm)(1−|φ(w)|2)γ+n+1p+1+⋯+⟨m∑i=jui(w)Bi,j(φ(w)),φ(w)j⟩(d0⋯dj−1c0+⋯+dm⋯dm+j−1cm)(1−|φ(w)|2)γ+n+1p+j+⋯+⟨um(w)Bm,m(φ(w)),φ(w)m⟩(d0⋯dm−1c0+⋯+dm⋯d2m−1cm)(1−|φ(w)|2)γ+n+1p+m|[log(1−1log|φ(w)|)]−δp. | (4.12) |
Since dk>0, k=¯0,m, by Lemma 4.4, we have the following linear equations
(11⋯1d0d1⋯dm⋮⋮⋱⋮j−1∏k=0dkj−1∏k=0dk+m⋯j−1∏k=0dk+m⋮⋮⋱⋮m−1∏k=0dkm−1∏k=0dk+m⋯m−1∏k=0dk+m)(c0c1⋮cj⋮cm)=(00⋮1⋮0). | (4.13) |
From (4.12) and (4.13), we have
Lj‖Sl→u,φ‖Apwγ,δ→H∞μ≥sup|φ(z)|>1/2μ(z)|∑mi=jui(z)Bi,j(φ(z))||φ(z)|j(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp≳sup|φ(z)|>1/2μ(z)|∑mi=jui(z)Bi,j(φ(z))|(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp. | (4.14) |
On the other hand, from (4.9), we have
sup|φ(z)|≤1/2μ(z)|∑mi=jui(z)Bi,j(φ(z))|(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp≤supz∈B(43)γ+n+1p+j[log(1−1log12)]−δpμ(z)|m∑i=jui(z)Bi,j(φ(z))|<+∞. | (4.15) |
From (4.14) and (4.15), we get that (4.2) holds for j=¯1,m.
For constants ck=c(0)k, k=¯0,m, let
h(0)w(z)=m∑k=0c(0)kfw,k(z). | (4.16) |
By Theorem 3.4, we know that L0=supw∈B‖h(0)w‖Apwγ,δ<+∞. From this, (4.12), (4.13) and Lemma 4.4, we get
L0‖Sm→u,φ‖Apwγ,δ→H∞μ≥μ(z)|u0(z)|(1−|φ(z)|2)γ+n+1p[log(1−1log|φ(z)|)]−δp. |
So, we have M0<+∞. Moreover, we have
‖Sm→u,φ‖Apwγ,δ→H∞μ≥m∑j=0Mj. | (4.17) |
From (4.5) and (4.17), we obtain (4.3). The proof is completed.
From Theorem 4.1 and (1.4), we obtain the following result.
Corollary 4.1. Let m∈N, u∈H(B), φ∈S(B) and μ is a weight function on B. Then, the operator CφℜmMu:Apwγ,δ→H∞μ is bounded if and only if
I0:=supz∈Bμ(z)|ℜmu∘φ(z)|(1−|φ(z)|2)γ+n+1p[log(1−1log|φ(z)|)]−δp<+∞ |
and
Ij:=supz∈Bμ(z)|∑mi=jℜm−iu∘φ(z)Bi,j(φ(z))|(1−|φ(z)|2)γ+n+1p+j[log(1−1log|φ(z)|)]−δp<+∞ |
for j=¯1,m.
Moreover, if the operator CφℜmMu:Apwγ,δ→H∞μ is bounded, then
‖CφℜmMu‖Apwγ,δ→H∞μ≍m∑j=0Ij. |
Theorem 4.2. Let −1<γ<+∞, δ≤0, 0<p<+∞, m∈N, uj∈H(B), j=¯0,m, and φ∈S(B). Then, the operator Sm→u,φ:Apwγ,δ→H∞μ is compact if and only if the operator Sm→u,φ:Apwγ,δ→H∞μ is bounded,
(4.18) |
for , and
(4.19) |
Proof. Assume that the operator is compact. It is obvious that the operator is bounded.
If , then it is clear that (4.18) and (4.19) are true. So, we suppose that . Let be a sequence in such that
where are defined in (4.10) for a fixed . Then, it follows that uniformly on any compact subset of as . Hence, by Lemma 4.1, we have
Then, we can find sufficiently large such that
(4.20) |
If , then (4.20) is true.
Now, we discuss the case of . Let , where is defined in (4.16). Then, we also have that and uniformly on any compact subset of as . Hence, by Lemma 4.1, one has that
(4.21) |
Then, by (4.21), we know that (4.18) is true.
Now, assume that is bounded, (4.18) and (4.19) are true. One has that
(4.22) |
and
(4.23) |
for any . By (4.18) and (4.19), for arbitrary , there is a , for any such that
(4.24) |
and
(4.25) |
Assume that is a sequence such that and uniformly on any compact subset of as . Then by Theorem 3.1, Theorem 3.2 and (4.22)–(4.25), one has that
(4.26) |
Since uniformly on any compact subset of as . By Cauchy's estimates, we also have that uniformly on any compact subset of as . From this and using the fact that is a compact subset of , by letting in inequality (4.26), one get that
Since is an arbitrary positive number, it follows that
By Lemma 4.1, the operator is compact.
As before, we also have the following result.
Corollary 4.2. Let , , and is a weight function on . Then, the operators is compact if and only if the operator is bounded,
and
for .
In this paper, we study and obtain some properties about the logarithmic Bergman-type space on the unit ball. As some applications, we completely characterized the boundedness and compactness of the operator
from the logarithmic Bergman-type space to the weighted-type space on the unit ball. Here, one thing should be pointed out is that we use a new method and technique to characterize the boundedness of such operators without the condition (1.5), which perhaps is the special flavour in this paper.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
This work was supported by Sichuan Science and Technology Program (2022ZYD0010) and the Graduate Student Innovation Foundation (Y2022193).
The authors declare that they have no competing interests.
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