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A hyperbolic polyharmonic system in an exterior domain

  • Received: 15 September 2024 Revised: 17 December 2024 Accepted: 23 December 2024 Published: 14 February 2025
  • MSC : 35A01, 35B33, 35L55, 31B30

  • A nonlinear hyperbolic polyharmonic system in an exterior domain of RN is considered under inhomogeneous Navier-type boundary conditions. Using nonlinear capacity estimates specifically adapted to the polyharmonic operator (Δ)m, the geometry of the domain, and the boundary conditions, a sharp criterium for the nonexistence of weak solutions is obtained. Next, an optimal nonexistence result for the corresponding stationary problem is deduced.

    Citation: Manal Alfulaij, Mohamed Jleli, Bessem Samet. A hyperbolic polyharmonic system in an exterior domain[J]. AIMS Mathematics, 2025, 10(2): 2634-2651. doi: 10.3934/math.2025123

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  • A nonlinear hyperbolic polyharmonic system in an exterior domain of RN is considered under inhomogeneous Navier-type boundary conditions. Using nonlinear capacity estimates specifically adapted to the polyharmonic operator (Δ)m, the geometry of the domain, and the boundary conditions, a sharp criterium for the nonexistence of weak solutions is obtained. Next, an optimal nonexistence result for the corresponding stationary problem is deduced.



    This article studies the questions of existence and nonexistence of weak solutions to the system of polyharmonic wave inequalities

    {utt+(Δ)mu|x|a|v|p,(t,x)(0,)×RN¯B1,vtt+(Δ)mv|x|b|u|q,(t,x)(0,)×RN¯B1. (1.1)

    Here, (u,v)=(u(t,x),v(t,x)), N2, B1 is the open unit ball of RN, m1 is an integer, a,b2m, (a,b)(2m,2m), and p,q>1. We will investigate (1.1) under the Navier-type boundary conditions

    {(Δ)iufi(x),i=0,,m1,(t,x)(0,)×B1,(Δ)ivgi(x),i=0,,m1,(t,x)(0,)×B1, (1.2)

    where fi,giL1(B1) and (Δ)0 is the identity operator. Notice that no restriction on the signs of fi or gi is imposed.

    The study of semilinear wave inequalities in RN was firstly considered by Kato [1] and Pohozaev & Véron [2]. It was shown that the problem

    uttΔu|u|p,(t,x)(0,)×RN (1.3)

    possesses a critical exponent pK=N+1N1 in the following sense:

    (ⅰ) If N2 and 1<ppK, then (1.3) possesses no global weak solution, provided

    RNut(0,x)dx>0. (1.4)

    (ⅱ) If p>pK, there are global positive solutions satisfying (1.4).

    Caristi [3] studied the higher-order evolution polyharmonic inequality

    jutj|x|αΔmu|u|p,(t,x)(0,)×RN, (1.5)

    where α2m. Caristi discussed separately the cases α=2m and α<2m. For instance, when j=2 and α=0, it was shown that, if Nm+1 and 1<pN+mNm, then (1.5) possesses no global weak solution, provided (1.4) holds. Other existence and nonexistence results for evolution inequalities involving the polyharmonic operator in the whole space can be found in [4,5,6].

    The study of the blow-up for semilinear wave equations in exterior domains was firstly considered by Zhang [7]. Namely, among many other problems, Zhang investigated the equation

    uttΔu=|x|a|u|p,(t,x)(0,)×RND, (1.6)

    where N3, a>2, and D is a smooth bounded subset of RN. It was shown that (1.6) under the Neumann boundary condition

    uν=f(x)0,(t,x)(0,)×D,

    admits a critical exponent N+aN2 in the following sense:

    (ⅰ) If 1<p<N+aN2, then (1.6) admits no global solution, provided f0.

    (ⅱ) If p>N+aN2, then (1.6) admits global solutions for some f>0.

    In [8,9], it was shown that the critical value p=N+aN2 belongs to case (ⅰ). Furthermore, the same result holds true, if (1.6) is considered under the Dirichlet boundary condition

    u=f(x)0,(t,x)(0,)×D,

    where D=¯B1.

    In [10], the authors considered the system of wave inequalities (1.1) in the case m=1. The system was studied under different types of inhomogeneous boundary conditions. In particular, under the boundary conditions (1.2) with m=1 (Dirichlet-type boundary conditions), the authors obtained the following result: Assume that a,b2, (a,b)(2,2), If0:=B1f0dSx0, Ig0:=B1g0dSx0, (If0,Ig0)(0,0), and p,q>1. If N=2; or N3 and

    N<max{sign(If0)2p(q+1)+pb+apq1,sign(Ig0)2q(p+1)+qa+bpq1},

    then (1.1)-(1.2) (with m=1) admits no weak solution. Moreover, the authors pointed out the sharpness of the above condition.

    In the case m=2, the system (1.1) was recently studied in [11] under different types of boundary conditions. In particular, under the boundary conditions (1.2) with f00 and g00, i.e.,

    {u0,Δuf1(x),(t,x)(0,)×B1,v0,Δvg1(x),(t,x)(0,)×B1. (1.7)

    Namely, the following result was obtained: Let N2, a,b4, (a,b)(4,4), B1f1dSx>0, B1g1dSx>0, and p,q>1. If N{2,3,4}; or

    N5,N<max{4p(q+1)+pb+apq1,4q(p+1)+qa+bpq1},

    then (1.1) (with m=2) under the boundary conditions (1.7) admits no weak solution. Moreover, it was shown that the above condition is sharp.

    Further results related to the existence and nonexistence of solutions for evolution problems in exterior domains can be found in [12,13,14,15,16,17].

    The present work aims to extend the obtained results in [10,11] from m{1,2} to an arbitrary m1. Before presenting our main results, we need to define weak solutions to the considered problem.

    Let

    Q=(0,)×RNB1,ΣQ=(0,)×B1.

    Notice that ΣQQ.

    Definition 1.1. We say that φ is an admissible test function, if

    (i) φC2,2mt,x(Q);

    (ii) supp(φ)⊂⊂Q (φ is compactly supported in Q);

    (iii) φ0;

    (iv) For all j=0,1,,m1,

    Δjφ|ΣQ=0,(1)j(Δjφ)ν|ΣQ0,

    where ν denotes the outward unit normal vector on B1, relative to RNB1.

    The set of all admissible test functions is denoted by Φ.

    Definition 1.2. We say that the pair (u,v) is a weak solution to (1.1)-(1.2), if

    (u,v)Lqloc(Q)×Lploc(Q),Q|x|a|v|pφdxdtm1i=0ΣQfi(x)((Δ)m1iφ)νdσdtQu(Δ)mφdxdt+Quφttdxdt (1.8)

    and

    Q|x|b|u|qφdxdtm1i=0ΣQgi((Δ)m1iφ)νdσdtQv(Δ)mφdxdt+Qvφttdxdt (1.9)

    for every φΦ.

    Notice that, if (u,v) is a regular solution to (1.1)-(1.2), then (u,v) is a weak solution in the sense of Definition 1.2.

    For every function fL1(B1), we set

    If=B1f(x)dσ.

    Our first main result is stated in the following theorem.

    Theorem 1.1. Let p,q>1, N2, and a,b2m with (a,b)(2m,2m). Let fi,giL1(B1) for every i=0,,m1. Assume that Ifm1,Igm10 and (Ifm1,Igm1)(0,0). If N2m; or N2m+1 and

    N<max{sign(Ifm1)×2mp(q+1)+pb+apq1,sign(Igm1)×2mq(p+1)+qa+bpq1}, (1.10)

    then (1.1)-(1.2) possesses no weak solution.

    Remark 1.1. Notice that (1.10) is equivalent to

    N2m<α,Ifm1>0; orN2m<β,Igm1>0, (1.11)

    where

    α=a+2m+p(b+2m)pq1 (1.12)

    and

    β=b+2m+q(a+2m)pq1. (1.13)

    On the other hand, due to the condition a,b2m and (a,b)(2m,2m), we have α,β>0, which shows that, if N2m, then (1.10) is always satisfied.

    The proof of Theorem 1.1 is based on the construction of a suitable admissible test function and integral estimates. The construction of the admissible test function is specifically adapted to the polyharmonic operator (Δ)m, the geometry of the domain, and the Navier-type boundary conditions (1.2).

    Remark 1.2. By Theorem 1.1, we recover the nonexistence result obtained in [10] in the case m=1. We also recover the nonexistence result obtained in [11] in the case m=2.

    Next, we are concerned with the existence of solutions to (1.1)-(1.2). Our second main result shows the sharpness of condition (1.10).

    Theorem 1.2. Let p,q>1 and a,b2m with (a,b)(2m,2m). If

    N2m>max{α,β}, (1.14)

    where α and β are given by (1.12) and (1.13), then (1.1)-(1.2) admits stationary solutions for some fi,giL1(B1) (i=0,,m1) with Ifm1,Igm1>0.

    Theorem 1.2 will be proved by the construction of explicit stationary solutions to (1.1)-(1.2).

    Remark 1.3. At this moment, we don't know whether there is existence or nonexistence in the critical case N2m+1,

    N=max{sign(Ifm1)×2mp(q+1)+pb+apq1,sign(Igm1)×2mq(p+1)+qa+bpq1}.

    This question is left open.

    From Theorem 1.1, we deduce the following nonexistence result for the corresponding stationary polyharmonic system

    {(Δ)mu|x|a|v|p,xRN¯B1,(Δ)mv|x|b|u|q,xRN¯B1, (1.15)

    under the Navier-type boundary conditions

    {(Δ)iufi(x),i=0,,m1,xB1,(Δ)ivgi(x),i=0,,m1,xB1. (1.16)

    Corollary 1.1. Let p,q>1, N2, and a,b2m with (a,b)(2m,2m). Let fi,giL1(B1) for every i=0,,m1. Assume that Ifm1,Igm10 and (Ifm1,Igm1)(0,0). If N2m; or N2m+1 and (1.10) holds, then (1.15)-(1.16) possesses no weak solution.

    The rest of this manuscript is organized as follows: Section 2 is devoted to some auxiliary results. Namely, we first construct an admissible test function in the sense of Definition 1.1. Next, we establish some useful integral estimates involving the constructed test function. The proofs of Theorems 1.1 and 1.2 are provided in Section 3.

    Throughout this paper, the letter C denotes a positive constant that is independent of the scaling parameters T, τ, and the solution (u,v). The value of C is not necessarily the same from one line to another.

    In this section, we establish some auxiliary results that will be used later in the proof of our main result.

    Let us introduce the radial function H defined in RNB1 by

    H(x)={ln|x|ifN=2,1|x|2NifN3. (2.1)

    We collect below some useful properties of the function H.

    Lemma 2.1. The function H satisfies the following properties:

    (i) H0;

    (ii) HC2m(RNB1);

    (iii) H|B1=0;

    (iv) ΔH=0 in RNB1;

    (v) For all j1,

    ΔjH|B1=(ΔjH)ν|B1=0;

    (vi) Hν|B1=C.

    Proof. (ⅰ)–(ⅴ) follow immediately from (2.1). On the other hand, we have

    Hν|B1={1ifN=2,(N2)ifN3,

    which proves (ⅵ).

    We next consider a cut-off function ξC(R) satisfying the following properties:

    0ξ1,ξ(s)=1 if |s|1,ξ(s)=0 if |s|2. (2.2)

    For all τ1, let

    ξτ(x)=ξ(|x|τ),xRNB1,

    that is (from (2.2)),

    ξτ(x)={1if1|x|τ,ξ(|x|τ)ifτ|x|2τ,0if|x|2τ. (2.3)

    For k1, we introduce the function

    ζτ(x)=H(x)ξkτ(x),xRNB1. (2.4)

    We now introduce a second cut-off function GC(R) satisfying the following properties:

    G0,supp(G)⊂⊂(0,1). (2.5)

    For T>0 and k1, let

    GT(t)=Gk(tT),t0. (2.6)

    Let φ be the function defined by

    φ(t,x)=GT(t)ζτ(x),(t,x)Q. (2.7)

    By Lemma 2.1, (2.3)–(2.7), we obtain the following result.

    Lemma 2.2. The function φ belongs to Φ.

    For all λ>1, μ2m, and φΦ, we consider the integral terms

    J(λ,μ,φ)=Q|x|μλ1φ1λ1|(Δ)mφ|λλ1dxdt (2.8)

    and

    K(λ,μ,φ)=Q|x|μλ1φ1λ1|φtt|λλ1dxdt. (2.9)

    Lemma 2.3. Let φ be the admissible test function defined by (2.7). Assume that

    (i) J(p,a,φ),J(q,b,φ),K(p,a,φ),K(q,b,φ)<;

    (ii) Ifm1,Igm10.

    If (u,v) is a weak solution to (1.1)-(1.2), then

    Ifm1CT1([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)ppq1([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)pqpq1 (2.10)

    and

    Igm1CT1([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)qpq1([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)pqpq1. (2.11)

    Proof. Let (u,v) be a weak solution to (1.1)-(1.2) and φ be the admissible test function defined by (2.7). By (1.8), we have

    Q|x|a|v|pφdxdtm1i=0ΣQfi(x)((Δ)m1iφ)νdσdtQu(Δ)mφdxdt+Quφttdxdt.

    On the other hand, by Lemma 2.1: (ⅴ), (ⅵ), (2.5)–(2.7), we have

    m1i=0ΣQfi(x)((Δ)m1iφ)νdσdt=ΣQfm1(x)φνdσdt=CΣQfm1(x)GT(t)dσdt=C(0GT(t)dt)B1fm1(x)dσ=C(0Gk(tT)dt)Ifm1=CT(10Gk(s)ds)Ifm1=CTIfm1.

    Consequently, we obtain

    Q|x|a|v|pφdxdt+CTIfm1Qu(Δ)mφdxdt+Quφttdxdt. (2.12)

    Similarly, by (1.9), we obtain

    Q|x|b|u|qφdxdt+CTIgm1Qv(Δ)mφdxdt+Qvφttdxdt. (2.13)

    Furthermore, by Hölder's inequality, we have

    Qu(Δ)mφdxdtQ|u||(Δ)mφ|dxdt=Q(|x|bq|u|φ1q)(|x|bq|(Δ)mφ|φ1q)dxdt(Q|x|b|u|qφdxdt)1q(Q|x|bq1|(Δ)mφ|qq1φ1q1dxdt)q1q,

    that is,

    Qu(Δ)mφdxdt(Q|x|b|u|qφdxdt)1q[J(q,b,φ)]q1q. (2.14)

    Similarly, we obtain

    Quφttdxdt(Q|x|b|u|qφdxdt)1q[K(q,b,φ)]q1q. (2.15)

    Thus, it follows from (2.12), (2.14), and (2.15) that

    Q|x|a|v|pφdxdt+CTIfm1(Q|x|b|u|qφdxdt)1q([J(q,b,φ)]q1q+[K(q,b,φ)]q1q). (2.16)

    Using (2.13) and proceeding as above, we obtain

    Q|x|b|u|qφdxdt+CTIgm1(Q|x|a|v|pφdxdt)1p([J(p,a,φ)]p1p+[K(p,a,φ)]p1p). (2.17)

    Using (2.16)-(2.17), and taking into consideration that Igm10, we obtain

    Q|x|a|v|pφdxdt+CTIfm1(Q|x|a|v|pφdxdt)1pq([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)1q([J(q,b,φ)]q1q+[K(q,b,φ)]q1q).

    Then, by Young's inequality, it holds that

    Q|x|a|v|pφdxdt+CTIfm11pqQ|x|a|v|pφdxdt+pq1pq([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)pqq(pq1)([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)pqpq1.

    Consequently, we have

    (11pq)Q|x|a|v|pφdxdt+CTIfm1pq1pq([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)ppq1([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)pqpq1,

    which yields (2.10). Similarly, using (2.16)-(2.17), and taking into consideration that Ifm10, we obtain

    Q|x|b|u|qφdxdt+CTIgm1(Q|x|b|u|qφdxdt)1pq([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)1p([J(p,a,φ)]p1p+[K(p,a,φ)]p1p),

    which implies by Young's inequality that

    Q|x|b|u|qφdxdt+CTIgm11pqQ|x|b|u|qφdxdt+pq1pq([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)pqp(pq1)([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)pqpq1.

    Thus, it holds that

    (11pq)Q|x|b|u|qφdxdt+CTIgm1pq1pq([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)qpq1([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)pqpq1,

    which yields (2.11).

    The aim of this subsection is to estimate the integral terms J(λ,μ,φ) and K(λ,μ,φ), where λ>1, μ2m, and φ is the admissible test function defined by (2.7) with τ,k1.

    The following result follows immediately from (2.5) and (2.6).

    Lemma 2.4. We have

    0GT(t)dt=CT.

    Lemma 2.5. We have

    0G1λ1T|d2GTdt2|λλ1dtCT12λλ1. (2.18)

    Proof. By (2.5) and (2.6), we have

    0G1λ1T|d2GTdt2|λλ1dt=T0G1λ1T|d2GTdt2|λλ1dt (2.19)

    and

    d2GTdt2(t)=kT2Gk2(tT)((k1)G2(tT)+G(tT)G(tT))

    for all t(0,T). The above inequality yields

    |d2GTdt2(t)|CT2Gk2(tT),t(0,T),

    which implies that

    G1λ1T|d2GTdt2|λλ1CT2λλ1Gk2λλ1(tT),t(0,T).

    Then, by (2.19), it holds that

    0G1λ1T|d2GTdt2|λλ1dtCT2λλ1T0Gk2λλ1(tT)dt=CT12λλ110Gk2λλ1(s)ds=CT12λλ1,

    which proves (2.18).

    To estimate J(λ,μ,φ) and K(λ,μ,φ), we consider separately the cases N3 and N=2.

    Lemma 2.6. We have

    RNB1|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dxCτNμ+2mλλ1. (2.20)

    Proof. Since H and ξτ are radial functions (see (2.1) and (2.3)), to simplify writing, we set

    H(x)=H(r),ξτ(x)=ξτ(r),

    where r=|x|. By (2.4) and making use of Lemma 2.1 (ⅳ), one can show that for all xRNB1, we have

    Δmζτ(x)=Δm(H(x)ξkτ(x))=2m1i=0diHdri(r)2mij=1Ci,jdjξkτdrj(r)ri+j2m,

    where Ci,j are some constants, which implies by (2.3) that

    supp(Δmζτ){xRN:τ|x|2τ} (2.21)

    and

    |Δmζτ(x)|C2m1i=0|diHdri(r)|2mij=1|djξkτdrj(r)|ri+j2m,xsupp(Δmζτ). (2.22)

    On the other hand, for all xsupp(Δmζτ), we have by (2.1) and (2.3) that

    |diHdri(r)|={H(r)ifi=0,Cr2Niifi=1,,2m1 (2.23)

    and (we recall that 0ξτ1)

    |djξkτdrj(r)|Cτjξkjτ(r)Cτjξk2mτ(r),j=1,,2mi. (2.24)

    Then, in view of (2.1), (2.21)–(2.24), we have

    |Δmζτ(x)|Cξk2mτ(r)(H(r)2mj=1τjrj2m+r2N2m1i=12mij=1τjrj2m)Cξk2mτ(r)(τ2m+τ2N2m)Cτ2mξk2mτ(x)

    for all xsupp(Δmζτ). Taking into consideration that HC for all xsupp(Δmζτ), the above estimate yields

    |x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1Cτ2mλμλ1ξk2mλλ1τ(x),xsupp(Δmζτ). (2.25)

    Finally, by (2.21) and (2.25), we obtain

    RNB1|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dx=τ<|x|<2τ|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dxCτ2mλμλ1τ<|x|<2τξk2mλλ1τ(x)dxCτ2mλμλ12τr=τrN1dr=CτNμ+2mλλ1,

    which proves (2.20).

    Lemma 2.7. We have

    J(λ,μ,φ)CTτNμ+2mλλ1.

    Proof. By (2.7) and (2.8), we have

    J(λ,μ,φ)=(0GT(t)dt)(RNB1|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dx).

    Then, using Lemmas 2.4 and 2.6, we obtain the desired estimate.

    Lemma 2.8. We have

    RNB1|x|μλ1ζτ(x)dxC(τNμλ1+lnτ). (2.26)

    Proof. By (2.1)–(2.4), we have

    RNB1|x|μλ1ζτ(x)dx=1<|x|<2τ|x|μλ1(1|x|2N)ξκ(|x|τ)dx1<|x|<2τ|x|μλ1dx=C2τr=1rN1μλ1dr{CτNμλ1ifNμλ1>0,[4pt]ClnτifNμλ1=0,[4pt]CifNμλ1<0C(τNμλ1+lnτ),

    which proves (2.26).

    Lemma 2.9. We have

    K(λ,μ,φ)CT12λλ1(τNμλ1+lnτ).

    Proof. By (2.7) and (2.9), we have

    K(λ,μ,φ)=(0G1λ1T|d2GTdt2|λλ1dt)(RNB1|x|μλ1ζτ(x)dx).

    Then, using Lemmas 2.5 and 2.7, we obtain the desired estimate.

    Lemma 2.10. We have

    R2B1|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dxCτ22mλ+μλ1lnτ. (2.27)

    Proof. Proceeding as in the proof of Lemma 2.6, we obtain

    supp(Δmζτ){xR2:τ|x|2τ}

    and

    |Δmζτ(x)|Cτ2mlnτξk2mτ(x),xsupp(Δmζτ).

    The above estimate yields

    |x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1Cτ2mλμλ1lnτξk2mλλ1τ(x),xsupp(Δmζτ).

    Then, it holds that

    R2B1|x|μλ1ζ1λ1τ|(Δ)mζτ|λλ1dxCτ2mλμλ1lnττ<|x|<2τξk2mλλ1τ(x)dxCτ2mλμλ1lnτ2τr=τrdrCτ22mλ+μλ1lnτ,

    which proves (2.27).

    Using (2.7)-(2.8), Lemma 2.4, and Lemma 2.10, we obtain the following estimate of J(λ,μ,φ).

    Lemma 2.11. We have

    J(λ,μ,φ)CTτ22mλ+μλ1lnτ.

    Lemma 2.12. We have

    R2B1|x|μλ1ζτ(x)dxClnτ(τ2μλ1+lnτ). (2.28)

    Proof. By (2.1)–(2.4), we have

    R2B1|x|μλ1ζτ(x)dx=1<|x|<2τ|x|μλ1ln|x|ξκ(|x|τ)dx1<|x|<2τ|x|μλ1ln|x|dx=C2τr=1r1μλ1lnrdr{Cτ2μλ1lnτif2μλ1>0,[4pt]C(lnτ)2if2μλ1=0,[4pt]Clnτif2μλ1<0Clnτ(τ2μλ1+lnτ),

    which proves (2.28).

    Using (2.7), (2.9), Lemma 2.5, and Lemma 2.12, we obtain the following estimate of K(λ,μ,φ).

    Lemma 2.13. We have

    K(λ,μ,φ)CT12λλ1lnτ(τ2μλ1+lnτ).

    This section is devoted to the proofs of Theorems 1.1 and 1.2.

    By Remark 1.1, (1.10) is equivalent to (1.11). Without restriction of the generality, we assume that

    N2m<α,Ifm1>0. (3.1)

    Indeed, exchanging the roles of (Ifm1,a,p) and (Igm1,b,q), the case

    N2m<β,Igm1>0

    reduces to (3.1).

    We use the contradiction argument. Namely, let us suppose that (u,v) is a weak solution to (1.1)-(1.2) (in the sense of Definition 1.2). For k,T,τ1, let φ be the admissible test function defined by (2.7). Then, by Lemma 2.3, we have

    Ipq1pfm1CTpq1p([J(p,a,φ)]p1p+[K(p,a,φ)]p1p)([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)q. (3.2)

    Making use of Lemmas 2.7 and 2.12, we obtain that for all N2,

    J(λ,μ,φ)CTτNμ+2mλλ1lnτ,λ>1,μ2m. (3.3)

    Similarly, by Lemmas 2.9 and 2.13, we obtain that for all N2,

    K(λ,μ,φ)CT12λλ1(τNμλ1+lnτ)lnτ,λ>1,μ2m. (3.4)

    In particular, for (λ,μ)=(p,a), we obtain by (3.3) and (3.4) that

    [J(p,a,φ)]p1p+[K(p,a,φ)]p1pC[Tp1pτ(Na+2mpp1)p1p(lnτ)p1p+T(12pp1)p1p(τNap1+lnτ)p1p(lnτ)p1p]=CTp1pτ(Na+2mpp1)p1p(lnτ)p1p[1+T2(τ2mpp1+τ(Na+2mpp1)lnτ)p1p]. (3.5)

    Furthermore, taking T=τθ, where

    θ>max{m,(a+2mpp1N)p1p}, (3.6)

    we obtain

    1+T2(τ2mpp1+τ(Na+2mpp1)lnτ)p1pC.

    Then, from (3.5), we deduce that

    [J(p,a,φ)]p1p+[K(p,a,φ)]p1pC[τθ+Na+2mpp1lnτ]p1p. (3.7)

    Similarly, for

    θ>max{m,(b+2mqq1N)q1q}, (3.8)

    we obtain

    ([J(q,b,φ)]q1q+[K(q,b,φ)]q1q)qC[τθ+Nb+2mqq1lnτ]q1. (3.9)

    Thus, for T=τθ, where θ satisfies (3.6) and (3.8), we obtain by (3.2), (3.7), and (3.9) that

    Ipq1pfm1Cτθ(pq1)p[τθ+Na+2mpp1lnτ]p1p[τθ+Nb+2mqq1lnτ]q1,

    that is,

    Ipq1pfm1Cτδ(lnτ)pq1p, (3.10)

    where

    δ=pq1p[N(b+2mq)p+a+2mppq1]=pq1p(N2mα).

    Since N2m<α, we have δ<0. Then, passing to the limit as τ in (3.10), we reach a contradiction with Ifm1>0. This completes the proof of Theorem 1.1.

    Let us introduce the family of polynomial functions {Pi}0im, where

    Pi(z)={1ifi=0,i1j=0(z+2j)ij=1(N2jz)ifi=1,,m.

    From (1.14), we deduce that

    N2j>max{α,β},j=1,,m.

    Furthermore, because a,b2m and (a,b)(2m,2m), we have α,β>0. Then,

    Pi(z)>0,i=0,1,,m,z{α,β}. (3.11)

    For all

    0<εmin{[Pm(α)]1p1,[Pm(β)]1q1}, (3.12)

    we consider functions of the forms

    uε(x)=ε|x|α,xRNB1 (3.13)

    and

    vε(x)=ε|x|β,xRNB1. (3.14)

    Since uε and vε are radial functions, elementary calculations show that

    (Δ)iuε(x)=εPi(α)|x|α2i,i=0,1,,m,xRNB1 (3.15)

    and

    (Δ)ivε(x)=εPi(β)|x|β2i,i=0,1,,m,xRNB1. (3.16)

    Taking i=m in (3.15), using (3.11)–(3.14), we obtain

    (Δ)muε(x)=εPm(α)|x|α2m=|x|aεp|x|βp(ε1pPm(α)|x|α2ma+βp)|x|avpε(x)|x|α2ma+βp.

    On the other hand, by (1.12) and (1.13), one can show that

    α2ma+βp=0.

    Then, we obtain

    (Δ)muε(x)|x|avpε(x),xRNB1. (3.17)

    Similarly, taking m=i in (3.16), using (3.11)–(3.14), we obtain

    (Δ)mvε(x)=εPm(β)|x|β2m=|x|bεq|x|αq(ε1qPm(β)|x|β2mb+αq)|x|buqε(x)|x|β2mb+αq.

    Using that

    β2mb+αq=0,

    we obtain

    (Δ)mvε(x)|x|buqε(x),xRNB1. (3.18)

    Furthermore, by (3.11) and (3.15), for all i=0,,m1, we have

    (Δ)iuε(x)=εPi(α)>0,xB1. (3.19)

    Similarly, by (3.11) and (3.16), for all i=0,,m1, we have

    (Δ)ivε(x)=εPi(β)>0,xB1. (3.20)

    Finally, (3.17)–(3.20) show that for all ε satisfying (3.12), the pair of functions (uε,vε) given by (3.13) and (3.14) is a stationary solution to (1.1)-(1.2) with fiεPi(α) and giεPi(β) for all i=0,,m1. The proof of Theorem 1.2 is then completed.

    The system of polyharmonic wave inequalities (1.1) under the inhomogeneous Navier-type boundary conditions (1.2) was investigated. First, we established a nonexistence criterium for the nonexistence of weak solutions (see Theorem 1.1). Namely, under condition (1.10), we proved that (1.1)-(1.2) possesses no weak solution, provided Ifm1,Igm10 and (Ifm1,Igm1)(0,0). Next, we proved the sharpness of the obtained criterium (1.10) by showing that under condition (1.14), (1.1)-(1.2) possesses weak solutions (stationary solutions) for some fi,giL1(B1) (i=0,,m1) with Ifm1,Igm1>0 (see Theorem 1.2). From Theorem 1.1, we deduced an optimal criterium for the nonexistence of weak solutions to the corresponding stationary polyharmonic system (1.15) under the Navier-type boundary conditions (1.16) (see Corollary 1.1).

    In this study, the critical case N2m+1,

    N=max{sign(Ifm1)×2mp(q+1)+pb+apq1,sign(Igm1)×2mq(p+1)+qa+bpq1}

    is not investigated. It would be interesting to know whether there is existence or nonexistence of weak solutions in this case.

    Manal Alfulaij: validation, investigation, writing review and editing; Mohamed Jleli: Conceptualization, methodology, investigation and formal analysis; Bessem Samet: Conceptualization, methodology, validation and investigation. All authors have read and approved the final version of the manuscript for publication.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    Mohamed Jleli is supported by Researchers Supporting Project number (RSP2024R57), King Saud University, Riyadh, Saudi Arabia.

    The authors declare no conflicts of interest.



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