In this paper, we study the following biharmonic elliptic equation in RN:
Δ2ψ−Δψ+P(x)ψ=g(x,ψ), x∈RN,
where g and P are periodic in x1,⋯,xN, g(x,ψ) is subcritical and odd in ψ. Without assuming the Ambrosetti-Rabinowitz condition, we prove the existence of infinitely many geometrically distinct solutions for this equation, and the existence of ground state solutions is established as well.
Citation: Dengfeng Lu, Shuwei Dai. On existence results for a class of biharmonic elliptic problems without (AR) condition[J]. AIMS Mathematics, 2024, 9(7): 18897-18909. doi: 10.3934/math.2024919
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In this paper, we study the following biharmonic elliptic equation in RN:
Δ2ψ−Δψ+P(x)ψ=g(x,ψ), x∈RN,
where g and P are periodic in x1,⋯,xN, g(x,ψ) is subcritical and odd in ψ. Without assuming the Ambrosetti-Rabinowitz condition, we prove the existence of infinitely many geometrically distinct solutions for this equation, and the existence of ground state solutions is established as well.
In the present paper, we consider the following biharmonic elliptic equation with potential:
{Δ2ψ−Δψ+P(x)ψ=g(x,ψ) in RN,ψ(x)∈H2(RN), | (1.1) |
where Δ2 is the biharmonic operator. We assume that P(x) and g(x,ψ) satisfy the hypotheses below:
(P)P(x)∈C(RN,R) is 1-periodic in each of xi,1≤i≤N, and infx∈RNP(x)≥a0>0.
(g1)g(x,t)∈C(RN×R,R) is 1-periodic in each of xi,1≤i≤N, and there exists a1>0 such that |g(x,t)|≤a1(1+|t|q−1) for 2<q<2∗, where 2∗=2NN−4 if N>4, 2∗=+∞ if N≤4.
(g2)lim|t|→0g(x,t)t=0 uniformly for x∈RN.
(g3)lim|t|→+∞G(x,t)t2=+∞ uniformly for x∈RN, where G(x,ψ)=∫ψ0g(x,t)dt.
(g4)g(x,t)t is strictly increasing on (−∞,0) and on (0,+∞).
Problem (1.1) is usually used to describe some phenomena appearing in different physical, engineering and other sciences. Over the course of the last decades, plenty of results for the biharmonic elliptic equations have been presented. When Ω⊂RN(N>4) is a smooth bounded domain, the problem
{Δ2ψ+aΔψ=g(x,ψ),x∈Ω,ψ=Δψ=0,x∈∂Ω, | (1.2) |
arising in the study of traveling waves in suspension bridges (see for instance, [2,8,9,15]) and the study of the static deflection of an elastic plate in a fluid, has drawn a great deal of attention, see for example, [1,3,7,11,12,13,14,23] and the references therein. Furthermore, biharmonic elliptic problems on the whole space RN also attract a lot of attention, see [4,5,10,21,22,24,25]. It is worth noticing that in the paper by Yin and Wu [22], a sequence of high energy solutions to problem (1.1) has been established by using variational methods. Later, based on Rabinowitz's symmetric mountain pass theorem, Ye and Tang extended the results in [21] to a more generic conditions, and obtained similar results. Subsequently, Zhang et al. [24] obtained the existence of infinitely many solutions by applying the genus properties in critical point theory.
Resting on the different assumptions (g1)−(g4) from those applied previously, our paper states some new existence results of problem (1.1) and, meanwhile, we do not assume the Ambrosetti-Rabinowitz condition ((AR) in short):
(AR) there is μ>2 such that 0<μG(x,ψ)≤g(x,ψ)ψ for ψ≠0 and x∈RN.
It is noticeable that the (AR) condition is to ensure the boundedness of the Palais-Smale sequences of the corresponding functional, which is very essential in applying the critical point theory. It would be more complicated for this problem without (AR) condition. However, there are numerous functions superlinear at infinity not satisfying the (AR) condition for any μ>2. Virtually, the (AR) condition implies that G(x,ψ)≥c1|ψ|μ−c2 for some c1,c2>0. Thus, for example the superlinear function
g(x,ψ)=a(x)ψln(1+|ψ|), where a(x)>0 is 1-periodic in xi,1≤i≤N, |
does not satisfy (AR) condition. But it satisfies our conditions (g1)−(g4).
To state our results, we need to present some notations. For y=(y1,⋯,yN)∈ZN, the action of ZN on H2(RN) is given by
τyψ(x)=ψ(x−y), y∈ZN. | (1.3) |
It follows from (P) and (g1) that if ψ0 is a solution of (1.1), then so is τyψ0 for all y∈ZN. Set O(ψ0)={τyψ0:y∈ZN}. Two solutions ψ1,ψ2 of (1.1) are regarded as geometrically distinct if O(ψ1)≠O(ψ2).
The main results of this paper are the following:
Theorem 1.1. Assume that P(x) satisfies (P), and g(x,ψ) satisfies (g1)−(g4). Then the Eq (1.1) has at least one ground state solution.
In our next result, we verify the existence of infinitely many solutions for (1.1) if g(x,t) is an odd function about t. More specifically, we suppose
(g5)g(x,−t)=−g(x,t) for all (x,t)∈RN×R.
Theorem 1.2. Assume that P(x) satisfies (P), and g(x,ψ) satisfies (g1)−(g5). Then problem (1.1) has infinitely many pairs ±ψ of geometrically distinct solutions.
The paper is organized as follows. In Section 2, some preliminary results for proving our main results are presented, and the fact that problem (1.1) has a ground state solution is proved. Section 3 is devoted to the proof of Theorem 1.2.
First, let us set some notations to be used in this paper. Lr(RN)(1≤r<+∞) denotes Lebesgue space, the usual norm of Lr(RN) is denoted by ‖⋅‖r for 1≤r<+∞. Let
E={ψ∈H2(RN):∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx<+∞}, |
then E is a Hilbert space with the inner product
⟨ψ,v⟩E=∫RN(ΔψΔv+∇ψ∇v+P(x)ψv)dx, |
and the induced norm is denoted by ‖ψ‖=√⟨ψ,ψ⟩E. Note that the following embedding is continuous:
E↪Lr(RN) (2≤r<2∗), |
consequently, for each r∈[2,2∗), there exists a constant ar>0 such that
‖ψ‖r≤ar‖ψ‖, ∀ ψ∈E. | (2.1) |
The dual space of a space E will be denoted by E−1 and S is the unit sphere in E, that is
S={ψ∈E:‖ψ‖=1}. |
The corresponding energy functional of problem (1.1) is defined on E by
E(ψ)=12∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx−∫RNG(x,ψ)dx, | (2.2) |
where G(x,ψ)=∫ψ0g(x,t)dt. Under the assumptions (g1)−(g4) and (P), we can easily check that E(ψ)∈C1(E,R) and
⟨E′(ψ),v⟩=∫RN(ΔψΔv+∇ψ∇v+P(x)ψv)dx−∫RNg(x,ψ)vdx, | (2.3) |
for all ψ,v∈E. Thus, solutions to problem (1.1) can be obtained as the critical points of the functional E(ψ). We consider the Nehari manifold
M={ψ∈E∖{0}:⟨E′(ψ),ψ⟩=0}, |
and let
c∗=infψ∈ME(ψ). |
Note that M contains every nonzero solution of problem (1.1). For t>0, we consider the fibering maps ϕψ:t→E(tψ) defined by
ϕψ(t)=E(tψ)=t22∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx−∫RNG(x,tψ)dx. |
Now we have the following lemma. Hereafter, we suppose that (P) and (g1)−(g4) are satisfied.
Lemma 2.1. (i) For each ψ∈E∖{0}, there is a unique tψ>0 such that ϕ′ψ(t)>0 for 0<t<tψ and ϕ′ψ(t)<0 for t>tψ. Moreover, tψ∈M if and only if t=tψ.
(ii) There exists ρ>0 such that c∗≥infψ∈SρE(ψ)>0, where Sρ={ψ∈E:‖ψ‖=ρ}.
(iii) For all ψ∈M, there holds ‖ψ‖≥√2c∗.
(iv) For all ψ∈M, there holds E(ψ)→∞ as ‖ψ‖→∞.
Proof. (i) First, we claim that ϕψ(t)>0 for t>0 small. Indeed, the conditions (g1) and (g2) imply that for any ε>0, there exists Cε>0 such that, for all (x,ψ)∈RN×R, there hold
|g(x,ψ)|≤ε|ψ|+Cε|ψ|q−1, |G(x,ψ)|≤ε|ψ|2+Cε|ψ|q. | (2.4) |
Then, by (2.4) and the Sobolev embedding theorem, for ε>0 sufficiently small, we obtain
ϕψ(t)≥t22∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx−εt22∫RN|ψ|2dx−Cεtqq∫RN|ψ|qdx≥t22‖ψ‖2−t22εC1‖ψ‖2−tqqCεC2‖ψ‖q, |
since q>2, ϕψ(t)>0 whenever t>0 is small enough.
On the other hand, we have
ϕψ(t)=t22∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx−∫RNG(x,tψ)dx=t2(12‖ψ‖2−∫RNG(x,tψ)(tψ)2⋅ψ2dx). |
By (g3) and Fatou's lemma, one has
∫RNG(x,tψ)(tψ)2⋅ψ2dx→+∞ (t→+∞). |
Hence ϕψ(t)→−∞ as t→+∞ and maxt>0ϕψ(t) is achieved at a t=tψ>0. In addition, the condition ϕ′ψ(t)=0 is equivalent to
∫RN(|Δψ|2+|∇ψ|2+P(x)ψ2)dx=∫RNg(x,tψ)tψ⋅ψ2dx. |
By (g4), the function g(x,t)t is strictly increasing for t>0, so there exists a unique tψ>0 such that ϕ′ψ(tψ)=0. On the other hand, we note that
ϕ′ψ(t)=t−1⟨E′(tψ),tψ⟩. |
Therefore, tψ∈M if and only if t=tψ.
(ii) For ψ∈E, we have
E(ψ)=12‖ψ‖2−∫RNG(x,ψ)dx, |
and thus by (2.3) there holds
∫RNG(x,ψ)dx=o(‖ψ‖2) as ψ→0, |
hence infψ∈SρE(ψ)>0 if ρ>0 is sufficiently small. The inequality infψ∈ME(ψ)≥infψ∈SρE(ψ) is a consequence of (i), since for every ψ∈M there exists t>0 such that tψ∈Sρ, and E(tψψ)≥E(tψ).
(iii) Note that by using (g2) and (g4), we can get
G(x,ψ)≥0, g(x,ψ)ψ≥2G(x,ψ), ∀ ψ≠0. | (2.5) |
Then by the definition of c∗ and (2.5), for ψ∈M one has
c∗≤12‖ψ‖2−∫RNG(x,ψ)dx≤12‖ψ‖2, |
hence ‖ψ‖≥√2c∗.
(iv) Arguing by contradiction, suppose there exists a sequence {ψm}⊂M such that ‖ψm‖→∞ and E(ψm)≤d for some d>0. Let vm=ψm‖ψm‖. Then {vm} is bounded (‖vm‖=1) in E, after passing to a subsequence, if necessary, we may assume that vm⇀v in E and vm(x)→v(x) a.e. in RN. Choose ym∈RN to satisfy
∫B1(ym)v2mdx=maxy∈RN∫B1(y)v2mdx. |
Since E and M are invariant with respect to the action of ZN given by (1.3), we may assume translating vm, if necessary, that {ym} is bounded in RN. If
limm→∞∫B1(ym)v2mdx=0, | (2.6) |
according to P. L. Lions' vanishing lemma (see [20], Lemma 1.21), we get vm→0 in Lr(RN) for 2<r<2∗. By (2.4), fixing an s>√2c∗ and using the Lebesgue dominated convergence theorem, we have
limm→∞∫RNG(x,svm)dx=∫RNlimm→∞G(x,svm)dx=0. |
Note that {ψm}⊂M, and then by Lemma 2.1, we obtain that
d≥E(ψm)≥E(svm)=s22‖vm‖2−∫RNG(x,svm)dx→s22, |
which is a contradiction for s>√2d. Hence (2.6) cannot hold, and then vm→v≠0 in L2loc(RN). Since |ψm(x)|→∞ if v(x)≠0, then by (g3) and Fatou's lemma, we have
∫RNG(x,ψm)ψ2mv2mdx→+∞ (m→∞), |
and therefore
0≤E(ψm)‖ψm‖2=12‖vm‖2−∫RNG(x,ψm)ψ2mv2mdx→−∞, |
as m→∞, which is a contradiction. This completes the proof.
Lemma 2.2. Let V be a compact subset of E∖{0}, then there exists R>0 such that E(ψ)<0 on (R+V)∖BR(0) for all ψ∈V, where R+V={tψ:t∈R+,ψ∈V}.
Proof. Without loss of generality, we may assume that V⊂S, i.e., ‖ψ‖=1 for every ψ∈V. Arguing by contradiction, suppose there exists ψm∈V and wm=tmψm such that E(wm)≥0 and tm→+∞ as m→∞. Passing to a subsequence, we may assume that ψm→ψ∈S. Note that |wm(x)|→∞ if ψ(x)≠0, then by (g3) and Fatou's lemma we have
∫RNG(x,wm)t2mdx=∫RNG(x,wm)w2mψ2mdx→+∞ (m→∞), |
and therefore
0≤E(wm)t2m=12−∫RNG(x,wm)t2mdx→−∞, |
which is a contradiction. This completes the proof.
Recall that S is the unit sphere in E, and define the mapping φ:S→M by setting
φ(w)=tww, |
where tw is the same as in Lemma 2.1 (i). Note that ‖φ(w)‖=tw.
Lemma 2.3. (i) The mapping φ is a homeomorphism between S and M, and the inverse of φ is given by φ−1(ψ)=ψ‖ψ‖.
(ii) The mapping φ−1 is Lipschitz continuous.
Proof. (i) See [19], Proposition 8.
(ii) For ψ,u∈M, by Lemma 2.1(iii), we have
‖φ−1(ψ)−φ−1(u)‖=‖ψ‖ψ‖−u‖u‖‖=‖ψ−u‖ψ‖+(‖u‖−‖ψ‖)u‖ψ‖‖u‖‖≤2‖ψ‖‖ψ−u‖≤√2c∗‖ψ−u‖, |
this implies that the mapping φ−1 is Lipschitz continuous.
Now we consider the functional I:S→R given by I(w)=E(φ(w)). Then we have
Lemma 2.4. (i) I∈C1(S,R) and
⟨I′(w),z⟩=‖φ(w)‖⟨E′(φ(w)),z⟩ for all z∈Tw(S)={u∈E:⟨w,u⟩=0}. |
(ii) If {wm} is a (PS) sequence for I, then {φ(wm)} is a (PS) sequence for E. If {ψm}⊂M is a bounded (PS) sequence for E, then {φ−1(ψm)} is a (PS) sequence for I.
(iii)
infψ∈SI(ψ)=infψ∈ME(ψ)=c∗. |
Moreover, w is a critical point of I if and only if φ(w) is a nontrivial critical point of E(ψ), and the corresponding critical values coincide.
(iv) If E(ψ) is even, then I(ψ) is also even.
Proof. The proof is entirely analogous to that of Corollary 10 in [19]. By Lemmas 2.1 and 2.3, it can be concluded that the hypotheses in [19] are satisfied. Indeed, if ϕw(t)=E(tw) and w∈S, then ϕ′w(t)>0 for 0<t<tw and ϕ′w(t)<0 for t>tw by Lemma 2.1(i), tw≥δ>0 by Lemma 2.1 (ii) and tw≤R for w∈V⊂S by Lemma 2.2.
Now we give the proof of Theorem 1.1.
Proof of Theorem 1.1. From the conclusion (ii) of Lemma 2.1, we know that c∗>0. Moreover, if ψ0∈M satisfies E(ψ0)=c∗, then φ−1(ψ0)∈S is a minimizer of I, and therefore a critical point of I, so that ψ0 is a critical point of E by Lemma 2.4. It remains to show that there exists a minimizer ψ of E|M. By Ekeland's variational principle [20], there exists a sequence {wm}⊂S such that
I(wm)→c∗ and I′(wm)→0 as m→∞. |
Set ψm=φ(wm)∈M for all m∈N. Then E(ψm)→c∗ and E′(ψm)→0 as m→∞. By Lemma 2.1(iv), we know that {ψm} is bounded and hence ψm⇀ψ after passing to a subsequence. Choose ym∈RN to satisfy
∫B1(ym)ψ2mdx=maxy∈RN∫B1(y)ψ2mdx. | (2.7) |
Since E and M are invariant with respect to the action of ZN given by (1.3), we may assume that {ym} is bounded in RN. If
limm→∞∫B1(ym)ψ2mdx=0, | (2.8) |
then by P. L. Lions' vanishing lemma, we have ψm→0 in Lr(RN) for 2<r<2∗. From (2.4) and the Sobolev embedding theorem, we infer that
∫RNg(x,ψm)ψmdx=o(‖ψm‖) as m→∞. |
Hence
o(‖ψm‖)=⟨E′(ψm),ψm⟩=‖ψm‖2−∫RNg(x,ψm)ψmdx=‖ψm‖2−o(‖ψm‖), |
and therefore ‖ψm‖→0, contrary to Lemma 2.1(iii). It follows that (2.8) cannot hold, and thus ψm⇀ψ≠0, E′(ψ)=0.
In the following we claim that E(ψ)=c∗. Notice that {ψm} is bounded, by (2.5) and Fatou's lemma we get that
c∗=lim infm→∞(E(ψm)−12⟨E′(ψm),ψm⟩)=lim infm→∞(∫RN(12g(x,ψm)ψm−G(x,ψm))dx)≥∫RN(12g(x,ψ)ψ−G(x,ψ))dx=E(ψ)−12⟨E′(ψ),ψ⟩=E(ψ). |
Hence E(ψ)≤c∗. On the other hand, by the definition of c∗ and note that ψ∈M, we have c∗≤E(ψ), so we obtain that E(ψ)=c∗. This completes the proof of Theorem 1.1.
We begin with the following lemma (see Lemma 2.13 in [18]).
Lemma 3.1. Let K={ψ∈S:I′(ψ)=0}, then α:=inf{‖ψ−w‖:ψ,w∈K,ψ≠w}>0.
As a consequence of Lemma 2.4, we see as Remark 2.12 of [18] that since φ,φ−1 are equivariant and E,I are invariant with respect to the action of ZN given by (1.3), there is a one-to-one correspondence between the critical orbits of E|M and I. Hence, the proof of Theorem 1.2 will be completed upon showing that I has infinitely many critical orbits. We shall proceed by contradiction. Namely let us suppose (to the contrary) that the set K only contains finitely many orbits.
Note that by Theorem 1.1 and Lemma 2.3, the set K is nonempty. Choose a subset J of K such that J=−J and each orbit O(ψ)⊂K has a unique representative in J. So we assume by contradiction that
J is a finite set. | (3.1) |
From now on, we assume that the nonlinearity g(x,t) is odd in t. For a functional F we put
Fd={ψ:F(ψ)≤d}, Fc={ψ:F(ψ)≥c}, Fdc={ψ:c≤F(ψ)≤d}. |
Lemma 3.2. Let d≥c∗. If {v1m}, {v2m}⊂Id are two Palais-Smale sequences for I, then
either ‖v1m−v2m‖→0 as m→∞ or lim supm→∞‖v1m−v2m‖≥ρ(d)>0, |
where ρ(d) depends on d but not on the particular choice of Palais-Smale sequences.
Proof. We put ψ1m:=φ(v1m) and ψ2m:=φ(v2m). By Lemma 2.4(ii), both sequences {ψ1m}, {ψ2m} are Palais-Smale sequences for E and since {ψ1m}, {ψ2m}⊂Ed, {ψ1m}, {ψ2m} are bounded. We consider two cases.
Case 1. For 2<q<2∗, ‖ψ1m−ψ2m‖q→0 as m→∞. From (g1) and (g2), it follows that for each ε>0 and m large enough, we have that
‖ψ1m−ψ2m‖2=⟨E′(ψ1m),ψ1m−ψ2m⟩−⟨E′(ψ2m),ψ1m−ψ2m⟩+∫RN[g(x,ψ1m)−g(x,ψ2m)](ψ1m−ψ2m)dx≤ε‖ψ1m−ψ2m‖+∫RN[ε(|ψ1m|+|ψ2m|)+Cε(|ψ1m|q−1+|ψ2m|q−1)](ψ1m−ψ2m)dx≤(1+C1)ε‖ψ1m−ψ2m‖+Dε‖ψ1m−ψ2m‖q, |
where ε>0 is arbitrary, and C1 does not depend on the choice of ε. Notice that ‖ψ1m−ψ2m‖q→0, therefore ‖ψ1m−ψ2m‖→0 and Lemma 3.1 implies
‖v1m−v2m‖=‖φ−1(ψ1m)−φ−1(ψ1m)‖→0 as m→∞. |
Case 2. For 2<q<2∗, ‖ψ1m−ψ2m‖q↛0 as m→∞. It can be concluded from Lemma 1.21 in [20] that there exists ε>0 and ym∈RN such that after passing to a subsequence,
∫B1(ym)(ψ1m−ψ2m)2dx=maxy∈RN∫B1(y)(ψ1m−ψ2m)2dx≥ε for all m. | (3.2) |
Since φ,φ−1 and E′,I′ are equivariant with respect to the action of ZN given by (1.3), we may assume that the sequence {ym} is bounded in RN. Passing to a subsequence once more, there exist ψ1,ψ2 and α1,α2 such that
ψ1m⇀ψ1, ψ2m⇀ψ2, ‖ψ1m‖→α1, ‖ψ2m‖→α2, |
and E′(ψ1)=E′(ψ2)=0. According to (3.2), ψ1≠ψ2 and by Lemma 2.1(iii),
√2c∗≤αi≤ν(d)<+∞,(i=1,2), where ν(d)=sup{‖ψ‖:ψ∈Ed∩M}. |
Suppose ψ1,ψ2≠0. Then ψ1,ψ2∈M and v1:=φ−1(ψ1)∈K, v2:=φ−1(ψ2)∈K,v1≠v2. Hence
lim infm→∞‖v1m−v2m‖=lim infm→∞‖ψ1m‖ψ1m‖−ψ2m‖ψ2m‖‖≥‖ψ1mα1−ψ2mα2‖=‖β1v1−β2v2‖, |
where
β1=‖ψ1‖α1≥√2c∗ν(d), β2=‖ψ2‖α2≥√2c∗ν(d). |
Since ‖v1‖=‖v2‖=1, it is easy to see from the inequalities above that
lim infm→∞‖v1m−v2m‖≥‖β1v1−β2v2‖≥min{β1,β2}‖v1−v2‖≥α√2c∗ν(d)>0, | (3.3) |
where α is the constant in Lemma 3.1. Hence, (3.3) implies that
lim infm→∞‖v1m−v2m‖≥ρ(d)>0. |
Now the case where either ψ1=0 or ψ2=0 remains to be considered. If ψ2=0, then ψ1≠0 and
lim infm→∞‖v1m−v2m‖=lim infm→∞‖ψ1m‖ψ1m‖−ψ2m‖ψ2m‖‖≥‖ψ1m‖α1≥√2c∗ν(d)>0. |
The case ψ1=0 is similar.
It is well known that I admits a pseudo-gradient vector field, i.e., there exists a Lipschitz continuous map H:S∖K→TS (see [17], p.86) such that
‖H(w)‖<2‖∇I(w)‖, ⟨H(w),∇I(w)⟩>12‖∇I(w)‖2, |
where TS denotes the tangent bundle of S. Moreover, seeing that I is even, we may assume H is odd. Let η:G→S∖K be the flow defined by the following Cauchy problem:
{ddtη(t,w)=−H(η(t,w)),η(0,w)=w, | (3.4) |
where
G={(t,w):w∈S∖K,T−(w)<t<T+(w)}, |
and (T−(w),T+(w)) is the maximal existence time for the trajectory t→η(t,w). Note that η is odd in w because H is odd, and t→I(η(t,w)) is strictly decreasing by the properties of a pseudo-gradient.
Remark 3.1. We note that by the same argument as Lemma 2.15 of [18], we can get: For w∈S, the limit limt→T+(w)η(t,w) exists and is a critical point of I.
Let A⊂S, δ>0 and define Uδ(A)={w∈S:dist(w,A)<δ}. Then we have
Lemma 3.3. Let Kd={ψ∈K:I(ψ)=d and I′(ψ)=0} and d≥c∗. Then for every δ>0 there exists ε=ε(δ)>0 such that there hold
(i) Id+εd−ε∩K=Kd.
(ii) limt→T+(w)I(η(t,w))<d−ε for all w∈Id+ε∖Uδ(Kd).
Proof. The proof is virtually identical to Lemma 2.16 in [18], and the details are omitted.
Now, we will prove the Theorem 1.2. For this purpose, we should first introduce the definition of genus.
Definition 3.1. For a closed symmetric set A that does not contain the origin, we define the Krasnoselskii genus of A, denoted γ(A), as the smallest integer k such that there exists an odd continuous mapping from A to Rk∖{0}. If there is no such mapping for any k, we define γ(A)=∞. Moreover, we set γ(∅)=0.
Proof of Theorem 1.2. Define
dk=inf{d∈R:γ(Id)≥k}, (k∈N). |
Then the dk are the numbers at which the sets Id change genus. It is noticeable that dk≤dk+1. Let k≥1 and set d=dk. By Lemma 3.1, Kd is either empty set or discrete set, hence γ(Kd)=0 or 1. By the continuity property of the genus, there exists δ>0 such that γ(¯Uδ(Kd))=γ(Kd), where δ<α2. For the δ, we can choose ε>0 such that the conclusions of Lemma 3.3 hold. Then for each w∈Id+ε∖Uδ(Kd) there exists t∈[0,T+(w)) such that I(η(t,w))<d−ε. Let ϱ=ϱ(w) be the infimum of the time for which I(η(t,w))≤d−ε, that is
ϱ(w)=inf{t∈[0,T+(w)):I(η(t,w))≤d−ε}. |
Since d−ε is not a critical value of I by Lemma 3.3, it is apparent that by the implicit function theorem, ϱ(w) is a continuous mapping and since I is even, ϱ(−w)=ϱ(w). Define a mapping h:Id+ε∖Uδ(Kd)→Id−ε by setting h(w):=η(ϱ(w),w). Then h is odd and continuous, so it can be derived from the properties of the genus and the definition of dk that
γ(Id+ε)≤γ(¯Uδ(Kd))+γ(Id−ε)≤γ(¯Uδ(Kd))+k−1=γ(Kd)+k−1. |
If γ(Kd)=0, then γ(Id+ε)≤k−1, contrary to the definition of dk, so γ(Kd)=1 and Kd≠∅. If dk+1=dk=d, then γ(Kd)>1 (see [16], Proposition 8.5). However, this is impossible, so we have dk+1>dk and Kdk≠∅ for all k≥1, hence there is an infinite sequence {±wk} of pairs of geometrically distinct critical points of I with I(wk)=dk, which is a contradiction to (3.1), and Theorem 1.2 is proved.
In this paper, we are interested in studying a class of biharmonic elliptic equations with potential functions. Our problem is more complicated by the fact that the classical (AR)-type condition is not assumed. We establish the existence results of ground state solutions for the biharmonic elliptic equation (1.1) by using the Nehari manifold method and critical point theories. Moreover, the existence of infinitely many geometrically distinct solutions for this equation is also investigated. We believe that the proposed approach in the present paper can also be applied to study other related equations and systems. An interesting question is whether similar results still hold for a class of biharmonic elliptic systems under the same conditions.
Dengfeng Lu: Investigation, Writing-original draft; Shuwei Dai: Writing-review & editing. The authors contributed equally to this paper. All authors have read and approved the final version of the manuscript for publication.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this paper.
The authors are grateful to the referees for their valuable comments and suggestions for improvement of the paper.
This work is partially supported by the fund from NSFC(12326408).
The authors declare that they have no competing interests.
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