The [p,q]-order of growth of solutions of the following linear differential equations (∗∗) is investigated,
f(k)+Ak−1(z)f(k−1)+⋯+A1(z)f′+A0(z)f=0,(∗∗)
where Ai(z) are analytic functions in the unit disc, i=0,1,...,k−1. Some estimations of [p,q]-order of growth of solutions of the equation (∗∗) are obtained when Aj(z) dominate the others coefficients near a point on the boundary of the unit disc, which is generalization of previous results from S. Hamouda.
Citation: Hongyan Qin, Jianren Long, Mingjin Li. On [p, q]-order of growth of solutions of linear differential equations in the unit disc[J]. AIMS Mathematics, 2021, 6(11): 12878-12893. doi: 10.3934/math.2021743
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The [p,q]-order of growth of solutions of the following linear differential equations (∗∗) is investigated,
f(k)+Ak−1(z)f(k−1)+⋯+A1(z)f′+A0(z)f=0,(∗∗)
where Ai(z) are analytic functions in the unit disc, i=0,1,...,k−1. Some estimations of [p,q]-order of growth of solutions of the equation (∗∗) are obtained when Aj(z) dominate the others coefficients near a point on the boundary of the unit disc, which is generalization of previous results from S. Hamouda.
For the following complex linear differential equation
f(k)+Ak−1(z)f(k−1)+⋯+A1(z)f′+A0(z)f=0, | (1.1) |
where Ai(z) are analytic in the unit disc Δ={z:|z|<1}, i=0,1,...,k−1, k≥2. For the properties of solutions of Eq (1.1), including growth, zero distribution and function space properties, many results have been obtained, for example [9,10,14,16,20,22,23,25] and therein references. In addition, the differential equations have wide applications in various science discipline, for example engineering, predator-prey equations, population growth and decay, Newton's law of cooling and so on, see [1,5,24,28,29] and therein references. This paper is mainly concerned with the growth of solution of the Eq (1.1). It has been widely noted that Bernal [4] firstly introduced the idea of iterated order to express the fast growth of solutions of (1.1). Since then, the iterated order of solutions of (1.1) is very interesting topic in the unit disc Δ, many results concerning iterated order of solutions of (1.1) in the unit disc are obtained, see [3,6,7,18,26]. In order to better estimate the fast growth of solutions of (1.1), [p,q]-order was introduced, and many results on [p,q]-order of solutions of (1.1) have been found by different researchers in Δ. For example, see [2,17,19,21,27].
To state our results, firstly, we assume that readers are familiar with the fundamental results and the standard notation of the Nevanlinna value distribution theory in the unit disc (see [12,13]). Secondly, we introduce some definitions, for all r∈[0,1), exp1r=er and expn+1r=exp(expnr), n∈N, and for all r∈(0,1), log1r=logr and logn+1r=log(lognr), n∈N. We also denote exp0r=r=log0r, exp−1r=log1r.
Definition 1. Let f be a meromorphic function in Δ, then the iterated n-order of f is defined by
σn(f)=¯limr→1−log+nT(r,f)−log(1−r), |
where log+1=log+x=max{logx,0}, log+n+1x=log+(log+nx). If f is an analytic in Δ, then its iterated n-order is defined by
σM,n(f)=¯limr→1−log+n+1M(r,f)−log(1−r), |
where M(r,f)=max|z|=r|f(z)|. For n=1,σM,1(f)=σM(f), σ1(f)=σ(f).
Suppose p and q are integers satisfying p≥q≥1. Then [p,q]-order is defined as follows.
Definition 2. Let f be a meromorphic function in Δ, then the [p,q]-order of f is defined by
σ[p,q](f)=¯limr→1−log+pT(r,f)−logq(1−r). |
If f is analytic in Δ, then its [p,q]-order is defined by
σM,[p,q](f)=¯limr→1−log+p+1M(r,f)−logq(1−r). |
Remark 1. [2] Let p and q be integers such that p≥q≥1, and f be an analytic function in Δ. The following two statements holds:
(ⅰ) If p=q, then σ[p,q](f)≤σM,[p,q](f)≤σ[p,q](f)+1.
(ⅱ) If p>q, then σ[p,q](f)=σM,[p,q](f).
Recently, Hamouda [11] considered the fast growing solutions of Eq (1.1) by using a new idea which A0 dominates the other coefficients near a point on the boundary of the unit disc, and obtained some results which improve and generalize results of Heittokangas et al. [15]. The following two results are proved.
Theorem 1.1. [11] Let A0(z),…,Ak−1(z) be analytic functions in Δ. If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that for any constant μ>0,
lim|z|→1−z∈γk−1∑j=1|Aj(z)|+1|A0(z)|(1−|z|)μ=0, |
then every nontrivial solution f(z) of (1.1) is of infinite order.
Theorem 1.2. [11] Let A0(z),…,Ak−1(z) be analytic functions in Δ. If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that
lim|z|→1−z∈γk−1∑j=1|Aj(z)|+1|A0(z)|expn{λ(1−|z|)μ}=0, |
where n≥1 is an integer, λ>0 is a real constant, then every nontrivial solution f(z) of (1.1) satisfies σn(f)=∞ and σn+1(f)≥μ.
A natural question is that how to character the [p,q]-order of growth of solutions of (1.1) under the similar conditions of Hamouda. Here, we study the problem and get the following results.
Theorem 1.3. Let A0(z),…,Ak−1(z) be analytic functions in Δ. If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 satisfying
lim|z|→1−z∈γk−1∑i=1|Ai(z)|+1|A0(z)|expp{λ(1−|z|)μ}<1, | (1.2) |
where λ>0 and μ>0 are two real constants, then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)≥μ.
Corollary 1. Let A0(z),…,Ak−1(z) be analytic functions in Δ. If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that for some constants 0≤β<α and any given ε(0<ε<∞), for z∈γ and |z|→1−, we have
|A0|≥expp{α(1−|z|)μ−ε} |
and
|Ai|≤expp{β(1−|z|)μ−ε},i=1,⋯,k−1, |
then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)≥μ.
In fact, by the assumptions and taking 0<λ<α−β, we can get
lim|z|→1−z∈γk−1∑i=1|Ai(z)|+1|A0(z)|expp{λ(1−|z|)μ}<1. |
Thus Corollary 1 is obtained by applying Theorem 1.3.
Theorem 1.4. Let A0(z),…,Ak−1(z) be analytic functions in Δ satisfying
max{σM,[p,q](Ai):i=1,⋯,k−1}≤σM,[p,q](A0)=μ, |
where μ∈(0,∞). If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that
lim|z|→1−z∈γk−1∏i=1eT(r,Ai)eT(r,A0)expp{λ(1−|z|)μ}<1, | (1.3) |
where λ>0 is a real constant, then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](A0).
Corollary 2. Let A0(z),…,Ak−1(z) be analytic functions in Δ satifying
max{σM,[p,q](Ai):i=1,⋯,k−1}≤σM,[p,q](A0)=μ, |
where μ∈(0,∞). If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that for some constants 0≤β<α and any given ε(0<ε<∞), for z∈γ and |z|→1−, we have
T(r,A0)≥expp−1{α(1−|z|)μ−ε} |
and
T(r,Ai)≤expp−1{β(1−|z|)μ−ε},i=1,⋯,k−1, |
then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](A0).
In fact, for any given ε(0<ε<μ), taking λ<α, for |z|→1− and z∈γ, we have
expp−1{λ(1−|z|)μ−ε}<o(expp−1{α(1−|z|)μ−ε}) |
and
expp−1{β(1−|z|)μ−ε}<o(expp−1{α(1−|z|)μ−ε}). |
From the condition of Corollary 2, we have
lim|z|→1−z∈γk−1∏i=1eT(r,Ai)eT(r,A0)expp{λ(1−|z|)μ−ε}=0<1,i=0,1,...,k−1. |
Thus Corollary 2 is obtained by applying Theorem 1.4.
In Theorems 1.3 and 1.4, the coefficient A0(z) is the dominant coefficient. A nature question: How to character [p,q]-order of growth of solutions of Eq (1.1) when As(z) dominates the other coefficients near a point on the boundary of the unit disc. Next, we study the growth of the solution of (1.1) when As(z) is the dominant coefficient, and get the following results.
Theorem 1.5. Let A0(z),…,Ak−1(z) be analytic functions in Δ. If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that for any μ>0, we have
lim|z|→1−z∈γ∏i≠seT(r,Ai)eT(r,As)(1−|z|)μ<1, | (1.4) |
then every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s−1), is of infinite order.
Theorem 1.6. Let A0(z),…,Ak−1(z) be analytic functions in Δ and there exists μ∈(0,∞) satisfying
max{σM,[p,q](Ai):i=0,1,⋯,s−1,s+1,⋯,k−1}≤σM,[p,q](As)=μ. |
If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that
lim|z|→1−z∈γ∏ieT(r,Ai)eT(r,As)expp{λ(1−|z|)μ}<1, | (1.5) |
where λ>0 is a real constant. Then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s−1), satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](As).
By Theorem 1.6 we can easily obtain the following Corollary 3.
Corollary 3. Let A0(z),…,Ak−1(z) be analytic functions in Δ and there exists μ∈(0,∞) satisfying
max{σM,[p,q](Ai):i=0,⋯,s−1,s+1,⋯,k−1}≤σM,[p,q](As)=μ. |
If there exists ω0∈∂Δ and a curve γ⊂Δ tending to ω0 such that for some constants 0≤β<α and any given ε(0<ε<∞), for z∈γ and |z|→1−, we have
T(r,As)≥expp−1{α(1−|z|)μ−ε} |
and
T(r,Ai)≤expp−1{β(1−|z|)μ−ε},i=0,⋯,s−1,s+1,⋯,k−1, |
then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s−1), satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](As).
Remark 2. The recent papers of Long et al. [20,22] and Sun et al. [25] discussed the function space properties of solutions of differential equation. Long et al. obtained analytic solutions of Eq (1.1) where k=2 belong to α−Bloch space and Morrey space and Sun et al. obtained analytic solutions of the nonlinear equations
f(k)+Ak−1(z)f(k−1)+⋯+A1(z)f′+A0(z)f=Ak(z) |
belong to in H∞Φ or Bα. However, the results of this paper is about growth of solutions of Eq (1.1). Obviously, The results of recent papers of Long et al. and Sun et al. and the results of this paper are not directly related to each other, but they are both properties of solutions of Eq (1.1).
Lemma 2.1. [8] Let k and j be integers satisfying k>j≥0, and let ε>0 and d ∈(0,1). If f(z) is a meromorphic in Δ such that f(j)(z) does not vanish identically, then
|f(k)(z)f(j)(z)|≤((11−|z|)2+εmax{log11−|z|,T(s(|z|),f)})k−j,|z|∉E, |
where E⊂[0,1) with finite logarithmic measure ∫Edr1−r<∞ and s(|z|)=1−d(1−|z|). Moreover, if σ1(f)<∞, then
|f(k)(z)f(j)(z)|≤(11−|z|)(k−j)(σ1(f)+2+ε),|z|∉E, |
while if σn(f)<∞ for n≥2, then
|f(k)(z)f(j)(z)|≤expn−1{(11−|z|)σn(f)+ε},|z|∉E. |
Lemma 2.2. Let f(z):Δ→R be a analytic or meromorphic function in Δ. If there exists a point ω0 on the boundary ∂Δ={z:|z|=1} and a curve γ⊂Δ tending to ω0 such that
limz→ω0z∈γf(z)<1, |
then there exists a set E⊂[0,1) with infinite logarithmic measure ∫Edr1−r=∞ such that for all |z|∈E, we have f(z)<1.
Proof. Let limz→ω0z∈γ|f(z)|=a, 0≤a<1. By definition, for ε=1−a, there exists δ>0 such that for all z∈γ and 0<|z−ω0|<δ, we have |f(z)|<a+ε=1. Let E={|z|:z∈γand0<|z−ω0|<δ}. We have
∫Edr1−r=∫11−δdr1−r=+∞. |
Lemma 2.3. [13] Let f(z) be a meromorphic function in Δ, and let k≥1 be an integer. Then
m(r,f(k)f)=S(r,f), |
where S(r,f)=O(log+T(r,f)+log(11−r)), possibly outside a set E⊂[0,1) with ∫Edr1−r<∞. If f(z) is of finite order, then
m(r,f(k)f)=O(log(11−r)). |
Lemma 2.4. [17] Let p and q be integers such that p≥q≥1, and let k≥1 be an integer and f(z) be a meromorphic function in Δ satisfies σ[p,q](f)=σ<+∞. Then for any ε>0 and for all r∈E⊂[0,1), we have
m(r,f(k)f)=O(expp−q−1{11−r}σ+ε), |
where E has finite logarithmic measure.
Lemma 2.5. [27] Let p and q be integers such that p≥q≥1. If the coefficient A0(z), A1(z), …, Ak−1(z) are analytic functions in Δ, then all solutions f(z) of (1.1) satisfies σ[p+1,q](f)≤max{σM,[p,q](Aj):j=0,…,k−1}.
Proof of Theorem1.3. Suppose that f is a nontrivial solution of (1.1) with σ[p,q](f)=σ<∞. From Lemma 2.1, for any given ε>0, there exists a set E1⊂[0,1) with ∫E1dr1−r<∞ such that for all z∈Δ satisfying |z|∉E1, we have that if p=q=1, σ[1,1](f)=σ, then
|f(j)(z)f(z)|≤(11−|z|)j(σ+2+ε),j=1,...,k. | (3.1) |
If p≥q>1, then σp(f)<σ[p,q](f)=σ,
|f(j)(z)f(z)|≤expp−1{(11−|z|)σ+ε},j=1,...,k. | (3.2) |
It follows from (1.1) that
|A0(z)|≤|f(k)(z)f(z)|+|Ak−1(z)||f(k−1)(z)f(z)|+…|A1(z)||f′(z)f(z)|. | (3.3) |
Combining (3.1), (3.2) and (3.3), we get
|A0(z)|≤(k−1∑i=1|Ai(z)|+1)(11−|z|)j(σ+2+ε), | (3.4) |
|A0(z)|≤(k−1∑i=1|Ai(z)|+1)expp−1{(11−|z|)σ+ε}. | (3.5) |
By the assumption (1.2) and Lemma 2.2, for any μ>0, there exists a set E2⊂[0,1) with ∫E2dr1−r=∞ such that for all z∈Δ satisfying |z|∈E2, we obtain
k−1∑i=1|Ai(z)|+1|A0(z)|expp{λ(1−|z|)μ}<1. |
Hence, for any z∈Δ satisfying |z|∈E2,
|A0(z)|>(k−1∑i=1|Ai(z)|+1)expp{λ(1−|z|)μ}. | (3.6) |
Obviously, (3.6) contradicts with (3.4) and (3.5) for all z∈{z∈Δ:|z|∈E2∖E1}, where E2∖E1 is of infinite logarithmic measure. So, σ[p,q](f)=∞.
From Lemma 2.1 and σ[p,q](f)=∞, there exists a set E3⊂[0,1) with ∫E3dr1−r<∞ such that for all z∈Δ satisfying |z|∉E3, we have
|f(j)(z)f(z)|≤(11−|z|)j(2+ε)[T(s(|z|),f)]j, | (3.7) |
where s(|z|)=1−d(1−|z|),d∈(0,1).
By (3.3) and (3.7), we get
|A0(z)|≤(k−1∑i=1|Ai(z)|+1)(11−|z|)j(2+ε)[T(s(|z|),f)]j. | (3.8) |
Thus, combining (3.8) and (3.6), for all z∈Δ satisfying |z|∈E2∖E3, we have
expp{λ(1−|z|)μ}≤(11−|z|)j(2+ε)[T(s(|z|),f)]j. | (3.9) |
Now, let s(|z|)=R, we have 1−|z|=1d(1−R) and ∫E3dR1−R<∞. Thus, (3.9) can be written as
expp{λdμ(1−R)μ}(1−Rd)j(2+ε)≤[T(R,f)]j, | (3.10) |
where R∈d(E2∖E3)+1−d. Obviously, {d(E2∖E3)+1−d} is of infinite logarithmic measure. Then by (3.10), we can get
σ[p+1,q](f)=¯limR→1−log+p+1T(R,f)−logq(1−R)≥μ. |
Proof of Theorem 1.4. Suppose that f is a nontrivial solution of (1.1) with σ[p,q](f)=σ<∞. If p=q=1, from Lemma 2.3, for any ε>0, for all r outside a set E4⊂[0,1) with ∫E4dR1−r<∞, we have
m(r,f(j)f)=O(log(11−r)),j=1,...,k. | (3.11) |
By (1.1), we have
−A0(z)=f(k)(z)f(z)+Ak−1(z)f(k−1)(z)f(z)+...+A1(z)f′(z)f(z), |
thus
m(r,A0)≤k−1∑i=1m(r,Ai)+k∑j=1m(r,f(j)f)+O(1). | (3.12) |
By (3.11) and (3.12), we have
T(r,A0)=m(r,A0)≤k−1∑i=1T(r,Ai)+O(log(11−r)),|z|∉E4. | (3.13) |
If p≥q>1, from Lemma 2.4, for any ε>0, for all r outside a set E5⊂[0,1) with ∫E5dR1−r<∞, we have
m(r,f(j)f)=O(expp−q−1(11−r)σ+ε),j=1,...,k. | (3.14) |
By (3.12) and (3.14), for all |z|=r∉E5,
T(r,A0)=m(r,A0)≤k−1∑i=1T(r,Ai)+O(expp−q−1(11−r)σ+ε). | (3.15) |
By the assumption (1.3) and Lemma 2.2, for any μ>0, there exists a set E6⊂[0,1) with ∫E6dr1−r=∞ such that for all |z|∈E6, we have
k−1∏i=1eT(r,Ai)eT(r,A0)expp{λ(1−|z|)μ}<1. |
It yields that
T(r,A0)−k−1∑i=1T(r,Ai)>expp−1{λ(1−|z|)μ},|z|∈E6. | (3.16) |
It is easy to see (3.16) contradicts with (3.15) in |z|∈E6∖E5 or contradicts with (3.13) in |z|∈E6∖E4. Therefore, σ[p,q](f)=∞.
Next, by Lemma 2.3, we have
m(r,f(j)f)≤O(log+T(r,f)+log11−r), | (3.17) |
possibly outside a set E7⊂[0,1) with ∫E7dr1−r<∞. By (3.12) and (3.17), we have
T(r,A0)≤k−1∑i=1T(r,Ai)+O(log+T(r,f)+log11−r),|z|∉E7. | (3.18) |
Combining (3.16) and (3.18), we have
expp−1{λ(1−|z|)μ}≤O(log+T(r,f)+log(11−r)),|z|∈E6∖E7. | (3.19) |
Obviously, E6∖E7 is of infinite logarithmic measure. Then by (3.19) we can get
σ[p+1,q](f)=¯limr→1−log+p+1T(r,f)−logq(1−r)≥μ. |
By Lemma 2.5 and the assumption of Theorem 1.4, we have σ[p+1,q](f)≤σM,[p,q](A0)=μ. Therefore, σ[p+1,q](f)=σM,[p,q](A0)=μ. The proof of Theorem 1.2 is completed.
Proof of Theorem 1.5. Suppose that f is a nontrivial solution of (1.1) with σ(f)=σ<∞. Taking s+1≤j≤k and by the first fundamental theorem of Nevanlinna, we have
m(r,f(j)f(s))≤m(r,f(j)f)+m(r,ff(s)). |
Because f just has finite many zeros, by the definition of the counting function, we get
N(r,f(s)f)=O(1). |
So,
m(r,ff(s))≤T(r,ff(s))=T(r,f(s)f)+O(1)=m(r,f(s)f)+N(r,f(s)f)+O(1)≤m(r,f(s)f)+O(1). |
Thus, from (3.11),
m(r,f(j)f(s))≤O(log(11−r)),|z|∉E4, | (4.1) |
where E4 with finite logarithmic measure. Taking 0≤j≤s−1, by the first fundamental theorem of Nevanlinna, we can get
T(r,f(j)f(s))=T(r,f(s)f(j))+O(1)=m(r,f(s)f(j))+N(r,f(s)f(j))+O(1). |
Because f(j) just has finite many zeros when 0≤j≤s−1, by the definition of the counting function, we get
N(r,f(s)f(j))=O(1). |
So,
m(r,f(j)f(s))≤T(r,f(j)f(s))=m(r,f(s)f(j))+O(1). | (4.2) |
From (1.1),
−As=f(k)f(s)+Ak−1f(k−1)f(s)+...+As+1f(s+1)f(s)+As−1f(s−1)f(s)+...+A0ff(s). |
It follows that
m(r,As)≤∑i≠sm(r,Ai)+∑s+1≤j≤km(r,f(j)f(s))+∑0≤j≤s−1m(r,f(j)f(s))+O(1). | (4.3) |
Combining (4.1), (4.2) in (4.3), we have
T(r,As)=m(r,As)≤∑i≠sT(r,Ai)+O(log(11−r)),|z|∉E4. | (4.4) |
By the assumption (1.4) and Lemma 2.2, for any μ>0, there exists a set E8⊂[0,1) with ∫E8dr1−r=∞ such that for all |z|∈E8, we have
∏i≠seT(r,Ai)eT(r,As)(1−|z|)μ<1. |
It yields that for any μ>0, |z|∈E8,
∑i≠sT(r,Ai)−T(r,As)+μlog(11−|z|)<0. | (4.5) |
By (4.4) and (4.5), for any |z|∈E8∖E4, we have
μlog(11−|z|)<O(log(11−r)). |
Obviously, E8∖E4 is of infinite logarithmic measure. It is easy to see this is a contradicts, thus σ(f)=∞.
Proof of Theorem 1.6. Suppose that f is a nontrivial solution of (1.1) with finite order σ[p,q](f)=σ<∞. If p=q=1, from Lemma 2.1, for any ε>0, there exists a set E9⊂[0,1) with ∫E9dr1−r<∞ such that s+1≤j≤k and r∈[0,1)∖E9, we have
|f(j)(z)f(s)(z)|≤O(11−r)(σ+2+ε)(j−s). |
Therefore,
m(r,f(j)(z)f(s)(z))≤O(log+(11−r)),r→1−. | (4.6) |
For 0≤j≤s−1, by (4.2), (4.3) and (4.6), we have
T(r,As)=m(r,As)≤∑i≠sT(r,Ai)+O(log+(11−r)). | (4.7) |
If p≥q>1, from Lemma 2.4 and for j=1,...,k,
m(r,f(j)f)=O(expp−q−1(11−r)σ+ε), |
holds for all r outside a set E10⊂[0,1) with ∫E10dr1−r<∞. Note that s+1≤j≤k, f just has finite many zeros, by the definition of the counting function, we get
N(r,f(s)f)=O(1). |
So,
m(r,f(j)f(s))≤m(r,f(j)f)+m(r,ff(s))≤O(expp−q−1(11−r)σ+ε)+T(r,f(s)f)≤O(expp−q−1(11−r)σ+ε)+T(r,ff(s))≤O(expp−q−1(11−r)σ+ε)+m(r,f(s)f)≤O(expp−q−1(11−r)σ+ε) |
For 0≤j≤s−1, by (4.2), (4.3) and (4.8), for any |z|∉E10, we have
T(r,As)≤∑i≠sT(r,Ai)+O(expp−q−1(11−r)σ+ε). | (4.8) |
By the assumption (1.5) and Lemma 2.2, for any μ>0, there exists a set E11⊂[0,1) with ∫E11dr1−r=∞ such that for all |z|∈E11, we have
∏i≠seT(r,Ai)eT(r,As)expp{λ(1−|z|)μ}<1,i=0,...,k−1. |
It yields that
T(r,As)−∑i≠sT(r,Ai)>expp−1{λ(1−|z|)μ},|z|=r∈E11. | (4.9) |
It is easy to see (4.10) contradicts with (4.9) in |z|∈E11∖E10 and contradicts with (4.7) in |z|∈E11∖E9. Therefore, σ[p,q](f)=∞.
Next from Lemma 2.1, for any ε>0, there exists a set E12⊂[0,1) with ∫E12dr1−r<∞ such that s+1≤j≤k and |z|∈[0,1)∖E12, we have
|f(j)(z)f(s)(z)|≤((11−|z|)2+εmax{log11−|z|,T(s(|z|),f)})j−s, |
where s(|z|)=1−d(1−|z|),d∈(0,1). Since limr→1−s(r)r=1, then let r→1−, we have log11−r>1, and T(s(|z|),f)=T(r,f). Thus,
m(r,f(j)f(s))≤log+((11−r)2+ε{log11−r+T(s(r),f)})j−s≤(j−s)log+((11−r)2+ε{log11−r+T(r,f)})≤O(log+T(r,f)+log+11−r),r→1−. | (4.10) |
For 0≤j≤s−1, combining (4.2), (4.3), (4.10) and (4.11), we have
expp−1{λ(1−|z|)μ}≤O(log+T(r,f)+log+(11−r)),|z|∈E11∖E12. | (4.11) |
Obviously, E11∖E12 is of infinite logarithmic measure. Then by (4.12) we can get
σ[p+1,q](f)=¯limr→1−log+p+1T(r,f)−logq(1−r)≥μ. |
By Lemma 2.5 and the assumption of Theorem 1.6, we have σ[p+1,q](f)≤σM,[p,q](As)=μ. So, σ[p+1,q](f)=σM,[p,q](As)=μ. The proof of Theorem 1.6 is completed.
Many results on [p,q]-order of solutions of (1.1) have been found by different researchers in Δ, in this paper the difference is that we discussed the [p, q]-order of growth of solutions of linear differential Eq (1.1) which Aj(z) dominate the others coefficients near a point on the boundary of the unit disc.
(1) Let A0(z),…,Ak−1(z) be analytic functions satisfying
lim|z|→1−z∈γk−1∑i=1|Ai(z)|+1|A0(z)|expp{λ(1−|z|)μ}<1, |
then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)≥μ by Theorem 1.3, and
max{σM,[p,q](Ai):i=1,⋯,k−1}≤σM,[p,q](A0)=μ, |
lim|z|→1−z∈γk−1∏i=1eT(r,Ai)eT(r,A0)expp{λ(1−|z|)μ}<1, |
then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](A0) by Theorem 1.4.
(2) At the same time, we considered j=s in Theorems 1.5 and 1.6 which add an essential condition for every nontrivial solution f(z) of (1.1), where s=1,2,...,k. Let A0(z),…,Ak−1(z) be analytic functions satisfying
lim|z|→1−z∈γ∏i≠seT(r,Ai)eT(r,As)(1−|z|)μ<1, |
then every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s−1), is of infinite order by Theorem 1.5,
and
max{σM,[p,q](Ai):i=0,1,⋯,s−1,s+1,⋯,k−1}≤σM,[p,q](As)=μ. |
lim|z|→1−z∈γ∏ieT(r,Ai)eT(r,As)expp{λ(1−|z|)μ}<1, |
then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s−1), satisfies σ[p,q](f)=∞ and σ[p+1,q](f)=σM,[p,q](As) by Theorem 1.6.
This research work is supported by the National Natural Science Foundation of China (Grant No. 11861023), and the Foundation of Science and Technology project of Guizhou Province of China (Grant No. [2018]5769-05).
The authors declare no conflicts of interest in this paper.
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