Research article Special Issues

On [p, q]-order of growth of solutions of linear differential equations in the unit disc

  • The [p,q]-order of growth of solutions of the following linear differential equations () is investigated,

    f(k)+Ak1(z)f(k1)++A1(z)f+A0(z)f=0,()

    where Ai(z) are analytic functions in the unit disc, i=0,1,...,k1. Some estimations of [p,q]-order of growth of solutions of the equation () are obtained when Aj(z) dominate the others coefficients near a point on the boundary of the unit disc, which is generalization of previous results from S. Hamouda.

    Citation: Hongyan Qin, Jianren Long, Mingjin Li. On [p, q]-order of growth of solutions of linear differential equations in the unit disc[J]. AIMS Mathematics, 2021, 6(11): 12878-12893. doi: 10.3934/math.2021743

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  • The [p,q]-order of growth of solutions of the following linear differential equations () is investigated,

    f(k)+Ak1(z)f(k1)++A1(z)f+A0(z)f=0,()

    where Ai(z) are analytic functions in the unit disc, i=0,1,...,k1. Some estimations of [p,q]-order of growth of solutions of the equation () are obtained when Aj(z) dominate the others coefficients near a point on the boundary of the unit disc, which is generalization of previous results from S. Hamouda.



    For the following complex linear differential equation

    f(k)+Ak1(z)f(k1)++A1(z)f+A0(z)f=0, (1.1)

    where Ai(z) are analytic in the unit disc Δ={z:|z|<1}, i=0,1,...,k1, k2. For the properties of solutions of Eq (1.1), including growth, zero distribution and function space properties, many results have been obtained, for example [9,10,14,16,20,22,23,25] and therein references. In addition, the differential equations have wide applications in various science discipline, for example engineering, predator-prey equations, population growth and decay, Newton's law of cooling and so on, see [1,5,24,28,29] and therein references. This paper is mainly concerned with the growth of solution of the Eq (1.1). It has been widely noted that Bernal [4] firstly introduced the idea of iterated order to express the fast growth of solutions of (1.1). Since then, the iterated order of solutions of (1.1) is very interesting topic in the unit disc Δ, many results concerning iterated order of solutions of (1.1) in the unit disc are obtained, see [3,6,7,18,26]. In order to better estimate the fast growth of solutions of (1.1), [p,q]-order was introduced, and many results on [p,q]-order of solutions of (1.1) have been found by different researchers in Δ. For example, see [2,17,19,21,27].

    To state our results, firstly, we assume that readers are familiar with the fundamental results and the standard notation of the Nevanlinna value distribution theory in the unit disc (see [12,13]). Secondly, we introduce some definitions, for all r[0,1), exp1r=er and expn+1r=exp(expnr), nN, and for all r(0,1), log1r=logr and logn+1r=log(lognr), nN. We also denote exp0r=r=log0r, exp1r=log1r.

    Definition 1. Let f be a meromorphic function in Δ, then the iterated n-order of f is defined by

    σn(f)=¯limr1log+nT(r,f)log(1r),

    where log+1=log+x=max{logx,0}, log+n+1x=log+(log+nx). If f is an analytic in Δ, then its iterated n-order is defined by

    σM,n(f)=¯limr1log+n+1M(r,f)log(1r),

    where M(r,f)=max|z|=r|f(z)|. For n=1,σM,1(f)=σM(f), σ1(f)=σ(f).

    Suppose p and q are integers satisfying pq1. Then [p,q]-order is defined as follows.

    Definition 2. Let f be a meromorphic function in Δ, then the [p,q]-order of f is defined by

    σ[p,q](f)=¯limr1log+pT(r,f)logq(1r).

    If f is analytic in Δ, then its [p,q]-order is defined by

    σM,[p,q](f)=¯limr1log+p+1M(r,f)logq(1r).

    Remark 1. [2] Let p and q be integers such that pq1, and f be an analytic function in Δ. The following two statements holds:

    (ⅰ) If p=q, then σ[p,q](f)σM,[p,q](f)σ[p,q](f)+1.

    (ⅱ) If p>q, then σ[p,q](f)=σM,[p,q](f).

    Recently, Hamouda [11] considered the fast growing solutions of Eq (1.1) by using a new idea which A0 dominates the other coefficients near a point on the boundary of the unit disc, and obtained some results which improve and generalize results of Heittokangas et al. [15]. The following two results are proved.

    Theorem 1.1. [11] Let A0(z),,Ak1(z) be analytic functions in Δ. If there exists ω0Δ and a curve γΔ tending to ω0 such that for any constant μ>0,

    lim|z|1zγk1j=1|Aj(z)|+1|A0(z)|(1|z|)μ=0,

    then every nontrivial solution f(z) of (1.1) is of infinite order.

    Theorem 1.2. [11] Let A0(z),,Ak1(z) be analytic functions in Δ. If there exists ω0Δ and a curve γΔ tending to ω0 such that

    lim|z|1zγk1j=1|Aj(z)|+1|A0(z)|expn{λ(1|z|)μ}=0,

    where n1 is an integer, λ>0 is a real constant, then every nontrivial solution f(z) of (1.1) satisfies σn(f)= and σn+1(f)μ.

    A natural question is that how to character the [p,q]-order of growth of solutions of (1.1) under the similar conditions of Hamouda. Here, we study the problem and get the following results.

    Theorem 1.3. Let A0(z),,Ak1(z) be analytic functions in Δ. If there exists ω0Δ and a curve γΔ tending to ω0 satisfying

    lim|z|1zγk1i=1|Ai(z)|+1|A0(z)|expp{λ(1|z|)μ}<1, (1.2)

    where λ>0 and μ>0 are two real constants, then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)μ.

    Corollary 1. Let A0(z),,Ak1(z) be analytic functions in Δ. If there exists ω0Δ and a curve γΔ tending to ω0 such that for some constants 0β<α and any given ε(0<ε<), for zγ and |z|1, we have

    |A0|expp{α(1|z|)με}

    and

    |Ai|expp{β(1|z|)με},i=1,,k1,

    then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)μ.

    In fact, by the assumptions and taking 0<λ<αβ, we can get

    lim|z|1zγk1i=1|Ai(z)|+1|A0(z)|expp{λ(1|z|)μ}<1.

    Thus Corollary 1 is obtained by applying Theorem 1.3.

    Theorem 1.4. Let A0(z),,Ak1(z) be analytic functions in Δ satisfying

    max{σM,[p,q](Ai):i=1,,k1}σM,[p,q](A0)=μ,

    where μ(0,). If there exists ω0Δ and a curve γΔ tending to ω0 such that

    lim|z|1zγk1i=1eT(r,Ai)eT(r,A0)expp{λ(1|z|)μ}<1, (1.3)

    where λ>0 is a real constant, then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](A0).

    Corollary 2. Let A0(z),,Ak1(z) be analytic functions in Δ satifying

    max{σM,[p,q](Ai):i=1,,k1}σM,[p,q](A0)=μ,

    where μ(0,). If there exists ω0Δ and a curve γΔ tending to ω0 such that for some constants 0β<α and any given ε(0<ε<), for zγ and |z|1, we have

    T(r,A0)expp1{α(1|z|)με}

    and

    T(r,Ai)expp1{β(1|z|)με},i=1,,k1,

    then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](A0).

    In fact, for any given ε(0<ε<μ), taking λ<α, for |z|1 and zγ, we have

    expp1{λ(1|z|)με}<o(expp1{α(1|z|)με})

    and

    expp1{β(1|z|)με}<o(expp1{α(1|z|)με}).

    From the condition of Corollary 2, we have

    lim|z|1zγk1i=1eT(r,Ai)eT(r,A0)expp{λ(1|z|)με}=0<1,i=0,1,...,k1.

    Thus Corollary 2 is obtained by applying Theorem 1.4.

    In Theorems 1.3 and 1.4, the coefficient A0(z) is the dominant coefficient. A nature question: How to character [p,q]-order of growth of solutions of Eq (1.1) when As(z) dominates the other coefficients near a point on the boundary of the unit disc. Next, we study the growth of the solution of (1.1) when As(z) is the dominant coefficient, and get the following results.

    Theorem 1.5. Let A0(z),,Ak1(z) be analytic functions in Δ. If there exists ω0Δ and a curve γΔ tending to ω0 such that for any μ>0, we have

    lim|z|1zγiseT(r,Ai)eT(r,As)(1|z|)μ<1, (1.4)

    then every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s1), is of infinite order.

    Theorem 1.6. Let A0(z),,Ak1(z) be analytic functions in Δ and there exists μ(0,) satisfying

    max{σM,[p,q](Ai):i=0,1,,s1,s+1,,k1}σM,[p,q](As)=μ.

    If there exists ω0Δ and a curve γΔ tending to ω0 such that

    lim|z|1zγieT(r,Ai)eT(r,As)expp{λ(1|z|)μ}<1, (1.5)

    where λ>0 is a real constant. Then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s1), satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](As).

    By Theorem 1.6 we can easily obtain the following Corollary 3.

    Corollary 3. Let A0(z),,Ak1(z) be analytic functions in Δ and there exists μ(0,) satisfying

    max{σM,[p,q](Ai):i=0,,s1,s+1,,k1}σM,[p,q](As)=μ.

    If there exists ω0Δ and a curve γΔ tending to ω0 such that for some constants 0β<α and any given ε(0<ε<), for zγ and |z|1, we have

    T(r,As)expp1{α(1|z|)με}

    and

    T(r,Ai)expp1{β(1|z|)με},i=0,,s1,s+1,,k1,

    then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s1), satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](As).

    Remark 2. The recent papers of Long et al. [20,22] and Sun et al. [25] discussed the function space properties of solutions of differential equation. Long et al. obtained analytic solutions of Eq (1.1) where k=2 belong to αBloch space and Morrey space and Sun et al. obtained analytic solutions of the nonlinear equations

    f(k)+Ak1(z)f(k1)++A1(z)f+A0(z)f=Ak(z)

    belong to in HΦ or Bα. However, the results of this paper is about growth of solutions of Eq (1.1). Obviously, The results of recent papers of Long et al. and Sun et al. and the results of this paper are not directly related to each other, but they are both properties of solutions of Eq (1.1).

    Lemma 2.1. [8] Let k and j be integers satisfying k>j0, and let ε>0 and d (0,1). If f(z) is a meromorphic in Δ such that f(j)(z) does not vanish identically, then

    |f(k)(z)f(j)(z)|((11|z|)2+εmax{log11|z|,T(s(|z|),f)})kj,|z|E,

    where E[0,1) with finite logarithmic measure Edr1r< and s(|z|)=1d(1|z|). Moreover, if σ1(f)<, then

    |f(k)(z)f(j)(z)|(11|z|)(kj)(σ1(f)+2+ε),|z|E,

    while if σn(f)< for n2, then

    |f(k)(z)f(j)(z)|expn1{(11|z|)σn(f)+ε},|z|E.

    Lemma 2.2. Let f(z):ΔR be a analytic or meromorphic function in Δ. If there exists a point ω0 on the boundary Δ={z:|z|=1} and a curve γΔ tending to ω0 such that

    limzω0zγf(z)<1,

    then there exists a set E[0,1) with infinite logarithmic measure Edr1r= such that for all |z|E, we have f(z)<1.

    Proof. Let limzω0zγ|f(z)|=a, 0a<1. By definition, for ε=1a, there exists δ>0 such that for all zγ and 0<|zω0|<δ, we have |f(z)|<a+ε=1. Let E={|z|:zγand0<|zω0|<δ}. We have

    Edr1r=11δdr1r=+.

    Lemma 2.3. [13] Let f(z) be a meromorphic function in Δ, and let k1 be an integer. Then

    m(r,f(k)f)=S(r,f),

    where S(r,f)=O(log+T(r,f)+log(11r)), possibly outside a set E[0,1) with Edr1r<. If f(z) is of finite order, then

    m(r,f(k)f)=O(log(11r)).

    Lemma 2.4. [17] Let p and q be integers such that pq1, and let k1 be an integer and f(z) be a meromorphic function in Δ satisfies σ[p,q](f)=σ<+. Then for any ε>0 and for all rE[0,1), we have

    m(r,f(k)f)=O(exppq1{11r}σ+ε),

    where E has finite logarithmic measure.

    Lemma 2.5. [27] Let p and q be integers such that pq1. If the coefficient A0(z), A1(z), , Ak1(z) are analytic functions in Δ, then all solutions f(z) of (1.1) satisfies σ[p+1,q](f)max{σM,[p,q](Aj):j=0,,k1}.

    Proof of Theorem1.3. Suppose that f is a nontrivial solution of (1.1) with σ[p,q](f)=σ<. From Lemma 2.1, for any given ε>0, there exists a set E1[0,1) with E1dr1r< such that for all zΔ satisfying |z|E1, we have that if p=q=1, σ[1,1](f)=σ, then

    |f(j)(z)f(z)|(11|z|)j(σ+2+ε),j=1,...,k. (3.1)

    If pq>1, then σp(f)<σ[p,q](f)=σ,

    |f(j)(z)f(z)|expp1{(11|z|)σ+ε},j=1,...,k. (3.2)

    It follows from (1.1) that

    |A0(z)||f(k)(z)f(z)|+|Ak1(z)||f(k1)(z)f(z)|+|A1(z)||f(z)f(z)|. (3.3)

    Combining (3.1), (3.2) and (3.3), we get

    |A0(z)|(k1i=1|Ai(z)|+1)(11|z|)j(σ+2+ε), (3.4)
    |A0(z)|(k1i=1|Ai(z)|+1)expp1{(11|z|)σ+ε}. (3.5)

    By the assumption (1.2) and Lemma 2.2, for any μ>0, there exists a set E2[0,1) with E2dr1r= such that for all zΔ satisfying |z|E2, we obtain

    k1i=1|Ai(z)|+1|A0(z)|expp{λ(1|z|)μ}<1.

    Hence, for any zΔ satisfying |z|E2,

    |A0(z)|>(k1i=1|Ai(z)|+1)expp{λ(1|z|)μ}. (3.6)

    Obviously, (3.6) contradicts with (3.4) and (3.5) for all z{zΔ:|z|E2E1}, where E2E1 is of infinite logarithmic measure. So, σ[p,q](f)=.

    From Lemma 2.1 and σ[p,q](f)=, there exists a set E3[0,1) with E3dr1r< such that for all zΔ satisfying |z|E3, we have

    |f(j)(z)f(z)|(11|z|)j(2+ε)[T(s(|z|),f)]j, (3.7)

    where s(|z|)=1d(1|z|),d(0,1).

    By (3.3) and (3.7), we get

    |A0(z)|(k1i=1|Ai(z)|+1)(11|z|)j(2+ε)[T(s(|z|),f)]j. (3.8)

    Thus, combining (3.8) and (3.6), for all zΔ satisfying |z|E2E3, we have

    expp{λ(1|z|)μ}(11|z|)j(2+ε)[T(s(|z|),f)]j. (3.9)

    Now, let s(|z|)=R, we have 1|z|=1d(1R) and E3dR1R<. Thus, (3.9) can be written as

    expp{λdμ(1R)μ}(1Rd)j(2+ε)[T(R,f)]j, (3.10)

    where Rd(E2E3)+1d. Obviously, {d(E2E3)+1d} is of infinite logarithmic measure. Then by (3.10), we can get

    σ[p+1,q](f)=¯limR1log+p+1T(R,f)logq(1R)μ.

    Proof of Theorem 1.4. Suppose that f is a nontrivial solution of (1.1) with σ[p,q](f)=σ<. If p=q=1, from Lemma 2.3, for any ε>0, for all r outside a set E4[0,1) with E4dR1r<, we have

    m(r,f(j)f)=O(log(11r)),j=1,...,k. (3.11)

    By (1.1), we have

    A0(z)=f(k)(z)f(z)+Ak1(z)f(k1)(z)f(z)+...+A1(z)f(z)f(z),

    thus

    m(r,A0)k1i=1m(r,Ai)+kj=1m(r,f(j)f)+O(1). (3.12)

    By (3.11) and (3.12), we have

    T(r,A0)=m(r,A0)k1i=1T(r,Ai)+O(log(11r)),|z|E4. (3.13)

    If pq>1, from Lemma 2.4, for any ε>0, for all r outside a set E5[0,1) with E5dR1r<, we have

    m(r,f(j)f)=O(exppq1(11r)σ+ε),j=1,...,k. (3.14)

    By (3.12) and (3.14), for all |z|=rE5,

    T(r,A0)=m(r,A0)k1i=1T(r,Ai)+O(exppq1(11r)σ+ε). (3.15)

    By the assumption (1.3) and Lemma 2.2, for any μ>0, there exists a set E6[0,1) with E6dr1r= such that for all |z|E6, we have

    k1i=1eT(r,Ai)eT(r,A0)expp{λ(1|z|)μ}<1.

    It yields that

    T(r,A0)k1i=1T(r,Ai)>expp1{λ(1|z|)μ},|z|E6. (3.16)

    It is easy to see (3.16) contradicts with (3.15) in |z|E6E5 or contradicts with (3.13) in |z|E6E4. Therefore, σ[p,q](f)=.

    Next, by Lemma 2.3, we have

    m(r,f(j)f)O(log+T(r,f)+log11r), (3.17)

    possibly outside a set E7[0,1) with E7dr1r<. By (3.12) and (3.17), we have

    T(r,A0)k1i=1T(r,Ai)+O(log+T(r,f)+log11r),|z|E7. (3.18)

    Combining (3.16) and (3.18), we have

    expp1{λ(1|z|)μ}O(log+T(r,f)+log(11r)),|z|E6E7. (3.19)

    Obviously, E6E7 is of infinite logarithmic measure. Then by (3.19) we can get

    σ[p+1,q](f)=¯limr1log+p+1T(r,f)logq(1r)μ.

    By Lemma 2.5 and the assumption of Theorem 1.4, we have σ[p+1,q](f)σM,[p,q](A0)=μ. Therefore, σ[p+1,q](f)=σM,[p,q](A0)=μ. The proof of Theorem 1.2 is completed.

    Proof of Theorem 1.5. Suppose that f is a nontrivial solution of (1.1) with σ(f)=σ<. Taking s+1jk and by the first fundamental theorem of Nevanlinna, we have

    m(r,f(j)f(s))m(r,f(j)f)+m(r,ff(s)).

    Because f just has finite many zeros, by the definition of the counting function, we get

    N(r,f(s)f)=O(1).

    So,

    m(r,ff(s))T(r,ff(s))=T(r,f(s)f)+O(1)=m(r,f(s)f)+N(r,f(s)f)+O(1)m(r,f(s)f)+O(1).

    Thus, from (3.11),

    m(r,f(j)f(s))O(log(11r)),|z|E4, (4.1)

    where E4 with finite logarithmic measure. Taking 0js1, by the first fundamental theorem of Nevanlinna, we can get

    T(r,f(j)f(s))=T(r,f(s)f(j))+O(1)=m(r,f(s)f(j))+N(r,f(s)f(j))+O(1).

    Because f(j) just has finite many zeros when 0js1, by the definition of the counting function, we get

    N(r,f(s)f(j))=O(1).

    So,

    m(r,f(j)f(s))T(r,f(j)f(s))=m(r,f(s)f(j))+O(1). (4.2)

    From (1.1),

    As=f(k)f(s)+Ak1f(k1)f(s)+...+As+1f(s+1)f(s)+As1f(s1)f(s)+...+A0ff(s).

    It follows that

    m(r,As)ism(r,Ai)+s+1jkm(r,f(j)f(s))+0js1m(r,f(j)f(s))+O(1). (4.3)

    Combining (4.1), (4.2) in (4.3), we have

    T(r,As)=m(r,As)isT(r,Ai)+O(log(11r)),|z|E4. (4.4)

    By the assumption (1.4) and Lemma 2.2, for any μ>0, there exists a set E8[0,1) with E8dr1r= such that for all |z|E8, we have

    iseT(r,Ai)eT(r,As)(1|z|)μ<1.

    It yields that for any μ>0, |z|E8,

    isT(r,Ai)T(r,As)+μlog(11|z|)<0. (4.5)

    By (4.4) and (4.5), for any |z|E8E4, we have

    μlog(11|z|)<O(log(11r)).

    Obviously, E8E4 is of infinite logarithmic measure. It is easy to see this is a contradicts, thus σ(f)=.

    Proof of Theorem 1.6. Suppose that f is a nontrivial solution of (1.1) with finite order σ[p,q](f)=σ<. If p=q=1, from Lemma 2.1, for any ε>0, there exists a set E9[0,1) with E9dr1r< such that s+1jk and r[0,1)E9, we have

    |f(j)(z)f(s)(z)|O(11r)(σ+2+ε)(js).

    Therefore,

    m(r,f(j)(z)f(s)(z))O(log+(11r)),r1. (4.6)

    For 0js1, by (4.2), (4.3) and (4.6), we have

    T(r,As)=m(r,As)isT(r,Ai)+O(log+(11r)). (4.7)

    If pq>1, from Lemma 2.4 and for j=1,...,k,

    m(r,f(j)f)=O(exppq1(11r)σ+ε),

    holds for all r outside a set E10[0,1) with E10dr1r<. Note that s+1jk, f just has finite many zeros, by the definition of the counting function, we get

    N(r,f(s)f)=O(1).

    So,

    m(r,f(j)f(s))m(r,f(j)f)+m(r,ff(s))O(exppq1(11r)σ+ε)+T(r,f(s)f)O(exppq1(11r)σ+ε)+T(r,ff(s))O(exppq1(11r)σ+ε)+m(r,f(s)f)O(exppq1(11r)σ+ε)

    For 0js1, by (4.2), (4.3) and (4.8), for any |z|E10, we have

    T(r,As)isT(r,Ai)+O(exppq1(11r)σ+ε). (4.8)

    By the assumption (1.5) and Lemma 2.2, for any μ>0, there exists a set E11[0,1) with E11dr1r= such that for all |z|E11, we have

    iseT(r,Ai)eT(r,As)expp{λ(1|z|)μ}<1,i=0,...,k1.

    It yields that

    T(r,As)isT(r,Ai)>expp1{λ(1|z|)μ},|z|=rE11. (4.9)

    It is easy to see (4.10) contradicts with (4.9) in |z|E11E10 and contradicts with (4.7) in |z|E11E9. Therefore, σ[p,q](f)=.

    Next from Lemma 2.1, for any ε>0, there exists a set E12[0,1) with E12dr1r< such that s+1jk and |z|[0,1)E12, we have

    |f(j)(z)f(s)(z)|((11|z|)2+εmax{log11|z|,T(s(|z|),f)})js,

    where s(|z|)=1d(1|z|),d(0,1). Since limr1s(r)r=1, then let r1, we have log11r>1, and T(s(|z|),f)=T(r,f). Thus,

    m(r,f(j)f(s))log+((11r)2+ε{log11r+T(s(r),f)})js(js)log+((11r)2+ε{log11r+T(r,f)})O(log+T(r,f)+log+11r),r1. (4.10)

    For 0js1, combining (4.2), (4.3), (4.10) and (4.11), we have

    expp1{λ(1|z|)μ}O(log+T(r,f)+log+(11r)),|z|E11E12. (4.11)

    Obviously, E11E12 is of infinite logarithmic measure. Then by (4.12) we can get

    σ[p+1,q](f)=¯limr1log+p+1T(r,f)logq(1r)μ.

    By Lemma 2.5 and the assumption of Theorem 1.6, we have σ[p+1,q](f)σM,[p,q](As)=μ. So, σ[p+1,q](f)=σM,[p,q](As)=μ. The proof of Theorem 1.6 is completed.

    Many results on [p,q]-order of solutions of (1.1) have been found by different researchers in Δ, in this paper the difference is that we discussed the [p, q]-order of growth of solutions of linear differential Eq (1.1) which Aj(z) dominate the others coefficients near a point on the boundary of the unit disc.

    (1) Let A0(z),,Ak1(z) be analytic functions satisfying

    lim|z|1zγk1i=1|Ai(z)|+1|A0(z)|expp{λ(1|z|)μ}<1,

    then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)μ by Theorem 1.3, and

    max{σM,[p,q](Ai):i=1,,k1}σM,[p,q](A0)=μ,
    lim|z|1zγk1i=1eT(r,Ai)eT(r,A0)expp{λ(1|z|)μ}<1,

    then every nontrivial solution f(z) of (1.1) satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](A0) by Theorem 1.4.

    (2) At the same time, we considered j=s in Theorems 1.5 and 1.6 which add an essential condition for every nontrivial solution f(z) of (1.1), where s=1,2,...,k. Let A0(z),,Ak1(z) be analytic functions satisfying

    lim|z|1zγiseT(r,Ai)eT(r,As)(1|z|)μ<1,

    then every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s1), is of infinite order by Theorem 1.5,

    and

    max{σM,[p,q](Ai):i=0,1,,s1,s+1,,k1}σM,[p,q](As)=μ.
    lim|z|1zγieT(r,Ai)eT(r,As)expp{λ(1|z|)μ}<1,

    then, every nontrivial solution f(z) of (1.1), in which f(n)(z) just has finite many zeros for all n<s(n=0,...,s1), satisfies σ[p,q](f)= and σ[p+1,q](f)=σM,[p,q](As) by Theorem 1.6.

    This research work is supported by the National Natural Science Foundation of China (Grant No. 11861023), and the Foundation of Science and Technology project of Guizhou Province of China (Grant No. [2018]5769-05).

    The authors declare no conflicts of interest in this paper.



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