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Existence and multiplicity of solutions for fractional p(x)-Kirchhoff-type problems

  • In this paper, we deal with the existence and multiplicity of solutions for fractional p(x)-Kirchhoff-type problems as follows:

    {M(Q1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy)(Δp(x))sv(x) =λ|v(x)|r(x)2v(x),inΩ,v=0,inRdΩ,

    where (p(x))s is the fractional p(x)-Laplacian. Different from the previous ones which have recently appeared, we weaken the condition of M and obtain the existence and multiplicity of solutions via the symmetric mountain pass theorem and the theory of the fractional Sobolev space with variable exponents.

    Citation: Zhiwei Hao, Huiqin Zheng. Existence and multiplicity of solutions for fractional p(x)-Kirchhoff-type problems[J]. Electronic Research Archive, 2023, 31(6): 3309-3321. doi: 10.3934/era.2023167

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  • In this paper, we deal with the existence and multiplicity of solutions for fractional p(x)-Kirchhoff-type problems as follows:

    {M(Q1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy)(Δp(x))sv(x) =λ|v(x)|r(x)2v(x),inΩ,v=0,inRdΩ,

    where (p(x))s is the fractional p(x)-Laplacian. Different from the previous ones which have recently appeared, we weaken the condition of M and obtain the existence and multiplicity of solutions via the symmetric mountain pass theorem and the theory of the fractional Sobolev space with variable exponents.



    In [1], Kirchhoff studied a stationary version of the equation

    ρ02vt2(p1h1+E02LL0|vx|2dx)2vt2=0, (1.1)

    where ρ0,p1,h1,L and E0 are constants. Such equation extends the classical D'Alembert wave equation by considering the effects of the changes in the length of the string during the vibrations. It is worthwhile to note that the Eq (1.1) received much attention only after Lions [2] put forward an abstract framework to the Eq (1.1). After this work, various equations of Kirchhoff-type have been studied extensively. For instance, many researchers have studied the Kirchhoff-type equations involving the p-Laplacian, which can be found in [3,4,5,6], p(x)-Laplacian (see, for example, [7,8,9,10,11]) and fractional p(x)-Laplacian (see [12,13,14,15]).

    Recently, lots of researchers have been interested in the Kirchhoff-type equations involving the p-Laplacian (see [16,17]).In [5], Liu proved the existence of infinite solutions for the p-Kirchhoff-type problems via the fountain theorem. Since the infimum of its principal eigenvalue is zero, the p-Laplacian is not homogenous, and generally it does not have the alleged first eigenvalue. Hence, more and more attention has been given to partial differential equations with nonstandard growth conditions. Dai and Hao [18] investigated the existence and multiplicity of solutions to Kirchhoff-type problems associated with the p(x)-Laplacian via a direct variational approach. The p(x)-Laplacian has more complex nonlinear properties than the p-Laplacian, and we can refer to [11,19] for more details about it.

    In the last few years, many researchers have tended to focus on the fractional p(x)-Kirchhoff-type problems. Kaufmann, Rossi and Vidal [20] introduced the fractional p(x)-Laplacian p(x)v=div(|v|p(x)2) (see, for example, [21,22]). In [23], the authors investigated the fractional p(x)-Laplace operator and associated fundamental properties about new fractional Sobolev spaces with variable exponents. In [14], by using dint of the variational methods, Azroul et al. investigated the existence of solutions for the Kirchhoff-type problems involving fractional p(x)-Laplacian as follows:

    (PsM){M(Q1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy)(Δp(x))sv(x)=λ|v(x)|r(x)2v(x),inΩ,v=0,inRdΩ,

    where MQ1, i.e., M satisfies the following: there exist 0<a1a2 and β>1 such that

    a1τβ1M(τ)a2τβ1for allτRd.

    In [24], applying the symmetric mountain pass theorem, Azroul, Benkirane and Shimi resolved the existence solutions to the following Kirchhoff-type problems involving fractional p(x,)-Laplacian in Rd:

    {M(Rd×Rd1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy)(Δp(x,))sv(x)+|v|ˉp(x)2v=f(x,v),inRd,vWs,p(x,y)(Rd),

    where MQ2, i.e., the continuous function M:R+0:=[0,+)R+0 satisfies the following conditions:

    (M1): Let ϵ0>0 and α(1,(ps)/p+). Suppose that

    kM(k)αˆM(k)for allkϵ0, (1.2)

    where

    ˆM(k)=k0M(ϵ0)dϵ0

    and (ps), p+ and p will be introduced in Section 2.

    (M2): let ϵ>0. Suppose l=l(ϵ)>0 such that

    M(k)lfor allkϵ. (1.3)

    By comparison their definitions, we find that the condition of Q2 is weaker than Q1. Hence the spontaneous question is to show which results we can obtain if we replace MQ1 by MQ2 in [14].

    Inspired by the fractional Sobolev spaces with variable exponents (for more details see [23]) and the papers referred to above, we aim to deal with the existence and multiplicity solutions to the fractional p(x)-Kirchhoff-type problem (PsM) which is introduced in [14], where

    MQ2 and λ is a positive real constant;

    Q:=R2d(Ωc×Ωc), where ΩRd is a Lipschitz bounded open domain and Ωc=RdΩ,d3;

    the continuous functions r:¯Ω(1,+) and p:¯Q(1,+) are bounded;

    for s(0,1), the operator (Δp(x))s is the following fractional p(x)-Laplacian

    (Δp(x))sv(x)=p.v.Rd|v(x)v(y)|p(x)2(v(x)v(y))|xy|d+sp(x,y)dyfor allxRd,

    where p.v. stands for Cauchy principle value for brevity.

    We introduce our main conclusions and results as follows:

    Theorem 1.1. For the continuous function r:¯Ω(1,+), let

    1<r:=infx¯Ωr(x)r(x)<r+:=supx¯Ωr(x)<ps(x). (1.4)

    Suppose that M satisfies (1.3) and rC+(¯Ω) such that

    1<r(x)r+<pfor allx¯Ω, (1.5)

    then problem (PsM) has a nontrivial weak solution, if there is λ1>0 such that

    λ1<λ<+.

    Theorem 1.2. Suppose that pC+(¯Q) is symmetric with sp+<d and s(0,1). Let MQ2, rC+(¯Q) with

    αp+<r, (1.6)
    r+<ps(x)for allx¯Ω. (1.7)

    Then problem (PsM) has a sequence {un}n of nontrivial solutions, if there is a constant c1>0 such that

    0<λ<c1.

    Remark 1.3. We discuss the p(x)-Kirchhoff-type problem (PsM) in two situations: if r satisfies (1.5), we apply the direct variational methods; we utilize the symmetric mountain pass theorem if r satisfies (1.6).

    The paper is organized as follows: we introduce the fractional Sobolev spaces with variable exponents and some necessary properties of variable Lebesgue spaces in Section 2. In the end, Section 3 gives the proofs of Theorems 1.1 and 1.2.

    In this section, we present some useful properties of the fractional Sobolev spaces with variable exponents and the generalized Lebesgue spaces. We can refer to [17,18,20,25,26] and the references therein for more details.

    We always suppose that Ω is a Lipschitz bounded open domain in Rd and ¯Ω is a closure of Ω. Consider a continuous function r:¯Ω(1,+) and set

    C+(¯Ω)={r(¯Ω)c:r(x)>1for allx¯Ω}.

    For a measurable function v and any rC+(¯Ω), the modular functional ρr(x)(v) is defined by

    ρr(x)(v)=Ω|v(x)|r(x)dx

    The variable Lebesgue space is defined as

    Lr(x):=Lr(x)(Ω)={v:ρr(x)(λv)<+}

    equipped with the norm

    vLr(x)=inf{λ>0:ρr(x)(f/λ)1}.

    Suppose rC+(¯Ω) such that 1r(x)+1r(x)=1, where r(x) is the conjugate exponent of r(x). Then the Hölder inequality is as follows:

    Lemma 2.1 ([20]). Let vLr(x) and uLr(x). There exists a positive constant c such that

    |Ωv(x)u(x)dx|cvLr(x)uLr(x).

    Proposition 2.2 ([27]). Let vLr(x). The following properties hold:

    (i) vLr(x)=1 (resp.>1,<1)ρr(x)(v)=1 (resp.>1,<1);

    (ii) vLr(x)<1vr+Lr(x)ρr(x)(v)vrLr(x);

    (iii) vLr(x)>1vrLr(x)ρr(x)(v)vr+Lr(x);

    (iv)limk+vkvLr(x)=0limk+ρr(x)(vkv)=0.

    We show the following proposition, which is from Theorems 1.6 and 1.10 in [26].

    Proposition 2.3. Suppose 1<rr(x)r+<; then, (Lr(x),Lr(x)) is a reflexive uniformly convex and separable Banach space.

    Let the continuous function p:¯Q(1,+) be bounded. We set

    1<p:=inf(x,y)¯Qp(x,y)p(x,y)p+:=sup(x,y)¯Qp(x,y) (2.1)

    and p is symmetric, if p(x,y) satisfies the following

    p(x,y)=p(y,x)for all(x,y)¯Q. (2.2)

    We assume that

    ˉp(x):=p(x,x)for allx=y.

    Throughout this paper, s(0,1) and the fractional Sobolev space with variable exponents is defined in [14] given by

    S={v:RdR measurable such that v|ΩLˉp(x) withQ|v(x)v(y)|p(x,y)λp(x,y)|xy|d+sp(x,y)dxdy<+ for some λ>0}.

    The norm of S is as follows

    vS=vLˉp(x)+[v]S,

    where [v]S is defined by

    [v]S=[v]s,p(x,y)(Q)=inf{λ>0:Q|v(x)v(y)|p(x,y)λp(x,y)|xy|d+sp(x,y)dxdy1}.

    Also, (S,S) is a separable reflexive Banach space which is introduced in [14].

    Now, we denote the linear subspace of S given by

    S0={vS:v=0a.e.inRdΩ};

    the modular norm is as follows

    vS0:=[v]S=inf{λ>0:Q|v(x)v(y)|p(x,y)λp(x,y)|xy|d+sp(x,y)dxdy1}.

    We know that (S0,S0) is a separable, reflexive and uniformly convex Banach space (see Lemma 2.3 in [14]).

    We denote the modular ρp(x,y):S0R by

    ρp(x,y)(v)=Q|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy,

    where

    vρp(x,y)(v)=inf{λ>0:ρp(x,y)(v/λ)1}=[v]S.

    Similarly to Proposition 2.1, ρp(x,y) has the following property:

    Lemma 2.4 ([13]). Let p satisfy (2.1) and s(0,1). Suppose vS0; we can obtain

    (i) vS01vp+S0ρp(x,y)(v)vpS0;

    (ii) vS01vpS0ρp(x,y)(v)vp+S0.

    We will introduce a continuous compact embedding theorem as follows.

    Theorem 2.5 ([13]). Let s(0,1) and p satisfy (2.1) and (2.2) with sp+<d. If r satisfies (1.4), i.e.,

    1<rr(x)<ps(x):=dˉp(x)dsˉp(x)for allx¯Ω.

    Then we have

    vLr(x)cvSfor anyvS,

    where c is a positive constant depending on p, s, r, d and Ω. In other words, the embedding SLr(x) is continuous and this embedding is compact.

    Remark 2.6. (i) Theorem 2.5 still holds if we replace S by S0.

    (ii) Since 1<rr(x)<ps(x), then according to Theorem 2.5, we can get that S0 and S are equivalent on S0.

    We need to introduce the functional L:S0S0 defined by

    L(v),φ=Q|v(x)v(y)|p(x,y)2(v(x)v(y))(φ(x)φ(y))|xy|d+sp(x,y)dxdy

    for all φS0, where S0 is the dual space of S0.

    Lemma 2.7 ([23]). Suppose that p satisfies (2.1), (2.2) and s(0,1). Then the following results hold:

    (i) L is a bounded and strictly monotone operator;

    (ii) L is a homeomorphism;

    (iii) L is a mapping of type (S+), i.e., vnv in S0, if vnv in S0 and L

    lim supn+L(vn)L(v),vnv0.

    Definition 3.1. We say that vS0 is a weak solution of problem (PsM), if

    M(σp(x,y)(v))Q|v(x)v(y)|p(x,y)2(v(x)v(y))(φ(x)φ(y))|xy|d+sp(x,y)dxdyλΩ|v(x)|r(x)2v(x)φ(x)dx=0

    for all φS0, where

    σp(x,y)(v)=Q1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy.

    For the purpose of formulating the variational method of problem (PsM), we present the functional Iλ:S0R given by

    Iλ(v)=ˆM(Q1p(x,y)|v(x)v(y)|p(x,y)|xy|d+sp(x,y)dxdy)λΩ1r(x)|v(x)|r(x)dx=ˆM(σp(x,y)(v))λΩ1r(x)|v(x)|r(x)dx.

    It is not tough to demonstrate that IλC1(S0,R) and Iλ is well defined. Moreover, for all v,φS0, the Gateaux derivative of Iλ is introduced by

    Iλ(v),φ=M(σp(x,y))(v)Qv(x)v(y)p(x,y)2(v(x)v(y))(φ(x)φ(y))|xy|d+sp(x,y)dxdyλΩ|v(x)|r(x)2v(x)φ(x)dx=0.

    Thus, the weak solutions of (PsM) correspond to the critical points of Iλ.

    To prove Theorem 1.1, we need to introduce the next result:

    Lemma 3.2. For λR, the functional Iλ is coercive on S0.

    Proof. We assume vS0>1. By (M2) we obtain that

    Iλ(v)lσp(x,y)(v)λrρp(x,y)(v).

    According to Remark 2.6 (i), we have

    Iλ(v)lp+vpS0λcrrmin{vrS0,vr+S0},

    where c is a positive constant depending on d,s,p,r and Ω. It follows from (1.5) that

    Iλ(v),asvS0.

    Next, we prove Theorem 1.1.

    Proof of Theorem 1.1: According to Lemma 3.2, we know that Iλ is coercive on S0. Moreover, Iλ is weakly lower semi-continuous on S0. Applying Theorem 1.2 in [28], we find that there exists ˉv1S0 which is a global minimizer of Iλ; thus, the problem (PsM) has a weak solution.

    Now, we claim that the weak solution ˉv1 is nontrivial for all λ large enough. Indeed, let δ0>1 and |Ω1|>0, where Ω1 is an open subset of Ω. Suppose η0C0(¯Ω) such that η0(x) satisfies

    {η0(x)=δ0for allx¯Ω1,0η0(x)δ0for allxΩΩ1.

    Then we have that

    Iλ(η0)=ˆM(σp(x,y)(η0))λΩ1r(x)|η0(x)|r(x)dxc3λr+Ω|η0(x)|r(x)dxc3λr+δr0|Ω1|,

    where c3 is a constant. Therefore, we get

    Iλ(η0)<0for allλ(λ1,+),

    if the nonnegative λ1 is large enough. The proof is now complete.

    We say that Iλ satisfies (Ce)c-condition for any cR if every sequence {vn} such that

    Iλ(vn)c,Iλ(vn)S0(1+vnS0)0

    has a strongly convergent subsequence in S0. In order to prove Theorem 1.2, we need the symmetric mountain pass theorem as follows.

    Theorem 3.3 ([29,30]). For the infinite dimensional Banach space S, we define

    S=2j=1Sj,

    where S2 is finite dimensional. Suppose IC1(S,R), if I satisfies the following

    (1) I(0)=0,I(v)=I(v) for all vS;

    (2) for all c>0, I satisfies (Ce)c-condition;

    (3) suppose constants ρ,a are positive, and we have I|BρZa;

    (4) for each finite dimensional subspace ˜SS, we obtain I(v)0 on ˜SBr, if r=r(˜S) is a positive constant.

    Then I possesses an unbounded sequence of critical values.

    The following result shows that the functional Iλ satisfies the geometrical condition of the mountain pass.

    Lemma 3.4. Let c1>0 and vS0 with vS0=ρ>0. Then for each λ(0,c1), we can choose a>0 such that Iλ|BρZa.

    Proof. Suppose vS0 and ρ(0,1) such that uS0=ρ. It follows from Theorem 2.5, (M1), (1.6) and (1.7) that

    Iλ(v)=ˆM(σp(x,y)(v))λΩ1r(x)|v(x)|r(x)dxˆM(1)(σp(x,y)(v))αλrΩ|v(x)|r(x)dxˆM(1)(p+)α(ρp(x,y)(v))αλrρr(x)(v)ˆM(1)(p+)αvαp+S0λrvr+Lr(x)ˆM(1)(p+)αvαp+S0λcr+rvr+S0ραp+(ˆM(1)(p+)αλcr+rρr+αp+).

    Thus, choosing ρ even smaller, we have

    Iλ(v)>0,

    since αp+<r<r+.

    Lemma 3.5. For each finite dimensional subspace ˜SS0, v˜S and λR, there exists r=r(˜S)>0 such that

    Iλ(v)0,

    where vS0r.

    Proof. Suppose ϕC0(Ω) with ϕ>0. According to (M1), one must have

    ˆM(k)ˆM(1)kα for all k1. (3.1)

    Therefore, by (3.1), we have

    Iλ(tϕ)=ˆM(σp(x,y)(tϕ))λΩ1r(x)|tϕ|r(x)dxˆM(1)tαp+(σp(x,y)(ϕ))αλr+Ω|tϕ|r(x)dxˆM(1)(p)αtαp+(ρp(x,y)(ϕ))αtrλr+Ω|ϕ|r(x)dx.

    It follows from (1.6) that

    limtIλ(tϕ)=.

    Thus, there exists a large t>1 such that

    Iλ(v)0.

    The statement holds.

    Lemma 3.6. The functional Iλ satisfies condition (Ce)c in S0.

    Proof. For all cR, suppose a sequence {vn}S0 such that

    Iλ(vn) n+c2,
    Iλ(vn) n+0. (3.2)

    First, we claim that {vn}S0 is bounded. Arguing by contrary, passing eventually to a subsequence, still denote by vn, we assume that limn+vnS0=+. Hence, for all n, we can consider that vnS0>1. According to (3.2), Lemma 2.4, (M1) and (M2), we get that

    1+c2+vnS0Iλ(vn)1αp+Iλ(vn),vn=ˆM(σp(x,y)(vn))λΩλr(x)|vn(x)|r(x)dx1αp+M(σp(x,y)(vn))Qvn(x)vn(y)p(x,y)xyd+sp(x,y)dxdy+λαp+Ω|vn(x)|r(x)dxˆM(σp(x,y)(vn))1αp+M(σp(x,y)(vn))Qvn(x)vn(y)p(x,y)xyd+sp(x,y)dxdyλrΩ|vn(x)|r(x)dx+λαp+Ω|vn(x)|r(x)dxlσp(x,y)(vn)1p+ˆM(1)(σp(x,y)(vn))α1ρp(x,y)(vn)(λrλαp+)ρr(x)(vn)lp+ρp(x,y)(vn)ˆM(1)p+(p)α1(ρp(x,y)(vn))α(λrλαp+)min{vnr+Lr(x),vnrLr(x)}lp+vnpS0ˆM(1)(p)αvnαp+S0(λcrrλcrαp+)min{vnr+S0,vnrS0},

    when n is large enough. Dividing the above inequality by vnS0. According to αp+<r<r+, we have (λrλαp+)>0. By passing to the limit as n+, we can get a contradiction.

    Since S0 is reflexive, then we can assume that vnˉv in S0. It follows from (3.2) that

    limn+Iλ(vn),vnˉv=0,

    that is

    M(σp(x,y))(vn)Q|vn(x)vn(y)|p(x,y)2(vn(x)vn(y))((vn(x)vn(y))(ˉv(x)ˉv(y)))|xy|d+sp(x,y)dxdyλΩ|vn(x)|r(x)2vn(x)(vn(x)ˉv(x))dx=0. (3.3)

    Moreover, due to r(x)<ps(x) for all x¯Ω and Remark 2.6 (i), we can conclude that vnˉv in Lr(x). Hence according to Lemma 2.1 and the proof of Theorem 3.1 in [14], we have that

    limn+Ω|vn|r(x)2vn(vnˉv)dx=0. (3.4)

    Since {vn} is bounded in S0, if necessary, we can suppose that

    σp(x,y)(vn) n+t20.

    If t2=0, then {vn}ˉv=0 in S0 and the proof is complete. If t2>0, according to the continuous function M, we have

    M(σp(x,y)(vn))n+M(t2)0.

    Thus, for n large enough and MQ2, we get that

    0<l<M(σp(x,y)(vn))<c3. (3.5)

    Combining (3.3)–(3.5), we deduce that

    limn+Ω|vn(x)vn(y)|p(x,y)2(vn(x)vn(y))((vn(x)vn(y))(ˉv(x)ˉv(y)))|xy|d+sp(x,y)dxdy=0. (3.6)

    Using (3.6), Lemma 2.7 (iii) and vnˉv in S0, we obtain that

    {limn+L(vn),vnˉv0vnˉv in S0L is a mapping of type (S+) vnˉv in S0.

    Moreover, according to (3.2), we have

    limn+Iλ(vn)=Iλ(ˉv)=c2andIλ(ˉv)=0.

    This completes the proof of Lemma 3.6.

    Proof of Theorem 1.2: Clearly, Iλ(0)=0 and Iλ(v)=Iλ(v). According to Theorem 3.3 and Lemmas 3.4–3.6, we deduce that Theorem 1.2 holds.

    This project was supported by the Hunan Provincial Natural Science Foundation (Nos. 2022JJ40145 and 2022JJ40146).

    The authors declare that there is no conflict of interest.



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