Processing math: 100%
Research article

Definite integrals involving product of logarithmic functions and logarithm of square root functions expressed in terms of special functions

  • Received: 02 June 2020 Accepted: 06 July 2020 Published: 09 July 2020
  • MSC : 01A55, 11M06, 11M35, 30-02, 30D10, 30D30, 30E20

  • The derivation of integrals in the table of Gradshteyn and Ryzhik in terms of closed form solutions is always of interest. We evaluate several of these definite integrals of the form 0lnk(αy)ln(R(y))dy in terms of a special function, where R(y) is a general function and k and α are arbitrary complex numbers.

    Citation: Robert Reynolds, Allan Stauffer. Definite integrals involving product of logarithmic functions and logarithm of square root functions expressed in terms of special functions[J]. AIMS Mathematics, 2020, 5(6): 5724-5733. doi: 10.3934/math.2020367

    Related Papers:

    [1] Robert Reynolds, Allan Stauffer . Definite integral of the logarithm hyperbolic secant function in terms of the Hurwitz zeta function. AIMS Mathematics, 2021, 6(2): 1324-1331. doi: 10.3934/math.2021082
    [2] Robert Reynolds, Allan Stauffer . Derivation of some integrals in Gradshteyn and Ryzhik. AIMS Mathematics, 2021, 6(2): 1816-1821. doi: 10.3934/math.2021109
    [3] Robert Reynolds, Allan Stauffer . Derivation of logarithmic integrals expressed in teams of the Hurwitz zeta function. AIMS Mathematics, 2020, 5(6): 7252-7258. doi: 10.3934/math.2020463
    [4] SAIRA, Wenxiu Ma, Suliman Khan . An efficient numerical method for highly oscillatory logarithmic-algebraic singular integrals. AIMS Mathematics, 2025, 10(3): 4899-4914. doi: 10.3934/math.2025224
    [5] Muhammmad Ghaffar Khan, Wali Khan Mashwani, Jong-Suk Ro, Bakhtiar Ahmad . Problems concerning sharp coefficient functionals of bounded turning functions. AIMS Mathematics, 2023, 8(11): 27396-27413. doi: 10.3934/math.20231402
    [6] Muhammmad Ghaffar Khan, Wali Khan Mashwani, Lei Shi, Serkan Araci, Bakhtiar Ahmad, Bilal Khan . Hankel inequalities for bounded turning functions in the domain of cosine Hyperbolic function. AIMS Mathematics, 2023, 8(9): 21993-22008. doi: 10.3934/math.20231121
    [7] Chuan-Yu Cai, Qiu-Ying Zhang, Ti-Ren Huang . Properties of generalized (p,q)-elliptic integrals and generalized (p,q)-Hersch-Pfluger distortion function. AIMS Mathematics, 2023, 8(12): 31198-31216. doi: 10.3934/math.20231597
    [8] Syed Ali Haider Shah, Shahid Mubeen . Expressions of the Laguerre polynomial and some other special functions in terms of the generalized Meijer G-functions. AIMS Mathematics, 2021, 6(11): 11631-11641. doi: 10.3934/math.2021676
    [9] Shuang-Shuang Zhou, Saima Rashid, Muhammad Aslam Noor, Khalida Inayat Noor, Farhat Safdar, Yu-Ming Chu . New Hermite-Hadamard type inequalities for exponentially convex functions and applications. AIMS Mathematics, 2020, 5(6): 6874-6901. doi: 10.3934/math.2020441
    [10] José R. Fernández, Ramón Quintanilla . Uniqueness and exponential instability in a new two-temperature thermoelastic theory. AIMS Mathematics, 2021, 6(6): 5440-5451. doi: 10.3934/math.2021321
  • The derivation of integrals in the table of Gradshteyn and Ryzhik in terms of closed form solutions is always of interest. We evaluate several of these definite integrals of the form 0lnk(αy)ln(R(y))dy in terms of a special function, where R(y) is a general function and k and α are arbitrary complex numbers.


    We will prove one of the formula in Gradshteyn and Ryzhik not previously done and derive other interesting integral formula similar to those in Gradshteyn and Ryzhik. We will evaluate the integrals 0ln(a2+2by+y2a22by+y2)lnk(αy)dyy and 0(y2z+z2+y2)myz2+y2lnk(αy2z+z2+y2)dy each in terms of a special function. The parameters k, α, a, m and b are arbitrary complex numbers subject to the restrictions given. These derivations are accomplished by the method used by us in [8].

    We use the method in [8] but because there are limits on w we have to define the contour C somewhat differently. We take the cut along the negative real axis a distance ϵ and then vertically to positive . The path of the contour C is to the right of the cut from (ϵ,) to the negative real axis, along the axis and around the origin with zero radius, along the negative real axis to the cut and along the left of the cut to (ϵ,). Then we take the limit as ϵ0.

    In Cauchy's integral formula we replace y by ln(αy) and multiply both sides by 1yln(a2+2by+y2a22by+y2) to get

    lnk(αy)yk!ln(a2+2by+y2a22by+y2)=12πiCyw1αwwk+1ln(a2+2by+y2a22by+y2)dw (2.1)

    the logarithmic function is defined in equation (4.1.2) in [1]. We then take the definite integral over y[0,) of both sides and factor the quadratic terms into their two roots to get

    1k!0lnk(αy)yln(a2+2by+y2a22by+y2)dy=12πi0Cyw1αwwk+1ln(a2+2by+y2a22by+y2)dwdy=12πiC(0yw1ln(a2+2by+y2a22by+y2)dy)αwdwwk+1=12iCαw(bb2a2)wcsc(πw)wk2dw+12iCαw(bb2a2)wcsc(πw)wk2dw12iCαw(b+b2a2)wcsc(πw)wk2dw+12iCαw(b+b2a2)wcsc(πw)wk2dw (2.2)

    from Eq (4.293.10) in [6] and the integral is valid for α, b and a complex, 1<Re(w)<0, |arg(±b±b2a2)|<π and α is not real and negative. The condition on α prevents a singularity in the range of integration.

    Again, using the method in [8], replacing y with πi(2p+1)+ln(α)+ln(bb2a2), we multiply both sides by 2πi to yield

    2πi(πi(2p+1)+ln(α)+ln(bb2a2))kk!=2πiCew(πi(2p+1)+ln(α)+ln(bb2a2))wk+1dw (2.3)

    followed by taking the infinite sum of both sides of Eq (2.3) with respect to p over [0,) and replace k with k+1 to get

    (2πi)k+2(k+1)!ζ(k1,12i(ln(α)+ln(bb2a2))2π)=2πip=0Cew(πi(2p+1)+ln(α)+ln(bb2a2))wk+2dw=2πiCp=0ew(πi(2p+1)+ln(α)+ln(bb2a2))wk+2dw=12iCαw(bb2a2)wcsc(πw)wk2dw (2.4)

    from (1.232.3) in [6] where csch(ix)=icsc(x) from (4.5.10) in [1] and Im(w)>0 for the convergence of the sum and if the Re(k)<0 then the argument of the sum over p cannot be zero for some value of p. We use (9.521.1) in [6] where ζ(s,u) is the Hurwitz Zeta function. Combining the log terms is not valid in general.

    Similarly, by replacing y in turn by πi(2p+1)+ln(α)+ln(bb2a2), πi(2p+1)+ln(α)+ln(b+b2a2) and πi(2p+1)+ln(α)+ln(b+b2a2) and following the steps in (4) and (5) and simplifying the infinite sum on the left-hand side we get

    0lnk(αy)yln(a2+2by+y2a22by+y2)dy=(2πi)k+2(k+1)ζ(k1,12i(ln(α)+ln(bb2a2))2π)(2πi)k+2(k+1)ζ(k1,12i(ln(α)+ln(bb2a2))2π)+(2πi)k+2(k+1)ζ(k1,12i(ln(α)+ln(b+b2a2))2π)(2πi)k+2(k+1)ζ(k1,12i(ln(α)+ln(b+b2a2))2π) (2.5)

    We will now use Eq (2.5) with a variety for values of the parameters to yield known integral forms. In the following sections we will make use of the Hurwitz Zeta function.

    The Hurwitz zeta function ζ(s,a) is a generalization of the Riemann zeta function ζ(s) that is also known as the generalized zeta function. It is classically defined by the formula

    ζ(s,a)=k=01(k+a)s

    for Re(s)>1, where any term with k+a=0 is excluded and analytically continued by

    ζ(s,a)=1Γ(s)0ts1eat(1et)dt

    for Re(s)>1, Re(a)>0 and s1.

    The Hurwitz Zeta function ζ(n,a) for n negative integers reduces to the Bernoulli polynomial given by ζ(n,a)=Bn+1(a)n+1 for n0, from Eq (12.11.17) in [2] and (23.1) in [1], specifically we will use B2(a)2 and B3(a)3 polynomials from Table 5.2 in [9]. The table lists the Bernoulli polynomials up to n=6 and gives the general formula for arbitrary integer n.

    0ln(a2+2by+y2a22by+y2)dyy=(2πi)2ζ(1,12iln(bb2a22π)(2πi)2ζ(1,12iln(bb2a22π)+(2πi)2ζ(1,12iln(b+b2a22π)(2πi)2ζ(1,12iln(b+b2a22π)=12((ln(bb2a2))2)+12((ln(bb2a2))2)+12((ln(b+b2a2))2)+12(ln((b+b2a2))2)=12((πi+ln(b+b2a2))2)+12((πi+ln(b+b2a2))2)+12((ln(b+b2a2))2)+12(ln((b+b2a2))2)=πiln(b+b2a2)πiln(b+b2a2)=πiln(b+b2a2b+b2a2)=2πiln(iba+1b2a2)=2πsin1(ba) (3.1)

    from Eq (12.11.17) in [2] where a|b|. Note we multiplied the ln-term in the third to last equation by bb2a2bb2a2 and simplified.

    0ln(y)yln(a2+2by+y2a22by+y2)dy=(2πi)32ζ(2,12iln(bb2a22π)(2πi)32ζ(2,12iln(bb2a22π)+(2πi)32ζ(2,12iln(b+b2a22π)(2πi)32ζ(2,12iln(b+b2a22π)=16(π2ln(bb2a2)(ln(bb2a2))3)+16(π2ln(bb2a2)+(ln(bb2a2))3)+16(π2ln(b+b2a2)+(ln(b+b2a2))3)+16(π2ln(b+b2a2)+(ln(b+b2a2))3)=π26ln(bb2a2)+π26ln(bb2a2)+2π23ln(b+b2a2)+πi2(ln(b+b2a2))2+2π23ln(b+b2a2)πi2(ln(b+b2a2))2
    =π2(πiln(a2))ln(b+b2a2b+b2a2)=2πln(a)(iln(iba+1b2a2))=2πln(a)sin1(ba) (3.2)

    from Eq (12.11.17) in [2] where a|b|. Note in the fourth to last equation we employed the difference of two squares and the addition of logs to simplify. This result is equivalent to Eq (4.313.5) in [6].

    We take the first partial derivative of Eq (2.5) with respect to k and set k=1, rationalize the denominator on the left-hand side, combine the logarithmic and log-gamma functions on the right-hand side then simplify to get

    0ln(a2+2by+y2a22by+y2)yln(eiαy)dy=2iπln[Γ(αiln(bb2a2)+π2π)Γ(αiln(b+b2a2)+π2π)Γ(αiln(bb2a2)+π2π)Γ(αiln(b2a2b)+π2π)]12i(π2iln(2π))(ln(b2a2b)ln(bb2a2))12i(π2iln(2π))(ln(b2a2b)ln(b2a2+b)) (3.3)

    Using Eq (3.3) and comparing the real and imaginary parts of the left-hand side we get

    0ln(1+y+y21y+y2)y(π2+ln2(y))dy=ln[Γ2(23)Γ2(43)Γ2(56)Γ2(76)]=ln(43) (3.4)

    where the integral

    0ln(1+y+y21y+y2)ln(y)y(π2+ln2(y))dy=0. (3.5)

    Using Eq (3.3) and comparing the real and imaginary parts of the left-hand side we get

    0ln(1y+y21+y+y2)y(π24+ln2(y))dy=ln[Γ4(712)Γ4(1112)Γ4(512)Γ4(1312)] (3.6)

    where the integral

    0ln(1+y+y21y+y2)ln(y)y(π24+ln2(y))dy=0. (3.7)

    Using the method in [8] we replace y by ln(αy2z+z2+y2) and multiply both sides by (y2z+z2+y2)myz2+y2 to get the Cauchy equation

    (y2z+z2+y2)mlnk(αy2z+z2+y2)yz2+y2(k!)=12πiC(αy2z+z2+y2)w+myz2+y2wk+1dw (4.1)

    the logarithmic function is defined in section (4.1) in [1], where k, α, z and m are general complex numbers. We then take the definite integral over y[0,) of both sides to get

    0(y2z+z2+y2)mlnk(αy2z+z2+y2)yz2+y2(k!)dy=12πi0(C(αy2z+z2+y2)w+myz2+y2wk+1dw)dy=12πiC(0(αy2z+z2+y2)w+myz2+y2dy)dwwk+1=12iCαw21+m+wz1+m+wcsc(π(m+w))dw (4.2)

    from 2.2.11.11 in [7] where Re(z)>0, 0<Re(w+m)<1.

    We once again use the method in [8], replacing y with πi(2p+1)+ln(α)+ln(z)+ln(2). Then we multiply both sides by 2mπizm1emπi(2p+1) to yield

    2mπizm1emπi(2p+1)(πi(2p+1)+ln(α)+ln(z)+ln(2))kk!=2mπizm1emπi(2p+1)Cew(πi(2p+1)+ln(α)+ln(z)+ln(2))wk+1dw (4.3)

    We now take the infinite sum of both sides of Eq (4.3) with respect to p over [0,) to get

    2mπiz1mp=0(πi(2p+1)+ln(α)+ln(z)+ln(2))kemπi(2p+1)k!=2mπiz1mp=0(Cew(πi(2p+1)+ln(α)+ln(z)+ln(2))emπi(2p+1)wk+1)dw=2mπiz1mC(p=0ew(πi(2p+1)+ln(α)+ln(z)+ln(2))emπi(2p+1))dwwk+1=12iCαw21+m+wz1+m+wcsc(π(m+w))dw (4.4)

    from (1.232.3) in [6] where csch(ix)=icsc(x) from (4.5.10) in [1] and Im(w)>0 for the sum to converge and if the Re(k)<0 then the argument of the sum over p cannot be zero for some value of p. The log terms cannot be combined in general.

    Since the right hand side of Eqs (4.2) and (4.4) are equal we can equate the left hand sides of these equations to yield

    0(y2z+z2+y2)mlnk(αy2z+z2+y2)yz2+y2(k!)dy=2mπiz1mp=0(πi(2p+1)+ln(α)+ln(z)+ln(2))kemπi(2p+1)k! (4.5)

    We can simplify the infinite sum on the right hand side to get

    0(y2z+z2+y2)mlnk(αy2z+z2+y2)yz2+y2dy=2k+memπi(πi)k+1zm1Φ(e2mπi,k,12i(ln(α)+ln(2z))2π) (4.6)

    from (9.550) in [6] where Φ(r,s,u) is the Lerch function. Note the left-hand side of Eq (4.6) converges for all finite k. The integral in Eq (4.6) can be used as an alternative method to evaluating the Lerch function. The Lerch function has a series representation given by

    Φ(z,s,v)=n=0(v+n)szn (4.7)

    where |z|<1,v0,1,.. and is continued analytically by its integral representation given by

    Φ(z,s,v)=1Γ(s)0ts1evt1zetdt=1Γ(s)0ts1e(v1)tetzdt (4.8)

    where Re(v)>0, or |z|1,z1,Re(s)>0, or z=1,Re(s)>1.

    Using Eq (4.6) with various values of the parameters we will derive interesting integrals in terms of famous formula.

    01+4y21y12+2y2ln(12(11+4y2))dy=21/2eπi/2(1/2)1/2Φ(1,1,12i(ln(1)2π)=iln(2) (5.1)

    from (0.232.1) in [6].

    01+4y21y12+2y2ln2(12(11+4y2))dy=23/2eπi/2(πi)1(1/2)1/2Φ(1,2,12i(ln(1)2π)=π24 (5.2)

    from (0.234.1) in [6].

    022/3(1+4y21)1/3y1+4y2ln2(12(11+4y2))dy=ieπi/32πΦ(e2πi/3,2,1)=ieπi/3Li2(e2πi/3)2π (5.3)

    from (6) in [5], where Li2(z)=zΦ(z,2,1) is the Dilogarithm, (1.11.14) in [3] also called Spence's function in honour of William Spence, the Scottish mathematician (1777-1815).

    In this article we derived the product of logarithmic functions in terms of the Hurwitz Zeta function. We also derived the definite integral of the logarithm of the square root of a function in terms of the Lerch function. Then we used these integral formula to derive known results for a famous integral and its generalized form. We were able to produce a closed form solution for Eq (25) Table 134 in Bierens de Haan [4] and Eq (4.313.5) in [6] not previously derived using Eq (2.5). The results presented were numerically verified for both real and imaginary values of the parameters in the integrals using Mathematica by Wolfram. In this work we used Mathematica software to numerically evaluate both the definite integral and associated Special function for complex values of the parameters k, α, a, m and b. We considered various ranges of these parameters for real, integer, negative and positive values. We compared the evaluation of the definite integral to the evaluated Special function and ensured agreement.

    In this paper, we have derived a method for expressing definite integrals in terms of Special functions using contour integration. The contour we used was specific to solving integral representations in terms of the Hurwitz zeta function. We expect that other contours and integrals can be derived using this method.

    Funding provided by a Natural Sciences Research Council of Canada Grant number 504070.

    The authors declare no conflict of interest.



    [1] M. Abramowitz, I. A. Stegun, Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables, 9 Eds., New York, Dover, 1982.
    [2] T. M. Apostol, Introduction to Analytic Number Theory, New York, Springer-Verlag, 1995.
    [3] A. Erdéyli, W. Magnus, F. Oberhettinger, et al. Higher Transcendental Functions, McGraw-Hill Book Company, Inc., New York-Toronto-London, 1953.
    [4] D. Bierens de Haan, Nouvelles Tables d'intégrales définies, Amsterdam, 1867.
    [5] J. Guillera, J. Sondow, Double integrals and infinite products for some classical constants via analytic continuations of Lerch's transcendent, Ramanujan J., 16 (2008), 247.
    [6] I. S. Gradshteyn, I. M. Ryzhik, Tables of Integrals, Series and Products, 6 Eds., Academic Press, USA, 2000.
    [7] A. P. Prudnikov, Y. A. Brychkov, O. I. Marichev, Integrals and Series, More Special Functions, USSR Academy of Sciences, Moscow, 1990.
    [8] R. Reynolds, A. Stauffer, A Method for Evaluating Definite Integrals in terms of Special Functions with Examples, Available from: https://arxiv.org/pdf/1906.04927.pdf.
    [9] H. J. Weber, G. B. Arfken, Mathematical Methods for Physicists, ISE. Academic Press, 2004.
  • This article has been cited by:

    1. Robert Reynolds, Allan Stauffer, Definite Integral of Algebraic, Exponential and Hyperbolic Functions Expressed in Terms of Special Functions, 2020, 8, 2227-7390, 1425, 10.3390/math8091425
    2. Robert Reynolds, Allan Stauffer, A Note on Some Definite Integrals of Arthur Erdélyi and George Watson, 2021, 9, 2227-7390, 674, 10.3390/math9060674
    3. Robert Reynolds, Allan Stauffer, Note on an integral by Anatolii Prudnikov, 2021, 6, 2473-6988, 2680, 10.3934/math.2021162
    4. Mykola Yaremenko, Generalization of the Fourier Calculus and Wigner Function, 2022, 2, 2732-9976, 104, 10.37394/232021.2022.2.17
    5. Mykola Yaremenko, General Periodic Functions and Generalization of Fourier analysis, 2022, 9, 2313-0571, 103, 10.46300/91019.2022.9.15
    6. Mykola Yaremenko, Generalization of Fourier Transform and Weyl Calculus, 2022, 16, 1998-4464, 904, 10.46300/9106.2022.16.112
  • Reader Comments
  • © 2020 the Author(s), licensee AIMS Press. This is an open access article distributed under the terms of the Creative Commons Attribution License (http://creativecommons.org/licenses/by/4.0)
通讯作者: 陈斌, bchen63@163.com
  • 1. 

    沈阳化工大学材料科学与工程学院 沈阳 110142

  1. 本站搜索
  2. 百度学术搜索
  3. 万方数据库搜索
  4. CNKI搜索

Metrics

Article views(4244) PDF downloads(240) Cited by(6)

Other Articles By Authors

/

DownLoad:  Full-Size Img  PowerPoint
Return
Return

Catalog