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Local existence and lower bound of blow-up time to a Cauchy problem of a coupled nonlinear wave equations

  • In this paper, we consider a Cauchy problem of a coupled linearly-damped wave equations with nonlinear sources. In the whole space, we establish the local existence and show that there are solutions with negative initial energy that blow up in a finite time. Moreover, under some conditions on the initial data, we estimate a lower bound of that time.

    Citation: Mohammad Kafini, Shadi Al-Omari. Local existence and lower bound of blow-up time to a Cauchy problem of a coupled nonlinear wave equations[J]. AIMS Mathematics, 2021, 6(8): 9059-9074. doi: 10.3934/math.2021526

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  • In this paper, we consider a Cauchy problem of a coupled linearly-damped wave equations with nonlinear sources. In the whole space, we establish the local existence and show that there are solutions with negative initial energy that blow up in a finite time. Moreover, under some conditions on the initial data, we estimate a lower bound of that time.



    In this work, we consider the following Cauchy problem of a coupled linearly-damped wave equations

    {uttΔu+λ1ut(x,t)=f1(u,v),inRn×(0,),vttΔv+λ2vt(x,t)=f2(u,v),inRn×(0,),u(x,0)=u0(x),ut(x,0)=u1(x),xRn,v(x,0)=v0(x),vt(x,0)=v1(x),xRn, (1.1)

    where λ1,λ2 are two positive constants. The functions u0, u1,v0, v1 are the initial data to be specified later.

    A single equation of problem (1.1), in a bounded domain Ω Rn (n1), has been extensively studied and many results concerning global existence and nonexistence have been proved. For instance, for the equation

    uttΔu+aut|ut|m=b|u|γu,    Ω×(0,), (1.2)

    m,γ0, it is well known that, for a=0, the source term bu|u|γ, (γ>0) causes finite time blow up of solutions with negative initial energy (see [1]). The interaction between the damping and the source terms was first considered by Levine [2,3] in the linear damping case (m=0). He showed that solutions with negative initial energy blow up in finite time. Georgiev and Todorova [4] extended Levine's result to the nonlinear damping case (m>0). In their work, the authors introduced a different method and showed that solutions with negative energy continue to exist globally 'in time' if mγ and blow up in finite time if γ>m and the initial energy is sufficiently negative. This last blow-up result has been extended to solutions with negative initial energy by Messaoudi [5] and others. For results of same nature, we refer the reader to Levine and Serrin [6], Vitillaro [7], Messaoudi and Said-Houari [8] and Messaoudi [9,10].

    For problem (1.2) in Rn, we mention, among others, the work of Levine Serrin and Park [11]. Where the authors established a global existence and global nonexistence of solutions of the Cauchy problem for a nonlinearly damped wave equation. Todorova [12,13], showed that restriction in the case of compactly supported initial data is crucial for the blow-up result and it is not essential for the global existence. The local existence theorem could be proved without the requirement for the compact support of the data. Messaoudi [14], consider the Cauchy problem for the nonlinearly damped wave equation with nonlinear source

    uttΔu+aut|ut|m=b|u|γu,  in Rn×(0,),

    where a,b>0 and m,γ>2. He proved that given any time T>0, there exist always initial data with sufficiently negative initial energy, for which the solution blows up in time T. This result improves an earlier one by Todorova [12]. Zhou [15], considered the Cauchy problem for a nonlinear wave equation with linear damping and source terms. He proved that the solution blows up in finite time even for vanishing initial energy if the initial datum u0, u1 satisfies Rnu0u1dx0.

    In [16], Kafini and Messaoudi considered the Cauchy problem

    {uttΔu+t0g(ts)Δu(x,s)ds+ut=|u|p1u,xRn,t>0u(x,0)=u0(x),ut(x,0)=u1(x),xRn

    with negative initial energy and

    t0g(s)ds<2p22p1  and   Rnu0u1dx0,

    they proved a finite-time blow-up result. In [17], the same authors proved a blow-up result to a coupled system

    {uttΔu+t0g(ts)Δu(x,s)ds=f1(u,v),   in Rn×(0,)vttΔv+t0h(ts)Δv(x,s)ds=f2(u,v),   in Rn×(0,)u(x,0)=u0(x),ut(x,0)=u1(x),xRnv(x,0)=v0(x),vt(x,0)=v1(x),xRn. (1.3)

    Systems in a bounded domains of Rn have been extensively studied by many authors. Messaoudi and Houari [18], established a global nonexistence of positive initial-energy solutions of a system of nonlinear viscoelastic wave equations with damping and source terms. Agre and Rammaha [19] studied the following system

    {uttΔu+ut|ut|m1=f1(u,v)vttΔv+vt|vt|r1=f2(u,v), (1.4)

    in Ω×(0,T) with initial and boundary conditions of Dirichlet type. They proved several results concerning local and global existence of a weak solution and showed that any weak solution with negative initial energy blows up in finite time. For more results on different systems, we refer to Messaoudi et al. [20], Santos [21], Cavalcanti et al. [22] and Wu [23].

    Looking at our system in (1.1) and the system in (1.3), they differ by the type of damping only. But the proof is completely different due to nature of the viscoelastic damping. Although the damping in (1.4) is nonlinear, but it is proved in a bounded domain ΩRn and for n=1,2,3 only. Also the method is different.

    Our aim is to study (1.1) and establish the local existence of solutions, the blow-up result in a finite time using the concavity method introduced by Levine in [2]. In addition, we obtain the lower bound of the blow-up time. To achieve this goal some conditions have to be imposed on the source functions f1 and f2 and the initial data as well. The paper is organized as follows. In section 2, we present conditions needed for our results and the proof of the local existence. In section 3, we present the statement and proof of the main result.

    We start with the following theorem and assumptions.

    Theorem 2.1. [24] (Sobolev, Gagliardo, Nirenberg)

    Suppose that 1p<n. If

    uW1,p(Rn),thenuLp(Rn),

    with

    1p=1p1n. (2.1)

    Moreover there exists a constant C = C(N, p) such that

    ||u||pC||u||p,uW1,p(Rn).

    Corollary 2.2.[24] Suppose that 1p<n. Then

    W1,p(Rn)Lq(Rn), q[p,p]

    with continuous injection.

    (G1) There exists a function I(u,v)0 such that

    Iu=f1(u,v), Iv=f2(u,v).

    (G2) There exists a constant ρ>2 such that

    Rn[uf1(u,v)+vf2(u,v)ρI(u,v)]dx0.u,vH1(Rn).

    (G3)There exists a constant d>0 such that

    |f1(χ,ϕ)|d(|χ|β1+|ϕ|β2), (χ,ϕ)R2,|f2(χ,ϕ)|d(|χ|β3+|ϕ|β4), (χ,ϕ)R2,

    where

    βi>2   if   n=1,2   and   n+2nβinn2, n3,   i=1,2,3,4. (2.2)

    (G4)Further assume that f1,f2C1(Rn) such that

    |fi(u,v)|C(|u|β1+|v|β1+1),  u,vR,  i=1,2,

    and β =max{βi, i=1,2,3,4}>1.

    Note that condition (G3) and (G4) are sufficient to establish the existence of a local solution of (1.1) in an interval (0,T] (see [20,25,26,27]) and not needed for the blow-up result.

    An example of a function that satisfying the other conditions (G1) and (G2) is

    I(u,v)=αρ|uv|ρ,

    where we have

    Iu=f1(u,v)=α|uv|ρ2(uv),Iv=f2(u,v)=α|uv|ρ2(uv).

    To start the proof, we set ϕ=ut, ψ=vt and denote by

    Φ=(u,ϕ,v,ψ)T,Φ(0)=Φ0=(u0,u1,v0,v1)T,J(Φ)=(0,f1,0,f2)T.

    Therefore (1.1) can be rewritten as an initial value problem:

    {tΦ+AΦ=J(Φ)Φ(0)=Φ0, (2.3)

    where the linear operator A:D(A)H is defined by

    AΦ=(ϕΔu+λ1ϕψΔv+λ2ψ). (2.4)

    The state space of Φ is the Hilbert space

    H=[H1(Rn)×L2(Rn)]2,

    equipped with the inner product

    Φ,˜ΦH=Rn(u.˜u+ϕ˜ϕ+v.˜v+ψ˜ψ)dx,

    for all Φ=(u,ϕ,v,ψ)T and ˜Φ=(˜u,˜ϕ,˜v,˜ψ)T in H. The domain of A is

    D(A)={ΦH:u,vH2(Rn), ϕ,ψH1(Rn)}.

    Then, we have the following local existence result.

    Theorem 2.3.Assume that (G4) holds. Then for any Φ0 H, problem (2.3) has a unique weak solution ΦC(R+;H).

    Proof. First, for all ΦD(A), we have

    AΦ,ΦH=Rnϕ.udx+Rn(Δu+λ1ϕ)ϕdxRnψ.vdx+Rn(Δv+λ2ψ)ψdx=λ1Rn|ϕ|2dx+λ2Rn|ψ|2dx0. (2.5)

    Therefore, A is a monotone operator.

    To show that A is maximal, we prove that for each

    G=(g1,g2,g3,g4)TH,

    there exists V=(u,ϕ,v,ψ)TD(A) such that (I+A)V=G. That is,

    {uϕ=g1ϕΔu+λ1ϕ=g2vψ=g3ψΔv+λ2ψ=g4. (2.6)

    From (2.6)1 and (2.6)3, we have ϕ= ug1 and ψ=vg3. Thus, (2.6)2 and (2.6)4 give

    u11+λ1Δu=11+λ1g2+g1,v11+λ2Δv=11+λ2g4+g3.

    Now we define, over [H1(Rn)×H1(Rn)]2, the bilinear form

    B((u,v),(˜u,˜v))=Rn(u˜u+v˜v+11+λ1u.˜u+11+λ2v.˜v)dx,

    and over H1(Rn)×H1(Rn), the linear form

    L((˜u,˜v))=Rn[(11+λ1g2+g1)˜u+(11+λ2g4+g2)˜v]dx.

    It is easy to verify that B is continuous and coercive over H1(Rn)×H1(Rn) and L is continuous on H1(Rn). Then, Lax-Milgram theorem implies that the equation

    B((u,v),(˜u,˜v))=L((˜u,˜v)),   (˜u,˜v)H1(Rn)×H1(Rn), (2.7)

    has a unique solution (u,v)H1(Rn)×H1(Rn). Hence,

    ϕ=ug1H1(Rn)   and   ψ=vg3H1(Rn).

    Thus, VH.

    Using (2.7) for ˜v=0, we get

    Rn(u˜u+11+λ1u.˜u)dx=Rn(11+λ1g2+g1)˜udx   ˜uH1(Rn). (2.8)

    The elliptic regularity theory, then, implies that uH2(Rn) and, in addition, Green's formula and (2.6)2 give

    Rn[u11+λ1Δu(11+λ1g2+g1)]˜u=0,    ˜uH1(Rn). (2.9)

    Hence,

    u11+λ1Δu=(11+λ1g2+g1)L2(Rn).

    Similarly, using (2.7) for ˜u=0, we get that vH2(Rn) and

    v11+λ2Δu=(11+λ2g4+g3)L2(Rn).

    Therefore,

    V=(u,ϕ,v,ψ)TD(A).

    Consequently, I+A is surjective and then A is maximal.

    Finally, we show that J:HH is locally Lipchitz. Hence, we estimate

    J(Φ)J(˜Φ)2H=(0,f1(u,v)f1(˜u,˜v),0,f2(u,v)f2(˜u,˜v))2H=f1(u,v)f1(˜u,˜v)2L2+f2(u,v)f2(˜u,˜v)2L2=Rn|f1(u,v)f1(˜u,˜v)|2dx+Rn|f2(u,v)f2(˜u,˜v)|2dx. (2.10)

    To handle the first term of the right-hand side of (2.10), we use the mean value theorem to get

    |f1(u,v)f1(˜u,˜v)||f1(u,v)|(|u˜u|+|v˜v|). (2.11)

    Therefore, (G4) implies

    Rn|f1(u,v)f1(˜u,˜v)|2dxCRn(|u˜u|2+|v˜v|2)×(|u|2(β1)+|˜u|2(β1)+|v|2(β1)+|˜v|2(β1)+1)dx. (2.12)

    All terms in (2.12) are estimated in the same manner. As u,˜u,v,˜vH1(Rn), we use Theorem 2.1, Corollary 2.2 and Hölder's inequality, to obtain

    Rn|u˜u|2|u|2(β1)dxC(Rn|u˜u|2nn2dx)n2n(Rn|u|n(β1)dx)2nCu˜u2L2nn2(Rn)u2(β1)Ln(β1)(Rn)Cu˜u2H1(Rn)(uLn(β1)(Rn))2(β1)Cu˜u2H1(Rn)(uH1(Rn))2(β1). (2.13)

    Hence

    Rn|f1(u,v)f1(˜u,˜v)|2dxC(u˜u2H1(Rn)+v˜v2H1(Rn)). (2.14)

    Also, similar estimations yield to

    Rn|f2(u,v)f2(˜u,˜v)|2dxC(u˜u2H1(Rn)+v˜v2H1(Rn)). (2.15)

    Inserting (2.14), (2.15) in (2.10), we have

    J(Φ)J(˜Φ)2HCΦ˜Φ2H. (2.16)

    Therefore, J is locally Lipchitz. Thanks to the theorems in Komornik [28] (See also Pazy [29]), the proof is completed.

    The energy functional associated to the above system is given by

    E(t):=12(||ut||22+||vt||22+||u(t)||22+||v(t)||22)RnI(u,v)dx,   t0. (2.17)

    Consequently, we present the following lemma.

    Lemma 2.4.The solution of (1.1) satisfies,

    E(t)λRn(|ut|2+|vt|2)dx0, (2.18)

    where λ=min{λ1,λ2}.

    Proof. Multiplying Eq (1.1)1 by ut, equation (1.1)2 by vt and integrating over Rn then summing up we get the result.

    Finally, we set

    F(t)=12Rn(|u(x,t)|2+|v(x,t)|2)dx+λ2L(t)+12β(t+t0)2, (2.19)

    for t0>0 and β>0 to be chosen later and L(t) is define by

    L(t)=t0Rn(|u(x,s)|2+|v(x,s)|2)dxds+(Tt)Rn(|u0(s)|2+|v0(s)|2)ds. (2.20)

    In this section we state and prove our main result.

    Theorem 3.1. Assume that (G1)–(G3) hold and the initial data

    (u0,v0),(u1,v1)H1(Rn)×L2(Rn),

    satisfying,

    E(0)=12(u122+u022+v122+v022)RnI(u0,v0)dx<0. (3.1)

    Then the corresponding solution of (1.1) blows up in finite time.

    Before the proof of this theorem, we need the following technical lemmas.

    Lemma 3.2.Along the solution of (1.1), the functional L(t) defined in (2.20) satisfies,

    L(t)=2t0Rn(uut(x,s)+vvt(x,s))dxds (3.2)

    and

    L(t)=2Rn(uut(x,s)+vvt(x,s))dxds. (3.3)

    Proof. A direct differentiation of (2.20) yields

    L(t)=Rn(|u(x,s)|2+|v(x,s)|2)dxRn(|u0(s)|2+|v0(s)|2)ds=2t0Rn(uut(x,s)+vvt(x,s))dxds

    and

    L(t)=2Rn(uut(x,s)+vvt(x,s))dxds.      

    Lemma 3.3.Along the solution of (1.1), we estimate,

    Rn(uutt+vvtt)dx=(ρ21)(u2+v2)+ρ2(Rnu2tdx+Rnv2tdx)ρE(t)λ(Rnuutdx+Rnvvtdx). (3.4)

    Proof. Multiply Eq (1.1)1 by u and Eq (1.1)2 by v and integrate by parts over Rn to get

    Rn(uutt+vvtt)dx=Rn(|u|2+|v|2)dxλ1Rnuutdxλ2Rnvvtdx+ρRnI(u,v)dx.

    Exploiting (2.17) to substitute for RnI(u,v)dx, we have

    Rn(uutt+vvtt)dx=(ρ21)(u2+v2)+ρ2(Rnu2tdx+Rnv2tdx)ρE(t)λ(Rnuutdx+Rnvvtdx).      

    Lemma 3.4.Along the solution of (1.1), we estimate, for any ϵ>0,

    J=(Rn(utu+vtv)dx+β(t+t0)+λ2L(t))2F(t)[(1+ϵ)(Rnu2tdx+Rnv2tdx)+2(1+1ϵ)(βλE(t))]. (3.5)

    Proof. By using Young's inequality, we have

    J(Rn(utu+vtv)dx)2+(β(t+t0)+λ2L(t))2+2[β(t+t0)+λ2L(t)]Rn(utu+vtv)dx(Rn(utu+vtv)dx)2+(β(t+t0)+λ2L(t))2+2[ϵ2(Rn(utu+vtv)dx)2+12ϵ(β(t+t0)+λ2L(t))2](1+ϵ)(Rn(utu+vtv)dx)2+(1+1ϵ)(β(t+t0)+λ2L(t))2

    and using Cauchy-Schwartz inequality yields

    J(1+ϵ)(Rnu2dx+Rnv2dx)(Rnu2tdx+Rnv2tdx)+2(1+1ϵ)[β2(t+t0)2+(λ2L(t))2].

    Recalling (3.2), we estimate

    (L(t))2=(2t0Rn(uut(x,s)+vvt(x,s))dxds)24(t0(u(τ)22+v(τ)22)dτ)(t0(ut(τ)22+vt(τ)22)dτ). (3.6)

    Using (2.18) and (3.1), we have

    E(t)E(0)<0.

    Hence,

    t0(ut(τ)22+vt(τ)22)dτ1λ[E(0)E(t)]1λE(t). (3.7)

    Using (2.19) and (3.7), estimation (3.6) becomes

    (λ2L(t))2λF(t)E(t).

    Hence,

    J[(1+ϵ)F(t)(Rnu2tdx+Rnv2tdx)]+2(1+1ϵ)F(t)[βλE(t)]F(t)[(1+ϵ)(Rnu2tdx+Rnv2tdx)+2(1+1ϵ)(βλE(t))]. 

    Proof of theorem 3.1. By differentiating F in (2.19) twice we get

    F(t)=Rn(utu+vtv)dx+λ2L(t)+β(t+t0) (3.8)

    and

    F(t)=Rn(uttu+vttv)dx+Rn(|ut|2+|vt|2)dx+λ2L(t)+β. (3.9)

    Inserting (3.3) and (3.4) in (3.9), yield

    F(t)(ρ2+1)(ut22+vt22)+(ρ21)[u22+v22]ρE(t)+β. (3.10)

    We then define

    G(t):=Fγ(t),

    for γ>0 to be chosen properly.

    Differentiating G twice we arrive at

    G(t)=γF(γ+1)(t)F(t)   and    G(t)=γF(γ+2)(t)Q(t),

    where

    Q(t)=F(t)F(t)(γ+1)F2(t). (3.11)

    Using (3.5), the last term of (3.11) takes the form

    (γ+1)(Rn(uut+vvt)dx+λ2L(t)+β(t+t0))2(γ+1)F(t)[(1+ϵ)(ut22+vt22)+2(1+1ϵ)(βλE(t))].

    Recalling (3.10), estimation (3.11) becomes

    Q(t)F(t)[(ρ21)(u22+v22)]+F(t)[(ρ2+1(1+ε)(γ+1))(ut22+vt22)]+F(t)[ρE(t)2(γ+1)(1+1ϵ)(βλE(t))],       ε>0. (3.12)

    It is known, from (G2), that ρ2>1. Consequently, we choose ε < ρ4 andγ so that

    0<γ<ρ4ε4(1+ε).

    Hence, (3.12) becomes

    Q(t)F(t){E(t)[ρ2(γ+1)(1+1ϵ)λ]2β(γ+1)(1+1ϵ)},  ε>0. (3.13)

    Now, the choice of

    λ<ρ2(γ+1)(1+1ϵ)

    will make

    k=ρ2(γ+1)(1+1ϵ)λ>0.

    Using the fact that

    kE(t)>kE(0)>0,

    we infer, from (3.13), that

    Q(t)F(t)[kE(0)2β(γ+1)(1+1ϵ)]. (3.14)

    Then for β small enough we conclude, from (3.14), that

    Q(t)0,         t0

    and

    G(t)0,    t0.

    Therefore, G is decreasing. By choosing t0 large enough we get

    F(0)=Rn(u0u1+v0v1)dx+βt0>0,

    hence G(0)<0.

    Finally Taylor expansion of G yields

    G(t)G(0)+tG(0),t0,

    which shows that G(t) vanishes at a time tmG(0)G(0). Consequently F(t) must become infinite at time tm.

    In this section, we estimate a lower bound for the blow-up time through the following theorem.

    Theorem 4.1. Assume that (G1)–(G3) hold and the initial data

    (u0,v0),(u1,v1)H1(Rn)×L2(Rn),

    are with compact support. Assume further u is a solution of (1.1) which blows up at a finite time T. Then there exists a positive constant C such that

    ψ(0)dyy+CyrT,

    where r =max{βi, i=1,2,3,4}1 and

    ψ(t)=(L+t)2rRnI(u,v)dx.

    Before we start the proof, we exploit the finite wave speed of propagation to have the following lemmas.

    Lemma 4.2. If the initial data u0,u1are with compact support then for any solution u of (1.1), we have

    ||u(t)||2C(L+t)||u(t)||2.

    Proof. In Theorem 2.1, if we let p=2 then we have p=2nn2,n3 and

    ||u||pC||u||2.

    Now

    Rn|u|2dx=B(L+t)|u|2dx,

    where L>0 is such that

    Supp{u0(x),u1(x)}B(L)

    and B(L+t) is the ball, with radius L+t, centered at the origin. Using Hölder inequality, we get

    Rn|u|2dx(B(L+t)1dx)12p(B(L+t)(|u|2)p2dx)2pC(L+t)2||u(t)||2p,

    or

    ||u(t)||2C(L+t)||u(t)||pC(L+t)||u(t)||2.

    Hence, the result follows.

    Proof of Theorem 4.1. A direct differentiation of ψ(t) yields

    ψ(t)=2r(L+t)2r1RnI(u,v)dx+(L+t)2rRn(utIu(u,v)+vtIv(u,v))dx(L+t)2rRn(utIu(u,v)+vtIv(u,v))dx.

    Using Young's inequality and (G1), we have

    (L+t)2rψ(t)12Rn(u2t+v2t)dx+12Rn(I2u+I2v)dx=12Rn(u2t+v2t)dx+12Rn(f21+f22)dx.

    Using (G3), we get

    (L+t)2rψ(t)12Rn(u2t+v2t)dx+dRn(|u|r+|v|r)2dx. (4.1)

    To estimate the last term of (4.1), we have two cases:

    Case I: For |u||v|.

    Using Theorem 2.1 and Corollary 2.2, we have

    Rn(|u|r+|v|r)2dx4Rn|v|2rdxC((L+t)2Rn|v|2dx)rC((L+t)2(||v||22+||u||22))r.

    Case II: For |u||v|.

    Similar to case I, we have

    Rn(|u|r+|v|r)2dx4Rn|u|2rdxC((L+t)2(||v||22+||u||22))r.

    Thus, estimation (4.1) becomes

    (L+t)2rψ(t)12(ut22+vt22)+C((L+t)2(||v||22+||u||22))r. (4.2)

    Recalling the fact that E(t)E(0)<0, we deduce, from (2.17), that

    ||u(t)||22+||v(t)||222RnI(u,v)dx. (4.3)

    Inserting (4.3) in (4.2), gives

    (L+t)2rψ(t)12(ut22+vt22)+C((L+t)2RnI(u,v)dx)r. (4.4)

    Again (2.17) yields

    ||ut||22+||vt||222RnI(u,v)dx2(L+t)2rψ(t),

    thus, from (4.4), we have

    (L+t)2rψ(t)(L+t)2rψ(t)+C((L+t)2ψ(t))r, (4.5)

    or

    ψ(t)ψ(t)+C(ψ(t))r.

    If we use the substitution y=ψ(t) and solve (4.5) over (0,T), then we reach

    ψ(0)dyy+CyrT.

    This completes the proof.

    The authors thank King Fahd University of Petroleum and Minerals (KFUPM) - Interdisciplinary Research Center (IRC) for Construction and Building Materials for their continuous supports. This work is supported by KFUPM under project # SR181024.

    The authors declare that there is no conflict of interest regarding the publication of this paper.



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