Citation: Yibing Sun, Yige Zhao. Oscillatory and asymptotic behavior of third-order neutral delay differential equations with distributed deviating arguments[J]. AIMS Mathematics, 2020, 5(5): 5076-5093. doi: 10.3934/math.2020326
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The purpose of this work is to investigate the oscillatory and asymptotic behavior of the third-order neutral delay differential equations with distributed deviating arguments
[r1(t)((r2(t)(z′(t))α2)′)α1]′+∫baq(t,ξ)f(x(σ(t,ξ)))dξ=0, | (1.1) |
where z(t)=x(t)+p(t)x(τ(t)), t≥t0>0, 0≤a<b. We also assume that the following conditions are satisfied:
● (H1) r1(t), r2(t), p(t)∈C([t0,∞),R), q(t,ξ)∈C([t0,∞)×[a,b],[0,∞)), r1(t)>0, r2(t)>0 and p(t)≥1 with p(t)≢1;
● (H2) τ(t)∈C([t0,∞),R) is invertible, τ(t)≤t and limt→∞τ(t)=∞;
● (H3) σ(t,ξ)∈C([t0,∞)×[a,b],R) is non-increasing for ξ and liminft→∞σ(t,ξ)=∞ for ξ∈[a,b];
● (H4) f(x)∈C(R,R) is assumed to satisfy xf(x)>0 and there exists a positive constant K such that
f(x)xα3≥K for any variable x≠0; |
● (H5) αi, i=1, 2, 3 are ratios of positive odd integers.
By a solution of Eq. (1.1) we mean a function x(t)∈C([Ty,∞),R), Ty≥t0, which has z(t), r2(t)(z′(t))α2, r1(t)((r2(t)(z′(t))α2)′)α1∈C1([Ty,∞),R) and satisfies (1.1) on [Ty,∞). A solution x(t) of (1.1) is said to be proper if it exists on the interval [Ty,∞) and satisfies the condition
sup{|x(t)|:T≤t<∞}>0 for any T≥Ty. |
Our attention is restricted to these solutions and we make the standing hypothesis that (1.1) admits such a solution. A solution of (1.1) is called oscillatory if it has arbitrarily large zeros on [Ty,∞) and otherwise it is called non-oscillatory, i.e., the solution is positive or negative eventually. Eq. (1.1) is said to be oscillatory if all its solutions are oscillatory.
Main results of this paper are organized into three parts in accordance with different assumptions on the coefficients r1(t) and r2(t). In Section 2, oscillation results of (1.1) are established in the case
∫∞t0r−1α11(t)dt=∞, ∫∞t0r−1α22(t)dt=∞. | (1.2) |
In Section 3, some new oscillation criteria for (1.1) are obtained in the case
∫∞t0r−1α11(t)dt<∞, ∫∞t0r−1α22(t)dt=∞. | (1.3) |
By assuming that
∫∞t0r−1α11(t)dt<∞, ∫∞t0r−1α22(t)dt<∞. | (1.4) |
Some oscillation theorems of (1.1) are given in Section 4. In order to illustrate the results reported in Sections 2, 3 and 4, we present some examples in Section 5.
During the last few decades, analysis of the oscillation and asymptotic behavior of solutions of third-order differential equations, difference equations and dynamic equations on time scales have experienced long-term interest and we refer the reader to the papers [1,2,3,4,5,6,7,8,9,10,11,12]. Due to the huge advantage of neutral differential equations in describing several neutral phenomena, there is of great scientific and academic values theoretically and practically for studying neutral differential equations. Hence, a large amount of research attention has been focused on the oscillation problem of third-order linear and nonlinear neutral differential equations in resent years; see, for example [13,14,15,16,17], and the references are cited therein.
The third-order neutral differential equation
[r(t)((x(t)+p(t)x(τ(t)))″)γ]′+q(t)f(x(σ(t)))=0, |
and its special cases have been studied by Şenel and Utku [8], Baculíková and Džurina [13], Jiang et al. [14,15], where ∫∞t0r−1γ(t)dt=∞, 0≤p(t)≤P<1. Candan [11], Došlá and Liška [16], and Li et al. [17] established some sufficient conditions for oscillation of the following class of third-order neutral differential equations
[a(t)(b(t)(x(t)+p(t)x(τ(t)))′)′]′+q(t)f(x(σ(t)))=0, |
where [11] and [16] only considered the conditions 0≤p(t)≤P<1 and
∫∞t01a(t)dt=∫∞t01b(t)dt=∞, |
and [17] also studied the cases
∫∞t01a(t)dt<∞, ∫∞t01b(t)dt=∞ and ∫∞t01a(t)dt=∫∞t01b(t)dt<∞. |
Recently, there has been an increasing interest in studying the oscillatory and asymptotic behavior of third-order neutral differential equations with distributed deviating arguments [18,19,20,21,22,23,24]. Elabbasy and Moaaz [19] considered the special cases of (1.1) and obtained several oscillation results under the assumption (1.2) and 0≤p(t)≤P<1. By using a new method different from the existing results, Tunç [22] established some new oscillation criteria for
(r(t)((x(t)+p(t)x(τ(t)))″)α)′+∫baq(t,ξ)xα(ϕ(t,ξ))dξ=0, |
where p(t)≥1, and the obtained results greatly enriched the oscillation theory.
It is clear that the above introduced equations are the special cases of (1.1), i.e., (1.1) can be transformed into these equations by letting the corresponding parameters being 1. To the best of our knowledge, there are few results in the literature which ensure that all solutions are either oscillatory or tends to zero monotonically for the third-order neutral differential equations with distributed deviating arguments under the conditions p(t)≥1, (1.3) or (1.4) holds, and the above mentioned results are inapplicable to these conditions. Motivated by Li et al. [17], Elabbasy and Moaaz [19] and Tunç [22], we consider Eq. (1.1) which is not studied in the past and utilize the Riccati transformation technique to establish several oscillation criteria for (1.1) by assume that p(t)≥1, (1.2), (1.3) or (1.4) holds. The results obtained in this paper improve and complement the related criteria reported in [13,16,17,19,22]. All functional inequalities considered here are assumed to hold eventually, that is, they are satisfied for all t large enough.
In the sequel, we use the following notations for a compact presentation of our results:
σ1(t)=σ(t,a), σ2(t)=σ(t,b),z′(τ(t))=(z(τ(t)))′, ρ′+(t)=max{0,ρ′(t)},δ1(t,t1)=∫tt1r−1α11(s)ds, δ2(t,t1)=(δ1(t,t1)r2(t))1α2,δ3(t,t1)=∫tt1δ2(s,t1)ds, t≥t1, |
where ρ(t) will be explained later and t1 is sufficiently large with t1≥t0. Furthermore, assume that
p1(t)=1p(τ−1(t))(1−1p(τ−1(τ−1(t))))>0, | (1.5) |
p2(t)=1p(τ−1(t))(1−δ3(τ−1(τ−1(t)),t1)p(τ−1(τ−1(t)))δ3(τ−1(t),t1))>0, | (1.6) |
where τ−1(t) is the inverse function of τ(t). Then let
q1(t)=K∫baq(t,ξ)pα31(σ(t,ξ))dξ, q2(t)=K∫baq(t,ξ)pα32(σ(t,ξ))dξ. |
We will present the main contribution of this paper as follows.
In this section, we respectively consider the following two cases
σ(t,ξ)≤τ(t), ξ∈[a,b], | (2.1) |
and
σ(t,ξ)≥τ(t), ξ∈[a,b]. | (2.2) |
We now begin with the case when (2.1) holds.
Theorem 2.1. Assume that conditions (H1)–(H5), (1.2), (1.5), (1.6) and (2.1) hold. Furthermore, assume that there exists a function ρ(t)∈C1([t0,∞),(0,∞)) such that for sufficiently large t∗>t2>t1≥t0,
lim supt→∞∫tt∗[(δ3(τ−1(σ2(s)),t1)δ2(τ−1(σ2(s)),t1))α1α2ρ(s)q2(s)γ(τ−1(σ2(s)))rα12(τ−1(σ2(s)))−(ρ′+(s))α1+1r1(τ−1(σ2(s)))(α1+1)α1+1ρα1(s)]ds=∞, | (2.3) |
and
∫∞t0[1r2(u)∫∞u(1r1(v)∫∞vq1(s)ds)1α1dv]1α2du=∞, | (2.4) |
where
γ(t)={m1(δ3(t,t1))α3−α1α2,m1 is any positive constant,if α1α2>α3,m2,m2 is any positive constant,if α1α2≤α3. |
Then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Proof. Suppose that (1.1) has a non-oscillatory solution x(t). Without loss of generality, we assume that there exists t1≥t0 such that x(t)>0, x(τ(t))>0 and x(σ(t,ξ))>0 for ξ∈[a,b] and t≥t1. Then from the definition of z(t), we have z(t)>0. Based on the condition (1.2), z(t) satisfies the following two cases (see, for example [18,19]):
(Ⅰ) z(t)>0, z′(t)>0, (r2(t)(z′(t))α2)′>0 and [r1(t)((r2(t)(z′(t))α2)′)α1]′≤0;
(Ⅱ) z(t)>0, z′(t)<0, (r2(t)(z′(t))α2)′>0 and [r1(t)((r2(t)(z′(t))α2)′)α1]′≤0, for t≥t1.
Assume first that Case (Ⅰ) holds. Then we get
x(t)=z(τ−1(t))p(τ−1(t))−z(τ−1(τ−1(t)))−x(τ−1(τ−1(t)))p(τ−1(t))p(τ−1(τ−1(t)))≥z(τ−1(t))p(τ−1(t))−z(τ−1(τ−1(t)))p(τ−1(t))p(τ−1(τ−1(t))). | (2.5) |
(2.5) can also be seen in [22]. Since r1(t)((r2(t)(z′(t))α2)′)α1 is non-increasing for t≥t1, it indicates that
r2(t)(z′(t))α2≥∫tt1r1α11(s)(r2(s)(z′(s))α2)′r1α11(s)ds≥δ1(t,t1)r1α11(t)(r2(t)(z′(t))α2)′. | (2.6) |
We deduce from (2.6) that
(r2(t)(z′(t))α2δ1(t,t1))′≤0, |
and z′(t)/δ2(t,t1) is non-increasing for t≥t1. Therefore, we obtain
z(t)≥∫tt1z′(s)δ2(s,t1)δ2(s,t1)ds≥δ3(t,t1)δ2(t,t1)z′(t), | (2.7) |
and
(z(t)δ3(t,t1))′≤0, | (2.8) |
which yields that
z(τ−1(τ−1(t)))≤δ3(τ−1(τ−1(t)),t1)δ3(τ−1(t),t1)z(τ−1(t)), t≥t1, | (2.9) |
for τ(t)≤t. Substituting (2.9) into (2.5), we have
x(t)≥p2(t)z(τ−1(t)). |
Then there exists t2>t1 such that σ(t,ξ)≥t1 and
x(σ(t,ξ))≥p2(σ(t,ξ))z(τ−1(σ(t,ξ))), t≥t2. | (2.10) |
Combining (1.1), (H3), (H4) and (2.10), we conclude that
[r1(t)((r2(t)(z′(t))α2)′)α1]′+q2(t)zα3(τ−1(σ2(t)))≤0. | (2.11) |
Define a Riccati transformation ω(t) by
ω(t)=ρ(t)r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1, t≥t2. | (2.12) |
Clearly, ω(t)>0, and
ω′(t)=ρ′(t)ρ(t)ω(t)+ρ(t)[r1(t)((r2(t)(z′(t))α2)′)α1]′(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1−α1ρ(t)r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)′(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1+1. | (2.13) |
Since σ(t,ξ)≤τ(t) and [r1(t)((r2(t)(z′(t))α2)′)α1]′≤0, we get τ−1(σ2(t))≤t and
r1α11(t)(r2(t)(z′(t))α2)′≤r1α11(τ−1(σ2(t)))(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)′. | (2.14) |
Combining (2.11), (2.13) and (2.14), we have
ω′(t)≤ρ′+(t)ρ(t)ω(t)−ρ(t)q2(t)zα3(τ−1(σ2(t)))(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1−α1ρ(t)r1α1+11(t)r1α11(τ−1(σ2(t)))((r2(t)(z′(t))α2)′r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1+1. | (2.15) |
From (2.7), we get
zα1α2(t)(r2(t)(z′(t))α2)α1≥(δ3(t,t1)δ2(t,t1))α1α2r−α12(t). | (2.16) |
Combining (2.12), (2.15) and (2.16), we obtain
ω′(t)≤ρ′+(t)ρ(t)ω(t)−(δ3(τ−1(σ2(t)),t1)δ2(τ−1(σ2(t)),t1))α1α2ρ(t)q2(t)zα3−α1α2(τ−1(σ2(t)))rα12(τ−1(σ2(t)))−α1(ρ(t)r1(τ−1(σ2(t))))1α1ω1α1+1(t). | (2.17) |
In order to compute zα3−α1α2(τ−1(σ2(t))), we consider the following two cases:
(1) α1α2>α3. From (2.8), there exist t3>t2 and h1>0 such that τ−1(σ2(t))≥t2 and
z(τ−1(σ2(t)))δ3(τ−1(σ2(t)),t1)≤z(t2)δ3(t2,t1)=h1, t≥t3, |
which implies that
zα3−α1α2(τ−1(σ2(t)))≥m1(δ3(τ−1(σ2(t)),t1))α3−α1α2, | (2.18) |
where m1=hα3−α1α21.
(2) α1α2≤α3. Based on the fact that z′(t)>0, there exists h2>0 such that
z(τ−1(σ2(t)))≥z(t2)=h2, t≥t3, |
which yields that
zα3−α1α2(τ−1(σ2(t)))≥m2, | (2.19) |
where m2=hα3−α1α22.
Substituting (2.18) and (2.19) into (2.17), we have
ω′(t)≤ρ′+(t)ρ(t)ω(t)−(δ3(τ−1(σ2(t)),t1)δ2(τ−1(σ2(t)),t1))α1α2ρ(t)q2(t)γ(τ−1(σ2(t)))rα12(τ−1(σ2(t)))−α1(ρ(t)r1(τ−1(σ2(t))))1α1ω1α1+1(t). | (2.20) |
Let
C=ρ′+(t)ρ(t), D=α1(ρ(t)r1(τ−1(σ2(t))))1α1, α=α1, u=ω(t). |
Applying the inequality (see [13])
Cu−Du1α+1≤αα(α+1)α+1Cα+1Dα, D>0, u>0, | (2.21) |
together with (2.20), we get
ω′(t)≤−(δ3(τ−1(σ2(t)),t1)δ2(τ−1(σ2(t)),t1))α1α2ρ(t)q2(t)γ(τ−1(σ2(t)))rα12(τ−1(σ2(t)))+(ρ′+(t))α1+1r1(τ−1(σ2(t)))(α1+1)α1+1ρα1(t). | (2.22) |
Integrating (2.22) from t3 to t, we obtain
∫tt3[(δ3(τ−1(σ2(s)),t1)δ2(τ−1(σ2(s)),t1))α1α2ρ(s)q2(s)γ(τ−1(σ2(s)))rα12(τ−1(σ2(s)))−(ρ′+(s))α1+1r1(τ−1(σ2(s)))(α1+1)α1+1ρα1(s)]ds<ω(t3), |
for all sufficiently large t, which contradicts (2.3).
Secondly, assume that Case (Ⅱ) holds. Since z′(t)<0 and τ(t)≤t, (2.5) yields that
x(t)≥p1(t)z(τ−1(t)), |
which indicates that
x(σ(t,ξ))≥p1(σ(t,ξ))z(τ−1(σ(t,ξ))), | (2.23) |
for t≥t2. Using (1.1), (H4) and (2.23), we conclude that
[r1(t)((r2(t)(z′(t))α2)′)α1]′≤−q1(t)zα3(τ−1(σ1(t))). | (2.24) |
By using a similar proof of [19,Lemma 2.2], we can obtain limt→∞x(t)=0 due to the condition (2.4). This completes the proof of Theorem 2.1.
Next, we turn our attention to the case when (2.2) holds.
Theorem 2.2. Assume that conditions (H1)–(H5), (1.2), (1.5), (1.6), (2.2) and (2.4) hold. Moreover, assume that there exists a function ρ(t)∈C1([t0,∞),(0,∞)) such that for sufficiently large t∗>t2>t1≥t0,
lim supt→∞∫tt∗[(δ3(τ(s),t1)δ2(τ(s),t1))α1α2ρ(s)q2(s)γ(τ(s))rα12(τ(s))−(ρ′+(s))α1+1r1(τ(s))(α1+1)α1+1ρα1(s)]ds=∞, | (2.25) |
where γ(t) is defined as in Theorem 2.1. Then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Proof. Suppose that (1.1) has a non-oscillatory solution x(t). Without loss of generality, we assume that there exists t1≥t0 such that x(t)>0, x(τ(t))>0 and x(σ(t,ξ))>0 for ξ∈[a,b] and t≥t1. As in the proof of Theorem 2.1, we have (2.11) and (2.16), and there exist two possible cases (Ⅰ) and (Ⅱ) for z(t) (as those in the proof of Theorem 2.1).
Assume that Case (Ⅰ) holds. Define a Riccati transformation ˜ω(t) by
˜ω(t)=ρ(t)r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ(t))((z(τ(t)))′)α2)α1, t≥t2>t1. | (2.26) |
Clearly, ˜ω(t)>0, and since τ(t)≤t,
˜ω′(t)=ρ′(t)ρ(t)˜ω(t)+ρ(t)[r1(t)((r2(t)(z′(t))α2)′)α1]′(r2(τ(t))((z(τ(t)))′)α2)α1−α1ρ(t)r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ(t))((z(τ(t)))′)α2)′(r2(τ(t))((z(τ(t)))′)α2)α1+1≤ρ′+(t)ρ(t)˜ω(t)−ρ(t)q2(t)zα3(τ−1(σ2(t)))(r2(τ(t))((z(τ(t)))′)α2)α1−α1ρ(t)r1α1+11(t)r1α11(τ(t))((r2(t)(z′(t))α2)′r2(τ(t))((z(τ(t)))′)α2)α1+1. | (2.27) |
From (2.2), we get τ−1(σ2(t))≥t≥τ(t), and then z(τ−1(σ2(t)))≥z(τ(t)). Therefore, based on (2.16), we obtain
zα1α2(τ−1(σ2(t)))(r2(τ(t))((z(τ(t)))′)α2)α1≥(δ3(τ(t),t1)δ2(τ(t),t1))α1α2r−α12(τ(t)). |
Substituting the later inequality, (2.18) and (2.19) into (2.27), we deduce that
˜ω′(t)≤ρ′+(t)ρ(t)˜ω(t)−(δ3(τ(t),t1)δ2(τ(t),t1))α1α2ρ(t)q2(t)γ(τ(t))rα12(τ(t))−α1(ρ(t)r1(τ(t)))1α1˜ω1α1+1(t). | (2.28) |
By using the inequality (2.21) and (2.28), we conclude that
˜ω′(t)≤−(δ3(τ(t),t1)δ2(τ(t),t1))α1α2ρ(t)q2(t)γ(τ(t))rα12(τ(t))+(ρ′+(t))α1+1r1(τ(t))(α1+1)α1+1ρα1(t). | (2.29) |
An integration of (2.29) from t3 (t3>t2) to t leads to a contradiction to (2.25).
Secondly, assume that Case (Ⅱ) holds. Proceeding as in the proof of Case (Ⅱ) in Theorem 2.1, we arrive at the conclusion limt→∞x(t)=0. This completes the proof of Theorem 2.2.
Remark 2.1. With different choices of the function ρ(t), one can derive a number of oscillation criteria for (1.1) from Theorems 2.1 and 2.2.
Remark 2.2. Our results in this section extend and improve those obtained by Tunç [22], and we can get some relevant results by using the technique presented in [22]. The established results here also complement and improve those in [13,16,17,19], since the considered equations in these papers are special cases of (1.1) and our results can be applied to (1.1) in the case where p(t)≥1.
In this section, we will establish some oscillation criteria for (1.1) under the assumption that (1.3) holds. Similarly as in Section 2, we start with the case when (2.1) is satisfied. Firstly, we define the following notations:
˜δ1(t)=∫∞tr−1α11(s)ds, ˜δ2(t,t1)=∫tt1r−1α22(s)ds. |
Furthermore, assume that
˜p2(t)=1p(τ−1(t))(1−˜δ2(τ−1(τ−1(t)),t1)p(τ−1(τ−1(t)))˜δ2(τ−1(t),t1))>0. | (3.1) |
Then let
˜q2(t)=K∫baq(t,ξ)˜pα32(σ(t,ξ))dξ. |
Theorem 3.1. Assume that conditions (H1)–(H5), (1.3), (1.5), (1.6), (2.1), (2.4) and (3.1) hold. Furthermore, assume that there exists ρ(t)∈C1([t0,∞),(0,∞)) such that (2.3) is satisfied for sufficiently large t∗>t2>t1≥t0. If
lim supt→∞∫tt∗[˜δα11(s)˜q2(s)˜γ(s)˜δα1α22(τ−1(σ2(s)),t1)−(α1α1+1)α1+11˜δ1(s)r1α11(s)]ds=∞, | (3.2) |
where
˜γ(t)={m3(˜δ2(t,t1))α3−α1α2,m3 is any positive constant,if α1α2>α3,m2,m2 is any positive constant,if α1α2≤α3, |
then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Proof. Suppose that (1.1) has a non-oscillatory solution x(t). Without loss of generality, we assume that there exists t1≥t0 such that x(t)>0, x(τ(t))>0 and x(σ(t,ξ))>0 for ξ∈[a,b] and t≥t1. Based on the condition (1.3), there exist three possible cases (Ⅰ), (Ⅱ) (as those in the proof of Theorem 2.1) and
(Ⅲ) z(t)>0, z′(t)>0, (r2(t)(z′(t))α2)′<0 and [r1(t)((r2(t)(z′(t))α2)′)α1]′≤0, for t≥t1.
We firstly prove that Case (Ⅲ) holds. It is easy to verify that
(r2(t)(z′(t))α2)′>0 or (r2(t)(z′(t))α2)′<0 |
holds under the condition
∫∞t0r−1α11(t)dt<∞, |
and in the proof of Theorem 2.1, we can see that z(t) has properties (Ⅰ) and (Ⅱ). If (r2(t)(z′(t))α2)′<0, then we claim that z′(t)>0. Otherwise, there exists a constant M1 such that
r2(t)(z′(t))α2≤M1<0, t≥t1. |
Integrating the last inequality from t1 to t, we have
z(t)≤z(t1)+M1∫tt1r−1α22(s)ds. |
Letting t→∞, we get z(t)→−∞, which contradicts the fact that z(t)>0. Hence we conclude that z′(t)>0 here.
Assume now that Cases (Ⅰ) and (Ⅱ) hold. Then we can obtain the conclusion of Theorem 3.1 by using the proof of Theorem 2.1.
Assume that Case (Ⅲ) holds. Since r1(t)((r2(t)(z′(t))α2)′)α1 is nonincreasing for t≥t1 and (r2(t)(z′(t))α2)′<0, we have
r2(l)(z′(l))α2−r2(t)(z′(t))α2=∫ltr1α11(s)(r2(s)(z′(s))α2)′r1α11(s)ds≤r1α11(t)(r2(t)(z′(t))α2)′∫ltr−1α11(s)ds<0. |
Letting l→∞, we get
r2(t)(z′(t))α2≥−˜δ1(t)r1α11(t)(r2(t)(z′(t))α2)′, |
that is
0<−˜δ1(t)r1α11(t)(r2(t)(z′(t))α2)′r2(t)(z′(t))α2≤1. | (3.3) |
In view of r1α22(t)z′(t) is non-increasing for t≥t1, we see that
z(t)≥˜δ2(t,t1)r1α22(t)z′(t), | (3.4) |
and
(z(t)˜δ2(t,t1))′≤0, | (3.5) |
which yields that
z(τ−1(τ−1(t)))≤˜δ2(τ−1(τ−1(t)),t1)˜δ2(τ−1(t),t1)z(τ−1(t)), t≥t1. | (3.6) |
Substituting (3.6) into (2.5), we get
x(t)≥˜p2(t)z(τ−1(t)). |
Then there exists t2>t1 such that σ(t,ξ)≥t1 and
[r1(t)((r2(t)(z′(t))α2)′)α1]′≤−˜q2(t)zα3(τ−1(σ2(t))), t≥t2. | (3.7) |
Define the function ν(t) by
ν(t)=r1(t)((r2(t)(z′(t))α2)′)α1(r2(t)(z′(t))α2)α1, t≥t2. | (3.8) |
Then ν(t)<0 for t≥t2. From (3.3) and (3.8), we obtain
−˜δα11(t)ν(t)≤1. | (3.9) |
Differentiating (3.8) and using (3.7) and (3.8), we get
ν′(t)=[r1(t)((r2(t)(z′(t))α2)′)α1]′(r2(t)(z′(t))α2)α1−α1r1(t)((r2(t)(z′(t))α2)′)α1(r2(t)(z′(t))α2)′(r2(t)(z′(t))α2)α1+1≤−˜q2(t)zα3(τ−1(σ2(t)))(r2(t)(z′(t))α2)α1−α1r1α11(t)ν1α1+1(t). | (3.10) |
From (1.5) and (3.5), we obtain
z(τ−1(σ2(t)))≥˜δ2(τ−1(σ2(t)),t1)˜δ2(t,t1)z(t). | (3.11) |
(3.4) implies that
zα1α2(t)(r2(t)(z′(t))α2)α1≥˜δα1α22(t,t1). | (3.12) |
Combining (3.10), (3.11) and (3.12), we get
ν′(t)≤−˜q2(t)˜δα1α22(τ−1(σ2(t)),t1)zα3−α1α2(t)−α1r1α11(t)ν1α1+1(t), | (3.13) |
due to ˜δ2(τ−1(σ2(t)),t1)≤˜δ2(t,t1). In order to compute zα3−α1α2(t), the case α1α2≤α3 is the same as that in the proof of Theorem 2.1. We now compute the case α1α2>α3. Applying the monotonicity of z(t)/˜δ2(t,t1) for t≥t2 derived from (3.5), there exists h3>0 such that
z(t)˜δ2(t,t1)≤z(t2)˜δ2(t2,t1)=h3, |
which implies that
zα3−α1α2(t)≥m3(˜δ2(t,t1))α3−α1α2, | (3.14) |
where m3=hα3−α1α23. Combining (2.19), (3.13) and (3.14), we conclude that
ν′(t)≤−˜q2(t)˜γ(t)˜δα1α22(τ−1(σ2(t)),t1)−α1r1α11(t)ν1α1+1(t). | (3.15) |
Multiplying (3.15) by ˜δα11(t) and integrating it from t2 to t, we obtain
˜δα11(t)ν(t)−˜δα11(t2)ν(t2)+∫tt2˜δα11(s)˜q2(s)˜γ(s)˜δα1α22(τ−1(σ2(s)),t1)ds |
+α1∫tt2[˜δα11(s)r1α11(s)|ν(s)|1α1+1−˜δα1−11(s)r1α11(s)|ν(s)|]ds≤0. | (3.16) |
By using the inequality (2.21) and (3.16) with
C=˜δα1−11(s)r1α11(s), D=˜δα11(s)r1α11(s), u=|ν(s)|, |
we conclude that
∫tt2[˜δα11(s)˜q2(s)˜γ(s)˜δα1α22(τ−1(σ2(s)),t1)−(α1α1+1)α1+11˜δ1(s)r1α11(s)]ds≤˜δα11(t2)ν(t2)+1, |
due to (3.9), which contradicts (3.2). This completes the proof of Theorem 3.1.
With a similar proof to that of Theorems 2.2 and 3.1, we can obtain the following criteria for (1.1) by assuming that (2.2) is satisfied.
Theorem 3.2. Assume that conditions (H1)–(H5), (1.3), (1.5), (1.6), (2.2), (2.4) and (3.1) hold. Furthermore, assume that there exists ρ(t)∈C1([t0,∞),(0,∞)) such that (2.25) is satisfied for sufficiently large t∗>t2>t1≥t0. If
lim supt→∞∫tt∗[˜δα11(s)˜q2(s)˜γ(τ−1(σ2(s)))˜δα1α22(τ−1(σ2(s)),t1)−(α1α1+1)α1+11˜δ1(s)r1α11(τ−1(σ2(s)))]ds=∞, | (3.17) |
where ˜γ(t) is defined as in Theorem 3.1, then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Proof. Suppose that (1.1) has a non-oscillatory solution x(t). Without loss of generality, we assume that there exists t1≥t0 such that x(t)>0, x(τ(t))>0 and x(σ(t,ξ))>0 for ξ∈[a,b] and t≥t1. As in the proof of Theorem 3.1, we have (3.3) and (3.7), and there exist three possible cases (Ⅰ), (Ⅱ) and (Ⅲ) for z(t).
Assume first that Cases (Ⅰ) and (Ⅱ) hold. We can obtain the conclusion of Theorem 3.2 by using the proof of Theorem 2.2.
Assume that Case (Ⅲ) holds. Define the function ˜ν(t) by
˜ν(t)=r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1, t≥t1. | (3.18) |
Then ˜ν(t)<0 for t≥t1. Since σ2(t)≥τ(t) and (r2(t)(z′(t))α2)′<0, we have
−˜δ1(t)r1α11(t)(r2(t)(z′(t))α2)′r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2≤−˜δ1(t)r1α11(t)(r2(t)(z′(t))α2)′r2(t)(z′(t))α2. | (3.19) |
From (3.3), (3.18) and (3.19), we get
−˜δα11(t)˜ν(t)≤1. |
Since r1α11(t)(r2(t)(z′(t))α2)′ is non-increasing for t≥t1, we obtain
(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)′≤r1α11(t)(r2(t)(z′(t))α2)′r1α11(τ−1(σ2(t))). | (3.20) |
Differentiating (3.18) and using (3.7), (3.18) and (3.20), we deduce that
˜ν′(t)=[r1(t)((r2(t)(z′(t))α2)′)α1]′(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1−α1r1(t)((r2(t)(z′(t))α2)′)α1(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)′(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1+1≤−˜q2(t)zα3(τ−1(σ2(t)))(r2(τ−1(σ2(t)))((z(τ−1(σ2(t))))′)α2)α1−α1r1α11(τ−1(σ2(t)))˜ν1α1+1(t). | (3.21) |
Furthermore, substituting (3.12) and the definition of ˜γ(t) into (3.21), we conclude that
˜ν′(t)≤−˜q2(t)˜γ(τ−1(σ2(t)))˜δα1α22(τ−1(σ2(t)),t1)−α1r1α11(τ−1(σ2(t)))˜ν1α1+1(t). |
The rest of the proof is similar to that of Theorem 3.1 and we can get a contradiction to (3.17). So we omit it here. This completes the proof of Theorem 3.2.
In this section, we will establish some oscillation criteria for (1.1) under the assumption that (1.4) holds. Similarly as in the previous sections, we start with the case when (2.1) is satisfied.
Theorem 4.1. Assume that conditions (H1)–(H5), (1.4), (1.5), (1.6), (2.1), (2.4), (3.1) and (3.2) hold. Furthermore, assume that there exists ρ(t)∈C1([t0,∞),(0,∞)) such that for sufficiently large t∗>t2>t1≥t0, one has (2.3). If
∫∞t∗[1r2(u)∫ut∗(1r1(v)∫vt∗q1(s)ds)1α1dv]1α2du=∞, | (4.1) |
then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Proof. Suppose that (1.1) has a non-oscillatory solution x(t). Without loss of generality, we assume that there exists t1≥t0 such that x(t)>0, x(τ(t))>0 and x(σ(t,ξ))>0 for ξ∈[a,b] and t≥t1. Based on the condition (1.4), there exist three possible cases (Ⅰ), (Ⅱ), (Ⅲ) (as those in the proof of Theorem 2.1) and (Ⅳ) z(t)>0, z′(t)<0, (r2(t)(z′(t))α2)′<0 and [r1(t)((r2(t)(z′(t))α2)′)α1]′≤0, for t≥t1.
Assume first that Cases (Ⅰ), (Ⅱ) and (Ⅲ) hold. We can obtain the conclusion of Theorem 4.1 by using the proof of Theorem 3.1.
Assume that Case (Ⅳ) holds. Then there exists a constant l≥0 such that
limt→∞z(t)=l. |
We claim that l=0. Otherwise, assume that l>0. We see that there exists t2>t1 such that τ−1(σ1(t))≥t1 and z(τ−1(σ1(t)))≥l, t≥t2. From (2.24), we obtain
[r1(t)((r2(t)(z′(t))α2)′)α1]′+lα3q1(t)≤0. | (4.2) |
Integrating (4.2) from t2 to t, we have
r1(t)((r2(t)(z′(t))α2)′)α1+lα3∫tt2q1(s)ds≤0, |
which can be rewritten as
(r2(t)(z′(t))α2)′+(lα3r1(t)∫tt2q1(s)ds)1α1≤0. |
Integrating again from t2 to t, we get
r2(t)(z′(t))α2+lα3α1∫tt2(1r1(v)∫vt2q1(s)ds)1α1dv≤0, |
which yields that
z′(t)+[lα3α1r2(t)∫tt2(1r1(v)∫vt2q1(s)ds)1α1dv]1α2≤0. |
Integrating the last inequality from t2 to t, we obtain
lα3α1α2∫tt∗[1r2(u)∫ut2(1r1(v)∫vt2q1(s)ds)1α1dv]1α2du≤z(t2), |
which contradicts (4.1). This completes the proof of Theorem 4.1.
With a similar proof to that of Theorems 3.2 and 4.1, we can obtain the following criteria for (1.1) assuming that (2.2) is satisfied.
Theorem 4.2. Assume that conditions (H1)–(H5), (1.4), (1.5), (1.6), (2.2), (2.4), (3.1), (3.17) and (4.1) hold. Furthermore, assume that there exists a function ρ(t)∈C1([t0,∞),(0,∞)) such that for sufficiently large t∗>t2>t1≥t0, one has (2.25). Then every solution of (1.1) is either oscillatory or tends to zero as t→∞.
Remark 4.1. The results in [13,16,19,22] are obtained only in the case (1.2) and they are inapplicable to (1.3) and (1.4). Hence, the main results of this paper complement and improve those in the literature.
In this section, we will present some examples to illustrate the main results.
Example 4.1 For t>k1≥1, consider the third-order neutral delay differential equation with distributed deviating arguments
[t((t12(x(t)+6t+5k1t+k1x(t3))′)′)13]′+∫k1+1k1155(t+ξ)x5(t3−ξ)dξ=0, | (5.1) |
where α1=1/3, α2=1, α3=5, a=k1, b=k1+1, f(x)=x5, r1(t)=t, r2(t)=t12,
τ(t)=t3, σ(t,ξ)=t3−ξ, p(t)=6t+5k1t+k1, q(t,ξ)=155(t+ξ). |
Choose t0=t1=k1. Then we get α1α2<α3, 5≤p(t)<6,
σ2(t)=σ(t,k1+1)=t3−(k1+1), δ1(t,t1)=∫tk1s−3ds=12k21−12t2,δ2(t,t1)=δ1(t,k1)t12=12k21t12−12t52,δ3(t,t1)=∫tk1(12k21s12−12s52)ds=1k21(t12−k121)+13(t−32−k−321),˜δ1(t)=∫∞ts−3ds=12t2, ˜δ2(t,t1)=∫tk1s−12ds=2(t12−k121). |
Furthermore, we deduce that
p1(t)>16(1−15)=215>0,p2(t)=16(1−15⋅1k21((9t)12−k121)+13((9t)−32−k−321)1k21((3t)12−k121)+13((3t)−32−k−321))>110>0,˜p2(t)=16(1−15⋅((9t)12−k121)((3t)12−k121))>115>0,q1(t)>∫k1+1k1(215)5⋅155(t+ξ)dξ=32(t+k1+12),q2(t)>∫k1+1k1(110)5⋅155(t+ξ)dξ=(32)5(t+k1+12),˜q2(t)>∫k1+1k1(115)5⋅155(t+ξ)dξ=t+k1+12. |
It is easy to verify that
∫∞t0[1r2(u)∫∞u(1r1(v)∫∞vq1(s)ds)1α1dv]1α2du>∫∞k1u−12∫∞u(∫∞v32(s+k1+12)ds)3dvdu=∞, |
and
∫tt∗[˜δα11(s)˜q2(s)˜γ(s)˜δα1α22(τ−1(σ2(s)),t1)−(α1α1+1)α1+11˜δ1(s)r1α11(s)]ds>∫t4k1+3[(12s2)13(s+k1+12)((s−3(k1+1))12−k121)13−4−43s]ds→∞, |
as t→∞, where we set t∗=4k1+3. Therefore, conditions (H1)–(H5), (1.3), (1.5), (1.6), (2.1), (2.4), (3.1) and (3.2) hold. We choose ρ(t)=1. Applying Theorem 3.1, it remains to check (2.3), and we see that
∫tt∗[(δ3(τ−1(σ2(s)),t1)δ2(τ−1(σ2(s)),t1))α1α2ρ(s)q2(s)γ(τ−1(σ2(s)))rα12(τ−1(σ2(s)))−(ρ′+(s))α1+1r1(τ−1(σ2(s)))(α1+1)α1+1ρα1(s)]ds>∫t4k1+3[(8948k21)13(32)5(s+k1+12)(s−3(k1+1))16]ds→∞, |
as t→∞. Hence, every solution of (5.1) is either oscillatory or converges to zero by Theorem 3.1.
Example 4.2 Consider the third-order neutral delay differential equation with distributed deviating arguments
[t2(t2(x(t)+2x(t−1))′)′]′+∫21123λtξx3(t−1+1ξ)dξ=0, t≥1, | (5.2) |
where λ is a positive constant. Choose t0=t1=1. Then we get
σ2(t)=σ(t,2)=t−12,δ1(t,t1)=∫t1s−2ds=1−1t, δ2(t,t1)=δ1(t,k1)t2=1t2−1t3,δ3(t,t1)=∫t1(1s2−1s3)ds=12t2−1t+12,˜δ1(t)=∫∞ts−2ds=1t, ˜δ2(t,t1)=∫t1s−2ds=1−1t. |
Furthermore, we deduce that
p1(t)=12(1−12)=14>0, p2(t)=12(1−12⋅12(t+2)2−1t+2+1212(t+1)2−1t+1+12)>112>0,q1(t)=∫21(14)3123λtξdξ=342λt, q2(t)>∫21(112)3123λtξdξ=32λt,˜p2(t)=12(1−12⋅1−1t+21−1t+1)>14>0, ˜q2(t)>∫21(14)3123λtξdξ=342λt. |
It is easy to verify that
∫∞t0[1r2(u)∫∞u(1r1(v)∫∞vq1(s)ds)1α1dv]1α2du=∫∞2u−2∫∞uv−2∫∞v342λsdsdvdu=∞, |
∫∞t∗[1r2(u)∫ut∗(1r1(v)∫vt∗q1(s)ds)1α1dv]1α2du=∫∞2u−2∫u2v−2∫v2342λsdsdvdu=∞, |
and
∫tt∗[˜δα11(s)˜q2(s)˜γ(τ−1(σ2(s)))˜δα1α22(τ−1(σ2(s)),t1)−(α1α1+1)α1+11˜δ1(s)r1α11(τ−1(σ2(s)))]ds>∫t2[1s342λs(1−1s+12)−14s(s+12)2]ds→∞, |
as t→∞, if λ≥1, where we set t∗=2. Therefore, conditions (H1)–(H5), (1.4), (1.5), (1.6), (2.2), (2.4), (3.1), (3.17) and (4.1) hold. We choose ρ(t)=t2. Applying Theorem 4.2, it remans to check (2.25), and we get
∫tt∗[(δ3(τ(s),t1)δ2(τ(s),t1))α1α2ρ(s)q2(s)γ(τ(s))rα12(τ(s))−(ρ′+(s))α1+1r1(τ(s))(α1+1)α1+1ρα1(s)]ds>∫t2[12(s−1)2−1s−1+121(s−1)2−1(s−1)3⋅32λs3(s−1)2−(s−1)2]ds→∞, |
as t→∞. Hence, every solution of (5.2) is either oscillatory or converges to zero by Theorem 4.2.
This research is supported by the National Natural Science Foundation of China (Grant No. 61803176, 61703180), and A Project of Shandong Province Higher Educational Science and Technology Program (Grant No. J18KA230).
The authors declare that they have no conflict of interest.
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1. | Sun Yibing, Zhao Yige, 2021, Oscillation and Asymptotic Behavior of Third-Order Neutral Differential Equations with Damping, Unbounded Neutral Coefficients and Distributed Deviating Arguments, 978-9-8815-6380-4, 87, 10.23919/CCC52363.2021.9550260 | |
2. | John Graef, Irena Jadlovská, Ercan Tunç, Oscillation of odd-order differential equations with a nonpositive sublinear neutral term and distributed deviating arguments, 2022, 16, 1452-8630, 350, 10.2298/AADM200918012G | |
3. | Yibing Sun, Yige Zhao, Qiangqiang Xie, Oscillation and Asymptotic Behavior of the Third-Order Neutral Differential Equation with Damping and Distributed Deviating Arguments, 2023, 22, 1575-5460, 10.1007/s12346-022-00733-4 |