Research article

Discontinuous solutions for the short-pulse master mode-locking equation

  • Received: 09 January 2019 Accepted: 18 April 2019 Published: 08 May 2019
  • MSC : 35G15, 35L65, 35L05, 35A05

  • The short-pulse master mode-locking equation is a model for ultrafast pulse propagation in a mode-locked laser cavity in the few-femtosecond pulse regime, that is a nonlinear evolution equation. In this paper, we prove the wellposedness of the Cauchy problem associated with this equation within a class of discontinuous solutions.

    Citation: Giuseppe Maria Coclite, Lorenzo di Ruvo. Discontinuous solutions for the short-pulse master mode-locking equation[J]. AIMS Mathematics, 2019, 4(3): 437-462. doi: 10.3934/math.2019.3.437

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  • The short-pulse master mode-locking equation is a model for ultrafast pulse propagation in a mode-locked laser cavity in the few-femtosecond pulse regime, that is a nonlinear evolution equation. In this paper, we prove the wellposedness of the Cauchy problem associated with this equation within a class of discontinuous solutions.


    In recent years, the ultrafast science has experimentally crossed the threshold from the routine and direct laser production of few-cycle optical pulses in the 58 fs regime [29,36,37], to subfemtosecond pulses in the range of hundreds of attoseconds [35,54], leading to the hitherto unexplored field of attosecond physics [24,39,58].

    Such short pulse durations and broad spectral content have opened up vast new possibilities for exploring the fundamental nature of atomic and molecular physics at the fastest time scales, including molecular vibrations, chemical reactions, and light-matter interactions. Indeed, even single-electron transition events can now be captured [35] and an absolute measure of time potentially established [23,25].

    Yet the achievement of attosecond pulses in experiments also highlights the difficulties in measurement and interpretation, especially as the optical field information is interwoven with the physics of the interaction. Thus, theoretical and experimental methods are needed to help guide the understanding of attosecond science.

    A first method is based on the master mode-locking (MML) equation. It was developed by Haus [33,34] and has dominated mode-locking theory for many years.

    The Haus theory is fundamentally based upon a center-frequency expansion of the electric field and a derivation of an envelope approximation of the nonlinear Schrödinger equation (NLS) type. Inherent in the model is the assumption that the envelope is slow in comparison to the underlying fast carrier.

    In the case of the pulses which contain only a few cycles of the carrier, this approximation fails to hold, even if higher-order terms are incorporated into the NLS-based description. Regardless, the NLS-based approach has been shown to work quantitatively beyond its expected breakdown, into the tens of femtoseconds regime, and has been used extensively for modeling supercontinuum generation [28].

    However, when pushed to the extreme of a few femtosecond pulses, the NLS description becomes suspect, and a theory not founded upon a center-frequency expansion is required.

    As an alternative to the Haus model, Farnum and Kutz [30,31,32] develop a model to describe the pulses like those described in [29,35,36,37,54] without relying on center-frequency expansion.

    The Farnum and Kutz model is based on a short-pulse master mode-locking (SPMML) theory, which derives from the Maxwell equations [1,2,4,5,38,50,51,55,59]. In such theories, it is assumed that the propagation occurs for a broadband pulse so that the center-frequency expansion is circumvented.

    From a mathematical point of view, the Farnum and Kutz model is formulated in terms of the following equation:

    x(tu+axu3+bu+cu3)=γu,a,b,c,γR, (1.1)

    also known as SPMML equation, where u(t,x) is the electric field amplitude, t is the time, x is distance propagated in the laser cavity [55], b is the linear attenuation, c is a cubic gain term giving rise to intensity discrimination (saturable absorption) [33,34] and γ is a real parameter [38,55].

    If b=c=0, (1.1) reads

    x(tu+axu3)=γu. (1.2)

    It was introduced by Kozlov and Sazonov [38] as a model equation describing the nonlinear propagation of optical pulses of a few oscillations duration in dielectric media, and by Schäfer and and Wayne [55] as a model equation describing the propagation of ultra-short light pulses in silica optical fibers. Hence, with respect to Kozlov, Sazonov, Schäfer and Wayne, Farnum and Kutz take into consideration the linear attenuation and the saturable absorption. Moreover, in [42,43,44] the authors show that (1.2) is a non-slowly-varying envelope approximation model that describes the physics of few-cycle-pulse optical solitons.

    If we take c=0 in (1.1), we have the short pulse equation with linear attenuation, which is deduced in [63].

    It also is interesting to remind that Eq (1.2) was proposed earlier in [48] in the context of plasma physic and that the similar equations describe the dynamics of radiating gases [41,57]. In [62], the authors deduce (1.2) to describe the short pulse propagation in nonlinear metamaterials characterized by a weak Kerr-type nonlinearity in their dielectric response. Moreover, [3,13,52,53] show that (1.2) is a particular Rabelo equation which describes pseudospherical surfaces.

    In literature, we have the following generalization of (1.2):

    x(tu+axu3β3xxxu)=γu. (1.3)

    It was derived by Costanzino, Manukian and Jones [22] in the context of the nonlinear Maxwell equations with high-frequency dispersion. Kozlov and Sazonov [38] show that (1.3) is an more general equation than (1.2) to describe the nonlinear propagation of optical pulses of a few oscillations duration in dielectric media.

    Recently, wellposedness results for the Cauchy problem of (1.2) are proven in the context of energy spaces (see [26,49,60]). A similar result is proven in [11,16] in the context of the entropy solution, while, in [7,12,18], the wellposedness of the homogeneous initial boundary value problem is studied. Finally, the convergence of a finite difference scheme is studied in [21].

    Moreover, mathematical properties of (1.3) are studied in many different contexts, including the local and global wellposedness in energy spaces [22,49] and stability of solitary waves [22,46]. Observe that, letting β0 in (1.3), we obtain (1.2). Hence, following [9,45,56], in [15,16], the convergence of the solution of (1.3) to the unique entropy solution of (1.2) is proven.

    In this papaer, we assume that c>0 and we write c=κ2. Therefore, (1.1) reads

    x(tu+axu3+bu+κ2u3)=γu. (1.4)

    We are interested in the Cauchy problem for this equation, thus we augment (1.4) with the initial condition

    u(0,x)=u0(x),xR, (1.5)

    on which assume that

    u0(x)L(R)L1(R),Ru0(x)dx=0. (1.6)

    Following [10,11,16], on the function

    P0(x)=xu0(y)dy, (1.7)

    we assume that

    P02L2(R)=R(xu0(y)dy)2dx<. (1.8)

    Integrating (1.4) in (0,x), we gain the integro-differential formulation of (1.4) and (1.6).

    {tu+axu3+bu+κ2u3=γx0udy,t0,xR,u(0,x)=u0(x),xR, (1.9)

    that is equivalent to

    {tu+axu3+bu+κ2u3=γP,t0,xR,xP=u,t0,xR,P(t,0)=0,t0,u(0,x)=u0(x),xR. (1.10)

    One of the main issues in the analysis of (1.10) is that the equation is not preserving the L1 norm, as a consequence the nonlocal source term P and the solution u are a priori only locally bounded. Indeed, from (1.9) and (1.10) is clear that we cannot have any L bound without an L1 bound. Since we are interested in the bounded solutions of (1.4), some assumptions on the decay at infinity of the initial condition u0 are needed (see (1.8)).

    The unique useful conserved quantities are

    tu(t,x)dx=0,tu2(t,x)dx. (1.11)

    In the sense that if u(t,) has zero mean at time t=0, then it will have zero mean at any time t>0. In addition, the L2 norm of u(t,) is constant with respect to t. Therefore, we require that initial condition u0 belongs to L2L and has zero mean.

    Due to the regularizing effect of the P equation in (1.10), we have that

    uL((0,T)×R)PL((0,T);W1,(R)),T>0. (1.12)

    Following [10,11,16], we give the following definition of solution.

    Definition 1. We say that uL((0,T)×R) is an entropy solution of the initial value problem (1.10) and (1.5) if

    i) u is a distributional solution of (1.10);

    ii) for every convex function ηC2(R) the entropy inequality

    tη(u)+xq(u)+bη(u)u+κ2η(u)u3γη(u)P0,q(u)=3auξ2η(ξ)dξ, (1.13)

    holds in the sense of distributions in (0,)×R.

    The main result of this paper is the following theorem.

    Theorem 1.1. Assume (1.6) and (1.8). The initial value problem (1.10) and (1.5) possesses an unique entropy solution u in the sense of Definition1. Moreover, if u and v are two entropy solutions (1.10) and (1.5) in the sense of Definition 1, the following inequality holds

    u(t,)v(t,)L1(R,R)eC(T)tu(0,)v(0,)L1(RC(T)t,R+C(T)t), (1.14)

    for almost every 0<t<T, R>0, and some suitable constant C(T)>0.

    The paper is organized as follows. In Section 2, we prove several a priori estimates on a vanishing viscosity approximation of (1.10). Those play a key role in the proof of our main result, that is given in Section 3.

    Our existence argument is based on passing to the limit in a vanishing viscosity approximation of (1.10).

    Fix ε>0 a small number and let uε=uε(t,x) be the unique classical solution of the following mixed problem [14,20]:

    {tuε+axu3ε+buε+κ2u3ε=γPε+ε2xxuε,t>0,xR,xPε=uε,t>0,xR,Pε(t,0)=0,t>0,xR,uε(0,x)=uε,0(x),xR, (2.1)

    where uε,0 is a C approximation of u0 such that

    uε,0L(R)u0L(R),uε,0L2(R)u0L2(R),uε,0L4(R)u0L4(R),Ruε,0(x)=0,Pε,0L2(R)P0L2(R),RPε,0(x)u3ε,0(x)dxC0, (2.2)

    where C0 is a constant independent on ε.

    Let us prove some a priori estimates on uε and Pε, denoting with C0 the constants which depend only on the initial data, and C(T) the constants which depend also on T.

    Arguing as in [8,Lemma 2.1], or [10,Lemma 2.1], we have the following result.

    Lemma 2.1. Let us suppose that

    Pε(t,)=0,t0,(or Pε(t,)=0). (2.3)

    Then, the following statements are equivalent

    Ruε(t,x)dx=0,t0, (2.4)
    ddtuε(t,)2L2(R)+κ2uε(t,)4L4(R)+2εxuε(t,)2L2(R)=2buε(t,)2L2(R),t>0. (2.5)

    Lemma 2.2. For each t[0,), (2.3) and (2.4) hold. In particular, fixed Tt0, we have that

    uε(t,)2L2(R)+κ2e|b|tt0e|b|suε(s,)4L4(R)ds+2εe|b|tt0e|b|sxuε(s,)2L2(R)dsC(T). (2.6)

    Proof. Arguing as in [8,Lemma 2.2], we have (2.3), and (2.4). Lemma 2.1 says that (2.5) also hold. Therefore, we get

    ddtuε(t,)2L2(R)+κ2uε(t,)4L4(R)+2εxuε(t,)2L2(R)2|b|uε(t,)2L2(R).

    Fixed T>0, the Gronwall Lemma and (2.2) give

    uε(t,)2L2(R)+κ2e2|b|tt0e2|b|suε(s,)4L4(R)ds+2εe2|b|tt0e2|b|sxuε(s,)2L2(R)dsu02L2(R)e|b|tC(T),

    that is (2.6).

    Lemma 2.3. Fix T>0. There exists a constant C(T)>0, independent on ε, such that

    uε(t,)4L4(R)+4κ2t0uε(s,)6L6(R)ds+12εt0uε(s,)xuε(s,)2L2(R)dsC(T)(1+PεL((0,T)×R)). (2.7)

    Proof. Let 0tT. Multiplying (2.1) by 4u3ε, an integration on R gives

    ddtuε(t,)4L4(R)=4Ru3εtuεdx=12aRu5εxuεdx4buε(t,)4L4(R)4κ2uε(t,)6L6(R)+4γRPεu3εdx+4εRu3ε2xxuεdx=4buε(t,)4L4(R)4κ2uε(t,)6L6(R)+4γRPεu3εdx12εuε(t,)xuε(t,)2L2(R).

    Hence,

    ddtuε(t,)4L4(R)+4κ2uε(t,)6L6(R)+12εuε(t,)xuε(t,)2L2(R)=4buε(t,)4L4(R)+4γRPεu3εdx4|b|uε(t,)4L4(R)+4|γ|R|Pε||uε|3dx. (2.8)

    Due to (2.6) and the Young inequality,

    4|γ|R|Pε||uε|3dx4|γ|PεL(0,T)×R)R|uε|3dx2|γ|PεL((0,T)×R)uε(t,)2L2(R)+2|γ|PεL(0,T)×R)uε(t,)4L4(R)C(T)PεL((0,T)×R)++2|γ|PεL((0,T)×R)uε(t,)4L4(R).

    Consequently, by (2.8),

    ddtuε(t,)4L4(R)+4κ2uε(t,)6L6(R)+12εuε(t,)xuε(t,)2L2(R)4|b|uε(t,)4L4(R)+C(T)PεL((0,T)×R)+2|γ|PεL((0,T)×R)uε(t,)4L4(R).

    It follows from (2.2), (2.5) and an integration on (0,t) that

    uε(t,)4L4(R)+4κ2t0uε(s,)6L6(R)ds+12εt0uε(s,)xuε(s,)2L2(R)dsC0+4|b|t0uε(s,)4L4(R)ds+C(T)PεL((0,T)×R)t+2|γ|PεL((0,T)×R)t0uε(s,)4L4(R)dsC0+4|b|e2|b|tt0e2|b|suε(s,)4L4(R)ds+C(T)PεL((0,T)×R)+2|γ|PεL((0,T)×R)e2|b|tt0e2|b|suε(s,)4L4(R)dsC(T)(1+PεL((0,T)×R)),

    which give (2.7).

    Lemma 2.4. Fix T>0. For each t[0,T], we have that

    0Pε(t,x)dxaγu3ε(t,0)εγxuε(t,0)+C(T)(1+PεL((0,T)×R)), (2.9)
    0Pε(t,x)dxaγu3ε(t,0)+εγxuε(t,0)+C(T)(1+PεL((0,T)×R)). (2.10)

    Moreover,

    RPε(t,x)dx=κ2γRu3ε(t,x)dx,t0. (2.11)

    Proof. We begin by observing that, integrating the second equation of (2.1) on (0,x), we have

    Pε(t,x)=x0uε(t,y)dy. (2.12)

    Consequently, by (2.3),

    0uε(t,x)dx=0. (2.13)

    Differentiating (2.13) with respect to t, we obtain

    ddt0uε(t,x)dx=0tuε(t,x)dx=0. (2.14)

    Integrating the first equation on (0,x), we have that

    γx0Pε(t,y)dy=x0tuε(t,y)dy+au3ε(t,x)auε(t,0)εxuε(t,x)+εxuε(t,0)bPε(t,x)κ2x0u3ε(t,x)dy. (2.15)

    It follows from (2.3) and the regularity of uε that

    limx(au3ε(t,x)εxuε(t,x)bPε(t,x))=0. (2.16)

    Consequently, by (2.3), (2.14), (2.15) and (2.16),

    γ0Pε(t,x)dx=auε(t,0)+εxuε(t,0)κ20u3ε(t,x)dx,

    that is

    0Pε(t,x)dx=aγuε(t,0)εγxuε(t,0)κ2γ0u3ε(t,x)dx (2.17)

    Due to (2.6), (2.7) and the Hölder inequality,

    κ2γ0u3εdxκ2|γ|R|uε|3dxκ2|γ|uε(t,)L2(R)uε(t,)2L4(R)C(T)uε(t,)2L4(R)C(T)(1+PεL((0,T)×R)). (2.18)

    (2.9) follows from (2.17) and (2.18).

    We prove (2.10). By (2.3) and (2.12), we have

    0uε(t,x)dx=0. (2.19)

    Consequently, differentiating (2.19) with respect to t, we obtain

    ddt0uε(t,x)dx=0tuε(t,x)dx=0. (2.20)

    (2.3) and the the regularity of uε give

    limx(au3ε(t,x)εxuε(t,x)bPε(t,x))=0. (2.21)

    Therefore, by (2.15), (2.20) and (2.21),

    0Pε(t,x)dx=aγuε(t,0)+εγxuε(t,0)κ2γ0u3ε(t,x)dx (2.22)

    Due to (2.6), (2.7) and the Hölder inequality,

    κ2γ0u3εdxκ2|γ|0|uε|3dxκ2|γ|uε(t,)L2(R)uε(t,)2L4(R)C(T)uε(t,)2L4(R)C(T)(1+PεL((0,T)×R)). (2.23)

    (2.22) and (2.23) give (2.10).

    Finally, we prove (2.11). Thanks to (2.9) and (2.10), we can consider (2.17) and (2.22) which give (2.11).

    Following [15,Lemma 2.4], we prove the following result.

    Lemma 2.5. Fix T>0. There exists a constant C(T)>0, independent on ε, such that

    PεL((0,T)×R)C(T). (2.24)

    In particular, for every 0tT, we have

    Pε(t,)2L2(R)C(T),t0Pε(s,)uε(s,)2L2(R)dsC(T),uε(t,)L4(R)C(T),t0uε(s,)6L6(R)C(T),εt0uε(s,)xuε(s,)2L2(R)dsC(T). (2.25)

    Proof. Let 0tT. We begin by observing that, thanks to (2.9), we can consider the following function

    Fε(t,x)=xPε(t,y)dy. (2.26)

    Integrating the second equation of (2.1), by (2.3), we get

    Pε(t,x)=xuε(t,y)dy. (2.27)

    Differentiating (2.27) with respect to t, we obtain that

    tPε(t,x)=ddtxuε(t,y)dy=xtuε(t,y)dy. (2.28)

    Integrating the first equation of (2.1) on (,x), from (2.26), (2.27) and (2.28), we have

    tPε(t,x)=au3ε(t,x)bPε(t,x)κ2xu3ε(t,y)dy+γFε(t,x)+εxuε(t,x). (2.29)

    Multiplying (2.29) by 2Pε, an integration on R give

    ddtPε(t,)2L2(R)=2RPεtPεdx=2aRPεu3εdx2bPε(t,)2L2(R)+2εRPεxuεdx2κ2RPε(xu3ε(t,y)dy)dx+2γRPεFεdx (2.30)

    Observe that, by (2.11) and (2.26),

    2γRPεFεdx=2γRFεxFεdx=γF2ε(t,)=γ(RPε(t,x)dx)2=κ4γ(Ru3εdx)2. (2.31)

    Again by (2.11) and (2.26),

    2κ2RPε(xu3ε(t,y)dy)dx=2κ2Fε(t,)Ru3εdx+2κ2RFεu3εdx=2κ2(RPεdx)(Ru3εdx)+2κ2RFεu3εdx=2κ4γ(Ru3εdx)2+2κ2RFεu3εdx. (2.32)

    Moreover, by (2.1) and (2.3),

    2εRPεxuεdx=2εRxPεuεdx=2εuε(t,)2L2(R). (2.33)

    Therefore, it follows from (2.30), (2.31), (2.32) and (2.33) that

    ddtPε(t,)2L2(R)+2εuε(t,)2L2(R)=2aRPεu3εdx2bPε(t,)2L2(R)+3κ4γ(Ru3εdx)2+2κ2RFεu3εdx. (2.34)

    By (2.29), we have

    Fε(t,x)=1γtPε(t,x)+aγu3ε(t,x)+bγPε(t,x)+κ2γxu3ε(t,y)dyεγxuε(t,x). (2.35)

    Multiplying (2.35) by 2κ2u3ε, an integration on R gives

    2κ2RFεu3εdx=2κ2γRtPεu3εdx+2aκ2γuε(t,)6L6(R)+2κ2bγRPεu3εdx+2κ4γRu3ε(xu3εdy)dx2κ2εγRu3εxuεdx.

    Since

    2κ4γRu3ε(xu3εdy)dx=κ4γ(Ru3εdx)2,2κ2εγRu3εxuεdx=0,

    we have that

    2κ2RFεu3εdx=2κ2γRtPεu3εdx+2aκ2γuε(t,)6L6(R)+2κ2bγRPεu3εdx+κ4γ(Ru3εdx)2. (2.36)

    Using (2.36) in (2.34), we get

    ddtPε(t,)2L2(R)+2εuε(t,)2L2(R)=2(κ2baγ)γRPεu3εdx2bPε(t,)2L2(R)+2aκ2γuε(t,)6L6(R)+4κ4γ(Ru3εdx)2+2κ2γRtPεu3εdx. (2.37)

    Observe that

    t(Pεu3ε)=tPεu3ε+Pεtu3ε=tPεu3ε+3Pεu2εtuε.

    Consequently,

    2κ2γRtPεu3εdx=2κ2γddtRPεu3εdx6κ2γRPεu2εtuεdxdx. (2.38)

    Using (2.38) in (2.37), we have

    dG(t)dt+2εuε(t,)2L2(R)=2(κ2baγ)γRPεu3εdx2bPε(t,)2L2(R)+2aκ2γuε(t,)6L6(R)+4κ4γ(Ru3εdx)26κ2γRPεu2εtuεdx, (2.39)

    where

    G(t):=Pε(t,)2L2(R)2κ2γRPεu3εdx. (2.40)

    Multiplying the first equation of (2.1) by 6κ2γPεu2ε, an integration on R give

    6κ2γRPεu2εtuεdx=18aκ2γRPεu4εxuεdx+6bκ2γRPεu3εdx+κ4γRPεu5εdx6κ2Pε(t,)uε(t,)2L2(R)6κ2εγRPεu2ε2xxuεdx. (2.41)

    Observe that by (2.1) and (2.3),

    18aκ2γRPεu4εxuεdx=18aκ25γRu5εxPεdx=18aκ25γuε(t,)6L6(R),6κ2εγRPεu2ε2xxuεdx=6κ2εγRxPεu2εxuεdx+12κ2εγRPεuε(xuε)2dx=6κ2εγRu3εxuεdx+12κ2εγRPεuε(xuε)2dx=12κ2εγRPεuε(xuε)2dx.

    Hence, by (2.41),

    6κ2γRPεu2εtuεdx=18aκ25γuε(t,)6L6(R)+6bκ2γRPεu3εdx+κ4γRPεu5εdx6κ2Pε(t,)uε(t,)2L2(R)+12κ2εγRPεuε(xuε)2dx. (2.42)

    Substituting (2.42) in (2.39), we get

    dG(t)dt+2εuε(t,)2L2(R)+6κ2Pε(t,)uε(t,)2L2(R)=8κ2b2aγγRPεu3εdx2bPε(t,)2L2(R)8aκ2γuε(t,)6L6(R)+4κ4γ(Ru3εdx)2+κ4γRPεu5εdx+12κ2εγRPεuε(xuε)2dx. (2.43)

    Due to (2.6), (2.7) and the Young inequality and the Hölder inequality,

    |8κ2b2aγ||γ|R|Pε||uε|3dx=|8κ2b2aγ||γ|R|Pεuε|u2εdx|8κ2b2aγ|2|γ|RP2εu2εdx+|8κ2b2aγ|2|γ|uε(t,)4L4(R)|8κ2b2aγ|2|γ|Pε2L((0,T)×R)uε(t,)2L2(R)+C(T)(1+PεL((0,T)×R))C(T)Pε2L((0,T)×R)+C(T),κ4|γ|R|Pε|uε|5dx=κ4|γ|R|DPεu2ε|u3εDdxDκ42|γ|RP2εu4εdx+κ42D|γ|uε(t,)6L6(R)=R|Dκ4P2εu2ε2E|γ|||Eu3ε|dx+κ42D|γ|uε(t,)6L6(R)D2κ84Eγ2RP4εu2εdx+(E2+κ42D|γ|)uε(t,)6L6(R)D2κ84Eγ2Pε4L((0,T)×R)uε(t,)2L2(R)+(E2+κ42D|γ|)uε(t,)6L6(R)D2C(T)EPε4L((0,T)×R)+(E2+κ42D|γ|)uε(t,)6L6(R),12κ2ε|γ|RPεuε(xuε)2dx=12κ2ε|γ|R|Pεxuε||uεxuε|dx6κ2ε|γ|RP2ε(xuε)2dx+6κ2ε|γ|uε(t,)xuε(t,)2L2(R)6κ2ε|γ|Pε2L((0,T)×R)xuε(t,)2L2(R)+6κ2ε|γ|uε(t,)xuε(t,)2L2(R),4κ4|γ|(R|uε|3dx)24κ4|γ|(uε(t,)L2(R)uε(t,)4L2(R))2C(T)uε(t,)4L4(R)C(T)(1+PεL((0,T)×R))C(T)+C(T)Pε(t,)2L((0,T)×R),

    where D,E are two positive constants which will be specified later. Consequently, by (2.43),

    dG(t)dt+2εuε(t,)2L2(R)+6κ2Pε(t,)uε(t,)2L2(R)2|b|Pε(t,)2L2(R)+(8|a|κ2|γ|+E2+κ42D|γ|)uε(t,)6L6(R)+6κ2ε|γ|Pε2L((0,T)×R)xuε(t,)2L2(R)+6κ2ε|γ|uε(t,)xuε(t,)2L2(R)+D2C(T)EPε4L((0,T)×R)+C(T)Pε(t,)2L((0,T)×R)+C(T). (2.44)

    Observe that by (2.40),

    2|b|Pε(t,)2L2(R)=2|b|G(t)+4|b|κ2γRPεu3εdx. (2.45)

    Thanks to (2.6), (2.7) and the Young inequality,

    4|b|κ2|γ|R|Pε||uε|3dx=4|b|κ2|γ|R|Pεuε|u2εdx2|b|κ2|γ|RP2εu2εdx+2|b|κ2|γ|uε(t,)4L4(R)2|b|κ2|γ|Pε2L((0,T)×R)uε(t,)2L2(R)+C(T)(1+PεL((0,T)×R))C(T)Pε2L((0,T)×R)+C(T). (2.46)

    It follows from (2.44), (2.45) and (2.46) that

    dG(t)dt+2εuε(t,)2L2(R)+6κ2Pε(t,)uε(t,)2L2(R)2|b|G(t)+(8|a|κ2|γ|+E2+κ42D|γ|)uε(t,)6L6(R)+6κ2ε|γ|Pε2L((0,T)×R)xuε(t,)2L2(R)+6κ2ε|γ|uε(t,)xuε(t,)2L2(R)+D2C(T)EPε4L((0,T)×R)+C(T)Pε(t,)2L((0,T)×R)+C(T).

    The Gronwall Lemma, (2.2), (2.6), (2.7), (2.40), (2.46) and the Young inequality give

    Pε(t,)2L2(R)+2εe2|b|tt0e2|b|suε(s,)2L2(R)ds+6κ2e2|b|tt0e2|b|sPε(s,)uε(s,)2L2(R)dsC0+2κ2γRPεu3εdx+(8|a|κ2|γ|+E2+κ42D|γ|)e2|b|tt0e2|b|suε(s,)6L6(R)ds+6κ2ε|γ|Pε2L((0,T)×R)e2|b|tt0e2|b|sxuε(s,)2L2(R)ds+6κ2ε|γ|e2|b|tt0e2|b|suε(s,)xuε(s,)2L2(R)ds+D2C(T)EPε4L((0,T)×R)e2|b|tt0e2|b|sds+C(T)Pε(t,)2L((0,T)×R)e2|b|tt0e2|b|sds+C(T)e2|b|tt0e2|b|sdsC(T)(8|a|κ2|γ|+E2+κ42D|γ|)t0uε(s,)6L6(R)ds+C(T)εt0uε(s,)xuε(s,)2L2(R)ds+D2C(T)EPε4L((0,T)×R)C(T)Pε(t,)2L((0,T)×R)+C(T)C(T)(E2+κ42D|γ|)(1+PεL((0,T)×R))+C(T)(1+PεL((0,T)×R))+D2C(T)EPε4L((0,T)×R)+C(T)Pε(t,)2L((0,T)×R)+C(T)C(T)(E2+κ42D|γ|+1)(1+Pε2L((0,T)×R))+D2C(T)EPε4L((0,T)×R)+C(T)Pε(t,)2L((0,T)×R)+C(T). (2.47)

    We prove (2.9). Thanks to (2.1), (2.3), (2.6) and the Hölder inequality,

    P2ε(t,x)=2xPεxPεdy2R|Pε||uε|dx2Pε(t,)L2(R)uε(t,)L2(R)C(T)Pε(t,)L2(R).

    Therefore, by (2.47),

    Pε4L((0,T)×R)C(T)Pε(t,)2L2(R)C(T)(E2+κ42D|γ|+1)(1+Pε2L((0,T)×R))+D2C(T)EPε4L((0,T)×R)+C(T)Pε(t,)2L((0,T)×R)+C(T).

    Hence,

    (1D2C(T)E)Pε4L((0,T)×R)C(T)(E2+κ42D|γ|+1)(1+Pε2L((0,T)×R))C(T)Pε(t,)2L((0,T)×R)C(T)0.

    Choosing

    E=D,D=12C(T), (2.48)

    we have

    12Pε4L((0,T)×R)C(T)Pε(t,)2L((0,T)×R)C(T)0,

    which gives (2.24).

    Finally (2.25) follows from (2.7), (2.24), (2.47) and (2.48).

    Following [10,Lemma 3.1], or [19,Lemma 3.1], we prove the following result.

    Lemma 2.6. Let T>0. There exists a constant C(T)>0, independent on ε, such that

    uεL((0,T)×R)C(T), (2.49)

    for every 0tT.

    Proof. Let 0tT. We begin by observing that, by (2.9), we have that

    |γPε(t,x)||γ|C(T),(t,x)(0,T)×R. (2.50)

    Therefore,

    |γ|C(T)γPε(t,x)|γ|C(T). (2.51)

    The proof of (2.49) splits into two parts. In the first part, we consider b0. Instead, in the second one, we consider b0.

    Case b0. We assume that

    b=α2. (2.52)

    Therefore, by the first equation of (2.1), (2.51) and (2.52), we have

    tuε+axu3εε2xxuε|γ|C(T)α2uεκ2u3ε. (2.53)

    A supersolution of (2.1) satisfies the following ordinary differential equation:

    dz1dt+α2z1+κ2z31|γ|C(T)=0,z1(0)=uε,0L(R). (2.54)

    We consider the map

    Z1(t)=At+A,t0. (2.55)

    where A is a positive constant, which will be specified later. Observe that

    dZ1dt+α2Z1+κ2Z31|γ|C(T)=A+α2A(t+1)+κ2A3(t+1)3|γ|C(T)

    Choosing

    A=|γ|C(T), (2.56)

    we have that

    dZ1dt+α2Z1+κ2Z31|γ|C(T)=α2|γ|C(T)(t+1)+κ2|γ|3C(T)(t+1)30, (2.57)

    for every t(0,T). Then, Z1(t) is a supersolution of (2.54). (2.56), the comparison principle for parabolic equations and the comparison principle for ordinary differential equations yield

    uε(t,x)z1(t)Z1(t)=|γ|C(T)(t+1),(t,x)(0,T)×R. (2.58)

    Observe that, by the first equation of (2.1), (2.51) and (2.52), we have

    tuε+axu3εε2xxuε|γ|C(T)α2uεκ2u3ε. (2.59)

    Therefore, a subsolution of (2.1) satisfies the following ordinary differential equation:

    dz2dt+α2z2+κ2z32+|γ|C(T)=0,z2(0)=uε,0L(R). (2.60)

    We consider the map

    Z2(t)=BtB,t0. (2.61)

    where B is a positive constant, which will be specified later. Observe that

    dZ2dt+α2Z2+κ2Z32+|γ|C(T)=Bα2B(t+1)κ2B3(t+1)3+|γ|C(T).

    Choosing

    B=|γ|C(T), (2.62)

    we have that

    dZ1dt+α2Z1+κ2Z31|γ|C(T)=α2|γ|C(T)(t+1)κ2|γ|3C(T)(t+1)30, (2.63)

    for every t(0,T). Then, Z2(t) is a subsolution of (2.61). (2.52), the comparison principle for parabolic equations and the comparison principle for ordinary differential equations yield

    |γ|C(T)(t+1)=Z2(t)z2(t)uε(t,x),(t,x)(0,T)×R. (2.64)

    It follows from (2.58) and (2.64) that

    |uε(t,x)||γ|C(T)(t+1)|γ|C(T)(T+1), (2.65)

    which give (2.49).

    Case b0. We assume that

    b=α2. (2.66)

    Thanks to (2.66), arguing as in previous case, we get

    tuε+axu3εε2xxuε|γ|C(T)+α2uεκ2u3ε. (2.67)

    A supersolution of (2.1) satisfies the following ordinary differential equation:

    dz3dtα2z3+κ2z33|γ|C(T)=0,z3(0)=uε,0L(R). (2.68)

    We consider the map

    Z3(t)=Dt+E,t0. (2.69)

    where D,E are two positive constants, which will be specified later. Observe that

    dZ3dtα2Z3+κ2Z33|γ|C(T)=Dα2(Dt+E)+κ2(Dt+E)3+|γ|C(T)=κ2D3t3+3κ2D2Et2+D(3κ2E2α2)t+D+κ2E3α2E|γ|C(T). (2.70)

    We search D,E such that,

    3κ2E2α20,D+κ2E3α2E|γ|C(T)0. (2.71)

    From the first inequality of (2.71), we obtain that

    E|α3κ|. (2.72)

    Choosing

    D=|γ|C(T), (2.73)

    it follows from the second inequality of (2.71) that

    κ2E3α2E0κ2E2α20,

    that is

    E|ακ|. (2.74)

    From (2.72) and (2.74), we get

    Emax{|α3κ|,|ακ|}=|ακ|. (2.75)

    Choosing

    E=|ακ|, (2.76)

    from (2.69) and (2.73), we have that

    Z3(t)=Dt+E=|γ|C(T)t+|ακ|. (2.77)

    Moreover, by (2.70), (2.73) and (2.76),

    dZ3dtα2Z3+κ2Z33|γ|C(T)0,

    for every 0tT. Then, Z3(t) is a supersolution of (2.68). (2.77), the comparison principle for parabolic equations and the comparison principle for ordinary differential equations yield

    uε(t,x)z3(t)Z3(t)=|γ|C(T)t+|ακ|,(t,x)(0,T)×R. (2.78)

    Arguing as in previous case, we have that

    tuε+axu3εε2xxuε|γ|C(T)+α2uεκ2u3ε. (2.79)

    Therefore, a subsolution of (2.1) satisfies the following ordinary differential equation:

    dz4dtα2z4+κ2z34+|γ|C(T)=0,z2(0)=uε,0L(R). (2.80)

    We consider the map

    Z4(t)=FtG,t0. (2.81)

    where F,G are two positive constants, which will be specified later. Observe that

    dZ4dtα2Z4+κ2Z34+|γ|C(T)=F+α2(Ft+G)κ2(Ft+G)3+|γ|C(T)=κ2F3t33κ2F2Gt2+F(α23κ2G2)tF+α2Gκ2G3+|γ|C(T) (2.82)

    We search F,G such that

    α23κ2G20,F+α2Gκ2G3+|γ|C(T)0. (2.83)

    Choosing

    F=|γ|C(T), (2.84)

    by (2.83), we have

    3κ2G2α20,κ2G3α2G0.

    Arguing as before, we gain

    Gmax{|α3κ|,|ακ|}=|ακ|. (2.85)

    Choosing

    G=|ακ|, (2.86)

    then, by (2.81) and (2.84),

    Z4(t)=FtG=|γ|C(T)t|ακ|. (2.87)

    Moreover, by (2.82), (2.84) and (2.86), we have

    dZ4dtα2Z4+κ2Z34+|γ|C(T)0,

    for every 0tT. Then, Z4(t) is a subsolution of (2.80). (2.87), the comparison principle for parabolic equations and the comparison principle for ordinary differential equations yield

    |γ|C(T)t|ακ|Z4(t)z4(t)uε(t,x),(t,x)(0,T)×R. (2.88)

    It follows from (2.78) and (2.88) that

    |γ|C(T)t|ακ|uε(t,x)|γ|C(T)t+|ακ|.

    Hence,

    |uε(t,x)||γ|C(T)t+|ακ||γ|C(T)T+|ακ|,

    which gives (2.49).

    This section is devoted to the proof of Theorem 1.1.

    Let us begin by proving the existence of a distributional solution to (1.10) satisfying (1.13).

    Lemma 3.1. Let T>0. There exists a function uL((0,T)×R) that is a distributional solution of (2.1) and satisfies (1.13) for every convex entropy ηC2(R).

    We construct a solution by passing to the limit in a sequence {uε}ε>0 of viscosity approximations (2.1). We use the compensated compactness method [61].

    Lemma 3.2. Let T>0. There exists a subsequence {uεk}kN of {uε}ε>0 and a limit function uL((0,T)×R) such that

    uεkua.e.and in Lploc((0,T)×R),1p<. (3.1)

    Moreover, we have that

    PεkP a.e.and in Lploc((0,T);W1,ploc(R)),1p<, (3.2)

    where

    P(t,x)=x0u(t,y)dy,t0,xR. (3.3)

    Proof. Let η:RR be any convex C2 entropy function, and q:RR be the corresponding entropy flux defined by q(u)=3au2η(u). By multiplying the first equation in (2.1) with η(uε) and using the chain rule, we get

    tη(uε)+xq(uε)=ε2xxη(uε)=:L1,εεη(uε)(xuε)2=:L2,ε+γη(uε)Pε=:L3,εbη(uε)uε=:L4,εκ2η(uε)u3ε=:L5,ε

    where L1,ε, L2,ε, L3,ε, L4,ε and L5,ε are distributions. Let us show that

    L1,ε0 in H1((0,T)×R),T>0.

    Since

    ε2xxη(uε)=x(εη(uε)xuε),

    by (2.6) and Lemma 2.6,

    εη(uε)xuε2L2((0,T)×R)ε2η2L(C(T),C(T))T0xuε(s,)2L2(R)dsεη2L(C(T),C(T))C(T)0.

    We claim that

    {L2,ε}ε>0 is uniformly bounded in L1((0,T)×R),T>0.

    Again by (2.6) and Lemma 2.6,

    εη(uε)(xuε)2L1((0,T)×R)ηL(C(T),C(T))εT0xuε(s,)2L2(R)dsηL(C(T),C(T))C(T).

    We have that

    {L3,ε}ε>0 is uniformly bounded in L1loc((0,T)×R),T>0.

    Let K be a compact subset of (0,T)×R. Using (2.24) and Lemma 2.6,

    |γ|η(uε)PεL1(K)=|γ|K|η(uε)||Pε|dtdx|γ|ηL(C(T),C(T))PεL((0,T)×R)|K|.

    We show

    {L4,ε}ε>0 is uniformly bounded in L1loc((0,T)×R),T>0.

    Let K be a compact subset of (0,T)×R. By Lemma 2.6,

    |b|η(uε)uεL1(K)=|b|K|η(uε)||uε|dtdx|b|ηL(C(T),C(T))uεL((0,T)×R)|K|ηL(C(T),C(T))|K|C(T).

    We claim that

    {L5,ε}ε>0 is uniformly bounded in L1loc((0,T)×R),T>0.

    Let K be a compact subset of (0,T)×R. Again by Lemma 2.6,

    κ2η(uε)u3εL1(K)=κ2K|η(uε)||uε|3dtdxκ2ηL(C(T),C(T))uε3L((0,T)×R)|K|ηL(C(T),C(T))|K|C(T).

    Therefore, Murat's lemma [47] implies that

    {tη(uε)+xq(uε)}ε>0 lies in a compact subset of H1loc((0,T)×R). (3.4)

    The L bound stated in Lemma 2.6, (3.4) and the Tartar's compensated compactness method [61] give the existence of a subsequence {uεk}kN and a limit function uL((0,T)×R),T>0, such that (3.1) holds.

    Finally, (3.2) follows from (3.1), the Hölder inequality and the identity

    Pεk=x0uεkdy,xPεk=uεk.

    Now, we prove Theorem 1.1.

    Proof of Theorem 1.1. Lemma 3.2 gives the existence of an entropy solution u for (1.9), or equivalently (1.10).

    We prove that u(t,x) is unique and (1.14) holds. Fix T>0. Let u(t,x) and v(t,x) be two entropy solution of (1.9), or (1.10) such that

    u,vL((0,T)×R) (3.5)

    Consequently, by (3.5), we have that

    |u3v3|C(T)|uv|, (3.6)

    where

    C(T)=3|a|sup(0,T)×R{u2,v2}. (3.7)

    We define

    Pu=x0udy,Pv=x0vdy (3.8)

    Thanks to (3.6), following [6,17,27,40], we can prove that

    t(|uv|)+x[(au3av3)sign(uv)]sign(uv)γ(PuPv)sign(uv)b(uv)sign(uv)κ2(u3v3)0,

    holds in sense of distributions in (0,)×R, and

    u(t,)v(t,)I(t)u0v0I(0)+γt0I(s)sign(uv)(PuPv)dsdx+bt0I(s)sign(uv)(uv)dsdx+κ2t0I(s)sign(uv)(u3v3)dsdx, (3.9)

    for 0<t<T, where

    I(s)=[RC(T)(ts),R+C(T)(ts)]. (3.10)

    Observe that

    bt0I(s)sign(uv)(uv)dsdx|b|t0I(s)|uv|dsdx=|b|t0u(s,)v(s,)L1(I(s))ds. (3.11)

    Instead, thanks to (3.6),

    κ2t0I(s)sign(uv)(u3v3)dsdxκ2t0I(s)|u3v3|dsdxC(T)t0u(s,)v(s,)L1(I(s))ds. (3.12)

    Since

    |I(s)|=2R+2C(T)(ts)2R+2C(T)tC(T), (3.13)

    due to (3.8),

    γt0I(s)sign(uv)(PuPv)dsdx|γ|t0I(s)|PuPv|dsdx|γ|t0I(s)(|x0|uv|dy|)dsdx|γ|t0I(s)(|I(s)|uv|dy|)dsdx=|γ|t0|I(s)|u(s,)v(s,)L1(I(s))dsC(T)t0u(s,)v(s,)L1(I(s))ds. (3.14)

    Considered the following function,

    G1(t)=u(t,)v(t,)I(t),t0. (3.15)

    It follows from (3.9), (3.11), (3.12) and (3.14) that

    G1(t)G1(0)+C(T)t0G1(s)ds. (3.16)

    The Gronwall inequality and (3.15) give

    u(t,)v(t,)L1(R,R)eC(T)tu0v0L1(RC(T)t,R+C(T)t),

    that is (1.14).

    The authors are members of the Gruppo Nazionale per l'Analisi Matematica, la Probabilità e le loro Applicazioni (GNAMPA) of the Istituto Nazionale di Alta Matematica (INdAM).

    The authors declare no conflict of interest.



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