The polynomial complementarity problem (PCP) is to find a vector $ {\bf x}\in \mathbb{R}^n_+ $ such that $ \sum_{h = 1}^{m-1}\mathcal{A}_h {\bf x}^{m-h} +{\bf q} \ge{\bf 0}, {\bf x}^{\top}\big(\sum_{h = 1}^{m-1}\mathcal{A}_h {\bf x}^{m-h}+{\bf q}\big) = 0 $. In this paper, we further investigate the lower bound for the solution set of the PCP with $ {\bf q} \in \mathbb{R}^n_{++} $. When $ \mathcal{A}_1 $ is an $ R_0 $-tensor, we present an improved upper bound for the solution set of the PCP, which is tighter than the bound given by Xu et al. in [Bounds of the solution set to the polynomial complementarity problem. J. Optim. Theory Appl. 203 (2024) 146-164]. Finally, we prove that the proposed lower and upper bounds for the solution set of the PCP with partially symmetric tensor tuples are attainable. Numerical examples are given to show the efficiency of the proposed results.
Citation: Jun He, Shi-Liang Wu, Dongsheng Luo, Qingyu Zeng. Some bounds of solutions to the polynomial complementarity problem[J]. Journal of Industrial and Management Optimization, 2026, 22(6): 2683-2696. doi: 10.3934/jimo.2026098
The polynomial complementarity problem (PCP) is to find a vector $ {\bf x}\in \mathbb{R}^n_+ $ such that $ \sum_{h = 1}^{m-1}\mathcal{A}_h {\bf x}^{m-h} +{\bf q} \ge{\bf 0}, {\bf x}^{\top}\big(\sum_{h = 1}^{m-1}\mathcal{A}_h {\bf x}^{m-h}+{\bf q}\big) = 0 $. In this paper, we further investigate the lower bound for the solution set of the PCP with $ {\bf q} \in \mathbb{R}^n_{++} $. When $ \mathcal{A}_1 $ is an $ R_0 $-tensor, we present an improved upper bound for the solution set of the PCP, which is tighter than the bound given by Xu et al. in [Bounds of the solution set to the polynomial complementarity problem. J. Optim. Theory Appl. 203 (2024) 146-164]. Finally, we prove that the proposed lower and upper bounds for the solution set of the PCP with partially symmetric tensor tuples are attainable. Numerical examples are given to show the efficiency of the proposed results.
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