A generalized mathematical model for a class of mechanical systems with lumped and distributed parameters

1.   Introduction

Throughout this article, we shall consider the following Dirichlet integro-differential problem

for $s \in (1/2, 1)$, $\Omega \subset \mathbb{R}^{N}$, $p > 1$ and $f$ a non-negative measurable function. When the nonlinear term appears in the righthand side the model (1.1) may be seen as a Kardar-Parisi-Zhang stationary problem driving by fractional diffusion (see ^[20] for the model in the local setting and ^[1] in the nonlocal case). The problem with the nonlinear term in the left hand side is the stationary counterpart of a Hamilton-Jacobi equation with a viscosity term, the principal nonlocal operator. See ^[30] and the references therein.

The fractional Laplacian operator $(-\Delta)^{s}$, and more general pseudo-differential operators, have been a classic topic in Harmonic Analysis and PDEs. Moreover, these is a renovated interest in these kind of operators. Non-local operators arise naturally in continuum mechanics, image processing, crystal dislocation, phase transition phenomena, population dynamics, optimal control and theory of games as pointed out in ^{[6,10,11,12,18]} and the references therein. For instance, the fractional heat equation may appear in probabilistic random-walk procedures and, in turn, the stationary case may do so in pay-off models (see ^[10] and the references therein). In the works ^[25] and ^[26] the description of anomalous diffusion via fractional dynamics is investigated and various fractional partial differential equations are derived from Lévy random walk models, extending Brownian walk models in a natural way. Fractional operators are also involved in financial mathematics, since Lèvy processes with jumps revealed as more appropriate models of stock pricing. The bounday condition

which is given in the whole complement may be interpreted from the stochastic point of view as the fact that a Lèvy process can exit the domain $\Omega$ for the first time jumping to any point in its complement.

Regarding the integro-differential problem that we discuss in the present manuscript, the main results of our research may be summarized as follows

● In the sub-critical scenario $1 < p < p_{*}: = \frac{N}{N-2s+1}$, there is a unique non-negative distributional solution $u \in W^{1, q}_0(\Omega)$ of (1.1) for any $1\leq q < p_{*}$.

● Now, for $x\in \Omega$, setting $\delta (x) = \text{dist}(x, \partial\Omega) = \text{dist}(x, \Omega^{c})$ (since $\Omega$ is a bounded regular domain), then if $1 < p < p_{*}$, with similar arguments to those in ^[1] and ^[15], we have

- If $m < \frac{N}{2s-1}$, then $|\nabla u|\delta ^{1-s} \in L^{q}(\Omega)$ for all $1\leq q < \frac{mN}{N-m(2s-1)}$.

- If $m = \frac{N}{2s-1}$, then $|\nabla u|\delta ^{1-s} \in L^{q}(\Omega)$ for all $1\leq q < \infty$.

- If $m > \frac{N}{2s-1}$, then $|\nabla u| \in \mathcal{C}^{\alpha}(\Omega)$ for some $\alpha \in (0, 1)$.

In the interval $1 < p < p_{*}$ the result lies on the estimates for the Green function by Bogdan and Jakubowski in ^[8].

● For any $1 < p < \infty$, $u$ is $\mathcal{C}^{1, \alpha}$ provided the source is sufficiently small.

● Any solution $u \in \mathcal{C}^{1, \alpha}(\Omega)$ with Hölder continuous source is a viscosity solution, and conversely.

Notice that in the local case $s = 1$, the main existing results can be summarized into two points: If $p\le 2$, then the existence of solution is obtained for all $f\in L^1(\Omega)$ using approximation arguments and suitable test function, see ^[7] and the references therein. However the truncating arguments are not applicable for $p > 2$ including for $L^\infty$ data. In the case of Lipschitz data, the author in ^[23] was able to get the existence and the uniqueness of a regular solution for all $p$. However this last argument is not applicable for $L^m$ data including for $p$ close to two.

For the non local case, the first existence result was obtained in ^[15]. Indeed, they consider the problem

with $\epsilon \in \left\lbrace -1, 1 \right\rbrace$, for a continuous and non-negative function $g$ satisfying $g(0) = 0$ and a non-negative Radon measure $\nu$ so that $\int_\Omega \delta^{\beta}d\nu < \infty$ with $\beta \in [0, 2s-1)$.

In [15,Thm. 1.1], they show that for $\epsilon = 1$ and under the integrability assumption

problem (1.2) admits a non-negative distributional solution $u \in W^{1, q}_0(\Omega)$, for all $1 \leq q < p_{*, \beta}$ where

In particular, this result implies that the Dirichlet problem (1.1) admits a solution $u$ in $W^{1, q}_0(\Omega)$ for all $q \in [1, p_{*})$ and for $1 < p < p_{*}$. Moreover, for $g$ Hölder continuous and bounded in $\mathbb{R}$, solutions to (1.2) becomes strong for a Hölder continuous source.

The regularity of solutions to (1.1) is strongly related to the corresponding issue for problems

As a by-product of the results in ^[1,15,16], we have the following result which will be largely used throughout our paper.

Theorem 1.1. Suppose that $f\in L^m(\Omega)$ with $m\ge 1$ and define $v$ to be the unique solution to problem (1.3) with $s > \frac12$. Then for all $1\leq p < \frac{m N}{N-m(2s-1)}$, there exists a positive constant $C\equiv \hat{C}(\Omega, N, s, p)$ such that

Moreover,

1) If $m = \frac{N}{2s-1}$, then $|\nabla v|\delta ^{1-s}\in L^p(\Omega)$ for all $1\leq p < \infty$.

2) If $m > \frac{N}{2s-1}$, then $v\in \mathcal{C}^{1, \sigma}(\Omega)$ for some $\sigma\in (0, 1)$, and

In the case where $f\in L^1(\Omega)\cap L^m_{loc}(\Omega)$ where $m > 1$, then as it was proved in ^[1], the above regularity results hold locally in $\Omega$. More precisely we have

Proposition 1.2. Assume that $f\in L^1(\Omega)\cap L^m_{loc}(\Omega)$ with $m > 1$. Let $v$ the unique solution to problem (1.3). Suppose that $m < \frac{N}{2s-1}$, then for any $\Omega _1\subset\subset \Omega '_1\subset \subset \Omega$ and for all $1\leq p\le \frac{m N}{N-m(2s-1)}$, there exists $\tilde{C}: = \tilde{C}(\Omega, \Omega _1, \Omega '_1, N, s, p)$ such that

Moreover,

1) If $m = \frac{N}{2s-1}$, then $|\nabla v|\in L^p_{loc}(\Omega)$ for all $1 \leq p < \infty$.

2) If $m > \frac{N}{2s-1}$, then $v\in \mathcal{C}^{1, \sigma}(\Omega)$ for some $\sigma\in (0, 1)$.

As a consequence we conclude that, if $f\in L^m(\Omega)$ with $m > 1$, then

$1)$ If $m\ge\frac{N}{2s-1}$, then $\int\limits_\Omega\, |\nabla v|^a dx < \infty$ for all $a < \frac{1}{1-s}$.

$2)$ If $1 < m < \frac{N+2s}{2s-1}$, then $\int\limits_\Omega\, |\nabla v|^a dx < \infty$ for all $a < \check{P}: = \frac{m N}{N(m(1-s)+1)-m(2s-1)}$.

Remark 1.3. It is clear that $a < a_0 = \frac{1}{1-s}$ is optimal. Before proving the optimality of $a_0$, let us recall the next Hardy inequality that will be used systematically in what follows.

Proposition 1.4. (Hardy inequality) Assume that $\Omega$ is a bounded regular domain of ${I\!\!R}^N$ and $1 < p < N$. Then there exists a positive constant $C(\Omega)$ such that for all $\phi\in W^{1, p}_0(\Omega)$, we have

We prove now the optimality of $a_0$. We argue by contradiction. Assume that, for $0\lneqq f\in L^\infty(\Omega)$, there exists a solution $v$ to (1.3) such that $v\in W^{1, p}_0(\Omega)$ with $p > \frac{1}{1-s}$.

By using the classical Hardy inequality we obtain that

By the results in ^[27] the solution behaves as $v\backsimeq \delta ^s$, therefore, as a consequence, $\dfrac{1}{\delta ^{p(1-s)}}\in L^1(\Omega)$, that is, $p < \frac{1}{1-s}$, a contradiction.

Hence, the bound for the exponent of the gradient seems to be natural if we impose that the solution lies in the Sobolev space $W^{1, p}_0(\Omega)$ for the problem with reaction gradient term.

In the case of absorption gradient term, this affirmation seems to be difficult to prove, however, in Theorem 2.9, we will show that the non existence result holds, at least, for large values of $p$ and for all bounded non negative data.

In the case of gradient reaction term and for $2s\le p < \dfrac{s}{1-s}$, the authors in ^[1] proved the existence of a solution $u$ with $|\nabla u|\in L^p_{loc}(\Omega)$ using a fixed point argument. In the present paper we will use the same approach to get the existence of a solution for $p\ge 2s$. However, in addition to the regularity condition of $f$, smallness condition on the source term $||f||_{L^m(\Omega)}$ is also needed.

The paper is organized as follows. In Section 2, we introduce the functional setting and we precise the notion of solutions that we will use throughout this work as the weak sense and the viscosity sense. We give also some useful estimates for weak solutions and the general comparison principle. A non existence result is proved using suitable estimates on the Green function for the fractional Laplacian with drift term.

The existence of a solution is proved in Section 3. In the Subsection 3.1 we treat the case of natural growth behavior in the gradient term, namely the case $1 < p < 2s$. In this case existence of a solution is obtained for all $L^1$ datum. As a complement of the result proved in ^[15], we prove that if $p > p_*$, the existence of a solution for general measure data $\nu$ is not true and additional hypotheses on $\nu$ related to a fractional capacity are needed.

Problem with a linear zero order reaction term is also analyzed. In such a case we are able to show existence for data in $L^1$ and then a breaking of resonance occurs under natural hypotheses on the zero order term and $p$.

Some additional regularity results are obtained in the subcritical case $1 < p < p_*$.

The general case, $p\ge 2s$, is treated in Subsection 3.3. Here and since we will use fixed point theorem, we need to impose some additional condition on the regularity and the size of $f$. The existence result is obtained in a suitable weighted Sobolev space under additional hypotheses on $p$. The above existence result holds trivially for the case $s = 1$ and then can be seen as an extension of the existence result obtained in ^[23] in the framework of $L^m$ datum.

The analysis of the viscosity solution is done is Section 4 where it is also proved that weak solution is a viscosity solution and viceversa if the data $f$ is sufficiently regular and $s$ is close to 1, compare with ^[28].

Some related open problems are given in the last section.

1.1.   Basic notation

In what follows, $\Omega$ will denote a bounded, open and $\mathcal{C}^{2}$ domain in $\mathbb{R}^{N}$ with bounded boundary, $N \geq 1$. We introduce some functional-space notation. By $USC(\Omega)$, $LSC(\Omega)$ and $\mathcal{C}(\Omega)$, we denote the spaces of upper semi-continuous, lower semi continuous and continuous real-valued functions in $\Omega$, respectively. Moreover, the space $\mathcal{C}^{k}(\Omega)$, $k \geq 1$, is defined as the set of functions which derivatives of orders $\leq k$ are continuous in $\Omega$. Also, the Hölder space $\mathcal{C}^{k, \alpha}(\Omega)$ is the set of $\mathcal{C}^{k}(\Omega)$ whose $k-$th order partial derivatives are locally Hölder continuous with exponent $\alpha$ in $\Omega$.

For $\sigma \in \mathbb{R}$, we define the truncation operator as follows

Finally, for any $u$, we denote by

2.   Preliminaries and technical tools

In order to introduce the notion of distributional solutions, we give some definitions. For $s \in (\frac12, 1)$ and $u\in\mathcal{S}(\mathbb{R}^{N})$, the fractional Laplacian $(-\Delta)^{s}$ is given by

where

with:

For larger class of functions the fractional Laplacian can be defined by density. See ^[17] or ^[29] for instance.

Definition 2.1. We say that a function $\phi \in \mathcal{C}(\mathbb{R}^{N})$ belongs to $\mathbb{X}_s(\Omega)$ if and only if the following holds

● supp$(\phi) \subset \overline{\Omega}$.

● The fractional Laplacian $(-\Delta)^{s}\phi(x)$ exists for all $x \in \Omega$ and there is $C > 0$ so that $|(-\Delta)^{s}\phi(x)|\leq C$.

● There is $\varphi \in L(\Omega, \delta^{s}dx)$ and $\epsilon_0 > 0$ so that

a.e. in $\Omega$ and for all $\epsilon \in (0, \epsilon_0)$.

Before staring the sense for which solutions are defined, let us recall the definition of the fractional Sobolev space and some of its properties.

Assume that $s\in (0, 1)$ and $p > 1$. Let $\Omega \subset {I\!\!R}^N$, then the fractional Sobolev Space $W^{s, p}(\Omega)$ is defined by

where $d\nu = \frac{dxdy}{|x-y|^{N+ps}}$.

Notice that $W^{s, p}(\Omega)$ is a Banach Space endowed with the norm

The space $W^{s, p}_{0} (\Omega)$ is defined as the completion of $\mathcal{C}^\infty_0(\Omega)$ with respect to the previous norm.

If $\Omega$ is a bounded regular domain, we can endow $W^{s, p}_{0}(\Omega)$ with the equivalent norm

Notice that if $ps < N$, then we have the next Sobolev inequality, for all $v\in C_{0}^{\infty}({I\!\!R}^N)$,

where $p^{*}_{s} = \dfrac{pN}{N-ps}$ and $S\equiv S(N, s, p)$.

In the following definition, we introduce the class of distributional solutions.

Assume that $\nu$ is a bounded Radon measure and consider the problem

Let us begin by precising the sense in which solutions are defined for general class of data.

Definition 2.2. We say that $u$ is a weak solution to problem (2.1) if $u\in L^1(\Omega)$, and for all $\phi\in \mathbb{X}_s$, we have

where $\mathbb{X}_s$ is given in Definition 2.1.

As a consequence of the properties of the Green function, the authors in ^[16] obtain the following regularity result.

Theorem 2.3. Suppose that $s\in (\frac 12, 1)$ and let $\nu \in \mathfrak{M}(\Omega)$, be a Radon measure such that

with $\beta \in [0, 2s-1)$. Then the problem (2.1) has a unique weak solution $u$ in the sense of Definition 2.2 such that $u \in W^{1, q}_0(\Omega)$, for all $1\leq q < p^{*}_{\beta}$ where $p_{*, \beta}: = \frac{N}{N-2s+1+\beta}.$ Moreover

For $\nu \in L^1(\Omega)$, setting $T: L^1(\Omega)\to W^{1, \theta}_0(\Omega)$, with $T(f) = u$, then $T$ is a compact operator.

Related to $T_k(u)$ and for $s > \frac 12$, we have the next regularity result obtained in ^[1].

Theorem 2.4. Assume that $f\in L^1(\Omega)$ and define $u$ to be the unique weak solution to problem (2.1), then $T_k(u)\in W^{1, \alpha }_0(\Omega)\cap H^s_0(\Omega)$ for any $\alpha < 2s$, moreover

We recall also the next comparison principle proved in ^[1]

Theorem 2.5. (Comparison Principle). Let $g\in L^1(\Omega)$ and suppose that $w_1, w_2\in W^{1, q}_0(\Omega)$ for all $1 \leq q < \frac{N}{N-2s+1}$ are such that $(- \Delta)^s w_1, (- \Delta)^s w_2\in L^1(\Omega)$ with

where $H: \Omega \times {I\!\!R}\times {I\!\!R}^N\to {I\!\!R}$ is a Carathéodoty function satisfying

1) $H_1(x, w_1, \nabla w_1), H_1(x, w_2, \nabla w_2)\in L^1(\Omega)$,

2) for a.e. $x\in \Omega$, we have

with $B\in (L^{a}(\Omega))^N$, $a > \frac{N}{2s-1}$ and $f\in L^1(\Omega)$ with $f\le 0$ a.e. in $\Omega$.

Then $w_1\le w_2$ in $\Omega$.

Recall that we are considering problem (1.1), then we have the next definition.

Definition 2.6. A function $u \in L^{1}(\Omega)$, with $|\nabla u|^{p}\in L^{1}_{loc}(\Omega)$, is a distributional solution to problem (1.1) if for any $\phi \in \mathbb{X}_s(\Omega)$, there holds

and $u = 0$ in $\mathbb{R}^{N}\setminus \Omega$.

We denote by $G_s$ the Green kernel of $(-\Delta)^{s}$ in $\Omega$ and by $\mathbb{G}_s[\cdot]$ the associated Green operator defined by

See ^[8] and ^[14] for the estimates of the Green function.

Definition 2.7. A function $u: \Omega \to \mathbb{R}$ is a strong solution to the equation

in $\Omega$ if $u \in \mathcal{C}^{2s+ \alpha}(\Omega)$, for some $\alpha > 0$ and

for every $x$ in $\Omega$.

The other class of solutions that we shall consider is the class of viscosity solutions. Unlike the distributional scenario, the notion of viscosity solutions requires the punctual evaluation of the equation using appropriate test functions that touch the solution from above or below. We refer to ^[5] and ^[13] for more details.

Definition 2.8. An upper semicontinuous function $u: \mathbb{R}^{N} \to \mathbb{R}$ is a viscosity subsolution to (1.1) in $\Omega$, if $u \in L_{loc}(\mathbb{R}^{N})$, and for any open set $U \subset \Omega$, any $x_0 \in U$ and any $\phi \in \mathcal{C}^{2}(U)$ such that $u(x_0) = \phi(x_0)$ and $\phi \geq u$ in $U$, if we let

we have

and $v\leq 0$ in $\mathbb{R}^{N}\setminus \Omega$. On the other hand, a lower semicontinuous function $u: \mathbb{R}^{N} \to \mathbb{R}$ is a viscosity supersolution to (1.1) in $\Omega$ if $u \in L_{loc}(\mathbb{R}^{N})$, and for any open set $U \subset \Omega$, any $x_0 \in U$ and any $\psi \in \mathcal{C}^{2}(U)$ such that $u(x_0) = \psi(x_0)$ and $\phi \leq u$ in $U$, if we define $v$ as

there holds

and $v\geq 0$ in $\mathbb{R}^{N}\setminus \Omega$. Finally, a viscosity solution to (1.1) is a continuous function which is both a subsolution and a supersolution to (1.1).

To end this section, we prove the next non existence result that justifies in some way the condition $p < \frac{1}{1-s}$ that we will be used later.

Theorem 2.9. Assume that $p > \frac{2s-1}{1-s}N+1$, then for all $0\lvertneqq f\in L^\infty(\Omega)$, problem (1.1) has no weak solution $u$ in the sense of Definition 2.2, such that $u\in W^{1, p}_0(\Omega)$.

Proof. Suppose by contradiction that problem (1.1) has a solution $u$ with $u\in W^{1, p}_0(\Omega)$. It is clear that $u$ solves the problem

where $B(x) = |\nabla u|^{p-2}\nabla u$. Since $p > \frac{2s-1}{1-s}N+1$, then $|B|\in L^\sigma (\Omega)$ with $\sigma > \frac{N}{2s-1}$ and then $B\in \mathcal{K}^{s}_N(\Omega)$ the Kato class of function defined by formula (30) in ^[8]. Thus

where $\hat{\mathcal{G}}_s$ is the Green function associated to the operator $(- \Delta)^s +B(x)\nabla$. From the result of ^[8], we know that $\hat{\mathcal{G}}_s\simeq \mathcal{G}_s$, the Green function associated to the fractional laplacian. Hence

Using the fact that $\dfrac{\delta ^s(x)}{|x-y|^{s}}\ge C(\Omega)\delta ^s(x)$, we reach that

Therefore, using the Hardy inequality we deduce that

Thus $\dfrac{1}{\delta ^{p(1-s)}}\in L^1(\Omega)$. Since $p(1-s)\ge 1$, then we reach a contradiction.

Corollary 2.10. Let $f$ be a Lipschitz function such that $f\gneqq 0$, then if $p > \frac{1}{1-s}$, problem (1.1) has no solution $u$ such that $u\in \mathcal{C}^1(\Omega)$ with $|\nabla u|\in L^p(\Omega)$.

Remark 2.11. It is clear that the above result makes a significative difference with the local case and the general existence result proved in ^[23] for Lipschitz function. We conjecture that the non existence result holds at least for all $p > \frac{1}{s-1}$ as in the case of gradient reaction term.

3.   Existence results

3.1.   The problem with natural growth in the gradient: $p < 2s$

In this section we consider the case of natural growth in the gradient, namely we will assume that $p < 2s$. Then using truncating arguments, we are able to show the existence of a solution to problem (1.1) for a large class of data. We also treat the case where a linear reaction term appears in (1.1).

In the case where $p < p_*$, then for more regular data $f$, we can show that the solution is in effect a classical solution.

Theorem 3.1. Let $f \in L^{m}(\Omega)$ with $m \geq 1$, and assume that $1 < p < p_{*}$. Then, the Dirichlet problem

has a unique distributional solution $w$ verifying

● if $m < \frac{N}{2s-1}$, then $|\nabla w| \in L^{q}_{loc}(\Omega)$ for all $1\leq q < \frac{mN}{N-m(2s-1)}$;

● if $m = \frac{N}{2s-1}$, then $|\nabla w| \in L^{q}_{loc}(\Omega)$ for all $1 \leq q < \infty$;

● if $m > \frac{N}{2s-1}$, then $|\nabla w |\in \mathcal{C}^{\alpha}(\Omega)$ for some $\alpha \in (0, 1)$.

Moreover, if in addition $f \in \mathcal{C}^{\epsilon}(\Omega)$, for some $\epsilon \in (0, 2s-1)$, then the $\mathcal{C}^{1, \alpha}$ distributional solution is a strong solution.

Proof. It is clear that the existence and the uniqueness follow using ^[15,1], however, the regularity in the local Sobolev space follows using Proposition 1.2. Notice that, in this case $|\nabla u|^{p-1}\in L^\sigma (\Omega)$ with $\sigma > \frac{N}{2s-1}$ and then we can iterate the local regularity result in Proposition 1.2 to deduce that $|\nabla u|\in L^\theta_{loc}(\Omega)$ for all $\theta > 0$. Hence $|\nabla u|\in \mathcal{C}^{a}(\Omega)$ for some $a < 1$.

Now, assume that $f \in \mathcal{C}^{\epsilon}(\Omega)$, and let $\Omega' \Subset \Omega$, open and let $u$ be a distributional solution to problem (1.1). Since $u \in L^{\infty}(\mathbb{R}^{N})$ and $f-|\nabla u|^{p} \in L^{\infty}(\Omega')$, we apply Proposition 2.3 in ^[27] to derive

In particular, we have $|\nabla u| \in \mathcal{C}^{\beta-1}(\Omega'')$ for any $\beta \in (1, 2s)$. Consequently, $f- |\nabla u|^{p} \in \mathcal{C}^{\epsilon}(\Omega'')$. Appealing now to Corollary 2.4 in ^[27], we obtain $u \in \mathcal{C}^{2s+\epsilon}$ in a smaller subdomain of $\Omega''$. Thus, $u \in \mathcal{C}^{2s+\epsilon}$ locally in $\Omega$.

We prove that $u$ is a strong solution. Since the term $f-|\nabla u|^{p}$ is $\mathcal{C}^{\epsilon}$ in $\Omega$, and then, by appropriate extension, in $\overline{\Omega}$, we deduce from [16,Lemma 2.1(ⅱ)] that $u \in \mathbb{X}_s$. Hence the integration by parts formula

holds for all $\phi \in \mathbb{X}_s$. For any $\phi \in \mathcal{C}^{\infty}_0(\Omega)$ we hence obtain

Therefore

for almost everywhere $x$ in $\Omega$. By continuity, it holds in the full set $\Omega$.

Remark 3.2. Observe that the reasoning employed to prove the above result gives the precise way in which the function $f$ transfers its regularity to a solution $u$. Indeed, if $f \in \mathcal{C}^{2ns+\epsilon -n}$ locally in $\Omega$, for $\epsilon \in (0, 2s-1)$ and $n \geq 0$, then $u \in \mathcal{C}^{2(n+1)s + \epsilon -n}$ locally in $\Omega$.

3.2.   The case $p_*\le p < 2s$ with general datum

In this subsection we will assume that $p_*\le p < 2s$, then the first existence result for problem (1.1) is the following.

Theorem 3.3. Assume that $p < 2s$, then for all $f\in L^1(\Omega)$ with $f\ge 0$, the problem (1.1) has a maximal weak solution $u$ such that $u\in W^{1, p}_0(\Omega)$ and $T_k(u)\in W^{1, \alpha }_0(\Omega)\cap H^s_0(\Omega)$ for any $1 < \alpha < 2s$ and for all $k > 0$.

Proof. We divide the proof into two steps.

The first step: We show for a fixed positive integer $n\in {I\!\!N}^*$, the problem

has a unique solution $u_n$ such that $u_n\in W^{1, q}_0(\Omega)$ for all $1\le q < \frac{N}{N-2s+1}$ and $T_k(u_n)\in H^s_0(\Omega)$. To prove that, we proceed by approximation.

Let $k\in {I\!\!N}^*$ and define $u_{n, k}$ to be the unique solution to the approximating problem

where $f_k = T_k(f)$. We claim that the sequence $\{u_{n, k}\}_k$ is increasing in $k$, namely $u_{n, k}\le u_{n, k+1}$ for all $k\ge 1$ and $n$ fixed. To see that, we have

Thus $u_{n, k+1}$ is a supersolution the problem solved by $u_{n, k}$. Setting $H(x, s, \xi) = -\dfrac{|\xi|^p}{1+\frac 1n |\xi|^p}$, then by the comparison principle in Theorem 2.5, it follows that $u_{n, k}\le u_{n, k+1}$ and then the claim follows. It is clear that $u_{n, k}\le w$ for all $n, k\in {I\!\!N}^*$ where $w$ is the unique solution to problem

Notice that $w\in W^{1, q}_0(\Omega)$ for all $1\le q < \frac{N}{N-2s+1}$ and $w\in L^r(\Omega)$ for all $1\le r < \frac{N}{N-2s}$.

Hence, we get the existence of $u_n$ such that $u_{n, k}\uparrow u_n$ strongly in $L^{\sigma }(\Omega)$ for all $1\le \sigma < \frac{N}{N-2s}$.

For $n$ fixed, we set $h_{n, k}: = f_{k}-\dfrac{|\nabla u_{n, k}|^p}{1+\frac 1n |\nabla u_{n, k}|^p}$, then $|h_{n, k}|\le f+n$. Thus $||h_{n, k}||_{L^1(\Omega)}\le ||f||_{L^1(\Omega)}+n|\Omega |$. Hence using the compactness result in Theorem 2.3 we deduce that up to a subsequence, $u_{n, k}\to u_n$ strongly in $W^{1, \alpha }_0(\Omega)$ for all $\alpha < \frac{N}{N-2s+1}$. Since the sequence $\{u_{k, n}\}_k$ is increasing in $k$, then the limit $u_n$ is unique. Thus, up to a further subsequence, $\nabla u_{n, k}\to \nabla u_n$ a.e. in $\Omega$. Hence using the dominated convergence Theorem it holds that

Hence $u_n$ solves the problem (3.1). To proof the uniqueness of $u_n$, we assume that $v_n$ is another solution to problem (3.1), then

where $\hat{H}(|\xi|) = -\dfrac{|\xi|^p}{1+\frac 1n |\xi|^p}$. Since $|\hat{H}(|\xi|)|\le n$, then we obtain that $u_n-v_n\in L^\infty(\Omega)$. Finally using the comparison principle in Theorem 2.5 it follows that $u_n = v_n$ and then we conclude.

Second step: Consider the sequence $\{u_n\}_n$ obtained in the first step, then we know that $u_n\le w$ for all $n$. We claim that $u_n$ is decreasing in $n$. Recall that $u_n$ is the unique solution to the problem

Thus

Hence $u_n$ is a supersolution to the problem solved by $u_{n+1}$. As a consequence and using the comparison principle in Theorem 2.5, it follows that $u_{n+1}\le u_{n}\le w$ for all $n$.

Hence, there exists $u$ such that $u_n\downarrow u$ strongly in $L^{\sigma }(\Omega)$ for all $1\le \sigma < \frac{N}{N-2s}$.

We set $g_n(|\nabla u_n|) = \dfrac{|\nabla u_n|^p}{1+\frac 1n |\nabla u_n|^p}$, and let $j > 0$, using $T_j(u_n)$ as a test function in (3.4) it follows that

Hence $\{T_j(u_n)\}_n$ is bounded in $H^s_0(\Omega)$ for all $j > 0$ and then, up to a subsequence, we have $T_j(u)\rightharpoonup T_j(u)$ weakly in $H^s_0(\Omega)$. We claim that $\{g_n\}_n$ is bounded in $L^1(\Omega)$. To see that, we fix $\varepsilon > 0$ and we use $v_{n, \varepsilon } = \frac{u_n}{\varepsilon +u_n}$ as a test function in (3.4). It is clear that $v_{n, \varepsilon }\le 1$, then taking into consideration that

it follows that

Letting $\varepsilon \to 0$, we reach that $\int\limits_\Omega\, g_n(|\nabla u_n|)dx\le C$ an the claim follows. Define $h_n = f-g_n$, then $||h_n||_{L^1(\Omega)}\le C$. As a consequence and by the compactness result in Theorem 2.3, we reach that, up to a subsequence, $u_n\to u$ strongly in $W^{1, \alpha }_0(\Omega)$ for all $1\le \alpha < \frac{N}{N-2s+1}$ and then, up to an other subsequence, $\nabla u_n\to \nabla u$ a.e in $\Omega$. Hence $g_n\to g$ a.e. in $\Omega$ where $g(x) = |\nabla u|^p$. Since $p < 2s$, then by Theorem 2.4 and using Vitali Lemma we conclude that

In particular

Hence to get the existence result we have just to show that $g_n\to g$ strongly in $L^1(\Omega)$.

Notice that, using $T_1(G_j(u_n))$ as a test function in (3.4) it holds that

Let $\varepsilon > 0$ and consider $E\subset \Omega$ to be a measurable set, then

By (3.5), letting $n\to \infty$, we can chose $|E|$ small enough such that

In the same way and since $f\in L^1(\Omega)$, we reach that

Hence, for $|E|$ small enough, we have

Thus by Vitali lemma we obtain that $g_n\to g$ strongly in $L^1(\Omega)$. Therefore we conclude that $u$ is a solution to problem (1.1).

If $\hat{u}$ is an other solution to (1.1), then

Hence $\hat{u}\le u_n$ and then $\hat{u}\le u$.

Remark 3.4. 1) The existence of a unique solution to the approximating problem (3.4) holds for all $p\ge 1$.

2) Problem of uniqueness of solution to problem (1.1) is an interesting open problem including for the local case $s = 1$ where partial results are known in the case $1 < p < \frac{N}{N-1}$ or $p = 2$.

3) As a consequence of the previous result and following closely the same argument we can prove that for all $p < 2s$, for all $a > 0$ and for all $(f, g)\in L^1(\Omega)\times L^1(\Omega)$ with $f, g\gneqq 0$, the problem

has a positive solution $u$.

In the case where the datum $f$ is substituted by a Radon measure $\nu$, existence of solutions holds for all $1 < p < p_*$ as it was proved in ^[15]. However, if $p\ge p_*$, then the situation changes completely as in the local case, and, additional hypotheses on $\nu$ related to a fractional capacity $\text{Cap}_{\sigma, p}$ are needed, with $\sigma < 1$.

The fractional capacity $\text{Cap}_{\sigma, p}$ is defined as follow.

For a compact set $K\subset \Omega$, we define

Now, if $U\subset \Omega$ is an open set, then

For any borel subset $B\subset \Omega$, the definition is extended by setting:

Notice that, using Sobolev inequality, we obtain that if $\text{Cap}_{\sigma, p}(A) = 0$ for some set $A\subset \subset \Omega$, then $|A| = 0$. We refer to ^[24] and ^[31] for the main properties of this capacity.

To show that the situation changes for the set of general Radon measure, we prove the next non existence result.

Theorem 3.5. Assume that $p > p_*$, $\frac 12 < s < 1$ and let $x_0\in \Omega$, then the problem

has non solution $u$ such that $u\in W^{1, p}_0(\Omega)$.

Proof. For simplify of tipping we assume that $x_0 = 0\in \Omega$ and we write $\delta$ for $\delta _0$. We follow closely the argument used in ^[4]. Assume by contradiction that for some $p > p_*$, problem (3.8) has a solution $u\in W^{1, p}_0(\Omega)$. Then $u\in W^{\sigma, p}_0(\Omega)$ for all $\sigma < 1$. We claim that $(-\Delta)^s u \in W^{-\sigma, p}(\Omega)$, the dual space of $W^{\sigma, p}_0(\Omega)$, for all $\sigma \in (2s-1, 2s)$. To see that, we consider $\phi\in \mathcal{C}^\infty_0(\Omega)$, then

Since $2s-\sigma \in (0, 1)$, then $\bigg(\iint_{ {I\!\!R}^{2N}} \dfrac{|u(x)-u(y)|^p}{|x-y|^{N+p(2s-\sigma)}}\, dxdy\bigg)^{\frac{1}{p}} \le C(\sigma, s, N, \Omega)||u||_{W^{1, p}_0(\Omega)}$. Thus

and then the claim follows. Hence going back to problem (3.8), we deduce that $\delta \in L^1(\Omega)+W^{-\sigma, p}(\Omega)$.

As in ^[7], let us now show that if $\nu\in W^{-\sigma, p}(\Omega)$, then $\nu < < \text{Cap}_{\sigma, p'}$. Notice that, if in addition, $\nu$ is nonnegative, then we can prove that

and we deduce easily that $\nu < < \text{Cap}_{\sigma, p'}$. Here we give the proof without the positivity assumption on $\nu$.

Let $A\subset\subset \Omega$ be such that $\text{Cap}_{\sigma, p'}(A) = 0$, then there exists a Borel set $A_0$ such that $A\subset A_0$ and $\text{Cap}_{\sigma, p'}(A_0) = 0$. Let $K\subset A_0$ be a compact set, then there exists a sequence $\{\psi_n\}_n\in \mathcal{C}^\infty_0(\Omega)$ such that $0\le \psi_n\le 1$, $\psi_n\ge \chi_K$ and $||\psi_n||^{p'}_{W^{\sigma, p'}_0(\Omega)}\to 0$ as $n\to \infty$. It is clear that $\psi_n\to \chi_K$ a.e in $\Omega$, as $n\to \infty$. Hence

Thus

Therefore, we conclude that for any compact set $K\subset A_0$, we have $|\nu (K)| = 0$. Hence $|\nu (A_0)| = 0$ and the result follows.

Notice that if $h\in L^1(\Omega)$, then $|h| < < \text{Cap}_{\sigma, p'}$. As a conclusion, we deduce that $\delta < < \text{Cap}_{\sigma, p'}$ for all $\sigma \in (2s-1, 2s)$.

Since $p > p_*$, we can choose $\sigma _0\in (2s-1, 2s)$ such that $p'\sigma _0 < N$. To end the proof, we have just to show that $\text{Cap}_{\sigma _0, p'}\{0\} = 0$. Without loss of generality, we can assume that $\Omega = B_1(0)$. Since $\sigma p' < N$, setting $w(x) = (\dfrac{1}{|x|^ \alpha }-1)_+$ with $0 < \alpha < \frac{N-\sigma _0 p'}{p'}$, we obtain that $w\in W^{\sigma, p'}_0(\Omega)$. Notice that, for all $v\in W^{\sigma, p'}_0(\Omega)$, we know that

Since $w(0) = \infty$, then $\{0\}\subset \{|w|\ge k\}$ for all $k > 0$. Thus

Letting $k\to \infty$, it holds that $\text{Cap}_{\sigma, p'}\{0\} = 0$ and the result follows.

As a direct consequence of the above Theorem we obtain that for $p > p_*$, to get the existence of a solution to problem (1.1) with measure data $\nu$, then necessarily $\nu$ is continuous with respect to the capacity $\text{Cap}_{\sigma, p}$ for all $\sigma \in (2s-1, 2s)$.

Let consider now the next problem

with $g\gneqq 0$ and $\lambda > 0$. As in local case studied in ^[3], we can show that under natural conditions on $q$ and $g$, the problem (3.9) has a solution for all $\lambda > 0$. Moreover, the gradient term $|\nabla u|^q$ produces a strong regularizing effect on the problem and kills any effect of the linear term $\lambda g u$.

Before stating the main existence result for problem (3.9), let us begin by the next definition.

Definition 3.6 Let $g$ be a nonnegative measurable function such that $g\in L^1(\Omega)$. We say that $g$ is an admissible weight if

$\bullet$ If $g \in L^{\frac{p N}{N(p-1)+p}}(\Omega)$ with $g\gneqq 0$, then using the Sobolev inequality in the space $W^{1, p}_0(\Omega)$, it holds that $g$ satisfies (3.10).

$\bullet$ If $p < N$ and $g(x) = \frac{1}{|x|^\sigma }$ with $\sigma < 1+\frac{N}{p'}$, then using the Hardy-Sobolev inequality in the space $W^{1, p}_0(\Omega)$, we deduce that $g$ satisfies (3.10).

Now, we are able to state the next result.

Theorem 3.7. Assume that $1 < p < 2s$ and suppose that $g$ is an admissible weight in the sense given in (3.10). Then for all $f\in L^1(\Omega)$ with $f\ge 0$ and for all $\lambda > 0$, the problem (3.9) has a solution $u$ such that $u\in W^{1, p}_0(\Omega)$ and $T_k(u)\in W^{1, \alpha }_0(\Omega)\cap H^s_0(\Omega)$ for any $1 < \alpha < 2s$ and for all $k > 0$.

Proof. Fix $\lambda > 0$ and define $\{u_n\}_n$ to be a sequence of positive solutions to problem

To reach the desired result we have just to show that the sequence $\{g(x)\dfrac{u_n}{1+\frac 1n _nu}\}_n$ is uniformly bounded in $L^1(\Omega)$. To do that, we use $T_k(u_n)$ as a test function in (3.11), hence

It is clear that

where $H_k(\sigma) = \int_0^ \sigma(T_k(t))^{\frac{1}{p}}dt$. By a direct computation we obtain that

Thus using (3.10) for $H_k(u_n)$ it holds that

where $C_1(k), C_2(k) > 0$ are independent of $n$.

Therefore, going back to (3.12), we conclude that

Since $p > 1$, then by Young inequality we reach that $\{g u_n\}_n$ is uniformly bounded in $L^1(\Omega)$. The rest of the proof follows exactly the same compactness arguments as in the proof of Theorem 3.3.

Remark 3.8. $\bullet$ In the case where $g(x) = \dfrac{1}{|x|^{2s}}$, the Hardy potential, the condition (3.10) holds if $p > \frac{N}{N-(2s-1)}$. Thus, in this case and for all $\lambda > 0$, problem (3.9) has a solution $u$ such that $u\in W^{1, p}_0(\Omega)$ and $T_k(u)\in W^{1, \alpha }_0(\Omega)\cap H^s_0(\Omega)$ for all $\alpha < 2s$.

$\bullet$ Notice that, in this case, without the absorption term $|\nabla u|^p$, the existence of solution holds under the restriction $\lambda \le \Lambda_{N, s}$, where $\Lambda_{N, s}$ is the Hardy constant, and with integral condition on the datum $f$ near the origin. We refer to ^[2] for more details.

3.3.   The case $2s\le p < \frac{s}{1-s}$: existence in a weighted Sobolev space

For $2s\le p < \dfrac{s}{1-s}$ and in the same way as above we can show the next existence result.

Theorem 3.9. Suppose that $f \in L^{m}(\Omega)$ with $m > N/[p'(2s-1)]$. Then there is $\lambda^* > 0$ such that if $||f||_{L^m(\Omega)}\le \lambda ^*$, problem (1.1) admits a solution $u\delta ^{1-s}\in W_0^{1, p}(\Omega)$.

Proof. The proof follows closely the argument used in ^[19] and ^[1], however, for the reader convenience we include here some details.

Without loss of generality we can assume that $N\ge 2$. Fix $\lambda ^* > 0$ such that if $||f||_{L^m(\Omega)}\le \lambda ^*$, then there exists $l > 0$ satisfies

where $\bar{C}(\Omega, N, s, m, p)$ is a positive constant which only depends on the data, it is independent of $f$ and its will be specified below.

Define now the set

It is clear that $E$ is a closed convex set of $W^{1, 1}_0(\Omega)$. Using Hardy inequality in (1.6), we deduce that if $v\in E$, then $|\nabla v|^{pm}\delta ^{pm(1-s)}\in L^1(\Omega)$ and

Define now the operator

where $u$ is the unique solution to problem

To prove that $T$ is well defined we will use Theorem 2.3, namely we show the existence of $\beta < 2s-1$ such that $\bigg|f-|\nabla v|^{p}\bigg|\delta ^\beta \in L^1(\Omega)$. To do that we have just to show that $|\nabla v|^{p}\delta ^\beta \in L^1(\Omega)$.

It is cleat that $|\nabla v|^{p}\in L^1_{loc}(\Omega)$, moreover, we have

If $p(1-s) < 2s-1$, we can chose $\beta < 2s-1$ such that $p(1-s) < \beta$. Hence $\int\limits_\Omega\, \delta ^{(\beta-p(1-s))m'}dx < \infty$.

Assume that $p(1-s)\ge 2s-1$, then $s\in (\frac{1}{2}, \frac{p+2}{p+1}]$. Notice that, since $p < \frac{s}{1-s}$, then $p(1-s)-(2s-1) < 1-s$. Since $m > \frac{N}{p'(2s-1)} > \frac{1}{s}$, then $(p(1-s)-(2s-1))m' < 1$. Hence we get the existence of $\beta < 2s-1$ such that $(p(1-s)-\beta)m' < 1$ and then we conclude.

Then using the fact that $v\in E$, we reach that $|\nabla v|^{p}\delta ^\beta +f \in L^1(\Omega)$. Therefore the existence of $u$ is a consequence of Theorems 2.3 and 1.1. Moreover, $|\nabla u|\in L^{ \alpha }(\Omega)$ for all $\alpha < \frac{N}{N-2s+1+\beta}$. Hence $T$ is well defined.

Now following the argument used in ^[1], for $l$ defined as above and using the regularity result in Theorem 1.1 where we choose the constant $\bar{C}$ strongly related to the constant $\hat{C}$ defined in formula (1.4), we can prove that $T$ is continuous and compact on $E$ and that $T(E)\subset E$. For the reader convenience we included some details

We have

then

Thus

Taking into consideration the properties of the Green function, it holds that

where

and

Following the arguments used in ^[1] and using the regularity result in Theorem 2.3, we get the existence of a positive constant $\breve{C}: = \breve{C}(\Omega, N, s, m)$ such that $I_i, J_i\in L^{pm}(\Omega)$ for $i = 1, 2$ and

Hence assuming that $\bar{C}(\Omega, N, s, m, p) = \breve{C}(\Omega, N, s, m, p)C_2(\Omega, N, s, m, p)$, it follows that

Thus $u\in E$ and then $T(E)\subset E$. In the same way we can prove that $T$ is compact.

Therefore by the Schauder Fixed Point Theorem, there exists $u\in E$ such that $T(u) = u$. Thus, $u\in W^{1, pm}_{loc}(\Omega)$ solves (1.1), at least in the sense of distribution.

Remark 3.10. 1) It is clear that the above argument does not take advantage of the fact that the gradient term appears as an absorption term.

2) The existence of a solution can be also proved independently of the sign of $f$.

As in Theorem 3.1, if in addition we suppose that $f$ is more regular, then under suitable hypothesis on $s$ and $p$, we get the following analogous result of Theorem 3.1.

Corollary 3.11. Assume that the conditions of Theorem 3.9 hold. Assume in addition that

If $f \in \mathcal{C}^{\epsilon}(\Omega)$, for some $\epsilon \in (0, 2s-1)$, then the $\mathcal{C}^{1, \alpha}$ distributional solutions from Theorem 3.9 is a strong solution.

Notice that the condition (3.15) is used in order to show that $|\nabla u|^{p-1}\in L^\sigma _{loc}(\Omega)$ for some $\sigma > \frac{N}{2s-1}$ which is the key point in order to get the desired regularity.

In the case where $f\gvertneqq 0$, we can prove also that $u\gneqq 0$, more precisely, we have

Corollary 3.12. Assume that the above conditions hold. Let $f \in \mathcal{C}^{\epsilon}(\Omega)\cap L^{\infty}(\overline{\Omega})$, for some $\epsilon \in (0, 2s-1)$. If $f(x)\geq 0$ for all $x \in \Omega$, then the solution from Theorem 3.9 is non-negative. Moreover, if $f_1 \leq f_2$ and $u_1$ and $u_2$ are the corresponding strong solutions to $f_1$ and $f_2$ from Corollary 3.11, respectively, then $u_1 \leq u_2$.

Proof. Suppose that there is a point $x_0 \in \Omega$ so that $u(x_0) < 0$. Since $u$ is continuous in $\mathbb{R}^{N}$ (see Proposition 1.1 in ^[27]), we have $u$ attains its negative minimum at an interior point $x_1$ of $\Omega$. Hence

But hence we obtain the contradiction $0 \leq f(x_1)-0 = (-\Delta)^{s}u(x_1) < 0$.

We next prove the last statement in the Corollary 3.12. Let $f_1 \leq f_2$. Let $u_1$ and $u_2$ be the corresponding strong solutions from Corollary 3.11, and assume that

Hence $\nabla(u_1-u_2)(x_0) = 0$ and $(-\Delta)^{s}(u_2-u_1)(x_0) < 0$, so we have the contradiction

4.   Equivalence between distributional and viscosity solutions

In this section, we investigate the relation between distributional solutions and viscosity solutions. Let us recall that according to Theorem 3.1 and Corollary 3.11, to obtain strong solutions to (1.1) it is sufficient that $f \in \mathcal{C}^{\epsilon}(\Omega)$ and that

or

for $\lambda ^*$ defined in Theorem 3.9. In this section we show that strong solutions to (1.1) are viscosity solutions. The converse is also true provided a comparison principle for viscosity solutions. We prove it in the next subsection.

4.1.   A comparison principle for viscosity solutions

We prove a comparison result for viscosity solutions of problem (1.1). This result requires a continuous source term $f$.

In order to state the result, we shall need some technical lemmas that could have interest by themselves. For related results see ^[22].

We start with a usual property for the fractional Laplacian of smooth functions. See [21,Lemma 2.6] for the proof.

Lemma 4.1. Let $B_\epsilon(x)\subset U \Subset\Omega$ and let $u \in \mathcal{C}^{2}(U)$. Then:

where $c_\epsilon$ is independent of $x$ and $c_\epsilon \to 0$ as $\epsilon \to 0$.

Observe that in the definition of viscosity solutions, we do not evaluate the given equation in the solution $u$. However, the following lemma states an extra information when $u$ is touched from below or above by $C^{2}$-test functions.

Lemma 4.2. Let $u$ be a viscosity supersolution to (1.1) and suppose that there exists $\phi \in C^{2}(U)$, $U \Subset \Omega$, touching $u$ from below at $x_0 \in U$. Then $(-\Delta)^{s}u(x_0)$ is finite and moreover:

A similar result holds for subsolutions.

Proof. We assume that $x_0 = 0$ and $u(0) = 0$. For $r > 0$ so that $B_r : = B(0, r)\subset U$, define:

Hence for all $0 < \rho < r$

where we have used that $\phi$ touches $u$ from below. As $\rho \to 0$, the last integral converges since $\phi \in \mathcal{C}^{2}(B_r)$. Hence

where

Also, from the fact that $u$ is a supersolution, we have $u \geq 0$ in $\mathbb{R}^{N}\setminus \Omega$. Thus

Since $u \in LSC(\overline{\Omega})$, there is a constant $m$ so that

Hence from (4.3), it follows

This fact, together with (4.2), imply that $(-\Delta)^{s}u(0) \in [-\infty, \infty)$.

We now prove the estimate (4.1), and consequently that $(-\Delta)^{s}u(0)$ is finite. For $\rho > 0$, we have by Lemma 4.1 that

choosing $r$ small enough. Hence

By letting $r \to 0$, and then $\rho\to 0$, we derive (4.1).

We now give the main result of this section.

Theorem 4.3 (Comparison principle for viscosity solutions). Assume that $f \in \mathcal{C}(\Omega)$. Let $v \in USC(\overline{\Omega})$ be a subsolution and $u\in LSC(\overline{\Omega})$ be a supersolution, respectively, of (1.1). Then $v \leq u$ in $\Omega$.

Proof. We argue by contradiction. Assume that there is $x_0 \in \Omega$ so that:

As usual, we double the variables and consider for $\epsilon > 0$ the function

By the upper semi continuity of $v$ and $-u$, there exist $x_\epsilon$ and $y_\epsilon$ in $\overline{\Omega}$ so that

By compactness, $x_\epsilon \to \overline{x}$ and $y_\epsilon \to \overline{y}$, up to subsequence that we do not re-label. From

and the upper boundedness of $v$ and $-u$ in $\overline{\Omega}$, we derive

hence $\overline{x} = \overline{y}$. Moreover

implies that:

As a consequence, by letting $\epsilon \to 0$ in (4.4) and using the semicontinuity of $u$ and $v$, we obtain

Also, observe that $\overline{x} \in \Omega$, because otherwise there is a contraction with $v \leq u$ in $\mathbb{R}^{N}\setminus\Omega$.

Define the $\mathcal{C}^2$ test functions

Then $\phi_\epsilon$ touches $v$ from above at $x_\epsilon$ and $\psi_\epsilon$ touches $u$ from below at $y_\epsilon$. By Lemma 4.2, we have

and

Therefore:

Since $f \in \mathcal{C}(\Omega)$ and

we have that the right hand side in (4.6) tends to $0$ as $\epsilon \to 0$. Thus, we obtain

Let $A_{1, \epsilon}: = \{z \in \mathbb{R}^{N}: x_\epsilon + z, y_\epsilon +z \in \Omega\}$. Hence for $z \in A_{1, \epsilon}$, we have from the inequality

that

Define $A_{2, \epsilon}: = \mathbb{R}^{N}\setminus A_{1, \epsilon}$. We will justify that we are allowed to use Fatou's Theorem in

by showing that the integrand is bounded from below by an $L^{1}$ function. Firstly, let $r > 0$ so that $B_{3r}(\overline{x}) \subset \Omega$ and take $\epsilon_0$ small enough such that $x_\epsilon, y_\epsilon \in B_r(\overline{x})$ for all $\epsilon < \epsilon_0$. Take $z \in A_{2, \epsilon}$. We show now that $|z|\geq 2r$. Indeed, to reach a contradiction, assume that $|z| < 2r$. Since $z \notin A_{1, \epsilon}$, it follows that $x_\epsilon + z$ or $y_\epsilon + z$ does not belong to $\Omega$. Without loss of generality, assume $x_\epsilon +z \notin \Omega$. Hence

and so $x_\epsilon+ z \in B_{3r}(\overline{x}) \subset \Omega$ which is a contradiction. Next, notice that

Hence, using that $z \notin B_{2r}$ when $z \in A_{2, \epsilon}$, we have

On the other hand

Since $v$ is a subsolution, we have $v \leq 0$ in $\mathbb{R}^{N}\setminus \Omega$. Hence

Observe that the last integral is finite since $v \in L^{1}_{loc}(\mathbb{R}^{N})$ by definition. In this way, recalling (4.10), the term

is bounded from below by an $L^{1}$-integrable function. A similar result follows for

Hence, we may use Fatou Lemma in (4.9) and derive

Here $A_{\overline{x}}: = \{z\in \mathbb{R}^{N}: \overline{x}+z \in \Omega\}$ and we have used the a.e. pointwise convergence of $\chi_{A_{2, \epsilon}}$ to $\chi_{A_{\overline{x}}}$, [9,Lemma 4.3] together with a diagonal argument to conclude for a subsequence

for a.e. $z \in \mathbb{R}^{N}$. Moreover, the inequality $u \geq v$ in $\mathbb{R}^{N}\setminus \Omega$ implies that the last integral in (4.11) is non-negative. Then

Therefore by Fatou Lemma, (4.12) and (4.7), we deduce

Hence

almost everywhere in $A_{1, \epsilon}$. In particular for $z \in A_{\overline{x}}$. We then have by the lower semicontinuity of $-v$ and $u$ in $\overline{\Omega}$ and (4.5), that

Since $z \in A_{\overline{x}}$ is arbitrary, we conclude $\sigma \leq v(x)-u(x)$ for a.e. in $\overline{\Omega}$, which implies for $x \in \partial \Omega$

A contradiction with the hypothesis.

4.2.   Equivalence between strong and viscosity solutions

In this subsection we prove that strong and viscosity solutions coincide.

Theorem 4.4. Any strong solution $u \in \mathcal{C}^{1, \alpha}(\Omega)$ to problem (1.1) is a viscosity solution as well.

Remark 4.5. For conditions to ensure the existence of strong solutions to problem (1.1) see Theorem 3.1, Theorem 3.9 and Corollary 3.11.

Proof. The proof is straightforward, we give it by completeness. Let $u \in \mathcal{C}^{1, \alpha}(\Omega)$ be such that

Let $U \subset \Omega$ be open, take $x_0 \in U$ and let $\phi \in \mathcal{C}^{2}(U)$ be such that $u(x_0) = \phi(x_0)$ and $\phi \geq u$ in $U$. Define

Hence, since $u$ is $\mathcal{C}^{1}$, $\nabla u(x_0) = \nabla \phi(x_0)$ and then we have that

By the assumption on $\phi$, we have that $(-\Delta)^{s}\phi(x_0) \leq (-\Delta)^{s}u(x_0)$ and so the $u$ is a viscosity sub-solution. In a similar way, $u$ is a super-solution and the conclusion follows.

Theorem 4.6. Assume that the condition (3.15) holds that $f \in \mathcal{C}^{\epsilon}(\Omega)\cap L^m(\Omega)$, for some $\epsilon > 0$ and $m > \frac{N}{2s-1}$. We suppose that $||f||_{L^m(\Omega)}\le \lambda ^*$ defined in Theorem 3.9. Then any viscosity solution is a strong solution.

Proof. To prove the converse, assume that $u$ is a viscosity solution to problem (1.1). In view of Theorem 3.9 and Corollary 3.11, there exists a distributional solution $v$ (which is also strong in view of the assumptions on $f$). Since any strong solution is of viscosity, we consequently infer from the Comparison Theorem 4.3 that $u = v$. This ends the proof of the theorem.

5.   Some open problems

$(1)$ For the existence of solution using approximating argument, the limitation $p < 2s$ seems to be technical, we hope that the existence of a solution holds for all $p\le 2s$ and for all $f\in L^1(\Omega)$. For $p > 2s$, this is an interesting open question, even for the Laplacian, with $L^m$ data. Notice that this is not the framework of the paper ^[23].

$(2)$ For $p > 2s$, it seems to be interesting to eliminate the smallness condition $||f||_{L^m(\Omega)}$ and to treat more general set of $p$ without the condition (3.15).

$(3)$ In order to understand a bigger class of linear integro-differential operators, is seems necessary to obtain alternative techniques independent of the representation formula.

Acknowledgments

The first and the third authors are partially supported by Project MTM2016-80474-P, MINECO, Spain. The first author also is partially supported by DGRSDT, Algeria and an Erasmus grant from Autonoma University of Madrid. The second author is partially supported by CONICET and grant PICT 2015-1701 AGENCIA.

The authors would like to thank the anonymous reviewer for his$/$her careful reading of the paper and his$/$her many insightful comments and suggestions.

Conflict of interest

The authors declare no conflict of interest.