This work deals with the construction and analysis of convexity and nabla positivity for discrete fractional models that includes singular (exponential) kernel. The discrete fractional differences are considered in the sense of Riemann and Liouville, and the υ1-monotonicity formula is employed as our initial result to obtain the mixed order and composite results. The nabla positivity is discussed in detail for increasing discrete operators. Moreover, two examples with the specific values of the orders and starting points are considered to demonstrate the applicability and accuracy of our main results.
Citation: Pshtiwan Othman Mohammed, Hari Mohan Srivastava, Sarkhel Akbar Mahmood, Kamsing Nonlaopon, Khadijah M. Abualnaja, Y. S. Hamed. Positivity and monotonicity results for discrete fractional operators involving the exponential kernel[J]. Mathematical Biosciences and Engineering, 2022, 19(5): 5120-5133. doi: 10.3934/mbe.2022239
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This work deals with the construction and analysis of convexity and nabla positivity for discrete fractional models that includes singular (exponential) kernel. The discrete fractional differences are considered in the sense of Riemann and Liouville, and the υ1-monotonicity formula is employed as our initial result to obtain the mixed order and composite results. The nabla positivity is discussed in detail for increasing discrete operators. Moreover, two examples with the specific values of the orders and starting points are considered to demonstrate the applicability and accuracy of our main results.
Discrete fractional calculus is of central importance in many fields of research and monotonicity analysis. In the past few decades, studies of discrete fractional operators have attracted significant attention in different fields of pure mathematics such as stability analysis, mathematical modelling, and topological spaces, see [1,2,3,4,5], and applied mathematics such as bioscience, numerical analysis, statistics, the system of difference equations, and calculus of variations, see [6,7,8,9,10] for more details.
Analyzing the discrete fractional operators for monotonicity and positivity is one of the most interesting studies in the discrete analysis. Various studies have dealt with this issue in discrete fractional calculus. There are certain limitations that researchers have shown [11,12,13,14].
On the other hand, a common strategy for analysing discrete fractional operators is simplifying their summations by using the forward difference operator (Δy)(x)=y(x+1)−y(x) or backward difference operator (∇y)(x)=y(x)−y(x−1), which reduces the components of the summations to zero. Monotonicity and positivity analyses have been found for different discrete fractional difference operators, such as nabla/delta Riemann-Liouville and Caputo fractional differences [15,16,17,18], nabla/delta Caputo-Fabrizio fractional differences involving exponential kernels [19,20], nabla/delta Atangana-Baleanu fractional differences involving Mittag-Leffler kernels [21,22,23,24].
In addition, several studies have examined the monotonicity and positivity for various fractional difference operators of mixed order, including Caputo-Fabrizio fractional differences involving exponential kernels [25,26,27], Atangana-Baleanu fractional differences involving Mittag-Leffler kernels [28]. Most of these studies have used one or two initial conditions to compute other positivity and monotonicity of the functions.
Motivated by those researches and results, we are interested in two types of results in the present study:
● Monotonicity-type results for variation operators of discrete nabla fractional differences with exponential kernels and their commutators on the time scale Nt0;
● Delta positivity results for the single operator and mixed operators of discrete nabla fractional differences with exponential kernels on the time scale Nt0 via two basic lemmas.
The rest of this paper is composed of the following sections: The first section (Section 2) includes two basic definitions of discrete fractional calculus, which we will use in our work. The next section (Section 3) includes our main results, which are separated into two subsections: In the first subsection (Subsection 3.1), we will prove some auxiliary lemmas, including the discrete operators, which we will use them in proving other results in the second subsection (Subsection 3.2). We will complete our article by summarizing our results and providing the future directions for the interested reader in Section 4.
We first give the definitions of discrete nabla Caputo-Fabrizio of Caputo-type and Caputo-Fabrizio of Riemann-type fractional differences with discrete exponential function kernels.
Definition 2.1. [2,19] For any function y defined on Nt0 the discrete nabla Caputo-Fabrizio of Riemann-type and Caputo-Fabrizio of Riemann-type fractional differences are defined, respectively, as follows:
(CFCt0∇υ1y)(x)=Λ(υ1)[x∑z=t0+1(∇zy)(z)(1−υ1)x−z] | (2.1) |
and
(CFRt0∇υ1y)(x)=Λ(υ1)∇x[x∑z=t0+1y(z)(1−υ1)x−z] | (2.2) |
for all υ1∈(0,1),t0∈R, and x in Nt0+1, where Λ(υ1) denotes a normalizing positive constant.
Definition 2.2. [29] The nth order discrete nabla Caputo-Fabrizio of Caputo-type and Caputo-Fabrizio of Riemann-type fractional differences can be expressed, respectively, as follows:
(CFCt0∇υ1y)(x)=(CFRt0∇υ1−M∇My)(x)=Λ(υ1−M)[x∑z=t0+1(∇M+1zy)(z)(M+1−υ1)x−z] | (2.3) |
and
(CFRt0∇υ1y)(x)=(CFRt0∇υ1−M∇My)(x)=Λ(υ1−M)∇x[x∑z=t0+1(∇Mzy)(z)(M+1−υ1)x−z] | (2.4) |
for all x in Na+M and υ1∈(M,M+1].
Remark 2.1. Throughout the rest of this paper, for ℓ1>ℓ2, we consider the classical convention that
ℓ2∑z=ℓ1Bz:=0. |
In this section, we mainly give some preliminaries and do the analysis of discrete operators. Hereafter, for any function y defined on Nt0 and satisfying y(t0)⩾0 the υ1-monotonicity increasing function on Nt0 can satisfy y(x+1)⩾υ1y(x), and the υ1-monotonicity decreasing function on Nt0 can satisfy y(x+1)⩽υ1y(x) for all x in Nt0. This section is separated into two subsections.
In this subsection, we will present the analyses of the υ1-monotonicity for the aforementioned discrete operators.
Lemma 3.1. Assume that a function y:Nt0→R satisfies y(t0)⩾0 and
(CFRt0−1∇υ1y)(x)⩾0 | (3.1) |
for υ1∈(0,1) and x in Nt0+1. Then, y(x) is positive and υ1–monotone increasing on Nt0.
Proof. In view of Definition 2.1, one can have for all x∈Nt0+1:
(CFRt0−1∇υ1y)(x)=Λ(υ1)∇x[x∑z=t0y(z)(1−υ1)x−z]=Λ(υ1)[x∑z=t0y(z)(1−υ1)x−z−x−1∑z=t0y(z)(1−υ1)x−z−1]=Λ(υ1)[y(x)−υ1x−1∑z=t0y(z)(1−υ1)x−z−1]=Λ(υ1)[y(x)−υ1(1−υ1)x−t0−1y(t0)−υ1x−1∑z=t0+1y(z)(1−υ1)x−z−1]. | (3.2) |
Since Λ(υ1)>0 and (CFRt0−1∇υ1y)(x)⩾0 by assumption, then we can express (3.2) as follows
y(x)⩾υ1(1−υ1)x−t0−1y(t0)+υ1x−1∑z=t0+1y(z)(1−υ1)x−z−1. | (3.3) |
For x=t0+1 and by assumption, then (3.3) gives
y(t0+1)⩾υ1y(t0)⩾0. |
For x=t0+2 and by assumption and the above result, then (3.3) leads to
y(t0+2)⩾υ1(1−υ1)y(t0)+υ1y(t0+1)⩾0. |
We can proceed in the same way to get y(x)⩾0 for each x∈Nt0.
To do the proof of the υ1–monotonicity increasing of y, we reuse (3.3) in the form:
y(x)⩾υ1y(x−1)+υ1(1−υ1)x−t0−1y(t0)+υ1x−2∑z=t0+1y(z)(1−υ1)x−z−1. | (3.4) |
We just proved that y(x)⩾0 for each x∈Nt0, and υ1∈(0,1),y(t0)⩾0 by assumption and (1−υ1)x−t0−1>0 for each x∈Nt0+1. So, we can deduce from (3.4) that
y(x)⩾υ1y(x−1)forallx∈Nt0+1, |
and this gives the υ1–monotonicity increasing of y on Nt0. Thus, our results are shown.
Our second and third main results regarding sequential operators depend on the above lemma as follows. For further details on the main concepts of sequential operators, one may read [30].
Theorem 3.1. Assume that a function y:Nt0→R satisfies y(t0+1)⩾y(t0)⩾0 and
(CFRt0∇υ2CFRt0−1∇υ1y)(x)⩾0 | (3.5) |
for υ1,υ2∈(0,1) with 0<υ1+υ2⩽1 and x in Nt0+2. Then, y(x) is positive and (υ1+υ2)–monotone increasing on Nt0.
Proof. Let us denote for x∈Nt0+1:
(CFRt0∇υ1y)(x):=y2(x). |
This enables us to write
(CFRt0∇υ2CFRt0−1∇υ1y)(x)=(CFRt0∇υ2y2)(x). |
Since y(t0+1)⩾y(t0)⩾0, (CFRt0+1∇υ2y2)(x)⩾0 for each x∈Nt0+2 by assumption, and
y2(t0+1)=(CFRt0∇υ1y)(t0+1)=Λ(υ1)(∇zy)(t0+1)⩾0, |
by Definition 2.1, we can deduce that y2 is positive and υ2–monotone increasing on Nt0+1 by Lemma 3.1. That is,
y2(x)⩾0forallx∈Nt0+1, |
and
y2(x)⩾υ2y2(x−1)forallx∈Nt0+2. | (3.6) |
Now, by our claim, we see that
(CFRt0∇υ1y)(x)=y2(x)⩾0 |
for all x∈Nt0+1, and since y(t0)⩾0 by assumption, then Lemma 3.1 guarantees that y is positive and υ1–monotone increasing on Nt0. That is,
y(x)⩾0forallx∈Nt0, | (3.7) |
and
y(x)⩾υ1y(x−1)forallx∈Nt0+1. | (3.8) |
To prove the rest of the theorem, we need to have
y(x)⩾(υ1+υ2)y(x−1)forallx∈Nt0+1. | (3.9) |
First, we see that (3.9) is true for x=t0+1 as follows:
y(t0+1)⩾(υ1+υ2)y(t0+1)⩾(υ1+υ2)y(t0), | (3.10) |
since 0<υ1+υ2⩽1.
By using (3.6) in (3.2) by replacing t0−1 with t0, we get for all x∈Nt0+2:
0⩽y2(x)−υ2y2(x−1)=(CFRt0∇υ1y)(x)−υ2(CFRt0∇υ1y)(x−1)=Λ(υ1)[y(x)−υ1(1−υ1)x−t0y(t0+1)−υ1x−1∑z=t0+2y(z)(1−υ1)x−z−1]−υ2Λ(υ1)[y(x−1)−υ1(1−υ1)x−t0−1y(t0+1)−υ1x−2∑z=t0+2y(z)(1−υ1)x−z−2]=Λ(υ1)[(y(x)−υ2y(x−1))−υ1(1−υ1−υ2)(1−υ1)x−t0−1y(t0+1)−υ1y(x−1)−υ1(1−υ1−υ2)x−2∑z=t0+2y(z)(1−υ1)x−z−2]. | (3.11) |
Since Λ(υ1)>0, it follows from (3.11) that
y(x)−(υ1+υ2)y(x−1)⩾υ1(1−υ1−υ2)⏟⩾0(1−υ1)x−t0−1⏟>0y(t0+1)⏟⩾0+υ1(1−υ1−υ2)⏟⩾0x−2∑z=t0+2y(z)⏟⩾0by(3.7)(1−υ1)x−z−2⏟>0, | (3.12) |
which together with (3.12) rearrange to y(x)⩾(υ1+υ2)y(x−1) for each x∈Nt0+1, as desired.
Corollary 3.1. Assume that a function y:Nt0→R satisfies y(t0+1)⩾y(t0)⩾0 and
(CFRt0∇υ2CFRt0−1∇υ1y)(x)⩾0 | (3.13) |
for υ1,υ2∈(0,1) and x in Nt0+2. Then, y is positive and υ1–monotone increasing on Nt0. Moreover, if 0<υ1+υ2⩽1, then y is υ2–monotone strictly increasing on Nt0.
Proof. It is evidence from (3.7) and (3.8) that y is positive and υ1–monotone increasing on Nt0. Now, if 0<υ1+υ2⩽1, then by using Theorem 3.1, we have that y is υ1+υ2–monotone increasing on Nt0. Hence,
y(x)⩾(υ1+υ2)y(x−1)>υ2y(x−1), |
for each x∈Nt0+1. This implies that y is υ2–monotone strictly increasing on Nt0. Hence the proof is done.
Example 3.1. Considering the definition of Caputo-Fabrizio of Riemann-type fractional difference (2.2), we have
(CFRt0+1∇υ1CFRt0∇υ2y)(x)=Λ(υ1)∇xx∑z=t0+2(CFRt0∇υ2y)(z)(1−υ1)x−z | (3.14) |
for υ1,υ2∈(0,1) and x∈Nt0+1.
The chosen t0=1 and x=t0+2 leads to
(CFR1∇υ1CFR0∇υ2y)(3)=Λ(υ1){3∑z=2(CFR0∇υ2y)(z)(1−υ1)3−z−2∑z=1(CFR0∇υ2y)(z)(1−υ1)2−z}=Λ(υ1){(1−υ1)(CFR0∇υ2y)(2)+(CFR0∇υ2y)(3)−(CFR0∇υ2y)(2)}=Λ(υ1){(CFR0∇υ2y)(3)−υ1(CFR0∇υ2y)(2)}. | (3.15) |
For the chosen y1=0.005,y2=0.01,y3=0.05, υ1=0.25 and υ2=0.25, we have
(CFR0∇υ2y)(3)=Λ(υ2)∇3∑z=1y(z)(1−υ2)3−z=Λ(υ2){3∑z=1y(z)(1−υ2)3−z−2∑z=1y(z)(1−υ2)2−z}=Λ(0.25){y(3)−υ2y(2)−υ2(1−υ2)y(1)}=0.0466Λ(0.25), | (3.16) |
and similarly,
(CFR0∇υ2y)(2)=Λ(υ2)∇2∑z=1y(z)(1−υ2)2−z=Λ(0.25){y(2)−υ2y(1)}=0.0088Λ(0.25). | (3.17) |
Substituting (3.16) and (3.17) into (3.15) for υ1=υ2=0.5, we get
(CFR1∇14CFR0∇14y)(3)=Λ(0.25){(CFR0∇14y)(3)−14(CFR0∇14y)(2)}=Λ2(0.25){0.0466+0.00884}=0.0444Λ2(0.25)>0. |
Also, it is clear that y(2)>y(1). Thus, we find that y is positive and 12–monotone increasing on N1 by Theorem 3.1.
In this section, we first prove two essential lemmas for which we need a new nabla condition. Then, we will extend the result obtained to the above Caputo-Fabrizio of Riemann-type operators via a Caputo-Fabrizio of Riemann-type operator of another Caputo-Fabrizio of Riemann-type operator with two different starting points.
Lemma 3.2. Assume that a function y:Nt0→R satisfies y(t0+1)⩾y(t0)⩾0 and
∇(CFRt0−1∇υ1y)(x)⩾0 | (3.18) |
for υ1∈(0,1) and x in Nt0+2. Then, (∇y)(x)⩾0 for all x in Nt0+1.
Proof. We will proceed by using (3.2):
∇x(CFRt0−1∇υ1y)(x)=Λ(υ1)∇x[y(x)−υ1x−1∑z=t0y(z)(1−υ1)x−z−1]=Λ(υ1)[(∇y)(x)−υ1x−1∑z=t0y(z)(1−υ1)x−z−1+υ1x−2∑z=t0y(z)(1−υ1)x−z−2]=Λ(υ1)[(∇y)(x)−υ1y(t0)(1−υ1)x−t0−1−υ1x−1∑z=t0+1y(z)(1−υ1)x−z−1+υ1x−1∑z=t0+1y(z−1)(1−υ1)x−z−1]=Λ(υ1)[(∇y)(x)−υ1y(t0)(1−υ1)x−t0−1−υ1x−1∑z=t0+1(∇y)(z)(1−υ1)x−z−1], | (3.19) |
for all x∈Nt0+2. Since Λ(υ1)>0 and ∇(CFRt0−1∇υ1y)(x)⩾0, for all x∈Nt0+2, from (3.19) we get
(∇y)(x)⩾υ1y(t0)(1−υ1)x−t0−1+υ1x−1∑z=t0+1(∇y)(z)(1−υ1)x−z−1. | (3.20) |
We will proceed by induction to complete the proof. We know from the assumption that (∇y)(t0+1)⩾0. Assume that (∇y)(t0+k)⩾0 for some k∈N1. Then, we need to show that (∇y)(t0+k+1)⩾0. By using (3.20) at x=t0+k+1, and our claim, we have
(∇y)(t0+k+1)⩾υ1y(t0)(1−υ1)k⏟⩾0+υ1a+k∑z=t0+1(∇y)(z)⏟⩾0(1−υ1)a+k−z⏟>0⏟⩾0⩾0, |
which rearranges to the required proof.
Lemma 3.3. Assume that a function y:Nt0→R satisfies (∇y)(t0+1)⩾0 and
(CFRt0∇υ1∇y)(x)⩾0 | (3.21) |
for υ1∈(0,1) and x in Nt0+2. Then, (∇y)(x)⩾0 for all x in Nt0+1.
Proof. By replacing t0−1 with t0, and y with (∇y) in (3.2), we get for all x∈Nt0+2:
(CFRt0∇υ1∇y)(x)=Λ(υ1)[(∇y)(x)−υ1x−1∑z=t0+1(∇y)(z)(1−υ1)x−z−1]=Λ(υ1)[(∇y)(x)−υ1(1−υ1)x−t0−2(∇y)(t0+1)−υ1x−1∑z=t0+2(∇y)(z)(1−υ1)x−z−1]. | (3.22) |
Since Λ(υ1)>0 and (CFRt0∇υ1∇y)(x)⩾0 for all x∈Nt0+2, then (3.22) can give us
(∇y)(x)⩾υ1(1−υ1)x−t0−2(∇y)(t0+1)+υ1x−1∑z=t0+2(∇y)(z)(1−υ1)x−z−1. | (3.23) |
Again, by induction we will show that (∇y)(t0+k+1)⩾0, where we assumed that (∇y)(t0+k)⩾0 for some k∈N1. From assumption, we have that (∇y)(t0+1)⩾0. But then from the lower bound for (∇y)(t0+k+1) in (3.23) and our claim, we have
(∇y)(t0+k+1)⩾υ1(1−υ1)k−1(∇y)(t0+1)⏟⩾0+υ1a+k∑z=t0+2(∇y)(z)(1−υ1)a+k−z⏟⩾0⏟⩾0⩾0, |
which completes the proof.
Next, we apply the lemmas so far obtained to prove a couple of results in the sequential setting for the discrete Caputo-Fabrizio of Riemann-type fractional operators perturbed by two different starting points.
Theorem 3.2. Assume that a function y:Nt0→R satisfies (∇y)(t0+2)⩾(∇y)(t0+1)⩾υ1y(t0)⩾0 and
(CFRt0+1∇υ2CFRt0−1∇υ1y)(x)⩾0 | (3.24) |
for υ1∈(0,1),υ2∈(1,2) and x in Nt0+3. Then, (∇y)(x)⩾0 for all x in Nt0+1.
Proof. Let us denote
(CFRt0−1∇υ1y)(x):=y2(x) |
for all x∈Nt0+1.Then, by using Definition 2.2 with n=2, we see that
(CFRt0+1∇υ2CFRt0−1∇υ1y)(x)=(CFRt0+1∇υ2−1∇CFRt0−1∇υ1y)(x)=(CFRt0+1∇υ2−1∇y2)(x). |
We know by assumption that (CFRt0+2∇υ2−1∇y2)(x)⩾0, for every x∈Nt0+3. Then, (3.11) helps us to write
(∇y2)(t0+2)=(∇CFRt0−1∇υ1y)(t0+2)=Λ(υ1)[(∇y)(t0+2)−υ1(∇y)(t0+1)−υ1(1−υ1)y(t0)]=Λ(υ1)[(∇y)(t0+2)−υ1(y(t0+1)−υ1y(t0))]⏟⩾0byassumption⩾0. | (3.25) |
Therefore, it follows from Lemma 3.3 that
(∇y2)(x)=(∇CFRt0−1∇υ1y)(x)⩾0 |
for all x∈Nt0+2. Also, we know that (∇y)(t0+1)⩾0, then by Lemma 3.2 we deduce that (∇y)(x)⩾0 for all x∈Nt0+1. This completes the proof.
Theorem 3.3. Assume that a function y:Nt0→R satisfies (∇y)(t0+2)⩾(∇y)(t0+1)⩾0 and
(CFRt0+1∇υ2CFRt0∇υ1y)(x)⩾0 | (3.26) |
for υ1∈(1,2),υ2∈(0,1) and x in Nt0+3. Then, (∇y)(x)⩾0 for all x in Nt0+1.
Proof. Let us denote
(CFRt0+1∇υ1y)(x):=(∇y2)(x) |
for all x∈Nt0+2. Hence,
(CFRt0+1∇υ2CFRt0∇υ1y)(x)=(CFRt0+1∇υ2∇y2)(x). |
Since we have (CFRt0+1∇υ2∇y2)(x)⩾0, for every x∈Nt0+3 by assumption, and from (3.11), we have
(∇y2)(t0+2)=(CFRt0+1∇υ1y)(t0+2)=(CFRt0+1∇υ1−1∇y)(t0+2)=Λ(υ1−1)[(∇y)(t0+2)−(υ1−1)(∇y)(t0+1)]⏟⩾0byassumption⩾0, | (3.27) |
where we have used that (∇y)(t0+2)⩾(∇y)(t0+1⩾(υ1−1)(∇y)(t0+1). Then, from Lemma 3 we get
(∇y2)(x)=(CFRt0+1∇υ1y)(x)⩾0 |
for all x∈Nt0+2. That is,
0⩽(CFRt0+1∇υ1y)(x)=(CFRt0+1∇υ1−1∇y)(x) |
for all x∈Nt0+2. Meanwhile, (∇y)(t0+1)⩾0, so Lemma 3.3 confirms that (∇y)(x)⩾0 for each x∈Nt0+1. Hence, the proof is complete.
We conclude by presenting a concrete example of a possible Caputo-Fabrizio of Riemann-type fractional difference problem that can be considered.
Example 3.2. Considering the definition of Caputo-Fabrizio of Riemann-type fractional difference (2.2), we have
(CFRt0+1∇υ1CFRt0∇υ2y)(x)=Λ(υ1)∇xx∑z=t0+2(CFRt0∇υ2y)(z)(1−υ1)x−z | (3.28) |
for υ1∈(0,1),υ2∈(1,2) and x∈Nt0+1.
The chosen t0=0 and x=t0+3 leads to
(CFR1∇υ1CFR0∇υ2y)(3)=Λ(υ1){3∑z=2(CFR0∇υ2y)(z)(1−υ1)3−z−2∑z=1(CFR0∇υ2y)(z)(1−υ1)2−z}=Λ(υ1){(1−υ1)(CFR0∇υ2y)(2)+(CFR0∇υ2y)(3)−(CFR0∇υ2y)(2)}=Λ(υ1){(CFR0∇υ2y)(3)−υ1(CFR0∇υ2y)(2)}. | (3.29) |
Calculating the inside terms for the chosen y0=0.001,y1=1.001,y2=1.01,y3=1.05, υ1=0.5 and υ2=1.5, we have
(CFR0∇υ2y)(3)=(CFR0∇υ2−1∇y)(3)=Λ(υ2−1)∇3∑z=1(∇y)(z)(2−υ2)3−z=Λ(υ2−1){3∑z=1(∇y)(z)(2−υ2)3−z−2∑z=1(∇y)(z)(2−υ2)2−z}=Λ(0.5){(∇y)(3)+(1−υ2)(∇y)(2)+(2−υ2)(1−υ2)(∇y)(1)}=−0.2145Λ(0.5), | (3.30) |
and similarly,
(CFR0∇υ2y)(2)=(CFR0∇υ2−1∇y)(2)=Λ(υ2−1)∇2∑z=1(∇y)(z)(2−υ2)2−z=Λ(0.5){(∇y)(2)+(1−υ2)(∇y)(1)}=−0.4910Λ(0.5). | (3.31) |
Substituting (3.30) and (3.31) into (3.29) for υ1=0.5 and υ2=1.5, we get
(CFR1∇12CFR0∇32y)(3)=Λ(0.5){(CFR0∇32y)(3)−12(CFR0∇32y)(2)}=Λ2(0.5){−0.2145+0.49102}=0.0310Λ2(0.5)>0. |
Therefore, we conclude that (∇y)(3)⩾0 by Theorem 3.3.
The conclusion of our results are as follows:
● The main result has been proved in Lemma 3.1. This lemma has shown that the function is positive and υ1-monotone increasing at the same time.
● Lemma 3.1 helped us to obtain the (υ1+υ2)-monotonicity and υ2-monotonicity of the composite discrete operators with different orders.
● Two positivity results have been proved in the next section. The first lemma considered the nabla of a discrete Caputo-Fabrizio of Riemann-type fractional difference. The other one considered the discrete Caputo-Fabrizio of Riemann-type fractional difference of a nabla function. Those both lemmas gave a nabla positivity result.
● Lemmas 3.2 and 3.3 enabled us to get the nabla positivity of the composite discrete operators with different orders.
● Examples 3.1 and 3.2 confirmed the applicability and validity of the main results on positivity.
As we know, one- and multi-parameter discrete Mittag-Liffler functions have been determined for some initial values in the references [21,22,23,24]. These basic results together with the results presented in this study, it will be helpful for the interested researchers to modify and extend our present results and obtain new results for the discrete fractional operators with non-singular (Mittag-Liffler) kernels.
This Research was supported by Taif University Researchers Supporting Project Number(TURSP-2020/217), Taif University, Taif, Saudi Arabia and the National Science, Research, and Innovation Fund (NSRF), Thailand.
The authors declare there is no conflict of interest.
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1. | Pshtiwan Othman Mohammed, Hari Mohan Srivastava, Dumitru Baleanu, Ehab E. Elattar, Y. S. Hamed, Positivity analysis for the discrete delta fractional differences of the Riemann-Liouville and Liouville-Caputo types, 2022, 30, 2688-1594, 3058, 10.3934/era.2022155 |