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Research article

Noble-Abel gas diffusion at convex corners of the two-dimensional compressible magnetohydrodynamic system

  • Received: 11 June 2024 Revised: 30 July 2024 Accepted: 05 August 2024 Published: 09 August 2024
  • MSC : 35A01, 76N25

  • In this paper, we study the expansion of Noble-Abel gas into a vacuum around the convex corner of the two-dimensional compressible magnetohydrodynamic system. We reduce this problem to the interaction of a centered simple wave emanating from the convex corner with a backward planar simple wave. Mathematically, this is a Goursat problem. By using the method of characteristic decomposition and construction of invariant regions, combining C0 and C1 estimation as well as hyperbolicity estimation, we obtain the existence of a global classical solution by extending the local classical solution.

    Citation: Fei Zhu. Noble-Abel gas diffusion at convex corners of the two-dimensional compressible magnetohydrodynamic system[J]. AIMS Mathematics, 2024, 9(9): 23786-23811. doi: 10.3934/math.20241156

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  • In this paper, we study the expansion of Noble-Abel gas into a vacuum around the convex corner of the two-dimensional compressible magnetohydrodynamic system. We reduce this problem to the interaction of a centered simple wave emanating from the convex corner with a backward planar simple wave. Mathematically, this is a Goursat problem. By using the method of characteristic decomposition and construction of invariant regions, combining C0 and C1 estimation as well as hyperbolicity estimation, we obtain the existence of a global classical solution by extending the local classical solution.



    A large number of fluids exist in nature. Neglecting viscosity and heat transfer, some fluids in nature can be viewed as ideal fluids [1,2,3,4]. The study of ideal fluid flow around a convex corner can be traced back to 1948, as proposed by Courant and Friedrichs[5]. They discovered the existence of a solution for this problem. Subsequently, Sheng and You[6] studied the problem of diffusion of the pseudo-steady supersonic flow of the polytropic gas into a vacuum at a convex corner and obtained the existence of a solution. Sheng and Yao[7] studied the problem of two-dimensional pseudo-steady isentropic irrotational supersonic flow of the polytropic gas around a convex corner. They obtained the structure of non-completely centered simple wave solutions. In 2023, Chen, Shen, and Yin[8] studied the problem of supersonic diffusion of a non-ideal gas around a convex corner into the vacuum. They proved the existence of classical solutions in the region of interaction between planar and centered simple waves. Li and Sheng[9] studied the expansion of the Van der Waals gas into the vacuum around a convex corner. The problem is studied in terms of the interaction of a completely centered simple wave with a backward planar simple wave and an incompletely centered simple wave with a backward planar simple wave. They constructively obtained the global existence of solutions to the gas expansion problem. For other studies on the convex corner winding problem, we refer to [10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25].

    Since magnetic fields may affect fluids during flow, it is natural to consider compressible magnetohydrodynamic equations. There have been some results in recent years about the flow of an ideal magnetic fluid around a convex corner. In 2020, Chen, Yin, and You[26] investigated the two-dimensional pseudo-steady compressible magnetohydrodynamic equations for the polytropic gas expansion into the vacuum at the convex corner. They obtained a classical solution for interacting with centered and planar simple waves.

    The two-dimensional isentropic compressible magnetohydrodynamic equations can be written as

    {ρt+(ρu)x+(ρv)y=0,(ρu)t+(ρu2+p+μk202ρ2)x+(ρuv)y=0,(ρv)t+(ρuv)x+(ρv2+p+μk202ρ2)y=0, (1.1)

    where q=(u,v) denotes the velocity, μ is the magnetic permeability, ρ is the density, k0 is the positive constant, t denotes time, and p is the gas pressure.

    The Noble-Abel gas is

    p(ρ)=Aργ(1aρ)γ,0<aρ<1,A>0,1<γ<3, (1.2)

    where a>0 is constant and represents the compressibility limit of a gas molecule, and γ represents the adiabatic index.

    It is assumed that the supersonic incoming flow in the second quadrant travels along the horizontal solid wall to the origin with a constant velocity q0=(u0,0), and the rest of the region is a vacuum (see Figure 1). The supersonic flow around a convex corner problem has the following initial value conditions:

    (u,v,ρ)(x,y,t)={(u0,0,ρ0),t=0,x<0,y0,vacuum,t=0,x>0,yxtanθ, (1.3)
    Figure 1.  Supersonic flow around convex corners to vacuum.

    And the boundary data

    {(ρv)(x,0,t)=0,x<0,y=0,t0,(ρv)(x,y,t)=(ρu)(x,y,t)tanθ,y<0,x=ycotθ,t0, (1.4)

    where ρ0 denotes the incoming flow density, is a constant, and θ is the solid wall inclination.

    For the sake of the discussion that follows, we propose the following notation,

    μ2(ρ)=(γ1+2aρ)c2+(1aρ)b2(γ+1)c2+3(1aρ)b2, (1.5)
    [μ2(ρ)]=2aρ(γ+1)c4+[2(γ2)2+14aρ(γ1)+aρ(18aρ8)]b2c2ρ[(γ+1)c2+(1aρ)3b2], (1.6)
    m(ρ)=(3γ4aρ)c2+(1aρ)b2(γ+1)c2+3(1aρ)b2, (1.7)
    m(ρ)=aρ[γ+γ2+4(1aρ)]c4+[27aρ(1γ)+aρ(1736aρ)4(γ2)2](1aρ)b2c2((γ+1)c2+(1aρ)b2)2(1aρ), (1.8)
    Π(ˆρ)=ˆw2γ(γ1)[γ(γ+1)2(γ+1)aˆρ+2a2ˆρ2], (1.9)
    Π(ˆρ)=Aγˆργ2(γ1+2aˆρ)+μκ20(1aˆρ)γ+2γ(γ1)(1aˆρ)γ+2[γ(γ+1)2(γ+1)aˆρ+2a2ˆρ2]ˆw2γ(γ1)[2(γ+1)a+4a2ρ], (1.10)
    α0=arcsinw0u0,αv=0ρ0ˆwˆq2ˆw2ˆq2ˆρdˆρ,ˉδ(ρ)=arctanm(ρ),ˆq2=ˆu2+ˆv2,c2=Aγργ1(1aρ)γ+1,b2=μk20ρ,c20=Aγργ10(1aρ0)γ+1,b20=μk20ρ0,ˉδ=ˉδ(0)={arctan3γγ+1(1<γ<2)π6(2γ<3),w=c2+b2,w0=c20+b20, (1.11)

    where u0>w0 denotes the incoming horizontal velocity as a constant and w0 denotes the incoming magnetoacoustic velocity as a constant. α0 is the maximum characteristic inclination of the C+ characteristic curve of the centered simple wave at point O, and αv is the minimum characteristic inclination of the C+ characteristic curve of the centered simple wave at point O, which is determined by (3.26). The variable (u,v,ρ)(ξ,η) is controlled by (ξ,η), and in order to solve for the main part of the properties of the centered simple wave, we have changed the variable to a variable controlled by a single parameter α, (ˆu,ˆv,ˆρ)(α), and ˆw, ˆu, and ˆv are determined by (3.25). b as the Alfven velocity, c as the speed of sound, and w=c2+b2 as the speed of magneto-sound. b0, c0, and w0=c20+b20 denote the Alfven velocity of the incoming flow at t = 0, the speed of sound, and the speed of magnetoacoustic sound, respectively. All other symbols are for ease of expression and calculation and have no real physical meaning.

    For the convenience of the following proof, we assume that there exists a constant ρ1, such that the following condition holds for any ρ<ρ1 when 0<aρ1<1

    μ2(ρ)>0,[μ2(ρ)]>0,m(ρ)>0,m(ρ)<0,Π(ρ)<0,Π(ρ)<0. (1.12)

    In this paper, we study the Riemannian problem of a supersonic magnetic fluid with Noble-Abel gas diffusing into the vacuum around a convex corner, which is essentially the interaction of a centered simple wave with a planar simple wave and which can be solved by reducing it to a Goursat problem. The solution's hyperbolicity and a priori C1 estimates are established using characteristic decompositions and invariant regions. In addition, pentagonal invariant regions are constructed to obtain global solutions. In addition, the generality of this gas, the sub-invariant region, is constructed, and the solved hyperbolicity is obtained based on the continuity of the sub-invariant region. Finally, the global existence of the solution to the gas expansion problem is constructively obtained. The main results of this paper are as follows:

    Theorem 1.1. If u0>w0, θαv, ρ0<ρ1,max(α04ˉδ(ρ0)+4ˉδπ2,α0αv2ˉδ(ρ0))<0, then the problem of a magnetoacoustic velocity flow with NobleAbel gas expanding into vacuum at the convex corner (1.1)–(1.4) has a global classical solution.

    The structure of the paper is as follows: In Section 2, the characteristic forms and characteristic decompositions related to the characteristic direction, the pseudo-flow direction, and the Mach angle are given. In Section 3, we provide the expressions for the centered simple and planar simple waves. In Section 4, the primary study is the interaction problem of centered simple and planar simple waves. The C0, C1, and hyperbolicity estimates of the solutions are obtained. Then, we obtain the existence of global classical solutions. In Section 5, we discuss the shortcomings of Theorem 1.1.

    By the self-similar transformation (ξ,η)=(x/t,y/t), the system of Eq (1.1) can be written as

    {(ρU)ξ+(ρV)η+2ρ=0,(ρU2+p+μk202ρ2)ξ+(ρUV)η+3ρU=0,(ρUV)ξ+(ρV2+p+μk202ρ2)η+3ρV=0, (2.1)

    where (U,V)=(uξ,vη) is the pseudo-flow velocity. The initial edge value condition (1.3) and (1.4) are transformed into a boundary conditions in the (ξ,η) plane (refer to Figure 2).

    (u,v,ρ)(ξ,η)={(u0,0,ρ0),ξ<0,η0,ξ2+η2,vacuum,ξ>0,ηξtanθ,ξ2+η2, (2.2)

    and

    {(ρv)(ξ,η)=0,ξ<0,η=0,(ρv)(ξ,η)=(ρu)(ξ,η)tanθ,η<0,ξ=ηcotθ, (2.3)

    where u0 and ρ0 are two different constants for the horizontal velocity and density of the incoming flow, respectively, and θ is the solid wall inclination.

    Figure 2.  Initial frontier conditions in self-similar plane.

    For smooth solutions, the system of Eq (2.1) can be written in the following form:

    {(ρU)ξ+(ρV)η+2ρ=0,UUξ+VUη+U+1ρ(p+μk202ρ2)ξ=0,UVξ+VVη+V+1ρ(p+μk202ρ2)η=0. (2.4)

    In the case of the irrotational condition uη=vξ, there exist potential functions φ such that φξ=U and φη=V. By the last two equations of (2.4), the pseudo-Bernoulli's law is obtained as follows:

    12(U2+V2)+(γaρ)(γ1)Aργ1(1aρ)γ+μk20ρ+φ=constant. (2.5)

    We define b=μk20ρ as the Alfven velocity, c=Aγργ1(1aρ)γ+1 as the speed of sound, and w=c2+b2 as the speed of magneto-sound. Through the irrotational condition uη=vξ, the system of Eq (2.4) can be transformed into

    {(w2U2)uξUV(uξ+vη)+(w2V2)vη=0,vξuη=0. (2.6)

    The matrix form of system (2.6) is as follows:

    (w2U2UV01)(uv)ξ+(UVw2V210)(uv)η=0. (2.7)

    The eigenvalues Λ of system (2.7) are given by

    (w2U2)Λ2+2UVΛ+(w2V2)=0. (2.8)

    That is

    (VΛU)2w2(1+Λ2)=0, (2.9)

    which yields

    Λ±=UV±w2(U2+V2w2)U2w2. (2.10)

    (2.10) indicates that when U2+V2>w2, the system (2.7) is hyperbolic, with two families of wave characteristics defined by

    dηdξ=Λ±. (2.11)

    Taking into account Eq (2.9), it is evident that w is essentially a projection of the pseudo-flow velocity in the normal direction of the C± feature line. The eigenvectors on the left side that correspond to the eigenvalues Λ± are

    l±=(1,w2(U2+V2w2)). (2.12)

    By left-multiplying (2.12) by (2.7), the system of Eq (2.7) can be transformed into the following characteristic form:

    {+u+Λ+v=0,u+Λ+v=0, (2.13)

    where ±=ξ+Λ±η.

    We define the characteristic inclinations α,β of Λ+ and Λ as follows:

    tanα=Λ+,tanβ=Λ. (2.14)

    Joining (2.14) and (2.10) yields

    tanαtanβ=2w2(U2+V2w2)U2w2,tanαtanβ=V2w2U2w2. (2.15)

    That is

    U4sin2(αβ)2U2w2(cos2α+cos2β)+w4sin2(α+β)=0. (2.16)

    The pseudo-streamline inclination is σ=α+β2 and the Mach angle is δ=αβ2 as shown in Figure 3, we have

    u=ξ+wcosσsinδ,v=η+wsinσsinδ, (2.17)
    δ=arcsin(wU2+V2). (2.18)
    Figure 3.  The relations between characteristics and local magneto-scoustic speed.

    By the first equation of (2.17), we have

    uξ=1+ccξ+bbξc2+b2cosσsinδc2+b22αξcosββξcosαsin2δ, (2.19)
    uη=ccη+bbηc2+b2cosσsinδc2+b22αηcosββηcosαsin2δ. (2.20)

    Thus

    ˉ±u=cos(σ±δ)+cosσsinδˉ±wwcosβˉ±αwcosαˉ±β2sin2δ, (2.21)

    where

    ˉ+=cosαξ+sinαη,ˉ=cosβξ+sinβη. (2.22)

    From the second equation (2.17), we can conclude that

    vξ=ccξ+bbξc2+b2sinσsinδc2+b22αξsinββξsinαsin2δ, (2.23)
    vη=1+ccη+bbηc2+b2sinσsinδc2+b22αηsinββηsinαsin2δ. (2.24)

    Subsequently

    ˉ±v=sin(σ±δ)+sinσsinδˉ±wwsinβˉ±αwsinαˉ±β2sin2δ, (2.25)
    ˉ±w=cˉ±c+bˉ±bc2+b2=Aγργ2[(γ1)+2aρ]+μκ20(1aρ)γ+22w(1aρ)γ+2ˉ±ρ. (2.26)

    According to (2.5), we have

    Uˉ±u+Vˉ±v+˜p(ρ)˜±ρ=0, (2.27)

    where

    ˜p(ρ)=Aγργ2(1aρ)γ+1+μκ20. (2.28)

    (2.13) and (2.27) lead to

    ˉ+u=Λ˜p(ρ)VΛUˉ+ρ, (2.29)
    ˉ+v=˜p(ρ)UΛVˉ+ρ, (2.30)
    ˉu=Λ+˜p(ρ)VΛ+Uˉρ, (2.31)
    ˉv=˜p(ρ)UΛ+Vˉρ. (2.32)

    Substituting (2.14), (2.17), (2.26), and (2.28) into (2.29)–(2.32) reaches

    ˉ+u=2(c2+b2)sinβM(ρ)c2+b2ˉ+w,ˉu=2(c2+b2)sinαM(ρ)c2+b2ˉw, (2.33)
    ˉ+v=2(c2+b2)cosβM(ρ)c2+b2ˉ+w,ˉv=2(c2+b2)cosαM(ρ)c2+b2ˉw, (2.34)

    where

    M(ρ)=γ1+2aρ1aρ. (2.35)

    Associating (2.21), (2.25), (2.33), and (2.34), we obtain

    wˉ+α=sin2δ2μ2(ρ)Ω(δ,ρ)ˉ+w, (2.36)
    wˉ+β=tanδμ2(ρ)ˉ+w2sin2δ, (2.37)
    wˉα=tanδμ2(ρ)ˉw+2sin2δ, (2.38)
    wˉβ=sin2δ2μ2(ρ)Ω(δ,ρ)ˉw, (2.39)

    where

    Ω(δ,ρ)=m(ρ)tan2δ. (2.40)

    In this section, we compute the characteristic decomposition of w using the commutator relations and the characteristic equations of α, β, w, and u.

    Lemma 2.1. The commutator relations (Li, Zhang, and Zheng [27]).

    ˉˉ+ˉ+ˉ=1sin(2δ){(cos(2δ)ˉ+βˉα)ˉ(ˉ+βcos(2δ)ˉα)ˉ+}. (2.41)

    Lemma 2.2.

    wˉ+ˉw=ˉw{sin2δ+ˉw2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+N(ρ))ˉ+w}, (2.42)
    wˉˉ+w=ˉ+w{sin2δ+ˉ+w2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+N(ρ))ˉw}, (2.43)

    where

    N(ρ)=a(γ+1)ρc2(c2+b2)+c2b2(γ2+3aρ)2((γ1+2aρ)c2+(1aρ)b2)2. (2.44)

    Proof. From Lemma 2.1

    ˉ+ˉuˉˉ+u=1sin(2δ){(cos(2δ)ˉ+βˉα)ˉu(ˉ+βcos(2δ)ˉα)ˉ+u}. (2.45)

    Substituting (2.33) into (2.45), we have

    ˉ+(2(c2+b2)sinαM(ρ)c2+b2ˉw)ˉ(2(c2+b2)sinβM(ρ)c2+b2ˉ+w)=1sin2δ{(cos(2δ)ˉ+βˉα)(2(c2+b2)sinαM(ρ)c2+b2)ˉw(ˉ+βcos(2δ)ˉα)2(c2+b2)sinβM(ρ)c2+b2ˉ+w}. (2.46)

    Simplifying and combining gives

    sinαˉ+ˉw+sinβˉˉ+w={1sin2δ(cos(2δ)ˉ+βˉα)sinα+2N(ρ)sinαwˉ+wcosαw2Θcos2δcos2δΘsin2δˉ+w}ˉw+{sinβsin2δ(cos(2δ)ˉαˉ+β)+2N(ρ)sinβwˉw+cosβw2Θcos2δcos2δΘsin2δˉw}ˉ+w, (2.47)

    where

    Θ(δ,ρ)=M(ρ)c2+b22[2w2sin2δ+M(ρ)c2+b2]. (2.48)

    Inserting (2.37) and (2.38) into (2.47) and using the commutator relation (2.41), we obtain

    w(sinα+sinβ)ˉ+ˉw=wsin2δ(cos(2δ)ˉ+βˉα)(sinα+sinβ)ˉw+2N(ρ)(sinα+sinβ)ˉ+wˉw+(cosαcosβ)sin2δ2μ2(ρ)Ω(δ,ρ)ˉ+wˉw. (2.49)

    Thus, we have

    wˉ+ˉw={sin2δ2Θcos2δ1Θsin2(2δ)ˉw+(2Θ(4sin2δ1)cos2(2δ)Θsin2(2δ)+2N(ρ))ˉ+w}ˉw. (2.50)

    Using a simple calculation, we have

    2Θ(δ,ρ)(4sin2δ1)cos2δ+cos2(2δ)Θ(δ,ρ)sin2(2δ)=1+Ω(δ,ρ)cos2δ2μ2(ρ), (2.51)

    and

    2Θ(δ,ρ)cos2δ1Θ(δ,ρ)sin2(2δ)=12μ2(ρ)cos2δ. (2.52)

    Therefore, (2.42) is established. The proof of (2.43) is similar, so we will not prove it in detail here.

    In this section, we focus on constructing centered and planar simple waves.

    In order to construct the centered simple wave solution for isentropic irrotational pseudo-steady flow at convex corners, we first discuss the nature of the general centered simple wave principal part of the equation.

    According to the definition [28] of a centered simple wave, its solution (u,v,ρ)(ξ,η) can be determined by the direct characteristic line η=ξtanα and the function (u,v,ρ)(ξ,η)=(¯u,¯v,¯ρ)(r,α) defined on the rectangular region ˜Λ(t)={(ξ,η)0rζ,˜α2α˜α1}, see Figure 4. It is easy to see that ξ=rcosα and η=rsinα, there are

    rξ=cosα,rη=sinα,αξ=1rsinα,αη=1rcosα,(u,v,ρ)(ξ,η)=(¯u,¯v,¯ρ)(ξ,α),ξ=ξ+tanαη,α=ξcos2αη. (3.1)
    Figure 4.  The centered simple wave flow region in the (ξ,η) and (r,α) planes.

    From the systems (2.13) and (2.5), it is clear that the main parts (u,v,ρ)(ξ,η) of the C+ type centered simple wave satisfy

    {¯uξ+tanβ¯vξ=0,ξ(1+tan2α)¯vξ+¯uα+tanα¯vα=0,12[(¯uξ)2+(¯vξtanα)2]+(γa¯ρ)(γ1)A¯ργ1(1a¯ρ)γ+¯b2+¯φ=constant. (3.2)

    For the potential function φ, we have

    ξ¯φξ=tanα+cotσ1+tan2α¯φα. (3.3)

    Let ξ0, then (3.2) and (3.3) become

    dˆudα+tanαdˆv(α)dα=0,ˆφ(α)=constant, (3.4)
    12(ˆu2(α)+ˆv2(α))+(γaˆρ)(γ1)Aˆργ1(1aˆρ)γ+ˆb2(α)=constant, (3.5)
    tanα=ˆu(α)ˆv(α)+ˆw(α)ˆu2(α)+ˆv2(α)ˆw2(α)ˆu2(α)ˆw2(α), (3.6)

    where (¯u(0,α),¯v(0,α),¯φ(0,α),¯ρ(0,α))=(ˆu(α),ˆv(α),ˆφ(α),ˆρ(α)).

    Lemma 3.1. If the principal part (¯u,¯v,¯ρ)(r,α)=(ˆu,ˆv,ˆρ)(α) satisfies

    dˆudα+tanαdˆv(α)dα=0, (3.7)
    12(ˆu2(α)+ˆv2(α))+(γaˆρ)(γ1)Aˆργ1(1aˆρ)γ+ˆb2(α)=constant, (3.8)
    tanα=ˆu(α)ˆv(α)+ˆw(α)ˆu2(α)+ˆv2(α)ˆw2(α)ˆu2(α)ˆw2(α), (3.9)

    then (u,v,ρ)(ξ,η)=(ˆu,ˆv,ˆρ)(α),η=ξtanα is the C+ centered simple wave solution of Eq (2.13) at the origin.

    Proof. This proof is divided into the following three steps:

    Step 1. First: prove that for any given α, the line η=ξtanα is the C+ characteristic curve. This only requires proving that η=ξtanα is circular with the speed of sound (ˆu(α)ξ)2+(ˆv(α)η)2=ˆw(α)2 tangent. In fact, substituting η=ξtanα into the velocity circle expression of sound is obtained

    (ˆu2+ˆv2ˆw2)2[ˆu+ˆvtanα]ξ+(1+tan2α)ξ2=0. (3.10)

    Substituting (3.8) into (3.9) yields the discriminant of the (3.10) root

    Δ=4[(ˆu2ˆv2)tan2α2ˆuˆvtanα+(ˆv2ˆw2)]=0. (3.11)

    So, for any given line, η=ξtanα is a C+ straight eigenline.

    Step 2. Prove that (u,v,ρ)(ξ,η) satisfies Eq (2.13) in the theorem. According to the definition of (u,v,ρ), it can be known that along C+ straight eigenline is constant, that is, +u=+v=+ρ=0 and

    +u+λ+v=0. (3.12)

    Under condition (3.4), it is obtained that

    u+λ+v=(dˆudα+tanαdˆv(α)dα)α=0. (3.13)

    Step 3. Prove that (u,v,ρ)(ξ,η) satisfies the proposed Bernoulli law in the theorem. This can be obtained from Eqs (3.4) and (3.5).

    +(12(U2+V2)+(γAρ)γ1Aργ1(1aρ)γ+μκ20ρ+φ)=(uξ)+u+(vη)+v+Aγργ2(1aρ)γ+1+ρ+μκ20+ρ=0, (3.14)

    and

    (12(U2+V2)+(γAρ)γ1Aργ1(1aρ)γ+μκ20ρ+φ)=(uξ)u+(vη)v+Aγργ2(1aρ)γ+1ρ+μκ20ρ=((ˆuξ)dˆudα+(ˆvη)dˆvdα+Aγˆργ2(1aˆρ)γ+1dˆρdα+μκ20dˆρdα)α=(ˆudˆudα+ˆvdˆvdα+Aγˆργ2(1aˆρ)γ+1dˆρdα+μκ20dˆρdα)αξ(dˆudα+tanαdˆvdα)α=0, (3.15)

    (3.14) and (3.15) show that Bernoulli's law holds.

    Next, we obtain the expression of the centered simple wave solution. Since (u,v,ρ)(ξ,η)=(ˆu,ˆv,ˆρ)(α) is the principal part of the centered simple wave for type C+ and α is the characteristic angle of the C+ characteristic line η=ξtanα. We decompose the pseudo-flow velocity (U,V)=(ˆu(α)ξ,ˆv(α)η) along the (sinα,cosα) and (cosα,sinα) directions, respectively. I obtain the velocity components w and g as follows:

    ¯w(ξ,α)=(ˆu(α)ξ)sinα(ˆv(α)ξtanα)cosα,¯g(ξ,α)=(ˆu(α)ξ)cosα+(ˆv(α)ξtanα)sinα. (3.16)

    When ξ0, we get

    ˆw(α)=ˆu(α)sinαˆv(α)cosα,ˆg(α)=ˆu(α)cosα+ˆv(α)sinα,ˆu(α)=ˆg(α)cosα+ˆw(α)sinα,ˆv(α)=ˆg(α)sinαˆw(α)cosα. (3.17)

    It is easy to see that ˆg(α)2+ˆw(α)2=ˆu(α)2+ˆv(α)2, derivation of α in each of the last two equations of (3.17) yields

    dˆudα=dˆgdαcosαˆgsinα+dˆwdαsinα+ˆwcosα,dˆvdα=dˆgdαsinα+^gcosαdˆwdαcosα+ˆwsinα. (3.18)

    Substituting Eq (3.18) into Eq (3.4), we have

    ˆgα=ˆw. (3.19)

    The derivation of α in Bernoulli's law (3.5) and then the union (3.19) yield

    ˆg=(γ+1)ˆc2+3(1aˆρ)ˆb2(γ1+2aˆρ)ˆc2+(1aˆρ)ˆb2ˆwα=ˆwαμ2(ˆρ). (3.20)

    Then the derivation of α in (3.20) yields

    (γ+1)ˆc2+3(1aˆρ)ˆb2(γ1+2aˆρ)ˆc2+(1aˆρ)ˆb2ˆwαα[(γ+1)aˆρˆw2+(2γ3aˆρ)2ˆb2](1aˆρ)ˆc2[(γ1+2aˆρ)ˆc2+(1aˆρ)ˆb2]34ˆw(ˆwα)2+ˆw=0. (3.21)

    Using the initial value condition (ˆu,ˆv,ˆρ)(α0)=(u0,0,ρ0) to solve Eq (3.21), we have

    ˆw=αα0μ2(ˆρ)Π(ˆρ)+Π0dα+w0,ˆg=ˆwαμ2(ˆρ)=Π(ˆρ)+Π0, (3.22)

    in which

    Π(ˆρ)=ˆw2γ(γ1)[γ(γ+1)2(γ+1)aˆρ+2a2ˆρ2], (3.23)

    and

    Π0=u20w20+w20γ(γ1)[γ(γ+1)2(γ+1)aρ0+2a2ρ20]. (3.24)

    According to (3.17), it is not hard to obtain

    ˆu=Π(ˆρ)+Π0cosα+ˆwsinα,ˆv=Π(ˆρ)+Π0sinαˆwcosα,ˆw=αα0μ2(ˆρ)Π(ˆρ)+Π0dα+w0. (3.25)

    Lemma 3.2. Suppose ρ0<ρ1 and θαv, then RC is a complete simple wave that connects the constant state with the vacuum (see Figure 5), where α0 and αv satisfy

    α0=arcsinw0u0,αv=0ρ0ˆwˆq2ˆw2ˆq2ˆρdˆρ, (3.26)

    and ˆq2=ˆu2+ˆv2.

    Proof. Deriving and substituting ˆu=ˆqcosσ and ˆv=ˆqsinσ into the first equation of (3.4), and also deriving Eq (3.5), we have

    dσdˆq=cosδˆqsinδ=ˆq2ˆw2ˆqˆw,dˆqdˆρ=ˆw2ˆqˆρ. (3.27)

    Therefore, we have

    σ=ˆρρ0ˆwˆq2ˆw2ˆq2ˆρdˆρ, (3.28)

    it is easy to see that αv=limρ0σ. By deflating αv one obtains

    αv(1u0(γaρ0γ1Aργ10(1aρ0)γ+μκ20ρ0),0). (3.29)

    So αv is bounded.

    Figure 5.  Interaction region.

    By (1.1) and its initial value condition

    (u,v,ρ)(x,y,0)={(u0,0,ρ0),n1x+n2y<0,Vacuum,n1x+n2y>0, (3.30)

    where n21+n22=1.

    By coordinate transformations ˆx=n1x+n2y, ˆy=n2x+n1y, let ˆu=n1u+n2v, ˆv=n2u+n1v. Solving a 1-D Riemann problem, we obtain

    (ˆu,ˆv,ˆρ)(ˆx,ˆy,t)={Vacuum,ˆξ>ˆξ1,(ur,0,ρr),ˆξ2ˆξˆξ1,(u0,0,ρ0),ˆξ<ˆξ2, (3.31)

    where ˆξ=ˆxt, ˆξ1=limρr0ur(ρr), ˆξ2=u0w(ρ0). The functions ur(ˆξ) and ρr(ˆξ) are implicitly determined by

    ur=u0+ρrρ0c2+b2ρdρ(ρr<ρ0),ˆξ=urw(ρr). (3.32)

    Therefore, the solutions of (1.1) and (3.30) are obtained as follows:

    (u,v,ρ)(x,y,t)={Vacuum,ˆξ>ˆξ1,(n1ur,n2ur,ρr),ˆξ2ˆξˆξ1,(u0,0,ρ0),ˆξ<ˆξ2. (3.33)

    Suppose that the centered simple wave Rc and the planar simple wave Rp start to interact at point I(u0w0,w0u0w0u0+w0) to form an interaction region Ω. Ω is enclosed by the C penetrating characteristic curve ~IH of the centered simple wave Rc, the C+ penetrating characteristic curve ~IK of the backward planar simple wave Rp, and the interface ~HK between the gas and the vacuum region, where ~IH is determined by the centered simple wave Rc and point Ⅰ, while ~IK is determined by the planar simple wave Rp and point Ⅰ; see Figure 5.

    According to [29], a simple calculation yields the following parametric expression for ~IK with respect to the density ρ

    {ξ=u0w+ρρ0Aγτγ1(1aτ)γ+1+μκ20ττdτ,η={ρwρ0w0[w20u0w0u0+w0ρ0w0ρρ0(γ+1)Aγτγ2(1aτ)γ+2+3μκ202τAγτγ1(1aτ)γ+1+μκ20τdτ]}12, (4.1)

    where

    w0=Aγργ10(1aρ0)γ+1+μκ20ρ0. (4.2)

    From (4.1), when ρ=0, the coordinates of the point K can be obtained as

    K(ξ,η)=(u0ρ00wρdρ,0). (4.3)

    The solution of the system of Eqs (2.1)–(2.3) outside the interaction region a consists of the constant state (u0,0,w0), the vacuum state, the centered simple wave Rc, and the backward planar simple wave Rp; see Figure 5. Solving the solution of the system of Eq (2.1) in the interaction region Ω boils down to a Goursat problem, i.e., the system of Eq (2.1) as well as the boundary conditions

    (u,v,ρ)(ξ,η)={(u+,v+,ρ+)(ξ,η),on~IK,(u,v,ρ)(ξ,η),on~IH, (4.4)

    where (u±,v±,ρ±)(ξ,η) is determined by the simple wave Rp (Rc).

    Lemma 4.1. For any ρ(0,ρ0), Ωwρ denotes the region enclosed by the C+ characteristic curve ~IK1, the C characteristic curve ~IH1, and the isomagnetoacoustic velocity line w(ξ,η)=wρ. Here K1 and H1 are the intersections of the isomagnetoacoustic velocity line w(ξ,η)=wρ with ~IK and ~IH, respectively. When ρ is sufficiently close to ρ0, then there exists a unique C1 solution to the Goursat problem (2.1) and (4.4) on Ωwρ.

    Proof. According to the theory of the existence of local classical solutions of hyperbolic equations [28], there is a local C1 solution to the Goursat problems (2.4) and (4.4). Thus, there is a sufficiently small normal number such that ε Goursat problems (2.4) and (4.4) have a C1 solution on Σε, where Σε is the closed region bounded by ~IK, ~IH, and the straight line

    ξ=u0w0+ε. (4.5)

    Let

    l=supξ=u0w0+εw(ξ,η). (4.6)

    In the planar simple wave Rp, we have β=π2. Combining with Eq (2.36), on the C+ characteristic curve ~IK, we obtain

    ˉ+w=[γ1+2aρ1aρc2+b2γ+11aρc2+3b2]sin(2δ)<0. (4.7)

    Similarly, in the centered simple wave Rc, from Eq (2.37), on the C characteristic curve ~IH, we have

    ˉw=μ2(ρ)tanα[wˉα2sin2δ]<0. (4.8)

    Combining with (4.7), (4.8), (2.42), and (2.43), we have ˉ±w<0 in the region Σε, evidently, l<w0. Therefore, there exists a unique C1 solution to the Goursat problem on Ωwρ.

    Lemma 4.2. On the C+ characteristic curve ~IK, there is

    ˉδ(ρ0)<δα02+π4,β=π2. (4.9)

    Meanwhile, on the C characteristic curve ~IH, there is

    αvαα0,min(αv2ˉδ,π2)β<α02ˉδ(ρ0), (4.10)

    where

    ˉδ(ρ)=arctanm(ρ),ˉδ={arctan3γγ+1(1<γ<2)π6(2γ<3),ˉδ(ρ(E))=δ(E). (4.11)

    Proof. In view of (2.36), we have

    wˉδ+δ=sin(2δ)4μ2(ρ)[m(ρ)tan2δ]ˉ+w. (4.12)

    Due to

    m(ρ)>0,m(ρ)<0. (4.13)

    We have

    ˉδ(ρ)<0,limρ0ˉδ=ˉδ<π4. (4.14)

    Moreover

    2δ(ρ0)=α0+π2>2ˉδ(ρ0). (4.15)

    Due to ˉ+m(ρ)>0, we have the following two possible cases, see Figure 6.

    Figure 6.  Boundary data estimates.

    Case 1. If the functions f and g have no intersection within (0,ρ0), then we have

    ˉδδα02+π4,2ˉδπ2αα0,β=π2,δ>ˉδ(ρ)on~IK. (4.16)

    Case 2. If the functions f and g intersect at point E in the range (0,ρ0), then we have m(ρ(E))=tan2δ(E). Clearly, tan2δ>m(ρ) holds on IE. Then, we get ˉ+δ~IE<0 and

    ˉδ(ρ(E))δα02+π4,2ˉδ(ρ(E))π2<α<α0,β=π2on~IE. (4.17)

    Furthermore, there are tan2δ<m(ρ) holds on EK; otherwise, there exists a point E1 on EK such that ˉ+δ(E1)=0, and m(ρ)<0. According to (4.12), ˉ+δ(E1)<0 holds, which contradicts the hypothesis. It is not difficult to obtain

    ˉδ(ρ(E))<δ<ˉδ,2ˉδ(ρ(E))π2<α<2ˉδπ2,β=π2on~EK. (4.18)

    Based on ˉδ>ˉδ(ρ0) and ˉδ(ρ(E))>ˉδ(ρ0), it is not difficult to obtain (4.9).

    Similarly, by (2.39), on the C cross characteristic curve ~IH, we obtain

    wˉβ=sin(2δ)2μ2(ρ)[m(ρ)tan2δ]ˉw, (4.19)

    we discuss this in the following two cases:

    Case 1. If ¯δ(ρ)δ as αvαα0. According to Eq (4.19), we have

    π2β<α02¯δ,¯δ(ρ)δon~IH. (4.20)

    Case 2. If not, there must exist a point F between δ=¯δ(ρ0) and δ=¯δ such that δ(F)=¯δ(ρ(F)). Clearly, δ>ˉδ holds on IF. Then, we obtain ¯βIF>0 and

    π2ββ(F)on~IF. (4.21)

    Additionally, there is δ<ˉδ holds on ~FH; otherwise, there exists a point F1 on ~FH such that ˉβ(F1)=0, and m(ρ)<0. According to (4.19), ˉβ(F1)<0 holds, which contradicts the hypothesis. It is not difficult to get

    αv2ˉδββ(F)on~FH. (4.22)

    Based on α02ˉδ<α02ˉδ(ρ0) and β(F)<α02ˉδ(ρ0), it is not difficult to obtain (4.10). Then, this lemma can be obtained.

    Lemma 4.3. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, and max(α04ˉδ(ρ0)+4ˉδπ2,α0αv2ˉδ(ρ0))<0, then the characteristic inclination (α,β) within Ω˜ρ satisfies

    α_<α<¯α,β_<β<¯β,2δ_<αβ<π, (4.23)

    where

    ¯α=2ˉδ+α02ˉδ(ρ0),α_=min(2ˉδ(ρ0)π2,αv),¯β=α02ˉδ(ρ0),β_=min(αv2ˉδ,π2+2ˉδ(ρ0)2ˉδ),¯α¯β=2ˉδ,α_β_=2ˉδ, (4.24)

    for every ˜ρ(0,ρ0) (Figure 7).

    Proof. Assume

    Σε1={(α,β)α_ε<α<¯α+ε,β_ε<β<¯β+ε,2δ_<αβ}, (4.25)

    where ε is any positive number close to zero and δ_ is a sufficiently small constant satisfied by 0<δ_<αv2α02+ˉδ(ρ0), such that

    1(1cos2δΩ)M1μ2(ρ)sin(2δ)>0asδδ_. (4.26)

    It is easy to see that when max(α04ˉδ(ρ0)+4ˉδπ2,α0αv2ˉδ(ρ0))<0, we have

    (¯α+ε)(β_ε)=2ˉδ+α02ˉδ(ρ0)+εmin(αv2ˉδε,π2+2ˉδ(ρ0)2ˉδε)=max(α0+4ˉδ2ˉδ(ρ0)+2ε,α0+4ˉδ4ˉδ(ρ0)+π2+2ε)<π. (4.27)

    Therefore, we have 0<2δ_<αβ<π, which shows that Σε1 satisfies the hyperbolicity condition. Choose any point P in Ω˜ρ, we have a C+ characteristic curve ~PH2 and a C characteristic curve ~PK2, where H2~IH and K2~IK. ΩP is a closed region delimited by the corresponding characteristic curves ~PK2, ~PH2, ~IH2 and ~IK2.

    Figure 7.  Invariant region.

    Provide that (α,β)(ξ,η)Σε1 for (ξ,η)ΩP{P}, then we have

    (α,β)(ξ,η)ΣεP, (4.28)

    for all (ξ,η)ΩP, where

    ΣεP={(α,β)α_ε<α<¯αP+ε,β_Pε<β<¯β+ε,2δ_<αβ<¯αPβ_P},¯αP¯β=2ˉδP,α_β_P=2ˉδP. (4.29)

    This lemma can be obtained. From Lemma 4.2, we obtain

    (α,β)(ξ,η)ΣεP,as(ξ,η)~IH2~IK2. (4.30)

    Let

    γ1={α=α_ε,β_Pε<β<¯β+ε,αβ>2δ_},γ2={α_ε<α<¯αP+ε,β=¯β+ε,αβ>2δ_},γ3={α=¯αP+ε,β_Pεβ<¯β+ε},γ4={α_ε<α<¯αP+ε,β=β_Pε},γ5={α=¯αP+ε,β=¯β+ε},γ6={α=α_ε,β=β_Pε},γ7={α_εα¯αP+ε,β_Pεβ¯β+ε,αβ=2δ_}.

    Assuming that (4.28) does not hold, there exists a point Q in the region ΩP for which (α,β)(Q)6i=1γi and (α,β)(ξ,η)ΣεP hold for all (ξ,η)ΩQ{Q}, where ΩQ is the closed region bounded by the characteristic curves ~QK3, ~QH3, ~IH3, and ~IK3. The C characteristic curve through point Q intersects ~IK at point K3, and the C+ characteristic curve through point Q intersects ~IH at point H3.

    If (α,β)(Q)γ1, on the basis of the assumed condition that (α,β)(ξ,η)Σε1 as (ξ,η)ΩP{P}, we have Q = P, according to (2.36), we obtain

    wˉ+α(Q)=sin2δ2μ2(ρ)[tan2ˉδPtan2δ(ρ(Q))]ˉ+w>0. (4.31)

    But based on our assumptions, we have

    α(ξ,η)>α(Q)=α_ε,(ξ,η)~H3Q{Q}. (4.32)

    Thus, we obtain ˉ+α(Q)0, and that contradicts my assumptions.

    If (α,β)(Q)γ2, we can export contradictions similarly.

    If (α,β)(Q)γ3, it is not hard to obtain ˉδ(ρ(Q))ˉδ(ρ(P))<δ(ρ(Q)). Then, we obtain

    wˉ+α(Q)=sin2δ2μ2(ρ)[tan2ˉδQtan2δ(ρ(Q))]ˉ+w<0. (4.33)

    But based on our assumptions, we have

    α(ξ,η)<α(Q)=¯αP+ε,(ξ,η)~H3Q{Q}. (4.34)

    Similarly, we obtain ˉ+α(Q)0. And that contradicts my assumptions.

    If (α,β)(Q)γ4, we can export contradictions similarly.

    If (α,β)(Q)γ5, we define ˜α on ~H3Q as follows:

    {wˉ+˜α=sin2δ2μ2(ρ)[tan2ˉδPtan2(˜α¯αPε2)]ˉ+w,˜α(H3)=α(H3). (4.35)

    Let z=tan˜α¯αPε2; (4.35) becomes

    {wˉ+z=14μ2(ρ)sin(2δ)(1+z2)(tan2ˉδPz2),z(H3)=tanα(H3)¯αPε2<tanˉδP. (4.36)

    A simple calculation based on the method of Lemma 4.2 in [6] yields

    ˜α(Q)<2ˉδP+¯αP+ε. (4.37)

    Combining (2.36) and (4.35), we have

    {wˉ+(˜αα)=sin2δ2μ2(ρ)[tan2ˉδPtan2ˉδ]ˉ+w+sin2δ2μ2(ρ)[tan2(˜α¯αPε2)tan2(αβ2)]ˉ+w,(˜αα)(H3)=0. (4.38)

    Substituting ˜α(H3)=α(H3) into the first equation of (4.38), we obtain ˉ+(˜αα)(H3)>0. We assert that (˜αα)(¯H)0, ¯H~H3Q. If not, there must be a point H~H3Q{H3,Q} such that (˜αα)(H)=0 and (˜αα)(ξ,η)>0, (ξ,η)~H3H{H3,H}. Thus, ˉ+(˜αα)(H)0. On the other hand, according to the hypothesis, there are (α,β)(H)ΣεP holds, and we obtain ˉ+(˜αα)(H)>0 according to equation (4.38), which contradicts ˉ+(˜αα)(H)0. Therefore, we have α(Q)˜α(Q)<2ˉδP+¯αP+ε, and that contradicts our assumptions.

    If (α,β)(Q)γ6, we can export contradictions similarly.

    If (α,β)(Q)γ7, we have ˉδ(Q)0. According to (2.38), (2.39), and (4.26), it is obtained that

    wˉδQ=12[tanδμ2(ρ)ˉw+2sin2δsin(2δ)2μ2(ρ)Ω(δ,ρ)ˉw]=tanδ2μ2(ρ)(1cos2δΩ)ˉw+sin2δ>(1(1cos2δΩ)M1μ2(ρ)sin(2δ))sin2δ>0, (4.39)

    and that contradicts our assumptions. Based on the above discussion, when ε tends to zero, it is easy to get this lemma.

    Lemma 4.4. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, then there exists a constant M0>0 independent of ˜ρ such that

    (u,v,ρ,φ)C0(Ω˜ρ)<M0, (4.40)

    where ˜ρ(0,ρ0).

    Proof. According to Lemma 4.3 and Eqs (2.5) and (2.17), we have

    {(uv)=(ξη)+wsinδ(cosσsinσ),12(U2+V2)+(γaρ)(γ1)Aργ1(1aρ)γ+μκ20ρ+φ=constant, (4.41)

    in the domain Ω˜ρ, then the lemma is easy to proved.

    Lemma 4.5. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, then we have

    (ˉ+w,ˉw)(M1,0)×(M1,0), (4.42)

    in the domain Ω˜ρ, where

    M1=max{2μ2(ρ0),Π0u20w20μ2(ρ0)}. (4.43)

    Proof. From Eq (4.7) and μ2(ρ)>0, we obtain

    μ2(ρ0)μ2(ρ)=[γ1+2aρ1aρc2+b2γ+11aρc2+3b2]<ˉ+w~IK<0. (4.44)

    Moreover, according to (3.22), (1.12), and (3.1), they lead to

    ˆwα=μ2(ρ)Π(ρ)+Π0>0, (4.45)
    ˉw~IH=ˆwα(cosβξα+sinβηα)=ˆwαgsin(2δ)=μ2(ρ)Π(ρ)+Π0sin(2δ)g>Π0μ2(ρ0)u20w20. (4.46)

    Based on the characteristic decompositions (2.42) and (2.43), we find by calculation that

    1+Ω(ξ,η)cos(2δ)2μ2(ρ)=1+(m(ρ)tan2δ)cos(2δ)2μ2(ρ)=1+[(12μ2(ρ))cos2δsin2δ]cos(2δ)2μ2(ρ)cos2δ=μ2(ρ)(12cos2(2δ))+cos2(2δ)2μ2(ρ)cos2δ=μ2(ρ)+m(ρ)cos2(2δ)2μ2(ρ)cos2δ>0. (4.47)

    Then, we obtain

    1+Ω(ξ,η)cos(2δ)2μ2(ρ)+(c2+b2)c2a(γ+1)ρ+c2b2(γ2+3aρ)2[(γ1+2aρ)c2+(1aρ)b2]2>0. (4.48)

    Next, using the converse, we prove the consistent boundedness of ˉ±w. Suppose that the conclusion of Lemma 4.5 does not hold, and that there exists a point P0 inside Ω˜ρ such that ˉw(P0)=M1, ˉ+w(P0)[M1,0) and (ˉ+w,ˉw)(M1,0)×(M1,0) in ΩP0{P0}, where ΩP0 is the region bounded by the C+ characteristic curve ~P0H0 over the point P0 and the C characteristic curve ~P0K0 over the point P0 and ~IK, ~IH. According to (2.42), we have

    wˉ+ˉw(P0)=ˉw{sin2δ+ˉw2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+(c2+b2)c2a(γ+1)ρ+c2b2(γ2+3aρ)2[(γ1+2aρ)c2+(1aρ)b2]2)ˉ+w}>ˉw{sin2δ+ˉw2μ2(ρ)cos2δ}ˉw{sin2δ1cos2δ}>0. (4.49)

    However, this would contradict the hypothesis, so ˉw(P0)(M1,0). Similarly, ˉ+w(P0)(M1,0) can be proved, and applying the continuity method yields (ˉ+w,ˉw)(M1,0)×(M1,0) in the domain Ω˜ρ.

    Lemma 4.6. If there exists a C1 solution to Goursat problem (2.1) and (4.4) in Ω˜ρ, then there exists a constant M2>0 independent of ˜ρ such that

    Du,Dv,DρC0(Ω˜ρ)<M2, (4.50)

    where ˜ρ(0,ρ0).

    Proof. The derivation of both sides of w2=c2+b2 in the direction of the C± characteristic curve can be obtained

    ˉ±ρ=2(1aρ)Aγργ1(1aρ)γ+1+μκ20ρ(1aρ)2γ+2Aγργ2(γ1+2aρ)+μκ20(1aρ)γ+2ˉ±w. (4.51)

    Observe

    ξ=sinβˉ+sinαˉsin(2δ),η=cosβˉ+cosαˉsin(2δ). (4.52)

    From Lemma 4.5, (2.33), and (2.34), it is known that there exists a normal number M2 independent of ˜ρ.

    Lemma 4.7. There is a global classical solution for the boundary problem (2.1) and (4.4) in the region Ω, where the Ω region is bounded by the C+ characteristic curve ~IK, the C characteristic curve ~IH, and the vacuum boundary ~HK.

    Proof. Suppose that the Goursat problem has a C1 solution on the area Ω˜ρ, where ˜ρ(0,ρ0). Similarly to the proof of Theorem 4.12 in [6], we have that the isomagnetic sound velocity line ρ(ξ,η)=˜ρ is Lipschitz continuous. The isomagnetic sound velocity line ρ(ξ,η)=˜ρ is solvable to length. Let P0,P1,P2,,Pn be ρ(ξ,η)=˜ρ on sequentially different n + 1 points; P0 is located in ~IH, and Pn is located in ~IK. The C+ eigencurve through point Pi intersects the C characteristic curve through the point Pi1 at point Ii, where i=0,1,,n1. The contour ρ(ξ,η)=˜ρ is a non-characteristic curve, for any i=0,1,,n1, both PiIi and Pi1Ii. For any i=0,1,,n1, the system of Eq (2.1) is characterized by the characteristic curves ~PiIi and ~Pi1Ii. The Goursat problem is in the quadrilateral region Ω˜ρ bounded by ~PiIi, ~Pi1Ii, ~Pi1Ti, and ~PiTi. There is a global smooth classical solution on Ω˜ρ, where ~PiTi is the C characteristic curve of the point Pi, and ~Pi1Ti is the C+ characteristic curve of the point Pi1.

    Let B=T0 and A=Tn+1. For each i=0,1,,n, there is a 0<˜ρi<˜ρ such that there is a C1 solution on the Goursat problem ρ(ξ,η)=~ρi, ~PiTi and ~PiTi+1 bounded by the characteristic curves ~PiTi and ~PiTi+1. Let ˜ρε=max{˜ρ0,˜ρ1,,˜ρn,ρ(T1),ρ(T2),,ρ(Tn)}. We obviously have a relationship ˜ρε<˜ρ established. Then, we obtain the solution to the Goursat problem (2.1) and (4.4) in the region Ω˜ρ. By repeating the above process, we can solve the problem at the regional Ω. So we obtain this lemma.

    Thus, we have completed all the discussions and obtained Theorem 1.1. The ideal magnetohydrodynamic system described in Theorem 1.1 can be used to model phenomena in astrophysics, laboratory plasmas, solar physics, etc. It represents an ideal plasma flow interacting with a magnetic field and is described by partial differential equations, including conservation of mass, momentum, total energy, and magnetic field. The conclusion of Theorem 1.1 shows that we only need to control the density ρ0 and velocity u0 of the incoming flow and the solidwall inclination θ so that they satisfy the conditions. We can guarantee that the problem of expanding a magnetic fluid with a NobleAbel gas into the vacuum at a convex corner has a global classical solution.

    We study the Riemann problem of a supersonic magnetic fluid with Noble-Abel gas diffusing into the vacuum around a convex corner, which is solved by reducing it to a Goursat problem. The solution's hyperbolicity and a priori C0, C1 estimates are established using characteristic decompositions and invariant regions. In addition, pentagonal invariant areas are constructed to obtain a global solution. In addition, sub-invariant regions are built, and the hyperbolicity of the solution is obtained based on the continuity of the sub-invariant regions. Finally, the global existence of the solution to the gas expansion problem is constructively received.

    This paper deals with this problem under the special assumption of the solid wall angle θ. For more general cases, the problem requires further attempts and discussions, for example, when the incoming flow velocity is not supersonic but sonic or subsonic. The authors will continue to study these issues later. In addition, we study the complete expansion problem in this work. How about incomplete expansion problems? These problems are interesting. Follow-up studies are needed.

    The author declares she have not used Artificial Intelligence (AI) tools in the creation of this article.

    The author would like to thank the anonymous referee and editor very much for their valuable comments and suggestions, which greatly help us improve the presentation of this article.

    The author declares no conflicts of interest in this paper.



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