
In this paper, we study the expansion of Noble-Abel gas into a vacuum around the convex corner of the two-dimensional compressible magnetohydrodynamic system. We reduce this problem to the interaction of a centered simple wave emanating from the convex corner with a backward planar simple wave. Mathematically, this is a Goursat problem. By using the method of characteristic decomposition and construction of invariant regions, combining C0 and C1 estimation as well as hyperbolicity estimation, we obtain the existence of a global classical solution by extending the local classical solution.
Citation: Fei Zhu. Noble-Abel gas diffusion at convex corners of the two-dimensional compressible magnetohydrodynamic system[J]. AIMS Mathematics, 2024, 9(9): 23786-23811. doi: 10.3934/math.20241156
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In this paper, we study the expansion of Noble-Abel gas into a vacuum around the convex corner of the two-dimensional compressible magnetohydrodynamic system. We reduce this problem to the interaction of a centered simple wave emanating from the convex corner with a backward planar simple wave. Mathematically, this is a Goursat problem. By using the method of characteristic decomposition and construction of invariant regions, combining C0 and C1 estimation as well as hyperbolicity estimation, we obtain the existence of a global classical solution by extending the local classical solution.
A large number of fluids exist in nature. Neglecting viscosity and heat transfer, some fluids in nature can be viewed as ideal fluids [1,2,3,4]. The study of ideal fluid flow around a convex corner can be traced back to 1948, as proposed by Courant and Friedrichs[5]. They discovered the existence of a solution for this problem. Subsequently, Sheng and You[6] studied the problem of diffusion of the pseudo-steady supersonic flow of the polytropic gas into a vacuum at a convex corner and obtained the existence of a solution. Sheng and Yao[7] studied the problem of two-dimensional pseudo-steady isentropic irrotational supersonic flow of the polytropic gas around a convex corner. They obtained the structure of non-completely centered simple wave solutions. In 2023, Chen, Shen, and Yin[8] studied the problem of supersonic diffusion of a non-ideal gas around a convex corner into the vacuum. They proved the existence of classical solutions in the region of interaction between planar and centered simple waves. Li and Sheng[9] studied the expansion of the Van der Waals gas into the vacuum around a convex corner. The problem is studied in terms of the interaction of a completely centered simple wave with a backward planar simple wave and an incompletely centered simple wave with a backward planar simple wave. They constructively obtained the global existence of solutions to the gas expansion problem. For other studies on the convex corner winding problem, we refer to [10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25].
Since magnetic fields may affect fluids during flow, it is natural to consider compressible magnetohydrodynamic equations. There have been some results in recent years about the flow of an ideal magnetic fluid around a convex corner. In 2020, Chen, Yin, and You[26] investigated the two-dimensional pseudo-steady compressible magnetohydrodynamic equations for the polytropic gas expansion into the vacuum at the convex corner. They obtained a classical solution for interacting with centered and planar simple waves.
The two-dimensional isentropic compressible magnetohydrodynamic equations can be written as
{ρt+(ρu)x+(ρv)y=0,(ρu)t+(ρu2+p+μk202ρ2)x+(ρuv)y=0,(ρv)t+(ρuv)x+(ρv2+p+μk202ρ2)y=0, | (1.1) |
where →q=(u,v) denotes the velocity, μ is the magnetic permeability, ρ is the density, k0 is the positive constant, t denotes time, and p is the gas pressure.
The Noble-Abel gas is
p(ρ)=Aργ(1−aρ)γ,0<aρ<1,A>0,1<γ<3, | (1.2) |
where a>0 is constant and represents the compressibility limit of a gas molecule, and γ represents the adiabatic index.
It is assumed that the supersonic incoming flow in the second quadrant travels along the horizontal solid wall to the origin with a constant velocity →q0=(u0,0), and the rest of the region is a vacuum (see Figure 1). The supersonic flow around a convex corner problem has the following initial value conditions:
(u,v,ρ)(x,y,t)={(u0,0,ρ0),t=0,x<0,y≥0,vacuum,t=0,x>0,y≥xtanθ, | (1.3) |
And the boundary data
{(ρv)(x,0,t)=0,x<0,y=0,t≥0,(ρv)(x,y,t)=(ρu)(x,y,t)tanθ,y<0,x=ycotθ,t≥0, | (1.4) |
where ρ0 denotes the incoming flow density, is a constant, and θ is the solid wall inclination.
For the sake of the discussion that follows, we propose the following notation,
μ2(ρ)=(γ−1+2aρ)c2+(1−aρ)b2(γ+1)c2+3(1−aρ)b2, | (1.5) |
[μ2(ρ)]′=2aρ(γ+1)c4+[2(γ−2)2+14aρ(γ−1)+aρ(18aρ−8)]b2c2ρ[(γ+1)c2+(1−aρ)3b2], | (1.6) |
m(ρ)=(3−γ−4aρ)c2+(1−aρ)b2(γ+1)c2+3(1−aρ)b2, | (1.7) |
m′(ρ)=−aρ[γ+γ2+4(1−aρ)]c4+[27aρ(1−γ)+aρ(17−36aρ)−4(γ−2)2](1−aρ)b2c2((γ+1)c2+(1−aρ)b2)2(1−aρ), | (1.8) |
Π(ˆρ)=−ˆw2γ(γ−1)[γ(γ+1)−2(γ+1)aˆρ+2a2ˆρ2], | (1.9) |
Π′(ˆρ)=−Aγˆργ−2(γ−1+2aˆρ)+μκ20(1−aˆρ)γ+2γ(γ−1)(1−aˆρ)γ+2[γ(γ+1)−2(γ+1)aˆρ+2a2ˆρ2]−ˆw2γ(γ−1)[−2(γ+1)a+4a2ρ], | (1.10) |
α0=arcsinw0u0,αv=∫0ρ0ˆw√ˆq2−ˆw2ˆq2ˆρdˆρ,ˉδ(ρ)=arctan√m(ρ),ˆq2=ˆu2+ˆv2,c2=Aγργ−1(1−aρ)γ+1,b2=μk20ρ,c20=Aγργ−10(1−aρ0)γ+1,b20=μk20ρ0,ˉδ∗=ˉδ(0)={arctan√3−γγ+1(1<γ<2)π6(2≤γ<3),w=√c2+b2,w0=√c20+b20, | (1.11) |
where u0>w0 denotes the incoming horizontal velocity as a constant and w0 denotes the incoming magnetoacoustic velocity as a constant. α0 is the maximum characteristic inclination of the C+ characteristic curve of the centered simple wave at point O, and αv is the minimum characteristic inclination of the C+ characteristic curve of the centered simple wave at point O, which is determined by (3.26). The variable (u,v,ρ)(ξ,η) is controlled by (ξ,η), and in order to solve for the main part of the properties of the centered simple wave, we have changed the variable to a variable controlled by a single parameter α, (ˆu,ˆv,ˆρ)(α), and ˆw, ˆu, and ˆv are determined by (3.25). b as the Alfven velocity, c as the speed of sound, and w=√c2+b2 as the speed of magneto-sound. b0, c0, and w0=√c20+b20 denote the Alfven velocity of the incoming flow at t = 0, the speed of sound, and the speed of magnetoacoustic sound, respectively. All other symbols are for ease of expression and calculation and have no real physical meaning.
For the convenience of the following proof, we assume that there exists a constant ρ1, such that the following condition holds for any ρ<ρ1 when 0<aρ1<1
μ2(ρ)>0,[μ2(ρ)]′>0,m(ρ)>0,m′(ρ)<0,Π(ρ)<0,Π′(ρ)<0. | (1.12) |
In this paper, we study the Riemannian problem of a supersonic magnetic fluid with Noble-Abel gas diffusing into the vacuum around a convex corner, which is essentially the interaction of a centered simple wave with a planar simple wave and which can be solved by reducing it to a Goursat problem. The solution's hyperbolicity and a priori C1 estimates are established using characteristic decompositions and invariant regions. In addition, pentagonal invariant regions are constructed to obtain global solutions. In addition, the generality of this gas, the sub-invariant region, is constructed, and the solved hyperbolicity is obtained based on the continuity of the sub-invariant region. Finally, the global existence of the solution to the gas expansion problem is constructively obtained. The main results of this paper are as follows:
Theorem 1.1. If u0>w0, θ≤αv, ρ0<ρ1,max(α0−4ˉδ(ρ0)+4ˉδ∗−π2,α0−αv−2ˉδ(ρ0))<0, then the problem of a magnetoacoustic velocity flow with Noble–Abel gas expanding into vacuum at the convex corner (1.1)–(1.4) has a global classical solution.
The structure of the paper is as follows: In Section 2, the characteristic forms and characteristic decompositions related to the characteristic direction, the pseudo-flow direction, and the Mach angle are given. In Section 3, we provide the expressions for the centered simple and planar simple waves. In Section 4, the primary study is the interaction problem of centered simple and planar simple waves. The C0, C1, and hyperbolicity estimates of the solutions are obtained. Then, we obtain the existence of global classical solutions. In Section 5, we discuss the shortcomings of Theorem 1.1.
By the self-similar transformation (ξ,η)=(x/t,y/t), the system of Eq (1.1) can be written as
{(ρU)ξ+(ρV)η+2ρ=0,(ρU2+p+μk202ρ2)ξ+(ρUV)η+3ρU=0,(ρUV)ξ+(ρV2+p+μk202ρ2)η+3ρV=0, | (2.1) |
where (U,V)=(u−ξ,v−η) is the pseudo-flow velocity. The initial edge value condition (1.3) and (1.4) are transformed into a boundary conditions in the (ξ,η) plane (refer to Figure 2).
(u,v,ρ)(ξ,η)={(u0,0,ρ0),ξ<0,η≥0,ξ2+η2→∞,vacuum,ξ>0,η≥ξtanθ,ξ2+η2→∞, | (2.2) |
and
{(ρv)(ξ,η)=0,ξ<0,η=0,(ρv)(ξ,η)=(ρu)(ξ,η)tanθ,η<0,ξ=ηcotθ, | (2.3) |
where u0 and ρ0 are two different constants for the horizontal velocity and density of the incoming flow, respectively, and θ is the solid wall inclination.
For smooth solutions, the system of Eq (2.1) can be written in the following form:
{(ρU)ξ+(ρV)η+2ρ=0,UUξ+VUη+U+1ρ(p+μk202ρ2)ξ=0,UVξ+VVη+V+1ρ(p+μk202ρ2)η=0. | (2.4) |
In the case of the irrotational condition uη=vξ, there exist potential functions φ such that φξ=U and φη=V. By the last two equations of (2.4), the pseudo-Bernoulli's law is obtained as follows:
12(U2+V2)+(γ−aρ)(γ−1)⋅Aργ−1(1−aρ)γ+μk20ρ+φ=constant. | (2.5) |
We define b=√μk20ρ as the Alfven velocity, c=√Aγργ−1(1−aρ)γ+1 as the speed of sound, and w=√c2+b2 as the speed of magneto-sound. Through the irrotational condition uη=vξ, the system of Eq (2.4) can be transformed into
{(w2−U2)uξ−UV(uξ+vη)+(w2−V2)vη=0,vξ−uη=0. | (2.6) |
The matrix form of system (2.6) is as follows:
(w2−U2−UV01)(uv)ξ+(−UVw2−V2−10)(uv)η=0. | (2.7) |
The eigenvalues Λ of system (2.7) are given by
(w2−U2)Λ2+2UVΛ+(w2−V2)=0. | (2.8) |
That is
(V−ΛU)2−w2(1+Λ2)=0, | (2.9) |
which yields
Λ±=UV±√w2(U2+V2−w2)U2−w2. | (2.10) |
(2.10) indicates that when U2+V2>w2, the system (2.7) is hyperbolic, with two families of wave characteristics defined by
dηdξ=Λ±. | (2.11) |
Taking into account Eq (2.9), it is evident that w is essentially a projection of the pseudo-flow velocity in the normal direction of the C± feature line. The eigenvectors on the left side that correspond to the eigenvalues Λ± are
l±=(1,∓√w2(U2+V2−w2)). | (2.12) |
By left-multiplying (2.12) by (2.7), the system of Eq (2.7) can be transformed into the following characteristic form:
{∂+u+Λ−∂+v=0,∂−u+Λ+∂−v=0, | (2.13) |
where ∂±=∂ξ+Λ±∂η.
We define the characteristic inclinations α,β of Λ+ and Λ− as follows:
tanα=Λ+,tanβ=Λ−. | (2.14) |
Joining (2.14) and (2.10) yields
tanα−tanβ=2√w2(U2+V2−w2)U2−w2,tanαtanβ=V2−w2U2−w2. | (2.15) |
That is
U4sin2(α−β)−2U2w2(cos2α+cos2β)+w4sin2(α+β)=0. | (2.16) |
The pseudo-streamline inclination is σ=α+β2 and the Mach angle is δ=α−β2 as shown in Figure 3, we have
u=ξ+wcosσsinδ,v=η+wsinσsinδ, | (2.17) |
δ=arcsin(w√U2+V2). | (2.18) |
By the first equation of (2.17), we have
uξ=1+ccξ+bbξ√c2+b2cosσsinδ−√c2+b22αξcosβ−βξcosαsin2δ, | (2.19) |
uη=ccη+bbη√c2+b2cosσsinδ−√c2+b22αηcosβ−βηcosαsin2δ. | (2.20) |
Thus
ˉ∂±u=cos(σ±δ)+cosσsinδˉ∂±w−wcosβˉ∂±α−wcosαˉ∂±β2sin2δ, | (2.21) |
where
ˉ∂+=cosα∂ξ+sinα∂η,ˉ∂−=cosβ∂ξ+sinβ∂η. | (2.22) |
From the second equation (2.17), we can conclude that
vξ=ccξ+bbξ√c2+b2sinσsinδ−√c2+b22αξsinβ−βξsinαsin2δ, | (2.23) |
vη=1+ccη+bbη√c2+b2sinσsinδ−√c2+b22αηsinβ−βηsinαsin2δ. | (2.24) |
Subsequently
ˉ∂±v=sin(σ±δ)+sinσsinδˉ∂±w−wsinβˉ∂±α−wsinαˉ∂±β2sin2δ, | (2.25) |
ˉ∂±w=cˉ∂±c+bˉ∂±b√c2+b2=Aγργ−2[(γ−1)+2aρ]+μκ20(1−aρ)γ+22w(1−aρ)γ+2ˉ∂±ρ. | (2.26) |
According to (2.5), we have
Uˉ∂±u+Vˉ∂±v+˜p′(ρ)˜∂±ρ=0, | (2.27) |
where
˜p′(ρ)=Aγργ−2(1−aρ)γ+1+μκ20. | (2.28) |
(2.13) and (2.27) lead to
ˉ∂+u=Λ−˜p′(ρ)V−Λ−Uˉ∂+ρ, | (2.29) |
ˉ∂+v=˜p′(ρ)UΛ−−Vˉ∂+ρ, | (2.30) |
ˉ∂−u=Λ+˜p′(ρ)V−Λ+Uˉ∂−ρ, | (2.31) |
ˉ∂−v=˜p′(ρ)UΛ+−Vˉ∂−ρ. | (2.32) |
Substituting (2.14), (2.17), (2.26), and (2.28) into (2.29)–(2.32) reaches
ˉ∂+u=2(c2+b2)sinβM(ρ)c2+b2ˉ∂+w,ˉ∂−u=−2(c2+b2)sinαM(ρ)c2+b2ˉ∂−w, | (2.33) |
ˉ∂+v=−2(c2+b2)cosβM(ρ)c2+b2ˉ∂+w,ˉ∂−v=2(c2+b2)cosαM(ρ)c2+b2ˉ∂−w, | (2.34) |
where
M(ρ)=γ−1+2aρ1−aρ. | (2.35) |
Associating (2.21), (2.25), (2.33), and (2.34), we obtain
wˉ∂+α=−sin2δ2μ2(ρ)Ω(δ,ρ)ˉ∂+w, | (2.36) |
wˉ∂+β=−tanδμ2(ρ)ˉ∂+w−2sin2δ, | (2.37) |
wˉ∂−α=tanδμ2(ρ)ˉ∂−w+2sin2δ, | (2.38) |
wˉ∂−β=sin2δ2μ2(ρ)Ω(δ,ρ)ˉ∂−w, | (2.39) |
where
Ω(δ,ρ)=m(ρ)−tan2δ. | (2.40) |
In this section, we compute the characteristic decomposition of w using the commutator relations and the characteristic equations of α, β, w, and u.
Lemma 2.1. The commutator relations (Li, Zhang, and Zheng [27]).
ˉ∂−ˉ∂+−ˉ∂+ˉ∂−=1sin(2δ){(cos(2δ)ˉ∂+β−ˉ∂−α)ˉ∂−−(ˉ∂+β−cos(2δ)ˉ∂−α)ˉ∂+}. | (2.41) |
Lemma 2.2.
wˉ∂+ˉ∂−w=ˉ∂−w{sin2δ+ˉ∂−w2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+N(ρ))ˉ∂+w}, | (2.42) |
wˉ∂−ˉ∂+w=ˉ∂+w{sin2δ+ˉ∂+w2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+N(ρ))ˉ∂−w}, | (2.43) |
where
N(ρ)=a(γ+1)ρc2(c2+b2)+c2b2(γ−2+3aρ)2((γ−1+2aρ)c2+(1−aρ)b2)2. | (2.44) |
Proof. From Lemma 2.1
ˉ∂+ˉ∂−u−ˉ∂−ˉ∂+u=−1sin(2δ){(cos(2δ)ˉ∂+β−ˉ∂−α)ˉ∂−u−(ˉ∂+β−cos(2δ)ˉ∂−α)ˉ∂+u}. | (2.45) |
Substituting (2.33) into (2.45), we have
ˉ∂+(−2(c2+b2)sinαM(ρ)c2+b2ˉ∂−w)−ˉ∂−(2(c2+b2)sinβM(ρ)c2+b2ˉ∂+w)=−1sin2δ{(cos(2δ)ˉ∂+β−ˉ∂−α)(−2(c2+b2)sinαM(ρ)c2+b2)ˉ∂−w−(ˉ∂+β−cos(2δ)ˉ∂−α)2(c2+b2)sinβM(ρ)c2+b2ˉ∂+w}. | (2.46) |
Simplifying and combining gives
sinαˉ∂+ˉ∂−w+sinβˉ∂−ˉ∂+w={−1sin2δ(cos(2δ)ˉ∂+β−ˉ∂−α)sinα+2N(ρ)sinα⋅wˉ∂+w−cosαw⋅2Θcos2δ−cos2δΘsin2δˉ∂+w}ˉ∂−w+{sinβsin2δ(cos(2δ)ˉ∂−α−ˉ∂+β)+2N(ρ)sinβ⋅wˉ∂−w+cosβw⋅2Θcos2δ−cos2δΘsin2δˉ∂−w}ˉ∂+w, | (2.47) |
where
Θ(δ,ρ)=M(ρ)c2+b22[2w2sin2δ+M(ρ)c2+b2]. | (2.48) |
Inserting (2.37) and (2.38) into (2.47) and using the commutator relation (2.41), we obtain
w(sinα+sinβ)ˉ∂+ˉ∂−w=−wsin2δ(cos(2δ)ˉ∂+β−ˉ∂−α)(sinα+sinβ)ˉ∂−w+2N(ρ)(sinα+sinβ)ˉ∂+wˉ∂−w+(cosα−cosβ)sin2δ2μ2(ρ)Ω(δ,ρ)ˉ∂+wˉ∂−w. | (2.49) |
Thus, we have
wˉ∂+ˉ∂−w={sin2δ−2Θcos2δ−1Θsin2(2δ)ˉ∂−w+(2Θ(4sin2δ−1)cos2(2δ)Θsin2(2δ)+2N(ρ))ˉ∂+w}ˉ∂−w. | (2.50) |
Using a simple calculation, we have
2Θ(δ,ρ)(4sin2δ−1)cos2δ+cos2(2δ)Θ(δ,ρ)sin2(2δ)=1+Ω(δ,ρ)cos2δ2μ2(ρ), | (2.51) |
and
2Θ(δ,ρ)cos2δ−1Θ(δ,ρ)sin2(2δ)=−12μ2(ρ)cos2δ. | (2.52) |
Therefore, (2.42) is established. The proof of (2.43) is similar, so we will not prove it in detail here.
In this section, we focus on constructing centered and planar simple waves.
In order to construct the centered simple wave solution for isentropic irrotational pseudo-steady flow at convex corners, we first discuss the nature of the general centered simple wave principal part of the equation.
According to the definition [28] of a centered simple wave, its solution (u,v,ρ)(ξ,η) can be determined by the direct characteristic line η=ξtanα and the function (u,v,ρ)(ξ,η)=(¯u,¯v,¯ρ)(r,α) defined on the rectangular region ˜Λ(t)={(ξ,η)∣0≤r≤ζ,˜α2≤α≤˜α1}, see Figure 4. It is easy to see that ξ=rcosα and η=rsinα, there are
∂r∂ξ=cosα,∂r∂η=sinα,∂α∂ξ=−1rsinα,∂α∂η=1rcosα,(u,v,ρ)(ξ,η)=(¯u,¯v,¯ρ)(ξ,α),∂∂ξ=∂∂ξ+tanα∂∂η,∂∂α=ξcos2α∂∂η. | (3.1) |
From the systems (2.13) and (2.5), it is clear that the main parts (u,v,ρ)(ξ,η) of the C+ type centered simple wave satisfy
{∂¯u∂ξ+tanβ∂¯v∂ξ=0,−ξ(1+tan2α)∂¯v∂ξ+∂¯u∂α+tanα∂¯v∂α=0,12[(¯u−ξ)2+(¯v−ξtanα)2]+(γ−a¯ρ)(γ−1)⋅A¯ργ−1(1−a¯ρ)γ+¯b2+¯φ=constant. | (3.2) |
For the potential function φ, we have
ξ∂¯φ∂ξ=tanα+cotσ1+tan2α∂¯φ∂α. | (3.3) |
Let ξ→0, then (3.2) and (3.3) become
dˆudα+tanαdˆv(α)dα=0,ˆφ(α)=constant, | (3.4) |
12(ˆu2(α)+ˆv2(α))+(γ−aˆρ)(γ−1)⋅Aˆργ−1(1−aˆρ)γ+ˆb2(α)=constant, | (3.5) |
tanα=ˆu(α)ˆv(α)+ˆw(α)√ˆu2(α)+ˆv2(α)−ˆw2(α)ˆu2(α)−ˆw2(α), | (3.6) |
where (¯u(0,α),¯v(0,α),¯φ(0,α),¯ρ(0,α))=(ˆu(α),ˆv(α),ˆφ(α),ˆρ(α)).
Lemma 3.1. If the principal part (¯u,¯v,¯ρ)(r,α)=(ˆu,ˆv,ˆρ)(α) satisfies
dˆudα+tanαdˆv(α)dα=0, | (3.7) |
12(ˆu2(α)+ˆv2(α))+(γ−aˆρ)(γ−1)⋅Aˆργ−1(1−aˆρ)γ+ˆb2(α)=constant, | (3.8) |
tanα=ˆu(α)ˆv(α)+ˆw(α)√ˆu2(α)+ˆv2(α)−ˆw2(α)ˆu2(α)−ˆw2(α), | (3.9) |
then (u,v,ρ)(ξ,η)=(ˆu,ˆv,ˆρ)(α),η=ξtanα is the C+ centered simple wave solution of Eq (2.13) at the origin.
Proof. This proof is divided into the following three steps:
Step 1. First: prove that for any given α, the line η=ξtanα is the C+ characteristic curve. This only requires proving that η=ξtanα is circular with the speed of sound (ˆu(α)−ξ)2+(ˆv(α)−η)2=ˆw(α)2 tangent. In fact, substituting η=ξtanα into the velocity circle expression of sound is obtained
(ˆu2+ˆv2−ˆw2)−2[ˆu+ˆvtanα]ξ+(1+tan2α)ξ2=0. | (3.10) |
Substituting (3.8) into (3.9) yields the discriminant of the (3.10) root
Δ=−4[(ˆu2−ˆv2)tan2α−2ˆuˆvtanα+(ˆv2−ˆw2)]=0. | (3.11) |
So, for any given line, η=ξtanα is a C+ straight eigenline.
Step 2. Prove that (u,v,ρ)(ξ,η) satisfies Eq (2.13) in the theorem. According to the definition of (u,v,ρ), it can be known that along C+ straight eigenline is constant, that is, ∂+u=∂+v=∂+ρ=0 and
∂+u+λ−∂+v=0. | (3.12) |
Under condition (3.4), it is obtained that
∂−u+λ+∂−v=(dˆudα+tanαdˆv(α)dα)∂−α=0. | (3.13) |
Step 3. Prove that (u,v,ρ)(ξ,η) satisfies the proposed Bernoulli law in the theorem. This can be obtained from Eqs (3.4) and (3.5).
∂+(12(U2+V2)+(γ−Aρ)γ−1⋅Aργ−1(1−aρ)γ+μκ20ρ+φ)=(u−ξ)∂+u+(v−η)∂+v+Aγργ−2(1−aρ)γ+1∂+ρ+μκ20∂+ρ=0, | (3.14) |
and
∂−(12(U2+V2)+(γ−Aρ)γ−1⋅Aργ−1(1−aρ)γ+μκ20ρ+φ)=(u−ξ)∂−u+(v−η)∂−v+Aγργ−2(1−aρ)γ+1∂−ρ+μκ20∂−ρ=((ˆu−ξ)dˆudα+(ˆv−η)dˆvdα+Aγˆργ−2(1−aˆρ)γ+1dˆρdα+μκ20dˆρdα)∂−α=(ˆudˆudα+ˆvdˆvdα+Aγˆργ−2(1−aˆρ)γ+1dˆρdα+μκ20dˆρdα)∂−α−ξ(dˆudα+tanαdˆvdα)∂−α=0, | (3.15) |
(3.14) and (3.15) show that Bernoulli's law holds.
Next, we obtain the expression of the centered simple wave solution. Since (u,v,ρ)(ξ,η)=(ˆu,ˆv,ˆρ)(α) is the principal part of the centered simple wave for type C+ and α is the characteristic angle of the C+ characteristic line η=ξtanα. We decompose the pseudo-flow velocity (U,V)=(ˆu(α)−ξ,ˆv(α)−η) along the (sinα,−cosα) and (cosα,sinα) directions, respectively. I obtain the velocity components w and g as follows:
¯w(ξ,α)=(ˆu(α)−ξ)sinα−(ˆv(α)−ξtanα)cosα,¯g(ξ,α)=(ˆu(α)−ξ)cosα+(ˆv(α)−ξtanα)sinα. | (3.16) |
When ξ→0, we get
ˆw(α)=ˆu(α)sinα−ˆv(α)cosα,ˆg(α)=ˆu(α)cosα+ˆv(α)sinα,ˆu(α)=ˆg(α)cosα+ˆw(α)sinα,ˆv(α)=ˆg(α)sinα−ˆw(α)cosα. | (3.17) |
It is easy to see that ˆg(α)2+ˆw(α)2=ˆu(α)2+ˆv(α)2, derivation of α in each of the last two equations of (3.17) yields
dˆudα=dˆgdαcosα−ˆgsinα+dˆwdαsinα+ˆwcosα,dˆvdα=dˆgdαsinα+^gcosα−dˆwdαcosα+ˆwsinα. | (3.18) |
Substituting Eq (3.18) into Eq (3.4), we have
ˆgα=−ˆw. | (3.19) |
The derivation of α in Bernoulli's law (3.5) and then the union (3.19) yield
ˆg=(γ+1)ˆc2+3(1−aˆρ)ˆb2(γ−1+2aˆρ)ˆc2+(1−aˆρ)ˆb2ˆwα=ˆwαμ2(ˆρ). | (3.20) |
Then the derivation of α in (3.20) yields
(γ+1)ˆc2+3(1−aˆρ)ˆb2(γ−1+2aˆρ)ˆc2+(1−aˆρ)ˆb2ˆwαα−[(γ+1)aˆρˆw2+(2−γ−3aˆρ)2ˆb2](1−aˆρ)ˆc2[(γ−1+2aˆρ)ˆc2+(1−aˆρ)ˆb2]34ˆw(ˆwα)2+ˆw=0. | (3.21) |
Using the initial value condition (ˆu,ˆv,ˆρ)(α0)=(u0,0,ρ0) to solve Eq (3.21), we have
ˆw=∫αα0μ2(ˆρ)√Π(ˆρ)+Π0dα+w0,ˆg=ˆwαμ2(ˆρ)=√Π(ˆρ)+Π0, | (3.22) |
in which
Π(ˆρ)=−ˆw2γ(γ−1)[γ(γ+1)−2(γ+1)aˆρ+2a2ˆρ2], | (3.23) |
and
Π0=u20−w20+w20γ(γ−1)[γ(γ+1)−2(γ+1)aρ0+2a2ρ20]. | (3.24) |
According to (3.17), it is not hard to obtain
ˆu=√Π(ˆρ)+Π0cosα+ˆwsinα,ˆv=√Π(ˆρ)+Π0sinα−ˆwcosα,ˆw=∫αα0μ2(ˆρ)√Π(ˆρ)+Π0dα+w0. | (3.25) |
Lemma 3.2. Suppose ρ0<ρ1 and θ≤αv, then RC is a complete simple wave that connects the constant state with the vacuum (see Figure 5), where α0 and αv satisfy
α0=arcsinw0u0,αv=∫0ρ0ˆw√ˆq2−ˆw2ˆq2ˆρdˆρ, | (3.26) |
and ˆq2=ˆu2+ˆv2.
Proof. Deriving and substituting ˆu=ˆqcosσ and ˆv=ˆqsinσ into the first equation of (3.4), and also deriving Eq (3.5), we have
dσdˆq=−cosδˆqsinδ=−√ˆq2−ˆw2ˆqˆw,dˆqdˆρ=−ˆw2ˆqˆρ. | (3.27) |
Therefore, we have
σ=∫ˆρρ0ˆw√ˆq2−ˆw2ˆq2ˆρdˆρ, | (3.28) |
it is easy to see that αv=limρ→0σ. By deflating αv one obtains
αv∈(−1u0(γ−aρ0γ−1⋅Aργ−10(1−aρ0)γ+μκ20ρ0),0). | (3.29) |
So αv is bounded.
By (1.1) and its initial value condition
(u,v,ρ)(x,y,0)={(u0,0,ρ0),n1x+n2y<0,Vacuum,n1x+n2y>0, | (3.30) |
where n21+n22=1.
By coordinate transformations ˆx=n1x+n2y, ˆy=−n2x+n1y, let ˆu=n1u+n2v, ˆv=−n2u+n1v. Solving a 1-D Riemann problem, we obtain
(ˆu,ˆv,ˆρ)(ˆx,ˆy,t)={Vacuum,ˆξ>ˆξ1,(ur,0,ρr),ˆξ2≤ˆξ≤ˆξ1,(u0,0,ρ0),ˆξ<ˆξ2, | (3.31) |
where ˆξ=ˆxt, ˆξ1=limρr→0ur(ρr), ˆξ2=u0−w(ρ0). The functions ur(ˆξ) and ρr(ˆξ) are implicitly determined by
ur=u0+∫ρrρ0√c2+b2ρdρ(ρr<ρ0),ˆξ=ur−w(ρr). | (3.32) |
Therefore, the solutions of (1.1) and (3.30) are obtained as follows:
(u,v,ρ)(x,y,t)={Vacuum,ˆξ>ˆξ1,(n1ur,n2ur,ρr),ˆξ2≤ˆξ≤ˆξ1,(u0,0,ρ0),ˆξ<ˆξ2. | (3.33) |
Suppose that the centered simple wave Rc and the planar simple wave Rp start to interact at point I(u0−w0,w0√u0−w0u0+w0) to form an interaction region Ω. Ω is enclosed by the C− penetrating characteristic curve ~IH of the centered simple wave Rc, the C+ penetrating characteristic curve ~IK of the backward planar simple wave Rp, and the interface ~HK between the gas and the vacuum region, where ~IH is determined by the centered simple wave Rc and point Ⅰ, while ~IK is determined by the planar simple wave Rp and point Ⅰ; see Figure 5.
According to [29], a simple calculation yields the following parametric expression for ~IK with respect to the density ρ
{ξ=u0−w+∫ρρ0√Aγτγ−1(1−aτ)γ+1+μκ20ττdτ,η={ρwρ0w0[w20u0−w0u0+w0−ρ0w0∫ρρ0(γ+1)Aγτγ−2(1−aτ)γ+2+3μκ202τ√Aγτγ−1(1−aτ)γ+1+μκ20τdτ]}12, | (4.1) |
where
w0=√Aγργ−10(1−aρ0)γ+1+μκ20ρ0. | (4.2) |
From (4.1), when ρ=0, the coordinates of the point K can be obtained as
K(ξ,η)=(u0−∫ρ00wρdρ,0). | (4.3) |
The solution of the system of Eqs (2.1)–(2.3) outside the interaction region a consists of the constant state (u0,0,w0), the vacuum state, the centered simple wave Rc, and the backward planar simple wave Rp; see Figure 5. Solving the solution of the system of Eq (2.1) in the interaction region Ω boils down to a Goursat problem, i.e., the system of Eq (2.1) as well as the boundary conditions
(u,v,ρ)(ξ,η)={(u+,v+,ρ+)(ξ,η),on~IK,(u−,v−,ρ−)(ξ,η),on~IH, | (4.4) |
where (u±,v±,ρ±)(ξ,η) is determined by the simple wave Rp (Rc).
Lemma 4.1. For any ρ∈(0,ρ0), Ωwρ denotes the region enclosed by the C+ characteristic curve ~IK1, the C− characteristic curve ~IH1, and the isomagnetoacoustic velocity line w(ξ,η)=wρ. Here K1 and H1 are the intersections of the isomagnetoacoustic velocity line w(ξ,η)=wρ with ~IK and ~IH, respectively. When ρ is sufficiently close to ρ0, then there exists a unique C1 solution to the Goursat problem (2.1) and (4.4) on Ωwρ.
Proof. According to the theory of the existence of local classical solutions of hyperbolic equations [28], there is a local C1 solution to the Goursat problems (2.4) and (4.4). Thus, there is a sufficiently small normal number such that ε Goursat problems (2.4) and (4.4) have a C1 solution on Σε, where Σε is the closed region bounded by ~IK, ~IH, and the straight line
ξ=u0−w0+ε. | (4.5) |
Let
l=supξ=u0−w0+εw(ξ,η). | (4.6) |
In the planar simple wave Rp, we have β=−π2. Combining with Eq (2.36), on the C+ characteristic curve ~IK, we obtain
ˉ∂+w=−[γ−1+2aρ1−aρc2+b2γ+11−aρc2+3b2]sin(2δ)<0. | (4.7) |
Similarly, in the centered simple wave Rc, from Eq (2.37), on the C− characteristic curve ~IH, we have
ˉ∂−w=μ2(ρ)tanα[wˉ∂−α−2sin2δ]<0. | (4.8) |
Combining with (4.7), (4.8), (2.42), and (2.43), we have ˉ∂±w<0 in the region Σε, evidently, l<w0. Therefore, there exists a unique C1 solution to the Goursat problem on Ωwρ.
Lemma 4.2. On the C+ characteristic curve ~IK, there is
ˉδ(ρ0)<δ≤α02+π4,β=−π2. | (4.9) |
Meanwhile, on the C− characteristic curve ~IH, there is
αv≤α≤α0,min(αv−2ˉδ∗,−π2)≤β<α0−2ˉδ(ρ0), | (4.10) |
where
ˉδ(ρ)=arctan√m(ρ),ˉδ∗={arctan√3−γγ+1(1<γ<2)π6(2≤γ<3),ˉδ(ρ(E))=δ(E). | (4.11) |
Proof. In view of (2.36), we have
wˉδ+δ=−sin(2δ)4μ2(ρ)[m(ρ)−tan2δ]ˉ∂+w. | (4.12) |
Due to
m(ρ)>0,m′(ρ)<0. | (4.13) |
We have
ˉδ′(ρ)<0,limρ→0ˉδ=ˉδ∗<π4. | (4.14) |
Moreover
2δ(ρ0)=α0+π2>2ˉδ(ρ0). | (4.15) |
Due to ˉ∂+m(ρ)>0, we have the following two possible cases, see Figure 6.
Case 1. If the functions f and g have no intersection within (0,ρ0), then we have
ˉδ∗≤δ≤α02+π4,2ˉδ∗−π2≤α≤α0,β=−π2,δ>ˉδ(ρ)on~IK. | (4.16) |
Case 2. If the functions f and g intersect at point E in the range (0,ρ0), then we have m(ρ(E))=tan2δ(E). Clearly, tan2δ>m(ρ) holds on IE. Then, we get ˉ∂+δ∣~IE<0 and
ˉδ(ρ(E))≤δ≤α02+π4,2ˉδ(ρ(E))−π2<α<α0,β=−π2on~IE. | (4.17) |
Furthermore, there are tan2δ<m(ρ) holds on EK; otherwise, there exists a point E1 on EK such that ˉ∂+δ(E1)=0, and m′(ρ)<0. According to (4.12), ˉ∂+δ(E1)<0 holds, which contradicts the hypothesis. It is not difficult to obtain
ˉδ(ρ(E))<δ<ˉδ∗,2ˉδ(ρ(E))−π2<α<2ˉδ∗−π2,β=−π2on~EK. | (4.18) |
Based on ˉδ∗>ˉδ(ρ0) and ˉδ(ρ(E))>ˉδ(ρ0), it is not difficult to obtain (4.9).
Similarly, by (2.39), on the C− cross characteristic curve ~IH, we obtain
wˉ∂−β=sin(2δ)2μ2(ρ)[m(ρ)−tan2δ]ˉ∂−w, | (4.19) |
we discuss this in the following two cases:
Case 1. If ¯δ(ρ)≤δ as αv≤α≤α0. According to Eq (4.19), we have
−π2≤β<α0−2¯δ∗,¯δ(ρ)≤δon~IH. | (4.20) |
Case 2. If not, there must exist a point F between δ=¯δ(ρ0) and δ=¯δ∗ such that δ(F)=¯δ(ρ(F)). Clearly, δ>ˉδ holds on IF. Then, we obtain ¯∂−β∣IF>0 and
−π2≤β≤β(F)on~IF. | (4.21) |
Additionally, there is δ<ˉδ holds on ~FH; otherwise, there exists a point F1 on ~FH such that ˉ∂−β(F1)=0, and m′(ρ)<0. According to (4.19), ˉ∂−β(F1)<0 holds, which contradicts the hypothesis. It is not difficult to get
αv−2ˉδ∗≤β≤β(F)on~FH. | (4.22) |
Based on α0−2ˉδ∗<α0−2ˉδ(ρ0) and β(F)<α0−2ˉδ(ρ0), it is not difficult to obtain (4.10). Then, this lemma can be obtained.
Lemma 4.3. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, and max(α0−4ˉδ(ρ0)+4ˉδ∗−π2,α0−αv−2ˉδ(ρ0))<0, then the characteristic inclination (α,β) within Ω˜ρ satisfies
α_<α<¯α,β_<β<¯β,2δ_<α−β<π, | (4.23) |
where
¯α=2ˉδ∗+α0−2ˉδ(ρ0),α_=min(2ˉδ(ρ0)−π2,αv),¯β=α0−2ˉδ(ρ0),β_=min(αv−2ˉδ∗,−π2+2ˉδ(ρ0)−2ˉδ∗),¯α−¯β=2ˉδ∗,α_−β_=2ˉδ∗, | (4.24) |
for every ˜ρ∈(0,ρ0) (Figure 7).
Proof. Assume
Σε1={(α,β)∣α_−ε<α<¯α+ε,β_−ε<β<¯β+ε,2δ_<α−β}, | (4.25) |
where ε is any positive number close to zero and δ_ is a sufficiently small constant satisfied by 0<δ_<αv2−α02+ˉδ(ρ0), such that
1−(1−cos2δ⋅Ω)M1μ2(ρ)sin(2δ)>0asδ≤δ_. | (4.26) |
It is easy to see that when max(α0−4ˉδ(ρ0)+4ˉδ∗−π2,α0−αv−2ˉδ(ρ0))<0, we have
(¯α+ε)−(β_−ε)=2ˉδ∗+α0−2ˉδ(ρ0)+ε−min(αv−2ˉδ∗−ε,−π2+2ˉδ(ρ0)−2ˉδ∗−ε)=max(α0+4ˉδ∗−2ˉδ(ρ0)+2ε,α0+4ˉδ∗−4ˉδ(ρ0)+π2+2ε)<π. | (4.27) |
Therefore, we have 0<2δ_<α−β<π, which shows that Σε1 satisfies the hyperbolicity condition. Choose any point P in Ω˜ρ, we have a C+ characteristic curve ~PH2 and a C− characteristic curve ~PK2, where H2∈~IH and K2∈~IK. ΩP is a closed region delimited by the corresponding characteristic curves ~PK2, ~PH2, ~IH2 and ~IK2.
Provide that (α,β)(ξ,η)∈Σε1 for (ξ,η)∈ΩP∖{P}, then we have
(α,β)(ξ,η)∈ΣεP, | (4.28) |
for all (ξ,η)∈ΩP, where
ΣεP={(α,β)∣α_−ε<α<¯αP+ε,β_P−ε<β<¯β+ε,2δ_<α−β<¯αP−β_P},¯αP−¯β=2ˉδP,α_−β_P=2ˉδP. | (4.29) |
This lemma can be obtained. From Lemma 4.2, we obtain
(α,β)(ξ,η)∈ΣεP,as(ξ,η)∈~IH2∪~IK2. | (4.30) |
Let
γ1={α=α_−ε,β_P−ε<β<¯β+ε,α−β>2δ_},γ2={α_−ε<α<¯αP+ε,β=¯β+ε,α−β>2δ_},γ3={α=¯αP+ε,β_P−ε≤β<¯β+ε},γ4={α_−ε<α<¯αP+ε,β=β_P−ε},γ5={α=¯αP+ε,β=¯β+ε},γ6={α=α_−ε,β=β_P−ε},γ7={α_−ε≤α≤¯αP+ε,β_P−ε≤β≤¯β+ε,α−β=2δ_}.
Assuming that (4.28) does not hold, there exists a point Q in the region ΩP for which (α,β)(Q)∈⋃6i=1γi and (α,β)(ξ,η)∈ΣεP hold for all (ξ,η)∈ΩQ∖{Q}, where ΩQ is the closed region bounded by the characteristic curves ~QK3, ~QH3, ~IH3, and ~IK3. The C− characteristic curve through point Q intersects ~IK at point K3, and the C+ characteristic curve through point Q intersects ~IH at point H3.
If (α,β)(Q)∈γ1, on the basis of the assumed condition that (α,β)(ξ,η)∈Σε1 as (ξ,η)∈ΩP∖{P}, we have Q = P, according to (2.36), we obtain
wˉ∂+α(Q)=−sin2δ2μ2(ρ)[tan2ˉδP−tan2δ(ρ(Q))]ˉ∂+w>0. | (4.31) |
But based on our assumptions, we have
α(ξ,η)>α(Q)=α_−ε,∀(ξ,η)∈~H3Q∖{Q}. | (4.32) |
Thus, we obtain ˉ∂+α(Q)≤0, and that contradicts my assumptions.
If (α,β)(Q)∈γ2, we can export contradictions similarly.
If (α,β)(Q)∈γ3, it is not hard to obtain ˉδ(ρ(Q))≤ˉδ(ρ(P))<δ(ρ(Q)). Then, we obtain
wˉ∂+α(Q)=−sin2δ2μ2(ρ)[tan2ˉδQ−tan2δ(ρ(Q))]ˉ∂+w<0. | (4.33) |
But based on our assumptions, we have
α(ξ,η)<α(Q)=¯αP+ε,∀(ξ,η)∈~H3Q∖{Q}. | (4.34) |
Similarly, we obtain ˉ∂+α(Q)≥0. And that contradicts my assumptions.
If (α,β)(Q)∈γ4, we can export contradictions similarly.
If (α,β)(Q)∈γ5, we define ˜α on ~H3Q as follows:
{wˉ∂+˜α=−sin2δ2μ2(ρ)[tan2ˉδP−tan2(˜α−¯αP−ε2)]ˉ∂+w,˜α(H3)=α(H3). | (4.35) |
Let z=tan˜α−¯αP−ε2; (4.35) becomes
{wˉ∂+z=−14μ2(ρ)sin(2δ)(1+z2)(tan2ˉδP−z2),z(H3)=tanα(H3)−¯αP−ε2<tanˉδP. | (4.36) |
A simple calculation based on the method of Lemma 4.2 in [6] yields
˜α(Q)<2ˉδP+¯αP+ε. | (4.37) |
Combining (2.36) and (4.35), we have
{wˉ∂+(˜α−α)=−sin2δ2μ2(ρ)[tan2ˉδP−tan2ˉδ]ˉ∂+w+sin2δ2μ2(ρ)[tan2(˜α−¯αP−ε2)−tan2(α−β2)]ˉ∂+w,(˜α−α)(H3)=0. | (4.38) |
Substituting ˜α(H3)=α(H3) into the first equation of (4.38), we obtain ˉ∂+(˜α−α)(H3)>0. We assert that (˜α−α)(¯H)≥0, ¯H∈~H3Q. If not, there must be a point H∗∈~H3Q∖{H3,Q} such that (˜α−α)(H∗)=0 and (˜α−α)(ξ,η)>0, ∀(ξ,η)∈~H3H∗∖{H3,H∗}. Thus, ˉ∂+(˜α−α)(H∗)≤0. On the other hand, according to the hypothesis, there are (α,β)(H∗)∈ΣεP holds, and we obtain ˉ∂+(˜α−α)(H∗)>0 according to equation (4.38), which contradicts ˉ∂+(˜α−α)(H∗)≤0. Therefore, we have α(Q)≤˜α(Q)<2ˉδP+¯αP+ε, and that contradicts our assumptions.
If (α,β)(Q)∈γ6, we can export contradictions similarly.
If (α,β)(Q)∈γ7, we have ˉ∂−δ(Q)≤0. According to (2.38), (2.39), and (4.26), it is obtained that
wˉ∂−δQ=12[tanδμ2(ρ)ˉ∂−w+2sin2δ−sin(2δ)2μ2(ρ)Ω(δ,ρ)ˉ∂−w]=tanδ2μ2(ρ)(1−cos2δ⋅Ω)ˉ∂−w+sin2δ>(1−(1−cos2δ⋅Ω)M1μ2(ρ)sin(2δ))sin2δ>0, | (4.39) |
and that contradicts our assumptions. Based on the above discussion, when ε tends to zero, it is easy to get this lemma.
Lemma 4.4. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, then there exists a constant M0>0 independent of ˜ρ such that
‖(u,v,ρ,φ)‖C0(Ω˜ρ)<M0, | (4.40) |
where ˜ρ∈(0,ρ0).
Proof. According to Lemma 4.3 and Eqs (2.5) and (2.17), we have
{(uv)=(ξη)+wsinδ(cosσsinσ),12(U2+V2)+(γ−aρ)(γ−1)⋅Aργ−1(1−aρ)γ+μκ20ρ+φ=constant, | (4.41) |
in the domain Ω˜ρ, then the lemma is easy to proved.
Lemma 4.5. If there exists a C1 solution to the Goursat problem (2.1) and (4.4) in Ω˜ρ, then we have
(ˉ∂+w,ˉ∂−w)∈(−M1,0)×(−M1,0), | (4.42) |
in the domain Ω˜ρ, where
M1=max{2μ2(ρ0),√Π0√u20−w20μ2(ρ0)}. | (4.43) |
Proof. From Eq (4.7) and μ2(ρ)>0, we obtain
−μ2(ρ0)≤−μ2(ρ)=−[γ−1+2aρ1−aρc2+b2γ+11−aρc2+3b2]<ˉ∂+w∣~IK<0. | (4.44) |
Moreover, according to (3.22), (1.12), and (3.1), they lead to
ˆwα=μ2(ρ)√Π(ρ)+Π0>0, | (4.45) |
ˉ∂−w∣~IH=ˆwα(cosβ⋅∂ξα+sinβ⋅∂ηα)=−ˆwαgsin(2δ)=−μ2(ρ)√Π(ρ)+Π0⋅sin(2δ)g>−√Π0⋅μ2(ρ0)√u20−w20. | (4.46) |
Based on the characteristic decompositions (2.42) and (2.43), we find by calculation that
1+Ω(ξ,η)cos(2δ)2μ2(ρ)=1+(m(ρ)−tan2δ)cos(2δ)2μ2(ρ)=1+[(1−2μ2(ρ))cos2δ−sin2δ]cos(2δ)2μ2(ρ)cos2δ=μ2(ρ)(1−2cos2(2δ))+cos2(2δ)2μ2(ρ)cos2δ=μ2(ρ)+m(ρ)cos2(2δ)2μ2(ρ)cos2δ>0. | (4.47) |
Then, we obtain
1+Ω(ξ,η)cos(2δ)2μ2(ρ)+(c2+b2)c2a(γ+1)ρ+c2b2(γ−2+3aρ)2[(γ−1+2aρ)c2+(1−aρ)b2]2>0. | (4.48) |
Next, using the converse, we prove the consistent boundedness of ˉ∂±w. Suppose that the conclusion of Lemma 4.5 does not hold, and that there exists a point P0 inside Ω˜ρ such that ˉ∂−w(P0)=−M1, ˉ∂+w(P0)∈[−M1,0) and (ˉ∂+w,ˉ∂−w)∈(−M1,0)×(−M1,0) in ΩP0∖{P0}, where ΩP0 is the region bounded by the C+ characteristic curve ~P0H0 over the point P0 and the C− characteristic curve ~P0K0 over the point P0 and ~IK, ~IH. According to (2.42), we have
wˉ∂+ˉ∂−w(P0)=ˉ∂−w{sin2δ+ˉ∂−w2μ2(ρ)cos2δ+(1+Ω(δ,ρ )cos2δ2μ2(ρ)+(c2+b2)c2a(γ+1)ρ+c2b2(γ−2+3aρ)2[(γ−1+2aρ)c2+(1−aρ)b2]2)ˉ∂+w}>ˉ∂−w{sin2δ+ˉ∂−w2μ2(ρ)cos2δ}≥ˉ∂−w{sin2δ−1cos2δ}>0. | (4.49) |
However, this would contradict the hypothesis, so ˉ∂−w(P0)∈(−M1,0). Similarly, ˉ∂+w(P0)∈(−M1,0) can be proved, and applying the continuity method yields (ˉ∂+w,ˉ∂−w)∈(−M1,0)×(−M1,0) in the domain Ω˜ρ.
Lemma 4.6. If there exists a C1 solution to Goursat problem (2.1) and (4.4) in Ω˜ρ, then there exists a constant M2>0 independent of ˜ρ such that
‖Du,Dv,Dρ‖C0(Ω˜ρ)<M2, | (4.50) |
where ˜ρ∈(0,ρ0).
Proof. The derivation of both sides of w2=c2+b2 in the direction of the C± characteristic curve can be obtained
ˉ∂±ρ=2(1−aρ)√Aγργ−1(1−aρ)γ+1+μκ20ρ(1−aρ)2γ+2Aγργ−2(γ−1+2aρ)+μκ20(1−aρ)γ+2ˉ∂±w. | (4.51) |
Observe
∂ξ=−sinβˉ∂+−sinαˉ∂−sin(2δ),∂η=cosβˉ∂+−cosαˉ∂−sin(2δ). | (4.52) |
From Lemma 4.5, (2.33), and (2.34), it is known that there exists a normal number M2 independent of ˜ρ.
Lemma 4.7. There is a global classical solution for the boundary problem (2.1) and (4.4) in the region Ω, where the Ω region is bounded by the C+ characteristic curve ~IK, the C− characteristic curve ~IH, and the vacuum boundary ~HK.
Proof. Suppose that the Goursat problem has a C1 solution on the area Ω˜ρ, where ˜ρ∈(0,ρ0). Similarly to the proof of Theorem 4.12 in [6], we have that the isomagnetic sound velocity line ρ(ξ,η)=˜ρ is Lipschitz continuous. The isomagnetic sound velocity line ρ(ξ,η)=˜ρ is solvable to length. Let P0,P1,P2,…,Pn be ρ(ξ,η)=˜ρ on sequentially different n + 1 points; P0 is located in ~IH, and Pn is located in ~IK. The C+ eigencurve through point Pi intersects the C− characteristic curve through the point Pi−1 at point Ii, where i=0,1,…,n−1. The contour ρ(ξ,η)=˜ρ is a non-characteristic curve, for any i=0,1,…,n−1, both Pi≠Ii and Pi−1≠Ii. For any i=0,1,…,n−1, the system of Eq (2.1) is characterized by the characteristic curves ~PiIi and ~Pi−1Ii. The Goursat problem is in the quadrilateral region Ω˜ρ bounded by ~PiIi, ~Pi−1Ii, ~Pi−1Ti, and ~PiTi. There is a global smooth classical solution on Ω˜ρ, where ~PiTi is the C− characteristic curve of the point Pi, and ~Pi−1Ti is the C+ characteristic curve of the point Pi−1.
Let B=T0 and A=Tn+1. For each i=0,1,…,n, there is a 0<˜ρi<˜ρ such that there is a C1 solution on the Goursat problem ρ(ξ,η)=~ρi, ~PiTi and ~PiTi+1 bounded by the characteristic curves ~PiTi and ~PiTi+1. Let ˜ρε=max{˜ρ0,˜ρ1,…,˜ρn,ρ(T1),ρ(T2),…,ρ(Tn)}. We obviously have a relationship ˜ρε<˜ρ established. Then, we obtain the solution to the Goursat problem (2.1) and (4.4) in the region Ω˜ρ. By repeating the above process, we can solve the problem at the regional Ω. So we obtain this lemma.
Thus, we have completed all the discussions and obtained Theorem 1.1. The ideal magnetohydrodynamic system described in Theorem 1.1 can be used to model phenomena in astrophysics, laboratory plasmas, solar physics, etc. It represents an ideal plasma flow interacting with a magnetic field and is described by partial differential equations, including conservation of mass, momentum, total energy, and magnetic field. The conclusion of Theorem 1.1 shows that we only need to control the density ρ0 and velocity u0 of the incoming flow and the solid–wall inclination θ so that they satisfy the conditions. We can guarantee that the problem of expanding a magnetic fluid with a Noble–Abel gas into the vacuum at a convex corner has a global classical solution.
We study the Riemann problem of a supersonic magnetic fluid with Noble-Abel gas diffusing into the vacuum around a convex corner, which is solved by reducing it to a Goursat problem. The solution's hyperbolicity and a priori C0, C1 estimates are established using characteristic decompositions and invariant regions. In addition, pentagonal invariant areas are constructed to obtain a global solution. In addition, sub-invariant regions are built, and the hyperbolicity of the solution is obtained based on the continuity of the sub-invariant regions. Finally, the global existence of the solution to the gas expansion problem is constructively received.
This paper deals with this problem under the special assumption of the solid wall angle θ. For more general cases, the problem requires further attempts and discussions, for example, when the incoming flow velocity is not supersonic but sonic or subsonic. The authors will continue to study these issues later. In addition, we study the complete expansion problem in this work. How about incomplete expansion problems? These problems are interesting. Follow-up studies are needed.
The author declares she have not used Artificial Intelligence (AI) tools in the creation of this article.
The author would like to thank the anonymous referee and editor very much for their valuable comments and suggestions, which greatly help us improve the presentation of this article.
The author declares no conflicts of interest in this paper.
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