Research article

Monotonicity properties and bounds for the complete p-elliptic integrals

  • Received: 15 June 2020 Accepted: 03 September 2020 Published: 10 September 2020
  • MSC : 33E05, 33F05

  • In the article, we establish some monotonicity properties for certain functions involving the complete p-elliptic integrals of the first and second kinds, and find several sharp bounds for the p-elliptic integrals. Our results are the generalizations and improvements of some previously known results for the classical complete elliptic integrals.

    Citation: Xi-Fan Huang, Miao-Kun Wang, Hao Shao, Yi-Fan Zhao, Yu-Ming Chu. Monotonicity properties and bounds for the complete p-elliptic integrals[J]. AIMS Mathematics, 2020, 5(6): 7071-7086. doi: 10.3934/math.2020453

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  • In the article, we establish some monotonicity properties for certain functions involving the complete p-elliptic integrals of the first and second kinds, and find several sharp bounds for the p-elliptic integrals. Our results are the generalizations and improvements of some previously known results for the classical complete elliptic integrals.


    Let r[0,1). Then the Legendre's complete elliptic integrals [1,2,3,4,5,6] of the first and second kinds are defined by

    K=K(r)=π/20dθ1r2sin2θ,K(0)=π2,K(1)=+, (1.1)
    E=E(r)=π/201r2sin2θdθ,E(0)=π2,E(1)=1, (1.2)

    respectively. It is well known that the complete elliptic integrals and integral inequalities [7,8,9,10,11,12,13,14,15,16,17,18,19,20] have wide applications in mathematics and physics, including the formula of the arc length of an ellipse, the evaluation of the circumferences ratio π, the computations of electromagnetic fields and related quantities, the study of simple pendulum period, and so on. Convexity and monotonicity are the indispensable tools in the study of inequality theory [21,22,23,24,25,26,27,28], the generalizations and variants for the convexity have attracted the attention of many researchers [29,30,31,32,33,34,35,36,37,38] in recent decades, and many inequalities have been established via the convexity and monotonicity theory [39,40,41,42,43,44].

    The recent interest of the complete elliptic integrals is motivated by their applications in geometric function theory due to many conformal invariants and distortion functions in the theory of quasi-conformal mappings can be expressed by the complete elliptic integrals.

    Alzer and Qiu [45] proved that the double inequality

    π2log2+α(11r2)+log(1+11r2)<K(r)<π2log2+β(11r2)+log(1+11r2) (1.3)

    holds for all r(0,1) with the best constant α=π/41/2 and β=3log2π/2.

    Wang et al. [46] proved that the function rr[π/2E(r)]/[r(1r2)arctanh(r)] is strictly decreasing from (0,1) onto (π/21,3π/16), and the double inequality

    π2π16r(1r2)arctanh(r)r<E(r)<π2(π21)r(1r2)arctanh(r)r (1.4)

    holds for all r(0,1). Here and in what follows we denote arctanh() the inverse hyperbolic tangent function.

    In 2018, Yang et al. [47] proved that the function reK(r)c/1r2 is strictly decreasing on (0,1) if and only if c4, strictly increasing on (0,1) if and only if cπeπ/2/4=3.77, the double inequality

    log41r2<K(r)<log(eπ/24+41r2) (1.5)

    holds for all r(0,1), and the two-sided inequality

    log(eπ/2s+s1r2)<K(r)<log(eπ/2t+t1r2) (1.6)

    takes place for all r(0,1) if and only if sπeπ/2/4 and t4.

    Takeuchi [48] introduced a new form of the generalized elliptic integrals with one real parameter p, called the complete p-elliptic integrals. For p(1,+) and r[0,1), the complete p-elliptic integrals of the first and second kinds are respectively defined by

    Kp=Kp(r)=πp/20dθ(1rpsinppθ)11/p,Kp(0)=πp2,Kp(1)=+ (1.7)

    and

    Ep=Ep(r)=πp/20(1rpsinppθ)1/pdθ,Ep(0)=πp2,Ep(1)=1, (1.8)

    where sinpθ is the generalized sine function, defined by the inverse function of

    sinp1θ=θ0dt(1tp)1/p,0θ1,

    and πp is the generalized circumference ratio defined by

    πp=210dt(1tp)1/p=2πpsin(π/p).

    Note that sin2θ=sinθ and π2=π. From (1.1), (1.2), (1.7) and (1.8) we know that K2(r)=K(r) and E2(r)=E(r).

    Takeuchi [48,49] provided the derivative formulas and identity for Kp and Ep as follows

    dKp(r)dr=EprpKprrp,dEp(r)dr=EpKpr,
    d(KpEp)dr=rp1Ep(r)rp,d(EprpKp)dr=(p1)rp1Kp(r)

    and

    Kp(r)Ep(r)+Kp(r)Ep(r)Kp(r)Kp(r)=πp2.

    where and in what follows, we denote r=p1rp for r[0,1]. Using (1.5), Takeuchi [48,50] found the formulas for π3 and π4. Moreover, the following formulas for the complete p-elliptic integrals in terms of the Gaussian hypergeometric function can be found in the literature [48]:

    Kp(r)=πp2F(11p,1p;1;rp),Ep(r)=πp2F(1p,1p;1;rp), (1.9)

    where

    F(a,b;c;x)=2F1(a,b;c;x)=n=0(a)n(b)n(c)nxnn! (|x|<1)

    is the Gaussian hypergeometric function [51,52] for real parameters a,b,c with c0,1,2,, and (a)0=1 for a0 and (a)n denotes the Pochhammer function (a)n=a(a+1)(a+2)(a+3)(a+n1) for n=1,2,. If a+b=c, then F(a,b;c;x) is called zero-balanced, which has the following asymptotic formula [53]:

    B(a,b)F(a,b;a+b;x)+log(1x)=R(a,b)+O((1x)log(1x)), (1.10)

    where B(z,w)=Γ(z)Γ(w)/[Γ(z+w)] is the classical Beta function for Re(z)>0 and Re(w)>0,

    R(a,b)=ψ(a)ψ(b)2γ,R(a)=R(a,1a),

    ψ(z)=Γ(z)/Γ(z) for Re(z)>0 and γ is the Euler-Mascheroni constant.

    The main purpose of this paper is to extend inequalities (1.4)–(1.6) to the case of the complete p-elliptic integrals. Our main results are the following Theorems 1.1–1.3.

    Theorem 1.1. Let p(1,+), p0=2.523 be the unique solution of the equation 2p2p2πp+4=0 and the function f be defined on (0,1) by

    fp(r)=πp/2Ep(r)1rp[arctanh(rp/2)]/rp/2.

    Then the following statements are true:

    (1) If p(1,5], then fp(r) is strictly decreasing from (0,1) onto (3πp/(4p2),πp/21), and the double inequality

    πp23πp4p2[1rparctanh(rp/2)rp/2]<Ep(r)<πp2(πp21)[1rparctanh(rp/2)rp/2] (1.11)

    holds for all r(0,1);

    (2) If p(5,p0), then there exists unique r0(0,1) such that fp(r) is strictly increasing on (0,r0), and strictly decreasing on (r0,1). Consequently, for r(0,1), one has

    Ep(r)<π2min{πp21,3πp4p2}[1rparctanh(rp/2)rp/2]; (1.12)

    (3) If p[p0,+), then fp(r) is strictly increasing from (0,1) onto (πp/21,3πp/(4p2)), and the reverse inequality of (1.11) holds for all r(0,1).

    Theorem 1.2. Let p[2,+), α,βR and the function F be defined on (0,1) by

    F(r)=Kp(r)(πp/2log2)log(1+1/r)1r.

    Then F(r) is strictly decreasing from (0,1) onto ((p1)πp/(2p)1/2,R(1/p)/p(πp/2log2)), and the double inequality

    πp2log2+log(1+1r)+α(1r)<Kp(r)<πp2log2+log(1+1r)+β(1r) (1.13)

    holds for all r(0,1) with the best possible constants α=(p1)πp/(2p)1/2 and β=R(1/p)/p(πp/2log2).

    Theorem 1.3. Let p[2,+), cR and the function Gc be defined on (0,1) by

    Gc(r)=eKp(r)cr,r(0,1).

    Then the following statements are true:

    (1) The function Gc(r) is strictly increasing on (0,1) if and only if ceπp/2(p1)πp/(2p), in this case the range of Gc is (eπp/2c,+);

    (2) The function Gc(r) is strictly decreasing (0,1) if and only if ceR(1/p)/p, in this case the range of Gc is (,eπp/2c) if c>eR(1/p)/p, while the range of Gc is (0,eπp/2c) if c=eR(1/p)/p. Furthermore, for all r(0,1), we have

    log(eR(1/p)/pr)<Kp(r)<log(eR(1/p)/pr+eπp/2eR(1/p)/p); (1.14)

    (3) If eπp/2(p1)πp/(2p)<c<eR(1/p)/p, then there exists r0(0,1) such that Gc(r) is strictly decreasing on (0,r0) and strictly increasing on (r0,1);

    (4) The double inequality

    log(eπ/2s+sr)<Kp(r)<log(eπ/2t+tr) (1.15)

    holds for all r(0,1) if and only if seπp/2(p1)πp/(2p) and teR(1/p)/p.

    In order to prove our main results, we need several lemmas, which we present in this section.

    Lemma 2.1. (See [54, Theorem 1.25])Let <a<b<, f,g:[a,b]R be continuous on [a,b] and be differentiable on (a,b) such that g(x)0 on (a,b). Then both the functions [f(x)f(a)]/[g(x)g(a)] and [f(x)f(b)]/[g(x)g(b)] are (strictly) increasing (decreasing) on (a,b) if f(x)/g(x) is (strictly) increasing (decreasing) on (a,b).

    Lemma 2.2. (See [55, Theorem 2.1])Suppose that the power series f(x)=n=0anxn and g(x)=n=0bnxn have the radius of convergence r>0 with bn>0 for all n{0,1,2,}. Let h(x)=f(x)/g(x) and Hf,g=(f/g)gf, then the following statements are true:

    (1) If the non-constant sequence {an/bn}n=0 is increasing (decreasing), then h(x) is strictly increasing (decreasing) on (0,r);

    (2) If the non-constant sequence {an/bn} is increasing (decreasing) for 0<nn0 and decreasing (increasing) for n>n0, then the function h is strictly increasing (decreasing) on (0,r) if and only if Hf,g(r)()0. While if Hf,g(r)<(>)0, then there exists δ(0,r) such that h(x) is strictly increasing (decreasing) on (0,δ) and strictly decreasing (increasing) on (δ,r).

    The following Lemma can be found in the literature [56,57].

    Lemma 2.3. Let p(1,+). Then we have the following five conclusions:

    (1) The function r(EprpKp)/rp is strictly increasing from (0,1) onto ((p1)πp/(2p),1);

    (2) The function rKp(r)+logr is strictly decreasing from (0,1) onto (R(1/p)/p,πp/2);

    (3) The function rrcKp is strictly decreasing on (0,1) if and only if c(p1)/p with the range (0,πp/2);

    (4) The function rrcEp is strictly increasing on (0,1) if and only if c1/p with the range (πp/2,);

    (5) The function rEp+[rp(KpEp)2]/(rpEp) is strictly decreasing from (0,1) onto (1,πp/2).

    Lemma 2.4. Let

    f(x)=1sinx1x2xπ2,x(0,1).

    Then there exists unique x0=1.244(0,π), such that f(x)<0 for x(0,x0), and f(x)>0 for x(x0,π).

    Proof. Since

    1sinx1x=k=122k2(2k)!|B2k|x2k1,|x|<π,

    where Bk are the Bernoulli numbers, one has

    f(x)=2xπ2+|B2|x+k=222k2(2k)!|B2k|x2k1=(162π2)x+k=222k2(2k)!|B2k|x2k1. (2.1)

    Differentiating f leas to

    f(x)=(162π2)+k=222k2(2k)!(2k1)|B2k|x2k2. (2.2)

    It is easy to check that f(x) is strictly increasing on (0,π), f(0)=1/62/π2<0 and f(π)=+. Hence there exists unique x0, such that f(x) is strictly decreasing on (0,x0) and strictly increasing on (x0,π). This, together with the limiting values

    f(0+)=0,f(π)=+, (2.3)

    implies that there exists a unique zero point x0(0,π), such that f(x0)=0, f(x) is negative on (0,x0), and f(x) is positive on (x0,π). By the mathematical software Maple 13, we compute that x0=1.244. This completes the proof.

    Corollary 2.5. Let p(1,+) and λ(p)=1πp/2+2/p2. Then there exists unique p0=2.523(1,+) such that λ(p0)=0, λ(p)<0 for p(1,p0) and λ(p)>0 for p(p0,+).

    Proof. Let x=π/p(0,π). Then

    1πp2+2p2=1xsinx+2x2π2=x(1sinx1x2πx).

    Therefore, Corollary 2.5 follows from Lemma 2.4.

    Lemma 2.6. Let p[2,+). Then one has

    (1) The function

    g(r)=(2p+2)r+2p4(1+r)4r2p2+πp2(p21)(2p1)(2p27p+61/p)24p3

    is strictly increasing and positive on (0,1).

    (2) The inequality

    14+(11/p)(p5+5/p1/p2)πp12>0

    holds for each p[2,+).

    Proof. It is clear to see that

    g(r)=(2p+2)r+2p4(1+r)4r2p2+πp2(p21)(2p1)(2p27p+61/p)24p3=2p+2(1+r)4r2p3+2p4(1+r)4r2p2+πp2(p21)(2p1)(2p27p+61/p)24p3

    is strictly increasing on (0,1). Since πp=2π/[psin(π/p)]>2 for p[2,+), one has

    limr0+g(r)=4p216+πp2(p21)(2p1)(p1)(2p25p+1)24p4>4p216+(p21)(2p1)(p1)(2p25p+1)24p4=(2p1)(2p54p4+4p3+6p26p+1)24p4=(2p1)[2p3(p22p+2)+6p(p1)+1]24p4>0.

    Therefore, part (1) follows.

    For part (2), employing inequality πp=2π/[psin(π/p)]>2 for p[2,+) again, we derive that

    14+(11/p)(p5+5/p1/p2)πp12>14+(11/p)(p5+5/p1/p2)6=(2p1)(p34p2+8p2)12p3=(2p1)[p(p24p+8)2]12p3>0

    immediately.

    Lemma 2.7. Let p[2,+). Then the function

    h(r)=1(1+r)2+rprp1Kpprp1(KpEp)r2p

    is strictly increasing and convex on (0,1).

    Proof. Differentiating h gives

    h(r)=2rp1(1+r)3rp1+rp1r[(p2+2p+1)rp+2r2p+2p2]Kp[2p2(p2+1)rp]Epr3p=rp1r{2(1+r)3rp2+[(p2+2p+1)rp+2r2p+2p2]Kp[2p2(p2+1)rp]Epr3p}=rp1r[h1(r)+h2(r)], (2.4)

    where

    h1(r)=2(1+r)3rp2+πp2(p21)(2p1)(2p27p+61/p)24p4rp (2.5)

    and

    h2(r)=[(p2+2p+1)rp+2r2p+2p2]Kp[2p2(p2+1)rp]Epr3pπp2(p21)(2p1)(2p27p+61/p)24p4rp. (2.6)

    Simple computations lead to

    limr0+h1(r)=14,limr1h1(r)=

    and

    h1(r)=2[(p2)(1+r)3rp3+3(1+r)2rp2](1+r)6r2p4(rp1rp1)+πp2(p21)(2p1)(2p27p+61/p)24p3rp1=rp1g(r),

    where g(r) is defined as in Lemma 2.6(1). By Lemma 2.6(1) we conclude that h1(r) is strictly increasing from (0,1) onto (1/4,+).

    Expanding the right side of (2.6) into power series, we have

    h2(r)=πp2{n=2(11/p,n+1)(1/p,n+1)[(p1)2n+p25p+51/p]n!(n+3)!rpn}+πp2(11/p)(p5+5/p1/p2)6.

    Note that

    (11/p,n+1)(1/p,n+1)[(p1)2n+p25p+51/p]n!(n+3)!>0

    for n2, h2 is strictly increasing on (0,1), and the range is ((11/p)(p5+5/p1/p2)πp/12,).

    Combining Lemma 2.6(2) and monotonicity properties together with the ranges of h1 and h2, we know that the sum function h1(r)+h2(r) is strictly increasing and positive on (0,1),

    Finally, according to equations (2.4)–(2.6) we obtain that h(r) is strictly increasing and convex on (0,1).

    Lemma 2.8. Let p[2,+). Then the function

    φ(r)=Kp(r)Ep(r)[Ep(r)rpKp(r)]Kp(r)

    is strictly increasing from (0,1) onto (2/[(p1)πp],1).

    Proof. Let φ1(r)=Kp(r)Ep(r) and φ2(r)=[Ep(r)rpKp(r)]Kp(r). Then φ(r)=φ1(r)/φ2(r), φ1(0)=φ2(0)=0 and

    φ1(r)φ2(r)=rpEp(p1)rprpKp2+(EprpKp)2=rpEp(p2)rprpKp2+rpEp2+rp(KpEp)2=1(p2)(rpKp2/Ep)+[Ep+rp(KpEp)2/(rpEp)]. (2.7)

    Since p2, the function rrpKp2/Ep is strictly decreasing on from (0,1) onto (0,πp/2). This together with Lemma 2.3(5) leads to the conclusion that the function φ1(r)/φ2(r) is strictly increasing from (0,1) onto (2/[(p1)πp],1). Applying Lemma 2.1, we obtain that φ(r) is also strictly increasing on (0,1). Moreover, limr1φ(r)=1, and

    limr0+φ(r)=limr0+φ1(r)φ2(r)=2(p1)πp.

    Lemma 2.9. Let p[2,+). Then the function

    ϕ(r)=Ep(r)rpKp(r)(p1)rp[Kp(r)Ep(r)](EprpKp)2

    is strictly increasing from (0,1) onto ((p+1)/[(p1)πp],1).

    Proof. Let ϕ1(r)=Ep(r)rpKp(r)(p1)rp(KpEp) and ϕ2(r)=(EprpKp)2. Then ϕ(r)=ϕ1(r)/ϕ2(r), ϕ1(0)=ϕ2(0=0 and

    ϕ1(r)ϕ2(r)=(p21)rp1(KpEp)2(p1)rp1Kp(EprpKp)=(p+1)(KpEp)2Kp(EprpKp). (2.8)

    Eq (2.8) and Lemma 2.8 show that ϕ1(r)/ϕ2(r) is strictly increasing on (0,1). By application of Lemma 2.1, the monotonicity of ϕ(r) follows. Clearly ϕ(1)=1, and by l'Hôpital's rule we get

    limr0+ϕ(r)=limr0+ϕ1(r)ϕ2(r)=p+122(p1)πp=p+1(p1)πp.

    Lemma 2.10. Let p[2,+). Then the function

    ω(r)=eKp(r)r(EprpKp)rp

    is strictly increasing from (0,1) onto (eπp/2(p1)πp/(2p),eR(1/p)/p).

    Proof. By differentiation, we have

    ω(r)=eKp(r)[(rp1/rp1)(EprpKp)+(p1)rrp1Kp]rpr(EprpKp)prp1r2p+eKp(r)(EprpKprrp)r(EprpKp)rp=eKp(r)rp1rp+1[rp(EprpKp)+(p1)rprpKpprp(EprpKp)+(EprpKp)2]=eKp(r)rp1rp+1{(EprpKp)2[(EprpKp)(p1)rp(KpEp)]}=eKp(r)(EprpKp)2rp1rp+1[1ϕ(r)], (2.9)

    where ϕ(r) is defined as in Lemma 2.9.

    The monotonicity of ω(r) on (0,1) directly follows from (2.9) and Lemma 2.9. By Lemma 2.3(1) and (3), one has ω(0+)=eπp/2(p1)πp/(2p) and ω(1)=eR(1/p)/p.

    Proof of Theorem 1.1. Let A(r)=πp/2Ep(r) and B(r)=1rparctanh(rp/2)/rp/2. Then using the series expansion (1.9) we get

    A(r)=πp2πp2n=0(1/p,n)(1/p,n)(1,n)rpnn!=πp2pn=1(1/p,n)(11/p,n)(n!)2)rpn,
    B(r)=1(1rp)n=012n+1rpn=2n=114n21rpn.

    Thus

    fp(r)=A(r)B(r)=πp4pn=1Rnrpnn=1Snrpn, (3.1)

    where

    Rn=(1/p,n)(11/p,n)(n!)2),Sn=14n21. (3.2)

    Let Tn=Rn/Sn. Then

    Tn+1Tn1=(n1/p)(n+1/p)[4(n+1)21](n+1)2(4n21)1=(2n+3)(n21/p2)(n+1)2(2n1)1=(2n+3)/p21(n+1)2(2n1). (3.3)

    Next, we divide the proof into two cases.

    Case 1. p(1,5]. Then from (3.3) we obtain that Tn+1/Tn1 for n1, and thereby {Tn} is decreasing with respect to n. With an application of Lemma 2.2 and Eqs (3.1) and (3.2), the monotonicity of fp on (0,1) in this case follows. Moreover, clearly fp(1)=πp/21, and by l'Hospital's rule, one has

    limr0+fp(r)=πp4pR1S1=3πp4p2.

    Therefore, inequality (1.11) takes place.

    Case 2. p(5,+). Then Eq (3.3) implies that there exists n0>1 such that sequence {Rn/Sn} is increasing for 1<nn0 and decreasing for n>n0. For the limiting value of HA,B(r) at 1, by differentiation we get

    A(r)=Kp(r)Ep(r)r,
    B(r)=[prp1arctanh(rp/2)+prp/21/2]prp/21rparctanh(rp/2)/2rp=p2r(rp/2+rp/2)arctanh(rp/2)p2r,

    so that

    HA,B(r)=A(r)B(r)B(r)A(r)=Epπp2+2p(KpEp)[rp/2rparctanh(rp/2)](1+rp)arctanh(rp/2)rp/2.

    It is not difficult to verify that

    limr1[rp/2rparctanh(rp/2)]=1,
    limr1log(1/r)arctanh(rp/2)=limr1rp1/rpprp/21/(2rp)=2p,
    limr1KpEplog(1/r)=limr1rp1Ep/rprp1/rp=1,

    thus

    HA,B(1)=limr1[Epπp2+2p(KpEp)[rp/2rparctanh(rp/2)](1+rp)arctanh(rp/2)rp/2]=1πp2+limr12plog(1/r)(1+rp)arctanh(rp/2)rp/2=1πp2+2p2. (3.4)

    It follows from (3.4) and Corollary 2.4 that HA,B(1)<0 for p(5,p0), and HA,B(1)0 for p[p0,). Applying Lemma 2.2(2), fp(r) is strictly increasing from (0,1) onto (πp/21,3πp/(4p2)) if and only if pp0, so that the reverse inequality of (1.11) holds. While p(5,p0), fp(r) is piecewise monotone on (0,1), and therefore the inequality

    πp/2Ep(r)1rp[arctanh(rp/2)]/rp/2>min{πp21,3πp4p2} (3.5)

    takes place for each r(0,1). Finally, by exchanging the terms of inequality (3.5), we obtain (1.12).

    Proof of Theorem 1.2. Let

    F1(r)=Kp(r)(πp/2log2)log(1+1/r),F2(r)=1r,
    F3(r)=Ep(r)rpKp(r)rp11+r,F4(r)=r.

    Then F(1)=F2(1)=0, F3(0+)=F4(0+)=0, and

    F1(r)F2(r)=F3(r)F4(r),F3(r)F4(r)=h(r),

    where h(r) is defined as in Lemma 2.7, is a increasing function on (0,1). Applying Lemma 2.1 twice, the monotonicity of F follows. Moreover, by Lemma 2.3(2) and Lemma 2.7 we have F(0+)=R(1/p)/p(πp/2log2) and

    limr1F(r)=limr1F1(r)F2(r)=limr1F3(r)F4(r)=(p1)πp2p12.

    Inequality (1.13) can be derived from the monotonicity of F(r) on (0,1) and the above limiting values immediately. The proof of Theorem 1.2 is completed.

    Proof of Theorem 1.3. Clearly,

    Gc(0+)=eπp/2c. (3.6)

    Substituting 11/p and 1/p respectively for a and b in (1.10), we get

    Kp(r)=R(1/p)p+log1r+O((1rp)log(1rp)),r1.

    Thus

    Gc(1)={+,c<eR(1/p)/p,0,c=eR(1/p)/p,,eR(1/p)/p. (3.7)

    Differentiating Gc yields

    Gc(r)=eKp(r)(EprpKp)rrpcrp1rp+1=rp1rp+1[ω(r)c], (3.8)

    where ω(r) is defined as in Lemma 2.10. According to Lemma 2.10 and (3.8), the assertion of the monotonicity of Gc(r) for any cR follows. Combining with (3.6) and (3.7), parts (1)–(3) hold.

    For part (4), it follows from parts (1)-(3) that inequality Gc(r)>Gc(0+)=eπp/2c holds for all r(0,1) if and only if ceπp/2(p1)πp/(2p), and Gc(r)<Gc(0+)=eπp/2c holds for all r(0,1) if and only if ceR(1/p)/p. Therefore, the inequality

    eπp/2s+sr<eKp(r)<eπp/2t+tr,

    namely,

    log(eπp/2s+sr)<Kp(r)<log(eπp/2t+tr),

    holds for all r(0,1) if and only if seπp/2(p1)πp/(2p) and teR(1/p)/p.

    In the article, we have found some new monotonicity properties for the functions involving the complete p-elliptic integrals of the first and second kinds, and provided several optimal upper and lower bounds for the p-elliptic integrals. Our ideas and approach may lead to a lot of follow-up research.

    The authors would like to thank the anonymous referees for their valuable comments and suggestions, which led to considerable improvement of the article.

    This work was supported by the National Natural Science Foundations of China (Grant Nos. 11971142, 61673169, 11701176, 11871202), the Natural Science Foundation of Zhejiang Province (Grant No. LY19A010012) and the research project for college students of Huzhou University (Grant No. 2019-111).

    The authors declare that they have no competing interests.



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