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Regularity criteria for weak solutions of the Magneto-micropolar equations

  • Received: 01 January 2020 Revised: 01 April 2020 Published: 24 August 2020
  • Primary: 76W05, 35D30, 35B65, 35Q30

  • In this paper, we show that a weak solution (u,w,b)(,t) of the magneto-micropolar equations, defined in [0,T), which satisfies u3,hw,hb L327(0,T; L2(R3)) or 3u3,3w,3bL(0,T;L2(R3)), is regular in R3×(0,T) and can be extended as a C solution beyond T.

    Citation: Jens Lorenz, Wilberclay G. Melo, Suelen C. P. de Souza. Regularity criteria for weak solutions of the Magneto-micropolar equations[J]. Electronic Research Archive, 2021, 29(1): 1625-1639. doi: 10.3934/era.2020083

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  • In this paper, we show that a weak solution (u,w,b)(,t) of the magneto-micropolar equations, defined in [0,T), which satisfies u3,hw,hb L327(0,T; L2(R3)) or 3u3,3w,3bL(0,T;L2(R3)), is regular in R3×(0,T) and can be extended as a C solution beyond T.



    In this paper we present some regularity criteria for weak solutions of the following magneto-micropolar fluid system in three space dimensions:

    {ut+uu+(p+12|b|2)=(μ+χ)Δu+bb+χ×w,wt+uw=γΔw+κ(w)+χ×u2χw,bt+ub=νΔb+bu,u=b=0,u(,0)=u0(),w(,0)=w0(),b(,0)=b0(), (1)

    where u(x,t)=(u1(x,t),u2(x,t),u3(x,t))R3 denotes the incompressible velocity field, w(x,t)=(w1(x,t),w2(x,t), w3(x,t))R3 denotes the micro-rotational velocity, b(x,t) =(b1(x,t),b2(x,t), b3(x,t)) R3 the divergence free magnetic field and p(x,t)R the hydrostatic pressure. As usual, xR3 denotes the space variable and 0t<T the time variable. The positive constants μ,χ,ν,κ, and γ are associated with specific properties of the fluid; precisely, μ is the kinematic viscosity, χ is the vortex viscosity, κ and γ are spin viscosities and, lastly, ν1 is the magnetic Reynolds number. The initial data for the velocity and magnetic fields, given by u0 and b0 in (1), are divergence free, i.e., u0=b0=0.

    Let us list some recent papers which discuss regularity of weak solutions of the magneto-micropolar equations (1) and systems that are particular cases of these equations as, for example, the classical Navier-Stokes equations.

    In 2010, Y. Baoquan [18] established the following regularity criteria: a solution (u,w,b)(t) of (1) can be extended smoothly beyond t=T if

    T0u(t)βαdt<,where 3α+2β1,3<α,

    or

    T0u(t)βαdt<,where 3α+2β2,32<α,

    provided that the initial data (u0,w0,b0) belong to H1(R3) and u0=b0=0. Here (u,w,b)C([0,T);H1(R3))C((0,T);H2(R3)) is assumed. Notice that Y. Baoquan [18] used only the velocity field or its gradient in the regularity criteria described above.

    In 2013, Y. Wang [14] showed that a weak solution (u,w,b)(t) of (1), defined on the interval [0,T), can be extended smoothly beyond t=T if one assumes

    T03u(t)βαdt<where 3α+2β1,α3, (2)

    provided that (u0,w0,b0)H1(R3) and u0=b0=0. Let us point out that Y. Wang [14] established the regularity criterion given above by considering only one component of the gradient of the velocity field (see (2)). The paper [14] deals with an extension of a regularity criterion obtained for weak solutions of the magneto-hydrodynamic equations (see [2]). This latter system is the special case of(1) obtained for w=0 and χ=0. Further results related to the current paper are in [2,21].

    The papers [14] and [18] (see also [3,8,12,13,15,17,19,20,22,23,24,28,29]), raised our interest to obtain regularity criteria for weak solutions of the magneto-micropolar system (1), which involve only one component of the velocity field u.

    Note that the magneto-micropolar system (1) reduces to the classical Navier-Stokes equations for the velocity field u and the pressure p if one assumes that w=b=0 and χ=0. Regularity criteria for weak solutions of Navier-Stokes equations, involving only one component of the velocity field, have been published recently. We want to comment on two results.

    First, Z. Zhang and X. Yang [22] present a regularity criterion for the Navier-Stokes equations involving the gradient of one component of the velocity field. Precisely, if u(t) is a weak solution of the Navier-Stokes equations in (0,T) and

    T0u3(t)3272dt<, (3)

    then u is C in R3×(0,T) and the solution can be extended as a C function beyond T. Here u0L2(R3) with u0=0 is assumed. In the current paper we prove that the criterion (3) can be extended from the Navier-Stokes equations to the magneto-micropolar system (1) under appropriate conditions on the other fields w and b. See Theorem 1.1 below.

    The second paper we cite is [23]. Z. Zhang and X. Yang [23] deal with one component of the gradient of one component of the velocity field. More precisely, regularity of a weak solution u(t) of the Navier-Stokes equations is obtained under the assumption

    3u3(t)L(0,T;L2(R3)). (4)

    Theorem 1.2 below establishes an extension of criterion (4) from the Navier-Stokes equations to the magneto-micropolar system (1).

    Further regularity results for weak solutions of the Navier-Stokes equations are established in [1,4,5,6,7,10,25,26].

    The main results of the current paper are:

    Theorem 1.1. Let (u0,w0,b0)L2(R3) with u0,b0=0. Let T>0 and let

    (u,w,b)C([0,T);H1(R3))C((0,T);H2(R3)) (5)

    denote a weak solution of the magneto-micropolar equations (1) in (0,T) satisfying the initial condition (u,w,b)(0)=(u0,w0,b0). If

    u3,hw,hbL327(0,T;L2(R3)), (6)

    then (u,w,b) is C in R3×(0,T) and the solution can be extended as a C function beyond T.

    Theorem 1.2. Let (u0,w0,b0)L2(R3) with u0,b0=0. Let T>0 and let

    (u,w,b)C([0,T);H1(R3))C((0,T);H2(R3)) (7)

    denote a weak solution of the magneto-micropolar equations (1) in (0,T) satisfying the initial condition (u,w,b)(0)=(u0,w0,b0). If

    3u3,3w,3bL(0,T;L2(R3)), (8)

    then (u,w,b) is C in R3×(0,T) and the solution can be extended as a C function beyond T.

    An outline of the paper follows: There are two sections after the Introduction. In Section 2, we list definitions and notations used throughout the paper and recall results that play an important role in our proofs of the main results. Section 3 presents the proofs of Theorems 1.1 and 1.2.

    We introduce notations and definitions used in the paper.

    ● Boldface letters denote vector fields; for example,

    a=a(x,t)=(a1(x,t),a2(x,t),a3(x,t)),xR3,t0.

    ● The Euclidean norm of any vector a=(a1,...,an)Rn is denoted and given by |a|=ni=1a2i.

    ● The notation Lα is used for the standard Lebesgue space equipped with the norm α, where 1α; more specifically,

    aα:=(R3|a(x)|αdx)1α,1α<, 

    and

    a:=ess supxR3{|a(x)|}, 

    where a:R3Rn (nN) is a mensurable function. We define the L2-inner product of two vector functions by

    (a,b)2:=R3a(x)b(x)dx, 

    where cd:=ni=1cidi for c=(c1,...,cn),d=(d1,...,dn)Rn; and a,b:R3Rn (nN) are mensurable functions.

    ● Let a=(a1,...,an) denote the gradient of a=(a1,...,an)Rn, where aj=(1aj,2aj,3aj), with i=/xi for all i=1,2,3 and j=1,...,n.

    ● The horizontal gradient is denoted by ha=(ha1,...,han), where a=(a1,...,an)Rn and haj=(1aj,2aj), with j=1,...,n.

    ● Here a:=3i=1aii, where a=(a1,a2,a3)R3.

    ×a denotes the curl of the vector field a=(a1,a2,a3)R3.

    ● Denote a=3i=1iai, where a=(a1,a2,a3)R3.

    Δ represents the standard Laplacian operator.

    ● The horizontal Laplacian is denoted by Δha=(Δha1,...,Δhan), where a=(a1,...,an)Rn and Δhaj=2i=12iaj, with j=1,...,n.

    ● Let (X,) be a Banach space and assume that 1β, c,dR,c<d. We denote by Lβ(c,d;X) the space of all measurable functions f:(c,d)X with f()Lβ(c,d) endowed with the norm fLβ(c,d;X):=(dcf(t)βdt)1β, where β<, and also fL(c,d;X)=ess supc<t<d{f(t)}.

    ● We define a weak solution of (1) as follows: Let T>0 and (u0,w0,b0)L2(R3), with u0=b0=0. A mensurable function (u,w,b)(t) is called a weak solution for (1) on [0,T) if the following conditions hold

    1. (u,w,b)(t)L(0,T;L2(R3))L2(0,T;H1(R3));

    2. the system (1) is satisfied in the sense of distributions;

    3. the energy inequality holds, i.e.,

    (u,w,b)(t)22+2(μ+χ)t0u(τ)22dτ+2γt0w(τ)22dτ+2νt0b(τ)22dτ+2κt0w(τ)22dτ+2χt0w(τ)22dτ(u0,w0,b0)22, (9)

    for all 0t<T.

    ● For brevity, dependencies on the variables x and t are often suppressed in our notation. For example, the function tu(,t)2 may also be written as u(t)2 or u2. Furthermore, as usual, the value of constants may change line by line in the paper.

    Now, we enunciate the lemmas that will be applied in the proofs of our main results. The first one is proved in [16].

    Lemma 2.1 (see [16]). Let i,j,k be a permutation of 1,2,3. Assume that

    f,g,ig,jg,h,jh,khL2(R3).

    Then,

    R3fghdxCf2g142ig122jg142h142kh122jh142.

    The second one was established in [23].

    Lemma 2.2 (see [23]). Let fL6(R3) and gL2(R3) with 3fL2(R3) and hgL2(R3). Then,

    R3f2g2dx22f3263f122g2hg2.

    The third one was written in [2].

    Lemma 2.3 (see [2]). Assume that θ,λ,ϑR satisfy

    1θ,λ,ϑ<,1θ+2λ>1,1+3ϑ=1θ+2λ.

    Consider that fH1(R3),1f,2fLλ(R3) and 3fLθ(R3). Then, there exists a positive constant C such that

    fϑC1f13λ2f13λ3f13θ.

    In particular, if λ=2 and fH1(R3), 3fLθ(R3) (with 1θ<), then there is a positive constant C such that

    f3θC1f1322f1323f13θ.

    In this section we prove Theorems 1.1 and 1.2. In both results, it is necessary to consider ϵ(0,T) arbitrary in order to obtain δ(0,ϵ) such that (u,w,b)(δ)L2(R3). It is known that there is a unique strong solution (u,w,b)C([δ,T);H1(R3))L2(δ,T;H2(R3)) for the system (1) (see [9,11] and references therein) that satisfies (u,w,b)(δ)=(u,w,b)(δ), where t=T is the maximum time of existence for this solution, and (u,w,b)C(R3×(0,T)) (since ϵ>0 is arbitrary). Therefore, if T<T, one concludes that (u,w,b)(t) is regular in R3×(0,T). On the other hand, assuming TT, we will prove below that (u,w,b)(t)2 is uniformly bounded for t[δ,T) (in Theorem 1.2) and bounded as tT (in Theorem 1.1). However, this is not possible. In fact, this boundedness would imply that (u,w,b)(t) could be extended beyond t=T, which contradicts the definition of T.

    First, notice that by applying the product (,Δhu)2 to the first equation of the magneto-micropolar system (1) and using the fact that u=0, one gets

    12ddthu22+(μ+χ)hu22=(uu,Δhu)2(bb,Δhu)2χ(×w,Δhu)2. (10)

    Similarly, from the second and third equations in (1), we obtain

    12ddthw22+γhw22+κh(w)22+2χhw22=(uw,Δhw)2χ(×u,Δhw)2 (11)

    and also

    12ddthb22+νhb22=(ub,Δhb)2(bu,Δhb)2. (12)

    By adding the results (10), (11) and (12) one infers

    12ddt(hu,hw,hb)22+(μ+χ)hu22+γhw22+νhb22+κh(w)22+2χhw22=(uu,Δhu)2(bb,Δhu)2χ(×w,Δhu)2+(uw,Δhw)2χ(×u,Δhw)2+(ub,Δhb)2(bu,Δhb)2. (13)

    Let us examine the terms on the right hand side of the above equality. We have

    (bb,Δhu)2=3i,j=12k=1R3biibj2kujdx=3i,j=12k=1R3kbiibjkujdx+3i,j=12k=1R3bikibjkujdx.

    Similarly, we get

    (bu,Δhb)2=3i,j=12k=1R3biiuj2kbjdx=3i,j=12k=1R3kbiiujkbjdx3i,j=12k=1R3bikibjkujdx,

    where we have used that b is divergence free. Hence,

    (bb,Δhu)2(bu,Δhb)2=3i,j=12k=1R3kbiibjkujdx+3i,j=12k=1R3kbiiujkbjdxC(R3|hb||b||hu|dx+R3|hb||u||hb|dx).

    Furthermore,

    (uw,Δhw)2=3i,j=12k=1R3uiiwj2kwjdx=3i,j=12k=1R3kuiiwjkwjdx3i,j=12k=1R3uikiwjkwjdx.

    On the other hand, by analysing the last term above it is easy to prove that it is actually null. In fact, since u=0, one has

    3i,j=12k=1R3uikiwjkwjdx=3i,j=12k=1R3uikwjikwjdx. 

    Therefore,

    (uw,Δhw)2CR3|hw||w||hu|dx. 

    Similarly, we obtain

    (ub,Δhb)2CR3|hb||b||hu|dx. 

    Also notice that, by applying Cauchy-Schwarz's inequality, one has

    χ(×u,Δhw)2χ(×w,Δhu)2χhu22+χhw22. (14)

    By [22], the following estimate holds:

    (uu,Δhu)2CR3|u3||u||hu|dx. 

    Consequently, from (13), we infer

    12ddt(hu,hw,hb)22+μhu22+γhw22+νhb22+κh(w)22+χhw22CR3|(u3,hw,hb)||(u,w,b)||(hu,hw,hb)|dx.

    By applying Lemma 2.1, one obtains

    12ddt(hu,hw,hb)22+μhu22+γhw22+νhb22+κh(w)22+χhw22C(u3,hw,hb)2(hu,hw,hb)142(u,w,b)142×(hu,hw,hb)322.

    By using Young's inequality, it follows that

    ddt(hu,hw,hb)22+α(hu,hw,hb)22+2κh(w)22+2χhw22C(u3,hw,hb)42(hu,hw,hb)2×(u,w,b)2,

    where α=min{μ,ν,γ}. Now, by integrating over [Tτ,t] the inequality above (τ will be chosen a posteriori), we obtain

    (hu,hw,hb)(t)22+αtTτ(hu,hw,hb)(s)22dsC+CtTτ(u3,hw,hb)(s)42(hu,hw,hb)(s)2×(u,w,b)(s)2ds. (15)

    In order to estimate the term (u,w,b)(t)2 for all t[Tτ,T), we define

    I(t):=sups[Tτ,t]{(hu,hw,hb)(s)2}+(tTτ(hu,hw,hb)(s)22ds)12 (16)

    and

    J(t):=sups[Tτ,t]{(u,w,b)(s)2}+(tTτ(Δu,Δw,Δb)(s)22ds)12, (17)

    where Tτt<T. First of all, let us establish a relationship between I and J. By (15), one has

    I2(t)2sups[Tτ,t]{(hu,hw,hb)(s)22}
    +2tTτ(hu,hw,hb)(s)22dsC+CI(t)J(t)34tTτ(u3,hw,hb)(s)42(u,w,b)(s)142dsC+CI(t)J(t)34T0(u3,hw,hb)(s)3272ds+CI(t)J(t)34T0(u,w,b)(s)22dsC+CI(t)J(t)34,

    where we have applied Young's inequality, (6) and (9). By using Young's inequality again, we get

    I2(t)C+CJ32(t)+12I2(t), 

    or equivalently,

    I(t)C+CJ34(t),t(Tτ,T). (18)

    The inequality (18) is useful to prove that (u,w,b)(t)2 is bounded in the interval [Tτ,T). In order to establish this last statement, we start noting that the system (1) lets us conclude the following:

    12ddtu22+(μ+χ)Δu22=(uu,Δu)2(bb,Δu)2χ(×w,Δu)2, 
    12ddtw22+γΔw22+κ(w)22+2χw22=(uw,Δw)2χ(×u,Δw)2

    and also

    12ddtb22+νΔb22=(ub,Δb)2(bu,Δb)2, 

    where we used the fact that u=0. Hence, by adding the three equalities above, one obtains

    12ddt(u,w,b)22+(μ+χ)Δu22+γΔw22+νΔb22+κ(w)22+2χw22=(uu,Δu)2(bb,Δu)2χ(×w,Δu)2+(uw,Δw)2χ(×u,Δw)2+(ub,Δb)2(bu,Δb)2. (19)

    Let us examine all the terms on the right hand side of the equality above. We have

    (uw,Δw)2=3i,j,k=1R3uiiwj2kwjdx=3j=12k=1R3u33wj2kwjdx+3j,k=12i=1R3uiiwj2kwjdx+3j=1R3u33wj23wjdx=:I1(t)+I2(t)+I3(t). (20)

    Here

    I1(t)=3j=12k=1R3u33wj2kwjdx=3j=12k=1R3ku33wjkwjdx3j=12k=1R3u3k3wjkwjdx=3j=12k=1R3ku33wjkwjdx+123j=12k=1R33u3(kwj)2dxCR3|u||w||hw|dx+CR3|u||hw|2dx.

    Similarly,

    I2(t)=3j,k=12i=1R3uiiwj2kwjdx=3j,k=12i=1R3kuiiwjkwjdx3j,k=12i=1R3uikiwjkwjdx=3j,k=12i=1R3kuiiwjkwjdx+123j,k=12i=1R3iui(kwj)2dxCR3|u||hw||w|dx+CR3|hu||w|2dx.

    By using that u is divergence free, one also has

    I3(t)=3j=1R3u33wj23wjdx=123j=1R33u3(3wj)2dx=123j=12k=1R3kuk(3wj)2dxCR3|hu||w|2dx.

    Therefore, using the above estimates, the equality (20) yields

    (uw,Δw)2CR3|u||hw|2dx+CR3|u||hw||w|dx+CR3|hu||w|2dx.

    Following the same process, we conclude that

    (ub,Δb)2CR3|u||hb|2dx+CR3|u||hb||b|dx+CR3|hu||b|2dx.

    It is important to point out that the technique applied to (uw,Δw)2 may not be useful when we consider the terms (bb,Δu)2 and (bu,Δb)2 (such expressions were obtained in (19)). However, we can argue as follows.

    (bb,Δu)2(bu,Δb)2=3i,j,k=1R3biibj2kujdx3i,j,k=1R3biiuj2kbjdx=3i,j,k=1R3kbiibjkujdx+3i,j,k=1R3bikibjkujdx+3i,j,k=1R3kbiiujkbjdx+3i,j,k=1R3bikiujkbjdx.

    Consequently,

    (bb,Δu)2(bu,Δb)2=3i,j,k=1R3kbiibjkujdx+3i,j,k=1R3bikibjkujdx+3i,j,k=1R3kbiiujkbjdx3i,j,k=1R3bikibjkujdx.

    By using b=0, we have

    (bb,Δu)2(bu,Δb)2=3i,j,k=1[R3kbiibjkujdx+R3kbiiujkbjdx] (21)
    =3j=12k=1[R3kb33bjkujdx+R3kb33ujkbjdx]+3j,k=12i=1[R3kbiibjkujdx+R3kbiiujkbjdx]+3j=1[R33b33bj3ujdx+R33b33uj3bjdx]=:J1(t)+J2(t)+J3(t). (22)

    Let us estimate each term Ji(t) for i=1,2,3. Hence,

    J1(t)=3j=12k=1[R3kb33bjkujdx+R3kb33ujkbjdx]CR3|hb||b||u|dx.

    Similarly, one obtains

    J2(t)=3j,k=12i=1[R3kbiibjkujdx+R3kbiiujkbjdx]CR3|b||hb||u|dx+CR3|hu||b|2dx

    and, by applying b=0, we have

    J3(t)=3j=1[R33b33bj3ujdx+R33b33uj3bjdx]=3j=12k=1[R3kbk3bj3ujdx+R3kbk3uj3bjdx]CR3|hb||b||u|dx.

    Replacing, in (21), the estimates obtained for Ji(t), i=1,2,3, we get

    (bb,Δu)2(bu,Δb)2CR3|hu||b|2dx+CR3|hb||b||u|dx. 

    Furthermore, notice that

    χ(×w,Δu)2χ(×u,Δw)2χw22+χΔu22, 

    where we have applied Cauchy-Schwarz's inequality. At last, Y. Zhou and M. Pokorný [29] proved that

    (uu,Δu)2CR3|hu||u|2dx. 

    Therefore, (19) reads

    12ddt(u,w,b)22+μΔu22+γΔw22+νΔb22+κ(w)22+χw22CR3|(hu,hw,hb)||(u,w,b)|2dx. (23)

    By using Lemma 2.1, one gets

    ddt(u,w,b)22+2α(Δu,Δw,Δb)22+2κ(w)22+2χw22C(hu,hw,hb)2(u,w,b)122(hu,hw,hb)2×(Δu,Δw,Δb)122, 

    where α=min{μ,γ,ν}. Now, by integrating over [Tτ,s], st, the inequality above yields

    (u,w,b)(s)22+2αsTτ(Δu,Δw,Δb)(τ)22dτC+CI(t)sTτ(u,w,b)(τ)122(hu,hw,hb)(τ)2×(Δu,Δw,Δb)(τ)122dτ, 

    where we applied the definition of I(t) given in (16). By Hölder's inequality, we have

    (u,w,b)(s)22+2αsTτ(Δu,Δw,Δb)(τ)22dτC+CI2(t)J12(t)(sTτ(u,w,b)(τ)22dτ)14, 

    for all st. In the inequality above the definitions of I(t) and J(t) were applied (see (16) and (17)). It follows, by using (17), that

    J2(t)C+CI2(t)J12(t)(tTτ(u,w,b)(τ)22dτ)14. 

    By using Young's inequality, we infer

    J2(t)C+CI83(t)(tTτ(u,w,b)(τ)22dτ)13+12J2(t). 

    Consequently, by applying (18), we obtain

    J(t)C+[C+CJ(t)](tTτ(u,w,b)(τ)22dτ)16. (24)

    From the energy inequality (9), one concludes that there exists 0<τ1 such that

    TTτ(u,w,b)(τ)22dτ1(2C)6.

    Now, we can obtain the desired estimate for (u,w,b)(t) in [Tτ,T). In fact, by replacing the bound above in (24), we get

    J(t)C, t[Tτ,T). 

    The definition (17) establishes the proof of Theorem 1.1.

    In order to prove Theorem 1.2 let us examine all the terms on the right hand side of (13) in an alternative way. We have

    (uw,Δhw)2=3i,j=12k=1R3uiiwj2kwjdx=3i,j=12k=1R3kuiiwjkwjdx=3i,j=12k=1R3wjkuikiwjdxCR3|w||u||hw|dx,

    since u=0. By arguing in the same way, one gets

    (ub,Δhb)2CR3|b||u||hb|dx.

    Notice that

    (bb,Δhu)2=3i,j=12k=1R3biibj2kujdxCR3|b||b||hu|dx

    and also

    (bu,Δhb)2=3i,j=12k=1R3biiuj2kbjdxCR3|b||u||hb|dx.

    The reader might check that (14) assures the following estimate:

    χ(×u,Δhw)2χ(×w,Δhu)2χhu22+χhw22. 

    At last, Y. Zhou and M. Pokorný [29] proved that

    (uu,Δhu)2CR3|u3||u||hu|dx. 

    By replacing all these last results obtained above in (13) and by using Young's inequality, one has

    12ddt(hu,hw,hb)22+α(hu,hw,hb)22+κh(w)22+χhw22CR3|(u3,w,b)|2|(u,w,b)|2dx+α2R3|(hu,hw,hb)|2dx, 

    where α=min{μ,γ,ν}. Hence,

    ddt(hu,hw,hb)22+α(hu,hw,hb)22+2κh(w)22+2χhw22CR3|(u3,w,b)|2|(u,w,b)|2dx. 

    By Lemmas 2.2 and 2.3, and also by (8), we obtain

    ddt(hu,hw,hb)22+α(hu,hw,hb)22+2κh(w)22+2χhw22C(hu,hw,hb)2(u,w,b)2×(hu,hw,hb)2. 

    By Young's inequality, one concludes

    ddt(hu,hw,hb)22+α2(hu,hw,hb)22+2κh(w)22+2χhw22C(hu,hw,hb)22(u,w,b)22. 

    By applying Gronwall's inequality, we get

    (hu,hw,hb)(t)2(hu,hw,hb)(δ)2×exp{CTδ(u,w,b)(s)22ds}, 

    for all t[δ,T). By energy inequality (9), we can guarantee the following estimate:

    (hu,hw,hb)(t)2C, t[δ,T). (25)

    In order to prove that the term (u,w,b)(t)2 is bounded in [δ,T), we recall that (23) and Hölder's inequality imply

    ddt(u,w,b)22+2α(Δu,Δw,Δb)22+2κ(w)22+2χw22C(hu,hw,hb)2(u,w,b)24, 

    where α=min{μ,γ,ν}. By using (25) and Gagliardo-Nirenberg's inequality, one has

    ddt(u,w,b)22+2α(Δu,Δw,Δb)22+2κ(w)22+2χw22C(u,w,b)122(Δu,Δw,Δb)322, 

    for all t[δ,T). By Young's inequality, we infer

    ddt(u,w,b)22+α(Δu,Δw,Δb)22+2κ(w)22+2χw22C(u,w,b)22. 

    By Gronwall's inequality,

    (u,w,b)(t)2C(u,w,b)(δ)2, t[δ,T).

    This completes the proof of Theorem 1.2.

    The authors would like to thank reviewers for their precious suggestions.



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