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Research article

On the global existence and blow-up for the double dispersion equation with exponential term


  • Received: 17 September 2022 Revised: 03 November 2022 Accepted: 06 November 2022 Published: 11 November 2022
  • This paper deals with the initial boundary value problem for the double dispersion equation with nonlinear damped term and exponential growth nonlinearity in two space dimensions. We first establish the local well-posedness in the natural energy space by the standard Galërkin method and contraction mapping principle. Then, we prove the solution is global in time by taking the initial data inside the potential well and the solution blows up in finite time as the initial data in the unstable set. Moreover, finite time blow-up results are provided for negative initial energy and for arbitrary positive initial energy respectively.

    Citation: Xiao Su, Hongwei Zhang. On the global existence and blow-up for the double dispersion equation with exponential term[J]. Electronic Research Archive, 2023, 31(1): 467-491. doi: 10.3934/era.2023023

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  • This paper deals with the initial boundary value problem for the double dispersion equation with nonlinear damped term and exponential growth nonlinearity in two space dimensions. We first establish the local well-posedness in the natural energy space by the standard Galërkin method and contraction mapping principle. Then, we prove the solution is global in time by taking the initial data inside the potential well and the solution blows up in finite time as the initial data in the unstable set. Moreover, finite time blow-up results are provided for negative initial energy and for arbitrary positive initial energy respectively.



    This paper is devoted to the following initial-boundary value problem for the double dispersion equation

    {uttΔuttΔu+Δ2uΔh(ut)+Δf(u)=0inΩ×R+u(x,0)=u0(x),ut(x,0)=u1(x)inΩu(x,t)=Δu(x,t)=0onΩ×R+, (1.1)

    where Ω is a bounded domain of R2 having smooth boundary Ω and u=u(x,t):Ω×R+R. The damped term h(ut) is given by h(ut)=|ut|q1ut with q>1, and the nonlinearity fC1(R,R) admits

    (H1) for each β>0, there exists a positive constant Cβ>0 depending only on β such that

    |f(t)|Cβeβt2,|f(t)|Cβeβt2,for alltR.

    On account of the possibility of energy exchange through lateral surfaces of the waveguide in the physical study of nonlinear wave propagation in waveguide, the longitudinal displacement u(x,t) of the rod satisfies the following double dispersion equation (DDE) [1,2]

    uttuxx=14(6u2+auttbuxx)xx,

    and the general cubic double dispersion equation (CDDE)

    uttuxx=14(cu3+6u2+auttbuxx+dut)xx. (1.2)

    Here a,b,c>0 and d0 are some constants depending on the Young modulus, the shearing modulus, the density of the waveguide and the Poisson coefficient.

    Due to the wide applications in the real world, the initial value problem and initial-boundary value problem of double dispersion equation have drawn much attention from mathematicians. In [3,4,5], the authors studied global solutions with f(s)C (bounded below) for following the generalized DDE which includes Eq (1.2) as special cases,

    uttauxxtt+buxxxxuxxduxxt=f(u)xx. (1.3)

    Moreover, they also showed the nonexistence of the global solution under some other conditions. When d=0, Liu [6] investigated the global existence and nonexistence of solutions for the initial-boundary value problem of (1.3) with |f(u)|C|u|p.

    For the multidimensional generalized form of (1.3)

    uttΔuaΔutt+bΔ2udΔut=Δf(u), (1.4)

    Polat [7] researched the existence of global solutions also in the cases of f(s)C. Wang [8] considered the global existence and asymptotic behavior of the small amplitude solution in the time-weighted Sobolev space for the Cauchy problem of (1.4) with |f(u)|C|u|αj. Wang [9,10] investigated the asymptotic profile of solutions for the Cauchy problem of (1.4) with f(u)=O(u2). Su [11] researched the existence and nonexistence of a global solution in the natural energy space for the initial-boundary value problem of (1.4) with f(u)=β|u|p1u. So, motivated by this fact and the so-called Moser-Trudinger type inequalities [12,13,14,15], it was natural to consider nonlinearities with exponential growth.

    For the generalized double dispersion (1.4) with exponential nonlinearity, Zhang [16,17] proved the existence and nonexistence of global weak solution for the Cauchy problem of (1.4) with d=0. Guo [18] established the sufficient conditions of finite time blow-up of solutions in the cases of arbitrary positive initial energy for the Cauchy problem of (1.4) with d=0. As far as we are concerned, there are no results on the global existence and finite time blow-up of solutions for the initial-boundary value problem of (1.4) with both nonlinear damped and exponential nonlinearity.

    Furthermore, there are many works that focus on the wave equation with exponential nonlinearity. Global well-posedness in the defocusing case was established by Nakamura [19] for small data, Atallah [20] in the radial case, then by Ibrahim [21] and Struwe [22,23], see also [24,25,26,27,28,29] and their references.

    It is the aim of this manuscript to obtain results about the global existence and finite time blow-up of solutions under sufficient conditions for the problem (1.1) in the case that f is a source term and admits an exponential growth and h(ut) is polynomial growth. This is the first attempt in the literature to take into account both nonlinear damped term and the exponential nonlinear source for the problem (1.1).

    This paper is organized as follows. We first establish the local well-posedness by the standard Galërkin method and contraction mapping principle(see Theorem 3.1). By means of the potential well theory, we provide the sufficient conditions of global solutions with subcritical initial energy (see Theorem 4.1). In the case of the negative initial energy or the initial data in the potential well, we prove the local solutions will blow up in finite time (see Theorems 5.1 and 5.2). Moreover, we also constructed the sufficient conditions of finite time blow-up of solutions in the case of arbitrary positive initial energy (see Theorem 5.3).

    It is worth mentioning here that the sufficient conditions of blow-up of solutions can be investigated based on the concave method [17,18,27] in the absence of the nonlinear damped term h(ut) or h(ut)=ut in (1.1). However, when nonlinear damping and exponential source terms are both present in the equation, it seems that their method does not work on our problem directly. We research the blow-up of solutions in the cases of E(0)<0 or subcritical initial energy mainly by exploiting an argument from the one devised in [30,31,32], which investigated the blow-up of solutions to the wave equations with polynomial-type nonlinearity of form |s|ms, and the case of E(0)>0 mainly by [33].

    We conclude this section with several notations given. The notation (,) stands for the L2-inner product and , is used for the notation of duality pairing between dual space. For brevity, we use the same letter C to denote different positive constants, and C() to denote positive constants depending on the quantities appearing in the parenthesis.

    For brevity, we use the following abbreviations:

    Lp=Lp(Ω)H10=H10(Ω),=L2,2H10=2+2,

    with 1p. H1=H1(Ω) is the dual space of H10. Let A=Δ. Then, Au,v=(u,v), for u,vH10 and the domain of A is D(A)=H2H10; A is a positive, self-adjoint and invertible operator and the inverse operator A1 is compact [34]. Consequently, the operator A possesses an infinitely countable positive eigenvalues:

    0<λ1<λ2<<λj<+,

    and a corresponding sequence of eigenfunctions {ej:j=1,2,} that forms an orthogonal basis for L2. Also, the sequence {ej:j=1,2,} is an orthogonal basis for H10. In addition, the linear span of {ej:j=1,2,} is dense in Lp for any 1p<. Since the domain Ω is smooth, then ejC(Ω).

    For any uL2, there exists uj=uj(t)=(u,ej) such that

    u=j=1ujej,u2=j=1|uj|2.

    The powers of A are defined as follows [34]

    Asu=j=1λsjujej,sR.

    For s0, As:D(As)L2L2, and the domain of As is given by

    D(As)={uL2:u=j=1ujej,j=1λ2sj|uj|2<},

    which endowed with the graph norm

    uD(As)=Asu=(j=1λ2sj|uj|2)12

    and the associated scalar product

    (u,v)D(As)=j=1λ2sjujvj,

    where vj=(v,ej). Especially, D(As)=H2s0 for 14<s12 (see [35]).

    It worth to be mentioned that we introduce the space Hs (with s>0) as the domain D(As) equipped with the graph norm uD(As)=Asu. If s is negative, we define Hs as the completion of L2 with respect to the norm uD(As)=A|s|u.

    By the Poincaré inequality, one can easily see that if uL2 then (Δ)12uL2. So, we can define a Hilbert space as follows

    H=(L2,(,)H),

    where the scalar product (,)H is defined by

    (u,v)H=(u,v)+((Δ)12u,(Δ)12v)

    and the norm H is defined by

    u2H=u2+(Δ)12u2. (2.1)

    We note that the Poincaré inequality implies that the norms and H are equivalent norms on L2.

    Applying the operator (Δ)1 to (1.1). Then (1.1) becomes

    (Δ)1utt+utt+u+(Δ)1Δ2u+h(ut)f(u)=0. (2.2)

    Since (Δ)1Δ2u=Δu, for any u{uH4H10:ΔuΩ=0} (see [34,Lemma 1.7]), then the Eq (2.2) can be written as

    (Δ)1utt+utt+uΔu+h(ut)f(u)=0. (2.3)

    Then, the weak solution of (2.2) with the initial data of (1.1) and boundary value condition uΩ=0 is said to be the weak solution of the problem (1.1). This leads to the following definition.

    Definition 2.1 (weak solution). A function uC([0,T];H10)C1([0,T];L2) with utLq+1((0,T)×Ω) is said to be a weak solution to the problem (1.1) over [0,T], if and only if for any t[0,T], it satisfies

    ((Δ)12ut,(Δ)12φ)+(ut,φ)+t0[(u,φ)+(u,φ)+h(ut),φ(f(u),φ)]dτ=((Δ)12u1,(Δ)12φ)+(u1,φ),

    for all test functions φH10, and

    u(x,0)=u0(x)H10,ut(x,0)=u1(x)L2.

    Now, we give the Trudinger-Moser inequality [14,15] which will be used repeatedly to estimate the exponential nonlinearity.

    Lemma 2.1. For all uW1,n0(n2)

    eα|u|nn1L1,for allα>0, (2.4)

    and there exist positive constants C(n) which depends on n only, such that

    supuW1,n01Ωeα|u|nn1dxC(n)|Ω|,for allαα(n),

    where |Ω|=Ωdx, α(n)=nw1n1n1, and wn1 is the (n1)-dimensional measure of the (n1)-sphere.

    Remark 2.1. From Lemma 2.1, we know that f(u)L1 (in fact, from (2.4), f(u)Lp for any p1) for all uH10, and let

    F(u)=u0f(τ)dτ,

    we also infer that F(u)L1 and

    |F(u)|Cβ|u|eβ|u|2.

    The following lemma is for the convergence of the approximate solutions.

    Lemma 2.2 ([36]). Let X and Y be Banach spaces, X and Y be the dual spaces of X and Y respectively, and X a dense subset of Y and the inclusion map of X into Y continuous. Assume that

    unuweakly-star inL(0,T;X);untχweakly-star inL(0,T;Y)

    then χ=ut in L(0,T;Y).

    The next lemma is straightforward and follows from the continuity and monotonicity of the function h(u)=|u|q1u=|u|qsgn(u).

    Lemma 2.3. Let h(u)=|u|q1u=|u|qsgn(u). Then h generates a monotone operator from L1+1q(Ω) into L1+1q(Ω), i.e.,

    h(u)h(v),uv0u,vLq+1.

    Moreover, the mapping λh(u+λv),η is continuous from R to R for every fixed u,v,ηLq+1.

    The continuity of the solutions needs the following result which can be found in [37].

    Lemma 2.4. Let V and Y be Banach spaces, V reflexive, V a dense subset of Y and the inclusion map of V into Y continuous. Then,

    L(0,T;V)Cω([0,T];Y)=Cω([0,T];V),

    where

    Cw([0,T];Y)={uL(0,T;Y);u(t),yis continuous on[0,T],for allyY}.

    This section focus on the local well-posedness of (1.1) in the natural energy space. First, we establish the existence of a local weak solution to the corresponding linear problem of (1.1) by using a standard Galerkin approximation scheme based on the eigenfunctions {ej}j=1 of the operator A=Δ. The well-posedness of the nonlinear problem (1.1) shall be researched by the contraction mapping principle, and mainly by the Trudinger-Moser inequality to deal with the nonlinearity.

    Theorem 3.1. Let f satisfy (H1), u0H10, and u1L2. Then there exists a unique weak solution u of (1.1) in Ω×(0,Tmax), where Tmax is the life time of solutions. In addition, u satisfies the energy identity

    E(t)+t0uτq+1q+1dτ=E(0), (3.1)

    where

    E(t)=12(ut2H+u2H10)ΩF(u)dx.

    Here and after H is denoted by (2.1). Moreover, if

    supt[0,Tmax)(ut2H+u2H10)<

    then Tmax=.

    In order to prove Theorem 3.1, we firstly consider the following auxiliary result.

    Lemma 3.1. Let T>0, u0H10, u1L2, and uC([0,T];H10) with the norm maxt[0,T]uH10R for some constant R>0. Assume that f satisfies (H1). Then, there exists a unique

    vC([0,T];H10)C1([0,T];L2),vtLq+1(Ω×(0,T))

    which solves the linear problem

    {(Δ)1vtt+vttΔv+v+h(vt)f(u)=0,inΩ×R+,v(x,0)=u0(x),vt(x,0)=u1(x),inΩ,vΩ=0,onΩ×R+. (3.2)

    Proof. Let {ej}j=1 be the orthonormal basis for L2, as described in Section 2. For mN given, we seek m functions g1,m,g2,m,...,gm,mC2[0,T] such that

    vm(x,t)=mj=1gj,mej(x) (3.3)

    solves the problem

    ((Δ)1vmtt+vmtt+vmΔvm+h(vmt)f(u),η)=0, (3.4)
    vm(x,0)=mj=1ρjeju0inH10,asm, (3.5)
    vmt(x,0)=mj=1ξjeju1inL2,asm, (3.6)

    for every ηSpan{e1,e2,,em}. Taking η=ej in (3.4) yields the following Cauchy problem for a linear ordinary differential equation with unknown gj,m:

    (1+λ1j)gj,m+(1+λj)gj,m+(h(vmt),ej)=(f(u),ej),gj,m(0)=ρj,gj,m(0)=ξj(j=1,2,...,m).

    Then, by the standard ordinary differential equations theory, for all j, the above Cauchy problem yields a unique global solution gj,mC2(0,tm). In turn, this gives a unique vm(t)H2H10 for every t(0,tm) defined by (3.3) and satisfying (3.4)–(3.6). Taking η=vmt in (3.4), and integrating over [0,t](0,tm), we obtain

    12(vmt2H+vm2H10)+t0vmτq+1Lq+1dτ=12(vmt(x,0)2H+vm(x,0)2H10)+t0Ωf(u)vmτdxdτ. (3.7)

    We estimate the last term in the right-hand side of (3.7) thanks to the assumption (H1), the Hölder inequality. More precisely,

    t0Ωf(u)vmτdxdτCβt0Ωeβu2|vmτ|dxdτCβt0vmτLq+1(Ωeq+1qβu2dx)qq+1dτ.

    By means of the Young inequality, we achieve

    t0Ωf(u)vmτdxdτεt0vmτq+1Lq+1dτ+Cβ,εt0Ωeq+1qβu2dxdτ,

    for a appropriate small constant 0<ε<1. Since the assumption on u that maxt[0,T]uH10R, we find

    Ωeq+1qβu2dx=Ωeq+1qβu2H10(|u|uH10)2dxΩeq+1qβR2(|u|uH10)2dx.

    With the Moser-Trudinger inequality, for each β<4qπ(q+1)R2, we get

    Ωeq+1qβu2dxC(β,Ω).

    Thus,

    t0Ωf(u)vmτdxdτεt0vmτq+1Lq+1dτ+CT. (3.8)

    From the facts (3.5)–(3.8) we obtain

    vmt2H+vm2H10+t0vmτq+1Lq+1dτCT, (3.9)

    for every m1, where CT>0 is independent of m. So we can extend the approximated solutions vm to the whole interval [0,T] and the uniform estimate (3.9) also holds on [0,T]. Besides we get

    vmis bounded inL(0,T;H10),vmtis bounded inL(0,T;L2)Lq+1((0,T)×Ω).

    By the definition of h(vmt), we have

    t0Ω|h(vmτ)|q+1qdxdτ=t0Ω|vmτ|q+1dτCT.

    That means

    h(vmt)is bounded inLq+1q((0,T)×Ω).

    Moreover, by the Eq (3.4) we know that

    vmttis bounded inLq+1q(0,T;H1).

    Therefore, we can extract from the sequence {vm} a subsequence which we still denote by {vm} such that

    vmvweakly-star inL(0,T;H10),h(vmt)χweakly inLq+1q((0,T)×Ω). (3.10)

    Since n=2 and Ω is bounded we deduce immediately that uH10Lr for all 1r<+. From Lemma 2.2, we have that

    vmtvtweakly-star inL(0,T;H)Lq+1((0,T)×Ω),vmttvttweakly-star inLq+1q(0,T;H1). (3.11)

    Integrating (3.4) with respect to t from 0 to t and let m we obtain

    ((Δ)12vt,(Δ)12η)+(vt,η)+t0[(v,η)+(v,η)+χ,η(f(u),η)]dτ=((Δ)12u1,(Δ)12η)+(u1,η),

    for all test functions ηH10. So, we get a solution v to the following initial-boundary problem

    {(Δ)1vtt+vttΔv+v+χf(u)=0,inΩ×R+,v(x,0)=u0(x),vt(x,0)=u1(x),inΩ,vΩ=0,onΩ×R+,

    and

    vL(0,T;H10),vtL(0,T;L2),vttLq+1q(0,T;H1).

    Consequently,

    vH1(0,T;L2)C([0,T];L2),vtH1(0,T;H1)C([0,T];H1).

    By making use of Lemma 2.4, we deduce immediately that

    vCw([0,T];H10),vtCw([0,T];L2). (3.12)

    Noting that

    vttΔv=(IΔ)1Δ(f(u)+h(vt))L(0,T;L2)+L1+1q((0,T)×Ω),

    then form Corollary 4.1 of Starauss in [37], we conclude that vt2+v2 is a continuous function of t. Combining with (3.12), we have

    vC([0,T];H10),vtC([0,T];L2).

    So far, we shall have proved the existence of the solution of (3.2), if we show that χ=h(vt). Observing the monotonicity and continuity of h(vt), we follow the idea of monotonicity argument used in [38].

    On the one hand, noting that

    (Δ)1vtt+vtt+vΔv=χ+f(u)Lq+1q((0,T)×Ω)+L1(0,T;L2),

    and by considering ideas from [37,Theorem 4.1], v satisfies for all t(0,T] the energy identity

    12(vt2H+v2H10)+t0χ,vτdτ=12(u12H+u02H10)+t0Ωf(u)vτdxdτ. (3.13)

    On the other hand, it follows from (3.7), (3.10) and (3.11) that

    12(vt2H+v2H10)+lim infmt0h(vmτ),vmτdτ12(u12H+u02H10)+t0Ωf(u)vτdxdτ. (3.14)

    Therefore, (3.13) and (3.14) yield

    lim infmt0h(vmτ),vmτdτt0χ,vτdτ. (3.15)

    Now, let φL1+1q(0,T×Ω) be arbitrary. Then it follows from Lemma 2.3 and (3.15) that

    0lim infmt0h(vmτ)h(φ),vmτφdτt0χh(φ),vτφdτ. (3.16)

    By choosing φ(t)=vtλψ(t), where λR, (3.16) yields

    t0χh(vτλψ(t)),ψ(t)dτ0,

    for all λ0 and ψLq+1(0,T×Ω). By letting λ0 and recalling the continuity of h, we achieve

    t0χh(vτ),ψ(t)dτ0,ψLq+1(0,T×Ω),

    which implies χ=h(vt).

    The last work is the uniqueness of solutions, which follows arguing for contradiction: if v and w are two solutions of (3.2) which share the same initial data, by subtracting the equations and v is substituted by vw, we would get

    12(vtwt2H+vw2H10)+t0Ω(h(vτ)h(wτ))(vτwτ)dτ=0. (3.17)

    Observing the Mazur inequality

    2p|xy|p+1|x|x|py|y|p|(p+1)|xy|(|x|p+|y|p),p0,x,yR,

    we get

    (|s|q1s|t|q1t)(st)C|st|q+1,for alls,tR. (3.18)

    So, (2.1) can be estimated as

    12(vtwt2H+vw2H10)+Ct0vτwτq+1Lq+1dτ0,

    which immediately yields wv. The proof of Lemma 3.1 is now completed.

    Now we turn to the nonlinear problem (1.1) by using the contraction mapping principle.

    Proof of Theorem 3.1 Taking (u0,u1)H10×L2, let R2=2(u02H10+u12H) and for any T>0 considering a closed convex set MT to be a ball of radius R in the space M=C([0,T];H10)C1([0,T];L2),

    MT={uM:uMTR}

    with the norm u2MT=maxt[0,T]{u2H10+ut2H} and metric d(u,v)=uvMT. Obviously, (MT,d) is a complete metric space. By Lemma 3.1, for any uMT we may define v=Φ(u), being v the unique solution to problem (3.2). We claim that, for a suitable T>0, Φ is a contractive map satisfying Φ(MT)MT.

    It follows from the fact (3.13) that

    12(vt2H+v2H10)+t0vτq+1Lq+1dτ=12(u12H+u02H10)+t0Ωf(u)vτdxdτ. (3.19)

    For the last term, we argue in the same spirit (although slightly differently) as for (3.8) and we get

    |t0Ωf(u)vτdxdτ|εt0vτq+1Lq+1dτ+C(β,Ω)T. (3.20)

    Combining (3.19) with (3.20) and taking the maximum over [0,T] gives

    v2MT12R2+C(β,Ω)T.

    Choosing T sufficiently small, we get vMTR, which shows that Φ(MT)MT. Now, taking w1 and w2 in MT, subtracting the two equations (3.2) for v1=Φ(u1) and v2=Φ(u2), and setting z=v1v2 then z is the unique solution of the problem

    {(Δ)12ztt+zttΔz+z+h(v1t)h(v2t)=f(u1)f(u2),inΩ×R+,z(x,0)=0,zt(x,0)=0,inΩ,zΩ=0,onΩ×R+.

    Taking the assumption (H1) into account, we have

    |f(u1)f(u2)|Cβ(eβ|u1|2+eβ|u2|2)|u1u2|. (3.21)

    Using (3.18) again it holds

    12(zt2H+z2H10)+Ct0zτq+1Lq+1dτt0Ω(f(u1)f(u2))zτdxdτ.

    By (3.21), Lemma 2.1, the Hölder inequality and the Sobolev imbedding inequality, it deduces that

    t0Ω(f(u1)f(u2))zτdxdτCβt0Ω(eβ|u1|2+eβ|u2|2)|u1u2||zτ|dxdτCβt0zτu1u2Lq+1Ω(e2(q+1)q1β|u1|2+e2(q+1)q1β|u2|2)dxdτC(β,Ω)t0zτ2u1u22H10dτ, (3.22)

    for each β<2(q1)π(q+1)R2, where we have used the fact that 12+1q+1+q12(q+1)=1. Using the Young inequality, the estimate (3.22) becomes

    t0Ω(f(u1)f(u2))zτdxdτ12C2(β,Ω)Tu1u22MT+12t0zτ2dτ.

    Consequently,

    12(zt2H+z2H10)+Ct0zτq+1Lq+1dτ12C2(β,Ω)Tu1u22MT+12t0zτ2dτ.

    Applying Gronwall inequality and taking the maximum over [0,T], it follows that

    zMT=Φ(u1)Φ(u2)MTδu1u2MT,

    for some δ<1 provided T is sufficiently small. By the contraction mapping principle, there exists a unique solution u to (1.1) defined on [0,T], uC([0,T];H10)C1([0,T];L2) and from (3.19) the energy equality (3.1) holds. Theorem 3.1 is proved.

    The goal of this section is to prove that the local solution established in Theorem 3.1 can be extended globally in time when the initial data inside the potential well. So that we firstly introduce Nehari functional, Nehari manifold and the stable sets. Let

    J(u)=12u2H10ΩF(u)dx,

    and

    I(u)=u2H10Ωuf(u)dx.

    Related to the functional J, we have the well known Nehari manifold

    N={uH10{0};I(u)=0}.

    Let f:RR is a C1 function verifying both the assumption (H1) and the following properties:

    (H2) The function f satisfies the following condition near the origin

    limt0f(t)t=0.

    (H3) There exists θ>2 such that

    0<θF(t)<f(t)t for alltR{0}. (4.1)

    (H4) There are constants R0,M0>0 such that, for all |t|R0,

    0<F(t)M0|f(t)|.

    Then, it can be checked that the mountain-pass level d can be characterized as

    d=inf{supλ0J(λu):uH10,u0}=infuNJ(u)>0.

    The proof is refered to [17,27].

    Hereafter, we will denote by W and V the following sets:

    W={uH10;I(u)>0,J(u)<d}{0},V={uH10;I(u)<0,J(u)<d}.

    Under the assumptions imposed on f, it is can be proved that W and V are invariant sets related to (1.1) (Lemmas 4.1 and 4.1), which provide the possibilities for us to establish the global existence and nonexistence of the solutions.

    Remark 4.1. An interesting question is whether there is a function that meets the conditions (H1)–(H4). Now, we construct explicitly an example such that all assumptions (H1)–(H4) are satisfied.

    Example 1. Let f(t)=|t|p1teβ2t2 with p>1. Then f(t) satisfies (H1)–(H4).

    Proof. It follows from the fundamental inequality

    tb(bea)beat,fora>0,b>0,t(0,+)

    that

    |f(t)|=|t|peβ2t2(2peβ)peβ2teβ2t2Ceβt2.

    Which shows f(t) satisfies (H1). Obviously, f(t) satisfies (H2).

    For (H3), by the definition of F(t), we get

    F(t)=t0f(τ)dτ=t0|τ|p1τeβ2|τ|2dτ=t0|τ|p1τ+n=0(β2)n|τ|2nn!dτ=t0+n=0(β2)n|τ|2n+p1τn!dτ=+n=0(β2)n|t|2n+p+1n!(2n+p+1). (4.2)

    For p>1, we have

    (p+1)F(t)<|t|p+1+n=0(β2)n|t|2nn!=|t|p+1eβ2|t|2=tf(t). (4.3)

    Thus, f(t) satisfies (H3).

    At last, we show f verifies (H4). It follows from (4.2) that

    F(t)=|t|p+n=0(β2)n|t|2n+1n!(2n+p+1)=|t|p+n=1(β2)n1|t|2n1(n1)!(2(n1)+p+1)=|t|p+n=1(β2)n|t|2nn!2nβ(2(n1)+p+1)|t|.

    Obviously, for any constant R0>0, |t|1<1R0 for |t|>R0, and 2nβ(2(n1)+p+1)<1β. Thus,

    F(t)M0|t|p+n=1(β2)n|t|2nn!M0|t|p+n=0(β2)n|t|2nn!=M0|f(t)|,

    where M0=1βR0. f satisfies (H4).

    The following result is about the invariance of the set W under the flow of (1.1).

    Lemma 4.1 ([17,27]). Let f satisfy (H1)–(H4) and u be the unique local solution to (1.1). Assume that E(0)<d, then for all t[0,T], u belongs to W provide that u0 belongs to W, and

    u2H10<2θdθ2.

    Now we concerned with the global existence of the solution for the problem (1.1).

    Theorem 4.1 (Global solutions for E(0)<d). Let f(u) satisfy (H1)–(H4), and u be the unique local solution to (1.1). Assume that E(0)<d, and I(u0)>0 or u0H10=0. Then, u exists globally and uW, for all t[0,).

    Proof. From (4.1) we have

    E(t)=12ut2H+12u2H10ΩF(u)dx12ut2H+θ22θu2H10+1θ(u2H10Ωuf(u)dx)=12ut2H+θ22θu2H10+1θI(u).

    Since E(0)<d and I(u0)>0 or u0=0, it follows from Lemma 4.1 that I(u)>0 or uH10=0 for all t[0,Tmax), which implies that

    12ut2H+θ22θu2H10+t0uτq+1Lq+1dτ<E(0)<d,

    for all t[0,Tmax) and θ>2. Therefore, by virtue of Theorem 3.1 it yields Tmax=.

    This section is concerned with results on finite time blow-up of the solutions for the problem (1.1) with f(u)=|u|p1ueβ2|u|2,p>1. We firstly prove that when the initial energy is negative, the local solution can not be extended globally in time. Secondly, in the case of E(0)<d, we prove that when the initial data u0V, the local solution blows up in finite time. Lastly, we construct the sufficient conditions of finite time blow-up of the solutions with arbitrary positive initial energy.

    Now, we state the main results on the finite time blow-up of the solutions.

    Theorem 5.1 (Blow-up for E(0)0). Let f(u)=|u|p1ueβ2|u|2 for p>1, and u be the unique local solution to (1.1). Assume that E(0)<0 or E(0)=0 and (u0,u1)H>0. Then, the problem (1.1) does not admit any global weak solution.

    From Theorem 5.1 we can easily obtain the following result.

    Corollary 5.1. Let f(u)=|u|p1ueβ2|u|2 with p>1 and u be the unique local solution to (1.1). If there exists t0[0,T] such that E(t0)<0, then the problem (1.1) does not admit any global weak solution.

    The result about finite time blow-up of the solutions with the subcritical initial energy is based on the following three lemmas.

    Lemma 5.1 ([17,27]). Let f(u)=|u|p1ueβ2|u|2 with p>1 and u be the unique local solution to (1.1). Assume that E(0)<d, then for all t[0,T], u belongs to V provide that u0 belongs to V, and

    u2H10>2d. (5.1)

    Lemma 5.2. Let f(u)=|u|p1ueβ2|u|2 with p>1 and

    φ(λ)=12Ωλuf(λu)dxΩF(λu)dx.

    Then φ(λ) is strictly increasing on 0<λ<.

    Proof. By a simple calculation, we check

    u(uf(u)f(u))0, (5.2)

    and the equality holds only for u=0. With (5.2) we get

    ddλφ(λ)=12Ωuf(λu)dx+12Ωλu2f(λu)dxΩuf(λu)dx=12(Ωλu2f(λu)dxΩuf(λu)dx)=12λΩλu(λuf(λu)f(λu))dx0,

    the equality holds only for u=0. Thus, the proof of Lemma 5.2 is completed.

    Lemma 5.3. Let f(u)=|u|p1ueβ2|u|2 with p>1 and u be the unique local solution to (1.1). Assume that u belongs to V then

    I(u)<2(dE(0))

    Proof. We define the function W(λ)=I(λu) for λ>0. Observe that W(1)=I(u)<0 and

    W(λ)=λ2u2H10Ωλuf(λu)dx>0

    for λ sufficiently small. Hence there exists some λ0(0,1) such that W(λ0)=I(λ0u)=0. That is λ20u2H10=Ωλ0uf(λ0u)dx. By the definition of d, we obtain

    d=infuNJ(u)J(λ0u)=12λ20u2H10ΩF(λ0u)dx=12Ωλ0uf(λ0u)dxΩF(λ0u)dx.

    It follows from Lemma 5.2 that

    12Ωλ0uf(λ0u)dxΩF(λ0u)dx<12Ωuf(u)dxΩF(u)dx=12u2H10ΩF(u)dx12(u2H10Ωuf(u)dx)=J(u)12I(u)E(t)12I(u)E(0)12I(u).

    That is,

    I(u)<2(E(0)d).

    This completes the proof of Lemma 5.3.

    Theorem 5.2 (Blow-up for E(0)<d). Let f(u)=|u|p1ueβ2|u|2 with p>1 and u be the unique local solution to (1.1). Assume that E(0)<γd for some constant 0<γ12, and u0V. Then, the problem (1.1) does not admit any global weak solution.

    Theorem 5.3 (Blow-up for E(0)>0). Let f(u)=|u|p1ueβ2|u|2 with p>1 and u be the unique local solution to (1.1). Assume that E(0)>0, and

    (u0,u1)H>qq+1M1qE(0)>0, (5.3)

    then the problem (1.1) does not admit any global weak solution, where M is the root of the equation

    K(M)ω(M)=qM1qq+1

    on (M0,+),

    M0={Cβ,Ω(p+1)(q+1)(p1),ifpq,(q1)λ1+pq(p1)2λ1,ifp>q,K(M)={(p+1)(1Cβ,Ω(q+1)M),ifpq,p+1q1M(p1),ifp>q,
    ω(M)={λ1(K(M)+2)(K(M)2),ifpq,(K(M)+2)[(K(M)2)λ1pq(p1)M],ifp>q,

    Cβ,Ω>0 is a constant depending on β and Ω, and λ1 is the first eigenvalue of Δ with zero Dirichlet boundary data on the smooth bounded domain ΩR2.

    Now, we concerned with our proofs of Theorems 5.1–5.3.

    Proof of Theorem 5.1 Arguing by contradiction, we suppose that Tmax=+. For any 0<T<, we define

    G(t)=u2H=(Δ)12u2+u2,t[0,T]. (5.4)

    Then,

    G(t)=2((Δ)12u,(Δ)12ut)+2(u,ut).

    Note that the standard approximation argument shows that G(t) exists and by the Eq (2.3), we have

    G(t)=2u2H10+2ut2H+2Ωuf(u)dx2Ωuh(ut)dx=4ut2H4E(t)+2Ω(uf(u)2F(u))dx2Ω|ut|q1utudx.

    Let

    H(t)=E(t).

    It follows from the energy equality (3.1) that

    H(t)=utq+1Lq+10.

    So that H(t) is increasing on [0,T] and noting the fact (4.3), we have

    0E(0)=H(0)H(t)ΩF(u)dx<1p+1Ωuf(u)dx. (5.5)

    Now considering the following function defined on [0,T]

    L(t)=H1α(t)+ϵG(t),

    where 0<α<1 and ϵ>0 are sufficiently small and given later. A simple computation entails

    L(t)=(1α)Hα(t)H(t)+ϵG(t)=(1α)Hα(t)H(t)+4ϵut2H4ϵE(t)+2ϵΩ(uf(u)2F(u))dx2ϵΩ|ut|q1utudx. (5.6)

    By the Young inequality we have

    |Ω|ut|q1utudx|δq+1q+1uq+1Lq+1+qq+1δq+1qutq+1Lq+1, (5.7)

    for some δ>0 to be fixed later. Substituting (5.7) into (5.6), and noting H(t)=E(t) we obtain

    L(t)[(1α)Hα(t)2ϵqq+1δq+1q]H(t)+4ϵut2H+4ϵH(t)+2ϵΩ(f(u)u2F(u)δq+1q+1uq+1Lq+1)dx. (5.8)

    Taking δ such that δq+1q=kHα(t), the constant k>0 will be chosen later, then from (5.5), we have

    δq+1=kqHαq(t)kq(ΩF(u)dx)αq(p+1)αqkq(Ωuf(u)dx)αq.

    For any m>q, by means of the Hölder inequality, we obtain

    uq+1Lq+1CΩuq+1Lm+1=CΩ(Ω|u|m+1dx)q+1m+1.

    Taking m>p, it holds

    Ω|u|m+1dx=Ω|u|p+1|u|mpdxC(β)Ω|u|p+1eβ2u2dx=C(β)Ωuf(u)dx. (5.9)

    Then, taking m>max{p,q}, we arrive at

    uq+1Lq+1CΩ,β(Ωuf(u)dx)q+1m+1.

    Thus,

    δq+1uq+1Lq+1CΩ,β(p+1)αqkq(Ωuf(u)dx)αq+q+1m+1.

    Taking 0<αmqq(m+1) such that αq+q+1m+11 and s=αq+q+1m+110. By (5.5) again,

    δq+1uq+1Lq+1CΩ,β(p+1)αq+skqH(0)sΩuf(u)dx.

    Therefore, (5.8) can be estimated by

    L(t)[(1α)2ϵkqq+1]Hα(t)H(t)+4ϵut2H+4ϵH(t)+2ϵ(12p+1CΩ,β(p+1)q+1m+11kqH(0)s)Ωuf(u)dx.

    Taking k>0 sufficiently large such that 12p+1CΩ,β(p+1)q+1m+11kqH(0)s>0, and for the fixed k picking ϵ>0 appropriate small such that (1α)2ϵkqq+1>0 and

    L(0)=H1α(0)+2ϵ(u0,u1)H>0, (5.10)

    for H(0)>0. Thus, we have

    L(t)γϵ(H(t)+ut2H+Ωuf(u)dx). (5.11)

    On the other hand, by the Hölder inequality and the Young inequality, we have

    G(t)11α211α|(u,ut)H|11αC(Δ)12u11α(Δ)12ut11α+Cu11αut11αC(u212αH+ut2H)C(u212α+ut2H),

    for 0<α<12.

    Case 1. When u1, taking αp12(p+1) such that 212αp+1, then by the Hölder inequality, we achieve

    u212α=u(p+1)+212αup+1Cup+1Lp+1CΩuf(u)dx

    Case 2. When u1, it follows from the energy equality (3.1), the assumption E(0)<0 and the last inequality of (5.5) that

    12u2ΩF(u)dx1p+1Ωuf(u)dx.

    Noting that 212α>2, then

    u212αu22p+1Ωuf(u)dx.

    Therefore, we obtain

    G(t)11αC(Ωuf(u)dx+ut2H).

    Consequently, by taking 0<αmin{mqq(m+1),p12(p+1)} and from the above argument we have

    L11α(t)=(H1α(t)+2ϵG(t))11αC(H(t)+ut2H+Ωuf(u)dx).

    Combining with (5.11), it holds that

    L(t)CL(t)11α,t[0,T].

    The fact (5.10) and the assumption (u0,u1)H>0 if E(0)=0 entail L(0)>0 for E(0)0. Then by a calculation we have

    L(t)[L(0)α1ααC1αt]1αα,t[0,T],

    which shows that L(t) blows up in finite time

    Tmax1ααCL(0)α1α.

    This completes the proof of Theorem 5.1.

    The proof of Theorem 5.2 Arguing by contradiction, we suppose that Tmax=+. Taking d1(E(0),γd) for 0<γ12 and setting

    ˜H(t)=d1E(t).

    It follows from the energy equality (3.1) that

    ˜H(t)=utq+1Lq+10.

    So that ˜H(t) is increasing on [0,T]. Noting that u(t)V we conclude from (5.1) that

    12u2H10d1>dd1>0,

    which deduce that

    0<˜H(0)˜H(t)ΩF(u)dx<1p+1Ωuf(u)dx,t[0,T].

    Considering the following function defined on [0,T]

    ˜L(t)=˜H1α(t)+ϵG(t),

    where G(t) is defined by (5.4), 0<α<1 and ϵ>0 are sufficiently small and given later. By the direct calculation as (5.6), we deduce that

    ˜L(t)=(1α)˜Hα(t)˜H(t)+4ϵut2H4ϵE(t)+2ϵΩ(uf(u)2F(u))dx2ϵΩ|ut|q1utudx=(1α)˜Hα(t)˜H(t)+3ϵut2H2ϵd1ϵu2H10+2ϵ˜H(t)+2ϵΩ(f(u)uF(u))dx2ϵΩ|ut|q1utudx=(1α)˜Hα(t)˜H(t)+3ϵut2H2ϵd1ϵI(u)+2ϵ˜H(t)+ϵΩ(f(u)u2F(u))dx2ϵΩ|ut|q1utudx. (5.12)

    It follows from Lemma 5.3 that

    2ϵd1ϵI(u)>2ϵd1+2ϵ(dE(0))>2ϵ(12γ)d0

    for 0<γ12. Substituting the above inequality into (5.12), it holds

    ˜L(t)(1α)˜Hα(t)˜H(t)+3ϵut2H+2ϵ˜H(t)+ϵΩ(f(u)u2F(u))dx2ϵΩ|ut|q1utudx.

    The remainder of the argument is analogous to that in (5.6) and so omitted. The proof Theorem 5.2 is completed.

    The proof of Theorem 5.3 Arguing by contradiction, we suppose that Tmax=+. For t[0,+), considering the function

    L1(t)=G(t)2qq+1M1qE(t),

    where G(t) is given by (5.4). Similar to the proof of Theorem 5.1, by the estimate (5.7) with δq+1q=M1q, we have

    L1(t)=2u2H10+2ut2H+2Ωuf(u)dx2Ω|ut|q1utudx+2qq+1M1qutq+1Lq+12u2H10+2ut2H+2Ωuf(u)dx2(q+1)MΩ|u|q+1dx.

    Case 1. For qp, by means of the fact (5.9), and recalling the assumption (4.3), we have

    L1(t)2u2H10+2ut2H+2(1Cβ,Ω(q+1)M)Ωuf(u)dx2u2H10+2ut2H+2(p+1)(1Cβ,Ω(q+1)M)ΩF(u)dx.

    Taking M>M0=(p+1)Cβ,Ω(q+1)(p1) such that (p+1)(1Cβ,Ω(q+1)M)2>0, and by using the Poincaré inequality, we deduce

    L1(t)λ1[(p+1)(1Cβ,Ω(q+1)M)2]u2H+[(p+1)(1Cβ,Ω(q+1)M)+2]ut2H2(p+1)(1Cβ,Ω(q+1)M)E(t)=λ1(K(M)2)u2H+(K(M)+2)ut2H2K(M)E(t).

    By using the Cauchy inequality,

    λ1(K(M)2)u2H+(K(M)+2)ut2H2λ1(K(M)2)(K(M)+2)(u,ut)H=2ω(M)(u,ut)H,

    we get

    L1(t)ω(M)(2(u,ut)H2K(M)ω(M)E(t)) (5.13)

    By a simple calculation, we have

    limMM0K(M)ω(M)=+,limMM0qq+1M1q=qq+1M1q0limM+K(M)ω(M)=p+1λ1(p1)(p+3),limM+qq+1M1q=+.

    Obviously, there exists M>M0 such that

    K(M)ω(M)=qq+1M1q,

    and the estimate (5.13) becomes

    L1(t)ω(M))L1(t).

    The condition (5.3) guarantees L1(0)>0. Thus, it yields

    L1(t)L1(0)eω(M)t,t0.

    By the assumption that u is the global solution, we have, from Corollary 5.1, we have 0E(t)E(0). Thus,

    G(t)L1(0)eω(M)t,t0.

    Therefore,

    G(t)=u2Hu02H+1α(M)L1(0)(eω(M)t1),t0. (5.14)

    Case 2. For q<p, observe that the function

    g(y)=ayy,a0,a1,y>0

    is convex. By the properties of convex functions, we have

    1q+1Ω|u|q+1dxpq2(p1)Ω|u|2dx+q1(p+1)(p1)Ω|u|p+1dxpq2(p1)u2+q1(p+1)(p1)Ωuf(u)dx.

    Thus, by the the Poincaré inequality we have

    L1(t)2u2H10pqM(p1)u2+2ut2H+2(1q1M(p+1)(p1))Ωuf(u)dx2u2H10pqM(p1)u2+2ut2H+2(p+1q1M(p1))ΩF(u)dx[(K(M)2)λ1pqM(p1)]u2H+[K(M)+2]ut2H2K(M)E(t),

    where K(M)=p+1q1M(p1)>0 and

    K1(M)(K(M)2)λ1pq(p1)M>0.

    By a similar argument to that in Case1, we can obtain (5.14), and in order to avoid redundancy, we omit it here.

    On the other hand, it follows from the Hölder inequality and the Poincaré inequality that

    uHu0H+t0uτHdτu0H+(1+1λ1)t0uτdτu0H+Ct0uτLq+1dτu0H+Ctqq+1(t0uτq+1Lq+1dτ)1q+1u0H+Ctqq+1E(0)1q+1,

    which is a contradiction with (5.14). The proof of Theorem 5.3 is completed.

    Remark 5.1. Asymptotic behavior of solutions for the problem (1.1) is also an interesting and important work, which is the further work to be considered.

    The authors thank the referees for their valuable comments and suggestions which helped improving the original manuscript.

    The project is supported by the Natural Science Foundation of Henan (202300410109), the Fundamental Research Funds for the Henan Provincial Colleges and Universities in Henan University of Technology (2018QNJH19), the training plan for young backbone teachers of Henan University of Technology, the Innovative Funds Plan of Henan University of Technology (2020ZKCJ09).

    The authors declare there is no conflicts of interest.



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