This work is devoted to studying the distribution of zeros of a first-order neutral differential equation with several delays
[y(t)+a(t)y(t−σ)]′+n∑j=1bj(t)y(t−μj)=0,t≥t0.
New estimations for the upper bounds of the distance between successive zeros are obtained. The properties of a positive solution of a first-order differential inequality with several delays in a closed interval are studied, and many results are established. We apply these results to a first-order neutral differential equation with several delays and also to a first-order differential equation with several delays. Our results for the differential equation with several delays not only provide new estimations but also improve many previous ones. Also, the results are formulated in a general way such that they can be applied to any functional differential equation for which studying the distance between zeros is equivalent to studying this property for a first-order differential inequality with several delays. Further, new estimations of the upper bounds for certain equations are given. Finally, a comparison with all previous results is shown at the end of this paper.
Citation: Emad R. Attia. On the upper bounds for the distance between zeros of solutions of a first-order linear neutral differential equation with several delays[J]. AIMS Mathematics, 2024, 9(9): 23564-23583. doi: 10.3934/math.20241145
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This work is devoted to studying the distribution of zeros of a first-order neutral differential equation with several delays
[y(t)+a(t)y(t−σ)]′+n∑j=1bj(t)y(t−μj)=0,t≥t0.
New estimations for the upper bounds of the distance between successive zeros are obtained. The properties of a positive solution of a first-order differential inequality with several delays in a closed interval are studied, and many results are established. We apply these results to a first-order neutral differential equation with several delays and also to a first-order differential equation with several delays. Our results for the differential equation with several delays not only provide new estimations but also improve many previous ones. Also, the results are formulated in a general way such that they can be applied to any functional differential equation for which studying the distance between zeros is equivalent to studying this property for a first-order differential inequality with several delays. Further, new estimations of the upper bounds for certain equations are given. Finally, a comparison with all previous results is shown at the end of this paper.
Consider the first-order neutral differential equation with several delays
[y(t)+a(t)y(t−σ)]′+n∑j=1bj(t)y(t−μj)=0,t≥t0,(E1) |
where a,bj∈C([t0,∞),[0,∞)), 0<σ<μ1≤μ2≤⋯≤μn, and the first-order differential equation with several delays
y′(t)+n∑j=1bj(t)y(t−μj)=0,t≥t0.(E2) |
By a solution of Eq (E1) on [t∗+μn,∞), t∗≥t0, we mean a function y∈C([t∗,∞),R) such that y(t)+a(t)y(t−σ)∈C1([t∗+μn−σ,∞),R) and satisfies (E1) for all t≥t∗+μn. The existence and uniqueness of a solution y(t) of Eq (E1) with an initial function ϕ∈C([t0−μn,t0],R) can be proved using the method of steps as in [24, Thereoem 1.1.2]. Also, the existence of a positive solution for some neutral differential equations can be found in [25].
A solution is said to be oscillatory if it is neither eventually negative nor eventually positive; otherwise, it is called non-oscillatory. If all solutions of a differential equation are oscillatory, then it is called oscillatory; otherwise, it is called non-oscillatory.
Recently, neutral differential equations have arisen in many applications; see [1,5,23,24,27,28,29,34,35,36]. In this type of equation, the delays appear in both the unknown function and its derivatives. The qualitative properties of neutral differential equations have received a great deal of attention from many mathematicians; see [1,2,5,6,7,9,12,14,15,16,19,20,21,22,23,24,26,27,28,29,34,35,36,37,38,40,41,42]. In dynamical models, delay and oscillation effects are often formulated by means of external sources and/or nonlinear diffusion, perturbing the natural evolution of related systems; see, e.g., [30,31]. The oscillation of neutral and delay differential equations has been extensively developed and studied in many works; see [2,5,6,7,9,12,13,14,15,16,19,20,21,22,24,26,37,38,40,41]. On the other hand, the oscillation of first-order differential equations has numerous applications in the study of the oscillatory behavior of higher-order neutral differential equations; see [32,33]. However, only a few works have been interested in studying the distance between zeros of all solutions for first-order neutral and delay differential equations; see [2,3,4,6,7,8,10,11,15,17,18,37,38,39,40,41]. In this type of study, the interest is not only in the existence of zeros of solutions (i.e., proving the oscillation) but also in determining their locations. Therefore, studying the distance between zeros for first-order linear neutral and delay differential equations can give a deeper understanding of the dynamics of nonlinear systems of neutral differential equations that are used to model many real-life phenomena. This motivates us to study the distance between successive zeros for all solutions of Eqs (E1) and (E2).
In the following, we display some results for the distance between zeros for Eqs (E1) and (E2):
The distribution of zeros in first-order differential equations with one delay or several delays was studied by [3,4,8,10,11,17,18,39]. Further, many estimations for the upper bounds of the distance between zeros for first-order neutral differential equations were established by [2,6,7,15,37,38,40,41]. However, there are no results dealing with the distribution of zeros in Eq (E1).
In this work, we obtain sufficient conditions ensuring that any solution of the first-order differential inequality with several delays
Y′(t)+n∑j=1Bj(t)Y(t−ηj)≤0,t∈[L+α,L0], | (1.1) |
where L0≥L+α, L≥t0, α≥0 such that 0<η1≤η2≤⋯≤ηn, and Bj∈C([L+α,∞),[0,∞)), j=1,2,...,n, cannot be positive on certain intervals. By using these results, many new estimations for the upper bounds of the distance between zeros for both Eqs (E1) and (E2) are obtained. A new approximation for the distance between successive zeros of a certain differential equation of the form (E2) is given, while all previous results cannot give this approximation. Since the distribution of zeros in all solutions of Eq (E1) has never been examined before, our results for Eq (E1) are obviously new. An illustrative example is given to show the applicability of our results to Eq (E1).
In this section, we study the properties of a positive solution to the first-order differential inequality with several delays (1.1).
Let Y(t) be a solution of inequality (1.1) on [L+α,L0], L0≥L+α such that
Y(t)>0 for t∈[L+γ,L+α] and Y′(t)≤0 for t∈[L+δ,L+β], | (2.1) |
where γ,δ≥0 and β=max{α,ηn+γ}.
Next, we prove some lemmas that play an important role in establishing the main results of this work.
Assume that s∈{1,2,...,n} and the sequence of nonnegative real numbers {Msl}l≥−1 is defined by
Ms−1=0,Ms0=1,e∫tt−ηs∑nj=1j≠sMjl−1Bj(v)dv1−∫tt−ηsBs(v)dv≥Msl,l=1,2,… . | (2.2) |
Lemma 2.1. Assume that l∈N0, Y(t) is a solution of inequality (1.1) on [L+α,L0] such that (2.1) is satisfied with L0≥L+max{δ,α}+(l+1)ηn and Y(t)>0 on [L+α,L0]. Then
Y(t−ηs)Y(t)≥Mslfort∈[L+max{δ,α}+(l+1)ηn,L0] | (2.3) |
for s=1,2,...,n.
Proof. In view of Y′(t)≤0 for t∈[L+δ,L+β] and Y(t)>0 for t∈[L+γ,L0], it follows from (1.1) that
Y′(t)≤0 for t∈[L+δ,L0]. | (2.4) |
Therefore,
Y(t−ηs)Y(t)≥1=Ms0 for t∈[L+δ+ηs,L0]⊆[L+max{δ,α}+ηn,L0]. | (2.5) |
Integrating (1.1) from t−ηs to t, it follows that
Y(t)−Y(t−ηs)+∫tt−ηsn∑j=1Bj(v)Y(v−ηj)dv≤0 for t∈[L+α+ηs,L0]. |
Therefore,
Y(t)−Y(t−ηs)+∫tt−ηsBs(v)Y(v−ηs)dv+n∑j=1j≠s∫tt−ηsBj(v)Y(v)Y(v−ηj)Y(v)dv≤0 | (2.6) |
for t∈[L+α+ηn,L0]. Dividing (1.1) by Y(t), and integrating the resulting inequality from ζ to μ, L+α+ηn≤ζ≤μ≤L0, we obtain
Y(ζ)≥Y(μ)e∫μζ∑nj1=1Bj1(v)Y(v−ηj1)Y(v)dv. | (2.7) |
Substituting into (2.6), we obtain
Y(t)−Y(t−ηs)+∫tt−ηsBs(v)Y(v−ηs)dv+Y(t)n∑j=1j≠s∫tt−ηsBj(v)Y(v−ηj)Y(v)e∫tv∑nj1=1Bj1(v1)Y(v1−ηj1)Y(v1)dv1dv≤0 |
for t∈[L+α+ηn+ηs,L0].
By (2.4), we have
Y(t)−Y(t−ηs)+Y(t−ηs)∫tt−ηsBs(v)dv+Y(t)∫tt−ηsn∑j=1j≠sBj(v)Y(v−ηj)Y(v)e∫tv∑nj1=1j1≠sBj1(v1)Y(v1−ηj1)Y(v1)dv1dv≤0 |
for t∈[L+max{δ+ηs,α+ηn}+ηs,L0]. This leads to
Y(t)−Y(t−ηs)+Y(t−ηs)∫tt−ηsBs(v)dv+Y(t)(e∫tt−ηs∑nj=1j≠sBj(v)Y(v−ηj)Y(v)dv−1)≤0 |
for t∈[L+max{δ+ηs,α+ηn}+ηs,L0]. That is,
Y(t−ηs)(1−∫tt−ηsBs(v)dv)≥Y(t)e∫tt−ηs∑nj=1j≠sBj(v)Y(v−ηj)Y(v)dv |
for t∈[L+max{δ+ηs,α+ηn}+ηs,L0]. Therefore
Y(t−ηs)Y(t)≥e∫tt−ηs∑nj=1j≠sBj(v)Y(v−ηj)Y(v)dv1−∫tt−ηsBs(v)dv>0 for t∈[L+max{δ+ηs,α+ηn}+ηs,L0]. | (2.8) |
In view of (2.5), we obtain
Y(t−ηs)Y(t)≥e∫tt−ηs∑nj=1j≠sMj0Bj(v)dv1−∫tt−ηsBs(v)dv≥Ms1 |
for t∈[L+max{δ+ηs,α+ηn}+ηn,L0]⊆[L+max{δ,α}+2ηn,L0]. Therefor,
Y(v−ηj)Y(v)≥Mj1,for t∈[L+max{δ+ηj,α+ηn}+ηn,L0],1≤j≤n. |
Substituting into (2.8), we have
Y(t−ηs)Y(t)≥e∫tt−ηs∑nj=1j≠sMj1Bj(v)dv1−∫tt−ηsBs(v)dv≥Ms2 |
for t∈[L+max{δ,α}+3ηn,L0]. By repeating this procedure, we obtain (2.3). The proof is complete.
Lemma 2.2. Assume that l∈N0, 0<ϵ≤1, and Y(t) is a solution of inequality (1.1) on [L+α,L0] such that (2.1) is satisfied with L0≥L+max{δ,α}+(l+1+ϵ)ηn. If,
n∏s=1(∏nj=1j≠s∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)1n−11−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv≥1(n−1)nfort≥L+2ηn, | (2.9) |
then Y(t) cannot be positive on [L+α,L0].
Proof. Assume the contrary, and let Y(t)>0 on [L+α,L0]. This together with (2.1) implies that Y(t)>0 on [L+γ,L0]. Form (2.4), we have
Y′(t)≤0 for t∈[L+δ,L0]. | (2.10) |
Integrating (1.1) from t to t−ϵηs, s=1,2,…,n, we obtain
Y(t)−Y(t−ϵηs)+∫tt−ϵηsn∑j=1Bj(v)Y(v−ηj)dv≤0 for t∈[L+α+ϵηs,L0]. |
Therefore,
Y(t)−Y(t−ϵηs)+∫tt−ϵηsBs(v)Y(v−ηs)dv+∫tt−ϵηsn∑j=1j≠sBj(v)Y(v−ηj)dv≤0 | (2.11) |
for t∈[L+α+ϵηs,L0]. By (2.10), we obtain
Y(t)−Y(t−ϵηs)+Y(t−ηs)∫tt−ϵηsBs(v)dv+n∑j=1j≠sY(t−ηj)∫tt−ϵηsBj(v)dv≤0 |
for t∈[L+max{δ,α}+ϵηs+ηn,L0]. That is,
Y(t−ϵηs)≥Y(t)+Y(t−ϵηs)∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mj−1dv1dv+n∑j=1j≠sY(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1−1dv1dv | (2.12) |
for t∈[L+max{δ,α}+ϵηs+ηn,L0].
From (2.7) and (2.11), we have
Y(t−ϵηs)≥Y(t)+Y(t−ϵηs)∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj1=1Bj1(v1)Y(v1−ηj1)Y(v1)dv1dv+n∑j=1j≠sY(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Y(v1−ηj1)Y(v1)dv1dv |
for t∈[L+α+ϵηs+2ηn,L0]. This, together with (2.3) leads to
Y(t−ϵηs)≥Y(t)+Y(t−ϵηs)∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv+n∑j=1j≠sY(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dvl=1,2,… |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηs,L0]. From this and (2.12), we have
Y(t−ϵηs)(1−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv)>n∑j=1j≠sY(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv,l=0,1,2,… |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηs,L0]. Using the arithmetic-geometric mean, we obtain
Y(t−ϵηs)(1−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv)>(n−1)(n∏j=1j≠sY(t−ϵηj))1n−1(n∏j=1j≠s∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)1n−1 |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηs,L0]. Taking the product on both sides,
n∏s=1Y(t−ϵηs)n∏s=1(1−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv)>(n−1)nn∏s=1(n∏j=1j≠sY(t−ϵηj))1n−1n∏s=1(n∏j=1j≠s∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)1n−1 |
for t∈[L+max{δ,α}+(l+1+ϵ)ηn,L0]. Therefore,
n∏s=1Y(t−ϵηs)n∏s=1(1−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv)>(n−1)nn∏s=1Y(t−ϵηs)n∏s=1(n∏j=1j≠s∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)1n−1 |
for t∈[L+max{δ,α}+(l+1+ϵ)ηn,L0]. Then
n∏s=1(∏nj=1j≠s∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)1n−11−∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv<1(n−1)n |
for t∈[L+max{δ,α}+(l+1+ϵ)ηn,L0]. This contradicts with (2.9). The proof is complete.
Lemma 2.3. Assume that l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1, and Y(t) is a solution of inequality (1.1) on [L+α,L0] such that (2.1) is satisfied with L0≥L+max{δ,α}+(l+1)ηn+ϵηk2. If,
k2∏s=k1∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj=1Bj(v1)Mjl−1dv1dv1−∑nj=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv≥1fort≥T+α+ϵηk2+ηn, | (2.13) |
then Y(t) cannot be positive on [L+α,L0].
Proof. As before, assume that Y(t)>0 on [L+α,L0]. Integrating (1.1) from t to t−ϵηs, s=1,2,…,k2, it follows that
Y(t)−Y(t−ϵηs)+∫tt−ϵηsn∑j=1Bj(v)Y(v−ηj)dv≤0 for t∈[L+α+ϵηs,L0]. |
Therefore,
Y(t)−Y(t−ϵηs)+∫tt−ϵηss∑j=1Bj(v)Y(v−ηj)dv+∫tt−ϵηsn∑j=s+1Bj(v)Y(v−ηj)dv≤0 |
for t∈[L+α+ϵηs,L0]. The same reasoning as in Lemma 2.2 leads to
Y(t−ϵηs)≥Y(t)+s∑j=1Y(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv+Y(t−ϵηs)n∑j=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηs,L0]. Consequently,
Y(t−ϵηs)(1−n∑j=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)>s∑j=1Y(t−ϵηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηs,L0]. Taking the product on both sides,
k2∏s=k1Y(t−ϵηs)k2∏s=k1(1−n∑j=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)>k2∏s=k1(s∑j=1Y(t−ηj)∫tt−ϵηsBj(v)e∫t−ϵηjv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv) |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηk2,L0]. That is,
k2∏s=k1Y(t−ϵηs)k2∏s=k1(1−n∑j=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv)>k2∏s=k1Y(t−ηs)k2∏s=k1(∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj1=1Bj1(v1)Mj1l−1dv1dv) |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηk2,L0]. Therefore,
k2∏s=k1∫tt−ϵηsBs(v)e∫t−ϵηsv−ηs∑nj1=1Bj1(v1)Mj1l−1dv1dv1−∑nj=s+1∫tt−ϵηsBj(v)e∫t−ϵηsv−ηj∑nj1=1Bj1(v1)Mj1l−1dv1dv<1 |
for t∈[L+max{δ,α}+(l+1)ηn+ϵηk2,L0], which contradicts (2.13). The proof is complete.
Assume that Dt≥t1(E), t1≥t0 is the upper bound of the distance between successive zeros of all solutions of a differential equation E on [t1,∞).
Below, we obtain new approximations for the upper bound of the distance between successive zeros of all solutions of Eq (E2).
Theorem 3.1. Let
Bj(t)=bj(t),ηj=μj,j=1,2,…,n. |
Assume that l∈N0, 0<ϵ≤1. If,
n∏s=1(∏nj=1j≠s∫tt−ϵμsbj(v)e∫t−ϵμjv−μj∑nj1=1bj1(v1)Mj1l−1dv1dv)1n−1(1−∫tt−ϵμsbs(v)e∫t−ϵμsv−μs∑nj=1bj(v1)Mjl−1dv1dv)≥1(n−1)nfort≥t0+2μn, |
then Dt1(E2)≤(l+2+ϵ)μn and every solution of Eq (E2) is oscillatory.
Proof. Assume the contrary, and let y(t) be a solution of Eq (E2) such that y(t)>0 on [L,L0], L≥t0, L0≥L+(l+2+ϵ)μn. Therefore, y′(t)≤0 for t∈[L+μn,L0]. Then, all assumptions of Lemma 2.2 are satisfied with α=γ=0, δ=β=μn, Bj(t)=bj(t), and ηj=μj, j=1,2,…,n. Therefore, y(t) cannot be positive on [L,L+(l+2+ϵ)μn]⊆[L,L0]. This contradiction completes the proof.
Using Lemma 2.3 instead of Lemma 2.2 in the proof of the preceding theorem, one can prove the following result, and hence the proof is omitted.
Theorem 3.2. Let
Bj(t)=bj(t),ηj=μj,j=1,2,…,n. |
Assume that l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1. If,
k2∏s=k1∫tt−ϵμsbs(v)e∫t−ϵμsv−μs∑nj1=1bj1(v1)Mj1l−1dv1dv(1−∑nj=s+1∫tt−ϵμsbj(v)e∫t−ϵμsv−μj∑nj1=1bj1(v1)Mj1l−1dv1dv)≥1fort≥t0+α+ϵμk2+μn, | (3.1) |
then Dt1(E2)≤(l+2)μn+ϵμk2 and every solution of Eq (E2) is oscillatory.
We obtain many upper bounds for the distance between zeros of all solutions of Eq (E1) with the following assumptions:
(H1) Let R∈C1[[t∗+σ,∞),[0,∞)], t∗≥t0, bj(t)a(t−μj)≤bj(t−σ)a(t−σ), j=1,2,…,n, and R(t)≥a(t−σ), t≥t1+σ for some t1≥t∗.
(H2) Let N∈C1[[t∗+μn,∞),[0,∞)], t∗≥t0, bj(t)>0, j=1,2,…,n, N(t)≥∑nj=1bj(t)a(t−μj)bj(t−σ), t≥t1+μn for some t1≥t∗.
Lemma 3.1. Assume that (H1) holds, R′(t)≤0 for t≥t1+σ. Let y(t) be a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥L0+2μn, L≥t1. Then, there exists a function z(t) that satisfies z(t)>0 on [L+2σ,L0] and z′(t)≤0 on [L+σ+μn,L0], and
z′(t)+n∑j=1bj(t)1+R(t)z(t+σ−μj)≤0fort∈[L+2μnL0]. | (3.2) |
Proof. Letting u(t)=y(t)+a(t)y(t−σ), so u(t)>0 for [L+σ,L0] and
u′(t)=−n∑j=1bj(t)y(t−μj)≤0fort∈[L+μn,L0]. |
Therefore u′(t)≤0 for t∈[L+μn,L0]. Note that
y(t−μj)=u(t−μj)−a(t−μj)y(t−σ−μj). |
Then
u′(t)=−n∑j=1bj(t)u(t−μj)+n∑j=1bj(t)a(t−μj)y(t−σ−μj)fort∈[L+μn,L0]. | (3.3) |
By (H1), we obtain
u′(t)≤−n∑j=1bj(t)u(t−μj)+n∑j=1bj(t−σ)a(t−σ)y(t−σ−μj)fort∈[L+μn+σ,L0]. |
Clearly,
a(t−σ)u′(t−σ)=−n∑j=1bj(t−σ)a(t−σ)y(t−μj−σ). |
Therefore,
u′(t)≤−n∑j=1bj(t)u(t−μj)−a(t−σ)u′(t−σ)fort∈[L+μn+σ,L0]. |
Consequently,
u′(t)+R(t)u′(t−σ)+n∑j=1bj(t)u(t−μj)≤0fort∈[L+μn+σ,L0]. |
Assume that v(t)=u(t)+R(t)u(t−σ), so v(t)>0 on [L+2σ,L0]. Then
v′(t)=u′(t)+R(t)u′(t−σ)+R′(t)u(t−σ)≤−n∑j=1bj(t)u(t−μj)+R′(t)u(t−σ)≤0 | (3.4) |
for t∈[L+μn+σ,L0], and so v′(t)≤0 on [L+μn+σ,L0]. Consequently,
v′(t)−R′(t)u(t−σ)+n∑j=1bj(t)u(t−μj)≤0fort∈[L+μn+σ,L0]. | (3.5) |
In view of u′(t)≤0 on [L+μn,L0], it follows that
v(t)=u(t)+R(t)u(t−σ)≤(1+R(t))u(t−σ)fort∈[L+μn+σ,L0]. |
Therefore,
u(t−σ)≥v(t)1+R(t)fort∈[L+μn+σ,L0] | (3.6) |
and
u(t−μj)≥v(t+σ−μj)1+R(t+σ−μj)fort∈[L+μn+μj,L0−σ+μj], j=1,2,…,n. | (3.7) |
Substituting into (3.5), we obtain
v′(t)−R′(t)1+R(t)v(t)+n∑j=1bj(t)1+R(t+σ−μj)v(t+σ−μj)≤0fort∈[L+2μn,L0]. |
Let z(t)=v(t)1+R(t). Then z(t)>0 on [L+2σ,L0] and
z′(t)+n∑j=1bj(t)1+R(t)z(t+σ−μj)≤0fort∈[L+2μn,L0]. |
Also, by using (3.4) and (3.6), we obtain
z′(t)=v′(t)(1+R(t))−v(t)R′(t)(1+R(t))2≤−∑nj=1bj(t)v(t−μj)1+R(t)≤0 |
for t∈[L+σ+μn,L0]. The proof is complete.
Lemma 3.2. Assume that (H2) holds, and N′(t)≤0 for t≥t1+σ. Let y(t) be a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥L0+2μn, L≥t1. Then, there exists a function z(t) that satisfies z(t)>0 on [L+2σ,L0] and z′(t)≤0 on [L+σ+μn,L0], and
z′(t)+n∑j=1bj(t)1+N(t)z(t+σ−μj)≤0fort∈[L+2μn,L0]. |
Proof. By the same method as in the proof of Lemma 2.1 we obtain (see (3.3))
u′(t)=−n∑j=1bj(t)u(t−μj)+n∑j=1bj(t)a(t−μj)y(t−σ−μj)fort∈[L+μn,L0], | (3.8) |
where u(t)=y(t)+a(t)y(t−σ), u(t)>0 for [L+σ,L0] and u′(t)≤0 for t∈[L+μn,L0]. Note that
u′(t)=−n∑j=1bj(t)y(t−μj)≤−bj(t)y(t−μj)fort∈[L+μn,L0]. |
Therefore,
y(t−σ−μj)≤−1bj(t−σ)u′(t−σ)fort∈[L+μn+σ,L0]. |
This together with (3.8) implies that
u′(t)≤−n∑j=1bj(t)u(t−μj)−u′(t−σ)n∑j=1bj(t)a(t−μj)bj(t−σ)fort∈[L+μn+σ,L0]. |
In view of (H2), it follows that
u′(t)+n∑j=1bj(t)u(t−μj)+N(t)u′(t−σ)≤0fort∈[L+μn+σ,L0]. | (3.9) |
By using the same method as in Lemma 2.1, we obtain
z′(t)+n∑j=1bj(t)1+N(t)z(t+σ−μj)≤0fort∈[L+2μn,L0], |
where z(t)>0 on [L+2σ,L0], z′(t)≤0 on t∈[L+μn+σ,L0], z(t)=v(t)1+N(t) and v(t)=u(t)+N(t)u(t−σ), u(t)=y(t)+a(t)y(t−σ). The proof is complete.
Lemma 3.3. Assume that (H1) holds and br(t)≥|R′(t)|, r∈{1,2,…,n}. Let y(t) be a solution of Eq (E1) such that y(t)>0 for t∈[L,L0], L≥L0+μn+μr, L≥t1. Then, there exists a function v(t) that satisfies v(t)>0 for t∈[L+2σ,L0] and v′(t)≤0 for t∈[L+μn+μr,L0], and
v′(t)+br(t)−|R′(t)|1+R(t+σ−μr)v(t+σ−μr)+n∑j=1j≠rbj(t)1+R(t+σ−μj)v(t+σ−μj)≤0 | (3.10) |
for t∈[L+μn+μr,L0].
Proof. Letting u(t)=y(t)+a(t)y(t−σ) and v(t)=u(t)+R(t)u(t−σ), so u′(t)≤0 for t∈[L+μn,L0] and v(t)>0 for [L+2σ,L0]. By (3.5), we have
v′(t)≤R′(t)u(t−σ)−n∑j=1bj(t)u(t−μj) for t∈[L+μn+σ,L0]. |
Since u′(t)≤0 for t∈[L+μn,L0], then
v′(t)≤R′(t)u(t−σ)−n∑j=1bj(t)u(t−μj)≤|R′(t)|u(t−σ)−n∑j=1bj(t)u(t−μj)≤|R′(t)|u(t−μr)−n∑j=1bj(t)u(t−μj)≤0 |
for t∈[L+μn+μr,L0]. Therefore, v′(t)≤0 for t∈[L+μn+μr,L0], and
v′(t)+(br(t)−|R′(t)|)u(t−μr)+n∑j=1j≠rbj(t)u(t−μj)≤0 for t∈[L+μn+μr,L0]. |
Using (3.7), we obtain
v′(t)+br(t)−|R′(t)|1+R(t+σ−μr)v(t+σ−μr)+n∑j=1j≠rbj(t)1+R(t+σ−μj)v(t+σ−μj)≤0 |
for t∈[L+μn+μr,L0], where v(t)>0 for [L+2σ,L0] and v′(t)≤0 for t∈[L+μn+μr,L0]. The proof is complete.
Lemma 3.4. Assume that (H2) holds and br(t)≥|N′(t)|, r∈{1,2,…,n}. Let y(t) be a solution of Eq (E1) such that y(t)>0 for t∈[L,L0], L0≥L+μn+μr, L≥t1. Then, there is a function v(t) that satisfies v(t)>0 for t∈[L+2σ,L0] and v′(t)≤0 for t∈[L+μn+μr,L0], and
v′(t)+br(t)−|N′(t)|1+N(t+σ−μr)v(t+σ−μr)+n∑j=1j≠rbj(t)1+N(t+σ−μj)v(t+σ−μj)≤0 |
for t∈[L+μn+μr,L0].
Proof. Using the same method as in the proof of Lemma 3.2, we obtain (see (3.9))
u′(t)+n∑j=1bj(t)u(t−μj)+N(t)u′(t−σ)≤0 for t∈[L+μn+σ,L0], |
where u(t)=y(t)+a(t)y(t−σ), u(t)>0 for t∈[L+σ,L0] and u′(t)≤0 for t∈[L+μn,L0]. Letting v(t)=u(t)+N(t)u(t−σ), then
v′(t)=u′(t)+N(t)u′(t−σ)+N′(t)u(t−σ)≤−n∑j=1bj(t)u(t−μj)+N′(t)u(t−σ) |
for t∈[L+μn+σ,L0]. Therefore,
v′(t)≤−n∑j=1bj(t)u(t−μj)+N′(t)u(t−σ)≤−n∑j=1bj(t)u(t−μj)+|N′(t)|u(t−σ) |
for t∈[L+μn+σ,L0]. That is,
v′(t)≤−n∑j=1bj(t)u(t−μj)+|N′(t)|u(t−σ)≤0for t∈[L+μn+σ,L0]. |
By using u′(t)≤0 for t∈[L+μn,L0], we obtain
v′(t)≤−(br(t)−|N′(t)|)u(t−μr)−n∑j=1j≠rbj(t)u(t−μj)≤0for t∈[L+μn+μr,L0], | (3.11) |
and
v(t)=u(t)+N(t)u(t−σ)≤(1+N(t))u(t−σ) for t∈[L+μn+σ,L0]. |
Therefore,
u(t−μj)≥v(t+σ−μj)1+N(t+σ−μj) for t∈[L+μn+μj,L0+μj−σ]. |
From this and (3.11), we have
v′(t)+br(t)−|N′(t)|1+N(t+σ−μr)v(t+σ−μr)+n∑j=1j≠rbj(t)1+N(t+σ−μj)v(t+σ−μj)≤0 |
for t∈[L+μn+μr,L0], where v(t)>0 for [L+2σ,L0] and v′(t)≤0 for t∈[L+μn+μr,L0]. The proof is complete.
Theorem 3.3. Let
Bj(t)=bj(t)1+R(t),ηj=μj−σ,j=1,2,…,n. | (3.12) |
Assume that (H1) holds, l∈N0, 0<ϵ≤1, R′(t)≤0 for t≥t1+σ. If condition (2.9) is satisfied, then Dt1(E1)≤(l+3+ϵ)μn−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Proof. Assume the contrary, and let y(t) be a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥t0, L0≥L+(l+3+ϵ)μn−(l+1+ϵ)σ. By using Lemma 3.1, then there exists a solution z(t) of (3.2) such that z(t)>0 on [L+2σ,L0] and z′(t)≤0 on [L+σ+μn,L0]. Clearly
max{δ,α}+(l+1+ϵ)ηn=(l+3+ϵ)μn−(l+1+ϵ)σ, |
where α=2μn, δ=σ+μn, and ηn=μn−σ. Applying Lemma 2.2 with γ=2σ, α=β=2μn, δ=σ+μn, so z(t) cannot be positive on [L+2μn,L0].
Theorem 3.4. Assume that (H1) holds, l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1, R′(t)≤0 for t≥t1+σ. If condition (2.13) is satisfied such that Bj(t), ηj, j=1,2,…,n, are defined by (3.12), then Dt1(E1)≤(l+3)μn+ϵμk2−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Proof. Assume y(t) is a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥t0, L0≥L+(l+3)μn+ϵμk2−(l+1+ϵ)σ. By using Lemma 3.1, there exists a solution z(t) of (3.2) such that z(t)>0 on [L+2σ,L0] and z′(t)≤0 on [L+σ+μn,L0]. It is clear that
max{δ,α}+(l+1)ηn+ϵηk2=(l+3)μn+ϵμk2−(l+1+ϵ)σ, |
where α=2μn, δ=σ+μn, and ηj=μj−σ. Applying Lemma 2.3 with γ=2σ, α=2μn, δ=σ+μn, so z(t) cannot be positive on [L+2μn,L0].
The following two theorems can be proven using Lemma 3.2 instead of Lemma 3.1 in the proofs of Theorems 3.3 and 3.4, respectively.
Theorem 3.5. Let
Bj(t)=bj(t)1+N(t),ηj=μj−σ,j=1,2,…,n. | (3.13) |
Assume that (H2) holds, l∈N0, 0<ϵ≤1, N′(t)≤0 for t≥t1+σ. If condition (2.9) is satisfied, then Dt1(E1)≤(l+3+ϵ)μn−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Theorem 3.6. Assume that (H2) holds, l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1, N′(t)≤0 for t≥t1+σ. If condition (2.13) is satisfied such that Bj(t), ηj, j=1,2,…,n, are defined by (3.13), then Dt1(E1)≤(l+3)μn+ϵμk2−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Theorem 3.7. Let r∈{1,2,…,n},
Bj(t)={bj(t)−|R′(t)|1+R(t+σ−μj)ifj=rbj(t)1+R(t+σ−μj)otherwise,ηj=μj−σ,j=1,2,…,n. | (3.14) |
Assume that (H1) holds, l∈N0, 0<ϵ≤1, br(t)≥|R′(t)| for t≥t1+σ. If condition (2.9) is satisfied, then Dt1(E1)≤(l+2+ϵ)μn+μr−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Proof. Assume the contrary, and let y(t) be a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥t0, L0≥L+(l+2+ϵ)μn+μr−(l+1+ϵ)σ. By using Lemma 3.3, there exists a solution v(t) of (3.10) on [L0+μn+μr,L] such that v(t)>0 on [L+2σ,L0] and v′(t)≤0 on [L+μn+μr,L0]. Clearly
max{δ,α}+(l+1+ϵ)ηn=(l+2+ϵ)μn+μr−(l+1+ϵ)σ, |
where α=δ=μn+μr, and ηn=μn−σ. Applying Lemma 2.2 with γ=2σ, α=δ=βμn+μr, so v(t) cannot be positive on [L+μn+μr,L0].
Theorem 3.8. Assume that (H1) holds, l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1, br(t)≥|R′(t)| for t≥t1+σ, r∈{1,2,…,n}. If condition (2.13) is satisfied with Bj(t) and ηj, j=1,2,…,n, are defined by (3.14), then Dt1(E1)≤(l+2)μn+μr+ϵμk2−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Proof. Assume the contrary, and let y(t) be a solution of Eq (E1) such that y(t)>0 on [L,L0], L≥t0, L0≥L+(l+2)μn+μr+ϵμk2−(l+1+ϵ)σ. By using Lemma 3.3, then there exists a solution v(t) of (3.10) on [L0+μn+μr,L] such that v(t)>0 on [L+2σ,L0] and v′(t)≤0 on [L+μn+μr,L0]. Clearly
max{δ,α}+(l+1)ηn+ϵηk2=(l+2)μn+μr+ϵμk2−(l+1+ϵ)σ, |
where α=δ=μn+μr, and ηj=μj−σ, j=1,2,…,n. Applying Lemma 2.3 with γ=2σ, α=δ=β=μn+μr, so v(t) cannot be positive on [L+μn+μr,L0].
Using Lemma 3.4 instead of Lemma 3.3 in the proofs of the preceding two theorems, we obtain the following results:
Theorem 3.9. Let r∈{1,2,…,n},
Bj(t)={bj(t)−|N′(t)|1+N(t+σ−μj)ifj=rbj(t)1+N(t+σ−μj)otherwise,ηj=μj−σ,j=1,2,…,n. | (3.15) |
Assume that (H2) holds, l∈N0, 0<ϵ≤1, br(t)≥|N′(t)| for t≥t1+σ. If condition (2.9) is satisfied, then Dt1(E1)≤(l+2+ϵ)μn+μr−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Theorem 3.10. Assume that (H2) holds, l∈N0, 1≤k1≤k2≤n, 0<ϵ≤1, br(t)≥|N′(t)| for t≥t1+σ, r∈{1,2,…,n}. If condition (2.13) is satisfied with Bj(t) and ηj=μj−σ, j=1,2,…,n, are defined by (3.15), then Dt1(E1)≤(l+2)μn+μr+ϵηk2−(l+1+ϵ)σ and every solution of Eq (E2) is oscillatory.
Remark 3.1. Following the same techniques used in the proof of our results, several sufficient criteria for the oscillation of both Eqs (E1) and (E2) can be obtained. For example, the conditions
lim supt→∞ n∏s=1(∏nj=1j≠s∫tt−ϵ(μs−σ)bj(v)1+R(v)e∫t−ϵ(μs−σ)v−(μs−σ)∑nj1=1bj1(v1)1+R(v1)Mj1l−1dv1dv)1n−1(1−∫tt−ϵ(μs−σ)bs(v)1+R(v)e∫t−ϵ(μs−σ)v−(μs−σ)∑nj=1bj(v1)1+R(v1)Mjl−1dv1dv)>1(n−1)n, |
where the sequence {Msl}l≥0 is defined by (2.2) with Bj(t)=bj(t)1+R(t) and ηj=μj−σ, j=1,2,…,n, and
lim supt→∞ k2∏s=k1∫tt−ϵμsbs(v)e∫t−ϵμsv−μs∑nj1=1bj1(v1)Mj1l−1dv1dv(1−∑nj=s+1∫tt−ϵμsbj(v)e∫t−ϵμsv−μj∑nj1=1bj1(v1)Mj1l−1dv1dv)>1, |
where the sequence {Msl}l≥0 is defined by (2.2) with Bj(t)=q(t) and ηj=μj, j=1,2,…,n, can be proved using the same proofs of Theorems 3.2 and 3.3, respectively.
Example 4.1. Consider the first-order differential equation with several delays
y′(t)+b1(t)y(t−μ1)+b2(t)y(t−μ2)=0, | (4.1) |
where b1(t)=185 and b2(t)=110, and μ1=δ, 0<δ<536, and μ2=1. Clearly,
∫tt−μ2b2(v)e∫t−μ2v−μ2∑2j1=1bj1(v1)dv1dv>1. |
Then, condition (3.1) is satisfied with l=1, k2=k3=3, and ϵ=1, and hence Dt1(4.1)≤4μ2=4, and every solution of Eq (4.1) is oscillatory for 0<δ<536. However, min1≤j≤2μj=μ1=δ. Then, δ can be chosen small enough such that all the results of [18] and [4,Theorem 2.2] fail to apply. Also, note that
∫tt−μ2b2(w)dw+1+∫tt−μ2b1(w)dw1−∫tt−μ2b2(w)dw∫tt−μ2b2(w)∫wt−μ2b2(w1)dw1dw<13100, |
and
∫tt−μ1b1(w)dw+1+∫tt−μ1b2(w)dw1−∫tt−μ1b1(w)dw∫tt−μ1b1(w)∫wt−μ1b1(w1)dw1dw=925δ(9δ2−90δ+50)5−18δ<1 |
for sufficiently small δ. Therefore, [4,Theorem 2.1] cannot give an approximation better than 4μ2.
Example 4.2. Consider the first-order neutral differential equation with several delays
[y(t)+a(t)y(t−σ)]′+b1(t)y(t−μ1)+b2(t)y(t−μ2)=0,t≥π, | (4.2) |
where a(t)=a∗=max{2π−99100,b∗π2−99100}, b1(t)=b∗>0, and b2(t)=2+sin(2t), σ=π, μ1=2π3, and μ2=2π. It is clear that condition (H1) is satisfied with R(t)=a∗. Note that
(∫tt−π22+sin(2v)1+a∗dv)(∫tt−πb∗1+a∗dv)(1−∫tt−π2b∗1+a∗dv)(1−∫tt−π2+sin(2v)1+a∗dv)=2b∗π(1+π−2cos2(t))(1+a∗−2π)(2+2a∗−b∗π)≥2b∗π(π−1)(1+a∗−2π)(2+2a∗−b∗π)>1 |
for b∗>150200π+1π(200π−199). Then, condition (2.9) is satisfied with B1(t)=b∗1+a∗, B2(t)=2+sin(2t)1+a∗, η1=μ1−σ=π2, η2=μ2−σ=π, l=0 and ϵ=1. Therefore, all requirements of Theorem 3.3 with l=0 are satisfied, and hence Dπ(4.2)≤4μ2−2σ=6π.
In this work, we obtained many new estimates for the upper bounds of the distance between adjacent zeros of Eqs (E1) and (E2). Our results are established in a general form (for inequality (1.1)), and hence they can be applied to any differential equation that can be transformed into an inequality of the form (1.1). Many new oscillation results for neutral differential equations with several not necessarily monotone delays can be obtained using the methods proposed in this work.
The author declares that he has not used Artificial Intelligence (AI) tools in the creation of this article.
The author extends their appreciation to Prince Sattam bin Abdulaziz University for funding this research work through the project number (PSAU/2024/01/29461).
The authors declare no conflict of interest.
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