Editorial

2021-end editorial: achievements, thanks, perspectives

  • Received: 24 December 2021 Revised: 29 December 2021 Accepted: 30 December 2021 Published: 30 December 2021
  • This year, the first one as Editor-in-chief of AIMS Biophysics, comes to an end. This Editorial is devoted to summarize the main results of this year and the perspectives of the journal. Last but not least to the Thanks.

    Citation: Carlo Bianca. 2022: 2021-end editorial: achievements, thanks, perspectives, AIMS Biophysics, 9(1): 1-4. doi: 10.3934/biophy.2022001

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  • This year, the first one as Editor-in-chief of AIMS Biophysics, comes to an end. This Editorial is devoted to summarize the main results of this year and the perspectives of the journal. Last but not least to the Thanks.



    Fractional calculus is like an extended version of regular calculus that allows us to deal with numbers that are not whole, like 1.5 or 2.3. This might not sound like a big deal, but it is incredibly useful in many fields. When we want to understand how things change or accumulate over time, fractional calculus helps us do that more accurately, especially when things are complicated and do not follow normal rules. These fractional calculations come in handy when we are dealing with stuff like how liquids flow, how materials deform, or how we control things like robots or machines. Inequalities, in the context of fractional calculus, are like special rules that help us understand when things are bigger or smaller than each other, but with these non-whole numbers involved. These rules are important because they help us figure out if systems with fractional calculus are stable and work the way they should. Thus, in a nutshell, fractional calculus and inequalities help us make sense of the world in a more precise and practical way. Thus, the term convexity and inequalities in the frame of fractional calculus have been recommended as an engrossing area for researchers due to their vital role and fruitful importance in numerous branches of science. Integral inequalities have remarkable uses in probability, optimization theory, information technology, stochastic processes, statistics, integral operator theory and numerical integration. For the applications, see references [1,2,3,4,5,6,7,8].

    In [9], a comprehensive and up-to-date review on Hermite-Hadamard-type inequalities for different kinds of convexities and different kinds of fractional integral operators is presented. In this review paper, we aim to discuss and present the up-to-date review of the Grüss type inequality via different fractional integral operators.

    In [10] (see also [11]), the Grüss inequality is defined as the integral inequality that establishes a connection between the integral of the product of two functions and the product of the integrals. The inequality is as follows.

    Theorem 1.1. If Ω,Π:[x1,x2]R are two continuous functions satisfying mΩ(t)M and pΠ(t)P, t[x1,x2], m,M,p,PR, then

    |1x2x1x2x1Ω(s)Π(s)ds1(x2x1)2x2x1Ω(s)dsx2x1Π(s)ds|14(Mm)(Pp).

    Our objective in this paper is to present a comprehensive and up-to-date review on Grüss-type inequalities for different kinds of fractional integral operators. In each section and subsection, we first introduce the basic definitions of fractional integral operators and then include the results on Grüss-type inequalities. We believe that the collection of almost all existing in the literature Grüss-type inequalities in one file will help new researchers in the field learn about the available work on the topic before developing new results. We present the results without proof but instead provide a complete reference for the details of each result elaborated in this survey for the convenience of the reader.

    The remainder of this review paper is as follows. In Sections 2–15, we summarize Grüss-type integral inequalities and especially for Riemann-Liouville fractional integral operators in Section 2, for Riemann-Liouville fractional integrals of a function with respect to another function in Section 3, in Section 4 for Katugampola fractional integral operators, in Section 5 for Hadamard's fractional integral operators, in Section 6 for k-fractional integral operators, in Section 7 for Raina's fractional integral operators, in Section 8 for tempered fractional integral operators, in Section 9 for conformable fractional integrals operators, in Section 10 for proportional fractional integrals operators, in Section 11 for generalized Riemann-Liouville fractional integral operators, in Section 12 for Caputo-Fabrizio fractional integrals operators, for Saigo fractional integral operators in Section 13, in Section 14 for quantum integral operators and in Section 15 for Hilfer fractional differential operators.

    Throughout this survey the following assumptions are used:

    (H) Assume that Ω,Π:IR are integrable functions on I for which there exist constants m,M,p,PR, such that

    mΩ(t)M,pΠ(t)P,tI.

    (H1) There exist two integrable functions Q1,Q2:[0,)R such that

    Q1(t)Ω(t)Q2(t)for allt[0,).

    (H2) There exist two integrable functions R1,R2:[0,)R such that

    R1(t)Π(t)R2(t)for allt[0,).

    In this subsection we give generalizations for Grüss-type inequalities by using the Riemann-Liouville fractional integrals. The first result deals with some inequalities using one fractional parameter.

    Definition 2.1. [12] A real valued function Ω(t),t0 is said to be in

    (ⅰ) the space Cμ,μR if there exists a real number p>μ such that Ω(t)=tpΩ1(t), where Ω1(t)C([0,),R),

    (ⅰ) the space Cnμ,μR if Ω(n)Cμ.

    Definition 2.2. [12] The Riemann-Liouville integral operator of fractional order α0, for an integrable function Ω is defined by

    JαΩ(t)=1Γ(α)t0(ts)α1Ω(s)ds,α>0,t>0,

    and J0Ω(t)=Ω(t).

    Theorem 2.1. [12] Assume that (H) holds on [0,). Then for all t>0 and α>0 we have:

    |tαΓ(α+1)JαΩ(t)Π(t)JαΩ(t)JαΠ(t)|(tα2Γ(α+1))2(Mm)(Pp).

    In the next result two real positive parameters are used.

    Theorem 2.2. [12] Assume that (H) holds on [0,). Then for all t>0 and α>0,β>0 we have:

    (tαΓ(α+1)JβΩ(t)Π(t)+tβΓ(β+1)JαΩ(t)Π(t)JαΩ(t)JβΠ(t)JβΩ(t)JαΠ(t))2[(MtαΓ(α+1)JαΩ(t))(JβΩ(t)mtβΓ(β+1))+(JαΩ(t)mtαΓ(α+1))(MtβΓ(β+1)JβΩ(t))]×[(PtαΓ(α+1)JαΠ(t))(JβΠ(t)ptβΓ(β+1))+(JαΠ(t)ptαΓ(α+1))(PtβΓ(β+1)JβΠ(t))].

    Next, we present some fractional integral inequalities of Grüss type by using the Riemann-Liouville fractional integral. The constants appeared as bounds of the functions Ω and Π, are replaced by four integrable functions.

    Theorem 2.3. [13] Assume that Ω:[0,)R is an integrable function satisfying (H1). Then, for t>0, α,β>0, we have:

    JβQ1(t)JαΩ(t)+JαQ2(t)JβΩ(t)JαQ2(t)JβQ1(t)+JαΩ(t)JβΩ(t).

    Theorem 2.4. [13] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then, for t>0, α, β>0, the fractional integral inequalities hold:

    (i)JβR1(t)JαΩ(t)+JαQ2(t)JβΠ(t)JβR1(t)JαQ2(t)+JαΩ(t)JβΠ(t).(ii)JβQ1(t)JαΠ(t)+JαR2(t)JβΩ(t)JβQ1(t)JαR2(t)+JβΩ(t)JαΠ(t).(iii)JαQ2(t)JβR2(t)+JαΩ(t)JβΠ(t)JαQ2(t)JβΠ(t)+JβR2(t)JαΩ(t).(iv)JαQ1(t)JβR1(t)+JαΩ(t)JβΠ(t)JαQ1(t)JβΠ(t)+JβR1(t)JαΩ(t).

    Theorem 2.5. [13] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all t>0, α>0, we have:

    |tαΓ(α+1)JαΩ(t)Π(t)JαΩ(t)JαΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where T(y,z,w) is defined by

    T(y,z,w)=(Jαw(t)Jαy(t))(Jαy(t)Jαz(t))+tαΓ(α+1)Jαz(t)y(t)Jαz(t)Jαy(t)+tαΓ(α+1)Jαw(t)y(t)Jαw(t)Jαy(t)+Jαz(t)Jαw(t)tαΓ(α+1)Jαz(t)w(t).

    In the next theorem we give an Ostrowski-Grüss type inequality of fractional type via Riemann-Liouville fractional integral.

    Theorem 2.6. [14] Let Ω:[x1,x2]R be a differentiable mapping on (x1,x2) and |Ω(x)|M for all x[x1,x2]. Then

    |12Ω(x)(α+1)Γ(α)(x2x)1α2(x2x1)Jαx1Ω(x2)+12Jα1x1((x2x)1αΓ(α)Ω(x2))+(x2x)2α2(x2x1)Γ(α)Jα1x1Ω(x2)+(x2x)1α(xx1)2(x2x1)2αΩ(x1)|M(x2x)1αx2x1[(x2x1)α(xx1)+(x2x)α(x1+x22x)2α],

    where x1x<x2.

    Definition 3.1. [15] Let ψ:[0,)R be positive, increasing function and also its derivative ψ be continuous on [0,) and ψ(0)=0. The fractional integral of Riemann-Liouville type of an integrable function Ω with respect to another function ψ is defined as

    Iα,ψΩ(t)=1Γ(α)t0(ψ(t)ψ(s))α1ψ(s)Ω(s)ds.

    In the next we include Grüss type integral inequalities with the help of ψ-Riemann-Liouville fractional integral.

    Theorem 3.1. [16] Assume that ψ:[0,)R is a positive, increasing function and also its derivative ψ is continuous on [0,) and ψ(0)=0. Assume that Ω:[0,)R is an integrable function satisfying (H1). Then the following inequality holds:

    Iβ,ψQ1(t)Iα,ψΩ(t)+Iα,ψQ2(t)Iβ,ψΩ(t)Iα,ψQ2(t)Iβ,ψQ1(t)+Iβ,ψΩ(t)Iβ,ψΩ(t).

    Theorem 3.2. [16] Let ψ be as in Theorem 3.1 and Ω,Π be two integrable functions satisfying (H1) and (H2). Then we have:

    (a) Iβ,ψR1(t)Iα,ψΩ(t)+Iα,ψQ2(t)Iβ,ψΠ(t)Iβ,ψR1(t)Iα,ψQ2(t)+Iα,ψΩ(t)Iβ,ψΠ(t).

    (b) Iβ,ψQ1(t)Iα,ψΠ(t)+Iα,ψR2(t)Iβ,ψΩ(t)Iβ,ψQ1(t)Iα,ψR2(t)+Iβ,ψΩ(t)Iα,ψΠ(t).

    (c) Iα,ψQ2(t)Iβ,ψR2(t)+Iα,ψΩ(t)Iβ,ψΠ(t)Iα,ψQ2(t)Iβ,ψΠ(t)+Iβ,ψR2(t)Iα,ψΩ(t).

    (d) Iα,ψQ1(t)Iβ,ψR1(t)+Iα,ψΩ(t)Iβ,ψΠ(t)Iα,ψQ1(t)Iβ,ψΠ(t)+Iβ,ψR1(t)Iα,ψΩ(t).

    Theorem 3.3. [16] Let ψ be as in Theorem 3.1 and Ω,Π be two integrable functions satisfying (H1) and (H2). Then the following inequality holds:

    |ψα(t)Γ(α+1)Iα,ψΩ(t)Π(t)Iα,ψΩ(t)Iα,ψΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(y,z,w)=(Iα,ψw(t)Iα,ψy(t))(Iα,ψy(t)Iα,ψz(t))+ψα(t)Γ(α+1)Iα,ψv(t)Iα,ψy(t)Iα,ψz(t)Iα,ψy(t)+ψα(t)Γ(α+1)Iα,ψw(t)y(t)Iα,ψw(t)Iα,ψy(t)+Iα,ψz(t)Iα,ψw(t)ψα(t)Γ(α+1)Iα,ψz(t)w(t).

    Now we define the space Xpc(x1,x2) in which Katugampola's fractional integrals are defined.

    Definition 4.1. [17] The space Xpc(x1,x2)(cR,1p<) consists of those complex-valued Lebesgue measurable functions ϕ on (x1,x2) for which ϕXpc<, with

    ϕXpc=(x2x1|xcϕ(x)|pdxx)1/p(1p<),

    and

    ϕXc=esssupx(x1,x2)[xc|ϕ(x)|].

    Definition 4.2. [17] Let ϕXpc(x1,x2), α>0 and β,ρ,η,κR. Then, the left- and right- sided fractional integrals of a function ϕ are defined respectively by

    ρJα,βx1+,η,κϕ(x)=ρ1βxκΓ(α)xx1τρ(η+1)1(xρτρ)1αϕ(τ)dτ,0x1<x<x2,

    and

    ρJα,βx2,η,κϕ(x)=ρ1βxρηΓ(α)x2xτκ+ρ1(τρxρ)1αϕ(τ)dτ,0x1<x<x2,

    if the integrals exist.

    Now, we present several Grüss-type inequalities involving Katugampola's fractional integral.

    Theorem 4.1. [17] Assume that (H) holds on [0,). Then we have:

    |Λρ,βx,κ(α,η)ρJα,βη,κΩ(x)Π(x)ρJα,βη,κΩ(x)ρJα,βη,κΠ(x)|(Λρ,βx,κ(α,η))2(Mm)(Pp),

    for all β,κR, x>0, α>0, ρ>0 and η0, where

    Λρ,βx,κ(α,η)=Γ(η+1)Γ(η+α+1)ρβxκ+ρ(η+α).

    Theorem 4.2. [17] Assume that (H) holds on [0,). Then for all β,κR, x>0, α>0, γ>0 and η0, we have:

    (Λρ,βx,κ(α,η)ρJγ,βη,κΩ(x)Π(x)+Λρ,βx,κ(γ,η)ρJα,βη,κΩ(x)Π(x)ρJα,βη,κΩ(x)ρJα,βη,κΠ(x)ρJγ,βη,κΩ(x)ρJα,βη,κΠ(x))2[(MΛρ,βx,κ(α,η)ρJα,βη,κΩ(x))(ρJγ,βη,κΩ(x)mΛρ,βx,κ(α,η))+(ρJα,βη,κΩ(x)mΛρ,βx,κ(α,η))(MΛρ,βx,κ(γ,η)ρJγ,βη,κΩ(x))]×[(PΛρ,βx,κ(α,η)ρJα,βη,κΠ(x))(ρJγ,βη,κΠ(x)pΛρ,βx,κ(γ,η))+(ρJα,βη,κΠ(x)pΛρ,βx,κ(α,η))(PΛρ,βx,κ(γ,η)ρJγ,βη,κΠ(x))].

    Theorem 4.3. [17] Let α>0, β,ρ,η,κR, Ω,ΠXpc(0,x) x>0 and p,q>1 such that 1p+1q=1. Then we have:

    (a)1pρJα,βη,κΩp(x)+1qρJα,βη,κΠq(x)Γ(η+α+1)ρβΓ(η+1)xρ(η+α)+κ(ρJα,βη,κΩ(x)ρJα,βη,κΠ(x)).(b)1pρJα,βη,κΩp(x)ρJα,βη,κΠp(x)+1qρJα,βη,κΩq(x)ρJα,βη,κΠq(x)(ρJα,βη,κΩ(x)Π(x))2.(c)1pρJα,βη,κΩp(x)ρJα,βη,κΠq(x)+1qρJα,βη,κΩq(x)ρJα,βη,κΠp(x)(ρJα,βη,κ(ΩΠ)p1(x))(ρJα,βη,κ(ΩΠ)q1(x)).(d)ρJα,βη,κΩp(x)ρJα,βη,κΠq(x)(ρJα,βη,κΩ(x)Π(x))(ρJα,βη,κΩp1(x)Πq1(x)).(e)1pρJα,βη,κΩp(x)ρJα,βη,κΠ2(x)+1qρJα,βη,κΩ2(x)ρJα,βη,κΠq(x)(ρJα,βη,κΩ(x)Π(x))(ρJα,βη,κΩ2/p(x)Π2/p(x)).(f)1pρJα,βη,κΩ2(x)ρJα,βη,κΠq(x)+1qρJα,βη,κΩq(x)ρJα,βη,κΠ2(x)(ρJα,βη,κΩ2/p(x)Π2/p(x))(ρJα,βη,κΩp1(x)Πq1(x)).(g)ρJα,βη,κΩ2(x)ρJα,βη,κ(Πq(x)p+Πq(x)q)(ρJα,βη,κΩ2/p(x)Π(x))(ρJα,βη,κΩ2/q(x)Π(x)).

    Theorem 4.4. [17]\ Assume that the assumptions of Theorem 4.3 are satisfied. In addition, let

    μ=min0txΩ(t)Π(t)andM=max0txΩ(t)Π(t).

    Then we have:

    (i)0(ρJα,βη,κΩ2(x)ρJα,βη,κΠ2(x))(M+μ)24μM(ρJα,βη,κΩ(x)Π(x))2.(ii)0ρJα,βη,κΩ2(x)ρJα,βη,κΠ2(x)(ρJα,βη,κΩ(x)Π(x))(Mμ)22μM(ρJα,βη,κΩ(x)Π(x)).(iii)0ρJα,βη,κΩ2(x)ρJα,βη,κΠ2(x)(ρJα,βη,κΩ(x)Π(x))2(Mμ)24μM(ρJα,βη,κΩ(x)Π(x))2.

    Theorem 4.5. [18] Assume that Ω:[0,)R is an integrable function satisfying (H1). Then we have:

    ρJα,βη,kQ2(t)ρJδ,λη,kΩ(t)+ρJα,βη,kΩ(t)ρJδ,λη,kQ1(t)ρJα,βη,kΩ(t)ρJδ,λη,kΩ(t)+ρJα,βη,kQ2(t)ρJδ,λη,kQ1(t),

    for all t>0,α,ρ,δ>0, β,η,k,λR.

    Theorem 4.6. [18] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all t>0 and α,ρ>0, β,η,kR we have:

    [Λρ,βt,k(α,η)ρJα,βη,kΩ(t)Π(t)(ρJα,βη,kΩ(t)ρJα,βη,kΠ(t))]2T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(y,z,w)=(ρJα,βη,kw(t)ρJα,βη,ky(t))(ρJα,βη,ky(t)ρJα,βη,kz(t))+Λρ,βt,k(α,η)ρJα,βη,ky(t)z(t)ρJα,βη,ky(t)ρJα,βη,kz(t)+Λρ,βt,k(α,η)ρJα,βη,ky(t)w(t)ρJα,βη,ky(t)ρJα,βη,kw(t)Λρ,βt,k(α,η)ρJα,βη,kz(t)w(t)+ρJα,βη,kz(t)ρJα,βη,kw(t).

    Theorem 4.7. [18] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all t>0 and α,δ,ρ>0, β,λ,η,kR we have:

    (a) ρJδ,λη,kΩ(t)ρJα,βη,kQ2(t)+ρJδ,λη,kR1(t)ρJα,βη,kΠ(t)ρJδ,λη,kR1(t)ρJα,βη,kQ2(t)+ρJδ,λη,kΩ(t)ρJα,βη,kΠ(t).

    (b) ρJδ,λη,kQ1(t)ρJα,βη,kΩ(t)+ρJα,βη,kR2(t)ρJδ,λη,kΠ(t)ρJδ,λη,kQ1(t)ρJα,βη,kR2(t)+ρJδ,λη,kΠ(t)ρJα,βη,kΩ(t).

    (c) ρJα,βη,kQ2(t)ρJδ,λη,kR2(t)+ρJα,βη,kΠ(t)ρJδ,λη,kΩ(t)ρJα,βη,kQ2(t)ρJδ,λη,kΩ(t)+ρJδ,λη,kR2(t)ρJα,βη,kΠ(t).

    (d) ρJα,βη,kQ1(t)ρJδ,λη,kR1(t)+ρJα,βη,kΠ(t)ρJδ,λη,kΩ(t)ρJα,βη,kQ1(t)ρJδ,λη,kΩ(t)+ρJδ,λη,kR1(t)ρJα,βη,kΠ(t).

    Definition 5.1. [15] The fractional integral of Hadamard type of order αR+ of an integrable function Ω(t), for all t>1 is defined as

    HJαΩ(t)=1Γ(α)t1(logts)α1Ω(s)dss, (5.1)

    provided the integral exists. (Here log()=loge()).

    We present, by using Hadamard's fractional integral, some Grüss-type fractional integral inequalities.

    Theorem 5.1. [19] Assume that Ω:[1,)R is an integrable function satisfying (H1). Then, for t>1, α,β>0, we have

    HJβQ1(t)HJαΩ(t)+HJαQ2(t)HJβΩ(t)HJαQ2(t)HJβQ1(t)+HJαΩ(t)HJβΩ(t).

    Theorem 5.2. [19] Assume that Ω:[1,)R is an integrable function satisfying (H1). Let θ1,θ2>0 satisfying 1/θ1+1/θ2=1. Then, for t>1, α,β>0, we have

    1θ1(logt)βΓ(β+1)HJα((Q2Ω)θ1)(t)+1θ2(logt)αΓ(α+1)HJβ((ΩQ1)θ2)(t)+HJαQ2(t)HJβQ1(t)+HJαΩ(t)HJβΩ(t)HJαQ2(t)HJβΩ(t)+HJαΩ(t)HJβQ1(t).

    Theorem 5.3. [19] Assume that Ω:[1,)R is an integrable function satisfying (H1). Let θ1,θ2>0 satisfying θ1+θ2=1. Then, for t>1, α,β>0, we have

    θ1(logt)βΓ(β+1)HJαQ2(t)+θ2(logt)αΓ(α+1)HJβΩ(t)HJα(Q2Ω)θ1(t)HJβ(ΩQ1)θ2(t)+θ1(logt)βΓ(β+1)HJαΩ(t)+θ2(logt)αΓ(α+1)HJβQ1(t).

    Theorem 5.4. [19] Assume that Ω:[1,)R is an integrable function satisfying (H1). Let pq0, p0. Then, we have the following two inequalities, for any k>0, t>1, α, β>0,

    (i)HJα(Q2Ω)qp(t)+qpkqppHJαΩ(t)qpkqppHJαQ2(t)+pqpkqp(logt)αΓ(α+1).(ii)HJα(ΩQ1)qp(t)+qpkqppHJαQ1(t)qpkqppHJαΩ(t)+pqpkqp(logt)αΓ(α+1).

    Theorem 5.5. [19] Suppose that Ω,Π:[1,)R are two integrable functions satisfying (H1) and (H2). Then, for t>0, α, β>0, we have:

    (a) HJβR1(t)HJαΩ(t)+HJαQ2(t)HJβΠ(t)HJβR1(t)HJαQ2(t)+HJαΩ(t)HJβΠ(t).

    (b) HJβQ1(t)HJαΠ(t)+HJαR2(t)HJβΩ(t)HJβQ1(t)HJαR2(t)+HJβΩ(t)HJαΠ(t).

    (c) HJβR2(t)HJαQ2(t)+HJαΩ(t)HJβΠ(t)HJαQ2(t)HJβΠ(t)+HJβR2(t)HJαΩ(t).

    (d) HJαQ1(t)HJβR1(t)+HJαΩ(t)HJβΠ(t)HJαQ1(t)HJβΠ(t)+HJβR1(t)HJαΩ(t).

    Theorem 5.6. [19] Suppose that Ω,Π:[1,)R are two integrable functions satisfying (H1) and (H2). Let θ1,θ2>0 such that 1/θ1+1/θ2=1. Then, for t>1, α, β>0, the following inequalities hold:

    () 1θ1(logt)βΓ(β+1)HJα(Q2Ω)θ1(t)+1θ2(logt)αΓ(α+1)HJβ(R2Π)θ2(t) HJα(Q2Ω)(t)HJβ(R2Π)(t).

    () 1θ1HJα(Q2Ω)θ1(t)HJβ(R2Π)θ1(t)+1θ2HJα(R2Π)θ2(t)HJβ(Q2Ω)θ2(t) HJα(Q2Ω)(R2Π)(t)HJβ(Q2Ω)(R2Π)(t).

    () 1θ1(logt)βΓ(β+1)HJα(ΩQ1)θ1(t)+1θ2(logt)αΓ(α+1)HJβ(ΠR1)θ2(t) HJα(ΩQ1)(t)HJβ(ΠR1)(t).

    () 1θ1HJα(ΩQ1)θ1(t)HJβ(ΠR1)θ1(t)+1θ2HJα(ΠR1)θ2(t)HJβ(ΩQ1)θ2(t) HJα(ΩQ1)(ΠR1)(t)HJβ(ΩQ1)(ΠR1)(t).

    Theorem 5.7. [19] Suppose that Ω,Π:[1,)R are two integrable functions satisfying (H1) and (H2). Let θ1,θ2>0 such that θ1+θ2=1. Then, for t>1, α, β>0, we have:

    (a) θ1(logt)βΓ(β+1)HJαQ2(t)+θ2(logt)αΓ(α+1)HJβR2(t) HJα(Q2Ω)θ1(t)HJβ(R2Π)θ2(t)+θ1(logt)βΓ(β+1)HJαΩ(t)+θ2(logt)αΓ(α+1)HJβΠ(t).

    (b) θ1HJαQ2(t)HJβR2(t)+θ1HJαΩ(t)HJβΠ(t) +θ2HJαR2(t)HJβQ2(t)+θ2HJαΠ(t)HJβΩ(t) HJα(Q2Ω)θ1(R2Π)θ2(t)HJβ(R2Π)θ1(Q2Ω)θ2(t) +θ1HJαQ2(t)HJβΠ(t)+θ1HJαΩ(t)HJβR2(t) +θ2HJαR2(t)HJβΩ(t)+θ2HJαΠ(t)HJβQ2(t).

    (c) θ1(logt)βΓ(β+1)HJαΩ(t)+θ2(logt)αΓ(α+1)HJβΠ(t) HJα(ΩQ1)θ1(t)HJβ(ΠR1)θ2(t)+θ1(logt)βΓ(β+1)HJαQ1(t)+θ2(logt)αΓ(α+1)HJβR1(t).

    (d) θ1HJαΩ(t)HJβΠ(t)+θ1HJαQ1(t)HJβR1(t) +θ2HJαΠ(t)HJβΩ(t)+θ2HJαR1(t)HJβQ1(t) HJα(ΩQ1)θ1(ΠR1)θ2(t)HJβ(ΠR1)θ1(ΩQ1)θ2(t) +θ1HJαΩ(t)HJβR1(t)+θ1HJαQ1(t)HJβΠ(t) +θ2HJαΠ(t)HJβQ1(t)+θ2HJαR1(t)HJβΩ(t).

    Theorem 5.8. [19] Suppose that Ω,Π:[1,)R are two integrable functions satisfying (H1) and (H2). Then for all t>1, α>0, we have

    |(logt)αΓ(α+1)HJαΩ(t)Π(t)HJαΩ(t)HJαΠ(t)||T(Ω,Q1,Q2)|12|T(Π,R1,R2)|12,

    where T(y,z,w) is defined by

    T(y,z,w)=(HJαw(t)HJαy(t))(HJαy(t)HJαz(t))+(logt)αΓ(α+1)HJαz(t)y(t)HJαz(t)HJαy(t)+(logt)αΓ(α+1)HJαw(t)y(t)HJαw(t)HJαy(t)+HJαz(t)HJαw(t)(logt)αΓ(α+1)HJαz(t)w(t).

    In this section we present Grüss-type fractional integral inequalities concerning k-fractional integral operators.

    k-fractional integral inequalities of Grüss-type are included in this section.

    Definition 6.1. [20] The k-fractional integral of the Riemann-Liouville type is defined as follows:

    kJαx1Ω(t)=1kΓk(α)tx1(xs)αk1Ω(s)ds,α>0,t>a.

    Theorem 6.1. [21] Assume that Ω:[0,) is an integrable function satisfying (H1). Then, for t>0, α,β>0, k>0, we have

    kJβQ1(t)kJαΩ(t)+ kJαQ2(t)kJβΩ(t) kJαQ2(t)kJβQ1(t)+ kJαΩ(t)kJβΩ(t).

    Theorem 6.2. [21] Assume that Ω:[0,) is an integrable function satisfying (H1). Let θ1,θ2>0 such that 1/θ1+1/θ2=1. Then, we have for t>0, α,β>0 and k>0,

    1θ1tβkΓk(β+k)kJα((Q2Ω)θ1)(t)+1θ2tαkΓk(α+k)kJβ((ΩQ1)θ2)(t)+kJαQ2(t)kJβQ1(t)+kJαΩ(t)kJβΩ(t)kJαQ2(t)kJβΩ(t)+kJαΩ(t)kJβQ1(t).

    Theorem 6.3. [21] Assume that Ω:[0,) is an integrable function satisfying (H1). Let θ1,θ2>0 such that θ1+θ2=1. Then, for t>0, α,β>0 and k>0, we have

    θ1tβkΓk(β+k)kJαQ2(t)+θ2tαkΓk(α+k)kJβΩ(t)kJα(Q2Ω)θ1(t)kJβ(ΩQ1)θ2(t)+θ1tβkΓk(β+k)kJαΩ(t)+θ2tαkΓk(α+k)kJβQ1(t).

    Theorem 6.4. [21] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then, for t>0, α, β>0, k>0  we have:

    (ⅰ) kJβR1(t) kJαΩ(t)+ kJαQ2(t) kJβΠ(t) kJβR1(t) kJαQ2(t)+ kJαΩ(t) kJβΠ(t).

    (ⅱ) kJβQ1(t) kJαΠ(t)+ kJαR2(t) kJβΩ(t) kJβQ1(t) kJαR2(t)+ kJβΩ(t) kJαΠ(t).

    (ⅲ) kJαQ2(t) kJβR2(t)+ kJαΩ(t) kJβΠ(t) kJαQ2(t) kJβΠ(t)+ kJβR2(t) kJαΩ(t).

    (ⅳ) kJαQ1(t)JβR1(t)+ kJαΩ(t) kJβΠ(t) kJαQ1(t) kJβΠ(t)+ kJβR1(t) kJαΩ(t).

    Theorem 6.5. [21] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all t>0, α>0, k>0, we have

    |tαkΓk(α+k) kJαΩ(t)Π(t) kJαΩ(t) kJαΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(y,z,w)=( kJαw(t) kJαy(t))( kJαy(t) kJαz(t))+tαkΓk(α+k) kJαz(t)y(t)kJαz(t) kJαy(t)+tαkΓk(α+k)Jαw(t)y(t)kJαw(t) kJαy(t)+kJαz(t) kJαw(t)tαkΓk(α+k) kJαz(t)w(t).

    Theorem 6.6. [22] Assume that (H) holds on [x1,x2] and p be a positive function on [x1,x2]. Then for all t>0, k>0,α>0, we have

    |(kJαx1p(t))(kJαx1p(t)Ω(t)Π(t))(kJαx1p(t)Ω(t))(kJαx1p(t)Π(t))|(kJαx1p(t))24(Mm)(Pp).

    Theorem 6.7. [22] Let the assumptions of Theorem 6.6 be satisfied. Then, for all t>0, k>0,α,β>0, t he following inequality holds:

    [(kJαx1p(t))(kJβx1p(t)Ω(t)Π(t))+(kJβx1p(t))(kJαx1p(t)Ω(t)Π(t))(kJαx1p(t)Ω(t))(kJαx1p(t)Π(t))(kJβx1p(t)Ω(t))(kJαx1p(t)Π(t))]2{[M(kJαx1p(t))(kJαx1p(t)Ω(t))][(kJβx1p(t)Ω(t))m(kJβx1p(t))]+[(kJαx1p(t)Ω(t))m(kJαx1p(t))][M(kJβx1p(t))(kJβx1pΩ(t))]}×{[P(kJαx1p(t))(kJαx1p(t)Π(t))][(kJβx1p(t)Π(t))p(kJβx1p(t))]+[(kJαx1p(t)Π(t))p(kJαx1p(t))][P(kJβx1p(t))(kJβx1p(t)Π(t))]}.

    Definition 6.2. [23] Let ψ be a positive and increasing function on [x1,x2]. Then the left-sided and right-sided generalized Riemann–Liouville fractional integrals of a function Ω with respect to another function ψ of order α>0 are defined by

    Jα,ψx1+,kΩ(t)=1kΓk(α)tx1(ψ(t)ψ(s))αk1ψ(s)Ω(s)ds,t>x1,
    Jα,ψx2,kΩ(t)=1kΓk(α)x2t(ψ(s)ψ(t))αk1ψ(s)Ω(s)ds,t<x2.

    Theorem 6.8. [23] Assume that Ω:[0,)R is an integrable function satisfying (H1). Then, for t>0, α,β>0, k>0, we have:

    Jβ,ψ0+,kQ1(t)Jα,ψ0+,kΩ(t)+ Jα,ψ0+,kQ2(t)Jβ,ψ0+,kΩ(t) Jα,ψ0+,kQ2(t)Jβ,ψ0+,kQ1(t)+ Jα,ψ0+,kΩ(t)Jβ,ψ0+,kΩ(t).

    Theorem 6.9. [23] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Assume that ψ is a positive and increasing function with ψ(0)=0 and ψ continuous on [0,). Then, for t>0, α, β>0, k>0 we have:

    (ⅰ) Jβ,ψ0+,kR1(t) Jα,ψ0+,kΩ(t)+ Jα,ψ0+,kQ2(t) Jβ,ψ0+,kΠ(t) Jβ,ψ0+,kR2(t) Jα,ψ0+,kQ2(t)+ Jα,ψ0+,kΩ(t) Jβ,ψ0+,kΠ(t).

    (ⅱ) Jβ,ψ0+,kQ1(t) Jα,ψ0+,kΠ(t)+ Jα,ψ0+,kR2(t) Jβ,ψ0+,kΩ(t) Jβ,ψ0+,kQ1(t) Jα,ψ0+,kR2(t)+ Jβ,ψ0+,kΩ(t) Jα,ψ0+,kΠ(t).

    (ⅲ) Jα,ψ0+,kQ2(t) kJβ,ψ0+,kR2(t)+ Jα,ψ0+,kΩ(t) Jβ,ψ0+,kΠ(t) Jα,ψ0+,kQ2(t) Jβ,ψ0+,kΠ(t)+ Jβ,ψ0+,kR2(t) Jα,ψ0+,kΩ(t).

    (ⅳ) Jα,ψ0+,kQ1(t)Jβ,ψ0+,kR1(t)+ Jα,ψ0+,kΩ(t) Jβ,ψ0+,kΠ(t) Jα,ψ0+,kQ1(t) Jβ,ψ0+,kΠ(t)+ Jβ,ψ0+,kR1(t) Jα,ψ0+,kΩ(t).

    Theorem 6.10. [23] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Assume that ψ is a positive and increasing function on [0,) such that ψ(0)=0 and ψ is continuous on [0,). Then for all t>0, α>0, k>0, we have

    |ψ(t)αkΓk(α+k) Jα,ψ0+,kΩ(t)Π(t) Jα,ψ0+,kΩ(t) Jα,ψ0+,kΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(y,z,w)=( Jα,ψ0+,kw(t) Jαy(t))( Jα,ψ0+,ky(t) Jα,ψ0+,kz(t))+ψ(t)αkΓk(α+k) Jα,ψ0+,kz(t)y(t)Jα,ψ0+,kz(t) Jα,ψ0+,ky(t)+ψ(t)αkΓk(α+k)Jα,ψ0+,kw(t)y(t)Jα,ψ0+,kw(t) Jα,ψ0+,ky(t)+Jα,ψ0+,kz(t) Jα,ψ0+,kw(t)tαkΓk(α+k) Jα,ψ0+,kz(t)w(t).

    Definition 7.1. [24] The function Ω is said to be Lp,r[x1,x2] if

    (x2x1|Ω(t)|ptrdt)1/p<,1<p<,r>0.

    Definition 7.2. [24] The Γk (generalized gamma function) is defined by

    Γk(z)=limnn!kn(nk)zk1(z)nk,k>0.

    Definition 7.3. [24] The function Fσ,kρ,λ is defined by

    Fσ,kρ,λ(z)=F(σ(0),σ(1),,),kρ,λ=m=0σ(m)kΓk(ρkm+λ)zm,ρ,λ>0,zC,|z|<R,

    where RR+ and σ=(σ(1),,σ(m),) is a bounded sequence of positive real numbers.

    Definition 7.4. [24] Let k>0, λ>0, ρ>0 and ωR. Assume that ψ:[x1,x2]R is an increasing function for which ψ is continuous on (x1,x2). Then the left and right generalized k-fractional integrals of the function Ω with respect to ψ on [x1,x2] are defined by

    Jσ,k,ψρ,λ,a+;ωΩ(z)=zx1ψ(t)(ψ(z)ψ(t))1λkFσ,kρ,λ[ω(ψ(z)ψ(t))ρ]Ω(t)dt,z>x1

    and

    Jσ,k,ψρ,λ,x2;ωΩ(z)=x2zψ(t)(ψ(t)ψ(z))1λkFσ,kρ,λ[ω(ψ(t)ψ(z))ρ]Ω(t)dt,z<x2,

    respectively.

    Theorem 7.1. [24] Let ρ,λ,δ>0, ωR, ΩL1,r[x1,x2], and (H1) holds. Then we have:

    Jσ,k,ψρ,λ,0+;ωQ2(x)Jσ,k,ψρ,δ,0+;ωΩ(x)+Jσ,k,ψρ,δ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,δ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωQ2(x)+Jσ,k,ψρ,δ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΩ(x).

    Theorem 7.2. [24] Under the assumptions of Theorem 7.1, we have:

    Jσ,k,ψρ,λ,0+;ωQ2(x)Jσ,k,ψρ,δ,0+;ωΩ(x)+Jσ,k,ψρ,δ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,δ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωQ2(x)+Jσ,k,ψρ,δ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΩ(x).

    Theorem 7.3. [24] Let ρ,λ,δ>0, ωR, Ω,ΠL1,r[x1,x2] satifying (H1) and (H2) for all x[0,). Then we have

    |Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)Aδ(x)+Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)Aλ(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,δ,0+;ωΠ(x)Jσ,k,ψρ,δ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΠ(x)|(Aλ(x)Aδ(x)2)2(Q2Q1)(R1R2),

    where Aλ and Aδ are defined as

    Aλ(z)=(ψ(z))λkFσ,kρ,λ+1(ω(ψ(z))ρ)andAδ=(ψ(z))δkFσ,kρ,δ+1(ω(ψ(z))ρ),

    respectively.

    Theorem 7.4. [24] Under the assumptions of Theorem 7.3, we have

    (i)Jσ,k,ψρ,λ,0+;ωQ2(x)Jσ,k,ψρ,δ,0+;ωΠ(x)+Jσ,k,ψρ,δ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,δ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωQ2(x)+Jσ,k,ψρ,δ,0+;ωΠ(x)Jσ,k,ψρ,λ,0+;ωΩ(x),(ii)Jσ,k,ψρ,λ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)+Jσ,k,ψρ,λ,0+;ωΠ(x)Jσ,k,ψρ,δ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωΠ(x)Jσ,k,ψρ,δ,0+;ωΩ(x)+Jσ,k,ψρ,λ,0+;ωR1(x)Jσ,k,ψρ,δ,0+;ωQ1(x),(iii)Jσ,k,ψρ,λ,0+;ωQ2(x)Jσ,k,ψρ,δ,0+;ωΠ(x)+Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,δ,0+;ωΠ(x)+Jσ,k,ψρ,δ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωQ2(x),(iv)Jσ,k,ψρ,λ,0+;ωQ1(x)Jσ,k,ψρ,δ,0+;ωΠ(x)+Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωR1(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΠ(x)+Jσ,k,ψρ,λ,0+;ωQ1(x)Jσ,k,ψρ,λ,0+;ωR1(x).

    Now we present certain other associated fractional integral inequalities.

    Theorem 7.5. [24] Let α,β>1 and a1+β1=1, and Ω,ΠL1,r[x1,x2]. Then we have:

    (i)a1Aδ(x)Jσ,k,ψρ,λ,0+;ωΩα(x)+β1Aλ(x)Jσ,k,ψρ,λ,0+;ωΠβ(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΠ(x).(ii)a1Jσ,k,ψρ,λ,0+;ωΩα(x)Jσ,k,ψρ,δ,0+;ωΠα(x)+β1Jσ,k,ψρ,λ,0+;ωΠβJσ,k,ψρ,δ,0+;ωΩβ(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)Jσ,k,ψρ,δ,0+;ωΩ(x)Π(x).(iii)a1Jσ,k,ψρ,λ,0+;ωΩα(x)Jσ,k,ψρ,δ,0+;ωΠβ(x)+β1Jσ,k,ψρ,δ,0+;ωΩβ(x)Jσ,k,ψρ,λ,0+;ωΠα(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Πα1(x)Jσ,k,ψρ,δ,0+;ωΩ(x)Πβ1(x).(iv)a1Jσ,k,ψρ,δ,0+;ωΩα(x)Jσ,k,ψρ,λ,0+;ωΠβ(x)+β1Jσ,k,ψρ,δ,0+;ωΠβ(x)Jσ,k,ψρ,λ,0+;ωΩα(x)Jσ,k,ψρ,λ,0+;ωΩα1(x)Πβ1(x)Jσ,k,ψρ,δ,0+;ωΩ(x)Π(x).(v)a1Jσ,k,ψρ,λ,0+;ωΩα(x)Jσ,k,ψρ,δ,0+;ωΠ2(x)+β1Jσ,k,ψρ,λ,0+;ωΠβ(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)Jσ,k,ψρ,δ,0+;ωΩ2/β(x)Π2/α(x).(vi)a1Jσ,k,ψρ,λ,0+;ωΩ2(x)Jσ,k,ψρ,δ,0+;ωΠβ(x)+β1Jσ,k,ψρ,δ,0+;ωΩα(x)Jσ,k,ψρ,λ,0+;ωΠ2(x)Jσ,k,ψρ,λ,0+;ωΩ2/α(x)Π2/β(x)Jσ,k,ψρ,δ,0+;ωΩα1(x)Πβ1(x).(vii)a1Aδ(x)Jσ,k,ψρ,λ,0+;ωΩ2(x)Πβ(x)+β1Aλ(x)Jσ,k,ψρ,δ,0+;ωΠβ(x)Ω2(x)Jσ,k,ψρ,λ,0+;ωΩ2/α(x)Πβ1(x)Jσ,k,ψρ,δ,0+;ωΩ2/β(x)Πα1(x).

    Theorem 7.6. [24] Assume that Ω,Π:[0,)R are two positive and integrable functions such that

    μ=min0txΩ(t)Ω(t),M=max0txΩ(t)Π(t).

    Then we have

    (a)0Jσ,k,ψρ,λ,0+;ωΩ2(x)Jσ,k,ψρ,λ,0+;ωΠ2(x)(μ+M)24μM(Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x))2,(b)0Jσ,k,ψρ,λ,0+;ωΩ2(x)Jσ,k,ψρ,λ,0+;ωΠ2(x)Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)(Mμ)22μM(Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x)),(c)0Jσ,k,ψρ,λ,0+;ωΩ2(x)Jσ,k,ψρ,λ,0+;ωΠ2(x)(Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x))2(Mμ)24μM(Jσ,k,ψρ,λ,0+;ωΩ(x)Π(x))2.

    In this section we define a generalized left sided tempered fractional integral with respect to another function. Then we present Grüss-type integral inequalities.

    Definition 8.1. [16] Suppose ΩL1[0,) and the function ψ:[0,)R is positive, and increasing with continuous derivative and ψ(0)=0. Then the Lebesgue real-valued measurable function Ω defined on [0,) is said to be in the space Xpψ, (1p<) for which

    ΩXpψ=(x2x1|Ω(t)|ψ(t)dt)1/p<,1p<.

    When p=, then

    ΩXψ=esssup0t<[ψ(t)Ω(t)].

    Definition 8.2. [25] Suppose that κ,ξC with (κ)>0 and (ξ)0. The tempered fractional left sided integral is defined by

    (x1Jκ,ξΩ)(t)=1Γ(κ)tx1eξ(ts)(ts)κ1Ω(s)ds,t>x1.

    Definition 8.3. [26] Let Ω be an integrable function in the space Xpψ(0,) and assume that ψ:[0,)R is positive, and increasing with continuous derivative and ψ(0)=0. Then the generalized left sided tempered fractional integral of a function Ω with respect to another function ψ is defined by

    (ψJκ,ξΩ)(t)=1Γ(κ)t0eξ(ψ(t)ψ(s))(ψ(t)ψ(s))κ1ψ(s)Ω(s)ds,t>0,

    where ξ>0, κC with (κ)>0.

    Theorem 8.1. [27] Suppose that ΩXpψ(0,) and assume that ψ:[0,)R is positive, and increasing with continuous derivative and ψ(0)=0. Moreover, we assume that (H1) holds. Then for t>0, κ,λ>0, we have

    ψJκ,ξQ2(t)ψJλ,ξΩ(t)+ψJκ,ξΩ(t)ψJλ,ξQ1(t)ψJκ,ξQ2(t)ψJλξQ1(t)+ψJκ,λΩ(t)ψJλ,ξΩ(t).

    Theorem 8.2. [27] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). In addition, we suppose that ψ:[0,)R is positive, and increasing with continuous derivative and ψ(0)=0. Then, for t>0 and κ,λ>0, the following inequalities hold:

    (a)ψJκ,ξQ2(t)ψJλ,ξΠ(t)+ψJλ,ξΩ(t)ψJκ,ξR1(t)ψJκ,ξQ2(t)ψJλ,ξR1(t)+ψJκ,ξΩ(t)ψJλ,ξΠ(t).(b)ψJλ,ξQ1(t)ψJκ,ξΠ(t)+ψJκ,ξR2(t)ψJλ,ξΩ(t)ψJκ,ξQ1(t)ψJλ,ξR2(t)+ψJκ,ξΩ(t)ψJλ,ξΠ(t).(c)ψJκ,ξQ2(t)ψJλ,ξR2(t)+ψJκ,ξΩ(t)ψJλ,ξΠ(t)ψJκ,ξQ2(t)ψJλ,ξΠ(t)+ψJκ,ξΩ(t)ψJλ,ξR2(t).(d)ψJκ,ξQ1(t)ψJλ,ξR1(t)+ψJκ,ξΩ(t)ψJλ,ξΠ(t)ψJκ,ξQ1(t)ψJλ,ξΠ(t)+ψJκ,ξΩ(t)ψJλ,ξR1(t).

    We present in the next certain other types of inequalities for tempered fractional integral.

    Theorem 8.3. [27] Assume that the assumptions on Theorem 8.2 hold. If p,q>1 are such that 1p+1q=1, then, for t>0 we have:

    (i)1pψJκ,ξΩp(t)ψJλ,ξΠp(t)+1qψJκ,ξΠq(t)ψJλ,ξΩq(t)ψJκ,ξΩ(t)Π(t)ψJλ,ξΠ(t)Ω(t).(ii)1pψJκ,ξΩp(t)ψJλ,ξΠp(t)+1qψJκ,ξΠq(t)ψJλ,ξΩp(t)ψJλ,ξΠq1(t)Ωp1(t)ψJκ,ξΠ(t)Ω(t).(iii)1pψJκ,ξΩp(t)ψJλ,ξΠ2(t)+1qψJκ,ξΠq(t)ψJλ,ξΩ2(t)ψJλ,ξΩ2/p(t)Π2/q(t)ψJκ,ξΩ(t)Π(t).(iv)1pψJκ,ξΩ2(t)ψJλ,ξΠq(t)+1qψJκ,ξΠ2(t)ψJλ,ξΩp(t)ψJλ,ξΩp1(t)Πq1(t)ψJκ,ξΩ2/p(t)Π2/q(t).

    Theorem 8.4. [27] Assume that the assumptions on Theorem 8.2 hold. If p,q>1 are such that 1p+1q=1, then, for t>0 we have:

    (a)pψJκ,ξΩ(t)ψJλ,ξΠ(t)+qψJκ,ξΠ(t)ψJλ,ξΩ(t)ψJκ,ξΩp(t)Πq(t)ψJλ,ξΩq(t)Πp(t).(b)pψJκ,ξΩp1(t)ψJλ,ξΩ(t)Πq(t)+qψJκ,ξΩq1(t)ψJλ,ξΩq(t)Π(t)ψJκ,ξΠq(t)ψJλ,ξΩp(t).(c)pψJκ,ξΩ(t)ψJλ,ξΠ2/p(t)+qψJκ,ξΠq(t)ψJλ,ξΩ2/q(t))ψJλ,ξΩp(t)Π(t)ψJκ,ξΠq(t)Ω2(t).(d)pψJκ,ξΩ2/p(t)Πq(t)ψJλ,ξΠq1(t)+qψJκ,ξΠq1(t)ψJλ,ξΩ2/q(t)Πp(t)ψJλ,ξΩ2(t)ψJκ,ξΠ2(t).

    Theorem 8.5. [27] Assume that the assumptions on Theorem 8.2 hold. Let p,q>1 be such that 1p+1q=1. Suppose that

    K=min0stΩ(t)Π(t)andH=max0stΩ(t)Π(t).

    Then, for t>0 we have:

    (i)ψJκ,ξΩ2(t)ψJκ,ξΠ2(t)(K+H)24KH(ψJκ,ξΩ(t)Π(t))2,(ii)0ψJκ,ξΩ2(t)ψJκ,ξΠ2(t)(ψJκ,ξΩ(t)Π(t))HK2KH(ψJκ,ξΩ(t)Π(t)),(iii)0ψJκ,ξΩ2(t)ψJκ,ξΠ2(t)(ψJκ,ξΩ(t)Π(t))2HK4KH(ψJκ,ξΩ(t)Π(t))2.

    In this section we deal with Grüss-type integral inequalities concerning conformable fractional integrals.

    We now introduced the definition of the generalized mixed η-conformable fractional integral.

    Definition 9.1. [28] Assume that Ω:[x1,x2]R and αC, (α)>0, ρ>0, η is defined on [x1,x2]×[x1,x2]. Then the mixed left η-conformable generalized fractional integral of Ω is defined by

    Jα,ρηΩ(x)=1Γ(α)x2x1+η(x,x1)Ω(s)((η(x2,s))ρ(x1x+η(x2,x1))ρρ)α1(η(x2,s))ρ1ds,

    and the mixed right η-conformable generalized fractional integral of Ω is defined by

    Jα,ρηΩ(x)=1Γ(α)x1+η(x,x1)x1Ω(s)((η(s,x1))ρ(xb+η(x2,x1))ρρ)α1(η(s,x1))ρ1ds.

    Theorem 9.1. [28] Assume that Ω:[0,) is an integrable function satisfying (H1) and t>0, α,β,ρ>0. Then, we have:

    Jβ,ρηQ1(t)Jα,ρηΩ(t)+Jα,ρηQ2(t)Jβ,ρηΩ(t)Jα,ρηQ2(t)Jβ,ρηQ1(t)+Jα,ρηΩ(t)Jβ,ρηΩ(t).

    Theorem 9.2. [28] Assume that Ω,Π:[0,)R are two integrable function satisfying (H1) and (H2) and t>0, α,β,ρ>0. Then we have:

    (ⅰ). Jβ,ρηR1(t)Jα,ρηΩ(t)+Jα,ρηQ2(t)Jβ,ρηΠ(t)Jβ,ρηR1(t)Jα,ρηQ2(t)+Jα,ρηΩ(t)Jβ,ρηΠ(t).

    (ⅱ). Jβ,ρηQ1(t)Jα,ρηΠ(t)+Jα,ρηR2(t)Jβ,ρηΩ(t)Jβ,ρηQ1(t)Jα,ρηR2(t)+Jβ,ρηΩ(t)Jα,ρηΠ(t).

    (ⅲ). Jα,ρηQ2(t)Jβ,ρηR2(t)+Jα,ρηΩ(t)Jβ,ρηΠ(t)Jα,ρηQ2(t)Jβ,ρηΠ(t)+Jβ,ρηR2(t)Jα,ρηΩ(t).

    (ⅳ). Jα,ρηQ1(t)Jβ,ρηR1(t)+Jα,ρηΩ(t)Jβ,ρηΠ(t)Jα,ρηQ1(t)Jβ,ρηΠ(t)+Jβ,ρηR1(t)Jα,ρηΩ(t).

    Theorem 9.3. [28] Assume that Ω,Π:[0,)R are two integrable function satisfying (H1) and (H2) and t>0, α,β,ρ>0. Then:

    |Jα,ρηΩ(t)Π(t){(η(x2,x1+η(t,x1))ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα(η(x2,x1)ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα}Jα,ρηΩ(t)Jα,ρηΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(u,v,w)=(Jα,ρηw(t)Jα,ρηu(t))(Jα,ρηu(t)Jα,ρηv(t))+Jα,ρηv(t)u(t)×{(η(x2,x1+η(t,x1))ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα(η(x2,x1)ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα}Jα,ρηv(t)Jα,ρηu(t)+Jα,ρηw(t){(η(x2,x1+η(t,x1))ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα(η(x2,x1)ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα}Jα,ρηw(t)Jα,ρηu(t)+Jα,ρηv(t)Jα,ρηw(t)Jα,ρηv(t)w(t){(η(x2,x1+η(t,x1))ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα(η(x2,x1)ρ(x1t+η(x2,x1))ρ)αΓ(α+1)ρα}.

    The (k,s)-fractional conformable integral operator is defined as

    Definition 9.2. [29] Let Ω be an integrable function, αC, (α)>0 and s>0. The (k,s)-fractional conformable integral operator is defined as

    Iα,skΩ(t)=s1αkkΓk(α)tx1[(tx1)s(xx1)s]αk1(xx1)s1Ω(x)ds,t[x1,x2].

    Here, we present Grüss type inequalities involving the (k,s)-fractional conformable integral Iα,sk defined in Definition 9.2.

    Theorem 9.4. [29] Assume that Ω:[0,)R is an integrable function satisfying (H1) and k,s,α,β>0. Then we have:

    Iβ,skQ1(t)Iα,skΩ(t)+Iα,skQ2(t)Iβ,skΩ(t)Iα,skQ2(t)Iβ,skQ1(t)+Iα,skΩ(t)Iβ,skΩ(t).

    Theorem 9.5. [29] Assume that Ω,Π:[0,)R are two integrable function satisfyingt (H1) and (H2) and k,s,α,β>0. Then we have:

    (ⅰ). Iβ,skR1(t)Iα,skΩ(t)+Iα,skQ2(t)Iβ,skΠ(t)Iβ,skR1(t)Iβ,skQ2(t)+Iα,skΩ(t)Iβ,skΠ(t).

    (ⅱ). Iβ,skQ1(t)Iα,skΠ(t)+Iα,skR2(t)Iβ,skΩ(t)Iβ,skQ1(t)Iβ,skR2(t)+Iα,skΠ(t)Iβ,skΩ(t).

    (ⅲ). Iα,skQ2(t)Iβ,skR2(t)+Iα,skΩ(t)Iβ,skΠ(t)Iα,skQ2(t)Iβ,skΠ(t)+Iβ,skR2(t)Iα,skΩ(t).

    (ⅳ). Iα,skQ1(t)Iβ,skR1(t)+Iα,skΩ(t)Iβ,skΠ(t)Iα,skQ1(t)Iβ,skΠ(t)+Iβ,skR1(t)Iα,skΩ(t).

    Theorem 9.6. [29] Assume that Ω,Π:[0,)R are two integrable function satisfyingt (H1) and (H2) and k,s,α>0. Then we have:

    |sαk(tx1)sαkΓk(α+k)Iα,sk(Ω(t)Π(t))Iα,skΩ(t)Iα,skΠ(t)|Tk(Ω,Q1,Q2)Tk(Π,R1,R2),

    where

    Tk(x,y,z)=(Iα,skz(t)Iα,skx(t))(Iα,skx(t)Iα,sky(t))+sαk(tx1)sαkΓk(α+k)Iα,sk(y(t)x(t))Iα,sky(t)Iα,skx(t)+sαk(tx1)sαkΓk(α+k)Iα,sk(z(t)x(t))Iα,skz(t)Iα,skx(t)sαk(tx1)sαkΓk(α+k)Iα,sk(y(t)z(t))+Iα,sky(t)Iα,skz(t).

    Definition 9.3. [30] Let λC,(λ)>0. We define the left and right sided fractional conformable integral operators as

    λx1JμΩ(x)=1Γ(λ)xx1((xx1)μ(tx1)μμ)λ1Ω(t)(tx1)1μdt,
    λx2JμΩ(x)=1Γ(λ)x2x((x2x)μ(x2t)μμ)λ1Ω(t)(x2t)1μdt.

    For the results in this section we consider x1=0.

    Theorem 9.7. [30] Suppose that Ω:[0,)R is an integrable function satisfying (H1). Then for x,α,β>0 we have:

    βJμQ1(t)αJμΩ(t)+αJμQ2(t)βJμΩ(t)αJμQ2(t)βJμQ1(t)+αJμΩ(t)βJμΩ(t).

    Theorem 9.8. [30] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for x,α,β>0 we have:

    (1) βJμR1(t)αJμΩ(t)+αJμQ2(t)βJμΠ(t)αJμQ2(t)βJμR1(t)+αJμΩ(t)βJμΠ(t).

    (2) βJμQ1(t)αJμΠ(t)+αJμR2(t)βJμΩ(t)αJμQ1(t)βJμR2(t)+αJμΩ(t)βJμΠ(t).

    (3) αJμQ2(t)βJμR2(t)+αJμΩ(t)βJμΠ(t)αJμQ2(t)βJμΠ(t)+βJμR2(t)αJμΩ(t).

    (4) αJμQ1(t)βJμR1(t)+αJμΩ(t)βJμΠ(t)αJμQ1(t)βJμΠ(t)+αJμΩ(t)βJμR1(t).

    Theorem 9.9. [30] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for x,α,β>0 we have:

    |tμαμαΓ(α+1)αJμΩ(t)Π(t)αJμΩ(t)αJμΠ(t)|T(Ω,Q1,Q2)T(Π,R1R2),

    where

    T(y,z,w)=(αJμw(t)αJμy(t))(αJμy(t)αJμz(t))+tμαμαΓ(α+1)αJμz(t)y(t)αJμz(t)αJμy(t)+tμαμαΓ(α+1)αJμw(t)y(t)αJμw(t)αJμy(t)+αJμz(t)αJμw(t)tμαμαΓ(α+1)αJμz(t)w(t).

    Definition 10.1. [31] The proportional fractional integrals, left- and right-sided, of a function Ω of order α and σ(0,1] are defined by

    Iα,σx1Ω(t)=1σαΓ(α)tx1eσ1σ(ts)(ts)α1Ω(s)ds,

    and

    Iα,σx2Ω(t)=1σαΓ(α)x2teσ1σ(st)(st)α1Ω(s)ds,

    where αC, (α)>0.

    In what follows, we present Grüss-type inequality with the help of the proportional fractional integral defined above.

    Theorem 10.1. [31] Assume that Ω:[0,)R is an integrable function satisfying (H1). Then:

    Iβ,σQ1(t)Iα,σΩ(t)+Iα,σQ2(t)Iβ,σΩ(t)Iα,σQ2(t)Iβ,σQ1(t)+Iβ,σΩ(t)Iβ,σΩ(t).

    Theorem 10.2. [31] Let σ(0,1]. Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then the following inequalities hold:

    (a) Iβ,σR1(t)Iα,σΩ(t)+Iα,σQ2(t)Iβ,σΠ(t)Iβ,σR1(t)Iα,σQ2(t)+Iα,σΩ(t)Iβ,σΠ(t).

    (b) Iβ,σQ1(t)Iα,σΠ(t)+Iα,σR2(t)Iβ,σΩ(t)Iβ,σQ1(t)Iα,σR2(t)+Iβ,σΩ(t)Iα,σΠ(t).

    (c) Iα,σQ2(t)Iβ,σR2(t)+Iα,σΩ(t)Iβ,σΠ(t)Iα,σQ2(t)Iβ,σΠ(t)+Iβ,σR2(t)Iα,σΩ(t).

    (d) Iα,σQ1(t)Iβ,σR1(t)+Iα,σΩ(t)Iβ,σΠ(t)Iα,σQ1(t)Iβ,σΠ(t)+Iβ,σR1(t)Iα,σΩ(t).

    Theorem 10.3. [31] Let x>0, α,β>0, and p,q>1 satisfying 1p+1q=1, and Ω,Π:[0,)R be two positive integrable functions. Then we have:

    (i)1pJα,σ0+Ωp(x)Jβ,σ0+Πp(x)+1qJα,σ0+Πq(x)Jβ,σ0+Ωq(x)(Jα,σ0+Ω(x)Π(x))(Jβ,σ0+Ω(x)Π(x)).(ii)1pJβ,σ0+Πq(x)Jα,σ0+Ωp(x)+1qJβ,σ0+Ωp(x)Jα,σ0+Πq(x)(Jβ,σ0+Ωp1Πq1(x))(Jα,σ0+Ω(x)Π(x)).(iii)1pJβ,σ0+Π2(x)Jα,σ0+Ωp(x)+1qJβ,σ0+Ω2(x)Jα,σ0+Πq(x)(Jβ,σ0+Ω2/q(x)Π2/p(x))(Jα,σ0+Ω(x)Π(x)).(iv)1pJβ,σ0+Πq(x)Jα,σ0+Ω2(x)+1qJβ,σ0+Ωp(x)Jα,σ0+Π2(x)(Jβ,σ0+Ωp1(x)Πq1(x))(Jα,σ0+Ω2/p(x)Π2/p(x)).

    Theorem 10.4. [31] Let the assumptions of Theorem 10.1 be hold. In addition, let

    μ=min0txΩ(t)Π(t)andM=max0txΩ(t)Π(t).

    Then, we have:

    (a)0(Jα,σ0+Ω2(x)Jα,σ0+Π2(x))(M+μ)24μM(Jα,σ0+Ω(x)Π(x))2.(b)0Jα,σ0+Ω2(x)Jα,σ0+Π2(x)(Jα,σ0+Ω(x)Π(x))(Mμ)22μM(Jα,σ0+Ω(x)Π(x)).(c)0Jα,σ0+Ω2(x)Jα,σ0+Π2(x)(Jα,σ0+Ω(x)Π(x))2(Mμ)24μM(Jα,σ0+Ω(x)Π(x))2.

    Definition 10.2. [32] Assume that Ω is integrable and ψ is a strictly increasing continuous function on [x1,x2]. For σ(0,1], αC,(α)0, kR+, we define the left- and right-sided proportional k-fractional integrals, respectively, as

    k,ψIα,σx1Ω(t)=1σαkkΓk(α)tx1eσ1σ(ψ(t)ψ(s))(ψ(t)ψ(s))αk1ψ(s)Ω(s)ds,

    and

    k,ψIα,σx2Ω(t)=1σαkkΓk(α)x2teσ1σ(ψ(s)ψ(t))(ψ(s)ψ(t))αk1ψ(s)Ω(s)ds.

    In what follows, we present Grüss-type inequality with the help of the generalized k-fractional integral.

    Theorem 10.5. [32] Let Ω,Π:[0,)R be positive integrable functions. satisfying (H1),(H2) with positive integrable functions Q1,Q2,R1,R2 and ψ be a strictly increasing continuous function. Tthen the following inequality also holds:

    |1α[ψ(t)ψ(0))αkσαkΓk(α)k,ψIα,σΩ(t)Π(t)k,ψIα,σΩ(t)k,ψIα,σΠ(t)|T(Ω,Q1,Q2)(t)T(Π,R1,R2)(t),

    where

    T(u,v,w)(t)=1α[ψ(t)ψ(0))αk4σαkΓk(α)(k,ψIα,σ{(v+w)u}(t))2k,ψIα,σΩ(t)Π(t)(k,ψIα,σ(u)(t))2.

    Definition 11.1. A function Ω is said to be Lp,s[x1,x2] if

    (x2x1|Ω(t)|ptsdt)1/p<,1p<,s0.

    Definition 11.2. [33] Let ΩL1,s[0,). The Riemann-Liouville generalized fractional integral of Ω of order α>0 and s0 is defined by

    Iα,sΩ(t)=(s+1)1αΓ(α)tx1(ts+1τs+1)α1τsΩ(τ)dτ,t[x1,x2].

    In this section, we present some Grüss type inequalities via the fractional integral defined in Definition 11.2.

    Theorem 11.1. [34] Let ΩL1,s[x1,x2] satisfying (H1) and k>0, s0, α,β>0. Then we have the following inequality:

    Iβ,sQ1(t)Iα,sΩ(t)+Iα,sQ2(t)Iβ,sΩ(t)Iα,sQ2(t)Iβ,sQ1(t)+Iα,sΩ(t)Iβ,sΩ(t).

    Theorem 11.2. [34] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2) and k>0, s0, α,β>0. Then we have the following inequalities:

    (ⅰ) Iβ,sR1(t)Iα,sΩ(t)+Iα,sQ2(t)Iβ,sΠ(t)Iβ,sR1(t)Iα,sQ2(t)+Iα,sΩ(t)Iβ,sΠ(t).

    (ⅱ) Iβ,sQ1(t)Iα,sΠ(t)+Iα,sR2(t)Iβ,sΩ(t)Iβ,sQ1(t)Iα,sR2(t)+Iα,sΠ(t)Iβ,sΩ(t).

    (ⅲ) Iα,sQ2(t)Iβ,sR2(t)+Iα,sΩ(t)Iβ,sΠ(t)Iα,sQ2(t)Iβ,sΠ(t)+Iβ,sR2(t)Iα,sΩ(t).

    (ⅳ) Iα,sQ1(t)Iβ,sR1(t)+Iα,sΩ(t)Iβ,sΠ(t)Iα,sQ1(t)Iβ,sΠ(t)+Iβ,sR1(t)Iα,sΩ(t).

    Theorem 11.3. [35] Under the assumptions of Theorem 11.2 we have for all t[x1,x2], s0 and α>0

    |(s+1)αt(s+1)αΓ(α+1)Iα,sΩ(t)Π(t)Iα,sΩ(t)Iα,sΠ(t)|T(Ω,Q1,Q1)T(Π,R1,R2),

    where

    T(x,y,z)=(Iα,sz(t)Iα,sx(t))(Iα,sx(t)Iα,sy(t))+(s+1)αt(s+1)αΓ(α+1)Iα,sy(t)x(t)Iα,sy(t)Iα,sx(t)+(s+1)αt(s+1)αΓ(α+1)Iα,sz(t)x(t)Iα,sz(t)Iα,sx(t)(s+1)αt(s+1)αΓ(α+1)Iα,sy(t)z(t)+Iα,sy(t)Iα,sx(t).

    Now we define (k,s)-Riemann-Liouville fractional integral.

    Definition 11.3. [33] Let Ω:[x1,x2]R be a continuous function. Then (k,s)-Riemann-Liouville fractional integral of Ω of order α>0 is defined by

    Jα,sx1,kΩ(t)=(s+1)1αkkΓk(α)tx1(ts+1τs+1)αk1τsΩ(τ)dτ,t[x1,x2],

    where k>0,sR{1}.

    Now, for the generalized (k,s)-Riemann-Liouville fractional integral defined above, we give some Grüss type inequalities.

    Theorem 11.4. [35] Let ΩL1,s[x1,x2] satisfying (H1) and k>0, s0, α,β>0. Then we have the following inequality:

    Jβ,sx1,kQ1(t)Jα,sx1,kΩ(t)+Jα,sx1,kQ2(t)Ω(t)Jα,sx1,kQ2(t)Jβ,sx1,kQ1(t)+Jα,sx1,kΩ(t)Jβ,sx1,kΩ(t).

    Theorem 11.5. [35] Assume that Ω,Π:[0,)Rare two integrable functions satisfying (H1) and (H2) and k>0, s0, α,β>0. Then we have:

    (ⅰ) Jβ,sx1,kR1(t)Jα,sx1,kΩ(t)+Jα,sx1,kQ2(t)Jβ,sx1,kΠ(t)Jβ,sx1,kR1(t)Jα,sx1,kQ2(t)+Jα,sx1,kΩ(t)Jβ,sx1,kΠ(t).

    (ⅱ) Jβ,sx1,kQ1(t)Jα,sx1,kΠ(t)+Jα,sx1,kR2(t)Jβ,sx1,kΩ(t)Jβ,sx1,kQ1(t)Jα,sx1,kR2(t)+Jα,sx1,kΠ(t)Jβ,sx1,kΩ(t).

    (ⅲ) Jα,sx1,kQ2(t)Jβ,sx1,kR2(t)+Jα,sx1,kΩ(t)Jβ,sx1,kΠ(t)Jα,sx1,kQ2(t)Jβ,sx1,kΠ(t)+Jβ,sx1,kR2(t)Jα,sx1,kΩ(t).

    (ⅳ) Jα,sx1,kQ1(t)Jβ,sx1,kR1(t)+Jα,sx1,kΩ(t)Jβ,sx1,kΠ(t)Jα,sx1,kQ1(t)Jβ,sx1,kΠ(t)+Jβ,sx1,kR1(t)Jα,sx1,kΩ(t).

    Theorem 11.6. [35] Under the assumptions of Theorem 11.5 we have for all t[x1,x2], s0 and α>0

    |(s+1)αkt(s+1)αkΓk(α+k)Jα,sx1,kΩ(t)Π(t)Jα,sx1,kΩ(t)Jα,sx1,kΠ(t)|Tsk(Ω,Q1,Q1)Tsk(Π,R1,R2),

    where

    Tsk(x,y,z)=(Jα,sx1,kz(t)Jα,sx1,kx(t))(Jα,sx1,kx(t)Jα,sx1,ky(t))+(s+1)αkt(s+1)αkΓk(α+k)Jα,sx1,ky(t)x(t)Jα,sx1,ky(t)Jα,sx1,kx(t)+(s+1)αkt(s+1)αkΓk(α+k)Jα,sx1,kz(t)x(t)Jα,sx1,kz(t)Jα,sx1,kx(t)(s+1)αkt(s+1)αkΓk(α+k)Jα,sx1,ky(t)z(t)+Jα,sx1,ky(t)Jα,sx1,kx(t).

    In this section, we present the Grüss-type fractional integral inequalities involving the Caputo-Fabrizio fractional integral.

    Definition 12.1. [36] Assume that αR such that 0<α<1. We define the Caputo-Fabrizio fractional integral of a function Ω of order α by

    Iα0,tΩ(t)=1αt0e(1αα)(ts)Ω(s)ds.

    Theorem 12.1. [37] Assume that Ω:[0,)R is an integrable function satisfying (H1). Then, for t>0, α,β>0, k>0, we have:

    Iβ0,tQ1(t)Iα0,tΩ(t)+ Iα0,tQ2(t)Iβ0,tΩ(t) Iα0,tQ2(t)Iβ0,tQ1(t)+ Iα0,tΩ(t)Iβ0,tΩ(t).

    Theorem 12.2. [37] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then, for t>0, α, β>0, k>0 we have the inequalities:

    (a) Iβ0,tR1(t) Iα0,tΩ(t)+ Iα0,tQ2(t) Iβ0,tΠ(t) Iβ0,tR1(t) Iα0,tQ2(t)+ Iα0,tΩ(t) Iβ0,tΠ(t).

    (b) Iβ0,tQ1(t) Iα0,tΠ(t)+ Iα0,tR2(t) Iβ0,tΩ(t) Iβ0,tQ1(t) Iα0,tR2(t)+ Iβ0,tΩ(t) Iα0,tΠ(t).

    (c) Iα0,tQ2(t) kIβ0,tR2(t)+ Iα0,tΩ(t) Iβ0,tΠ(t) Iα0,tQ2(t) Iβ0,tΠ(t)+ Iβ0,tR2(t) Iα0,tΩ(t).

    (d) Iα0,tQ1(t)Iβ0,tR1(t)+ Iα0,tΩ(t) Iβ0,tΠ(t) Iα0,tQ1(t) Iβ0,tΠ(t)+ Iβ0,tR1(t) Iα0,tΩ(t).

    Theorem 12.3. [37] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all t>0, α>0, we have:

    |(11α[1e(1αα)t]) Iα0,tΩ(t)Π(t) Iα0,tΩ(t) Iα0,tΠ(t)|T(Ω,Q1,Q2)T(Π,R1,R2),

    where

    T(y,z,w)=( Iα0,tw(t) Jαy(t))( Iα0,ty(t) Iα0,tz(t))+(11α[1e(1αα)t])Iα0,tz(t)y(t)Iα0,tz(t) Iα0,ty(t)+(11α[1e(1αα)t])Iα0,tw(t)y(t)Iα0,tw(t) Iα0,ty(t)+Iα0,tz(t) Iα0,tw(t)+(11α[1e(1αα)t])Iα0,tz(t)w(t).

    In this section, Grüss-type fractional integral inequalities are presented via Saigo fractional integer operator.

    Definition 13.1. [38] Assume that α>0,β,ηR. The Saigo fractional integral Iα,β,η0,x[Ω(x)] of order α for a real-valued continuous function Ω is defined by

    Iα,β,η0,x[Ω(x)]=xαβΓ(α)x0(xt)α12F1(α+β,η;α;1tx)Ω(t)dt,

    where 2F1 is the Gaussian hypergeometric function defined by

    2F1(a,b;c;x)=n=0(a)n(b)nxn(c)nn!,

    and (a)n is the Pochhammer symbol

    (a)0=1,(a)n=a(a+1)(a+n1)=Γ(a+n)Γ(a).

    Theorem 13.1. [39] Assume that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all x>0, α>max{0,β}, β<1, β1<η<0, one has

    |Γ(1β+η)Γ(1β)Γ(1+α+η)xβIα,β,η0,x[Ω(x)Π(x)]Iα,β,η0,x[Ω(x)]Iα,β,η0,x[Π(x)]|T(Ω,Q1(x),Q2(x))T(Π,R1(x),R2(x)),

    where

    T(a,b,c)=(Iα,β,η0,x[c(x)]Iα,β,η0,x[a(x)])(Iα,β,η0,x[a(x)]Iα,β,η0,x[b(x)])+Γ(1β+η)Γ(1β)Γ(1+α+η)xβIα,β,η0,x[b(x)a(x)]Iα,β,η0,x[b(x)]Iα,β,η0,x[a(x)]+Γ(1β+η)Γ(1β)Γ(1+α+η)xβIα,β,η0,x[c(x)a(x)]Iα,β,η0,x[c(x)]Iα,β,η0,x[a(x)]+Iα,β,η0,x[b(x)]Iα,β,η0,x[c(x)]+Γ(1β+η)Γ(1β)Γ(1+α+η)xβIα,β,η0,x[b(x)c(x)].

    Theorem 13.2. [39] Suppose that Ω,Π:[0,)R are two integrable functions satisfying (H1) and (H2). Then for all x>0, α>max{0,β}, ψ>max{0ϕ}, β<1, β1<η<0, ϕ<1, ϕ1<ζ<0, we have:

    (a)Iψ,ϕ,ζ0,x[Q1(x)]Iα,β,η0,x[Ω(x)]+Iα,β,η0,x[Q2(x)]Iψ,ϕ,ζ0,x[Ω(x)]Iψ,ϕ,ζ0,x[Q2(x)]Iα,β,η0,x[Q1(x)]+Iα,β,η0,x[Ω(x)]Iψ,ϕ,ζ0,x[Ω(x)].(b)Iψ,ϕ,ζ0,x[R1(x)]Iα,β,η0,x[Ω(x)]+Iα,β,η0,x[Q2(x)]Iψ,ϕ,ζ0,x[Π(x)]Iψ,ϕ,ζ0,x[R1(x)]Iα,β,η0,x[Q2(x)]+Iα,β,η0,x[Ω(x)]Iψ,ϕ,ζ0,x[Π(x)].(c)Iψ,ϕ,ζ0,x[Q1(x)]Iα,β,η0,x[Π(x)]+Iα,β,η0,x[R2(x)]Iψ,ϕ,ζ0,x[Ω(x)]Iψ,ϕ,ζ0,x[Q1(x)]Iα,β,η0,x[R2(x)]+Iψ,ϕ,ζ0,x[uΩ(x)]Iα,β,η0,x[Π(x)].(d)Iα,β,η0,x[Q2(x)]Iψ,ϕ,ζ0,x[R2(x)]+Iα,β,η0,x[Ω(x)]Iψ,ϕ,ζ0,x[Π(x)]Iα,β,η0,x[Q2(x)]Iψ,ϕ,ζ0,x[Π(x)]+Iψ,ϕ,ζ0,x[R2(x)]Iα,β,η0,x[Ω(x)].(e)Iα,β,η0,x[Q1(x)]Iψ,ϕ,ζ0,x[R1(x)]+Iα,β,η0,x[Ω(x)]Iψ,ϕ,ζ0,x[Π(x)]Iα,β,η0,x[Q1(x)]Iψ,ϕ,ζ0,x[Π(x)]+Iψ,ϕ,ζ0,x[R1(x)]Iα,β,η0,x[Ω(x)].

    We define a fractional integral Kα,β,η associated with the Gauss hypergeometric function as follows:

    Definition 13.2. [40] Let ΩCμ. For α>max{0,(η+1)}, ηβ>1, β<1, we define a fractional integral Kα,β,ηf as follows:

    Kα,β,ηΩ(t)=Γ(1β)Γ(α+η+1)Γ(ηβ+1)tβIα,β,η0+Ω(t),

    where Iα,β,η0+f is the right-hand sided Gauss hypergeometric fractional integral of order α defined in Definition 13.1.

    We present integral inequalities of Grüss type for the above defined hypergeometric fractional integral.

    Theorem 13.3. [40] Let Ω,ΠCμ satisfying the condition (H) on [0,). Then for all t>0, α>max{0,(η+1)}, ηβ>1, β<1, we have

    |Kα,β,ηΩ(t)Π(t)Kα,β,ηΩ(t)Kα,β,ηΠ(t)|14(Mm)(Pp).

    Theorem 13.4. [40] Let Ω and Π be two synchronous functions on [0,). Then the following inequality holds:

    Kα,β,ηΩ(t)Π(t)Kα,β,ηΩ(t)Kα,β,ηΠ(t).

    Another fractional integral operator Kα,β,η,δ associated with the Gauss hypergeometric function is defined as follows.

    Definition 13.3. [41] Let ΩCμ. For α>max{0,(δ+η+1)}, ηβ>1, β<1, δ>1 we define a fractional integral Kα,β,η,δΩ as follows:

    Kα,β,η,δΩ(t)=Γ(1β)Γ(α+δ+η+1)Γ(ηβ+1)Γ(δ+1)tβ+βIα,β,η,δ0+Ω(t),

    where Iα,β,η,δ0+Ω is the right-hand sided Gauss hypergeometric fractional integral of order α defined by

    Iα,β,η,δ0,x[Ω(x)]=xαβ2δΓ(α)x0tδ(xt)α12F1(α+β+δ,η;α;1tx)Ω(t)dt,

    and 2F1 is the Gaussian hypergeometric function defined in Definition 13.1.

    We establish two Grüss-type fractional integral inequalities involving the Gauss hypergeometric function.

    Theorem 13.5. [41] Assume that Ω,Π:[x1,x2]R are two integrable functions satisfying the condition (H) on [0,). Then, for all x[0,), α>0, δ>1, and β,ηR with α+β+δ0 and η0, we have:

    |Kα,β,η;δΩ(t)Π(t)Kα,β,η,δΩ(t)Kα,β,η,δΠ(t)|14(Mm)(Pp).

    Theorem 13.6. [41] Suppose that Ω,Π:[0,)R are two synchronous functions (i.e (Ω(t)Ω(s))(Π(t)Π(s))0,t,s[0,)). Then, for all x[0,), α>0, δ>1, and β,ηR with α+β+δ0 and η0, we have:

    Kα,β,η,δΩ(t)Π(t)Kα,β,η,δΩ(t)Kα,β,η,δΠ(t).

    Now we give some Grüss-type inequalities for generalized hypergeometric function fractional order integral operators. We start with the following definitions.

    Definition 13.4. [42] Let α,α,β,β,γR and γ>0. Then the Saigo and Maeda fractional integral operator Iα,α,β,β,γt[Ω(x)] of order α for a real-valued continuous function Ω is defined by

    Iα,α,β,β,γt[Ω(x)]=xαΓ(γ)x0(xt)γ1tαF3(α,α,β,β,γ,1tx,1xt)Ω(t)dt,

    where F3 is the Appell hypergeometric function defined by

    F3(α,α,β,β,γ,x,y)=n=0n=0(α)n(α)n(β)n(β)nxmyn(γ)m+nm!n!,max{|x|,|y|}<1,

    and (a)n is the Pochhammer symbol.

    Definition 13.5. [43] Assume that α,α,β,β,γR such that

    γ>max{0,α+α+β1,α+α1,α+β1}andβ>max{1,α1}.

    Then we define a fractional integral operator

    (Sα,α,β,β,γtΩ)(x)=Γ(1+γαα)Γ(1+γαβ)Γ(1+β)Γ(1+γααβ)Γ(1+βα)xα+αγ(Iα,α,β,β,γtΩ)(x),

    where Iα,α,β,β,γt is the Saigo-Maeda fractional integral of order γ.

    The main results for Grüss inequalities are given now.

    Theorem 13.7. [43] Assume that h:[0,)R is an integrable function satisfying the condition m1h(x)M1 for all x[0,). Then for α,α,β,β,γR we have:

    |(Sα,α,β,β,γth2)(x)((Sα,α,β,β,γth)(x))2=(M1(Sα,α,β,β,γth)(x))((Sα,α,β,β,γth)(x)m)(M1h)(hm1)(x),

    provided α,α,β,β,γ>0.

    Theorem 13.8. [43] Assume that (H) holds on [0,). In addition, let Ω,ΠCμ. Then for α,α,β,β,γR and α,α,β,β,γ>0 we have:

    |(Sα,α,β,β,γΩ(x)Π(x)(Sα,α,β,β,γΩ)(x)(Sα,α,β,β,γΠ)(x)|14(Mm)(Pp),x[0,).

    Theorem 13.9. [43] Let Ω and Π be two synchronous functions on [0,) and let v,w:[0,)[0,). Then for all t>0,

    (Sα,α,β,β,γtvΩΠ)(x)(Sα,α,β,β,γtw)(x)+(Sα,α,β,β,γtwΩΠ)(x)(Sα,α,β,β,γtv)(x)(Sα,α,β,β,γtwΠ)(x)(Sα,α,β,β,γtvΩ)(x)+(Sα,α,β,β,γtwΩ)(x)(Sα,α,β,β,γtvΠ)(x).

    In this section we present Grüss-type integral inequalities via quantum calculus.

    Definition 14.1. [44] The Jakson's q-derivarive and q-integral of a function Ω defined on J are, respectively, given by

    DqΩ(t)=Ω(t)Ω(tq)t(1q),t0,q1,
    t0Ω(s)dqs=t(1q)k=0qkΩ(tqk).

    Definition 14.2. [45] The Riemann-Liouville fractional q-integral operator of a function Ω of order α is given by

    IαqΩ(t)=tα1Γq(α)t0(qst,q)α1Ω(s)dqs,α>0,0<q<1,

    where

    (a,q)α=(a;q)(aqα;q),αR

    and

    (α,q)=j=0(1αqj).

    Now, we present some q-Grüss integral inequalities.

    Theorem 14.1. [46] Assume that Ω,Π:[0,)R are two integrable functions satisfyingt (H1) and (H2). Then, for t>0 and α>0, we have:

    |tαΓq(α+1)IαqΩ(t)Π(t)IαqΩ(t)IαqΠ(t)|Tq(Ω,Q1.Q2)Tq(Π,R1,R2),

    where

    Tq(u,v,w)=(Iαqw(t)Iαqu(t))(Iαqu(t)Iαqv(t))+tαΓq(α+1)Iαqv(t)u(t)Iαqv(t)Iαqu(t)+Iαqv(t)Iαqw(t)tαΓq(α+1)Iαqv(t)w(t).

    Definition 14.3. [47] Assume Ω:JR is a continuous function and let xJ. Then the expression

    x1DqΩ(x)=Ω(x)Ω(qx+(1q)x1)(1q)(xx1),tx1,x1DqΩ(x1)=limxx1x1DqΩ(x),

    is called the q-derivative on J of function Ω at x.

    Definition 14.4. [47] Assume Ω:JR is a continuous function. Then the q-integral on J is defined by

    xx1Ω(t)x1dqt=(1q)(xx1)n=0qnΩ(qnx+(1qn)x1)

    for xJ. Moreover, if c(a,x) then the definite q-integral on J is defined by

    xcΩ(t)x1dqt=xx1Ω(t)x1dqtcx1Ω(t)x1dqt=(1q)(xx1)n=0qnΩ(qnx+(1qn)x1)(1q)(cx1)n=0qnΩ(qnc+(1qn)x1).

    Theorem 14.2. [47] Assume Ω,Π:JR are continuous functions on J satisfying the vondition (H). Then we have the inequality

    |1x2x1x2x1Ω(x)Π(x)x1dqx(1x2x1x2x1Ω(x)x1dqx)(1x2x1x2x1Π(x)x1dqx)|14(Mm)(Pp).

    Now, we are going to present the q-Grüss-ˇCebyˇsev integral inequality on interval [x1,x2].

    Theorem 14.3. [47] Let Ω,Π:JR be L1, L2-Lipschitzian continuous functions on [x1,x2], so that

    |Ω(u)Ω(v)|L1|uv|,|Π(u)Π(v)|L2|uv|,

    for all u,v[x1,x2]. Then we have:

    |1x2x1x2x1Ω(x)Π(x)x1dqx(1x2x1x2x1Ω(x)x1dqx)(1x2x1x2x1Π(x)x1dqx)|qL1L2(1+q+q2)(1+q)2(x2x1)2.

    Let q(0,1) and let I be any interval of R containing 0, and denote by Iq the set

    Iq=qI={qX:XI};IqI.

    Definition 14.5. [44] Let Ω:IR. The q-symmetric difference operator of Ω is defined by

    (˜DqΩ)(t)=Ω(qt)Ω(q1t)(qq1)t;tIq{0},

    and

    (˜DqΩ)(t)=Ω(0),t=0.

    Definition 14.6. [44] Suppose that x1,x2I and x1<x2. For Ω:IR and for q(0,1), the q-symmetric integral of Ω is given by

    x2x1Ω(t)˜dqt=x20Ω(t)˜dqtx10Ω(t)˜dqt,

    where

    x0Ω(t)˜dqt=x(1q2)n=0q2nΩ(q2n+1x),xI,

    provided that the series converges at x=x1 and x=x2.

    Now, the concepts of q-symmetric derivative and q-symmetric integral are extended on finite intervals. We fix sN{0}. Let Js=[ts,ts+1]R be an interval containing 0 and 0<qs<1 be a constant. For a function Ω:IsR, we define the qs-symmetric derivative at a point tIs as follows:

    Definition 14.7. [48] Assume that Ω:IsR is continuous and tIs. The qs-symmetric derivative of Ω at t is defined as

    (DqsΩ)(t)=Ω(q1st+(1q1s)ts)Ω(qst+(1qs)ts)(q1sqs)(tts);tts,
    (DqsΩ)(ts)limtts(DqsΩ)(t).

    Definition 14.8. [48] Assume that Ω:IsR is a continuous function. The qs-symmetric integral is defined as

    ttsΩ(s)dqst=(tts)(1q2s)n=0q2nsΩ(q2n+1st+(1q2n+1s)ts).

    Now, we present qs-symmetric analogue of Grüss-Chebyshev integral inequality.

    Theorem 14.4. [48] Let Ω and Π:J=[x1,x2]R be L1,L2-Lipschitzian continuous functions on [x1,x2] so that

    |Ω(u)Ω(v)|L1|uv|,|Π(u)Π(v)|L2|uv|,

    for all u,v[x1,x2]. Then:

    |1x2x1x2x1Ω(x)Π(x)dqsx(1x2x1x2x1Ω(x)dqsx)(1x2x1x2x1Π(x)dqsx)|L1L2q4s(x2x1)2(1+q2s+q4s)(1+q2s)2.

    The following concepts are adapted by Ref. ([49]). We state a q-shifting operator as

    x1Φq(m)=qm+(1q)x1,0<q<1,m,x1R.

    The q-analog is stated by

    (m;q)0=1,(m;q)k=k1i=1(1qim),kN{}.

    The q number is stated by

    [m]q=1qm1q,mR.

    The -Gamma function is stated by

    Here, we add some definitions regarding fractional -calculus, namely the Riemann-Liouville fractional -integral.

    Definition 14.9. [49] Let and function be a continuous stated on Then is given by

    Now, we present the fractional -Grüss integral inequality on the interval

    Theorem 14.5. [50] Let be continuous functions satisfying For and we have the inequality

    Next, we give the fractional -Grüss-Čebyšev integral inequality on the interval

    Theorem 14.6. [50] Let be -, -Lipschitzian continuous functions, so that

    for all and Then we have the inequality

    In this section we give Grüss-type integral inequalities via fractional Hilfer derivative operators.

    In this section we present several integral inequalities for the -Hilfer fractional derivative operator.

    Definition 15.1. [51] Let Then the following

    is called the Hiler -fractional derivative.

    Theorem 15.1. [51] Let and be a positive function on and let denote the Hilfer -fractional derivative of order and type Suppose that:

    There exist such that

    for all

    Then

    In this section, we present inequalities of the Grüss-type via -fractional Hilfer-Katugampola generalized derivative.

    Definition 15.2. [52] Let and The generalized -fractional Hilfer-Katugampola derivatives (left-sided and right-sided) are defined as

    where

    Theorem 15.2. [52] Let and be positive integrable function on satisfying Then we have:

    Theorem 15.3. [52] Let and be positive integrable functions on satisfying and Then we have:

    Theorem 15.4. [52] Let and be positive integrable functions on satisfying and If and then we have:

    Theorem 15.5. [52] Let and be positive integrable functions on Let

    Then we have:

    Our objective in this paper was to present a comprehensive and up-to-date review on Grüss-type inequalities for fractional differential operators. We presented results including inequalities of the Grüss-type for different kinds of fractional integral and differential operators. Grüss-type inequalities for fractional integrals of Riemann-Liouville, Katugampola, Hadamard's, Raina's, tempered, conformable, proportional, Caputo-Fabrizio, Saigo's are included. Moreover Grüss-type inequalities concerning Hilfer fractional differential operators and quantum Grüss-type integral inequalities are also presented. We believe that the present survey will provide a platform for the researchers working on Grüss-type inequalities to learn about the available work on the topic before developing the new results. Future research regarding this review paper is fascinating. Our review paper might inspire a good number of additional studies.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors extend their appreciation to the Deputyship for Research & Innovation, Ministry of Education in Saudi Arabia for funding this research work through the project no. (IFKSUOR3-340-1).

    The authors declare that they do not have conflict of interest regarding this manuscript.



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    1. HUI-YAN CHENG, IBRAHIM MEKAWY, JUAN WANG, HUMERA BATOOL, MUHAMMAD IMRAN QURESHI, ANALYSIS OF NEWTON AND HERMITE–HADAMARD-TYPE LOCAL FRACTIONAL INTEGRAL INEQUALITIES ON FRACTAL SETS USING GENERALIZED PRE-INVEXITY, 2025, 33, 0218-348X, 10.1142/S0218348X25401036
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