In this paper, we investigated the asymptotic symmetry and monotonicity of positive solutions to a reaction-diffusion equation in the unit ball, utilizing techniques from elliptic geometry. First, we discussed the properties of solutions in the elliptic space. Then, we established crucial principles, including the asymptotic narrow region principle. Finally, we employed the method of moving planes to demonstrate the asymptotic symmetry of the solutions.
Citation: Baiyu Liu, Wenlong Yang. Asymptotic symmetry of solutions for reaction-diffusion equations via elliptic geometry[J]. Communications in Analysis and Mechanics, 2025, 17(2): 341-364. doi: 10.3934/cam.2025014
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In this paper, we investigated the asymptotic symmetry and monotonicity of positive solutions to a reaction-diffusion equation in the unit ball, utilizing techniques from elliptic geometry. First, we discussed the properties of solutions in the elliptic space. Then, we established crucial principles, including the asymptotic narrow region principle. Finally, we employed the method of moving planes to demonstrate the asymptotic symmetry of the solutions.
In this paper, we investigate the asymptotic symmetry and monotonicity of positive solutions to the following reaction-diffusion equation:
{∂u∂t(x,t)−Δu(x,t)=f(|x|,u(x,t),t),(x,t)∈B1(0)×(0,∞),u(x,t)=0,(x,t)∈∂B1(0)×(0,∞), | (1.1) |
where B1(0) is the unit ball in RN, N⩾2.
Reaction-diffusion equations are fundamental mathematical models that describe how the concentration of substances evolves over time under the influence of both chemical reactions and diffusion. They are widely applied in fields such as biology for pattern formation, chemistry for reaction waves, ecology for population dynamics, neuroscience for modeling brain activity, and physics for phase transitions and material science [1,2]. These equations provide critical insights into self-organization in complex systems and form a theoretical basis for understanding various spatial structures and dynamic behaviors in nature. In terms of the application to the asymptotic symmetry of solutions, they also have been used in the proofs of convergence results for some autonomous and time-periodic equations [3].
For elliptic equations, the method of moving planes, initially introduced by Alexandrov [4] and Serrin [5], and later developed by Berestycki and Nirenberg [6], Gidas, Ni, and Nirenberg [7], and Chen and Li [8], among others, is a powerful tool for investigating the symmetry and monotonicity of solutions. In [7], Gidas, Ni, and Nirenberg proved that if for each u∈(0,∞), the function r↦f(r,u):(0,1)→R is non-increasing, then any positive C2(ˉBR(0)) solution of
{Δu+f(|x|,u)=0,x∈BR(0),u=0,x∈∂BR(0), | (1.2) |
is radially symmetric and decreasing in r. In recent years, several systematic approaches have emerged for studying symmetry and monotonicity in both local and nonlocal elliptic equations. These include the method of moving planes in integral form [9,10,11,12], the direct method of moving planes [13,14,15,16,17,18], the method of moving spheres [19,20,21,22,23], and sliding methods [6,24,25]. For further details on these methods, we refer to [26,27,28,29] and the references therein.
Notably, by combining hyperbolic geometry with the spirit of the moving plane method, a completely new monotonicity result can be achieved. Under the condition that (1−r2)(N+2)/2f(r,(1−r2)−(N−2)/2u) is decreasing in r∈(0,1), for a fixed u∈(0,∞), Naito, Nishimoto, and Suzuki have sequentially achieved that each positive solution of (1.2) is radially symmetric and (1−r2)−(N−2)/2u is decreasing in r∈(0,1) in the cases of N=2 [30] and N⩾2 [31]. In [32], using not only hyperbolic geometry but also elliptic geometry, Shioji and Watanabe established the symmetry and monotonicity properties of a wide class of strong solutions of (1.2).
As to the parabolic equations, the situation becomes significantly more intricate. There have been some preliminary studies of symmetric solutions of the periodic-parabolic problem [33,34,35] and further results concerning entire solutions where the time variable t∈R [36,37]. In a different type of symmetry considering the Cauchy-Dirichlet problem of reaction-diffusion equations, asymptotic symmetry shows a tendency of positive solutions to improve their symmetry as time variable t∈(0,∞) increases, becoming "symmetric and monotone in the limit" as t→∞. In this context, Li [38] obtained symmetry for positive solutions in the case that the initial solutions are symmetric. Without the symmetric initial solutions, in bounded, symmetric, and strictly convex domain Ω, Hess and Poláčik [39] showed the asymptotic symmetry and monotonicity of positive solutions to the following problem:
{∂tu=Δu(x,t)+f(u(x,t),t),(x,t)∈Ω×(0,∞),u(x,t)=0,(x,t)∈∂Ω×(0,∞). | (1.3) |
It was assumed in [39] that f is uniformly Lipschitz-continuous in u and Hölder-continuous of exponent (α,(α/2)) with respect to (u,t). Subsequently, in both bounded and unbounded domains, Poláčik [40,41] extended the result to the following generalized fully nonlinear parabolic equation:
{ut=F(t,x,u,Du,D2u),(x,t)∈Ω×(0,∞),u(x,t)=0,(x,t)∈∂Ω×(0,∞). | (1.4) |
In an independent work, Babin and Sell [42] gave a similar result. With the symmetry conclusion of entire solutions of (1.4), Poláčik [37] gave a survey that summarized the following limitations of existing asymptotic symmetry results: the regularity requirements of the time-dependence of the nonlinearities and domain, the compactness requirements of spatial derivatives, and the strong positivity requirements on the nonlinearities in the case of nonsmooth domains [43]. Moreover, Saldaña and Weth [44] established the asymptotic foliated Schwarz symmetry which indicates that all positive solutions of (1.1) become axially symmetric with respect to a common axis passing through the origin as t→∞.
The motivation for this paper is to extend the results of [30,31,32] to the framework of reaction-diffusion equations. Our approach, which integrates elliptic geometry with the method of moving planes, is inspired by the work of [45] and [32].
In order to clarify the theorem, we first introduce the ω-limit-set of u:
ω(u):={φ∈C0(¯B1(0))|∃tk→∞suchthatφ=limk→∞u(⋅,tk)}. | (1.5) |
By the discussion of u in the Appendix, the orbit {u(⋅,t):t>0} is relatively compact in C(¯B1(0)) and ω(u) is a nonempty compact subset of C(¯B1(0)).
From now on, we will assume the nonlinearity f:(0,1)×(0,∞)×[0,∞)→R satisfies
(F1) for each M>0, f(r,u,t) is Lipschitz-continuous in u uniformly with respect to t and r in the region (0,1)×[−M,M]×[0,∞);
(F2) for each r∈(0,1) and τ>0 there exist a constant H and a small constant ε0 both independent of τ such that
|f(r1,u,t1)−f(r2,u,t2)|⩽H(|r1−r2|α+|t1−t2|α2), |
for all u∈(0,∞) and (r1,t1),(r2,t2)∈(0,1)×[τ−ε0,τ+ε0];
(F3) for all t∈[0,∞) and each fixed u∈(0,∞), (1+r2)N+22f(r,(1+r2)−N−22u,t) is decreasing in r∈(0,1).
Theorem 1.1. Let f satisfy conditions (F1), (F2), and (F3). Assume u∈C2,1(B1(0)×(0,∞))∩C(¯B1(0)×[0,∞)) is a positive bounded solution of (1.1) satisfies that ∂u/∂t is non-negative, bounded, and ∇u(x,t) is bounded for all (x,t)∈B1(0)×(0,∞). Then for each φ(x)∈ω(u), the following holds:
● Either φ(x)≡0;
● Or φ(x) is radially symmetric about the origin and satisfies ∂r((1+|r|2)N−22φ(r))<0 for r=|x|∈(0,1), where x∈B1(0).
The structure of the paper is as follows: Section 2 presents the preliminary results that form the foundation for our main findings. In Section 3, we introduce the asymptotic narrow region principle, which plays a crucial role in the proof of our main theorem. The proof of Theorem 1.1 is provided in detail in Section 4. Finally, the Appendix includes additional properties of the solutions.
In this section, we will establish some essential preliminaries for applying the moving plane method in the space (B1(0),g), where the metric tensor g is defined by
4|dx|2(1+|x|2)2. | (2.1) |
Here, |⋅| denotes the standard Euclidean norm, consistent with the notation used in other sections. For each λ∈(0,1), let Tλ⊂B1(0) be a totally geodesic plane intersecting the x1-axis orthogonally at the point (λ,0,…,0). It follows that
Tλ={x∈B1(0):|x−eλ|=(1+λ22λ)}, | (2.2) |
where
eλ=((1−λ2−2λ),0,⋯,0). | (2.3) |
Define
Σλ={x∈B1(0) | |x−eλ|>(1+λ22λ)}. | (2.4) |
For each x∈Σλ, let xλ denote the reflection of x with respect to Tλ in the space (B1(0),g). This reflection can be expressed as
xλ=eλ+(1+λ22λ)2x−eλ|x−eλ|2. | (2.5) |
We remark that
|x|2>|xλ|2. | (2.6) |
The proof is presented in Lemma 5.1.
The Laplace-Beltrami operator Δ(g,x) in the space (B1(0),g) at x∈B1(0) is defined by
Δ(g,x)=(1+|x|22)2(Δ−2(N−2)1+|x|2N∑i=1xi∂∂xi), | (2.7) |
where Δ=∑Ni=1∂2∂x2i.
Let u(x,t) be a solution to the parabolic problem given by equation (1.1). For each λ∈(0,1), we introduce new functions v(x,t), wλ(x,t), and zλ(x,t) to compare the value of u(x,t) with u(xλ,t) and to simplify the analysis of the gradient's impact. These functions are defined as follows:
v(x,t)=(1+|x|2)N−22u(x,t),(x,t)∈B1(0)×(0,∞), | (2.8) |
wλ(x,t)=v(xλ,t)−v(x,t),(x,t)∈Σλ×(0,∞), | (2.9) |
zλ(x,t)=(1+|x|2)−N−22wλ(x,t),(x,t)∈Σλ×(0,∞). | (2.10) |
From (2.8)–(2.10), for (x,t)∈Σλ×(0,∞), we obtain
zλ(x,t)=(1+|x|2)−N−22((1+|xλ|2)N−22u(xλ,t)−(1+|x|2)N−22u(x,t))=(1+|xλ|21+|x|2)N−22u(xλ,t)−u(x,t). | (2.11) |
Clearly, zλ∈C2,1(Σλ×(0,∞))∩C(¯Σλ×[0,∞)]) and zλ=0 on Tλ. For each φ(x)∈ω(u), denote
ψλ(x)=(1+|x|2)−N−22((1+|xλ|2)N−22φ(xλ)−(1+|x|2)N−22φ(x))=(1+|xλ|21+|x|2)N−22φ(xλ)−φ(x), | (2.12) |
which is an ω-limit of zλ(x,t).
By virtue of the definitions given in (2.7) and (2.8), we observe that for x∈B1(0), the function v satisfies
Δ(g,x)v(x,t)=(1+|x|22)2(Δv(x,t)−2(N−2)1+|x|2N∑i=1xi∂v∂xi)=(1+|x|2)N+224Δu(x,t)+N(N−2)4(1+|x|2)N−22u(x,t)=(1+|x|2)N+224(∂u∂t−f(|x|,u(x,t),t))+N(N−2)4v(x,t)=(1+|x|22)2∂v∂t−(1+|x|2)N+224f(|x|,(1+|x|2)−N−22v(x,t),t)+N(N−2)4v(x,t). | (2.13) |
In addition to the above notations, we now present the following lemmas to establish the properties of zλ(x,t).
Lemma 2.1. Let u∈C2,1(B1(0)×(0,∞))∩C(¯B1(0)×[0,∞)) be a positive bounded solution of (1.1) that satisfies ∂u∂t(x,t)⩾0 for all (x,t)∈B1(0)×(0,∞). Assume that the function (1+r2)N+22f(r,(1+r2)−N−22s,t) is nonincreasing in r∈(0,1) for each fixed s∈(0,∞) and t∈(0,∞). Under these conditions, zλ satisfies
∂zλ∂t−Δzλ⩾cλ(x,t)zλ | (2.14) |
in Σλ×(0,∞), where
cλ(x,t)=f(|x|,(1+|x|2)−N−22v(xλ,t),t)−f(|x|,(1+|x|2)−N−22v(x,t),t)(1+|x|2)−N−22v(xλ,t)−(1+|x|2)−N−22v(x,t). | (2.15) |
Proof. Let λ∈(0,1), x∈Σλ, and set y=xλ. Since the Laplace-Beltrami operator is invariant under the isometry, as shown in Lemma 5.2 in the Appendix, we have
Δ(g,y)v(y,t)=Δ(g,x)v(xλ,t). | (2.16) |
Using this equality, together with (2.6) and the monotonicity assumption (F3) of (1+r2)N+22f(r,(1+r2)−N−22s,t), we deduce that
0=Δ(g,y)v(y,t)−N(N−2)4v(y,t)+(1+|y|2)N+224f(|y|,(1+|y|2)−N−22v(y,t),t)−(1+|y|22)2∂v(y,t)∂t−Δ(g,x)v(x,t)+N(N−2)4v(x,t)−(1+|x|2)N+224f(|x|,(1+|x|2)−N−22v(x,t),t)+(1+|x|22)2∂v(x,t)∂t=Δ(g,x)wλ(x,t)−N(N−2)4wλ(x,t)+(1+|xλ|2)N+224f(|xλ|,(1+|xλ|2)−N−22v(xλ,t),t)−(1+|x|2)N+224f(|x|,(1+|x|2)−N−22v(x,t),t)−(1+|x|22)2∂wλ(x,t)∂t+∂v(y,t)∂t((1+|x|22)−(1+|xλ|22))⩾Δ(g,x)wλ(x,t)−N(N−2)4wλ(x,t)−(1+|x|22)2∂wλ(x,t)∂t+(1+|x|2)N+224f(|x|,(1+|x|2)−N−22v(xλ,t),t)−(1+|x|2)N+224f(|x|,(1+|x|2)−N−22v(x,t),t)=Δ(g,x)wλ(x,t)−N(N−2)4wλ(x,t)+(1+|x|22)2cλ(x,t)wλ(x,t)−(1+|x|22)2∂wλ(x,t)∂t=(1+|x|22)2(−∂wλ(x,t)∂t+Δwλ−2(N−2)1+|x|2N∑i=1xi∂wλ∂xi−N(N−2)(1+|x|2)2wλ(x,t)+cλ(x,t)wλ(x,t)). |
Thus we obtain
∂wλ(x,t)∂t−Δwλ+2(N−2)1+|x|2N∑i=1xi∂wλ∂xi+N(N−2)(1+|x|2)2wλ(x,t)⩾cλ(x,t)wλ(x,t). | (2.17) |
From (2.10), an elementary computation shows that
∂wλ(x,t)∂t=(1+|x|2)N−22∂zλ∂t,Δzλ(x,t)=(Δ(1+|x|2)−N−22)wλ+2∇(1+|x|2)−N−22)⋅∇wλ+(1+|x|2)−N−22)Δwλ=(1+|x|2)−N−22(Δwλ−2(N−2)1+|x|2N∑i=1xi∂wλ∂xi−N(N−2)(1+|x|2)2wλ(x,t)). |
Therefore, zλ, as defined in (2.10), satisfies the inequality given in (2.14).
Lemma 2.2. Assume that for some (x0,t0)∈Tλ×(0,∞), there holds
∂zλ∂n(x0,t0)<0, |
where n denotes the unit outer normal to ∂Σλ. Then,
∂v∂n(x0,t0)>0. | (2.18) |
Proof. Since zλ(x,t)=0 on Tλ×(0,∞), we have
∂wλ∂n(x0,t0)=(1+|x0|2)N−22∂zλ∂n(x0,t0)<0. | (2.19) |
We define xp as xp=x0−pn(x0), p>0, and n(x0) is the unit outer normal to ∂Σλ at point x0. Specifically, n(x0)=−(x0−eλ)/|x0−eλ|.
For xp∈Σλ, using the definition in (2.5), we find that
xλp=xq=x0+qn(x0), |
where
q=(1+λ2)p1+λ2+2pλ>0. |
This result follows from the property given in (2.5) that
|xp−eλ|=1+λ22λ+p,|xq−eλ|=1+λ22λ−q,|xp−eλ||xq−eλ|=(1+λ22λ)2. |
Then, it follows that
∂wλ(x0,t)∂n=limp→0+wλ(xp,t)−wλ(x0,t)−p=limp→0+(v(xq,t)−v(x0,t)−p+v(xp,t)−v(x0,t)p)=limq→0+v(xq,t)−v(x0,t)−q(qp)+limp→0+v(xp,t)−v(x0,t)p=−2∂v(x0,t)∂n. |
From (2.19), we conclude that inequality (2.18) holds.
In this section, we present the following asymptotic narrow region principle, which will play a crucial role in establishing Theorem 1.1.
Lemma 3.1. (Asymptotic narrow region principle) Assume that Ω is a bounded narrow region with respect to eλ contained within the annulus defined by
{x∈B1(0) | 1+λ22λ<|x−eλ|<1+λ22λ+δ}, | (3.1) |
for some small δ>0, where eλ is defined by (2.3).
For sufficiently large ¯t, assume that zλ(x,t)∈C2(Ω)×C1([¯t,∞]) is bounded and lower semi-continuous in x on ¯Ω, and satisfies
{∂zλ(x,t)∂t−Δzλ(x,t)⩾cλ(x,t)zλ(x,t),(x,t)∈Ω×[¯t,∞),zλ(x,t)⩾0,(x,t)∈∂Ω×[¯t,∞), | (3.2) |
where cλ(x,t) is bounded from above. Then for sufficiently small δ the following statement holds:
lim_t→∞zλ(x,t)⩾0,∀x∈Ω. | (3.3) |
Proof. Let m be a fixed positive constant that will be determined later. Define
˜zλ(x,t)=emtzλ(x,t)ϕ(x). |
Then ˜zλ(x,t) satisfies
∂˜zλ(x,t)∂t=memtzλ(x,t)ϕ(x)+emtϕ(x)∂zλ(x,t)∂t, |
and
Δ˜zλ(x,t)=emt(Δzλ(x,t)ϕ(x)−2∇˜zλ(x,t)∇ϕ(x)ϕ(x)−Δϕ(x)ϕ(x)zλ(x,t)ϕ(x)). |
Thus, we find that
∂˜zλ(x,t)∂t−Δ˜zλ(x,t)−2emt∇˜zλ(x,t)∇ϕ(x)ϕ(x)⩾(cλ(x,t)+Δϕ(x)ϕ(x)+m)˜zλ(x,t). | (3.4) |
Let ϕ(x) be defined as
ϕ(x)=sin(|x−eλ|−1+λ22λδ+π2)=sin(√|x1−1−λ2−2λ|2+|x2|2+⋯+|xN|2−1+λ22λδ+π2). |
For each x∈Ω, we have
π2<|x−eλ|−1+λ22λδ+π2<1+π2<π. |
Direct calculation shows
Δϕ(x)=−1δ2sin(|x−eλ|−1+λ22λδ+π2)+cos(|x−eλ|−1+λ22λδ+π2)1|x−eλ|δ(n−1)<−1δ2sin(|x−eλ|−1+λ22λδ+π2). |
Thus,
Δϕ(x)ϕ(x)<−1δ2. | (3.5) |
We claim that for any T>¯t,
˜zλ(x,t)⩾min{0,infΩ˜zλ(x,¯t)},(x,t)∈Ω×[¯t,T]. | (3.6) |
If (3.6) is not true, by (3.2) and the lower semi-continuity of zλ on ¯Ω×[¯t,T], there exists (x0,t0) in Ω×(¯t,T] such that
˜zλ(x0,t0)=min¯Ω×(¯t,T]˜zλ(x,t)<min{0,infΩ˜zλ(x,˜t)}. | (3.7) |
Since
˜zλ(x,t)=0,(x,t)∈¯Ω∩Tλ, |
and
˜zλ(x,t)>0,(x,t)∈¯Ω∩∂B1(0), |
where Tλ is defined in (2.2), the minimum point x0 is an interior point of Ω. Therefore,
∂˜zλ(x0,t0)∂t⩽0, | (3.8) |
Δ˜zλ(x0,t0)⩾0, | (3.9) |
∇˜zλ(x0,t0)=0. | (3.10) |
From (3.4), (3.5), and (3.8)–(3.10), we have
0⩾∂˜zλ(x0,t0)∂t−Δ˜zλ(x0,t0)>(cλ(x0,t0)−1δ2+m)˜zλ(x0,t0). | (3.11) |
Since cλ(x,t) is bounded from above for all (x,t)∈B1(0)×(0,∞), we can choose δ small enough such that
cλ(x0,t0)−1δ2<−12δ2. |
Taking m=1/2δ2, we derive that the right-hand side of the second inequality of (3.11) is strictly greater than 0, since ˜zλ(x0,t0)<0. This contradicts with (3.11).
Therefore, given the boundedness of zλ, there exists a constant C>0 such that
˜zλ(x,t)⩾min{0,infΩ˜zλ(x,¯t)}⩾−C,(x,t)∈Ω×[¯t,T]. |
Thus, we have
zλ(x,t)⩾e−mt(−C),∀t>¯t. |
Taking the limit t→∞, we obtain
lim_t→∞zλ(x,t)⩾0,∀x∈Ω. |
This completes the proof of Lemma 3.1.
In the proof of the main theorem, we will also use the following two classical maximum principles. For the convenience of the reader, we now show them in the version suitable for this article.
Lemma 3.2. (Strong parabolic maximum principle for a not necessarily non-negative coefficient) For each λ∈(0,1), assume z(x,t)∈C2,1(Σλ×(0,∞))∩C(¯Σλ×[0,∞)) and for (x,t)×Σλ×(0,∞), z(x,t)⩾0 satisfies that
∂z(x,t)∂t−Δz(x,t)−c(x,t)z(x,t)⩾0, |
where c(x,t) is bounded in Σλ×(0,∞). If z(x,t) attains its minimum 0 over ¯Σλ×[0,∞) at a point (x0,t0)∈Σλ×(0,∞), then z(x,t)≡0 in Σλ×(0,t0].
Proof. For each λ∈(0,1), we set c0=supΣλ×(0,∞)c(x,t) and let
¯z(x,t)=e−c0tz(x,t), |
and then for (x,t)×Σλ×(0,∞), ¯z(x,t)=e−c0tz(x,t)⩾0 and satisfies that
∂¯z(x,t)∂t−Δ¯z(x,t)+(c0−c(x,t))¯z(x,t)=−c0e−c0tz(x,t)+e−c0t∂z(x,t)∂t−e−c0tΔz(x,t)+c0e−c0tz(x,t)−c(x,t)e−c0tz(x,t)=e−c0t(∂z(x,t)∂t−Δz(x,t)−c(x,t)z(x,t))⩾0. |
If z(x,t) attains its minimum 0 at (x0,t0), then ¯z(x,t) also gets its minimum 0 at the point (x0,t0) over ¯Σλ×[0,∞). Considering c0−c(x,t)⩾0 in Σλ×(0,∞), then from the strong parabolic maximum principle with c(x,t)⩾0 (Theorem 12 in [46], Chapter 7), we can obtain that for (x,t)∈Σλ×(0,t0], we have ¯z(x,t)≡0 and therefore z(x,t)=ec0t¯z(x,t)≡0.
Lemma 3.3 (Parabolic Hopf's lemma for a not necessarily non-negative coefficient). For each λ∈(0,1), we let (x0,t0) be a point on the boundary of Σλ×(0,T) for ∀T>0 such that z(x0,t0)=0 is the minimum in ¯Σλ×[0,T]. Assume that there exists a neighborhood V:=|x−x0|2+|t−t0|2<R20 of (x0,t0) such that for (x,t)∈V∩(Σλ×(0,T)), z(x,t)>0 and satisfies
∂z(x,t)∂t−Δz(x,t)−c(x,t)z(x,t)⩾0, |
where c(x,t) is bounded in Σλ×(0,T). If there exists a sphere S:=|x−x′|2+|t−t′|2<R passing through (x0,t0) and contained in ¯Σλ×[0,T] and (x0,t0)≠(x′,t′), then under the assumptions made above, we have
∂z∂n(x0,t0)<0, |
where n is the unit outer normal of ∂Σλ for the fixed t0.
Proof. For each λ∈(0,1), we set c0=supΣλ×(0,∞)c(x,t) and let
¯z(x,t)=e−c0tz(x,t). |
Then at the point (x0,t0), z(x,t) also gets its minimum 0 and for (x,t)∈V∩(Σλ×(0,T)), ¯z(x,t)>0 and satisfies that
∂¯z(x,t)∂t−Δ¯z(x,t)+(c0−c(x,t))¯z(x,t)⩾0. |
Considering (c0−c(x,t))⩾0 in σλ×(0,T), then from the parabolic Hopf's lemma (Theorem 2 in [47]), we can derive that every outer non-tangential derivative ∂¯z∖∂ν at (x0,t0) is negative, where ν represents any outer non-tangential vector. Particularly, by the definition of ¯z(x,t), for the fixed t0 and the unit outer normal n of ∂Σλ, we have ∂z∖∂n(x0,t0)=∂¯z∖∂n(x0,t0)<0.
We will carry out the proof in two steps. For simplicity, choose any direction within the region to be the x1 direction. The first step is to show that for λ sufficiently close to the right end of the domain, the following holds for all φ∈ω(u):
ψ(x)⩾0,∀x∈Σλ. | (4.1) |
This provides the initial position to move the plane. We then move the plane Tλ to the left as long as the inequality (4.1) continues to hold, until it reaches its limiting position. Define
λ0=inf{λ⩾0|ψμ(x)⩾0,for allφ∈ω(u),x∈Σμ,μ⩾λ}. | (4.2) |
We will show that λ0=0. Since the x1 direction can be chosen arbitrarily, this implies that for any φ∈ω(u), φ(x) is radially symmetric and (1+|x|2)N−22φ(x) is monotone decreasing about the origin. We will now detail these two steps.
Proof of Theorem 1.1. For all φ∈ω(u), we assume φ≢0 in B1(0).
Step 1. We show that for λ<1 and sufficiently close to 1, the following holds:
ψλ(x)⩾0,∀x∈Σλ,∀φ∈ω(u). | (4.3) |
The Lipschitz continuity assumption (F1) on f implies that cλ(x,t) is bounded. Additionally, we have
zλ(x,t)=(1+|xλ|21+|x|2)N−22u(xλ,t)−u(x,t)>0,(x,t)∈∂Σλ×(0,∞), |
since u(x,t)=0, for (x,t)∈∂B1(0)×(0,∞), and u is positive in B1(0). Combining this with (2.14), we can apply Lemma 3.1 to conclude that (4.3) holds.
Step 2. We will demonstrate that the parameter λ0, as defined in (4.2), is equal to zero, that is to say
λ0=0. | (4.4) |
Assume for contradiction that λ0>0. We will demonstrate that Tλ0 can be shifted slightly to the left, thereby contradicting the definition of λ0.
To begin with, we intend to determine the sign of ψλ0 for any φ∈ω(u) and all x∈Σλ0 under the case λ0>0. To achieve this, according to the definition (2.12), we now need to discuss the inequality that zλ0(x,t) satisfies as t→∞. From the definition of ω(u), for each φ∈ω(u), there exists a sequence {tk} such that u(x,tk)→φ(x) as tk→∞. Define
uk(x,t)=u(x,t+tk−1), | (4.5) |
and
fk(|x|,u,t)=f(|x|,u,t+tk−1). | (4.6) |
Then we have uk(x,1)→φ(x) in the sense of C(B1(0)) as k→∞. Let Q1:=B1(0)×[1−ε0,1+ε0]. We now have
{∂uk∂t(x,t)−Δuk(x,t)=fk(|x|,uk(x,t),t),(x,t)∈Q1,uk(x,t)=0,(x,t)∈∂B1(0)×[1−ε0,1+ε0]. | (4.7) |
Similarly as in (2.8)–(2.11), we have the following definitions of functions:
vk(x,t)=(1+|x|2)N−22uk(x,t), | (4.8) |
wλ0,k(x,t)=vk(xλ0,t)−vk(x,t), | (4.9) |
zλ0,k(x,t)=zλ0(x,t+tk−1)=(1+|xλ0|21+|x|2)N−22uk(xλ0,t)−uk(x,t). | (4.10) |
It follows from (4.7) and Lemma 2.1 that
∂zλ0,k∂t(x,t)−Δzλ0,k(x,t)⩾cλ0,k(x,t)zλ0,k(x,t),(x,t)∈Σλ0×[¯t,∞), |
where
cλ0,k(x,t)=cλ0(x,t+tk−1)=fk(|x|,(1+|x|2)−N−22vk(xλ0,t),t)−fk(|x|,(1+|x|2)−N−22vk(x,t),t)(1+|x|2)−N−22vk(xλ0,t)−(1+|x|2)−N−22vk(x,t). |
Based on the relationship between the functions (4.8)–(4.10) and uk defined as (4.5), using Lemma 5.3, we deduce the existence of subsequences vk, wλ0,k, and zλ0,k which converge uniformly to the respective functions v∞, wλ0,∞, and zλ0,∞ all in the sense of C2,1(Σλ0×[1−ε0,1+ε0]) as k→∞ and they satisfy
zλ0,∞(x,t)=(1+|x|2)−N−22wλ0,∞(x,t)=(1+|x|2)−N−22(v∞(xλ0,t)−v∞(x,t))=(1+|xλ0|21+|x|2)N−22u∞(xλ0,t)−u∞(x,t). |
Furthermore, both in the sense of C(Σλ0×[1−ε0,1+ε0]) as k→∞ we have
∂zλ0,k∂t(x,t)−Δzλ0,k(x,t)→∂zλ0,∞∂t(x,t)−Δzλ0,∞(x,t),cλ0,k(x,t)→cλ0,∞(x,t), |
where cλ0,∞(x,t) is bounded in Σλ0×[1−ε0,1+ε0]. This follows from the proof of Lemma 5.3, where it is established that the sequence fk within the definition of cλ0,k uniformly converges to f∞ satisfying (F1) in the sense of C(Σλ0×[1−ε0,1+ε0]). For any φ∈ω(u), by the definition of the limit set ω(u), there exists tk such that zλ0(x,tk)→ψλ0(x) in the sense of C(Σλ0) as tk→∞. Particularly, according to the convergence of zλ0,k, in the sense of C2(Σλ0) we have
zλ0(x,tk)=zλ0,k(x,1)→zλ0,∞(x,1)=ψλ0(x),ask→∞. | (4.11) |
Combining the continuity of zλ0,∞ with respect to t and the definition of λ0, we deduce that zλ0,∞(x,t) satisfies the following inequalities:
{∂zλ0,∞(x,t)∂t−Δzλ0,∞(x,t)⩾cλ0,∞(x,t)zλ0,∞(x,t),(x,t)∈Σλ0×[1−ε0,1+ε0],zλ0,∞(x,t)⩾0,(x,t)∈Σλ0×[1−ε0,1+ε0]. | (4.12) |
We apply Lemma 3.2 to (4.12) in Σλ0×[1−ε0,1+ε0] to get either
zλ0,∞(x,t)≡0for(x,t)∈Σλ0×[1−ε0,1+ε0], | (4.13) |
or
zλ0,∞(x,t)>0for(x,t)∈Σλ0×(1−ε0,1+ε0]. | (4.14) |
In case (4.13), since zλ0,∞(x,t)≡0, for all (x,t)∈Σλ0×[1−ε0,1+ε0], we have
wλ0,∞(x,t)≡0,i.e.,v∞(xλ0,t)≡v∞(x,t). | (4.15) |
From (2.13), for (x,t)∈Σλ0×(1−ε0,1+ε0], we have
Δ(g,x)v∞(x,t)=(1+|x|22)2∂v∞∂t(x,t)−(1+|x|2)N+224f∞(|x|,(1+|x|2)−N−22v∞(x,t),t)+N(N−2)4v∞(x,t), | (4.16) |
and
Δ(g,x)v∞(xλ0,t)=(1+|xλ0|22)2∂v∞∂t(xλ0,t)−(1+|xλ0|2)N+224f∞(|xλ0|,(1+|xλ0|2)−N−22v∞(xλ0,t),t)+N(N−2)4v∞(xλ0,t). | (4.17) |
By (4.15) we can obtain that
Δ(g,x)wλ0,∞(x,t)≡0,(1+|xλ|22)2∂wλ0,∞∂t(xλ,t)≡0,N(N−2)4wλ0,∞(x,t)≡0, |
for (x,t)∈Σλ0×[1−ε0,1+ε0]. Combining (4.16) and (4.17), we finally arrive at
(1+|x|2)N+22f∞(|x|,(1+|x|2)−N−22v∞(x,t),t)≡(1+|xλ0|2)N+22f∞(|xλ0|,(1+|xλ0|2)−N−22v∞(x,t),t), | (4.18) |
for (x,t)∈Σλ0×(1−ε0,1+ε0]. Since Lemma 5.1 implies that |x|>|xλ0|, (4.18) contradicts the assumption (F3) of f. It follows that case (4.13) is invalid.
Next from case (4.14), we can derive that for all φ∈ω(u),
zλ0,∞(x,1)=ψλ0(x)>0,x∈Σλ0. | (4.19) |
Since λ0>0, we now attempt to slightly shift λ0 to the left. If λ0 still meets definition (4.2), we can construct a contradiction. For any small l>0, we set ¯Vλ0+l=x∈{x∈¯B1(0)||x−eλ0|⩾1+λ202λ0+l}, and for ψλ0, there exists a Cφ>0, such that
ψλ0⩾Cφ>0,x∈¯Vλ0+l. | (4.20) |
We now show that, for all φ∈ω(u), there exists a universal constant C0 such that
ψλ0⩾C0>0,x∈¯Vλ0+l. | (4.21) |
If not, there exists a sequence of functions {ψkλ0} with respect to φk⊂ω(u) and a sequence of points {xk}⊂¯Vλ0+l such that for each k we have
ψkλ0(xk)<1k. | (4.22) |
By the compactness of ω(u) in C(¯B1(0)), there exists ψ0λ0 which corresponds to some φ0∈ω(u) and x0∈¯Vλ0+l such that
ψkλ0(xk)→ψ0λ0(x0), |
as k→∞ in the sense of C(B1(0)). Now by (4.22) and the definition of λ0, we obtain
ψ0λ0(x0)=0, |
which contradicts (4.19), since φ0∈ω(u). Thus (4.21) must be established.
From (4.21) and the continuity of ψλ with respect to λ, for each ψλ, under a fixed C0, there exists εφ>0 such that
ψλ(x)⩾C02>0,x∈¯Vλ0+l,∀λ∈(λ0−εφ,λ0). |
Similarly due to the compactness of ω(u) in C(¯B1(0)), for all ψλ, there exists a universal ε>0 such that
ψλ(x)⩾C02>0,x∈¯Vλ0+l,∀λ∈(λ0−ε,λ0). | (4.23) |
Consequently, for t sufficiently large, we have
zλ(x,t)⩾0,x∈¯Vλ0+l,∀λ∈(λ0−ε,λ0). |
Since l>0 is small, by (4.22), we can choose ε>0 small, such that Σλ∖Vλ0+l is a narrow region defined as (3.1) for λ∈(λ0−ε,λ0), and then applying the asymptotic narrow region principle (Lemma 3.1), we arrive at
ψλ(x)⩾0,∀x∈Σλ∖Vλ0+l. | (4.24) |
Combining (4.23) and (4.24), we derive that
ψλ(x)⩾0,∀x∈Σλ,∀λ∈(λ0−ε,λ0),∀φ∈ω(u). |
This contradicts the definition of λ0. Therefore, λ0=0 must be true.
As a result, (4.4) implies that for all φ∈ω(u),
ψ0(x)⩾0,∀x∈Σ0, |
that is to say, for all φ∈ω(u) and x∈Σ0,
z0(x,1)=(1+|x0|21+|x|2)N−22u∞(x0,1)−u∞(x,1)=(1+|x0|21+|x|2)N−22φ(x0)−φ(x)⩾0. |
Since x0=(−x1,x2,⋯,xN) for x∈Σ0 with 0<x1<1, finally we can get that
φ(−x1,x2,⋯,xN)⩾φ(x1,x2,⋯,xN). | (4.25) |
Since the x1 direction can be chosen arbitrarily, (4.25) implies that all φ(x) are radially symmetric about the origin. Combining with (4.12) and the proof of (4.19), we can derive that for 0<λ<1, zλ,∞ satisfies
{∂zλ,∞(x,t)∂t−Δzλ,∞(x,t)⩾cλ,∞(x,t)zλ,∞(x,t),(x,t)∈Σλ×[1−ε0,1+ε0],zλ,∞(x,t)=0,(x,t)∈Tλ×[1−ε0,1+ε0],zλ,∞(x,t)>0,(x,t)∈Σλ×[1−ε0,1+ε0], |
where cλ,∞ is bounded. Then we can apply Lemma 3.3 to obtain that
∂zλ,∞(x,1)∂n=∂ψλ(x)∂n<0,x∈Tλ,∀0<λ<1, |
where n is the outer normal vector of ∂¯Σλ. From Lemma 2.2, we can conclude that
∂[(1+|x|2)N−22φ(x)]∂n>0. | (4.26) |
Under the conclusion that all φ(x) are radially symmetric about the origin, from (4.26) we can infer that for all 0<r<1,
∂r((1+r2)N−22φ(r))<0, | (4.27) |
which shows asymptotic monotonicity. Now we complete the proof of Theorem 1.1.
We note that B1(0)={x∈RN:|x|<1}, N⩾3, we set S+={X∈RN+1:|X|=1,XN+1>0}, and define a mapping P:(S+,|dX|2)→(B1(0),g) by
P(X1,⋯,XN,XN+1)=1XN+1+1(X1,⋯,XN). |
The overall idea of the proof of (2.2)–(2.5) is similar to that in [32] in the case a=1, so we omit the proof process. Strongly inspired by Lemma A.1 and Lemma A.2 in [31], here we give the proof of (2.6) and (2.16).
Lemma 5.1. We have
1+|x|21+|xλ|2=(2λ1+λ2)2|x−eλ|2. | (5.1) |
Therefore, we can derive |x|>|xλ| for x∈Σλ.
Proof. We define a=−eλ/|eλ|2=(2λ/(1−λ2),0,⋯,0). From this definition, (2.3), and (2.5), by some elementary computations, we note that
aλ=eλ+(1+λ22λ)2a−eλ|a−eλ|2=0,|eλ|2+1=(1+λ22λ)2=1−λ22λ⋅(1+λ2)22λ(1−λ)2=|eλ||a−eλ|. |
Then we have
|xλ|2=|xλ−aλ|2=|(1+λ22λ)2(x−eλ|x−eλ|2−a−eλ|a−eλ|2)|2=(|eλ|2+1)2|x−eλ|x−eλ|2−a−eλ|a−eλ|2|2=(|eλ|2+1)2|x−a|2|x−eλ|2|a−eλ|2=|eλ|2|a−eλ|2|x−a|2|x−eλ|2|a−eλ|2=|eλ|2|x−a|2|x−eλ|2, |
where we use the property of distance operations that for p,q∈RN∖{0},
|p|p|2−q|q|2|=|p−q||p||q|. |
Thus we obtain
1+|xλ|2=1+|eλ|2|x−a|2|x−eλ|2=1+|eλ|2|x+eλ/|eλ|2|2|x−eλ|2=(|eλ|2+1)(1+|x|2)|x−eλ|2=(1+λ22λ)2(1+|x|2)|x−eλ|2, |
which implies (5.1). Due to the definition of Σλ, for x∈Σλ, we have
1+|x|21+|xλ|2=(2λ1+λ2)2|x−eλ|2>(2λ1+λ2)2(1+λ22λ)2=1, |
and then we can find that |x|>|xλ|.
Lemma 5.2. Assume that v(x)∈C2(B1(0)). Let y=xλ and v(y) is a function with y as the independent variable. We define vλ(x)=v(xλ) as a new form of the function with x as the independent variable. Then
Δ(g,x)vλ(x)=(1+|x|22)2(Δxvλ(x)−2(N−2)1+|x|2x⋅∇xvλ(x))=(1+|y|22)2(Δyv(y)−2(N−2)1+|y|2y⋅∇yv(y))|y=xλ=Δ(g,y)v(y)|y=xλ, | (5.2) |
where Δx=∑Ni=1∂2/∂x2i, x⋅∇x=∑Ni=1xi∂/∂xi, and Δ(g,x) are defined as in (2.7).
Proof. To compare the values of Δ(g,x)vλ(x) and Δ(g,y)v(y) through direct computation, we define u(y) and uλ(x) as
u(y)=(1+|y|2)−(N−2)/2v(y),uλ(x)=(1+|x|2)−(N−2)/2vλ(x). |
Then we can find that
14(1+|y|2)(N+2)/2Δyu(y)=(1+|y|22)2(Δyv−2(N−2)1+|y|2y⋅∇yv)−N(N−2)4v, | (5.3) |
14(1+|x|2)(N+2)/2Δxuλ(x)=(1+|x|22)2(Δxvλ−2(N−2)1+|x|2x⋅∇xvλ)−N(N−2)4vλ, | (5.4) |
u(y)=(1+|x|21+|y|2)(N−2)/2uλ(x). | (5.5) |
For simplicity, we define
X=x−eλ,Y=y−eλ,Uλ(X)=uλ(x),andU(Y)=u(y). | (5.6) |
By (2.5), (5.1), and (5.5), it follows that
Y=(1+λ22λ)2X|X|2,X=(1+λ22λ)2Y|Y|2, | (5.7) |
U(Y)=(2λ1+λ2)N−2|X|N−2Uλ(X). | (5.8) |
Then we can calculate that
∂Xj∂Yi|i=j=(1+λ22λ)2|Y|2−2Y2i|Y|4,∂Xj∂Yi|i≠j=(1+λ22λ)2−2YiYj|Y|4,∂U(Y)∂Yi=N∑j=1∂U(Y)∂Xj∂Xj∂Yi=(2λ1+λ2)N−2N∑j=1(∂|X|N−2∂XjUλ(X)+∂Uλ(X)∂Xj|X|N−2)∂Xj∂Yi,∂2U(Y)∂Y2i=N∑j=1(∂2U(Y)∂X2j(∂Xj∂Yi)2+∂U(Y)∂Xj∂2Xj∂Y2i)+N∑1⩽p≠q∂2U(Y)∂Xp∂Xq∂Xp∂Yi∂Xq∂Yi,∂2U(Y)∂X2j=(2λ1+λ2)N−2(∂2|X|N−2∂X2jUλ(X)+2∂|X|N−2∂X1∂Uλ(X)∂Xj+|X|N−2∂2Uλ(X)∂X2j),∂2U(Y)∂XpXq=(2λ1+λ2)N−2(∂2|X|N−2∂Xp∂XqUλ(X)+|X|N−2∂Uλ(X)∂Xp∂Xq)+(2λ1+λ2)N−2(∂|X|N−2∂Xp∂Uλ(X)∂Xq+∂|X|N−2∂Xq∂Uλ(X)∂Xp). |
Then we obtain
ΔYU(Y)=N∑i=1∂2U(Y)∂Y2i=(2λ1+λ2)N−2|X|N−2(N∑j=1∂2Uλ(X)∂X2jN∑i=1(∂Xj∂Yi)2+N∑1⩽p≠q∂2Uλ(X)∂Xp∂XqN∑i=1∂Xp∂Yi∂Xq∂Yi)+(2λ1+λ2)N−2N∑j=1∂Uλ(X)∂Xj(2∂|X|N−2∂XjN∑i=1(∂Xj∂Yi)2+|X|N−2N∑i=1∂2Xj∂Y2i)+(2λ1+λ2)N−2N∑j=1∂Uλ(X)∂Xj(N∑i⩽m≠j∂|X|N−2∂XmN∑i=1∂Xj∂Yi∂Xm∂Yi)+(2λ1+λ2)N−2Uλ(X)(N∑j=1∂2|X|N−2∂X2jN∑i=1(∂Xj∂Yi)2+N∑1⩽p≠q∂2|X|N−2∂Xp∂XqN∑i=1∂Xp∂Yi∂Xq∂Yi)+(2λ1+λ2)N−2Uλ(X)(N∑j=1∂|X|N−2∂XjN∑i=1∂2Xj∂Y2i). |
From (5.7) we also have
N∑i=1(∂Xj∂Yi)2=(1+λ22λ)41|Y|4=(1+λ22λ)4(2λ1+λ2)8|X|4=(2λ1+λ2)4|X|4,N∑i=1∂Xp∂Yi∂Xq∂Yi=0,2∂|X|N−2∂XjN∑i=1(∂Xj∂Yi)2+|X|N−2N∑i=1∂2Xj∂Y2i=0,N∑j=1∂2|X|N−2∂X2jN∑i=1(∂Xj∂Yi)2+N∑j=1∂|X|N−2∂XjN∑i=1∂2Xj∂Y2i=0. |
Through the above calculation process, we finally get that
ΔYU(Y)=(2λ1+λ2)N−2|X|N−2(N∑j=1∂2Uλ(X)∂X2jN∑i=1(∂Xj∂Yi)2)=(2λ1+λ2)N+2|X|N+2ΔXUλ(X). | (5.9) |
By (5.6), for each i, we have
∂Uλ(X)∂Xi=∂uλ(x)∂xi∂xi∂Xi=∂uλ(x)∂xi,∂2Uλ(X)∂X2i=∂(∂Uλ(X)∂Xi)∂Xi=∂(∂uλ(x)∂xi)∂xi∂xi∂Xi=∂2uλ(x)∂x2i,∂U(Y)∂Yi=∂u(y)∂yi∂yi∂Yi=∂u(y)∂yi,∂2U(U)∂Y2i=∂(∂U(Y)∂Yi)∂Yi=∂(∂u(y)∂yi)∂yi∂yi∂Yi=∂2u(y)∂y2i. |
Then (5.9) implies
Δyu=(2λ1+λ2)N+2|x−eλ|N+2Δxuλ. |
By (5.1), we have
(1+|y|2)N+22Δyu=(1+|x|2)N+22Δxuλ. |
From (5.3) and (5.4), we can conclude that (5.2) holds.
For each fixed τ>0 and 0<α<1, we define the parabolic cylinder Qτ:=B1(0)×[τ−ε0,τ+ε0], where ε0 is a small constant. For any points (x,t),(˜x,˜t)∈Qτ, since u(x,t)∈C2,1(Qτ), there exist two constants ξt∈(min{t,˜t},max{t,˜t}), ξx∈(0,1), such that
|u(x,t)−u(˜x,˜t)||x−˜x|α+|t−˜t|α2=|u(x,t)−u(x,˜t)+u(x,˜t)−u(˜x,˜t)||x−˜x|α+|t−˜t|α2⩽|u(x,t)−u(x,˜t)|+|u(x,˜t)−u(˜x,˜t)||x−˜x|α+|t−˜t|α2<|ut(x,ξt)||t−˜t|1−α2+|∇u(x+ξx(˜x−x),t)||x−˜x|1−α. |
Again by u(x,t)∈C2,1(Qτ) and the boundedness of Qτ, we have |ut(x,ξt)|, |∇u(x+ξx(˜x−x),t)|, |t−˜t|1−α2, and |x−˜x|1−α are all bounded. Then for some 0<α<1, there exists a constant C0>0 such that
u(x,t)−u(˜x,˜t)⩽C0(|x−˜x|α+|t−˜t|α2). | (5.10) |
Combining (5.10) with the boundedness of u(x,t) in Qτ, for any τ>0, the orbit {u(⋅,t),t∈[τ−ε0,τ+ε0]} is relatively compact in C(B1(0)). To directly address the properties of the functions in ω(u), we present the following lemma.
Lemma 5.3. Let M:=sup{‖u(⋅,t)‖L∞:t>0}, and then, under definitions (4.5) and (4.6), for each k, uk and fk satisfy the problem (4.7).
Then there exist some functions u∞∈C2,1(B1(0)×[1−ε0,1+ε0]) and f∞∈C((0,1)×[−M,M]×[1−ε0,1+ε0]) such that uk→u∞ in the sense of C2,1(B1(0)×[1−ε0,1+ε0]) and fk→f∞ as k→∞ in the sense of C((0,1)×[−M,M]×[1−ε0,1+ε0]). With a constant ε0, u∞(x,t) satisfies
{∂u∞∂t−Δu∞=f∞(|x|,u∞(x,t),t),(x,t)∈B1(0)×[1−ε0,1+ε0],u∞=0,(x,t)∈∂B1(0)×[1−ε0,1+ε0]. | (5.11) |
Proof. For each K and any (x,t),(u,˜u),(˜x,˜t) in the bounded domain Qu:=(0,1)×[−M,M]×[1−ε0,1+ε0], by (5.13) and definition (4.6), we set C′ to be the maximum of Cu, Cx, and Ct appearing in (5.13), with any ε>0, if ||x|−|˜x||α+|u−˜u|+|t−˜t|α2<δ(ε)=ε∖C′, and then we have
|fk(|x|,u(x,t),t)−fk(|˜x|,u(˜x,˜t),˜t)|⩽C′(|x−˜x|α+|u−˜u|+|t−˜t|α2)<C′⋅εC′=ε, |
which means the sequence {fk}k∈N is equicontinuous in Qu. In addition, owing to the boundedness of Qu and the continuity of f in Qu, we deduce that {fk}k∈N is bounded in Qu for each k. Then the Ascoli-Azela theorem implies that there exists a function f∞∈C(Qu) such that fk→f∞ in the sense of C(Qu) as k→∞, and f∞ is Lipschitz continuous in u by (F1).
Next we discuss the convergence of {uk}k∈N. Set Q1:=B1(0)×[1−ε0,1+ε0], and from (4.7), for each k, let ˜fk(x,t)=fk(|x|,uk(x,t),t). Then we have
∂uk(x,t)∂t−Δuk(x,t)=˜fk(x,t),(x,t)∈Q1. | (5.12) |
Additionally, for any (x,t),(˜x,˜t)∈Q1, by conditions (F1) and (F2), we have three constants Cx, Cu, and Ct such that
|~fk(x,t)−~fk(˜x,˜t)=|fk(|x|,uk(x,t),t)−fk(|˜x|,uk(˜x,˜t),˜t)|⩽|f(|x|,uk(x,t),t)−f(|˜x|,uk(x,t),t)|+|f(|˜x|,uk(x,t),t)−f(|˜x|,uk(˜x,˜t),t)|+|f(|˜x|,uk(˜x,˜t),t)−f(|˜x|,uk(˜x,˜t),˜t)|⩽Cx|x−˜x|α+Cu|uk(x,t)−uk(˜x,˜t)|+Ct|t−˜t|α2. | (5.13) |
By (5.10), we set C=max{Cx,CuC0,Ct}, and then for any (x,t),(˜x,˜t)∈Q1, we have
|~fk(x,t)−~fk(˜x,˜t)|⩽C(|x−˜x|α+|t−˜t|α2), | (5.14) |
which means for any two points P(x,t) and ˜P(˜x,˜t), we define d(P,˜P)=(|x−˜x|+|t−˜t|12), and then we can get that
supP,˜P∈Q1P≠˜P|˜fk(P)−˜fk(˜P)|dα(P,˜P)<+∞. | (5.15) |
Given that uk is the solution of (4.7), then the existence and uniqueness theorem of classical solutions for heat equations (Theorem 3.3.7 in [48]) implies that
|uk|2+α,1+α2;Q1:=supP∈Q1|uk(P)|+supP∈Q1|Duk(P)|+supP∈Q1|D2uk(P)|+supP∈Q1|∂uk∂t(P)|+supP,˜P∈Q1P≠˜P|uk(P)−uk(˜P)|dα(P,˜P)+supP,˜P∈Q1P≠˜P|Duk(P)−Duk(˜P)|dα(P,˜P)+supP,˜P∈Q1P≠˜P|D2uk(P)−D2uk(˜P)|dα(P,˜P)+supP,˜P∈Q1P≠˜P|∂uk∂t(P)−∂uk∂t(˜P)|dα(P,˜P)⩽C<+∞, | (5.16) |
where C is a constant independent of k, Duk=(∂uk/∂x1,∂uk/∂x2,⋯,∂uk/∂xN), and D2uk is the Hessian matrix of uk. On the one hand (5.16) shows the equicontinuity of uk, Duk, D2uk, and ∂uk/∂t in C(Q1), which means for a given ε>0, we can choose δ>0 independent of k such that
|uk(P)−uk(˜P)|+|∂uk∂t(P)−∂uk∂t(˜P)|+|Duk(P)−Duk(˜P)|+|D2uk(P)−D2uk(˜P)|⩽Cδα<ε, |
for all P,˜P∈Q1 and k. On the other hand (5.16) also ensures that for each k, uk, Duk, D2uk, and ∂uk/∂t are all bounded in Q1. By the Ascoli-Azela theorem, there exist functions u∞, ut∞, {ui∞}Ni=1, {uij∞}Ni,j=1∈C(Q1) such that as k→∞ for each i and j we have
uk→u∞,∂uk∂t→ut∞,∂uk∂xi→ui∞,∂uk∂xi∂xj→uij∞, |
which are all in the sense of C(Q1). Employing the fundamental theorem of caculus and (5.16), for ε>0, (x,t)∈Q1, and fixed i, we can choose ¯δ=min(δ,1)>0 independent of k such that B¯δ(x)×[1−ε0,1+ε0]∈Q1 and for all |h|<¯δ and k we have
|∂uk∂xi(x1,⋯,xj+h,⋯,xN,t)−∂uk∂xi(x1,⋯,xj,⋯,xN,t)−∂2uk∂xi∂xj(x,t)h|=|∫10∂2uk∂xi∂xj(x1,⋯,xj+sh,⋯,xN,t)hds−∂2uk∂xi∂xj(x,t)h|⩽∫10|∂2uk∂xi∂xj(x1,⋯,xj+sh,⋯,xN,t)−∂2uk∂xi∂xj(x,t)||h|ds⩽|h|1+αC<Cδα|h|<ε|h|. |
Similarly we can get that
|uk(x1,⋯,xi+h,⋯,xN,t)−uk(x,t)−∂uk∂xi(x,t)h|⩽supQ1|D2uk||h|1+α⩽C|h|1+α<ε|h|,|uk(x,t+h)−uk(x,t)−∂uk(x,t)∂th|⩽∫10|∂uk∂t(x,t+sh)−∂uk∂t(x,t)||h|ds<ε|h|. |
Letting k→∞, we can derive that
|ui∞(x1,⋯,xj+hj,⋯,xN,t)−ui∞(x1,⋯,xj,⋯,xN,t)−uij∞(x,t)h|<ε|h|,|u∞(x1,⋯,xi+hi,⋯,xN,t)−u∞(x1,⋯,xi,⋯,xN,t)−ui∞(x,t)h|<ε|h|,|u∞(x,t+h)−u∞(x,t)−ut∞h|<ε|h|. | (5.17) |
Then (5.17) means that for each i and j,
uij∞=∂2u∞∂xi∂xj,ui∞=∂u∞∂xi,ut∞=∂u∞∂t, | (5.18) |
as h→0. The above discussion shows that u∞∈C2,1(Q1) and as k→∞ we observe that uk→u∞ in the sense of C2,1(Q1) and
∂uk∂t→∂u∞∂t,Duk→Du∞,D2uk→D2u∞, | (5.19) |
all in the sense of C(Q1). By (5.19) and the existence of u∞ and f∞, considering the problem (4.7) as k→∞, we can deduce that u∞ satisfies
{∂u∞∂t(x,t)−Δu∞(x,t)=f∞(|x|,u∞(x,t),t),(x,t)∈B1(0)×[1−ε0,1+ε0],u∞(x,t)=0,(x,t)∈∂B1(0)×[1−ε0,1+ε0]. |
Then we complete the proof of Lemma 5.3.
Baiyu Liu: Methodology, writing–review and editing; Wenlong Yang: Writing–original draft preparation.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors wish to thank the handing editor and the referees for their valuable comments and suggestions. Baiyu Liu is supported by the National Natural Science Foundation of China (No. 12471089).
The authors declare there is no conflict of interest.
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