Citation: Jonas Schnitzer. No-go theorems for r-matrices in symplectic geometry[J]. Communications in Analysis and Mechanics, 2024, 16(3): 448-456. doi: 10.3934/cam.2024021
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The study of solutions to superlinear problems driven by the double phase operator is a new and important topic, since it sheds light on a range of applications in the field of mathematical physics such as elasticity theory, strongly anisotropic materials, Lavrentiev's phenomenon, etc. (see [1,2,3]).
In the present paper, we study the existence and multiplicity of solutions for the following double–phase problems with mixed boundary conditions:
{D(u)+|u|p(x)−2u+b(x)|u|q(x)−2u=f(x,u) in Ω,u=0 on Λ1,(|∇u|p(x)−2u+b(x)|∇u|q(x)−2u)⋅ν=g(x,u) on Λ2, | (1.1) |
where Ω⊂RN(N≥2) is a bounded domain with Lipschitz boundary ∂Ω, Λ1,Λ2 are disjoint open subsets of ∂Ω such that ∂Ω=¯Λ1∪¯Λ2 and Λ1≠∅, 1<p(x)<q(x)<N for all x∈¯Ω, b:¯Ω↦[0,+∞) is Lipschitz continuous, ν denotes the outer unit normal of Ω at the point x∈Λ2, f:Ω×R→R and g:Λ2×R→R are Carathéodory functions, and D is the double phase variable exponents operator given by
D(u):=div(|∇u|p(x)−2∇u+b(x)|∇u|q(x)−2∇u), for u∈W1,D(Ω). | (1.2) |
Note that the differential operator defined above in (1.2) is called the double phase operator with variable exponents, which is a natural generalization of the classical double phase operator when p and q are constant functions
u↦div(|∇u|p−2∇u+b(x)|∇u|q−2∇u). |
From the physical point of view, while studying the behavior of strongly anisotropic materials, V.V. Zhikov [2] in 1986 discovered that their hardening properties changed radically point by point, what is known as the Lavrentiev phenomenon [3]. To describe this phenomenon, he initially introduced the functional
v⟼∫Ω(|∇v|p+b(x)|∇v|q)dx, | (1.3) |
where the integrand changes its ellipticity and growth properties according to the point in the domain. In the framework of mathematics, the functional (1.3) has been investigated by many authors with respect to regularity and nonstandard growth. For instance, we refer to the papers of P. Baroni et al. [4,5], P. Baroni et al. [6], G. Cupini [7], and the references therein.
Multiple authors have recently concentrated on the study of double phase problems in the case when the exponents p and q are constants, and a plethora of results have been obtained; see, for example, W. Liu and G. Dai [8], M. El Ahmadi et al. [9], L. Gasiński and P. Winkert [10], N. Cui and H.R. Sun [11], Y. Yang et al. [12], and the references therein. For example, N. Cui and H.R. Sun [11] considered the following problem in the particular case: p(x)=p, q(x)=q, and λ=1
{D(u)+|u|p−2u+b(x)|u|q−2u=f(x,u) in Ω,(|∇u|p−2u+b(x)|∇u|q−2u)⋅ν=g(x,u) on ∂Ω, |
where D(u):=div(|∇u|p−2∇u+b(x)|∇u|q−2∇u). The authors have proved the existence and multiplicity of nontrivial weak solutions for the above problem with superlinear nonlinearity. Their approach was based on critical point theory with Cerami condition.
Very recently, Y. Yang et al. [12] considered the problem (1.1) in the particular case of p(x)=p and q(x)=q. Based on the maximum principle and homological local linking, they proved the existence of at least two bounded nontrivial weak solutions.
The main novelty of the current paper is the combination of the double phase variable exponents operator with mixed boundary conditions, that is, the Dirichlet condition on Λ1 and the Steklov condition on Λ2, which is different from [13]. To the best of our knowledge, there are only a few results related to the study of such problems.
To state our results, we make the subsequent hypotheses on f and g:
(H0) There exist C1,C2>0, s1∈C+(Ω), and s2∈C+(Λ2) such that
(ⅰ) |f(x,t)|≤C1(1+|t|s1(x)−1) for all (x,t)∈Ω×R,
(ⅱ) |g(x,t)|≤C2(1+|t|s2(x)−1) for all (x,t)∈Λ2×R.
(H1) (ⅰ) 1<p+≤q+<s−1≤s+1<p∗(x) for all x∈Ω, $
(ⅱ) 1<p+≤q+<s−2≤s+2<p∗(x) for all x∈Λ2,
where
p∗(x):={Np(x)N−p(x) if p(x)<N,∞ if p(x)≥N,p∗(x):={(N−1)p(x)N−p(x) if p(x)<N,∞ if p(x)≥N.. |
(H2) (ⅰ) lim inf|t|→∞F(x,t)|t|q+=+∞ uniformly a.e. x∈Ω,
(ⅱ) lim inf|t|→∞G(x,t)|t|q+=+∞ uniformly a.e. x∈Λ2,
where F(x,t)=∫t0f(x,s)ds and G(x,t)=∫t0g(x,s)ds.
(H3) (ⅰ) There exist c1,r1≥0 and l1∈L∞(Ω) with l1(x)>Np− such as
|F(x,t)|l(x)≤c1|t|l(x)p−F(x,t), |
for all (x,t)∈Ω×R, |t|≥r1 and F(x,t):=1q+f(x,t)t−F(x,t)≥0.
(ⅱ) There exist c2,r2≥0 and l2∈L∞(Λ2) with l2(x)>N−1p−−1 such as
|G(x,t)|l(x)≤c2|t|l(x)p−G(x,t), |
for all (x,t)∈Λ2×R, |t|≥r2 and G(x,t):=1q+g(x,t)t−G(x,t)≥0.
(H4) (ⅰ) f(x,t)=∘(|t|p+−1) as t→0 uniformly for a.e. x∈Ω,
(ⅱ) g(x,t)=∘(|t|p+−1) as t→0 uniformly for a.e. x∈Λ2.
(H5) (ⅰ) f(x,−t)=−f(x,t) for all (x,t)∈Ω×R,
(ⅱ) g(x,−t)=−g(x,t) for all (x,t)∈Λ2×R.
Let us consider ϕ:X0→R the Euler functional corresponding to problem (1.1), which is defined as follows:
ϕ(u)=I(u)−φ(u), |
where
I(u)=∫Ω(1p(x)|∇u|p(x)+b(x)q(x)|∇u|q(x))dx+∫Ω(1p(x)|u|p(x)+b(x)q(x)|u|q(x))dx, |
and
φ(u)=∫ΩF(x,u)dx+∫Λ2G(x,u)dσ, |
with X0 will be defined in preliminaries and dσ is the measure on the boundary.
Then, it follows from the hypothesis (H0) that the functional ϕ∈C1(X0,R), and its Fréchet derivative is
⟨ϕ′(u),v⟩=∫Ω(|∇u|p(x)−2+b(x)|∇u|q(x)−2)∇u.∇v dx+∫Ω(|u|p(x)−2+b(x)|u|q(x)−2)u.v dx−∫Ωf(x,u)vdx−∫Λ2g(x,u)vdσ, |
for any u,v∈X0. It is clear that any critical point of ϕ is a weak solution to the problem (1.1).
Now, we present the main results of this paper.
Theorem 1. Suppose that (H0),(H1),(H2),(H3) and (H4) hold. Then problem (1.1) has at least one nontrivial weak solution.
Theorem 2. Suppose that (H0),(H1),(H2),(H3) and (H5) hold. Then problem (1.1) possesses a sequence of weak solutions (un) such that ϕ(un)→+∞ as n→+∞.
To study double phase problems, we need some definitions and basic properties of W1,D(Ω), which are called Musielak–Orlicz–Sobolev spaces. For more details, see [14,15,16,17,18,19] and references therein.
First, we recall the definition of variable exponent Lebesgue space. For p∈C+(¯Ω):={p∈C(¯Ω):p−:=infx∈¯Ωp(x)>1}, we designate the variable exponent Lebesgue space by
Lp(x)(Ω)={u:Ω→R is measurable and ∫Ω|u(x)|p(x)dx<+∞}, |
equipped with the Luxemburg norm
|u|p(x)=inf{μ>0:∫Ω|u(x)μ|p(x)dx≤1}. |
Proposition 1. [20]
1. The Sobolev space (Lp(x)(Ω),|.|p(x)) is defined as the dual space Lq(x)(Ω), where q(x) is conjugate to p(x), i.e., 1p(x)+1q(x)=1. For any u∈Lp(x)(Ω) and v∈Lq(x)(Ω), we have
|∫Ωuv dx|≤(1p−+1q−)|u|p(x)|v|q(x)≤2|u|p(x)|v|q(x). |
2. If p1,p2∈C+(¯Ω), p1(x)≤p2(x), for all x∈¯Ω, then Lp2(x)(Ω)↪Lp1(x)(Ω) and the embedding is continuous.
Let p∈C+(∂Ω):={p∈C(∂Ω):p−:=infx∈∂Ωp(x)>1} and denote by dσ the Lebesgue measure on the boundary. We define
Lp(x)(∂Ω)={u:∂Ω→R is measurable and ∫∂Ω|u|p(x)dσ<+∞}, |
with the norm
|u|p(x),∂Ω=inf{α>0:∫∂Ω|u(x)α|q(x)dσ≤1}. |
Now, we give the main properties of the Musielak–Orlicz–Sobolev functional space that we will use in the rest of this paper. Denote by N(Ω) the set of all generalized N-functions. Let us denote by
D:Ω×[0,+∞)→[0,+∞) |
the function defined as
D(x,t)=tp(x)+b(x)tq(x), for all (x,t)∈Ω×[0,+∞), |
where the weight function b(.) and the variable exponents p(.),q(.)∈C+(¯Ω) satisfies the following hypothesis:
p(x)<q(x)<N,Nq(x)N+q(x)−1<p(x) for all x∈¯Ω and 0≤b(.)∈L∞(Ω). | (2.1) |
Note that the role of assuming the inequality Nq(x)N+q(x)−1<p(x) is to ensure that q(x)<p∗(x) and q(x)<p∗(x) for all x∈¯Ω, where p∗(x)=Np(x)N−p(x) and p∗(x)=(N−1)p(x)N−p(x).
It is clear that D is a generalized N-function, locally integrable, and
D(x,2t)≤2q+D(x,t), for all (x,t)∈Ω×[0,+∞), |
which is called condition (Δ2).
We designate the Musielak–Orlicz space by
LD(Ω)={u:Ω→R is measurable and ∫ΩD(x,|u|)dx<+∞}, |
equipped with the so-called Luxemburg norm
|u|D=inf{μ>0:∫ΩD(x,|uμ|)dx≤1}. |
The Musielak–Orlicz–Sobolev space W1,D(Ω) is defined as
W1,D(Ω)={u∈LD(Ω):|∇u|∈LD(Ω)}, |
endowed with the norm
∥u∥1,D=|u|D+|∇u|D. |
With such norms, LD(Ω) and W1,D(Ω) are separable, uniformly convex, and reflexive Banach spaces.
On LD(Ω), we consider the function ρ:LD(Ω)→R defined by
ρ(u)=∫Ω(|u|p(x)+b(x)|u|q(x))dx. |
The relationship between ρ and |.|D is established by the next result.
Proposition 2. (see [16]) For u∈LD(Ω), (un)⊂LD(Ω), and μ>0, we have
1. For u≠0, |u|D=μ⟺ρ(uμ)=1;
2. |u|D<1(=1,>1)⟺ρ(u)<1(=1,>1);
3. |u|D>1⟹|u|p−D≤ρ(u)≤|u|q+D;
4. |u|D<1⟹|u|q+D≤ρ(u)≤|u|p−D;
5. limn→+∞|un|D=0⇔limn→+∞ρ(un)=0 and limn→+∞|un|D=+∞⇔limn→+∞ρ(un)=+∞.
On W1,D(Ω), we introduce the equivalent norm by
‖ | (2.2) |
Similar to Proposition (2), we have
Proposition 3. (see [16]) Let
For , , and , we have
1. For ,
2.
3.
4.
5. and .
We recall that problem (1.1) has a mixed boundary condition. For this, our Banach space workspace is given by
endowed with the equivalent norm (2.2). Obviously, since is a closed subspace of , then is a reflexive Banach space.
Proposition 4. (see [16]) Let hypothesis (2.1) be satisfied. Then the following embeddings hold:
1. There is a continuous embedding for with for all .
2. There is a compact embedding for with for all .
3. If Then, there is a continuous embedding for with for all .
4. There is a compact embedding for with for all .
It is important to note that when we replace by in Proposition 4, the embeddings 2 and 4 remain valid.
Let be defined by
for all , where denotes the dual space of and stands for the duality pairing between and .
Proposition 5. (see [16,Proposition 3.4]) Let hypothesis (2.1) be satisfied.
1. is a continuous, bounded, and strictly monotone operator.
2. satisfies the -property, i.e., if in and , then in .
Definition 1. Let . We say that is a weak solution to the problem (1.1) if
for all .
Now, we give the definition of the Cerami condition that was first introduced by G. Cerami in [21].
Definition 2. Let be a real Banach space and . We say that satisfies the Cerami condition (we denote condition) in , if any sequence such that is bounded and as has a strong convergent subsequence in .
Remark 1. 1. It is clear from the above definition that if satisfies the -condition, then it satisfies the -condition. However, there are functionals that satisfy the -condition but do not satisfy the -condition (see [21]). Consequently, the -condition implies the -condition.
2. The -condition and the -condition are equivalent if is bounded below (see [22]).
Next, we present the following theorems, which will play a fundamental role in the proof of the main theorems.
Theorem 3. (see [23]) Let be a real Banach space; satisfies the -condition; , and the following conditions hold:
1. There exist positive constants and such that for any with .
2. There exists a function such that and
Then, the functional has a critical value , that is, there exists such that and in .
Let be a real, reflexive, and separable Banach space. Then there exist and such that
and if , if .
We denote , , and .
Theorem 4. (see [24]) Assume that is a Banach space, and let be an even functional of class that satisfies the condition. For every , there exists such that
as ;
.
Then, has a sequence of critical values tending to
First of all, we are going to show that the functional fulfills the -condition.
Lemma 3.1. If assumptions and hold, then the functional satisfies the -condition.
Proof. Let be a Cerami sequence for , namely,
(3.1) |
which implies that
(3.2) |
where and .
We need to prove the boundedness of the sequence in . To this end, assume to the contrary, that the sequence is unbounded in . Without loss of generality, we can assume that . By virtue of , for large enough, we have
where and .
Then, we obtain
which implies
(3.3) |
and
(3.4) |
On the other hand, by Proposition 3, we have
Because , we can obtain
(3.5) |
Since as , we deduce that
(3.6) |
Furthermore, using Proposition 3, we have
Then, we obtain
(3.7) |
In view of condition , there exist such that
Since and are continuous functions on and , respectively, there exist such that
Then, there exist two real numbers and , such that
Hence,
(3.8) |
for all .
Put , so . Up to subsequences, for some , we have
(3.9) |
for and .
Define the sets and .
Obviously, since as , we have
for any .
Therefore, due to , for all , we deduce
(3.10) |
Thus, and . In fact, suppose by contradiction that or . Using (3.6), (3.7), (3.10), and Fatou's lemma, we get
which is a contradiction. Therefore, for a.e. and for a.e. .
From (3.5) and (3.9), respectively, we can deduce that
(3.11) |
for , , and
(3.12) |
Using and , we obtain
(3.13) |
where , is either or and comes from .
Put . Since with , it follows that
On the other hand, by virtue of hypothesis , (3.3), and (3.11), we deduce
Combining this with (3.13), we obtain
(3.14) |
Similarly, let . Since with , it follows that Then, by , (3.4), and (3.11), we can prove in a similar way that
(3.15) |
Consequently, combining (3.14) with (3.15), we obtain
which is a contradiction to (3.12). Thus, is bounded in .
Finally, we need to prove that any -sequence has a convergent subsequence. Let be a -sequence. Then, is bounded in . Passing to the limit, if necessary, to a subsequence, from Proposition 4, we have
(3.16) |
for and . It is easy to check from , (3.16) and Hölder's inequality that
(3.17) |
and
(3.18) |
where and .
Next, since , from (3.1), we have
(3.19) |
Then
where is given in Proposition 5.
Finally, the combination of (3.17), (3.18), and (3.19) implies
Since the operator satisfies the property in view of Proposition 5, we can obtain that in . The proof is complete.
Proof of Theorem 1
Let us check that the functional satisfies the geometric conditions of the mountain pass in Theorem 3. By Lemma 3.1, satisfies the condition. According to the definition of , we have . Then, to apply Theorem 3, it remains to prove that
(ⅰ) There exist positive constants and such that for any with .
(ⅱ) There exists a function such that and
For , let . Then, by Proposition 3, we have
(3.20) |
Using and , for be small enough, there exist such that
(3.21) |
Since and for all and for all in view of condition , we have from Proposition 4 that
So, there exist such that
Therefore, by (3.20) and (3.21), for sufficiently small, we obtain
Since in view of condition and , then . Thus, we obtain
Since , then by the standard argument, there exist positive constants and such that for any with .
Next, we affirm that there exists with such that
(3.22) |
In fact, from , it follows that for every , there exist constants and such that
Since and are continuous functions on and , respectively, there exist constants such that
Thus,
(3.23) |
Let such that and be large enough. Using the above inequality, we obtain
As
for large enough, we deduce
Thus, there exist and such that .
Proof of Theorem 2
To prove Theorem 2, we need the following auxiliary lemmas:
Lemma 3.2. (see [25,26]) For and such that for all and for all . Let
Then, .
Lemma 3.3. (see [27]) For all () and (), there exists () such that
(3.24) |
Now, we return to the proof of Theorem 2. To this end, based on Fountain Theorem 4, we will show that the problem (1.1) possesses infinitely many weak solutions with unbounded energy. Evidently, according to , is an even functional. By Lemma 3.1, we know that satisfies the -condition. Then, to prove Theorem 2, it only remains to verify the following assertions:
as ,
.
For any such that . It follows from , Proposition 3, and Lemma 3.3 that
where .
Then, it follows that
(3.25) |
Let us consider the following equations:
(3.26) |
and
(3.27) |
Let and be the two non-zero solutions of (3.26) and (3.27), respectively. Then, we obtain
We fix as follows
Then, by Lemma 3.2, (3.25) and , we obtain
where . Hence, holds.
In view of Proposition 3 and (3.23), for with , we have
Since , then all norms are equivalent in . Therefore, as , for large enough, we obtain
Finally, the assertion is also valid.
This completes the proof.
Mahmoud El Ahmadi: Writing-original draft, Writing-review & editing; Mohammed Barghouthe: Formal Analysis, Methodology; Anass Lamaizi: Formal Analysis; Mohammed Berrajaa: Supervision, Validation.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors would like to thank the referees for their valuable comments and suggestions, which have improved the quality of this paper.
The authors declare there is no conflict of interest.
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