Microorganisms make use of heavy metals through enzymatic, non-enzymatic processes or bioaccumulation in bacterial cells in insoluble or particulate forms and by-products. Increasing effectiveness of bioremediation is still being explored and other stimulation techniques cited by various authors used mostly EDTA, nitrogen fertiliser and other amendments. The use of mechanical aeration combined with bioremediation using Bacillus subtilis, Bacillus cereus, Pseudomonas aeruginosa and Pseudomonas fluoresecens offer a greener approach with more efficient remediation capabilities. Zinc exceeded the permissible limit recommended by FAO/WHO by more than two folds while other metals were close to the threshold limit posing a dangerous threat to human health. Implementation of the current package treatment showed statistically significant decreases in heavy metal concentrations in both soils and coastal sediments in a 90 days experiment under atmospheric conditions. For sediments, 21.4% to 100% bioremediation was achieved under mechanical aeration conditions representing an increase of up to 60% efficiency compared to non-aeration while for soil highest efficacy achieved was 63.1%. However, the mechanisms and pathways of bioremediation were noticed to depend according to biotic and abiotic factors. This article provides an insight on the comparison between proposed stimulation technique and other methods reported.
Citation: Gireshsingh Mungla, Sunita Facknath, Bhanooduth Lalljee. Assessing the Potential of Mechanical Aeration Combined with Bioremediation Process in Soils and Coastal Sediments Impacted by Heavy Metals[J]. AIMS Environmental Science, 2022, 9(5): 692-707. doi: 10.3934/environsci.2022039
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Microorganisms make use of heavy metals through enzymatic, non-enzymatic processes or bioaccumulation in bacterial cells in insoluble or particulate forms and by-products. Increasing effectiveness of bioremediation is still being explored and other stimulation techniques cited by various authors used mostly EDTA, nitrogen fertiliser and other amendments. The use of mechanical aeration combined with bioremediation using Bacillus subtilis, Bacillus cereus, Pseudomonas aeruginosa and Pseudomonas fluoresecens offer a greener approach with more efficient remediation capabilities. Zinc exceeded the permissible limit recommended by FAO/WHO by more than two folds while other metals were close to the threshold limit posing a dangerous threat to human health. Implementation of the current package treatment showed statistically significant decreases in heavy metal concentrations in both soils and coastal sediments in a 90 days experiment under atmospheric conditions. For sediments, 21.4% to 100% bioremediation was achieved under mechanical aeration conditions representing an increase of up to 60% efficiency compared to non-aeration while for soil highest efficacy achieved was 63.1%. However, the mechanisms and pathways of bioremediation were noticed to depend according to biotic and abiotic factors. This article provides an insight on the comparison between proposed stimulation technique and other methods reported.
Variational inequalities earlier introduced and studied by Stampacchia [1] are now interestingly applied in the fields of management, finance, economics, optimization and almost in all branches of pure and applied sciences, see [2,3,4,5,6,7,8,9,10,11,12,13,14,15]. Since variational inequalities provide a natural framework to solve different mathematical and scientific problems, various techniques including projection method, auxiliary principle technique, Wiener-Hopf equations and dynamical systems have been developed for finding the solution of variational inequalities and associated optimization problems, see [2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25] the references therein.
Absolute value variational inequalities are the significant and useful generalizations of variational inequalities which were introduced and studied by Mangasarian, see [26]. It was shown by Rohn [27] that absolute value variational inequalities are equivalent to complementarity problem and further considered by Mangasarian and Meyer [29] using different methodology. Absolute value variational inequalities are more general as they contain classical variational inequalities as a special case. It has been proved through projection lemma that the absolute value variational inequality and fixed point problem are equivalent, see [2,3]. Using this equivalence between absolute value variational inequality and fixed point problem, various iterative schemes are developed for solving absolute value variational inequalities and to examine the associated optimization problems, see [3,14].
An innovative aspect in the study of variational inequalities concerns merit functions through which the variational inequality problem can be reformulated into an optimization problem. It was Auslender [28], who introduced the first merit function in optimization theory. Merit functions play important roles in developing globally convergent iterative schemes and investigating the rate of convergence for some iterative schemes, see [20,21,22,23,24,25,26]. Several merit functions are being suggested and analyzed for variational inequalities and hence for the complementarity problems as a variational inequality problem can be rephrased into a complementarity problem, see [30,31,32,33,34,35,36,37,38,39,40,41] and the references therein. Error bounds also contribute significantly in the study of variational inequalities as error bounds are the functions which estimate the closeness of an arbitrary point to the solution set in an approximate computation of the iterates for solving variational inequalities, see [31,32,33,34,35].
In spite of the huge lift in the field of variational inequalities and optimization theory, we present and investigate some new merit functions for absolute variational inequalities in this work. We also suggest the error bounds for the solution of absolute variational inequalities under some suitable constraints. The proofs of our proposed results are easy and direct in comparison with other methods and these results also remain true for the associated problems of absolute value variational inequalities. Hence, the findings of this paper provide a substantial addition in this field.
Let H be a real Hilbert space, whose norm and inner product are denoted by ‖.‖ and <.,.> respectively. Let K be a closed and convex set in H. For given operators T,B:H→H, consider the problem of finding u∈K such that
⟨Tu+B|u|,v−u⟩≥0,∀v∈H, | (2.1) |
where |u| contains the absolute values of components of u∈H. The inequality (2.1) is called absolute value variational inequality. The absolute value variational inequality (2.1) can be viewed as a difference of two operators and includes previously known classes of variational inequalities as special cases. For the recent applications of absolute value variational inequalities, see [2,3,33,35,40] and the references therein.
In order to derive the main results of this paper, we recall some standard definitions and results.
Definition 2.1. An operator T:H→H is said to be strongly monotone, if there exists a constant α>0 such that
⟨Tu−Tv,u−v⟩≥α‖u−v‖2,∀u,v∈H. |
Definition 2.2. An operator T:H→H is said to be Lipschitz continuous, if there exists a constant β>0 such that
‖Tu−Tv‖≤β‖u−v‖,∀u,v∈H. |
If T is strongly monotone and Lipschitz continuous operator, then from definitions (2.1) and (2.2), we have α≤β.
Definition 2.3. An operator T:H→H is said to be monotone, if
⟨Tu−Tv,u−v⟩≥0,∀u,v∈H. |
Definition 2.4. An operator T:H→H is said to be pseudomonotone, if
⟨Tu,v−u⟩≥0, |
implies
⟨Tv,v−u⟩≥0∀u,v∈H. |
Definition 2.5. [37] A function M:H→RU{+∞} is called a merit (gap) function for the inequality 2.1, if and only if
(i) M(u)≥0,∀u∈H.
(ii) M(ˉu)=0, if and only if, ˉu∈H solves inequality (2.1).
We now consider the well-known projection lemma which is due to [6]. This lemma is useful to reformulate the variational inequalities into a fixed point problem.
Lemma 2.6. [6] Let K be a closed and convex set in H. Then for a given z∈H,u∈K satisfies
⟨u−z,v−u⟩≥0,∀v∈K, |
if and only if
u=PKz, |
where PK is the projection of H onto a closed and convex set K in H.
It is remarkable that the projection operator PK is non-expansive operator, that is
‖PK[u]−PK[v]‖≤‖u−v‖,∀u,v∈H. |
In this section, we suggest some merit functions associated with absolute value variational inequalities. Using these merit functions, we attain some error bounds for absolute value variational inequalities. To obtain this, we show that the variational inequalities are equivalent to the fixed point problem.
Lemma 3.1. [2,14] Let K be a closed convex set in H. The function u∈K is a solution of absolute value variational inequality (2.1), if and only if, u∈K satisfies the relation
u=PK[u−ρTu−ρB|u|], | (3.1) |
where ρ>0 is a constant.
It follows from the above lemma that the absolute value variational inequality (2.1) and the fixed point problem (3.1) are equivalent. This alternative equivalent formulation is very advantageous from the theoretical as well as from the numerical point of view and is obtained by using projection technique. The projection methods are due to Lions and Stampacchia [4] which provide several effective schemes to approximate the solution of variational inequalities. The equivalence between variational inequalities and the fixed point problem plays a significant role in establishing the various results for problem (2.1) and its related formulations.
Lemma 3.2. For all u,v∈H, we have
‖u‖2+⟨u,v⟩≥−14‖v‖2. |
Now, we define the residue vector R(u) by the following relation
Rρ(u)≡R(u)=u−PK[u−ρTu−ρB|u|]. | (3.2) |
From lemma 2.6, it can also be concluded that u∈K is a solution of the absolute value variational inequality (2.1), if and only if, u∈K is a zero of the equation
Rρ(u)≡R(u)=0. |
We now show that the residue vector Rρ(u) is strongly monotone and Lipschitz continuous.
Lemma 3.3. Let the operators T and B be Lipschitz continuous with constants βT>0 and βB>0 and T be strongly monotone with constant αT>0, respectively then the residue vector Rρ(u), defined by (3.2) is strongly monotone on H.
Proof. For all u,v∈H, consider
⟨Rρ(u)−Rρ(v),u−v⟩=⟨u−PK[u−ρTu−ρB|u|]−v+PK[v−ρTv−ρB|v|],u−v⟩=⟨u−v−PK[u−ρTu−ρB|u|]+PK[v−ρTv−ρB|v|],u−v⟩=⟨u−v,u−v⟩−⟨PK[u−ρTu−ρB|u|]−PK[v−ρTv−ρB|v|],u−v⟩≥‖u−v‖2−‖PK[u−ρTu−ρB|u|−PK[v−ρTv−ρB|v|]‖‖u−v‖≥‖u−v‖2−‖(u−v)−ρ(Tu−Tv)‖‖u−v‖‖(B|u|−B|v|)‖−ρ‖u−v‖≥‖u−v‖2−{√1−2ρβT+ρ2β2T+ρβB}‖u−v‖2=(1−√1−2ρβT+ρ2β2T−ρβB)‖u−v‖2, |
which implies that
⟨Rρ(u)−Rρ(v),u−v⟩≥ϑ‖u−v‖2, |
where
ϑ=(1−√1−2ρβT+ρ2β2T−ρβB)>0, |
which proves that the residue vector Rρ(u) is strongly monotone with constant ϑ>0.
Lemma 3.4. Let the operators T and B be Lipschitz continuous with constants βT>0 and βB>0 and T be strongly monotone with constant αT>0, respectively then the residue vector Rρ(u), defined by ((3.2)), is Lipschitz continuous on H.
Proof. For all u,v∈H, consider
‖Rρ(u)−Rρ(v)‖=‖u−PK[u−ρTu−ρB|u|]−v+PK[v−ρTv−ρB|v|]‖≤‖u−v‖+‖PK[u−ρTu−ρB|u|]−PK[v−ρTv−ρB|v|‖≤‖u−v‖+‖(u−v)−ρ(Tu−Tv)−ρ(B|u|−B|v|)‖≤2‖u−v‖+√1−2ραT+ρ2β2T‖(u−v)‖+√1−2ραB+ρ2β2B‖(u−v)‖=(2+√1−2ραT+ρ2β2T+√1−2ραB+ρ2β2B)‖(u−v)‖=φ‖(u−v)‖, |
where
φ=2+√1−2ραT+ρ2β2T+√1−2ραB+ρ2β2B>0. |
For the proof of above result, we have used the Lipschitz continuity and strongly monotonicity of the operators T and B with constants βT>0,βB>0 and αT>0,αB>0, respectively. Thus the residue vector Rρ(u) is Lipschitz continuous with constant φ>0. This completes the proof. We now use the residue vector Rρ(u), defined by (3.2), to derive the error bound for the solution of the problem (2.1).
Theorem 3.5. Let ˆu∈H be a solution of the absolute value variational inequality (2.1). If the operators T and B are Lipschitz continuous with constants βT>0 and βB>0 and strongly monotone with constants αT>0 and αB>0, respectively then
1l1‖Rρ(u)‖≤‖ˆu−u‖≤l2‖Rρ(u)‖,∀u∈H. |
Proof. Let ˆu∈H solves the absolute value variational inequality (2.1). Then we have
⟨ρTˆu+ρB|ˆu|,v−ˆu⟩≥0,∀v∈H. | (3.3) |
Take v=PK[u−ρTu−ρB|u|] in (3.3), to have
⟨ρTˆu+ρB|ˆu|,PK[u−ρTu−ρB|u|]−ˆu⟩≥0. | (3.4) |
Take u=PK[u−ρTu−ρB|u|], z=u−ρTu−ρB|u| and v=ˆu in projection lemma 2.6 to have
⟨PK[u−ρTu−ρB|u|]−u+ρTu+ρB|u|,ˆu−PK[u−ρTu−ρB|u|]⟩≥0, |
which shows that
⟨−ρTu−ρB|u|+u−PK[u−ρTu−ρB|u|],PK[u−ρTu−ρB|u|]−ˆu⟩≥0. | (3.5) |
Addition of the inequalities (3.4) and (3.5) implies
⟨ρ(Tˆu−Tu)+ρ(B|ˆu|−B|u|)+(u−PK[u−ρTu−ρB|u|]),PK[u−ρTu |
−ρB|u|]−ˆu⟩≥0, |
Using (3.2), we obtain
⟨Tˆu−Tu,PK[u−ρTu−ρB|u|]⟩+⟨B|ˆu|−B|u|,ˆu−PK[u−ρTu | (3.6) |
−ρB|u|]⟩≤1ρ⟨R(u),PK[u−ρTu−ρB|u|]−ˆu⟩. | (3.7) |
By the strong monotonicity of the operators T and B with constants αT>0 and αB>0, respectively, we obtain
αT‖ˆu−u‖2≤⟨Tˆu−Tu,ˆu−u⟩≤⟨Tˆu−Tu,ˆu−PK[u−ρTu−ρB|u|]⟩+⟨Tˆu−Tu,PK[u−ρTu−ρB|u|]−u⟩, |
and
αB‖ˆu−u‖2≤⟨Bˆu−Bu,ˆu−u⟩≤⟨Bˆu−Bu,ˆu−PK[u−ρTu−ρB|u|]⟩+⟨Bˆu−Bu,PK[u−ρTu−ρB|u|]−u⟩, |
using (3.2) and (3.6), we obtain
(αT+αB)‖ˆu−u‖2≤1ρ⟨R(u),PK[u−ρTu−ρB|u|]−ˆu⟩+⟨Tˆu−Tu,−R(u)⟩+⟨Bˆu−Bu,−R(u)⟩, |
Using the Lipschitz continuity of the operators T and B with constants βT>0,βB>0, respectively, we obtain
ρ(αT+αB)‖ˆu−u‖2≤1ρ⟨R(u),PK[u−ρTu−ρB|u|]−ˆu⟩+ρ⟨Tˆu−Tu,−R(u)⟩+ρ⟨Bˆu−Bu,−R(u)⟩≤⟨R(u),−R(u)⟩−⟨R(u),ˆu−u⟩+ρ⟨Tˆu−Tu,−R(u)⟩+ρ⟨Bˆu−Bu,−R(u)⟩≤−‖R(u)‖2+‖ˆu−u‖‖R(u)‖+ρβT‖ˆu−u‖‖R(u)‖+ρβB‖ˆu−u‖‖R(u)‖=−‖R(u)‖2+(1+ρ(βT+βB))‖ˆu−u‖‖R(u)‖≤(1+ρ(βT+βB))‖ˆu−u‖‖R(u)‖, |
which implies that
‖ˆu−u‖≤(1+ρ(βT+βB))ρ(αT+αB)‖R(u)‖=l2‖R(u)‖, | (3.8) |
where
l2=(1+ρ(βT+βB))ρ(αT+αB). |
Now, using the relation (3.2), we have
‖R(u)‖=‖u−PK[u−ρTu−ρB|u|‖≤‖ˆu−u‖+‖ˆu−PK[u−ρTu−ρB|u|]‖≤‖ˆu−u‖+‖PK[ˆu−ρTˆu−ρB|ˆu|]−PK[u−ρTu−ρB|u|]‖≤‖ˆu−u‖+‖ˆu−ρTˆu−ρB|ˆu|−u+ρTu+ρB|u|‖≤‖ˆu−u‖+‖ˆu−u‖+ρ‖Tˆu−Tu‖+ρ‖B|ˆu|−B|u|‖≤2‖ˆu−u‖+ρβT‖ˆu−u‖+ρβB‖ˆu−u‖=(2+ρ(βT+βB))‖ˆu−u‖=l1‖ˆu−u‖, |
which shows that
1l1‖R(u)‖≤‖ˆu−u‖, | (3.9) |
where
l1=(2+ρ(βT+βB)). |
Combining (3.8) and (3.9), we obtain
1l1‖R(u)‖≤‖ˆu−u‖≤l2‖R(u)‖,∀u∈H. | (3.10) |
which is the required result. Now, substituting u=0 in (3.10), we obtain
1l1‖R(0)‖≤‖ˆu−u‖≤l2‖R(0)‖,∀u∈H. | (3.11) |
Combining (3.10) and (3.11), we get a relative error bound for any u∈H.
Theorem 3.6. Suppose that all the conditions of Theorem 3.5 hold. If 0≠u∈H is a solution of the absolute value variational inequality (2.1), then
s1‖R(u)‖‖R(0)‖‖≤‖u−ˆu‖ˆu≤s2‖R(u)‖‖R(0)‖. |
It is noted that the normal residue vector R(u), defined in (3.2), is nondifferentiable. To resolve the nondifferentiability which is a significant limitation of the regularized merit function, we examine another merit function associated with the absolute value variational inequality (2.1). This merit function can be regarded as a regularized merit function. For all u∈H, consider the function, such that
Mρ(u)=⟨Tu+B|u|,u−PK[u−ρTu−ρB|u|]⟩−12ρ‖u−PK[u−ρTu−ρB|u|‖2. | (3.12) |
It is clear from the above equation that Mρ(u)≥0, for all u∈H.
Now, we prove that the function established in (3.12), is a merit function and this is the leading objective of our next results.
Theorem 3.7. For all u∈H, we have
Mρ(u)≥12ρ‖Rρ(u)‖2. |
In particular, we have Mρ(u)=0, if and only if u∈H is a solution of the absolute value variational inequality (2.1).
Proof. By substituting u=PK[u−ρTu−ρB|u|],z=u−ρTu−ρB|u| and v=u in lemma 2.6, we obtain
⟨ρTu+ρB|u|+PK[u−ρTu−ρB|u|]−u,u−PK[u−ρTu−ρB|u|]⟩≥0. |
Using (3.12) and lemma 3.2, we obtain
0≤⟨ρTu+ρB|u|−(u−PK[u−ρTu−ρB|u|]),u−PK[u−ρTu−ρB|u|]⟩=⟨ρTu+ρB|u|−Rρ(u),Rρ(u)⟩=⟨Tu+B|u|,Rρ(u)⟩−1ρ⟨Rρ(u),Rρ(u)⟩=Mρ(u)+12ρ‖Rρ(u)‖2−1ρ‖Rρ(u)‖2=Mρ(u)−12ρ‖Rρ(u)‖2, |
which shows that
Mρ(u)≥12ρ‖Rρ(u)‖2, |
which is the required result.
It is clear from the above inequality that Mρ(u)≥0,∀u∈H. Also, if Mρ(u)=0, then from the above inequality, we obtain Rρ(u)=0. Hence, according to lemma 3.1, it is clear that u∈H solves the absolute value variational inequality (2.1). On the other hand, if u∈H is a solution of absolute value variational inequality (2.1), then by lemma 3.1, we have u=PK[u−ρTu−ρB|u|]. Therefore, from (3.12), we obtain, Mρ(u)=0, which was the required result.
It is observed from Theorem 3.7 that Mρ(u) defined by (3.12), is a merit function for the absolute value variational inequality (2.1). We also notice that the regularized merit function is differentiable, if the operators T and B are differentiable. Now, we obtain the error bounds for the absolute value variational inequality if both the operators T and B are not Lipschitz continuous.
Theorem 3.8. Let ˆu∈H be a solution of the absolute value variational inequality (2.1). Let the operators T and B be strongly monotone with the constants αT>0,αB>0, respectively. Then
‖u−ˆu‖2≤4ρρ(αT+αB)[Mρ(u)+1ρ‖ρTˆu+ρB|ˆu|‖2],∀u∈H. |
Proof. Let ˆu∈H be a solution of the absolute value variational inequality (2.1) and by taking v=u, we have
⟨ρTˆu+ρB|ˆu|,u−ˆu⟩≥0, |
using lemma 3.1, we have
⟨Tˆu+B|ˆu|,u−ˆu⟩≥14ρ‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2. |
Using (3.12) and strong monotonicity of the operators T and B, we have
Mρ(u)=⟨Tu+B|u|,u−ˆu]⟩−12ρ‖u−ˆu‖2=⟨Tu−Tˆu+Tˆu+B|u|−B|ˆu|+B|ˆu|,u−ˆu]⟩−12ρ‖u−ˆu‖2=⟨Tu−Tˆu,u−ˆu]⟩+⟨B|u|−B|ˆu|,u−ˆu]⟩+⟨Tˆu+B|ˆu|,u−ˆu⟩−12ρ‖u−ˆu‖2≥αT‖u−ˆu‖2+αB‖u−ˆu‖2+⟨Tˆu+B|ˆu|,u−ˆu⟩−12ρ‖u−ˆu‖2≥(αT+αB−12ρ)‖u−ˆu‖2+14ρ‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2=(αT+αB−12ρ+14ρ)‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2, |
which shows that
‖u−ˆu‖2≤4ρ4ρ(αT+αB)−1[Mρ(u)+1ρ‖ρTˆu+ρB|ˆu|‖2], |
which is the required result. Now, we study one more merit function associated to the absolute value variational inequality. This merit function is the difference between two regularized merit functions associated with (2.1). Many authors used to study such type of merit functions to find the solution of variational inequalities and complementarity problems, see [2,3,38,39,40,41]. We define the D-merit function for absolute value variational inequality, which is the difference of regularized merit function defined by (3.12). We consider the following function
Dρ,ζ(u)=Mρ(u)−Mζ(u)=⟨Tu+B|u|,u−PK[u−ρTu−ρB|u|]⟩−12ρ‖u−PK[u−ρTu−ρB|u|]‖2−⟨Tu+B|u|,u−PK[u−ζTu−ζB|u|]⟩+12ζ‖u−PK[u−ζTu−ζB|u|]‖2⟩=⟨Tu+B|u|,Rρ(u)⟩−12ρ‖Rρ(u)‖2−⟨Tu+B|u|,Rζ(u)⟩+12ζ‖Rζ(u)‖2⟩=⟨Tu+B|u|,Rρ(u)−Rζ(u)⟩−12ρ‖Rρ(u)‖2+12ζ‖Rζ(u)‖2,∀u∈H. | (3.13) |
It is clear from (3.13) that Dρ,ζ(u) is finite everywhere. We will now prove that Dρ,ζ(u) is in fact a merit function for the absolute value variational inequality which is the prime inspiration for the following result.
Theorem 3.9. For all u∈H and ρ≥ζ, we have
(ρ−ζ)‖Rρ(u)‖2≥2ρζDρ,ζ(u)≥(ρ−ζ)‖Rρ(u)‖2‖Rζ(u)‖2. |
Particularly, Dρ,ζ(u)=0, if and only if u∈H is the solution of the absolute value variational inequality (2.1).
Proof. Take u=PK[u−ρTu−ρB|u|],v=PK[u−ζTu−ζB|u| and z=u−ρTu−ρB|u| in lemma 2.6, to have
⟨PK[u−ρTu−ρB|u|]−u+ρTu+ρB|u|,PK[u−ζTu−ζB|u|]−PK[u−ρTu−ρB|u|]⟩≥0, |
which shows that
⟨Tu+B|u|,Rρ(u)−Rζ(u)⟩≥1ρ⟨Rρ(u),Rρ(u)−Rζ(u)⟩. | (3.14) |
From (3.13) and (3.14), we obtain
Dρ,ζ(u)≥12ζ‖Rζ(u)‖2−12ρ‖Rρ(u)‖2+1ρ‖Rρ(u)‖2−1ρ⟨Rρ(u),Rζ(u)⟩=12(1ζ−1ρ)‖Rζ(u)‖2+1ρ‖Rρ(u)‖2−12ρ‖Rρ(u)‖2+12ρ‖Rζ(u)‖2−1ρ⟨Rρ(u),Rζ(u)⟩=12(1ζ−1ρ)‖Rζ(u)‖2+12ρ‖Rρ(u)‖2+12ρ‖Rζ(u)‖2−1ρ⟨Rρ(u),Rζ(u)⟩=12(1ζ−1ρ)‖Rζ(u)‖2+12ρ‖Rζ(u)−Rρ(u)‖2≥12(1ζ−1ρ)‖Rζ(u)‖2, |
which clearly shows that
2ρζDρ,ζ(u)≥(ρ−ζ)‖Rζ(u)‖2. | (3.15) |
Similarly, by substituting u=PK[u−ζTu−ζB|u|],v=PK[u−ρTu−ρB|u|] and z=u−ζTu−ζB|u| in lemma 2.6, we obtain
⟨PK[u−ζTu−ζB|u|]−u+ζTu+ζB|u|,PK[u−ρTu−ρB|u|]−Pv[u−ζTu−ζB|u|]⟩≥0, |
which shows that
⟨Tu+B|u|,Rρ(u)−Rζ(u)⟩≤1ζ⟨Rζ(u),Rρ(u)−Rζ(u)⟩. | (3.16) |
From (3.13) and (3.16), we obtain
Dρ,ζ(u)≤−12ρ‖Rρ(u)‖2+12ζ‖Rζ(u)‖2+1ζ⟨Rζ(u),Rρ(u)−Rζ(u)⟩=12ζ‖Rζ(u)‖2−12ρ‖Rρ(u)‖2−1ζ‖Rζ(u)‖2+1ζ⟨Rζ(u),Rρ(u)⟩=12(1ζ−1ρ)‖Rρ(u)‖2−12ζ‖Rρ(u)‖2−12ζ‖Rζ(u)‖2+1ζ⟨Rζ(u),Rρ(u)⟩=12(1ζ−1ρ)‖Rρ(u)‖2−12ζ‖Rρ(u)−Rζ(u)‖2≤12(1ζ−1ρ)‖Rρ(u)‖2, |
which proves the left most inequality of the required result, that is,
(ρ−ζ)‖Rρ(u)‖2≥2ρζDρ,ζ(u). | (3.17) |
Combining (3.15) and (3.17), we obtain
(ρ−ζ)‖Rρ(u)‖2≥2ρζDρ,ζ(u)≥(ρ−ζ)‖Rζ(u)‖2, |
which is the required result.
Theorem 3.10. Let ˆu∈H be a solution of the absolute value variational inequality (2.1). If the operators T and B are strongly monotone with constants αT>0 and αB>0, respectively then
‖u−ˆu‖2≤4ρζ4(αT+αB)−3ζ+2ρ[Dρ,ζ(u)+1ρ‖Tˆu+B|ˆu|‖2],∀u∈H. |
Proof. Since ˆu∈H is a solution of the absolute value variational inequality (2.1) and by substituting v=u in (2.1), we obtain
⟨ρTˆu+ρB|ˆu|,u−ˆu⟩≥0, |
using lemma 3.2, we obtain
⟨Tˆu+B|ˆu|,u−ˆu⟩≥−1ρ‖Tˆu+B|ˆu|‖2−14ρ‖u−ˆu‖2. | (3.18) |
From (3.13), using the strong monotonicity of the operators T and B with constants αT>0 and αB>0 respectively and (3.18), we obtain
Dρ,ζ(u)=⟨Tu+B|u|,Rρ(u)−Rζ(u)⟩−12ρ‖Rρ(u)‖2+12ζ‖Rζ(u)‖2=⟨Tu+B|u|,u−ˆu⟩−12ρ‖u−ˆu‖2+12ζ‖u−ˆu‖2=⟨Tu−Tˆu,u−ˆu⟩+⟨B|u|−B|ˆu|,u−ˆu⟩+⟨Tˆu+B|ˆu|,u−ˆu⟩−12ρ‖u−ˆu‖2+12ζ‖u−ˆu‖2⟩≥αT‖u−ˆu‖2+αB‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2−14ρ‖u−ˆu‖2−12ρ‖u−ˆu‖2+12ζ‖u−ˆu‖2⟩=(αT+αB−34ρ+12ζ)‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2=4(αT+αB)−3ζ+2ρ4ρζ‖u−ˆu‖2−1ρ‖Tˆu+B|ˆu|‖2, |
which shows that
‖u−ˆu‖2≤4ρζ4(αT+αB)−3ζ+2ρ[Dρ,ζ(u)+1ρ‖Tˆu+B|ˆu|‖2], |
the required result.
In this paper, we have proposed and investigated various merit functions for a new type of variational inequalities, namely absolute value variational inequalities. These merit functions are utilized to obtain error bounds for the estimated solution of absolute value variational inequalities and the associated optimization problems. The results proved in this paper may be considered as primary contribution in this alluring domain. Interested researchers are urged to discover the uses of absolute value variational inequalities in a variety of pure and applied disciplines. The suggestions made in this paper may be used in further research work.
Authors would like to thank the referees for their valuable and constructive comments.
The authors declare that they have no competing interests.
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