This article presents the existence outcomes concerning a family of singular nonlinear differential equations containing Caputo's fractional derivatives with nonlocal double integral boundary conditions. According to the nature of Caputo's fractional calculus, the problem is converted into an equivalent integral equation, while two standard fixed theorems are employed to prove its uniqueness and existence results. An example is presented at the end of this paper to illustrate our obtained results.
Citation: Debao Yan. Existence results of fractional differential equations with nonlocal double-integral boundary conditions[J]. Mathematical Biosciences and Engineering, 2023, 20(3): 4437-4454. doi: 10.3934/mbe.2023206
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This article presents the existence outcomes concerning a family of singular nonlinear differential equations containing Caputo's fractional derivatives with nonlocal double integral boundary conditions. According to the nature of Caputo's fractional calculus, the problem is converted into an equivalent integral equation, while two standard fixed theorems are employed to prove its uniqueness and existence results. An example is presented at the end of this paper to illustrate our obtained results.
Due to its extensive applications in several fields like science and engineering, fractional calculus (FC) has acquired remarkable generality and significance, especially within the last few decades. FC is widely used to describe such practical problems as viscoelastic bodies, continuous media with memory, transformation of temperature, etc. Compared with the traditional integer-order models, the fractional order models can accurately reflect the properties and laws of related phenomena. Recently, there has been a lot of literature on FC. Some of them focus on the basic theory of FC, and the others focus their research on the solvability of initial problems or boundary problems in term of special functions, readers can refer to references [1,2,3,4,5,6,7] for details. Researchers have made great advancement in the study of qualitative and quantitative properties of solutions for fractional differential equations (FDEs), including existence, uniqueness, boundedness, continuous dependence on initial data and so on [8,9,10,11,12,13,14,15]. The methods used for analysis include fixed point theorems, the comparison principle, chaos control, nonlinear alternatives of the Leray-Schauder type, upper and lower solutions and numerical calculation. For various studies performed on FC, we refer the reader to more literature [16,17,18,19,20,21,22,23] and the references therein.
In recent years, the issues related to singular FDEs (SFDEs) have been verified. The positive solutions regarding a category of SFDEs were verified in [21] by
{Dα0+u(t)=f(t,u(t)),2<α≤3,0<t<1,u(0)=u′(0)=u″(0)=0, |
where f:(0,1]×[0,+∞) and limt→0+f(t,x(t))=∞. They employed the fixed-point theorem and the Leray-Schauder type with nonlinear form in a cone to obtain two results for this problem.
Other works related to this kind of problem have been presented in [24,25,26,27,28,29,30,31].
FDEs have been investigated in various studies when integral boundary conditions (BCs) are under consideration. This type of problems arose from many research areas such as heat conduction, chemical engineering, underground water flow, population dynamics, and so forth. For further information about FDEs with integral BCs, we refer the reader to the [32,33,34,35,36,37,38,39] and the references therein. For instance, Ahmad and Agarwal [39] investigated both the existence and uniqueness of solutions (EUS) for fractional boundary value problems (FBVPs) with some novel versions regarding slit-strips conditions. One of the problems that they considered is as follows:
{cDq0+x(t)=f(t,x(t)),n−1<q≤n,t∈(0,1)x(0)=x′(0)=x″(0)=⋯=xn−2(0)=0,x(ζ)=a∫η0x(s)ds+b∫1ξx(s)ds,0<η<ζ<ξ<1, |
where cDq stands for a special derivative with order q called the fractional derivative of Caputo type and a continuous mapping expressed by f(t,x(t)) in ([0,1]×R) is considered. They obtained the EUS conditions for the mentioned problems by applying fixed principles.
Researchers are also interested in singular nonlinear FDEs with integral BCs [40,41,42,43,44]. Yan [44] investigated just such a problem. Specifically, the upcoming problem was studied:
Dα0+x(t)=f(t,x(t)),0<t<1, |
subject to conditions: x(0)=0=x′(0) and x(1)=∫1γx(τ)dτ,0<γ<1. Both t=0 and t=1 lead to the singular non-linear mapping f(t,x(t)).
Inspired by the mentioned studies, the current study discusses the following singular nonlinear FDE containing nonlocal double integral BCs:
{cDδ0+x(t)=f(t,x(t)),0<t<1,x(0)=∫η0x(τ)dτ,x′(0)=x″(0)=⋯=x(n−2)(0)=0,x(1)=∫1γx(τ)dτ | (1.1) |
where cDδ0+ is Caputo's differentiation of order δ; δ,η and γ are real numbers satisfying 1≤n−1<δ≤n<+∞ and 0<η<γ<1, and n=[δ] + 1 is an integer number, the nonlinear term f(t,x(t))∈((0,1)×R,R) becomes singular when both t=0 and t=1, namely, limt→0+f(t,⋅)=∞ and limt→1−f(t,⋅)=∞. For the physical meaning of the integral BCs in (1.1), x(t) can be interpreted as the distribution of heat on a linear body, and the integral condition x(0)=∫η0x(τ)dτ states that the heat absorbed or emitted by the body at t=0 is equal to the variable of its heat over [0,η]. The other integral condition has a similar explanatory and physical meaning. The current study aims to demonstrate the EUS to the problem (1.1). The generalized Hölder's inequality and fixed-point theories are applied in this paper, while the use of the generalized Hölder's inequality is the highlight of this article. This category of problems discussed in this article and the methods used make a contribution to the existing literature.
This paper consists of a total of five parts. In the first part, the related situation of FDEs is introduced. The second part mainly introduces some basic knowledge of FC, such as definitions and related lemmas, which will be employed in the following content. The third part is the core of the manuscript, including the key conclusions and their proofs. The fourth part includes an example, which aims to use the results of this paper to solve the relevant problems. The last part is the summary of this paper.
The characteristics of FC, the lemmas to be used, and pertinent principles are presented in the current subsection.
Definition 2.1([3]) Consider that Ω=[a,b](−∞<a<b<+∞) is a limited range in R. The fractional integrals denoted by Iαa+f and Iαb−f of order α∈C(ℜ(α)>0) called the Riemann-Liouville type can be represented by
(Iαa+f)(x)=1Γ(α)∫xaf(t)(x−t)1−αdt(x>a;ℜ(α)>0) |
and
(Iαb−f)(x)=1Γ(α)∫bxf(t)(t−x)1−αdt(x<b;ℜ(α)>0), |
respectively. In the above relations, Γ(⋅) stands for the gamma function.
Definition 2.2([3]) Consider y(x)∈ACn[a,b]. Now, the derivatives (cDαa+y)(x) and (cDαb−y)(x), called the Caputo's, can subsist nearly on the whole interval [a,b].
(1) If α∉N0, (cDαa+y)(x) and (cDαb−y)(x) are defined as follows:
(cDαa+y)(x)=1Γ(n−α)∫xay(n)(t)(x−t)α−n+1dt |
and
(cDαb−y)(x)=(−1)nΓ(n−α)∫bxy(n)(t)(t−x)α−n+1dt, |
respectively, where D describes the derivative operator and n=[ℜ(α)]+1, α∈C, ℜ(α)≥0.
(2) If α∈N0, then
(cDna+y)(x)=y(n)(x), (cDnb−y)(x)=(−1)(n)y(n)(x),n∈N0. |
Lemma 2.1([3]) The FDE's public solutions denoted by (cDαa+y)(x)=0 is derived as
y(x)=n−1∑k=0y(i)(a)i!(x−a)i. |
Especially, for a=0, this result can be presented as
y(x)=c0+c1x+c2x2+⋯+cn−1xn−1, |
where ci=y(i)(0)i!(i=0,1,⋯n−1) denotes certain constants.
Lemma 2.2 Suppose x(t) fulfills the subsequent BVP:
{cDδ0+x(t)=h(t),0<t<1,x(0)=∫η0x(τ)dτ,x′(0)=x″(0)=⋯=x(n−2)(0)=0,x(1)=∫1γx(τ)dτ. | (2.1) |
Now, BVP (2.1) possesses the following unique solution for a certain function h(t)∈C[0,1]
x(t)=1Γ(δ)∫t0(t−τ)δ−1h(τ)dτ+a+btn−1Γ(δ)∫10(1−τ)δ−1h(τ)dτ+c+dtn−1Γ(δ+1)∫10(1−τ)δh(τ)dτ +e+ftn−1Γ(δ+1)∫η0(η−τ)δh(τ)dτ+a+btn−1Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ | (2.2) |
where cDδ0+ stands for the Caputo's differentiation of order δ; δ,η,γ and n are defined as in problem (1.1), and a=−ηnΔ1,b=−n(1−η)Δ1,c=ηΔ1,d=n+ηn−(n+1)ηΔ1,e=n+γn−1Δ1,f=−nγΔ1 and Δ1=[(n−1)+γn](1−η)+γηn.
Proof According to Lemma 2.1, one can gain
x(t)=1Γ(δ)∫t0(t−τ)δ−1h(τ)dτ+c0+c1t+c2t2+⋯+cn−1tn−1 | (2.3) |
for some c0, c1, c2⋯cn−1∈R. From the condition x(0)=∫η0x(τ)dτ, we get
c0=∫η0x(τ)dτ | (2.4) |
By differentiating x(t) based on the expression in (2.3), the following relations are obtained
x′(t)=1Γ(δ−1)∫t0(t−τ)δ−2h(τ)dτ+c1+2c2t+3c3t2⋯+(n−1)cn−1tn−2, |
x″(t)=1Γ(δ−2)∫t0(t−τ)δ−3h(τ)dτ+2c2+3⋅2c3t⋯+(n−1)(n−2)cn−1tn−3, |
⋮ |
x(n−2)(t)=1Γ(δ−n+2)∫t0(t−τ)δ−n+1h(τ)dτ+(n−2)(n−3)⋯2⋅1cn−2+(n−1)(n−2)⋯2⋅1cn−1t. |
From the BCs x′(0)=x″(0)=⋯=x(n−2)(0)=0,x(1)=∫1γx(τ)dτ in (2.1), we have
c1=⋯=cn−2=0 | (2.5) |
and
cn−1=∫1γx(τ)dτ−1Γ(δ)∫10(1−s)δ−1h(τ)dτ−∫η0x(τ)dτ | (2.6) |
Combining (2.3)–(2.6) gives
x(t)=1Γ(δ)∫t0(t−τ)δ−1h(τ)dτ−tn−1Γ(δ)∫10(1−τ)δ−1h(τ)dτ+(1−tn−1)∫η0x(τ)dτ+tn−1∫1γx(τ)dτ | (2.7) |
Both sides' integration of (2.7) regarding the lower and upper bounds of 0 and η, respectively is denoted by
∫η0x(t)dt=1Γ(δ+1)∫η0(η−τ)δh(τ)dτ−ηnnΓ(δ)∫10(1−τ)δ−1h(τ)dτ+(η−1nηn)∫η0x(τ)dτ+1nηn∫1γx(τ)dτ. |
By transposing and rearranging, we can get the following from the above formula
(n+ηn−nη)∫η0x(t)dt−ηn∫1γx(τ)dτ=nΓ(δ+1)∫η0(η−τ)δh(τ)dτ−ηnΓ(δ)∫10(1−τ)δ−1h(τ)dτ | (2.8) |
Both sides' integration of (2.7) by using the lower and upper bounds γ and 1, respectively is represented by
∫1γx(t)dt=1Γ(δ+1)∫10(1−τ)δh(τ)dτ−1Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ−1−γnnΓ(δ)∫10(1−τ)δ−1h(τ)dτ |
+n+γn−nγ−1n∫η0x(τ)dτ+1−γnn∫1γx(τ)dτ. |
By transposing and rearranging, we can get the following from the above formula
(n+γn−nγ−1)∫η0x(t)dt−(n+γn−1)∫1γx(τ)dτ=nΓ(δ+1)∫γ0(γ−τ)δh(τ)dτ +1−γnΓ(δ)∫10(1−τ)δ−1h(τ)dτ−nΓ(δ+1)∫10(1−τ)δh(τ)dτ | (2.9) |
Equations (2.8) and (2.9) constitute a system with ∫η0x(τ)dτ and ∫1γx(τ)dτ as the unknown elements, and the coefficients of this system are represented by
Δ=|n+ηn−nη−ηnn+γn−nγ−1−(n+γn−1)|=−n[(n−1)+γn](1−η)−nγηn<0. |
So, using the Cramer's rule, we can get
∫η0x(t)dt=n+γn−1Δ1Γ(δ+1)∫η0(η−τ)δh(τ)dτ+ηΔ1Γ(δ+1)∫10(1−τ)δh(τ)dτ −ηnΔ1Γ(δ)∫10(1−τ)δ−1h(τ)dτ−ηnΔ1Γ(δ+1)∫γ0(1−τ)δh(τ)dτ | (2.10) |
and
∫1γx(t)dt=−n+ηn−nηΔ1Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ−(1−η)(1−γn)+(1−γ)ηnΔ1Γ(δ)∫10(1−τ)δ−1h(τ)dτ +n+ηn−nηΔ1Γ(δ+1)∫10(1−τ)δh(τ)dτ+n+γn−nγ−1Δ1Γ(δ+1)∫η0(η−τ)δh(τ)dτ | (2.11) |
where Δ1=[(n−1)+γn](1−η)+γηn>0.
The result can be derived after substituting Eqs (2.10) and (2.11) into Eq (2.7). This finishes the proof.
Banach's fixed point theorem and its subsequent theorem help to attain the main outcomes of the current article.
Lemma 2.3([45]) (The fixed point theorem by Krasnoselskii) Suppose that M is defined as a non-empty subset of a Banach space X with properties of closedness, boundedness and convexity. Moreover, consider that A and B stand for the operators meeting the subsequent requirements (a) Ax+By∈M, for x,y∈M; (b) both compactness and continuity of A exist; (c) a contraction mapping is represented by B. Now, z∈M exists such that z=Az+Bz.
This part ends with showing some fundamental understanding of the Lp space and introducing an inequality and its corresponding extended format called the Hölder's inequality [46].
Consider that an open (or measurable) set is denoted by V⊂Rn and a measurable mapping of real numbers defined on V is denoted by g(x). |g(x)|p turns out to be measurable on V for 1≤p<∞ and ∫V|g(x)|pdx is meaningful. Now, we introduce a function space Lp(V) as follows:
Lp(V)={g(x)|g(x) is measurable on V, ∫V|g(x)|pdx<∞}. |
For g∈Lp(V), the upcoming norm is defined
∥g∥p=(∫V|g(x)|pdx)1/p. |
1<p1 and p2<∞ are called conjugate exponentials of each other if 1p1+1p2=1.
Lemma 2.4([46]) (Hölder's inequality) Consider that V⊂Rn is an open set, p1 and p2 are conjugate exponentials, g(x)∈Lp1(V),h(x)∈Lp2(V) and g(x)h(x) is integrable on V, while the following equality holds
∫V∣g(x)h(x)∣dx≤∥g∥p1∥g∥p2. |
The mentioned result is extended as
∫V∣g1(x)⋯gn(x)∣dx≤∥g1∥p1⋯∥gn∥pn, |
where gi(x)∈Lpi(V) and ∑ni=11pi=1. The above expression is just called the generalized Hölder's inequality.
Suppose that E=C([0,1],R) encompasses continuous function space on interval [0,1]. Now, a Banach space is denoted by X=(E,∥⋅∥), where ∥⋅∥ is the maximum norm ∥x∥ = maxt∈[0,1]∣x(t)∣ with x(t)∈E.
Define an operator ϕ:X→X as
(ϕx)(t)=1Γ(δ)∫t0(t−τ)δ−1f(τ,x(τ))dτ+a+btn−1Γ(δ)∫10(1−τ)δ−1f(τ,x(τ))dτ+c+dtn−1Γ(δ+1)∫10(1−τ)δf(τ,x(τ))dτ+e+ftn−1Γ(δ+1)∫η0(η−τ)δf(τ,x(τ))dτ+a+btn−1Γ(δ+1)∫γ0(γ−τ)δf(τ,x(τ))dτ | (3.1) |
There exists equality between the solutions of the problem (1.1) and the fixed points regarding the operator ϕ. This paper presents the following assumptions that are put on f(t,x(t)) that appears in (1.1) in the sequel.
(H1) Both t=0 and t=1 lead to a singular f(t,x(t)) which satisfies
limt→0+f(t,⋅)=∞,limt→1−f(t,⋅)=∞. |
Besides, there are two constants σ1>0 and σ2>0, where tσ1(1−t)σ2f(t,x(t)) is a continuous function in [0,1].
By the assumption of (H1), it can be deduced that a number N0 exists and meets
|tσ1(1−t)σ2f(t,x(t))|≤N0 | (3.2) |
where t∈[0,1] and x(t)∈E. Throughout the rest of this article, we always employ s,s1 and s2 to represent any set of real numbers that meet the following conditions
(H2) (i) s>1,s1>1,s2>1; (ii) 1s+1s1+1s2=1; (iii) 0<s1σ1<1,0<s2σ2<1.
Accordingly, avoiding excessive conjugate exponent notations is possible while using the generalized Hölder's inequality in different contexts.
Lemma 3.1 Assume that 1≤n−1<δ≤n, and s,s1,s2,σ1 and σ2 are positive constants satisfying (H2). Define an operator Kl(t) for some real number l≥1 as
Kl(t)=∫t0(t−τ)lτ−θ1(1−τ)−θ2dτ,t∈[0,1]. |
Then, the following results are valid:
(1)limt→0+Kl(t)=0;
(2)Kl(t)≤1s√1+sl1s1√1−s1σ11s2√1+s2σ2for any t∈[0,1];
(3)For any t1,t2∈[0,1],∣Kl(t1)−Kl(t2)∣<ls√1+s(l−1)1s1√1−s1σ11s2√1+s2σ2∣t1−t2∣.
Proof (1) Recall Lemma 3.2 in [44].
(2) According to the generalized Hölder's inequality, one obtains
Kl(t)=∫t0(t−τ)lτ−θ1(1−τ)−θ2dτ≤[∫t0(t−τ)sldτ]1/s[∫t0τ−s1σ1dτ]1/s1[∫t0(1−τ)−s2σ2dτ]1/s2≤1s√1+sls√t1+sl1s1√1−s1σ1s1√t1−s1σ11s2√1−s2σ2s2√1−(1−t)1−s2σ2≤1s√1+sl1s1√1−s1σ11s2√1−s2σ2. |
(3) Deriving the function Kl(t) and using the generalized Hölder's inequality, one can obtain
K′l(t)=l∫t0(t−τ)l−1τ−θ1(1−τ)−θ2dτ≤l[∫t0(t−τ)s(l−1)dτ]1/s[∫t0τ−s1σ1dτ]1/s1[∫t0(1−τ)−s2σ2dτ]1/s2≤ls√1+s(l−1)s√t1+s(l−1)1s1√1−s1σ1s1√t1−s1σ11s2√1−s2σ2s2√1−(1−t)1−s2σ2≤ls√1+s(l−1)1s1√1−s1σ11s2√1−s2σ2. |
By the mean value theorem, we have
∣Kl(t1)−Kl(t2)∣≤K′l(ξ)∣t1−t2∣≤ls√1+s(l−1)1s1√1−s1σ11s2√1+s2σ2∣t1−t2∣, |
where ξ is a number between t1 and t2.
Lemma 3.2 Assume that 1≤n−1<δ≤n and a function h(t):(0,1)→R is continuous and satisfying limt→0+h(t)=∞ and limt→1−h(t)=∞. A new function H(t) is defined as
H(t)=1Γ(δ)∫t0(t−τ)δ−1h(τ)dτ+a+btn−1Γ(δ)∫(01−τ)δ−1h(τ)dτ+c+dtn−1Γ(δ+1)∫10(1−τ)δh(τ)dτ+e+ftn−1Γ(δ+1)∫η0(η−τ)δh(τ)dτ+a+btn−1Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ. |
Then the continuity of tσ1(1−t)σ2h(t) on [0,1] leads H(t) to be continuous in [0,1].
Proof Since tσ1(1−t)σ2h(t) is a continuous mapping in [0,1], there is a positive constant N1 that satisfies |tσ1(1−t)σ2h(t)|≤N1.
According to the definition of H(t), we have
H(0)=aΓ(δ)∫10(1−τ)δ−1h(τ)dτ+cΓ(δ+1)∫10(1−τ)δh(τ)dτ+eΓ(δ+1)∫η0(η−τ)δh(τ)dτ+aΓ(δ+1)∫γ0(γ−τ)δh(τ)dτ. |
For any t′∈[0,1],H(t) is continuous and t′ will be proven.
(Ⅰ) For t′=0 and t∈[0,1], the following equality is attained.
∣H(t)−H(0)∣=∣1Γ(δ)∫t0(t−τ)δ−1h(τ)dτ+btn−1Γ(δ)∫10(1−τ)δ−1h(τ)dτ+dtn−1Γ(δ+1)∫10(1−τ)δh(τ)dτ+ftn−1Γ(δ+1)∫η0(η−τ)δh(τ)dτ+btn−1Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ∣≤N1Γ(δ)∫t0(t−τ)δ−1τ−σ1(1−τ)−σ2dτ+|b|N1tn−1Γ(δ)∫10(1−τ)δ−1τ−σ1(1−τ)−σ2dτ+|d|N1tn−1Γ(δ+1)∫10(1−τ)δτ−σ1(1−τ)−σ2dτ+|f|N1tn−1Γ(δ+1)∫η0(η−τ)δτ−σ1(1−τ)−σ2dτ+|b|N1tn−1Γ(δ+1)∫γ0(γ−τ)δτ−σ1(1−τ)−σ2dτ≤N1Γ(δ)Kδ−1(t)+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)Γ(δ+1)+|f|Kδ(η)Γ(δ+1)+|b|Kδ(γ)Γ(δ+1)]tn−1. |
Thus, by the results (1) and (2) in Lemma 3.1, we have ∣H(t)−H(0)∣→0 as t→t′=0 that is
limt→0+H(t)=H(0). |
(Ⅱ) For each t′∈(0,1] and t∈[0,1],t′≠t, one can obtain
∣H(t)−H(t′)∣=∣1Γ(δ)[∫t0(t−τ)δ−1h(τ)dτ−∫t′0(t′−τ)δ−1h(τ)dτ]+b(tn−1−t′n−1)Γ(δ)∫10(1−τ)δ−1h(τ)dτ+d(tn−1−t′n−1)Γ(δ+1)∫10(1−τ)δh(τ)dτ+f(tn−1−t′n−1)Γ(δ)∫η0(η−τ)δh(τ)dτ+b(tn−1−t′n−1)Γ(δ+1)∫γ0(γ−τ)δh(τ)dτ∣≤1Γ(δ)∣∫t′0(t′−τ)δ−1h(τ)dτ−∫t0(t−τ)δ−1h(τ)dτ∣+|b|N1|tn−1−t′n−1|Γ(δ)∫10(1−τ)δ−1τ−σ1(1−τ)−σ2dτ+|d|N1|tn−1−t′n−1|Γ(δ+1)∫10(1−τ)δτ−σ1(1−τ)−σ2dτ+|f|N1|tn−1−t′n−1|Γ(δ+1)∫η0(η−τ)δτ−σ1(1−τ)−σ2dτ+|b|N1|tn−1−t′n−1|Γ(δ+1)∫γ0(γ−τ)δτ−σ1(1−τ)−σ2dτ≤1Γ(δ)∣∫t0[(t′−τ)δ−1−(t−τ)δ−1]h(τ)dτ+∫t′t(t′−τ)δ−1h(τ)dτ∣+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)+|f|Kδ(η)+|b|Kδ(γ)Γ(δ+1)]|tn−1−t′n−1|≤N1Γ(δ)∣∫t0[(t′−τ)δ−1−(t−τ)δ−1]τ−σ1(1−τ)−σ2dτ+∫t′t(t′−τ)δ−1τ−σ1(1−τ)−σ2dτ∣+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)+|f|Kδ(η)+|b|Kδ(γ)Γ(δ+1)]|tn−1−t′n−1|=N1Γ(δ)∣∫t′0(t′−τ)δ−1τ−σ1(1−τ)−σ2dτ−∫t0(t−τ)δ−1τ−σ1(1−τ)−σ2dτ∣+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)+|f|Kδ(η)+|b|Kδ(γ)Γ(δ+1)]|tn−1−t′n−1|=N1Γ(δ)∣Kδ−1(t′)−Kδ−1(t)∣+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)+|f|Kδ(η)+|b|Kδ(γ)Γ(δ+1)]|tn−1−t′n−1|. |
By the results (2) and (3) in Lemma 3.1, one can obtain
∣H(t)−H(t′)∣≤N1Γ(δ)ls√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2|t′−t|+N1[|b|Kδ−1(1)Γ(δ)+|d|Kδ(1)+|f|Kδ(η)+|b|Kδ(γ)Γ(δ+1)]|tn−1−t′n−1|→0 |
when t→t′, and this means that
limt→t′H(t)=H(t′). |
Since t′ is any point in [0,1], we prove the assertion of Lemma 3.2.
Theorem 3.1 Assume that 1≤n−1<δ≤n,σ1>0 and σ2>0 are constants; (H1) and the subsequent assumption are satisfied by f(t,x(t)):
(H3) m(t)∈C([0,1],R) is a mapping such that
tσ1(1−t)σ2∣f(t,x(t))−f(t,y(t))∣≤∣m(t)∣∣x(t)−y(t)∣. |
Assume that the condition (H2) and the subsequent inequality are fulfilled
∥m∥{1+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]}<1 | (3.3) |
Now, a unique solution regarding the ([0,1],R) space is possessed for the problem (1.1).
Proof For every x,y∈X=(C[0,1],R), the second assertion of Lemma 3.1 and the generalized Hölder's inequality can be deduced by (H3)
∣(ϕx)(t)−(ϕy)(t)∣≤1Γ(δ)∫t0(t−τ)δ−1∣f(τ,x(τ))−f(τ,y(τ))∣dτ |
+∣a∣+∣b∣Γ(δ)∫10(1−τ)δ−1∣f(τ,x(τ))−f(τ,y(τ))∣dτ+∣c∣+∣d∣Γ(δ+1)∫10(1−τ)δ∣f(τ,x(τ))−f(τ,y(τ))∣dτ |
+∣e∣+∣f∣Γ(δ+1)∫η0(η−τ)δ∣f(τ,x(τ))−f(τ,y(τ))∣dτ+∣a∣+∣b∣Γ(δ+1)∫γ0(γ−τ)δ∣f(τ,x(τ))−f(τ,y(τ))∣dτ≤1Γ(δ)∫t0(t−τ)δ−1τ−σ1(1−τ)−σ2∣m(τ)∣∣x(τ)−y(τ)∣dτ+∣a∣+∣b∣Γ(δ)∫10(1−τ)δ−1τ−σ1(1−τ)−σ2∣m(τ)∣∣x(τ)−y(τ)∣dτ+∣c∣+∣d∣Γ(δ+1)∫10(1−τ)δτ−σ1(1−τ)−σ2∣m(τ)∣∣x(τ)−y(τ)∣dτ+∣e∣+∣f∣Γ(δ+1)∫η0(η−τ)δτ−σ1(1−τ)−σ2∣m(τ)∣∣x(τ)−y(τ)∣dτ+∣a∣+∣b∣Γ(δ+1)∫γ0(γ−τ)δτ−σ1(1−τ)−σ2∣m(τ)∣∣x(τ)−y(τ)∣dτ≤‖m(τ)‖‖x(τ)−y(τ)‖{1Γ(δ)Kδ−1(t)+∣a∣+∣b∣Γ(δ)Kδ−1(1)+∣c∣+∣d∣Γ(δ+1)Kδ(1)+∣e∣+∣f∣Γ(δ+1)[∫η0(η−τ)sδdτ]1/s[∫η0τ−s1σ1dτ]1/s1[∫η0(1−τ)−s2σ2dτ]1/s2+∣a∣+∣b∣Γ(δ+1)[∫γ0(γ−τ)sδdτ]1/s[∫γ0τ−s1σ1dτ]1/s1[∫γ0(1−τ)−s2σ2dτ]1/s2}≤‖m(τ)‖‖x(τ)−y(τ)‖{1Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+∣c∣+∣d∣Γ(δ+1)1s√1+s(δ)1s1√1−s1σ11s2√1−s2σ2+∣e∣+∣f∣Γ(δ+1)1s√1+sδs√η1+sδ1s1√1−s1σ1s1√η1−s1σ11s2√1−s2σ2s2√1−(1−η)1−s2σ2+∣a∣+∣b∣Γ(δ+1)1s√1+sδs√γ1+sδ1s1√1−s1σ1s1√γ1−s1σ11s2√1−s2σ2s2√1−(1−γ)1−s2σ2}≤∥m∥{1+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]}⋅‖x(τ)−y(τ)‖. |
The condition (3.3) ensures that the operator ϕ is a contractive mapping. Accordingly, Banach's fixed-point theorem indicates that ϕ possesses a unique fixed-point that is equal to the problem (1.1) unique solution.
Theorem 3.2 Suppose that 1≤n−1<δ≤n,σ1>0 and σ2>0 are constants; both (H1) and (H3) are satisfied by f(t,x(t)). Assume that (H2) and the subsequent inequality are true
∥m∥{∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]}<1 | (3.4) |
Now, the interval ([0,1],R) contains at least one solution for the problem (1.1).
Proof Take a constant L satisfying
N0{1+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2 |
⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2 |
+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]}≤L. |
The number N0 is defined in (3.2).
The set BL={x∈X=C([0,1],∣∥x∥≤L} is a ball in X. Define two operators ϕ1 and ϕ2 on BL as
(ϕ1x)(t)=1Γ(δ)∫t0(t−τ)δ−1f(τ,x(τ))dτ,(ϕ2x)(t)=a+btn−1Γ(δ)∫10(1−τ)δ−1f(τ,x(τ))dτ+c+dtn−1Γ(δ+1)∫10(1−τ)δf(τ,x(τ))dτ+e+ftn−1Γ(δ+1)∫η0(η−τ)δf(τ,x(τ))dτ+a+btn−1Γ(δ+1)∫γ0(γ−τ)δf(τ,x(τ))dτ. |
For any x,y∈BL, the following relation can be obtained by taking a process similar to Theorem 3.1:
∥ϕ1x+ϕ2∥≤N0Γ(δ)∫t0(t−τ)δ−1τ−σ1(1−τ)−σ2dτ+(∣a∣+∣b∣)N0Γ(δ)∫10(1−τ)δ−1τ−σ1(1−τ)−σ2dτ+(∣c∣+∣d∣)N0Γ(δ+1)∫10(1−τ)δτ−σ1(1−τ)−σ2dτ+(∣e∣+∣f∣)N0Γ(δ+1)∫η0(η−τ)δτ−σ1(1−τ)−σ2dτ+(∣a∣+∣b∣)N0Γ(δ+1)∫γ0(γ−τ)δτ−σ1(1−τ)−σ2dτ≤N0{1+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]}≤L. |
This means that ϕ1x+ϕ2y∈BL.
The operator ϕ2 is a contractive mapping deduced from (H1)–(H3) and (3.4) with a process similar to Theorem 3.1.
The operator ϕ1 is continuous in BL by (H1) and Lemma 3.2. ϕ1 is uniformly bounded on BL since the following inequality is true
∥ϕ1x∥≤N0Γ(δ)Kδ−1(t)≤N0Γ(δ)ls√1+s(δ−1)1s1√1−s1σ1ls2√1−s2σ2, |
where x∈BL.
For every t1,t2∈[0,1] and t1<t2, one can obtain
∣(ϕ1x)(t2)−(ϕ2x)(t1)∣=1Γ(δ)∣∫t20(t2−τ)δ−1f(τ,x(τ))dτ−∫t10(t1−τ)δ−1f(τ,x(τ))dτ∣≤N0Γ(δ){∫t10[(t2−τ)δ−1−(t1−τ)δ−1]τ−σ1(1−τ)−σ2dτ+∫t2t1(t2−τ)δ−1τ−σ1(1−τ)−σ2dτ}≤N0Γ(δ)[Kδ−1(t2)−Kδ−1(t1)]. |
By the third assertion in Lemma 3.1, we have
∣(ϕ1x)(t2)−(ϕ2x)(t1)∣≤N0Γ(δ)ls√1+s(δ−1)1s1√1−s1σ1ls2√1−s2σ2∣t2−t1∣. |
Thus, both the equicontinuity and relative compactness of ϕ1 on BL are attained. The Arzelà-Ascoli theorem ensures that the operator ϕ1 is compact in BL. Therefore, the existence of a solution in ([0,1],R) is ensured by Lemma 2.3.
The current section introduces an example to verify the efficiency of the fundamental outcomes in the current article.
Example 4.1 Assume the upcoming fractional BVP:
{cD2.50+x(t)=sinrx12√t⋅20√1−t,0<t<1,x(0)=∫130x(τ)dτ,x′(0)=0,x(1)=∫10.5x(τ)dτ. | (4.1) |
In this BVP, f(t,x)=sinrx12√t⋅20√1−t,r≥1 is a real number, δ=2.5, n=3,η=13,γ=12. Take σ1=σ2=110; we have
t110(1−t)110∣f(t,x(t))−f(t,y(t))∣=t160(1−t)120∣sinrx−sinry∣≤rt160(1−t)120∣x−y∣. |
Thus, m(t)=rt160(1−t)120,t∈[0,1] and ∥m∥=max0≤t≤1∣m(t)∣=r60√14(34)3≈0.9627r.
Now, the following values can be obtained:
Δ1=261108,a=−4261,b=−216261,c=36261,d=184261,e=459522,f=−5487, |
Γ(2.5)≈1.3293,Γ(1+2.5)≈3.3233. |
Take conjugate exponentials s,s1 and s2 when s=43 and s1=s2=8. Then, we can calculate
∥m∥{1+∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2 |
⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2 |
+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]} |
≈0.9627r×0.4793+0.0636×[0.8589+2.0455]≈0.6393r. |
And
∥m∥{∣a∣+∣b∣Γ(δ)1s√1+s(δ−1)1s1√1−s1σ11s2√1−s2σ2+1Γ(δ+1)1s√1+sδ1s1√1−s1σ11s2√1−s2σ2 |
⋅[∣c∣+∣d∣+(∣e∣+∣f∣)s√η1+sδs1√η1−s1σ1s2√1−(1−η)1−s2σ2 |
+(∣a∣+∣b∣)s√γ1+sδs1√γ1−s1σ1s2√1−(1−γ)1−s2σ2]} |
≈0.9627r×0.2102+0.0636×[0.8589+2.0455]≈0.3802r. |
Thus, we can deduce the following:
(a1) When 0.6393r<1, or 1≤r<1.5642, a unique solution in [0,1] for the problem (4.1) is possessed by Theorem 3.1.
(a2) When 0.3802r<1, or 1≤r<2.63019, Theorem 3.2 guarantees that the problem (4.1) attains solutions on the interval [0,1].
This work dealt with the existence results for a category of singular nonlinear FDEs with nonlocal double integral BCs. The results we obtained depended on the parameters that appeared in the integral BCs, this is due to the use of the generalized Hölder's inequality. So the type of problems, conclusions and methods discussed in this paper complemented the existing literature.
The author wishes to express his sincere appreciation to the editors, reviewers and the anonymous referees for their valuable comments and suggestions.
The author declares that there is no conflict of interest.
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