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Asymptotic behavior of the one-dimensional compressible micropolar fluid model

  • In this paper, we study the large time behavior of the solution for one-dimensional compressible micropolar fluid model with large initial data. This model describes micro-rotational motions and spin inertia which is commonly used in the suspensions, animal blood, and liquid crystal. We get the uniform positive lower and upper bounds of the density and temperature independent of both space and time. In particular, we also obtain the asymptotic behavior of the micro-rotation velocity.

    Citation: Haibo Cui, Junpei Gao, Lei Yao. Asymptotic behavior of the one-dimensional compressible micropolar fluid model[J]. Electronic Research Archive, 2021, 29(2): 2063-2075. doi: 10.3934/era.2020105

    Related Papers:

    [1] Haibo Cui, Junpei Gao, Lei Yao . Asymptotic behavior of the one-dimensional compressible micropolar fluid model. Electronic Research Archive, 2021, 29(2): 2063-2075. doi: 10.3934/era.2020105
    [2] Zhi-Ying Sun, Lan Huang, Xin-Guang Yang . Exponential stability and regularity of compressible viscous micropolar fluid with cylinder symmetry. Electronic Research Archive, 2020, 28(2): 861-878. doi: 10.3934/era.2020045
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  • In this paper, we study the large time behavior of the solution for one-dimensional compressible micropolar fluid model with large initial data. This model describes micro-rotational motions and spin inertia which is commonly used in the suspensions, animal blood, and liquid crystal. We get the uniform positive lower and upper bounds of the density and temperature independent of both space and time. In particular, we also obtain the asymptotic behavior of the micro-rotation velocity.



    In this paper, we consider the one-dimensional compressible micropolar fluid model in Lagrange coordinates:

    {vt=ux,ut+Px=μ(uxv)x,wt+νvw=λ(wxv)x,(e+u22)t+(Pu)x=(μuuxv+kθxv)x+νvw2+λw2xv,e=cvθ,P=Rθv, (1.1)

    where t>0 is time, xΩR denotes the Lagrange mass coordinate, v=v(x,t)>0, u=u(x,t), w=w(x,t), θ=θ(x,t)>0, e and P, which represent the specific volume, fluid velocity, micro-rotation velocity, absolute temperature, internal energy and pressure, respectively. Moreover, μ>0 is the viscosity coefficient, κ>0 is the heat conductivity coefficient, R>0 is the specific gas constant, ν>0 and λ>0 are the coefficients of micro-viscosity, cv is the heat capacity at constant volume. The model of micropolar fluid was first introduced by Eringen [7] in 1966. This model can be used to describe the motions of a large variety of complex fluids consisting of dipole elements such as the suspensions, animal blood, liquid crystal, etc. For more physical background on this model, we can refer to [8,15].

    When w=0, the system (1.1) reduces to the standard compressible Navier-Stokes equations. It has attracted great interest among many analysts and there have been many important developments. Kazhikhov and Shelukhin [12] firstly obtained the global existence of solutions in bounded domains for large initial data. Then, Jiang [10,11] studied the large-time behavior of solutions to the compressible Navier-Stokes system in unbounded domains for large initial data. He proved the specific vomule was pointwise bounded from below and above independent of both space and time. Recently, Li and Liang [13] proved the large-time behavior of solutions to the initial and initial boundary value problems with large initial data. They showed that the temperature was bounded from below and above independent of both space and time. See also [5] for the spherically symmetric and cylindrically symmetric non-barotropic flows.

    When w0, we get the micropolar fluid model. Now more and more mathematicians devoted to the research of micropolar fluid model (1.1). For the incompressible fluid, we refer to [3] and references therein. For the complete fluid, Mujakovic [16,17] obtained a series of results about the local, global in time existence theorem and regularity of solutions for the model with homogeneous boundary condition in one dimension. Next, Chen [2] proved the global existence of strong solutions for the initial boundary problem in one dimension that vacuum can be allowed initially. Yin [19] established the stationary solutions to the inflow problem in a half-line, the time asymptotically stability for the H1 solutions was also obtained. Recently, Cui and Yin [6] obtained the convergence rates of global solutions toward corresponding stationary solutions if the initial perturbation belongs to the weighted Sobolev space. Qin et al. [18] studied the global existence and asymptotic behavior of H1 solutions to the Cauchy problem of one-dimensional model with the weighted small initial data. Based on the assumption κ(θ)=O(1)(1+θq) with q0, Feng and Zhu [9] considered the existence of global classical solution with large initial data and vacuum. For three-dimensional micropolar fluid model, Chen et al. [4] gave the global weak solutions with discontinuous initial data and vacuum. Liu and Zhang [14] obtained the optimal time decay of the 3-dimensional compressible micropolar fluid model.

    In this paper, motivated by the result of [13], we get asymptotic behavior of the one-dimensional compressible micropolar fluid model with large initial data. We supplement the system (1.1) with the initial condition

    (v,u,w,θ)|t=0=(v0,u0,w0,θ0), (1.2)

    and three types of far-field and boundary conditions:

    (1) Cauchy problem

    Ω=R,  lim|x|(v(x,t),u(x,t),w(x,t),θ(x,t))=(1,0,0,1),t>0; (1.3)

    (2) Boundary and far-field conditions for Ω=(0,)

    u(0,t)=0,   θx(0,t)=0,  limx(v(x,t),u(x,t),w(x,t),θ(x,t))=(1,0,0,1),t>0; (1.4)

    (3) Boundary and far-field conditions for Ω=(0,)

    u(0,t)=0,   θ(0,t)=1,  limx(v(x,t),u(x,t),w(x,t),θ(x,t))=(1,0,0,1),t>0. (1.5)

    We now state the main result of this paper as follows:

    Theorem 1.1. Consider the initial value problem given by (1.1)-(1.3), and initial-boundary value problem given by (1.1), (1.2), (1.4) and (1.1), (1.2), (1.5). Assume that v0(x)>0, θ0(x)>0, v01, u0, w0, θ01 H1(Ω) and the initial data are compatible with boundary conditions. Then there exists a unique global strong solution (v,u,w,θ)C([0,),H1(Ω)), (v1,u,w,θ1)L([0,),H1(Ω)), and there exists positive constants C1 and C depending only on μ, κ, R, cv, ν satisfying

    1C1v(x,t)C1, (1.6)
    1Cθ(x,t)C, (1.7)

    and for any t0, p>2

    limt((v1,u,w,θ1)(t)Lp(Ω)+(vx,ux,wx,θx)(t)L2(Ω))=0.

    Remark 1. Compared with the work [13], we have to deal with the strong couple of the micro-rotation velocity w and the fluid motion, which will lead to some difficulties. In particular, we solve it by obtaining some new estimates (2.16), (2.31). We also obtain the asymptotic behavior of w(x,t).

    Lemma 2.1. (Energy inequality) Under the conditions of Theorem 1.1, the following inequality holds

    sup0t<Ω(12u2+12w2+R(vlnv1)+cv(θlnθ1))dx+0Ω(μu2xvθ+κθ2xvθ2+λw2xvθ+νvw2θ)dxdsC0, (2.1)
    0<α1i+1ivdxα2,0<α1i+1iθdxα2, (2.2)

    and there are ai(t),bi(t)[i,i+1] satisfying

    α1v(ai(t),t)α2,α1θ(bi(t),t)α2, (2.3)

    where α1,α2 are two positive roots of the equation ylny1=C0min{R,cv}, iN for the initial boundary value problems and iZ for the Cauchy problem.

    Proof. The above estimates can been obtained by the similar arguments as that in [10].

    Lemma 2.2. Under the conditions of Theorem 1.1, there holds

    sup0t<Ω12w2dx+0Ω(λw2xv+νvw2)dxdsΩ12w20dx, (2.4)

    and

    sup0t<Ω14w4dx+0Ω(λw2w2xv+νvw4)dxdsΩ14w40dx. (2.5)

    Proof. Multiplying (1.1)3 by w, using the boundary condition of w, one directly gets (2.4).

    Multiplying (1.1)3 by w3, using the boundary condition of w, one gets (2.5).

    In this subsection, the specific volume v(x,t) is proved to be bounded from below and above, independent of both time and space.

    Lemma 2.3. Under the hypotheses of Theorem 1.1, it holds that

    0<C11v(x,t)C1. (2.6)

    For more detailed proof of Lemma 2.3, refer to [5,10,11] and references therein.

    Lemma 2.4. Under the conditions of Theorem 1.1, let (v,u,w,θ) be a solution to the system (1.1) on Ω×[0,T], it holds for any T>0

    Ω(|θ1|2+u2θ+w2θ+u4)dx+T0Ω(θ2x+u2xθ+w2xθ+w2θ+u2u2x)dxdsC. (2.7)

    Proof. Motivated by [13], the proof will be divided into three steps.

    Step 1. At first, for any t0 and a>1, denoting

    Ωa(t){xΩ|θ(x,t)>a},

    and we derive from (2.1) that

    sup0t<Ωa(t)θC(a)sup0t<Ω(θlnθ1)C(a).

    Using (1.1)1, (1.1)3, (1.1)5, we rewrite (1.1)4 as

    cvθt+Rθuxv=(κθxv)x+μu2xv+νvw2+λw2xv. (2.8)

    Multiplying (2.8) by (θ2)+=sup{θ2,0} and integrating the result over Ω×[0,T], we have

    cv2Ω(θ2)2+dx+κT0Ω2(s)θ2xvdxds=cv2Ω(θ02)2+dxRT0Ωθuxv(θ2)+dxds+μT0Ωu2xv(θ2)+dxds+λT0Ωw2xv(θ2)+dxds+νT0Ωvw2(θ2)+dxds. (2.9)

    Next, multiplying (1.1)2 by 2u(θ2)+ and integrating the result over Ω×[0,T], we obtain

    Ωu2(θ2)+dx+2μT0Ωu2xv(θ2)+dxds=Ωu20(θ02)+dx+2RT0Ωθuxv(θ2)+dxds+2RT0Ω2(s)θuθxvdxds2μT0Ω2(s)uuxθxvdxds+T0Ω2(s)u2θsdxds. (2.10)

    Then multiplying (1.1)3 by 2w(θ2)+ and integrating the result over Ω×[0,T], yields

    Ωw2(θ2)+dx+2λT0Ωw2xv(θ2)+dxds+2νT0Ωvw2(θ2)+dxds=Ωw20(θ02)+dx2λT0Ω2(s)wwxθxvdxds+T0Ω2(s)w2θsdxds.

    Adding the above three integral expressions together and using (2.8) to get

    Ω(cv2(θ2)2++u2(θ2)++w2(θ2)+)dx+κT0Ω2(s)θ2xvdxds+μT0Ωu2xv(θ2)+dxds+λT0Ωw2xv(θ2)+dxds+νT0Ωvw2(θ2)+dxds=Ω(cv2(θ02)2++u20(θ02)++w20(θ02)+)dx+RT0Ωθuxv(θ2)+dxds+2RT0Ω2(s)θuθxvdxds2μT0Ω2(s)uuxθxvdxds+1cvT0Ω2(s)u2(μu2xvRθuxv)dxds+κcvT0Ω2(s)u2(θxv)xdxdsλcvT0Ω2(s)u2w2xvdxds+νcvT0Ω2(s)vu2w2dxds+λcvT0Ω2(s)w2w2xvdxds+1cvT0Ω2(s)w2(μu2xvRθuxv)dxds+κcvT0Ω2(s)w2(θxv)xdxds+νcvT0Ω2(s)vw4dxds2λT0Ω2(s)wwxθxvdxds=:Ω(cv2(θ02)2++u20(θ02)++w20(θ02)+)dx+12j=1Ij. (2.11)

    Now the main task is to estimate I1,I2,I3......,I12 term by term.

    For I1, using Cauchy inequality and (2.6), one obtains

    |I1|=R|T0Ωθuxv(θ2)+dxds|ϵT0Ω2(s)u2xv(θ2)+dxds+C(ϵ)T0Ωθ2(θ2)+dxds
    ϵT0Ω2(s)u2xv(θ2)+dxds+C(ϵ)T0supΩ(θ32)2+ds.

    It follows from Cauchy inequality and (2.6) that for any ϵ>0

    |I2|=R|T0Ω2(s)θuθxvdxds|ϵT0Ω2(s)θ2xdxds+C(ϵ)T0Ω2(s)u2θ2dxdsϵT0Ωθ2xdxds+C(ϵ)T0supΩ(θ32)2+ds,

    where we have used the fact that

    T0Ω2(s)u2θ2dxds16T0Ωu2(θ32)2+dxdsCT0supΩ(θ32)2+ds. (2.12)

    Then for I3, it follows from Cauchy inequality and (2.12)

    |I3|=2μ|T0Ω2(s)uuxθxvdxds|ϵT0Ωθ2xdxds+C(ϵ)T0Ωu2u2xdxds.

    For I4,

    |I4|CT0Ωu2u2xdxds+CT0supΩ(θ32)2+ds.

    For any η>0, set

    χη(θ)={0, θ2,θ2η,2θη+2,2,θη+2.

    For I5, we immediately get for any ϵ>0

    I5=κcvT0Ωlimη0χη(θ)u2(θxv)xdxds=limη0κcvT0Ω(2χη(θ)uuxθxvχη(θ)u2θ2xv)dxdsϵT0Ωθ2xdxds+C(ϵ)T0Ωu2u2xdx.

    It follows from Cauchy inequality that

    |I6|+|I7|CT0Ωu2w2xdxds+CT0Ωu2w2dxds.

    For I8,

    |I8|CT0Ωu2xw2dxds+CT0Ω2(s)w2θ2dxdsCT0Ωu2xw2dxds+CT0supΩ(θ32)2+ds.

    For I9, using (2.5), we have

    I9=κcvT0Ωlimη0χη(θ)w2(θxv)xdxds=limη0κcvT0Ω(2χη(θ)wwxθxvχη(θ)w2θ2xv)dxdsϵT0Ω2(s)θ2xdxds+CT0Ωw2w2xdxdsϵT0Ω2(s)θ2xdxds+C.

    For the terms I10-I12, it follows from Cauchy inequality that

    |I10|+|I11|C,

    and

    |I12|ϵT0Ωθ2xdxds+C.

    Noticing that

    T0Ω(θ2x+u2xθ+w2xθ+w2θ)dxds=T0Ω3(s)(θ2x+u2xθ+w2xθ+w2θ)dxds+T0ΩΩ3(s)(θ2x+u2xθ+w2xθ+w2θ)dxds3T0Ω3(s)(θ2x+u2x(θ2)++w2x(θ2)++w2(θ2)+)dxds+CT0Ω(μu2xvθ+κθ2xvθ2+λw2xvθ+νvw2θ)dxdsCT0Ω2(s)(κθ2xv+μu2xv(θ2)++λw2xv(θ2)++νvw2(θ2)+)dxds+C.

    Then

    Ω(cv2(θ2)2++u2(θ2)++w2(θ2)+)dx+T0Ω(θ2x+u2xθ+w2xθ+w2θ)dxdsC+CT0Ωu2u2xdx+CT0supΩ(θ32)2+ds+CT0Ωu2w2xdxds+CT0Ωu2w2dxds+CT0Ωu2xw2dx. (2.13)

    Step 2. Multiplying (1.1)3 by 2u2w and integrating the result over Ω×[0,T], we have

    Ωu2w2dx+2λT0Ωu2w2xvdxds+2νT0Ωvu2w2dxds=Ωu20w20dx4λT0Ωuuxwwxvdxds+2T0Ωuusw2dxds.

    Using (1.1)2, we obtain

    Ωu2w2dx+2λT0Ωu2w2xvdxds+2νT0Ωvu2w2dxds+2μT0Ωu2xw2vdxds=Ωu20w20dx4λT0Ωuuxwwxvdxds4μT0Ωuuxwwxvdxds
    +2RT0Ωθuxw2vdxds+4RT0Ωuθwwxvdxds=:Ωu20w20dx+4j=1Jj. (2.14)

    What's more, it follows from (2.1) and (2.6) that for any α[2,3],

    sup0tTΩ(v1)2dx+sup0tTΩΩα(θ1)2dxCsup0tTΩ(vlnv1)dx+Csup0tTΩ(θlnθ1)dxC. (2.15)

    Then we can estimate Jj(j=1,2,3,4),

    |J1|+|J2|CT0Ωu2u2xdxds+CT0Ωw2w2xdxdsCT0Ωu2u2xdxds+C,
    |J3|μT0Ωu2xw2vdx+CT0Ω2(s)w2θ2dxdsμT0Ωu2xw2vdx+CT0Ω2(s)w2θ2dxds+CT0ΩΩ2(s)w2θ2dxdsμT0Ωu2xw2vdx+CT0supΩ(θ32)2+ds+C,

    and

    |J4|λT0Ωu2w2xvdx+CT0Ω2(s)w2θ2dxds+CT0ΩΩ2(s)w2θ2dxdsλT0Ωu2w2xvdx+CT0supΩ(θ32)2+ds+C.

    Therefore, we have

    Ωu2w2dx+T0Ω(u2w2x+u2w2+u2xw2)dxdsC+CT0Ωu2u2xdxds+CT0supΩ(θ32)2+ds. (2.16)

    And similarly,

    sup0t<Ωu4dx+0Ωu2u2xdxdsC+CδT0Ωθu2xdxds+CT0supΩ(θ32)2+ds.

    Adding all the above inequalities, one obtains

    Ω(cv2(θ2)2++u2(θ2)++w2(θ2)++u4)dx+T0Ω(θ2x+u2xθ+w2xθ+w2θ+u2u2x)dxdsC+CT0supΩ(θ32)2+ds. (2.17)

    Step 3. We estimate the last term on the right hand side of (2.17).

    T0supΩ(θ32)2+dsC(ϵ)+ϵT0Ωθ2xdxds. (2.18)

    Then

    Ω(cv2(θ2)2++u2(θ2)++w2(θ2)++u4)dx+T0Ω(θ2x+u2xθ+w2xθ+w2θ+u2u2x)dxdsC. (2.19)

    The proof of Lemma 3.4 is complete.

    Lemma 2.5. There exists a positive constant C such that for any T>0, it holds that

    sup0tTΩ(v2x+u2x+θ2x+w2x)dx+T0Ω(θv2x+u2xx+θ2xx+w2xx)dxdsC. (2.20)

    Moreover,

    supΩ×[0,T]θ(x,t)C. (2.21)

    Proof. The process will be divided into five steps:

    Step 1. Integrating (1.1)2×vxv over Ω, we get by using (1.1)1

    μ2ddtΩ(vxv)2dx+RΩθv2xv3dx=ddtΩuvxvdx+RΩvxθxv2dx+Ωu2xvdx.

    Integrating the above equality on [0,T], we have

    Ω(vxv)2dx+RT0Ωθv2xv3dxdsC+Ωuvxvdx+CT0Ω(vxθxv2+u2xv)dxdsC+δΩ(vxv)2dx+C(δ)Ωu2dx+δT0Ωθv2xdxds+C(δ)T0Ωθ2xθdxds.

    It follows from Cauchy inequality, (1.6), (2.1), (2.6), (2.7) and (2.18) that

    sup0tTΩv2xdx+T0Ωθv2xdxdsC. (2.22)

    Step 2. Integrating (1.1)2×(uxx) over Ω leads to

    12ddtΩu2xdx+μΩu2xxvdx=μΩuxvxuxxv2dxRΩuxxθxvdx+RΩθvxuxxv2dx. (2.23)

    Using (2.7), (2.22) and Sobolev inequality, we get

    T0μΩuxvxuxxv2dxRΩuxxθxvdx+RΩθvxuxxv2dxdsμ4T0Ωu2xxvdxds+CT0Ωu2xv2xdxds+CT0Ωθ2xdxds+CT0Ωθ2v2xdxdsC+μ4T0Ωu2xxvdxds+CsupΩ×[0,T]θT0Ωθv2xdxds+CT0ux2L(Ω)dsC+μ2T0Ωu2xxvdxds+CsupΩ×[0,T]θ, (2.24)

    then by using (2.23), one has

    sup0tTΩu2xdx+T0Ωu2xxdxdsC+CsupΩ×[0,T]θ. (2.25)

    Step 3. Integrating (2.8)×(θxx) over Ω leads to

    12ddtΩθ2xdx+κΩθ2xxvdx=κΩθxvxθxxv2dxμΩu2xθxxvdx+RΩθuxθxxvdxΩνvw2θxxdxλΩw2xθxxvdx, (2.26)

    then using Cauchy inequality, (2.7), (2.22), (2.25), Sobolev inequality, we get

    T0κΩθxvxθxxv2dxμΩu2xθxxvdx+RΩθuxθxxvΩνvw2θxxdxλΩw2xθxxvdxdsCT0θxxL2(Ω)θxL(Ω)vxL2(Ω)ds+CT0θxxL2(Ω)uxL(Ω)uxL2(Ω)ds+CT0θxxL2(Ω)θL(Ω)uxL2(Ω)ds+CT0θxxL2(Ω)dsCT0θxxL2(Ω)θx12L2(Ω)θxx12L2(Ω)vxL2(Ω)ds+CT0θxxL2(Ω)uxH1(Ω)uxL2(Ω)ds+CT0θxxL2(Ω)uxH1(Ω)θL(Ω)ds+CT0θxxL2(Ω)dsκ4T0Ωθ2xxvdxds+C+CsupΩ×[0,T]θ3. (2.27)

    Hence we obtain by using (2.26) that

    sup0tTΩθ2xdx+T0Ωθ2xxdxdsC+CsupΩ×[0,T]θ3. (2.28)

    Step 4. Integrating (1.1)3×(wxx) over Ω, we have

    12ddtΩw2xdx+λΩw2xxvdx=λΩwxvxwxxv2dxνΩvwwxxdx, (2.29)

    using (2.1), (2.22) and Lemma 2.2, one has

    T0λΩwxvxwxxv2dxνΩvwwxxdxdsλ4T0Ωw2xxvdxds+C. (2.30)

    Then, by using (2.29), we get

    sup0tTΩw2xdx+T0Ωw2xxdxdsC. (2.31)

    Step 5. Using Sobolev inequality and (2.7), for any 0tT

    θ12C(Ω)Cθ1L2(Ω)θxL2(Ω)CθxL2(Ω). (2.32)

    Combining (2.28), yields

    supΩ×[0,T](θ1)2C+CmaxˉΩ×[0,T]θ32.

    It implies that there exists a positive constant C for any (x,t)ˉΩ×[0,T]

    θ(x,t)C. (2.33)

    Hence, putting together (2.22), (2.25), (2.28), (2.31) and (2.33), we finish the proof of Lemma 2.5.

    Lemma 2.6. Under the conditions of Theorem 1.1, it holds that

    limt((v1,u,w,θ1)(t)Lp(Ω)+(vx,ux,wx,θx)(t)L2(Ω))=0, (2.34)

    for any p>2, there also exists a positive constant C2

    C12θ(x,t)C2,for(x,t)ˉΩ×[0,). (2.35)

    Proof. First, it follows from (2.7), (2.20), (2.23), (2.24), (2.26), (2.27), (2.29) and (2.30) that

    0(ux2L2(Ω)+|ddtux2L2(Ω)|)dt+0(θx2L2(Ω)+|ddtθx2L2(Ω)|)dt+0(wx2L2(Ω)+|ddtwx2L2(Ω)|)dtC,

    which directly gives

    limt(uxL2(Ω)+θxL2(Ω)+wxL2(Ω))=0. (2.36)

    By applying (2.36) to (2.32), we get

    limtθ1C(ˉΩ)=0.

    Hence, there exists some T>0

    12θ32,for any(x,t)ˉΩ×[T,). (2.37)

    Combining (2.20), leads to

    Tvx2L2(Ω)dsC. (2.38)

    Then combining (1.1)1 and (2.20), one has

    Tddtvx2L2(Ω)ds=2TΩuxxvxdxdsTΩu2xxdxds+TΩv2xdxdsC,

    which together with (2.38) implies

    limtvxL2(Ω)=0. (2.39)

    Therefore, combining (2.1), (2.7), (2.36), (2.39) and (2.15), we can get (2.34).

    Finally, we will establish the lower bound of θ. According to [1,12], there exists a constant C3>2

    C13eC3tθ,,for any(x,t)ˉΩ×[0,),

    which together with (2.37), yield

    C13eC3Tθ.

    Combining (2.33) and (2.35), we choose Cmax{C2,C3eC3T}. The proof of Lemma 3.6 is finished.



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