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Research article

The Cauchy problem for general nonlinear wave equations with doubly dispersive

  • Received: 06 February 2024 Revised: 08 April 2024 Accepted: 10 April 2024 Published: 03 June 2024
  • 35A01, 35D30, 35L05

  • This paper focuses on a class of generalized nonlinear wave equations with doubly dispersive over equation whole lines. By employing the potential well theory, we classify the initial profile such that the solution blows up or globally exists.

    Citation: Yue Pang, Xiaotong Qiu, Runzhang Xu, Yanbing Yang. The Cauchy problem for general nonlinear wave equations with doubly dispersive[J]. Communications in Analysis and Mechanics, 2024, 16(2): 416-430. doi: 10.3934/cam.2024019

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  • This paper focuses on a class of generalized nonlinear wave equations with doubly dispersive over equation whole lines. By employing the potential well theory, we classify the initial profile such that the solution blows up or globally exists.



    The focus of this work is a general nonlinear doubly dispersive wave equation:

    uttLuxx=B(h(u))xx,           (x,t)R×(0,T) (1.1)

    associated with the following initial profile:

    u(x,0)=u0,   ut(x,0)=u1,   xR. (1.2)

    Hereafter the nonlinearity h(u) indicates the following:

    (H)    h(u)=±α|u|θ or α|u|θ1u, α>0 and  θ>1.

    Both L and B are linear pseudo-differential operators that can be respectively written as follows:

    F(Lv)(ζ)=l(ζ)F(v)(ζ) (1.3)

    and

    F(Bv)(ζ)=b(ζ)F(v)(ζ), (1.4)

    whose symbols are l(ζ) and b(ζ) respectively satisfying

    c21(1+ζ2)ρ2l(ζ)c22(1+ζ2)ρ2,ρ0 (1.5)

    and

    0<b(ζ)c23(1+ζ2)r2,r0 (1.6)

    for all ζR. Henceforth F denotes the Fourier transform and F1 denotes the inverse Fourier transform.

    We note that Equation (1.1) arose from an integral-type non-locality of elastic materials (see [1,2] and the references therein for more information about its physical background), and some Boussinesq-type equations can be covered by Equation (1.1). For example, with the substitutions L=a2x+1, B=I and h(u)=αu2, (1.1) becomes the classical Boussinesq equation:

    utt=auxxxx+uxx+α(u2)xx, (1.7)

    for shallow water (see [3]). Liu in [4] demonstrated that the traveling wave for the corresponding (1.7) may be stable or unstable and established sharp conditions to support this. Using the potential well method, the qualitative behavior for (1.7) with h(u)=u2 was derived in [5]. Also Equation (1.1) can be reduced to the improved fourth-order Boussinesq equation:

    uttuxxuxxtt=(u2)xx, (1.8)

    with the selections B=(12x)1,L=(12x)1 and h(u)=u2 in Equation (1.1). Physically, Equation (1.8) can be used to describe the role of inertia in the one-dimensional lateral dynamics of the elastic rod [6]. Besides that, a class of fourth-order double-dispersion Boussinesq-type equations with terms uxxxx and uxxtt given by

    uttuxxuxxtt+uxxxx=(h(u))xx (1.9)

    can also be derived by setting B=(12x)1 and L=I in Equation (1.1). It is well known that Equation (1.9) can yield longitudinal strain waves in a nonlinearly elastic rod [6] and has many interesting results involving the initial data. For example, Liu and Xu in [7] demonstrated the influence of the nonlinearity as h(u)=|u|p along with the initial data on dynamical behavior for Equation (1.9) with sub-critical and critical initial energy. Further, a high-order Boussinesq equation written as

    uttuxxuxxtt+uxxxx+uxxxxtt=(h(u))xx (1.10)

    can also be included by setting B=(12x+4x)1, L=(12x+4x)1(12x) and h(u)=|u|p in (1.1), which can be applied to simulate the surface tension of water waves and the long-time behavior of small initial data. And the nonlinear scattering for Equation (1.10) when h(u)=up (p>1) as u0 was established in [8].

    From the above statements, we see that the general form, i.e., (1.1), can represent many important interesting mathematical physics models reflecting the meaningful phenomenon from the real world, and that the results on such models will deepen our knowledge regarding these physical problems. Hence, the main goal of our work is to deal with how the structure of the wave Equation (1.1), especially the dispersive effect induced by its pseudo-differential operator B and L, along with the initial condition (1.2), affects the dynamical characteristics of the corresponding solution. In fact, because the pseudo-differential operators B and L in Equation (1.1) are identical and become a convolution integral operator of the form

    (Bv)(x)=(βv)(x)=β(xy)v(y)dy, (1.11)

    the considered Equation (1.1) reduces to

    utt(βu)xx=(βh(u))xx,

    which was first considered in [2] with β(x)=F1(b(ζ)) and b(ζ) satisfying (1.6). And the existence of the local solution and global positive-definite energy solution as well as negative initial energy finite time blowup were constructed in [2]. After that, some attention is paid to the case of BL in Equation (1.1) given that B behaves like case (1.11) with β(x)=F1(b(ζ)) and b(ζ) satisfies (1.6) or B=I, whereas the symbol l(ζ) of L is subject to (1.5).

    For the case that the symbol l(ζ) of L satisfies (1.5) and B=I, the considered Equation (1.1) becomes

    uttLuxx=(h(u))xx.

    It is noted that for some sufficiently smooth nonlinearities h(u), Babaoglu et al., in [1], established the local existence of the solution, the existence of the global positive-definite energy solution, and the global non-existence of the sufficiently negative initial energy solution. Then, some improvements of [1] were established in [9] and [10] by considering the non-positive-definite energy case due to the nonlinearities. For the nonlinearity h(u)=|u|p1u as one case of (H), the dynamical behavior for low initial energy was dealt with in [10] with the symbol b(ζ) of B as follows

    c23(1+ζ2)r2b(ζ)c24(1+ζ2)r2,c3,c4>0, r0, (1.12)

    which also satisfies (1.6) considered in our work. In fact we can see that some special cases such as b(ζ)=c23(1+ζ2)˜r2 with ˜r>r0 for all ζR can be included in (1.6) but not (1.12). The above analysis means that some results obtained in [9] and [10] are special cases of our work. In fact, although we carefully introduced these established related results above, it is still not easy to distinguish the differences between them from the results of the present paper. Hence we use Table 1 to make it clear.

    Table 1.  A comparison among the results in References [1,3,5,6] and our paper.

     | Show Table
    DownLoad: CSV

    Hence our work considers the generalized case that the pseudo-differential operators B and L satisfy Equations (1.5) and (1.6), respectively. Some typical nonlinear terms like |h(u)|=α|u|p with α>0 shown in (H) are considered, and the qualitative behavior for non-positive-definite energy (sub-critical, critical and super-critical levels) is derived. Our work also improves some corresponding results for those special cases.

    The organization of this paper is as follows. Section 2 gives some preliminaries. The global existence and finite time blowup for E(0)<d and E(0)=d are proved in Section 3 and Section 4, respectively. Section 5 proves the finite time blowup for E(0)>0.

    Throughout this paper,

    u2Hs=R(1+ζ2)s|ˆu(ζ)|2dζ,

    u and (u,v) respectively represent the norm of Hs:=Hs(R), the L2 norm and the inner product in L2. Further, we define K=L12 with κ(ζ)=l(ζ) and Λαω=F1[|ζ|αFω].

    Some preliminaries are first introduced to help us consider the well-posedness for the considered problem.

    Definition 2.1 (Weak solution) A function u(t)C1(0,T;Hρ2+r2) with utC(0,T;Hr21) is called a weak solution to (1.1) and (1.2) if u0Hρ2+r2, u1Hr21 and

    (B1/2Λ1utt,B1/2Λ1ω)+(B1/2Ku,B1/2Kω)+(h(u),ω)=0, (2.1)

    where ωC1(0,T;Hρ2+r2).

    Lemma 2.2 ([9]). Let (H), u0Hρ2+r2 and u1Hr21 hold and H(u)=u0h(s)ds hereafter; then, the following conditions hold:

    (i) |uh(u)|=α|u|θ+1, |H(u)|=αθ+1|u|θ+1\ for all uR;

    (ii) (θ+1)H(u)=uh(u) \ for all uR.

    Lemma 2.3 (Local existence [1]). Let ρ2+r1, s>12, u0Hs, u1Hs1ρ2 and h(u)C[s]+1(R). Then there exist some functions T(u0,u1)[0,Tmax] such that the problem (1.1)-(1.2) have a unique solution uC([0,Tmax],Hs)C1([0,Tmax],Hs1ρ2). If the maximum time Tmax<, then

    limtTmaxsup(u(t)s+uts1ρ2)=+.

    Lemma 2.4 (Law of conservation of energy [1]). Let (H), u0Hρ2+r2, u1Hr21, B1/2Λ1u1L2, B1/2Ku0L2 and H(u0)L1. Then, over t[0,Tmax), we have

    E(t)=12B1/2Λ1ut2+12B1/2Ku2+RH(u)dx=E(0). (2.2)

    Now some auxiliary functionals and sets for the problem (1.1)-(1.2) are introduced

    J(u)=12B1/2Ku2+RH(u)dx, (2.3)
    I(u)=B1/2Ku2+Rh(u)udx, (2.4)
    W={uHρ2+r2|I(u)>0}{0} (2.5)

    and

    V={uHρ2+r2I(u)<0}.

    The following lemmas provide some properties of the functionals J(u) and I(u) defined above to consider the depth of the potential well.

    Lemma 2.5. Let (H), u0Hρ2+r2, u1Hr21, B1/2Ku0 and Ruh(u)dx<0 hold. Then, we have the following:

    (i) limς0J(ςu)=0, \ limς+J(ςu)=;

    (ii) Over (0,+), there is a unique ς=ς(u) assuring that

    ddςJ(ςu)>0,  as  0<ς<ς,
    ddςJ(ςu)=0,  as  ς=ς,
    ddςJ(ςu)<0,  as  ς<ς<+

    and

    maxς(0,+)J(ςu)=J(ςu);

    (iii) I(ςu) is positive as ς(0,ς), arrives at zero when ς=ς and becomes negative as ς(ς,+).

    Proof.

    (ⅰ) From the fact that θ>1 and ς0, one knows that

    J(ςu)=ς22B1/2Ku2+ςθ+1θ+1Ruh(u)dx0.

    For ς+ and Ωuh(u)dx<0, we know that

    J(ςu)=ς2(12B1/2Ku2+ςθ1θ+1Ruh(u)dx).

    (ⅱ) The conclusion follows from

    ddςJ(ςu)=ςB1/2Ku2+ςθRuh(u)dx. (2.6)

    (ⅲ) The fact that

    I(ςu)=ς2B1/2Ku2+ςθ+1Ruh(u)dx=ςddςJ(ςu)

    directly gives the conclusion.

    With a similar argument as in Lemma 2.5, one can infer the following lemma.

    Lemma 2.6. Let (H), u0Hρ2+r2, u1Hr21, B1/2Ku0 and Ruh(u)dx>0 hold. Then, we have the following:

    (i) limς0J(ςu)=0, limς+J(ςu)=+;

    (ii) dJ(ςu)dς>0 over (0,+);

    (iii) I(ςu) is positive over (0,+).

    Now, with the above estimates in hand, the depth of the potential well can be estimated in the following lemma.

    Lemma 2.7. Let (H), u0Hρ2+r2 and u1Hr21 hold. The depth of the potential well d=infuNJ(u) with

    N={uHρ2+r2{0}|I(u)=0}

    for the problem (1.1)-(1.2) can be formulated as follows:

    d=θ12(θ+1)(c1c3)2(θ+1)θ1α2θ1C2(θ+1)θ1

    with

    C=supuHρ2+r2{0}uθ+1uHρ2+r2.

    Proof. Given that uN, we can infer that

    B1/2Ku2=Rh(u)udx=αuθ+1θ+1αCθ+1uθ+1Hρ2+r2,

    which together with

    u(t)2Hρ2+r2=R(1+ζ2)ρ2+r2|ˆu(ζ)|2dζc23c21Rb1(ζ)κ2(ζ)|ˆu(ζ)|2dζ=c23c21B1/2Ku2 (2.7)

    yields

    u2Hρ2+r2(c1c3)4θ1α2θ1C2(θ+1)θ1. (2.8)

    Now, from (2.3), (2.4), uN, (2.7) and (2.8), we have

    J(u)=θ12(θ+1)B1/2Ku2+1θ+1I(u)=θ12(θ+1)B1/2Ku2θ12(θ+1)c12c32u2Hρ2+r2θ12(θ+1)(c1c3)2(θ+1)θ1α2θ1C2(θ+1)θ1,

    which completes the proof of this lemma.

    The following lemma shows that both the sets W and V are invariant for E(0)<d.

    Lemma 3.1. Let (H), u0Hρ2+r2, u1Hr21, B1/2Ku0 and E(0)<d. Then, we have the following:

    (i) uW if u0W;

    (ii) uV if u0V,

    where u(t) denotes a local solution to the problem (1.1)-(1.2).

    Proof. Because the proofs of (ⅰ) and (ⅱ) are similar, we only prove one. From the contradiction arguments, it is supposed that there exists a first time t1(0,Tmax) such that I(u(t1))0, which together with Lemma 2.3, indicates that I(u(t2))=0 for certain t2(0,t1). Together with Lemma 2.7 we can conclude the following contradiction

    dJ(u(t2))E(u(t2))=E(0)<d.

    The following theorem presents the global existence for E(0)<d.

    Theorem 3.2. If (H), u0Hρ2+r2, u1Hr21, E(0)<d and u0W, then the problem (1.1)-(1.2) admits a global weak solution

    u(t)C1(0,+;Hρ2+r2),ut(t)C(0,+;Hr21).

    Proof. Let

    un(x,t)=nj=1 ϕjn(t)wj(x),  n=1,2,

    be the corresponding approximate solution that satisfies

    (B1/2Λ1untt,B1/2Λ1ws)+(B1/2Kun,B1/2Kws)+(h(un),ws)=0, (3.1)
    un(x,0)=nj=1ιjnwj(x)u0(x)  in Hρ2+r2, (3.2)
    unt(x,0)=nj=1¯ιjnwj(x)u1(x)  in Hr21, (3.3)
    B1/2Kun(x,0)L2

    and

    B1/2Λ1unt(x,0)L2

    with a system of base functions denoted by {ωj(x)} in Hρ2+r2Hr21. From (3.2) and (3.3), we get

    B1/2Λ1unt(0)2+B1/2Kun(0)2B1/2Λ1u12+B1/2Ku02

    as n+. Now we claim that

    RH(un(0))dxRH(u(0))dx, n+.

    Indeed

    |RH(un(0))dxRH(u(0))dx|R|h(φn)||un(0)u0|dxh(φn)un(0)u0,

    where φn=u0+ϑ(un(0)u0)Hρ2+r2 and ϑ(0,1). For θ>1 and N=1, it follows that h(φn)2=α2φn2θ2θ<C(α,ρ,θ)φn2θHρ2+r2<C with C,C>0. Thus the claim is proved and

    Em(0)E(0) as n+. (3.4)

    Recalling u0W, and the fact that (3.2) and (3.3) imply that un(0)W as n+, combining the arguments of Lemma 3.1 and (3.4), one can see that un(t)W as n+ for t[0,+). Consequently, multiplying (3.1) by ϕsn(t) and summing for s we have

    12ddt(B1/2Λ1unt2+B1/2Kun2)+ddt(RH(un)dx)=0,

    which gives

    En(0)=En(t)=12B1/2Λ1unt2+12B1/2Kun2+RH(un)dx=12B1/2Λ1unt2+θ12(θ+1)B1/2Kun2+1θ+1I(un)θ12(θ+1)B1/2Kun2.

    Incorporating (3.4) we get

    B1/2Kun2<2(θ+1)θ1d

    and

    B1/2Λ1unt2<2d

    for t[0,+) as n+. Thus, by ({1.5}) and (1.6), we have

    un(t)2Hρ2+r2=R(1+ζ2)ρ2+r2|ˆun(ζ)|2dζc23c21Rb1(ζ)κ2(ζ)|ˆun(ζ)|2dζ=c23c21B1/2Kun2

    and

    unt2Hr21=R(1+ζ2)r21|ˆunt(ζ)|2dζR(1+ζ2)r2ζ2|unt(ζ)|2dζc23Rb1(ζ)ζ2|ˆunt(ζ)|2dζ=c23B1/2Λ1unt2,

    which gives the following:

    unis bounded inC1(0,+;Hρ2+r2);unt is bounded inC(0,+;Hr21).

    By an argument similar to that for h(φn), one can infer that

    h(un)is bounded inC1(0,+;L2).

    Integrating (3.1) over (0,t) yields

    (B1/2Λ1unt,B1/2Λ1ws)+t0(B1/2Kun,B1/2Kws)ds=(B1/2Λ1unt(0),B1/2Λ1ws)t0(h(un),ws)ds. (3.5)

    In (3.5), fix s and let n+, then, we get

    (B1/2Λ1ut,B1/2Λ1ws)+t0(h(u),ws)ds=t0(B1/2Ku,B1/2Kws)ds.

    From (3.2) and (3.3) it follows that u(x,0)=u0(x) is bounded in Hρ2+r2 and ut(x,0)=u1(x) is bounded in Hr21. Thus, Theorem 3.2 is proved.

    The following lemma is used to prove the finite time blowup for E(0)<d.

    Lemma 3.3. Let (H), u0Hρ2+r2 and u1Hr21 hold. If u0V and E(0)<d, then

    d<θ12(θ+1)B1/2Ku2. (3.6)

    Proof. Lemma 2.7 implies that

    u2Hρ2+r22c23(θ+1)c21(θ1)d. (3.7)

    Note that Lemma 3.1 (ⅱ) ensures that uV, which together with (2.7) and (3.7) gives (3.6). So this lemma is proved.

    The next theorem states the finite time blowup for E(0)<d.

    Theorem 3.4. If (H), u0Hρ2+r2, u1Hr21, E(0)<d and u0V, then the problem (1.1)-(1.2) admits a finite time blowup result.

    Proof. Arguing by contradiction, we suppose that there exists a global solution u. Define

    η(t)=B1/2Λ1u2,t[0,T1] (3.8)

    for any T1>0. So,

    η(t)>σ>0,t[0,T1]. (3.9)

    Then,

    ˙η(t)=2(B1/2Λ1u,B1/2Λ1ut). (3.10)

    Applying the definition of I(u) and taking ω=u in (2.1), we get

    ¨η(t)=2B1/2Λ1ut2+2(B1/2Λ1u,B1/2Λ1utt)=2B1/2Λ1ut22((B1/2Ku,B1/2Ku)+(h(u),u))=2B1/2Λ1ut22I(u). (3.11)

    A substitution of both (2.2) and (2.4) into (3.11) gives

    ¨η(t)=(θ+3)B1/2Λ1ut2+(θ1)B1/2Ku22(θ+1)E(0).

    Then by Lemma 3.3, we see that

    ¨η(t)(θ+3)B1/2Λ1ut2=χ(t)>μ>0, (3.12)

    where we use the following relation:

    χ(t):=(θ1)B1/2Ku22(θ+1)E(0)=(θ1)B1/2Ku22(θ+1)d+2(θ+1)d2(θ+1)E(0).

    At this point, (3.12) and (3.9) with the estimation

    (˙η(t))24B1/2Λ1u2B1/2Λ1ut2=4η(t)B1/2Λ1ut2

    and

    η(t)¨η(t)θ+34(˙η(t))2η(t)(¨η(t)(θ+3)B1/2Λ1ut2)=η(t)χ(t), (3.13)

    imply that

    η(t)¨η(t)θ+34(˙η(t))2σμ>0.

    Hence

    ¨ηθ14(t)θ14σμηθ+7θ,t[0,T1].

    Set tT<T1; then,

    limtTη(t)=+.

    Thus we complete the proof.

    In this section, we aim to adapt the method used in [11,12,13] to the critical initial energy case E(0)=d.

    Theorem 4.1. If (H), u0Hρ2+r2, u1Hr21, E(0)=d and u0W, then the problem (1.1)-(1.2) has a global solution \ u(t)C1(0,+;Hρ2+r2), ut(t)C(0,+;Hr21).

    Proof. The proof is established by considering the following two cases.

    Case Ⅰ. B1/2Ku020.

    (1) Ruh(u)dx<0. Let ςn=11n and u0n=ςnu0, n=2,3. Consider Equation (1.1) with

    u(x,0)=u0n(x),ut(x,0)=u1(x). (4.1)

    From u0W and (2.5), it follows that ς=ς(u0)>1 and hence 11n<1<ς, which implies that I(u0n)>0, J(u0n)<J(u0), and

    0<En(0)=12u12+J(u0n)<12u12+J(u0)=E(0)=d.

    (2) Ruh(u)dx>0. From u0W and Lemma 2.6, it follows that I(ςu0)|ς=1=ςddςJ(ςu0)|ς=1>0, and I(ςu0)>0 for ς(ς,ς) with 1(ς,ς). Lemma 2.6 yields that ddςJ(ςu0)>0 over (ς,ς), which yields a sequence ςn(ς,1), n=1,2,3, and ςn1 as n+. Let u0n=ςnu0, n=1,2,3,. Consider Equation (1.1) with

    u(x,0)=u0n(x), ut(x,0)=u1(x).

    At this point

    I(u0n)=I(ςnu0)>0

    and Lemma 2.6 implies that

    J(u0n)=J(ςnu0)<J(u0)

    and

    0<En(0)=12u12+J(u0n)<12u12+J(u0)=E(0)=d.

    Case Ⅱ. B1/2Ku02=0.

    Let ςn=11n, u1n(x)=ςnu1(x), n=2,3. Consider (1.1) with

    u(x,0)=u0(x),ut(x,0)=u1n(x). (4.2)

    From B1/2Ku02=0, it follows that J(u0)=0 and 12u12=E(0)=d. As a result,

    0<En(0)=12u1n2+J(u0)=12ςnu12<E(0)=d.

    Combining Case Ⅰ and Case Ⅱ, again by the argument of Theorem 3.2, we can conclude the result of Theorem 4.1.

    The next lemma is used to consider the finite time blowup for E(0)=d.

    Lemma 4.2. Let (H), u0Hρ2+r2 and u1Hr21 hold. Assume that E(0)=d, (B1/2Λ1u0,B1/2Λ1u1)0 and u0V; then, uV.

    Proof. Arguing by contradiction, we suppose that I(u(˜t0))=0 and I(u(t))<0 for 0<t<˜t0 and ˜t0(0,Tmax). So Lemma 2.7 implies that J(u(˜t0))d. By E(0)=d and Lemma 2.4, we have that J(u(˜t0))=d and B1/2Λ1ut(˜t0)=0. As a result, (3.8), (3.10) and (3.11) yield

    ˙η(0)=2(B1/2Λ1u0,B1/2Λ1u1)0

    and

    ¨η(t)>0,t[0,˜t0),

    also

    ˙η(t)=2(B1/2Λ1u(t),B1/2Λ1ut(t))>0, t(0,˜t0),

    which implies that η(t) is increasing on [0,˜t0]. It contradicts that B1/2Λ1ut(˜t0)=0. So, we complete the proof.

    Theorem 4.3. If (H), u0Hρ2+r2, u1Hr21, (B1/2Λ1u0,B1/2Λ1u1)0, E(0)=d and u0V hold, then the problem (1.1)-(1.2) has a finite time blowup result.

    Proof. It is not necessary to write down the completed proof as we can use the proof of Theorem 3.4 to make it. First, Equation (3.8) and the proof of Theorem 3.4 imply Equation (3.11). Then applying Lemma 4.2, we obtain Equation (3.13). The reminder proof is similar to Theorem 3.4.

    Theorem 5.1. Assume that (H), u0Hρ2+r2, u1Hr21 and the following three conditions all hold

    (i) I(u0)<0;

    (ii) (B1/2Λ1u0,B1/2Λ1u1)0;

    (iii) B1/2Λ1u02>2γ(θ+1)θ1E(0)>0 with γ>0.

    Then, the problem given by Equations (1.1)-(1.2) has an arbitrarily positive initial energy finite time blowup solution.

    Proof. Step Ⅰ. We claim over [0,Tmax) that

    I(u)<0,B1/2Λ1u2>2γ(θ+1)θ1E(0).

    Arguing by contradiction, suppose that I(u(¯t0))=0 for certain ¯t0[0,Tmax) and I(u(t))<0 for 0t<¯t0. So, (3.11) implies that

    ¨η(t)>0,t[0,¯t0)

    where ˙η(0)0, which yields that ˙η(t)>0 over [0,¯t0) and

    η(t)>η(0)=B1/2Λ1u02>2γ(θ+1)θ1E(0),t[0,¯t0).

    Consequently,

    η(¯t0)>2γ(θ+1)θ1E(0). (5.1)

    Further (2.2), I(u(¯t0))=0 and Lemma 2.2 imply that

    B1/2Ku(¯t0)22(θ+1)θ1E(0). (5.2)

    By the multiplier theorem in [14], the definitions of operators B, Λ and (1.5), we infer that

    B1/2Λ1u2=Λ1B1/2u2˜CB1/2u2c1˜CB1/2Ku2:=γB1/2Ku2, (5.3)

    where

    γ:=c1˜C, ˜C:=sup{M|ζ1M, ζC(R)}.

    Now, both (5.2) and (5.3) imply that

    η(¯t0)=B1/2Λ1u(¯t0)2γB1/2Ku(¯t0)22γ(θ+1)θ1E(0),

    which contradicts (5.1) and then confirms that I(u(t))<0 over [0,Tmax).

    Combining (3.11) and I(u(t))<0 on [0,Tmax), one has

    ¨η(t)=2B1/2Λ1ut22I(u)>0,

    then ˙η(t)>0 on [0,Tmax) due to the condition (ⅱ) as follows

    ˙η(0)=(B1/2Λ1u0,B1/2Λ1u1)0,

    which implies that

    η(t)>η(0),t[0,Tmax).

    By the definition of η(t) in (3.8) and the condition (ⅲ), we get

    B1/2Λ1u2>2γ(θ+1)θ1E(0).

    Step Ⅱ. By using the claim in Step Ⅰ, i.e., B1/2Λ1u2>2γ(θ+1)θ1E(0) over [0,Tmax), we can infer (3.13) with χ(t)=(θ1)B1/2Ku22(θ+1)E(0)>˜δ>0 over [0,Tmax), where (3.8) has been recalled. The proof is similar to Theorem 3.4.

    The authors declare that they have not used artificial intelligence tools in the creation of this article.

    Runzhang Xu was supported by the National Natural Science Foundation of China (No. 12271122). Yanbing Yang was supported by the Heilongjiang Provincial Natural Science Foundation of China (No. LH2021A002), the Heilongjiang Postdoctoral Research Start-up Funding Project (No. LBH-Q20086), and the Research Funds for the Central Universities.

    The authors declare that there is no conflict of interest.



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