
We investigate a non-autonomous discrete-time SIRS epidemic model with nonlinear incidence rate and distributed delays combined with a nonlinear recovery rate taken into account the impact of health care resources. Two threshold parameters R0,R∞ are obtained so that the disease dies out when R0<1; and the infective persists indefinitely when R∞>1.
Citation: Butsayapat Chaihao, Sujin Khomrutai. Extinction and permanence of a general non-autonomous discrete-time SIRS epidemic model[J]. AIMS Mathematics, 2023, 8(4): 9624-9646. doi: 10.3934/math.2023486
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We investigate a non-autonomous discrete-time SIRS epidemic model with nonlinear incidence rate and distributed delays combined with a nonlinear recovery rate taken into account the impact of health care resources. Two threshold parameters R0,R∞ are obtained so that the disease dies out when R0<1; and the infective persists indefinitely when R∞>1.
In recent years, mathematical epidemic models have been extensively investigated in order to understand the dynamics and control the spreading of various diseases, see for instance [4,5,6,7,11,13,14,15,19,20,23,24,25,26,27] and the references therein. Related to this work are the following studies. Zhang et al. [26] investigated a non-autonomous SIRS epidemic model with a standard incidence rate and distributed delays of the form
{˙S(t)=Λ(t)−β(t)∫τ0p(ξ)I(t−ξ)S(t)dξ−μ1(t)S(t)+γ(t)R(t),˙I(t)=β(t)∫τ0p(ξ)I(t−ξ)S(t)dξ−(μ2(t)+k(t))I(t),˙R(t)=k(t)I(t)−(μ3(t)+γ(t))R(t), | (1.1) |
where S(t), I(t), and R(t) are the numbers of susceptible, infectious, and recovered individuals at time t, respectively. The distributed delays are used to model the infection mechanisms of some diseases, where infected individuals may not be infectious until some time after becoming infected, and that the infectivity is a function of the duration since infection, up to some maximum duration. Various (time-dependent) parameters in (1.1) are defined as follows: Λ is the growth (or recruitment) rate of the population, β is the daily contact rate, that is the average number of contacts per day, μi, for i=1,2,3, are the instantaneous per capita mortality rates of S-, I-, and R-classes, respectively, γ is the rate that the recovered individual loses immunity and returns to be susceptible, ξ is a time taken for an infected individual to become infectious and p(ξ) is the distributed proportion of the population taking time ξ after being infected to become infectious, τ is the infected period, and k is the recovery rate that can incorporate basic medical treatment and prevention of the disease. The main result in [26] is that they obtain two threshold values R⋆ and R⋆, which depend on the parameters of the model, so that the disease is permanent if R⋆>1 while if R⋆<1 then the disease extincts. Global behavior of the model is also studied using the Lyapunov functional method.
Enatsu et al. [3] investigated an autonomous version of (1.1), i.e. Λ,β,μ1, γ,μ2,k,μ3 are constants, but with a general nonlinear incidence rate and distributed delays of the form
β∫τ0p(ξ)g(I(t−ξ))S(t)dξ, | (1.2) |
where the nonlinear function g(I) satisfies
(A1) g(I) is continuous and monotone increasing on [0,∞) with g(0)=0, and
(A2) g(I)/I is monotone decreasing on (0,∞) with limI→0+g(I)/I=1.
Using the Lyapunov functional method, the authors derived the basic reproduction number R0 and established sufficient conditions of the rate of immunity loss for the global asymptotic stability of an endemic equilibrium for the model.
To mitigate the impact of the disease, some control and prevention should be included into modeling the disease. [16,22] investigated SIR and SIRS epidemic models where the impact of health care resources especially hospital beds is included, so that the recovery rate is a nonlinear function of I of the form
k(I,t)=k0+(k1−k0)b(t)I+b(t)(0<k0≤k1,b(t)>0). | (1.3) |
Here, according to [22], k1 is the maximum per capita recovery rate when health care resources are adequate and the number of infected people is low, k0 is the minimum per capita recovery rate due to the lack of basic clinical resources, and b is a parameter measuring the availability of hospital beds. Complex dynamics of the models are then derived in those papers.
Based on the above discussions, it is interesting to consider the following general non-autonomous SIRS epidemic model
{˙S(t)=Λ(t)−β(t)∫τ0p(ξ)g(I(t−ξ))S(t)dξ−μ1(t)S(t)+γ(t)R(t),˙I(t)=β(t)∫τ0p(ξ)g(I(t−ξ))S(t)dξ−(μ2(t)+k(I(t),t))I(t),˙R(t)=k(I(t),t)I(t)−(μ3(t)+γ(t))R(t), | (1.4) |
where S(t), I(t), and R(t) and Λ(t),β(t),μ1(t),γ(t),μ2(t),μ3(t),p(ξ) are the same as explained in (1.1) and (1.2). In the model (1.4), however, we relax the assumptions (A1), (A2) and also we do not require the nonlinear recovery rate k(I,t) to have the form (1.3). Namely, for k(I,t), we assume that there are positive constants k0,k1 such that
k0≤k(I,t)≤k1 | (1.5) |
for all I≥0 and t≥0. For g(I), it is assumed to be continuous, g(I)≥0 on [0,∞), g(0)=0 and g(I)>0 for I>0, and also that limx→0+(g(x)/x) exists and is positive. Now we define the function
f(I)={g(I)/Iif I>0,limx→0+(g(x)/x)if I=0. | (1.6) |
In epidemiology, f is the transmission function of the disease. Observe that f is continuous and f(I)>0 on [0,∞). Clearly, g(I)=If(I), so the incidence rate appearing in (1.4) can be expressed as
β(t)∫τ0p(ξ)f(I(t−ξ))I(t−ξ)S(t)dξ. | (1.7) |
Let us mention some specific examples of incidence rates. If f(I)=1 is constant, then g(I)S=IS is simply the standard (or bilinear) incidence rate; if f(I)=α3/(1+α1I), then g(I)S=α3IS/(1+α1I) is the saturated incidence rate [2]; if f(I)=α3/(1+α2I+α1I2), then g(I)S=α3IS/(1+α2I+α1I2) is the non-monotone incidence rate [8,19,20].
An interesting and important question is whether the results obtained for the continuous-time SIRS model (1.4) can be extended to the corresponding discrete-time epidemic model. In this work, we investigate the following discrete-time non-autonomous SIRS epidemic model: For a step size h>0 and the maximum infectious period m∈N, consider
{Sn+1=h(Λ(n)−β(n)m∑j=0pjf(In−j)In−jSn+1−μ1(n)Sn+1+γ(n)Rn+1)+Sn,In+1=h(β(n)m∑j=0pjf(In−j)In−jSn+1−(μ2(n)+k(In,n))In+1)+In,Rn+1=h(k(In,n)In+1−(μ3(n)+γ(n))Rn+1)+Rn,Sj≥0,Ij≥0,Rj≥0(−m≤j≤0),S0>0,I0>0, | (1.8) |
where Sn,In, and Rn are the numbers of susceptible, infectious, and recovered individuals at time n, respectively, and pj≥0(j=0,1,…,m) is the distributed proportion of the population taking time j to become infectious, and Λ(n), β(n), μ1(n), γ(n), μ2(n), k(In,n), μ3(n) are the discretized values of the corresponding continuous-time functions explained in (1.1), (1.2), and (1.5). We have obtained (1.8) from (1.4) by applying Mickens's nonstandard finite difference discretization (see [10,17,27]; see also Appendix for a brief introduction). Let us list some known results for (1.8). A global attractivity for the autonomous version of (1.8) with k=k(n) and a bit more general f is investigated in [17]. In [27], the threshold conditions are obtained for (1.8) with the non-delay standard incidence rate.
This paper is organized as follows. In Section 2 we introduce notations and basic results used in this work. Then we derive the positivity and boundedness of solutions (Sn,In,Rn) of (1.8) in Section 3. In Section 4, a threshold condition is obtained so that the permanence of disease for the model (1.8) is guaranteed. Then, we derive in Section 5 a threshold condition so that the extinction of the disease for (1.8) holds. In Section 6, some numerical simulations are presented. Finally, a discussion is given in Section 7.
Notation. In this work, we denote
● Gn=β(n)m∑j=0pjf(In−j)In−j and Kn=k(In,n).
● Π1(n)=1+hμ1(n), Π2(n)=1+hμ2(n), and Π3(n)=1+h(μ3(n)+γ(n)).
● For a sequence {a(n)}, denote au=lim supn→∞a(n), al=lim infn→∞a(n), aM=supn∈N0a(n), aL=infn∈N0a(n). Same notations are applied to functions as well, e.g. fM=supI≥0f(I) and GM=supn∈N0Gn.
The system (1.8) is said to be permanent if there exist constants li,Li>0 (i=1,2,3) such that any solution (Sn,In,Rn) satisfies
{l1≤lim infn→∞Sn≤lim supn→∞Sn≤L1,l2≤lim infn→∞In≤lim supn→∞In≤L2,l3≤lim infn→∞Rn≤lim supn→∞Rn≤L3. | (2.1) |
On the other hand, (1.8) is said to exhibit extinction provided limn→∞In=0 for any solution.
We assume the following conditions for (1.8). First of all, Λ(n),β(n),μ1(n),μ2(n),μ3(n),γ(n) are bounded and positive for all n∈N0, ∑mj=0pj=1, and there are constants k0>0,k1>0 such that k0≤K(I,n)≤k1 for all I≥0 and n∈N0. We list all other assumptions that will be used in this work.
(H1) f≥0 is a bounded continuous function on [0,∞).
(H2) μ1(n)≤min{μ2(n),μ3(n)} for all n∈N0.
(H3) There exist n0∈N, χ≥1, and 0<q<1 such that
N∏n=n111+hμ1(n)≤χqN−n1+1∀N≥n1≥n0. |
(H4) There exist λ>0 and r∈N∪{0} such that
n1+r∑n=n1Λ(n)≥λ∀n1≥0. |
The following key result will be used in the study of disease-free states of (1.8) and also employed repeatedly in the investigation of the permanence and extinction phenomena. The proof is inspired by Lemma 2 in [21] and Lemma 2.2 in [24].
Lemma 1. Let {a(n)},{b(n)} be sequences such that a(n)>0 and 0<b(n)<1 for all n∈N0. Assume that au<∞, bl>0, and that there exist n0, χ>0, and q∈(0,1) such that
b(n1)b(n1+1)⋯b(n2)≤χqn2−n1+1∀n2≥n1≥n0. | (2.2) |
Let xn be a positive solution to the equation
xn+1=a(n)b(n)+b(n)xn(n≥0) | (2.3) |
with initial value x0≥0. Then the following results hold:
(1) There exist constants x⋆≥0,x⋆≥0 depending only upon {a(n)} and {b(n)} such that
lim supn→∞xn=x⋆andlim infn→∞xn=x⋆, |
independent of the initial condition x0. In fact, we have
x⋆=lim supN→∞N∑n=n1a(n)b(n)b(n+1)⋯b(N), | (2.4) |
x⋆=lim infN→∞N∑n=n1a(n)b(n)b(n+1)⋯b(N), | (2.5) |
for any n1≥n0, and the following estimate holds
x⋆≤auχq1−q. | (2.6) |
Moreover, each fixed solution of (2.3) is globally uniformly attractive, i.e. if x′n is also a solution of (2.3) with initial value x′0≥0, then
limn→∞(xn−x′n)=0. |
(2) Suppose there exist constants a0>0 and r∈N∪{0} such that
n1+r∑n=n1a(n)≥a0∀n1≥0. | (2.7) |
Then x⋆>0 and x⋆>0.
(3) Suppose yn satisfies
yn+1≤a(n)b(n)+b(n)yn∀n≥0. |
Then
lim supn→∞yn≤x⋆. |
If in addition y0≤x0 then yn≤xn for all n.
(4) Suppose zn satisfies
zn+1≥a(n)b(n)+b(n)zn∀n≥0. |
Then
lim infn→∞zn≥x⋆. |
If in addition z0≥x0 then zn≥xn for all n.
(5) Let {a(n)},{b(n)} be as above and {˜b(n)} be another sequence satisfying ˜b(n)∈(0,1) for all n∈N0, ˜bl>0, and (2.2) holds with b(n),χ,q,n0 replaced by ˜b(n),χ,q,˜n0, respectively. Assume also that there exist constants ε>0 and N0∈N such that
|b(n)−˜b(n)|<ε∀n≥N0. | (2.8) |
Let ˜xn be a positive solution of the equation
˜xn+1=a(n)˜b(n)+˜b(n)˜xn(n≥0). |
Then there is a constant C=C(au,x⋆,χ,q)>0 such that
|˜x⋆−x⋆|<Cε,|˜x⋆−x⋆|<Kε, |
where according to (1), ˜x⋆=lim supn→∞˜xn and ˜x⋆=lim infn→∞˜xn.
(6) For each ε>0 small, there exist positive integers Nε and Dε such that if n1≥Nε and n2−n1≥Dε, then
n2∑n=n1a(n)b(n)⋯b(n2)>x⋆−ε. |
Proof. (1) For N>n1, it is directly to show that
xN=A(N,n1)+B(N,n1)xn1,yN≤A(N,n1)+B(N,n1)yn1,zN≥A(N,n1)+B(N,n1)zn1, |
where A(N,n1)=∑N−1n=n1a(n)b(n)b(n+1)⋯b(N−1) and B(N,n1)=b(n1)b(n1+1)⋯b(N−1). For fixed n1≥n0, we have by assumption (2.2) that
B(N,n1)xn1=b(n1)b(n1+1)⋯b(N−1)xn1≤χqN−n1xn1→0as N→∞, |
and
A(N,n1)≤(supn≥n1a(n))N−1∑n=n1b(n)b(n+1)⋯b(N−1)≤(supn≥n1a(n))N−1∑n=n1χqN−n≤(supn≥n1a(n))χq1−q, |
so {A(N,n1)}∞N=n1+1 is bounded. Now limN→∞(xN−A(N,n1))=limN→∞B(N,n1)xn1=0, it follows by the boundedness of {A(N,n1)}∞N=n1+1 that
lim supN→∞xN=lim supN→∞A(N,n1)=x⋆,lim infN→∞xN=lim infN→∞A(N,n1)=x⋆ |
and the two limits do not depend on n1. This proves the first part and (2.4), (2.5).
For each ε>0, by taking n1 large enough, we get supn≥n1a(n)≤au+ε, hence
x⋆≤auχq1−q, |
proving (2.6).
The last part of (1) is true because
limN→∞(xN−x′N)=limN→∞(xN−A(N,n1))−limN→∞(x′N−A(N,n1))=0. |
(3) and (4) immediately follow from the proof of (1). We prove (2). By assumption bl>0, so there exist b0∈(0,1) and N0∈N such that b(n)≥b0 for all n≥N0. Fix n1≥max{n0,N0}. Then we have for all N≥n1+r+1 that
A(N,n1)≥N−1∑n=N−1−ra(n)b(n)b(n+1)⋯b(N−1)≥N−1∑n=N−1−ra(n)br+10≥a0br+10. |
Since a0br+10>0, we have x⋆≥x⋆=lim infN→∞A(N,n1)>0.
(5) Recall the well-known fact* that, for bounded sequences,
* Let c=lim sup|˜xn−xn|, a=lim sup˜xn,b=lim supxn. By the triangle inequality ˜xn≤|˜xn−xn|+xn, we get a≤c+b, similarly, we also have b≤c+a. Thus |a−b|≤c. For the other fact, we simply use that lim infxn=−lim sup(−xn).
max{|lim infn→∞˜xn−lim infn→∞xn|,|lim supn→∞˜xn−lim supn→∞xn|}≤lim supn→∞|˜xn−xn|. |
So it suffices to show that lim supn→∞|˜xn−xn|≤Cε. For each n, we have
˜xn+1−xn+1=(a(n)˜b(n)+˜b(n)˜xn)−(a(n)b(n)+b(n)xn)=a(n)(˜b(n)−b(n))+˜b(n)˜xn−b(n)xn+˜b(n)xn−˜b(n)xn=a(n)(˜b(n)−b(n))+(˜b(n)−b(n))xn+˜b(n)(˜xn−xn). |
By the assumption (2.8), it follows that
|˜xn+1−xn+1|≤ε(a(n)+xn)+˜b(n)|˜xn−xn|. |
Note that lim supn→∞ε(a(n)+xn)≤ε(au+x⋆). Using part (3) and (2.6), we have
lim supn→∞|˜xn−xn|≤(au+x⋆)χq1−qε. |
so lim supn→∞|˜xn−xn|≤Cϵ, where C=(au+x⋆)χq/(1−q)>0.
(6) We have xn≤xM:=maxxn for all n. For ε>0, there exists Nε≥n0 such that if n≥Nε then xn≥x⋆−ε2. By (2.2), there exists Dε such that if N−n1≥Dε then b(n1)b(n1+1)⋯b(N)xM≤ε2. Now let n1≥Nε and N≥n1+Dε. Then we have
N−1∑n=n1a(n)b(n)b(n+1)⋯b(N−1)=xN−b(n1)b(n1+1)⋯b(N−1)xn1≥x⋆−ε, |
as desired.
The following elementary result is employed throughout this work.
Lemma 2. The system (1.8) can be expressed as
{Sn+1=hΛ(n)+Sn+hγ(n)Rn+1Π1(n)+hGn,In+1=In+hGnSn+1Π2(n)+hKn,Rn+1=Rn+hKnIn+1Π3(n). | (2.9) |
where Π1(n)=1+hμ1(n),Π2(n)=1+hμ2(n), Kn=k(In,n), and Π3(n)=1+h(μ3(n)+γ(n)).
Proof. By (1.8), we have Sn+1=hΛ(n)−hGnSn+1−hμ1(n)Sn+1+hγ(n)Rn+1+Sn, which directly leads to the first expression. Similarly, we have In+1=hGnSn+1−h(μ2(n)+k(In,n))In+1+In and Rn+1=hk(In,n)In+1−h(μ3(n)+γ(n))Rn+1+Rn, so the other two expressions follow.
We prove the positivity of solutions of (1.8).
Proposition 3. Assume f(I)≥0 for all I≥0. Then every solution of the problem (1.8) is positive, that is Sn>0,In>0,Rn>0 for all n>0.
Proof. For simplicity, we omit the dependence of Π1,Π2,Π3,γ on n in the following calculations. By (2.9), one can directly manipulate the identities to obtain
(Π2+Kn)Π3(Π1+hGn)Sn+1=(Π2+Kn)Π3(hΛ+Sn)+hγ(Π2+Kn)Π3Rn+1=(Π2+Kn)Π3(hΛ+Sn)+hγ(Π2+Kn)(Rn+KnIn+1)=(Π2+Kn)Π3(hΛ+Sn)+hγ(Π2+Kn)Rn+hγKn(In+hGnSn+1)=(Π2+Kn)Π3(hΛ+Sn)+hγ(Π2+Kn)Rn+hγKnIn+h2γKnGnSn+1 |
thus
Sn+1=(Π2+Kn)Π3(hΛ+Sn)+hγ(Π2+Kn)Rn+hγKnInΠ1(Π2+Kn)Π3+((Π2+Kn)Π3−hγKn)hGn. |
From the initial condition in (1.8), it is easily seen that G0≥0 so S1>0. Observe that Πi>1 for i=1,2,3 and (Π2+Kn)Π3−hγKn>0. Using (2.9), we also have I1>0 and R1>0. Applying the same argument, we obtain Gn,Kn≥0 and so Sn+1,In+1,Rn+1>0 for all n.
In this work, we are interested in the extinction and permanence of disease of the model (1.8), so the asymptotic behaviors of disease-free states of the system is crucial. By definition, a disease-free state of (1.8) is a solution (Sn,In,Rn) where In=0 for all n≥0. From Lemma 2, the system is reduced in this case to
Sn+1=hΛ(n)11+hμ1(n)+11+hμ1(n)Sn+hγ(n)Rn+11+hμ1(n),Rn+1=Rn1+h(μ3(n)+γ(n)). |
Let N>n1≥n0. By (H2), (H3), and Proposition 3, we have that
hγ(N)RN+1=hγ(N){N∏n=n111+h(μ3(n)+γ(n))}Rn1≤{N−1∏n=n111+hμ1(n)}Rn1≤χqN−n1Rn1→0, |
as N→∞. Similarly, RN→0. Thus the asymptotic behaviors of the disease-free states of (1.8) are closely related to the properties of solutions S0n of the following equation
S0n+1=hΛ(n)11+hμ1(n)+11+hμ1(n)S0n. | (3.1) |
The following proposition gives the uniform upper and lower bounds for any positive solution of (3.1).
Proposition 4. Suppose that (H3) and (H4) hold. Then there exist constants S0,⋆,S0⋆>0 such that
S0⋆=lim infn→∞S0n≤lim supn→∞S0n=S0,⋆, |
for any positive solution S0n of (3.1) regardless of the initial condition. In fact, we have
S0,⋆=lim supN→∞N∑n=n1hΛ(n)(1+hμ1(n))⋯(1+hμ1(N)), | (3.2) |
S0⋆=lim infN→∞N∑n=n1hΛ(n)(1+hμ1(n))⋯(1+hμ1(N)), | (3.3) |
for all n1≥n0
Proof. Set a(n)=hΛ(n) and b(n)=11+μ1(n). It is obvious that au<∞ and bl>0. Also, the hypotheses (H3) and (H4) are equivalent to (2.2) and (2.7) in Lemma 1, respectively. Hence, the proof immediately follows from Lemmas 1(1) and (2).
The following proposition is a generalized version of the preceding one. It will be used in the proof of the permanence of disease (Theorem 8).
Proposition 5. Suppose that (H3) and (H4) hold. Let ν≥0 and define μν1 by
μν1(n):=μ1(n)+βMfMνfor all n . |
Then there exist constants Sν,⋆,Sν⋆>0 such that if Sνn is a positive solution of the equation
Sνn+1=hΛ(n)11+hμν1(n)+11+hμν1(n)Sνn, | (3.4) |
then
Sν⋆=lim infn→∞Sνn≤lim supn→∞Sνn=Sν,⋆. |
Proof. As in the proof of Proposition 4, choosing a(n)=hΛ(n) and b(n)=11+μν1(n), and applying (H3) and (H4), we get the conditions (2.2) and (2.7). By Lemmas 1(1) and (2), the result is true and the quantities Sν,⋆,Sν⋆ are given by replacing μ1 in the formulas (3.2) and (3.3) with μν1.
Notice that
Sν,⋆=lim supN→∞N∑n=n1hΛ(n)(1+hμν1(n))⋯(1+hμν1(N)), | (3.5) |
Sν⋆=lim infN→∞N∑n=n1hΛ(n)(1+hμν1(n))⋯(1+hμν1(N)). | (3.6) |
The following result shows that the "total population" of the model (1.8) is bounded above.
Proposition 6. Assume f(I)≥0 for all I≥0 and that (H2), (H3) hold. Then the total population Tn:=Sn+In+Rn for (1.8) satisfies
lim supn→∞Tn≤S0,⋆, |
where S0,⋆ is given by (3.2).
Proof. Adding the equations in (1.8), applying the hypothesis (H2), and Proposition 3, we get
Tn+1=Tn+h(Λ(n)−μ1(n)Sn+1−μ2(n)In+1−μ3(n)Rn+1)≤Tn+h(Λ(n)−μ1(n)Tn+1), |
which implies
Tn+1≤hΛ(n)11+hμ1(n)+11+hμ1(n)Tn. |
The desired conclusion now follows from Lemma 1(3) and (H3).
As a corollary, we obtain the boundedness of solutions (Sn,In,Rn) of (1.8).
Corollary 7. Assume f(I)≥0 for all I≥0 and that (H2), (H3) hold. Then
lim supn→∞Sn≤S0,⋆,lim supn→∞In≤S0,⋆,lim supn→∞Rn≤S0,⋆. |
Proof. Since f≥0, we have by Proposition 3 that Sn>0,In>0,Rn>0 for all n>0. Then, we have Sn≤Tn,In≤Tn, and Rn≤Tn, hence the desired conclusion follows from Proposition 6.
Now we prove our first main result.
Theorem 8. Suppose that (H1)-(H4) hold, and that
R∞:=βlf(0)S0⋆μu2+k1>1, | (4.1) |
where S0⋆ is given by (3.3), βl=lim infn→∞β(n), and μu2=lim supn→∞μ2(n). Then the model (1.8) is permanent. Moreover, we will show that if
βlf(0)S0⋆μu2+Ku>1, | (4.2) |
where Ku=lim supn→∞Kn≤k1, then (1.8) is permanent.
Proof. It suffices to prove the second statement because βlf(0)S0⋆μu2+Ku≥R∞. Our proof is inspired by [18] and [14]. By the positivity (Proposition 3) and boundedness of solutions (Corollary 7), it suffices to prove uniform lower bounds (2.1) for Sn,In, and Rn of (1.8).
By the assumption (4.2) and (H1), there exist θ0>0 and ε0>0 sufficiently small such that
ξ:=(βl−θ0)(infI∈[0,ε0]f(I))(S0⋆−θ0)μu2+Ku+θ0>1. | (4.3) |
This also implies βl−θ0>0 and S0⋆−θ0>0. We also assume Kl−θ0>0.
Choose Q0∈N independent of solutions to (1.8) such that
if n≥n0+Q0then βl−θ0≤β(n)≤βu+θ0 and μ2(n)+Kn≤μu2+Ku+θ0. | (4.4) |
Estimate for Sn. There is a constant lS>0 such that lim infn→∞Sn≥lS.
Proof of Estimate for Sn. By the second estimate in Corollary 7, we can take P0∈N which depend on solution (Sn,In,Rn) so that
if n≥n0+P0thenmax0≤j≤m{S(n−j),I(n−j),R(n−j)}≤S0,⋆+θ0. |
Let n>n1≥n0+max{P0,Q0}. By Proposition 3, we have Rn+1≥0. Also, β(n)∑mj=0pjf(In−j)In−j≤(βu+θ0)fM(S0,⋆+θ0)<∞. Using the first equation in (1.8), we get
Sn+1≥h(Λ(n)−(βu+θ0)fM(S0,⋆+θ0)Sn+1−μ1(n)Sn+1)+Sn, |
that is
Sn+1≥hΛ(n)11+h˜μ1(n)+11+h˜μ1(n)Sn, |
where ˜μ1(n)=μ1(n)+(βu+θ0)fM(S0,⋆+θ0). Applying Lemma 1(4) and Proposition 5, we find that lim infn→∞Sn≥˜S0⋆>0 where
˜S0⋆=lim infN→∞N∑n=n1hΛ(n)(1+h˜μ1(n))⋯(1+h˜μ1(N)). | (4.5) |
Estimate for In. There is a constant lI>0 such that lim infn→∞In≥lI.
Proof of Estimate for In. We begin by proving a continuity result for the sum in (3.5) as ν→0.
Claim 1. Let θ0>0 be as specified in (4.3). Then there exist ν0,n′0,ρ, depending only on parameters in (1.8) and θ0 and satisfying
0<ν0≤ε0,n′0≥n0+max{m,Q0},ρ∈N, |
such that the following statement holds:
ifn1≥n′0,N≥n1+ρmthenN∑n=n1hΛ(n)(1+hμν01(n))⋯(1+hμν01(N))>S0⋆−θ0, |
where μν01:=μ1+βMfMν0 and S0⋆ is given by (3.3).
Proof of Claim 1. First we specify ν0. By (3.6), we have
Sν⋆=lim infN→∞N∑n=n1hΛ(n)(1+hμν1(n))⋯(1+hμν1(N)), |
and the limit does not depend on n1. We apply Lemma 1(5) with a(n)=hΛ(n),b(n)=1/(1+hμ1(n)), and ˜b(n)=1/(1+hμν1(n)) and ν>0. Note that ˜b(n)≥11+h(μM1+βMfMν)>0, where μM1=maxnμ1(n), and ˜b(n)≤b(n) for all n, so ˜bl>0 and ˜b satisfies (2.2). Also, |b(n)−˜b(n)|≤hβMfMν, so applying Lemma 1(5), there is a constant C>0 independent of ν such that
|Sν⋆−S0⋆|≤ChβMfMν. |
Now we choose ν0 small enough so that ν0≤ε0 and
ChβMfMν0<θ02. | (4.6) |
Then we have
Sν0⋆>S0⋆−θ02. |
Now we choose n′0,ρ. By Lemma 1(6), there exist n′0,ρ depending only on the Λ,μ1,f,m, and θ0, so that
ifn1≥n′0,N≥n1+ρmthenN∑n=n1hΛ(n)(1+hμν01(n))⋯(1+hμν01(n2))>Sν0⋆−θ02. |
Combining the above two estimates, we obtain the desired result.
Fix θ0>0 and ν0,n′0,ρ as above. Notice that n′0≥n0+Q0, so according to (4.4) we get
∀n≥n′0:βl−θ0≤β(n)≤βu+θ0,μ2(n)+Kn≤μu2+Ku+θ0. | (4.7) |
Next, we prove that if In≤ν0 on an interval of length at least ρ(m+1), then SN+1>S0⋆−θ0, where N is the right endpoint.
Claim 2. Let n1≥n′0, N≥n1+ρm, and (Sn,In,Rn) be a solution of (1.8). Then the following statement holds. If 0≤In≤ν0 for all n∈[n1−m,N], then
SN+1>S0⋆−θ0. | (4.8) |
Proof of Claim 2. Since Ip≤ν0 on [n1−m,N], we have for all n∈[n1,N] that
Gn=β(n)m∑j=0pjf(In−j)In−j≤βMm∑j=0pjfMν0=βMfMν0. |
This gives using (1.8) that Sn+1≥h(Λ(n)−βMfMν0Sn+1−μ1(n)Sn+1)+Sn, i.e.
Sn+1≥hΛ(n)11+hμν01(n)+11+hμν01(n)Snfor n=n1,n1+1,…,N. |
By induction, it is directly to see that
SN+1≥N∑n=n1hΛ(n)(1+hμν01(n))⋯(1+hμν01(N))+1(1+hμν01(n1))⋯(1+hμν01(N))Sn1≥N∑n=n1hΛ(n)(1+hμν01(n))⋯(1+hμν01(N)), |
by the positivity of Sn1. Applying Claim 1, the last term on the right hand side is greater than S0⋆−θ0, which implies SN+1>S0⋆−θ0. So the claim is proved.
In addition to the previous estimate for SN+1, at a right endpoint N, we also have the following boosting estimate for IN+1.
Claim 3. Let n1≥n′0, N≥n1+ρm, and (Sn,In,Rn) be a solution of (1.8). Then the following statement holds. If 0≤In≤ν0 for all n∈[n1−m,N], then
IN+1≥κIN,whereIN:=minp∈[N−m,N]Ip, | (4.9) |
and κ>1 is the constant given by
κ:=1+hξ(μu2+Ku+θ)1+h(μu2+Ku+θ). | (4.10) |
Proof of Claim 3. Observe that κ>1 because ξ>1. We can apply Claim 2 to get SN+1>S0⋆−θ0 and by (4.7) with that N≥n′0, we also have β(N)≥βl−θ0. Using (4.3) and that ν0≤ε0, we obtain
β(N)f(IN−j)SN+1≥(βl−θ0)(infI∈[0,ε0]f(I))(S0⋆−θ0)=ξ(μu2+Ku+θ0) |
for j=0,1,…,m. Also, noting that μ2(N)+KN≤μu2+Ku+θ0 by (4.7). Applying Lemma 2, we have
IN+1=IN+hβ(N)m∑j=0pjf(IN−j)IN−jSN+11+h(μ2(N)+KN)≥IN+hβ(N)m∑j=0pjf(IN−j)INSN+11+h(μ2(N)+KN)≥1+hm∑j=0pjξ(μu2+Ku+θ0)1+h(μu2+Ku+θ0)IN≥κIN, |
where we have used that ∑mj=0pj=1.
Claim 4. It is impossible that In≤ν0 for all sufficiently large n.
Proof of Claim 4. Suppose on the contrary that there is N0≥n′0 such that In≤ν0 for all n≥N0. Denote N1=N0+(ρ+1)m, and define In as in (4.9) above. Since In≤ν0 for all n∈[N0,N1], we have by Claim 3 that
IN1+1≥κIN1. |
This implies in particular that IN1+1=minn∈[N1+1−m,N1+1]In≥IN1 because κ>1. Repeating the preceding argument with that IN1+1≥IN1, we get IN1+2≥κIN1+1≥κIN1. Continuing the argument, we finally obtain
In≥κIN1for all n≥N1+1. |
This implies
∀n≥N1+1+m:In=min{In−m,…,In}≥κIN1. |
Let N2=N1+1+ρm. Since In≤ν0 for all n∈[N1+1−m,N2] and observe that IN2≥κIN1, it follows by the same argument as above that In≥κIN2≥κ2IN1 for all n≥N2+1. Repeating the process, we obtain, for Nl:=Nl−1+1+ρm, that
In≥κlIN1for all n≥Nl+1. |
Recalling κ>1, so κl→∞ as l→∞. Now by selecting l large enough, we get from the above that there is n>N0 such that In≥κlIN1>ν0. This contradicts that In≤ν0 for all n≥N0. Therefore the claim is proved.
After the above preparations, now we can prove the lower estimate for In. According to Claim 4, there are two possibilities: either
(i) In>ν0 for all n sufficiently large, or
(ii) In oscillates about ν0 for large n.
Obviously, if (i) occurs then the desired estimate follows, namely
lim infn→∞In≥ν0. |
So assume (ii).
It suffices to prove the following statement. Suppose n1,N are such that N>n1≥n′0 and
In1≥ν0,IN≥ν0,andIn<ν0for all n1<n<N. |
Then
∀n∈(n1,N):In≥lI:=ν0(1+h(μu2+Ku+θ0))Δ,Δ:=1+(ρ+1)m. | (4.11) |
Denote
n2=n1+1+Δ,n3=n2+1+Δ,n4=n3+1+Δ,… |
Let n>n1, so n−1≥n1≥n′0. By (4.7), we have μ2(n−1)+Kn−1≤μu2+Ku+θ0. Employing the second identity in Lemma 2 and the positivity of Gn−1,Sn, we get
In≥In−11+h(μ2(n−1)+Kn−1)≥In−11+h(μu2+Ku+θ0). |
By induction, we have for all p∈N satisfying n−p≥n1 that
In≥In−p(1+h(μu2+Ku+θ0))p. |
Case N≤n2. For any n∈(n1,N), it follows by taking p=n−n1, which satisfies p≤Δ, that
In≥In1(1+h(μu2+Ku+θ0))n−n1≥ν0(1+h(μu2+Ku+θ0))Δ=lI, |
where we have employed the fact that In1≥ν0. Thus in this case (4.11) is true.
Case n2<N≤n3. We use the preceding case on (n1,n2) to conclude that In≥lI for all n∈(n1,n2]. This implies In2≥lI. We show that In≥lI for n∈(n2,N] as well. Since In≤ν0 on [n1+1,n2] and n2≥(n1+1)+(ρ+1)m, it follows by Claim 3 that
In2+1≥κIn2≥κlI>lI(∵κ>1). |
If n2+1=N then we are done. Otherwise, we employ that In≤ν0 on [n1+2,n2+1] to continue the preceding argument and get
In2+2≥κminp∈[n2+1−m,n2+1]Ip≥κlI>lI. |
By induction, we finally conclude that In≥lI for all n∈(n2,N] as desired.
Cases that n3<N≤n4 and so on can be proved by the same argument and is omitted.
Now (4.11) is proved hence establishing the desired estimate for In.
Estimate for Rn. There exists a positive constant lR such that lim infn→∞Rn≥lR.
Proof of Estimate for Rn. First observe that, from the estimate for In, we get that
∀n≥n′0:In≥lI, |
where lI is given by (4.11). Choose Q′0>0 so that
if n≥n′0+Q′0 thenμ3(n)+γ(n)≤μu3+γu+θ0,Kn≥Kl−θ0. |
Note that Kl−θ0>0 according to (4.3). Let n≥n′0+Q′0. Using the third equation of Lemma 2, we get
Rn+1=Rn+hKnIn+1Π3(n)≥hlI(Kl−θ0)11+h(μu3+γu+θ0)+11+h(μu3+γu+θ0)Rn. | (4.12) |
We can apply parts (2) and (4) of Lemma 1 to find that there is a constant lR>0, independent of solutions to (1.8) such that
lim infn→∞Rn≥lR. | (4.13) |
This establish the estimate for Rn, therefore it completes the proof of Theorem 8.
We prove that under a certain condition the disease of the model (1.8) always extincts.
Theorem 9. Suppose that (H1)-(H4) hold and that
R0:=βu(supI∈[0,S0,⋆]f(I))S0,⋆μl2+k0<1, | (5.1) |
where S0,⋆ is given by (3.2), βu=lim supn→∞β(n), and μl2=lim infn→∞μ2(n). Then (1.8) exhibits the extinction of the disease. Moreover, we will show that if
βu(supI∈[0,S0,⋆]f(I))S0,⋆μl2+Kl<1, | (5.2) |
where Kl:=lim infn→∞Kn≥k0, then (1.8) exhibits the extinction of the disease.
Proof of Theorem 9. It suffices to prove the second statement because βu(supI∈[0,S0,⋆]f(I))S0,⋆μl2+Kl≤R0. We shall repeatedly employ the results on positivity (Proposition 3) and boundedness of solutions (Proposition 6 and Corollary 7).
By the assumption (5.2) and the continuity of f (H1), we choose θ0 and ε0>0 such that
ξ:=(βu+θ0)(supI∈[0,S0,⋆+ε0]f(I))(S0,⋆+θ0)μl2+Kl−θ0<1. | (5.3) |
Warning! Here and below, for simplicity, the parameters θ0,ε0,ξ,n′0,κ,… have been reused and are in no connection to corresponding ones appeared in the proof of Theorem 8.
Let (Sn,In,Rn) be a solution of (1.8). We also choose n′0>0 such that if n≥n′0 then
β(n)≤βu+θ0,μ2(n)+Kn≥μl2+Kl−θ0 |
and
In≤S0,⋆+ε0,Sn≤S0,⋆+θ0. |
Now let n≥n′0+m. We observe that
f(In−j)≤supI∈[0,S0,⋆+ε0]f(I),j=0,1,…,m. |
So Gn=β(n)m∑j=0pjf(In−j)In−j≤(βu+θ0)(supI∈[0,S0,⋆+ε0]f(I))˜In, where
˜In:=maxp∈[n−m,n]Ip. | (5.4) |
Applying the second equation in (2.9) and that Sn+1≤S0,⋆+θ0, we get
In+1=In+hGnSn+1Π2(n)+hKn≤˜In+h(βu+θ0)(supI∈[0,S0,⋆+ε0]f(I))˜In(S0,⋆+θ0)1+h(μ2(n)+Kn)=1+hξ(μl2+Kl−θ0)1+h(μ2(n)+Kn)˜In≤1+hξ(μl2+Kl−θ0)1+h(μl2+Kl−θ0)˜In. |
In other words, we now obtain
In+1≤κ˜In, | (5.5) |
where 0<κ<1 is the constant given by
κ=1+hξ(μl2+Kl−θ0)1+h(μl2+Kl−θ0). | (5.6) |
Employing (5.5), we are going to show that
˜In+m+1≤κ˜In | (5.7) |
for all n≥n′0+m.
By (5.5) we have In+1≤κ˜In, so ˜In+1=maxp∈[n+1−m,n+1]Ip≤˜In. Then by (5.5) again In+2≤κ˜In+1, hence In+2≤κ˜In. Similarly, (5.5) gives In+3≤κ˜In+2 and ˜In+2=max[n+2−m,n+2]Ip≤˜In, so In+3≤κ˜In. By induction, we get In+p≤κ˜In for all p=1,2,…. Now
˜In+m+1=max{In+1,…,In+m+1}≤κ˜In, |
proving (5.7).
We apply the conclusion from (5.7). Setting
N0=n′0+m,Nj+1=Nj+m+1,j=0,1,2,…, |
we directly get
˜INj+1≤κ˜INj. |
Since κ<1, the sequence {˜INj} is monotonically decreasing. It is easy to see that ˜INj≤κj˜IN0, hence
limj→∞˜INj=0. | (5.8) |
Now we prove the extinction of the disease, i.e. limn→∞In=0.
Let ε>0. By (5.8) we can find j such that ˜INj≤ε. Now let n≥Nj. We have n∈[Nr−1,Nr) for some r≥j+1. Then In≤˜INr≤˜INj≤ε. Therefore In→0 as desired.
In this section, the model (1.8) is considered with non-monotone incidence rate
g(I)=α3I1+α2I+α1I2. |
For simplicity, some parameters are fixed as follows: h=1, m=2, p0=0.2, p1=0.3, p2=0.5, α3=2, α1=1, {Λ(n)}=(1,1.2,1,1.2,…), {γ(n)}=(0.3,0.3,0.3,…), {μ2(n)}=(0.5,0.8,0.5,0.8,…), {μ1(n)}={μ3(n)}=(0.2,0.4,0.2,0.4,…), {β(n)}=(1,1,1,…). We also impose the following initial conditions: Sj=3, Ij=1, Rj=0.5 (j=0,−1,−2). From the formulas (3.2) and (3.3), we have S0,⋆=S0⋆=3.2353.
Now, we present the examples and numerical simulations for different α2,k0,k1.
Example 1. Choose α2=0.3. We have f(I)=g(I)I=21+0.3I+I2. Since f is a decreasing function, we have f(0)=supI∈[0,S0,⋆]f(I)=2. Also βu=βl=1. We use Kn=k0+(k1−k0)10In+10.
(a) If k0=8 and k1=9, then we get Ku=Kl=9 and βu(supI∈[0,S0,⋆]f(I))S0,⋆μl2+Kl=0.6811, R0=0.7612<1. Figure 1(a) indicates that the disease exhibits extinction.
(b) If k0=1 and k1=3, we get Ku=2.9556, Kl=2.9525, and βlf(0)S0⋆μu2+Ku=1.7229, and R∞=1.7029>1. Figure 1(b) indicates that the disease is permanent.
Example 2. Choose α2=−1. We have f(I)=g(I)I=21−I+I2. It is directly to calculate that f(0)=2 and supI∈[0,S0,⋆]f(I)=2.6667. Again βu=βl=1. We use Kn=k0+(k1−k0)10In+10.
(a) If k0=9 and k1=10, then we get Ku=Kl=10, βu(supI∈[0,S0, ⋆ ] f(I))S0,⋆μl2+Kl=0.8217, and R0=0.9082<1. Figure 2(a) indicates that the disease exhibits extinction.
(b) If k0=2 and k1=4, we get Ku=3.9618,Kl=3.9595, βlf(0)S0⋆μu2+Ku=1.3589, and R∞=1.3480>1. Figure 2(b) indicates that the disease is permanent.
In this paper, we investigate the discrete-time non-autonomous SIRS epidemic model (1.8), which is a discretization by the nonstandard finite difference method of the continuous-time model (1.4). In the model, a general nonlinear incidence rate with distributed delays is included together with a nonlinear recovery rate which takes into account the effect of health care resources such as the hospital beds (1.3). Two threshold parameters R0 and R∞ are obtained so that if R0<1 then the disease dies out while if R∞>1 then the disease is permanent.
In the special case of autonomous (1.8), f is a decreasing function, and k a constant, our results imply that R0=R∞=βf(0)Λμ1(μ2+k), which gives the basic reproduction number of the model. The same number is reported in Corollary 5.4 of [27] when f=1. This result is also in line with the known results for the continuous-time models [12] when f=1, and [3] when f is decreasing and f(0)=1.
For the non-autonomous model (1.8), we obtain the following corollary. Suppose that, as n→∞, we have β(n)→β′, Λ(n)→Λ′, μ1(n)→μ′1, μ2(n)→μ′2, k(n)→k′ (k does not depend on In), and f=1. Then we obtain the reproduction number of the model to be R0=R∞=β′S′μ′2+k′, which is the same number implied by Theorem 4.1 and Theorem 5.1 in [27]. Comparing this result to that from the continuous-time model in [25,26], we find an improvement because the threshold parameters obtained in those two papers do not lead to the reproduction number of the model.
A novelty of this paper is that our results are mathematically more tractable (compared e.g. to [27]) so they can be effective tools in practice to help the policy-makers fight the spread of the disease. To employ the condition (5.2), for example, one can first set the "ultimate" contact rate β∞ and health care resources K∞ so that the condition is met with βu,Kl replaced by β∞,K∞ (assuming all other parameters are available and fixed). Then set a certain starting time N0 and control the transmission rate and the hospital beds to satisfy β(n)≤β∞ and Kn≥K∞ for all n≥N0 onward. It then follows from Theorem 9 that the spreading of the disease will be suppressed eventually.
For further investigations, it is interesting to extend the results of this paper to the model (1.8) where the transmission function f depends not only on I but also on S, such as the Beddington-DeAngelis function f(S,I)=S/(1+m1S+m2I) and the saturated incidence f(S,I)=S/(1+m1S)(1+m2I). It is also interesting to apply the technique in this paper to explore the threshold dynamics for other non-autonomous models such as a model with vaccination, a model with age structures, multi-strain diseases, etc.
Another interesting question is the chaotic dynamics of epidemic models with seasonality in the transmission rate [1,9]. It was shown in [1] for the classical SIR model that the disease dies out when R0<1, where R0 is the reproduction number, while if R0>1 the model admits periodic and aperiodic patterns together with sensitive dependence on the initial conditions of the solution. The SIR model with logistic growth rate was explored in [9] and it was shown that the condition R0<1 is not sufficient to guarantee the extinction of the disease due to backward bifurcation and the model exhibits persistent strange attractors. For our model (1.8), the condition R0<1 always implies the elimination of the disease regardless of the initial infectives. Moreover, for the periodic forced model with f=1, it was shown in Corollary 5.3 [27] that if R0<1 the disease dies out while it is permanent when R0>1, where R0 is given explicitly by R0=∏ω−1k=0(1+β(k)z∗k1+μ(k)+γ(k)+α(k))1/ω and z∗k is a unique ω-periodic solution of (3.1). In our work, f is a nonlinear function, so it is an interesting open problem to see whether a chaotic behavior can happen when R0>1 due to the seasonally forced contact rate β.
We briefly discuss the basic idea of the nonstandard finite difference (NSFD) method that enables to get the discrete model (1.8) from the continuous model (1.4). NSFD is a discretization technique consisting of some rules with the aim to preserve significant properties of the related continuous problem (such as positivity, boundedness, stability, etc.) and avoid numerical instabilities. The following rules were proposed by Mickens [10] for constructing a NSFD scheme from a continuous problem:
Rule 1. The orders of the discrete derivatives of the scheme should be equal to the orders of the corresponding derivatives of the differential equation.
Rule 2. The denominator function for each discrete derivative should, in general, be expressed as a function of step-size which is more complicated than the conventional one. This rule is not strict and in this work, to get (1.8), we choose ϕ(h)=h.
Example. Consider a first-order differential equation of the form
dxdt=f(t,x). | (8.1) |
Conventionally, the discrete derivative for dx/dt in (8.1) is given by
xk+1−xkΔt, |
but, in the NSFD scheme, the denominator Δt is replaced by a denominator function ϕ(h) with the property
ϕ(h)=h+O(h2) as h→0. |
Rule 3. Nonlinear terms should, in general, be replaced by nonlocal discrete representations using more than one mesh point. For example, the nonlinear term x2 can be replaced by a nonlocal representation evaluated at two mesh points such as xk+1xk or 2x2k−xk+1xk.
To get (1.8), the incidence rate (1.7) is discretized by β(n)∑mj=0pjf(In−j)In−jSn+1.
Rule 4. Special conditions that hold for the solutions of the differential equations should also hold for the solutions of the finite difference scheme. An important example is the positivity of solutions when the solutions represent some physical positive quantities. If the discrete equations allow their solutions to become negative, then numerical instabilities will occur.
We have shown the basic properties including Propositions 3 and 6.
Rule 5. The finite difference scheme should not introduce extraneous or spurious solutions that do not correspond to any solution of the corresponding differential equations.
The authors declare that there are no conflicts of interest.
The authors would like to thank the reviewers for valuable comments and suggestions which are tremendously helpful to improve the manuscript. We are thankful for financial support by Science Achievement Scholarship of Thailand (SAST). We are also supported by the 90th Anniversary of Chulalongkorn University Fund, Thailand (Ratchadaphiseksomphot Endowment Fund).
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