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Research article

A dissipative third-order boundary value problem with distributional potentials and eigenparameter-dependent boundary conditions

  • Received: 27 December 2024 Revised: 08 May 2025 Accepted: 23 May 2025 Published: 29 May 2025
  • This paper investigates a class of dissipative boundary value problems arising from a third-order differential equation with distributional potentials and eigenparameter-dependent boundary conditions. Initially, we transform the boundary value problem into the corresponding operator problem. We then demonstrate that the operator is dissipative and examine certain eigenvalue properties of the operator. Furthermore, by applying Krein's theorem, we establish the completeness theorems for both the boundary value problem and the corresponding operator.

    Citation: Fei-fan Li, Ji-jun Ao. A dissipative third-order boundary value problem with distributional potentials and eigenparameter-dependent boundary conditions[J]. Electronic Research Archive, 2025, 33(5): 3378-3393. doi: 10.3934/era.2025149

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  • This paper investigates a class of dissipative boundary value problems arising from a third-order differential equation with distributional potentials and eigenparameter-dependent boundary conditions. Initially, we transform the boundary value problem into the corresponding operator problem. We then demonstrate that the operator is dissipative and examine certain eigenvalue properties of the operator. Furthermore, by applying Krein's theorem, we establish the completeness theorems for both the boundary value problem and the corresponding operator.



    Boundary value problems (BVPs) with distributional potentials hold significant theoretical and practical importance. They are not only utilized in the study of Schrödinger operators with distributional potentials in quantum mechanics but also encompass boundary value problems with transmission conditions. Within quantum mechanics, Schrödinger equations incorporating generalized potential functions are commonly employed to portray the interactions between individual particles[1,2]. These potentials are frequently associated with issues described as point interactions. Beyond quantum mechanics, such potentials are present in disciplines like solid-state physics, atomic and nuclear physics, and electromagnetism[1,3]. To provide a robust mathematical framework for addressing problems with distributional potentials, it is necessary to relax the integrability condition of the potential function in classical Sturm-Liouville theory. This approach not only extends classical Sturm-Liouville theory but also introduces new characteristics pertinent to physical problems. In recent years, scholars have explored this area from multiple perspectives, resulting in significant discoveries [1,2,3,4,5,6].

    Recently, third-order boundary value problems with non-smooth coefficients and distributional potentials have garnered significant attention from scholars[7,8,9,10]. Third-order differential equations are pivotal in a variety of physical applications, such as in modeling thin membrane flow of viscous liquid and elastic beam vibrations [11,12,13].

    In addition, one of the research topics of boundary value problems is boundary value problems with eigenparameter-dependent boundary conditions. A specific example is the equation of motion of a clamped-free elastic beam with a mass-spring system attached at its free end, which leads to a boundary eigenvalue problem[14]

    y(4)=λ(y(2)cy),y(0)=0,y(0)=0,y(2)(1)=0,β(λ)y(3)(1)+α(λ)y(1)=0.

    Here the coefficients α(λ) and β(λ) are polynomials in λ of degree 3 and 2, respectively. The constant c in the differential equation is nonzero if, in addition, a fluid is flowing over the bar with constant velocity, which may be regarded as a model for pulling out glass or plastics on a solid foundation. Furthermore, many other problems in various engineering fields can also be transformed into boundary value problems with eigenparameter-dependent boundary conditions, such as heat conduction problems, and vibrating string problems and so on[14,15,16]. In recent years, scholars have had a strong interest in this kind of problem, and published a series of excellent research results[14,15,16,17].

    There are many methods to study boundary value problems; one of the most important and effective methods is the spectral analysis method. That is, by defining an appropriate inner product space, the boundary value problem is transformed into a related operator problem. The operator has the same eigenvalues as the original boundary value problem, and their eigenfunctions are the same or have special correspondences.

    Dissipative differential operators are a significant topic in the study of the spectral theory of differential operators and have a broad range of applications. For instance, they are widely used in various areas, including the analysis of Cauchy problems in partial differential equations, scattering theory, and infinite-dimensional dynamical systems[18,19].

    In the past period of time, dissipative differential operators with general separated or coupled boundary conditions have been investigated by many authors. For example, in [20,21] the authors have investigated the general dissipative Sturm-Liouville operator and gave all the dissipative boundary conditions of order 2. Significantly, the determinant of perturbation connected with the dissipative operator L generated in L2(I) by the Sturm-Liouville differential expression has been studied by Bairamov and Uğurlu in [22], they used the Liv˘sic theorem to prove the completeness of the system of eigenfunctions and associated functions of this operator. They also have studied the dissipative boundary value problems with transmission conditions and have shown the completeness of the root functions by using Krein's theorem[23,24]. The study of fractional dissipative Sturm-Liouville operator can be found in recent work [25] and the studies of higher order dissipative operators can be found in [26,27,28], respectively.

    However, there remains relatively little research on dissipative operators with special boundary conditions, such as those with eigenparameter-dependent boundary conditions[29,30]. Particularly, no conclusions have been drawn yet for such problems of odd orders. Based on the aforementioned studies, the goal of this paper is to study a dissipative third-order boundary value problem with distributional potentials and eigenparameter-dependent boundary conditions, in further by using Krein's theorem to prove the completeness theorems of the root vectors of the boundary value problem.

    The paper is organized as follows: Following this introduction, in Section 2 we introduce the notation of the problems studied here and transform the original boundary value problem into a related isospectral operator problem. Section 3 shows the proof of the operator being dissipative and lists some properties of the eigenvalues of the operator. In Section 4, we review the characteristic function and the Green's function of the dissipative boundary value problem and prepare for the proof of the completeness theorems. Then we prove the completeness theorems of the boundary value problem and the operator by using Krein's theorem in Section 5. Finally, a brief conclusion is given in Section 6.

    Consider the general third-order differential equation with distributional potentials

    l(u)=1w{i(q0(q0u))+i[q1u+(q1u)](p0[u+su])+sp0[u+su]+p1u}=λuonJ, (2.1)

    here

    J=[a,b],<a<b<, (2.2)

    and the coefficients satisfy:

    q0,q1,p0,p1,s,w:JR,q10,q1,p0,p1,s,sp0,s2p0,q1q0,sp0q0,p0q20,wL1(J),q0>0onJandw>0a.e.onJ. (2.3)

    Similar to [9] and [28], we can introduce the following notations. Firstly, let us introduce the quasi-derivative u[j] (since the equation is third-order here, we chose j = 0,1,2) of a function u as follows:

    u[0]=u,u[1]=q0u,u[2]=iq0(q0u)iq1u+p0(u+su),

    then (2.1) can be expressed as

    l(u)=1w[(u[2])+iq1+sp0q0u[1]+(s2p0+p1)u]=λu,onJ, (2.4)

    and further, it can be handled as the following Hamiltonian system

    GY=(λW+P)Y,

    where W and P are 3×3 matrices, Y is a 3×1 vector such that

    G=(0010i0100),W=(w00000000),Y=(uu[1]u[2]),

    and

    P=((s2p0+p1)iq1+sq0q00iq1sq0q0p0q201q001q00).

    For the next discussions, we first define a weighted space

    H=L2w(J)={u:ba|u(x)|2w(x)dx<},

    and the inner product in this space as f,gH=bafˉgw(x)dx for any f,gH.

    For arbitrary u,vH, the Lagrange identity can be introduced as

    [u,v]:=u¯v[2]u[2]¯v+iu[1]¯v[1]. (2.5)

    Now consider the set

    Ω={uH:u,u[1],u[2]AC[a,b],l(u)H},

    for arbitrary two functions u,vΩ, we have the Green's formula

    l(u),vHu,l(v)H=[u,v]ba, (2.6)

    where [u,v]t2t1=[u,v](t2)[u,v](t1).

    Then we consider the BVP consisting of the following differential equation

    i(q0(q0u))+i[q1u+(q1u)](p0[u+su])+sp0[u+su]+p1u=λwuonJ, (2.7)

    and the boundary conditions (BCs):

    l1(u)=(ˆα1λα1)u(a)(ˆα2λα2)u[2](a)=0, (2.8)
    l2(u)=u[1](a)ru[1](b)β1u[2](b)=0, (2.9)
    l3(u)=u(b)ir¯β1u[1](b)β2u[2](b)=0, (2.10)

    where λ is a complex parameter, and the coefficients satisfy the conditions:

    αj,ˆαj,rR,j=1,2,βkC,k=1,2,η:=ˆα1α2ˆα2α1>0,|r|1,andβ212r2. (2.11)

    In this paper will use the symbols and to denote the real and imaginary parts of a certain operator or parameter, respectively.

    Next, define a direct sum space H=HC with a new inner product

    (f,f1)T,(g,g1)TH=f,gH+1ηf1¯g1,

    for any (f,f1)T,(g,g1)TH.

    From BC (2.8), one has

    λ(ˆα1u(a)ˆα2u[2](a))=α1u(a)α2u[2](a),

    which can be written as

    λR(u)=˜R(u),

    by setting

    R(u)=ˆα1u(a)ˆα2u[2](a),˜R(u)=α1u(a)α2u[2](a).

    Now consider the following set

    D(Lh)={U=(uR(u))H:uΩ,R(u)C,lj(u)=0,j=2,3},

    and define the operator Lh on D(Lh) as

    Lh(uR(u))=(l(u)˜R(u))=λ(uR(u)).

    Then we will present the relationship between the BVP (2.7)–(2.11) and the operator Lh.

    Definition 1. The system of functions u0,u1,...,un is called a chain of eigenfunctions and associated functions of the BVP (2.7)–(2.11) corresponding to the eigenvalue λj if the conditions

    l(u0)=λju0,˜R(u0)λjR(u0)=0,l2(u0)=0,l3(u0)=0, (2.12)
    l(us)λjusus1=0,˜R(us)λjR(us)R(us1)=0, (2.13)
    l2(us)=0,l3(us)=0,s=1,...,n, (2.14)

    are realized.

    Then we have

    Lemma 1. Including their multiplicity, the eigenvalues of the BVP (2.7)–(2.11) and the eigenvalues of the operator Lh coincide. Each chain of eigenfunctions and associated functions of the BVP (2.7)–(2.11), meeting the requirements of the eigenvalue λj, corresponds to the chain of eigenvectors and associated vectors U0,U1,...,Un of the operator Lh corresponding to the same eigenvalue λj. In this case, the equalities

    Uk=(ukR(uk)),k=0,1,...,n, (2.15)

    take place.

    Proof. If U0D(Lh) and LhU0=λjU0, then the equalities l(u0)=λju0,˜R(u0)λjR(u0)=0,l2(u0)=0,l3(u0)=0 take place, i.e., u0 is an eigenfunction of the BVP (2.7)–(2.11). Conversely, if conditions (2.12) are realized, then (u0R(u0))=U0D(Lh) and LhU0=λjU0, i.e., U0 is an eigenvector of the operator Lh.

    Furthermore, if U0,U1,...,Un are a chain of the eigenvectors and associated vectors of the operator Lh corresponding to the eigenvalue λj, then by implementing the conditions UkD(Lh),k=0,1,...,n, and equality LhU0=λjU0,LhUs=λjUs+Us1,s=1,...,n, we get the equalities (2.12)–(2.14), where u0,u1,...,un are the first components of the vectors U0,U1,...,Un. On the contrary, on the basis of the elements u0,u1,...,un corresponding to the BVP (2.7)-(2.11), one can construct the vectors Uk=(ukR(uk)) for which UkD(Lh),k=0,1,...,n, and LhU0=λjU0,LhUs=λjUs+Us1,s=1,...,n.

    Now the proof is finished.

    The dissipative operator is defined as follows.

    Definition 2. A linear operator Lh, acting in the Hilbert space H and having domain D(Lh), is said to be dissipative if (LhF,F)0,FD(Lh).

    Theorem 1. The operator Lh is dissipative in H.

    Proof. For UD(Lh), we have

    2i(LhU,U)=(LhU,U)(U,LhU)=[u,u]ba+1η˜R(u)¯R(u)1ηR(u)¯˜R(u), (3.1)

    where

    1η˜R(u)¯R(u)1ηR(u)¯˜R(u)=1η[(α1u(a)α2u[2](a))(ˆα1¯u(a)ˆα2¯u[2](a))(ˆα1u(a)ˆα2u[2](a))(α1¯u(a)α2¯u[2](a))]=1η[(ˆα1α2α1ˆα2)u(a)¯u[2](a)(ˆα1α2α1ˆα2)u[2](a)¯u(a)]=u(a)¯u[2](a)u[2](a)¯u(a),

    then, applying (2.5), it follows that

    2i(LhU,U)=u(b)¯u[2](b)u[2](b)¯u(b)+iu[1](b)¯u[1](b)(u(a)¯u[2](a)u[2](a)¯u(a)+iu[1](a)¯u[1](a))+(u(a)¯u[2](a)u[2](a)¯u(a))=u(b)¯u[2](b)u[2](b)¯u(b)+iu[1](b)¯u[1](b)iu[1](a)¯u[1](a). (3.2)

    From (2.9) and (2.10), it has

    u[1](a)=ru[1](b)+β1u[2](b), (3.3)

    and

    u(b)=ir¯β1u[1](b)+β2u[2](b), (3.4)

    substituting (3.3) and (3.4) into (3.2), one obtains

    2i(LhU,U)=(LhU,U)(U,LhU)=i(1r2)u[1](b)¯u[1](b)+i(2γ2r2)u[2](b)¯u[2](b), (3.5)

    and hence

    2(LhU,U)=su[1](b)¯u[1](b)+du[2](b)¯u[2](b)=s|u[1](b)|2+d|u[2](b)|2, (3.6)

    where

    s=1r2,d=2β2r2.

    Since |r|1,β212r2, we have s0 and d0, that is

    (LhU,U)0,UD(Lh).

    Hence Lh is a dissipative operator in H.

    Theorem 2. If |r|<1,β2>12r2, then the operator Lh has no real eigenvalue.

    Proof. Suppose λ0 is a real eigenvalue of Lh. Let Φ0(x)=(ϕ0(x)R(ϕ0(x)))=(ϕ(x,λ0)R(ϕ(x,λ0)))0 be a corresponding eigenvector. Since

    (LhΦ0,Φ0)=(λ0(||ϕ0||2+|R(ϕ0)|2))=0,

    from (3.6), it follows that

    (LhΦ0,Φ0)=12(sϕ[1]0(b)¯ϕ[1]0(b)+dϕ[2]0(b)¯ϕ[2]0(b))=12(¯ϕ[1]0(b)¯ϕ[2]0(b))(s00d)(ϕ[1]0(b)ϕ[2]0(b))=0,

    since |r|<1,β2>12r2, the matrix

    (s00d)

    is positive definite. Hence ϕ[1]0(b)=0 and ϕ[2]0(b)=0, and by the BCs (2.9) and (2.10), we obtain that ϕ[1]0(a)=0 and ϕ0(b)=0. Let ϕ0(x)=ϕ(x,λ0),τ0(x)=τ(x,λ0) and σ0(x)=σ(x,λ0), be three linearly independent solutions of equation l(u)=λ0u; then by the above results it has

    |ϕ0(b)τ0(b)σ0(b)ϕ[1]0(b)τ[1]0(b)σ[1]0(b)ϕ[2]0(b)τ[2]0(b)σ[2]0(b)|=0, (3.7)

    however, on the other hand the Wronskian of ϕ0(x),τ0(x),σ0(x) is not 0; this is a contradiction. Thus the theorem is proven.

    In this section, to prepare for the proof of the completeness theorems, we review the characteristic function and Green's function and use the Green's function to study the inverse of Lh.

    Let φ,ψ, and χ be the linearly independent solutions of the third-order equation (2.7) on [a,b] satisfying the following initial conditions:

    (φψχφ[1]ψ[1]χ[1]φ[2]ψ[2]χ[2])(a,λ)=(100010001), (4.1)

    and let

    Ψ(x,λ)=(φψχφ[1]ψ[1]χ[1]φ[2]ψ[2]χ[2])(x,λ),x[a,b],

    and the coefficient matrix of the BCs (2.8)–(2.10) be denoted by (Aλ:B), where Aλ and B are both 3×3 matrices, then we have the following conclusions.

    Lemma 2. The complex number λ is an eigenvalue of the BVP (2.7)–(2.11) if and only if the characteristic function

    Δ(λ):=|l1(φ)l1(ψ)l1(χ)l2(φ)l2(ψ)l2(χ)l3(φ)l3(ψ)l3(χ)|=det[Aλ+BΨ(b,λ)]=0.

    Proof. If λ is an eigenvalue of BVP (2.7)–(2.11), then there exists a non-trivial solution

    u(x,λ)=c1φ(x,λ)+c2ψ(x,λ)+c3χ(x,λ) (4.2)

    of (2.7), and the BCs (2.8)–(2.10) are satisfied, where c1,c2,c3C are not all zero. Since u(x,λ) satisfies the BCs (2.8)–(2.10), we have

    Aλ(c1(φ(a,λ)φ[1](a,λ)φ[2](a,λ))+c2(ψ(a,λ)ψ[1](a,λ)ψ[2](a,λ))+c3(χ(a,λ)χ[1](a,λ)χ[2](a,λ)))
    +B(c1(φ(b,λ)φ[1](b,λ)φ[2](b,λ))+c2(ψ(b,λ)ψ[1](b,λ)ψ[2](b,λ))+c3(χ(b,λ)χ[1](b,λ)χ[2](b,λ)))=0,

    via the initial conditions (4.1), we have

    (Aλ+BΨ(b,λ))(c1,c2,c3)T=0. (4.3)

    Since c1,c2, and c3 are not all zero, then the determinant of the coefficient matrix

    Δ(λ):=det[Aλ+BΨ(b,λ)]=0.

    Conversely, if Δ(λ)=0, then equation (4.3) has a non-zero solution (c1,c2,c3)T. Choose such a solution and define u(x,λ) as in (4.2). Then u(x,λ) satisfies the BVP ((2.7)–(2.11) and thus is an eigenfunction. Therefore, λ is an eigenvalue of the BVP (2.7)–(2.11).

    Definition 3. Let g(λ) be an entire function of λ, if for any ε>0, there exists a positive constant Cε>0, such that

    |g(λ)|Cεeε|λ|,λC,

    then g(λ) is called an entire function with growth of order 1 and minimal type.

    According to Definition 3, we can easily obtain that φ(b,λ),ψ(b,λ), and χ(b,λ) are entire functions of λ with growth of order 1 and minimal type; therefore, Δ(λ) is an entire function of λ with growth of order 1 and minimal type, and then we have the following conclusion.

    Corollary 1. The entire function Δ(λ) is of growth order 1 and minimal type: for any ε>0, there exists a positive constant Cε such that

    |Δ(λ)|Cεeε|λ|,λC, (4.4)

    and hence

    lim sup|λ|ln|Δ(λ)||λ|0. (4.5)

    From Theorem 3.2 it follows that zero is not an eigenvalue of Lh(i.e.,KerLh=0), hence the operator L1h exists. Now we show an analytical representation of L1h.

    Consider the operator equation

    LhU=F,F=(f(x)f1)H,

    then the operator equation is equivalent to the non-homogeneous boundary value problem composed of the equation l(u)=f(x) and the boundary condition ˜R(u)f1=0 and the BCs (2.9) and (2.10). Let u(x) be the solution of the above non-homogeneous boundary value problem, and set φ0(x)=φ(x,0),ψ0(x)=ψ(x,0),χ0(x)=χ(x,0), then

    u(x)=C1φ0(x)+C2ψ0(x)+C3χ0(x)+u(x),

    where Cj,j=1,2,3 are arbitrary constants and u(x) is a special solution.

    It can be obtained by the method of constant variation

    u(x)=C1(x)φ0(x)+C2(x)ψ0(x)+C3(x)χ0(x),

    where Cj,j=1,2,3 satisfies

    {C1(x)φ0(x)+C2(x)ψ0(x)+C3(x)χ0(x)=0,C1(x)φ[1]0(x)+C2(x)ψ[1]0(x)+C3(x)χ[1]0(x)=0,1w(C1(x)φ[2]0(x)+C2(x)ψ[2]0(x)+C3(x)χ[2]0(x))=f(x).

    Solve the equations above, one has

    C1(x)=w(x)f(x)D(x)|ψ0(x)χ0(x)ψ[1]0(x)χ[1]0(x)|,C2(x)=w(x)f(x)D(x)|φ0(x)χ0(x)φ[1]0(x)χ[1]0(x)|,C3(x)=w(x)f(x)D(x)|φ0(x)ψ0(x)φ[1]0(x)ψ[1]0(x)|,

    where

    D(x)=det[Ψ(x,0)].

    By proper calculation, it can be obtained that

    u(x)=baK(x,ξ)f(ξ)dξ,

    where

    K(x,ξ)={w(ξ)D(ξ)|φ0(ξ)ψ0(ξ)χ0(ξ)φ[1]0(ξ)ψ[1]0(ξ)χ[1]0(ξ)φ0(x)ψ0(x)χ0(x)|,a<ξx<b,0,a<xξ<b. (4.6)

    Then

    u(x)=C1φ0(x)+C2ψ0(x)+C3χ0(x)+baK(x,ξ)f(ξ)dξ,

    substituting u(x) into ˜R(u)f1=0 and the BCs (2.9) and (2.10), one obtains

    Cj=1Δ(0)baFj(ξ)f(ξ)dξ,j=1,2,3, (4.7)

    where

    Δ(0):=det[A0+BΨ(b,0)], (4.8)
    F1(ξ)=|˜R(K)f1(ba)f(ξ)˜R(ψ0)˜R(χ0)l2(K)l2(ψ0)l2(χ0)l3(K)l3(ψ0)l3(χ0)|, (4.9)
    F2(ξ)=|˜R(φ0)˜R(K)f1(ba)f(ξ)˜R(χ0)l2(φ0)l2(K)l2(χ0)l3(φ0)l3(K)l3(χ0)|, (4.10)
    F3(ξ)=|˜R(φ0)˜R(ψ0)˜R(K)f1(ba)f(ξ)l2(φ0)l2(ψ0)l2(K)l3(φ0)l3(ψ0)l3(K)|, (4.11)

    then u(x) can be represented as

    u(x)=ba1Δ(0)[F1(ξ)φ0(x)+F2(ξ)ψ0(x)+F3(ξ)χ0(x)K(x,ξ)Δ(0)]f(ξ)dξ.

    Let

    G(x,ξ)=1Δ(0)|φ0(x)ψ0(x)χ0(x)K(x,ξ)˜R(φ0)˜R(ψ0)˜R(χ0)˜R(K)f1(ba)f(ξ)l2(φ0)l2(ψ0)l2(χ0)l2(K)l3(φ0)l3(ψ0)l3(χ0)l3(K)|, (4.12)

    then

    u(x)=baG(x,ξ)f(ξ)dξ.

    Now define the operator Th as

    ThF=(baG(x,ξ)f(ξ)dξR(baG(x,ξ)f(ξ)dξ)),F=(f(x)f1)H, (4.13)

    clearly, Th is the inverse operator of Lh; this implies that the root vectors (eigenvectors and associated vectors) of the operators Th and Lh coincide.

    Further, in order to better illustrate the completeness theorems, we define the operator T as

    Tf=baG(x,ξ)f(ξ)dξ,fH, (4.14)

    then from Lemma 1, it follows easily that the completeness of the system of root vectors (eigenfunctions and associated functions) of the BVP (2.7)–(2.11) is equivalent to the completeness of the system of root vectors of the operator T. Since φ0(x),ψ0(x),χ0(x)H, then

    baba|G(x,ξ)|2dxdξ<+, (4.15)

    hence the integral operator T is a Hilbert–Schmidt operator, i.e., T is compact.

    In this section, we show the completeness theorems here. Before we can state our main completeness theorem, some supplementary lemmas are needed. The first lemma is known as Krein's Theorem.

    Lemma 3. ([31], page 238) Let S be a compact dissipative operator in H with nuclear imaginary part S. The system of all root vectors of S is complete in H so long as at least one of the following two conditions is fulfilled:

    limmn+(m,S)m=0,limmn(m,S)m=0, (5.1)

    where n+(m,S) and n(m,S) denote the number of eigenvalues of the real component S of S in the intervals [0,m] and [m,0], respectively.

    Lemma 4. Let S be an invertible operator. Then, S is dissipative if and only if the inverse operator S1 of S is dissipative.

    Proof. Assume that S is dissipative. Then, for all yD(S),

    (y,Sy)=(Sy,y)=(Sy,y)0.

    Hence, for any zD(S1),

    (S1z,z)=(S1z,S(S1z))0,

    since S1zD(S). Hence S1 is dissipative.

    Let K be a differential operator generated by the differential expression l(u) in (2.1) and a set of boundary conditions denoted by B(u). Let K and A denote the adjoint operator and the inverse of K, respectively. Set A=A1+iA2. From the preceding analysis, it follows that A is an integral operator satisfying

    A=K1,A=(K)1.

    Therefore, the inverse operator of the real part of A, denoted as ˜K, satisfies

    ˜K=A11=(A+A2)1=2(K1+(K)1)1.

    Clearly, operator ˜K is a differential operator, and we denote its corresponding differential expression and boundary conditions as ˜l(u) and ˜B(u), respectively.

    If K is a self-adjoint operator, then K=K. In this case,

    ˜K=2(K1+(K)1)1=(K1)1=K,

    and it evidently follows that ˜l(u)=l(u), ˜B(u)=B(u).

    Next, consider the integral operator Th defined by (4.13); we set Th=Th1+iTh2 with Th1=Th and Th2=Th. Since Th is a bounded operator, then Th1 and Th2 are self-adjoint ([21], page 6), and we can obtain the following results:

    Lemma 5. The operator Th1 is the inverse of Lh1, where Lh1 is the operator generated by the differential expression in (2.1) and the unique set of boundary conditions. Of course, the operator Lh1 is self-adjoint.

    Proof. Clearly, the operator Lh1 is a differential operator. Analogous to the differential operator ˜K, we denote its corresponding differential expression as ˆl(u).

    Note that in this paper, the operator Lh is dissipative, but its dissipativity stems solely from the BCs (2.8)–(2.10) and is independent of the differential structure l(u). Moreover, the differential expression l(u) is symmetric. Consequently, we can conclude that the differential expression corresponding to operator Lh1 is ˆl(u)=l(u); this means that the differential expression associated with Lh1 is also l(u) in (2.1).

    Furthermore, the self-adjoint operator Lh1=T1h1 is uniquely determined by the integral operators Th and Th, where both Th and Th possess unique explicit representations; it follows that the boundary conditions for Lh1 are unique.

    Now the proof is finished.

    Lemma 6. ([32], page 295 Theorem 1) If an entire function h(μ) is of order 1 and minimal type, then

    limρn+(ρ,h)ρ=0,limρn(ρ,h)ρ=0, (5.2)

    where n+(ρ,h) and n(ρ,h) denote the number of the zeros of the function h(μ) in the intervals [0,ρ] and [ρ,0], respectively.

    Corollary 2. If the operator Lh1 is defined as in Lemma 5, then

    limmn+(m,Lh1)m=0,limmn(m,Lh1)m=0, (5.3)

    where n+(m,Lh1) and n(m,Lh1) denote the number of eigenvalues of Lh1 in the intervals [0,m] and [m,0], respectively.

    Proof. From Corollary 1 and Lemma 5, we can easily obtain that the characteristic function Δ1(λ) of Lh1 is an entire function of λ with growth of order 1 and minimal type. Then from Lemma 6, we have

    limρn+(ρ,Δ1(λ))ρ=0,limρn(ρ,Δ1(λ))ρ=0.

    From Lemma 2, we know that a complex number λ is an eigenvalue of the operator L1 if and only if it is the zeros of the characteristic function Δ1(λ). Therefore, we can obtain that

    limmn+(m,Lh1)m=0,limmn(m,Lh1)m=0.

    Now, we are ready to state and prove the completeness theorem.

    Theorem 3. The system of eigenfunctions and associated functions of the BVP (2.7)–(2.11) is complete in the Hilbert space H.

    Proof. Consider the operator T defined by (4.14); similarly to Th=Th1+iTh2, let T=T1+iT2 with T1=T and T2=T. By the above discussions, the operator T is a compact dissipative operator in H with a nuclear imaginary part, T2.

    Let rj be the eigenvalue of Lh1; then 1rj is the eigenvalue of T1. From Corollary 2, we can obtain that

    limmn+(m,T1)m=0,limmn(m,T1)m=0,

    that is

    limmn+(m,(T))m=0,limmn(m,(T))m=0.

    Then from Lemma 3, we can get the system of all root vectors of T is complete in H. And since the completeness of the system of root vectors (eigenfunctions and associated functions) of the BVP (2.7)–(2.11) is equivalent to the completeness of the system of root vectors of the operator T, then the system of eigenfunctions and associated functions of the BVP (2.7)–(2.11) is complete in the Hilbert space H.

    Obviously, from Lemma 1 and Theorem 3, we can easily obtain that the system of eigenfunctions and associated functions of Lh is complete in H.

    Remark 1. Our conclusion can be extended to the case of singular end points case by using the method in [21].

    In the present paper, we considered the dissipative third-order boundary value problems with distributional potentials and eigenparameter-dependent boundary conditions. By transforming the considered problem to an isospectral operator problem, we prove that the operator is dissipative and has no real eigenvalues under certain conditions. Furthermore, by applying Krein's theorem, we establish the completeness theorems for both the boundary value problem and the corresponding operator.

    To our best knowledge, for third-order boundary value problems with distributional potentials and eigenparameter-dependent boundary conditions, the corresponding results have not been studied yet. The eigenvalue problems and completeness of the system of eigenfunctions and associated functions are essential to problems such as the non-classical wavelets and open quantum systems. The results here are more general than the previously known results.

    The authors declare that they have not used artificial intelligence (AI) tools in the creation of this article.

    The authors thank the referees for their comments and detailed suggestions. These have significantly improved the presentation of this paper. This work was supported by National Natural Science Foundation of China (Grant No. 12261066), Natural Science Foundation of Inner Mongolia Autonomous Region (Grant Nos. 2025MS01015 and 2023LHMS01015).

    The authors declare that there is no conflict of interest.



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