Citation: Luca Spolaor, Bozhidar Velichkov. On the logarithmic epiperimetric inequality for the obstacle problem[J]. Mathematics in Engineering, 2021, 3(1): 1-42. doi: 10.3934/mine.2021004
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To Sandro Salsa on the occasion of his 70th birthday.
For any u∈H1(B1), we define the functionals (Weiss' boundary adjusted energies)
W0(u):=∫B1|∇u|2dx−2∫∂B1u2dHd−1andW(u):=W0(u)+∫B1udx. |
We denote by S the following class of 2-homogeneous polynomials :
S:={QA:Rd→R:QA(x)=x⋅Ax, where A=(aij)ij is a symmetric non-negative matrix such thattrA=d∑i=1aii=14 }. | (1.1) |
Notice that the functional W is constant on S. We will use the notation
W(S):=W(QA)for anyQA∈S. | (1.2) |
This paper is dedicated to the so-called logarithmic epiperimetric inequality, which was first introduced in [3], for the functional W and the set S, and already found several applications to different variational free boundary problems (see for instance [4,6,7,15]).
Theorem 1 (Log-epiperimetric inequality for W). There are dimensional constants δ>0, ε>0 and γ∈[0,1) such that the following claim holds. For every non-negative function c∈H1(∂B1), with 2-homogeneous extension z on B1, satisfying
dist2(c,S)≤δandW(z)−W(S)≤1, |
there is a non-negative function h∈H1(B1) with h=c on ∂B1 satisfying the inequality
W(h)−W(S)≤(W(z)−W(S))(1−ε|W(z)−W(S)|γ). | (1.3) |
The epiperimetric inequalities are powerful tools in the regularity theory of free boundary problems and minimal surfaces. The concept of an epiperimetric inequality (which is (1.3) with γ=0) was first introduced by Reifenberg in [14] in the context of minimal surfaces in the 60s. In the late 90s, Weiss [17] used an epiperimetric inequality approach to study the free boundaries of the obstacle problem.
The Weiss' epiperimetric inequality was still of the form (1.3), with γ=0 and for the same energy W, but the set S defined in (1.1) was replaced by the set of the 'flat' blow-up limits
R={Q(x)=14(x⋅ν)2+whereν∈∂B1}. |
In [17] Weiss used the epiperimetric inequality to prove the C1,α regularity of the 'flat' free boundaries. It is now known that the epiperimetric inequality ((1.3) with γ=0) cannot hold in a neighborhood of the set S; this follows from the counterexample to the C1,α regularity of the singular free boundaries given in [10].
There are several other epiperimetric inequalities for free boundary problems in the literature. By using the technique of Weiss, Focardi-Spadaro [12] and Garofalo-Petrosyan-Smit Vega Garcia [13] proved an epiperimetric inequality at the regular points of the thin-obstacle free boundaries. Then, in [16], by using a different (direct) approach, we proved an epiperimetric inequality for the Bernoulli free boundary problems in dimension two.
The log-epiperimetric inequality ((1.3) with γ∈[0,1)) was introduced in our work [3], in collaboration with M. Colombo, where we first proved Theorem 1. The initial idea in [3] was to attack the epiperimetric inequality for S (left open in the work of Weiss [17]) by the direct approach from [16]. As we already mentioned above, this cannot be actually done, but it led to the formulation of the log-epiperimetric inequality (1.3), from which we obtained the C1,log regularity of the singular part of the free boundary (from where the name logarithmic).
Following the original spirit of [16], our approach in [3] was still direct in the sense that we built the competitor explicitly. We later used this idea to prove a log-epiperimetric inequality at the singular points of the thin-obstacle free boundaries [4]. Constructing explicit competitors has the advantage to provide proofs that use only elementary tools and essentially boils down to constructing sub and supersolutions starting from a trace, which is close to the set S. This requires the set S to be known explicitly. On the other hand, one is mainly interested in the case when S is a set of global homogeneous solutions to some free boundary variational problem and the classifications of these solutions is known only for some specific problems.
In [6] and [7], in collaboration with Max Engelstein, we elaborated a different approach to the log-epiperimetric inequality and we constructed the competitor by reparametrizing the solution of an evolution problem on the sphere. Finally, in [5], we exploited some of the ideas from [6] and [7] to give new proofs of the log-epiperimetric inequalities (for the obstacle and the thin-obstacle problems) from [3] and [4], and we showed its relation to a class of parabolic variational inequalities.
This paper has several objectives. Our first aim is to provide a different (and hopefully easier) direct proof of Theorem 1. Our new proof (see Section 4) is based on a specific decomposition of the trace inspired by the competitor that we used to prove the constrained Łojasiewicz inequality in [5]. Then, we notice that the competitor built this way in fact simulates the behavior the gradient flow from [5] and so, we give a second proof of Theorem 1 (see Section 5) by using a construction in the spirit of [5].
We explain the ideas behind the two different constructions in Section 7, which can be read independently. Moreover, in order to give our second proof of Theorem 1, we give a new general result in which the construction of the competitor is reduced to finding a flow on the sphere that satisfies two specific inequalities (see Theorem A.1). This general result applies both to the gradient flow from [5] and to the flow from Section 5. It is also intended to facilitate the construction of competitors for other variational problems, for instance, non-local obstacle problems.
In the first three sections we give a direct proof of Theorem 1 in the spirit of [3], but using a different competitor. Section 2 contains the notations and some basic facts about the functional W. Section 3 is dedicated to the main estimate that we need in the proof of Theorem 1. In Section 4 we give the proof of the theorem by putting together the estimates from Section 2 and Section 3.
In Section 5 and Section 6 we give a proof of Theorem 1 based on the definition of a flow on the sphere. Then, we use the estimates from Section 2 and Section 3 to prove that these flows satisfy the condition of Theorem A.1.
In Section 7, we explain the main ideas behind the direct proofs from Section 4 and [3], and the constructive, gradient flow approach from Sections 5 and 6. This section can be read independently; we only use some of the notations and preliminary results from Section 2.
In Theorem A.1 we show how to construct a competitor out of a flow defined in H1(∂B1); we prove that competitor satisfies a log-epiperimetric inequality provided that the flow satisfies two main conditions:
an energy dissipation inequality (A.3),andŁojasiewicz inequality (A.5). |
This result applies to both the flow from Section 5 and the gradient flow from Section 6; in the first case, the exponent γ in the log-epiperimetric inequality (1.3) appears as a consequence of the energy dissipation inequality (A.3), while in the case of the gradient flow (Section 6), the exponent is due to the Łojasiewicz inequality (A.5). In both cases, Theorem A.1 allows to reduce the proof of the log-epiperimetric inequality to verifying that (A.3) and (A.5) hold along the flow.
A consequence of Theorem 1 is the following result on the structure of the singular free boundaries of solutions to the obstacle problem, which we give here for the sake of completeness. We recall that u:B1→R is a solution to the obstacle problem (in the unit ball B1⊂Rd) if u≥0 and
∫B1(|∇u|2+u)dx≤∫B1(|∇v|2+v)dxfor everyv∈H1(B1)such thatv≥0inB1andu−v∈H10(B1). | (1.4) |
We define Ωu:={u>0} and the set of singular points
Sing(∂Ωu):={x0∈∂Ωu : limr→0|Br(x0)∩Ωu||Br|=1}. |
Let u be a solution to the obstacle problem. We say that Q:B1→R is a blow-up limit of u at x0∈∂Ωu∩B1 (and we write Q∈BU(u,x0)), if there is a sequence rn→0 such that
limn→∞‖urn,x0−Q‖L2(∂B1)whereurn,x0(x)=1r2nu(x0+rnx). |
It is well-known that x0∈ Sing(∂Ωu) if and only if BU(u,x0)⊂S (see, for instance, [2] and [9]).
Finally, we define the strata Singk(∂Ωu), for every k∈{0,1,…,d−1}, as
Singk(∂Ωu):={x0∈ Sing(∂Ωu) : there is QA∈BU(u,x0) such that dim(KerA)=k}. |
As an immediate consequence of Theorem 1, we obtain Theorem 2, proved in [3]. A finer result on the structure of the singular set (in any dimension) was obtained by Figalli and Serra [10], and more recently, by Figalli, Serra and Ros-Oton [11].
Theorem 2 (Structure of the singular free boundaries). Let u:B1→R be a solution to the obstacle problem (1.4). Then, the following holds.
(i) Uniqueness of the blow-up limit. At every x0∈Sing(∂Ωu), the blow-up limit is unique, that is, there is QAx0∈S such that
limr→0‖ur,x0−QAx0‖L2(∂B1)=0. |
(ii) Rate of convergence of the blow-up sequence. For every x∈B1, there is a ball B=Bρ(x) and R>0 such that
‖ur,x0−QAx0‖L2(∂B1)≤C(−lnr)−δfor everyx0∈Sing(∂Ωu)∩Band everyr≤R. |
(iii) Distance between the blow-up limits at different points. For every x∈B1, there is a ball Bρ(x) such that
‖QAy0−QAx0‖L2(∂B1)≤C(−ln|x0−y0|)−δfor everyx0,y0∈Sing(∂Ωu)∩Bρ(x). |
(iv) Structure of the strata. The set Sing0(∂Ωu) is discrete. For every 1≤k≤d−1, there is δ, depending on d and eventually on k such that the following holds.
For every x∈Singk(∂Ωu), there is a ball Bρ(x)⊂B1 such that Singk(∂Ωu)∩Bρ(x) is contained in a C1,log-regular k-dimensional manifold. Precisely, up to a rotation of the coordinate system, there is a C1 regular function φ:Rk→Rd−k such that
Singk(∂Ωu)∩Bρ(x)⊂Graph(φ)∩Bρ(x), |
and ∇φ(0)=0 and
|∇φ(x′0)−∇φ(y′0)|≤C(−ln|x′0−y′0|)−δfor everyx′0,y′0∈Rk∩Bρ(x). |
Proof. The claims (i) and (ii) follow by the log-epiperimetric inequality (1.3) and a standard general procedure, which we explain in the appendix (Proposition B.1) for the sake of completeness. The claim (iii) follows directly from (ii), while (iv) is a consequence of (iii) and a Whitney extension theorem (see, for instance, [8]).
In this section we prove some preliminary results about the energy W (Section 2.1) and we recall some a basic facts about the decomposition in spherical harmonics (Section 2.2) that we use in the construction of the competitors for the log-epiperimetric inequality.
In the direct proof of Theorem 1 (see Section 4) we will use only Lemma 2.1, Lemma 2.2 and Corollary 2.3. Lemma 2.4 will be used in the second proof, given in Section 5.
Lemma 2.1 (W and W0). Let u∈H1(B1) and Q∈S. Then
W0(u−Q)=W(u)−W(Q). |
Proof. We compute
W0(u−Q)=∫B1|∇(u−Q)|2−2∫∂B1(u−Q)2dHd−1=W0(u)+W0(Q)−2(∫B1∇u⋅∇Qdx−2∫∂B1uQdHd−1)=W0(u)+W0(Q)+2∫B1uΔQdx=W0(u)+W0(Q)+∫B1udx=W(u)−W(Q), | (2.1) |
where we integrated by parts and, in the last line, we used the identity
W0(Q)=∫B1|∇Q|2dx−2∫∂B1Q2dHd−1=−∫B1QΔQdx=−12∫B1Qdx, |
so that W(Q)=W0(Q)+∫B1Qdx=12∫B1Qdx=−W0(Q).
The following simple lemma will be fundamental in both proofs so we collect it here.
Lemma 2.2 (Slicing Lemma). Let u=u(r,θ)∈H1(B1). Then, computing the energy W0(r2u) of the function written in polar coordinates as (r,θ)↦r2u(r,θ), we obtain
W0(r2u)=∫10rd+1∫∂B1(|∇θu|2−2du2)dθdr+∫10rd+3∫∂B1|∂ru|2dθ. | (2.2) |
In particular, if we set
F(ϕ):=∫∂B1(|∇θϕ|2−2dϕ2+ϕ)dHd−1, | (2.3) |
we have the equality
W(r2u)=∫10F(u(r,⋅))rd+1dr+∫10rd+3∫∂B1|∂ru|2dHd−1dr. | (2.4) |
Finally, if u(r,θ)=rεc(θ), then
W0(r2+εc(θ))=1d+2α−2∫∂B1(|∇θc|2−2dc2)dθ+(α−2)2d+2α−2∫∂B1c2dθ, | (2.5) |
where α=2+ε and ε≥0.
Proof. Setting θ∈∂B1, dθ=dHd−1, we calculate for a function u=u(r,θ)
W0(r2u)=∫10∫∂B1(|2ru+r2∂ru|2+r2|∇θu|2)dθrd−1dr−2∫∂B1u2dθ=∫10∫∂B1(2r2u2+r4|∂ru|2+2r3∂r(u2)+r2|∇θu|2)dθrd−1dr−2∫∂B1u2dθ=∫10∫∂B1(4r2u2+r4|∂ru|2−2(d+2)r2u2+r2|∇θu|2)dθrd−1dr=∫10rd+1∫∂B1(|∇θu|2−2du2)dθdr+∫10rd+3∫∂B1|∂ru|2dθdr, |
which is precisely (2.2). The identity (2.4) follows from (2.2) by the formula
∫B1udx=∫10∫∂BrudHd−1dr. |
Finally, Eq (2.5) directly follows from (2.2) by integrating in r.
Corollary 2.3 (Decomposition of the energy). Suppose that z1,z2∈H1(B1) are of the form zj(r,θ)=r2gj(r)cj(θ), for j=1,2, where the traces c1,c2∈H1(∂B1) are orthogonal on the sphere in the following sense:
∫∂B1c1c2dθ=∫∂B1∇θc1⋅∇θc2dθ=0. | (2.6) |
Then, we have
W0(z1+z2)=W0(z1)+W0(z2)andW(z1+z2)=W(z1)+W(z2). | (2.7) |
Proof. It is sufficient to apply the formulas (2.2) and (2.4), and then use (2.6).
The next lemma is essentially the identity (2.4) from the Slicing Lemma for competitors defined by reparametrization of the radial coordinate. We will use the following notation:
∇F(ϕ)=−2Δ∂B1ϕ−4dϕ+1forϕ∈H2(∂B1), | (2.8) |
ψ⋅∇F(ϕ)=∫∂B1ψ(−2Δ∂B1ϕ−4dϕ+1)dHd−1forϕ∈H2(∂B1)andψ∈L2(∂B1). |
Lemma 2.4 (The slicing lemma reparametrized). Suppose that ψ:[0,+∞)→H2(∂B1) is a function such that
ψ∈C1((0,+∞);L2(∂B1))∩C0([0,+∞);H1(∂B1))∩C0((0,+∞);H2(∂B1)), |
and let T∈(0,+∞]. We define φ:[0,+∞)→H2(∂B1) as
φ(t):=ψ(t)ift∈[0,T),φ(t):=ψ(T)ift≥T. |
and the function u:B1→R as
u(r,θ)=φ(−κlnr,θ), |
where κ>0 is fixed. Then, we have
W(r2u)=1κ∫∞0F(φ(t))e−t(d+2)κdt+κ∫∞0‖φ′(t)‖2L2(∂B1)e−t(d+2)κdt, | (2.9) |
and also
W(r2u)=F(ψ(0))d+2+∫T0(1d+2∇F(ψ(t))⋅ψ′(t)+κ‖ψ′(t)‖2L2(∂B1))e−t(d+2)κdt. | (2.10) |
In particular, if φ is constant in t, then
W(r2u)=F(φ(0))d+2. | (2.11) |
Proof. Using the identity (2.4) and the change of variables t=−κlnr, we compute
W(r2u)=∫10F(u(r))rd+1dr+∫10rd+3∫∂B1|∂ru|2dHd−1dr=∫10F(φ(−κlnr))rd+1dr+∫10κ2rd+1‖φ′(−κlnr)‖2L2(∂B1)dr=1κ∫∞0F(φ(t))e−t(d+2)κdt+κ∫∞0‖φ′(t)‖2L2(∂B1)e−t(d+2)κdt |
Now, by the definition of ψ, we get
W(r2u)=1κ∫T0F(ψ(t))e−t(d+2)κdt+1κ∫+∞TF(ψ(T))e−t(d+2)κdt+κ∫T0‖ψ′(t)‖2L2(∂B1)e−t(d+2)κdt=1κ∫T0F(ψ(t))e−t(d+2)κdt+F(ψ(T))d+2e−T(d+2)κ+κ∫T0‖ψ′(t)‖2L2(∂B1)e−t(d+2)κdt. |
Now, an integration by parts gives
1κ∫T0F(ψ(t))e−t(d+2)κdt=1d+2∫T0ψ′(t)⋅∇F(ψ(t))e−t(d+2)κdt+F(ψ(0))d+2−e−T(d+2)κF(ψ(T))d+2, |
which concludes the proof.
Let 0<λ1≤λ2≤⋯≤λj≤… be the eigenvalues (counted with multiplicity) of the spherical Laplace-Beltrami operator and {ϕj}j≥1 be the corresponding family of eigenfunctions, that is the solutions of
−ΔSd−1ϕj=λjϕjonSd−1,∫Sd−1ϕ2j(θ)dθ=1. | (2.12) |
Then, for any fixed i,j∈N, we have
∫∂B1ϕiϕjdθ=δijand∫∂B1∇θϕi⋅∇θϕjdθ=λiδij. |
It is well known that the eigenfunctions of the Spherical Laplacian on Sd−1 are in fact the traces of homogeneous harmonic polynomials in Rd. In fact, for a given α≥0, it is immediate to check that a function ϕ:∂B1→R is an eigenfunction corresponding to the eigenvalue
λ(α):=α(α+d−2), |
if and only if, its α-homogeneous extension φ(r,θ)=rαϕ(θ) is harmonic in B1. We will denote by αj the homogeneity corresponding to the eigenvalue λj, that is, we have
λj=λ(αj)=αj(αj+d−2). | (2.13) |
Notice that, since the homogeneous harmonic functions in Rd are polynomials, we have that αj∈N. Thus, we can easily identify the eigenvalues and the eigenfunctions of the spherical Laplacian corresponding to the first few elements of the spectrum. Precisely, we have that :
∙ α1=λ1=0 and the corresponding eigenfunction is the constant ϕ1=|∂B1|−1/2=(dωd)−1/2.
∙ λ2=⋯=λd+1=d−1, the corresponding homogeneity is α2=⋯=αd+1=1, while the eigenspace coincides with the (d-dimensional) space of linear functions in Rd.
∙ λd+2=⋯=λd(d+3)/2=2d, the corresponding homogeneity is αd+2=⋯=αd(d+3)/2=2; the corresponding eigenspace E2d is generated by the (restrictions to Sd−1 of the) 2-homogeneous harmonic polynomials:
E2d={QA:Rd→R:QA(x)=x⋅Ax, A symmetric with trA=0}. |
In particular, if Q∈S is an admissible singular blow-up limit, then Q is of the form
Q(x)=14d|x|2+QA(x)for some harmonic polynomialQA∈E2d. |
∙ Finally, if j>d(d+3)2 (that is λj>2d), then the corresponding homogeneity is at least 3 and so
λj≥3(3+d−2)=3(d+1). |
Let c be as in Theorem 1. Throughout the rest of the paper we will use the same decomposition of the trace with the same notation. We will denote by Q∈S the projection of c on the set of critical points S given in (1.1). Precisely, Q realizes the minimum
dist2(c,S):=min{‖c−Q‖L2(∂B1) : Q∈S}. |
We now decompose the function c−Q∈H1(∂B1) in Fourier series as
c(θ)−Q(θ)=∞∑j=1cjϕj(θ) |
where cj are the Fourier coefficients
cj:=∫∂B1(c(θ)−Q(θ))ϕj(θ)dθ. | (2.14) |
Finally, we will write c:∂B1→R as
c=Q+η++η0+η−, | (2.15) |
where the functions η+, η0 and η− (defined on ∂B1) are given by
η−:=∑j:αj<2cjϕj ,η0:=∑j:αj=2cjϕjandη+:=∑j:αj>2cjϕj . |
In terms of the decomposition (2.15), 2-homogeneous extension of c(θ) can be written as:
z(r,θ)=r2c(θ)=Q(rθ)+r2η−(θ)+r2η0(θ)+r2η+(θ), | (2.16) |
where we recall that Q∈S is 2-homogeneous:
Q(rθ)=r2Q(θ)for everyr>0andθ∈∂B1. |
Notice that the functions η−, η0 and η+ are orthogonal on the sphere in the sense that
∫∂B1ηi(θ)ηj(θ)dθ=∫∂B1∇θηi(θ)⋅∇θηj(θ)dθ=0wheneveri≠j∈{+,−,0}. |
Thus, by Lemma 2.1 and Corollary 2.3, we can compute the term in the right-hand side of the log-epiperimetric inequality in terms of η+, η0 and η−.
W(z)−W(Q)=W0(z−Q)=W0(r2η−(θ))+W0(r2η0(θ))+W0(r2η+(θ)). | (2.17) |
Let c=Q+η++η0+η− be as in Section 2.4. Let M be the maximum of the negative part of η−+η0+Q, that is,
M:=maxθ∈∂B1{−η−(θ)−η0(θ)−Q(θ)}. | (3.1) |
We define the functions h2:∂B1→R and hα:∂B1→R as
h2:=Q+η−+η0+8dM(14d−Q)andhα:=η+−8dM(14d−Q). | (3.2) |
The role of the correction term 8dM(14d−Q) will be explained in Section 7.1. In the lemma below we gather the key estimates, which we will use in both proofs of Theorem 1 – the one based on the direct construction of the competitor (Section 4) and the one based on the definition of a flow and a Łojasiewicz-type inequality (Section 5).
Lemma 3.1 (Key Estimate). Let c, Q, η−, η0, η+, M, h2 and hα be as above :
c(θ)=Q(θ)+η−(θ)+η0(θ)+η+(θ)=h2(θ)+hα(θ),θ∈∂B1. |
Then, there is a dimensional constant δ>0 such that the following holds. If
‖c−Q‖L2(∂B1)≤δ, |
then we have:
(i) h2(θ)≥0 for every θ∈∂B1.
(ii) there is a dimensional constant Cd>0 such that
Md+1≤Cd‖η+‖2L2(∂B1) ; | (3.3) |
(iii) for every t∈R, we have the following identities :
hα⋅∇F(h2+thα)=2t∫∂B1(|∇θη+|2−2dη2+)dθ, | (3.4) |
F(h2+thα)=F(Q)+∫∂B1(|∇θη−|2−2dη2−)dθ+t2∫∂B1(|∇θη+|2−2dη2+)dθ, | (3.5) |
where we recall that F and ∇F are given by (2.3) and (2.8).
Proof. We start by proving (i). Notice that there is a dimensional constant Cd such that
‖ϕj‖L∞(∂B1)+‖∇θϕj‖L∞(∂B1)≤Cdfor everyj∈Nsuch thatαj≤2d. |
Now, since by definition
η−(θ)+η0(θ)=∑j:αj≤2dcjϕj(θ), |
we can find another dimensional constant C>0 such that
‖η−+η0‖L∞≤∑j:αj≤2d|cj|‖ϕj‖L∞(∂B1)≤C(∑j:αj≤2dc2j )1/2=C‖η−+η0‖L2(∂B1)≤C‖c−Q‖L2(∂B1), |
where we recall that
‖c−Q‖L2(∂B1)=‖η−+η0+η+‖L2(∂B1). |
We now choose δ>0 such that 4Cδ≤14d. We next show that h2≥0 on each of the sets
{θ∈∂B1 : Q(θ)≥2Cδ}and{θ∈∂B1 : Q(θ)≤2Cδ}. |
Indeed, we have the following two cases.
● Consider the set {Q≥2Cδ}⊂∂B1. We first notice that
η−+η0+12Q≥0 |
on this set. Indeed, for any θ∈{Q≥2Cδ}, we have
η−(θ)+η0(θ)+12Q(θ)≥−‖η−+η0‖L∞(∂B1)+12Q(θ)≥−C‖c−Q‖L2(∂B1)+Cδ≥0. |
We now decompose h2 as follows :
h2=(η−+η0+12Q)+2M+Q(12−8dM), |
where the first and the second terms are nonnegative. In order to prove that also the third one is nonnegative, we notice that since Q≥0, we have
M≤‖η−+η0‖L∞(∂B1)≤Cδ, |
so, by the choice of δ,
12−8dM≥12−8dCδ=2d(14d−4Cδ)≥0. |
This concludes the first part of the proof of (i).
● Consider the set {Q≤2Cδ}⊂∂B1. We have that
h2=η−+η0+Q+8dM(14d−Q)≥η−+η0+Q+8dM(14d−2Cδ)≥η−+η0+Q+M≥0, |
where the last inequality is due to the choice (3.1) of M. This concludes the proof of (i).
Next we prove (ii). We set for simplicity
P:=η−+η0+Q |
and we notice that P is a polynomial of degree two (a linear combination of eigenfunctions corresponding to eigenvalues ≤2d). We claim that there is a dimensional constant L such that ‖∇P‖L∞(∂B1)≤L. Indeed, reasoning as in the proof of (i), we have that there is a dimensional constant Cd such that
‖∇θη−+∇θη0‖L∞(∂B1)≤∑j:αj≤2d|cj|‖∇θϕj‖L∞(∂B1)≤Cd(∑j:αj≤2dc2j )1/2=Cd‖η−+η0‖L2(∂B1)≤Cd‖c−Q‖L2(∂B1)≤Cdδ. |
On the other hand, by the definition of S (see (1.1)), Q is of the form
Q(x)=x⋅Axfor a nonnegative symmetric matrixAwithtrA=14. |
Thus, for the gradient of Q, we have
‖∇Q‖L∞=supx≠02|Ax||x|≤2 trA=12. |
In particular,
‖∇θP‖L∞(∂B1)≤Cdδ+12. |
Now, since Q is non-negative and η−+η0 is small, we have that the negative part inf{P,0} is also small. Precisely,
M=‖inf{P,0}‖L∞(∂B1)≤‖η−+η0‖L∞(∂B1)≤Cδ. |
Since the function inf{P,0}:∂B1→R is L-Lipschitz and is small (in L∞(∂B1)), we can deduce that there is a dimensional constant Cd>0 such that
‖inf{P,0}‖2L2(∂B1)≥CdMd−1Ld−1M2=CdL−d+1‖inf{P,0}‖d+1L∞(∂B1)=CdL−d+1Md+1, |
where the first inequality follows from Lemma 3.2. Indeed, let F:Rd−1→R be the function inf{P,0} written in local coordiantes around the point, where its maximum is achieved on the sphere. In this local chart, we can use Lemma 3.2 to estimate the integral of F2 over BR, where R:=1L‖inf{P,0}‖L∞. On the other hand, the trace c:∂B1→R is non-negative :
c(θ):=P(θ)+η+(θ)≥0for everyθ∈∂B1. |
Thus, necessarily,
−inf{P,0}≤|η+|on∂B1, |
and so,
CdL−d+1Md+1≤‖inf{P,0}‖2L2(∂B1)≤‖η+‖2L2(∂B1), |
which (since L is a dimensional constant) gives (3.3).
Finally we prove (iii). We start with computing ∇F(h2). First, we notice that, since Q∈S, it is a solution to the PDE
∇F(Q)=−2Δ∂B1Q−4dQ+1=0. | (3.6) |
As a consequence of (3.6) and the definition of η0, we have that both η0 and (14d−Q) are eigenfunctions of the spherical Laplacian, corresponding to the eigenvalue 2d, that is,
−Δ∂B1η0−2dη0=−Δ∂B1(14d−Q)−2d(14d−Q)=0. | (3.7) |
Thus, we have
∇F(h2)=−2Δ∂B1h2−4dh2+1=−2Δ∂B1η−−4dη−. |
Analogously, we compute ∇F(hα). Indeed, we have
∇F(hα)=−2Δhα−4dhα=−2Δ(η+−8dM(14d−Q))−4d(η+−8dM(14d−Q))=−2Δη+−4dη+ |
where in the last equality we used again (3.7).
In order to compute hα⋅∇F(h2+thα), we first write hα in the form
hα=η++˜η0where˜η0:=−8dM(14d−Q), |
and we notice that by (3.7), ˜η0 is a (2d)-eigenfunction of the spherical Laplacian. Using the definition of ∇F (2.8) and the fact that ∇F(Q)=0 (3.6), we compute
hα⋅∇F(h2+thα)=(η++˜η0)⋅∇F(Q+η−+η0−˜η0+tη++t˜η0)=(η++˜η0)⋅∇F(η−+η0−˜η0+tη++t˜η0)=(η++˜η0)⋅[(−2Δ−4d)(η−+η0−˜η0+thα+t˜η0)+1]. |
Now, since ∫∂B1(η++˜η0)=0 and since both η0 and ˜η0 are (2d)-eigenfunctions, we get
hα⋅∇F(h2+thα)=(η++˜η0)⋅(−2Δ−4d)(η−+tη+). |
Next, notice that by the definition of η−, η+ and ˜η0, they are orthogonal in L2(∂B1) and H1(∂B1):
∫∂B1η+(θ)˜η0(θ)dθ=∫∂B1η−(θ)˜η0(θ)dθ=∫∂B1η+(θ)η−(θ)dθ=0, |
∫∂B1∇θη+⋅∇θ˜η0dθ=∫∂B1∇θη−⋅∇θ˜η0dθ=∫∂B1∇θη+⋅∇θη−dθ=0. |
Thus, integrating by parts on ∂B1, we obtain
hα⋅∇F(h2+thα)=2t∫∂B1(|∇θη+|2−2dη2+)dθ, |
as required. It remains to prove (3.5). Using (3.6), we compute
F(h2+thα)−F(Q)=F(Q+η−+η0+tη++(t−1)˜η0)−F(Q)=∫∂B1|∇θ(η−+η0+tη++(t−1)˜η0)|2dθ−2d∫∂B1(η−+η0+tη++(t−1)˜η0)2dθ=∫∂B1(|∇θη−|2−2dη2−)dθ+t2∫∂B1(|∇θη+|2−2dη2+)dθ, |
where the last equality follows from the orthogonality (in L2(∂B1) and H1(∂B1)) of η+, η− and η0+(t−1)˜η0, and from the fact that η0+(t−1)˜η0 is an eigenfunction of the spherical Laplacian corresponding precisely to the eigenvalue 2d.
Lemma 3.2. Suppose that n≥1 and that F:Rn→R is a function which is nonnegative a and L-Lipschitz continuous for some constant L>0. Let x0∈Rn and let M:=F(x0)>0. Then,
∫BR(x0)F2(x)dx≥2ωn(n+1)(n+2)Mn+2Ln, | (3.8) |
where ωn is the volume of the unit ball in Rn and R=M/L.
Proof. First notice that the L-Lipschit continuity of F implies that
F(x)≥M−L|x−x0|≥0for everyx∈BR(x0). |
Thus, integrating over BR(x0), we get that
∫BR(x0)F2(x)dx≥∫BR(x0)(M−L|x−x0|)2dx. |
Integrating the right-hand side in polar coordiantes and using the definition of R, we obtain
∫BR(x0)F2(x)dx≥nωn∫R0(M2−2LMr+L2r2)2dr=nωn(1nRnM2−2n+1LMRn+1+1n+2L2Rn+2), |
which is precisely (3.8).
In this section we prove Theorem 1 by giving the competitor explicitly, as in Subsection 7.1.
Proof of Theorem 1. We decompose the trace c:∂B1→R as
c=Q+η++η0+η− , |
as in Subsection 2.4 and we recall that the 2-homogeneous extension z is given by (2.17).
Definition of the competitor. We define the competitor h:B1→R as
h(r,θ):=r2h2(θ)+rαhα(θ), | (4.1) |
where α:=(2+ε)>2, the functions h2 and hα are given by (3.2) as in Section 3.
Positivity of the competitor. We first notice that the competitor h defined in (4.1) is non-negative. Indeed, we can write the competitor h as
h(r,θ)=r2h2(θ)+rαhα(θ)=(r2−rα)h2(θ)+rαc(θ). |
Now, the first term (r2−rα)h2(θ) is non-negative by Lemma 3.1 and the fact that r≤1; the second term rαc(θ) is non-negative since the trace c is non-negative by hypothesis.
Decomposition of the energy. We first decompose the energy of z. We recall (2.17) and we set
z−(r,θ):=r2η−(θ),z0(r,θ):=r2η0(θ)andz+(r,θ):=r2η+(θ). |
Since η−, η0 and η+ are orthogonal, we have
W(z)−W(Q)=W0(z−Q)=W0(z−)+W0(z0)+W0(z+). |
We now estimate W0(z−), W0(z0) and W0(z+). By (2.7) and (2.5), we have
W0(z0)=0andW0(z−)=∑j:αj<2c2jW0(r2ϕj(θ))=1d+2∑j:αj<2c2j(λj−2d)≤0. |
On the other hand, for the higher modes, we have
W0(z+)=∑j:αj>2c2jW0(r2ϕj(θ))=1d+2∑j:αj>2c2j(λj−2d)≥13(d+2)∑j:αj>2c2j(λj+1)=13(d+2)‖η+‖2H1(∂B1)≥0, | (4.2) |
where we used that, if αj>2, then αj≥3 and λj≥3(d+1).
We now study W(h), where h is the competitor from (4.1). On the other hand, setting
Q0:=8d(14d−Q), |
we get
W(h)−W(Q)=W0(h−Q)=W0(z−)+W0(z0+(r2−rα)MQ0)+W0(rαη+(θ))=W0(z−)+W0(z0)+M2W0((r2−rα)Q0)+W0(rαη+(θ)), |
where in the last equality we used that z0 is harmonic in B1 and (r2−rα)Q0(θ) vanishes on ∂B1. Using the fact that Q0 is a 2d-eigenfunction and ‖Q0‖L2(∂B1)≤Cd, we calculate
W0((r2−rα)Q0)=∫10rd−1dr∫∂B1((2r−αrα−1)2Q20+(r−rα−1)2|∇θQ0|2)dθ=‖Q0‖2L2(∂B1)∫10rd+1((2−αrα−2)2+2d(1−rα−2)2)dr=‖Q0‖2L2(∂B1)(α−2)2d+2α−2≤Cd(α−2)2=Cdε2. |
Putting together this estimate, (2.5) and (4.2), we get
W0(h−Q)−W0(z−Q)=W0(rαη+(θ))−W0(r2η+(θ))+CdM2ε2≤−εd+2W0(z+)+ε2‖η+‖2L2(∂B1)+CdM2ε2. | (4.3) |
Conclusion of the proof. We are finally in position to prove (1.3). We first notice that by (4.3) and Lemma 3.1 (ii), we have
W0(h−Q)−W0(z−Q)≤−εd+2W0(z+)+ε2‖η+‖2L2(∂B1)+Cd‖η+‖2d+1L2(∂B1)ε2. |
Recall that ‖η+‖L2(∂B1)≤δ. Choosing δ≤1, we have
W0(h−Q)−W0(z−Q)≤−εd+2W0(z+)+2Cd‖η+‖2d+1L2(∂B1)ε2≤−εd+2W0(z+)+CdW0(z+)2d+1ε2, |
where in the last inequality we used (4.2). Finally, setting ε=CdW0(z+)d−1d+1, for some dimensional constant Cd, and using the inequality W0(z−Q)≤W+(z+), we get
W0(h−Q)−W0(z−Q)≤−Cd(W0(z−Q))2dd+1, |
which is precisely (1.3) (see Lemma 2.1).
Let c be given by Theorem 1. We will use the general construction from Theorem A.1. In our case the homogeneity α is 2, the functional G is the Weiss' boundary adjusted energy W, F is given by (2.3), and the set S is (1.1). Thus, it only remains to define a flow ψ that satisfies the energy dissipation inequality (A.3) and the Łojasiewicz inequality (A.5).
We write the trace c:∂B1→R as
c(θ)=h2(θ)+hα(θ), |
where h2 and hα are given by (3.2). We define the flow ψ as
ψ(t)=h2+e−thαfor everyt≥0. |
Below we verify that ψ satisfies the hypotheses of Proposition A.1.
We first prove that the Łojasiewicz inequality (A.5) holds along the flow. Indeed, by (3.4), we have
−ψ′(t)⋅∇F(ψ(t))=e−thα⋅∇F(h2+e−thα)=2e−2t∫∂B1(|∇θη+|2−2dη2+)dθ. |
On the other hand, (3.5) implies that
F(h2+e−thα)−F(S)=∫∂B1(|∇θη−|2−2dη2−)dθ+e−2t∫∂B1(|∇θη+|2−2dη2+)dθ. |
Finally, since
∫∂B1(|∇θη−|2−2dη2−)dθ≤0, |
we obtain the Łojasiewicz inequality (A.5) with constant CLS=1 and exponent β=0.
In order to prove that (A.3) holds, we compute
‖ψ′(t)‖2L2(∂B1)=e−2t‖hα‖2L2(∂B1)=e−2t(‖η+‖2L2(∂B1)+(8dM)2‖(14d−Q)‖2L2(∂B1)), |
where we used the fact that 14d−Q is an eigenfunction of the Spherical Laplacian corresponding to the eigenvalue 2d and so it is orthogonal to η+ in L2(∂B2). In conclusion, since Q∈S and all the functions in S are bounded, we get that there is a dimensional constant Cd such that
‖ψ′(t)‖2L2(∂B1)≤e−2t(‖η+‖2L2(∂B1)+CdM2)≤e−2t(‖η+‖2L2(∂B1)+Cd‖η+‖4d+1L2(∂B1)), |
where the second inequality follows from (3.3). Now, since the Fourier decomposition of η+ contains only eigenfunctions corresponding to eigenvalues λj≥3(d+1)>2d, we get
‖η+‖2L2(∂B1)≤∫∂B1(|∇θη+|2−2dη2+)dθ. |
Thus, we consider the following two cases :
● If ‖η+‖L2(∂B1)≥1, then
‖ψ′(t)‖2L2(∂B1)≤e−2t(‖η+‖2L2(∂B1)+Cd‖η+‖4d+1L2(∂B1))≤e−2t(1+Cd)‖η+‖2L2(∂B1)≤e−2t(1+Cd)∫∂B1(|∇θη+|2−2dη2+)dθ≤1+Cd2(−ψ′(t)⋅∇F(ψ(t))). | (5.1) |
● Conversely, if ‖η+‖L2(∂B1)≤1, then
‖ψ′(t)‖2L2(∂B1)≤e−2t(‖η+‖2L2(∂B1)+Cd‖η+‖4d+1L2(∂B1))≤e−2t(1+Cd)(‖η+‖2L2(∂B1))2d+1≤(1+Cd)(e−2t∫∂B1(|∇θη+|2−2dη2+)dθ)2d+1≤1+Cd22d+1(−ψ′(t)⋅∇F(ψ(t)))2d+1. | (5.2) |
Combining (5.1) and (5.2), we obtain (A.3) with a dimensional constant CED and an exponent p=d+1. This concludes our second proof of Theorem 1.
In this section we review the proof of the log-epiperimetric inequality from [5] in terms of Theorem A.1. Let c:∂B1→R be as Theorem 1. As in the previous section, we will apply Theorem A.1 with α=2, G=W, F as in (2.3), and S given by (1.1).
As in [5], we define
ψ∈H1(]0,+∞[;L2(B1))∩L2(]0,+∞[;H2(B1)∩K) |
to be the strong solution of the following parabolic variational inequality (for the existence we refer to [1])
{(ψ′(t)+∇F(ψ(t)))⋅(v−ψ(t))≥0,for everyv∈Kandt>0,ψ(0)=c, | (6.1) |
where K is the convex set
K={v∈L2(∂B1) : v≥0on∂B1}. |
The energy dissipation inequality (A.3) is automaticaly satisfied along the flow with p=2. Precisely, we have
‖ψ′(t)‖2L2(∂B1)=−ψ′(t)⋅∇F(ψ(t))for almost everyt>0. | (6.2) |
Indeed, by taking the test function ψ:=u(t+h), for some t>0 and h∈R, we get
0≤(ψ(t+h)−ψ(t))⋅(ψ′(t)+∇F(ψ(t))), |
Dividing by h and taking the limits as h→0+ and h→0−, we obtain the inequalities
0≤limh→0+1h(ψ(t+h)−ψ(t))⋅(ψ′(t)+∇F(ψ(t)))=‖ψ′(t)‖2L2(∂B1)+ψ′(t)⋅∇F(ψ(t)),0≥limh→0−1h(ψ(t+h)−ψ(t))⋅(ψ′(t)+∇F(ψ(t)))=‖ψ′(t)‖2L2(∂B1)+ψ′(t)⋅∇F(ψ(t)), |
which give precisely (6.2).
Now, in order to conclude the proof of the log-epiperimetric inequality (Theorem 1), it is sufficient to check that (A.5) holds along the flow. We fix t>0 and we reason precisely as in [5]. We decompose the function ψ(t) as
ψ(t)=Q+η++η0+η− , |
exactly as in (2.15) with ψ(t) in place of c; moreover, we define h2 and hα as in (3.2), so we have
ψ(t)=h2+hα . |
Now, by Lemma 3.1, we have that h2∈K. Thus, using (6.1), we can compute
‖ψ(t)‖L2(∂B1)≥(h2−ψ(t))⋅ψ′(t)‖h2−ψ(t)‖L2(∂B1)≥−(h2−ψ(t))⋅∇F(ψ(t))‖h2−ψ(t)‖L2(∂B1), |
in order to estimate the right-hand side from below, we use Lemma 3.1.
−(h2−ψ(t))⋅∇F(ψ(t))‖h2−ψ(t)‖L2(∂B1)=−hα⋅∇F(h2+hα)‖hα‖L2(∂B1)=2‖hα‖L2(∂B1)∫∂B1(|∇θη+|2−2dη2+)dθ≥2(‖η+‖2L2(∂B1)+CdM2)−1/2∫∂B1(|∇θη+|2−2dη2+)dθ≥2(‖η+‖2L2(∂B1)+Cd‖η+‖4d+1L2(∂B1))−1/2∫∂B1(|∇θη+|2−2dη2+)dθ≥Cd‖η+‖−2d+1L2(∂B1)∫∂B1(|∇θη+|2−2dη2+)dθ , |
where in the last inequality we used that
‖η+‖L2(∂B1)≤dist2(ψ(t),S)≤1, |
which holds for every t∈[0,Tmax], by choosing Tmax small enough and ψ(0) close enough to S, as in Lemma 6 below. As a consequence, we get that
−ψ′(t)⋅∇F(ψ(t))=‖ψ′(t)‖2L2(∂B1)≥Cd‖η+‖−4d+1L2(∂B1)(∫∂B1(|∇θη+|2−2dη2+)dθ)2≥Cd(∫∂B1(|∇θη+|2−2dη2+)dθ)2dd+1≥Cd(F(ψ(t))−F(S))2dd+1, |
where in the last inequality we used again Lemma 3.1. Finally, this implies (A.5) with γ=d−1d+1. This concludes our third proof of Theorem 1.
We notice that the estimates from Lemma 3.1 were crucial in the three proofs (section 4, 5 and 6). In the first two proofs it was immediate to notice that the trace satisfies the hypotheses of Lemma 3.1. In the case of the proof that we presented in this section, we can apply Lemma 3.1 because the flow ψ remains close to the critical set S. This follows by a standard argument that we sketch in the lemma below.
Lemma 6.1. For every ε>0, there are constants δ>0 and T>0 such that the following holds. If ψ is a solution to (6.1) and is such that dist2(ψ(0),S)<δ, then
dist2(ψ(t),S)<εfor everyt∈[0,T]. |
Proof. Let Q∈S be the projection of ψ(0) on S, with respect to the distance L2(∂B1). By definition Q is a critical point for F and Q≥0. Thus, using (6.1), we get
∂∂t‖ψ(t)−Q‖2L2(∂B1)=−2ψ′(t)⋅(Q−ψ(t))≤2(Q−ψ(t))⋅∇F(ψ(t))=−2(Q−ψ(t))⋅∇F(Q−ψ(t))≤8d∫∂B1(Q−ψ(t))2dθ−2∫∂B1(Q−ψ(t))dθ≤(8d+1)∫∂B1(Q−ψ(t))2dθ+Hd−1(∂B1). |
Now, setting a=8d+1 and b=Hd−1(∂B1) and applying the Gronwall inequality, we get that
‖ψ(t)−Q‖2L2(∂B1)≤ba(eat−1)+eat‖ψ(0)−Q‖2L2(∂B1), |
which gives the claim.
In this section we sketch the main ideas behind the proof of the log-epiperimetric inequality for the obstacle problem (Theorem 1) and that led us to the two constructions from [3,4,5], Section 4 and Section 5.
The log-epiperimetric inequality. We recall that given a 2-homogeneous function z:B1→R, in polar coordinates z(r,θ)=r2c(θ), our aim is to construct a competitor h:B1→R such that h=z on ∂B1 and
W(h)−W(S)≤W(z)−W(S)−ε|W(z)−W(S)|1+γ, | (7.1) |
which can also be written as
W(h)−W(z)≤−ε|W(z)−W(S)|1+γ, | (7.2) |
where ε>0, γ∈[0,1), S is the set of singular 2-homogeneous solutions to the obstacle problem and where we use the notation (recall that W is constant on S) :
W(S):=W(Q)for everyQ∈S. |
In this subsection we present the main ideas that led to the construction of the competitors in [3] and in Section 4, and also in [4], the latter in the context of the thin-obstacle problem.
We notice that if the function h is such that the log-epiperimetric inequality (7.1) holds, then it must have a lower energy than the 2-homogeneous function z, so we start by analyzing the energy W(z). We decompose the trace c as
c=Q+η−+η0+η+, |
where Q∈S, η0 contains only lower modes, η0 is a (2d)-eigenfunction of the spherical Laplacian and the Fourier expansion of η+ contains only eigenfunctions corresponding to eigenvalues higher than 2d. Then, we recall that
W(z)−W(Q)=W0(r2η−(θ))+W0(r2η0(θ))+W0(r2η+(θ)). |
We next examine the different terms in the right-hand side of the above identity. By Lemma (2), we have :
● η− gives a negative contribution to the energy :
W0(r2η−(θ))≤0,the inequality being strict ifη−≠0 ; |
● the energy of η0 is zero: W0(r2η0(θ))=0;
● the energy of η+ is positive:
W0(r2η+(θ))≥0,the inequality being strict ifη+≠0. |
In particular, this means that, in order to build a competitor h with lower energy than z, we have to act on the term containing the higher modes
W0(r2η+(θ))=∫B1|∇(r2η+(θ))|dx−2∫∂B1η2+dθ. |
Since we are looking for a competitor that coincides with z on ∂B1, we cannot expect a contribution from the second (boundary) term of W0(r2η+(θ)). Thus, in order to decrease the energy, one has to act on the first term, which is the Dirichlet energy of r2η+(θ). Of course, the best way to decrease the Dirichlet energy is to replace r2η+ by the harmonic extension of η+ in B1. Since the harmonic extension can be explicitly written in Fourier series, we get that the competitor has the form
f(r,θ)=Q(rθ)+r2η−(θ)+r2η0(θ)+∑j:αj>2cjr2+εjϕj(θ), | (7.3) |
where the coefficients cj are given by (2.14) and αj are the corresponding homogeneities, related too the eigenvalues λj of ϕj through the formula (2.13). We also notice that εj>0, for every j. In fact, since we take
∑j:αj>2cjr2+εjϕj(θ) |
to be precisely the harmonic extension of η+, we have that εj=αj−2≥1.
We can compute the energy W(f) by using Lemma 2.1 and Corollary 2.3
W(f)−W(Q)=W0(f−Q)=W0(r2η−(θ))+W0(r2η0(θ))+∑j:αj>2c2jW0(r2+εjϕj(θ)). |
Now, using the Fourier expansion of η+ and Corollary 2.3, we have
W0(r2η+(θ))=∑j:αj>2c2jW0(r2ϕj(θ)), | (7.4) |
so, the energy gain is given by:
W(f)−W(z)=∑j:αj>2c2j(W0(r2+εjϕj(θ))−W0(r2ϕj(θ))). | (7.5) |
In order to estimate W(f)−W(z), we compute each of the terms in the right-hand side of (7.5). We use the fact that ϕj is an eigenfunction :
∫∂B1|∇θϕj|2dθ=λj∫∂B1ϕ2jdθ=λj, |
and we apply the identity (2.5) from the Slicing Lemma 2.2
W0(r2+εjϕj(θ))−W0(r2ϕj(θ))=λj−2dd+2+2εj+ε2jd+2+2εj−λj−2dd+2=−εj2(λj−2d)(d+2)(d+2+2εj)+ε2jd+2+2εj. |
Now, a direct computation gives that if we replace εj=αj−2 and λj=αj(αj+d−2), we get
W0(r2+εjϕj(θ))−W0(r2ϕj(θ))=ε2jd+2+2εj(−2(d+2+εj)d+2+1)=−ε2jd+2=−ε2j(2+εj)(d+εj)λj−2dd+2≤−13(d+1)λj−2dd+2=−13(d+1)W0(r2ϕj(θ)). |
We now notice that the above estimate implies (7.2) in its strongest form (with γ=0): this inequality is known as epiperimetric inequality. Indeed, as a consequence of the above estimate, (7.4) and (7.5), we have
W(f)−W(z)≤−13(d+1)∑j:αj>2c2jW0(r2ϕj(θ))=−13(d+1)W0(r2η+(θ)). |
Now, since the energy of z is given by
W(z)−W(Q)=W0(r2η−(θ))+W0(r2η+(θ))≤W0(r2η+(θ)), | (7.6) |
we get the following estimate (called epiperimetric inequality)
W(f)−W(z)≤−13(d+1)(W(z)−W(Q)), | (7.7) |
which is precisely (7.2) with γ=0, which is also the best possible exponent that we can expect.
Unfortunately, the function f cannot be used as a competitor in Theorem 1 as it might not fulfill the requirement that
the competitor should be non-negative. |
In fact, by taking the harmonic extension of η+ (which might change sign on ∂B1) we lose any information on the sign of f as each of the terms cjϕj(θ) of the Fourier expansion of η+ is multiplied by a different homogeneity rαj.
Thus, the challenge is to find a competitor that at the same time remains positive and decreases the energy. |
We now try to modify the function f from (7.3) in order to have some more control on its sign, but we also try to keep the energy gain provided by the 'harmonic' competitor f. The starting point is the following observation.
Claim. In (7.3) we can take all exponents εj to be the sameand still have the epiperimetric inequality (7.7). |
Precisely, taking in (7.3) εj=ε, for every j, we consider the new competitor
˜f(r,θ)=Q(rθ)+r2η−(θ)+r2η0(θ)+r2+εη+(θ). | (7.8) |
By using the computations that we already performed in the estimate of W(f)−W(z), we can compute
W(˜f)−W(z)=∑j:αj>2c2j(W0(r2+εϕj(θ))−W0(r2ϕj(θ)))=∑j:αj>2c2j(−2ε(λj−2d)(d+2)(d+2+2ε)+ε2d+2+2ε). |
Now, for ε small enough the first (negative) term of the right-hand side wins against the second (positive) one. Thus, choosing ε small enough and isolating a dimensional constant Cd, we get
W(˜f)−W(z)≤−εCd∑j:αj>2c2jλj−2dd+2=−εCdW0(r2η+(θ)), |
which implies (after (7.6)) that the epiperimetric inequality holds for ˜f :
W(˜f)−W(z)≤−εCd(W(z)−W(Q)). |
Unfortunately, we still cannot prove that ˜f is non-negative. For instance, what can go wrong is that, for some θ∈∂B1, we have
Q(θ)+η−(θ)+η0(θ)<0andη+(θ)>−(Q(θ)+η−(θ)+η0(θ)). |
In this way the trace
c(θ)=Q(θ)+η−(θ)+η0(θ)+η+(θ) |
is non-negative, but the competitor ˜f(r,θ) becomes negative when r is small enough.
In this section, we finally discuss the idea behind the direct constructions from [3,4], and Section 4. Precisely, in order to build a nonnegative competitor, we add a correction term H:∂B1→R such that
Q(θ)+η−(θ)+η0(θ)+H(θ)≥0for everyθ∈∂B1, | (7.9) |
and we consider the competitor
h(r,θ)=r2(Q(θ)+η−(θ)+η0(θ)+H(θ))+r2+ε(η+(θ)−H(θ)). |
Since, by hypothesis the trace c=Q+η−+η0+η+ is non-negative, we get that
(Q+η−+η0+H)+(η+−H)≥0, |
but (together with (7.9)) this implies that h(r,θ)≥0 for every r>0.
Notice that, if we want the condition (7.9) to be fulfilled, we need H to be large enough in order to compensate the negative part of Q+η−+η0. On the other hand, H increases the energy. In fact, we can re-write the competitor h as
h(r,θ)=˜f(r,θ)+(r2−r2+ε)H(θ). |
Since ˜f is qualitatively the best possible choice for the energy (recall that ˜f is as good as the harmonic extension f), the function h will have bigger energy, which, of course, depends on the error introduced by the correction term (r2−r2+ε)H(θ); finally, this means that in order to keep the energy of h as small as possible, we need H to be small.
This competition between the constraint and the energy is precisely what makes appear the exponent γ in the log-epiperimetric inequality. |
Following the construction presented here, one can build many different competitors. For instance, in [3], we use a function H that depends on all the lower modes (including the linear ones) of the trace c. In Section 4 we propose a different function H, which is (2d)-eigenfunction on the sphere; this leads to a shorter proof, but the exponent γ we get is not optimal.
This section is dedicated to the constructive approach from [5] and Section 5. It is based on the idea that any function h:B1→R can be seen as a family of functions (a flow) h(r,⋅):∂B1→R parametrized over the radial coordinate r∈(0,1]. This way to see the competitor was first used in the context of the one-phase Bernoulli problem, in [16] and later in [6], where the competitor is not explicit, but is constructed starting from a solution of an evolution problem. Recently, in [5] we applied this idea to the case of the obstacle and the thin-obstacle problems. In Section 5, we used a general result (that we prove in the Appendix) and we construct a new flow, which simulates the behavior of the gradient flow from [5], but is also closely related to the explicit competitor from Section 5. As in the previous Section 7.1, we proceed by dividing the exposition in several paragraphs, each one representing a different step of the construction.
The starting point is the slicing lemma (Lemma 2.2) which allows to write down the energy of the competitor h(r,θ) as an integral over the different spheres (slices) ∂Br, r∈(0,1]. Precisely, one can compute that (see Lemma 2.2) if h is of the form
h(r,θ)=r2u(r,θ), |
then its energy W(h) is given by
W(h)=W(r2u)=∫10F(u(r,⋅))rd+1dr+∫10rd+3∫∂B1|∂ru|2dHd−1dr, | (7.10) |
where F is a functional acting on H1(∂B1).
Thus, we will search for a competitor of the form h(r,θ)=r2u(r,θ), where u can be read as a one-parameter family of functions
u(r,⋅):∂B1→R,r∈(0,1]. |
In this framework, the 2-homogeneous extension z, given in polar coordinates by
z(r,θ)=r2c(θ), |
corresponds to the case in which the flow r↦u(r,⋅)∈H1(∂B1) is constant in r. In this case, the second term in the right-hand side of (7.10) is zero and so we get
W(z)=∫10F(c)rd+1dr=1d+2F(c). |
As a consequence, the log-epiperimetric inequality (7.1), for h(r,θ)=r2u(r,θ) and the 2-homogeneous extension z(r,θ)=r2c(θ), can be written in terms of the new functional F as:
∫10(F(u(r,⋅))−F(c))rd+1dr+∫10rd+3∫∂B1|∂ru|2dHd−1dr≤−ε(F(c)−F(S))1+γ, | (7.11) |
where F(S):=(d+2)W(S). Thus, in order to find a function u for which (7.11) holds, we have to search for a function u:(0,1]×∂B1→R, which in particular satisfies
u(1,θ)=c(θ)forθ∈∂B1andF(u(r,⋅))≤F(c)forr≤1, |
but we also have to take into account the cost of modifying u from one scale to another, which is given by the error term
∫10rd+3∫∂B1|∂ru|2dHd−1dr. |
Now, since we will work with flows, it is convenient to consider functions of the form φ:[0,+∞)→H1(∂B1) and to define the competitor u as
u(r,θ)=φ(−κlnr,θ)forr∈(0,1]andθ∈∂B1. |
Thus, we have that
φ(0,⋅)=c(⋅)on∂B1, |
and the energy of the competitor
h(r,θ)=r2φ(−κlnr,θ), |
can be written as (see Lemma 3)
W(h)=F(φ(0))d+2+∫+∞0(1d+2φ′(t)⋅∇F(φ(t))+κ‖φ′(t)‖2L2(∂B1))e−t(d+2)κdt, |
or, alternatively, as
W(h)=F(φ(0))d+2+1κ∫∞0(F(φ(t))−F(φ(0)))e−t(d+2)κdt+κ∫∞0‖φ′(t)‖2L2(∂B1)e−t(d+2)κdt. |
The last expression of the energy W(h) suggests that, in order to construct a competitor with lower energy, we have to act on the term F(φ(t)). A natural way to do so, is to choose φ=ψ, where ψ is the gradient flow of F
{ψ′(t)=−∇F(ψ(t))fort∈(0,+∞),ψ(0)=c. | (7.12) |
The basic idea behind any of the constructions we propose is, given a homogeneous function z:B1→R, to build a competitor that simulates the behavior of the solution (in our case, the solution of the obstacle problem) with the same values as z on ∂B1. Now, for the obstacle problem, it is well known that if h(r,θ)=r2u(r,θ) is precisely the solution of the obstacle problem, then the energy F(u(r,⋅)) remains positive for every r>0 (this is a consequence of the Weiss' monotonicity formula [17]). Thus, we do not expect to find a good competitor with negative energy. So, instead of taking φ to be precisely the gradient flow ψ, we stop ψ at a certain time T. The choice of the stopping time is fundamental step in the epiperimetric inequality and will be chosen in function of the energy F(ψ(T)).
We define the flow φ(t,θ) as
φ(t):=ψ(t)ift∈[0,T],φ(t):=ψ(T)ift≥T, |
and teh competitor h as
h(r,θ)=r2φ(−κlnr,θ), |
where κ and T will be chosen below.
Again, the energy of the competitor u can be expressed in two different ways (we refer to Lemma 3 for the computation):
W(h)−W(z)=∫T0(1d+2ψ′(t)⋅∇F(ψ(t))+κ‖∇F(ψ(t))‖2L2(∂B1))e−t(d+2)κdt, | (7.13) |
where we recall that W(z)=1d+2F(ψ(0)), and
W(h)−W(z)=1κ∫T0(F(ψ(t))−F(ψ(0)))e−t(d+2)κdt+1d+2(F(ψ(T))−F(ψ(0)))e−T(d+2)κ+κ∫T0‖ψ′(t)‖2L2(∂B1)e−t(d+2)κdt. | (7.14) |
Moreover, we notice that, by summing up (7.13) and (7.14), we obtain
W(h)−W(z)=12(d+2)∫T0ψ′(t)⋅∇F(ψ(t))e−t(d+2)κdt+12κ∫T0(F(ψ(t))−F(ψ(0)))e−t(d+2)κdt+12(d+2)(F(ψ(T))−F(ψ(0)))e−T(d+2)κ+κ∫T0‖ψ′(t)‖2L2(∂B1)e−t(d+2)κdt. |
First, notice that the second term in the right-hand side of the above identity is negative. This is due to the fact that the energy F is decreasing along the flow ψ(t). Thus, we get
W(r2u)−W(z)≤12(d+2)∫T0ψ′(t)⋅∇F(ψ(t))e−t(d+2)κdt | (7.15) |
+12(d+2)(F(ψ(T))−F(ψ(0)))e−T(d+2)κ | (7.16) |
+κ∫T0‖ψ′(t)‖2L2(∂B1)e−t(d+2)κdt. | (7.17) |
Now since for the gradient flow ψ we have the identities
∂∂tF(ψ(t))=ψ′(t)⋅∇F(ψ(t))=−‖∇F(ψ(t))‖2L2(∂B1)=−‖ψ′(t)‖2L2(∂B1), | (7.18) |
the terms (7.15) and (7.16) are negative. Thus, we start by estimating the third term (7.17).
Using again (7.18), we get that (7.17) can be absorbed in (7.15). Indeed, by choosing κ small enough, for instance,
κ=14(d+2), |
we obtain
W(h)−W(z)≤14(d+2)∫T0ψ′(t)⋅∇F(ψ(t))e−t(d+2)κdt | (7.19) |
+12(d+2)(F(ψ(T))−F(ψ(0)))e−T(d+2)κ. | (7.20) |
Now, both terms (7.19) and (7.20) are negative.
Let T1/2 be defined as
T1/2=sup{τ : F(ψ(t))−F(S)≥12(F(ψ(0))−F(S))for everyt∈[0,τ]}. |
We consider two cases.
Case 1. The energy decreases rapidly along the flow: T1/2≤1. In this case, we choose T=T1/2 and we compute
W(h)−W(z)≤e−T(d+2)κ2(d+2)(F(ψ(T))−F(ψ(0)))≤e−d+2κ2(d+2)(F(ψ(T))−F(ψ(0)))=e−d+2κ2(d+2)((F(ψ(T))−F(S))−(F(ψ(0))−F(S)))=−12e−d+2κ2(d+2)(F(ψ(0))−F(S)), |
which concludes the proof of the log-epiperimetric inequality (7.1) (equivalently (7.11)) in this first case, in which we get (7.1) with the best possible exponent γ=0.
Case 2. The energy decreases slowly along the flow: T1/2≥1. In this case, we choose T=1 and the energy gain comes from the term (7.19). Indeed,
W(h)−W(z)≤∫T0ψ′(t)⋅∇F(ψ(t))e−t(d+2)κdt=−∫T0‖∇F(ψ(t))‖2L2(∂B1)e−t(d+2)κdt. |
In this second case, the proof of (7.11) is more involved and is based on the so-called Łojasiewicz inequality.
In order to conclude the proof of (7.11) also in the second case, we need to estimate ‖∇F(ψ(t))‖ from below in terms of the energy (F(ψ(t))−F(S)). Precisely, we need an inequality of the form
CLS(F(ϕ)−F(S))1+β≤‖∇F(ϕ)‖2for everyϕsuch thatF(ϕ)≥F(S), | (7.21) |
where CLS>0 and 0≤β<1. The above estimate is called Łojasiewicz inequality and is well-known in the case when F is an analytic function on a finite dimensional space; we refer to [5] for a more detailed discussion on the Łojasiewicz inequality and its different versions and applications. Now, using this estimate and the choice of the stopping time T=1≤T1/2 and κ=14(d+2), we can estimate (7.19) as follows:
−∫T0‖∇F(ψ(t))‖2L2(∂B1)e−t(d+2)κdt≤−CLS∫T0(F(φ(t))−F(S))1+βe−t(d+2)κdt≤−CLS21+γ∫T0(F(φ(0))−F(S))1+βe−t(d+2)κdt≤−CLSκ(d+2)21+β(1−e−T(d+2)κ)(F(φ(0))−F(S))1+β=−CdCLS(F(φ(0))−F(S))1+β, |
where Cd is a dimensional constant. This concludes the proof of the log-epiperimetric inequality (7.11) in the second case; the exponent γ=β is precisely the one from the Łojasiewicz inequality.
Up to this point, we have proved that the competitor h from Section 7.2.7 satisfies the log-epiperimetric inequality provided that the Łojasiewicz inequality (7.25) holds along the flow. For what concerns the functional F the Łojasiewicz inequality holds and is relatively easy to prove (see for instance the Introduction of [5]). On the other hand, in order to conclude that h is an admissible competitor in Theorem 1, we must have that h is non-negative, or in terms of the flow ψ, that ψ(t) is non-negative on ∂B1, for every t∈[0,T]. Unfortunately, we cannot assure that, for any ψ(0)=c, the flow remains positive. Thus, in [5], we propose a different construction.
In [5], we construct the competitor h from Subsection 7.2.7 starting from a flow ψ, which is the gradient flow of F constrained to remain in the (convex) space K of nonnegative functions defined on ∂B1. This constrained flow, is of course different with respect to the original gradient flow as the decay of the energy F may become much slower when the flow hits the boundary of the constraint K, but still, this flow has several properties, that make it very similar to the (unconstrained) gradient flow of F. In particular, we can repeat precisely the same construction presented above: the equalities (7.13) and (7.14) are general and hold for any function ψ:[0,+∞)→H1(∂B1), while the identities (7.18) should be replaced by
ψ′(t)⋅∇F(ψ(t))=−‖∇F(ψ(t))‖2K=−‖ψ′(t)‖2L2(∂B1). | (7.22) |
Thus, the proof of the epiperimetric inequality is precisely the same, with the only difference that the norm of ∇F is replaced by
‖∇F(ϕ)‖K=sup{0,supv∈K∖{ϕ}{−(v−ϕ)⋅∇F(ϕ)‖v−ϕ‖L2(∂B1)}}, | (7.23) |
for any nonnegative ϕ∈H2(∂B1). Now, the positivity constraint for this flow is automatically satisfied, so the main challenge is to prove an estimate that can replace the Łojasiewicz inequality (7.25). Indeed, in order to complete the proof, in [5], we prove the following stronger version of (7.25), that we called constrained Łojasiewicz inequality :
C\sc cls(F(ϕ)−F(S))1+β≤‖∇F(ϕ)‖2K . | (7.24) |
The proof is based on the choice of a suitable test direction ϕ in (7.23), that turns out to be precisely the function h2 from (7.9).
In Theorem A.1 of the Appendix, we make a more general construction of a competitor h starting from a flow ψ:[0,+∞)→H1(∂B1) that satisfies the following conditions :
(ⅰ) for any t≥0, the function ψ(t) remains nonnegative along the flow; this assures that the final competitor is admissible;
(ⅱ) the following inequality holds :
−ψ′(t)⋅∇F(ψ(t))≥‖ψ′(t)‖2L2(∂B1)for everyt>0 ; |
this guarantees that the energy F(ψ(t)) is decreasing in t and that the error term (7.17) can be absorbed by the energy gain (7.15);
(ⅲ) the following Łojasiewicz-type inequality (which replaces (7.25)) hold
C\sc lst(F(ψ(t))−F(S))1+β≤−ψ′(t)⋅∇F(ψ(t)) , | (7.25) |
for every t>0 such that ψ′(t)≠0.
This abstract result can be used also in other contexts (for instance, in can be applied to the thin-obstacle problem). In Section 4 we apply Theorem A.1 to a specific flow, for which the derivative ψ′(t) does not depend on t and we choose the direction ψ′ to be precisely the one from (7.9); thus, recovering the competitor from Section 4.
L. S. has been partially supported by the NSF grant DMS 1810645. B. V. has been supported by the European Research Council (ERC) under the European Union's Horizon 2020 research and innovation programme (grant agreement VAREG, No. 853404).
The authors declare no conflict of interest.
In this section we give a general procedure that reduces the construction of a competitor for the log-epiperimetric inequality to the construction of a flow that satisfies two key hypotheses: an energy dissipation estimate and a Łojasiewicz inequality. Our construction applies not only to the specific case of the obstacle problem, but can be used to prove log-epiperimetric inequalities for any functional that satisfies suitable homogeneity properties. In particular, it can be used in the context of to the thin-obstacle problem and, more generally, to the obstacle problem for the s-Laplacian. Our main result is Theorem A.1. Before stating it, we introduce some notation and we list the main assumptions that we make.
Homogeneity. We fix a positive real constant α>0; in the case of the obstacle problem (that is, in Theorem 1) α is equal to 2.
Energy. We consider two functionals
G:H1(B1)→RandF:H1(∂B1)→R , |
with the following properties.
● F is differentiable. Precisely, there is a functional ∇F:H2(∂B1)→L2(∂B1) such that
F(u+v)=F(u)+v⋅∇F(u)+o(‖v‖H1(∂B1)), |
for every u∈H2(∂B1) and every v∈H1(∂B1).
● G and F are related through a slicing identity. Precisely, we assume that there is a constant CLS>0 such that, for any function u=u(r,θ)∈H1([0,1]×∂B1), we have
G(rαu(r,θ))≤∫10F(u(r,⋅))r2α+d−3dr+CLS∫10∫∂B1|∂ru|2r2α+d−1dHd−1dr, | (A.1) |
with equality if u is constant in the r variable. In this case, we have
G(rαu(θ))=∫10F(u)r2α+d−3dr=12α+d−2F(u). | (A.2) |
Critical set. We suppose that there is a compact set S⊂H2(∂B1) such that:
● S is a set of critical points for F, that is :
∇F(Q)=0for everyQ∈S. |
● F is constant on S; and we denote this constant by F(S):
F(Q)=F(S)for everyQ∈S. |
Flow. We suppose to be given a constant Tmax>0 and a function ψ:[0,Tmax]→H2(∂B1) such that
ψ∈L2([0,Tmax];H2(∂B1))∩H1((0,Tmax);L2(∂B1)), |
orψ∈L2([0,Tmax];H1(∂B1))∩H1((0,Tmax);H1(∂B1)). |
In both cases the energy F(ψ(t)) is well-defined and (weakly) differentiable in t. Precisely,
ddtF(ψ(t))=ψ′(t)⋅∇F(ψ(t))for everyt∈(0,Tmax), |
and the map
(0,Tmax)∋t↦ψ′(t)⋅∇F(ψ(t))∈R |
is integrable, where the dot indicates the scalar product in L2(∂B1), or the pairing between H1(∂B1) and its dual space. Moreover, we assume that the flow and the energy F satisfy the following properties.
Energy dissipation inequality. There are constants CED>0 and p≥2 such that the following inequality holds
CEDmin{‖ψ′(t)‖2L2(∂B1),‖ψ′(t)‖pL2(∂B1)}≤−ψ′(t)⋅∇F(ψ(t)), | (A.3) |
for almost every t≥0. In particular, the energy is non-increasing along the flow :
F(ψ(t))−F(ψ(s))=∫tsψ′(τ)⋅∇F(ψ(τ))dτ≤0for every0≤s≤t. | (A.4) |
Łojasiewicz inequality. There are constants C\tiny\sc ls>0 and β∈[0,1) such that F satisfies the following inequality along the flow
C\tiny\sc ls(F(ψ(t))−F(S))1+β≤−ψ′(t)⋅∇F(ψ(t))for almost everyt>0. | (A.5) |
Theorem A.1. Suppose that the functionals G and F, and the flow ψ satisfy the hypotheses above. Moreover, we assume that the exponents β∈[0,1) and p≥2, from (A.3) and (A.5) respectively, are such that
(1+β)(1−1p)<1. |
Then, there are constants δ0>0, E>0, γ∈[0,1) and ε>0, depending on d, α, p, β, Tmax, CSL, CLS and CED, such that the following holds. If c∈H1(∂B1) satisfies
c=ψ(0)andF(c)−F(S)≤E, |
then there exists a function h=h(r,θ)∈H1(B1) satisfying h(1,⋅)=c(⋅) on ∂B1, and
G(h)−G(S)≤(1−ε|G(z)−G(S)|γ)(G(z)−G(S)) | (A.6) |
where γ=(1+β)(2−2p)−1, and where we used the notations
z(r,θ):=rαc(θ)andG(S):=12α+d−2F(S). |
Remark A.2 (The two extremal cases). When p=2 and β>0, Theorem A.1 corresponds precisely to [5, Proposition 3.1]. On the other hand, in Section 5, we apply Theorem A.1 to a flow for which p>2 and β=0.
Remark A.3 (About a missing hypothesis). In the proposition above there is one hypothesis less with respect to [5, Proposition 3.1] and Theorem 1, where it is also required that the trace c is L2(∂B1)-close to the set S of critical points. This closeness condition is hidden in the hypotheses that the energy dissipation and the Łojasiewicz inequalities (A.3) and (A.5) hold for every t along the flow ψ. In fact, in Section 5, in order to prove (A.3) and (A.5) are satisfied for our specific choice of the flow, we use the closeness condition, which was essential in the proof of the key estimates in Section 3; similarly, in [5, Proposition 3.1], we used that the trace c lies close to S in the proof of the Łojasiewicz inequality.
Remark A.4 (About G(S)). Let Q∈S. Then, G(S) is precisely the energy G(rαQ(θ)) of the α-homogeneous extension rαQ(θ) of Q.
Proof of Theorem A.1. First, notice that if G(z)−G(S)≤0, then choosing h=z we immediately get A.6. Throughout the rest of the proof we will assume that
0<G(z)−G(S)=12α+d−2(F(c)−F(S)). |
We define the competitor h as
h(r,θ)=rαu(r,θ), |
where, as in Section 7.2,
u(r,θ)=φ(−κlnr,θ)forr∈(0,1]andθ∈∂B1, |
for some κ>0, and φ is the stopped flow
φ(t):=ψ(t)ift∈[0,T],φ(t):=ψ(T)ift≥T, |
where the stopping time T will be chosen later.
We will divide the rest of the proof in several steps. Before we proceed, we notice that the log-epiperimetric inequality for G A.6 is equivalent to:
G(h)−G(z)≤−ε(G(z)−G(S))1+γ, | (A.7) |
where the right-hand side of the above inequality can also be written as
ε(G(z)−G(S))1+γ=ε(2α+d−2)1+γ(F(c)−F(S))1+γ. |
We start with estimating from above the energy gap G(h)−G(z) in terms of the flow ψ.
Estimating the energy gap. We first give the energy G(h) in terms of the flow ψ and the variable t. Using (A.1) and reasoning as in Lemma 2.4, we have
G(rαu(r,θ))≤∫10F(u(r,⋅))r2α+d−3dr+CSL∫10∫∂B1|∂ru|2r2α+d−1dHd−1dr=∫10F(φ(−κlnr))r2α+d−3dr+CSL∫10κ2r2α+d−3‖φ′(−κlnr)‖2L2(∂B1)dr=1κ∫+∞0F(φ(t))e−(2α+d−2)tκdt+κCSL∫+∞0‖φ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt. | (A.8) |
In particular, this implies that
G(rαu(r,θ))−G(rαc(θ))≤1κ∫T0(F(ψ(t))−F(ψ(0)))e−(2α+d−2)tκdt+1d+2α−2(F(ψ(T))−F(ψ(0)))e−(2α+d−2)tκ+κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt. | (A.9) |
Moreover, integrating by parts the first term on the right-hand side, we get
G(rαu(r,θ))−G(rαc(θ))≤1d+2α−2∫T0ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt+κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt. | (A.10) |
Recall that by (A.4), the energy is decreasing along the flow. Thus, the first term in the right-hand side of (A.9) is negative (thus we simply estimate it from above by zero). Finally, multiplying (A.9) and (A.10) by 1/2 and summing them, we obtain the following estimate
G(rαu(r,θ))−G(rαc(θ))≤12(d+2α−2)e−(2α+d−2)Tκ(F(ψ(T))−F(ψ(0)))+12(d+2α−2)∫T0ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt+κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt. | (A.11) |
We notice that, up to this point, we used only (A.1) and (A.2), and an integration by parts.
Estimating the error term. We now estimate the last term in the right-hand side of (A.11), which is also the only positive one. We notice that the energy dissipation condition (A.3) is equivalent to the following :
‖ψ′(t)‖2L2(∂B1)≤C1[−ψ′(t)⋅∇F(ψ(t))]+C2[−ψ′(t)⋅∇F(ψ(t))]2/p, | (A.12) |
for some positive constant C1 and C2. As a consequence, we can estimate
κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt≤κCSLC1∫T0(−ψ′(t)⋅∇F(ψ(t)))e−(2α+d−2)tκdt+κCSLC2∫T0(−ψ′(t)⋅∇F(ψ(t)))2/pe−(2α+d−2)tκdt. |
Now, the first term on the right hand side can be absorbed into the first term of (A.11) by choosing κ small enough, in function of the constants involved. In order to estimate the second term, we use the Hölder inequality :
∫T0(−ψ′(t)⋅∇F(ψ(t)))2/pe−(2α+d−2)tκdt≤(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)2/p(∫T0e−(2α+d−2)tκdt)1−2/p≤(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)2/p(κ2α+d−2(1−e−(2α+d−2)Tκ))1−2/p≤(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)2/p(κ2α+d−2)1−2/p. |
In conclusion, we obtain
κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt≤Cκ2−2/p(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)2/p+Cκ∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt, | (A.13) |
where C is a constant depending on d,α,p,CSL and CED.
Stopping time. Recall that, by hypothesis, the flow ψ is defined on the interval [0,Tmax]. We define T1/2 as
T1/2=sup{s∈[0,Tmax] : F(ψ(t))−F(S)≥12(F(ψ(0))−F(S))for everyt∈[0,s]}, |
and we consider two cases. Below, we will choose the stopping time T such that
0≤T≤T1/2. |
Choice of κ. We choose
κ=εκ(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)p−22p−2, | (A.14) |
where εκ>0 is a small constant, depending on d,α,p,CSL and CED, such that
εκ≤1 ,εκC≤11012(2α+d−2)andεk≤Tmax. | (A.15) |
We notice that by the choice T≤T1/2, we have that:
∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt≤∫T0−ψ′(t)⋅∇F(ψ(t))dt=F(ψ(0))−F(ψ(T))≤F(ψ(0))−F(S)≤E, |
which gives that
κ≤εκEp−22p−2≤εκ, |
where the last inequality holds when E≤1.
Now, notice that the last term of the right-hand side of (A.11) can be estimated as follows :
κCSL∫T0‖ψ′(t)‖2L2(∂B1)e−(2α+d−2)tκdt≤2Cεk∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt≤14(2α+d−2)∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt, | (A.16) |
where the first inequality follows by the first inequality for εk in (A.15) and the second one is a consequence of the second bound for εk in (A.15). This is the estimate in which we use the first two inequalities in the choice of the constant εκ. The last inequality of (A.15) is only needed for the bound
κ≤Tmax, |
which we will use in the two possible choices of T that we discuss below. Before we proceed with the choice of T, we notice that by combining the inequalities (A.16) and (A.11), we can eliminate the last term in the right-hand side of (A.11). Precisely, the energy gap G(rαu)−G(z) can be estimated as follows:
G(rαu(r,θ))−G(rαc(θ))≤12(d+2α−2)e−(2α+d−2)Tκ(F(ψ(T))−F(ψ(0)))+14(d+2α−2)∫T0ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt. | (A.17) |
Choice of the stopping time. We now proceed with the choice of T, which is the last point of the construction of the competitor. As in Subsection 7.2, we consider two cases.
Case 1. The energy decreases rapidly along the flow: T1/2≤κ.
In this case, we choose T=T1/2 and we estimate the first term in the right-hand side of (A.17). Indeed, since Tκ≤1 and since the function x↦−e−x is increasing in x, we have :
−e−T(2α+d−2)κ2(2α+d−2)(F(ψ(0))−F(ψ(T)))≤−e−(2α+d−2)2(2α+d−2)(F(ψ(0))−F(ψ(T)))=−12e−(2α+d−2)2(2α+d−2)(F(ψ(0))−F(S)), |
which concludes the proof of (A.6) in this case.
Case 2. The energy decreases slowly along the flow: κ≤T1/2.
In this case, we choose T=κ and we estimate the second term in the right-hand side of (A.17). By the Łojasiewicz inequality (A.5), we have
−∫T0−ψ′(t)⋅∇F(ψ(t))e−t(2α+d−2)κdt≤−CLS∫T0(F(ψ(t))−F(Q))1+βe−t(2α+d−2)κdt≤−CLS21+γ∫T0(F(ψ(0))−F(Q))1+βe−t(2α+d−2)κdt=−CLSκ(2α+d−2)21+β(1−e−T(2α+d−2)κ)(F(ψ(0))−F(Q))1+γ=−CLS(1−e−(2α+d−2))(2α+d−2)21+βκ(F(ψ(0))−F(Q))1+β, |
where the second inequality follows from the fact that
F(φ(t))−F(Q)≥12(F(φ(0))−F(Q))for everyt≤T=κ≤T1/2. |
Now, setting
C=εkCLS(1−e−(2α+d−2))(2α+d−2)21+β |
and using the definition of κ, we get that
−∫T0−ψ′(t)⋅∇F(ψ(t))e−t(2α+d−2)κdt≤−C(∫T0−ψ′(t)⋅∇F(ψ(t))e−(2α+d−2)tκdt)p−22p−2(F(ψ(0))−F(Q))1+β, |
which implies
−(∫T0−ψ′(t)⋅∇F(ψ(t))e−t(2α+d−2)κdt)p2p−2≤−C(F(ψ(0))−F(Q))1+β, |
and finally,
−∫T0−ψ′(t)⋅∇F(ψ(t))e−t(2α+d−2)κdt≤−C2−2/p(F(ψ(0))−F(Q))(1+β)(2−2p), |
which concludes the proof of Theorem A.1, since 1+γ=(1+β)(2−2/p).
In this section, we show how to deduce the rate of convergence of the blow-up sequence starting from the log-epiperimetric inequality. The argument holds for a general energy E and can be used in several different contests: for the obstacle and the thin-obstacle problems, as well as for Bernoulli-type free boundary problems and minimal surfaces (see, for instance [6] and [7]).
Proposition B.1. Let α>0 be fixed. Let the function u∈H1(B1) and the energy E:H1(B1)→R be given and, for every 0<r≤1, let ur∈H1(B1) be defined as
ur(x):=1rαu(rx)for everyx∈B1. |
(a) The function r↦E(ur) is differentiable on (0,1] and
∂∂rE(ur)≥CarD(ur) for every0<r<1, | (B.1) |
where Ca>0 is a given constant and
D(u):=∫∂B1|x⋅∇u−αu|2dHd−1(x). |
(b) There is a constant Cb>0 such that
∂∂rE(ur)≥Cbr(E(zr)−E(ur))for every0<r<1, |
where zr:B1→R is the α-homogeneous extension of ur|∂B1, that is,
zr(x)=|x|αur(x/|x|)for everyx∈B1. |
(c) There are constants Cc>0 and γ∈[0,1) such that, for every r∈]0,1], there exists a function hr∈H1(B1) for which the following log-epiperimetric inequality holds :
E(hr)≤(1−Cc|E(zr)|γ)E(zr). |
(d) For every 0<r≤1, we have
0≤E(ur)≤E(zr)and0≤E(ur)≤E(hr). |
Then, for every u∈H1(B1) satisfying hypotheses (a), (b), (c) and d), and such that E(u)≤E, for some constant E, there exists u0∈H1(B1) such that
‖ur−u0‖L2(∂B1)≤C(−lnr)−1−γ2γ for every 0<r≤1, |
where the constant C depends on Ca, Cb, Cc, the dimension d, the exponent γ, and on E.
Proof. First, notice that by (b), (c) and (d), we have
∂∂rE(ur)≥Cbr(E(zr)−E(ur))≥Cbr(E(hr)+CcE(zr)1+γ−E(ur))≥CbCcrE(ur)1+γ. | (B.2) |
Consider the change of coordinates t(r)=−logr (thus, r(t)=e−t and r′(t)=−r(t)), and let
e(t):=E(ur(t))andf(t):=D(ur(t)), |
for every t≥0. Then, we have
e′(t)=r′(t)∂∂rE(ur(t))=−r(t)∂∂rE(ur(t)). |
In particular, using (B.1) and (B.2)
e′(t)≤−Caf(t)ande′(t)≤−CbCce(t)1+γ. |
The second inequality implies the decay of e(t). Indeed,
∂∂t[e(t)−γ−γtCbCc]=γ(−e(t)−1−γe′(t)−CbCc)≥0, |
which implies that, for every t≥0,
e(t)−γ−γtCbCc≥e(0)−γ, |
which after rearranging the terms gives
e(t)≤(e(0)−γ+tγCbCc)−1/γfor everyt≥0. |
In particular, there is a constant C, depending on Cb, Cc, e(0) and γ, such that
e(t)≤Ct−1/γfor everyt≥1. | (B.3) |
Let now 0<r<R≤1, t=−lnR and T=−lnr be fixed; in particular, 0≤t<T<+∞. \\ For every x∈∂B1 we compute
∂∂tut(x)=∂∂t[u(tx)tα]=x⋅∇u(tx)tα−αtu(tx)tα=1t(x⋅∇ut(x)−αut(x)). |
Integrating over ∂B1, we get
∫∂B1|uR−ur|2dHd−1≤∫∂B1(∫Rr1ρ|x⋅∇uρ−uρ|dρ)2dHd−1=∫∂B1(∫Tt|x⋅∇uρ(τ)−uρ(τ)|dτ)2dHd−1, |
where we used the change of variables τ=−lnρ. By the Cauchy-Schwartz inequality, we get
∫∂B1|uR−ur|2dHd−1≤∫∂B1((T−t)∫Tt|x⋅∇uρ(τ)−uρ(τ)|2dτ)dHd−1=(T−t)∫Tt∫∂B1|x⋅∇uρ(τ)−uρ(τ)|2dHd−1dτ=:(T−t)∫Ttf(τ)dτ. |
Now, using the inequality f(τ)≤−1Cae′(τ), and integrating in τ, we obtain
∫∂B1|uR−ur|2dHd−1≤T−tCa(e(t)−e(T))≤T−tCae(t). |
Applying the above inequality to
T=tn+1=2n+1 ,t=tn=2n ,r=rn+1=e−2n+1 ,R=rn=e−2n, |
and using (B.3), we get
∫∂B1|urn+1−urn|2dHd−1≤1Ca(T−t)e(t)≤CCa(21−γγ)−n. |
Let now σ=2−1−γ2γ. Thus, σ<1 and
‖urn+1−urn‖L2(∂B1)≤(C/Ca)1/2σn, |
which implies that, for every N∈N and for every m>n≥N, we have
‖urm−urn‖L2(∂B1)≤(C/Ca)1/21−σσN, |
which proves that urn is a Cauchy sequence in L2(∂B1) and so, it converges to some u0∈L2(∂B1), for which we have
‖urn−u0‖L2(∂B1)≤(C/Ca)1/21−σσn. |
In order to conclude the proof, it only remains to notice that if r∈(rn+1,rn), then
∫∂B1|urn−ur|2dHd−1≤tn+1−tnCae(tn)≤CCa2n2−n/γ=CCaσ2n, |
which, by the triangular inequality and the fact that tn<−lnr<tn+1, implies that
‖ur−u0‖L2(∂B1)≤‖ur−urn‖L2(∂B1)+‖urn−u0‖L2(∂B1)≤(C/Ca)1/2(1+11−σ)σn=(C/Ca)1/22−σ1−σ(2−n)1−γ2γ=[(C/Ca)1/22−σ1−σ21−γ2γ]t−1−γ2γn+1≤[(C/Ca)1/22−σ1−σ21−γ2γ](−lnr)1−γ2γ, |
which proves that ur converges to u0 in L2(∂B1).
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1. | Nick Edelen, Luca Spolaor, Bozhidar Velichkov, The symmetric (log-)epiperimetric inequality and a decay-growth estimate, 2024, 63, 0944-2669, 10.1007/s00526-023-02610-7 |