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On the logarithmic epiperimetric inequality for the obstacle problem

  • We give three different proofs of the log-epiperimetric inequality at singular points for the obstacle problem. In the first, direct proof, we write the competitor explicitly; the second proof is also constructive, but this time the competitor is given through the solution of an evolution problem on the sphere. We compare the competitors obtained in the different proofs and their relation to other similar results that appeared recently. Finally, in the appendix, we give a general theorem, which can be applied also in other contexts and in which the construction of the competitor is reduced to finding a flow satisfying two differential inequalities.

    Citation: Luca Spolaor, Bozhidar Velichkov. On the logarithmic epiperimetric inequality for the obstacle problem[J]. Mathematics in Engineering, 2021, 3(1): 1-42. doi: 10.3934/mine.2021004

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  • We give three different proofs of the log-epiperimetric inequality at singular points for the obstacle problem. In the first, direct proof, we write the competitor explicitly; the second proof is also constructive, but this time the competitor is given through the solution of an evolution problem on the sphere. We compare the competitors obtained in the different proofs and their relation to other similar results that appeared recently. Finally, in the appendix, we give a general theorem, which can be applied also in other contexts and in which the construction of the competitor is reduced to finding a flow satisfying two differential inequalities.


    To Sandro Salsa on the occasion of his 70th birthday.

    For any uH1(B1), we define the functionals (Weiss' boundary adjusted energies)

    W0(u):=B1|u|2dx2B1u2dHd1andW(u):=W0(u)+B1udx.

    We denote by S the following class of 2-homogeneous polynomials :

    S:={QA:RdR:QA(x)=xAx, where A=(aij)ij is a symmetric non-negative matrix such thattrA=di=1aii=14 }. (1.1)

    Notice that the functional W is constant on S. We will use the notation

    W(S):=W(QA)for anyQAS. (1.2)

    This paper is dedicated to the so-called logarithmic epiperimetric inequality, which was first introduced in [3], for the functional W and the set S, and already found several applications to different variational free boundary problems (see for instance [4,6,7,15]).

    Theorem 1 (Log-epiperimetric inequality for W). There are dimensional constants δ>0, ε>0 and γ[0,1) such that the following claim holds. For every non-negative function cH1(B1), with 2-homogeneous extension z on B1, satisfying

    dist2(c,S)δandW(z)W(S)1,

    there is a non-negative function hH1(B1) with h=c on B1 satisfying the inequality

    W(h)W(S)(W(z)W(S))(1ε|W(z)W(S)|γ). (1.3)

    The epiperimetric inequalities are powerful tools in the regularity theory of free boundary problems and minimal surfaces. The concept of an epiperimetric inequality (which is (1.3) with γ=0) was first introduced by Reifenberg in [14] in the context of minimal surfaces in the 60s. In the late 90s, Weiss [17] used an epiperimetric inequality approach to study the free boundaries of the obstacle problem.

    The Weiss' epiperimetric inequality was still of the form (1.3), with γ=0 and for the same energy W, but the set S defined in (1.1) was replaced by the set of the 'flat' blow-up limits

    R={Q(x)=14(xν)2+whereνB1}.

    In [17] Weiss used the epiperimetric inequality to prove the C1,α regularity of the 'flat' free boundaries. It is now known that the epiperimetric inequality ((1.3) with γ=0) cannot hold in a neighborhood of the set S; this follows from the counterexample to the C1,α regularity of the singular free boundaries given in [10].

    There are several other epiperimetric inequalities for free boundary problems in the literature. By using the technique of Weiss, Focardi-Spadaro [12] and Garofalo-Petrosyan-Smit Vega Garcia [13] proved an epiperimetric inequality at the regular points of the thin-obstacle free boundaries. Then, in [16], by using a different (direct) approach, we proved an epiperimetric inequality for the Bernoulli free boundary problems in dimension two.

    The log-epiperimetric inequality ((1.3) with γ[0,1)) was introduced in our work [3], in collaboration with M. Colombo, where we first proved Theorem 1. The initial idea in [3] was to attack the epiperimetric inequality for S (left open in the work of Weiss [17]) by the direct approach from [16]. As we already mentioned above, this cannot be actually done, but it led to the formulation of the log-epiperimetric inequality (1.3), from which we obtained the C1,log regularity of the singular part of the free boundary (from where the name logarithmic).

    Following the original spirit of [16], our approach in [3] was still direct in the sense that we built the competitor explicitly. We later used this idea to prove a log-epiperimetric inequality at the singular points of the thin-obstacle free boundaries [4]. Constructing explicit competitors has the advantage to provide proofs that use only elementary tools and essentially boils down to constructing sub and supersolutions starting from a trace, which is close to the set S. This requires the set S to be known explicitly. On the other hand, one is mainly interested in the case when S is a set of global homogeneous solutions to some free boundary variational problem and the classifications of these solutions is known only for some specific problems.

    In [6] and [7], in collaboration with Max Engelstein, we elaborated a different approach to the log-epiperimetric inequality and we constructed the competitor by reparametrizing the solution of an evolution problem on the sphere. Finally, in [5], we exploited some of the ideas from [6] and [7] to give new proofs of the log-epiperimetric inequalities (for the obstacle and the thin-obstacle problems) from [3] and [4], and we showed its relation to a class of parabolic variational inequalities.

    This paper has several objectives. Our first aim is to provide a different (and hopefully easier) direct proof of Theorem 1. Our new proof (see Section 4) is based on a specific decomposition of the trace inspired by the competitor that we used to prove the constrained Łojasiewicz inequality in [5]. Then, we notice that the competitor built this way in fact simulates the behavior the gradient flow from [5] and so, we give a second proof of Theorem 1 (see Section 5) by using a construction in the spirit of [5].

    We explain the ideas behind the two different constructions in Section 7, which can be read independently. Moreover, in order to give our second proof of Theorem 1, we give a new general result in which the construction of the competitor is reduced to finding a flow on the sphere that satisfies two specific inequalities (see Theorem A.1). This general result applies both to the gradient flow from [5] and to the flow from Section 5. It is also intended to facilitate the construction of competitors for other variational problems, for instance, non-local obstacle problems.

    In the first three sections we give a direct proof of Theorem 1 in the spirit of [3], but using a different competitor. Section 2 contains the notations and some basic facts about the functional W. Section 3 is dedicated to the main estimate that we need in the proof of Theorem 1. In Section 4 we give the proof of the theorem by putting together the estimates from Section 2 and Section 3.

    In Section 5 and Section 6 we give a proof of Theorem 1 based on the definition of a flow on the sphere. Then, we use the estimates from Section 2 and Section 3 to prove that these flows satisfy the condition of Theorem A.1.

    In Section 7, we explain the main ideas behind the direct proofs from Section 4 and [3], and the constructive, gradient flow approach from Sections 5 and 6. This section can be read independently; we only use some of the notations and preliminary results from Section 2.

    In Theorem A.1 we show how to construct a competitor out of a flow defined in H1(B1); we prove that competitor satisfies a log-epiperimetric inequality provided that the flow satisfies two main conditions:

    an  energy  dissipation  inequality  (A.3),andŁojasiewicz  inequality  (A.5).

    This result applies to both the flow from Section 5 and the gradient flow from Section 6; in the first case, the exponent γ in the log-epiperimetric inequality (1.3) appears as a consequence of the energy dissipation inequality (A.3), while in the case of the gradient flow (Section 6), the exponent is due to the Łojasiewicz inequality (A.5). In both cases, Theorem A.1 allows to reduce the proof of the log-epiperimetric inequality to verifying that (A.3) and (A.5) hold along the flow.

    A consequence of Theorem 1 is the following result on the structure of the singular free boundaries of solutions to the obstacle problem, which we give here for the sake of completeness. We recall that u:B1R is a solution to the obstacle problem (in the unit ball B1Rd) if u0 and

    B1(|u|2+u)dxB1(|v|2+v)dxfor everyvH1(B1)such thatv0inB1anduvH10(B1). (1.4)

    We define Ωu:={u>0} and the set of singular points

     Sing(Ωu):={x0Ωu : limr0|Br(x0)Ωu||Br|=1}.

    Let u be a solution to the obstacle problem. We say that Q:B1R is a blow-up limit of u at x0ΩuB1 (and we write QBU(u,x0)), if there is a sequence rn0 such that

    limnurn,x0QL2(B1)whereurn,x0(x)=1r2nu(x0+rnx).

    It is well-known that x0 Sing(Ωu) if and only if BU(u,x0)S (see, for instance, [2] and [9]).

    Finally, we define the strata  Singk(Ωu), for every k{0,1,,d1}, as

     Singk(Ωu):={x0 Sing(Ωu) : there is  QABU(u,x0)  such that  dim(KerA)=k}.

    As an immediate consequence of Theorem 1, we obtain Theorem 2, proved in [3]. A finer result on the structure of the singular set (in any dimension) was obtained by Figalli and Serra [10], and more recently, by Figalli, Serra and Ros-Oton [11].

    Theorem 2 (Structure of the singular free boundaries). Let u:B1R be a solution to the obstacle problem (1.4). Then, the following holds.

    (i) Uniqueness of the blow-up limit. At every x0Sing(Ωu), the blow-up limit is unique, that is, there is QAx0S such that

    limr0ur,x0QAx0L2(B1)=0.

    (ii) Rate of convergence of the blow-up sequence. For every xB1, there is a ball B=Bρ(x) and R>0 such that

    ur,x0QAx0L2(B1)C(lnr)δfor everyx0Sing(Ωu)Band everyrR.

    (iii) Distance between the blow-up limits at different points. For every xB1, there is a ball Bρ(x) such that

    QAy0QAx0L2(B1)C(ln|x0y0|)δfor everyx0,y0Sing(Ωu)Bρ(x).

    (iv) Structure of the strata. The set Sing0(Ωu) is discrete. For every 1kd1, there is δ, depending on d and eventually on k such that the following holds.

    For every xSingk(Ωu), there is a ball Bρ(x)B1 such that Singk(Ωu)Bρ(x) is contained in a C1,log-regular k-dimensional manifold. Precisely, up to a rotation of the coordinate system, there is a C1 regular function φ:RkRdk such that

    Singk(Ωu)Bρ(x)Graph(φ)Bρ(x),

    and φ(0)=0 and

    |φ(x0)φ(y0)|C(ln|x0y0|)δfor everyx0,y0RkBρ(x).

    Proof. The claims (i) and (ii) follow by the log-epiperimetric inequality (1.3) and a standard general procedure, which we explain in the appendix (Proposition B.1) for the sake of completeness. The claim (iii) follows directly from (ii), while (iv) is a consequence of (iii) and a Whitney extension theorem (see, for instance, [8]).

    In this section we prove some preliminary results about the energy W (Section 2.1) and we recall some a basic facts about the decomposition in spherical harmonics (Section 2.2) that we use in the construction of the competitors for the log-epiperimetric inequality.

    In the direct proof of Theorem 1 (see Section 4) we will use only Lemma 2.1, Lemma 2.2 and Corollary 2.3. Lemma 2.4 will be used in the second proof, given in Section 5.

    Lemma 2.1 (W and W0). Let uH1(B1) and QS. Then

    W0(uQ)=W(u)W(Q).

    Proof. We compute

    W0(uQ)=B1|(uQ)|22B1(uQ)2dHd1=W0(u)+W0(Q)2(B1uQdx2B1uQdHd1)=W0(u)+W0(Q)+2B1uΔQdx=W0(u)+W0(Q)+B1udx=W(u)W(Q), (2.1)

    where we integrated by parts and, in the last line, we used the identity

    W0(Q)=B1|Q|2dx2B1Q2dHd1=B1QΔQdx=12B1Qdx,

    so that W(Q)=W0(Q)+B1Qdx=12B1Qdx=W0(Q).

    The following simple lemma will be fundamental in both proofs so we collect it here.

    Lemma 2.2 (Slicing Lemma). Let u=u(r,θ)H1(B1). Then, computing the energy W0(r2u) of the function written in polar coordinates as (r,θ)r2u(r,θ), we obtain

    W0(r2u)=10rd+1B1(|θu|22du2)dθdr+10rd+3B1|ru|2dθ. (2.2)

    In particular, if we set

    F(ϕ):=B1(|θϕ|22dϕ2+ϕ)dHd1, (2.3)

    we have the equality

    W(r2u)=10F(u(r,))rd+1dr+10rd+3B1|ru|2dHd1dr. (2.4)

    Finally, if u(r,θ)=rεc(θ), then

    W0(r2+εc(θ))=1d+2α2B1(|θc|22dc2)dθ+(α2)2d+2α2B1c2dθ, (2.5)

    where α=2+ε and ε0.

    Proof. Setting θB1, dθ=dHd1, we calculate for a function u=u(r,θ)

    W0(r2u)=10B1(|2ru+r2ru|2+r2|θu|2)dθrd1dr2B1u2dθ=10B1(2r2u2+r4|ru|2+2r3r(u2)+r2|θu|2)dθrd1dr2B1u2dθ=10B1(4r2u2+r4|ru|22(d+2)r2u2+r2|θu|2)dθrd1dr=10rd+1B1(|θu|22du2)dθdr+10rd+3B1|ru|2dθdr,

    which is precisely (2.2). The identity (2.4) follows from (2.2) by the formula

    B1udx=10BrudHd1dr.

    Finally, Eq (2.5) directly follows from (2.2) by integrating in r.

    Corollary 2.3 (Decomposition of the energy). Suppose that z1,z2H1(B1) are of the form zj(r,θ)=r2gj(r)cj(θ), for j=1,2, where the traces c1,c2H1(B1) are orthogonal on the sphere in the following sense:

    B1c1c2dθ=B1θc1θc2dθ=0. (2.6)

    Then, we have

    W0(z1+z2)=W0(z1)+W0(z2)andW(z1+z2)=W(z1)+W(z2). (2.7)

    Proof. It is sufficient to apply the formulas (2.2) and (2.4), and then use (2.6).

    The next lemma is essentially the identity (2.4) from the Slicing Lemma for competitors defined by reparametrization of the radial coordinate. We will use the following notation:

    F(ϕ)=2ΔB1ϕ4dϕ+1forϕH2(B1), (2.8)
    ψF(ϕ)=B1ψ(2ΔB1ϕ4dϕ+1)dHd1forϕH2(B1)andψL2(B1).

    Lemma 2.4 (The slicing lemma reparametrized). Suppose that ψ:[0,+)H2(B1) is a function such that

    ψC1((0,+);L2(B1))C0([0,+);H1(B1))C0((0,+);H2(B1)),

    and let T(0,+]. We define φ:[0,+)H2(B1) as

    φ(t):=ψ(t)ift[0,T),φ(t):=ψ(T)iftT.

    and the function u:B1R as

    u(r,θ)=φ(κlnr,θ),

    where κ>0 is fixed. Then, we have

    W(r2u)=1κ0F(φ(t))et(d+2)κdt+κ0φ(t)2L2(B1)et(d+2)κdt, (2.9)

    and also

    W(r2u)=F(ψ(0))d+2+T0(1d+2F(ψ(t))ψ(t)+κψ(t)2L2(B1))et(d+2)κdt. (2.10)

    In particular, if φ is constant in t, then

    W(r2u)=F(φ(0))d+2. (2.11)

    Proof. Using the identity (2.4) and the change of variables t=κlnr, we compute

    W(r2u)=10F(u(r))rd+1dr+10rd+3B1|ru|2dHd1dr=10F(φ(κlnr))rd+1dr+10κ2rd+1φ(κlnr)2L2(B1)dr=1κ0F(φ(t))et(d+2)κdt+κ0φ(t)2L2(B1)et(d+2)κdt

    Now, by the definition of ψ, we get

    W(r2u)=1κT0F(ψ(t))et(d+2)κdt+1κ+TF(ψ(T))et(d+2)κdt+κT0ψ(t)2L2(B1)et(d+2)κdt=1κT0F(ψ(t))et(d+2)κdt+F(ψ(T))d+2eT(d+2)κ+κT0ψ(t)2L2(B1)et(d+2)κdt.

    Now, an integration by parts gives

    1κT0F(ψ(t))et(d+2)κdt=1d+2T0ψ(t)F(ψ(t))et(d+2)κdt+F(ψ(0))d+2eT(d+2)κF(ψ(T))d+2,

    which concludes the proof.

    Let 0<λ1λ2λj be the eigenvalues (counted with multiplicity) of the spherical Laplace-Beltrami operator and {ϕj}j1 be the corresponding family of eigenfunctions, that is the solutions of

    ΔSd1ϕj=λjϕjonSd1,Sd1ϕ2j(θ)dθ=1. (2.12)

    Then, for any fixed i,jN, we have

    B1ϕiϕjdθ=δijandB1θϕiθϕjdθ=λiδij.

    It is well known that the eigenfunctions of the Spherical Laplacian on Sd1 are in fact the traces of homogeneous harmonic polynomials in Rd. In fact, for a given α0, it is immediate to check that a function ϕ:B1R is an eigenfunction corresponding to the eigenvalue

    λ(α):=α(α+d2),

    if and only if, its α-homogeneous extension φ(r,θ)=rαϕ(θ) is harmonic in B1. We will denote by αj the homogeneity corresponding to the eigenvalue λj, that is, we have

    λj=λ(αj)=αj(αj+d2). (2.13)

    Notice that, since the homogeneous harmonic functions in Rd are polynomials, we have that αjN. Thus, we can easily identify the eigenvalues and the eigenfunctions of the spherical Laplacian corresponding to the first few elements of the spectrum. Precisely, we have that :

    α1=λ1=0 and the corresponding eigenfunction is the constant ϕ1=|B1|1/2=(dωd)1/2.

    λ2==λd+1=d1, the corresponding homogeneity is α2==αd+1=1, while the eigenspace coincides with the (d-dimensional) space of linear functions in Rd.

    λd+2==λd(d+3)/2=2d, the corresponding homogeneity is αd+2==αd(d+3)/2=2; the corresponding eigenspace E2d is generated by the (restrictions to Sd1 of the) 2-homogeneous harmonic polynomials:

    E2d={QA:RdR:QA(x)=xAx, A symmetric with trA=0}.

    In particular, if QS is an admissible singular blow-up limit, then Q is of the form

    Q(x)=14d|x|2+QA(x)for some harmonic polynomialQAE2d.

    Finally, if j>d(d+3)2 (that is λj>2d), then the corresponding homogeneity is at least 3 and so

    λj3(3+d2)=3(d+1).

    Let c be as in Theorem 1. Throughout the rest of the paper we will use the same decomposition of the trace with the same notation. We will denote by QS the projection of c on the set of critical points S given in (1.1). Precisely, Q realizes the minimum

     dist2(c,S):=min{cQL2(B1) : QS}.

    We now decompose the function cQH1(B1) in Fourier series as

    c(θ)Q(θ)=j=1cjϕj(θ)

    where cj are the Fourier coefficients

    cj:=B1(c(θ)Q(θ))ϕj(θ)dθ. (2.14)

    Finally, we will write c:B1R as

    c=Q+η++η0+η, (2.15)

    where the functions η+, η0 and η (defined on B1) are given by

    η:=j:αj<2cjϕj ,η0:=j:αj=2cjϕjandη+:=j:αj>2cjϕj .

    In terms of the decomposition (2.15), 2-homogeneous extension of c(θ) can be written as:

    z(r,θ)=r2c(θ)=Q(rθ)+r2η(θ)+r2η0(θ)+r2η+(θ), (2.16)

    where we recall that QS is 2-homogeneous:

    Q(rθ)=r2Q(θ)for everyr>0andθB1.

    Notice that the functions η, η0 and η+ are orthogonal on the sphere in the sense that

    B1ηi(θ)ηj(θ)dθ=B1θηi(θ)θηj(θ)dθ=0wheneverij{+,,0}.

    Thus, by Lemma 2.1 and Corollary 2.3, we can compute the term in the right-hand side of the log-epiperimetric inequality in terms of η+, η0 and η.

    W(z)W(Q)=W0(zQ)=W0(r2η(θ))+W0(r2η0(θ))+W0(r2η+(θ)). (2.17)

    Let c=Q+η++η0+η be as in Section 2.4. Let M be the maximum of the negative part of η+η0+Q, that is,

    M:=maxθB1{η(θ)η0(θ)Q(θ)}. (3.1)

    We define the functions h2:B1R and hα:B1R as

    h2:=Q+η+η0+8dM(14dQ)andhα:=η+8dM(14dQ). (3.2)

    The role of the correction term 8dM(14dQ) will be explained in Section 7.1. In the lemma below we gather the key estimates, which we will use in both proofs of Theorem 1 – the one based on the direct construction of the competitor (Section 4) and the one based on the definition of a flow and a Łojasiewicz-type inequality (Section 5).

    Lemma 3.1 (Key Estimate). Let c, Q, η, η0, η+, M, h2 and hα be as above :

    c(θ)=Q(θ)+η(θ)+η0(θ)+η+(θ)=h2(θ)+hα(θ),θB1.

    Then, there is a dimensional constant δ>0 such that the following holds. If

    cQL2(B1)δ,

    then we have:

    (i) h2(θ)0  for every  θB1.

    (ii) there is a dimensional constant Cd>0 such that

    Md+1Cdη+2L2(B1) ; (3.3)

    (iii) for every tR, we have the following identities :

    hαF(h2+thα)=2tB1(|θη+|22dη2+)dθ, (3.4)
    F(h2+thα)=F(Q)+B1(|θη|22dη2)dθ+t2B1(|θη+|22dη2+)dθ, (3.5)

    where we recall that F and F are given by (2.3) and (2.8).

    Proof. We start by proving (i). Notice that there is a dimensional constant Cd such that

    ϕjL(B1)+θϕjL(B1)Cdfor everyjNsuch thatαj2d.

    Now, since by definition

    η(θ)+η0(θ)=j:αj2dcjϕj(θ),

    we can find another dimensional constant C>0 such that

    η+η0Lj:αj2d|cj|ϕjL(B1)C(j:αj2dc2j )1/2=Cη+η0L2(B1)CcQL2(B1),

    where we recall that

    cQL2(B1)=η+η0+η+L2(B1).

    We now choose δ>0 such that 4Cδ14d. We next show that h20 on each of the sets

    {θB1 : Q(θ)2Cδ}and{θB1 : Q(θ)2Cδ}.

    Indeed, we have the following two cases.

    ● Consider the set {Q2Cδ}B1. We first notice that

    η+η0+12Q0

    on this set. Indeed, for any θ{Q2Cδ}, we have

    η(θ)+η0(θ)+12Q(θ)η+η0L(B1)+12Q(θ)CcQL2(B1)+Cδ0.

    We now decompose h2 as follows :

    h2=(η+η0+12Q)+2M+Q(128dM),

    where the first and the second terms are nonnegative. In order to prove that also the third one is nonnegative, we notice that since Q0, we have

    Mη+η0L(B1)Cδ,

    so, by the choice of δ,

    128dM128dCδ=2d(14d4Cδ)0.

    This concludes the first part of the proof of (i).

    ● Consider the set {Q2Cδ}B1. We have that

    h2=η+η0+Q+8dM(14dQ)η+η0+Q+8dM(14d2Cδ)η+η0+Q+M0,

    where the last inequality is due to the choice (3.1) of M. This concludes the proof of (i).

    Next we prove (ii). We set for simplicity

    P:=η+η0+Q

    and we notice that P is a polynomial of degree two (a linear combination of eigenfunctions corresponding to eigenvalues 2d). We claim that there is a dimensional constant L such that PL(B1)L. Indeed, reasoning as in the proof of (i), we have that there is a dimensional constant Cd such that

    θη+θη0L(B1)j:αj2d|cj|θϕjL(B1)Cd(j:αj2dc2j )1/2=Cdη+η0L2(B1)CdcQL2(B1)Cdδ.

    On the other hand, by the definition of S (see (1.1)), Q is of the form

    Q(x)=xAxfor a nonnegative symmetric matrixAwithtrA=14.

    Thus, for the gradient of Q, we have

    QL=supx02|Ax||x|2 trA=12.

    In particular,

    θPL(B1)Cdδ+12.

    Now, since Q is non-negative and η+η0 is small, we have that the negative part inf{P,0} is also small. Precisely,

    M=inf{P,0}L(B1)η+η0L(B1)Cδ.

    Since the function inf{P,0}:B1R is L-Lipschitz and is small (in L(B1)), we can deduce that there is a dimensional constant Cd>0 such that

    inf{P,0}2L2(B1)CdMd1Ld1M2=CdLd+1inf{P,0}d+1L(B1)=CdLd+1Md+1,

    where the first inequality follows from Lemma 3.2. Indeed, let F:Rd1R be the function inf{P,0} written in local coordiantes around the point, where its maximum is achieved on the sphere. In this local chart, we can use Lemma 3.2 to estimate the integral of F2 over BR, where R:=1Linf{P,0}L. On the other hand, the trace c:B1R is non-negative :

    c(θ):=P(θ)+η+(θ)0for everyθB1.

    Thus, necessarily,

    inf{P,0}|η+|onB1,

    and so,

    CdLd+1Md+1inf{P,0}2L2(B1)η+2L2(B1),

    which (since L is a dimensional constant) gives (3.3).

    Finally we prove (iii). We start with computing F(h2). First, we notice that, since QS, it is a solution to the PDE

    F(Q)=2ΔB1Q4dQ+1=0. (3.6)

    As a consequence of (3.6) and the definition of η0, we have that both η0 and (14dQ) are eigenfunctions of the spherical Laplacian, corresponding to the eigenvalue 2d, that is,

    ΔB1η02dη0=ΔB1(14dQ)2d(14dQ)=0. (3.7)

    Thus, we have

    F(h2)=2ΔB1h24dh2+1=2ΔB1η4dη.

    Analogously, we compute F(hα). Indeed, we have

    F(hα)=2Δhα4dhα=2Δ(η+8dM(14dQ))4d(η+8dM(14dQ))=2Δη+4dη+

    where in the last equality we used again (3.7).

    In order to compute hαF(h2+thα), we first write hα in the form

    hα=η++˜η0where˜η0:=8dM(14dQ),

    and we notice that by (3.7), ˜η0 is a (2d)-eigenfunction of the spherical Laplacian. Using the definition of F (2.8) and the fact that F(Q)=0 (3.6), we compute

    hαF(h2+thα)=(η++˜η0)F(Q+η+η0˜η0+tη++t˜η0)=(η++˜η0)F(η+η0˜η0+tη++t˜η0)=(η++˜η0)[(2Δ4d)(η+η0˜η0+thα+t˜η0)+1].

    Now, since B1(η++˜η0)=0 and since both η0 and ˜η0 are (2d)-eigenfunctions, we get

    hαF(h2+thα)=(η++˜η0)(2Δ4d)(η+tη+).

    Next, notice that by the definition of η, η+ and ˜η0, they are orthogonal in L2(B1) and H1(B1):

    B1η+(θ)˜η0(θ)dθ=B1η(θ)˜η0(θ)dθ=B1η+(θ)η(θ)dθ=0,
    B1θη+θ˜η0dθ=B1θηθ˜η0dθ=B1θη+θηdθ=0.

    Thus, integrating by parts on B1, we obtain

    hαF(h2+thα)=2tB1(|θη+|22dη2+)dθ,

    as required. It remains to prove (3.5). Using (3.6), we compute

    F(h2+thα)F(Q)=F(Q+η+η0+tη++(t1)˜η0)F(Q)=B1|θ(η+η0+tη++(t1)˜η0)|2dθ2dB1(η+η0+tη++(t1)˜η0)2dθ=B1(|θη|22dη2)dθ+t2B1(|θη+|22dη2+)dθ,

    where the last equality follows from the orthogonality (in L2(B1) and H1(B1)) of η+, η and η0+(t1)˜η0, and from the fact that η0+(t1)˜η0 is an eigenfunction of the spherical Laplacian corresponding precisely to the eigenvalue 2d.

    Lemma 3.2. Suppose that n1 and that F:RnR is a function which is nonnegative a and L-Lipschitz continuous for some constant L>0. Let x0Rn and let M:=F(x0)>0. Then,

    BR(x0)F2(x)dx2ωn(n+1)(n+2)Mn+2Ln, (3.8)

    where ωn is the volume of the unit ball in Rn and R=M/L.

    Proof. First notice that the L-Lipschit continuity of F implies that

    F(x)ML|xx0|0for everyxBR(x0).

    Thus, integrating over BR(x0), we get that

    BR(x0)F2(x)dxBR(x0)(ML|xx0|)2dx.

    Integrating the right-hand side in polar coordiantes and using the definition of R, we obtain

    BR(x0)F2(x)dxnωnR0(M22LMr+L2r2)2dr=nωn(1nRnM22n+1LMRn+1+1n+2L2Rn+2),

    which is precisely (3.8).

    In this section we prove Theorem 1 by giving the competitor explicitly, as in Subsection 7.1.

    Proof of Theorem 1. We decompose the trace c:B1R as

    c=Q+η++η0+η ,

    as in Subsection 2.4 and we recall that the 2-homogeneous extension z is given by (2.17).

    Definition of the competitor. We define the competitor h:B1R as

    h(r,θ):=r2h2(θ)+rαhα(θ), (4.1)

    where α:=(2+ε)>2, the functions h2 and hα are given by (3.2) as in Section 3.

    Positivity of the competitor. We first notice that the competitor h defined in (4.1) is non-negative. Indeed, we can write the competitor h as

    h(r,θ)=r2h2(θ)+rαhα(θ)=(r2rα)h2(θ)+rαc(θ).

    Now, the first term (r2rα)h2(θ) is non-negative by Lemma 3.1 and the fact that r1; the second term rαc(θ) is non-negative since the trace c is non-negative by hypothesis.

    Decomposition of the energy. We first decompose the energy of z. We recall (2.17) and we set

    z(r,θ):=r2η(θ),z0(r,θ):=r2η0(θ)andz+(r,θ):=r2η+(θ).

    Since η, η0 and η+ are orthogonal, we have

    W(z)W(Q)=W0(zQ)=W0(z)+W0(z0)+W0(z+).

    We now estimate W0(z), W0(z0) and W0(z+). By (2.7) and (2.5), we have

    W0(z0)=0andW0(z)=j:αj<2c2jW0(r2ϕj(θ))=1d+2j:αj<2c2j(λj2d)0.

    On the other hand, for the higher modes, we have

    W0(z+)=j:αj>2c2jW0(r2ϕj(θ))=1d+2j:αj>2c2j(λj2d)13(d+2)j:αj>2c2j(λj+1)=13(d+2)η+2H1(B1)0, (4.2)

    where we used that, if αj>2, then αj3 and λj3(d+1).

    We now study W(h), where h is the competitor from (4.1). On the other hand, setting

    Q0:=8d(14dQ),

    we get

    W(h)W(Q)=W0(hQ)=W0(z)+W0(z0+(r2rα)MQ0)+W0(rαη+(θ))=W0(z)+W0(z0)+M2W0((r2rα)Q0)+W0(rαη+(θ)),

    where in the last equality we used that z0 is harmonic in B1 and (r2rα)Q0(θ) vanishes on B1. Using the fact that Q0 is a 2d-eigenfunction and Q0L2(B1)Cd, we calculate

    W0((r2rα)Q0)=10rd1drB1((2rαrα1)2Q20+(rrα1)2|θQ0|2)dθ=Q02L2(B1)10rd+1((2αrα2)2+2d(1rα2)2)dr=Q02L2(B1)(α2)2d+2α2Cd(α2)2=Cdε2.

    Putting together this estimate, (2.5) and (4.2), we get

    W0(hQ)W0(zQ)=W0(rαη+(θ))W0(r2η+(θ))+CdM2ε2εd+2W0(z+)+ε2η+2L2(B1)+CdM2ε2. (4.3)

    Conclusion of the proof. We are finally in position to prove (1.3). We first notice that by (4.3) and Lemma 3.1 (ii), we have

    W0(hQ)W0(zQ)εd+2W0(z+)+ε2η+2L2(B1)+Cdη+2d+1L2(B1)ε2.

    Recall that η+L2(B1)δ. Choosing δ1, we have

    W0(hQ)W0(zQ)εd+2W0(z+)+2Cdη+2d+1L2(B1)ε2εd+2W0(z+)+CdW0(z+)2d+1ε2,

    where in the last inequality we used (4.2). Finally, setting ε=CdW0(z+)d1d+1, for some dimensional constant Cd, and using the inequality W0(zQ)W+(z+), we get

    W0(hQ)W0(zQ)Cd(W0(zQ))2dd+1,

    which is precisely (1.3) (see Lemma 2.1).

    Let c be given by Theorem 1. We will use the general construction from Theorem A.1. In our case the homogeneity α is 2, the functional G is the Weiss' boundary adjusted energy W, F is given by (2.3), and the set S is (1.1). Thus, it only remains to define a flow ψ that satisfies the energy dissipation inequality (A.3) and the Łojasiewicz inequality (A.5).

    We write the trace c:B1R as

    c(θ)=h2(θ)+hα(θ),

    where h2 and hα are given by (3.2). We define the flow ψ as

    ψ(t)=h2+ethαfor everyt0.

    Below we verify that ψ satisfies the hypotheses of Proposition A.1.

    We first prove that the Łojasiewicz inequality (A.5) holds along the flow. Indeed, by (3.4), we have

    ψ(t)F(ψ(t))=ethαF(h2+ethα)=2e2tB1(|θη+|22dη2+)dθ.

    On the other hand, (3.5) implies that

    F(h2+ethα)F(S)=B1(|θη|22dη2)dθ+e2tB1(|θη+|22dη2+)dθ.

    Finally, since

    B1(|θη|22dη2)dθ0,

    we obtain the Łojasiewicz inequality (A.5) with constant CLS=1 and exponent β=0.

    In order to prove that (A.3) holds, we compute

    ψ(t)2L2(B1)=e2thα2L2(B1)=e2t(η+2L2(B1)+(8dM)2(14dQ)2L2(B1)),

    where we used the fact that 14dQ is an eigenfunction of the Spherical Laplacian corresponding to the eigenvalue 2d and so it is orthogonal to η+ in L2(B2). In conclusion, since QS and all the functions in S are bounded, we get that there is a dimensional constant Cd such that

    ψ(t)2L2(B1)e2t(η+2L2(B1)+CdM2)e2t(η+2L2(B1)+Cdη+4d+1L2(B1)),

    where the second inequality follows from (3.3). Now, since the Fourier decomposition of η+ contains only eigenfunctions corresponding to eigenvalues λj3(d+1)>2d, we get

    η+2L2(B1)B1(|θη+|22dη2+)dθ.

    Thus, we consider the following two cases :

    ● If η+L2(B1)1, then

    ψ(t)2L2(B1)e2t(η+2L2(B1)+Cdη+4d+1L2(B1))e2t(1+Cd)η+2L2(B1)e2t(1+Cd)B1(|θη+|22dη2+)dθ1+Cd2(ψ(t)F(ψ(t))). (5.1)

    ● Conversely, if η+L2(B1)1, then

    ψ(t)2L2(B1)e2t(η+2L2(B1)+Cdη+4d+1L2(B1))e2t(1+Cd)(η+2L2(B1))2d+1(1+Cd)(e2tB1(|θη+|22dη2+)dθ)2d+11+Cd22d+1(ψ(t)F(ψ(t)))2d+1. (5.2)

    Combining (5.1) and (5.2), we obtain (A.3) with a dimensional constant CED and an exponent p=d+1. This concludes our second proof of Theorem 1.

    In this section we review the proof of the log-epiperimetric inequality from [5] in terms of Theorem A.1. Let c:B1R be as Theorem 1. As in the previous section, we will apply Theorem A.1 with α=2, G=W, F as in (2.3), and S given by (1.1).

    As in [5], we define

    ψH1(]0,+[;L2(B1))L2(]0,+[;H2(B1)K)

    to be the strong solution of the following parabolic variational inequality (for the existence we refer to [1])

    {(ψ(t)+F(ψ(t)))(vψ(t))0,for everyvKandt>0,ψ(0)=c, (6.1)

    where K is the convex set

    K={vL2(B1) : v0onB1}.

    The energy dissipation inequality (A.3) is automaticaly satisfied along the flow with p=2. Precisely, we have

    ψ(t)2L2(B1)=ψ(t)F(ψ(t))for almost everyt>0. (6.2)

    Indeed, by taking the test function ψ:=u(t+h), for some t>0 and hR, we get

    0(ψ(t+h)ψ(t))(ψ(t)+F(ψ(t))),

    Dividing by h and taking the limits as h0+ and h0, we obtain the inequalities

    0limh0+1h(ψ(t+h)ψ(t))(ψ(t)+F(ψ(t)))=ψ(t)2L2(B1)+ψ(t)F(ψ(t)),0limh01h(ψ(t+h)ψ(t))(ψ(t)+F(ψ(t)))=ψ(t)2L2(B1)+ψ(t)F(ψ(t)),

    which give precisely (6.2).

    Now, in order to conclude the proof of the log-epiperimetric inequality (Theorem 1), it is sufficient to check that (A.5) holds along the flow. We fix t>0 and we reason precisely as in [5]. We decompose the function ψ(t) as

    ψ(t)=Q+η++η0+η ,

    exactly as in (2.15) with ψ(t) in place of c; moreover, we define h2 and hα as in (3.2), so we have

    ψ(t)=h2+hα .

    Now, by Lemma 3.1, we have that h2K. Thus, using (6.1), we can compute

    ψ(t)L2(B1)(h2ψ(t))ψ(t)h2ψ(t)L2(B1)(h2ψ(t))F(ψ(t))h2ψ(t)L2(B1),

    in order to estimate the right-hand side from below, we use Lemma 3.1.

    (h2ψ(t))F(ψ(t))h2ψ(t)L2(B1)=hαF(h2+hα)hαL2(B1)=2hαL2(B1)B1(|θη+|22dη2+)dθ2(η+2L2(B1)+CdM2)1/2B1(|θη+|22dη2+)dθ2(η+2L2(B1)+Cdη+4d+1L2(B1))1/2B1(|θη+|22dη2+)dθCdη+2d+1L2(B1)B1(|θη+|22dη2+)dθ ,

    where in the last inequality we used that

    η+L2(B1)dist2(ψ(t),S)1,

    which holds for every t[0,Tmax], by choosing Tmax small enough and ψ(0) close enough to S, as in Lemma 6 below. As a consequence, we get that

    ψ(t)F(ψ(t))=ψ(t)2L2(B1)Cdη+4d+1L2(B1)(B1(|θη+|22dη2+)dθ)2Cd(B1(|θη+|22dη2+)dθ)2dd+1Cd(F(ψ(t))F(S))2dd+1,

    where in the last inequality we used again Lemma 3.1. Finally, this implies (A.5) with γ=d1d+1. This concludes our third proof of Theorem 1.

    We notice that the estimates from Lemma 3.1 were crucial in the three proofs (section 4, 5 and 6). In the first two proofs it was immediate to notice that the trace satisfies the hypotheses of Lemma 3.1. In the case of the proof that we presented in this section, we can apply Lemma 3.1 because the flow ψ remains close to the critical set S. This follows by a standard argument that we sketch in the lemma below.

    Lemma 6.1. For every ε>0, there are constants δ>0 and T>0 such that the following holds. If ψ is a solution to (6.1) and is such that dist2(ψ(0),S)<δ, then

    dist2(ψ(t),S)<εfor everyt[0,T].

    Proof. Let QS be the projection of ψ(0) on S, with respect to the distance L2(B1). By definition Q is a critical point for F and Q0. Thus, using (6.1), we get

    tψ(t)Q2L2(B1)=2ψ(t)(Qψ(t))2(Qψ(t))F(ψ(t))=2(Qψ(t))F(Qψ(t))8dB1(Qψ(t))2dθ2B1(Qψ(t))dθ(8d+1)B1(Qψ(t))2dθ+Hd1(B1).

    Now, setting a=8d+1 and b=Hd1(B1) and applying the Gronwall inequality, we get that

    ψ(t)Q2L2(B1)ba(eat1)+eatψ(0)Q2L2(B1),

    which gives the claim.

    In this section we sketch the main ideas behind the proof of the log-epiperimetric inequality for the obstacle problem (Theorem 1) and that led us to the two constructions from [3,4,5], Section 4 and Section 5.

    The log-epiperimetric inequality. We recall that given a 2-homogeneous function z:B1R, in polar coordinates z(r,θ)=r2c(θ), our aim is to construct a competitor h:B1R such that h=z on B1 and

    W(h)W(S)W(z)W(S)ε|W(z)W(S)|1+γ, (7.1)

    which can also be written as

    W(h)W(z)ε|W(z)W(S)|1+γ, (7.2)

    where ε>0, γ[0,1), S is the set of singular 2-homogeneous solutions to the obstacle problem and where we use the notation (recall that W is constant on S) :

    W(S):=W(Q)for everyQS.

    In this subsection we present the main ideas that led to the construction of the competitors in [3] and in Section 4, and also in [4], the latter in the context of the thin-obstacle problem.

    We notice that if the function h is such that the log-epiperimetric inequality (7.1) holds, then it must have a lower energy than the 2-homogeneous function z, so we start by analyzing the energy W(z). We decompose the trace c as

    c=Q+η+η0+η+,

    where QS, η0 contains only lower modes, η0 is a (2d)-eigenfunction of the spherical Laplacian and the Fourier expansion of η+ contains only eigenfunctions corresponding to eigenvalues higher than 2d. Then, we recall that

    W(z)W(Q)=W0(r2η(θ))+W0(r2η0(θ))+W0(r2η+(θ)).

    We next examine the different terms in the right-hand side of the above identity. By Lemma (2), we have :

    η gives a negative contribution to the energy :

    W0(r2η(θ))0,the inequality being strict ifη0 ;

    ● the energy of η0 is zero: W0(r2η0(θ))=0;

    ● the energy of η+ is positive:

    W0(r2η+(θ))0,the inequality being strict ifη+0.

    In particular, this means that, in order to build a competitor h with lower energy than z, we have to act on the term containing the higher modes

    W0(r2η+(θ))=B1|(r2η+(θ))|dx2B1η2+dθ.

    Since we are looking for a competitor that coincides with z on B1, we cannot expect a contribution from the second (boundary) term of W0(r2η+(θ)). Thus, in order to decrease the energy, one has to act on the first term, which is the Dirichlet energy of r2η+(θ). Of course, the best way to decrease the Dirichlet energy is to replace r2η+ by the harmonic extension of η+ in B1. Since the harmonic extension can be explicitly written in Fourier series, we get that the competitor has the form

    f(r,θ)=Q(rθ)+r2η(θ)+r2η0(θ)+j:αj>2cjr2+εjϕj(θ), (7.3)

    where the coefficients cj are given by (2.14) and αj are the corresponding homogeneities, related too the eigenvalues λj of ϕj through the formula (2.13). We also notice that εj>0, for every j. In fact, since we take

    j:αj>2cjr2+εjϕj(θ)

    to be precisely the harmonic extension of η+, we have that εj=αj21.

    We can compute the energy W(f) by using Lemma 2.1 and Corollary 2.3

    W(f)W(Q)=W0(fQ)=W0(r2η(θ))+W0(r2η0(θ))+j:αj>2c2jW0(r2+εjϕj(θ)).

    Now, using the Fourier expansion of η+ and Corollary 2.3, we have

    W0(r2η+(θ))=j:αj>2c2jW0(r2ϕj(θ)), (7.4)

    so, the energy gain is given by:

    W(f)W(z)=j:αj>2c2j(W0(r2+εjϕj(θ))W0(r2ϕj(θ))). (7.5)

    In order to estimate W(f)W(z), we compute each of the terms in the right-hand side of (7.5). We use the fact that ϕj is an eigenfunction :

    B1|θϕj|2dθ=λjB1ϕ2jdθ=λj,

    and we apply the identity (2.5) from the Slicing Lemma 2.2

    W0(r2+εjϕj(θ))W0(r2ϕj(θ))=λj2dd+2+2εj+ε2jd+2+2εjλj2dd+2=εj2(λj2d)(d+2)(d+2+2εj)+ε2jd+2+2εj.

    Now, a direct computation gives that if we replace εj=αj2 and λj=αj(αj+d2), we get

    W0(r2+εjϕj(θ))W0(r2ϕj(θ))=ε2jd+2+2εj(2(d+2+εj)d+2+1)=ε2jd+2=ε2j(2+εj)(d+εj)λj2dd+213(d+1)λj2dd+2=13(d+1)W0(r2ϕj(θ)).

    We now notice that the above estimate implies (7.2) in its strongest form (with γ=0): this inequality is known as epiperimetric inequality. Indeed, as a consequence of the above estimate, (7.4) and (7.5), we have

    W(f)W(z)13(d+1)j:αj>2c2jW0(r2ϕj(θ))=13(d+1)W0(r2η+(θ)).

    Now, since the energy of z is given by

    W(z)W(Q)=W0(r2η(θ))+W0(r2η+(θ))W0(r2η+(θ)), (7.6)

    we get the following estimate (called epiperimetric inequality)

    W(f)W(z)13(d+1)(W(z)W(Q)), (7.7)

    which is precisely (7.2) with γ=0, which is also the best possible exponent that we can expect.

    Unfortunately, the function f cannot be used as a competitor in Theorem 1 as it might not fulfill the requirement that

     the competitor should be non-negative.

    In fact, by taking the harmonic extension of η+ (which might change sign on B1) we lose any information on the sign of f as each of the terms cjϕj(θ) of the Fourier expansion of η+ is multiplied by a different homogeneity rαj.

     Thus, the challenge is to find a competitor that at the same time remains positive and decreases the energy.

    We now try to modify the function f from (7.3) in order to have some more control on its sign, but we also try to keep the energy gain provided by the 'harmonic' competitor f. The starting point is the following observation.

    Claim.  In (7.3) we can take all exponents εj to be the sameand still have the epiperimetric inequality (7.7).

    Precisely, taking in (7.3) εj=ε, for every j, we consider the new competitor

    ˜f(r,θ)=Q(rθ)+r2η(θ)+r2η0(θ)+r2+εη+(θ). (7.8)

    By using the computations that we already performed in the estimate of W(f)W(z), we can compute

    W(˜f)W(z)=j:αj>2c2j(W0(r2+εϕj(θ))W0(r2ϕj(θ)))=j:αj>2c2j(2ε(λj2d)(d+2)(d+2+2ε)+ε2d+2+2ε).

    Now, for ε small enough the first (negative) term of the right-hand side wins against the second (positive) one. Thus, choosing ε small enough and isolating a dimensional constant Cd, we get

    W(˜f)W(z)εCdj:αj>2c2jλj2dd+2=εCdW0(r2η+(θ)),

    which implies (after (7.6)) that the epiperimetric inequality holds for ˜f :

    W(˜f)W(z)εCd(W(z)W(Q)).

    Unfortunately, we still cannot prove that ˜f is non-negative. For instance, what can go wrong is that, for some θB1, we have

    Q(θ)+η(θ)+η0(θ)<0andη+(θ)>(Q(θ)+η(θ)+η0(θ)).

    In this way the trace

    c(θ)=Q(θ)+η(θ)+η0(θ)+η+(θ)

    is non-negative, but the competitor ˜f(r,θ) becomes negative when r is small enough.

    In this section, we finally discuss the idea behind the direct constructions from [3,4], and Section 4. Precisely, in order to build a nonnegative competitor, we add a correction term H:B1R such that

    Q(θ)+η(θ)+η0(θ)+H(θ)0for everyθB1, (7.9)

    and we consider the competitor

    h(r,θ)=r2(Q(θ)+η(θ)+η0(θ)+H(θ))+r2+ε(η+(θ)H(θ)).

    Since, by hypothesis the trace c=Q+η+η0+η+ is non-negative, we get that

    (Q+η+η0+H)+(η+H)0,

    but (together with (7.9)) this implies that h(r,θ)0 for every r>0.

    Notice that, if we want the condition (7.9) to be fulfilled, we need H to be large enough in order to compensate the negative part of Q+η+η0. On the other hand, H increases the energy. In fact, we can re-write the competitor h as

    h(r,θ)=˜f(r,θ)+(r2r2+ε)H(θ).

    Since ˜f is qualitatively the best possible choice for the energy (recall that ˜f is as good as the harmonic extension f), the function h will have bigger energy, which, of course, depends on the error introduced by the correction term (r2r2+ε)H(θ); finally, this means that in order to keep the energy of h as small as possible, we need H to be small.

     This competition between the constraint and the energy is precisely what makes appear the exponent γ in the log-epiperimetric inequality. 

    Following the construction presented here, one can build many different competitors. For instance, in [3], we use a function H that depends on all the lower modes (including the linear ones) of the trace c. In Section 4 we propose a different function H, which is (2d)-eigenfunction on the sphere; this leads to a shorter proof, but the exponent γ we get is not optimal.

    This section is dedicated to the constructive approach from [5] and Section 5. It is based on the idea that any function h:B1R can be seen as a family of functions (a flow) h(r,):B1R parametrized over the radial coordinate r(0,1]. This way to see the competitor was first used in the context of the one-phase Bernoulli problem, in [16] and later in [6], where the competitor is not explicit, but is constructed starting from a solution of an evolution problem. Recently, in [5] we applied this idea to the case of the obstacle and the thin-obstacle problems. In Section 5, we used a general result (that we prove in the Appendix) and we construct a new flow, which simulates the behavior of the gradient flow from [5], but is also closely related to the explicit competitor from Section 5. As in the previous Section 7.1, we proceed by dividing the exposition in several paragraphs, each one representing a different step of the construction.

    The starting point is the slicing lemma (Lemma 2.2) which allows to write down the energy of the competitor h(r,θ) as an integral over the different spheres (slices) Br, r(0,1]. Precisely, one can compute that (see Lemma 2.2) if h is of the form

    h(r,θ)=r2u(r,θ),

    then its energy W(h) is given by

    W(h)=W(r2u)=10F(u(r,))rd+1dr+10rd+3B1|ru|2dHd1dr, (7.10)

    where F is a functional acting on H1(B1).

    Thus, we will search for a competitor of the form h(r,θ)=r2u(r,θ), where u can be read as a one-parameter family of functions

    u(r,):B1R,r(0,1].

    In this framework, the 2-homogeneous extension z, given in polar coordinates by

    z(r,θ)=r2c(θ),

    corresponds to the case in which the flow ru(r,)H1(B1) is constant in r. In this case, the second term in the right-hand side of (7.10) is zero and so we get

    W(z)=10F(c)rd+1dr=1d+2F(c).

    As a consequence, the log-epiperimetric inequality (7.1), for h(r,θ)=r2u(r,θ) and the 2-homogeneous extension z(r,θ)=r2c(θ), can be written in terms of the new functional F as:

    10(F(u(r,))F(c))rd+1dr+10rd+3B1|ru|2dHd1drε(F(c)F(S))1+γ, (7.11)

    where F(S):=(d+2)W(S). Thus, in order to find a function u for which (7.11) holds, we have to search for a function u:(0,1]×B1R, which in particular satisfies

    u(1,θ)=c(θ)forθB1andF(u(r,))F(c)forr1,

    but we also have to take into account the cost of modifying u from one scale to another, which is given by the error term

    10rd+3B1|ru|2dHd1dr.

    Now, since we will work with flows, it is convenient to consider functions of the form φ:[0,+)H1(B1) and to define the competitor u as

    u(r,θ)=φ(κlnr,θ)forr(0,1]andθB1.

    Thus, we have that

    φ(0,)=c()onB1,

    and the energy of the competitor

    h(r,θ)=r2φ(κlnr,θ),

    can be written as (see Lemma 3)

    W(h)=F(φ(0))d+2++0(1d+2φ(t)F(φ(t))+κφ(t)2L2(B1))et(d+2)κdt,

    or, alternatively, as

    W(h)=F(φ(0))d+2+1κ0(F(φ(t))F(φ(0)))et(d+2)κdt+κ0φ(t)2L2(B1)et(d+2)κdt.

    The last expression of the energy W(h) suggests that, in order to construct a competitor with lower energy, we have to act on the term F(φ(t)). A natural way to do so, is to choose φ=ψ, where ψ is the gradient flow of F

    {ψ(t)=F(ψ(t))fort(0,+),ψ(0)=c. (7.12)

    The basic idea behind any of the constructions we propose is, given a homogeneous function z:B1R, to build a competitor that simulates the behavior of the solution (in our case, the solution of the obstacle problem) with the same values as z on B1. Now, for the obstacle problem, it is well known that if h(r,θ)=r2u(r,θ) is precisely the solution of the obstacle problem, then the energy F(u(r,)) remains positive for every r>0 (this is a consequence of the Weiss' monotonicity formula [17]). Thus, we do not expect to find a good competitor with negative energy. So, instead of taking φ to be precisely the gradient flow ψ, we stop ψ at a certain time T. The choice of the stopping time is fundamental step in the epiperimetric inequality and will be chosen in function of the energy F(ψ(T)).

    We define the flow φ(t,θ) as

    φ(t):=ψ(t)ift[0,T],φ(t):=ψ(T)iftT,

    and teh competitor h as

    h(r,θ)=r2φ(κlnr,θ),

    where κ and T will be chosen below.

    Again, the energy of the competitor u can be expressed in two different ways (we refer to Lemma 3 for the computation):

    W(h)W(z)=T0(1d+2ψ(t)F(ψ(t))+κF(ψ(t))2L2(B1))et(d+2)κdt, (7.13)

    where we recall that W(z)=1d+2F(ψ(0)), and

    W(h)W(z)=1κT0(F(ψ(t))F(ψ(0)))et(d+2)κdt+1d+2(F(ψ(T))F(ψ(0)))eT(d+2)κ+κT0ψ(t)2L2(B1)et(d+2)κdt. (7.14)

    Moreover, we notice that, by summing up (7.13) and (7.14), we obtain

    W(h)W(z)=12(d+2)T0ψ(t)F(ψ(t))et(d+2)κdt+12κT0(F(ψ(t))F(ψ(0)))et(d+2)κdt+12(d+2)(F(ψ(T))F(ψ(0)))eT(d+2)κ+κT0ψ(t)2L2(B1)et(d+2)κdt.

    First, notice that the second term in the right-hand side of the above identity is negative. This is due to the fact that the energy F is decreasing along the flow ψ(t). Thus, we get

    W(r2u)W(z)12(d+2)T0ψ(t)F(ψ(t))et(d+2)κdt (7.15)
    +12(d+2)(F(ψ(T))F(ψ(0)))eT(d+2)κ (7.16)
    +κT0ψ(t)2L2(B1)et(d+2)κdt. (7.17)

    Now since for the gradient flow ψ we have the identities

    tF(ψ(t))=ψ(t)F(ψ(t))=F(ψ(t))2L2(B1)=ψ(t)2L2(B1), (7.18)

    the terms (7.15) and (7.16) are negative. Thus, we start by estimating the third term (7.17).

    Using again (7.18), we get that (7.17) can be absorbed in (7.15). Indeed, by choosing κ small enough, for instance,

    κ=14(d+2),

    we obtain

    W(h)W(z)14(d+2)T0ψ(t)F(ψ(t))et(d+2)κdt (7.19)
    +12(d+2)(F(ψ(T))F(ψ(0)))eT(d+2)κ. (7.20)

    Now, both terms (7.19) and (7.20) are negative.

    Let T1/2 be defined as

    T1/2=sup{τ : F(ψ(t))F(S)12(F(ψ(0))F(S))for everyt[0,τ]}.

    We consider two cases.

    Case 1. The energy decreases rapidly along the flow: T1/21. In this case, we choose T=T1/2 and we compute

    W(h)W(z)eT(d+2)κ2(d+2)(F(ψ(T))F(ψ(0)))ed+2κ2(d+2)(F(ψ(T))F(ψ(0)))=ed+2κ2(d+2)((F(ψ(T))F(S))(F(ψ(0))F(S)))=12ed+2κ2(d+2)(F(ψ(0))F(S)),

    which concludes the proof of the log-epiperimetric inequality (7.1) (equivalently (7.11)) in this first case, in which we get (7.1) with the best possible exponent γ=0.

    Case 2. The energy decreases slowly along the flow: T1/21. In this case, we choose T=1 and the energy gain comes from the term (7.19). Indeed,

    W(h)W(z)T0ψ(t)F(ψ(t))et(d+2)κdt=T0F(ψ(t))2L2(B1)et(d+2)κdt.

    In this second case, the proof of (7.11) is more involved and is based on the so-called Łojasiewicz inequality.

    In order to conclude the proof of (7.11) also in the second case, we need to estimate F(ψ(t)) from below in terms of the energy (F(ψ(t))F(S)). Precisely, we need an inequality of the form

    CLS(F(ϕ)F(S))1+βF(ϕ)2for everyϕsuch thatF(ϕ)F(S), (7.21)

    where CLS>0 and 0β<1. The above estimate is called Łojasiewicz inequality and is well-known in the case when F is an analytic function on a finite dimensional space; we refer to [5] for a more detailed discussion on the Łojasiewicz inequality and its different versions and applications. Now, using this estimate and the choice of the stopping time T=1T1/2 and κ=14(d+2), we can estimate (7.19) as follows:

    T0F(ψ(t))2L2(B1)et(d+2)κdtCLST0(F(φ(t))F(S))1+βet(d+2)κdtCLS21+γT0(F(φ(0))F(S))1+βet(d+2)κdtCLSκ(d+2)21+β(1eT(d+2)κ)(F(φ(0))F(S))1+β=CdCLS(F(φ(0))F(S))1+β,

    where Cd is a dimensional constant. This concludes the proof of the log-epiperimetric inequality (7.11) in the second case; the exponent γ=β is precisely the one from the Łojasiewicz inequality.

    Up to this point, we have proved that the competitor h from Section 7.2.7 satisfies the log-epiperimetric inequality provided that the Łojasiewicz inequality (7.25) holds along the flow. For what concerns the functional F the Łojasiewicz inequality holds and is relatively easy to prove (see for instance the Introduction of [5]). On the other hand, in order to conclude that h is an admissible competitor in Theorem 1, we must have that h is non-negative, or in terms of the flow ψ, that ψ(t) is non-negative on B1, for every t[0,T]. Unfortunately, we cannot assure that, for any ψ(0)=c, the flow remains positive. Thus, in [5], we propose a different construction.

    In [5], we construct the competitor h from Subsection 7.2.7 starting from a flow ψ, which is the gradient flow of F constrained to remain in the (convex) space K of nonnegative functions defined on B1. This constrained flow, is of course different with respect to the original gradient flow as the decay of the energy F may become much slower when the flow hits the boundary of the constraint K, but still, this flow has several properties, that make it very similar to the (unconstrained) gradient flow of F. In particular, we can repeat precisely the same construction presented above: the equalities (7.13) and (7.14) are general and hold for any function ψ:[0,+)H1(B1), while the identities (7.18) should be replaced by

    ψ(t)F(ψ(t))=F(ψ(t))2K=ψ(t)2L2(B1). (7.22)

    Thus, the proof of the epiperimetric inequality is precisely the same, with the only difference that the norm of F is replaced by

    F(ϕ)K=sup{0,supvK{ϕ}{(vϕ)F(ϕ)vϕL2(B1)}}, (7.23)

    for any nonnegative ϕH2(B1). Now, the positivity constraint for this flow is automatically satisfied, so the main challenge is to prove an estimate that can replace the Łojasiewicz inequality (7.25). Indeed, in order to complete the proof, in [5], we prove the following stronger version of (7.25), that we called constrained Łojasiewicz inequality :

    C\sc cls(F(ϕ)F(S))1+βF(ϕ)2K . (7.24)

    The proof is based on the choice of a suitable test direction ϕ in (7.23), that turns out to be precisely the function h2 from (7.9).

    In Theorem A.1 of the Appendix, we make a more general construction of a competitor h starting from a flow ψ:[0,+)H1(B1) that satisfies the following conditions :

    (ⅰ) for any t0, the function ψ(t) remains nonnegative along the flow; this assures that the final competitor is admissible;

    (ⅱ) the following inequality holds :

    ψ(t)F(ψ(t))ψ(t)2L2(B1)for everyt>0 ;

    this guarantees that the energy F(ψ(t)) is decreasing in t and that the error term (7.17) can be absorbed by the energy gain (7.15);

    (ⅲ) the following Łojasiewicz-type inequality (which replaces (7.25)) hold

    C\sc lst(F(ψ(t))F(S))1+βψ(t)F(ψ(t)) , (7.25)

    for every t>0 such that ψ(t)0.

    This abstract result can be used also in other contexts (for instance, in can be applied to the thin-obstacle problem). In Section 4 we apply Theorem A.1 to a specific flow, for which the derivative ψ(t) does not depend on t and we choose the direction ψ to be precisely the one from (7.9); thus, recovering the competitor from Section 4.

    L. S. has been partially supported by the NSF grant DMS 1810645. B. V. has been supported by the European Research Council (ERC) under the European Union's Horizon 2020 research and innovation programme (grant agreement VAREG, No. 853404).

    The authors declare no conflict of interest.

    In this section we give a general procedure that reduces the construction of a competitor for the log-epiperimetric inequality to the construction of a flow that satisfies two key hypotheses: an energy dissipation estimate and a Łojasiewicz inequality. Our construction applies not only to the specific case of the obstacle problem, but can be used to prove log-epiperimetric inequalities for any functional that satisfies suitable homogeneity properties. In particular, it can be used in the context of to the thin-obstacle problem and, more generally, to the obstacle problem for the s-Laplacian. Our main result is Theorem A.1. Before stating it, we introduce some notation and we list the main assumptions that we make.

    Homogeneity. We fix a positive real constant α>0; in the case of the obstacle problem (that is, in Theorem 1) α is equal to 2.

    Energy. We consider two functionals

    G:H1(B1)RandF:H1(B1)R ,

    with the following properties.

    F is differentiable. Precisely, there is a functional F:H2(B1)L2(B1) such that

    F(u+v)=F(u)+vF(u)+o(vH1(B1)),

    for every uH2(B1) and every vH1(B1).

    G and F are related through a slicing identity. Precisely, we assume that there is a constant CLS>0 such that, for any function u=u(r,θ)H1([0,1]×B1), we have

    G(rαu(r,θ))10F(u(r,))r2α+d3dr+CLS10B1|ru|2r2α+d1dHd1dr, (A.1)

    with equality if u is constant in the r variable. In this case, we have

    G(rαu(θ))=10F(u)r2α+d3dr=12α+d2F(u). (A.2)

    Critical set. We suppose that there is a compact set SH2(B1) such that:

    S is a set of critical points for F, that is :

    F(Q)=0for everyQS.

    F is constant on S; and we denote this constant by F(S):

    F(Q)=F(S)for everyQS.

    Flow. We suppose to be given a constant Tmax>0 and a function ψ:[0,Tmax]H2(B1) such that

    ψL2([0,Tmax];H2(B1))H1((0,Tmax);L2(B1)),
    orψL2([0,Tmax];H1(B1))H1((0,Tmax);H1(B1)).

    In both cases the energy F(ψ(t)) is well-defined and (weakly) differentiable in t. Precisely,

    ddtF(ψ(t))=ψ(t)F(ψ(t))for everyt(0,Tmax),

    and the map

    (0,Tmax)tψ(t)F(ψ(t))R

    is integrable, where the dot indicates the scalar product in L2(B1), or the pairing between H1(B1) and its dual space. Moreover, we assume that the flow and the energy F satisfy the following properties.

    Energy dissipation inequality. There are constants CED>0 and p2 such that the following inequality holds

    CEDmin{ψ(t)2L2(B1),ψ(t)pL2(B1)}ψ(t)F(ψ(t)), (A.3)

    for almost every t0. In particular, the energy is non-increasing along the flow :

    F(ψ(t))F(ψ(s))=tsψ(τ)F(ψ(τ))dτ0for every0st. (A.4)

    Łojasiewicz inequality. There are constants C\tiny\sc ls>0 and β[0,1) such that F satisfies the following inequality along the flow

    C\tiny\sc ls(F(ψ(t))F(S))1+βψ(t)F(ψ(t))for almost everyt>0. (A.5)

    Theorem A.1. Suppose that the functionals G and F, and the flow ψ satisfy the hypotheses above. Moreover, we assume that the exponents β[0,1) and p2, from (A.3) and (A.5) respectively, are such that

    (1+β)(11p)<1.

    Then, there are constants δ0>0, E>0, γ[0,1) and ε>0, depending on d, α, p, β, Tmax, CSL, CLS and CED, such that the following holds. If cH1(B1) satisfies

    c=ψ(0)andF(c)F(S)E,

    then there exists a function h=h(r,θ)H1(B1) satisfying h(1,)=c() on B1, and

    G(h)G(S)(1ε|G(z)G(S)|γ)(G(z)G(S)) (A.6)

    where γ=(1+β)(22p)1, and where we used the notations

    z(r,θ):=rαc(θ)andG(S):=12α+d2F(S).

    Remark A.2 (The two extremal cases). When p=2 and β>0, Theorem A.1 corresponds precisely to [5, Proposition 3.1]. On the other hand, in Section 5, we apply Theorem A.1 to a flow for which p>2 and β=0.

    Remark A.3 (About a missing hypothesis). In the proposition above there is one hypothesis less with respect to [5, Proposition 3.1] and Theorem 1, where it is also required that the trace c is L2(B1)-close to the set S of critical points. This closeness condition is hidden in the hypotheses that the energy dissipation and the Łojasiewicz inequalities (A.3) and (A.5) hold for every t along the flow ψ. In fact, in Section 5, in order to prove (A.3) and (A.5) are satisfied for our specific choice of the flow, we use the closeness condition, which was essential in the proof of the key estimates in Section 3; similarly, in [5, Proposition 3.1], we used that the trace c lies close to S in the proof of the Łojasiewicz inequality.

    Remark A.4 (About G(S)). Let QS. Then, G(S) is precisely the energy G(rαQ(θ)) of the α-homogeneous extension rαQ(θ) of Q.

    Proof of Theorem A.1. First, notice that if G(z)G(S)0, then choosing h=z we immediately get A.6. Throughout the rest of the proof we will assume that

    0<G(z)G(S)=12α+d2(F(c)F(S)).

    We define the competitor h as

    h(r,θ)=rαu(r,θ),

    where, as in Section 7.2,

    u(r,θ)=φ(κlnr,θ)forr(0,1]andθB1,

    for some κ>0, and φ is the stopped flow

    φ(t):=ψ(t)ift[0,T],φ(t):=ψ(T)iftT,

    where the stopping time T will be chosen later.

    We will divide the rest of the proof in several steps. Before we proceed, we notice that the log-epiperimetric inequality for G A.6 is equivalent to:

    G(h)G(z)ε(G(z)G(S))1+γ, (A.7)

    where the right-hand side of the above inequality can also be written as

    ε(G(z)G(S))1+γ=ε(2α+d2)1+γ(F(c)F(S))1+γ.

    We start with estimating from above the energy gap G(h)G(z) in terms of the flow ψ.

    Estimating the energy gap. We first give the energy G(h) in terms of the flow ψ and the variable t. Using (A.1) and reasoning as in Lemma 2.4, we have

    G(rαu(r,θ))10F(u(r,))r2α+d3dr+CSL10B1|ru|2r2α+d1dHd1dr=10F(φ(κlnr))r2α+d3dr+CSL10κ2r2α+d3φ(κlnr)2L2(B1)dr=1κ+0F(φ(t))e(2α+d2)tκdt+κCSL+0φ(t)2L2(B1)e(2α+d2)tκdt. (A.8)

    In particular, this implies that

    G(rαu(r,θ))G(rαc(θ))1κT0(F(ψ(t))F(ψ(0)))e(2α+d2)tκdt+1d+2α2(F(ψ(T))F(ψ(0)))e(2α+d2)tκ+κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdt. (A.9)

    Moreover, integrating by parts the first term on the right-hand side, we get

    G(rαu(r,θ))G(rαc(θ))1d+2α2T0ψ(t)F(ψ(t))e(2α+d2)tκdt+κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdt. (A.10)

    Recall that by (A.4), the energy is decreasing along the flow. Thus, the first term in the right-hand side of (A.9) is negative (thus we simply estimate it from above by zero). Finally, multiplying (A.9) and (A.10) by 1/2 and summing them, we obtain the following estimate

    G(rαu(r,θ))G(rαc(θ))12(d+2α2)e(2α+d2)Tκ(F(ψ(T))F(ψ(0)))+12(d+2α2)T0ψ(t)F(ψ(t))e(2α+d2)tκdt+κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdt. (A.11)

    We notice that, up to this point, we used only (A.1) and (A.2), and an integration by parts.

    Estimating the error term. We now estimate the last term in the right-hand side of (A.11), which is also the only positive one. We notice that the energy dissipation condition (A.3) is equivalent to the following :

    ψ(t)2L2(B1)C1[ψ(t)F(ψ(t))]+C2[ψ(t)F(ψ(t))]2/p, (A.12)

    for some positive constant C1 and C2. As a consequence, we can estimate

    κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdtκCSLC1T0(ψ(t)F(ψ(t)))e(2α+d2)tκdt+κCSLC2T0(ψ(t)F(ψ(t)))2/pe(2α+d2)tκdt.

    Now, the first term on the right hand side can be absorbed into the first term of (A.11) by choosing κ small enough, in function of the constants involved. In order to estimate the second term, we use the Hölder inequality :

    T0(ψ(t)F(ψ(t)))2/pe(2α+d2)tκdt(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)2/p(T0e(2α+d2)tκdt)12/p(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)2/p(κ2α+d2(1e(2α+d2)Tκ))12/p(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)2/p(κ2α+d2)12/p.

    In conclusion, we obtain

    κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdtCκ22/p(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)2/p+CκT0ψ(t)F(ψ(t))e(2α+d2)tκdt, (A.13)

    where C is a constant depending on d,α,p,CSL and CED.

    Stopping time. Recall that, by hypothesis, the flow ψ is defined on the interval [0,Tmax]. We define T1/2 as

    T1/2=sup{s[0,Tmax] : F(ψ(t))F(S)12(F(ψ(0))F(S))for everyt[0,s]},

    and we consider two cases. Below, we will choose the stopping time T such that

    0TT1/2.

    Choice of κ. We choose

    κ=εκ(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)p22p2, (A.14)

    where εκ>0 is a small constant, depending on d,α,p,CSL and CED, such that

    εκ1 ,εκC11012(2α+d2)andεkTmax. (A.15)

    We notice that by the choice TT1/2, we have that:

    T0ψ(t)F(ψ(t))e(2α+d2)tκdtT0ψ(t)F(ψ(t))dt=F(ψ(0))F(ψ(T))F(ψ(0))F(S)E,

    which gives that

    κεκEp22p2εκ,

    where the last inequality holds when E1.

    Now, notice that the last term of the right-hand side of (A.11) can be estimated as follows :

    κCSLT0ψ(t)2L2(B1)e(2α+d2)tκdt2CεkT0ψ(t)F(ψ(t))e(2α+d2)tκdt14(2α+d2)T0ψ(t)F(ψ(t))e(2α+d2)tκdt, (A.16)

    where the first inequality follows by the first inequality for εk in (A.15) and the second one is a consequence of the second bound for εk in (A.15). This is the estimate in which we use the first two inequalities in the choice of the constant εκ. The last inequality of (A.15) is only needed for the bound

    κTmax,

    which we will use in the two possible choices of T that we discuss below. Before we proceed with the choice of T, we notice that by combining the inequalities (A.16) and (A.11), we can eliminate the last term in the right-hand side of (A.11). Precisely, the energy gap G(rαu)G(z) can be estimated as follows:

    G(rαu(r,θ))G(rαc(θ))12(d+2α2)e(2α+d2)Tκ(F(ψ(T))F(ψ(0)))+14(d+2α2)T0ψ(t)F(ψ(t))e(2α+d2)tκdt. (A.17)

    Choice of the stopping time. We now proceed with the choice of T, which is the last point of the construction of the competitor. As in Subsection 7.2, we consider two cases.

    Case 1. The energy decreases rapidly along the flow: T1/2κ.

    In this case, we choose T=T1/2 and we estimate the first term in the right-hand side of (A.17). Indeed, since Tκ1 and since the function xex is increasing in x, we have :

    eT(2α+d2)κ2(2α+d2)(F(ψ(0))F(ψ(T)))e(2α+d2)2(2α+d2)(F(ψ(0))F(ψ(T)))=12e(2α+d2)2(2α+d2)(F(ψ(0))F(S)),

    which concludes the proof of (A.6) in this case.

    Case 2. The energy decreases slowly along the flow: κT1/2.

    In this case, we choose T=κ and we estimate the second term in the right-hand side of (A.17). By the Łojasiewicz inequality (A.5), we have

    T0ψ(t)F(ψ(t))et(2α+d2)κdtCLST0(F(ψ(t))F(Q))1+βet(2α+d2)κdtCLS21+γT0(F(ψ(0))F(Q))1+βet(2α+d2)κdt=CLSκ(2α+d2)21+β(1eT(2α+d2)κ)(F(ψ(0))F(Q))1+γ=CLS(1e(2α+d2))(2α+d2)21+βκ(F(ψ(0))F(Q))1+β,

    where the second inequality follows from the fact that

    F(φ(t))F(Q)12(F(φ(0))F(Q))for everytT=κT1/2.

    Now, setting

    C=εkCLS(1e(2α+d2))(2α+d2)21+β

    and using the definition of κ, we get that

    T0ψ(t)F(ψ(t))et(2α+d2)κdtC(T0ψ(t)F(ψ(t))e(2α+d2)tκdt)p22p2(F(ψ(0))F(Q))1+β,

    which implies

    (T0ψ(t)F(ψ(t))et(2α+d2)κdt)p2p2C(F(ψ(0))F(Q))1+β,

    and finally,

    T0ψ(t)F(ψ(t))et(2α+d2)κdtC22/p(F(ψ(0))F(Q))(1+β)(22p),

    which concludes the proof of Theorem A.1, since 1+γ=(1+β)(22/p).

    In this section, we show how to deduce the rate of convergence of the blow-up sequence starting from the log-epiperimetric inequality. The argument holds for a general energy E and can be used in several different contests: for the obstacle and the thin-obstacle problems, as well as for Bernoulli-type free boundary problems and minimal surfaces (see, for instance [6] and [7]).

    Proposition B.1. Let α>0 be fixed. Let the function uH1(B1) and the energy E:H1(B1)R be given and, for every 0<r1, let urH1(B1) be defined as

    ur(x):=1rαu(rx)for everyxB1.

    (a) The function rE(ur) is differentiable on (0,1] and

    rE(ur)CarD(ur) for  every0<r<1, (B.1)

    where Ca>0 is a given constant and

    D(u):=B1|xuαu|2dHd1(x).

    (b) There is a constant Cb>0 such that

    rE(ur)Cbr(E(zr)E(ur))for  every0<r<1,

    where zr:B1R is the α-homogeneous extension of ur|B1, that is,

    zr(x)=|x|αur(x/|x|)for everyxB1.

    (c) There are constants Cc>0 and γ[0,1) such that, for every r]0,1], there exists a function hrH1(B1) for which the following log-epiperimetric inequality holds :

    E(hr)(1Cc|E(zr)|γ)E(zr).

    (d) For every 0<r1, we have

    0E(ur)E(zr)and0E(ur)E(hr).

    Then, for every uH1(B1) satisfying hypotheses (a), (b), (c) and d), and such that E(u)E, for some constant E, there exists u0H1(B1) such that

    uru0L2(B1)C(lnr)1γ2γ for every 0<r1,

    where the constant C depends on Ca, Cb, Cc, the dimension d, the exponent γ, and on E.

    Proof. First, notice that by (b), (c) and (d), we have

    rE(ur)Cbr(E(zr)E(ur))Cbr(E(hr)+CcE(zr)1+γE(ur))CbCcrE(ur)1+γ. (B.2)

    Consider the change of coordinates t(r)=logr (thus, r(t)=et and r(t)=r(t)), and let

    e(t):=E(ur(t))andf(t):=D(ur(t)),

    for every t0. Then, we have

    e(t)=r(t)rE(ur(t))=r(t)rE(ur(t)).

    In particular, using (B.1) and (B.2)

    e(t)Caf(t)ande(t)CbCce(t)1+γ.

    The second inequality implies the decay of e(t). Indeed,

    t[e(t)γγtCbCc]=γ(e(t)1γe(t)CbCc)0,

    which implies that, for every t0,

    e(t)γγtCbCce(0)γ,

    which after rearranging the terms gives

    e(t)(e(0)γ+tγCbCc)1/γfor everyt0.

    In particular, there is a constant C, depending on Cb, Cc, e(0) and γ, such that

    e(t)Ct1/γfor everyt1. (B.3)

    Let now 0<r<R1, t=lnR and T=lnr be fixed; in particular, 0t<T<+. \\ For every xB1 we compute

    tut(x)=t[u(tx)tα]=xu(tx)tααtu(tx)tα=1t(xut(x)αut(x)).

    Integrating over B1, we get

    B1|uRur|2dHd1B1(Rr1ρ|xuρuρ|dρ)2dHd1=B1(Tt|xuρ(τ)uρ(τ)|dτ)2dHd1,

    where we used the change of variables τ=lnρ. By the Cauchy-Schwartz inequality, we get

    B1|uRur|2dHd1B1((Tt)Tt|xuρ(τ)uρ(τ)|2dτ)dHd1=(Tt)TtB1|xuρ(τ)uρ(τ)|2dHd1dτ=:(Tt)Ttf(τ)dτ.

    Now, using the inequality f(τ)1Cae(τ), and integrating in τ, we obtain

    B1|uRur|2dHd1TtCa(e(t)e(T))TtCae(t).

    Applying the above inequality to

    T=tn+1=2n+1 ,t=tn=2n ,r=rn+1=e2n+1 ,R=rn=e2n,

    and using (B.3), we get

    B1|urn+1urn|2dHd11Ca(Tt)e(t)CCa(21γγ)n.

    Let now σ=21γ2γ. Thus, σ<1 and

    urn+1urnL2(B1)(C/Ca)1/2σn,

    which implies that, for every NN and for every m>nN, we have

    urmurnL2(B1)(C/Ca)1/21σσN,

    which proves that urn is a Cauchy sequence in L2(B1) and so, it converges to some u0L2(B1), for which we have

    urnu0L2(B1)(C/Ca)1/21σσn.

    In order to conclude the proof, it only remains to notice that if r(rn+1,rn), then

    B1|urnur|2dHd1tn+1tnCae(tn)CCa2n2n/γ=CCaσ2n,

    which, by the triangular inequality and the fact that tn<lnr<tn+1, implies that

    uru0L2(B1)ururnL2(B1)+urnu0L2(B1)(C/Ca)1/2(1+11σ)σn=(C/Ca)1/22σ1σ(2n)1γ2γ=[(C/Ca)1/22σ1σ21γ2γ]t1γ2γn+1[(C/Ca)1/22σ1σ21γ2γ](lnr)1γ2γ,

    which proves that ur converges to u0 in L2(B1).



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