Research article

Analysis of a Holling-type IV stochastic prey-predator system with anti-predatory behavior and Lévy noise

  • In this paper, we investigate a stochastic prey-predator model with Holling-type IV functional responses, anti-predatory behavior (referring to prey resistance to predator), gestation time delay of prey and Lévy noise. We investigate the existence and uniqueness of global positive solutions through Itô's formulation and Lyapunov's method. We also provide sufficient conditions for the persistence and extinction of prey-predator populations. Additionally, we examine the stability of the system distribution and validate our analytical findings through detailed numerical simulations. Our paper concludes with the implications of our results.

    Citation: Chuanfu Chai, Yuanfu Shao, Yaping Wang. Analysis of a Holling-type IV stochastic prey-predator system with anti-predatory behavior and Lévy noise[J]. AIMS Mathematics, 2023, 8(9): 21033-21054. doi: 10.3934/math.20231071

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  • In this paper, we investigate a stochastic prey-predator model with Holling-type IV functional responses, anti-predatory behavior (referring to prey resistance to predator), gestation time delay of prey and Lévy noise. We investigate the existence and uniqueness of global positive solutions through Itô's formulation and Lyapunov's method. We also provide sufficient conditions for the persistence and extinction of prey-predator populations. Additionally, we examine the stability of the system distribution and validate our analytical findings through detailed numerical simulations. Our paper concludes with the implications of our results.



    The Ambartsumian equation is of practical interest in astrophysics [1]. It describes the surface brightness in the Milky Way. This paper focuses on an extended version of this equation. The extended Ambartsumian delay differential equation (EADDE) is considered in the following form:

    y(t)=y(t)+αξeσty(tξ),y(0)=λ,ξ>1,t0, (1.1)

    where α, ξ, σ, and λ are constants. If σ=0 and α=1, the EADDE (1.1) becomes the standard Ambartsumian delay differential equation (SADDE):

    y(t)=y(t)+1ξy(tξ),y(0)=λ,ξ>1,t0. (1.2)

    Moreover, the case α=0 transforms Eq. (1.1) to the initial value problem (IVP) y(t)=y(t), y(0)=λ. Such IVP consists of a simple linear ordinary differential equation (ODE) in which the exact solution is well-known as y(t)=λet. When α0, the exact solution of the EADDE (1.1) is still unavailable. So, the main objective of this work is to report some new results in this regard. In the last decade, several techniques have been discussed and proposed for analyzing the SADDE (1.2) in classical form [2,3,4] and also in a generalized form; see, for example [5,6]. However, the EADDE (1.1) may be considered for the first time in this paper.

    In order to solve the present model, there are many numerical and analytical methods that can be used. For the numerical methods, there are the Taylor method [7], Chebyshev polynomials [8], the Bernoulli operational matrix [9], Bernstein polynomials [10], spectral methods [11,12] and other numerical approaches [13,14]. The analytic methods include the Laplace transform (LT) [15,16,17], the combined Laplace transform-Adomian decomposition method [18], the double integral transform [19], Adomian's method [20,21,22], the Homotopy perturbation method (HPM) [23,24,25,26], the differential transform method [27,28], and the homotopy analysis method [29,30,31,32] and its modifications/extensions [33,34].

    However, a simpler approach is to be developed in this paper to treat the model (1.1) in an analytical sense. Our procedure depends mainly on two basic steps. The first step is to produce an efficient transformation to put Eq (1.1) in a new form that contains no exponential-function coefficient. The second step is to solve the transformed equation in which the coefficients will be constants. It will be demonstrated that the transformed equation possesses the same structure as the Pantograph delay differential equation (PDDE) [35,36,37,38,39]:

    z(t)=a z(t)+b z(ct),z(0)=λ,t0, (1.3)

    where a, b, and c are constants. To the best of our knowledge, there are several available analytical solutions for the PDDE (1.3) in different forms. Such ready solutions of the PDDE are to be invested in constructing the analytical solution of the present model in different forms. In addition, it will be revealed that the exact solution of the model (1.1) is still available when specific constraints on the involved parameters are satisfied. The next section highlights the basic transformation that is capable of converting the EADDE to the PDDE.

    Theorem 1. The transformation:

    y(t)=eμtz(t), (2.1)

    converts the EADDE (1.1) to

    z(t)=(1+μ)z(t)+αξz(tξ),z(0)=λ, (2.2)

    where

    μ=ξσξ1. (2.3)

    Proof. Suppose that

    y(t)=eμtz(t), (2.4)

    where μ is an unknown parameter to be determined later. Substituting Eq (2.4) into Eq (1.1), then

    eμtz(t)+μeμtz(t)=eμtz(t)+αξe(σ+μξ)tz(tξ),z(0)=λ, (2.5)

    i.e.,

    z(t)+μz(t)=z(t)+αξe[σ+(1ξ1)μ]tz(tξ),z(0)=λ, (2.6)

    or

    z(t)=(1+μ)z(t)+αξe[σ+(1ξ1)μ]tz(tξ),z(0)=λ. (2.7)

    Let

    σ+(1ξ1)μ=0, (2.8)

    then

    μ=ξσξ1. (2.9)

    Hence, Eq (2.7) becomes

    z(t)=(1+μ)z(t)+αξz(tξ),z(0)=λ, (2.10)

    and this completes the proof.

    Remark 1. Based on Theorem 1, we have

    y(t)=eξσtξ1z(t), (2.11)

    as a solution for the EADDE (1.1) such that z(t) is a solution of the PDDE:

    z(t)=az(t)+bz(ct),z(0)=λ, (2.12)

    where a, b, and c are defined as

    a=(1+μ),b=αξ,c=1ξ, (2.13)

    and μ is already given by μ=ξσξ1.

    In the literature, the solutions for the PDDE (1.3) have been obtained in different forms. Two kinds of solutions were found and addressed below. The first kind expresses the solution in the form of a power series, i.e., a power series solution (PSS). The second kind uses the exponential function solution (EFS) in closed form. Both the PSS and the EFS will be implemented in this section to formulate the solution of the current model.

    In [36], the author solved the PDDE (1.3) and obtained the PSS:

    z(t)=λ[1+i=1(ik=1(a+bck1))tii!]. (3.1)

    Implementing the values of a, b, and c given by Eq (2.13), then Eq (3.1) yields

    z(t)=λ[1+i=1(ik=1(1μ+αξk))tii!], (3.2)

    i.e.,

    z(t)=λi=0(ik=1(1μ+αξk))tii!. (3.3)

    Note that ik=1(1μ+αξk)=1 when i=0. Substituting (3.3) into (2.11) leads to the following solution for the model (1.1):

    y(t)=λ eξσtξ1i=0(ik=1(1μ+αξk))tii!. (3.4)

    It should be noted that the solution (3.4) reduces to the corresponding solution of the SADDE (1.2) when σ=0 and α=1. For declaration, utilizing these values in (3.4) gives

    y(t)=λi=0(ik=1(ξk1))tii!, (3.5)

    which agrees with the obtained PSS in [2] for the SADDE (1.2). It may be important to mention that the series (3.3) converges in the whole domain for all real values of σ, α, and ξ>1. Consequently, the solution (3.4) is convergent; this issue is discussed by Theorem 2 below.

    Theorem 2. For σ,αR, the series z(t)=λi=0(ik=1(1μ+αξk))tii! has an infinite radius of convergence ξ>1 and hence the series is uniformly convergent on any compact interval on R.

    Proof. Let us rewrite Eq (3.3) as

    z(t)=i=0hi(t), (3.6)

    where hi is

    hi(t)=λtii!ik=1(1μ+αξk),i1. (3.7)

    Assume that ρ is the radius of convergence, and applying the ratio test, then

    1ρ=limi|hi+1(t)hi(t)|=limi|ti+1(i+1)!i+1k=1(1μ+αξk)tii!ik=1(1μ+αξk)|,=|t|limi|1μ+αξ(i+1)i+1|. (3.8)

    For ξ>1, we have limiξ(i+1)=0, thus

    1ρ=|t|limi|1+μi+1|=0,μ=ξσξ1R,t0, (3.9)

    which completes the proof.

    In [37], the authors determined the following solution for the PDDE (1.3)

    z(t)=λi=0(ba)iij=0(1)jc12(ij)(ij1)eacjt(c:c)ij(c:c)j, (3.10)

    in terms of the exponential functions. Implementing the values of a, b, and c in (2.13), then the solution of the EADDE (1.1) reads

    y(t)=λ eξσtξ1i=0(αξ(1+μ))iij=0(1)jξ12(ij)(ij1)e(1+μ)ξjt(1/ξ:1/ξ)ij(1/ξ:1/ξ)j, (3.11)

    where μ=ξσξ1 and (1/ξ:1/ξ)j is the Pochhammer symbol:

    (1/ξ:1/ξ)j=j1k=0(1ξ(k+1))=jk=1(1ξk). (3.12)

    In general, (p:q)j is defined by the product:

    (p:q)j=j1k=0(1pqk)=jk=1(1pqk1). (3.13)

    In addition, El-Zahar and Ebaid [38] introduced the following solution for Eq (1.3)

    z(t)=λ(b/a:c)i=0(b/a)ieacit(c:c)i. (3.14)

    Hence, the solution of the EADDE (1.1) is

    y(t)=λ eξσtξ1(αξ(1+μ):1ξ)i=0(αξ(1+μ))ie(1+μ)ξit(1ξ:1ξ)i. (3.15)

    Moreover, the authors [38] showed that the convergence of z(t) holds if the conditions |b/a|<1 and |c|<1 are satisfied. For our model (1.1), the condition |c|<1 is already satisfied for |c|=|1/ξ|<1, where ξ>1. The other condition |b/a|<1 becomes |αξ(1+μ)|<1, i.e., |α1+μ|<ξ.

    One of the main advantages of the PSS is that it can be used to generate several exact solutions at specific cases of the model's parameters. This section focuses on this issue. Before launching to the target of this section, we put the solution (3.4) in the form:

    y(t)=λ eξσtξ1i=0vitii!,vi=ik=1(1μ+αξk). (4.1)

    The second equation in (4.1) reveals that

    v0=1,v1=1μ+αξ1,v2=(1μ+αξ1)(1μ+αξ2),v3=(1μ+αξ1)(1μ+αξ2)(1μ+αξ3),.,.,vi=(1μ+αξ1)(1μ+αξ2)(1μ+αξ3)(1μ+αξi),i1. (4.2)

    This section implements Eqs (4.1) and (4.2) to determine several exact solutions of the model (1.1) under different constraints such as 1μ+αξ1=0, 1μ+αξ2=0, 1μ+αξ3=0, , and 1μ+αξn=0 (nN+).

    From Eqs (4.1) and (4.2), it will be shown in the next theorem that only the first term v0 in series (4.1) has a non-zero value when 1μ+αξ1=0, while the other higher-order terms vi,i1 are zeros. So, the series (4.1) transforms to the exact solution for the EADDE (1.1).

    Lemma 1. If 1μ+αξ1=0, then the EADDE (1.1) becomes

    y(t)=y(t)+αξe(11ξ)(1αξ)ty(tξ),y(0)=λ,t0, (4.3)

    with exact solution:

    y(t)=λe(αξ1)t. (4.4)

    Proof. Consider 1μ+αξ1=0; in this case we have μ=1+αξ which implies σ=(11ξ)(1αξ) and the model (1.1) takes the form:

    y(t)=y(t)+αξe(11ξ)(1αξ)ty(tξ),y(0)=λ. (4.5)

    On using the relation μ=1+αξ in Eq (4.2) gives vi=0 i1. Hence, the series (4.1) contains only the first term v0 (which equals one), consequently

    y(t)=λe(αξ1)t, (4.6)

    and this completes the proof.

    Remark 2. As a direct result of this lemma, we have at α=ξ the constant function y(t)=λ as a solution of the 1st-order delay equation y(t)+y(t)=y(tξ) whatever the value of ξ. For a further validation of the solution (4.6), we consider the additional special case α=0. Then Eq (4.5) becomes y(t)+y(t)=0 and the solution is derived directly by setting α=0 into Eq (4.4); this gives y(t)=λet which is the well-known solution.

    This case gives the solution as a product of the exponential function and a polynomial of first degree in t.

    Lemma 2. If 1μ+αξ2=0, then the EADDE (1.1) becomes

    y(t)=y(t)+αξe(11ξ)(1αξ2)ty(tξ),y(0)=λ,t0, (4.7)

    and the exact solution is

    y(t)=λe(αξ21)t[1+αξ(11ξ)t]. (4.8)

    Proof. Let 1μ+αξ2=0, then σ=(11ξ)(1αξ2). Hence, Eq (1.1) yields

    y(t)=y(t)+αξe(11ξ)(1αξ2)ty(tξ),y(0)=λ,t0. (4.9)

    From Eqs (4.2), we find

    v0=1,v1=αξ(11ξ),vi=0i2, (4.10)

    and accordingly,

    y(t)=λe(αξ21)t(v0+v1t). (4.11)

    Inserting the values (4.10) into (4.11) completes the proof.

    Remark 3. An interesting case arises from this lemma when α=ξ2. This case implies the 1st-order delay equation y(t)+y(t)=ξy(tξ). The corresponding solution does not contain the term of the exponential function; the solution is a pure linear polynomial given by y(t)=λ[1+(ξ1)t].

    Lemma 3. If 1μ+αξ3=0, the corresponding equation is

    y(t)=y(t)+αξe(11ξ)(1αξ3)ty(tξ),y(0)=λ,t0, (4.12)

    with the exact solution:

    y(t)=λe(αξ31)t[1+αξ(11ξ2)t+α2ξ3(11ξ)(11ξ2)t22]. (4.13)

    Proof. The proof follows immediately by repeating the above analysis.

    Remark 4. Choosing α=ξ3 yields the 1st-order delay equation y(t)+y(t)=ξ2y(tξ) and the corresponding solution is the polynomial given by y(t)=λ[1+(ξ21)t+(ξ1)(ξ21)t22].

    This case generalizes the previous cases. The present case expresses the solution as a product of an exponential function and a polynomial of degree n.

    Theorem 3. If 1μ+αξn=0, the corresponding equation is

    y(t)=y(t)+αξe(11ξ)(1αξn)ty(tξ),y(0)=λ,t0, (4.14)

    with the exact solution:

    y(t)=λe(αξn1)tn1i=0vitii!, (4.15)

    where vi is

    vi=αiξ12i(i+1)ik=1(1ξn+k)=αiξ12i(i+1)(ξn:ξ)i. (4.16)

    Proof. Since 1μ+αξn=0, then we have from Eq (4.1) that

    vi=ik=1(1μ+αξk)=ik=1(αξn+αξk), (4.17)

    which implies vi=0 in. Hence, vi exists 0in1. Thus, the infinite series in (4.1) is truncated to

    y(t)=λe(αξn1)tn1i=0vitii!. (4.18)

    On the other hand, vi can be rewritten as

    vi=ik=1(αξk)ik=1(1ξn+k)=αiξ12i(i+1)ik=1(1ξn+k)=αiξ12i(i+1)(ξn:ξ)i, (4.19)

    which finalizes the proof.

    This section explores some numerical results for the obtained PSS and the EFS in the previous sections. The current discussion focuses on several issues, such as the behavior of the PSS and the EFS, their accuracy, the domain of the involved parameters to ensure the convergence, and also the advantages of each solution over the other. It was shown in a previous section that the PSS can be used to generate exact solutions for the EADDE (1.1) under the restriction 1μ+αξn=0 (nN+) or, equivalently, σ=(11ξ)(1αξn). Regarding the obtained exact solution in Theorem 3, it depends mainly on n. The behavior of such exact solution is plotted in Figures 1 and 2 at different values of n. In the general case, in which the restriction σ=(11ξ)(1αξn) is not satisfied, the series form (3.4) is used to obtain the m-term approximate solution of the PSS as

    Φm(t)=λ eξσtξ1m1i=0(ik=1(1μ+αξk))tii!. (5.1)
    Figure 1.  Plots of the exact solution (4.15-4.16) for the EADDE y(t)=y(t)+αξe(11ξ)(1αξn)ty(tξ),y(0)=λ when λ=1, α=2, and ξ=1.4 at different values of n, n=1,2,3,4.
    Figure 2.  Plots of the exact solution (4.15-4.16) for the EADDE y(t)=y(t)+αξe(11ξ)(1αξn)ty(tξ),y(0)=λ when λ=1, α=2, and ξ=1.4 at different values of n, n=5,6,7,8.

    Figures 3 and 4 show the convergence of the approximations Φm(t) at selected values of the parameters α, ξ, and σ, where λ=1 is fixed in all computations. These figures also indicate the difference in the behavior of the PSS when the exponent σ is changed from negative to positive. In order to estimate the accuracy of these approximations, we construct the residuals:

    REm(t)=|Φm(t)+Φm(t)αβeσtΦm(tξ)|,m1. (5.2)
    Figure 3.  Convergence of the PSS approximations Φm(t), m=12,13,14,15 at λ=1, ξ=1.2, α=1, and σ=1.
    Figure 4.  Convergence of the PSS approximations Φm(t), m=17,18,19,20 at λ=1, ξ=1.2, α=1, and σ=1.

    The numerical results displayed in Figures 5 and 6 declare that the residuals REm(t) are acceptable; especially, they approach zero as t tends to infinity. It may be important here to mention that the PSS (3.4) is convergent for all real values of α, σ, and ξ (>1) as proved by Theorem 2.

    Figure 5.  Plots of the PSS-residuals REm(t), m=20,25,30,35 at ξ=1.2, α=1, and σ=1.
    Figure 6.  Plots of the PSS-residuals REm(t), m=50,55,60,65 at ξ=2, α=1, and σ=3.

    However, the situation for the EFS (3.15) is different because of the condition of convergence given by |α1+μ|<ξ, where μ=ξσξ1. So, the m-term approximate solution of the EFS:

    Ψm(t)=λ eξσtξ1(αξ(1+μ):1ξ)m1i=0(αξ(1+μ))ie(1+μ)ξit(1ξ:1ξ)i, (5.3)

    converges in certain domains of the parameters α, σ, and ξ. Figures 7 and 8 determine the domain of the parameters ξ and α for which the EFS converges at selected values of σ, where σ=1 in Figure 7 and σ=1 in Figure 8. Similarly, Figures 9 and 10 show the domains of σ and α for which the EFS converges at selected values of ξ, where ξ=1.7 in Figure 9 and ξ=5.7 in Figure 10.

    Figure 7.  Domain of ξ and α for the convergence of the EFS (3.15) at σ=1.
    Figure 8.  Domain of ξ and α for the convergence of the EFS (3.15) at σ=1.
    Figure 9.  Domain of α and σ for the convergence of the EFS (3.15) at ξ=1.7.
    Figure 10.  Domain of α and σ for the convergence of the EFS (3.15) at ξ=5.7.

    Figures 11 and 12 show the convergence of the approximations Ψm(t) at selected values of the parameters α, ξ, and σ. In addition, the residuals corresponding to the approximations Ψm(t) are introduced in Figures 1316, which confirm the accuracy of the EFS.

    Figure 11.  Convergence of the EFS approximations Ψm(t), m=3,4,5,6,7 at λ=1, ξ=1.2, α=1, and σ=1.
    Figure 12.  Convergence of the EFS approximations Ψm(t), m=3,4,5,6,7 at λ=1, ξ=1.2, α=1, and σ=1.
    Figure 13.  Plots of the EFS-residuals REm(t), m=22,23,24 at ξ=2, α=1, and σ=1.
    Figure 14.  Plots of the EFS-residuals REm(t), m=18,19,20 at ξ=2, α=1, and σ=1.
    Figure 15.  Plots of the EFS-residual RE24(t) when α=1 and σ=1 at different values of ξ.
    Figure 16.  Plots of the EFS-residual RE5(t) when α=2 and ξ=8 at different values of σ.

    The extended Ambartsumian delay differential equation with a variable coefficient was analyzed in this paper. By the aid of a suitable transformation, the extended model was converted to the standard pantograph model. The available/known solutions in the literature for the pantograph model were employed to construct two kinds of analytical solutions, mainly, the power series solution PSS and the exponential function solution EFS. The PSS was successfully reformulated to generate several exact solutions for different forms of the present extended Ambartsumian model utilizing certain relations between the variable coefficient and the involved parameters. The obtained exact solutions reflect the advantage of the PSS over the EFS. Additionally, the PSS was found valid and convergent for any real values of the model's parameters. In contrast to the PSS, the EFS requires specific domains for the involved parameters to achieve the convergence criteria. However, the EFS enjoys better accuracy over the PSS. This is simply because the EFS needs a lower number of terms if compared with the EFS. However, the residuals both of the PSS and the EFS tend to zero, which reflect the effectiveness and efficiency of the developed analysis. Perhaps the suggested approach needs a further validation for applied problems such as delay-differential equations in pharmacokinetic compartment modeling [40]. Although the present extended model was analytically analyzed via a transformation approach, it may also be treated numerically via applying the randomized Euler scheme [41] as future work.

    Rana M. S. Alyoubi: Conceptualization, methodology, validation, formal analysis, investigation, writing-review and editing, visualization; Abdelhalim Ebaid: Methodology, validation, formal analysis, investigation, writing-original draft preparation; Essam R. El-Zahar: Conceptualization, methodology, validation, formal analysis, investigation, writing-review and editing; Mona D. Aljoufi: Conceptualization, methodology, software, validation, formal analysis, investigation, data curation, writing-review and editing. All authors have read and agreed to the published version of the manuscript.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This study is supported via funding from Prince Sattam bin Abdulaziz University project number (PSAU/2024/R/1446).

    All authors declare no conflict of interest in this paper.



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