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A spectral collocation method for the coupled system of nonlinear fractional differential equations

  • This paper analyzes the coupled system of nonlinear fractional differential equations involving the caputo fractional derivatives of order α(1,2) on the interval (0, T). Our method of analysis is based on the reduction of the given system to an equivalent system of integral equations, then the resulting equation is discretized by using a spectral method based on the Legendre polynomials. We have constructed a Legendre spectral collocation method for the coupled system of nonlinear fractional differential equations. The error bounds under the L2 and Lnorms is also provided, then the theoretical result is validated by a number of numerical tests.

    Citation: Xiaojun Zhou, Yue Dai. A spectral collocation method for the coupled system of nonlinear fractional differential equations[J]. AIMS Mathematics, 2022, 7(4): 5670-5689. doi: 10.3934/math.2022314

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  • This paper analyzes the coupled system of nonlinear fractional differential equations involving the caputo fractional derivatives of order α(1,2) on the interval (0, T). Our method of analysis is based on the reduction of the given system to an equivalent system of integral equations, then the resulting equation is discretized by using a spectral method based on the Legendre polynomials. We have constructed a Legendre spectral collocation method for the coupled system of nonlinear fractional differential equations. The error bounds under the L2 and Lnorms is also provided, then the theoretical result is validated by a number of numerical tests.



    Fractional-order derivatives arise in many applied fields, because the nonlocality for fractional calculus operator is very suitable for describing materials with memory and genetic properties. Such as control theory in power system [1,2], viscoelastic materials [3,4,5], information theory [6], electrical properties of materialsand [7], abnormal diffusion of ions in nerve cells [8,9,10], the modeling and analysis of various problems in bio-mathematical sciences [11,12], and etc.

    Inspired by the great popularity of the subject, many researchers turned to the further development of this branch of mathematical analysis. Coupled boundary conditions arise in the study of reaction-diffusion equations, Sturm-Liouville problems, mathematical biology [13,14,15] and so on; Many scholars have analyzed the existence of solutions of boundary value problems for coupled systems of nonlinear fractional differential equations [16,17,18,19,20,21,22], many of these are discussions of fractional α(1,2), but there are few numerical solutions.

    In general, there exists no method that yields an exact solution for the coupled system of nonlinear fractional differential equations. Only approximate solutions can be derived using linearization or perturbation methods. Z. Odibat et al. [23] presented He's homotopy perturbation method; H. Jafari et al. [24] employed Adomians decomposition method to give approximate solutions; S. Momani et al. [25] implemented variation iteration method to obtain approximate solutions; Zhou et al. [26] constructed a high order schemes for the numerical solution.

    These methods Most of the existing methods are discussed on α(0,1) and rarely on α(1,2). Moreover, Either these methods are based on local operations, and the effect of these methods is not good for nonlocality and weak singularity problems, or the convergence region of the corresponding results is rather small. Therefore, we construct a numerical method to solve them For the coupled fractional differential equations of α(1,2), this method converges rapidly when the solution is smooth, and still has good convergence when the solution is weakly singular.

    A general technique to construct legendre spectral collocation method for the numerical solution of the nonlinear fractional boundary value problems has been presented in [27]. In this paper we will extend this legendre spectral collocation method that is mentioned to the coupled system of nonlinear fractional differential equations. Due to the influence of coupling system and nonlinear term, the convergence analysis of spectral collocation method becomes very difficult. For this purpose, we use two kinds of polynomial interpolation, namely Legendre-Gauss interpolation and Jacobian-Gauss interpolation.

    The outline of the paper is as follows: In Sect. 2, We introduce some definitions and lemmas that will be used later. In Sect. 3, we transform the Eq (3.1) into an equivalent Volterra Fredholm integral equations, and replace the equations with a variable to get an equations defined on the interval (1,1). Then, we obtain a numerical scheme for problem (3.6) by using Legendre spectral collocation method. In Sect. 4, we derive the error analysis of the numerical scheme (3.9). In Sect. 5, some numerical experiments are provided to support the theoretical statement. Finally, some concluding remarks are given in the final section.

    Definition 2.1.(cf. p. 70 [28]) Let t(0,1), the left-sided Caputo derivative of order α, n1<α<n, nN+, are defined as:

    C0Dαtu(t)=1Γ(nα)t0(tτ)nα1u(n)(τ)dτ,

    where Γ() denotes Gamma function.

    Definition 2.2.(cf. [29]) Let Jα,βn(x),xΛ be the standard Jacobi polynomial of degree n. The set of Jacobi polynomials is a complete L2ωα,β(Λ)-orthogonal system, i.e.

    11Jα,βm(x)Jα,βn(x)ωα,β(x)dx=γα,βnδm,n, (2.1)

    where δm,n is the Kronecker function, and

    ωα,β(x)=(1x)α(1+x)β,forα,β>1.
    γα,βn={2α+β+1Γ(α+1)Γ(β+1)Γ(α+β+2),n=0,2α+β+1(2n+α+β+1)Γ(n+α+1)Γ(n+β+1)n!Γ(n+α+β+1),n1.

    Specially,

    Jα,β0(x)=1,Jα,β1(x)=12(α+β+2)x+12(αβ).

    Definition 2.3.(cf. [27]) For any of the Gauss-type quadratures defined above with the points and weights {xα,βn,ωα,βn}Nn=0(N0), we can define a discrete inner product in interval Λ :

    Λϕ(x)ωα,β(x)dxNn=0ϕ(xα,βn)ωα,βn. (2.2)

    Lemma 2.1.(cf. [29]) Let PN be the space of all polynomials of degree at most N, which is exact for any ϕ(x)P2N+1. Particularly,

    Nn=0Jα,βp(xα,βn)Jα,βq(xα,βn)ωα,βn=γα,βpδp,q,0p+q2N+1. (2.3)

    Lemma 2.2.(Lemma 2.1. [27]) For boundary value problem C0Dαty(t)=f(t,y(t)),t(0,T) with y(0)=y(T)=0, Let 1<α<2. Assume that y(t) is a function with an absolutely continuous first derivative, and f:[0,T]×RR is continuous. Then we have that yC1[0,T] is a solution of the problem if and only if it is a solution of the Fredholm integral equation:

    y(t)=1Γ(α)t0(tτ)α1f(τ,y(τ))dτtTΓ(α)T0(Tτ)α1f(τ,y(τ))dτ.

    We consider the coupled system of nonlinear fractional differential equations:

    {C0Dα1ty1(t)=f1(t,y1(t),y2(t)),C0Dα2ty2(t)=f2(t,y1(t),y2(t)),t(0,T),y1(0)=y1(T)=0,y2(0)=y2(T)=0, (3.1)

    where f1,f2:[0,T]×RR is continuous, and C0Dα1t, C0Dα2t is the left-sided Caputo derivative of order α1,α2 (1, 2).

    By Lemma 2.2, it has been proved easily that the problem (3.1) is equivalent to the following Fredholm integral equations when αi,yi(t),fi satisfy the condition of Lemma 2.2:

    yi(t)=1Γ(αi)t0(tτ)αi1fi(τ,y1(τ),y2(τ))dτtTΓ(αi)T0(Tτ)αi1fi(τ,y1(τ),y2(τ))dτ, (3.2)

    for t[0,T],i=1,2.

    Lemma 3.1. Let αi,yi(t),fi satisfy the condition of Lemma 2.2. Futhermore, let fi satisfy a Lipschitz condition with the Lipschitz constant L<Γ(α+1)4Tα. Γ(α+1)Tα=max(Γ(α1+1)Tα1,Γ(α2+1)Tα2). Then the system (3.1) has a unique solution.

    Proof. Let y(t)=(y1(t),y2(t)), define the operator Ay(t)=(A1y(t),A2y(t)). where

    Aiy(t)=1Γ(αi)t0(tτ)αi1fi(τ,y(τ))dτtTΓ(αi)T0(Tτ)αi1fi(τ,y(τ))dτ.

    Similar to Lemma 2.3 of [27], we have the following formula

    |Aiy(t)Aiˆy(t)|2LTαiΓ(αi+1)yˆyL(0,T).

    Let yˆyL(0,T)=max(y1^y1,y2^y2), we get

    |Aiyi(t)Aiˆyi(t)|4LTαΓ(α+1)yˆyL(0,T).

    We know C1[0,T] L(0,T), this means that Ai and A is contraction. Then, by Banach's fixed point theorem, we know A is a unique fixed point.

    Let Λ=[1,1], then use the change of variable t=12T(x+1),xΛ. We transfer the problem (3.2) to an equivalent problem defined in Λ, then arrive at the following schema:

    yi(12T(x+1))=1Γ(αi)12T(x+1)0(12T(x+1)τ)αi1fi(τ,y1(τ),y2(τ))dτx+12Γ(αi)T0(Tˆτ)αi1fi(ˆτ,y1(ˆτ),y2(ˆτ))dˆτ, (3.3)

    where τ=12T(ξ+1) and ˆτ=12T(λ+1). Furthermore, transfer the interval (0,12T(x+1)) to (1,x) and (0,T) to (1,1).

    For the convenience, let

    Yi(x)=yi(12T(x+1)),Fi(ξ,Y1(ξ),Y2(ξ))=fi(12T(ξ+1),y1(12T(ξ+1)),y2(12T(ξ+1))).

    Using the abbreviation, (3.3) can be read to

    Yi(x)=Tαi2αiΓ(αi)x1(xξ)αi1Fi(ξ,Y1(ξ),Y2(ξ))dξTαi(x+1)2αi+1Γ(αi)11(1λ)αi1Fi(λ,Y1(λ),Y2(λ))dλ. (3.4)

    Finally, under the linear transformation

    ξ=ξ(x,θ):=x+12θ+x12,θΛ. (3.5)

    In summary, we obtain

    Yi(x)=Tαi(x+1)αi4αiΓ(αi)11(1θ)αi1Fi(ξ(x,θ),Y1(ξ(x,θ)),Y2(ξ(x,θ)))dθTαi(x+1)2αi+1Γ(αi)11(1λ)αi1Fi(λ,Y1(λ),Y2(λ))dλ. (3.6)

    In the following, we will give a Legendre spectral collocation method for solving the system (3.6).

    For vC(Λ), we denote the Jacobi-Gauss interpolation operator in the x-direction: Iα,βx,N:C(Λ)PN, such that

    Iα,βx,Nv(xα,βn)=v(xα,βn),0nN. (3.7)

    Obviously

    Iα,βx,Nv(x)=Np=0vα,βpJα,βp(x),wherevα,βp=1γα,βpNn=0v(xn)Jα,βp(xn)ωα,βn. (3.8)

    When α=β=0, the Jacobi polynomial is equivalent to the Legendre polynomial Lk(x). Moreover, we read xn=x0,0n,ωn=ω0,0n and Ix,N=I0,0x,N.

    Then we construct the schema for the next steps. We want to derive Ui(x)PN(Λ) with N1, such that

    Ui(x)=Tαi4αiΓ(αi)Ix,N[(x+1)αi11(1θi)αi1Iαi1,0θi,NFi(ξ(x,θi),U1(ξ(x,θi)),U2(ξ(x,θi)))dθi]Tαi(x+1)2αi+1Γ(αi)11(1λi)αi1Iαi1,0λi,NFi(λi,U1(λi),U2(λi))dλi, (3.9)

    where x=x0,0,θi=θαi1,0,λi=λαi1,0.

    The above formula is an implicit format. (3.9) has unique solution if Fi satisfies the Lipschitz condition with the Lipschitz constant L<Γ(α+1)4Tα.

    Remark 1. The proof are similar to Appendix in [27] (reference therein), it is easy to the proof, so we omit the details.

    Next, we want to derive an approximation of scheme (3.9). We set

    Ui(x)=Np=0ui,pLp(x),Ix,NIαi1,0θi,N((x+1)αiFi(ξ(x,θi),U1(ξ(x,θi),U2(ξ(x,θi)))=Np=0Np=0di,p,pLp(x)Jαi1,0p(θi). (3.10)

    Using (3.10) and (2.1), we arrive at the following schema:

    Tαi4αiΓ(αi)11(1θi)αi1Ix,NIαi1,0θi,N((x+1)αiFi(ξ(x,θi),U1(ξ(x,θi)),U2(ξ(x,θi)))dθi=Tαi4αiΓ(αi)Np=0Np=0di,p,pLp(x)11(1θi)αi1Jαi1,0p(θi)dθi=Tαi2αiΓ(αi+1)Np=0di,p,0Lp(x), (3.11)

    where

    di,p,0=αi(2p+1)21+αiNm=0Nn=0(xm+1)αiFi(ξ(xm,θαi1,0n),U1(ξ(xm,θαi1,0n)),U2(ξ(xm,θαi1,0n)))Lp(xm)ωmωαi1,0n. (3.12)

    Futhermore, by (2.2) we obtain

    11(1λi)αi1Iαi1,0λi,NFi(λi,U1(λi),U2(λi))dλi=Nn=0Fi(λαi1,0n,U1(λαi1,0n),U2(λαi1,0n))ωαi1,0n. (3.13)

    To summarize, that is by combining (3.9)-(3.13), we arrive at the following overall schema

    Np=0ui,pLp(x)=Tαi2αiΓ(αi+1)Np=0di,p,0Lp(x)Tαi(x+1)2αi+1Γ(αi)Nn=0Fi(λαi1,0n,U1(λαi1,0n),U2(λαi1,0n))ωαi1,0n. (3.14)

    The coefficients of (3.14) yields are expanded and compared, we have

    {ui,p=Tαi2αiΓ(αi+1)di,p,0Tαi2αi+1Γ(αi)Nn=0Fi(λαi1,0n,U1(λαi1,0n),U2(λαi1,0n))ωαi1,0n,forp=0,1,ui,p=Tαi2αiΓ(αi+1)di,p,0for2pN. (3.15)

    Remark 2. For the sake of economy of exposition, we focus on the coupled system C0Dαityi(t)=fi(t,y1(t),y2(t)),t(0,T) with yi(0)=yi(T)=0 in which i=1,2. In fact, Similar to the provied method in this paper, we can easily get the numerical scheme and error analysis of the system C0Dαityi(t)=fi(t,y1(t),y2(t),,yz(t)),t(0,T) with yi(0)=yi(T)=0 in which i=1,2,,z. In Example 5.3, we also give the numerical experiment when z=3.

    Remark 3. If yi(0)0,yi(T)0, That is, the initial value problem, with the initial value is not zero.

    {C0Dα1ty1(t)=f1(t,y1(t),y2(t)),C0Dα2ty2(t)=f2(t,y1(t),y2(t)),t(0,T),y(k)1(0)=ck1,y(k)2(0)=ck2. (3.16)

    By Volterra integral equations the problem (3.16) is equivalent to the following Fredholm integral equations

    {y1(t)=g1(t)+1Γ(α1)t0(tτ)α11f1(τ,y1(τ),y2(τ))dτ,y2(t)=g2(t)+1Γ(α1)t0(tτ)α11f2(τ,y1(τ),y2(τ))dτ, (3.17)

    where gi(t)=ni1k=0ckitkk!,i=1,2,,n.

    Similarly, we can get

    {ui,p=c0i+c1iT2+Tαi2αiΓ(αi+1)di,p,0,forp=0,ui,p=c1iT2+Tαi2αiΓ(αi+1)di,p,0,forp=1,ui,p=Tαi2αiΓ(αi+1)di,p,0for2pN. (3.18)

    In the next sections, we will give a error analysis for the above schema under the space L2(Λ) and L(Λ), respectively.

    We introduce the Jacobi-weighted Sobolev space and the norm and semi-norm.

    Hlωα,β(Λ)={v:vHlωα,β<},l0,
    vHlωα,β=(lk=0|v|Hlωα,β)12,|v|Hkωα,β=kxvωα+k,β+k,

    where ωα,β is the weighted L2ωα,β(Λ)-norm. Especially, L2(Λ)=H0ω0,0(Λ), =L2(Λ) and =L(Λ).

    Now, we analyze the errors of numerical scheme (3.9). Let ei(x)=Yi(x)Ui(x),(i=1,2) and using I to represent identity operator. Observely,

    eiYiIx,NYi+Ix,NYiUi. (4.1)

    Moreover, let e(x)=Y(x)U(x). where Y(x)=(Y1(x),Y2(x)), U(x)=(U1(x),U2(x)).

    Lemma 4.1. For N1, We can get the following inequality

    ei5n=1Bi,n,fori=1,2,

    where

    Bi,1(x)=Yi(x)Ix,NYi(x),Bi,2(x)=Tαi2αiΓ(αi)Ix,Nx1(xξi)αi1(Ix˜Iαi1,0ξi,N)Fi(ξi,Y(ξi))dξi,Bi,3(x)=Tαi2αiΓ(αi)Ix,Nx1(xξi)αi1x˜Iαi1,0ξi,N(Fi(ξi,Y(ξi))Fi(ξi,U(ξi)))dξi,Bi,4(x)=Tαi(x+1)2αi+1Γ(αi)11(1λi)αi1Iαi1,0λi,N(Fi(λi,U(λi))Fi(λi,Y(λi)))dλi,Bi,5(x)=Tαi(x+1)2αi+1Γ(αi)11(1λi)αi1(Iαi1,0λi,NI)Fi(λi,Y(λi))dλi.

    Proof. Similar to Lemma 4.3 of [27], we can easily prove it.

    Lemma 4.2. Assume the hypothesis of Lemma 4.1. We have the following inequality

    e5n=1B1,n+5n=1B2,n.

    Proof. For e(x)=Y(x)U(x). we have

    e(x)=Y(x)U(x)=(Y1(x),Y2(x))(U1(x),U2(x))=(Y1(x)U1(x),Y2(x)U2(x))=(e1(x),e2(x)).

    Then, combination with Lemma 4.1

    e=(e1,e2)=e12+e22e1+e25n=1B1,n+5n=1B2,n.

    We set the Nemytskii operator

    F:Hlωl,l(Λ)Hlωαi+l1,l(Λ)(lN,1lN+1).

    Let Y(x) as the solution of system (3.6) and U(x) as the solution of system (3.9). We define that

    F(Y)(x):=F(x,Y(x)),
    lxYωl,l=max(lxY1ωl,l,lxY2ωl,l),
    lxF(,Y())ωα+l1,l=max(lxF1(,Y())ωα1+l1,l,lxF2(,Y())ωα2+l1,l).

    Now we prove the convergence of the spectral collocation method in the space L2(Λ).

    Lemma 4.3. Suppose that αi(1,2), YiHlωl,l(Λ),i=1,2, Fi fulfills the Lipschitz condition with the Lipschitz constant L<Γ(α+1)4Tα. Then we can obtain

    YiUicNl(lxYωl,l+lxF(,Y())ωαi+l1,l).

    Proof. Similar to Lemma 4.4 of [27], we can easily get

    Bi,1=YiIx,NYicNllxYiωl,l,Bi,2cNllξFi(,Y()ωαi+l1,l,Bi,312(cNllxYωαi+l1,l+αi3×2αie),Bi,412(αi12e+cNllxYωαi+l1,l),Bi,5cNllxFi(,Y())ωαi+l1,l. (4.2)

    Then by Lemma 4.1, we get

    eicNllxYiωl,l+cNllξFi(,Y()ωαi+l1,l+12(cNllxYωαi+l1,l+αi3×2αie)+12(αi12e+cNllxYωαi+l1,l)+cNllxFi(,Y())ωαi+l1,lcNl(lxYωl,l+lxF(,Y())ωα+l1,l)+12(αi3×2αi+αi12)e. (4.3)

    Then, by (4.3) and Lemma 4.2, we have

    YUcNl(lxYωl,l+lxF(,Y())ωα+l1,l)+12(α13×2α1+α112)e+12(α23×2α2+α212)e.

    Clearly,

    αi3×2αi+αi12<1,αi(1,2).

    Then, we easily get

    YUcNl(lxYωl,l+lxF(,Y())ωα+l1,l). (4.4)

    Thus

    YiUicNl(lxYωl,l+lxF(,Y())ωα+l1,l).

    Let ui(t):=Ui(2tT1)(i=1,2) be the approximate solution obtained by using the Legendre spectral collocation method with t(0,T), χα,β(t):=(Tt)αtβ is defined as a weighting function. Furthermore, define the Nemytskii operator

    K:Hlχl,l(0,T)Hlχαi+l1,l(0,T)(lN,1lN+1).

    Let y(t)=(y1(t),y2(t)) as the exact solution to the system (3.1), and u(t)=(u1(t),u2(t)) be the approximate solution. We define that

    K(yi)(t):=fi(t,y1(t),y2(t)),i=1,2,
    ltyL2χl,l(0,T)=max(lty1L2χl,l(0,T),lty2L2χl,l(0,T)),
    ltf(,y())L2χα+l1,l(0,T)=max(ltf1(,y())L2χα1+l1,l(0,T),ltf2(,y())L2χα2+l1,l(0,T)).

    Then, according to the above Lemma, we can get the following theorem.

    Theorem 4.1. Suppose that αi(1,2), yiHlχl,l(0,T). Moreover, fi fulfills the Lipschitz condition with the Lipschitz constant L<Γ(αi+1)4Tαi. Then we get

    yiuicNl(ltyL2χl,l(0,T)+ltf(,y())L2χα+l1,l(0,T)).

    Next, we estimate the error in function space L(Λ).

    Lemma 4.4. Suppose that αi(1,2), YiL(Λ)Hl(Λ), Fi fulfills the Lipschitz condition with the Lipschitz constant L<Γ(α+1)4Tα. Then we get

    YiUicN34llxYωl,l+cN12llxF(,Y())ωαi+l1,l,i=1,2.

    Proof. Similarly, we get that

    eiYiIx,NYi+Ix,NYiUi5n=1Bi,n. (4.5)

    Then, similar to Lemma 4.5 of [27], we can easily get

    Bi,1cN34llxYi,Bi,2cN12llξFi(,Y())ωαi+l1,l,Bi,312(cN12llxYωαi+l1,l+cN12e),|Bi,4|12(12e+cNllxYωαi+l1,l),|Bi,5|cNllxFi(,Y())ωαi+l1,l. (4.6)

    By (4.6) and Lemma 4.2, we have

    YU(cN34llxY1)+(cN34llxY2)+(cN12llξF1(,Y())ωα1+l1,l)+(cN12llξF2(,Y())ωα2+l1,l)+12cN12llxYωα1+l1,l+12cN12llxYωα2+l1,l+cN12e+12e+12cNllxYωα1+l1,l+12cNllxYωα2+l1,l+cNllxF1(,Y())ωα1+l1,l+cNllxF2(,Y())ωα2+l1,lcN34llxY+cN12llxF(,Y())ωα+l1,l+cN12e+12e.

    Then, combination with (4.4) we can obtain

    YUcN34llxY+cN12llxF(,Y())ωα+l1,l.

    Thus

    YiUicN34llxY+cN12llxFi(,Y())ωα+l1,l.

    Then, according to the Lemma 4.5, we can get the following theorem.

    Theorem 4.2. Suppose that αi(1,2), yiL(0,T)Hl(0,T). Futhermore, fi fulfills the Lipschitz condition with the Lipschitz constant L<Γ(α+1)4Tα. Then we have

    yiuiL(0,T)cN34lltyL2(0,T)+cN12lltf(,y())L2χα+l1,l(0,T).

    In this section, we carry out some numerical experiments to verify the theoretical results of the previous method.

    Example 5.1. We consider the coupled system of nonlinear problems with weakly singular solutions as follows:

    {C0Dα1ty1(t)=y21(t)+y22(t)+g1(t),C0Dα2ty2(t)=y21(t)y22(t)+g2(t),t(0,1),y1(0)=y1(1)=0,y2(0)=y2(1)=0,

    where g1(t)=Γ(2+α1)t(tt1+α1)2(tt1+α22)2, g2(t)=Γ(2+α22)Γ(2α22)t1α22(tt1+α1)2+(tt1+α22)2. It can be verified that the exact solution is y1(t)=tt1+α1, y2(t)=tt1+α22, which is weakly singular at the endpoint t = 0.

    When N=2, by (3.10) we have

    Ui(x)=ui,0L0(x)+ui,1L1(x)+ui,2L2(x), (5.1)

    where L0(x),L1(x),L2(x) known, ui,0,ui,1,ui,2 by (3.15) we can obtain

    {ui,0=Tαi2αiΓ(αi+1)di,0,0Tαi2αi+1Γ(αi)Nn=0Fi(λαi1,0n,U1(λαi1,0n),U2(λαi1,0n))ωαi1,0n,ui,1=Tαi2αiΓ(αi+1)di,1,0Tαi2αi+1Γ(αi)Nn=0Fi(λαi1,0n,U1(λαi1,0n),U2(λαi1,0n))ωαi1,0n,ui,2=Tαi2αiΓ(αi+1)di,2,0.

    di,p,0 is given in (3.12). Substitute the above results into (5.1) to obtain Ui(x), by (3.2), (3.3), (3.6), (3.7), (3.9), we know

    Ui(x)=Yi(x)=yi(12T(x+1))=yi(t).

    In Table 1, we show The value of ui,p when α1=α2=5/4, N=2. In Table 2, we show substitute the results of tab 1 into (5.1) to obtain numerical solution and the exact solution. In Table 3, we show the error of y1,y2 varies with N when α1=α2=5/4. Moreover, In Figures 1 and 2, we show the error between the approximate solution and the exact solution in L(Λ) and L2(Λ) space, respectively. It is observed that for all α(1,2), the method has good convergence even though the solution is weakly singular.

    Table 1.  The value of ui,p when α1=α2=5/4, N=2.
    i ui,0 ui,1 ui,2
    1 0.1923 0.0115 -0.1951
    2 0.1201 -0.0129 -0.1145

     | Show Table
    DownLoad: CSV
    Table 2.  Numerical solution and exact solution when α1=α2=5/4, N=2.
    x U1(x)1 U2(x)2 t3 y1(t) y2(t)
    -1.0000 -0.0144 0.0186 0 0 0
    -0.9195 0.0318 0.0441 0.0402 0.0395 0.0348
    -0.7388 0.1216 0.0932 0.1306 0.1204 0.0940
    -0.4779 0.2175 0.1443 0.2610 0.2123 0.1483
    -0.1653 0.2800 0.1748 0.4174 0.2774 0.1756
    0.1653 0.2838 0.1706 0.5826 0.2861 0.1669
    0.4779 0.2285 0.1320 0.7390 0.2327 0.1273
    0.7388 0.1387 0.0741 0.8694 0.1395 0.0728
    0.9195 0.0530 0.0203 0.9598 0.0480 0.0243
    1.0000 0.0087 -0.0073 1.0000 0 0
    Note: 1 U1(x)=2p=0u1,pLp(x). 2 U2(x)=2p=0u2,pLp(x). 3 t=12T(x+1).

     | Show Table
    DownLoad: CSV
    Table 3.  Numerical solution and exact solution when α1=α2=5/4, N=2.
    N Lerror of y1 L2error of y1 Lerror of y2 L2error of y2
    2 1.4362e-02 4.3702e-03 1.8581e-02 4.3702e-03
    4 7.9055e-04 4.5786e-04 3.0695e-03 4.5786e-04
    6 1.6147e-04 1.3548e-04 1.0241e-03 1.3548e-04
    8 5.1592e-05 6.0834e-05 4.5738e-04 6.0834e-05
    10 2.1007e-05 3.3689e-05 2.4107e-04 3.3689e-05
    12 9.9849e-06 2.1058e-05 1.4155e-04 2.1058e-05
    14 5.2881e-06 1.4235e-05 8.9695e-05 1.4235e-05
    16 3.0344e-06 1.0160e-05 6.0167e-05 1.0160e-05
    18 1.8525e-06 7.5343e-06 4.2182e-05 7.5343e-06
    20 1.1881e-06 5.7290e-06 3.0635e-05 5.7290e-06

     | Show Table
    DownLoad: CSV
    Figure 1.  Lerrors and L2errors of y1 for Expample 5.1.
    Figure 2.  Lerrors and L2errors of y2 for Expample 5.1.

    Example 5.2. We consider the coupled system of nonlinear problems with smooth solutions as follows:

    {C0Dα1ty1(t)=y21(t)+y22(t)+g1(t),C0Dα2ty2(t)=y21(t)y22(t)+g2(t),t(0,1),y1(0)=y1(1)=0,y2(0)=y2(1)=0,

    where g1(t)=Γ(17/4)Γ(17/4α1)t13/4α1(tt13/4)2(tt15/4)2, g2(t)=Γ(19/4)Γ(19/4α2)t15/4α2(tt13/4)2+(tt15/4)2. It can be verified that the exact solution is y1(t)=tt134, y2(t)=tt154, which is smooth on the interval [0, 1].

    In Figures 3 and 4, we show the error between the approximate solution and the exact solution in L(Λ) and L2(Λ) space, respectively. It is observed that for all α(1,2), the method converges rapidly when the exact solution is very smooth.

    Figure 3.  Lerrors and L2errors of y1 for Expample 5.2.
    Figure 4.  Lerrors and L2errors of y2 for Expample 5.2.

    Example 5.3. We consider the system of nonlinear problems as follows:

    {C0Dα1ty1(t)=y21(t)+y22(t)+y23(t)+g1(t),C0Dα2ty2(t)=y21(t)y22(t)+y23(t)+g2(t),C0Dα3ty3(t)=y21(t)+y22(t)y23(t)+g3(t),t(0,1),y1(0)=y1(1)=0,y2(0)=y2(1)=0,y3(0)=y3(1)=0,

    where g1(t)=Γ(2+α1)t(tt1+α1)2(tt1+α22)2(tt5/4)2, g2(t)=Γ(2+α22)Γ(2α22)t1α22(tt1+α1)2+(tt1+α22)2(tt5/4)2, g3(t)=Γ(17/4)Γ(17/4α3)t13/4α3(tt1+α1)2(tt1+α22)2+(tt13/4)2. It can be verified that the exact solution is y1(t)=tt1+α1, y2(t)=tt1+α22, y3(t)=tt13/4.

    In Figures 57, we show the error between the approximate solution and the exact solution in L(Λ) and L2(Λ) space, respectively. The results show that this method still has good convergence when z=3.

    Figure 5.  Lerrors and L2errors of y1 for Expample 5.3.
    Figure 6.  Lerrors and L2errors of y2 for Expample 5.3.
    Figure 7.  Lerrors and L2errors of y3 for Expample 5.3.

    Example 5.4. We consider the coupled system of nonlinear problems with initial value is not zero as follows:

    {C0Dα1ty1(t)=y21(t)+y22(t)+g1(t),C0Dα2ty2(t)=y21(t)y22(t)+g2(t),t(0,1),y(k)1(0)=ck1,y(k)2(0)=ck2,

    where g1(t)=Γ(2+α1)t(t1+α13t+2)2(t13/45t+2)2, g2(t)=Γ(17/4)Γ(17/4α2)t13/4α2(t1+α13t+2)2+(t13/45t+2)2. It can be verified that the exact solution is y1(t)=t1+α13t+2, y2(t)=t13/45t+2. y1(0)=2,y1(0)=3,y1(1)=0,y2(0)=2,y2(0)=5,y2(1)=2.

    In Figures 8 and 9, we show the error between the approximate solution and the exact solution in L(Λ) and L2(Λ) space, respectively, where yi(0)0. The results show that this method still has good convergence when the initial value is not zero.

    Figure 8.  Lerrors and L2errors of y1 for Expample 5.4.
    Figure 9.  Lerrors and L2errors of y2 for Expample 5.2.

    We presented a Legendre spectral collocation method for the system of nonlinear fractional differential equations. We established an error estimate for the numerical solution, and showing that the proposed schema is converges. The carried out numerical tests confirmed the theoretical prediction.

    The authors would like to thank the referees and editor for their valuable comments and suggestions which helped to improve the results of this paper. This work was supported by the Ph.D. Research-Starting Foundation of Guizhou Normal University, China ([2016] Numerical Method of Anomalous Diffusion and Its Related Problems)

    The authors declare that there are no conflicts of interest.



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