Research article

Some inequalities for multiplicative tempered fractional integrals involving the λ-incomplete gamma functions

  • Received: 08 March 2021 Accepted: 30 April 2021 Published: 07 May 2021
  • MSC : 26A33, 26A51, 26D10, 26D15

  • In this paper, we introduce a class of the multiplicative tempered fractional integral operators. Then, we investigate two Hermite–Hadamard type inequalities for this class. By using the established identity and the multiplicative convexity, we establish some integral inequalities for the multiplicative tempered fractional integrals involving the λ-incomplete gamma functions. And our results obtained in the present paper generalize some results given by Budak and Tunç (2020) and Ali et al. (2019). Also, we provide three examples to demonstrate the simplicities of the calculations.

    Citation: Hao Fu, Yu Peng, Tingsong Du. Some inequalities for multiplicative tempered fractional integrals involving the λ-incomplete gamma functions[J]. AIMS Mathematics, 2021, 6(7): 7456-7478. doi: 10.3934/math.2021436

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  • In this paper, we introduce a class of the multiplicative tempered fractional integral operators. Then, we investigate two Hermite–Hadamard type inequalities for this class. By using the established identity and the multiplicative convexity, we establish some integral inequalities for the multiplicative tempered fractional integrals involving the λ-incomplete gamma functions. And our results obtained in the present paper generalize some results given by Budak and Tunç (2020) and Ali et al. (2019). Also, we provide three examples to demonstrate the simplicities of the calculations.



    The convexity of functions is a powerful tool to deal with many kinds of issues of pure and applied science. In recent decades, many authors have devoted themselves to studying the properties and inequalities related to convexity in different directions, see [13,21,23,34,52] and the references cited therein. One of the most important mathematical inequalities concerning convex mapping is Hermite–Hadamard inequality, which is also utilized widely in many other disciplines of applied mathematics. Let's review it as follows:

    Let f:KRR be a convex mapping defined on the interval K of real numbers and τ1,τ2K with τ1<τ2. The subsequent inequalities are called Hermite–Hadamard inequalities:

    f(τ1+τ22)1τ2τ1τ2τ1f(t)dtf(τ1)+f(τ2)2. (1.1)

    Many inequalities have been established in terms of inequalities (1.1) via functions of different classes, such as convex functions [28], s-convex functions [33], (α,m)-convex functions [47], harmonically convex functions [16], h-convex functions [18], strongly exponentially generalized preinvex functions [29], h-preinvex functions [37], p-quasiconvex functions [27], N-quasiconvex functions [3], etc. For more recent results about this topic, the readers may refer to [13,22,25,26,30,32,36] and the references cited therein.

    The multiplicatively convex function is one of the most significant functions, which can be defined as follows.

    Definition 1. A mapping f: IR[0,) is said to be multiplicatively convex or log-convex, if log f is convex or equivalently for all τ1, τ2 I and t [0,1], one has the following inequality:

    f(tτ1+(1t)τ2)[f(τ1)]t[f(τ2)]1t.

    From Definition 1, it follows that

    f(tτ1+(1t)τ2)[f(τ1)]t[f(τ2)]1ttf(τ1)+(1t)f(τ2),

    which reveals that every multiplicatively convex function is a convex mapping, but the converse is not true.

    Many properties and inequalities associated with log-convex mappings have been studied by plenty of researchers. For example, Bai and Qi [9] gave several integral inequalities of the Hermite–Hadamard type for log-convex mappings. Dragomir [20] provided some unweighted and weighted inequalities of Hermite–Hadamard type related to log-convex mappings on real intervals. Set and Ardiç [46] established certain Hermite–Hadamard-like type integral inequalities involving log-convex mappings and p-functions. Zhang and Jiang [53] researched some properties for log-convex mapping. For more results on the basis of log-convex mappings, one can see, for example, [10,39,40,49,50] and the references cited therein.

    In 2008, Bashirov [11] proposed a class of the multiplicative operators called integral, which is denoted by ba(f(x))dx and the ordinary integral is denoted by baf(x)dx. Recall that the function f is multiplicatively integrable on [a,b], if f is positive and Riemann integrable on [a,b] and

    ba(f(x))dx=ebaln(f(x))dx.

    Definition 2. [11] Let f:RR+ be a positive function. The multiplicative derivative of function f is given by

    dfdt(t)=f(t)=limh0(f(t+h)f(h))1h.

    If f has positive values and is differentiable at t, then f exists and the relation between f and ordinary derivative f is as follows:

    f(t)=e[lnf(t)]=ef(t)f(t).

    The following properties of differentiable exist:

    Theorem 1. [11] Let f and g be differentiable functions. If c is an arbitrary constant, then functions cf, fg, f+g, f/g and fg are differentiable and

    (i)(cf)(t)=f(t),(ii)(fg)(t)=f(t)g(t),(iii)(f+g)(t)=f(t)f(t)f(t)+g(t)g(t)g(t)f(t)+g(t),(iv)(fg)(t)=f(t)g(t),(v)(fg)(t)=f(t)g(t)f(t)g(t).

    Moreover, Bashirov et al. show that the multiplicative integral has the following properties:

    Proposition 1. [11] If f is positive and Riemann integrable on [a,b], then f is integrable on [a,b] and

    (i)ba((f(x))p)dx=ba((f(x))dx)p,(ii)ba(f(x)g(x))dx=ba(f(x))dx.ba(g(x))dx,(iii)ba(f(x)g(x))dx=ba(f(x))dxba(g(x))dx,(iv)ba(f(x))dx=ca(f(x))dx.bc(f(x))dx,acb,(v)aa(f(x))dx=1andba(f(x))dx=(ab(f(x))dx)1.

    The interesting geometric mean type inequalities, known as the Hermite–Hadamard inequality for the multiplicatively convex functions, are shown by the following theorem in [7].

    Theorem 2. Let f be a positive and multiplicatively convex function on interval [a,b], then the following inequalities hold

    f(a+b2)(ba(f(x))dx)1baf(a)f(b). (1.2)

    Fractional calculus, as an advantageous tool, reveals its significance to implement differentiation and integration of real or complex number orders. Furthermore, it recently emerged rapidly due to its applications in modelling a number of problems especially in dealing with the dynamics of the complex systems, decision making in structural engineering and probabilistic problems, etc., see, for instance, [6,31]. The research of mathematical inequalities including many different types of fractional integral operators, especially the Hermite–Hadamard type inequalities, is a current research focus. For example, refer to [8,19,22] for Riemann–Liouville integrals, to k-Riemann–Liouville integrals [41], to Hadamard fractional integrals [4,48], to conformable fractional integrals [2,14], to Katugampola fractional integrals [17,51], and to exponential kernel integrals [5], etc.

    An imperative generalization of Riemann–Liouville fractional integrals was considered by Abdeljawad and Grossman in [1], which is named the multiplicative Riemann–Liouville fractional integrals.

    Definition 3. [1] The multiplicative left-sided Riemann–Liouville fractional integral aIαf(x) of order α C, Re(α)>0 is defined by

    aIαf(x)=e(Iαa+(lnf))(x),

    and the multiplicative right-sided one Iαbf(x) is defined by

    Iαbf(x)=e(Iαb(lnf))(x),

    where the symbols Iαa+f(x) and Iαbf(x) denote respectively the left-sided and right-sided Riemann–Liouville fractional integrals, which are defined by

    Iαa+f(x)=1Γ(α)xa(xt)α1f(t)dt,x>a,

    and

    Iαbf(x)=1Γ(α)bx(tx)α1f(t)dt,x<b,

    respectively.

    On the other hand, Sarikaya et al. proved the following noteworthy inequalities which are the Hermite–Hadamard inequalities for Riemann–Liouville fractional integrals.

    Theorem 3. [44] Let f:[a,b]R be a positive function with 0a<b and fL1([a,b]). If f is a convex function on [a,b], then the following inequalities for fractional integrals hold:

    f(a+b2)Γ(α+1)2(ba)α[Iαa+f(b)+Iαbf(a)]f(a)+f(b)2, (1.3)

    with α>0.

    Also, Sarikaya and Yildirim built another form relevant to Riemann–Liouville fractional Hermite–Hadamard type inequalities as follows.

    Theorem 4. [45] Under the same assumptions of Theorem 3, we have

    f(a+b2)2α1Γ(α+1)(ba)α[Iα(a+b2)+f(b)+Iα(a+b2)f(a)]f(a)+f(b)2. (1.4)

    Sabzikar et al. provided the following tempered fractional operators.

    Definition 4. [35] Let [a,b] be a real interval and λ0, α>0. Then for a function f L1([a,b]), the left-sided and right-sided tempered fractional integrals are, respectively, defined by

    Iα,λa+f(x)=1Γ(α)xa(xt)α1eλ(xt)f(t)dt,x>a,

    and

    Iα,λbf(x)=1Γ(α)bx(tx)α1eλ(tx)f(t)dt,x<b.

    For several recent related results involving the tempered fractional integrals, see [24,38,42,43] and the references included there.

    Motivated by the results in the papers above, especially these developed in [12,38], this work aims to investigate some inequalities of Hermite–Hadamard type, which involve the tempered fractional integrals and the notion of the λ-incomplete gamma function for the multiplicatively convex functions. For this purpose, we establish two Hermite–Hadamard type inequalities for the multiplicative tempered fractional integrals, then we present an integral identity for differentiable mappings, from which we provide certain estimates of the upper bounds for trapezoid inequalities via the multiplicative tempered fractional integral operators.

    As one can see, the definitions of the tempered fractional integrals and the multiplicative fractional integrals have similar configurations. This observation leads us to present the following definition of fractional integral operators, to be referred to as the multiplicative tempered fractional integrals.

    Definition 5. The multiplicative left-sided tempered fractional integral aIα,λf(x) of order αC, Re(α)>0, is defined by

    aIα,λf(x)=e(Iα,λa+(lnf))(x),λ0,

    and the multiplicative right-sided one Iα,λbf(x) is defined by

    Iα,λbf(x)=e(Iα,λb(lnf))(x),λ0,

    where the symbols Iα,λa+f(x) and Iα,λbf(x) denote the left-sided and right-sided tempered fractional integrals, respectively.

    Observe that, for λ=0, the multiplicative tempered fractional integrals become to the multiplicative Riemann–Liouville fractional integrals.

    The following facts will be required in establishing our main results.

    Remark 1. For the real numbers α>0 and x,λ0, the following identities hold:

    (i) γλ(ba)(α,1)=γλ(α,ba)(ba)α, (2.1)
    (ii)10γλ(ba)(α,x)dx=γλ(α,ba)(ba)αγλ(α+1,ba)(ba)α+1, (2.2)

    where γλ(,) is the λ-incomplete gamma function [38], which is defined as follows:

    γλ(α,x)=x0tα1eλtdt.

    If λ=1, the λ-incomplete gamma function reduces to the incomplete gamma function [15]:

    γ(α,x)=x0tα1etdt.

    Proof. (i) By using the changed variable u=(ba)t in the (2.1), we get

     γλ(ba)(α,1)=10tα1eλ(ba)tdt=ba0(uba)α1eλu(1ba)du=γλ(α,ba)(ba)α,

    which ends the identity (2.1).

    (ii) From the definition of λ-incomplete gamma function, we have

    10γλ(ba)(α,x)dx=10x0yα1eλ(ba)ydydx.

    By changing the order of the integration, we get

    10γλ(ba)(α,x)dx=101yyα1eλ(ba)ydxdy=10(1y)yα1eλ(ba)ydy=10yα1eλ(ba)ydy10yαeλ(ba)ydy.

    Applying the Remark 1 (i), we get the identity (2.2).

    Our first main result is presented by the following theorem.

    Theorem 5. Let f be a positive and multiplicatively convex function on interval [a,b], then we have the following Hermite–Hadamard inequalities for the multiplicative tempered fractional integrals:

    f(a+b2)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)f(a)f(b), (2.3)

    where γλ(,) is the λ-incomplete gamma function.

    Proof. On account of the multiplicative convexity of f on interval [a,b], we have

    f(a+b2)=f(at+(1t)b+(1t)a+tb2)[f(at+(1t)b)]12[f((1t)a+tb)]12,

    i.e.

    lnf(a+b2)12[lnf(at+(1t)b)+lnf((1t)a+tb)]. (2.4)

    Multiplying both sides of (2.4) by tα1eλ(ba)t then integrating the resulting inequality with respect to t over [0, 1], we obtain

    lnf(a+b2)10tα1eλ(ba)tdt12[10tα1eλ(ba)tlnf(at+(1t)b)dt+10tα1eλ(ba)tlnf((1t)a+tb)dt].

    Utilizing the changed variable, we have

    1(ba)αlnf(a+b2)ba0xα1eλxdx12(ba)α[ba(bx)α1eλ(bx)lnf(x)dx+ba(xa)α1eλ(xa)lnf(x)dx].

    That is,

    γλ(α,ba)(ba)αlnf(a+b2)12(ba)α[ba(bx)α1eλ(bx)lnf(x)dx+ba(xa)α1eλ(xa)lnf(x)dx],lnf(a+b2)Γ(α)2γλ(α,ba)[Iα,λa+lnf(b)+Iα,λblnf(a)].

    Thus we get,

    f(a+b2)eΓ(α)2γλ(α,ba)[Iα,λa+lnf(b)+Iα,λblnf(a)]=[eIα,λa+lnf(b)eIα,λblnf(a)]Γ(α)2γλ(α,ba)=[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba),

    which completes the proof of the first inequality in (2.3).

    On the other hand, as f is multiplicatively convex on interval [a,b], we have

    f(at+(1t)b)[f(a)]t[f(b)]1t,

    and

    f((1t)a+tb)[f(a)]1t[f(b)]t.

    Thus,

    lnf(at+(1t)b)+lnf((1t)a+tb)tlnf(a)+(1t)lnf(b)+(1t)lnf(a)+tlnf(b)=lnf(a)+lnf(b). (2.5)

    Multiplying both sides of (2.5) by tα1eλ(ba)t then integrating the resulting inequality with respect to t over [0,1], we obtain

    10tα1eλ(ba)tlnf(at+(1t)b)dt+10tα1eλ(ba)tlnf((1t)a+tb)dt[lnf(a)+lnf(b)]10tα1eλ(ba)tdt.

    Hence,

    Γ(α)2γλ(α,ba)[Iα,λa+lnf(b)+Iα,λblnf(a)]12[lnf(a)+lnf(b)].

    Consequently, we have the following inequality

    e[Iα,λa+lnf(b)+Iα,λblnf(a)]Γ(α)2γλ(α,ba)f(a)f(b),

    i.e.

    [aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)f(a)f(b).

    This ends the proof.

    Remark 2. Considering Theorem 5, we have the following conclusions:

    (i) The inequalities (2.3) are equivalent to the following inequalities:

    lnf(a+b2)Γ(α)2γλ(α,ba)[Iα,λa+lnf(b)+Iα,λblnf(a)]12[lnf(a)+lnf(b)].

    (ii) If we choose λ=0, then we have the following inequalities:

    f(a+b2)[aIαf(b)Iαbf(a)]Γ(α+1)2(ba)αf(a)f(b),

    which is given by Budak in [12].

    (iii) If we choose λ=0 and α=1, then we obtain Theorem 2 given by Ali et al. in [7].

    Corollary 1. Suppose that f and g are two positive and multiplicatively convex functions on [a,b], then we have

    f(a+b2)g(a+b2)[aIα,λfg(b)Iα,λbfg(a)]Γ(α)2γλ(α,ba)f(a)f(b)g(a)g(b). (2.6)

    Proof. As f and g are positive and multiplicatively convex, the function fg is positive and multiplicatively convex. If we apply Theorem 5 to the function fg, then we obtain the required inequalities (2.6).

    Remark 3. If we take λ=0 in Corollary 1, then we have the following inequalities:

    f(a+b2)g(a+b2)[aIαfg(b)Iαbfg(a)]Γ(α+1)2(ba)αf(a)f(b)g(a)g(b),

    which is established by Budak in [12]. Especially if we take α = 1, we obtain Theorem 7 in [7].

    Hermite–Hadamard's inequalities involving midpoint can be represented in the multiplicative tempered fractional integral forms as follows:

    Theorem 6. Under the same assumptions of Theorem 5, we have

    f(a+b2)[a+b2Iα,λf(b)Iα,λa+b2f(a)]Γ(α)2γλ(α,ba2)f(a)f(b), (2.7)

    where γλ(,) is the λ-incomplete gamma function.

    Proof. On account of the multiplicative convexity of f on interval [a,b], we have

    f(a+b2)=f[12(t2a+2t2b)+12(2t2a+t2b)],

    i.e.

    lnf(a+b2)12[lnf(t2a+2t2b)+lnf(2t2a+t2b)]. (2.8)

    Multiplying both sides of (2.8) by tα1eλ(ba)2t then integrating the resulting inequality with respect to t over [0, 1], we obtain

    lnf(a+b2)10tα1eλ(ba)2tdt12[10tα1eλ(ba)2tlnf(t2a+2t2b)dt+10tα1eλ(ba)2tlnf(2t2a+t2b)dt].

    That is,

    2α(ba)αγλ(α,ba2)lnf(a+b2)2α1(ba)αΓ(α)[Iα,λ(a+b2)+lnf(b)+Iα,λ(a+b2)lnf(a)],

    which yields that,

    f(a+b2)e[Iα,λ(a+b2)+lnf(b)+Iα,λ(a+b2)lnf(a)]Γ(α)2γλ(α,ba2)=[a+b2Iα,λf(b)Iα,λa+b2f(a)]Γ(α)2γλ(α,ba2).

    This completes the proof of the first inequality in inequalities (2.7).

    On the other hand, as f is multiplicatively convex, we get

    f(t2a+2t2b)[f(a)]t2[f(b)]2t2,

    and

    f(2t2a+t2b)[f(a)]2t2[f(b)]t2.

    Thus, we have

    lnf(t2a+2t2b)+lnf(2t2a+t2b)lnf(a)+lnf(b). (2.9)

    Multiplying both sides of (2.9) by tα1eλ(ba)2t then integrating the resulting inequality with respect to t over [0, 1], we have

    2α(ba)αΓ(α)[Iα,λ(a+b2)+lnf(b)+Iα,λ(a+b2)lnf(a)]2α(ba)αγλ(α,ba2)[lnf(a)+lnf(b)],

    i.e.

    Γ(α)2γλ(α,ba2)[Iα,λ(a+b2)+lnf(b)+Iα,λ(a+b2)lnf(a)]12[lnf(a)+lnf(b)].

    Consequently, we get the inequality

    [a+b2Iα,λf(b)Iα,λa+b2f(a)]Γ(α)2γλ(α,ba2)f(a)f(b).

    This ends the proof.

    Next, we are going to establish several integral inequalities concerning the multiplicative tempered fractional integral operators. To this end, we present the following lemma.

    Lemma 1. Let f:IRR+ be a differentiable mapping on I, a,bI with a<b. If f is integrable on [a,b], then we have

    f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)=10[f(ta+(1t)b)η(γλ(ba)(α,t)γλ(ba)(α,1t))]dt, (2.10)

    where

    η=(ba)α2γλ(α,ba). (2.11)

    Proof. Applying the multiplicative integration by parts, we have

    10[f(ta+(1t)b)η(γλ(ba)(α,t)γλ(ba)(α,1t))]dt=f(a)ηγλ(ba)(α,1)f(b)ηγλ(ba)(α,1)110(f(ta+(1t)b)η(tα1eλ(ba)t+(1t)α1eλ(ba)(1t)))dt=[f(a)f(b)]ηγλ(ba)(α,1)exp{10ηlnf(ta+(1t)b)tα1eλ(ba)tdt+10ηlnf(ta+(1t)b)(1t)α1eλ(ba)(1t)dt}=[f(a)f(b)]ηγλ(α,ba)(ba)αexp{I1+I2}.

    Utilizing the changed variable, we obtain

    I1=η10lnf(ta+(1t)b)tα1eλ(ba)tdt=η(ba)αbalnf(u)(bu)α1eλ(bu)du=ηΓ(α)(ba)αIα,λa+lnf(b),

    and

    I2=η10lnf(ta+(1t)b)(1t)α1eλ(ba)(1t)dt=η(ba)αbalnf(u)(ua)α1eλ(ua)du=ηΓ(α)(ba)αIα,λblnf(a).

    Then, we have

    10[f(at+(1t)b)η(γλ(ba)(α,t)γλ(ba)(α,1t))]dt=f(a)f(b)exp{Γ(α)2γλ(α,ba)[Iα,λa+lnf(b)+Iα,λblnf(a)]}=f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba).

    This ends the proof.

    Remark 4. Considering Lemma 1, we have the following conclusions:

    (i) If we take λ=0, then we have

    f(a)f(b)[aIαf(b)Iαbf(a)]Γ(α+1)2(ba)α=10(f(ta+(1t)b)12[tα(1t)α])dt. (2.12)

    (ii) If we take λ=0 and α=1, then we have

    f(a)f(b)ba(f(u)1ba)du=10(f(ta+(1t)b)12(2t1))dt. (2.13)

    It is worth mentioning that, to the best of our knowledge, the identities (2.12) and (2.13) obtained here are new in the literature.

    Theorem 7. Let f:IRR+ be a differentiable mapping on I, a,bI with a<b. If |f| is multiplicatively convex on [a,b], then we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|[|f(a)||f(b)|]ηδ, (2.14)

    where η is defined by (2.11) in Lemma 1 and

    δ=γλ(α,ba)(ba)αγλ(α,ba2)(ba)α+2γλ(α+1,ba2)(ba)α+1γλ(α+1,ba)(ba)α+1. (2.15)

    Proof. Making use of Lemma 1, we deduce

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|=|10[f(at+(1t)b)η(γλ(ba)(α,t)γλ(ba)(α,1t))]dt|exp{10|lnf(at+(1t)b)η[γλ(ba)(α,t)γλ(ba)(α,1t)]|dt}=exp{10|η[γλ(ba)(α,t)γλ(ba)(α,1t)]||lnf(at+(1t)b)|dt}. (2.16)

    As t[0,1], we can know

    |γλ(ba)(α,t)γλ(ba)(α,1t)|={ 1ttuα1eλ(ba)udu,0t12,t1tuα1eλ(ba)udu,12<t1. (2.17)

    Since |f| is multiplicatively convex, we get

    |lnf(ta+(1t)b)|tln|f(a)|+(1t)ln|f(b)|. (2.18)

    If we apply (2.17) and (2.18) to the inequality (2.16), we obtain

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{η120 1ttuα1eλ(ba)udu[tln|f(a)|+(1t)ln|f(b)|]dt+η112t1tuα1eλ(ba)udu[tln|f(a)|+(1t)ln|f(b)|]dt}=exp{ηln|f(a)|1201tttuα1eλ(ba)ududt+ηln|f(b)|1201tt(1t)uα1eλ(ba)ududt+ηln|f(a)|112t1ttuα1eλ(ba)ududt+ηln|f(b)|112t1t(1t)uα1eλ(ba)ududt}=exp{η(ln|f(a)|Δ1+ln|f(b)|Δ2+ln|f(a)|Δ3+ln|f(b)|Δ4)}.

    Here, let's evaluate an integral by changing the order of it.

    Δ1=1201tttuα1eλ(ba)ududt=120u0tuα1eλ(ba)udtdu+1121u0tuα1eλ(ba)udtdu=12[120uα+1eλ(ba)udu+112(u22u+1)uα1eλ(ba)udu]=12[γλ(ba)(α+2,12)+112uα+1eλ(ba)udu2112uαeλ(ba)udu+112uα1eλ(ba)udu]=12{γλ(ba)(α+2,12)+[γλ(ba)(α+2,1)γλ(ba)(α+2,12)]2[γλ(ba)(α+1,1)γλ(ba)(α+1,12)]+[γλ(ba)(α,1)γλ(ba)(α,12)]}. (2.19)

    Analogously, we can get

    Δ2=12{2γλ(ba)(α+1,12)γλ(ba)(α+2,12)+[γλ(ba)(α,1)γλ(ba)(α,12)][γλ(ba)(α+2,1)γλ(ba)(α+2,12)]}, (2.20)
    Δ3=12{2γλ(ba)(α+1,12)γλ(ba)(α+2,12)+[γλ(ba)(α,1)γλ(ba)(α,12)][γλ(ba)(α+2,1)γλ(ba)(α+2,12)]}, (2.21)

    and

    Δ4=12{γλ(ba)(α+2,12)+[γλ(ba)(α+2,1)γλ(ba)(α+2,12)]2[γλ(ba)(α+1,1)γλ(ba)(α+1,12)]+[γλ(ba)(α,1)γλ(ba)(α,12)]}. (2.22)

    Consequently,

    ln|f(a)|Δ1+ln|f(b)|Δ2+ln|f(a)|Δ3+ln|f(b)|Δ4=[ln|f(a)|+ln|f(b)|][γλ(α,ba)(ba)αγλ(α,ba2)(ba)α+2γλ(α+1,ba2)(ba)α+1γλ(α+1,ba)(ba)α+1].

    Thus, we deduce

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{η[ln|f(a)|+ln|f(b)|][γλ(α,ba)(ba)αγλ(α,ba2)(ba)α+2γλ(α+1,ba2)(ba)α+1γλ(α+1,ba)(ba)α+1]}=exp{ηδ[ln|f(a)|+ln|f(b)|]}=[|f(a)||f(b)|]ηδ.

    The proof is completed.

    Theorem 8. Let f:IRR+ be a differentiable mapping on I, a,bI with a<b. For q>1 with p1+q1=1, if |f|q is multiplicatively convex on [a,b], then we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{ητ1p(ln|f(a)|q+ln|f(b)|q2)1q}, (2.23)

    where η is defined by (2.11) in Lemma 1 and

    τ=10|γλ(ba)(α,t)γλ(ba)(α,1t)|pdt.

    Proof. Making use of Lemma 1 and Hölder's inequality, we deduce

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|=|10[f(at+(1t)b)η(γλ(ba)(α,t)γλ(ba)(α,1t))]dt|exp{10|lnf(at+(1t)b)η[γλ(ba)(α,t)γλ(ba)(α,1t)]|dt}=exp{10|η[γλ(ba)(α,t)γλ(ba)(α,1t)]lnf(at+(1t)b)|dt}=exp{10|η[γλ(ba)(α,t)γλ(ba)(α,1t)]||lnf(at+(1t)b)|dt}. (2.24)

    Due to the Hölder's inequality, we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{η(10|γλ(ba)(α,t)γλ(ba)(α,1t)|pdt)1p×(10|lnf(ta+(1t)b)|qdt)1q}. (2.25)

    By virtue of the multiplicative convexity of |f|q, we obtain

    10|lnf(at+(1t)b)|qdt10[tln|f(a)|q+(1t)ln|f(b)|q]dt=ln|f(a)|q+ln|f(b)|q2. (2.26)

    Combining (2.26) with (2.25), we know that Theorem 8 is true. Thus the proof is completed.

    Remark 5. Considering Theorem 8, we have the following conclusions:

    (i) If we choose λ=0, then we have

    |f(a)f(b)[aIαf(b)Iαbf(a)]Γ(α+1)2(ba)α|exp{12(10|tα(1t)α|pdt)1p(ln|f(a)|q+ln|f(b)|q2)1q}exp{12(1αp+1(212αp1))1p(ln|f(a)|q+ln|f(b)|q2)1q}.

    To prove the second inequality above, we use the fact

    [(1t)αtα]p(1t)αptαp,

    for t [0,12] and

    [tα(1t)α]ptαp(1t)αp,

    for t [12,1], which follows from (AB)q AqBq for any AB0 and q1.

    (ii) If we choose λ=0 and α=1, then we have

    f(a)f(b)ba(f(u)1ba)duexp{12(1p+1)1p(ln|f(a)|q+ln|f(b)|q2)1q}.

    Theorem 9. Let f:IRR+ be a differentiable mapping on I, a,bI with a<b. If |f|q, q>1, is multiplicatively convex on [a,b], then we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{211qηδ(ln|f(a)|q+ln|f(b)|q)1q}, (2.27)

    where η is defined by (2.11) in Lemma 1 and δ is defined by (2.15) in Theorem 7, respectively.

    Proof. Continuing from the inequality (2.24) in the proof of Theorem 8, using the power-mean inequality, we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{η(10|γλ(ba)(α,t)γλ(ba)(α,1t)|dt)11q×(10|γλ(ba)(α,t)γλ(ba)(α,1t)||lnf(at+(1t)b)|qdt)1q}.

    For the convenience of expression, let us define the quantities

    J1=10|γλ(ba)(α,t)γλ(ba)(α,1t)|dt,

    and

    J2=10|γλ(ba)(α,t)γλ(ba)(α,1t)||lnf(at+(1t)b)|qdt.

    According to the equalities (2.17), we have

    J1=1201ttuα1eλ(ba)ududt+112t1tuα1eλ(ba)ududt=2{2γλ(ba)(α+1,12)+[γλ(ba)(α,1)γλ(ba)(α,12)]γλ(ba)(α+1,1)}. (2.28)

    Utilizing the multiplicative convexity of |f|q, we obtain

    J210|γλ(ba)(α,t)γλ(ba)(α,1t)|[tln|f(a)|q+(1t)ln|f(b)|q]dt=1201ttuα1eλ(ba)u[tln|f(a)|q+(1t)ln|f(b)|q]dudt+112t1tuα1eλ(ba)u[tln|f(a)|q+(1t)ln|f(b)|q]dudt=ln|f(a)|q1201tttuα1eλ(ba)ududt+ln|f(b)|q1201tt(1t)uα1eλ(ba)ududt+ln|f(a)|q112t1ttuα1eλ(ba)ududt+ln|f(b)|q112t1t(1t)uα1eλ(ba)ududt=ln|f(a)|qΔ1+ln|f(b)|qΔ2+ln|f(a)|qΔ3+ln|f(b)|qΔ4,

    where Δi(i=1,2,3,4) are given by (2.19)–(2.22) in the proof of Theorem 7, respectively.

    Consequently,

    ln|f(a)|qΔ1+ln|f(b)|qΔ2+ln|f(a)|qΔ3+ln|f(b)|qΔ4=[ln|f(a)|q+ln|f(b)|q][γλ(α,ba)(ba)αγλ(α,ba2)(ba)α+2γλ(α+1,ba2)(ba)α+1γλ(α+1,ba)(ba)α+1]. (2.29)

    Combining (2.28) with (2.29), we have

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|exp{η(2δ)11q(δ(ln|f(a)|q+ln|f(b)|q))1q}=exp{211qηδ(ln|f(a)|q+ln|f(b)|q)1q}.

    The proof is completed.

    The main point of the results established in this paper is that the calculation of the right-hand side is much easier than that of the left-hand side. To show this, three interesting examples are demonstrated below.

    Example 1. Let the log-convex function f: (0,)(0,) be defined by f(x)=2x23. If we take a=1,b=2, α=12 and λ=14, then all assumptions in Theorem 5 are satisfied.

    The left-hand side term of (2.3) is

    f(a+b2)=f(1+22)=2340.5946.

    The middle term of (2.3) is

    [aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)=[eI12,141+lnf(2)eI12,142lnf(1)]Γ(12)2γ14(12,1)=[e21(u23)ln2(2u)12e14(2u)du+21(u23)ln2(u1)12e14(u1)du]1210u12e14udu0.6461.

    The right-hand side term of (2.3) is

    f(a)f(b)=f(1)f(2)=2120.7071.

    It is clear that 0.5946<0.6461<0.7071, which demonstrates the result described in Theorem 5.

    Example 2. Let the log-convex function f: (0,)(0,) be defined by f(x)=ex2. If we take a=1,b=2, α=12 and λ=12, then all assumptions in Theorem 6 are satisfied.

    The left-hand side term of (2.7) is

    f(a+b2)=f(1+22)=e949.4877.

    The middle term of (2.7) is

    [a+b2Iα,λf(b)Iα,λa+b2f(a)]Γ(α)2γλ(α,ba2)=[eI12,1232+lnf(2)eI12,1232lnf(1)]Γ(12)2γ12(12,12)=[e232u2(2u)12e12(2u)du+321u2(u1)12e12(u1)du]12120u12e12udu10.9088.

    The right-hand side term of (2.7) is

    f(a)f(b)=f(1)f(2)=e5212.1825.

    It is clear that 9.4877<10.9088<12.1825, which demonstrates the result described in Theorem 6.

    Example 3. Let the log-convex function f(x)f(x): (0,)(0,) be defined by f(x)f(x)=1x. We can get f(x)=e1x, f(x)=x. If we take a=1,b=2, α=12 and λ=12, then all assumptions in Theorem 7 are satisfied.

    The left-hand side term of (2.14) is

    |f(a)f(b)[aIα,λf(b)Iα,λbf(a)]Γ(α)2γλ(α,ba)|=|f(1)f(2)[eI12,121+lnf(2)eI12,122lnf(1)]Γ(12)2γ12(12,1)|=|2[e21lnu(2u)12e12(2u)du+21lnu(u1)12e12(u1)du]12γ12(12,1)|0.9702.

    The right-hand side term of (2.14) is

    [|f(a)||f(b)|]ηδ=(e32)12γ12(12,1)[γ12(12,1)γ12(12,12)+2γ12(32,12)γ12(32,1)]1.1480.

    It is clear that 0.9702<1.1480, which demonstrates the result described in Theorem 7.

    To the best of our knowledge, this is a first pervasive work on the multiplicative tempered fractional Hermite–Hadamard type inequalities via the multiplicatively convex functions. Two Hermite–Hadamard type inequalities for the multiplicative tempered fractional integrals are hereby established. An integral identity for differentiable mappings is presented. By using it, some estimates of the upper bounds pertaining to trapezoid type inequalities via the multiplicative tempered fractional integral operators are obtained. Inequalities obtained in this paper generalize some results given by Budak and Tunç (2020) and Ali et al. (2019). Also, three examples show that the calculation of the right-hand side is much easier than that of the left-hand side. The ideas and techniques of this article may inspire further research in this field. This promising field about the multiplicative tempered fractional inequalities is worth further exploration.

    The authors would like to thank the reviewer for his/her valuable comments and suggestions.

    The authors declare no conflict of interest.



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