
Citation: Wei Liu. Global injectivity of differentiable maps via W-condition in R2[J]. AIMS Mathematics, 2021, 6(2): 1624-1633. doi: 10.3934/math.2021097
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In this paper, we study the shapes of bifurcation curves of positive solutions for the one-dimensional Minkowski curvature problem
{−(u′√1−u′2)′=λf(u), x∈(−L,L),u(−L)=u(L)=0, | (1.1) |
where λ>0 is a bifurcation parameter, L>0 is a constant and f:[0,∞)→R is a continuous function. By a solution of Problem (1.1), we understand that it is a function that belongs to C1[0,1] with ||u′||∞<1, such that u′/√1−u′2 is differentiable and Problem (1.1) is satisfied.
Notice that Problem (1.1) is the one-dimensional version of the Dirichlet problem associated with the prescribed mean curvature equation in Minkowski space
{−div(∇u√1−|∇u|2)=λf(x,u), in Ω,u=0, on ∂Ω, | (1.2) |
where λ>0, Ω is a bounded domain in RN(N≥1) and the nonlinearity f:Ω×R→R is continuous.
Problem (1.2) comes from the study of spacelike submanifolds of codimension one in the flat Minkowski space LN+1 with a prescribed mean extrinsic curvature (see [7]), where LN+1:={(x,t):x∈RN, t∈R} is endowed with the Lorentzian metric ∑Ni=1(dxi)2−(dt)2. These kinds of problems originate from classical relativity. To determine the existence and regularity properties of maximal and constant mean curvature hypersurfaces is very important in classical relativity. These are spacelike submanifolds of codimension one in the spacetime manifold, with the property that the trace of the extrinsic curvature is zero and constant respectively. Such surfaces are important because they provide Riemannian submanifolds with properties that reflect those of the spacetime. Recently, a great deal of research has been devoted to the study of these types of problems; see [8,9,10,23] for zero or constant curvature, and [2,3] for variable curvature.
Recently, work led by Huang [15,16,17,18] used the time mapping to study the classification and evolution of bifurcation curves of positive solutions for Problem (1.1), where λ>0, f∈C[0,∞)∩C2(0,∞) and f(u)>0 for u≥0. However, to the authors' best knowledge, most of the results in the above-mentioned references are focused on f having a fixed sign while few works have considered that f may change its sign (see [3,4,20]).
On the other hand, the semilinear elliptic boundary value problem
△u+λf(u)=0 in Ω, u=0 on ∂Ω, | (1.3) |
and its special case
u″+λf(u)=0, t∈(0,1), u(0)=u(1)=0, | (1.4) |
have been extensively studied since early 1970s (see [1,5,6,19]). In 1979, Brown and Budin [6] applied the quadrature arguments to obtain the following result.
Theorem 1.1. Assume that f:[0,∞)→R satisfies the following:
(A1) f has a continuous derivative;
(A2) f(0)>0;
(A3) There exist a1,a2,⋯an∈R such that 0<a1<a2<⋯<an and f(ai)≤0 for i=1,2,⋯,n;
(A4) If F(u):=∫u0f(s)ds, there exist b1,⋯,bn−1 with a1<b1<a2<⋯<bn−1<an such that
f(bi)>0andF(bi)>F(u)for0≤u<bi, i=1,2,⋯,n−1. |
Then,
(a) For all λ>0, there exists a solution (λ,u) of Problem (1.4);
(b) If λ>inf{λ(ρ)|ρ∈(αi,βi)}, there exist at least two solutions (λ,u) of Problem (1.4) suchthat
αi≤||u||∞≤βi, i=1,2,⋯,n−1, |
where
βi=inf{u|u>bi,f(u)=0}, αi=inf{u|(u,βi)⊆S}, | (1.5) |
and S:={u|u>0,f(u)>0,F(u)>F(s) for all s:0≤s<u}, ||u||∞:=maxt∈[0,1]u(t);
(c) If (λ,u) is any solution of Problem (1.4) such that αi≤||u||∞≤βi, then λ>4αiM−1f, where Mf=sup{|f(u)||0≤u≤βi}.
However, to the best of our knowledge, the one-dimensional Minkowski-curvature problem given by Problem (1.1) wherein f undergoes a sign change, in spite of its simple looking structure, is considered to be a hard problem in the literature. One of the difficulties is related to developing some new time mapping techniques. The other difficulty is how to prove the direction of bifurcation curves.
Motivated by the interesting studies of [3,4,5,8,15,16,20,21] and some earlier works in the literature (see in particular [6] and the references therein), here, we continue the investigations into the bifurcation curves of positive solutions for Problem (1.1) when f may change its sign. To the best of our knowledge, such a scheme is completely new and has not been described before for related problems.
Throughout, we assume the following:
(H1) f∈C[0,∞)∩C2(0,∞);
(H2) There exist a1,a2,⋯,an∈R such that 0<a1<a2<⋯<an<L and f(ai)≤0 for i=1,2,⋯,n;
(H3) There exist b1,⋯,bn with a1<b1<a2<b2<⋯<an−1<bn−1<an<bn<L such that
f(s)>0,s∈(bn,L),f(bi)>0 and F(bi)>F(u) for 0≤u≤bi, i=1,2,⋯,n, |
where F(u)=∫u0f(s)ds.
Roughly speaking, the above hypotheses imply that, the graph of f has n+1 positive humps and n negative bumps, with each positive hump having a larger area than the previous negative hump.
The rest of the paper is organized as follows: Section 2 contains statements on the main result. Section 3 contains preparatory lemmas. Section 4 contains the proof of the result. Finally, in Section 5, we give two examples to illustrate the feasibility of our result.
In this section, in order to state our main result, we first give some terminologies related to the shape of the bifurcation curve. Let
SL:={(λ,||uλ||∞):λ>0 and uλ is a positive solution of Problem (1.1)} | (2.1) |
be the bifurcation curve for Problem (1.1) on the (λ,||u||∞) plane.
Definition 2.1 [15,18] Let SL be the bifurcation curve for Problem (1.1) on the (λ,||u||∞) plane.
(i) S-like shaped: The curve SL is said to be S-like shaped if SL has at least two turning points at some points (λ1,||uλ1||∞) and (λ2,||uλ2||∞) where λ1<λ2 are two positive numbers such that:
(a) At (λ1,||uλ1||∞), the bifurcation curve SL turns to the right;
(b) ||uλ2||∞<||uλ1||∞;
(c) At (λ2,||uλ2||∞), the bifurcation curve SL turns to the left.
(ii) Monotone increasing: The curve SL is said to be monotone increasing if SL is a continuous curve and for each pair of points (λ1,||uλ1||∞) and (λ2,||uλ2||∞) of SL, ||uλ1||∞<||uλ2||∞ implies λ1≤λ2.
(iii) ⊂-shaped: The curve SL is said to be ⊂-shaped if SL is a continuous curve that initially continues to the left and eventually continues to the right.
Throughout this paper, assume, in addition to (H1)–(H3), that f satisfies one of the following several possibilities:
(C1) f0=0 and limu→0+f″(u)∈(0,∞], where f0:=lims→0f(s)s.
(C2) f0=∞.
(C3) f0∈(0,∞) and limu→0+f″(u)∈(0,∞].
(C4) f0∈(0,∞) and limu→0+f″(u)∈(−∞,0].
Theorem 2.1. Assume that (H1)–(H3) hold. Then
(i) (See Figure 1) The bifurcation curve SL starts from (K,0) and goes to infinity along the horizontal line ||u||∞=r (r be as in (3.8)), where
K≡{∞, if f0=0,π24f0L2, if f0∈(0,∞),0, if f0=∞. |
Furthermore, if either (C1) and (C3) holds, then SL is ⊂-shaped; if either (C2) and (C4) holds, then SL is either monotone increasing or S-like shaped.
(ii) The bifurcation curve SL is ⊂-shaped for all ρ∈(αi,βi), i=1,2,⋯,n−1, where
βi=inf{u|u>bi,f(u)=0}, αi=inf{u|(u,βi)⊆S}, |
ρ is defined in Problem (3.1) and S={u|u>0,f(u)>0,F(u)>F(s) for all s:0≤s<u}.
(iii) The bifurcation curve SL is ⊂-shaped for all ρ∈(αn,L), where αn=inf{u|(u,βn)⊆S}.
Corollary 2.1. (See Figure 2) Assume that (H1)–(H3) hold. Then for all ρ∈S, we have the following:
(i) If f0∈(0,∞), then Problem (1.1) has a positive solution (λ,u) satisfying ||u||∞<r for all λ>π24f0L2; if f0=0, then Problem (1.1) has at least two positive solutions (λ,u1) and (λ,u2) satisfying 0<||u1||∞<||u2||∞<r for all λ>inf{λ(ρ)|ρ∈(0,r)}; if f0=∞, then for all λ>0, Problem (1.1) has at least one positive solution (λ,u) satisfying 0<||u||∞<r.
(ii) If λ>inf{λ(ρ)|ρ∈(αi,βi)}, then Problem (1.1) has at least two positive solutions (λ,ui1) and (λ,ui2) satisfying αi<||ui1||∞<||ui2||∞<βi, i=1,⋯,n−1.
Remark 2.1. Conditions (H2) and (H3) contain three cases:
Case 1. f(ai)=0, and bi∈(ai,ai+1),i=1,2,⋯,n;
Case 2. f(ai)<0, and bi,i=1,2,⋯,n satisfies (H3). Roughly speaking, the graph of f has n+1 positive humps and n negative bumps, with each positive hump having a larger area than the previous negative hump (see Figure 3).
Case 3. f(ai)<0 for some i∈I0⊆I:={1,2,⋯,n}, and f(ai)=0, for i∈I∖I0, where bi,i=1,2,⋯,n, satisfies (H3).
Remark 2.2. It is worth remarking that References [8,11,12,13,14,15,16,17,18,22,24] provided some sufficient conditions to determine the shape of the bifurcation curve or multiplicity of positive solutions of Problem (1.1) or (1.2) with the general f∈C([0,∞),[0,∞)). However, these results cannot be applied to our Problem (1.1) because the nonlinearity f in this paper is not always positive in [0,∞).
Remark 2.3. Let (λ,u) be a solution of Problem (1.1), then, it follows from ||u′||∞<1 that
||u||∞<L. |
This causes the bifurcation diagrams to be mainly dependent on the behavior of f=f(s) near s=0. In addition, if we compare it with known results for semilinear elliptic problems with convex-concave nonlinearities, the bifurcation diagram is reversed in some sense. This reveals a significant difference between Minkowski curvature problems and corresponding semilinear elliptic problems.
Remark 2.4. Note that the condition f(0)>0 is a special case of Condition (C2), so Theorem 2.1 improves and generalizes the main result in [20].
Remark 2.5. By virtue of quadrature arguments, Ma and Lu [20] presented a full description of the set of positive solutions of Problem (1.1) for certain classes of f nonlinearity (that is, f(0)>0, or f(0)=0, f0>0), they provided no information about the directions of a bifurcation. Therefore, our main result generalizes generalize and improves the main result in [20].
In this section, we shall make a detailed analysis of the so-called time map for Problem (1.1). Various properties of the time map will be used to obtain the existence and multiplicity results of the positive solutions for Problem (1.1).
Lemma 3.1. Suppose that f:R→R is continuous. Let (λ,u) be a positive solution of Problem (1.1) with ||u||∞=ρ∈S and λ>0. Let x0∈(−L,L) be such that u′(x0)=0. Then,
(i) x0=0;
(ii) x0 is the unique point at which u attains its maximum;
(iii) u′(x)>0,x∈(−L,x0) and u′(x)<0,x∈(x0,L).
Proof. The arguments are quite similar to those from the proof of Lemma 2.4 in [20]. However, for the sake of completeness, we give a sketch of the proof below.
(i) Suppose on the contrary that x0≠0 also without loss of generality, suppose that x0<0, then, u(2x0−x) is also a solution of Problem (1.1). Moreover,
u(x0)=u(2x0−x0),u′(x0)=u′(2x0−x0)=0. |
Therefore, by the uniqueness of the associated Cauchy problem, we have that u(x)=u(2x0−x) for all x∈[−L,L]. In particular, 0=u(−L)=u(L+2x0), which contradicts the fact that u(x)>0 for all x∈(−L,L). Similarly, if x0>0, we get a similar contradiction. Therefore, x0=0.
(ii) Suppose on the contrary that there exists x1∈(−L,L) with x1≠x0 such that u(x1)=u(x0)=ρ. Without loss of generality, assume that x1<x0. Because x1>x0 can be treated in a similar way, if u(x)=u(x0) for x∈(x1,x0), then from [20, Lemma 2.3], we have that
u(x)≡u(x0)=ρ>0,x∈(−L,L). |
This contradicts the boundary conditions u(−L)=u(L)=0. Therefore, u(x)≢u(x0) in any subinterval of (−L,L). So, there exists x∗∈(x1,x0) such that
u(x∗)=min{u(x)|x∈(x1,x0)}. |
Clearly, 0<u(x∗)<ρ and u′(x∗)=0. Multiplying both sides of the equation given by Problem (1.1) by u′ and integrating from x to x0, we get that, for x∈[−L,0],
(u′(x))2=√1−(u′(x))2[1−√1−(u′(x))2+λ(F(ρ)−F(u(x)))]. |
Subsequently,
0=(u′(x∗)2=√1−(u′(x∗))2[1−√1−(u′∗(x))2+λ(F(ρ)−F(u(x∗)))]=1+λ(F(ρ)−F(u(x∗)))>0. |
This is a contradiction because of ρ∈S and u(x∗)<ρ. Thus, x0 is unique and u(0)>u(t), t∈[−L,0). By a similar argument, we can prove that u(0)>u(t), t∈(0,L]. Therefore, x0=0 is the unique point on which u attains its maximum.
(iii) Suppose on the contrary that there exists ˆx∈(−L,0) with u′(ˆx)=0. Then u(ˆx)<ρ. Therefore,
0=(u′(ˆx))2=1+λ(F(ρ)−F(u(ˆx))). |
This contradicts the fact that ρ∈S and u(ˆx)<ρ. Thus, u′(t)>0, t∈(−L,0). By a similar argument, it follows that u′(t)<0, t∈(0,L).
By Lemma 3.1, we know that u(x) takes its maximum at 0 and u(x) is symmetric with respect to 0, u′(x)>0 for −L≤x<0 and u′(x)<0 for 0<x≤L. Hence, Problem (1.1) is equivalent to the following problem defined on [0,L]:
{(u′√1−u′2)′+λf(u)=0, x∈(0,L),u′(0)=u(L)=0, u(0)=ρ∈S. | (3.1) |
To prove Theorem 2.1, we shall first define the time-map formula for Problem (3.1) as
Tλ(ρ)=∫ρ01+λF(ρ)−λF(u)√[1+λF(ρ)−λF(u)]2−1du with ρ∈S. | (3.2) |
Notice that the function Tλ(ρ) is well-defined and continuous on ρ∈S (see [20]). Therefore, the positive solutions uλ∈C2(−L,L)∩C[−L,L] of Problem (3.1) correspond to curves for which
||uλ||∞=ρ∈S and Tλ(ρ)=L. |
So, by the definition of SL in Eq (2.1), we may see that
SL={(λ,ρ):Tλ(ρ)=L for λ>0,ρ∈S}={(λL(ρ),ρ):ρ∈S}. | (3.3) |
This leads us to investigate the shape of Tλ(ρ).
By an argument similar to proving [20, Lemma 3.1] with obvious changes, we may obtain the following result.
Lemma 3.2. If ρ∈S, then there exists a unique λ>0 such that (λ,u) is a positive solution of Problem (3.1) satisfying ||u||∞=ρ. Moreover, the bifurcation curve {(λL(ρ),ρ):ρ∈S} is continuous on the (λ,||u||∞)-plane.
Lemma 3.3. Consider Problem (3.1). Then
limρ→0+Tλ(ρ)={0, if f0=∞,π2√λf0, if f0∈(0,∞), for λ>0,∞, if f0=0. |
Proof. Assume that f0=0 or f0∈(0,∞). By L'Hopital's rule, we observe that, for 0<t<1,
limρ→0+F(ρ)−F(ρt)ρ2=limρ→0+f(ρ)−tf(ρt)2ρ=(1−t2)f02. | (3.4) |
Assume that f0=∞. If f(0)>0, we apply L'Hopital's rule to get
limρ→0+F(ρ)−F(ρt)ρ2=limρ→0+f(ρ)−tf(ρt)2ρ=∞. |
If f(0)=0, and by L'Hopital's rule, we observe that limu→0+f′(u)=∞; for 0<t<1,
limρ→0+F(ρ)−F(ρt)ρ2=limρ→0+f(ρ)−tf(ρt)2ρ≥limρ→0+f(ρt)−tf(ρt)2ρ=(1−t)tlimρ→0+f(ρt)2ρt=∞. |
Therefore,
limρ→0+F(ρ)−F(ρt)ρ2={∞, if f0=∞,1−t22f0, if f0∈(0,∞),0, if f0=0. | (3.5) |
By Eq (3.5), we have
limρ→0+Tλ(ρ)=limρ→0+ρ∫101+λ(F(ρ)−F(ρt))√λ2[F(ρ)−F(ρt)]2+2λ[F(ρ)−F(ρt)]dt=limρ→0+∫101+λ(F(ρ)−F(ρt))√{λ2[F(ρ)−F(ρt)]+2λ}[F(ρ)−F(ρt)ρ2]dt={0, if f0=∞,π2√2λf0, if f0∈(0,∞),∞, if f0=0. |
The proof of Lemma 3.3 is complete.
Using an argument similar to proving [16, Lemma 3.2] with obvious changes, we have the following lemma.
Lemma 3.4. Consider Problem (3.1). Then
limρ→0+T′λ(ρ)={−∞, if limu→0+f″(u)=∞,−13f0√λf0limu→0+f″(u), if limu→0+f″(u) exists, for λ>0,∞, if limu→0+f″(u)=−∞. |
Lemma 3.5. Consider Problem (3.1). Then for any ρ∈S, the following statements (i) and (ii) hold:
(i) ∂Tλ(ρ)/∂λ<0 for λ>0 and ρ∈S;
(ii) Assume 3f(u)+uf′(u)>0 for 0<u<r. Then
∂∂λ[√λT′λ(ρ)]=√λ∂∂λT′λ(ρ)+12√λT′λ(ρ)>0 for λ>0, ρ∈S. |
Proof. Let B=B(ρ,u)≡F(ρ)−F(u), combining this with the fact that f(s)>0 for s∈S gives
B(ρ,u)=F(ρ)−F(u)=∫ρuf(t)dt>0 for ρ∈S and 0<u<r. | (3.6) |
By Eqs (3.2) and (3.6), we see that
∂∂λTλ(ρ)=∫ρ0−B(ρ,u)[λ2B2(ρ,u)+2λB(ρ,u)]3/2du<0 for λ>0, ρ∈S. |
So Statement (i) holds.
Let
A(ρ,u)≡ρf(ρ)−uf(u). |
It is easy to check that
T′λ(ρ)=1ρ∫ρ0λ3B3+3λ2B2+λ(2B−A)(λ2B2+2λB)3/2du for λ>0,ρ∈S. |
Since A(ρ,ρ)+2B(ρ,ρ)=0 and
∂∂u[A(ρ,u)+2B(ρ,u)]=−[3f(u)+uf′(u)]<0 for 0<u<r, |
we observe that
A(ρ,u)+2B(ρ,u)>0 for 0<u<r. | (3.7) |
Then by Eqs (3.6) and (3.7), we see that, for λ>0 and ρ∈S,
∂∂λ[√λT′λ(ρ)]=√λ∂∂λT′λ(ρ)+12√λT′λ(ρ)=12ρ√λ∫ρ0λ3B2(B3λ2+5B2λ+3A+6B)λ2B2+2λB5/2du>0. |
So Statement (ii) holds. The proof is complete.
Lemma 3.6. sgn(λ′L(ρ))=sgn(T′λL(ρ)(ρ)) for ρ∈S, where sgn(u) is the signum function.
Proof. Since limλ→0+Tλ(ρ)=∞ and limλ→∞Tλ(ρ)=ρ for ρ∈S. By Lemma 3.2, there exists a unique λL(ρ)>0 such that TλL(ρ)(ρ)=L for ρ∈S. Since
0=∂∂ρTλL(ρ)(ρ)=T′λL(ρ)(ρ)+∂∂λTλ(ρ)|λ=λL(ρ)λ′L(ρ) for ρ∈S. |
So by Lemma 3.5(i), we can obtain the desired result.
Let
r:=inf{u>0:f(u)=0}. | (3.8) |
Since f(u)>0, 0<u<r. Then (0,r)⊆S.
By the definitions of βi and αi, we have
ai≤αi<bi<βi≤ai+1≤αi+1<⋯ |
and (αi,βi)⊆S for i=1,2,⋯,n−1.
Lemma 3.7. Consider Problem (3.1). Then we have limρ→0+λL(ρ)=K, where K is defined in Theorem 2.1. Moreover, the bifurcation curve SL starts from the point (K,0) and goes to infinity along the horizontal line ||u||∞=r.
Proof. We divide the proof into the following four steps.
Step 1. We prove that limρ→0+λL(ρ)=0 if f0=∞. Assume that f0=∞. If lim supρ→0+λL(ρ)>0, there exist M1>0 and {ρn}n∈N⊂(0,r) such that
limn→∞ρn=0 and λL(ρn)>M1 for n∈N. | (3.9) |
Since TλL(ρ)(ρ)=L, and by Lemmas 3.3 and 3.5 and Eq (3.9), we see that
L=limn→∞TλL(ρn)(ρn)≤limn→∞TM1(ρn)=0, |
which is a contradiction. Thus, limρ→0+λL(ρ)=0.
Step 2. We prove that limρ→0+λL(ρ)=∞ if f0=0. Assume that f0=0. If lim infρ→0+λL(ρ)<∞, there exist M2>0 and {ρn}n∈N⊂(0,r) such that
limn→∞ρn=0 and λL(ρn)<M2 for n∈N. | (3.10) |
Since TλL(ρ)(ρ)=L, and by Lemmas 3.3 and 3.5 and Eq (3.10), we see that
L=limn→∞TλL(ρn)(ρn)≥limn→∞TM2(ρn)=∞, |
which is a contradiction. Thus limρ→0+λL(ρ)≥lim infρ→0+λL(ρ)=∞.
Step 3. Inspired by the idea presented in [20], we prove that limρ→0+λL(ρ)=π24f0L2 if f0∈(0,∞). Since f0∈(0,∞), for any ϵ>0, there exists 0<δ<r such that
|f(u)u−f0|<ϵ, ∀ 0<u<δ. |
Thus, if ρ<δ, then
(f0−ϵ)(ρ2−u22)≤F(ρ)−F(u)=∫ρuf(s)ds≤(f0+ϵ)(ρ2−u22). |
This together with Eq (3.2) yields that
L=∫ρ0du√1−[1+λ(F(ρ)−F(u))]−2≤ρ∫10dt√1−[1+λ(f0−ϵ)ρ2(1−t2)2]−2=ρ∫101+λ(f0−ϵ)2ρ2(1−t2)√[λ(f0−ϵ)ρ2(1−t2)2]2+λ(f0−ϵ)ρ2(1−t2)dt=1√λ(f0−ϵ)∫101+λ(f0−ϵ)2ρ2(1−t2)√λρ24(1−t2)2(f0−ϵ)+(1−t2)dt, |
and
L=∫ρ0du√1−[1+λ(F(ρ)−F(u))]−2≥ρ∫10dt√1−[1+λ(f0+ϵ)ρ2(1−t2)2]−2=1√λ(f0+ϵ)∫101+λ(f0+ϵ)2ρ2(1−t2)√λρ24(1−t2)2(f0+ϵ)+(1−t2)dt, |
which imply that
√λ≤1√(f0−ϵ)L∫101+λ(f0−ϵ)2ρ2(1−t2)√λρ24(1−t2)2(f0−ϵ)+(1−t2)dt, |
and
√λ≥1√(f0+ϵ)L∫101+λ(f0+ϵ)2ρ2(1−t2)√λρ24(1−t2)2(f0+ϵ)+(1−t2)dt, |
and subsequently,
π2√f0L=limρ→01√(f0+ϵ)L⋅π2=limρ→01√(f0+ϵ)L∫10dt√1−t2≤limρ→0√λL(ρ)≤limρ→01√(f0−ϵ)L∫10dt√1−t2=limρ→01√(f0−ϵ)L⋅π2=π2√f0L for ϵ>0 small enough as ρ→0. |
Therefore, we have that
limρ→0λL(ρ)=π24f0L2. |
Step 4. We prove that limρ→r−λL(ρ)=∞.
From the definition of r, we have that
f(r)=0 and limu→r−f(u)u=0. |
Hence, for any ϵ>0, there exists δ∈(0,r) such that
f(u)≤ϵu, ∀r−δ<u<r, |
and for ρ<r, it follows that
F(ρ)−F(u)=∫ρuf(s)ds≤ϵ∫ρusds=ϵ(ρ2−u2)2. |
This together with Eq (3.2) implies that
L=∫ρ0du√1−[1+λ(F(ρ)−F(u))]−2≥∫ρ0du√1−[1+λϵ(ρ2−u2)/2]−2=∫102+λϵρ2(1−t2)√λ2ϵ2ρ4(1−t2)2+4λϵρ2(1−t2)dt, |
which implies that
√λL(ρ)≥1√ϵL∫102+λϵρ2(1−t2)√λϵρ4(1−t2)2+4ρ2(1−t2)dt. |
So, we get that
limρ→r−√λL(ρ)≥limρ→r−1√ϵLr∫101√1−t2dt=∞, for ϵ>0 small enough as ρ→r−, |
that is
limρ→r−λL(ρ)=∞. |
Proof of Theorem 2.1. (i) Let L>0 be given. By Lemmas 3.2 and 3.7, the bifurcation curve SL of Problem (3.1) is continuous in the (λ,||u||∞) plane, starts from the point (K,0) and goes to infinity along the horizontal line ||u||∞=r. Next, we divide the remainder proofs of Theorem 2.1(i) into the following two steps.
Step 1. Assume that (C1) holds. By Lemma 3.7, we see that
limρ→0+λL(ρ)=limρ→r−λL(ρ)=∞. |
So SL is ⊂-shaped. Assume that (C3) holds. By Lemma 3.4, we see that
limρ→0+T′π24f0L2(ρ)<0. |
Then there exists δ1∈(0,r) such that
T′π24f0L2(ρ)<0 for 0<ρ<δ1. | (4.1) |
Since f0∈(0,∞), and by Lemmas 3.2 and 3.3 and Eq (4.1), we observe that
Tπ24f0L2(ρ)<limρ→0+Tπ24f0L2(ρ)=π2√f0(π24f0L2)=L=TλL(ρ)(ρ) for 0<ρ<δ1. |
It follows that λL(ρ)<π24f0L2 for 0<ρ<δ1 by Lemma 3.5(i). Then by Lemma 3.5(ii) and Eq (4.1), we see that T′λL(ρ)(ρ)<0 for 0<ρ<δ1. By Lemmas 3.6 and 3.7, we further see that
limρ→r−λL(ρ)=∞ and λ′L(ρ)<0 for 0<ρ<δ1. |
So SL is ⊂-shaped by Lemma 3.2.
Step 2. Assume that (C2) holds. By Lemma 3.7, we see that
limρ→0+λL(ρ)=0 and limρ→r−λL(ρ)=∞. |
So SL is S-like shaped or monotone increasing by Lemma 3.2. Assume that (C4) holds. By Lemma 3.4, we have
limρ→0+T′π24f0L2(ρ)>0. |
By a similar proof in Step 1, there exists δ2>0 such that
limρ→r−λL(ρ)=∞ and λ′L(ρ)>0 for 0<ρ<δ2. |
So SL is S-like shaped or monotone increasing by Lemma 3.2.
(ii) The arguments are quite similar to those from the proof of Lemma 3.3 in [20]. However, for the sake of completeness, we give a sketch of the proof below. We considered two cases:
Case 1. Suppose that f(αi)>0. Since S is open, αi∉S, so, there exists p:0<p<αi such that F(αi)=F(p). Clearly, p must be a local maximum for F, so f(p)=0.
Let M3=max{|f′(u)||0≤u≤bi}, then, f(u)≤M3|u−p|, 0≤u≤bi. Let M4=max{|f(u)||0≤u≤bi}, then, for αi<ρ<bi,
F(ρ)−F(u)=F(ρ)−F(αi)+F(p)−F(u)=(ρ−αi)f(ζ)+(p−u)f(ξ), ∃ζ∈(αi,ρ),ξ∈(p,u)≤M4(ρ−αi)+M3(p−u)2=:κ(ρ,αi,u). |
So, we obtain that
L=∫ρ0du√1−[1+λ(F(ρ)−F(u))]−2≥∫ρ0du√1−[1+λκ(ρ,αi,u)]−2=1√λ∫ρ01+λ[κ(ρ,αi,u)]√2κ(ρ,αi,u)+λκ(ρ,αi,u)−2du, |
and
√λ≥1L∫ρ01+λ[κ(ρ,αi,u)]√2κ(ρ,αi,u)+λκ(ρ,αi,u)−2du≥1L∫αi01+λ[κ(ρ,αi,u)]√2κ(ρ,αi,u)+λκ(ρ,αi,u)−2du=1L∫αi0Hρ(u)du. |
As ρ→α+i, it is easy to verify that
Hρ(u)=∫αi01+λ[κ(ρ,αi,u)]√2κ(ρ,αi,u)+λκ(ρ,αi,u)−2du |
is a nondecreasing sequence of measurable functions. Therefore, by the monotone convergence theorem, it follows that
limρ→α+i√λL(ρ)≥limρ→α+i1L∫αi0Hρ(u)du=limρ→α+i1L∫αi01+λM3(p−u)2|p−u|√2M3+λM23(p−u)2du=∞, since p∈(0,αi). |
Case 2. Suppose that f(αi)=0, then, F′(α)=0. Since F(αi)−F(u)=f(ξ)(αi−u) with ξ∈(u,αi), and |f(u)|=|f(u)−f(αi)|≤M3|u−αi|, we can obtain that
F(αi)−F(u)≤M3(u−αi)2 |
and
L=∫ρ0du√1−[1+λ(F(ρ)−F(u))]−2≥∫ρ0du√1−[1+λM3(u−αi)2]−2=1√λ∫ρ01+λM3(u−αi)2√2M3(u−αi)2+λM23(u−αi)4du, |
which implies that
√λ≥1L∫ρ01+λM3(αi−u)2√2M23(αi−u)2+λM3(αi−u)4du≥1L∫αi01+λM3(αi−u)2√2M23(αi−u)2+λM3(αi−u)4du. |
So,
limρ→α+i√λL(ρ)≥limρ→α+i1L∫αi01+λM3(αi−u)2|αi−u|√2M3+λM23(αi−u)2du. |
Therefore, limρ→α+iλL(ρ)=∞.
Following similar arguments, we can prove limρ→β−iλL(ρ)=∞. Therefore, the bifurcation curve Tλ(ρ) goes to infinity along the horizontal lines ||u||∞=αi, ||u||∞=βi, for i∈{1,2,⋯,n−1}.
(iii) Following similar arguments in the proof of Theorem 2.1(ii), we have limρ→α+nλL(ρ)=∞. Next, we prove limρ→L−λL(ρ)=∞.
Assume that lim infρ→L−λL(ρ)<∞. Then there exist M5>0 and {ρn}n∈N⊆S such that
limn→∞ρn=L and λL(ρn)<M5 for n∈N. |
By Lemmas 3.2 and 3.5(i), we see that
L=limn→∞TλL(ρn)(ρn)≥limn→∞TM5(ρn)=TM5(L). |
By Eq (3.2), it is easy to see that
limn→∞TM5(ρn)>TM5(L)>L, |
which is a contradiction. So limρ→L−λL(ρ)≥lim infρ→L−λL(ρ)=∞. Therefore, the bifurcation curve SL goes to infinity along the horizontal line ||u||∞=L for L>0.
In this section, we give two examples to demonstrate the feasibility of our result.
Example 5.1. Let us consider the following boundary value problem:
{−(u′√1−u′2)′=λsinu, in (0,3π),u′(0)=u(3π)=0. | (5.1) |
Obviously, f(0)=0, f0=1, r=π and α1=2π. Let a1=4 and b1=8. Then it is easy to verify that a1<α1<b1<8 and F(b1)>F(u) for 0≤u≤b1.
Therefore, from Theorem 2.1, Problem (5.1) has a positive solution (λ,u) satisfying ||u||∞<π for all λ>136; if λ>inf{λ(ρ)|ρ∈(2π,3π)}, then Problem (5.1) has at least two positive solutions (λ,u1) and (λ,u2) satisfying
2π<||u1||∞<||u2||∞<3π. |
Example 5.2. Let us consider the following boundary value problem:
{−(u′√1−u′2)′=λ(u3−4u2+3u), in (0,5),u′(0)=u(5)=0. | (5.2) |
Obviously, f(0)=0, f0=3, r=1 and α1=8+√103. Let a1=3 and b1=4. Then it is easy to verify that a1<α1<b1<5 and F(b1)>F(u) for 0≤u≤b1. Therefore, from Theorem 2.1, Problem (5.2) has a positive solution (λ,u) satisfying ||u||∞<1 for all λ>π2300; if λ>inf{λ(ρ)|ρ∈(3,5)}, then Problem (5.2) has at least two positive solutions (λ,u1) and (λ,u2) satisfying
8+√103<||u1||∞<||u2||∞<5. |
By using time mapping techniques, we study the shape of the bifurcation curves of positive solutions for the one-dimensional Minkowski curvature problem. In particular, we prove that the bifurcation curve is ⊂-shaped/monotone increasing/S-like shaped on the (λ,||u||∞) plane when the nonlinear term f satisfies some appropriate assumptions. By figuring the shape of bifurcation curves of positive solutions, we show the existence and multiplicity of positive solutions with respect to the parameter λ.
The author Z. He was supported by the Natural Science Foundation of Qinghai Province (No. 2021-ZJ-957Q), M. Xu was supported by the Natural Science Foundation of Gansu Province (No. 21JR1RA230) and X. Yao was supported by the Natural Science Foundation of China (No. 12161071).
The authors declare that there is no conflict of interests regarding the publication of this article.
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1. | Shao-Yuan Huang, Wei-Hsun Lee, Sufficient conditions for exact bifurcation curves in Minkowski curvature problems and their applications, 2025, 33, 2688-1594, 2325, 10.3934/era.2025103 |