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Generalized linear differential equation using Hyers-Ulam stability approach

  • In this paper, we study the Hyers-Ulam stability with respect to the linear differential condition of fourth order. Specifically, we treat ψ as an interact arrangement of the differential condition, i.e., ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) where ψc4[,μ],Ψ[,μ]. We demonstrate that ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers-Ulam stability. Two examples are provided to illustrate the usefulness of the proposed method.

    Citation: Bundit Unyong, Vediyappan Govindan, S. Bowmiya, G. Rajchakit, Nallappan Gunasekaran, R. Vadivel, Chee Peng Lim, Praveen Agarwal. Generalized linear differential equation using Hyers-Ulam stability approach[J]. AIMS Mathematics, 2021, 6(2): 1607-1623. doi: 10.3934/math.2021096

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  • In this paper, we study the Hyers-Ulam stability with respect to the linear differential condition of fourth order. Specifically, we treat ψ as an interact arrangement of the differential condition, i.e., ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) where ψc4[,μ],Ψ[,μ]. We demonstrate that ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers-Ulam stability. Two examples are provided to illustrate the usefulness of the proposed method.


    The challenge of stability with respect to the functional equation stemmed from an issue of Ulam [1] concerning the strength of gathering homomorphisms. Suppose G1 is a group, and G2 is a measurement group with metric d(.,.). Given ∈>0, does a δ>0 exist to such an extent that if a mapping H:G1G2 fulfills the imbalance d(H(ϰν),H(ϰ)H(ν))<δ with respect to ϰ,νG1, and as such, there exists a homomorphism h:G1G2 with d(H(ϰ),h(ϰ))<ϵ with respect to ϰG1? If the mapping is almost a homomorphism, and as such, there exists a true homomorphism of s, what would be the error that could reasonably be expected?

    The problem from the instance of roughly additive mappings was formulated by Hyers [2] with G1 and G2 as the Banach spaces. Then, Rassias (see [3]) summed up the effects of the study of Hyers. Since then, the dependability issues of practical conditions have been widely examined by researchers, e.g. see [2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18]).

    Supposedly, the study of Ozawa [8] was among the first attempts on managing the HU stability of differential equations. In [5], the HU stability of differential condition ψ(ϰ)=ψ(ϰ) was analyzed. Then, the studies of [18,19] have been further extended to the Banach space differential condition ψ(ϰ)=λψ(ϰ). Utilizing a direct strategy, cycle technique, find point technique, and open mapping theorem, the HU stability of certain classes of useful fractional differential equations have been explored, e.g. see [1,12,13,18,19,20]).

    In this paper, we investigate the Hyers-Ulam stability of linear differential equation of the fourth order. Specifically, ψ is an interact arrangement of the following differential equation:

    ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ)

    where ψc4[,μ],Ψ[,μ]. We demonstrate that ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers-Ulam stability. A numerical example is provided to illustrate the proposed method.

    Moreover, the effects of HU stability for the first order differential conditions were studied in [14,16,19]. These studies focused on the non-homogeneous straight differential equation of the first order, i.e.,

    ψ+ξ(s)ψ+σ(s)=0. (1.1)

    Jung [14] demonstrated the HU stability with respect to the differential condition of the following form:

    sψ(s)+ψ(s)+μsψϰ0=0

    and further applied the outcome to examine the HU stability of the following differential equation

    s2ψ(s)+asψ(s)+bψ(s)=0. (1.2)

    Then, Wang, Zhon and Sun [20] examined the HU stability of the the first order linear differential condition, i.e.,

    ξ(ϰ)ψ+σ(ϰ)ψ+ν(ϰ)=0. (1.3)

    In this study, we study the following implication of HU stability.

    Definition 1.1. We denote that Eq 1.2 has the HU Stability if there exists a steady λ>0 with the accompanying property of: for every ϵ>0,ψc2[,μ], if

    |ψ+aψ+bψ|ϵ, (1.4)

    as such, there exists some uc2[,μ] that fulfill:

    |u+au+bu|=0 (1.5)

    such that |ψ(ϰ)u(ϰ)|<λϵ. We denote such λ a HU stability constant for Eq 1.2.

    Definition 1.2. We denote that the extension of Eq 1.2 has the HU stability, if there exists a steady λ>0 with the accompanying property of: for every ϵ>0,ψc3[,μ], if

    |ψ+aψ+bψ+cψ|ϵ, (1.6)

    As such, there exist some uc3[,μ] that fulfill

    |u+au+bu+cu|=0 (1.7)

    such that |ψ(ϰ)u(ϰ)|<λϵ. We denote such λ a HU stability constant for Equation 1.6.

    Definition 1.3. We denote that the extension of Eq 1.6 has the HU stability, if there exists a steady λ>0 with the accompanying property of: for every ϵ>0,ψc4[,μ], if

    |ψiv+ξ1ψ+ξ2ψ+ξ3ψ+ξ4ψ|ϵ, (1.8)

    as such, there exist some uc4[,μ] that fulfill

    |uiv+ξ1u+ξ2u+ξ3u+ξ4u|=0 (1.9)

    such that |ψ(ϰ)u(ϰ)|<λϵ. We denote such λ a HU stability constant for Eq 1.8.

    Now, the key results of this study are given in the following hypothesis.

    Lemma 2.1. The differential equation j ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers -Ulam stability, where ψc4[,μ] and Ψ[,μ].

    Proof. Assume that u1,u2,u3, and u4 are the roots of ν4+ξ1ν3+p2ν2+p3ν+p4=0 with q1=Ru1,q2=Ru2,q3=Ru4, and q4=Ru3. Here R means the real parts.

    Suppose ϵ>0 and ψc4[,μ]

    |ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)Ψ(ϰ)|ϵ (2.1)

    and let

    g1(ϰ)=ψ(ϰ)+(u1+ξ1)ψ(ϰ)+(u21+ξ1u1+ξ2)ψ(ϰ)                                     +(u31+ξ1u21+ξ2u1+ξ3)ψ(ϰ),

    we obtain

    g1(ϰ)=ψ(ϰ)+(u1+ξ1)ψ(ϰ)+(u21+ξ1u1+ξ2)ψ(ϰ)+(u31+ξ1u21+ξ2u1+ξ3)ψ(ϰ)+(u41+ξ1u31+ξ2u21+ξ3u1+ξ4)ψ(ϰ) (2.2)

    with respect to ϰ[,μ]. As such,

    |g1(ϰ)u1g1(ϰ)Ψ(ϰ)|ϵ (2.3)

    with respect to ϰ[,μ], it yields that

    |g1(ϰ)u1g1(ϰ)Ψ(ϰ)|=|ψ(ϰ)+(u1+ξ1)ψ(ϰ)+(u21+ξ1u+ξ2)ψ(ϰ)+(u31+ξ1u21+ξ2u2+ξ3)ψ(x)+(u41+ξ1u31+ξ2u21+ξ3u1+ξ4)ψ(ϰ)u1(ψ(ϰ)+(u1+ξ)ψ(ϰ)+u21+(ξ1u1+ξ2)ψ(ϰ)+((u31+ξ1u21+ξ2u1+ξ3)ψ(ϰ))Ψ(ϰ)| (2.4)

    with respect to ϰ[,μ]. Utilizing the above condition, we obtain

    |g1(ϰ)u1g1(ϰ)Ψ(ϰ)|=|ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψn(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)|<ϵ.

    with respect to ϰ[,μ]. Similarly, g1 fulfills

    ϵg1(ϰ)u1g1(ϰ)Ψ(ϰ)ϵ (2.5)

    with respect to ϰ[,μ]. Multiplying the above condition by eu1(ϰ) yields

    ϵeu1(ϰ)g1(ϰ)eu1(ϰ)u1g1(ϰ)eu1(ϰ)Ψ(ϰ)eu1(ϰ)≤∈eu1(ϰ) (2.6)

    with respect to ϰ[,μ]. Without loss of generality, we accept that u1>1; therefore

    u1ϵeu1(ϰ)g1(ϰ)eu1(ϰ)u1g1(ϰ)eu1(ϰ)Ψ(ϰ)eu1(ϰ)u1eu1(ϰ) (2.7)

    with respect to ϰ[,μ]. Integrating 2.7 from ϰ to μ, we obtain

    ϵ(eu1(μ)+eu1(ϰ))g1(μ)eu1(μ)g1(ϰ)eu1(ϰ)μϰΨ(s)eu1(s)dsϵ(eu1(μ)+eu1(ϰ)) (2.8)

    with respect to ϰ[,μ]; therefore

    ϵeu1(ϰ)g1(μ)eu1(ϰ)ϵeu1(μ)g1(ϰ)eu1(ϰ)μϰΨ(s)eu1(s)ds≤∈(eu1(ϰ)+eu1(μ)) (2.9)

    with respect to ϰ[,μ]. The above condition yields

    ϵeu1(ϰ)g1(μ)eu1(ϰ)ϵeu1(μ)g1(ϰ)eu1(ϰ)μϰΨ(s)eu1(s)dsϵeu1(ϰ) (2.10)

    with respect to ϰ[,μ]. Multiplying 2.10 by eu1(ϰ) on both sides, we obtain

    ϵg1(μ)eu1(μϰ)ϵeu1(μϰ)g1(ϰ)eu1ϰμϰΨ(s)eu1sdsϵ (2.11)

    therefore

    ϵg1(μ)eu1(ϰμ)ϵeu1(ϰμ)g1(ϰ)eu1ϰμϰΨ(s)eu1sdsϵ (2.12)

    with respect to ϰ[,μ]. Let

    ζ(ϰ)=g1(μ)eu1(ϰμ)eu1(ϰ)μϰΨ(s)eu1sds,

    then ζ(ϰ) fulfills ζ(ϰ)=u1ζ(ϰ)+Ψ(ϰ) with respect to ϰ[,μ]. It satisfies the inequality of

    |ζ(ϰ)g1(ϰ)|=|g1(μ)eu1(ϰμ)g1(ϰ)eu1ϰμϰΨ(s)eu1sds|=eξϰ|μϰ[eu1sg1(s)]ldsμϰΨ(s)eu1sds|eξϰμϰeξs|g1(s)u1g1(s)Ψ(s)|dsϵeξϰμϰeξsds (2.13)

    with respect to ϰ[,μ]. If ξ0, then

    |ζ(ϰ)g1(ϰ)|ϵeξϰμϰeξsdsϵξ(1eξ(μ)) (2.14)

    with respect to ϰ[,μ]. If ξ=0, then

    |ζ(ϰ)g1(ϰ)|ϵeξϰμϰeξsdsϵ(μ) (2.15)

    with respect to ϰϵ[,μ]. Therefore

    |ζ(ϰ)g1(ϰ)|{1eξ(μ)ξ;if  ξ0(μ)ϵ;if  ξ=0. (2.16)

    Theorem 2.2. The differential equation ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the HU stability, where ψc4[,μ] and Ψ[,μ]. Therefore

    |λ(ϰ)h(ϰ)|{(1eψ(μ))(1eξ(μ))ϵψξ;if  ξ,ψ01eψ(μ)(μ)ϵψ;if  ξ0,ψ01eξ(μ)(μ)ϵξ;if  ξ0,ψ=0(μ)2ϵ;if  ξ=0,ψ=0

    with respect to ϰ[,μ].

    Proof. Similar to the proof of Lemma 2.1. Let H(ϰ)=ψ(ϰ)u2ψ(ϰ) by H(ϰ)=ψ(ϰ)u1ψ(ϰ) and let ϵ>0;ψc4[,μ].

    In addition,

    |H(ϰ)u4H(ϰ)ζ(ϰ)|=|ζ(ϰ)g(ϰ)| (2.17)

    with respect to ϰ[,μ]. Therefore

    |H(ϰ)u4H(ϰ)ζ(ϰ)|ϵ (2.18)

    with respect to ϰ[,μ]. Equivalently H fulfills

    |H(ϰ)u4H(ϰ)ζ(ϰ)|=|ψ(ϰ)(u1+u4)ψ(ϰ)+u1u4ψ(ϰ)ζ(ϰ)|=|ψ(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)ζ(ϰ)|<ϵ (2.19)

    with respect to ϰ[,μ]. Multiplying 2.19 by eu4(ϰ) on both sides yields

    ϵeu4(ϰ)H(ϰ)eu4(ϰ)u4H(ϰ)eu4(ϰ)ζ(ϰ)eu4(ϰ)ϵeu4(ϰ) (2.20)

    with respect to ϰ[,μ]. Without loss of generality, we accept that u4>1; therefore

    u4eu4(ϰ)H(ϰ)eu4(ϰ)H(ϰ)eu4(ϰ)ζ(ϰ)eu4(ϰ)ϵu4eu4(ϰ) (2.21)

    with respect to ϰ[,μ]. Integrating 2.21 from ϰ to μ, we obtain

    ϵ(eu4(ϰ)eu4(μ))H(μ)eu4(μ)H(ϰ)eu4(ϰ)μϰζ(s)eu4(ϰ)dsϵ(eu4(ϰ)eu4(μ)) (2.22)

    with respect to ϰ[,μ]. Based on 2.22, we obtain

    ϵeu4(ϰ)H(μ)eu4(μ)ϵeu4(μ)H(ϰ)eu4(ϰ)μϰζ(s)eu4(ϰ)dsϵ(eu4(ϰ)) (2.23)

    with respect to ϰ[,μ]. Multiplying 2.23 by the function eu4(ϰ), we obtain

    ϵH(μ)eu4(μϰ)ϵeu4(μϰ)H(ϰ)eu4ϰμϰζ(s)eu4sdsϵ (2.24)

    with respect to ϰ[,μ]. Based on 2.24, we obtain

    ϵH(μ)eu4(ϰμ)ϵeu4(ϰμ)H(ϰ)eu4ϰμϰζ(s)eu4sdsϵ (2.25)

    with respect to ϰ[,μ]. Let λ(ϰ)=H(μ)eu4(ϰμ)eu4ϰμϰζ(s)eu4sds with respect to ϰ[,μ]. Then

    λ(ϰ)u4λ(ϰ)ζ(ϰ)=0  byλ(ϰ)=u4λ(ϰ)+ζ(ϰ).

    Therefore

    |λ(ϰ)H(ϰ)|=eu4(ϰμ)H(μ)H(ϰ)eu4ϰμζ(s)eu4sds=eψϰ|μ[eu4sH(s)]μζ(s)eu4sds|eψϰμϰ|eu4s||H(s)u4H(s)ζ(t)|dseψϰμϰeψs|H(s)u4H(s)ζ(t)|ds|λ(ϰ)H(ϰ)|ϵeψϰμϰeψsds (2.26)

    with respect to ϰ[,μ]. If ψ0, then

    |λ(ϰ)H(ϰ)|ϵeψϰμϰeψsdsϵψ[1eψ(μϰ)]|λ(ϰ)H(ϰ)|ϵψ[1eψ(μ)] (2.27)

    with respect to ϰ[,μ]. If ψ=0, then

    |λ(ϰ)H(ϰ)|ϵ(μ) (2.28)

    with respect to ϰ[,μ]. Based on 2.16, we obtain

    |λ(ϰ)H(ϰ)|{(1eψ(μ))(1eξ(μ))ϵψξ;if  ξ,ψ01eψ(μ)(μ)ϵψ;if  ξ=0,ψ01eξ(μ)(μ)ϵξ;if  ξ0,ψ=0(μ)2ϵ;if  ξ=0,ψ=0 (2.29)

    with respect to ϰ[,μ].

    Theorem 2.3. The DE ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers Ulam stability, where ψc4[,μ] and with respect to ϰ[,μ], |u(ϰ)ψ(ϰ)|T

    where

    T={(1eψ(μ))(1eξ(μ))(1eσ(μ))ϵψξσ;if  (ξ,ψ,σ)0(1eψ(μ))(1eξ(μ))(μ)ϵψξ;if  σ=0;(ξ,ψ)0(1eψ(μ))(1eσ(μ))(μ)ϵσψ;if  ξ=0;(σ,ψ)0(1eξ(μ))(1eσ(μ))(μ)ϵξσ;if  ψ=0;(ξ,σ)0(1eξ(μ))(μ)2ϵξ;if  (σ,ψ)=0;ξ0(1eσ(μ))(μ)2ϵσ;if  (ξ,ψ)=0;σ0(1eψ(μ))(μ)2ϵψ;if  (ξ,σ)=0;ψ0(μ)3ϵ;if  (ξ,σ,ψ)=0

    with respect to ϰ[,μ].

    Proof. Based on Theorem 2.2, let us choose

    ψ(ϰ)=u3(ϰ)+(u2+ξ1)u3(ϰ)+(u22+ξ1u2+ξ2)u2(ϰ)

    by

    ψ(ϰ)=u3(ϰ)+(u2+ξ1)u3(ϰ)+(u22+ξ1u2+ξ2)u3(ϰ)+(u32+ξ1u22+ξ2u2+ξ3)u2(ϰ).

    Then

    |ψ(ϰ)u2ψ(ϰ)λ(ϰ)|=|u3(ϰ)+(u2+ξ1)u3(ϰ)+(u22+ξ1u2+ξ2)u3(ϰ)              +(u32+ξ1u22+ξ2u2+ξ3)u3(ϰ)u2(u3(ϰ)              +(u2+ξ1)u3(ϰ)+(u22+ξ1u2+ξ2)u3(ϰ)λ(ϰ)|=|u3(ϰ)+ξ1u2(ϰ)+ξ2u2(ϰ)+ξ3u+3(ϰ)λ(ϰ)|ϵ

    with respect to ϰ[,μ]. As such, we have

    |ψ(ϰ)u2ψ(ϰ)λ(ϰ)|ϵ (2.30)

    with respect to ϰ[,μ]. Equivalently, ψ fulfills

    ϵψ(ϰ)u2ψ(ϰ)λ(ϰ)ϵ (2.31)

    with respect to ϰ[,μ]. Multiplying the condition by the function eu3(ϰ)

    ϵeu3(ϰ)ψ(ϰ)eu3(ϰ)u2ψ(ϰ)eu3(ϰ)λ(ϰ)eu3(ϰ)ϵeu3(ϰ) (2.32)

    with respect to ϰ[,μ]. Without loss of generality, we accept that u3>1. Then

    u3ϵeu3(ϰ)ψ(ϰ)eu3(ϰ)u3ψ(ϰ)eu3(ϰ)λ(ϰ)eu3(ϰ)ϵeu3(ϰ) (2.33)

    with respect to ϰ[,μ]. Integrating 2.33 from ϰ to μ, we obtain

    ϵ(eu3(ϰ)eu3(μ))eu3(μ)ψ()ψ(ϰ)eu3(ϰ)μϰλ(s)eu3(s)dsϵ(eu3(ϰ)eu3(μ)) (2.34)

    with respect to ϰ[,μ]. Based on 2.34, we obtain

    ϵeu3(ϰ)eu3(μ)ψ()ϵeu3(μ)ψ(ϰ)eu3(ϰ)μϰλ(s)eu3(s)dsϵeu3(ϰ) (2.35)

    with respect to ϰ[,μ]. Again, multiplying the condition by function eu3(ϰ) yields

    ϵeu3(μ)ψ()ϵeu3(μϰ)ψ(ϰ)μϰλ(s)eu3(s)dsϵ (2.36)

    with respect to ϰ[,μ]. Based on 2.36, we have

    ϵeu3(ϰμ)ψ()ϵeu3(μ)ψ(ϰ)eu3ϰμϰλ(s)eu3(s)dsϵ (2.37)

    for all ϰ[,μ]. Let u2(ϰ)=ψ(μ)eu3(ϰμ)eu3ϰμϰλ(s)eu3(s)ds, then u2(ϰ)u3u2(ϰ)λ(ϰ)=0 by u2(ϰ)=u3u2(ϰ)+λ(ϰ), for all ϰ[,μ]. Therefore

    |u2(ϰ)ψ(ϰ)|=|ψ(μ)eu3(ϰμ)ψ(ϰ)eu3ϰμϰλ(s)eu3(s)ds|eσϰμϰeσs|ψ(s)u3ψ(s)λ(s)|ds|u2(ϰ)ψ(ϰ)|ϵeσϰμϰeσsds (2.38)

    with respect to ϰ[,μ]. If σ0, then

    |u2(ϰ)ψ(ϰ)|ϵσ(1eσ(μϰ))ϵσ(1eσ(μ)) (2.39)

    with respect to ϰ[,μ]. If σ=0, then

    |u2(ϰ)ψ(ϰ)|ϵeσϰμϰeσsdsϵ(μϰ)ϵ(μ) (2.40)

    with respect to ϰ[,μ]. Based on 2.40, we obtain

    |u(ϰ)ψ(ϰ)|T, where

    T={(1eψ(μ))(1eξ(μ))(1eσ(μ))ψξσ;if(ξ,ψ,σ)0(1eψ(μ))(1eξ(μ))(μ)ψξ;ifσ=0;(ξ,ψ)0(1eψ(μ))(1eσ(μ))(μ)σψ;ifξ=0;(σ,ψ)0(1eξ(μ))(1eσ(μ))(μ)ξσ;ifψ=0;(ξ,σ)0(1eξ(μ))(μ)2ξ;if(σ,ψ)=0;ξ0(1eσ(μ))(μ)2σ;if(ξ,ψ)=0;σ0(1eψ(μ))(μ)2ψ;if(ξ,σ)=0;ψ0(μ)3;if(ξ,σ,ψ)=0 (2.41)

    with respect to ϰ[,μ].

    Theorem 2.4. The differential equation ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)=Ψ(ϰ) has the Hyers Ulam stability, where ψc4[,μ] and with respect to ϰ[,μ], as such

    |Ψ(ϰ)ζ(ϰ)|Θ, where

    Θ={(1eψ(μ))(1eξ(μ))(1eσ(μ))(1eν(μ))ψξσνϵ;if  (ξ,ψ,σ,ν)0(1eψ(μ))(1eξ(μ))(1eσ(μ))ψξσ(μ)ϵ;if  ξψσ0,ν=0(1eψ(μ))(1eξ(μ))(1eν(μ))ψξν(μ)ϵ;if  ξψν0,σ=0(1eψ(μ))(1eν(μ))(1eσ(μ))ψνσ(μ)ϵ;if  νψσ0,ξ=0(1eν(μ))(1eξ(μ))(1eσ(μ))νξσ(μ)ϵ;if  ξνσ0,ψ=0(1eξ(μ))(1eσ(μ))ξσ(μ)2ϵ;if  ξσ0,ψ=ν=0(1eξ(μ))(1eψ(μ))ξσ(μ)2ϵ;if  ξψ0,σ=ν=0(1eξ(μ))(1eν(μ))ξν(μ)2ϵ;if  ξν0,ψ=σ=0(1eσ(μ))(1eψ(μ))σψ(μ)2ϵ;if  σψ0,ξ=ν=0(1eξ(μ))(1eν(μ))ξν(μ)2ϵ;if  ξν0,ψ=σ=0(1eψ(μ))(1eν(μ))ψν(μ)2ϵ;if  ψν0,ξ=σ=0(1eξ(μ))ξ(μ)3ϵ;if  ξ0,σ=ψ=ν=0(1eψ(μ))ψ(μ)3ϵ;if  ψ0,σ=ξ=ν=0(1eσ(μ))σ(μ)3ϵ;if  σ0,ξ=ψ=ν=0(1eν(μ))ν(μ)3ϵ;if  ν0,σ=ψ=ξ=0(μ)4ϵ;if  ξ=σ=ψ=ν=0

    with respect to ϰ[,μ].

    Proof. Similar to the proof of theorem 2.3, let ∈>0 and ψc4[,μ].

    Consider

    ζ(ϰ)=ψ(ϰ)+(u2+ξ1)ψ(ϰ)+(u22+ξ1u2+ξ2)ψ(ϰ)+(u32+ξ1u22+ξ2u2+ξ3)ψ(ϰ),

    we obtain

    ζ(ϰ)=ψiv(ϰ)+(u2+ξ1)ψ(ϰ)+(u22+ξ1u2+ξ3)ψ(ϰ)+(u32+ξ1u2+ξ2u2+ξ3)ψ(ϰ)+(u42+ξ1u32+ξ2u22+ξ3u2+ξ4)ψ(ϰ) (2.42)

    with respect to ϰ[,μ]. As such

    |ζ(ϰ)u2ζ(ϰ)H(ϰ)|<ϵ (2.43)

    with respect to ϰ[,μ]. If follows from 2.42 that

    |ζ(ϰ)u2ζ(ϰ)H(ϰ)|=|ψiv(ϰ)+(u2+ξ1)ψ(ϰ)+(u22+ξ1u2+ξ3)ψ(ϰ)              +(u32+ξ1u2+ξ2u2+ξ3)ψ(ϰ)              +(u42+ξ1u32+ξ2u22+ξ3u2+ξ4)ψ(ψ)              u2(ψ(ϰ)+(u2+ξ1)ψ(ϰ)              +(u22+ξ1u2+ξ2)ψ(ϰ)              +(u32+ξ1u22+ξ2u2+ξ3)ψ(ϰ))H(ϰ)|=|ψiv(ϰ)+ξ1ψ(ϰ)+ξ2ψ(ϰ)+ξ3ψ(ϰ)+ξ4ψ(ϰ)H(ϰ)|ϵ.

    So

    |ζ(ϰ)u2ζ(ϰ)H(ϰ)|<ϵ

    for all ϰ[,μ]. Equivalently, ζ fulfills

    ϵζ(ϰ)u2ζ(ϰ)H(ϰ)<ϵ (2.44)

    with respect to ϰ[,μ]. Multiplying the formula by the function eu2(ϰ) satisfies

    ϵeu2(ϰ)ζ(ϰ)eu2(ϰ)u2ζ(ϰ)eu2(ϰ)H(ϰ)eu2(ϰ) (2.45)
    ϵeu2(ϰ) (2.46)

    with respect to ϰϵ[,μ]. Without loss of generality, we accept that u2>1. As such

    ϵu2eu2(ϰ)ζ(ϰ)eu2(ϰ)u2ζ(ϰ)eu2(ϰ)H(ϰ)eu2(ϰ)ϵu2eu2(ϰ) (2.47)

    for all ϰ[,μ]. Integrating 2.45 from ϰ to μ. As such

    ϵ(eu2(ϰ)eu2(μ))ζ(μ)eu2(μ)ζ(ϰ)eu2(ϰ)μϰH(s)eu2(s)dsϵ(eu2(ϰ)eu2(μ)) (2.48)

    with respect to ϰ[,μ]. It follows from 2.48 that

    ϵ(eu2(ϰ))ζ(μ)eu2(μ)ϵeu2(μ)ζ(ϰ)eu2(ϰ)μϰH(s)eu2(s)dsϵ(eu2(ϰ)) (2.49)

    for all ϰ[,μ]. Multiplying the formula by the function eu2(ϰ), we obtain

    ϵζ(μ)eu2(ϰμ)ϵeu2(ϰμ)ζ(ϰ)eu2ϰμϰH(s)eu2(s)dsϵ (2.50)

    with respect to ϰ[,μ].

    Let Ψ(ϰ)=ζ(μ)eu2(2Heu2ϰμϰH(s)eu2(s)ds. As such, Ψ(ϰ) satisfies Ψ(ϰ)u2Ψ(ϰ)H(ϰ)=0 by

    Ψ(ϰ)=u2Ψ(ϰ)+H(ϰ) (2.51)

    with respect to ϰ[,μ]. As such,

    |Ψ(ϰ)ζ(ϰ)|=|ζ(μ)eu2(ϰμ)ζ(ϰ)eu2ϰμϰH(s)eu2sds|eνϰ|μϰ[eu2sζ(s)]"dsμϰH(s)eu2sds|ϵeνϰμϰeνsds|Ψ(ϰ)ζ(ϰ)|eνϰμϰeνsϵds (2.52)

    with respect to ϰ[,μ]. If ν0, then

    |Ψ(ϰ)ζ(ϰ)|ϵν(1eν(μϰ)ϵν(1eν(μ)

    with respect to ϰ[,μ]. If ν=0, then

    |Ψ(ϰ)ζ(ϰ)|ϵ(μϰ)ϵ(μ)

    with respect to ϰ[,μ]. If follows from 2.41 that

    |Ψ(ϰ)ζ(ϰ)|Θ,  where (2.53)
    Θ={(1eψ(μ))(1eξ(μ))(1eσ(μ))(1eν(μ))ψξσνϵ;if  (ξ,ψ,σ,ν)0(1eψ(μ))(1eξ(μ))(1eσ(μ))ψξσ(μ)ϵ;if  ξψσ0,ν=0(1eψ(μ))(1eξ(μ))(1eν(μ))ψξν(μ)ϵ;if  ξψν0,σ=0(1eψ(μ))(1eν(μ))(1eσ(μ))ψνσ(μ)ϵ;if  νψσ0,ξ=0(1eν(μ))(1eξ(μ))(1eσ(μ))νξσ(μ)ϵ;if  ξνσ0,ψ=0(1eξ(μ))(1eσ(μ))ξσ(μ)2ϵ;if  ξσ0,ψ=ν=0(1eξ(μ))(1eψ(μ))ξσ(μ)2ϵ;if  ξψ0,σ=ν=0(1eξ(μ))(1eν(μ))ξν(μ)2ϵ;if  ξν0,ψ=σ=0(1eσ(μ))(1eψ(μ))σψ(μ)2ϵ;if  σψ0,ξ=ν=0(1eξ(μ))(1eν(μ))ξν(μ)2ϵ;if  ξν0,ψ=σ=0(1eψ(μ))(1eν(μ))ψν(μ)2ϵ;if  ψν0,ξ=σ=0(1eξ(μ))ξ(μ)3ϵ;if  ξ0,σ=ψ=ν=0(1eψ(μ))ψ(μ)3ϵ;if  ψ0,σ=ξ=ν=0(1eσ(μ))σ(μ)3ϵ;if  σ0,ξ=ψ=ν=0(1eν(μ))ν(μ)3ϵ;if  ν0,σ=ψ=ξ=0(μ)4ϵ;if  ξ=σ=ψ=ν=0 (2.54)

    with respect to ϰ[,μ].

    Two examples to illustrate the results in this study are provided, as follows.

    Example 3.1. Consider a differential equation of the form σiv(ϰ)+2σ(ϰ)+σ(ϰ)=Ψ(ϰ);ϰ[2,3].

    Suppose ϵ>0, as such

    |σiv(ϰ)+2σ(ϰ)+σ(ϰ)Ψ(ϰ)|ϵ.

    with respect to ϰ[2,3]. Suppose λ=1, then

    g(ϰ)=σ(ϰ)+3σ(ϰ)+4σ(ϰ)+4σ(ϰ)  andg(ϰ)=σiv(ϰ)+3σ(ϰ)+4σ(ϰ)+4σ(ϰ)+4σ(ϰ)

    with respect to ϰ[2,3]. The conditions 2.16, 2.18 and 2.30 of Theorem 2.4 are satisfied. Therefore, there is a function ϰc4[2,3], which is a mild solution of uiv(ϰ)+2u(ϰ)+u(ϰ)=Ψ(ϰ) that is satisfied by 2.54.

    Figure 1.  The solution of Ψ(ϰ) and ζ(ϰ) for Eq 2.54.

    Example 3.2. Consider a differential equation of the form σiv(ϰ)+σ(ϰ)+σ(ϰ)=Ψ(ϰ);ϰ[3,2].

    Suppose ϵ>0, and ψ[3,2], such that

    |σiv(ϰ)+σ(ϰ)+σ(ϰ)Ψ(ϰ)|ϵ.

    with respect to ϰ[3,2]. We take

    g(ϰ)=σ(ϰ)+2σ(ϰ)+3σ(ϰ)+3σ(ϰ)

    with respect to ϰ[3,2]. Then,

    g(ϰ)=σiv(ϰ)+2σ(ϰ)+3σ(ϰ)+3σ(ϰ)+3σ(ϰ)

    with respect to ϰ[3,2]. As such,

    |g(ϰ)g(ϰ)Ψ(ϰ)|=|σiv(ϰ)+σ(ϰ)+σ(ϰ)Ψ(ϰ)|ϵ

    with respect to ϰ[,μ]. The conditions 2.16, 2.18 and 2.30 of Theorem 2.4 are satisfied. Therefore, there is a function ϰc4[3,2], which is a mild solution of uiv(ϰ)+u(ϰ)+u(ϰ)=Ψ(ϰ) that is satisfied by 2.54.

    Figure 2.  The solution Ψ(ϰ) and ζ(ϰ) for Eq 2.54.

    We have investigated the Hyers-Ulam stability with respect to the linear differential condition of fourth order in this study. The effectiveness of the proposed method has been illustrated in the examples.

    This research is made possible through financial support from the Phuket Rajabhat University, Thailand, and the Thailand Research Fund (RSA6280004). The authors are grateful to the Phuket Rajabhat University, Thailand, and the Thailand Research Fund (RSA6280004) for supporting this research. The authors are grateful to the referees for their valuable comments and suggestions.

    The authors declares no conflict of interest.



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