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Research article

Existence of positive weak solutions for a nonlocal singular elliptic system

  • Received: 18 April 2019 Accepted: 27 June 2019 Published: 05 July 2019
  • MSC : Primary 35A15; Secondary 35S15, 47G20, 46E35

  • Let Ω be a bounded domain in Rn with C1,1 boundary, and let s(0,1) be such that s<n2. We give sufficient conditions for the existence of a weak solution (u,v)Hs(Rn)×Hs(Rn) of the nonlocal singular system (Δ)su=adγ1Ωvβ1 in Ω, (Δ)sv=bdγ2Ωuβ2 in Ω, u=v=0 in RnΩ, u>0 in Ω, v>0 in Ω, where a and b are nonnegative bounded measurable functions such that infΩa>0 and infΩb>0. For the found weak solution (u,v), the behavior of u and v near Ω is also investigated.

    Citation: Tomas Godoy. Existence of positive weak solutions for a nonlocal singular elliptic system[J]. AIMS Mathematics, 2019, 4(3): 792-804. doi: 10.3934/math.2019.3.792

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  • Let Ω be a bounded domain in Rn with C1,1 boundary, and let s(0,1) be such that s<n2. We give sufficient conditions for the existence of a weak solution (u,v)Hs(Rn)×Hs(Rn) of the nonlocal singular system (Δ)su=adγ1Ωvβ1 in Ω, (Δ)sv=bdγ2Ωuβ2 in Ω, u=v=0 in RnΩ, u>0 in Ω, v>0 in Ω, where a and b are nonnegative bounded measurable functions such that infΩa>0 and infΩb>0. For the found weak solution (u,v), the behavior of u and v near Ω is also investigated.


    Singular elliptic problems of the form

    {Δu=g(.,u) in Ω,u=0 on Ω,u>0 in Ω, (1.1)

    with g such that lims0+g(x,s)=, have been extensively studied in the literature. Starting with the pioneering works [9,10,17], a vast amount of works was devoted to these problems, see for instance, [2,5,8,12,13,14,16,19,20,25,26,27,30], and [37].

    In particular, [26] gives an existence result for classical solutions to problem (1.1), in the case when g(.,u)=adγΩuβ, with 0aCσ(¯Ω) for some σ(0,1), β>0 and γ<2; and [13] gives an existence result for very weak solutions of the same problem. Notice that, in this case, g(x,s) becomes singular at s=0 and also at xΩ. Let us mention also that existence and uniqueness results for singular problems involving the p-laplacian operator on exterior domains were recently obtained in [6].

    The existence of positive solutions of singular elliptic systems is addressed (in the local case), in [22], [29], and [1]. In [22] and [29] the results are obtained via the sub-supersolutions method, while in [1] (where appear also multiplicity results), the methods are variational and topological.

    A systematic study of local singular elliptic problems, as well as additional references, can be found in [21,33]. For a thorough introduction to the variational analysis of nonlinear problems described by nonlocal operators, we refer the reader to the reference [28].

    Concerning nonlocal elliptic problems, let us mention that in [32], existence and multiplicity results were obtained for some singular elliptic problems driven by fractional powers of the p-Laplacian operator. In [11], global bifurcation problems for the fractional p-Laplacian were studied and, in [3], existence and multiplicity results were obtained for singular bifurcation problems of the form (Δ)su=f(x)uβ+λup in Ω, u=0 in RnΩ, u>0 in Ω, in the case where Ω is a bounded and regular enough domain in Rn, s(0,1), n>2s, β>0, p>1, λ>0, and f is a nonnegative function belonging to a suitable Lebesgue space. There, it was proved the existence of at least two solutions for this problem when λ is positive and small enough. In [23], a more precise existence and multiplicity result was obtained for the same problem in the case when f1 and the nonlinearity has critical growth at infinity, (i.e., when p=2s1, with 2s=2nn2s). In fact, in [23], it was proved that, under these assumptions, there exists Λ>0 such that:

    ⅰ) There exist exactly two positive solutions when 0<λ<Λ,

    ⅱ) There exists at least one positive solution when λ=Λ,

    ⅲ) No solution exists when λ>Λ.

    Also, in [24], it was investigated the existence of positive weak solutions to problems like (Δ)su=auβ+λh in Ω, u=0 in RnΩ, u>0 in Ω, in the case where s(0,1), n>2s, β(0,1), λ>0, and where a and h are nonnegative bounded functions with h0.

    Our aim in this work is to obtain sufficient conditions on β1, β2, γ1 and γ2 for the existence of positive weak solutions to the following problem

    {(Δ)su=adγ1Ωvβ1 in Ω,(Δ)sv=bdγ2Ωuβ2 in Ω,u=v=0 in RnΩ,u,vHs(Rn)u>0 in Ω, v>0 in Ω. (1.2)

    Here, and from now on, Ω is a bounded domain in Rn with C1,1 boundary, s(0,1), dΩ:=dist(.,Ω), β1(0,1), β2(0,1), γ1<2s, γ2<2s, a and b belong to L(Ω), and satisfy infΩa>0 and infΩb>0.

    Before stating our main results, let us recall the definition of the fractional Sobolev space Hs(Rn) and some well known facts related to this space. For s(0,1) and nN, let

    Hs(Rn):={uL2(Rn):Rn×Rn|u(x)u(y)|2|xy|n+2sdxdy<},

    and for uHs(Rn), let

    uHs(Rn):=(Rnu2+Rn×Rn|u(x)u(y)|2|xy|n+2sdxdy)12,

    and let

    Xs0(Ω):={uHs(Rn):u=0 a.e. in RnΩ},

    and for uXs0(Ω), let

    uXs0(Ω):=(Rn×Rn|u(x)u(y)|2|xy|n+2sdxdy)12.

    With these norms, Hs(Rn) and Xs0(Ω) are Hilbert spaces (see [36], Lemma 7), Cc(Ω) is dense in Xs0(Ω) (see [18], Theorem 6). Also, Xs0(Ω) is a closed subspace of Hs(Rn), and from the fractional Poincarè inequality (as stated e.g., in [15], Theorem 6.5; see also Remark 2.1 below), if n>2s then .Xs0(Ω) and .Hs(Rn) are equivalent norms on Xs0(Ω).

    For fL1loc(Ω) we will write f(Xs0(Ω)) to mean that exists a positive constant c such that |Ωfφ|cuXs0(Ω) for any φXs0(Ω). For f(Xs0(Ω)) we will write ((Δ)s)1f for the unique weak solution u (given by the Riesz theorem) of the problem

    {(Δ)su=f in Ω,u=0 in RnΩ. (1.3)

    The notion of weak solution that we use in this work is the given by the following definition:

    Definition 1.1. Let s(0,1), let f:ΩR be a Lebesgue measurable function such that fφL1(Ω) for any φXs0(Ω). We say that u:RnR is a weak solution to the problem

    {(Δ)su=f in Ω,u=0 in RnΩ

    if uXs0(Ω), u=0 in RnΩ and, for any φ Xs0(Ω),

    Rn×Rn(u(x)u(y))(φ(x)φ(y))|xy|n+2sdxdy=Ωfφ.

    For uXs0(Ω) and fL1loc(Ω), we will write (Δ)suf in Ω (respectively (Δ)suf in Ω) to mean that, for any nonnegative φHs0(Ω), it hold that fφL1(Ω) and

    Rn×Rn(u(x)u(y))(φ(x)φ(y))|xy|n+2sdxdyΩfφ (resp. Ωfφ).

    For u,vXs0(Ω), we will write (Δ)su(Δ)sv in Ω (respectively (Δ)su(Δ)sv in Ω), to mean that (Δ)s(uv)0 in Ω (resp. (Δ)s(uv)0 in Ω).

    If f and g are measurable real valued functions defined on Ω, we will write fg to mean that there exists a positive constant c, such that c1fgcf a.e. in Ω. We will write fg (respectively fg in Ω) to mean that, for some positive constant c, fcg a.e. in Ω (resp. fcg a.e. in Ω).

    Also, we set ω0:=2diam(Ω). With these notations, our main results read as follow:

    Theorem 1.2. Let β1(0,1), β2(0,1), let γ1<2s, γ2<2s, and let a and b be functions in L(Ω) such that a1, b1. Assume that one of the following three conditions i) - iii) holds:

    i) γ1+sβ1<s and γ2+sβ2<s,

    ii) γ1+sβ1<s and γ2+sβ2=s,

    iii) γ1+sβ1=s and γ2+sβ2<s.

    Then problem has a weak solution (u,v)Xs0(Ω)×Xs0(Ω) such that uϑ1 and vϑ2 in Ω, where

    ϑ1:=dsΩ and ϑ2:=dsΩif i) holds,ϑ1:=dsΩ and ϑ2:=dsΩln(ω0dΩ) if ii) holdsϑ1:=dsΩ and ϑ2:=dsΩ if iii) holds.

    Theorem 1.3. Let β1(0,1), β2(0,1), let γ1<2s, γ2<2s, and let a and b be functions in L(Ω) such that a1, b1. Assume that γ1+sβ1=s and γ2+sβ2=s. Then problem (1.2) has a weak solution (u,v)Xs0(Ω)×Xs0(Ω) such that dsΩudsΩln(ω0dΩ) and dsΩvdsΩln(ω0dΩ) in Ω.

    Theorem 1.4. Let β1(0,1), β2(0,1), let γ1<2s, γ2<2s, and let a and b be functions in L(Ω) such that a1, b1. Assume that one of the following two conditions holds:

    i) γ1+sβ1<s and s<γ2+sβ2<min{2s,12+s},

    ii) s<γ1+sβ1<min{2s,12+s} and γ2+β2s<s.

    Then problem (1.2) has a weak solution (u,v)Xs0(Ω)×Xs0(Ω) such that uϑ1 and vϑ2 in Ω, where

    ϑ1:=dsΩ and ϑ2:=d2sγ2sβ2Ωif i) holds,ϑ1:=d2sγ1sβ1Ω and ϑ2:=dsΩif ii) holds.

    The article is organized as follows: In Section 2, we quote some known facts and state some preliminary results. Lemma 2.2 quotes a result from [7], which gives accurate two side estimates for the values of the Green operator on negative powers of the distance function dΩ (where the Green operator is the associated to the fractional laplacian with homogeneous Dirichlet condition on RnΩ). Using this result and some of its consequences, Lemmas 2.4 and 2.5 states that, if the assumptions of Theorem 1.2 (respectively of Theorem 1.4) are assumed, and if ϑ1 and ϑ2 are as given in the statement of the respective Theorem, then dγ1Ωϑβ12 and dγ2Ωϑβ21 belong to (Xs0(Ω)), ((Δ)s)1(dγ1Ωϑβ12)ϑ1, and ((Δ)s)1(dγ2Ωϑβ21)ϑ2 in Ω. Similarly, using again Lemma 2.2, Lemma 2.6 states that if γ+βs=s and ϑ:=dsΩln(ω0dΩ), then dγΩϑβ belongs to (Xs0(Ω)) and dsΩ((Δ)s)1(dγΩϑβ)ϑ.

    In Section 3, Lemmas 3.1 and 3.2 adapt, to our setting, the ideas of the sub-supersolution method developed, for (local) elliptic systems, in ([29], Theorem 3.2).

    In Lemma 3.1 we consider, for ε>0 and under the hypothesis of either Theorem 1.2 or Theorem 1.4, the set Cε:={(ζ1,ζ2)L2(Ω)×L2(Ω):εϑiζiε1ϑi for i=1,2}, and the operator T:Cε L2(Ω)×L2(Ω) defined by

    T(ζ1,ζ2):=(((Δ)s)1(adγ1Ωζβ12),((Δ)s)1(bdγ2Ωζβ21));

    and we show that T is a continuous and compact map and that, for ε small enough, T(Cε)Cε. Lemma 3.2 says that the same conclusions hold if the hypothesis of Theorem 1.3 are assumed and Cε is defined by

    Cε:={(ζ1,ζ2)L2(Ω)×L2(Ω):εϑiζiε1ϑi for i=1,2}.

    Finally, Theorems 1.2, 1.3, and 1.4 are proved using the Schauder fixed point theorem combined with Lemmas 3.1 and 3.2.

    Remark 2.1. (ⅰ) (see e.g., [34], Proposition 4.1 and Corollary 4.2) The following comparison principle holds: If u,vXs0(Ω) and (Δ)su(Δ)sv in Ω, then uv in Ω. In particular, if vXs0(Ω), (Δ)sv0 in Ω, and v0 in RnΩ, then v0 in Ω.

    (ⅱ) (see e.g., [34], Lemma 7.3) Let f:ΩR be a nonnegative and nonidentically zero measurable function such that f(Xs0(Ω)), and let u be the weak solution of problem (1.3). Then u satisfies, for some positive constant c,

    ucdsΩ in Ω. (2.1)

    (ⅲ) (see e.g., [35], Proposition 1.1) If fL(Ω) then the weak solution u of problem (1.3) belongs to Cs(Rn). In particular, there exists a positive constant c such that

    |u|cdsΩ in Ω. (2.2)

    For additional regularity resuls see, for instance, [4] and [28].

    (ⅳ) (Poincarè inequality, see [15], Theorem 6.5) Let s(0,1), let n>2s, and let 2s:=2nn2s. Then there exists a positive constant C=C(n,s) such that, for any measurable and compactly supported function f:RnR,

    fL2s(Rn)CRn×Rn(f(x)f(y))2|xy|n+spdxdy.

    (ⅴ) From the Hölder's inequality and the Poincarè inequality it follows that v(Xs0(Ω)) for any vL(2s)(Ω).

    (ⅵ) (Hardy inequality, see [32], Theorem 2.1) There exists a positive constant c such that, for any φXs0(Ω),

    dsΩφ2cφXs0(Ω). (2.3)

    (ⅶ) Let G:Ω×ΩR{} be the Green function for (Δ)s in Ω, with homogeneous Dirichlet boundary condition on RnΩ. Then, for any fC(¯Ω), the weak solution u of problem (1.3) is given by u(x)=ΩG(x,y)f(y)dy for xΩ and by u(x)=0 for xRnΩ.

    Let us recall the following result of [7]:

    Lemma 2.2. (See [7], Lemma 2) Let G be the Green function for (Δ)s in Ω, with homogeneous Dirichlet boundary condition on RnΩ. Then

    ΩG(.,y)dρΩ(y)dydsΩ if ρ<s,ΩG(.,y)dρΩ(y)dydsΩln(ω0dΩ) if ρ=s,ΩG(.,y)dρΩ(y)dyd2sρΩ if s<ρ<s+1.

    As a consequence of Lemma 2.2, we have the following

    Lemma 2.3. Let ρ[0,s+12). Then dρΩ(Xs0(Ω)) and

    ((Δ)s)1(dρΩ)dsΩ if ρ<s,((Δ)s)1(dρΩ)dsΩln(ω0dΩ) if ρ=s,((Δ)s)1(dρΩ)d2sρΩ if s<ρ<s+12 (2.4)

    Proof. Let φXs0(Ω). Since dsρΩL2(Ω), the Holder and the Hardy inequalities give Ω|dρΩφ|ΩdsρΩ|φdsΩ|cdsρΩ2φXs0(Ω)cφXs0(Ω) with c and c positive constants independent of φ. Thus dρΩ(Xs0(Ω)).

    Let G be the Green function for (Δ)s in Ω, with homogeneous Dirichlet boundary condition on RnΩ. To prove (2.4) it is enough (thanks to Lemma 2.2) to show that ((Δ)s)1(dρΩ)=ΩG(.,y)dρΩ(y)dy. Let {εj}jN(0,1) be a decreasing sequence such that limjεj=0, and for jN, let uεjXs0(Ω) be the weak solution of the problem

    (Δ)suεj=(dΩ+εj)ρ in Ω,uεj=0 on RnΩ. (2.5)

    Thus uεj=ΩG(.,y)(dΩ(y)+εj)ρdy in Ω and, by Lemma 2.2, there exists a positive constant c, independent of j, such that uεjcdsΩ if ρ<s, uεjcdsΩln(ω0dΩ) if ρ=s, and  uεjcd2sρΩ if s<ρ<12+s. In particular, there exists a positive constant c such that ΩuεjdρΩc for all jN. Let u(x):=limjuεj(x). By the monotone convergence theorem, u(x)=ΩG(x,y)dβΩ(y)dy. Taking uεj as a test function in (2.5) we get

    Rn×Rn(uεj(x)uεj(y))2|xy|n+2sdxdy=Ωuεj(y)(dΩ(y)+εj)ρdyΩuεjdρΩc,

    with c independent of j. For jN, let Uεj and U be the functions, defined on Rn×Rn, by

    Uεj(x,y):=uεj(x)uεj(y), U(x,y):=u(x)u(y).

    Then {Uεj}jN is bounded in H=L2(Rn×Rn,1|xy|n+2sdxdy). Thus, after pass to a subsequence if necessary, we can assume that {Uεj}jN is weakly convergent in H to some VH. Since {Uεj}jN converges pointwise to U on Rn×Rn, we conclude that UH and that {Uεj}jN converges weakly to U in H. Thus uXs0(Ω) and, for any φXs0(Ω),

    Rn×Rn(u(x)u(y))(φ(x)φ(y))|xy|n+2sdxdy=limjRn×Rn(uεj(x)uεj(y))(φ(x)φ(y))|xy|n+2sdxdy=limjΩ(dΩ+εj)βφ=ΩdβΩφ,

    Therefore u=((Δ)s)1(dρΩ) and so ((Δ)s)1(dρΩ)=ΩG(x,y)dβΩ(y)dy.

    Lemma 2.4. Assume the hypothesis of Theorem 1.2 and let ϑ1 and ϑ2 be as given there. Then, in each one of the cases i) and ii) of Theorem 1.2, dγ1Ωϑβ12(Xs0(Ω)), dγ2Ωϑβ21(Xs0(Ω)), ((Δ)s)1(dγ1Ωϑβ12)ϑ1, and ((Δ)s)1(dγ2Ωϑβ21)ϑ2 in Ω.

    Proof. When the condition i) of Theorem 1.2 holds we have ϑ1=ϑ2=dsΩ, and the lemma follows directly from Lemma 2.3. If the condition ii) holds, then γ1+sβ1<s, γ2+sβ2=s, ϑ1=dsΩ and ϑ2=dsΩln(ω0dΩ). Since (ln(ω0dΩ))β1L(Ω) we have dγ1Ωϑβ12=dγ1sβ1Ω(ln(ω0dΩ))β1dγ1sβ1Ω and so, by Lemma 2.3, dγ1Ωϑβ12(Xs0(Ω)) and ((Δ)s)1(dγ1Ωϑβ12)dsΩ=ϑ1 in Ω. Also, for δ>0 we have infΩdδΩ(ln(ω0dΩ))θβ1>0, and so

    dγ1Ωϑβ12=dγ1sβ1Ω(ln(ω0dΩ))β1=d(γ1+sβ1δ)ΩdδΩ(ln(ω0dΩ))β1d(γ1+sβ1δ)Ω in Ω.

    Then, by the comparison principle of Remark 2.1 ⅰ), and by Lemma 2.3,

    ((Δ)s)1(dγ1Ωϑβ12)((Δ)s)1(d(γ1+sβ1δ)Ω)dsΩ=ϑ1

    On the other hand, dγ2Ωϑβ21=dγ2sβ2Ω=dsΩ, and so, again by Lemma 2.3, dγ2Ωϑβ21(Xs0(Ω)) and ((Δ)s)1(dγ2Ωϑβ21)dsΩln(ω0dΩ)=ϑ2 in Ω.

    By replacing β1, γ1, ϑ1 and ϑ2 by β2, γ2, ϑ2 and ϑ1 respectively, the same argument proves the lemma in the case iii).

    Lemma 2.5. Assume the hypothesis of Theorem 1.4 and let ϑ1 and ϑ2 be as given there. Then the conclusions of Lemma 2.4 remain true for ϑ1 and ϑ2.

    Proof. Consider the case when the condition i) of Theorem 1.4 holds, i.e., the case when γ1+sβ1<s, s<γ2+sβ2<min{2s,12+s}, ϑ1=dsΩ and ϑ2=d2sγ2sβ2Ω. Then dγ1Ωϑβ12=dγ1β1(2sγ2sβ2)Ω. Since 0<γ1+β1(2sγ2sβ2)<γ1+sβ1<s, Lemma 2.3 gives that dγ1Ωϑβ12(Xs0(Ω)) and that ((Δ)s)1(dγ1Ωϑβ12)dsΩ=ϑ1 in Ω. On the other hand, dγ2Ωϑβ21=dγ2sβ2Ω and s<γ2+sβ2<min{2s,12+s}, and so, by Lemma 2.3,

    dγ2Ωϑβ21(Xs0(Ω)) and ((Δ)s)1(dγ2Ωϑβ21)d2sγ2sβ2Ω=ϑ2 in Ω.

    The proof when the condition ii) holds is similar.

    Lemma 2.6. Let ϑ:=dsΩln(ω0dΩ). If γ+sβ=s and β>0, then dγΩϑβ(Xs0(Ω)) and dsΩ((Δ)s)1(dγΩϑβ)ϑ in Ω.

    Proof. Since (ln(ω0dΩ))βL(Ω), we have dγΩϑβ=dsΩ(ln(ω0dΩ))βdsΩ. Then, by Lemma 2.3 and the comparison principle, dγΩϑβ(Xs0(Ω)) and ((Δ)s)1(dγΩϑβ)((Δ)s)1(dsΩ)dsΩln(ω0dΩ)=ϑ in Ω. On the other hand, since infΩdδΩ(ln(ω0dΩ))β1>0 for any δ>0, we have

    dγΩϑβ=d(γ+sβδ)ΩdδΩ(ln(ω0dΩ))β1d(γ+sβδ)Ω in Ω,

    and then so, by Lemma 2.3 and the comparison principle, ((Δ)s)1(dγΩϑβ)((Δ)s)1(d(γ+sβδ)Ω)dΩ.

    Lemma 3.1. Assume the hypothesis of Theorem 1.2 (respectively of Theorem 1.4), and let ϑ1 and ϑ2 be as defined there. For ε>0, let

    Cε:={(ζ1,ζ2)L2(Ω)×L2(Ω):εϑiζi1εϑi for i=1,2},

    and let T:CεL2(Ω)×L2(Ω) be defined by

    T(ζ1,ζ2)=(((Δ)s)1(adγ1Ωζβ12),((Δ)s)1(bdγ2Ωζβ21)). (3.1)

    Then:

    1) Cε is a closed convex set in L2(Ω)×L2(Ω).

    2) T(Cε)Cε for any ε positive and small enough.

    3) T:CεL2(Ω)×L2(Ω) is continuous

    4) T:CεL2(Ω)×L2(Ω) is a compact map.

    Proof. Clearly Cε is a closed convex set in L2(Ω)×L2(Ω). To see 2), note that, for any (ζ1,ζ2)Cε, adγ1Ωζβ12dγ1Ωϑβ12 and bdγ2Ωζβ21dγ2Ωϑβ21 and then, when the hypothesis of Theorem 1.2 hold (respectively of Theorem 1.4 hold), Lemma 2.5 (resp. Lemma 2.4) gives that T is well defined on Cε and that T(Cε)Xs0(Ω)×Xs0(Ω)L2(Ω)×L2(Ω).

    To see 2) observe that, for any (ζ1,ζ2)Cε,

    εβ1infΩ(a)dγ1Ωϑβ12adγ1Ωζβ12εβ1supΩ(a)dγ1Ωϑβ12 in Ω,εβ2infΩ(b)dγ2Ωϑβ21adγ2Ωζβ21εβ2supΩ(b)dγ2Ωϑβ21 in Ω

    and then, by the comparison principle and by Lemmas 2.5 and 2.4, there exist positive constants c1 and c2, both independent of ε, ζ1 and ζ2, such that

    c1εβ1ϑ1((Δ)s)1(εβ1infΩ(a)dγ1Ωϑβ12)((Δ)s)1(adγ1Ωζβ12)((Δ)s)1(εβ1supΩ(a)dγ1Ωϑβ12)c2εβ1ϑ1 in Ω

    and, similarly,

    c1εβ2ϑ2((Δ)s)1(adγ2Ωζβ21)c2εβ2ϑ2 in Ω,

    Since 0<β1<1 and 0<β2<1, for ε small enough we have

    εc1εβ1,εc1εβ2,c2εβ1ε1,and c2εβ2ε1. (3.2)

    Thus, for such a ε, T(Cε)Cε.

    To prove that T:CεL2(Ω)×L2(Ω) is continuous, consider an arbitrary (ζ1,ζ2)Cε, and a sequence {(ζ1,j,ζ2,j)}jNCε that converges to (ζ1,ζ2) in L2(Ω)×L2(Ω). After pass to a subsequence we can assume that {(ζ1,j,ζ2,j)}jN converges to (ζ1,ζ2) a.e. in Ω. Since 0adγ1Ωζβ12,jsupΩ(a)εβ1dγ1Ωϑβ12 and since, by Lemmas 2.5 and 2.4, dγ1Ωϑβ12(X10(Ω)), it follows that {adγ1Ωζβ12,j}jN is bounded in (X10(Ω)). Similarly, {adγ2Ωζβ21,j}jN is bounded in (X10(Ω)). Let (ξ1,j,ξ2,j):=T(ζ1,j,ζ2,j). Then {(ξ1,j,ξ2,j)}jN is bounded in X10(Ω)×X10(Ω). After pass to a further subsequence if necessary, we can assume that there exists (ξ1,ξ2)X10(Ω)×X10(Ω) such that {(ξ1,j,ξ2,j)}jN converges to (ξ1,ξ2) in L2(Ω)×L2(Ω), {(ξ1,j,ξ2,j)}jN converges (ξ1,ξ2) a.e. in Ω, and {ξ1,j,ξ2,j}jN converges weakly to (ξ1,ξ2) in X10(Ω)×X10(Ω). Let φX10(Ω). We have, for each j,

    Rn×Rn(ξ1,j(x)ξ1,j(y))(φ(x)φ(y))|xy|n+2sdxdy=Ωadγ1Ωζβ12,jφ, (3.3)
    Rn×Rn(ξ2,j(x)ξ2,j(y))(φ(x)φ(y))|xy|n+2sdxdy=Ωbdγ2Ωζβ21,jφ. (3.4)

    Now, {(ζ1,j,ζ2,j)}jNCε and so |adγ1Ωζβ12,jφ|εβ1a|dγ1Ωϑβ12φ|L1(Ω). Therefore, by the Lebesgue dominated convergence theorem,

    limjΩadγ1Ωζβ12,jφ=Ωadγ1Ωζβ12φ. (3.5)

    Similarly,

    limjΩbdγ2Ωζβ21,jφ=Ωbdγ2Ωζβ21φ. (3.6)

    Then

    Rn×Rn(ξ1(x)ξ1(y))(φ(x)φ(y))|xy|n+2sdxdy=Ωadγ1Ωζβ12φ, (3.7)
    Rn×Rn(ξ2(x)ξ2(y))(φ(x)φ(y))|xy|n+2sdxdy=Ωbdγ1Ωζβ11φ. (3.8)

    and so (ξ1,ξ2)=T(ζ1,ζ2). Then {T(ζ1,j,ζ2,j)}jN converges to T(ζ1,ζ2) in L2(Ω)×L2(Ω). Thus, for any sequence {(ζ1,j,ζ2,j)}jNCε that converges to (ζ1,ζ2) in L2(Ω)×L2(Ω), we have found a subsequence {(ζ1,jk,ζ2,jk)}kN such that {T(ζ1,jk,ζ2,jk)}kN converges to T(ζ1,ζ2) in L2(Ω)×L2(Ω). Therefore T is continuous.

    To see that T:CεL2(Ω)×L2(Ω) is a compact map, consider a bounded sequence {(ζ1,j,ζ2,j)}jNCε. Then 0adγ1Ωζβ12,jsupΩ(a)εβ1dγ1Ωϑβ12 and so, as above, {adγ1Ωζβ12,j}jN is bounded in (X10(Ω)). Then {((Δ)s)1(adγ1Ωζβ12,j)}jN is bounded in X10(Ω). Thus there exists a subsequence {(ζ1,jk,ζ2,jk)}kN such that (((Δ)s)1(adγ1Ωζβ12,j)}jN converges in L2(Ω). Since 0adγ2Ωζβ21,jksupΩ(b)εβ2dγ1Ωϑβ21 we can repeat the above argument to obtain (after pass to a further subsequence if necessary) that {((Δ)s)1(adγ2Ωζβ21,jk)}kN converges in L2(Ω). Therefore {T(ζ1,jk,ζ2,jk)}jN converges in L2(Ω)×L2(Ω).

    Lemma 3.2. Assume the hypothesis of Theorem 1.3, and let ϑ be as given in Lemma 2.6. For ε>0, let

    Cε:={(ζ1,ζ2)L2(Ω)×L2(Ω):εdΩζi1εϑ for i=1,2},

    and let T:CεL2(Ω)×L2(Ω) be defined by (3.1). Then, for ε positive and small enough, the conclusions 1)-4) of Lemma 3.1 hold for Cε and T.

    Proof. The proof of the lemma is similar to the proof of Lemma 3.1. Clearly 1) holds. To prove 2), consider an arbitrary (ζ1,ζ2)Cε. Since 0adγ1Ωζβ12εβ1supΩ(a)dsΩ and 0bdγ2Ωζβ21εβ1supΩ(b)dsΩ a.e. in Ω, we have that adγ1Ωζβ12 and bdγ2Ωζβ21 belong to (Xs0(Ω)). Then T(ζ1,ζ2) is well defined and belongs to L2(Ω)×L2(Ω). Also, εβ1infΩ(a)dγ1Ωϑβ1adγ1Ωζβ12εβ1supΩ(a)dsΩ in Ω, and εβ2infΩ(b)dγ2Ωϑβ2adγ2Ωζβ21εβ2supΩ(b)dsΩ in Ω. Then, by the comparison principle and Lemma 2.6, there exist positive constants c1 and c2, both independent of ε, ζ1, and ζ2, such that

    c1εβ1dsΩ((Δ)s)1(adγ1Ωζβ12) c2εβ1ϑ in Ω, andc1εβ2dsΩ((Δ)s)1(adγ2Ωζβ11)c2εβ2ϑ in Ω,

    and so, as in Lemma 3.1, (3.2) holds for ε small enough. Then, for such a ε, T(Cε)Cε.

    To prove 3), consider an arbitrary (ζ1,ζ2)Cε, and a sequence {(ζ1,j,ζ2,j)}jNCε that converges to (ζ1,ζ2) in L2(Ω)×L2(Ω). After pass to a subsequence we can assume that {(ζ1,j,ζ2,j)}jN converges to (ζ1,ζ2) a.e. in Ω. Since 0adγ1Ωζβ12,jsupΩ(a)εβ1dsΩ, and 0bdγ2Ωζβ21,jsupΩ(b)εβ1dsΩ, and taking into account that dsΩ(X10(Ω)), it follows that {adγ1Ωζβ12,j}jN and {bdγ2Ωζβ21,j}jN are bounded in (X10(Ω)). Let (ξ1,j,ξ2,j):=T(ζ1,j,ζ2,j). Then {(ξ1,j,ξ2,j)}jN is bounded in X10(Ω)×X10(Ω). Therefore, after pass to a further subsequence if necessary, we can assume that, for some (ξ1,ξ2)X10(Ω)×X10(Ω), {(ξ1,j,ξ2,j)}jN converges to (ξ1,ξ2) in L2(Ω)×L2(Ω) and a.e. in Ω; and that {ξ1,j,ξ2,j}jN converges weakly to (ξ1,ξ2) in X10(Ω)×X10(Ω). Let φX10(Ω). Since {(ζ1,j,ζ2,j)}jNCε and γ1+sβ1=s, we have |adγ1Ωζβ12,jφ|εβ1a|dsΩφ| and by the Hardy inequality, |dsΩφ|L1(Ω). Then, from (3.3) and (3.4), the Lebesgue dominated convergence theorem gives (3.5). (3.6) is obtained similarly. Then (3.7) and (3.8) hold. Thus (ξ1,ξ2)=T(ζ1,ζ2) and so {T(ζ1,j,ζ2,j)}jN converges to T(ζ1,ζ2) in L2(Ω)×L2(Ω). Then, as in the proof of Lemma 3.1, the conclusion that T is continuous is reached.

    To see 4), consider a bounded sequence {(ζ1,j,ζ2,j)}jNCε. We have 0adγ1Ωζβ12,jsupΩ(a)εβ1dsΩ and 0bdγ2Ωζβ21,jksupΩ(b)εβ2dsΩ in Ω, and so {adγ1Ωζβ12,j}jN and {bdγ2Ωζβ21,j}jN are bounded in (X10(Ω)). Now 4) follows as in the proof of Lemma 3.1

    Proof of Theorems 1.2, 1.3, and 1.4. Theorems 1.2, 1.3 and 1.4 follow from the Schauder fixed point theorem (as stated e.g., in [31], Theorem 3.2.20), combined with Lemma 3.1 in the case of Theorems 1.2 and 1.4; and with Lemma 3.2 in the case of Theorem 1.3.

    The author declare no conflicts of interest in this paper.



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