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Coordinated location-allocation of cruise ship emergency supplies under public health emergencies

  • For the rapid development of the cruise industry, the cruise disaster relief supply chain has attracted extensive attention, especially because COVID-19 cases on international cruise ships occurred. In this paper, we propose an idea of coordination layout for cruise ship emergency supplies, the problem optimized two objective functions of maximizing coverage satisfaction and minimizing the total cost, addressing the low efficiency of resource utilization at the same. By applying to cruise ship emergency supplies layout of Northeast Asia cruise port group system, using expert scoring method and AHP to evaluate cruise port security vulnerability. The NSGA-II algorithm is used to solve the multi-objective programming model. A numerical example shows that the optimization design model and method are valid and feasible, and the algorithm is efficient for solving the above collaborative location and allocation problem of sectional reserves, which can also offer a variety of decision-making options.

    Citation: Liling Huang, Yong Tan, Jinzhu Ye, Xu Guan. Coordinated location-allocation of cruise ship emergency supplies under public health emergencies[J]. Electronic Research Archive, 2023, 31(4): 1804-1821. doi: 10.3934/era.2023093

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  • For the rapid development of the cruise industry, the cruise disaster relief supply chain has attracted extensive attention, especially because COVID-19 cases on international cruise ships occurred. In this paper, we propose an idea of coordination layout for cruise ship emergency supplies, the problem optimized two objective functions of maximizing coverage satisfaction and minimizing the total cost, addressing the low efficiency of resource utilization at the same. By applying to cruise ship emergency supplies layout of Northeast Asia cruise port group system, using expert scoring method and AHP to evaluate cruise port security vulnerability. The NSGA-II algorithm is used to solve the multi-objective programming model. A numerical example shows that the optimization design model and method are valid and feasible, and the algorithm is efficient for solving the above collaborative location and allocation problem of sectional reserves, which can also offer a variety of decision-making options.



    The investigation of exact solutions to nonlinear fractional differential equations (NLFDEs) plays an active role in nonlinear sciences in the perspective of the physical phenomena of real world can effectively be modeled by the making use of the theory of derivatives and integrals of fractional order. NLFDEs have recently proved to be valuable tools to the modeling of many physical phenomena and have expanded the attention of many studies due to their frequent entrance in various applications, such as optical fibers, plasma physics, solid state physics, control theory, chemical kinematics, signal processing, fractional dynamics, fluid flow and other areas. The NLFDEs are also used in modeling of many chemical progressions, mathematical biology and many other problems in physics and engineering. In the last two decades, numerous techniques have been suggested to examine the exact solution to NLFDEs. As a consequence, a variety of methods have been established to get the exact solution to NLFDEs such as the variational iteration method [1,2,3,4,5], the Adomian's decomposition method [6,7,8], the differential transformation method [9,10], the Laplace perturbation method [11], the homotopy perturbation method [12,13,14] the finite element method [15], the (G/G)-expansion method [16,17,18,19], the improve Bernoulli sub-equation method [20,21,22], the Hirota bilinear method [23], the extended sinh-Gordon expansion method [24], the exp-function method [25,26,27], the fractional sub-equation method [28,29,30], the first integral method [31,32], the two variable (G/G,1/G)-expansion method [33,34,35] and so forth [36,37,38].

    Alzaidy [39] derived the exact and analytical solution to space-time fractional mBBM and space-time fractional ZKBBM equation by using fractional sub-equation method. Ege et al. [40] established the analytical and approximate solution to the space time fractional mBBm and space time fractional potential Kadomtsev-Petviashvili equation by the modified Kudryashov method. Recently, Bekir et al. [41] studied the exact solution to the space time fractional mKdV and space time fractional mBBM equation by the first integral method. On the other hand, Song et al. [42] investigated the exact traveling wave solution to the space time fractional ZKBBM equation by Bifurcation method. Aksoy et al. [43] derived the analytical solution to the time fractional Fokas equation, fractional ZKBBM equation, and fractional couple Burgers equation by means of the exponential rational function method. In addition, Ekici et al. [44] studied the solitary wave solution and periodic wave solution to the space-time fractional ZKBBM by a fractional sub-equation method. To our comprehension, the space-time fractional mBBM and fractional ZKBBM equation have not been studied by means of recently established two variables (G/G,1/G)-expansion method. So, the goal of this study is to establish new solutions to the above-mentioned equation by means of the proposed method. It is noteworthy to observe that, the two variable (G/G,1/G)-expansion method is the generalization of (G/G)-expansion method. The main idea of this method is that the solutions to NLFDEs are represented as a polynomial in two variables (G/G) and (1/G), wherein G=G(ξ) satisfies the second order ODE G(ξ)+λG(ξ)=μ, where G(ξ)+λG(ξ)=μ and μ are constants. The objective of this article is to establish further general and some fresh close form solitary wave solution to the space-time fractional mBBM equation and the space-time fractional ZKBBM equation by means of the two variable (G/G,1/G)-expansion method. The results obtained in this article have been associated with those existing in the literature and shown that the achieved solutions are new and further general. We have to end with determined that the solution might bring up their prominence throughout the contribution and be recorded in the literature.

    The rest of this article is organized as follows: In section 2, we have introduced preliminaries and fundamental tools, in section 3, we have described the two variable (G/G,1/G)-expansion method, in section 4, we have established the exact solution to the space-time fractional mBBM equation and the space time fractional ZKBBM equation by the proposed method. In section 5, we investigate results and discussion and in the last section, the conclusions are drawn.

    Let f:[0,)R, be a function. The α-order "conformable derivative" of f is defined by [45]:

    Tα(f)(t)=limε0f(t+εt1α)f(t)ε, (1)

    for all t > 0, α∈(0, 1). If f is α-differentiable in some (0, a), a > 0, and limt0+f(α)(t) exists, then define f(α)(0)=limt0+f(α)(t). The following theorems point out some properties which are satisfied with the conformable derivative.

    Theorem 1. Let α(0,1] and suppose f,g be α-differentiable at a point t>0. Then

    Tα(cf+dg)=cTα(f)+dTα(g), for all c,dR.

    Tα(tp)=ptpα, for all pR.

    Tα(c)=0, for all constant function f(t)=c.

    Tα(fg)=fTα(g)+gTα(f).

    Tα(fg)=gTα(f)fTα(g)g2.

    • In addition, if f is differentiable, then Tα(f)(t)=t1αdfdt.

    Some more properties involving the chain rule, Gronwall's inequality, some integration techniques, Laplace transform, Tailor series expansion and exponential function with respect to the conformable fractional derivative are explained in the study [46].

    Theorem 2. Let f be an α-differentiable function in conformable differentiable and suppose that g is also differentiable and defined in the range of f. Then

    Tα(fg)(t)=t1αv(t)u(v(t)). (2.2)

    Suppose the second order differential equation

    G(ξ)+λG(ξ)=μ, (3.1)

    and let us consider the following relations

    ϕ=G/G,ψ=1/G. (3.2)

    Thus, it is obtained

    ϕ=ϕ2+μψλ,ψ=ϕψ. (3.3)

    The solution to the mentioned equation in (3.1) depends on λ for which its values as λ<0,λ>0 and λ=0.

    Remark 1: If λ<0, the general solution to equation (3.1) is:

    G(ξ)=A1sinh(λξ)+A2cosh(λξ)+μλ, (3.4)

    where A1 and A2 are arbitrary constants. Accordingly, it yields

    ψ2=λλ2σ+μ2(ϕ22μψ+λ), (3.5)

    where σ=A21A22.

    Remark 2: If λ>0, the general solution to equation (3.1) is:

    G(ξ)=A1sin(λξ)+A2cos(λξ)+μλ, (3.6)

    where A1 and A2 are arbitrary constants. Consequently, it provides

    ψ2=λλ2σμ2(ϕ22μψ+λ), (3.7)

    where σ=A21+A22.

    Remark 3: If λ=0, the general solution to equation (3.1) is:

    G(ξ)=μ2ξ2+A1ξ+A2, (3.8)

    where A1 and A2 are arbitrary constants. As a result, it delivers

    ψ2=1A212μA2(ϕ22μψ). (3.9)

    Let us suppose the general nonlinear fractional differential equation (NLFDE) of the form

    P(u,Dαtu,Dβxu,DαtDαtu,DαtDβxu,DβxDβx,)=0,0<α1,0<β1, (3.10)

    where u is an unidentified function of spatial derivative x and temporal derivative t and p is a polynomial of u and its partial fractional derivatives wherein the maximum number of derivatives and the nonlinear terms are involved.

    Step 1: We suppose the traveling wave transformation in the subsequent

    ξ=kxββ+ctαα,u(x,t)=u(ξ) (3.11)

    where c and k are nonzero arbitrary constants.

    Using this wave transformation, we can rewrite the equation (3.10) as:

    R(u,u,u,u,)=0, (3.12)

    where prime stands for the derivative of u with respect to ξ.

    Step 2: Assume that the solution of (3.12) can be revealed as a polynomial in two variables ϕ and ψ as the following form:

    u(ξ)=Ni=0aiϕi+Ni=1biϕi1ψ (3.13)

    where in ai(i=0,1,2,) and bi(i=0,1,2,) are constants to be evaluated afterword.

    Step 3: The homogeneous balancing between the highest order derivatives and the nonlinear terms appearing in equation (3.12) determined the positive integer N.

    Step 4: Setting (3.13) into (3.12) together with (3.3) and (3.5), the equation (3.12) can be reduced into a polynomial in ϕ and ψ, where the degree of ψ is not greater than one. Equating the coefficients of this polynomial of like power to zero give a system of algebraic equations which can be solved by using the computer algebra, like Maple or Mathematica yields the values of ai,bi,μ,A1,A2 and λ where λ<0, which provide hyperbolic function solutions.

    Step 5: Similarly, we examine the values of ai,bi,μ,A1,A2 and λ when λ>0 and λ=0, yield the trigonometric and rational function solutions respectively.

    In this subsection, we investigate more general and new closed form wave solutions to the space time fractional mBBM equation by means of the two variables (G/G,1/G)-expansion method. We introduce the space time fractional mBBM equation [39] as follows:

    Dαtu+Dαxuvu2Dαxu+D3αxu=0, (4.1)

    where v is a nonzero constant. If spatial derivative term Dαxu is removed then the equation (4.1) transformed into mKdV equation. This equation was first derived to designate an approximation for surface long waves in nonlinear dispersive media. It is also describe the acoustic waves in inharmonic crystals, the hydro-magnetic waves in cold plasma and acoustic gravity waves in compressible fluids.

    For the mBBM equation (4.1), we present the following transformation:

    ξ=kxαα+ctαα,u(x,t)=u(ξ), (4.2)

    where c is the speed of the traveling wave. Using the transformation (4.2), the equation (4.1) reduces to the following integer order ordinary differential equation (ODE):

    (c+k)uvku2u+k3u=0. (4.3)

    Integrating equation (4.3) with zero constant (see [47] for details), we attain

    (c+k)uvku33+k3u=0. (4.4)

    Balancing the highest order derivative u and the nonlinear term u3, yields N=1. So, the solution to (4.3) converted to the following form:

    u(ξ)=a0+a1ϕ(ξ)+b1ψ(ξ), (4.5)

    where a0,a1 and b1 are constants to be determined.

    Case 1: For λ<0, setting equation (4.5) into (4.4) along with (3.3) and (3.5) yields a set of algebraic equations and solving these equations by using symbolic computation software Maple, we obtained the following results:

    a1=±b1λμ2+λ2σ,k=±b12vλ3μ2+3λ2σ,a0=0andc=132vλ3μ2+3λ2σ×b1(3μ2vb21λ2+3λ2σ)μ2+λ2σ.

    Substituting these values into (4.5), we find the solution to the mBBM equation as the form:

    u11(x,t)=±b1λμ2+λ2σ×λ(A1cosh(λξ)+A2sinh(λξ))A1sinh(λξ)+A2cosh(λξ)+μλ+b1A1sinh(λξ)+A2cosh(λξ)+μλ, (4.6)

    where ξ=±b12vλ3μ2+3λ2σxαα132vλ3μ2+3λ2σ×b1(3μ2vb21λ2+3λ2σ)μ2+λ2σtαα and σ=A21A22.

    Since A1 and A2 are integral constants, one may choose arbitrarily their values. Therefore, if we choose A1=0, A20 and μ=0 in (4.6), we obtain the following solitary wave solution

    u12(x,t)=±b1σ×tanh(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ2+3λ2σ)λ2σtαα))+b1×sech(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ2+3λ2σ)λ2σtαα)). (4.7)

    Again if A10, A2=0 and μ=0 in (4.6), we obtain the solitary wave solution.

    u13(x,t)=±b1σ×coth(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ2+3λ2σ)λ2σtαα))+b1×cosech(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ2+3λ2σ)λ2σtαα)). (4.8)

    Case 2: In a similar manner, substituting (4.5) into (4.4) along side with (3.3) and (3.7) yield a set of algebraic equations for a0,a1, c and k and solving these equations, we obtain the following solutions:

    a0=0,a1=±b1λλ2σμ2,b1=b1,k=±b12vλ3λ2σ3μ2,c=±132vλ3λ2σ3μ2×b1(3μ2vb21λ23λ2σ)μ2λ2σ.

    When we substituted these values into equation (4.5), we found the following solution to mBBM equation:

    u14(x,t)=±b1λμ2λ2σ×λ(A1cos(λξ)A2sin(λξ))A1sin(λξ)+A2cos(λξ)+μλ+b1A1sin(λξ)+A2cos(λξ)+μλ, (4.9)

    where ξ=b12vλ3λ2σ3μ2xαα±132vλ3λ2σ3μ2×b1(3μ2vb21λ23λ2σ)μ2λ2σtαα and σ=A21+A22.

    If we set A1=0, A20 (or A10, A2=0) and μ=0 in (4.9), we obtain the solitary wave solution

    u15(x,t)=±b1σ×tan(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ23λ2σ)λ2σtαα))+b1×sec(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ23λ2σ)λ2σtαα)), (4.10)
    u16(x,t)=±b1σ×cot(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ23λ2σ)λ2σtαα))+b1×cosec(±λ(b12vλ3λ2σxαα+132vλ3λ2σ×b1(vb21λ23λ2σ)λ2σtαα)). (4.11)

    Case 3: In the similar fashion when λ=0, using(4.5) and (4.4) along with(3.3) and (3.9), we will find a group of algebraic equations, whose solutions are as follows:

    a0=0,a1=±b11A212μA2,b1=b1,c=b12v3A216μA2,andk=±b12v3A216μA2k=±b12v3A216μA2.

    Substituting these values into equation (4.5), we attained the solution to equation (4.3)

    u17(x,t)=±b11A212μA2×μ(b12v3A216μA2xααb12v3A216μA2tαα)+A1+μ2(b12v3A216μA2xααb12v3A216μA2tαα)2+A1×(b12v3A216μA2xααb12v3A216μA2tαα)+A2+b1×1μ2(b12v3A216μA2xααb12v3A216μA2tαα)2+A1×(b12v3A216μA2xααb12v3A216μA2tαα)+A2. (4.12)

    It is remarkable to see that the traveling wave solution u11u17 of the space-time fractional mBBM equation are new and further general and have not been investigated in the previous study. These solutions forces are convenient to characterize the hydromagnetic waves in cold plasma, acoustic waves in inharmonic crystals and acoustic-gravity waves incompressible fluids.

    In this subsection, we establish the general and some fresh solutions to the space-time fractional ZKBBM equation over the two variable (G/G,1/G)-expansion method. This equation is significant in many physical phenomena and it arises as an explanation of gravity water waves in the long-wave regime. We consider the space-time fractional ZKBBM equation [39] as follows:

    Dαtu+Dαxu2auDαxubDαt(D2αxu)=0.t>0,0<α1, (4.13)

    where a and b are arbitrary constants. If we removed the spatial derivative term Dαxu, the equation (4.13) converted to BBM equation.

    For the space-time fractional ZKBBM equation, we present the following transformation:

    ξ=kxαα+ctαα,u(x,t)=u(ξ), (4.14)

    where c is the velocity of the traveling wave. Using traveling wave variable (4.14) equation (4.13) reduces to the following ODE for u=u(ξ):

    (c+k)u2akuubck2u=0 (4.15)

    Integrating (4.15) once with respect to ξ with zero constant, we obtain

    (c+k)uaku2bck2u=0 (4.16)

    Balancing the highest order derivatives and nonlinear terms, we obtained N=2. Therefore, the solution to equation (4.16) is of the following form:

    u(ξ)=a0+a1ϕ(ξ)+a2ϕ2(ξ)+b1ψ(ξ)+b2ϕ(ξ)ψ(ξ). (4.17)

    Case 1: For λ<0, inserting equation (4.17) into (4.16) along with (3.3) and (3.5) yields a set of algebraic equations whose solutions from the symbolic computation software Maple are as follows:

    Set1:a0=3bk2λ(bk2λ+1)a,a1=0,a2=3k2b(bk2λ+1)a,b1=3k2bμ(bk2λ+1)a,b2=±9μ29λ2σλ×bk2(bk2λ+1)aandc=kbk2λ+1,
    Set2:a0=2bk2λ(bk2λ1)a,a1=0,a2=3k2b(bk2λ1)a,b1=3k2bμ(bk2λ1)a,b2=±9μ29λ2σλ×bk2(bk2λ1)aandc=kbk2λ1.

    where k is an arbitrary constant.

    For Set 1, we obtain the following general solution to the space time fractional ZKBBM equation:

    u21(x,t)=3bk2λ(bk2λ+1)a+3k2b(bk2λ+1)a×(A1.λcosh(λξ)+A2.λsinh(λξ)A1sinh(λξ)+A2cosh(λξ)+μλ)23k2bμ(bk2λ+1)a×1A1sinh(λξ)+A2cosh(λξ)+μλ±9μ29λ2σλ×bk2(bk2λ+1)a×A1.λcosh(λξ)+A2.λsinh(λξ)A1sinh(λξ)+A2cosh(λξ)+μλ×1A1sinh(λξ)+A2cosh(λξ)+μλ, (4.18)

    where ξ=kxααkbk2λ+1tαα and σ=A21A22.

    Here A1 and A2 are constants of integration. Therefore, one can freely select their values. If we choose A1=0, A20 and μ=0 in (4.18), we attain the solitary wave solution

    u22(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×tanh2(λ(kxααkbk2λ+1tαα))±3λbk2σ(bk2λ+1)a×tanh(λ(kxααkbk2λ+1tαα))×sech(λ(kxααkbk2λ+1tαα)). (4.19)

    Again if we set A10,A2=0 and μ=0 in (4.18), we obtain the solitary wave solution

    u23(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×coth2(λ(kxααkbk2λ+1tαα))±3λbk2σ(bk2λ+1)a×coth(λ(kxααkbk2λ+1tαα))×cosech(λ(kxααkbk2λ+1tαα)). (4.20)

    Again for Set 2, we obtain the following general solution to the space time fractional ZKBBM equation:

    u24(x,t)=2bk2λ(bk2λ1)a3k2b(bk2λ1)a×(A1.λcosh(λξ)+A2.λsinh(λξ)A1sinh(λξ)+A2cosh(λξ)+μλ)2+3k2bμ(bk2λ1)a×1A1sinh(λξ)+A2cosh(λξ)+μλ±9μ29λ2σλ×bk2(bk2λ1)a×A1.λcosh(λξ)+A2.λsinh(λξ)A1sinh(λξ)+A2cosh(λξ)+μλ×1A1sinh(λξ)+A2cosh(λξ)+μλ, (4.21)

    where ξ=kxαα+kbk2λ+1tαα and σ=A21A22.

    If we choose A1=0, A20 (or A10, A10) and μ=0 in (4.21), we obtain the solitary wave solution

    u25(x,t)=2bk2λ(bk2λ1)a+3k2bλ(bk2λ1)a×tanh2(λ(kxαα+kbk2λ+1tαα))±3λbk2σ(bk2λ1)a×tanh(λ(kxαα+kbk2λ+1tαα))×sech(λ(kxαα+kbk2λ+1tαα)). (4.22)
    u26(x,t)=2bk2λ(bk2λ1)a+3k2bλ(bk2λ1)a×coth2(λ(kxαα+kbk2λ+1tαα))±3λbk2σ(bk2λ+1)a×coth(λ(kxαα+kbk2λ+1tαα))×cosech(λ(kxαα+kbk2λ+1tαα)). (4.23)

    Case 2: In the similar manner, when λ>0 inserting (4.17) into (4.16) along with (3.3) and (3.7) yields a set of algebraic equation for a0,a1,b1,a2,b2,c,k and solving these equations we have achieved the following results:

    Set1:a0=2bk2λ(bk2λ1)a,a1=0,a2=3k2b(bk2λ1)a,b1=3k2bμ(bk2λ1)a,b2=±9μ2+9λ2σλ×bk2(bk2λ1)a,c=kbk2λ+1andk=k.
    Set2:a0=3bk2λ(bk2λ+1)a,a1=0,a2=3k2b(bk2λ+1)a,b1=3k2bμ(bk2λ+1)a,b2=±9μ2+9λ2σλ×bk2(bk2λ+1)a,c=kbk2λ+1andk=k.

    Now, we find the following exact solution to the space time fractional ZKBBM equation (4.13) for Set 1:

    u27(x,t)=2bk2λ(bk2λ1)a3k2b(bk2λ1)a×(A1.λcos(λξ)A2.λsin(λξ)A1sin(λξ)+A2cos(λξ)+μλ)2+3k2bμ(bk2λ1)a×1A1sin(λξ)+A2cos(λξ)+μλ±9μ2+9λ2σλ×bk2(bk2λ1)a×A1.λcos(λξ)A2.λsin(λξ)A1sin(λξ)+A2cos(λξ)+μλ×1A1sin(λξ)+A2cos(λξ)+μλ. (4.24)

    where ξ=kxαα+kbk2λ+1tαα and σ=A21+A22.

    As A1 and A2 are integral constants, if we select A1=0, A20(or A10, A2=0) and μ=0 into (4.24), we attain the solitary wave solution

    u28(x,t)=2bk2λ(bk2λ1)a3k2bλ(bk2λ1)a×tan2(λ(kxαα+kbk2λ+1tαα))±3λbk2σ(bk2λ1)a×tan(λ(kxαα+kbk2λ+1tαα))×sec(λ(kxαα+kbk2λ+1tαα)), (4.25)
    u29(x,t)=2bk2λ(bk2λ1)a3k2bλ(bk2λ1)a×cot2(λ(kxαα+kbk2λ+1tαα))±3λbk2σ(bk2λ1)a×cot(λ(kxαα+kbk2λ+1tαα))×cosec(λ(kxαα+kbk2λ+1tαα)). (4.26)

    Again, we find the following exact solution to the space time fractional ZKBBM equation for Set 2:

    u210(x,t)=3bk2λ(bk2λ+1)a3k2b(bk2λ+1)a×(A1.λcos(λξ)A2.λsin(λξ)A1sin(λξ)+A2cos(λξ)+μλ)2+3k2bμ(bk2λ+1)a×1A1sin(λξ)+A2cos(λξ)+μλ±9μ2+9λ2σλ×bk2(bk2λ+1)a×A1.λcos(λξ)A2.λsin(λξ)A1sin(λξ)+A2cos(λξ)+μλ×1A1sin(λξ)+A2cos(λξ)+μλ, (4.27)

    where ξ=kxααkbk2λ+1tαα and σ=A21+A22.

    If we set A1=0, A20 (or A10, A2=0) and μ=0 into (4.27), we find the solitary wave solution:

    u211(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×tan2(λ(kxααkbk2λ+1tαα))±3λbk2σ(bk2λ+1)a×tan(λ(kxααkbk2λ+1tαα×sec(λ(kxααkbk2λ+1tαα)). (4.28)
    u212(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×cot2(λ(kxααkbk2λ+1tαα))±3λbk2σ(bk2λ+1)a×cot(λ(kxααkbk2λ+1tαα×cosec(λ(kxααkbk2λ+1tαα)). (4.29)

    Case 3: Finally when λ=0, substituting equation (4.17) into (4.16) along with (3.3) and (3.9) yields a set of algebraic equations for a0,a1,b1,a2,b2,c,k and whose solution are as follows:

    a0=0,a1=0,a2=3bk2a,b1=3bk2μa,b2=±9A21+18μA2×bk2a,c=kandk=k.

    Inserting these values into equation (4.16), we attain the rational function solution to the space time fractional ZKBBM equation (4.13) as follows:

    u213(x,t)=3bk2a×(μ×(kxααktαα)+A1μ2×(kxααktαα)2+A1×(kxααktαα)+A2)23bk2μa×1μ2×(kxααktαα)2+A1×(kxααktαα)+A2±9A21+18μA2×bk2a×μξ+A1μ2×(kxααktαα)2+A1×(kxααktαα)+A2×1μ2×(kxααktαα)2+A1×(kxααktαα)+A2. (4.30)

    It is remarkable to observe that some of the obtained solutions demonstrate good similarity with earlier established solutions. A comparison between Mohyud-Din et al. [48] solutions and our obtained solutions is presented in the following Table 1:

    Table 1. Comparison between Mohyud-Din et al. [48] solutions and the obtained solutions.

    Table 1.  Comparison between Mohyud-Din et al. [48] solutions and the obtained solutions.
    Mohyud-Din et al. solutions [48] Obtained solutions
    If μ=D=1 and C=0 the solution U31(ξ) becomes:
    U31(ξ)=2bk2λ(4bk2λ1)a6k2bλ(4bk2λ1)a×tan2(λξ)
    If A1=μ=σ=0 and A2=1 then our solution u28(x,t) becomes:
    u28(x,t)=2bk2λ(bk2λ1)a3k2bλ(bk2λ1)a×tan2(λ(kxαα+kbk2λ+1tαα
    If μ=C=1 and D=0 the solution U31(ξ) becomes:
    U31(ξ)=2bk2λ(4bk2λ1)a+6k2bλ(4bk2λ1)a×cot2(λξ)
    If A2=μ=σ=0 and A1=1 then our solution u29(x,t) becomes:
    u29(x,t)=2bk2λ(bk2λ1)a3k2bλ(bk2λ1)a×cot2(λ(kxαα+kbk2λ+1tαα
    If μ=D=1 and C=0 then the solution U41(ξ) becomes:
    U41(ξ)=6bk2λ(4bk2λ+1)a6k2bλ(4bk2λ+1)atan2(λξ)
    If A1=μ=σ=0 and A2=1 then obtain solution u211(x,t) becomes:
    u211(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×tan2(λ(kxααkbk2λ+1tαα
    If μ=C=1 and D=0 then the solution U41(ξ) becomes:
    6bk2λ(4bk2λ+1)a6k2bλ(4bk2λ+1)acot2(λξ)
    If A2=μ=σ=0 and A1=1 then obtain solution u212(x,t) becomes:
    u212(x,t)=3bk2λ(bk2λ+1)a3k2bλ(bk2λ+1)a×cot2(λ(kxααkbk2λ+1tαα

     | Show Table
    DownLoad: CSV

    The trigonometric function solutions referred to the above table is similar and if we set definite values of the arbitrary constants they are identical. It is substantial to understand that the traveling wave solutions u22(x,t), u23(x,t), u25(x,t), u26(x,t), and u22(x,t) of the fractional ZKBBM equation are all new and very much important which were not originate in the previous work. This diffusion equation is significant in various physical phenomena. Itarises as an explanation of gravity water waves in the long-wave regime that creates outstanding model in physics and engineering.

    In this study, we have obtained some new and further general solitary wave solutions to two nonlinear space time fractional differential equation, namely, the time fractional mBBM equation and the fractional ZKBBM equation in terms of hyperbolic, trigonometric and rational function solution involving parameters. It is remarkable to see that our achieve solutions through the suggested method are more new and further general compared to the existing literature. The obtained solutions to these equations are capable to investigate the mathematical model of gravity water waves in the long-wave regime, the acoustic waves in inharmonic crystals, hydromagnetic waves in cold plasma and acoustic-gravity waves incompressible fluids. The competence of the two variables (G/G,1/G)-expansion method is consistent, reliable and very much attractive. Since each nonlinear equation has its own inconsistent characteristic, the future research might be how to recommend method is compatible for revealing the solutions to other NLFDEs.

    The authors would like to express their deepest appreciation to the reviewers for their valuable suggestions and comments to improve the article.

    The authors declare no conflict of interest.



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