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Kirchhoff-type differential inclusion problems involving the fractional Laplacian and strong damping

  • The aim of this paper is to investigate the existence of weak solutions for a Kirchhoff-type differential inclusion wave problem involving a discontinuous set-valued term, the fractional p-Laplacian and linear strong damping term. The existence of weak solutions is obtained by using a regularization method combined with the Galerkin method.

    Citation: Mingqi Xiang, Binlin Zhang, Die Hu. Kirchhoff-type differential inclusion problems involving the fractional Laplacian and strong damping[J]. Electronic Research Archive, 2020, 28(2): 651-669. doi: 10.3934/era.2020034

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  • The aim of this paper is to investigate the existence of weak solutions for a Kirchhoff-type differential inclusion wave problem involving a discontinuous set-valued term, the fractional p-Laplacian and linear strong damping term. The existence of weak solutions is obtained by using a regularization method combined with the Galerkin method.



    In this paper, we consider the following initial boundary value problem

    {utt+M([u]ps,p)(Δ)spu+(Δ)αut+μ(x,t)=f,  (x,t)QT,μΦ(x,t,ut),  a.e. (x,t)QT,u(x,t)=0,  (x,t)(RNΩ)×(0,T),u(x,0)=u0(x), ut(x,0)=u1(x),  xΩ, (1)

    where s,α(0,1), 1<p<N/s, ΩRN is a bounded domain with smooth boundary Ω, 0<T< is a given constant and QT=Ω×(0,T), M:R+0R+ is a continuous function and Φ is a discontinuous and nonlinear set valued mapping by filling in jumps of a function a(x,t,s):QT×RR, [u]s,p is the Gagliardo seminorm defined by

    [u]s,p=(R2N|u(x,t)u(y,t)|p|xy|N+psdxdy)1/p.

    Here (Δ)sp is the fractional p-Laplace operator which, up to a normalization constant, is defined as

    (Δ)spφ(x)=2limε0+RNBε(x)|φ(x)φ(y)|p2(φ(x)φ(y))|xy|N+psdy,xRN,

    along functions φC0(RN). Henceforward Bε(x) denotes the ball of RN centered at xRN and radius ε>0. In particular, if p=2 the fractional p-Laplacian (Δ)sp reduces to the fractional Laplacian (Δ)s.

    Furthermore, we assume a and Φ satisfy the following assumptions.

    (H1) For each ξR, a is a continuous function with respect to (x,t)QT and for each (x,t)QT, aLloc(R). Moreover, there exist positive constants a0,a1,a2 such that

    a0|ξ|qa1a(x,t,ξ)ξ,  |a(x,t,ξ)|a2(|ξ|q1+1),  for each (x,t,ξ)QT×R,

    where q(1,ps) and ps=Np/(Nsp).

    (H2) The set valued function Φ:QT×R2R is obtained by filling in jumps of the function a in (H1) by means of the functions a_ε,¯aε,a_,¯a:RR as follows

    a_ε(x,t,ξ)=inf|ηξ|εa(x,t,η),  ¯aε(x,t,ξ)=sup|ηξ|εa(x,t,η),  a_(x,t,ξ)=limε0+a_ε(x,t,ξ),¯a(x,t,ξ)=limε0+¯aε(x,t,ξ),  Φ(x,t,ξ)=[a_(x,t,ξ),¯a(x,t,ξ)].

    (H3) u0Ws,p(Ω)Wα,20(Ω), u1L2(Ω), fLq(QT), where q=qq1.

    Throughout the paper, without explicit mention, we assume that M:[0,)R+ is continuous and verifies

    (M1) there exists m0>0 such that M(τ)m0 for all τ0.

    A typical example of M is given by M(t)=m0+m1t for t0, where m0>0,m10. When M is of this type, problem (1) is said to be degenerate if a=0, while it is called non–degenerate if a>0. As for some recent existence results on Kirchhoff-type problems, we refer the interested readers to [5,11]. Recently, the fractional Kirchhoff problems have received more and more attention. Some new existence results for fractional Kirchhoff problems were given, for example, in [18,19,20,24,25,26,27,34].

    In recent years, fractional Laplacian operator and related equations have an increasingly wide utilization in many important fields, as explained by Caffarelli in [4], Laskin in [15] and Vázquez in [36]. In [8], a stationary Kirchhoff variational equation was first proposed by Fiscella and Valdinoci as a model to study the nonlocal aspect of the tension arising from nonlocal measurements of the fractional length of the string. Indeed, the stationary problem of (1) is a fractional version of a model, the so-called stationary Kirchhoff equation, which was introduced by Kirchhoff in [12] as a model to study elastic string vibrations. The literature on elliptic type problems involving fractional Laplacian and its variant is rich and very vast, see for example [8,25,26,27,35] and the references cited there.

    Recently, the fractional hyperbolic problems with continuous nonlinearities have been studied by many researchers. For example, Pan, Pucci and Zhang [29] studied the initial-boundary value problem of degenerate Kirchhoff-type

    utt+[u]2(θ1)s(Δ)su=|u|p1u  in Ω×R+, (2)

    where ΩRN is a bounded domian with Lipshcitz boundary, θ[1,2s/2), p(2θ1,2s1) and [u]s is the Gagliardo seminorm of u defined by

    [u]s=(R2N|u(x,t)u(y,t)|2|xy|N+2sdxdy)1/2.

    Under some appropriate conditions, the authors obtained the global existence, vacuum isolating and blow up of solutions for (2) by using the Galerkin method combined with the potential wells theory. Moreover, the authors also investigated the global existence of solutions under the critical initial conditions. Furthermore, Pan et al. in [28] considered the following degenerate Kirchhoff equation with nonlinear damping term

    utt+[u]2(θ1)s(Δ)su+|ut|a2ut+u=|u|b2u  in Ω×R+, (3)

    2<a<2θ<b<2s. Under some natural assumptions, the authors obtained the global existence, vacuum isolating, asymptotic behavior and blow up of solutions for (3) by combining the Galerkin method with potential wells theory. In [20], Lin et al. studied the initial-boundary value problem of Kirchhoff wave equation

    utt+[u]2(θ1)s(Δ)su=f(u)  in Ω×R+.

    The authors established some sufficient conditions on initial data such that the solutions blow up in finite time for arbitrary positive initial energy by using an modified concavity method. Moreover, when f(u)=|u|p2u, the authors obtained the upper and lower bounds for blow up time. Concerning the related diffusion problems, for instance, we refer to [30,31,33,39] for more results and methods.

    It is worth mentioning that problem (1) can be regard as a fractional version of the initial-boundary value problem of the following equation

    {uttM(upLp(RN))div(|u|p2u)Δut+π=f,  (x,t)QT,πΦ(x,t,ut),  a.e. (x,t)QT,u(x,t)=0,  (x,t)Ω×(0,T),u(x,0)=u0(x), ut(x,0)=u1(x),  xΩ. (4)

    In [32], Park and Kim studied the existence of solutions for problem (4) without the Kirchhoff function M. The research on differential inclusions is an interesting topic in recent years. These problems arise mainly from physics and optimization, especially continuum mechanics, where non-monotone, multi-valued constitutive laws lead to a class of differential inclusions (variational inequalities). For a brief account of works on such variational inequalities we refer to [21] for the details. For the analysis of nonlinear second order or fourth order or six order hyperbolic partial differential equations with damping, we refer to the seminal work of Lions and Strauss [22], see also [9,16,17,40,41] for more recent results. In recent years, partial differential equations of hyperbolic type with variable exponent growth conditions were studied by Antontsev [1], see also Autuori and Pucci [2,3] for Kirchhoff systems with p(x)-growth.

    However, to the best of our knowledge, there are no papers that deal with the global existence and blow-up results for problems like (1). Inspired by above papers, we study the existence of global solutions that vanish at infinity or solutions that blow up in finite time for problem (1) involving the fractional p-Laplacian and discontinuous nonlinearity. Since our problem is nonlocal and the diffusion coefficient M([u]ps,p) is a function, our discussion is more elaborate than the papers in the literature.

    The rest of this paper is organized as follows. In section 2, we will give some necessary definitions and properties of fractional Sobolev spaces. In section 3, we obtain the existence of weak solutions for problem (1.1) by Galerkin's approximation method. In section 4, we give an example to illustrate our result.

    To study the existence of solutions for equation (1), let us first recall some results related to the fractional Sobolev space Ws,p0(Ω). For convenience, we shortly denote by 2 the norm of L2(Ω). Let ΩRN be a bounded domain, 1<p< and set

    Ws,p0(Ω)={uLp(Ω):[u]s,p<, u=0 a.e. in RNΩ},

    where the Gagliardo seminorm [u]s,p is defined as

    [u]s,p=(RN|u(x)u(y)|p|xy|N+spdxdy)1/p.

    Equipped with the norm

    u=[u]s,p,

    Ws,p0(Ω) is a uniformly convex Banach space, and hence reflexive. The fractional critical exponent is defined by

    ps={NpNsp  if sp<N;  if spN.

    Moreover, the fractional Sobolev embedding states that Ws,p0(Ω)Lq(Ω) is continuous if sp<N and 1q<ps. For more detailed account on the properties of Ws,p0(Ω), we refer to [7].

    Definition 2.1. Let ΩRN be a bounded domain with smooth boundary. We define

    W(QT)={uLq(QT):uLp(0,T;Ws,p0(Ω))},

    with the norm

    uW(QT)=uLq(QT)+(T0R2N|u(x,t)u(y,t)|p|xy|N+psdxdydt)1/p.

    Remark 1. Following the standard proof of Sobolev spaces, we can prove that W(QT) is a reflexive Banach space if 1<p,q<.

    In the following, we give a useful result which will be used to get the existence of solutions for problem (1).

    Proposition 1. Let Ω be a bounded domain in RN and let {ωi}i=1 be an orthogonal basis in L2(Ω). Then for any ε>0, there exists a constant Nε>0 such that

    uL2(Ω)(Nεi=1(Ωuωidx)2)12+εuWs,p0(Ω)

    for all uWs,p0(Ω) where 2N/(N+2s)p<N/s.

    Proof. Following the idea of [13], we first show that for any δ>0 and ε>0 there exists positive integer number Nε,δ such that

    u2(1+δ)(Nε,δi=1Ωu(x)ωi(x)dx)1/2+ε[u]s,p. (5)

    Arguing by contradiction, we assume that there exists an ϵ0>0 and a sequence {un}n=1Ws,p0(Ω) such that

    un2>(1+δ)(ni=1(Ωun(x)ωi(x)dx)2)1/2+ε0[un]s,p,

    for any n. Let vn=un/un2. Then

    1=vn2>(1+δ)(ni=1(Ωvn(x)ωi(x)dx)2)1/2+ε0[vn]s,p, (6)

    which means that

    [vn]s,p1ε0  for any n=1,2,.

    Since 2N/(N+2s)p<N/s and the embedding of Ws,p0(Ω) into L2(Ω) is compact, there exists a subsequence {vnk}k=1 such that {vnk}k=1 strongly converges to some function v in L2(Ω). Hence v2=vn2=1. Since {ωi}i=1 is an orthogonal basis of L2(Ω), we also have

    Pnkvnk:=nki=1(Ωvnk(x)ωi(x)dx)ωi

    converges strongly to v. Indeed, we have

    vPnkvnk2=Pnk(vvnk)+vPnkv2vvnk2+vPnkv20

    as k. Using (6) and letting k, we deduce 11+δ, which is absurd. Thus, (5) holds true.

    By (5), we obtain

    u2(Nε,δi=1Ωu(x)ωi(x)dx)1/2+δ(Nε,δi=1Ωu(x)ωi(x)dx)1/2+ε[u]s,p(Nε,δi=1Ωu(x)ωi(x)dx)1/2+δu2+ε[u]s,p(Nε,δi=1Ωu(x)ωi(x)dx)1/2+(Cδ+ε)[u]s,p,

    where C>0 is the embedding constant of Ws,p0(Ω) into L2(Ω). Therefore, the proof is complete.

    In this section, we prove the main result of this paper.

    Definition 3.1. A pair of functions u,μ:QTR is called a weak solution of (1.1), if

    {uW(QT)L(0,T;Ws,p0(Ω))C(0,T;Wα,20(Ω)),utL(0,T;L2(Ω))L2(0,T;Wα,20(Ω))Lq(QT),fLq(QT),  μΦ(x,t,ut) a.e. (x,t)QT,

    and

    Ωut(x,T)φ(x,T)dxQTutφtdxdt+T0M([u]ps,p)u,φs,pdt+T0ut,φα,2dt+QTμφdxdt=QTfφdxdt+Ωu1φ(x,0)dx

    hold for all φC1(0,T;C0(Ω)). Here u,φs,p and ut,φα,2 are defined as

    u,φs,p:=R2N|u(x,t)u(y,t)|p2(u(x,t)u(y,t))|xy|N+ps(φ(x,t)φ(y,t))dxdy

    and

    ut,φα,2=R2N(ut(x,t)ut(y,t))(φ(x,t)φ(y,t))|xy|N+2αdxdy.

    We need a regularization of a defined by

    an(x,t,ξ)=na(x,t,ξτ)ρ(nτ)dτ,

    where ρC0(1,1), ρ0 and 11ρ(τ)dτ=1.

    Lemma 3.2. The function an is continuous and satisfies the following inequalities

    an(x,t,ξ)ξa02q|ξ|qC0

    and

    |an(x,t,ξ)|2qa2(|ξ|q1+1),

    for each (x,t,ξ)QT×R, where C0=a02+a1+a2+a2(2a2a0)q1.

    Proof. Since for each (x,t)QT, aLloc(R), it's easy to show that anC(QT×R) for each nN. From assumption (H2) and Young's inequality, for each (x,t,s)QT×R, we have

    an(x,t,ξ)ξ=na(x,t,ξτ)ξρ(nτ)dτ=11a(x,t,ξτn)ξρ(τ)dτa011|ξτn|qρ(τ)dτa211|ξτn|q1ρ(τ)dτa1a2
    a0211|ξτn|qρ(τ)dτa2(2a2a0)q1a1a2=a02|ξτn|qa2(2a2a0)q1a1a2

    where τ0[1,1]. From the inequality

    |ξ|q2q1(|ξτn|q+|τ0n|q),

    we obtain

    an(x,t,ξ)ξa02q|ξ|qC0, (7)

    where C0=a02+a1+a2+a2(2a2a0)q1. Similarly, by (H2), we get

    |an(x,t,ξ)|a211|ξτn|q1ρ(τ)dτ+a22qa2(|ξ|q1+1). (8)

    Thus, the proof is finished.

    We choose a sequence {ωj}j=1C0(Ω) such that C0(Ω)¯n=1VnC1(ˉΩ) and {ωj}j=1 is a complete orthonormal basis in L2(Ω), where Vn=span{ω1,ω2, ,ωn}, see [10,24].

    Since C0(Ω)¯n=1VnC1(ˉΩ), we have the following lemma.

    Lemma 3.3. For the function u0Ws,p(Ω)Wα,20(Ω), there exists a sequence {ψn} with ψnVn such that ψnu0 in Ws,p(Ω)Wα,20(Ω) as n.

    Proof. For u0Ws,p(Ω)Wα,20(Ω), there exists a sequence {vn} in C0(Ω) such that vnu0 in Ws,p(Ω)Wα,20(Ω). Since {vn}n=1C0(Ω)¯m=1VmC1(¯Ω), we can find a sequence {vkn}m=1Vm such that for each nN, there holds vknun in C1(¯Ω) as k. For 12n, there exists kn1 such that vknnunC1(¯Ω)12n. Thus

    vknnu0Ws,p(Ω)Wα,20(Ω)CvknnvnC1(¯Ω)+vnu0Ws,p(Ω)Wα,20(Ω).

    That is vknnu0 in Ws,p(Ω)Wα,20(Ω) as n. Denote un=vknn. Since unm=1Vm, there exists Vmnsuch that unVmn, without lost of generality, we assume that Vm1Vm2 as m1m2. We suppose that m1>1 and define ψn as follows: ψn(x)=0, n=1,,m11; ψn=u1,n=m1,,m21; ψn=u2,n=m2,,m31;, then we obtain the sequence {ψn} and ψnu0 in Ws,p(Ω)Wα,20(Ω) as n.

    The existence of weak solutions for problem (1.1) is proved by Galerkin's approximation method. We shall find the sequence of approximate solutions with the form

    un(x,t)=nj=1(ηn(t))jωj(x).

    The unknown functions (ηn(t))j are determined by an ordinary differential system as follows:

    {η(t)+Pn(t,η(t),η(t))=Fn(t),η(0)=U0n, η(0)=U1n, (9)

    where (U0n)i=Ωψnωidx, (U1n)i=Ωϕnωidx, (Fn)i=Ωfnωidx, ψnVn,ϕnVn,fnC0(QT), and ψnu0 strongly in Ws,p(Ω)Wα,20(Ω), ϕnu1 strongly in L2(Ω), fnf strongly in Lq(x,t)(QT). Here the vector-valued function Pn(t,μ,ν):[0,T]×Rn×RnRn is defined as:

    (Pn(t,μ,ν))i=M([nj=1μjωj]ps,p)nj=1μjωj,ωis,p+nj=1νjωj,ωiα,2+Ωan(x,t,nj=1νjωj)ωidx,i=1,,n,

    where μ=(μ1,,μn) and ν=(ν1,,νn).

    Let η(t)=X(t),Y(t)=(η(t),X(t)) and Hn(t,Y)=(X,FnPn(t,η,X)). Then the problem (9) is transformed into the following problem

    {Y(t)=Hn(t,Y(t)),Y(0)=(U0n,U1n). (10)

    The inequality (7) implies

    Pn(t,η,X)X=Pn(t,η,η)η=M([un]ps,p)un,unts,p+unt,untα,2+Ωan(x,t,unt)untdx1pddt[un]ps,p+[unt]2α,2+a02qΩ|unt|qdxC0.

    From (10) and Young's inequality, we obtain

    YY+1pddt˜M([un]ps,p)+[unt]2α,2+a02qΩ|unt|qdx|X||η(t)|+|Fn(t)||X|+C012|X|2+12|η(t)|2+12|X|2+12|Fn(t)|2+C0|Y|2+12|Fn(t)|2+C0,

    where ˜M([un]ps,p)=[un]ps,p0M(τ)dτ. Denote En(t)=12|Y|2+1p˜M([un]ps,p). Then,

    En(t)2En(t)+12|Fn(t)|2+C0.

    This together with Gronwall's inequality yields that

    En(t)En(0)e2t+e2tt0|Fn(t)|2e2τdτ+C02(e2t1)En(0)e2T+e2TT0|Fn(t)|2dt+C02(e2T1):=Cn(T),  for each t[0,T].

    Thus, |Y(t)Y(0)|22Cn(T). Denote

    Ln=max(t,Y)[0,T]×B(Y(0),22Cn(T))|Hn(t,Y)|, τn=min{T,22Cn(T)Ln},

    where B(Y(0),22Cn(T)) is the ball of radius 22Cn(T) with center at the point Y(0) in R2n. From the definition of H(t,Y), H(t,Y) is continuous with respect to (t,Y). By Peano's Theorem, we know that (10) admits a C1 solution on [0,τn], that is, (9) has a C2 solution on [0,τn] denoted by η1n(t). Let η(τn),η(τn)t be the initial value of problem (9), then we can repeat the above process and get a C2 solution η2n(t) on [τn,2τn]. Without lost of generality, we assume that T=[Tτn]τn+(Tτn)τn,0<(Tτn)<1, where [Tτn] is the integer part of Tτn, (Tτn) is the decimal part of Tτn. We can divide [0,T] into [(i1)τn,iτn],i=1,...,L and [Lτn,T] where L=[Tτn], then there exist C2 solution ηin(t) in [(i1)τn,iτn],i=1,...,L and ηL+1n(t) in [Lτn,T]. Therefore, we get a solution ηn(t) C2([0,T]) defined by

    ηn(t)={η1n(t), if t[0,τn],η2n(t), if t(τn,2τn],ηLn(t), if t((L1)τn,Lτn],ηL+1n(t), if t(Lτn,T].

    Lemma 3.4. (A priori estimate) There exists C(T)>0 independent of n such that the following estimates

    Ω|un(x,t)t|2dx+[un(x,t)]ps,p+[un(x,t)]2α,2C(T),  t[0,T],QT|unt|qdxdt+T0[un]ps,pdt+T0[unt]2α,2dtC(T),

    hold.

    Proof. By (9), for each 1in, we have

    Ω2unt2ωidx+M([un]ps,p)un,ωis,p+unt,ωiα,2+Ωan(x,t,unt)ωidx=Ωfnωidx. (11)

    Multiplying (11) by ddt(ηn(t))i, then summing up i from 1 to n, we obtain

    Ω2unt2untdx+M([un]ps,p)un,unts,p+unt,untα,2+Ωan(x,t,unt)untdx=Ωfnuntdx.

    The inequality (7), (11) and Young's inequality imply

    12ddtΩ|un(x,t)t|2dx+1pddt˜M([un]ps,p)+[unt]2α,2+a02q+1Ω|un(x,t)t|qdx(2q+1a0)1q1Ω|fn(x,t)|qdx+C0|Ω|. (12)

    Further,

    ddt(12Ω|un(x,t)t|2dx+1p˜M([un]ps,p))(2q+1a0)1q1Ω|fn(x,t)|qdx+C0|Ω|.

    Thus,

    12Ω|un(x,t)t|2dx+1p˜M([un]ps,p)(12Ω|un(x,0)t|2dx+1p[un(x,0)]ps,p)(2q+1a0)1q1t0Ω|fn(x,t)|qdxdt+C0|Ω|T. (13)

    Since un(x,0)=ψnu0 strongly in Ws,p(Ω)Wα,20(Ω), un(x,0)t=ϕnu1 strongly in L2(Ω) and fnf strongly in Lq(QT), we deduce from (13) that

    12Ω|un(x,t)t|2dx+1p˜M([un]ps,p)C(T),

    which together with assumption (M1) yields that

    12Ω|un(x,t)t|2dx+[un]ps,pC(T)  for all t[0,T].

    Moreover, integrating (12) with respect to t over (0,T), we have

    QT|unt|qdxdt+T0[unt]2α,2dtC(T).

    Furthermore, for each t[0,T], by Hölder's inequality, we get

    [un(x,t)]2α,2=R2N(t0(un(x,τ)τun(y,τ)τ)dτ+(un(x,0)τun(y,0)τ))2|xy|N+2αdxdy2TT0[unt]2α,2dt+2[un(x,0)]2α,2.

    Thus, we obtain that [un(x,t)]2α,2C(T) for each t[0,T].

    By Lemma 3.4, we have

    Lemma 3.5. The estimate

    unW(QT)+an(x,t,unt)Lq(QT)C(T),

    holds uniformly with respect to n.

    Proof. By (8), we have

    an(x,t,unt)Lq(x,t)(QT)C(T).

    From the fractional Sobolev inequality, there holds

    unLq(Ω)C[un]ps,pC(T).

    Furthermore, QT|un|qdxdtC(T).

    Theorem 3.6. Under the conditions (H1)(H3), problem (1.1) has a weak solution.

    Proof. By Lemma 3.4 and Lemma 3.5, there exist a subsequence of {un}n=1 still denoted by {un}n=1 and u,μ:QTR such that

    {unu  weaklyin L(0,T;Ws,p0(Ω))L(0,T;Wα,20(Ω)),unu  weakly in W(QT),untut weakly  in L(0,T;L2(Ω)),untut  weakly in Lq(QT),untut  weakly in L2(0,T;Wα,20(Ω)),an(x,t,unt)π  weakly in Lq(x,t)(QT).

    First, we prove that there exists a subsequence of {un}n=1 (still denoted by {un}n=1) such that untut strongly in L2(QT) and unu strongly in Lq(QT).

    Since (ηn(t))j=Ωuntωjdx, by Lemma 3.4, (ηn(t))j is uniformly bounded on [0,T]. For all 0t1<t2T, integrating (11) with respect to t from t1 to t2, we have

    Ωun(x,t1)tωjdxΩun(x,t2)tωjdx+t2t1(un,ωjs,p+un(x,t1)t,ωjα,2)dt+t2t1Ωan(x,t,unt)ωjdxdt=t2t1Ωfnωjdxdt.

    Hölder's inequality, Lemmas 3.4–3.5 yield

    |(ηn(t1))j(ηn(t2))j|(t2t1[un]p1s,p[ωj]s,pdt+t2t1[un]α,2[ωj]α,2dt+an(x,t,unt)Lq(QT)ωjLq(Qt2t1)+fnLq(QT)ωjLq(Qt2t1))C(T)((t2t1[ωj]ps,pdt)1/p+(t2t1[ωj]pα,2dt)1/2+ωjLq(x,t)(Qt2t1))C(j,T)max{|t1t2|1p,|t1t2|12,|t1t2|1q},

    where Qt2t1=Ω×(t1,t2). Thus, the sequence {(ηn(t))j}n=1 is uniformly bounded and equi-continuous for fixed j. By Ascoli-Arzela Theorem, for j=1, there exists a subsequence of {n} denoted by {n1,k} such that {(ηn1,k(t))1} converges uniformly on [0,T] to some continuous function ζ1(t); for j=2, there exists a subsequence of {n1,k} denoted by {n2,k} such that {(ηn2,k(t))2} converges uniformly on [0,T] to ζ2(t); generally, for j, there exists a subsequence of {nj1,k} denoted by {nj,k} such that {(ηnj,k(t))j} converges uniformly on [0,T] to ζj(t); . The diagonal procedure imply that there exists a sequence of {(ηnk,k(t))j}k=1 still denoted by {(ηn(t))j}n=1 such that {(ηn(t))j} converges uniformly on [0,T] to ζj(t) for each j=1,2,.

    For rn with rN, by Lemma 3.4, we have

    rj=1|(ηn(t))j|2Ω|unt|2dxC(T), for each t[0,T].

    Letting n, we get

    rj=1|ζj(t)|2C(T), for each t[0,T].

    Letting r, we obtain

    j=1|ζj(t)|2C(T), for each t[0,T].

    Denote ¯u(x,t)=j=1ζj(t)ωj(x), then sup0tT¯u(x,t)L2(Ω)C(T) and for each jN, there holds

    limnΩuntωjdx=Ω¯uωjdx. (14)

    uniformly on [0,T]. For each ε1>0 and ϕL2(Ω), by the completeness of {ωj}, there exists a m0>0 such that ϕm0i=1(Ωϕωidx)ωiL2(Ω)ε1. Thus,

    |Ω(untˉu)ϕdx|untˉuL2(Ω)ϕm0i=1(Ωϕωidx)ωiL2(Ω)+|Ω(utˉu)m0i=1(Ωϕωidx)ωidx|C(T)ε1+|Ω(untˉu)m0i=1(Ωϕωidx)ωidx|. (15)

    For the ε1>0, by (14), there exists a nε1>0 such that

    |Ω(untˉu)ωidx|ε1m0,  for n>nε1 and i=1,,m0.

    From (15) and Hölder's inequality, we have

    |Ω(untˉu)ϕdx|untˉuL2(Ω)ϕm0i=1(Ωϕωidx)ωiL2(Ω)+|Ω(utˉu)m0i=1(Ωϕωidx)ωidx|C(T)ε1+m0i=1|Ωϕωidx||Ω(untˉu)ωidx|(C(T)+ϕL2(Ω))ε1,  for n>nε1. (16)

    It follows from (16) that

    unt¯u  weakly in L2(Ω). (17)

    uniformly on [0,T] as n. For each φC0(QT), by Lebesgue's Dominated Convergence Theorem, we obtain

    limnQT(unt¯u)φdxdt=0.

    By integration by parts, we get

    QTuntφdxdt=QTunφtdxdt.

    Letting n, we have

    QT¯uφdxdt=QTuφtdxdt,  for φC0(QT).

    Thus, we obtain that ¯u=ut. Moreover, for each jN, Lemma 3.3 and Lebesgue's dominated convergence theorem yield

    limnT0(Ω(untut)ωjdx)2dt=0.

    Thus, for ε>0, by Proposition 1, there exists a positive number Nε independent of n such that

    untutL2(QT)2Nεi=1T0(Ω(untut)ωidx)2dt+2ε2T0[untut]2α,2dt.

    From a discussion similar to that of (17), there is a ˜n(ε)>0 such that

    untutL2(QT)Cε2,  for n>˜n(ε).

    Thus, untut strongly in L2(QT). Further, there exists a subsequence of {un} still denoted by {un} such that untut a.e. on QT.

    As unL(0,T;Wα,20(Ω)) and untL2(QT), by the Lions-Aubin Lemma (see Lions [21]), there exists a subsequence of {un} still labelled by {un} such that unu strongly in L2(QT) and a.e. on QT. Since 1q<ps:=Np/(Nsp), by Lemma 3.4 we have

    unLps(Ω)CuWs,p(Ω)C(T).

    Furthermore, T0Ω|un|psdxdtC(T). For each measurable subset UQT with |U|1, Hölder's inequality yields

    U|un|qdxdt2|un|Lpsq(QT)1Lpspsq(U)C(T)1Lpspsq(U)C(T)|U|psqps.

    Thus, the sequence {|un|q}n=1 is equi-integrable on L1(QT). Vitali Theorem implies that limnQT|unu|qdxdt=0, that is to say, unu strongly in Lq(QT).

    For each uLp(0,T;Ws,p0(Ω)), we define a linear functional L:Lp(0,T;Ws,p0(Ω))R as:

    L(u),v=T0M([u]ps,p)u,vps,pdt

    for all vLp(0,T;Ws,p0(Ω)). By Hölder's inequality, we have

    |L(u),v|C(T0[u]ps,pdt)(p1)/p(T0[v]ps,pdt)1/p.

    This means that L(u) is a bounded linear functional on Lp(0,T;Ws,p0(Ω)). Thus,

    L(un)C,

    where C>0 independent of n. Further, up to a subsequence we assume that there exists χ(Lp(0,T;Ws,p0(Ω))) such that

    L(un)χ weakly in (Lp(0,T;Ws,p0(Ω))).

    Here (Lp(0,T;Ws,p0(Ω))) denotes the dual space of Lp(0,T;Ws,p0(Ω)). Then,

    limnL(un),v=χ,v

    for all vLp(0,T;Ws,p0(Ω)). From (11), for φC1(0,T,Vk) (kn), we have

    Ωun(x,τ)tφ(x,τ)dxΩun(x,0)tφ(x,0)dxQτ0untφtdxdt+τ0(M([un]ps,p)un,φs,p+unt,φα,2)dt+Qτ0an(x,t,unt)φdxdt=Qτ0fnφdxdt, (18)

    where 0<τT. Letting n in (18), we obtain

    Ωu(x,τ)tφ(x,τ)dxΩu1φ(x,0)dxQτ0utφtdxdt+χ,φ+τ0ut,φα,2dt+Qτ0μ(x,t)φdxdt=Qτ0fφdxdt, (19)

    where φC1(0,T;Vk) (kN). Since C0(Ω)¯n=1VnC1(¯Ω), for each φC0(Ω), there exists a sequence {φnk}k=1 with φnkVnk such that φnkφ in C1(¯Ω). Taking φnk in (19) and letting k, we get

    Ωu(x,τ)tφdxΩu1φdxQτ0utφtdxdt+χ,φ+τ0ut,φα,2dt=Qτ0fφdxdt,  for φC0(Ω). (20)

    Letting τ0, then we have

    limτ0Ωu(x,τ)tφdx=Ωu1φdx,  for φC0(Ω).

    Similarly, for t0[0,T], there holds

    limτt0Ωu(x,τ)tφdx=Ωu(x,t0)tφdx,  for φC0(Ω).

    Furthermore, we obtain that u(x,0)t=u1(x) for xΩ.

    Since uL(0,T;Wα,20(Ω)) and utL2(0,T;Wα,20(Ω)), we can assume that uC(0,T;Wα,20(Ω)) (see Lions [21]). By Lemma 3.4 and the embedding Wα,20(Ω)L2(Ω) is continuous, we deduce that Ωu2n(x,T)dxC(T). Thus, there exist a subsequence of {un} still denoted by {un} and a function ˆu such that un(x,T)ˆu  weakly in L2(Ω). For each φC0(Ω) and ηC1([0,T]), we have

    QTuntφηdxdt=Ωun(x,T)φη(T)un(x,0)φη(0)dxQTunφη(t)dxdt.

    Letting n, we get

    QTutφηdxdt=Ωˆuφη(T)u0φη(0)dxQTuφη(t)dxdt.

    Integration by parts yields

    Ω(u(x,T)ˆu)φη(T)dx=Ω(u(x,0)u0)φη(0)dx.

    Choosing η(T)=1,η(0)=0 or η(T)=0,η(0)=1, we obtain that ˆu=u(x,T) and u(x,0)=u0(x) for xΩ. Similarly, we can prove that un(x,T)u(x,T) weakly in Wα,20(Ω) and

    [u(x,T)]2α,2lim infn[un(x,T)]2α,2. (21)

    Further, by the compactness of embedding Wα,20(Ω) to L2(Ω), we get un(x,T)u(x,T) strongly in L2(Ω). Taking φ=uk in (19), then letting k, we obtain

    Ωu(x,T)tu(x,T)u1u0dxQT|ut|2dxdt+χ,u+T0ut,uα,2dt+QTμudxdt=QTfudxdt. (22)

    Finally, we prove that πΦ(x,t,ut) a.e. on QT and unu strongly in Lp(0,T;Ws,p0(Ω)). Since untut a.e. on QT, for each δ>0, by Lusin's theorem and Egoroff's theorem, we can choose a subset EδQT such that meas(Eδ)<δ, utL(QTEδ) and untut uniformly on QTEδ. Then, for each 0<ε<1, there exists a K>0 such that

    |un(x,t)tu(x,t)t|<ε2,  for all n>K and (x,t)QTEδ.

    If |un(x,t)tτ|<1n, then we have |u(x,t)tτ|<ε, for all n>max{K,2ε} and (x,t)QTEδ. From the definition of an, there holds

    an(x,t,un(x,t)t)=na(x,t,un(x,t)tτ)ρ(nτ)dτ=na(x,t,τ)ρ(n(un(x,t)tτ))dτ.

    Thus, |un(x,t)tτ|<1n, for each (x,t)QTEδ. Furthermore,

    a_ε(x,t,ut)an(x,t,unt)¯aε(x,t,ut),

    for all n>max{K,2ε} and (x,t)QTEδ. Let φL(QT) with φ0. Then,

    QTEδa_ε(x,t,ut)φdxdtQTEδan(x,t,unt)φdxdtQTEδ¯aε(x,t,ut)φdxdt.

    Letting n and using the weak convergence of an(x,t,unt), we get

    QTEδa_ε(x,t,ut)φdxdtQTEδμφdxdtQTEδ¯aε(x,t,ut)φdxdt.

    By (H1), the definition of a_ε and ¯aε, we have

    |a_ε(x,t,ξ)|a2(|ξ|q1+1)

    and

    |¯aε(x,t,ξ)|a2(|ξ|q1+1),

    for each x,t,ξQT×R. Thus, a_ε(x,t,unt) and ¯aε(x,t,unt) are bounded on QTEδ. By a_=limε0a_ε(x,t,ut), ¯a=limε0¯aε(x,t,ut) and Lebesgue's dominated convergence theorem, we obtain

    QTEδa_(x,t,ut)φdxdtQTEδμ(x,t)φdxdtQTEδ¯a(x,t,ut)φdxdt. (23)

    It's easy to check that a_ and ¯a still satisfy the same conditions imposed on a in (H2). Thus, a_(x,t,ut) and a_(x,t,ut) belong to the space Lq(QT). Letting δ0 in (23), we have

    QTa_(x,t,ut)φdxdtQTμ(x,t)φdxdtQT¯a(x,t,ut)φdxdt. (24)

    Without loss of generality, we assume that |{(x,t)QT:π(x,t)<a_(x,t,ut)}|>0. Taking

    φ={1,  μ(x,t)<a_(x,t,ut),0,  μ(x,t)a_(x,t,ut),

    in the first inequality of (24), we have

    0<QT(a_(x,t,ut)μ(x,t))+dxdt0,

    where (a_(x,t,ut)μ(x,t))+=max{a_(x,t,ut)μ(x,t),0}. Thus, from the contradiction above, a_(x,t,ut)μ(x,t) a.e. on QT. Similarly, we can deduce that μ(x,t)¯a(x,t,ut) a.e. on QT.

    Multiplying (11) by (ηn(t))j and summing up j from 1 to n, and integrating with respect to t from 0 to T, we have

    T0Ω2unt2undxdt+T0M([un]ps,p)[un]ps,pdt+T0unt,unα,2dt+T0Ωan(x,t,unt)undxdt=T0Ωfn(x,t)undxdt.

    Thus,

    0T0M([un]ps,p)(un,unus,pu,unus,p)dt=T0Ω(fnunan(x,t,unt)un)dxdtT0unt,unα,2dtΩun(x.T)tun(x,T)dx
    +Ωun(x,0)tun(x,0)dx+T0Ω|unt|2dxdtT0M([un]ps,p)un,us,pdt+T0M([un]ps,p)u,unus,pdt.

    By (21), (22), the weak convergence of un(x,T)tu(x,T)t in L2(Ω) and the strong convergence of un(x,T)u(x,T) in L2(Ω), we get

    lim supnT0M([un]ps,p)(un,unus,pu,unus,p)dtT0Ω(fuμu)dxdt12[u(x,T)]2α,2+12[u(x,0)]2α,2Ωu(x,T)tu(x,T)dx+Ωu1u0dx+T0Ω|ut|2dxdtχ,u=0.

    This together with (M1) implies that

    limnT0(un,unus,pu,unus,p)dt=0.

    Similar to the discussion as in [37,26], we get unu strongly in Lp(0,T;Ws,p0(Ω)) and χ,u=M([u]ps,p)[u]ps,p. It follows from (19) that the theorem is proved.

    Remark 2. Obviously, if the function a:QT×RR is continuous with respect to (x,t,s)QT×R, then μ(x,t)=a(x,t,ut).

    We consider the following problem

    {utt+(m0+m1[u]ps,p)(Δ)spu+(Δ)αut+μ=f,  (x,t)QT,μΦ(x,t,ut),  a.e. (x,t)QT,u(x,t)=0,  (x,t)(RNΩ)×(0,T),u(x,0)=u0(x), ut(x,0)=u1(x),  xΩ, (25)

    where m0,m1>0 and the set valued function Φ is obtained by filling in jumps of the function a defined by

    a(x,t,ξ)={|ξ|q2ξ+ξlnξ,  |ξ|1,|ξ|q2ξ+e|ξ|ξ,  |ξ|>1,

    After a simple calculation, we have

    a_(x,t,ξ)={|ξ|q2ξ+ξlnξ,  |ξ|<1,1,  ξ=1,1e1,  ξ=1,|ξ|q2ξ+e|ξ|ξ,  |ξ|>1,

    and

    ¯a(x,t,ξ)={|ξ|q2ξ+ξlnξ,  |ξ|<1,1+e1,  ξ=1,1,  ξ=1,|ξ|q2ξ+e|ξ|ξ,  |ξ|>1.

    Then Φ(x,t,ut)=[a_(x,t,ut),¯a(x,t,ut)] a.e. on QT. Suppose that (H1) and (H4) are satisfied and let q be defined as in (H3). Then by Theorem 3.6, there exists a weak solution for problem (25).

    The authors would like to express their gratitude to the referees for valuable comments and suggestions. M. Xiang was supported by the Natural Science Foundation of China (No. 11601515) and the Tianjin Youth Talent Special Support Program. B. Zhang was supported by the National Natural Science Foundation of China (No. 11871199), the Heilongjiang Province Postdoctoral Startup Foundation (LBH-Q18109), and the Cultivation Project of Young and Innovative Talents in Universities of Shandong Province.



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