In this paper, the necessary and sufficient conditions under which the matrix inequality C∗XC≥D (>D) subject to the linear constraint A∗XA=B is solvable are deduced by means of the spectral decompositions of some matrices and the generalized singular value decomposition of a matrix pair. An explicit expression of the general Hermitian solution is also provided. One numerical example demonstrates the effectiveness of the proposed method.
Citation: Yinlan Chen, Wenting Duan. The Hermitian solution to a matrix inequality under linear constraint[J]. AIMS Mathematics, 2024, 9(8): 20163-20172. doi: 10.3934/math.2024982
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In this paper, the necessary and sufficient conditions under which the matrix inequality C∗XC≥D (>D) subject to the linear constraint A∗XA=B is solvable are deduced by means of the spectral decompositions of some matrices and the generalized singular value decomposition of a matrix pair. An explicit expression of the general Hermitian solution is also provided. One numerical example demonstrates the effectiveness of the proposed method.
Throughout this paper, we denote the complex m×n matrix space by Cm×n, the set of all Hermitian matrices in Cm×m by Cm×mH, the conjugate transpose, the range space, and the Moore-Penrose generalized inverse of a matrix A by A∗, R(A) and A†, respectively. In is the n×n identity matrix and A≥0 (>0) means that A∈Cn×n is Hermitian nonnegative definite (positive definite). PL represents the orthogonal projector on the subspace L. Given a matrix A∈Cm×n, EA=Im−AA† and FA=In−A†A are two orthogonal projectors. Besides, ‖⋅‖F stands for the Frobenius norm.
A lot of work with the Hermitian solutions of the matrix equations have been published [1,2,3,4,5,6,7]. However, the problem of solving the Hermitian solution of the matrix inequality under the symmetric matrix equation constraint is considered by only a few authors. To the best of our knowledge, the constrained matrix inequality:
C∗XC≥D (>D), s.t. A∗XA=B, | (1.1) |
where A∈Cm×n, B∈Cn×n, C∈Cm×p and D∈Cp×p, and X∈Cm×mH is an unknown matrix to be determined, was first investigated by Liu [8]. Observe that Liu derived the necessary and sufficient conditions for the solvability of (1.1) using the maximal and minimal ranks and inertias of the matrix polynomials. In this paper, we provide an alternative approach to find the Hermitian solution of (1.1). Compared with the approach proposed by Liu [8], the method used in this paper is from a new perspective, using the decompositions of matrices to reduce the calculations of the rank and inertia, which makes it easier to obtain the representation of the Hermitian solution of (1.1).
In what follows, we discuss the necessary and sufficient conditions for the solvability of (1.1) using the spectral decompositions (SDs) and the generalized singular value decomposition (GSVD) of some matrices, and give an explicit representation of the general Hermitian solution of (1.1) when the consistent conditions are satisfied. Further, one numerical example shows that the introduced method is correct.
In order to solve the Hermitian solution of (1.1), we need the following lemmas.
Lemma 1. ([9]) If A∈Cm×n and B∈Cn×nH, then the matrix equation A∗XA=B has a solution X∈Cm×mH if and only if
R(B)⊆R(A∗). | (2.1) |
In which case, the general Hermitian solution can be expressed as
X=(A∗)†BA†+EAZ+Z∗EA, | (2.2) |
where Z∈Cm×m is an arbitrary matrix.
Lemma 2. ([10,11]) Assume that A1∈Cp×m, A2∈Cn×p and A3∈Cp×pH. Then the matrix equation A1XA2+(A1XA2)∗=A3 has a solution if and only if
EA1A3EA1=0, FA2A3FA2=0, [A1, A2∗][A1, A2∗]†A3=A3. |
In this case, the general solution with respect to X∈Cm×n gives
X=A†1(Γ+F˜LSXF˜LA1A1†)A2†+Y−A1†A1YA2A2†, |
where ˜L=FA2A1A1†, Γ=12A3(2Ip−A1A1†)+12(Ψ−Ψ∗)A1A1†, and Ψ=2˜L†FA2A3+(Ip−˜L†FA2)A3˜L†˜L, Y∈Cm×n and SX∈Cp×p are arbitrary matrices with S∗X=−SX.
Lemma 3. ([12,13]) Given matrices ˜A∈Cp×m and ˜D∈Cp×m. Let the singular value decomposition (SVD) of the matrix ˜A be ˜A=˜P[Σ000]˜Q∗, where Σ=diag(α1, ⋯, αr)>0, r=rank(˜A) and ˜P=[˜P1, ˜P2]∈Cp×p, ˜Q=[˜Q1, ˜Q2]∈Cm×m are unitary matrices with ˜P1∈Cp×r, ˜Q1∈Cm×r and ˜Q2∈Cm×(m−r). Then:
(ⅰ) The matrix equation ˜AY=˜D has a Hermitian nonnegative definite solution Y∈Cm×mH if and only if ˜D˜A∗≥0, R(˜D)=R(˜D˜A∗), and the general nonnegative definite solution can be expressed as
Y=Y0+F˜AKF˜A, |
where Y0=˜A†˜D+F˜A(˜A†˜D)∗+F˜A˜D∗(˜D˜A∗)†˜DF˜A, and K∈Cm×mH is an arbitrary nonnegative definite matrix.
(ⅱ) The matrix equation ˜AY=˜D has a Hermitian positive definite solution if and only if ˜A˜A†˜D=˜D, ˜P∗1˜D˜A∗˜P1>0, and the general positive definite solution is
Y=Y0+F˜AKF˜A, |
where Y0=˜A†˜D+F˜A(˜A†˜D)∗+F˜A˜D∗(˜D˜A∗)†˜DF˜A, and K∈Cm×mH is an arbitrary positive definite matrix.
According to Lemma 1, we know that the matrix equation A∗XA=B has a Hermitian solution if and only if the condition (2.1) holds, then the general solution is given by (2.2), where Z∈Cm×m is an arbitrary matrix. Substituting (2.2) into the first matrix inequality of (1.1) yields
C∗EAZC+C∗Z∗EAC≥D−C∗(A∗)†BA†C (>D−C∗(A∗)†BA†C). | (3.1) |
Clearly, the inequality (3.1) can be equivalently written as
GZC+C∗Z∗G∗=K−˜D, | (3.2) |
where ˜D=−D+C∗(A∗)†BA†C, G=C∗EA and K≥0 (>0) is an unknown matrix to be determined. By utilizing Lemma 2, we see that Eq (3.2) with respect to Z is solvable if and only if the following three matrix equations hold simultaneously:
EGKEG=EG˜DEG, | (3.3) |
FCKFC=FC˜DFC, | (3.4) |
[G, C∗][G, C∗]†(K−˜D)=K−˜D. | (3.5) |
Now, we will seek the solvability conditions with respect to K≥0 (>0) such that (3.3)–(3.5) are consistent. If let PL=[G, C∗][G, C∗]†, Eq (3.5) can be equivalently written as
(Ip−PL)K=(Ip−PL)˜D. | (3.6) |
From Lemma 3, Eq (3.6) has a Hermitian nonnegative definite solution K∈Cp×p if and only if
(Ip−PL)˜D(Ip−PL)≥0, R((Ip−PL)˜D)=R((Ip−PL)˜D(Ip−PL)), | (3.7) |
in this case, the general Hermitian nonnegative definite solution can be expressed as
K=K0+PLSPL, | (3.8) |
where
K0=˜D−PL˜DPL+PL˜D(Ip−PL)[(Ip−PL)˜D(Ip−PL)]†(Ip−PL)˜DPL, | (3.9) |
and S∈Cp×pH is an arbitrary nonnegative matrix.
Assume that the SD of Ip−PL is
Ip−PL=Q[Is000]Q∗=Q1Q∗1, | (3.10) |
where s=rank(Ip−PL) and Q=[Q1, Q2] is a unitary matrix with Q1∈Cp×s and Q2∈Cp×(p−s). By Lemma 3, Eq (3.6) has a Hermitian positive definite solution if and only if
Q∗1˜DQ1>0, | (3.11) |
then the general Hermitian positive definite solution can be formulated as
K=K0+PLSPL, | (3.12) |
where K0 is given by (3.9), and S is an arbitrary Hermitian positive definite matrix. Due to L=R(G)+R(C∗), then
PLGG†=GG†=GG†PL, PLC†C=C†C=C†CPL. |
Substituting (3.8) ((3.12)) into (3.3) and (3.4), we can obtain that
(PL−GG†)S(PL−GG†)=(Ip−GG†)W(Ip−GG†), | (3.13) |
(PL−C†C)S(PL−C†C)=(Ip−C†C)W(Ip−C†C), | (3.14) |
where W=˜D−K0. According to (3.9), it follows that
(PL−GG†)W(PL−GG†)=(Ip−GG†)W(Ip−GG†), | (3.15) |
(PL−C†C)W(PL−C†C)=(Ip−C†C)W(Ip−C†C). | (3.16) |
By Eqs (3.15) and (3.16), Eqs (3.13) and (3.14) are equivalent to
(PL−GG†)S(PL−GG†)=(PL−GG†)W(PL−GG†), | (3.17) |
(PL−C†C)S(PL−C†C)=(PL−C†C)W(PL−C†C). | (3.18) |
It is easily verified that PL−GG† and PL−C†C are orthogonal projection operators, then there exists unitary matrices U and V such that
PL−GG†=U[Ia000]U∗=U1U∗1, PL−C†C=V[Ib000]V∗=V1V∗1, | (3.19) |
where a=rank(PL−GG†), b=rank(PL−C†C), U1∈Cp×a and V1∈Cp×b are full column rank unitary matrices. Substituting (3.19) into (3.17) and (3.18), we can get that
U∗1SU1=U∗1WU1, V∗1SV1=V∗1WV1. | (3.20) |
Let the GSVD [14] of the matrix pair [U1, V1] be:
U1=MΔ1N∗1, V1=MΔ2N∗2, | (3.21) |
where M∈Cp×p is a nonsingular matrix, and N1∈Ca×a, N2∈Cb×b are unitary matrices, and
Δ1=[I00Υ0000]a−eef−ap−f, a−eeΔ2=[00Θ00I00]a−eef−ap−f, eb−e |
f=rank([U1, V1])=a+b−e, Υ=diag(δ1, δ2, ⋯, δe) and Θ=diag(ϑ1, ϑ2, ⋯, ϑe) with 1>δ1≥δ2≥⋯≥δe>0, 0<ϑ1≤ϑ2≤⋯≤ϑe<1, δ2i+ϑ2i=1, i=1, 2, ⋯, e. Substituting (3.21) into (3.20) and partitioning the matrix M∗WM as:
M∗WM=[M11 M12 M13 M14M∗12 M22 M23 M24M∗13 M∗23 M33 M34M∗14 M∗24 M∗34 M44]a−eef−ap−f. a−e e f−ap−f | (3.22) |
Then, it follows from Lemma 2.6 of [15] that:
(i) Equation (3.20) has a solution S≥0 if and only if
[M11 M12M∗12 M22]≥0,[M22 M23M∗23 M33]≥0, | (3.23) |
and the general Hermitian nonnegative definite solution of Eq (3.20) is
S=(M∗)−1[Ω(S13)Ω(S13)J1J∗1Ω(S13)J2+J∗1Ω(S13)J1]M−1, | (3.24) |
where
Ω(S13)≜[M11 M12 S13M∗12 M22 M23S∗13 M∗23 M33], | (3.25) |
with
S13=M12M†22M23+(M11−M12M†22M∗12)12J3(M33−M∗23M†22M23)12, | (3.26) |
and J1∈Cf×(p−f), J2∈C(p−f)×(p−f) are arbitrary matrices with J2≥0, and J3∈C(a−e)×(f−a) is an arbitrary contraction matrix (that is, the maximum singular value with respect to J3 cannot exceed 1).
(ii) Equation (3.20) has a Hermitian positive solution of S if and only if
[M11 M12M∗12 M22]>0,[M22 M23M∗23 M33]>0, | (3.27) |
and the representation of the general solution for Eq (3.20) can be expressed as
S=(M∗)−1[Ω(S13)J4J∗4J5+J∗4[Ω(S13)]−1J4]M−1, | (3.28) |
where Ω(S13) is given by (3.25) with
S13=M12M−122M23+(M11−M12M−122M∗12)12J6(M33−M∗23M−122M23)12, | (3.29) |
and J4∈Cf×(p−f), J5∈C(p−f)×(p−f) are arbitrary matrices with J5>0, and J6∈C(a−e)×(f−a) is an arbitrary strict contraction matrix (that is, the maximum singular value with respect to J6 is less than 1).
Furthermore, when the conditions (3.3)–(3.5) hold simultaneously, the general expression with respect to Z in Eq (3.2) is
Z=G†(Γ+F˜LNXF˜LGG†)C†+Y−G†GYCC†, | (3.30) |
where
Γ=12(PLSPL−W)(2Ip−GG†)+12(Ψ−Ψ∗)GG†, | (3.31) |
with
Ψ=2˜L†FC(PLSPL−W)+(Ip−˜L†FC)(PLSPL−W)˜L†˜L, | (3.32) |
and S is given by Eq (3.24) ((3.28)), ˜L=FCGG†, and Y∈Cm×m, NX∈Cp×p are arbitrary matrices with N∗X=−NX. By substituting (3.30) into (2.2), we can get the Hermitian solution of (1.1).
With the above discussion, we can obtain the following theorem.
Theorem 1. Given matrices A∈Cm×n, B∈Cn×n, C∈Cm×p and D∈Cp×p. Let ˜D=−D+C∗(A∗)†BA†C, G=C∗EA, L=R(G)+R(C∗), and let the SDs of the matrices Ip−PL, PL−GG† and PL−C†C be respectively given by (3.10) and (3.19). Suppose that the GSVD of the matrix pair [U1, V1] is given by (3.21), and the partition of the matrix M∗WM is given by (3.22). Then,
(i) The matrix inequality C∗XC≥D s.t. A∗XA=B has a Hermitian solution if and only if the conditions (2.1), (3.7) and (3.23) hold, in which case, the general Hermitian solution X∈Cm×mH can be expressed as
X=(A∗)†BA†+EAG†(Γ+F˜LNXF˜LGG†)C†+EAY−EAG†GYCC†+(C†)∗(Γ∗−GG†F˜LNXF˜L)(G†)∗EA+Y∗EA−CC†Y∗G†GEA, | (3.33) |
where W=˜D−K0, ˜L=FCGG†, and K0, S, Ω(S13), S13, Γ and Ψ are respectively given by (3.9), (3.24)–(3.26), (3.31) and (3.32), and NX∈Cp×p, Y∈Cm×m, J1∈Cf×(p−f) and J2∈C(p−f)×(p−f) are arbitrary matrices with N∗X=−NX and J2≥0, and J3∈C(a−e)×(f−a) is an arbitrary contraction matrix.
(ii) The matrix inequality C∗XC>D s.t. A∗XA=B has a Hermitian solution X∈Cm×mH if and only if the conditions (2.1), (3.11) and (3.27) are satisfied, in this case, the Hermitian solution can be expressed as
X=(A∗)†BA†+EAG†(Γ+F˜LNXF˜LGG†)C†+EAY−EAG†GYCC†+(C†)∗(Γ∗−GG†F˜LNXF˜L)(G†)∗EA+Y∗EA−CC†Y∗G†GEA, | (3.34) |
where W=˜D−K0, ˜L=FCGG†, and K0, S, Ω(S13), S13, Γ and Ψ are respectively given by (3.9), (3.28), (3.25), (3.29), (3.31) and (3.32), and NX∈Cp×p, Y∈Cm×m, J4∈Cf×(p−f) and J5∈C(p−f)×(p−f) are arbitrary matrices with N∗X=−NX and J5>0, and J6∈C(a−e)×(f−a) is an arbitrary strict contraction matrix.}$
According to Theorem 1, we can describe the numerical algorithm to solve the Hermitian solution of (1.1) as follows.
Algorithm 1.
(1) Input matrices A, B, C and D.
(2) If the condition (2.1) holds, then continue; or else, (1.1) has no solution X∈Cm×mH.
(3) Compute matrices ˜D, G and Ip−PL.
(4) If the condition (3.7) holds, then continue; or else, the matrix inequality C∗XC≥D s.t. A∗XA=B has no solution X.
(5) Compute the SD of the matrix Ip−PL by (3.10).
(6) If the condition (3.11) holds, then continue; or else, the matrix inequality C∗XC>D s.t. A∗XA=B has no solution X.
(7) Compute the matrices K0 and W in the light of (3.9), (3.13) and (3.14), respectively.
(8) Compute the SDs of the matrices PL−GG† and PL−C†C by (3.19).
(9) Compute the GSVD of the matrix pair [U1, V1] by (3.21).
(10) Compute the matrix M∗WM by (3.22).
(11) (ⅰ) If the condition (3.23) holds, then continue; or else, the matrix inequality C∗XC≥D s.t. A∗XA=B has no solution X.
(ⅱ) If the condition (3.27) holds, then continue; or else, the matrix inequality C∗XC>D s.t. A∗XA=B has no solution X.
(12) (ⅰ) Select matrices J1, J2≥0 and a contraction matrix J3, compute matrices S, Ω(S13) and S13 based on (3.24)–(3.26), respectively.
(ⅱ) Select matrices J4, J5>0 and a strict contraction matrix J6, compute matrices S, Ω(S13) and S13 by (3.28), (3.25) and (3.29), respectively.
(13) Calculate matrices Z, \ Γ and Ψ on the basis of (3.30)–(3.32), respectively.
(14) (ⅰ) Select matrices NX and Y, compute the Hermitian solution of C∗XC≥D s.t. A∗XA=B in the light of (3.33).
(ⅱ) Select matrices NX and Y, compute the Hermitian solution of C∗XC>D s.t. A∗XA=B based on (3.34).
Remark 1. Through careful statistics, the amount of computations required by Algorithm 1 is about 146p3+84m3+46m2p+22mp2+2mnp+n2p+9n3+9mn2+5m2n flops, where the generalized inverse matrices C†, G† and ˜L† are calculated by the SVDs of the matrices C, G and ˜L. Further, to compute the time complexity of Algorithm 1, the readers can see a survey [16].
Example 1. Let m=6, n=5 and p=7. The matrices A, B, C and D are presented by
A=[0.69370.44210.25100.56620.89730.39210.55090.26580.41140.49820.80971.01340.72900.69780.80020.38210.75600.29890.80280.71990.98981.25021.05751.26971.11790.97041.11410.56951.11981.3391],B=[5.01196.07433.95095.86276.27976.07437.35514.78277.10497.61403.95094.78273.10964.62124.95315.86277.10494.62126.85797.34606.27977.61404.95317.34607.8667],C=[0.79910.65640.44840.55500.44100.22780.47401.05140.78191.64300.59191.76051.16201.23370.85630.78620.88610.55200.77990.45980.89680.60530.48500.84880.32910.75180.58470.73470.71850.72180.92060.44740.75710.45320.95631.15490.87731.35600.63281.12600.98941.1950],D=[−5.2636−7.9819−2.6335−2.2506−1.2401−10.0230−0.1972−7.9819−11.1637−5.6897−3.8471−3.8013−12.9962−2.3591−2.6335−5.6897−0.2158−0.87590.9846−7.53191.9655−2.2506−3.8471−0.8759−1.0109−0.1707−5.12240.3619−1.2401−3.80130.9846−0.17071.6595−5.55332.6673−10.0230−12.9962−7.5319−5.1224−5.5533−15.5151−4.0797−0.1972−2.35911.96550.36192.6673−4.07973.0450]. |
It is easy to validate that the stated conditions (2.1), (3.7) and (3.23) are satisfied. In fact, ‖FAB‖F=1.6310×10−15, the eigenvalues of the matrix (Ip−PL)˜D(Ip−PL) are 0.0000, 0.0000, 0.0000, 0.0000, 0.1016, 0.2585, 4.3461, ‖E(Ip−PL)˜D(Ip−PL)˜D(Ip−PL)‖F=1.3311×10−15, and ‖E(Ip−PL)˜D(Ip−PL)(Ip−PL)˜D‖F=1.8544×10−15, the eigenvalues of the matrix [M11 M12M∗12 M22]=[0.4079−0.2813−0.28130.1940] are 0.6018, 2.1184×10−5, and the matrix [M22 M23M∗23 M33] is 0. According to Algorithm 1 and choosing the matrices J1=0, J2=I5, NX=0 and Y=I6, we can obtain that
X=[3.70606.020315.48709.2670−8.1450−12.59266.0203−12.77484.597949.2869−10.9899−16.323815.48704.597916.3503−0.5303−1.4077−21.24189.267049.2869−0.5303−7.48632.6776−23.5101−8.1450−10.9899−1.40772.6776−1.720512.6190−12.5926−16.3238−21.2418−23.510112.619032.0736]. |
The absolute error is estimated by
‖A∗XA−B‖F=2.6065×10−14, |
and the eigenvalues of (C∗XC−D) are 0.0000, 0.1172, 0.1505, 0.3321, 0.5119, 4.4760, 72.3055, which implies that X is the Hermitian solution of the matrix equality C∗XC≥D s.t. A∗XA=B.
In this paper, we have established the necessary and sufficient conditions (see (2.1), (3.7), (3.23), and (2.1), (3.11), and (3.27)) for the Hermitian solution of (1.1), and achieve the explicit representation of the general Hermitian solution by the SD and the GSVD when the stated conditions are satisfied. One numerical example verifies the correctness of the introduced method.
Yinlan Chen: Conceptualization, Methodology, Project administration, Supervision, Writing-review & editing; Wenting Duan: Investigation, Software, Validation, Writing-original draft, Writing-review & editing. All authors have read and approved the final version of the manuscript for publication.
The authors declare that they have not used Artificial Intelligence (AI) tools in this article.
The authors would like to express their gratitude to the anonymous reviewers for their valuable suggestions and comments that improved the presentation of this manuscript.
The authors declare no conflicts of interest in this article.
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