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Sharp inequalities for q-starlike functions associated with differential subordination and q-calculus

  • This paper employs differential subordination and quantum calculus to investigate a new class of q-starlike functions associated with an eight-like image domain. Our study laid a foundational understanding of the behavior of these q-starlike functions. We derived the results in first-order differential subordination. We established sharp inequalities for the initial Taylor coefficients and provided optimal estimates for solving the Fekete-Szegö problem and a second-order Hankel determinant applicable to all q-starlike functions in this class. Furthermore, we presented a series of corollaries that demonstrate the broader implications of our findings in geometric function theory.

    Citation: Jianhua Gong, Muhammad Ghaffar Khan, Hala Alaqad, Bilal Khan. Sharp inequalities for q-starlike functions associated with differential subordination and q-calculus[J]. AIMS Mathematics, 2024, 9(10): 28421-28446. doi: 10.3934/math.20241379

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  • This paper employs differential subordination and quantum calculus to investigate a new class of q-starlike functions associated with an eight-like image domain. Our study laid a foundational understanding of the behavior of these q-starlike functions. We derived the results in first-order differential subordination. We established sharp inequalities for the initial Taylor coefficients and provided optimal estimates for solving the Fekete-Szegö problem and a second-order Hankel determinant applicable to all q-starlike functions in this class. Furthermore, we presented a series of corollaries that demonstrate the broader implications of our findings in geometric function theory.



    Quantum calculus (known as q-calculus) extends traditional calculus by introducing the parameter q, offering flexible and powerful tools for analyzing mathematical functions. This framework has attracted growing attention due to its applications in various fields, including mathematics, engineering, and physics. Recent advancements have amplified its relevance, with notable applications in q-transform analysis, q-difference and q-integral equations, optimal control, and fractional calculus.

    The q-derivative operator plays a central role in the theory of special functions, enabling the definition and in-depth analysis of various subclasses of analytic functions. For instance, Mahmood et al. [1] investigated the coefficients of q-starlike functions associated with conic domains, Ahmad et al. [2] explored the Hankel determinants and Zalcman conjecture for q-starlike functions associated with the balloon-shaped domain, and Shi et al. [3] studied the properties of generalized integral operators in the lemniscate domain of Bernoulli. Ahmad et al. [4] extended these ideas by exploring Janowski functions to establish q-analogues of differential subordination results. The q-derivative operator also underpins the q-extension of starlike functions, as discussed in [5].

    Recent research highlights the significant role of q-calculus in advancing contemporary mathematical theory. Studies such as [6,7,8] deepen our understanding of analytic and symmetric functions through q-analytic techniques. This body of work demonstrates the broad applicability of q-calculus, with potential implications across quantum theory, number theory, and statistical mechanics. For further exploration of fractional derivatives, including Caputo and conformable fractional derivatives, readers may consult [9,10] and their references.

    We present some basic definitions related to our work before moving on to our primary findings.

    Let H(D) denote the class of all analytic functions f defined in the open unit disk

    D={εC:   |ε|<1},

    where C represents the set of complex numbers. Let AH(D) be the subclass of all analytic functions f having the Taylor series representation:

    f(ε)=ε+k=2ξkεk      (εD). (1.1)

    Suppose that P represents the Carathéodory class of analytic functions h normalized by

    h(ε)=1+n=1cnεn, (1.2)

    such that the real part is positive:

    (h(ε))>0.

    For each given analytic function fA, the rth Hankel determinant Hr,n is defined in [11] as follows,

    Hr,n(f)=|ξnξn+1 ξn+r1ξn+1ξn+2 ξn+r    ξn+r1ξn+r ξn+2r2|,

    where r,nN and ξ1=1. The following are two second Hankel determinants.

    H2,1(f)=|1ξ2ξ2ξ3|=ξ3ξ22, H2,2(f)=|ξ2ξ3ξ3ξ4|=ξ2ξ4ξ23. (1.3)

    In recent years, considerable attention has been devoted to investigating the upper bounds of the expression |H2,2(f)| across various subclasses of analytic functions. Key contributions in this domain have been made by researchers such as Noonan and Thomas [12], Hayman [13], Ohran et al. [14], and Shi et al. [15]. Babalola [16] initiated the study of bounds for the third Hankel determinant, further enriching the field.

    For a deeper exploration of this subject, recent studies provide valuable insights and are discussed in references [17,18,19]. This growing body of research highlights the importance of Hankel determinants in analytic function theory, offering the potential for discoveries and advancing our understanding of this mathematical area.

    For the functions f and g H(D), we say that f is subordinated to g, written as

    f(ε)g(ε),

    if there exists a Schwarz function ω(ε), which is an analytic function in D with ω(0)=0 and |ω(ε)|1, such that

    f(ε)=g(ω(ε)).

    Furthermore, if two functions f and g are analytic in D and g is univalent, then f is subordinated to g if and only if\

    f(D)g(D)   and    f(0)=g(0).

    There are some applications of subordination below; see [20] for more applications.

    Definition 1.1. A function pP[A,B] if

    p(ε)1+Aε1+Bε       (1B<A1).

    Equivalently,

    |p(ε)1ABp(ε)|<1.

    In particular, f is a Janowski starlike function if εf(ε)f(ε)P[A,B]. See [21] for more details about Janowski starlike functions.

    We take into consideration a class of functions in the domain bounded by a tangent function. All functions h will belong to such a class if they fulfill

    h(ε)1+12tan(ε). (1.4)

    The images of these functions lie in the right-half plane and the geometrical representation is like an eight-shape domain. Simple computations allow the above (1.4) to be expressed as

    |tan1(2h(ε)2)|<1 (1.5)

    In parallel comparison to starlike functions, Khan et al. [22] introduced the following class of Janowski-type starlike functions along with some properties.

    Stan={f(ε)A:εf(ε)f(ε)1+12tan(ε)}. (1.6)

    Thus, by the relation of (1.4) and (1.5),

    Stan={f(ε)A:|tan1(2εf(ε)f(ε)2)|<1}.

    Definition 1.2. [23] For a function f, the q-derivative (also known as the q-difference operator) is defined by

    (Dqf)(ε)=f(ε)f(qε)(1q)ε, (1.7)

    where ε0 and 0<q<1.

    For example, for nN and εD, we have

    Dq{n=1ξnεn}=n=1[n]qξnεn1, (1.8)

    where the q-number is defined by

    [n]q=1qn1q=1+n1l=1ql and  [0]q=0.

    Now, we introduce a new class Stan(q) of Janowski-type q-starlike functions associated with the eight-shaped image domain. Several classes of Janowski-type q-starlike functions have been investigated previously (see [24]).

    Definition 1.3. A function f in A is said to belong to Stan(q) if the following holds

    εDqf(ε)f(ε)1+12tan(ε). (1.9)

    Remark 1.1. One can see that

    limq1Stan(q)=Stan.

    The graphological representation for the class Stan(q) is given in the following Figure 1.

    Figure 1.  Graph of 2+tan(ε)2 under open unit disc D.

    In our research, we set out to explore and characterize a novel class of q-starlike functions associated with an eight-like image domain. We employed differential subordination and quantum calculus techniques to achieve this goal. Our primary aim is to establish a fundamental understanding of the behavior of these q-starlike functions, focusing on deriving first-order differential subordination results. Additionally, we sought to determine sharp inequalities for initial Taylor coefficients and provide optimal estimates for the Fekete-Szegö problem and a second-order Hankel determinant applicable to all q-starlike functions within this newly defined class. Through this work, we intend to contribute to the broader field of geometric function theory, demonstrating the wider implications of our findings through a series of corollaries.

    The following lemmas are essential to investigate our main results.

    Lemma 2.1. [25] (q-Jack's Lemma) Let ω(ε)H(D) with ω(0)=0. If |ω(ε)| achieves the maximum value on the circle |ε|=r at a point ε0, then

    ε0(Dqω)(ε0)=mω(ε0),

    where 0<q<1 and m1.

    Lemma 2.2. [26] Let hP have the series of the form (1.2). Then the following inequalities hold true:

    |ct|2     (t1), (2.1)
    |ct+kνctck|<2     (0ν1). (2.2)

    Lemma 2.3. [27] Let hP be represented by (1.2), and then the following inequality holds.

    |p2λp21|2  max{1;|2λ1|}   (λC).

    Lemma 2.4. Let hP be given in (1.2), and then there exist k and δD such that

    c2=12(c21+k(4c21)), (2.3)
    c3=14(c31+2c1k(4c21)(4c21)c1k2+2(4c21)(1|k|2)δ). (2.4)

    The values given in (2.3) and (2.4) are due to [26] and [28], respectively.

    Lemma 2.5. [28] If hP has the form (1.2), then

    |α1c312α2c1c2+c3|2, (2.5)

    where

    0α11    and    α1(2α11)α2α1.

    Lemma 2.6. [29] Suppose that

    max{|P+Qx+Rx2|+1|x|2}=χ(P,Q,R), (2.6)

    where P, Q, and R are real numbers, and x¯D={εC:|ε|1}.

    If PR0, then

    χ(P,Q,R)={|P|+|Q|+|R|,  |Q|2(1|R|),1+|P|+Q24(1|R|),  |Q|<2(1|R|).

    In this section, we start with the results of differential subordination. In the next section, we derive the sharp constraints for the first three unknown coefficients, the sharp Fekete-Szegö problem, and the sharp estimate of the second-order Hankel determinant for the newly defined class of q-starlike functions. In addition, the consequences of these results are given in the form of corollaries. In the last section, we establish the sufficient criteria for functions belonging to the class Stan(q).

    Theorem 3.1. Let f(ε)A and h(ε)H(D). Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|2(AB)(sech2(1)|B|sec2(1)). (3.1)

    If the following condition holds:

    1+δεDqh(ε)1+Aε1+Bε. (3.2)

    Then

    h(ε)2+tan(ε)2.

    Proof. Suppose that

    p(ε)=1+δεDqh(ε). (3.3)

    Also, for ω(ε)H(D), we consider

    h(ε)=1+tan(ω(ε))2. (3.4)

    It is sufficient to demonstrate that |ω(ε)|<1 in order to yield the required result. Using (3.3) and (3.4), we have

    p(ε)=1+δsec2(ω(ε))εDqω(ε)2,

    and hence,

    |p(ε)1ABp(ε)|=|δsec2(ω(ε))εDqω(ε)AB(1+δsec2(ω(ε))εDqω(ε)2)|=|δsec2(ω(ε))εDqω(ε)2(AB)Bδsec2(ω(ε))εDqω(ε)|.

    If ω(ε) achieves, at some point ε=ε0, its maximum value |ω(ε0)|=1, i.e., ω(ε0)=eiθ, θ[π,π], then, by Lemma 2.1, for m1,

    ε0Dqω(ε0)=mω(ε0).

    Thus,

    |p(ε0)1ABp(ε0)|=|δsec2(eiθ)mω(ε0)2(AB)Bδsec2(eiθ)mω(ε0)||δ|m|sec(eiθ)|22(AB)+|B||δ|m|sec(eiθ)|2. (3.5)

    A direct computation gives that

    |sec(eiθ)|2=1|cos(cosθ)cosh(sinθ)isin(cosθ)sinh(sinθ)|2=1cosh2(sinθ)+cos2(cosθ)1:=φ(θ).

    Since φ(θ)=φ(θ), for θ[0,π], then

    min{φ(θ)}=φ(π2)=sech2(1),max{φ(θ)}=φ(0)=φ(π)=sec2(1).

    Therefore,

    sech2(1)|sec(eiθ)|2sec2(1). (3.6)

    Putting values of (3.6) into (3.5), we get

    |p(ε0)1ABp(ε0)||δ|msech2(1)2(AB)+|B||δ|msec2(1). (3.7)

    Let

    ϕ(m)=|δ|msech2(1)2(AB)+|B||δ|msec2(1).

    Then

    ϕ(m)=2(AB)sech2(1)|δ|(2(AB)+|B||δ|msec2(1))2>0,

    which shows the increasing behavior of ϕ(m), so the maximum of ϕ(m) will be obtained at m=1. It follows that

    |p(ε0)1ABp(ε0)||δ|sech2(1)2(AB)+|B||δ|sec2(1).

    From (3.1),

    |p(ε0)1ABp(ε0)|1,

    which contradicts (3.2), thus |ω(ε)|<1 and we achieve the intended outcome.

    By taking h(ε)=εDqf(ε)f(ε), we deduce the following result.

    Corollary 3.1. Let f(ε)A and h(ε)=εDqf(ε)f(ε). Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|2(AB)(sech2(1)|B|sec2(1)). (3.8)

    If the following condition holds:

    1+δεDq(ε(Dqf)(ε)f(ε))1+Aε1+Bε. (3.9)

    Then

    εDqf(ε)f(ε)2+tan(ε)2.

    Theorem 3.2. Let h(ε)H(D) with h(0)=1. Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|(AB)(2+tan(1))2(sech2(1)|B|sec2(1)). (3.10)

    If the following subordination criteria hold:

    1+δ(εDqh(ε)h(ε))1+Aε1+Bε. (3.11)

    Then the following subordination holds:

    h(ε)2+tan(ε)2.

    Proof. Define

    p(ε)=1+δ(εDqh(ε)h(ε)). (3.12)

    Let ω(ε)H(D), and consider

    h(ε)=2+tan(ω(ε))2. (3.13)

    We need to show that |ω(ε)|1. Using logarithmic differentiation on (3.13), we obtain from (3.12) that

    p(ε)=1+δ2sec2(ω(ε))εDqω(ε)2+tan(ω(ε)),

    and so

    |p(ε)1ABp(ε)|=|δ2sec2(ω(ε))εDqω(ε)2+tan(ω(ε))AB(1+δ2sec2(ω(ε))εDqω(ε)2+tan(ω(ε)))|=|2δsec2(ω(ε))εDqω(ε)(AB)(2+tan(ω(ε)))2δBsec2(ω(ε))εDqω(ε)|.

    If at some ε=ε0, ω(ε) attains its maximum value for example |ω(ε0)|=1, then, by Lemma 2.1,

    |p(ε0)1ABp(ε0)|=|2δsec2(eiθ)mω(ε0)(AB)(2+tan(eiθ))2δBsec2(eiθ)mω(ε0)|2m|δ||sec2(eiθ)|(AB)(2+|tan(eiθ)|)+2m|δ|B|sec2(eiθ)|. (3.14)

    Now, a direct, simple calculation gives us

    |tan(eiθ)|2=|sin(cos(θ))cosh(sin(θ))+icos(cos(θ))sinh(sin(θ))cos(cos(θ))cosh(sin(θ))isin(cos(θ))sinh(sin(θ))|2=cosh2(sin(θ))cos2(sin(θ))cos2(cos(θ))+cosh2(sin(θ))1:=φ1(θ).

    Since φ1(θ)=φ1(θ), consider θ[0,π]. Then

    min{φ1(θ)}=φ1(π2)=tanh2(1),max{φ1(θ)}=φ1(0)=φ1(π)=tan2(1).

    Therefore,

    tanh(1)|tan(eiθ)|tan(1). (3.15)

    Now set (3.6) and (3.15) in Eq (3.14), and we get

    ϕ(m)=2m|δ|sech2(1)(AB)(2+tan(1))+2m|δ||B|sec2(1),
    ϕ(m)=2|δ|(AB)(2+tan(1))|B|sech2(1)((AB)(2+tan(1))+2m|δ||B|sec2(1))2>0.

    Clearly, one can observe that ϕ(m) is increasing in nature so its maximum value is obtained at m=1, thus

    |p(ε0)1ABp(ε0)|2|δ|sech2(1)(AB)(2+tan(1))+2|δ||B|sec2(1).

    By (3.10), we have

    |p(ε0)1ABp(ε0)|1,

    which contradicts (3.11), therefore |ω(ε)|<1 and so the desired result is obtained.

    By taking h(ε)=εDqf(ε)f(ε), we deduce the following corollary.

    Corollary 3.2. Let fA. Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|(AB)(2+tan(1))2(sech2(1)|B|sec2(1)). (3.16)

    If the following subordination holds:

    1+δε(f(ε)εDq(f(ε)))Dq(εDqf(ε)f(ε))1+Aε1+Bε, (3.17)

    then we have

    εDqf(ε)f(ε)2+tan(ε)2.

    Theorem 3.3. Let h(ε)H(D) with h(0)=1. Suppose that

    |δ|(AB)(2+|tan(1)|)222(|sech2(1)||B||sec1|),  for 1B<sech2(1)sec2(1)<A1. (3.18)

    If the following subordination criteria are fulfilled:

    1+δεDqh(ε)(h(ε))21+Aε1+Bε,

    then we have

    h(ε)2+tan(ε)2.

    Proof. We define a function:

    p(ε)=1+δεDqh(ε)(h(ε))2.

    If there exists ω(ε)H(D) such that

    h(ε)=2+tan(ω(ε))2,

    then, we obtain that

    p(ε)=1+δ4sec2(ω(ε))εDqω(ε)(2+tan(ω(ε)))2,

    and hence,

    |p(ε)1ABp(ε)|=|δ4sec2(ω(ε))εDqω(ε)(2+tan(ω(ε)))2AB(1+δ4sec2(ω(ε))εDqω(ε)(2+tan(ω(ε)))2)|=|4δsec2(ω(ε))εDqω(ε)(AB)(2+tan(ω(ε)))2B(4δsec2(ω(ε))εDqω(ε))|.

    If ω(ε) attains its maximum value at some point ε=ε0, which is |ω(ε0)|=1:ω(ε0)=eiθ, for some θ[π,π], then, by Lemma 2.1,

    ε0Dqω(ε0)=mω(ε0),   for m1.

    Thus, we have

    |p(ε0)1ABp(ε0)|=|4δsec2(eiθ)mω(ε0)(AB)(2+tan(eiθ))2Bδ(4sec2(eiθ)mω(ε0))|4m|δ||sec2(eiθ)|(AB)(2+|tan(eiθ)|)2+4m|δ||B||sec2(eiθ)|. (3.19)

    Applying (3.6) and (3.15) in Eq (3.19),

    ϕ(m)=4m|δ|sech2(1)(AB)(2+tan(1))2+4m|δ||B|sec2(1)ϕ(m)=4|δ|(AB)(2+|tan(1)|)2sech2(1)((AB)(2+tan(1))2+4m|δ||B|sec2(1))2>0.

    Thus, the function ϕ(m) is increasing; hence, it has its maximum value at m=1. Now, we have

    |p(ε0)1ABp(ε0)|4|δ|sech2(1)(AB)(2+tan(1))2+4|δ||B|sec2(1).

    By (3.18),

    |p(ε0)1ABp(ε0)|1.

    It is a contradiction to

    p(ε)1+Aε1+Bε.

    Therefore, |ω(ε)|<1, and the required result is obtained.

    By taking h(ε)=ε(Dqf)(ε)(f(ε))2, we deduce the following corollay.

    Corollary 3.3. Let fA. Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|(AB)(2+tan(1))24(sech2(1)|B|sec2(1)). (3.20)

    If the following holds:

    1+δε(f(ε)ε(Dqf)(ε))2Dq(ε(Dqf)(ε)f(ε))1+Aε1+Bε, (3.21)

    then, we have

    ε(Dqf)(ε)(f(ε))22+tan(ε)2.

    Theorem 3.4. Let h(ε)H(D) with h(0)=1. Suppose that

    |δ|(AB)(2+|tan(eiθ)|)323(|sec2(eiθ)||B||sec2(eiθ)|),    for 1B<sech2(1)sec2(1)<A1. (3.22)

    If the following subordination holds:

    1+δε(Dqh)(ε)(h(ε))31+Aε1+Bε, (3.23)

    then,

    h(ε)2+tan(ε)2.

    Proof. Suppose that

    p(ε)=1+δεDqh(ε)(h(ε))3.

    Now if

    h(ε)=2+tan(ω(ε))2,

    then we can easily obtain

    p(ε)=1+δ8εDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))3,

    and so,

    |p(ε)1ABp(ε)|=|δ8εDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))3AB(1+δ8εDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))3)|=|8δsec2(ω(ε))εDqω(ε)(AB)(2+tan(ω(ε)))38Bδsec2(ω(ε))εDqω(ε)|.

    If the function ω achieves its maximum value, |ω(ε0)|=1, at some point ε=ε0, applying Lemma 2.1 gives us,

    |p(ε0)1ABp(ε0)|=|8δsec2(ω(ε0))mω(ε0)(AB)(2+tan(ω(ε0)))38δBsec2(ω(ε0))mω(ε0)|8mδ|sec2(eiθ)|(AB)(2+|tan(eiθ)|)3+8m|δ||B||sec2(eiθ)|. (3.24)

    Substituting (3.6) and (3.15) into Eq (3.24), we have

    ϕ(m)=8m|δ|sech2(1)(AB)(2+tan(1))38m|δ||B|sec2(1),
    ϕ(m)=8|δ|(AB)(2+tan(1))3sech2(1)((AB)(2+tan(1))3+8m|δ||B|sec2(1))2>0.

    It demonstrates that the function ϕ(m) is increasing. So, its maximum value is obtained at m=1. Thus,

    |p(ε0)1ABp(ε0)|8|δ||sec2(eiθ)|(AB)(2+|tan(eiθ)|)3+8|δ||B||sec2(eiθ)|,

    and hence

    |p(ε0)1ABp(ε0)|1.

    By (3.23), a contradiction occurs. We must have |ω(ε)|<1, so we obtain the needed outcome.

    By taking h(ε)=εDqf(ε)(f(ε))3, we deduce the following result.

    Corollary 3.4. Let fA. Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|(AB)(2+tan(1))323(sech2(1)|B|sec2(1)). (3.25)

    If the following condition holds:

    1+δε(f(ε)εDq(f(ε)))3Dq(εDqf(ε)f(ε))1+Aε1+Bε, (3.26)

    then,

    εDqf(ε)(f(ε))32+tan(ε)2.

    Theorem 3.5. Let h(ε)H(D) with h(0)=1. Suppose that

    |δ|(AB)(2+|tan(eiθ)|)n2n(|sec2(eiθ)||B||sec2(eiθ)|),    for 1B<sech2(1)sec2(1)<A1. (3.27)

    If the following subordination is provided:

    1+δεDqh(ε)(h(ε))n1+Aε1+Bε, (3.28)

    then,

    h(ε)2+tan(ε)2.

    Proof. Suppose

    p(ε)=1+δεDqh(ε)(h(ε))n.

    Now consider

    h(ε)=2+tan(ω(ε))2.

    We can easily obtain that

    p(ε)=1+δ2nεDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))n,

    and hence,

    |p(ε)1ABp(ε)|=|δ2nεDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))nAB(1+δ2nεDqω(ε)sec2(ω(ε))(2+tan(ω(ε)))n)|=|2nδεDqω(ε)sec2(ω(ε))(AB)(2+tan(ω(ε)))n2nBδεDqω(ε)sec2(ω(ε))|.

    If the function ω accomplishes its maximum value, |ω(ε0)|=1, at some point ε=ε0, then, utilizing Lemma 2.1, we have

    |p(ε0)1ABp(ε0)|=|2nδεDqω(ε)sec2(ω(ε))(AB)(2+tan(ω(ε)))n2nBδεDqω(ε)sec2(ω(ε))|2nmδ|sec2(eiθ)|(AB)(2+|tan(eiθ)|)n+2nm|δ||B||sec2(eiθ)|. (3.29)

    Now set (3.6) and (3.15) in (3.29), and we get

    ϕ(m)=2nmδ|sec2(eiθ)|(AB)(2+|tan(eiθ)|)n+2nm|δ||B||sec2(eiθ)|ϕ(m)=2n|δ|(AB)(2+tan(1))nsech2(1)((AB)(2+|tan(eiθ)|)n+2nm|δ||B||sec2(eiθ)|)2>0.

    It demonstrates that ϕ(m) increases, achieving the maximum value at m=1. Thus,

    |p(ε0)1ABp(ε0)|2nδ|sec2(eiθ)|(AB)(2+|tan(eiθ)|)n+2n|δ||B||sec2(eiθ)|,

    and hence

    |p(ε0)1ABp(ε0)|1,

    which contradicts the assumption (3.28), so |ω(ε)|<1. We complete the proof.

    By taking h(ε)=εDqf(ε)(f(ε))n, we deduce the following corollary.

    Corollary 3.5. Let fA. Suppose that

    1B<sech2(1)sec2(1)<A1,
    |δ|(AB)(2+tan(1))n2n(sech2(1)|B|sec2(1)). (3.30)

    If the following is given:

    1+δε(f(ε)εDq(f(ε)))nDq(εDqf(ε)f(ε))1+Aε1+Bε, (3.31)

    then,

    εDqf(ε)(f(ε))n2+tan(ε)2.

    Remark 3.1. One can obtain new results for the class Stan by taking the limit q1 in our results.

    Theorem 4.1. If fStan(q) is of the form (1.1), then

    |ξ2|12q     (0<q<1),|ξ3|12q(q+1)     (0.5<q<1),|ξ4|12q(q2+q+1)  (0.41310<q<0.57708).

    All these estimates are extreme for a function defined below:

    εDqf(ε)f(ε)=2+tan(εn)2=1+12εn+      (n=1,2,3). (4.1)

    Proof. Suppose fStan(q), and then there exists a Schwarz function ω(ε) such that

    ε(Dqf)(ε)f(ε)=2+tan(ω(ε))2,

    where ω(ε)=p(ε)1p(ε)+1. If p(ε) follows the form of (1.2), then

    ω(ε)=c1ε+c2ε2+c3ε3+c4ε4+2+c1ε+c2ε2+c3ε3+c4ε4+.

    Using this, one can easily find

    2+tan(ω(ε))2=1+14c1ε+(14c218c21)ε2+(112c3114c2c1+14c3)ε3+(116c41+14c21c214c3c118c22+14c4)ε4+. (4.2)

    Then

    εDqf(ε)f(ε)=1+qξ2ε+[q(q+1)ξ3qξ22]ε2+[q(2n=0qn)ξ4q(q+2)ξ2ξ3+qξ32]ε3+q[q3ξ5+(ξ5ξ2ξ4)q2+(ξ5ξ23+ξ22ξ3ξ2ξ4)q+ξ5+3ξ22ξ32ξ2ξ4ξ42ξ23]ε4+. (4.3)

    Comparing (4.2) and (4.3), we obtain

    ξ2=14qc1, (4.4)
    ξ3=14q(q+1)(c22q14qc21), (4.5)
    ξ4=14q(1+q+q2)((16q3+10q212q+348q2(q+1))c31(4q2+3q2)4q(q+1)c1c2+c3). (4.6)

    Applying (2.1) to (4.4), and we have

    |ξ2|12q.

    To find the bound of ξ3, apply (2.2) to (4.5) with 0.5<q<1, and we have

    |ξ3|12q(q+1).

    From Lemma 2.5,

    α1=16q3+10q212q+348q2(q+1),

    and

    α2=(4q2+3q2)2q(q+1),

    so the conditions 0α21 and α2(2α21)α1α2 are satisfied for 0.41310<q<0.57708. Applying Lemma 2.5, we get

    |ξ4|12q(1+q+q2).

    Corollary 4.1. If fStan, then

    |ξ2|12,|ξ3|14,|ξ4|16.

    The above three bounds are sharp for the function defined below:

    εf(ε)f(ε)=2+tan(εn)2=1+12εn+    (n=1,2,3). (4.7)

    Theorem 4.2. If fStan(q), then

    |ξ3λξ22|12q(q+1)max{1,|(1+q)ξ12q|}.

    The result is sharp for the function defined in (4.1), for n=2.

    Proof. From (4.4) and (4.5), we have

    |ξ3λξ22|=14q(q+1)|c2(a(1+q)+2q1)4qc21c21|.

    Applying Lemma 2.3 to the preceding equation yields the desired outcome.

    Corollary 4.2. If fStan, then

    |ξ3λξ22|14max{1,|2λ12|}.

    The result is sharp for the function defined in (4.7), for n=2.

    Theorem 4.3. If fStan(q), then

    |ξ2ξ3ξ4|12q(1+q+q2)    (0.14527<q<0.22265).

    The outcome is sharp for the function defined in (4.1), for n=3.

    Proof. From (4.4)–(4.6), we have

    |ξ2ξ3ξ4|=14q(1+q+q2)|922q48qc31(15q)4qc1c2+c3|.

    Comparing with Lemma 2.5, we have

    α1=922q48q     and    α2=(15q)2q,

    and the conditions 0α21 and α2(2α21)α1α2 are satisfied for 0.14527<q<0.22265, so Lemma 2.5 is valid to apply. Hence

    |ξ2ξ3ξ4|12q(1+q+q2).

    Corollary 4.3. If fStan, then

    |ξ2ξ3ξ4|16.

    The result is sharp for the function defined in (4.7), for n=3.

    Theorem 4.4. Let fStan(q) be given in the form (1.1), and then

    |ξ2ξ4ξ23|14(1+q+q2)2,     for q(0.8382,1). (4.8)

    Proof. From (4.4)–(4.6), we have

    |ξ2ξ4ξ23|=|(1+q)16(1+q+q2)(1+q+q2+q3)c1c3116(1+q+q2)2c22(q5+q4+8q35q2+10q5)64(1+q)(1+q+q2)2(1+q+q2+q3)c21c211024(q8+4q7+14q640q5+11q4116q3+186q260q+88)(1+q)3(1+q+q2)2(1+q+q2+q3)c41|.

    Using Lemma 2.4 for c1=c, we have

    |ξ2ξ4ξ23|=|(q8+12q7+38q6+32q5+43q4148q3+202q276q+48)1024(q+1)3(q2+q+1)2(q3+q2+q+1)c4(q5+q4+4q313q2+6q5)128(q+1)(q2+q+1)2(q3+q2+q+1)c2(4c2)x((1+q+q2+q3)(4c2)+(1+q)(1+q+q2)c264(1+q+q2)2(1+q+q2+q3))(4c2)x2+(1+q)32(1+q+q2)(1+q+q2+q3)(4c2)c(1|x|2)ε|.

    For c[0,2], the simple calculation gives

    |ξ2ξ4ξ23|=(1+q)32(1+q+q2)(1+q+q2+q3)|(q8+12q7+38q6+32q5+43q4148q3+202q276q+48)32(q+1)4(q2+q+1)c4(q5+q4+4q313q2+6q5)4(q+1)2(q2+q+1)c2(4c2)x((1+q+q2+q3)(4c2)+(1+q)(1+q+q2)c22(1+q)(1+q+q2))(4c2)x2+(4c2)c(1|x|2)ε|,

    where x and δ satisfy |x|1 and |δ|1.

    Next, we will find the maximum value of |ξ2ξ4ξ23| for c[0,2].

    Case 1. When c=0, we have

    |ξ2ξ4ξ23|14(1+q+q2)2         q(0,1).

    Case 2. When c=2, we get

    |a2a4a23|=14(1+q+q2)2(q8+12q7+38q6+32q5+43q4148q3+202q276q+48)16(q+1)3(1+q+q2+q3)14(1+q+q2)2       q(0,1).

    Case 3. Assume c(0,2). Then, by the above equation and the triangular inequality,

    |ξ2ξ4ξ23|(1+q)(4c2)c32(1+q+q2)(1+q+q2+q3)|(q8+12q7+38q6+32q5+43q4148q3+202q276q+48)32(q+1)4(q2+q+1)(4c2)c3(q5+q4+4q313q2+6q5)c4(q+1)2(q2+q+1)x((1+q+q2+q3)(4c2)+(1+q)(1+q+q2)c22c(1+q)(1+q+q2))x2+(1|x|2)|.

    By Lemma 2.6, we can write it as

    |ξ2ξ4ξ23|(1+q)(4c2)c32(1+q+q2)(1+q+q2+q3)ψ(P,Q,R),

    where

    P=(q8+12q7+38q6+32q5+43q4148q3+202q276q+48)32(q+1)4(q2+q+1)(4c2)c3,
    Q=(q5q44q3+13q26q+5)c4(q+1)2(q2+q+1),

    and

    R=((1+q+q2+q3)(4c2)+(1+q)(1+q+q2)c2)2c(1+q)(1+q+q2).

    Clearly, for all q(0,1) and c(0,2), we have

    PR=(c2q+4q2+4)(q8+12q7+38q6+MD)64(4c2)(q+1)4(q2+q+1)2c2>0,

    where

    MD=32q5+43q4148q3+202q276q+48.

    Now we consider |Q|2(1|R|). Let

    φ(c)=8(q+1)2(q2+q+1)c{|Q|2(1|R|)},

    which implies

    φ(c)=2(52q+21q2q4q5)c216(q+1)2(q2+q+1)c+32(q2+1)(q+1)2.

    Differentiating φ(c) twice, we have

    φ(c)=4(52q+21q2q4q5)c16(q+1)2(q2+q+1),
    φ(c)=4(52q+21q2q4q5)>0       q(0,1).

    This shows that φ(c) is an increasing function and

    maxφ(c)=φ(2)=8q524q448q3+104q264q+24<0           q(0.8382,1).

    It follows that

    φ(c)<0c(0,2)q(0.8382,1).

    Hence, φ(c) is a decreasing function and

    minφ(c)=φ(2)=8q58q432q3+104q248q+400    q(0,1).

    This implies |Q|2(1|R|)>0, and then by Lemma 2.6,

    |ξ2ξ4ξ23|(1+q)(4c2)c32(1+q+q2)(1+q+q2+q3)(|P|+|Q|+|R|)=h(c),

    where

    h(c)=Mc4+Nc2256(q2+1)(q+1)41024(q+1)3(q2+q+1)2(1+q+q2+q3).

    By differentiating, we have

    h(c)=11024(q+1)3(q2+q+1)2(1+q+q2+q3)(Mc3+Nc),

    where

    M=(q820q762q672q5+53q4+372q390q2+124q8)0   for  q(0.0669,1),

    and

    N=(32q7+160q6+416q5+64q4384q3+64q96)0  for q(0.8382,1),

    which implies

    h(c)0.

    We conclude that the function h(c) is a decreasing function and

    h(c)h(0)=14(q2+q+1)2.

    From all of the above discussion, we conclude that

    |ξ2ξ4ξ23|14(1+q+q2)2,   for  q(0.8382,1).

    Theorem 5.1. A function fStan(q) if and only if

    1ε[f(ε)Hε2Gε2(1ε)(1qε)]0, (5.1)

    where

    G=2+tan(eiθ),H=tan(eiθ),  or G=H=1. (5.2)

    Proof. If a function f Stan(q), then f is analytic in D, and hence 1εf(ε)0 for all ε in D=D{0}. Thus, we have the Eq (5.1) for G=H=1.

    Now, by using (1.9) along with the principle of subordination, there exists a Schwarz function ω such that

    ε(Dqf)(ε)f(ε)=1+tan(ω(ε))2.

    Taking into consideration ω(ε)=eiθ, for 0θ2π, then the above expression becomes

    ε(Dqf)(ε)f(ε)1+tan(eiθ)2, (5.3)
    ε(Dqf)(ε)(2+tan(eiθ)2)f(ε)0. (5.4)

    Now, by using the relations

    f(ε)=f(ε)ε1ε  and   ε(Dqf)(ε)=f(ε)ε(1ε)(1qε),

    the Eq (5.4) becomes

    f(ε)ε(1ε)(1qε)(2+tan(eiθ)2)(f(ε)ε1ε)0.

    After some simple calculations, we get

    f(ε)(((2+tan(eiθ))qε2tan(eiθ)ε)2(1ε)(1qε))0,12ε(f(ε)Hε2Gε(1ε)(1qε))0,

    where H and G are given in (1.3), and thus the the necessary condition holds.

    Conversely, assume that the condition in (5.1) satisfies, then 1εf(ε)0, for all εD. Let K(ε)=ε(Dqf)(ε)f(ε), which is regular in D and K(0)=1. 

    Also, assume that f(ε)=1+tan(ε)2, and from (5.3), f(D)K(ε)=.

    Therefore, the connected component Cf(D) containing the domain K(ε) is connected as well. Given the univalence of "K" and the supposition that f(0)=K(0)=1,  it is evident that Kf, indicating that fStan(q).

    In conclusion, leveraging the framework of q-calculus, we have introduced a novel class of q-starlike functions associated with the eight-shaped image domain, offering new insights into their geometric behavior. Our research successfully established results in differential subordination and derived sharp inequalities for the first three unknown coefficients of the Taylor series. Additionally, we provided precise solutions to the Fekete-Szegö problem and second-order Hankel determinants for this newly defined class, with the broader implications demonstrated through a series of corollaries.

    The scope of these findings extends beyond the specific class of functions examined. Our methodology offers a flexible foundation for analyzing other image domains and subclasses within geometric function theory. This opens avenues for future work that could explore more general families of functions, potentially leading to new results in related areas, such as higher-order Hankel determinants, multi-variable quantum calculus, and further applications of q-differential operators. The results enhance the current understanding of q-starlike functions and provide a robust platform for future investigations into the more profound applications of quantum calculus in geometric and analytic function theory.

    Jianhua Gong, Muhammad Ghaffar Khan, Hala Alaqad and Bilal Khan: Writing-original draft, writing-review and editing. All authors contributed equally to the manuscript. All authors have read and approved the final version of the manuscript for publication.

    The first author is supported by the UAEU Program for Advanced Research (UPAR12S127) from United Arab Emirates University.

    The authors declare that they have no competing interests.



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