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Remarks on parabolic equation with the conformable variable derivative in Hilbert scales

  • In this paper, we are interested in diffusion equations with conformable derivatives with variable order. We will study two different types of models: the initial value model and the nonlocal in time model. With different values of input values, we investigate the well-posedness of the mild solution in suitable spaces. We also prove the convergence of mild solution of the nonlocal problem to solutions of the initial problem. The main technique of our paper is to use the theory of Fourier series in combination with evaluation techniques for some generalized integrals. Our results are one of the first directions on the diffusion equation with conformable variable derivative in Hilbert scales.

    Citation: Phuong Nguyen Duc, Ahmet Ocak Akdemir, Van Tien Nguyen, Anh Tuan Nguyen. Remarks on parabolic equation with the conformable variable derivative in Hilbert scales[J]. AIMS Mathematics, 2022, 7(11): 20020-20042. doi: 10.3934/math.20221095

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  • In this paper, we are interested in diffusion equations with conformable derivatives with variable order. We will study two different types of models: the initial value model and the nonlocal in time model. With different values of input values, we investigate the well-posedness of the mild solution in suitable spaces. We also prove the convergence of mild solution of the nonlocal problem to solutions of the initial problem. The main technique of our paper is to use the theory of Fourier series in combination with evaluation techniques for some generalized integrals. Our results are one of the first directions on the diffusion equation with conformable variable derivative in Hilbert scales.



    Fractional calculus has recently attracted the attention of many researchers and has become an attractive field of study with its different application areas. Some researchers have discovered that fractional differential equations with different singular or non-singular kernel need to be determined by real-world problems in the fields of engineering and science. Some definitions/approaches, for example, Riemann-Liouville, Hadamard, Katugampola, Riesz, Caputo-Fabrizio, and Atangana-Baleanu operators, were presented and tested using a variety of theories. Many important analytical methods have been used to achieve analytical solutions to fractional diffusion equations. By replacing many differential operators of fractional order with different PDE types of integer order, we form different types of boundary value problems with fractional order. However, the types of diffusion equations with fractional derivatives in Hilbert scales space are not really abundant because of their difficulty. We can list a few interesting works on PDEs with fractional derivatives, for example, [7,8,9,12,13,14,16,21,22,27,28,29] and the references therein.

    Let T be a positive number. In this paper, we consider the initial value problem for the conformable heat equation (or called parabolic equation with conformable operator)

    {β(t)tβ(t)y+Ay(x,t)=F(x,t),xΩ,t(0,T),y(x,t)=0,xΩ,t(0,T), (1.1)

    where β(t)tβ(t)y=T0β(t)y(t) is defined in Definition (2.3). Here ΩRN (N1) is a bounded domain with the smooth boundary Ω. We are interested to study two following conditions

    y(x,0)=y0(x),xΩ. (1.2)

    or nonlocal in time condition

    y(x,0)+hy(x,T)=y0(x),h>0,xΩ. (1.3)

    The condition (1.2) is also known as initial conditions, which is familiar to mathematicians in the field of PDEs. Let us provide some remarks on the condition (1.3). Non-local conditions present and explain some more realistic perspectives for some particular phenomena for which usual initial conditions are replaced by multi-time point data such as studying atomic reactors [1,2,26]. In terms of mathematical aspect, since these conditions provide different data from the usual initial/terminal conditions problems with associated nonlocal conditions possess particular properties. In particular, it is well-known that while the problem for the usual parabolic equation is well-posed with the initial Cauchy condition at t=0 and such problem is ill-posed with given data at terminal time t=T>0, the well-posedness can be witnessed for the problems involving forward parabolic equations with non-local in time conditions connecting the values at different times [5]. In fact, throughout this work, we can see that the techniques to derive well-posed results for the initial value problem and the nonlocal in time problem are quite different. The above remarks play an important role in our motivation for deciding to carry out this study. As far as we know, there is very little documentation on the solution connection boundary conditions at different points in time, for example, at the beginning and at the end. Consideration of non-local initial conditions or non-local final conditions derived from actual processes.

    Before we cover our problem, we give some background on conformable derivatives. A Conformable derivative can be first stated by Khalil and his colleagues [3] for functions f:[0,]+, it can be considered as the general form of the classical derivative and follows the same properties as the classical derivative. Furthermore, the physical meaning of the conformable derivative is assumed to be a modification of the classical derivative of direction and magnitude. More precisely, the general conformable derivative possesses similar physical and geometrical interpretations of Newton's derivative. However, while Newton's derivative describes the velocity of a particle or slope of a tangent, the general conformable derivative can be regarded as a special velocity, its direction and strength rely on a particular function [23].

    Let us take M as a Banach space, and the function f:[0,)M and Cβtβ be the conformable derivative of order 0<β1 locally defined by

    Cβf(t)tβ:=limh0f(t+ht1β)f(t)hin M, (1.4)

    for each t>0. For additive information about the above definition, we refer the reader to [3,4,6,10,11,20]. An easy observation is that if β=1 then the definition given above is the definition of the classical derivative. To further understand the relationship between conformable and classical derivatives, we direct the reader to the interesting paper [15]. This paper can be considered as one of the first works to investigate diffusion equations with conformable derivative in the Sobolev space. According to natural development, based on the conformable derivative, mathematicians have built a good theory for conformable derivative with orders dependent on a variable.

    For the reader to better understand the history of this problem, we present a number of related works. Let us provide the comments of some fractional diffusion equations associated with fractional derivative whose order is a constant, i.e., β(t)=β.

    Now, we introduce some previous work mentioned on fractional diffusion equation with variable order. In [18], the authors considered the relaxation-type equation with fractional variable order as follows

    {α(t)tα(t)y(t)+By(t)=F(t),0<α(t)1,y(0)=1, (1.5)

    where α(t)tα(t) is the left Caputo derivative of order α(t), B is the relaxation coefficient, f(t) denotes the external source term. The authors investigated the cable equation with fractional variable order [19]. In [24], the authors studied a dynamical system described by the following fractional differential equation with variable order

    {α(t,y(t))tα(t)y(t)=F(t,y(t)),0<α(t,y(t))1,y(c)=y0,, (1.6)

    The authors considered the following dynamical system with variable-order fractional derivative

    {CDq(t)x(t)=f(t,x),x(a)=0,

    where q(t) is the variable-order of differentiation [25].

    To the best of our knowledge, there are not any results for considering the well-posedness of two problem (3.1)–(1.2) and (3.1)–(1.3). We draw attention to the paper [17] since it mentioned variable conformable derivative. They investigated the fundamental solutions for initial value problem for linear diffusion differential equations with the conformable variable order derivative. Their techniques are based on upper and lower solutions and monotone iterative method. One difference is that they consider (3.1) on the unbounded domain, while we consider it on the bounded domain. Our approach in this paper is different from [17] because we have to learn the ideas of Fourier series. A new point of the current paper is that we carefully examine the well-posedness of our problem.

    Let us assert that the problem with the variable conformable derivative is more difficult than the derivatives of constant derivative. The main reason is the appearance of integrals with exponents as functions, for example t0rβ(r)1dr causing many difficulties in calculation and evaluation. To overcome these difficulties, we need to have skillful judgment to control the components containing these singular integrals.

    The main objective of this paper is to investigate the existence and regularization of solutions for two problems. With different assumptions of the input functions F and u0, we will show the space containing the solution. As introduced above, we have a challenge with components that contain singular integrals. Another interesting contribution is that we will examine the relationship between the solutions of two problems: nonlocal problem (3.1)–(1.3) and (3.1)–(1.2). The result is proven convergent of the mild solution to (3.1)–(1.3) when h0+. This proof of convergent is understood as a non-trivial task.

    The structure of the paper is given as follows. Section 3 examines the well-posedness for the initial value problem (3.1)–(1.2). The existence for the mild solution to (3.1)–(1.3) is investigated in section 4. We also derive that the convergence of the mild solution to problem (3.1)–(1.3) when h0.

    In this section, we introduce notations and functional settings which will be used throughout this work. Recall that the spectral problem

    {Aψj(x)=λjψj(x),xΩ,ψj(x)=0,xΩ,

    admits the eigenvalues 0<λ1λ2λj with λj as j and the corresponding set of eigenfunctions {ψj}j1H10(Ω).

    Definition 2.1. We recall the Hilbert scale space as follows

    Zs(Ω)={fL2(Ω),j=1λ2sj(Ωf(x)ψj(x)dx)2<},

    for any s0. It is well-known that Zs(Ω) is a Hilbert space corresponding to the norm

    fZs(Ω)=(n=1λ2sj(Ωf(x)ψj(x)dx)2)1/2,fZs(Ω).

    In the following, we provide definitions of the left integral and the (left) variable order fractional derivative which are taken from [17].

    Definition 2.2. Let f:[a,)(0,1]. The left integral begin at a of variable function h:(a,)R is given by

    Iah(t)f(t)=ta(sa)h(s)1f(s)ds,t>a. (2.1)

    Definition 2.3. The (left) variable order fractional derivative starting at a of a function f:[a,) of order h:[a,)(0,1] is defined by

    Tah(t)f(t)=limϵ0f(t+ϵ(ta)1h(t))f(t)ϵ,t>a. (2.2)

    When a=0, one can write Th(t). Moreover if Tah(t)f(t) exists on (a,) then Tah(t)f(a)=limta+Tah(t)f(t).

    In addition, if the fractional derivative of order h(t)(0,1] of f exists for all t(a,), we simply say f is h(t) differentiable.

    In this section, we focus on the initial value problem

    {β(t)tβ(t)y+Ay(x,t)=F(x,t),xΩ,t(0,T),y(x,t)=0,xΩ,t(0,T),y(x,0)=y0(x),xΩ, (3.1)

    where y0 and F will be defined later. Our main purpose in this section is to study the well-posedness of Problem (3.1). We use the Fourier analysis to construct the mild solution. Let us assume that y(x,t)=j=1y(.,t),ψjψj(x) where y(.,t),ψj:=Ωy(x,t)ψj(x)dx. Taking the inner product , of the main equation of Problem (3.1) with ψj gives

    {β(t)tβ(t)y(.,t),ψj+λjy(.,t),ψj=F(.,t),ψj,t(0,T),y(.,0),ψj=y0,ψj. (3.2)

    By the result in [17], we obtain the following equality

    y(.,t),ψj=exp(λjt0rβ(r)1dr)y0,ψj+t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr, (3.3)

    where we remind that β:[0,)(0,1]. By the definition of Fourier series, we have the following formula of the mild solution

    y(x,t)=jexp(λjt0rβ(r)1dr)y0,ψjψj(x)+j[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]ψj(x)=:J1+J2. (3.4)

    Lemma 3.1. Let m=min0t1|β(t)| and b=max0t1|β(t)|.

    i) If 0t1 then

    tbb|t0rβ(r)1dr|tmm. (3.5)

    ii) If t1 then

    1b+tm1m|t0rβ(r)1dr|1m+tb1b. (3.6)

    Proof. We claim (i) as follows. Since β(r)m and 0<β(r)1, we know that 01β(r)1m. Since 0rt<1, we know that 1r>1. It follows that

    (1r)1β(r)(1r)1m. (3.7)

    This implies that

    |t0rβ(r)1dr|=t0(1r)1β(r)drt0(1r)1mdr=tmm. (3.8)

    Since 1β(r)1b0, we know that

    (1r)1β(r)(1r)1b.

    It implies the following lower bound

    |t0rβ(r)1dr|=t0(1r)1β(r)drt0(1r)1bdr=tbb. (3.9)

    We next provide the proof of (ii). Since t1, we derive

    t0rβ(r)1dr=10rβ(r)1dr+t1rβ(r)1dr. (3.10)

    Using (3.5) with t=1, we obtain the following upper and lower bound

    1b10rβ(r)1dr1m. (3.11)

    Our next aim is to consider the term t1rβ(r)1dr. It is easy to observe that

    1b1β(r)1m.

    From the fact that 0<1r<1, we get the upper bound below

    t1rβ(r)1dr=t1(1r)1β(r)drt1(1r)1bdr=tb1b, (3.12)

    and also, the lower bound

    t1rβ(r)1dr=t1(1r)1β(r)drt1(1r)1mdr=tm1m. (3.13)

    Connecting all the above inequalities (3.11), (3.12) and (3.13) gives us the assertion (3.6).

    Lemma 3.2. Let m=min0t1|β(t)| and b=max0t1|β(t)|.

    i) If 0rt1 then

    tbrbbtrzβ(z)1dztmrmm. (3.14)

    ii) If 0<r1t, we get

    1rbb+tm1mtrzβ(z)1dz1rmm+tb1b. (3.15)

    iii) If 01rt then

    tmrmmtrzβ(z)1dztbrbb. (3.16)

    Proof. The proof of this lemma is almost the same as that of Lemma (3.1). Our claim is divided into three cases.

    The case 0<t1. For this case, it is easy to see that

    (1z)1b(1z)1β(z)(1z)1m.

    This implies that

    tr(1z)1bdztrzβ(z)1dz=tr(1z)1β(z)dztr(1z)1mdz. (3.17)

    It is easy to verify that

    tr(1z)1bdz=trzb1dz=tbrbb (3.18)

    and

    tr(1z)1mdz=trzm1dz=tmrmm. (3.19)

    Hence, we obtain that for any 0<rt1

    tbrbbtrzβ(z)1dztmrmm. (3.20)

    The case 0rt1. For this case, we get the following identity

    trzβ(z)1dz=1rzβ(z)1dz+t1zβ(z)1dz. (3.21)

    By setting t=1 into (3.20), we arrive at

    1rbb1rzβ(z)1dz1rmm. (3.22)

    This implies the following estimate

    1rbb+tm1m1rzβ(z)1dz+t1zβ(z)1dz1rmm+tb1b, (3.23)

    which allows us to deduce the desired result.

    The case 01rt. Under this case, we obtain that if rzt then

    (1z)1m(1z)1β(z)(1z)1b.

    This implies that

    tr(1z)1mdztrzβ(z)1dztr(1z)1bdz. (3.24)

    Hence, we find that

    tmrmmtrzβ(z)1dztbrbb. (3.25)

    The well-posedness of Problem (3.1) is described by the following theorem.

    Theorem 3.3. i) Let y0Zsε(Ω) for ε>0 and FL(0,T;Zs(Ω)). Then we get

    y(.,t)Zs(Ω)(Tbε+1)tbεy0Zsε(Ω)+tb+tmmFL(0,T;Zs(Ω)),t>0. (3.26)

    ii) Let y0Zsε(Ω) for ε>0 and FL(0,T;Zsδ(Ω)) for any 0<δ<12. Let us assume that 2m>b. Then we obtain

    y(.,t)Zs(Ω)(Tbε+1)tbεy0Zsε(Ω)+tmbδFL(0,T;Zsδ(Ω)). (3.27)

    Proof. Let us recall the mild solution

    y(x,t)=jexp(λjt0rβ(r)1dr)y0,ψjψj(x)+j[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]ψj(x)=J1+J2. (3.28)

    Step 1. Estimate of the term J1. Using the inequality eaC(ε)aε for any ε>0, we find that

    exp(λjt0rβ(r)1dr)C(ε)λεj(t0rβ(r)1dr)ε. (3.29)

    If 0<t1 in view of (3.5), we obtain

    exp(λjt0rβ(r)1dr)C1λεjtbε, (3.30)

    where

    C1=C(ε)bε.

    By Parseval's equality and using (3.30), we derive that

    jexp(λjt0rβ(r)1dr)y0,ψjψj(x)2Zs(Ω)=jλ2sjexp(2λjt0rβ(r)1dr)y0,ψj2C21t2bεjλ2s2εjy0,ψj2. (3.31)

    This implies that for t1

    jexp(λjt0rβ(r)1dr)y0,ψjψj(x)Zs(Ω)C1tbεy0Zsε(Ω). (3.32)

    If t1 thanks to (3.6) of Lemma (3.1), we obtain

    exp(λjt0rβ(r)1dr)C(ε)λεj(1b+tm1m)ε. (3.33)

    Since t1, it is obvious to see that the following inequality is satisfied

    (1b+tm1m)εbε.

    From the previous observations, we get that

    jexp(λjt0rβ(r)1dr)y0,ψjψj(x)Zs(Ω)C1y0Zsε(Ω)C1Tbεtbεy0Zsε(Ω). (3.34)

    Combining (3.32) and (3.34), we deduce the following estimate for any 0tT

    jexp(λjt0rβ(r)1dr)y0,ψjψj(x)Zs(Ω)=J1(.,t)Zs(Ω)C1(Tbε+1)tbεy0Zsε(Ω). (3.35)

    Step 2. Estimate of the term J2.

    By Parseval's equality and Hölder's inequality, we find that

    J2(.,t)2Zs(Ω)=jλ2sj[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]2jλ2sj[t0rβ(r)1exp(λjtrzβ(z)1dz)dr][t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψj2dr]. (3.36)

    Let us now consider possible cases as follows.

    Case 1: 0<t1 and FL(0,T;Zs(Ω)).

    In view of (3.14) and the fact that exp(λjtrzβ(z)1dz)1, we derive

    t0rβ(r)1exp(λjtrzβ(z)1dz)drt0rβ(r)1drtmm. (3.37)

    It follows from (3.36) that

    J2(.,t)2Zs(Ω)tmmjλ2sj[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψj2dr]tmmt0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r)2Zs(Ω)drtmmt0rβ(r)1F(.,r)2Zs(Ω)drtmmF2L(0,T;Zs(Ω))(t0rβ(r)1dr). (3.38)

    From (3.14) we obtain that the following estimate

    J2(.,t)Zs(Ω)tmmFL(0,T;Zs(Ω)). (3.39)

    Case 2: t1 and FL(0,T;Zs(Ω)).

    Using (3.38) and by a similar claim in case 1, we get that

    J2(.,t)2Zs(Ω)jλ2sj[t0rβ(r)1dr][t0rβ(r)1F(.,r),ψj2dr][t0rβ(r)1dr]2F2L(0,T;Zs(Ω)). (3.40)

    In view of (3.6), we obtain

    J2(.,t)Zs(Ω)(t0rβ(r)1dr)FL(0,T;Zs(Ω))(1m+tb1b)FL(0,T;Zs(Ω)). (3.41)

    Since bm, we have the following inequality

    1m+tb1b1m+tb1m=tbm.

    Therefore, we derive that for any t1

    J2(.,t)Zs(Ω)tbmFL(0,T;Zs(Ω)). (3.42)

    Combining case 1 and case 2, we get the following estimate for any t>0 and FL(0,T;Zs(Ω))

    J2(.,t)Zs(Ω)tb+tmmFL(0,T;Zs(Ω)). (3.43)

    Case 3: 0<t1 and FL(0,T;Zsδ(Ω)).

    Using the inequality eaC(δ)aδ for any δ>0, we obtain that

    exp(λjtrzβ(z)1dz)C(δ)λδj(trzβ(z)1dz)δ. (3.44)

    From the fact that t1, we use (3.14) to get

    (trzβ(z)1dz)δ(tbrbb)δ=bδ(tbrb)δ. (3.45)

    Hence, we get the following estimate

    t0rβ(r)1exp(λjtrzβ(z)1dz)drC(δ,b)λδjt0rβ(r)1(tbrb)δdrC(δ,b)λδjt0rm1(tbrb)δdr, (3.46)

    where we have used (3.7). Let us now treat the integral term on the right hand side of (3.46). By applying Hölder inequality and noting that 2m>b, we derive that

    t0rm1(tbrb)δdr=t0r2mb12rb12(tbrb)δdr(t0r2mb1dr)1/2(t0rb1(tbrb)2δdr)1/2=t2mb2mbt0rb1(tbrb)2δdr. (3.47)

    Set r=rb, then dr=brb1dr. Then, since 2δ<1, we have

    t0rb1(tbrb)2δdr=1btb0(tbr)2δdr=1btb(12δ)12δ. (3.48)

    Combining (3.46), (3.47) and (3.48), we get the following estimate for t1

    t0rβ(r)1exp(λjtrzβ(z)1dz)dr¯C1λδjtmbδ, (3.49)

    where

    ¯C1=C(δ,b)b12δ2mb.

    This inequality together with (3.36) yields

    J2(.,t)2Zs(Ω)¯C1tmbδjλ2sδj[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψj2dr]¯C1C(δ,b)tmbδjλ2s2δjt0rm1(tbrb)δF(.,r),ψj2dr¯C2tmbδt0rm1(tbrb)δF(.,r)2Zsδ(Ω)dr, (3.50)

    where ¯C2=¯C1C(δ,b). It is obvious to see that

    t0rm1(tbrb)δF(.,r)2Zsδ(Ω)drFL(0,T;Zsδ(Ω))t0rm1(tbrb)δdr. (3.51)

    In the previous claim, we showed that

    t0rm1(tbrb)δdrtmbδb12δ2mb. (3.52)

    Combining (3.50), (3.51) and (3.52), we obtain that for any 0<t1

    J2(.,t)Zs(Ω)¯C3tmbδFL(0,T;Zsδ(Ω)), (3.53)

    where we denote by

    ¯C3=C(δ,b)(12δ)(2mb)b.

    Case 4: t1 and FL(0,T;Zsδ(Ω)).

    We need to deal with the integral term

    I=t0rβ(r)1exp(λjtrzβ(z)1dz)dr.

    To this end, we derive the following equality

    I=10rβ(r)1exp(λj1rzβ(z)1dz)dr+t1rβ(r)1exp(λjtrzβ(z)1dz)dr=I1+I2. (3.54)

    For the term I1, we put t=1 into (3.49) to obtain

    I1¯C1λδj. (3.55)

    For the second term I2, we note that 1rt. Hence rβ(r)1rb1. In view of the inequality eaC(δ)aδ for any δ>0, we get

    exp(λjtrzβ(z)1dz)C(δ)λδj(trzβ(z)1dz)δ. (3.56)

    Using (3.16) and (3.56), we find that

    I2C(δ)λδjt1rb1(trzβ(z)1dz)δdr. (3.57)

    In view of (3.16), we can check easily that

    (trzβ(z)1dz)δ(tmrmm)δ=mδ(tmrm)δ.

    It follows from (3.57) that

    I2C(δ)mδλδjt1rb1(tmrm)δdr. (3.58)

    Next, using Hölder inequality to derive that

    t1rb1(tmrm)δdr=t1r2bm12rm12(tmrm)δdr(t1r2bm1dr)1/2(t1rm1(tmrm)2δdr)1/2=t2bm12bm(t1rm1(tmrm)2δdr)1/2. (3.59)

    It is not difficult to compute that

    t1rm1(tmrm)2δdr=1mtm1(tm(r)m)2δdr=(tm1)12δm(12δ). (3.60)

    From the above two observations, we find that

    t1rb1(tmrm)δdr¯C4t2bm1(tm1)12δ, (3.61)

    where

    ¯C4=12bmm(12δ).

    This combined with (3.58) yields to the following bound

    I2¯C5λδjt2bm1(tm1)12δ¯C5λδjtbm2tm(12δ)=¯C5tmbδλδj, (3.62)

    where ¯C5=C(δ)mδ¯C4. Combining (3.54), (3.55) and (3.57) and noting that 1tmbδ we derive that

    t0rβ(r)1exp(λjtrzβ(z)1dz)dr¯C6tmbδλδj,¯C6=max(¯C1,¯C5). (3.63)

    Therefore, we obtain that for t1

    J2(.,t)2Zs(Ω)=jλ2sj[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]2=jλ2sj[10rβ(r)1exp(λj1rzβ(z)1dz)F(.,r),ψjdr]2+jλ2sj[t1rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]2=I+¯I(t). (3.64)

    It is obvious to see that the following inequality holds

    I=J2(.,1)2Zs(Ω)|¯C3|2F2L(0,T;Zsδ(Ω)), (3.65)

    where we hace applied (3.53). This together with (3.36) and (3.56) allow us to obtain that

    ¯I(t)¯C6tmbδjλ2sδj(t1rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψj2dr)¯C6C(δ)tmbδjλ2s2δj(t1rβ(r)1(trzβ(z)1dz)δF(.,r),ψj2dr)¯C6C(δ)tmbδ(t1rβ(r)1mδ(tmrm)δdr)F2L(0,T;Zsδ(Ω))¯C7tmbδ(t1rb1(tmrm)δdr)F2L(0,T;Zsδ(Ω)), (3.66)

    where ¯C7=¯C6C(δ)mδ. By looking at the estimate (3.61), we infer the following estimate

    ¯I(t)¯C7¯C4t2m2bδF2L(0,T;Zsδ(Ω)), (3.67)

    where ¯C8=¯C7¯C4. Combining (3.64), (3.65) and (3.67), we derive the following bound

    J2(.,t)2Zs(Ω)|¯C3|2F2L(0,T;Zsδ(Ω))+¯C8t2m2bδF2L(0,T;Zsδ(Ω)). (3.68)

    Since t1, we follows from (3.68) that

    J2(.,t)Zs(Ω)¯C9tmbδFL(0,T;Zsδ(Ω)). (3.69)

    Summarizing two cases 3 and 4, we provide the following statement

    J2(.,t)Zs(Ω)¯C10tmbδFL(0,T;Zsδ(Ω)),t>0. (3.70)

    Hence, the proof of (3.26) is finished by combining (3.35) and (3.43). At the same time, the proof of (3.27) is derived from (3.35) and (3.70).

    In this section, we focus the nonlocal value problem

    {β(t)tβ(t)y+Ay(x,t)=F(x,t),xΩ,t(0,T),y(x,t)=0,xΩ,t(0,T),y(x,0)+hy(x,T)=y0(x),xΩ. (4.1)

    Our main purpose in this section is to study the well-posedness of problem (4.1) and the convergence of the mild solution when h0+.

    Theorem 4.1.

    i) Let y0Zsε(Ω) for ε>0 and FL(0,T;Zs(Ω)). Then Problem (4.1) has a unique solution yh such that

    yh(.,t)Zs(Ω)tbεy0Zsε(Ω)+htbεFL(0,T;Zsε(Ω))+FL(0,T;Zs(Ω)). (4.2)

    where the hidden constant depends on T,b,ε,m.

    ii) Let y0Zsε(Ω) for ε>0 and FL(0,T;Zsδ(Ω)) for any 0<δ<12. Let us assume that 2m>b. Then we get

    yh(.,t)Zs(Ω)tbεy0Zsε(Ω)+htbεFL(0,T;Zsδ(Ω))+tmbδFL(0,T;Zsδ(Ω)), (4.3)

    where the hidden constant depends on T,b,ε,m,δ.

    Proof. Let us first establish the fomula of the mild solution to nonlocal problem (4.1). Suppose that Problem (4.1) has a solution yh. From (3.3), we get

    yh(.,t),ψj=exp(λjt0rβ(r)1dr)y0,ψj+t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr (4.4)

    By let t=T into the above expression, we see that

    yh(.,T),ψj=exp(λjT0rβ(r)1dr)y0,ψj+T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr. (4.5)

    From the above two equalities and the nonlocal-in-time condition

    yh(x,0)+hyh(x,T)=f(x),

    we deduce the following equality

    [1+hexp(λjT0rβ(r)1dr)]y0,ψj+hT0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr=f,ψj. (4.6)

    This implies that the following equality is satisfied

    y0,ψj=f,ψjhT0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr). (4.7)

    Combining (4.4) and (4.7), we derive that

    yh(.,t),ψj=exp(λjt0rβ(r)1dr)y0,ψj1+hexp(λjT0rβ(r)1dr)+t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdrhexp(λjt0rβ(r)1dr)T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr). (4.8)

    By the theory of Fourier series, the mild solution is given by

    yh(x,t)=j=1exp(λjt0rβ(r)1dr)y0,ψj1+hexp(λjT0rβ(r)1dr)ψj(x)hj=1exp(λjt0rβ(r)1dr)T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr)ψj(x)+j=1[t0rβ(r)1exp(λjtrzβ(z)1dz)F(.,r),ψjdr]ψj(x)=K1(x,t)+K2(x,t)+K3(x,t). (4.9)

    Let us consider the first term K1. By Parseval's equality, using (3.30), (3.35) and noting that 1+hexp(λjT0rβ(r)1dr)>1, we derive

    K12Zs(Ω)=jλ2sj(exp(λjt0rβ(r)1dr)1+hexp(λjT0rβ(r)1dr))2y0,ψj2jλ2sjexp(2λjt0rβ(r)1dr)y0,ψj2C21(Tbε+1)2t2bεjλ2s2εjy0,ψj2=C21(Tbε+1)2t2bεy02Zsε(Ω), (4.10)

    where we have used (3.31). Therefore, we obtain that the following estimate

    K1Zs(Ω)C1(Tbε+1)tbεy0Zsε(Ω). (4.11)

    Proof of i). Suppose FL(0,T;Zs(Ω)).

    We deal with the second term K2. We first obtain

    K22Zs(Ω)=h2jλ2sj(exp(λjt0rβ(r)1dr)T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr))2h2jλ2sjexp(2λjt0rβ(r)1dr)(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2h2C21t2bεjλ2s2εj(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2. (4.12)

    From (3.43), we can easily to verify that

    J2(.,T)2Zsε(Ω)=jλ2s2εj(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2(Tb+Tmm)2F2L(0,T;Zsε(Ω)). (4.13)

    Combining (4.12) and (4.13), we derive the following bound

    K2Zs(Ω)C1h(Tb+Tmm)tbεFL(0,T;Zsε(Ω)). (4.14)

    Let us now treat the third term K3. In view of (3.43), we infer that

    K3(.,t)Zs(Ω)=J2(.,t)Zs(Ω)tb+tmmFL(0,T;Zs(Ω)). (4.15)

    Combining (4.9), (4.11), (4.14) and (4.15) yields

    yh(.,t)Zs(Ω)3j=1Kj(.,t)Zs(Ω)C1(Tbε+1)tbεy0Zsε(Ω)+C1h(Tb+Tmm)tbεFL(0,T;Zsε(Ω))+tb+tmmFL(0,T;Zs(Ω)). (4.16)

    Proof of ii). Suppose that FL(0,T;Zsδ(Ω)).

    From (3.70), we obtain the following bound

    J2(.,T)Zs(Ω)¯C10TmbδFL(0,T;Zsδ(Ω)),t>0, (4.17)

    where we note that tmbδTmbδ. This estimate together with (4.12) yield

    K2Zs(Ω)C1¯C10TmbδhtbεFL(0,T;Zsδ(Ω)). (4.18)

    In view of (3.70), we infer that

    K3(.,t)Zs(Ω)=J2(.,t)Zs(Ω)¯C10tmbδFL(0,T;Zsδ(Ω)). (4.19)

    Combining (4.9), (4.11), (4.18) and (4.19), we deduce that

    yh(.,t)Zs(Ω)3j=1Kj(.,t)Zs(Ω)C1(Tbε+1)tbεy0Zsε(Ω)+C1¯C10TmbδhtbεFL(0,T;Zsδ(Ω))+¯C10tmbδFL(0,T;Zsδ(Ω)). (4.20)

    The proof is completed.

    The following theorem shows the convergence of the mild solution to (3.1)-(1.3) when h0.

    Theorem 4.2. i) Let y0Zsε(Ω) and FL(0,T;Zsε(Ω)) for any 0<ε<1b. Then, h(0,1) and k(1,2) we get

    yh(.,t)y(.,t)Lp(0,T;Zs(Ω))C(h2k2y0Zsε(Ω)+hFL(0,T;Zsε(Ω))), (4.21)

    where C depends on T,b,ε,p.

    ii) Let y0Zsε(Ω) for ε>0 and FL(0,T;Zs(Ω)) for any ε>0. Let us assume that 2m>b. Then we get

    yh(.,t)y(.,t)L(0,T;Zs(Ω))C(h2k2y0Zsε(Ω)+hFL(0,T;Zs(Ω))),0<h<1, (4.22)

    where the hidden constant depends on T,b,ε,m.

    Proof. First, we focus on the formulas of solutions (4.9) and (3.28). Taking the difference, we get

    yh(x,t)y(x,t)=j=1exp(λjt0rβ(r)1dr)y0,ψj1+hexp(λjT0rβ(r)1dr)ψj(x)jexp(λjt0rβ(r)1dr)y0,ψjψj(x)hj=1exp(λjt0rβ(r)1dr)T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr)ψj(x)=K0(x,t)+K2(x,t). (4.23)

    By a simple transformation, it is easy to verify that

    K0(x,t)=hj=1exp(λjt0rβ(r)1dr)exp(λjT0rβ(r)1dr)1+hexp(λjT0rβ(r)1dr)y0,ψjψj(x). (4.24)

    We need to consider the term

    K4(t)=hexp(λjt0rβ(r)1   dr)1+hexp(λjT0rβ(r)1   dr)=hexp(λjt0rβ(r)1   dr)(1+hexp(λjT0rβ(r)1   dr))t0rβ(r)1   drT0rβ(r)1   dr(1+hexp(λjT0rβ(r)1   dr))Ttrβ(r)1   drT0rβ(r)1   dr. (4.25)

    We consider the denominator component of the above fraction. In view of the inequality

    1+z>zk2,1<k<2,z>0,

    we get the following inequality

    (1+hexp(λjT0rβ(r)1dr))t0rβ(r)1drT0rβ(r)1dr>hkt0rβ(r)1dr2T0rβ(r)1drexp(λjk2t0rβ(r)1dr)

    and

    (1+hexp(λjT0rβ(r)1dr))Ttrβ(r)1drT0rβ(r)1dr>1.

    Since k<2, the latter three observations infer that

    K4(t)h1kt0r β(r)1   dr2T0r β(r)1   drexp(λjk22t0r β(r)1   dr)h1kt0r β(r)1   dr2T0r β(r)1   dr. (4.26)

    From this result and (4.26), we derive that

    K0(.,t)2Zs(Ω)=jλ2sj|K4(t)|2exp(2λjT0rβ(r)1dr)y0,ψj2h2kt0rβ(r)1drT0rβ(r)1drjλ2sjexp(2λjT0rβ(r)1dr)y0,ψj2. (4.27)

    Using (3.35), we obtain

    K0(.,t)Zs(Ω)h1kt0rβ(r)1dr2T0rβ(r)1drJ1(.,T)Zs(Ω)C1(Tbε+1)h1kt0rβ(r)1dr2T0rβ(r)1drTbεy0Zsε=C1(Tbε+1)h1kt0rβ(r)1dr2T0rβ(r)1dry0Zsε(Ω). (4.28)

    It is obvious to check that the following estimate holds

    1kt0rβ(r)1dr2T0rβ(r)1dr>2k2. (4.29)

    Since 0<h<1, we get

    h1kt0rβ(r)1dr2T0rβ(r)1drh2k2. (4.30)

    Combining (4.28) and (4.30), we deduce that

    K0(.,t)Zs(Ω)C1(Tbε+1)h2k2y0Zsε(Ω) (4.31)

    Next, we consider K2(.,t)Zs(Ω) in two cases corresponding to part i) and part ii). We use the results in the proof of Theorem (4.1).

    Case 1. Proof of (4.21).

    Since F is in the space L(0,T;Zsε(Ω)), we follows from (4.14) that

    K2Zs(Ω)C1h(Tb+Tmm)tbεFL(0,T;Zsε(Ω)). (4.32)

    Combining (4.23), (4.31) and (4.32), we find that

    yh(.,t)y(.,t)Zs(Ω)K0Zs(Ω)+K2Zs(Ω)C1(Tbε+1)h2k2y0Zsε(Ω)+C1h(Tb+Tmm)tbεFL(0,T;Zsε(Ω)). (4.33)

    Let us choose ε such that 0<ε<1b. Since 1<p<1bε, we know that the proper integral T0tbεpdt is convergent. By a simple computation, we deduce that

    yh(.,t)y(.,t)Lp(0,T;Zs(Ω))C(h2k2y0Zsε(Ω)+hFL(0,T;Zsε(Ω))), (4.34)

    where C depends on T,b,ε,p.

    Case 2. Proof of (4.22).

    From the definition of K2 as in (4.23), we derive that

    K22Zs(Ω)=h2jλ2sj(exp(λjt0rβ(r)1dr)T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr1+hexp(λjT0rβ(r)1dr))2h2jλ2sjexp(2λjt0rβ(r)1dr)(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2h2jλ2sj(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2. (4.35)

    We have the following observation

    jλ2sj(T0rβ(r)1exp(λjTrzβ(z)1dz)F(.,r),ψjdr)2=J2(.,T)2Zs(Ω)T2mm2F2L(0,T;Zs(Ω)). (4.36)

    Combining (4.23), (4.31) and (4.36), we find that

    yh(.,t)y(.,t)Zs(Ω)K0Zs(Ω)+K2Zs(Ω)C1(Tbε+1)h2k2y0Zsε(Ω)+hTmmFL(0,T;Zs(Ω)). (4.37)

    From the right-hand side of the above estimate, we deduce the desired result (4.22). The proof of our theorem is completed.

    This work considers a time-fractional parabolic equation with conformable variable derivative. We derive the well-posedness for mild solutions in Hilbert spaces for linear initial problem and linear nonlocal problem. We also shows the convergence of non-local solutions to local solutions. The techniques obtained in this study can be further extended to complicated nonlinear problem.

    The author Van Tien Nguyen thanks the support from FPT University.

    The authors declare no conflict of interest.



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