Research article Special Issues

Degree-based graphical indices of k-cyclic graphs

  • Let G be a graph with edge set E(G). Let dx denote the degree of a vertex x in G. For a nonnegative integer k, a connected graph of order n and size n+k1 is called a k-cyclic graph. This paper is concerned with k-cyclic graphs and their graphical indices of the form BIDf(G)=uvE(G)f(du,dv), where f is a symmetric function whose outputs are real numbers. Particularly, the graphs minimizing or maximizing BIDf among all k-cyclic graphs with a given order are studied under certain constraints on f. Various existing indices meet these constraints, and hence the obtained results hold for those indices; more precisely, one of the obtained results covers the recently developed elliptic Sombor and Zagreb-Sombor indices, while another result covers the recently introduced Euler-Sombor index.

    Citation: Akbar Ali, Darko Dimitrov, Tamás Réti, Abdulaziz Mutlaq Alotaibi, Abdulaziz M. Alanazi, Taher S. Hassan. Degree-based graphical indices of k-cyclic graphs[J]. AIMS Mathematics, 2025, 10(6): 13540-13554. doi: 10.3934/math.2025609

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  • Let G be a graph with edge set E(G). Let dx denote the degree of a vertex x in G. For a nonnegative integer k, a connected graph of order n and size n+k1 is called a k-cyclic graph. This paper is concerned with k-cyclic graphs and their graphical indices of the form BIDf(G)=uvE(G)f(du,dv), where f is a symmetric function whose outputs are real numbers. Particularly, the graphs minimizing or maximizing BIDf among all k-cyclic graphs with a given order are studied under certain constraints on f. Various existing indices meet these constraints, and hence the obtained results hold for those indices; more precisely, one of the obtained results covers the recently developed elliptic Sombor and Zagreb-Sombor indices, while another result covers the recently introduced Euler-Sombor index.



    This paper considers only connected and simple graphs. For the basic terminology regarding graph theory, we refer the reader to the books [7,8,13].

    Real-valued graph invariants are sometimes called graphical indices (or more frequently, topological indices) in chemical graph theory [35,38]. By utilizing some concepts from geometry, Gutman [16] put forward a novel perspective on vertex-degree-based graphical indices and introduced the Sombor index. For any graph G, its Sombor index is given as follows:

    SO(G)=uvE(G)d2u+d2v,

    where E(G) consists of edges of G and du is the degree of vertex uV(G). When two or more graphs are under consideration, we write du(G) to denote the degree of vertex uV(G) in G. We refer the reader to the articles [24,29] for some applications of the SO index and to review articles [15,26] for various properties associated with this index.

    Quite recently, Gutman, Furtula, and Oz [18] proposed a new geometric method for designing graphical indices and introduced the elliptic Sombor (ESO) index. The ESO index of G is defined as

    ESO(G)=uvE(G)(du+dv)d2u+d2v.

    Information on some of the known mathematical properties of the ESO index can be found in the recent papers [27,28,34].

    Another graphical index designed by the method outlined in [18] is the Euler-Sombor (EU) index [17,33], which is generated using Euler's formula for approximating the perimeter of an ellipse. The mathematical form of the EU index is

    EU(G)=uvE(G)d2u+d2v+dudv.

    Several existing mathematical aspects of the EU index can be found in [1,20,32].

    In the definition of the ESO index, if one replaces the sum "du+dv" of the degrees of the end vertices of the edge uv with the product "dudv" of the aforementioned degrees, then the so-called Zagreb-Sombor (ZSO) index [5,6] is obtained:

    ZSO(G)=uvE(G)dudvd2u+d2v.

    The SO, ESO, EU, and ZSO indices are special cases of the following general form [14,19,37] of certain graphical indices:

    BIDΨ(G)=uvE(G)Ψ(du,dv), (1.1)

    where Ψ is a symmetric function (defined on the degree set of G) whose outputs are real numbers. (The degree set of a graph is the set of all different degrees of its vertices.) Vukičević and Đurđević [36] coined the name "bond incident degree indices", say BID indices in short, for the indices of the form (1.1). Many existing results associated with BID indices were reported in the papers [9,39,40].

    A connected graph having order n and size n+μ1 is named as an n-order μ-cyclic graph, where μ is a nonnegative integer. A graph whose maximum degree does not exceed 4 is known as a molecular graph. In this paper, we study the problem of characterizing graphs minimizing or maximizing BIDΨ (defined via (1.1)) among all k-cyclic graphs, with a given order, under certain constraints on Ψ. The obtained results help in solving similar problems for many particular BID indices.

    Let G be a given graph. Let G be a graph obtained from G by applying a transformation such that V(G)=V(G). Throughout this section, whenever such two graphs are under consideration, dv denotes the degree of vertex vV(G) in G.

    The known result presented below is due to Hu et al. [21].

    Theorem 1. [21] Let G be an n-order non-trivial graph of size m1. If Ψ(x1,x2) is a real-valued convex symmetric function such that the partial derivative Ψ/x1 of Ψ with respect to x1 exists and is non-negative, then

    BIDΨ(G)mΨ(2mn,2mn). (2.1)

    The equality in (2.1) is attained if G is regular.

    Although Theorem 1 yields a nice lower bound on BIDΨ for n-order graphs of size m, we are not able to deduce from it graphs minimizing BIDΨ in the set of n-order μ-cyclic graphs, except for the case μ=1.

    Define mα,β=|{xyE(G):dx=α,dy=β}|. Now, we recall a result of Liu et al. [25], which is applicable in characterizing graphs minimizing many BID indices, including the EU index (see [1]), among n-order μ-cyclic graphs for n5(μ1) and μ3.

    Theorem 2. [25] Let Ψ(x1,x2), with x11 and x21, be a real-valued symmetric function satisfying the following:

    (ⅰ) Ψ is increasing in x1 (and hence in x2).

    (ⅱ) f defined as f(x)=Ψ(a,x)Ψ(b,x), with x1 and a>b0, is strictly decreasing.

    (ⅲ) If a>b+12, then

    a[Ψ(a,a)Ψ(a1,a)]b[Ψ(b+1,b)Ψ(b,b)]>0.

    Indicate by Gn,μ the collection of n-order μ-cyclic graphs having degree set {2,3} and satisfying m2,3=2, m2,2=n2μ+1,m3,3=3μ4. Among n-order μ-cyclic graphs, with μ3 and n5(μ1), only the member(s) of Gn,μ minimize(s) BIDΨ.

    If we take Ψ(x1,x2)=(x1+x2)x21+x22 or Ψ(x1,x2)=(x1x2)x21+x22, or Ψ(x1,x2)=(x1x2)3/2, with x21 and x11, then constraint number (ⅱ) of Theorem 2 does not hold for any of these choices of Ψ. Hence, Theorem 2 does not cover any of the three BID indices corresponding to the aforementioned choices of Ψ.

    The above-mentioned observations motivated us to establish the rest of the results of the present section.

    A nontrivial path P:x1x2...xt in a graph G is said to be pendent path if min{dx1(G),dxt(G)}=1, max{dx1(G),dxt(G)}3, and dxi(G)=2 whenever 2it1. Let R1 be the set of all real numbers greater than or equal to 1.

    Lemma 1. Let Ψ be a real-valued symmetric function defined on R1×R1 such that the following two conditions hold:

    (ⅰ) f defined as f(x)=Ψ(c1,x)Ψ(c2,x) with x1 is increasing, where c1 and c2 are integers satisfying c1>c22.

    (ⅱ) The following inequalities hold for every integer c3:

    cΨ(c,1)(c2)Ψ(c1,1)Ψ(c1,2)Ψ(2,1)>0, (2.2)
    (c2)[Ψ(c,1)Ψ(c1,1)]+Ψ(c,2)Ψ(c1,2)+Ψ(c,1)Ψ(2,2)>0. (2.3)

    If a graph G minimizes BIDΨ among n-order μ-cyclic graphs, then G does not contain any pendent path.

    Proof. Contrarily, assume that the conclusion of the lemma does not hold. Let zx1x2...xt be a pendent path of G, with dz3. Take yV(G){x1} in such a way that yzE(G). Let G denote the graph constructed from G by inserting edge xty and dropping the edge zy. The case t=1 yields a contradiction because, by condition (ⅰ) and inequality (2.2), we have

    BIDΨ(G)BIDΨ(G)=Ψ(dz,1)Ψ(dz1,2)+Ψ(dz,dy)Ψ(2,dy) +wN(z){x1,y}[Ψ(dz,dw)Ψ(dz1,dw)]Ψ(dz,1)Ψ(dz1,2)+Ψ(dz,1)Ψ(2,1) +(dz2)[Ψ(dz,1)Ψ(dz1,1)]>0.

    If t2, then by condition (ⅰ) and inequality (2.3), we have

    BIDΨ(G)BIDΨ(G)=Ψ(dz,2)Ψ(dz1,2)+Ψ(1,2)Ψ(2,2)+Ψ(dz,dy)Ψ(2,dy) +wN(z){x1,y}[Ψ(dz,dw)Ψ(dz1,dw)]Ψ(dz,2)Ψ(dz1,2)+Ψ(1,2)Ψ(2,2)+Ψ(dz,1)Ψ(2,1) +(dz2)[Ψ(dz,1)Ψ(dz1,1)]>0,

    a contradiction again.

    The proof of the subsequent result is very similar to that of Lemma 1, and so we omit it.

    Lemma 2. Let Ψ be a real-valued symmetric function defined on R1×R1 such that the following two conditions hold:

    (ⅰ) f defined as f(x)=Ψ(c1,x)Ψ(c2,x) with x1 is decreasing, where c1 and c2 are integers satisfying c1>c22.

    (ⅱ) The following inequalities hold for every integer c3:

    cΨ(c,1)(c2)Ψ(c1,1)Ψ(c1,2)Ψ(2,1)<0,
    (c2)[Ψ(c,1)Ψ(c1,1)]+Ψ(c,2)Ψ(c1,2)+Ψ(c,1)Ψ(2,2)<0.

    If a graph G maximizes BIDΨ among n-order μ-cyclic graphs, then G does not contain any pendent path.

    Lemma 1 provides the following.

    Corollary 1. If Ψ is the function defined in Lemma 1 such that Ψ meets the constraints listed therein, then the path/cycle graph uniquely minimizes BIDΨ among n-order trees/unicyclic graphs, respectively, for every n4.

    Corollary 1 covers the EU index; the corresponding results regarding the EU index have recently been derived in [1,22,32].

    Lemma 2 provides the following.

    Corollary 2. If Ψ is the function defined in Lemma 2 such that Ψ meets the constraints listed therein, then the path/cycle graph uniquely maximizes BIDΨ among n-order trees/unicyclic graphs, respectively, for every n4.

    For a graph G and its vertex v, define nr=|{xV(G):dx=r}| and N(v)={wV(G):wvE(G)}. The members of N(v) are called neighbors of v. Corollaries 1 and 2 provide extremal results concerning BIDΨ under certain constraints on Ψ for fixed-order μ-cyclic graphs when μ{0,1}. Next, we establish similar results for μ2.

    Lemma 3. Let Ψ be the function defined in Lemma 1 such that Ψ meets the constraints listed therein. Additionally, let

    (c2)[Ψ(c,2)Ψ(c1,2)]+3Ψ(c,2)Ψ(c,3)Ψ(c1,3)Ψ(3,2)>0 (2.4)

    and

    (c1)[Ψ(c,3)Ψ(c1,3)]+2Ψ(c,2)Ψ(c,3)Ψ(3,3)>0 (2.5)

    for every integer c4. If a graph G minimizes BIDΨ among n-order μ-cyclic graphs, with μ2, n5, and n2(μ1), then the maximum degree of G is 3.

    Proof. By Lemma 1, G contains no pendent vertex. Let Δ denote G's maximum degree. The inequality μ2 forces that Δ3. Contrarily, we assume that Δ4. Let m=|E(G)|. Then, μ1=mn, and thus

    2iΔni2(mn)=2(3iΔini23iΔni),

    which implies that

    n24iΔ(i3)ni. (2.6)

    Inequality (2.6) ensures that n21. Let uV(G) be a vertex of degree Δ.

    Case 1. u possesses a neighbor, say w, with degree 2.

    Certainly, the vertex w is not a neighbor of at least one neighbor, say v, of u. Let G denote the graph constructed from G by inserting the edge vw and dropping the edge vu. Let t(u) denote the other neighbor of w. By condition (i) of Lemma 1 and inequality (2.4), we have

    BIDΨ(G)BIDΨ(G)=[Ψ(du,dv)Ψ(3,dv)]+[Ψ(dt,2)Ψ(dt,3)]+Ψ(du,2)Ψ(du1,3) +zN(u){v,w}[Ψ(du,dz)Ψ(du1,dz)][Ψ(du,2)Ψ(3,2)]+[Ψ(du,2)Ψ(du,3)]+Ψ(du,2)Ψ(du1,3) +(du2)[Ψ(du,2)Ψ(du1,2)]>0,

    a contradiction.

    Case 2. No neighbor of u has degree 2.

    In this case, every neighbor of u has degree greater than 2. Note that there exists at least one vertex wV(G)N(u) having degree 2 that is not a neighbor of at least two neighbors of u. Among these neighbors of u, we pick v provided that the graph G" is connected, where G" is the graph constructed from G by inserting the edge vw and dropping the edge vu. By condition (ⅰ) of Lemma 1 and inequality (2.5), we have

    BIDΨ(G)BIDΨ(G)=xN(u){v}[Ψ(du,dx)Ψ(du1,dx)]+yN(w)[Ψ(2,dy)Ψ(3,dy)] +[Ψ(du,dv)Ψ(3,dv)](du1)[Ψ(du,3)Ψ(du1,3)]+2[Ψ(2,du)Ψ(3,du)] +[Ψ(du,3)Ψ(3,3)]>0,

    a contradiction again.

    Since the following lemma can be proved in a fully analogous way to that of Lemma 3, we omit its proof.

    Lemma 4. Let Ψ be the function defined in Lemma 2 such that Ψ meets the constraints listed therein. Additionally, let

    (c2)[Ψ(c,2)Ψ(c1,2)]+3Ψ(c,2)Ψ(c,3)Ψ(c1,3)Ψ(3,2)<0 (2.7)

    and

    (c1)[Ψ(c,3)Ψ(c1,3)]+2Ψ(c,2)Ψ(c,3)Ψ(3,3)<0 (2.8)

    for every integer c4. If a graph G maximizes BIDΨ among n-order μ-cyclic graphs, with μ2, n5, and n2(μ1), then the maximum degree of G is 3.

    Theorem 3. Let Ψ be the function defined in Lemma 1 such that Ψ satisfies the constraints listed therein, and that inequalities (2.4) and (2.5) hold. If a graph G minimzes BIDΨ among n-order μ-cyclic graphs, with μ2, n5 and n2(μ1), then the degree sequence of G is

    (3,,32(μ1),2,,2n2(μ1)).

    Proof. By Lemmas 1 and 3, the degree set of G is either {2,3} or {3}. Now, the equations n2+n3=n and 2n2+3n3=2(n+μ1) yield n2=n2(μ1) and n3=2(μ1).

    Remark 1. Since each of the functions associated with the elliptic Sombor index and Zagreb-Sombor index satisfies both the constraints listed in Lemma 1 as well as inequalities (2.4) and (2.5), Theorem 3 holds for both of these indices. Also, we have verified that each of the functions associated with the first ten indices given in Table 5.1 of [10] satisfies both the constraints listed in Lemma 1 as well as inequalities (2.4) and (2.5). Hence, Theorem 3 also covers these ten indices. (We provide a few comments concerning the main results derived in [10] at the end of the present section.)

    Using Lemmas 2 and 4, we establish the next result.

    Theorem 4. Let Ψ be the function defined in Lemma 2 such that Ψ satisfies the constraints listed therein, and that inequalities (2.7) and (2.8) hold. If a graph G maximzes BIDΨ among n-order μ-cyclic graphs, with μ2, n5, and n2(μ1), then the degree sequence of G is

    (3,,32(μ1),2,,2n2(μ1)).

    If n=2(μ1), then one obtains the exact structure of the extremal graphs given Theorems 3 and 4. Particularly, such graphs are 3-regular when n=2(μ1). In what follows, we study the structure of the mentioned extremal graphs for the case n>2(μ1).

    Lemma 5. Let G be an n-order μ-cyclic graph having degree set {2,3}, where μ2, n5, and n>2(μ1).

    (a) If 2(μ1)<n<5(μ1), then m3,30.

    (b) If n>5(μ1), then m2,20.

    (c) If n=5(μ1), then m3,3=m2,2.

    Proof. (a) Note that n2=n2(μ1) and n3=2(μ1), which yield 2n2<3n3 because n<5(μ1). If m3,3=0, then we obtain 3n32m2,2+3n3=2n2, a contradiction. For the proofs of parts (b) and (c), see the proof of Lemma 15 in [4].

    Lemma 6. Let Ψ be the function defined in Lemma 1 such that Ψ satisfies the constraints listed therein, and that inequalities (2.4) and (2.5) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)>0. If a graph G minimizes BIDΨ among n-order μ-cyclic graphs, with μ2 and n>5(μ1), then either dx=2 or dy=2 for every xyE(G).

    Proof. By Lemmas 1, 3, and 5, G possesses degree set {2,3}, and it holds that m2,20. Consider uvE(G) provided that 2=dv=du. Contrarily, assume that there exists wtE(G) such that dw=dt=3. Take N(v)={u,x}. One may have that x{w,t}; however, in this scenario, we assume that x=t, without loss of generality.

    Case 1. u and v do not lie on a triangle.

    In this case, we have uxE(G). If G denotes the graph constructed from G by dropping the edges vu,vx,wt and inserting the edges ux,wv,tv, then

    BIDΨ(G)BIDΨ(G)=Ψ(3,3)+Ψ(2,2)2Ψ(2,3)>0,

    which contradicts the definition of G.

    Case 2. u and v lie on a triangle.

    In this case, we have uxE(G) and dx=3. If the vertices x and t are distinct, then the graph G" constructed from G by dropping the edges tw,vx and inserting the edges xw,tv, satisfies BIDΨ(G")=BIDΨ(G). Since u and v do not lie on a triangle in G", by Case 1, we arrive at a contradiction. If the vertices x and t are the same, then the graph G" constructed from G by dropping the edges ww1,vt and inserting the edges tw1,wv, satisfies BIDΨ(G")=BIDΨ(G), where w1t is a neighbor of w. Since u and v do not lie on a triangle in G", by Case 1, we arrive at a contradiction.

    Since the subsequent lemma may be proved in a completely analogous way to that of Lemma 6, we omit its proof.

    Lemma 7. Let Ψ be the function defined in Lemma 2 such that Ψ satisfies the constraints listed therein, and that inequalities (2.7) and (2.8) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)<0. If a graph G maximizes BIDΨ among n-order μ-cyclic graphs, with μ2 and n>5(μ1), then either dx=2 or dy=2 for every xyE(G).

    Lemma 8. Let Ψ be the function defined in Lemma 1 such that Ψ satisfies the constraints listed therein, and that inequalities (2.4) and (2.5) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)>0. If a graph G minimizes BIDΨ among n-order μ-cyclic graphs, with μ2 and n=5(μ1), then {2,3}={dx,dy} for every xyE(G).

    Proof. By Lemmas 1, 3, and 5, the degree set of G is {2,3}, and it holds that m3,3=m2,2. If m2,20m3,3, then by the proof of Lemma 6, we find a graph G that is μ-cyclic n-order such that BIDΨ(G)>BIDΨ(G), which yields a contradiction.

    Since the subsequent lemma may be proved in a completely analogous way to that of Lemma 8, we omit its proof.

    Lemma 9. Let Ψ be the function defined in Lemma 2 such that Ψ satisfies the constraints listed therein, and that inequalities (2.7) and (2.8) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)<0. If a graph G maximizes BIDΨ among n-order μ-cyclic graphs, with μ2 and n=5(μ1), then {2,3}={dx,dy} for every xyE(G).

    Lemma 10. Let Ψ be the function defined in Lemma 1 such that Ψ satisfies the constraints listed therein, and that inequalities (2.4) and (2.5) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)>0. If a graph G minimizes BIDΨ among n-order μ-cyclic graphs, with μ3 and 2(μ1)<n<5(μ1), then m2,2=0.

    Proof. By Lemmas 1, 3, and 5, the degree set of G is {2,3}, and it holds that m3,30. If m2,20, then, by the proof of Lemma 6, we find an n-order μ-cyclic graph G such that BIDΨ(G)>BIDΨ(G), which yields a contradiction.

    Since the proof of the subsequent lemma is completely analogous to that of Lemma 10, we omit it.

    Lemma 11. Let Ψ be the function defined in Lemma 2 such that Ψ satisfies the constraints listed therein, and that inequalities (2.7) and (2.8) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)<0. If a graph G maximizes BIDΨ among n-order μ-cyclic graphs, with μ3 and 2(μ1)<n<5(μ1), then m2,2=0.

    Theorem 5. Let Ψ be the function defined in Lemma 1 such that Ψ satisfies the constraints listed therein, and that inequalities (2.4) and (2.5) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)>0. Then, among n-order μ-cyclic graphs,

    (a) only the graphs with degree set {2,3} such that m2,2=0 minimize BIDΨ for 2(μ1)<n<5(μ1) and μ3;

    (b) only the graphs with degree set {2,3} such that m2,2=0=m3,3 minimize BIDΨ for n=5(μ1) and μ2;

    (c) only the graphs with degree set {2,3} such that m3,3=0 minimize BIDΨ for n>5(μ1) and μ2.

    Proof. Assume that G is a graph minimizing BIDΨ among μ-cyclic n-order graphs, with n>2(μ1), μ2, and n5. Thanks to Lemmas 1 and 3, the degree set of G is {2,3}.

    (a) This part follows from Lemma 10.

    (b) This part follows from Lemma 8.

    (c) This part follows from Lemma 6.

    Since the subsequent theorem may be proved in a completely analogous way to that of Theorem 5, we omit its proof.

    Theorem 6. Let Ψ be the function defined in Lemma 2 such that Ψ satisfies the constraints listed therein, and that inequalities (2.7) and (2.8) hold. Additionally, assume that Ψ(3,3)+Ψ(2,2)2Ψ(2,3)<0. Then, among n-order μ-cyclic graphs,

    (a) only the graphs with degree set {2,3} such that m2,2=0 maximize BIDΨ for 2(μ1)<n<5(μ1) and μ3;

    (b) only the graphs with degree set {2,3} such that m2,2=0=m3,3 maximize BIDΨ for n=5(μ1) and μ2;

    (c) only the graphs with degree set {2,3} such that m3,3=0 maximize BIDΨ for n>5(μ1) and μ2.

    Remark 2. Recall that a graph in which every vertex has a degree smaller than 5 is called a molecular graph. If we replace the text "μ-cyclic graphs" with "μ-cyclic molecular graphs" in the statements of Theorems 5 and 6, then the modified results are also valid.

    Remark 3. If an n-order μ-cyclic graph has size m, then μ=mn+1, and thus Theorems 5 and 6 can be stated in terms of order and size of graphs.

    Remark 4. Since each of the functions associated with the elliptic Sombor index and Zagreb-Sombor index meets all the constraints mentioned in Theorem 5, this result holds for both of these indices.

    Remark 5. In the definition of the ESO index, by replacing the degrees du and dv of the end vertices of the edge uv with du1 and dv1, respectively, we obtain

    RES(G)=uvE(G)(du+dv2)(du1)2+(dv1)2.

    Using the existing terminology of reduced graphical indices, we refer to the index RES as the reduced elliptic Sombor (RES) index. We note that the function Ψ(x1,x2)=(x1+x22)(x11)2+(x21)2 satisfies all the constraints of Theorem 5, and hence this theorem covers the RES index.

    Here, we point out that the recent paper [10] contains several general results similar to Theorems 3–6. In order to demonstrate the difference between the main results of this section and the main results established in [10], we consider the following index, which is not covered by any of the aforementioned results of [10]:

    R3/2(G)=uvE(G)(dudv)3/2.

    Since the function Ψ(x1,x2)=(x1x2)3/2 satisfies all the constraints of Theorems 3 and 5, the conclusions of these theorems hold for the index R3/2. On the other hand, it is interesting to note that none of the theorems of the present section covers any of the last five indices of Table 5.1 of [10].

    In the same way as we defined the RES index in Remark 5, we now define the reduced Zagreb-Sombor (RZS) index:

    RZS(G)=uvE(G)(du1)(dv1)(du1)2+(dv1)2.

    It seems that none of the main results of [10,25] and the present section covers the RZS index. Actually, there are many well-known graphical indices (for instance, the reduced second Zagreb index [11] and the irregularity [12]) that are not covered by any of the main results of the aforementioned papers and section. Hence, it would be interesting to extend the results of [10,25] and the present section in such a way that the extended result(s) cover(s) such indices.

    In an n-order graph, a vertex of degree n1 is called a universal vertex. The following two lemmas are obtained by utilizing Lemma 2.1 of [3].

    Lemma 12. Let Ψ be a real-valued symmetric function defined on R1×R1 such that its partial derivative function Ψxi with respect to xi exists for i=1,2, Ψ as well as Ψxi are increasing in xi for i=1,2, and the inequality Ψ(x1+k,x2k)Ψ(x1,x2)0 holds for x1x2k+12. Also, assume that at least one of the following constraints holds:

    (ⅰ) Ψ(x1,x2) is strictly increasing in xi for i=1,2.

    (ⅱ) Ψxi is strictly increasing in xi for i=1,2.

    (ⅲ) Ψ(x1+k,x2k)Ψ(x1,x2)>0 for x1x2k+12.

    If a graph G maximizes BIDΨ among μ-cyclic n-order graphs, then G has at least one universal vertex.

    Lemma 13. Let Ψ be a real-valued symmetric function defined on R1×R1 such that its partial derivative function Ψxi with respect to xi exists for i=1,2, and Ψ as well as Ψxi are decreasing in xi for i=1,2, and the inequality Ψ(x1+k,x2k)Ψ(x1,x2)0 holds for x1x2k+12. Also, assume that at least one of the following constraints holds:

    (ⅰ) Ψ(x1,x2) is strictly decreasing in xi for i=1,2.

    (ⅱ) Ψxi is strictly decreasing in xi for i=1,2.

    (ⅲ) Ψ(x1+k,x2k)Ψ(x1,x2)<0 for x1x2k+12.

    If a graph G minimizes BIDΨ among μ-cyclic n-order graphs, then G has at least one universal vertex.

    Lemmas 12 and 13 provide the next result.

    Corollary 3. Let Ψ be the function defined in Lemma 12 (Lemma 13, respectively) such that it meets all the constraints given therein. Then, the star Sn uniquely maximizes (minimizes, respectively) BIDΨ among n-order trees for every n4. Also, the unicyclic graph generated by putting a single edge in Sn uniquely maximizes (minimizes, respectively) BIDΨ among n-order unicyclic graphs for n4.

    For a vertex w in a graph G, we take N(w){w}=N[w].

    Lemma 14. Let Ψ be the function defined in Lemma 12 such that it meets all the constraints given therein. Let G be a graph maximizing BIDΨ over the class of n-order μ-cyclic graphs, where 2μn2. If the vertices u,v are non-pendent in G such that dudv, then every neighbor of u distinct from v is a neighbor of v.

    Proof. (Note that N(u)N[v] for every two vertices u and v in any G.) Because of the constraints of Lemma 12, the proof of the present result is almost the same as that of Lemma 2.3 reported in [30]; the second summation in Equation (3) of the mentioned proof should be taken over N(v)N[u] instead of N(v)N(u).

    The subsequent lemma's proof is completely analogous to that of the previous result, and so we omit it.

    Lemma 15. Let Ψ be the function defined in Lemma 13 such that it meets all the constraints given therein. Let G be a graph minimizing BIDΨ over the class of n-order μ-cyclic graphs, where 2μn2. If the vertices u,v are non-pendent in G such that dudv, then every neighbor of u distinct from v is a neighbor of v.

    Lemma 16. Let Ψ be the function defined in Lemma 12 such that it meets all the constraints given therein. Let G satisfy the constraints mentioned in the 2nd sentence of Lemma 14. If V(G)={x1,x2,,xn} and dxndx2dx1, then every non-pendent vertex (different from x2) of G is a neighbor of x2.

    Proof. By Lemma 12, dx1=n1. Suppose, contrarily, that xk is a non-pendent vertex that is not a neighbor of x2 for some k{3,4,,n}. Then, dx2n2. Since every pendent vertex (if it exists) is a neighbor of x1, the vertex xk has a non-pendent neighbor xr for some r{3,4,,n}{k}. Since dx2dxr, by Lemma 14, the vertex xk is a neighbor of x2, which is a contradiction.

    The subsequent lemma's proof is completely analogous to that of the previous result (that is, Lemma 16), and so we omit it.

    Lemma 17. Let Ψ be the function defined in Lemma 13 such that it meets all the constraints given therein. Let G satisfy constraints mentioned in the 2nd sentence of Lemma 15. If V(G)={x1,x2,,xn} and dxndx2dx1, then every non-pendent vertex (different from x2) of G is a neighbor of x2.

    For μ1, let Hn,μ be the n-order graph formed by putting μ edge(s) to the star graph Sn between a certain vertex with degree one and μ other vertex/vertices with degree one. For μ3, let Hn,μ indicate the graph generated by putting a single edge to Hn,μ1 betwixt two vertices of degree 2.

    Theorem 7. Let Ψ be the function defined in Lemma 12 such that it meets all the constraints given therein. In the graph class mentioned in Lemma 14, let G be a graph maximizing BIDΨ such that nμ+2 and μ{2,3,4,5}.

    (i) If μ=2, then G=Hn,μ.

    (ii) If μ{3,4}, then either G=Hn,μ or G=Hn,μ.

    (iii) If μ=5, then G{Hn,5,Hn,5,Hn,5"}, where Hn,5" is the graph generated from Hn,4 by putting a single edge betwixt a vertex with degree 3 and another vertex with degree 2.

    Proof. Let the vertices of G be u1,u2,,un such that du1du2dun. By Lemma 12, du1=n1. For every μ{2,3,4}, all n-order μ-cyclic graphs of maximum degree n1 can be found in [3]. Also, all n-order 5-cyclic graphs of maximum degree n1 can be found in [2]. By Lemma 16, every non-pendent vertex (different from u2) of G is a neighbor of u2; applying this fact on all aforementioned graphs of maximum degree n1 yields the required conclusions for every μ{2,3,4,5}.

    In the same way as we defined the RES index in Remark 5, we now define the reduced Euler-Sombor (REU) index:

    REU(G)=uvE(G)(du1)2+(dv1)2+(du1)(dv1).

    We note that each of the functions associated with the SO index, reduced Sombor (RSO) index, EU index, and REU index satisfies all the constraints of Lemma 12, and hence the conclusions of Corollary 3 (corresponding to Lemma 12) and Theorem 7 hold for these indices, where the RSO index is defined [16] as

    RSO(G)=uvE(G)(du1)2+(dv1)2.

    If BIDΨ is any of the SO, EU, RSO, and REU indices, then we obtain BIDΨ(Hn,μ)>BIDΨ(Hn,μ) for nμ+2 and μ{3,4,5}, and also BIDΨ(Hn,5)>BIDΨ(Hn,5") for n7. Therefore, by Corollary 3 and Theorem 7, we have the following result.

    Corollary 4. If BIDΨ is any of the SO, EU, RSO and REU indices, then Hn,μ uniquely maximizes BIDΨ among n-order μ-cyclic graphs for μ{0,1,2,3,4,5}, nμ+2, and n4, where Hn,0 is the n-order star graph.

    Corollary 4 covers some results regarding the EU index reported in [23,31].

    The subsequent theorem's proof is completely analogous to that of the previous result (that is, Theorem 7), and so we omit it.

    Theorem 8. Let Ψ be the function defined in Lemma 13 such that it meets all the constraints given therein. In the graph class mentioned in Lemma 15, let G be a graph minimizing BIDΨ, such that nμ+2 and μ{2,3,4,5}.

    (i) If μ=2, then G=Hn,μ.

    (ii) If μ{3,4}, then either G=Hn,μ or G=Hn,μ.

    (iii) If μ=5, then G{Hn,5,Hn,5,Hn,5"}.

    Investigation: Abdulaziz M. Alanazi, Abdulaziz Mutlaq Alotaibi, Taher S. Hassan; Methodology: Akbar Ali, Darko Dimitrov, Tamás Réti; Writing – original draft: Akbar Ali, Darko Dimitrov, Tamás Réti; Validation: Abdulaziz M. Alanazi, Abdulaziz Mutlaq Alotaibi, Taher S. Hassan; Writing – review & editing: Akbar Ali, Darko Dimitrov, Tamás Réti. All authors have read and approved the final version of the manuscript for publication.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This study is supported via funding from Prince Sattam bin Abdulaziz University, Saudi Arabia (project number PSAU/2025/R/1446).

    The authors have no conflicts of interest to declare.



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