Research article Special Issues

Non-destructive test method of wood moisture content based on multiple varying bounds integral numerical method

  • For the wood moisture content (MC) detection engineering problem by planar capacitive sensors, a high accuracy is required. To meet this demand, we constructed a mathematical model in this paper, as this is an inverse problem in the multi-physics fields. Furthermore, we proposed a new numerical method with high accuracy, which is called the multiple varying bounds integral method. We applied this numerical method to establish a high accuracy and compact numerical scheme for solving this model. Because the unknown function is continuous in some physical fields and discontinuous in others, we needed to use different numerical methods to construct numerical schemes in these fields. For example, we used the multiple varying bounds integral (MVBI) method and interpolation methods. Next, based on the results of the numerical experiments, a regression model was established between capacitance and the dielectric constant of wood. The results indicated that the larger the value of dielectric constant, the larger the value of capacitance. This is consistent with the physical principle. Moreover, the determination coefficient R2 of the regression model was greater than 0.91. Additionally, the confidence degree exceeded 0.99, which implies that the reliability of the regression model is strong. This indicates that the regression model shows a high goodness of fit and high confidence degree.

    Citation: Cui Guo, Yixue Wang, Haibin Wang, Xiongbo Zheng, Bin Zhao. Non-destructive test method of wood moisture content based on multiple varying bounds integral numerical method[J]. Electronic Research Archive, 2025, 33(4): 2246-2274. doi: 10.3934/era.2025098

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  • For the wood moisture content (MC) detection engineering problem by planar capacitive sensors, a high accuracy is required. To meet this demand, we constructed a mathematical model in this paper, as this is an inverse problem in the multi-physics fields. Furthermore, we proposed a new numerical method with high accuracy, which is called the multiple varying bounds integral method. We applied this numerical method to establish a high accuracy and compact numerical scheme for solving this model. Because the unknown function is continuous in some physical fields and discontinuous in others, we needed to use different numerical methods to construct numerical schemes in these fields. For example, we used the multiple varying bounds integral (MVBI) method and interpolation methods. Next, based on the results of the numerical experiments, a regression model was established between capacitance and the dielectric constant of wood. The results indicated that the larger the value of dielectric constant, the larger the value of capacitance. This is consistent with the physical principle. Moreover, the determination coefficient R2 of the regression model was greater than 0.91. Additionally, the confidence degree exceeded 0.99, which implies that the reliability of the regression model is strong. This indicates that the regression model shows a high goodness of fit and high confidence degree.



    Some notations and basic assumptions are given in this paper:

    1) B1 and B2 denote two thin electrode plates of the capacitive sensor.

    2) B denotes the measured wood, and B, B1, B2 do not intersect each other.

    3) ε=ε(x,y,z) denotes the dielectric constant of the wood at the point (x,y,z).

    4) ˜ε denotes the dielectric constant of air.

    5) V=V(x,y,z) denotes the potential at the point (x,y,z).

    6) V1 and V2 denote the potentials of B1 and B2, respectively.

    7) E=E(x,y,z) denotes the electric field strength at the point (x,y,z).

    8) C denotes the capacitance of the capacitive sensor.

    9) q1 and q2 denote the charge carried by B1 and B2, respectively, with q1=q2. Additionally, q1 also satisfies

    C=q1V1V2.

    10) Bin and Bout denote the interior and exterior of the wood boundary, respectively.

    Wood moisture content (MC) detection is one essential problem in the modern world. All wood products contain some level of moisture, and too high or too low MC can cause quality issues in wood products. Thus, inaccurate MC detection severely impacts quality control in the wood processing industry. It also impacts the maintenance of wooden historical buildings and the protection of rare tree species [1,2,3,4,5,6,7]. Once wood products or wooden structures are completed, their shape and material no longer change. The key factors determining their internal quality are primarily the MC and drying stress. When the equilibrium moisture content is reached, cracking and deformation are least likely to occur. In recent years, inaccurate MC detection has resulted in a wood utilization rate of only 50%–60%. In contrast, technologically advanced countries have achieved rates as high as 90%. This has led to frequent significant economic losses in the national economy.

    Due to the significant social and economic benefits of MC detection, scholars from various countries have conducted extensive and in-depth research on this topic. With continuous research, methods for MC detection [8] have also been continuously developed and improved. Martin et al.[9] used the resistance method to study the relationship between MC and average resistivity of silver fir. Van Blokland and Adamopoulos [10] analyzed the electrical resistance characteristics of Norway spruce. Through simple linear regression, they derived a first-order polynomial function relationship between MC and resistance of the wood. However, the resistance method can obtain only ideal measurement results when the MC is between 6% and 25%. The measurement error is severely limited by the value of MC. Edwards and Jarvis [11], Batranin et al. [12], and Penttila et al. [13] used the ray technique to detect changes in MC, which are not limited by specific MC values. However, the ray technique has high detection costs, slow speeds, and safety hazards, posing challenges for inspectors. Qin et al. [14] studied the relationship between MC and ε but noted that different tree species require different dielectric models. Compared to these methods, we aim to find a more widely applicable method that can meet more measurement requirements. Capacitive sensors [15] are electronic components that can convert the measured physical quantities and their variation laws into capacitance and capacitance change laws. They have the outstanding advantage of performing non-contact, continuous, and high-precision measurements. Therefore, we consider measuring the capacitance between the electrode plates to calculate MC [16,17,18,19]. On the other hand, we found that most researchers use only experimental methods to MC detection. We propose combining experiments with mathematical methods to build a mathematical model and complete the MC detection.

    For the mathematical model, it is also very important to choose the appropriate numerical method, which will have a great influence on numerical accuracy and speed. To some extent, the finite volume method [20,21,22] has absorbed some advantages of the finite element method and the finite difference method. The finite volume method is mainly applied to solve fluid flow and heat transfer problems. With this method, the numerical scheme obtained can keep some properties of original differential equations, such as the conservation of mass, momentum, and energy.

    The multiple varying bounds integral method [23,24,25,26,27] is a new numerical method developed based on the finite volume method. First, by means of multiple integrals, all the derivatives in the space direction of the differential equation can be eliminated. In this way, the differential equation can be equitably represented by another new equation that contains only the unknown function than its derivatives. On this basis, we begin to construct the corresponding numerical scheme for this new equation. This avoids the occurrence of large errors greatly, especially where the change rate of the derivative is large. Furthermore, multiple integrals with varying bounds are important. Different Integral bounds can help us get different numerical schemes. Depending on the physical properties of differential equation, we can choose an appropriate scheme from them.

    The layout of the paper is as follows. In Section 2, we provide the methodology for MC detection. In Section 3, we discuss the steps for MC detection. In Section 4, by multiple varying bounds integral method, we construct second-order compact discrete schemes in fields where the potential is continuous and discontinuous, respectively, and conduct error estimation and numerical experiments. In Section 5, a conclusion is provided.

    A core issue for wood moisture content detection is to construct the function relationship between the capacitance C and the dielectric constant ε. The methodology is shown in Figure 1. This is a multi-physics inverse problem with partial differential equations. We choose many suitable values of ε. On this basis, through the mathematics model we constructed, we obtain the values of C. The data C and ε are regressed to fit a function ε=ε(C). Then, by capacitive sensor, we measure the value of C, and substitute it into the aforementioned fitted function to calculate ε. Ultimately, by the one-to-one correspondence between ε and MC, we obtain the value of MC.

    Figure 1.  Methodology for wood moisture content detection.

    We focus on constructing the function relationship between ε and C. The steps are as follows:

    1) The measured wood B and the electrode plates B1 and B2 are shown in Figure 2.

    Figure 2.  The placement of B,B1, and B2.

    During practical wood detection, MC is always indirectly measured. This is accomplished by finding a physical quantity correlated with MC, measuring this quantity, and establishing its relationship with MC to determine MC. In this paper, we use the dielectric constant as the physical quantity related to MC.

    As shown in Figure 2, two metal plates of identical material and specifications are used as the electrode plates of the capacitive sensor and are fixed at specific positions, labeled B1 and B2. According to physical law, the capacitive sensor's internal dielectric material affects the amount of charge it can store. Therefore, the capacitance between the two plates is influenced by the surrounding environment. If the surrounding environment remains unchanged, and the measured wood is placed on top of the plates, an electromagnetic field is generated around it. If the dimension of measured wood is known, the value of C will be uniquely determined by ε, establishing a one-to-one correspondence between C and ε. Thus, by measuring C, we can obtain ε. Additionally, we have found that there is a one-to-one relationship between ε and MC. Therefore, by ε as an intermediary, we first establish the relationship between C and ε, and then leverage the corresponding relationship between ε and MC to determine MC.

    2) According to the mathematical model in [28], satisfied by the potential V(x,y,z),

    {2V(x,y,z)=0,(x,y,z)(R3B1B2¯B),˜εB1|gradV(x,y,z)|dS=˜εB2|gradV(x,y,z)|dS,εV(x,y,z)n|Bin=˜εV(x,y,z)n|Bout,V(x,y,z)|Bin=V(x,y,z)|Bout,limx2+y2+z2V(x,y,z)=0. (3.1)

    If V1 and ε are given, then V=V(x,y,z) and V2 are uniquely determined.

    3) If V(x,y,z) is determined, the electric field strength E(x,y,z) can be determined by

    E(x,y,z)=gradV(x,y,z).

    It can be seen that E(x,y,z) is related to ε(x,y,z).

    4) By integral,

    q1=˜εB1|gradV1(x,y,z)|dS=B1˜εE1(x,y,z)dS,

    and

    q2=˜εB2|gradV2(x,y,z)|dS=B2˜εE2(x,y,z)dS,

    the charge q1 (or q2) of B1 (or B2) is obtained [29]. Obviously, q1 (or q2) is also related to ε(x,y,z).

    5) By the equation

    C=q1V1V2,

    the capacitance C can be obtained, and it can be seen that C is also related to ε(x,y,z).

    Thus, V(x,y,z), E(x,y,z), and C are related to ε(x,y,z). Therefore, when Vl and ε are given, it means that the system is determined. In view of this, when we regard the values of ε as integers from 1 to 20, a series of corresponding C can be obtained. Through regression analysis, we can construct the function relationship between ε and C.

    To maintain the advantages of the finite volume method and meet the high-precision demands of detection problems, we develop a new method called the multiple varying bounds integral method to calculate the capacitive sensor model.

    The two electrode plates occupy the domain

    B1={(x,y,z)|axa,byc,0zd},

    and

    B2={(x,y,z)|axa,byc,0zd}.

    The measured wood occupies the domain

    B={(x,y,z)|kxk,lyl,mzn}.

    This is an unbounded problem. To achieve numerical computation, we set a reasonable artificial boundary [xL,xR]×[yL,yR]×[zL,zR]. The computational domain is discretized by taking hx=xRxLNx,hy=yRyLNy and hz=zRzLNz as the step size in the direction of the x-axis, y-axis, and z-axis, respectively. Here Nx,Ny, and Nz are three given positive integers, so we get (Nx+1)×(Ny+1)×(Nz+1) grid nodes. Let each grid node be (xi,yj,zk), where xi=xL+ihx(i=0,1,,Nx),yj=yL+jhy(j=0,1,,Ny) and zk=zL+khz(k=0,1,,Nz). Set V(xi,yj,zk)=Vi,j,k, which approximately represents the corresponding potential at each node.

    In fact, the mathematical model to be solved is a multi-physics inverse problem. Therefore, for different fields, we should select appropriate numerical methods for different differential equations. We divide physical fields into two regions: Field 1, where Vi,j,k is continuous, and field 2, where Vi,j,k is discontinuous.

    In the computational domain, the variable Vi,j,k is continuous except at the faces, vertices and edges of the wood. Therefore, the multiple varying bounds integral method can be directly applied to discretize the equation in field 1.

    When (x,y,z)(R3B1B2¯B), the potential V(x,y,z) satisfies

    2V(x,y,z)=0, (4.1)

    and is continuous, so we can directly apply the multiple varying bounds integral method in this field to integrate Eq (4.1). We perform multiple varying bound integrals with respect to x, y, and z on both sides of Eq (4.1), so we have

    z2z1y2y1x2x1(2Vx2+2Vy2+2Vz2)dxdydz=0. (4.2)

    By Eq (4.2)

    z2z1y2y1(Vx2Vx1)dydz+z2z1x2x1(Vy2Vy1)dxdz+y2y1x2x1(Vz2Vz1)dxdy=0. (4.3)

    Then, integrating both sides of Eq (4.3) within the control volume, we have

    zkzkαzzk+αz2zkyjyjαyyj+αy2yjxixiαxxi+αx2xi[z2z1y2y1(Vx2Vx1)dydz+z2z1x2x1(Vy2Vy1)dxdz+y2y1x2x1(Vz2Vz1)dxdy]dx1dx2dy1dy2dz1dz2=0. (4.4)

    The three terms on the left-hand side of Eq (4.4) have identical structures. Therefore, we compute only the first term on the left-hand side. The other two terms can be handled similarly.

    zkzkαzzk+αz2zkyjyjαyyj+αy2yjxixiαxxi+αx2xi[z2z1y2y1(Vx2Vx1)dydz]dx1dx2dy1dy2dz1dz2=zkzkαzzk+αz2zkyjyjαyyj+αy2yjz2z1y2y1[xixiαxxi+αx2xi(Vx2Vx1)dx1dx2]dydzdy1dy2dz1dz2=zkzkαzzk+αz2zkyjyjαyyj+αy2yjz2z1y2y1{αx[V(xi+αx2,y,z)V(xi,y,z)]αx2[V(xi,y,z)V(xiαx,y,z)]}dydzdy1dy2dz1dz2=zkzkαzzk+αz2zkyjyjαyyj+αy2yjz2z1y2y1{αx[V(xi+αx2,y,z)32V(xi,y,z)+12V(xiαx,y,z)]}dydzdy1dy2dz1dz2, (4.5)

    where, αx,αy and αz are undetermined parameters. In the case of following the wood physical properties, we set αx=αy=αz=α and hx=hy=hz=h.

    Through the integral, the derivative function of an unknown function V(x,y,z) can be eliminated, thus reducing numerical errors, especially where the rate of change of the derivative is large. Next, we interpolate the original function of V(x,y,z). Here, let the node step size in each direction be h. We select three interpolation nodes in each of the x, y, and z directions, generating a total of 27 grid nodes (xi,yj,zk), (xi,yj1,zk), (xi,yj+1,zk), (xi1,yj,zk), (xi1,yj1,zk), (xi1,yj+1,zk), (xi+1,yj,zk), (xi+1,yj1,zk), (xi+1,yj+1,zk), (xi,yj,zk1), (xi,yj1,zk1), (xi,yj+1,zk1), (xi1,yj,zk1), (xi1,yj1,zk1), (xi1,yj+1,zk1), (xi+1,yj,zk1), (xi+1,yj1,zk1), (xi+1,yj+1,zk1), (xi,yj,zk2), (xi,yj1,zk2), (xi,yj+1,zk2), (xi1,yj,zk2), (xi1,yj1,zk2), (xi1,yj+1,zk2), (xi+1,yj,zk2), (xi+1,yj1,zk2), (xi+1,yj+1,zk2), as shown in Figure 3.

    Figure 3.  The interpolation nodes in field 1.

    Based on these 27 nodes, we construct the interpolating function for the unknown function V(x,y,z), as follows

    V(x,y,z)=i+1m=i1j+1s=j1k+1t=k1V(xm,ys,zt)i+1p=i1pmxxpxmxpj+1q=j1qsyyqysyqk+1r=k1rtzzrztzr. (4.6)

    Substituting Eq (4.6) into Eq (4.5), we have

    λ1Vi1,j1,k12λ1Vi,j1,k1+λ1Vi+1,j1,k1+λ2Vi1,j,k12λ2Vi,j,k1+λ2Vi+1,j,k1+λ3Vi1,j+1,k12λ3Vi,j+1,k1+λ3Vi+1,j+1,k1+λ2Vi1,j1,k2λ2Vi,j1,k+λ2Vi+1,j1+λ4Vi1,j,k2λ4Vi,j,k+λ4Vi+1,j,k+λ5Vi1,j+1,k2λ5Vi,j+1,k+λ5Vi+1,j+1,k+λ3Vi1,j1,k+12λ3Vi,j1,k+1+λ3Vi+1,j1,k+1+λ5Vi1,j,k+12λ5Vi,j,k+1+λ5Vi+1,j,k+1+λ6Vi1,j+1,k+12λ6Vi,j+1,k+1+λ6Vi+1,j+1,k+1=0, (4.7)

    where λ1=α2(4h+3α)24, λ2=3α(32h324h2α+4hα2+3α3)2, λ3=α2(16h2+9α2)4,λ4=9(8h2+α2)2, λ5=3α(32h324h2α4hα2+3α3)2 and λ6=(4h3α)2α24. To this end, we have completed the discretization of Eq (4.1) by the multiple varying bounds integral method.

    We divide the wood boundary into three parts: Faces, vertices, and edges. We found that Vn is discontinuous in these fields, so direct integral cannot be performed and special treatment is required.

    1) Analysis about faces of wood.

    The wood has a total of six faces. We use the upper face as an example. The other faces follow in a similar fashion. By the Taylor expansion exterior to the upper face, we have

    Vi,j,k+1=Vi,j,k+hVi,j,k+12h2Vi,j,k, (4.8)

    and

    Vi,j,k+2=Vi,j,k+2hVi,j,k+12(2h)2Vi,j,k. (4.9)

    From Eqs (4.8) and (4.9), it follows that

    Vi,j,k=4Vi,j,k+1Vi,j,k+23Vi,j,k2h. (4.10)

    Similarly, within the interior of the upper face of the wood, there are

    Vi,j,k=Vi,j,k24Vi,j,k1+3Vi,j,k2h. (4.11)

    Since the upper face is horizontal, the Vi,j,k direction is vertical. Thus, Vi,j,k=Vn. Consequently, εVn|Bin=˜εVn|Bout can be rewritten as

    εVi,j,k24εVi,j,k1+3(ε+˜ε)Vi,j,k4˜εVi,j,k+1+˜εVi,j,k+2=0. (4.12)

    Similarly, we can obtain the discrete equations for the other 5 faces of the wood.

    2) Analysis about vertices of wood.

    The wood has a total of eight vertices. We use the upper front right vertex of the wood as an example. By model (3.1), there is

    0=εΩ1Vnds+˜εΩ2Vnds=εΩ1Vnds+˜εΩ21Vnds+˜εΩ22Vnds+˜εΩ23Vnds. (4.13)

    This is assuming that Ω represents a spherical surface with its center at the upper front right vertex and a radius of h. Ω1 and Ω2 denote the parts of Ω interior and exterior the wood, respectively. There are Ω1=18Ω and Ω2=78Ω. Ω2 can also be divided into three parts based on the vertices, edges, and faces into three parts, that is Ω2=Ω21+Ω22+Ω23. Moreover, Ω21=18Ω,Ω22=14Ω, and Ω23=12Ω, as shown in Figure 4.

    Figure 4.  Field division when processing vertices.

    From Vn=Vxcosα+Vycosβ+Vzcosγ, we have Eq (4.13), which can be written as

    εΩ1(Vxdydz+Vydxdz+Vzdxdy)+˜εΩ21(Vxdydz+Vydxdz+Vzdxdy)+˜εΩ22(Vxdydz+Vydxdz+Vzdxdy)+˜εΩ23(Vxdydz+Vydxdz+Vzdxdy)=0. (4.14)

    Next, we discuss each of the items in Eq (4.14).

    (ⅰ) Consider the interior of the sphere

    Take Ω1Vxdydz as an example. When calculating Ω1Vxdydz, we take (xi,yj,zk) as the center and extend two steps in the negative x, y, and z directions, with a step length of 2h. We define the upper front right vertex as (x0,y0,z0). At this point, 27 points (x0,y0,z0), (x0,y0,z1), (x0,y0,z2), (x0,y1,z0), (x0,y1,z1), (x0,y1,z2), (x0,y2,z0), (x0,y2,z1), (x0,y2,z2), (x1,y0,z0), (x1,y0,z1), (x1,y0,z2), (x1,y1,z0), (x1,y1,z1), (x1,y1,z2), (x1,y2,z0), (x1,y2,z1), (x1,y2,z2), (x2,y0,z0), (x2,y0,z1), (x2,y0,z2), (x2,y1,z0), (x2,y1,z1), (x2,y1,z2), (x2,y2,z0), (x2,y2,z1), (x2,y2,z2) inside the wood are selected for interpolation, as shown in Figure 5.

    Figure 5.  The interpolation points used when handling the vertex and calculating Ω1.

    The interpolation function is

    Vx=0i=20j=20k=2[(Vx|i,j,k)0m=2mixxmxixm0s=2sjyysyjys0t=2tkzztzkzt]=1h60i=20j=20k=2[(Vx|i,j,k)0m=2mixxmim0s=2sjyysjs0t=2tkzztkt]. (4.15)

    Since Vx|i,j,k is unknown, it is represented by the difference quotient, and we have

    Vx|i,j,k=Vi,j,kVi1,j,kh. (4.16)

    In that case,

    Vx=1h70i=20j=20k=2[(Vi,j,kVi1,j,k)0m=2mixxmim0s=2sjyysjs0t=2tkzztkt], (4.17)

    then there is

    Ω1Vxdydz=1h70j=20k=2[12(V0,j,kV1,j,k)A1(V1,j,kV2,j,k)A2+12(V2,j,kV3,j,k)A3]. (4.18)

    The integration domain of A1 can be seen according to the yoz plane of Figure 6, so there is

    A1=h03π2π[(h2ρ2+2h)(h2ρ2+h)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ. (4.19)

    The same reasoning leads to

    A2=h03π2π[(h2ρ2)(h2ρ2+2h)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ, (4.20)

    and

    A3=h03π2π[(h2ρ2)(h2ρ2+h)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ. (4.21)

    Further simplification and organization gives

    Ω1Vxdydz=0i=20j=20k=21h7(Vi,j,kVi1,j,k)B1, (4.22)

    where,

    B1=h03π2π[0m=2mi(h2ρ2mhim)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ. (4.23)
    Figure 6.  Ω1 in the coordinate system.

    Similarly, when calculating Ω1Vydxdz and Ω1Vzdxdy, it is also necessary to construct an interpolation function. The interpolation nodes used for this purpose are illustrated in Figure 5. Thus, there are

    Ω1Vydxdz=0i=20j=20k=21h7(Vi,j,kVi,j1,k)B2, (4.24)

    and

    Ω1Vzdxdy=0i=20j=20k=21h7(Vi,j,kVi,j,k1)B3, (4.25)

    among them,

    B2=h03π2π[0m=2mi(ρsinθmhim)0s=2sj(h2ρ2shjs)0t=2tk(ρcosθthkt)]ρdρdθ, (4.26)

    and

    B3=h03π2π[0m=2mi(ρcosθmhim)0s=2sj(ρsinθshjs)0t=2tk(h2ρ2thkt)]ρdρdθ. (4.27)

    Therefore,

    Ω1(Vxdydz+Vydxdz+Vzdxdy)=1h70i=20j=20k=2[(Vi,j,kVi1,j,k)B1+(Vi,j,kVi,j1,k)B2+(Vi,j,kVi,j,k1)B3]. (4.28)

    We have completed the discretization at Ω1.

    (ⅱ) Consider the exterior of the sphere

    We use the method for calculating Ω1 to compute the integral on Ω2i(i=1,2,3). First, consider field Ω21. We need to interpolate around it by selecting 27 points (x0,y0,z0), (x0,y0,z1), (x0,y0,z2), (x0,y1,z0), (x0,y1,z1), (x0,y1,z2), (x0,y2,z0), (x0,y2,z1), (x0,y2,z2), (x1,y0,z0), (x1,y0,z1), (x1,y0,z2), (x1,y1,z0), (x1,y1,z1), (x1,y1,z2), (x1,y2,z0), (x1,y2,z1), (x1,y2,z2), (x2,y0,z0), (x2,y0,z1), (x2,y0,z2), (x2,y1,z0), (x2,y1,z1), (x2,y1,z2), (x2,y2,z0), (x2,y2,z1), (x2,y2,z2) on the exterior of the wood, as shown in Figure 7.

    Figure 7.  The interpolation points used when handling the vertex and calculating Ω21.

    At this point, the interpolating polynomial constructed are

    Vx=0i=20j=22k=0[(Vx|i,j,k)0m=2mixxmxixm0s=2sjyysyjys2t=0tkzztzkzt]=1h60i=20j=22k=0[(Vx|i,j,k)0m=2mixxmim0s=2sjyysjs2t=0tkzztkt], (4.29)
    Vy=0i=20j=22k=0[(Vy|i,j,k)0m=2mixxmxixm0s=2sjyysyjys2t=0tkzztzkzt]=1h60i=20j=22k=0[(Vy|i,j,k)0m=2mixxmim0s=2sjyysjs2t=0tkzztkt], (4.30)

    and

    Vz=0i=20j=22k=0[(Vz|i,j,k)0m=2mixxmxixm0s=2sjyysyjys2t=0tkzztzkzt]=1h60i=20j=22k=0[(Vz|i,j,k)0m=2mixxmim0s=2sjyysjs2t=0tkzztkt]. (4.31)

    Thus, we can get

    Ω21(Vxdydz+Vydxdz+Vzdxdy)=1h70i=20j=22k=0[(Vi,j,kVi1,j,k)B4+(Vi,j,kVi,j1,k)B5(Vi,j,k+1Vi,j,k)B6], (4.32)

    where,

    B4=h0ππ2[0m=2mi(h2ρ2mhim)0s=2sj(ρcosθshjs)2t=0tk(ρsinθthkt)]ρdρdθ, (4.33)
    B5=h02π3π2[0m=2mi(ρsinθmhim)0s=2sj(h2ρ2shjs)2t=0tk(ρcosθthkt)]ρdρdθ, (4.34)

    and

    B6=h03π2π[0m=2mi(ρcosθmhim)0s=2sj(ρsinθshjs)2t=0tk(h2ρ2thkt)]ρdρdθ. (4.35)

    Next, consider field Ω22, as shown in Figure 8.

    Figure 8.  The interpolation points used when handling the vertex and calculating Ω22.

    Thus, we obtain

    Ω22(Vxdydz+Vydxdz+Vzdxdy)=1h72i=00j=21k=1[(Vi+1,j,kVi,j,k)B7(Vi,j,kVi,j1,k)B8+(Vi,j,k+1Vi,j,k)(B9B10)], (4.36)

    where,

    B7=h03π2π2[2m=0mi(h2ρ2mhim)0s=2sj(ρcosθshjs)1t=1tk(ρsinθthkt)]ρdρdθ, (4.37)
    B8=h0π0[2m=0mi(ρsinθmhim)0s=2sj(h2ρ2shjs)1t=1tk(ρcosθthkt)]ρdρdθ, (4.38)
    B9=h02π3π2[2m=0mi(ρcosθmhim)0s=2sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ, (4.39)

    and

    B10=h02π3π2[2m=0mi(ρcosθmhim)0s=2sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ. (4.40)

    Finally, consider region Ω23, as shown in Figure 9.

    Figure 9.  The interpolation points used when handling the vertex and calculating Ω23.

    We can get

    Ω23(Vxdydz+Vydxdz+Vzdxdy)=1h71i=12j=01k=1[(Vi+1,j,kVi,j,k)(B11B12)+(Vi,j+1,kVi,j,k)B13+(Vi,j,k+1Vi,j,k)(B14B15)], (4.41)

    among it,

    B11=h0π2π2[1m=1mi(h2ρ2mhim)2s=0sj(ρcosθshjs)1t=1tk(ρsinθthkt)]ρdρdθ, (4.42)
    B12=h0π2π2[1m=1mi(h2ρ2mhim)2s=0sj(ρcosθshjs)1t=1tk(ρsinθthkt)]ρdρdθ, (4.43)
    B13=h02π0[1m=1mi(ρsinθmhim)2s=0sj(h2ρ2shjs)1t=1tk(ρcosθthkt)]ρdρdθ, (4.44)
    B14=h0π0[1m=1mi(ρcosθmhim)2s=0sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ, (4.45)

    and

    B15=h0π0[1m=1mi(ρcosθmhim)2s=0sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ. (4.46)

    Consequently, Eqs (4.28), (4.32), (4.36), and (4.41) constitute the discrete scheme of the upper front right vertex Eq (4.13). After rearrangement, we have

    ε0i=20j=20k=2[(Vi,j,kVi1,j,k)B1+(Vi,j,kVi,j1,k)B2+(Vi,j,kVi,j,k1)B3]˜ε0i=20j=22k=0[(Vi,j,kVi1,j,k)B4+(Vi,j,kVi,j1,k)B5(Vi,j,k+1Vi,j,k)B6]+˜ε2i=00j=21k=1[(Vi+1,j,kVi,j,k)B7(Vi,j,kVi,j1,k)B8+(Vi,j,k+1Vi,j,k)(B9B10)]+˜ε1i=12j=01k=1[(Vi+1,j,kVi,j,k)(B11B12)+(Vi,j+1,kVi,j,k)B13+(Vi,j,k+1Vi,j,k)(B14B15)]=0. (4.47)

    Similarly, discrete schemes for the other 7 vertices can be obtained.

    3) Analysis about edges of wood.

    The wood has twelve edges. We use the upper right edge of the wood as an example. By model (3.1), there is

    0=εΩ1Vnds+˜εΩ2Vnds=εΩ1Vnds+˜εΩ21Vnds+˜εΩ22Vnds, (4.48)

    where Ω denotes a cylindrical surface with the upper right edge as the axis and h as the radius. Ωl and Ω2 denote the parts of Ω in the interior and exterior of the wood, respectively. There are Ω1=14Ω and Ω2=34Ω. Ω2 is also divided into two parts according to the edges and faces, that is Ω2=Ω21+Ω22, where Ω21=14Ω and Ω22=12Ω, as illustrated in Figure 10.

    Figure 10.  Field division when processing edges.

    First, consider region Ω1. We need to interpolate around it by selecting 27 points (x0,y0,z0), (x0,y0,z2), (x0,y0,z1), (x0,y1,z0), (x0,y1,z1), (x0,y1,z2), (x0,y2,z0), (x0,y2,z1), (x0,y2,z2), (x1,y0,z0), (x1,y0,z1), (x1,y0,z2), (x1,y1,z0), (x1,y1,z1), (x1,y1,z2), (x1,y2,z0), (x1,y2,z1), (x1,y2,z2), (x2,y0,z0), (x2,y0,z1), (x2,y0,z2), (x2,y1,z0), (x2,y1,z1), (x2,y1,z2), (x2,y2,z0), (x2,y2,z1), (x2,y2,z2) on the interior of the wood as shown in Figure 11.

    Figure 11.  The interpolation points used when handling the edge and calculating Ω1.

    The interpolating polynomial constructed are

    Vx=1i=10j=20k=2[(Vx|i,j,k)1m=1mixxmxixm0s=2sjyysyjys0t=2tkzztzkzt]=1h61i=10j=20k=2[(Vx|i,j,k)1m=1mixxmim0s=2sjyysjs0t=2tkzztkt], (4.49)
    Vy=1i=10j=20k=2[(Vy|i,j,k)1m=1mixxmxixm0s=2sjyysyjys0t=2tkzztzkzt]=1h61i=10j=20k=2[(Vy|i,j,k)1m=1mixxmim0s=2sjyysjs0t=2tkzztkt], (4.50)

    and

    Vz=1i=10j=20k=2[(Vz|i,j,k)1m=1mixxmxixm0s=2sjyysyjys0t=2tkzztzkzt]=1h61i=10j=20k=2[(Vz|i,j,k)1m=1mixxmim0s=2sjyysjs0t=2tkzztkt]. (4.51)

    Therefore,

    Ω1(Vxdydz+Vydxdz+Vzdxdy)=1h71i=10j=20k=2[(Vi+1,j,kVi,j,k)(C1C2)(Vi,j,kVi,j1,k)C3(Vi,j,kVi,j,k1)C4], (4.52)

    where,

    C1=h03π2π[1m=1mi(h2ρ2mhim)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ, (4.53)
    C2=h03π2π[1m=1mi(h2ρ2mhim)0s=2sj(ρcosθshjs)0t=2tk(ρsinθthkt)]ρdρdθ, (4.54)
    C3=h03π2π2[1m=1mi(ρsinθmhim)0s=2sj(h2ρ2shjs)0t=2tk(ρcosθthkt)]ρdρdθ, (4.55)

    and

    C4=h02ππ[1m=1mi(ρcosθmhim)0s=2sj(ρsinθshjs)0t=2tk(h2ρ2thkt)]ρdρdθ. (4.56)

    Second, we consider Ω21Vnds. The interpolation nodes of field Ω21 are shown in Figure 12.

    Figure 12.  The interpolation points used when handling the edge and calculating Ω21.

    Equally,

    Ω21(Vxdydz+Vydxdz+Vzdxdy)=1h71i=10j=22k=0[(Vi+1,j,kVi,j,k)(C5C6)(Vi,j,kVi,j1,k)C7+(Vi,j,k+1Vi,j,k)C8], (4.57)

    among it

    C5=h0ππ2[1m=1mi(h2ρ2mhim)0s=2sj(ρcosθshjs)2t=0tk(ρsinθthkt)]ρdρdθ, (4.58)
    C6=h0ππ2[1m=1mi(h2ρ2mhim)0s=2sj(ρcosθshjs)2t=0tk(ρsinθthkt)]ρdρdθ, (4.59)
    C7=h0π2π2[1m=1mi(ρsinθmhim)0s=2sj(h2ρ2shjs)2t=0tk(ρcosθthkt)]ρdρdθ, (4.60)

    and

    C8=h02ππ[1m=1mi(ρcosθmhim)0s=2sj(ρsinθshjs)2t=0tk(h2ρ2thkt)]ρdρdθ. (4.61)

    Finally, we consider Ω22Vnds. The interpolation nodes of field Ω22 are shown in Figure 13.

    Figure 13.  The interpolation points used when handling the edge and calculating Ω21.

    With the same way,

    Ω22(Vxdydz+Vydxdz+Vzdxdy)=1h71i=12j=01k=1[(Vi+1,j,kVi,j,k)(C9C10)+(Vi,j+1,kVi,j,k)C11+(Vi,j,k+1Vi,j,k)(C12C13)], (4.62)

    where,

    C9=h0π2π2[1m=1mi(h2ρ2mhim)2s=0sj(ρcosθshjs)1t=1tk(ρsinθthkt)]ρdρdθ, (4.63)
    C10=h0π2π2[1m=1mi(h2ρ2mhim)2s=0sj(ρcosθshjs)1t=1tk(ρsinθthkt)]ρdρdθ, (4.64)
    C11=h02π0[1m=1mi(ρsinθmhim)2s=0sj(h2ρ2shjs)1t=1tk(ρcosθthkt)]ρdρdθ, (4.65)
    C12=h0π0[1m=1mi(ρcosθmhim)2s=0sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ, (4.66)

    and

    C13=h0π0[1m=1mi(ρcosθmhim)2s=0sj(ρsinθshjs)1t=1tk(h2ρ2thkt)]ρdρdθ. (4.67)

    Thus, Eqs (4.52), (4.57), and (4.62) constitute the discrete scheme of the upper right edge Eq (4.48), organized as

    ε1i=10j=20k=2[(Vi+1,j,kVi,j,k)(C1C2)(Vi,j,kVi,j1,k)C3(Vi,j,kVi,j,k1)C4]+˜ε1i=10j=22k=0[(Vi+1,j,kVi,j,k)(C5C6)(Vi,j,kVi,j1,k)C7+(Vi,j,k+1Vi,j,k)C8]+˜ε1i=12j=01k=1[(Vi+1,j,kVi,j,k)(C9C10)+(Vi,j+1,kVi,j,k)C11+(Vi,j,k+1Vi,j,k)(C12C13)]=0. (4.68)

    Similarly, we can obtain discrete equations for the other 11 edges of the wood.

    We take the first equation and third equation in system (3.1) as examples for error estimation, and the remaining equations follow a similar approach.

    1) Error estimation of the first equation

    Since the first equation 2V(x,y,z)=0 employs the Lagrange interpolation function, the remainder term of the Lagrange interpolation is given by

    R(x,y,z)=9V(ξ,η,ζ)3!3!3!x3y3z3i+1p=i1(xxp)j+1q=j1(yyq)k+1r=k1(zzr), (4.69)

    where, ξ(xi1,xi+1),η(yj1,yj+1),ζ(zk1,zk+1). If |9V(ξ,η,ζ)x3y3z3|M, we have

    |R(x,y,z)|M216|i+1p=i1(xxp)j+1q=j1(yyq)k+1r=k1(zzr)|. (4.70)

    Therefore, the error of the first equation is

    |zkzkαzzk+αz2zkyjyjαyyj+αy2yjxixiαxxi+αx2xi[z2z1y2y1x2x1(2Rx2+2Ry2+2Rz2)dxdydz]dx2dx1dy2dy1dz2dz1|. (4.71)

    Due to the identical structure of the three terms, we perform only the calculation for 2Rx2, as the other two terms can be computed similarly. First, integrating with respect to x, we have

    xixiαxxi+αx2xix2x12Rx2dxdx2dx1=xixiαxxi+αx2xi(Rx2Rx1)dx2dx1=xixiαxxi+αx2xiRx2dx2dx1xixiαxxi+αx2xiRx1dx2dx1=αxxi+αx2xiRx2dx2αx2xixiαxRx1dx1=O(h4x). (4.72)

    Next, integrating with respect to y, we have

    yjyiαyyj+αy2yjy2y1(yyj1)(yyj)(yyj+1)dydy2dy1=yjyjαyyj+αy2yjy2y1(yyjhy)(yyj)(yyj+hy)dydy2dy1=yjyjαyyj+αy2yjy2y1[(yyj)2h2y](yyj)dydy2dy1=yjyjαyyj+αy2yj[14(yyj)4h2y2(yyj)2]|y2y1dy2dy1=yjyjαjyj+αy2yj[14(y2yj)4h2y2(y2yj)214(y1yj)4+h2y2(y1yj)2]dy2dy1. (4.73)

    At this point, integrating with respect to y2, we have

    yjyjαyyj+αy2yj[14(y2yj)4h2y2(y2yj)2]dy2dy1=αyyj+αy2yj[14(y2yj)4h2y2(y2yj)2]dy2=αyαy20(14t4h2y2t2)dt=12025(αy)6h2y623(αy)4=O(h6y). (4.74)

    Similarly, the integral for y1 is

    yjyjαyyj+αy2αyy2y1(yyj1)(yyj)(yyj+1)dydy2dy1=O(h6y). (4.75)

    Likewise, the integral with respect to the z direction is also O(h6z). Therefore,

    |zkzkαzzk+αz2zkyjyjαyyj+αy2yjxixiαxxi+αx2xiz2z1y2y1x2x12Rx2dxdydzdx2dx1dy2dy1dz2dz1|=O(h4x+h6y+h6z). (4.76)

    However, to ensure accuracy, it is also necessary to divide by the integration factor. The integration factor is

    zkzkαzzk+αz2zkz2z1dzdz2dz1yjyjαyyj+αy2yjy2y1dydy2dy1=O(h3y+h3z). (4.77)

    Therefore, the accuracy of Eq (4.76) should be O(h4x+h3y+h3z). Thus, the error of Eq (4.71) is

    O(h4x+h3y+h3z)+O(h4y+h3z+h3x)+O(h4z+h3y+h3x)=O(h3x+h3y+h3z).

    Hence, the local truncation error of the discrete scheme is O(h3x+h3y+h3z), and the global error is O(h2x+h2y+h2z).

    2) Error estimation of the third equation

    By the Taylor expansion, we have

    Vi,j,k+1=Vi,j,k+hzVi,j,k+12h2zVi,j,k+13!h3zVi,j,k+14!h4zV(4)i,j,k, (4.78)
    Vi,j,k+2=Vi,j,k+2hzVi,j,k+12(2hz)2Vi,j,k+13!(2hz)3Vi,j,k+14!(2hz)4V(4)i,j,k, (4.79)
    Vi,j,k1=Vi,j,khzVi,j,k+12h2zVi,j,k13!h3zVi,j,k+14!h4zV(4)i,j,k, (4.80)

    and

    Vi,j,k2=Vi,j,k2hzVi,j,k+12(2hz)2Vi,j,k13!(2hz)3Vi,j,k+14!(2hz)4V(4)i,j,k. (4.81)

    By 4×(4.78)(4.79) and (4.81)4×(4.80), we eliminate Vi,j,k and obtain

    Vi,j,k=4Vi,j,k+1Vi,j,k+23Vi,j,k2hz+13h2zVi,j,k+14h3zV(4)i,j,k, (4.82)

    and

    Vi,j,k=Vi,j,k24Vi,j,k1+3Vi,j,k2hz+13h2zVi,j,k14h3zV(4)i,j,k. (4.83)

    Thus,

    ˜εVn|BinεVn|Bout=˜ε(4Vi,j,k+1Vi,j,k+23Vi,j,k2hz+13h2zVi,j,k+14h3zV(4)i,j,k)ε(Vi,j,k24Vi,j,k1+3Vi,j,k2hz+13h2zVi,j,k14h3zV(4)i,j,k). (4.84)

    In practical situations, ˜εε. Therefore, the error is O(h2z). Similarly, it can be concluded that the error in the x and y directions are O(h2x) and O(h2y). As a result, the third equation error is O(h2x+h2y+h2z).

    We illustrate the theory in this paper through a numerical example using the multiple varying bounds integral method.

    The two electrode plates occupy the domain

    B1={(x,y,z)|3x3,1y6,0z2},

    and

    B2={(x,y,z)|3x3,6y1,0z2}.

    The measured wood occupies the domain

    B={(x,y,z)|3x3,5y5,3z5}.

    Moreover, we set the artificial boundaries to [10,10]×[10,10]×[10,10]. In the above domains, the unit of length is centimeters and the step size is αx=αy=αz=α=hx=hy=hz=h=1. It is clear that the domain is symmetric. Based on the physical principles, V2=V1. Suppose V1=1 and V2=a (where a is an unknown to be determined). If, through numerical computation, the value of a is close to -1, it indicates that the multiple varying bounds integral method is reasonable.

    We perform numerical experiments on the above example and obtain the data in Table 1. These data are consistent with the physical principle that C increases as ε increases. Based on the data, the corresponding image is shown in Figure 14(a). It can be seen that, compared with other methods [30], our method eliminates the initial oscillations and maintains the original trend of C variation. Figure 14(b) shows the fitted function image derived from Reference [30]. Then, we perform a regression analysis on these data to establish a regression model:

    ε=1.45C297.31C+1635.10. (4.85)
    Table 1.  The numerical results of C about ε.
    Dielectric constant ε Capacitance value C V2
    1 33.2245 -1.0458
    2 33.8890 -1.0088
    3 34.3597 -0.9900
    4 34.7295 -1.0288
    5 35.0345 -1.0198
    6 35.2935 -1.0147
    7 35.5178 -1.0112
    8 35.7151 -1.0087
    9 35.8906 -1.0067
    10 36.0483 -1.0051
    11 36.1910 -1.0039
    12 36.3212 -1.0028
    13 36.4407 -1.0019
    14 36.5508 -1.0011
    15 36.6528 -1.0050
    16 36.7477 -0.9999
    17 36.8363 -0.9994
    18 36.9194 -0.9989
    19 36.9974 -0.9985
    20 37.0709 -0.9981

     | Show Table
    DownLoad: CSV
    Figure 14.  The function image of C about ε.

    First, we evaluate the goodness of fit for Eq (4.85). A higher goodness of fit indicates a stronger ability of the model to predict the dependent variable. As calculated from the data presented in Table 2, the determination coefficient R2=SSRSST=603.42665=0.91, where SSR represents the sum of squares regression and SST denotes the sum of squares total for Eq (4.85). This indicates that, when C is given, the regression model can more accurately predict the value of ε.

    Table 2.  The analysis of variance of regression model between C and ε.
    Model df Sum of variance MS F Significance F
    Regression 1 603.42 603.42 176.39 9.69×1011
    Residual 18 61.58 3.42
    Total 19 665

     | Show Table
    DownLoad: CSV

    In addition, we consider the confidence degree, which represents the reliability of ε. The higher the confidence degree, the stronger the reliability. Table 2 shows that F(1,18)=176.39, and according to the F-distribution table, F(1,18)=8.29(α=0.01). Because 176.39 > 8.29, it can be concluded that the confidence degree of the model is greater than 0.99. This means the values of ε obtained through (4.85) are highly reliable and more concentrated around the true value. The results of this regression analysis indicate that the functional relationship model between ε and C that we established can effectively predict the value of ε from C, with small errors. It can be seen that the multiple varying bounds integral method is a valid numerical method for this kind of problem.

    Wood moisture content detection is an inverse problem in multi-physics fields. Based on the high precision demand for moisture content detection, we propose a new numerical method, that is, the multiple varying bounds integral method. Moreover, in different physics fields, we choose different discrete methods to construct numerical schemes. For the physical field where the unknown function is discontinuous, this field has to be divided into several additional parts. For each smaller part, such as faces, vertices, and edges, we build corresponding interpolation functions and handle the integral to meet the precision requirements for the engineering problem. Moreover, we carry out numerical experiments and perform regression analysis to obtain the function relationship between ε and C. This model obeys the physical principle that C increases with an increase in ε. Moreover, the established regression model R2 is greater than 0.91, indicating a high goodness of fit and effectively reflecting the relationship between ε and C. This demonstrates that the data derived from this method are valid. Additionally, this numerical method is applicable to other engineering problems.

    On the other hand, the discrete scheme constructed in this paper has second-order precision. There are 2982 unknowns, and the computation time is 875.57 s. If a higher precision is desired, we can consider adding interpolation nodes to improve precision. Moreover, this would also increase the computational cost.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors would like to thank all the references which arehelpful for this article and the valuable suggestions which are put out by experts andreaders. These have improved this paper greatly and made it perfect. This paper was supported by the National Natural Science Foundation of China (Grant No. NSFC11526064), the Fundamental Research Funds for the Central Universities (Grant No. 3072024XX2402), and Harbin Engineering University (Grant No. KYWZ220240710).

    The authors declare there are no conflicts of interest.



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