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The well-posedness for semilinear time fractional wave equations on RN


  • This paper is concerned with the semilinear time fractional wave equations on the whole Euclidean space, also known as the super-diffusive equations. Considering the initial data in the fractional Sobolev spaces, we prove the local/global well-posedness results of L2-solutions for linear and semilinear problems. The methods of this paper rely upon the relevant wave operators estimates, Sobolev embedding and fixed point arguments.

    Citation: Yong Zhou, Jia Wei He, Ahmed Alsaedi, Bashir Ahmad. The well-posedness for semilinear time fractional wave equations on RN[J]. Electronic Research Archive, 2022, 30(8): 2981-3003. doi: 10.3934/era.2022151

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  • This paper is concerned with the semilinear time fractional wave equations on the whole Euclidean space, also known as the super-diffusive equations. Considering the initial data in the fractional Sobolev spaces, we prove the local/global well-posedness results of L2-solutions for linear and semilinear problems. The methods of this paper rely upon the relevant wave operators estimates, Sobolev embedding and fixed point arguments.



    In this paper, we focus on the following time fractional wave equation

    βtuΔu=f(u),t>0, (1.1)

    supplemented with the initial conditions

    u(0,x)=ϕ(x), tu(0,x)=ψ(x),xRN, (1.2)

    where βt stands for the Caputo fractional derivative operator of order β(1,2), Δ is the Laplacian operator, and f is the semilinear data to be specified later, initial data ϕ, ψ are given in certain fractional Sobolev spaces, likely (ϕ,ψ)Hs(RN)×Hs1(RN) for sR.

    From the point of view of physics, it's often better for fractional derivatives to fit practical problems than the integer order setting counterpart in many cases, for example, Hamiltonian chaos [1], biophysics [2,3], control engineering [4,5], viscoelasticity [6,7], anomalous diffusion [8,9,10,11], switched systems [12], and other problems [13,14,15]. In particular, the study of the Eq (1.1) has always been an important topic in the mathematical physics as it represents anomalous diffusion phenomena. The time fractional partial differential equation βtu=Δu of order β(0,1) models anomalous diffusion phenomena ensuring the behavior of a subdiffusion process driven by a fractional Brownian motion [16]. The case of order β(1,2) will govern intermediate processes between diffusion and wave propagation, for example, see [7], and it also ensures the behavior of superdiffusion process, for instance, see [17]. While the cases β1+ and β2 respectively correspond to standard diffusion equation (heat equation) and ballistic diffusion (wave equation). Besides, in anomalous diffusion equations of order β(0,1) or β(1,2), the mean squared displacement of a diffusive particle behavior likes x2(t)tβ, in contrast to normal diffusion behavior (Brownian motion) x2(t)t.

    There are many recent interesting works about time fractional wave equations. One of the most favorable reasons is that the integral kernel in fractional time derivative represents memory of a long-time tail of the power order. The investigation of existence and uniqueness of solutions for a low regularity initial data is a matter of interest in the mathematical analysis. For instance, Kian and Yamamoto [18] investigated a weak solution for semilinear case of (1.1) in bounded domain Ω for dimension n=2,3. By using the technique of eigenvalue expansion together with the properties of Mittag-Leffler functions, they established the existence and uniqueness results, which the solution shall lie in Lp(0,T;Lq(Ω))C([0,T];H2r(Ω)) for r=min(11/β,γ) with some 1p,q,0<γ<1. Following this technique, Alvarez et al. [19] considered the well-posedness for an abstract Cauchy problem in a Hilbert space, where the solutions will lie in Lrq(0,T;L2r(X)) associated with initial data (ϕ,ψ)D(Aγ)×L2(X), D(Aγ) are the fractional power spaces with spectrum form of A (nonnegative self-adjoint operator) for some β(1,2), γ=1/β, X is a (relatively) compact metric space and q(1/(β1),], r>1. Moreover, Otarola and Salgado [20] studied the time and space regularities of weak solutions for the space-time fractional wave equations, Zhou and He [21] discussed a well-posedness and time regularity of mild solutions for time fractional damped wave equations, etc. For more details, we refer to see the papers [22,23,24,25,26].

    However, few results discuss the unbounded domain case, likely the whole Euclidean space RN. This is due the difficulty to establish the relevant estimates on solution operators, also the method of eigenvalue expansion is not appropriate to such problem. As we know, Alemida and Precioso [27] investigated the global existence with large initial data in the framework of Besov-Morrey spaces, Alemida and Viana [28] studied existence, stability, self-similarity and symmetries of solutions with initial data in Sobolev-Morrey space. Zhang and Li [29] studied the local existence on C([0,T],Lq(RN)) for βN(p1)/2<q for a special semilinear function f|u|p, also the critical exponents of the global existence and blow-up solutions are determined when ψ0 and ψ0. Djida et al. [30] worked on a well-posedness result for semilinear space-time fractional wave equations, by adopting the method of Laplace-Fourier transforms, the properties of Mittag-Leffler functions and Fox H-functions.

    Our goal in this work is to establish the well-posedness results for time fractional wave equations with initial conditions in certain function spaces. More precisely, we consider linear and semilinear problems on RN, and present a general assumption in semilinear function and a special case λ|u|αu to deal with the current problem. In addition, this paper is devoted to studying the well-posedness of mild solutions to the current problems. In order to obtain the solution operators for time fractional wave equation and their properties, we shall establish some useful estimates which depend on that of wave operators. We remark that our proofs and results are completely different from the previous mentioned works. We will concern about the local/global well-posedness of solutions. Let us now enlist the main results presented in this paper:

    Ⅰ. The solution operators of Eq (1.1). Let ϖ=(Δ)1/2, we know that the wave operators can be given by cos(ϖt) and ϖ1sin(ϖt). Concerned with the principle of subordination, two inherent relationships between probability density function and wave operators are presented. More precisely, we get

    Cσ(t)=0Mσ(θ)cos(ϖtσθ)dθ,Sσ(t)=σtσ10θMσ(θ)ϖ1sin(ϖtσθ)dθ.

    To the best of our knowledge, these forms of solution operators are completely different from the existing literatures, relying upon the estimates of wave operators, some useful estimates of solution operators can be derived, which provide very helpful tools for the proofs. Observe that, the probability density function builds a bridge between integer wave equations and the fractional ones.

    Ⅱ. The well-posedness results on RN. We first establish some estimates on several spaces for the linear problem with initial data (ϕ,ψ)Hs(RN)×Hs1(RN), and then an existence of L2-solution is established on a space of continuous functions. Next, under the case that the semilinear function f:L2(RN)Lr(RN)Lr(RN), and satisfies

    f(u)f(v)Lr(RN)Cα(R)(uαLr(RN)+vαLr(RN))uvLr(RN),

    where constants r and α satisfy some restriction requirements, the local well-posedness results of mild solutions are established in the framework of Lγ(Lγ) spaces, here γ and γ are the conjugate indices. By concerning with a special semilinear data fλ|u|αu, we show that the local well-posedness on Besov space Bsr,2(RN). Furthermore, when ψ0, we also show the global existence to the Cauchy problem (1.1)–(1.2).

    The rest of this paper is divided into three sections. In Section 2, some basic notations and useful preliminaries are introduced. In Section 3, for the linear problem, we derive the solution operators and establish their some properties. In addition, two existence of L2-solutions are given. In Section 4, we prove some local/global well-posedness results on Lebesgue and Besov spaces for the semilinear problems.

    In this section, some notations and preliminaries related to our work will be introduced.

    Denote by Lq(RN) (q1) the Lebesgue space of q-integrable functions with the norm Lq(RN). Let S(RN) be the Schwartz space and let S(RN) denote its topological dual, for any vS(RN), F represents the Fourier transform

    ˆv(ξ)=F(v)(ξ)=(2π)N/2RNeixξv(x)dx,

    with its inverse

    ˇv(x)=F1(v)(x)=(2π)N/2RNeixξv(x)dx.

    Define the Sobolev space by

    Hs,q(RN)={uS(RN): F1[(1+|ξ|2)s2F(u)]Lq(RN)},

    equipped with the norm

    uHs,q(RN):=F1[(1+|ξ|2)s2F(u)]Lq(RN),

    for sR, 1q. We also use the Besov space Bsp,q:=Bsp,q(RN) and homogeneous Besov space ˙Bsp,q:=˙Bsp,q(RN), for sR, 1p,q. For the definitions and properties of Besov spaces, we refer to see [31,32]. In particular, it yields H0,p(RN)=Lp(RN) and Hs(RN)=Hs,2(RN)=Bs2,2(RN) for p1 and sR. Throughout this paper, we denote the notation ab that stands for aCb, with a positive generic constant C that does not depend on a,b, the notations , stand for ab=max{a,b} and ab=min{a,b}, respectively. Let p and p be the conjugate indices such that 1/p+1/p=1.

    Let T>0 (or T=+) and let X be a usual Banach space. For any uL1(0,T;X) and vL1(0,T;X), denote the convolution by

    (uv)(t)=t0u(ts)v(s)ds,t0,

    and for β0 let the weak singular kernel gβ() be defined by

    gβ(t)=tβ1/Γ(β),t>0,

    where Γ() is the usual gamma function. We denote g0(t)=δ(t), the Dirac measure is concentrated at the origin. Next, let us recall the concepts of fractional calculus and Mittag-Leffler functions. The Riemann-Liouville fractional integral of order β0 for a function vL1(0,T;X) is defined as

    Jβtv(t)=1Γ(β)t0(ts)β1v(s)ds=(gβv)(t), t>0.

    Definition 2.1. Let β(1,2). Consider a function vL1(0,T;X) such that convolution g2βvW2,1(0,T;X). The representation

    βtv(t)=2tt(g2β[v(t)v(0)ttv(0)]),t>0,

    is called the Caputo fractional derivative of order β.

    An important special function for the fractional differential equations involving the Caputo fractional derivative is the Mittag-Leffler function, which is defined by

    Eν,μ(z)=k=0zkΓ(νk+μ),zC, ν>0, μR.

    Note that, if w(t):=Eν,1(atν), ν(0,2), aR, then one can check that w is the solution of the equation νtw(t)=aw(t).

    Let the probability density function Mυ() (also called Mainardi's Wright function) be defined by

    Mυ(z)=k=0(z)kk!Γ(1υ(k+1)),υ(0,1), zC.

    For θ>0, this probability density function has the properties

    Mυ(θ)0,0θδMυ(θ)dθ=Γ(1+δ)Γ(1+υδ),for 1<δ<. (2.1)

    Next, we see that the probability density function can be viewed as a bridge between the classical and fractional wave equations.

    Lemma 2.1. Let β(1,2) [21]. Then for zC, the following formulas expressing the Mittag-Leffler function in term of probability density function hold:

    Eβ,1(z2)=0Mβ/2(θ)cos(zθ)dθ,Eβ,β(z2)=β2z0θMβ/2(θ)sin(zθ)dθ.

    Lemma 2.2. Let fL1(0,T;R) [33]. The unique solution of the fractional order problem

    {βtu(t)+au(t)=f(t),a0, t0,u(0)=u0, u(0)=u1,

    is give by

    u(t)=Eβ,1(atβ)u0+tEβ,2(atβ)u1+t0(ts)β1Eβ,β(a(ts)β)f(s)ds.

    In particular,

    u(t)=cos(at)u0+1asin(at)u1+1at0sin(a(ts))f(s)ds,

    which is the unique solution to the corresponding classical wave equation, i.e., β=2.

    In this section, we are concerned with the following linear Cauchy problem

    {βtu(t,x)Δu(t,x)=f(t,x),t>0, xRN,u(0,x)=ϕ(x), tu(0,x)=ψ(x). (3.1)

    Without loss of generality, the solutions in this paper are defined as mild solutions associated with the corresponding initial data.

    We first establish the solution representation of linear problem (3.1). Let u satisfies (3.1), taking the Fourier transform of both sides in (3.1) with respect to xRN, we obtain

    {βtˆu(t,ξ)+|ξ|2ˆu(t,ξ)=ˆf(t,ξ),t>0,ˆu(0,ξ)=ˆϕ(ξ), tˆu(0,ξ)=ˆψ(ξ).

    It follows from [4,(1.100)] that

    tEβ,2(tβ|ξ|2)=1Γ(2β)t0(ts)1βEβ,β(sβ|ξ|2)sβ1ds.

    Therefore, by virtue of Lemma 2.2, we get

    ˆu(t,ξ)=ˆφ(t,ξ)ˆϕ(ξ)+(ˆϑ(,ξ)g2β)(t)ˆψ(ξ)+(ˆϑ(,ξ)ˆf)(t),

    where

    ˆφ(t,ξ)=Eβ,1(tβ|ξ|2),ˆϑ(t,ξ)=tβ1Eβ,β(tβ|ξ|2).

    By using the inverse Fourier transform, we get

    u(t,x)=RNφ(t,xy)ϕ(y)dy+t0RNg2β(ts)ϑ(s,xy)ψ(y)dyds+t0RNϑ(ts,xy)f(s,y)dyds,

    where

    φ(t,x)=(2π)N/2RNeixξEβ,1(tβ|ξ|2)dξ,ϑ(t,x)=(2π)N/2RNeixξtβ1Eβ,β(tβ|ξ|2)dξ.

    On the other hand, set σ=β/2(1/2,1), it follows from Lemma 2.1 that

    φ(t,x)=(2π)N/20RNeixξMσ(θ)cos(tσθ|ξ|)dξdθ,

    and

    ϑ(t,x)=tσ1(2π)N/20RNeixξσθMσ(θ)sin(tσθ|ξ|)|ξ|dξdθ.

    Let

    ˙K(t)v=F1[cos(t|ξ|)ˆv(ξ)],K(t)v=F1[sin(t|ξ|)|ξ|ˆv(ξ)],

    and

    Sσ(t)v=σtσ10θMσ(θ)K(tσθ)vdθ.

    Rewriting u(t) for the function u(t,), we get an equivalent integral representation for problem (3.1) by

    u(t)=Cσ(t)ϕ+Pσ(t)ψ+t0Sσ(ts)f(s)ds, (3.2)

    where solution operators Cσ() and Pσ() are defined by

    Cσ(t)ϕ=0Mσ(θ)˙K(tσθ)ϕdθ,Pσ(t)ψ=(g22σSσ)(t)ψ.

    Let α(r)=121r for r[2,], and

    β(r)=N+12α(r),γ(r)=(N1)α(r),δ(r)=Nα(r).

    Let us recall the following two results in [34,35], which play a key role in proving the general results on the solution operators.

    Lemma 3.1. Let 2p< and 2β(p)ν2δ(p). Then for t0, it follows that

    F1[|ξ|νeit|ξ|ˆv(ξ)]Lp(RN)|t|ν2δ(p)vLp(RN).

    Lemma 3.2. Let 2p< and 2β(p)ν2δ(p), 0μs+ν. Then for 1q, t0, it follows that

    F1[|ξ|μeit|ξ|ˆv(ξ)]Bsp,q(RN)|t|ν2δ(p)vBs+νμp,q(RN).

    In the sequel, we set ϖ=(Δ)12 and U(t)=exp(iϖt)=F1[exp(i|ξ|t)F], so that K(t)=ϖ1sin(ϖt), ˙K(t)=cos(ϖt). Hence, it follows that

    K(t)=ϖ1U(t)U(t)2i,˙K(t)=U(t)+U(t)2.

    Lemma 3.3. Let N2, 2N/(N1)p2(N+1)/(N1), then Sσ(t):Lp(RN)Lp(RN) and moreover

    Sσ(t)vLp(RN)t2σ2σδ(p)1vLp(RN),vLp(RN),  t>0.

    Proof. Obviously, the condition 2NN1p2(N+1)N1 for N2 implies that 1/2δ(p)N/(N+1). Hence, it follows from Lemma 3.1 that

    K(t)vLp(RN)t12δ(p)vLp(RN).

    By the definition of Sσ(t), and (2.1) we obtain

    Sσ(t)vLp(RN)σtσ10θMσ(θ)K(tσθ)vLp(RN)dθσtσ1+σ(12δ(p))0θ22δ(p)Mσ(θ)dθvLp(RN)t2σ2σδ(p)1vLp(RN).

    Consequently, we get the desired inequality.

    Lemma 3.4. Let 2p<, 1q, sR, t>0.

    If (s)(2δ(p)1)(2β(p))ν2δ(p), then

    Cσ(t)vBsp,q(RN)tσ(ν2δ(p))vBs+νp,q(RN).

    If (1s)(2δ(p)2)(2β(p))ν2δ(p), then

    Sσ(t)vBsp,q(RN)tσ(ν2δ(p)+1)1vBs+ν1p,q(RN).

    Proof. From Lemma 3.2, for t>0 we have the following estimates

    ˙K(t)vBsp,q(RN)tν2δ(p)vBs+νp,q(RN),0s+ν,
    K(t)vBsp,q(RN)tν2δ(p)vBs+ν1p,q(RN),1s+ν.

    Therefore, using the same argument as employed in Lemma 3.3, we obtain the desired results.

    Let σ=β/2 for β(1,2). We now introduce an operator Qσ defined by

    (Qσf)(t)=t0Sσ(ts)f(s)ds.

    In order to obtain the existence of L2-solutions, we need the following lemma.

    Lemma 3.5. For each hLp(0,T;X) with 1p<+ [36], we have

    limτ0T0h(t+τ)h(t)pXdt=0,

    where we suppose that h(s)=0 for s not belonging to [0,T].

    Lemma 3.6. For any q and μ with 1<q2 and μ=N(1/q1/21/N), N1, let fLr(0,T;Hμ,q(RN)), then

    QσfL(0,T;L2(RN))fLr(0,T;Hμ,q(RN)),

    for r>1/σ. Furthermore, let q=2N/(N+2) for N3, and fLr(0,T;Lq(RN)), then

    QσfL(0,T;L2(RN))fLr(0,T;Lq(RN)).

    Moreover the operator Qσ maps Lr(0,T;H1(RN)) into C([0,T];L2(RN)).

    Proof. The inequality |sinα|1|α| for any αR implies

    |(sin(t|ξ|)ξ)/|ξ||(1(t|ξ|))ξ/|ξ|(1+t)(1|ξ|)ξ/|ξ|2(1+t), (3.3)

    where ξ=1+|ξ|2, for t0, ξRN. Let g(t,s,ξ)=sin((ts)σθ|ξ|)ˆf(s,ξ)/|ξ| and y(t,x)=x1ˆf(s,x), for s(0,t), ξ,xRN. It is clear by (3.3) that

    |g(t,s,ξ)|2(1+(ts)σθ)|y(s,ξ)|,for s(0,t), ξRN.

    Then it follows from the Plancherel theorem (see e.g. [37]) that

    ˇg(t,s,)L2(RN)=g(t,s,)L2(RN)2(1+(ts)σθ)y(s,)L2(RN)=2(1+(ts)σθ)ˇy(s,)L2(RN).

    Therefore, we have

    (Qσf)(t)L2(RN)t0Sσ(ts)f(s,)L2(RN)dst00σ(ts)σ1θMσ(θ)ˇg(t,s,)L2(RN)dθds2t00σ(ts)σ1θMσ(θ)(1+(ts)σθ)ˇy(s,)L2(RN)dθds.

    Due to ˇy(s,)L2(RN)=F1[ξ1ˆf(s,ξ)]L2(RN)=f(s,)H1(RN), in view of (2.1) and Hölder inequality, for r>1/σ we get

    (Qσf)(t)L2(RN)2t00σ(ts)σ1θMσ(θ)f(s,)H1(RN)dθds+2t00σ(ts)2σ1θ2Mσ(θ)f(s,)H1(RN)dθds=2t0gσ(ts)f(s,)H1(RN)ds+2t0g2σ(ts)f(s,)H1(RN)dsCfLr(0,T;H1(RN)), (3.4)

    where C depends on σ,r,N and T.

    Now, let us show the first estimate. Due to the embedding Hs,p(RN)Hs1,p1(RN) for 1<pp1<, s,s1R, and sN/p=s1N/p1, (see e.g., [31,32]) we know that Hμ,q(RN)H1(RN) for μ=N(1/q1/21/N). This means that

    (Qσf)(t)L2(RN)fLr(0,T;Hμ,q(RN)).

    Hence, the first estimate holds. On the other hand, since Bs2,2(RN)=Hs,2(RN) for sR, recall the embedding Hs,q(RN)Bsq,2(RN) for 1<q2 and the embedding (see e.g., [31,32])

    Bs0p0,q0(RN)Bs1p1,q1(RN),  for  s0N/p0=s1N/p1, (3.5)

    for any s0,s1R, 1p0p1, 1q0q1, we have

    B0q,2(RN)B12,2(RN),for q=2NN+2,

    by virtue of H0,q(RN)B0q,2(RN), and H0,q(RN)=Lq(RN) for q1, we obtain the embedding Lq(RN)H1(RN) when q=2N/(N+2). These means that

    (Qσf)(t)L2(RN)fLr(0,T;Lq(RN)).

    Hence, the second estimate holds.

    Finally, in order to obtain the conclusion that the operator Qσ maps Lr(0,T;H1(RN)) into C([0,T];L2(RN)), by (3.4) it suffices to prove the continuity of operator Qσ for any fLr(0,T;H1(RN)), i.e., we next to check that for 0t<t+hT

    (Qσf)(t+h)(Qσf)(t)L2(RN)0,as h0.

    In fact, we first have

    (Qσf)(t+h)(Qσf)(t)L2(RN)t+htSσ(t+hs)f(s,)dsL2(RN)+t00σ((t+hs)σ1(ts)σ1)θMσ(θ)ˇg(t+h,s,)dθdsL2(RN)+t00σ(ts)σ1θMσ(θ)(ˇg(t+h,s,)ˇg(t,s,))dθdsL2(RN):=I1+I2+I3.

    Obviously, applying (2.1) and Hölder inequality, it follows that

    I12t+ht0σ(t+hs)σ1θMσ(θ)f(s,)H1(RN)dθds+2t+ht0σ(t+hs)2σ1θ2Mσ(θ)f(s,)H1(RN)dθds=2t+htgσ(t+hs)f(s,)H1(RN)ds+2t+htg2σ(t+hs)f(s,)H1(RN)dshσ1/rfLr(0,T;H1(RN))+h2σ1/rfLr(0,T;H1(RN))0,as h0.

    For the second term I2, similarly to (3.4) we have

    I22t00σ|(t+hs)σ1(ts)σ1|θMσ(θ)f(s,)H1(RN)dθds+2t00σ|(t+hs)σ1(ts)σ1|(t+hs)σθ2Mσ(θ)f(s,)H1(RN)dθds=Cht0|(t+hs)σ1(ts)σ1|f(s,)H1(RN)dsCh(t0|(t+hs)σ1(ts)σ1|r/(r1)ds)11/rfLr(0,T;H1(RN)),

    where Ch=(2/Γ(σ)+2(T+h)σ/Γ(2σ)). Using the Lebesgue dominated convergence theorem and Lemma 3.5 we find that I20 as h0.

    For estimating the third term I3, by virtue of (3.3), we first have

    ˇg(t+h,s,)ˇg(t,s,)L2(RN)22(1+(t+hs)σθ)f(s,)H1(RN),

    which means that

    I3t00σ(ts)σ1θMσ(θ)ˇg(t+h,s,)ˇg(t,s,)L2(RN)dθds22t00σ(ts)σ1θMσ(θ)f(s,)H1(RN)dθds+22t00σ(ts)σ1(t+hs)σθ2Mσ(θ)f(s,)H1(RN)dθdsfLr(0,T;H1(RN)).

    Hence, by the Lebesgue dominated convergence theorem, we conclude that I30 as h0. Similarly, for any 0th<tT, it is not difficult to verify that (Qσf)(t)(Qσf)(th)L2(RN)0, as h0. Thus, the proof is completed.

    Lemma 3.7. For any sR, operators Cσ() and Pσ() satisfy

    Cσ()ϕC([0,T];Hs(RN))ϕHs(RN),  Pσ()ψC([0,T];Hs(RN))ψHs1(RN),

    for any (ϕ,ψ)Hs(RN)×Hs1(RN).

    Proof. By virtue of |cos(t|x|)|1 for all t0, xRN, it is easy to get ˙K(t)ϕHs(RN)ϕHs(RN). In fact, for any ϕHs(RN), we have

    ˙K(t)ϕHs(RN)=F1[cos(t||)ˆϕ]Hs(RN)=F1[(1+||2)s/2cos(t||)ˆϕ]L2(RN).

    The Plancherel theorem implies

    F1[(1+||2)s/2cos(t||)ˆϕ]L2(RN)=(1+||2)s/2cos(t||)ˆϕL2(RN)(1+||2)s/2ˆϕL2(RN)=F1[(1+||2)s/2ˆϕ]L2(RN),

    which means that ˙K(t)ϕHs(RN)ϕHs(RN). In addition, by virtue of the inequality |sin(t|x|)|t|x|, for all t0, xRN, as repeating the above processes, by (3.3) it is easy to check that K(t)ψHs(RN)2(1+t)ψHs1(RN) for any ψHs1(RN).

    Let us show that Cσ(t)ϕHs(RN)ϕHs(RN). In fact, from the definition of operator Cσ(), we have

    Cσ(t)ϕHs(RN)0Mσ(θ)˙K(tσθ)ϕHs(RN)dθϕHs(RN),

    where we have used the identity (2.1). Moreover, from the definition of operator Sσ() and the semigroup (gagb)(t)=ga+b(t) for a,b>0, t>0, we have

    Pσ(t)ψHs(RN)t0g22σ(ts)Sσ(s)ψHs(RN)dst00g22σ(ts)σsσ1θMσ(θ)K(sσθ)ψHs(RN)dθds2t00g22σ(ts)σsσ1(1+sσθ)θMσ(θ)ψHs1(RN)dθds=2((g22σgσ)(t)+(g22σg2σ)(t))ψHs1(RN)ψHs1(RN),

    where (g22σgσ)(t)+(g22σg2σ)(t)g2σ(T)+g2(T). Hence, it yields Pσ(t)ψHs(RN)ψHs1(RN). To end this proof, it suffices to check the continuity of Cσ(t)ϕ and Pσ(t)ψ.

    By the continuity of cos(t|ξ|), for h>0 and 0t<t+hT, by the Plancherel theorem we know that

    ˙K((t+h)σθ)ϕ˙K(tσθ)ϕHs(RN)=F1[s(cos((t+h)σθ||)cos(tσθ||))ˆϕ]L2(RN)=s(cos((t+h)σθ||)cos(tσθ||))ˆϕL2(RN)2sˆϕL2(RN)=2ϕHs(RN).

    Hence, passing to the Fourier representation and the Lebesgue dominated convergence theorem, we have the pointwise convergence

    ˙K((t+h)σθ)ϕ˙K(tσθ)ϕHs(RN)0,as h0, a.e.  θ(0,).

    On the other hand, by (2.1) we have

    Mσ(θ)˙K((t+h)σθ)ϕ˙K(tσθ)ϕHs(RN)Mσ(θ)ϕHs(RN)

    is integrable for a.e. θ(0,), hence Lebesgue dominated convergence theorem implies

    Cσ(t+h)ϕCσ(t)ϕHs(RN)=0Mσ(θ)(˙K((t+h)σθ)ϕ˙K(tσθ)ϕdθHs(RN)0,as h0.

    This means that Cσ()ϕC([0,T],Hs(RN)). Furthermore, as repeating the above processes, we also get the continuity of Pσ(t)ψ. Hence, Pσ()ψC([0,T],Hs(RN)). The proof is completed.

    Remark 3.1. Obviously, in view of the inequality |sin(t|x|)|t|x|, for all t0, xRN, from the same way as in Lemma 3.7, we get,

    QσfC([0,T];L2(RN))fL(0,T;L2(RN)).

    By using Lemma 3.6 and Lemma 3.7, it is not difficult to obtain the existence theorem to linear problem (3.1).

    Theorem 3.1. Let T>0. Given (ϕ,ψ)Hs(RN)×Hs1(RN) for sR, let r>2/β and fLr(0,T;Hμ,q(RN)), for any q and μ satisfying 1<q2 and μ=N(1/q1/21/N), N1, then there exists a unique solutionuC([0,T];L2(RN)) to the linear problem (3.1), and moreover

    uL(0,T;L2(RN))ϕHs(RN)+ψHs1(RN)+fLr(0,T;Hμ,q(RN)).

    Let q=2N/(N+2) for N3, if fLr(0,T;Lq(RN)), then

    uL(0,T;L2(RN))ϕHs(RN)+ψHs1(RN)+fLr(0,T;Lq(RN)).

    In the sequel, we consider the global existence to the linear Cauchy problem (3.1).

    Theorem 3.2. Given ϕHs(RN), ψ0 for sR. Let N2, σ=β/2 for β(1,2) and fCσ([0,);Hs1(RN)), where the Banach space

    Cσ([0,);Hs1(RN))={uC([0,);Hs1(RN)): tσu(t)Hs1(RN)<, t0},

    equipped with its natural norm uσ=supt[0,)tσu(t)Hs1(RN). Then there exists a unique solutionuC([0,);Hs(RN)) to the linear problem (3.1), and moreover

    uL(0,;Hs(RN))ϕHs(RN)+fCσ([0,);Hs1(RN)). (3.6)

    Proof. Observe that, for t0, from Lemma 3.7, Cσ(t)ϕHs(RN)ϕHs(RN). Moreover, for any vHs1(RN), Lemma 3.4 implies

    Sσ(t)vBs2,2(RN)tσ1vBs12,2(RN),

    which means that Sσ(t)vHs(RN)tσ1vHs1(RN). Hence, we have

    Cσ(t)ϕHs(RN)+(Qσf)(t)Hs(RN)ϕHs(RN)+t0Sσ(ts)f(s,)Hs(RN)dsϕHs(RN)+t0(ts)σ1f(s)Hs1(RN)dsϕHs(RN)+fCσ([0,);Hs1(RN)),

    where we have used the semigroup (gagb)(t)=ga+b(t) for a,b>0. Similarly to Lemma 3.6 and Lemma 3.7, the continuity is easy to check, where we can use the Plancherel theorem and Lebesgue dominated convergence theorem. Consequently, there exists a solution satisfying (3.2) and its values lie in C([0,);Hs(RN)), and then (3.6) holds. Moreover, the uniqueness follows (3.6). The proof is completed.

    In this section, we focus on the well-posedness results of the semilinear problem, we first establish a local well-posed result of L2-solutions that also belong to the setting of Lγ(0,T;Lr(RN)), furthermore, by a similar way in Theorem 3.2, another conclusion will be given in the framework of L(0,T;Hs(RN)). In the sequel, for a given semilinear function, we obtain the well-posedness results in the setting of Besov space Bsr,2.

    Theorem 4.1. Let N2 and (ϕ,ψ)Hs(RN)×Hs1(RN) for any s(1/2,N/2). Assume that

    f:L2(RN)Lr(RN)Lr(RN),

    where index r satisfying

    2NN1r2(N+1)N1|N22NN2s|N>2s2NN2|N3.

    For every R>0, there exist α0 and constant Cα(R)(0,)such that

    f(u)f(v)Lr(RN)Cα(R)(uαLr(RN)+vαLr(RN))uvLr(RN),

    for all u,vL2(RN)Lr(RN) with uL2(RN),vL2(RN)R. Let γ>0 be an element to the admissible set

    {γR+: γ>2+α, γ(β2)+2>0, γ(σN1)+1>0},

    for σN=β(1δ(r)).Then there exists a unique mild solutionuC([0,T];L2(RN))Lγ(0,T;Lr(RN))of the problem (1.1)–(1.2) for some T>0. Moreover, u depends continuously on ϕ,ψ in the following sense. If ϕmϕ in Hs(RN) and ψmψ in Hs1(RN) and if um denotes the solution of problem (1.1)-(1.2) with the initial value ϕm,ψm, then for all sufficiently large m, um converges to u in C([0,T];L2(RN))Lγ(0,T;Lr(RN)).

    Proof. Let σ=β/2 for β(1,2). We want to construct a local (in t) solution to the integral equation

    (Φu)(t)=Cσ(t)ϕ+Pσ(t)ψ+(Qσf)(u)(t).

    By applying Lemma 3.6, Lemma 3.7, and Remark 3.1, it is clear that Φ is well defined. We next shall use a fixed point argument to verify this proof. Fixed T,R>0 and set a space by

    UT={uL(0,T;L2(RN))Lγ(0,T;Lr(RN));d(u,0)R},

    where d(,) is the distance to the space UT given by

    d(u,v)=uvL(0,T;L2(RN))+uvLγ(0,T;Lr(RN)),for u,vUT.

    Obviously, (UT,d) is a complete metric space.

    For uUT and every R>0, from the assumption of nonlinearity f, by the trigonometric inequality we first have

    f(u)Lr(RN)f(u)f(0)Lr(RN)+f(0)Lr(RN)Cα(R)uα+1Lr(RN)+f(0)Lr(RN).

    Therefore, for γ>α+2, Hölder inequality yields

    f(u)Lγ(0,T;Lr(RN))Cα(R)uα+1L(α+1)γ(0,T;Lr(RN))+T1γf(0)Lr(RN)Cα(R)Tγ(α+2)γuα+1Lγ(0,T;Lr(RN))+Tγ1γf(0)Lr(RN).

    Similarly, for u,vUT, we have

    f(u)f(v)Lγ(0,T;Lr(RN))Cα(R)(T0(u(t)αLr(RN)+v(t)αLr(RN))γu(t)v(t)γLr(RN)dt)1/γ,

    which, by Hölder inequality and Minkowski inequality, leads to

    f(u)f(v)Lγ(0,T;Lr(RN))Cα(R)(uαLr(RN)+vαLr(RN)Lγγ2(0,T))uvLγ(0,T;Lr(RN))2Cα(R)Tγ(α+2)γRαuvLγ(0,T;Lr(RN)). (4.1)

    Next, we obtain the existence and uniqueness results for T small. By Lemma 3.3, for 2N/(N1)r2(N+1)/(N1) and (σN1)γ+1>0, we have

    (Qσf)(u)(t)Lr(RN)t0(ts)σN1f(u)(s)Lr(RN)dstσN1+1γf(u)Lγ(0,T;Lr(RN)).

    Observe that the embedding Hs(RN)Lr(RN) for s[0,N/2), 2r<2N/(N2s), we have

    Φ(u)(t)Lr(RN)Cσ(t)ϕHs(RN)+Pσ(t)ψHs(RN)+(Qσf)(u)(t)Lr(RN).

    Therefore, we have

    Φ(u)Lγ(0,T;Lr(RN))T1γϕHs(RN)+T1γψHs1(RN)+(Qσf)(u)(t)Lγ(0,T;Lr(RN))T1γϕHs(RN)+T1γψHs1(RN)+TσNf(0)Lr(RN)+Cα(R)TσNα+1γRα+1.

    On the other hand, by Lemma 3.6, for any uUT, we have

    Φ(u)L(0,T;L2(RN))ϕHs(RN)+ψHs1(RN)+(Qσf)(u)L(0,T;L2(RN))ϕHs(RN)+ψHs1+f(u)Lγ(0,T;Lr(RN))ϕHs(RN)+ψHs1(RN)+Tγ1γf(0)Lr(RN)+Cα(R)Tγ(α+2)γRα+1.

    Therefore, there exists a constant C1 such that

    Φ(u)L(0,T;L2(RN))+Φ(u)Lγ(0,T;Lr(RN))C(1+T1γ)(ϕHs(RN)+ψHs1(RN))+C(Tγ1γ+TσN)f(0)Lr(RN)+CCα(R)(Tγ(α+2)γ+TσNα+1γ)Rα+1.

    Fixed R>0 satisfying C(ϕHs(RN)+ψHs1(RN))R/4, let T be small enough such that

    CT:=CCα(R)Rα(Tγ(α+2)γ+TσNα+1γ)<12, (4.2)

    and

    C(ϕHs(RN)+ψHs1(RN))T1γ+(TσN+Tγ1γ)f(0)Lr(RN)<R2.

    Hence, it follows that Φ(u)UT for any uUT. Moreover, from Lemma 3.6 we deduce

    Φ(u)Φ(v)L(0,T;L2(RN))=(Qσf)(u)(Qσf)(v)L(0,T;L2(RN))f(u)f(v)Lγ(0,T;Lr(RN)),

    where γ>1/σ, 1<r2 for N=1,2 and 2N/(N+2)r2 for N3. Hence, by selecting T small enough so that (4.2) holds, by virtue of (4.1), we have

    Φ(u)Φ(v)L(0,T;L2(RN))13d(u,v),

    for all u,vUT. Since

    (Qσf)(u)(t)(Qσf)(v)(t)Lr(RN)tσN1+1γf(u)f(v)Lγ(0,T;Lr(RN)),

    for T small enough so that (4.2) holds, by virtue of (4.1), it follows that

    Φ(u)Φ(v)Lγ(0,T;Lr(RN))=(Qσf)(u)(Qσf)(v)Lγ(0,T;Lr(RN))13d(u,v).

    Consequently, Φ is a strict contraction on UT. From the similar proof of continuity in Theorem 3.1 taking on Φ(u), it follows that Φ has a fixed point uC([0,T];L2(RN))Lγ(0,T;Lr(RN)), which is the unique mild solution of problem (1.1)–(1.2).

    For the choice of T (independent to ϕHs(RN) and ψHs1(RN)), as before, R is determined only by the size of the norm of initial data. Hence T and R are independent of umUT for m sufficiently large. Suppose ϕmϕ in Hs(RN) and ψmψ in Hs1(RN) when m. Now, let m be large enough, then

    uumL(0,T;L2(RN))ϕϕmHs(RN)+ψψmHs1(RN)+Qσ(f(u)f(um))L(0,T;L2(RN))ϕϕmHs(RN)+ψψmHs1(RN)+f(u)f(um)Lγ(0,T;Lr(RN)).

    By the same argument, one can conclude that

    uumLγ(0,T;Lr(RN))T1γϕϕmHs(RN)+T1γψψmHs1(RN)+TσN1+1γf(u)f(um)Lγ(0,T;Lr(RN)).

    Then, (4.1) implies that

    d(u,um)(1+T1γ)ϕϕmHs(RN)+(1+T1γ)ψψmHs1(RN)+2Cα(R)Tγ(α+2)γRα(1+Tσn1+1γ)d(u,um).

    Let T be chosen so small such that (4.2) holds, then

    (1CT)d(u,um)(1+T1γ)(ϕϕmHs(RN)+ψψmHs1(RN)).

    Consequently, we deduce that d(u,um)0 as m. The proof is completed.

    Remark 4.1. From the above theorem, we have the following remarks:

    i) The admissible set of γ is not empty. Indeed, for α=2, r=3, N=3 and taking initial values (ϕ,ψ)H1(R3)×L2(R3), for a suitable semilinear function f(u) satisfying the assumptions in Theorem 4.1, likely f(u)=λ|u|2u for λ>0, it follows that 4<γ<2/(2β) for β(3/2,2).

    ii) Let α,r,N and f satisfy the assumptions of Theorem 4.1, noting that if δ(r)1/2, then the restrictions in the admissible set of γ reduce to 2+α<γ<2/(2β), or if 0α<2(β1)/(2β) and 1/2<δ(r)<1(1+α)/(β(2+α)), then the restrictions in the admissible set of γ reduce to 2+α<γ<1/(1σN).

    iii) By the embedding Hs(RN)Lr(RN) for s[0,N/2), the requirement 2N/(N1)r<2N/(N2s) implies that the conclusion fails for 0s1/2, and thus the assumption s>1/2 is needed in the initial value conditions.

    Noting that, by virtue of the critical embedding Hs(RN)Lr(RN), for 2r<, s=N/2, we obtain a weaken requirement of index r in Theorem 4.1.

    Corollary 4.1. Let N2 and (ϕ,ψ)HN/2(RN)×HN/21(RN). Assume that

    f:L2(RN)Lr(RN)Lr(RN),

    where index r satisfying

    2NN1r2(N+1)N1|N22NN2|N3.

    For every R>0, there exist α0 and constant Cα(R)(0,)such that

    f(u)f(v)Lr(RN)Cα(R)(uαLr(RN)+vαLr(RN))uvLr(RN),

    for all u,vL2(RN)Lr(RN) with uL2(RN),vL2(RN)R. Let γ>0 be an element to the admissible set

    {γR+: γ>2+α, γ(β2)+2>0, γ(β(1δ(r))1)+1>0}.

    Then the problem (1.1)–(1.2) is local well-posed on C([0,T];L2(RN))Lγ(0,T;Lr(RN)).

    By using the embedding

    Hs(RN)L2(RN)L(RN),for s>N/2,

    one can prove the following result by employing the arguments used in the proof of Theorem 4.1.

    Corollary 4.2. Let s>N/2. Assume that for every R>0, there exists C(R)< such that

    f(u)Hs(RN)C(R)uHs(RN),
    f(u)f(v)L2(RN)C(R)uvL2(RN),

    for all u,vHs(RN) and that of uL(RN)R, vL(RN)R. Then for (ϕ,ψ)Hs(RN)×Hs1(RN), problem (1.1)–(1.2) is local well-posed on u(WT,R,d) for some T,R>0, where (WT,R,d) is the metric space given by

    WT,R={uL(0,T;Hs(RN)): uL(0,T;Hs(RN))R},

    equipped with the distance

    d(u,v)=uvL(0,T;L2(RN)),for u,vWT,R.

    In the sequel, we consider a semilinear function of the form f(u)=λ|u|αu for λR and for α0, a well-posed result on Besov setting is also established. In order to complete the proof, we need the following result [38].

    Lemma 4.1. Let f(u)=λ|u|αu for λR and for α0. If 0<s<N/2, 2ρρ=N(α+2)/(N2s), then

    f(u)Bsρ,2uα+1Bsρ,2,

    and

    f(u)f(v)Lρ(RN)(uαBsρ,2+vαBsρ,2)uvLρ(RN),

    for any u,vBsρ,2.

    Proof. Noting that

    ||u|αu|v|αv|(α+1)(|u|α+|v|α)|uv|,

    we obtain by Hölder inequality and the embedding ˙Bsρ,2(RN)Lρ(RN) that

    f(u)Lρ(RN)uα˙Bsρ,2uLρ(RN),

    and

    f(u)f(v)Lρ(RN)(uα˙Bsρ,2+vα˙Bsρ,2)uvLρ(RN).

    In view of the inequality

    f(u)˙Bsρ,2uα+1˙Bsρ,2,

    and the interpolation property Bsρ,2(RN)=Lρ(RN)˙Bsρ,2(RN), the desired inequalities follow.

    Theorem 4.2. Let N2, s(0,N/2) and f(u)=λ|u|αu for α0, λR. Let

    2NN1r2(N+1)N1N(α+2)N2s,

    given (ϕ,ψ)Hs+1,r(RN)×Hs,r(RN).Moreover, let γ>0 being an element tothe set

    {γR+: γ>α+2, γ(β(22δ(r))2)+2>0}. (4.3)

    Then the problem (1.1)–(1.2) is local well-posed on Lγ(0,T;Bsr,2).

    Proof. Following the method of proof for Theorem 4.1, we just need to construct a local solution to the operator equation (Ψu)(t)=u(t) for t[0,T] in a suitable ball in Lγ(0,T;Bsr,2), where the ball is defined by

    BM={uLγ(0,T;Bsr,2): uLγ(0,T;Bsr,2)M},

    with the radius M>0. Note that this space is not trivial. Indeed, for ϕHs+1,r(RN), by virtue of Lemma 3.4, and the embedding (3.5) and Hs1,r(RN)Hs0,r(RN) for s1s0, s1,s0R we have

    Cσ(t)ϕBsr,2ϕBs+δ(r)r,2ϕHs+δ(r),r(RN)ϕHs+1,r(RN),

    which shows that Cσ()ϕLγ(0,T;Bsr,2)ϕHs+1,r(RN). Similarly, by (g22σgσ)(t)=g2σ(t)Lγ(0,T;R) we also get Pσ()ψLγ(0,T;Bsr,2)ψHs,r(RN). Thus, u(t)=Cσ(t)ϕ is in BM if ϕHs+1,r(RN) and ϕHs+1,r(RN) is small enough. Endowed with the metric

    d(u,v)=uvLγ(0,T;Lr(RN)),

    then (BM,d) is a complete metric space. Indeed, since Lγ(0,T;Bsr,2) is reflexive, the closed ball of radius M is weakly compact, for details, see [38].

    From Lemma 4.1, we get f(u)Bsr,2uα+1Bsr,2, for all uBsr,2. Thus, it remains to consider the case ΦuLγ(0,T;Bsr,2) for some T>0. Noting that from the requirements of index r, it yields 1/2δ(r)N/(N+1), consider any uBsr,2, then it follows from (4.3) that

    (Φu)(t)Bsr,2Cσ(t)ϕBsr,2+Pσ(t)ψBsr,2+(Qσf)(u)(t)Bsr,2Cσ(t)ϕHs+1,r(RN)+Pσ(t)ψHs,r(RN)+t0Sσ(ts)f(u)(s)Bsr,2dsϕHs+1,r(RN)+ψHs,r(RN)+t0(ts)σ(22δ(r))1u(s)α+1Bsr,2ds.

    Noting that

    |u|αuLγ(0,t;Bsr,2)tγ(α+2)γuα+1Lγ(0,t;Bsr,2),

    we obtain

    Φ(u)Lγ(0,T;Bsr,2)T1γϕHs+1,r(RN)+T1γψHs,r(RN)+Tσ(22δ(r))α+1γuα+1Lγ(0,T;Bsr,2).

    On the other hand, from Lemma 4.1, for any u,vBM, we get

    f(u)f(v)Lγ(0,T;Lr(RN))Tγ(α+2)γMαuvLγ(0,T;Lr(RN)).

    Therefore, we have

    Φ(u)Φ(v)Lγ(0,T;Lr(RN))=(Qσf)(u)(Qσf)(v)Lγ(0,T;Lr(RN))TσN1+1γf(u)f(v)Lγ(0,T;Lr(RN))TσNα+1γMαuvLγ(0,T;Lr(RN)).

    This means that there exists a constant C>0 such that

    Φ(u)Lγ(0,T;Bsr,2)CT1γ(ϕHs+1,r(RN)+ψHs,r(RN))+CTσ(22δ(r))α+1γMα+1,

    and

    Φ(u)Φ(v)Lγ(0,T;Lr(RN))CTσNα+1γMαuvLγ(0,T;Lr(RN)).

    Hence, fixed M>0, let T be small enough such that

    CT1γ(ϕHs+1,r(RN)+ψHs,r(RN))<M/2, CMα(Tσ(22δ(r))α+1γ+TσNα+1γ)<1/2.

    Then Φ maps BM into itself and we obtain

    d(Φ(u),Φ(v))12d(u,v).

    Thus, there exists a unique solution of problem (1.1)–(1.2). The remaining proof is similar to that of Theorem 4.1. So we omit its details. The proof is completed.

    Remark 4.2. Observe that, the embedding Hs,r(RN)Bsr,2(RN), Lemma 3.4 yields

    Cσ(t)ϕBsr,2tβδ(r)ϕHs,r(RN),

    which belongs to Lγ(0,T;R). Hence, it shall possess a decay rate βδ(r), which implies that the solution does not belong to C([0,T];Bsr,2)L(0,T;Bsr,2).

    Concerning with Remark 4.2, in the sequel, we establish the global well-posed result for a special initial data.

    Theorem 4.3. Let N2, β(1,4/3), s(0,N/2), δ(r)=1/2 and f(u)=λ|u|2u for λR.Given ϕHs+12,r(RN) with ϕHs+12,r(RN)ϵ for some ϵ>0 and ψ0.Then the problem (1.1)–(1.2) is global well-posed on YR, where (YR,d) (R>0) is the metric space given by

    YR={uC((0,);Bsr,2(RN)): supt[0,)tβ/4u(t)Bsr,2R},

    equipped with the distance

    d(u,v)=supt[0,)tβ/4u(t)v(t)Lr(RN),for u,vYR.

    Proof. Let σ=β/2 for β(1,2). We next verity the operator Φ maps YR into itself. Indeed, for uYR, by virtue of Lemma 3.4, we have

    (Φu)(t)Bsr,2tσ/2ϕHs+12,r(RN)+t0Sσ(ts)f(u)(s)Bsr,2dstσ/2ϵ+t0(ts)σ1f(u)(s)3Bs12r,2dstσ/2ϵ+t0(ts)σ1u(s)3Bsr,2dstσ/2ϵ+t0(ts)σ1s3σ/2dsR3,

    where we have used the embedding Bs0r,2Bs1r,2 for s0s1, s0,s1R. Therefore, there exists a constant C>0 such that

    tσ/2(Φu)(t)Bsr,2Cϵ+CR3.

    Taking ϵR/(2C) for R(1/(2C))1/2, due to the Fourier representation of operators and the Lebesgue dominated convergence theorem, the proof of the continuity of Φ is similar to Lemma 3.6. Hence, we deduce that Φ(u)YR for any uYR.

    Next, we show that Φ is a contraction on YR. Indeed, for any u,vYR, combined the requirement of δ(r)=1/2 and Lemma 3.3 imply

    (Φu)(t)(Φv)(t)Lr(RN)t0Sσ(ts)(f(u)(s)f(v)(s))Lr(RN)dst0(ts)σ1f(u)(s)f(v)(s)Lr(RN)ds.

    Lemma 4.1 shows that

    (Φu)(t)(Φv)(t)Lr(RN)t0(ts)σ1(u2Bsr,2+v2Bsr,2)uvLr(RN)dst0(ts)σ1s3σ/2dsR2d(u,v).

    Therefore, there exists a constant C>0 for R(2/C)1/2(1/(2C))1/2 such that

    d(Φ(u),Φ(v))CR2d(u,v)12d(u,v).

    Consequently, Φ is a strict contraction on YR. This means that Φ has a unique fixed point uYR. The proof is completed.

    In this paper, we proved some well-posedness results for linear and semilinear time fractional wave equations, which are also called super-diffusive equations. Under the probability density function and wave operators, we construct the solution operators that are differential to the references therein, which are also useful to establish the local well-posedness of L2-solutions as well as the local well-posedness on Besov space. Moreover, based on the standard fixed point arguments, the initial data ϕ and ψ are taking in the more regularity fractional Sobolev spaces, respectively. Finally, we also establish the global existence results for a linear and a spacial semilinear fractional Cauchy problems.

    The work was supported by National Natural Science Foundation of China (Nos. 12071396, 12101142).

    The authors declare there is no conflicts of interest.



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