Research article

Some congruences for -regular partitions with certain restrictions

  • Received: 20 November 2023 Revised: 27 December 2023 Accepted: 02 January 2024 Published: 05 February 2024
  • MSC : 11P83

  • Let pod(n) and ped(n) denote the number of -regular partitions of a positive integer n into distinct odd parts and the number of -regular partitions of a positive integer n into distinct even parts, respectively. Our first goal in this note was to prove two congruence relations for pod(n). Furthermore, we found a formula for the action of the Hecke operator on a class of eta-quotients. As two applications of this result, we obtained two infinite families of congruence relations for pod5(n). We also proved a congruence relation for ped(n). In particular, we established a congruence relation modulo 2 connecting pod(n) and ped(n).

    Citation: JingJun Yu. Some congruences for -regular partitions with certain restrictions[J]. AIMS Mathematics, 2024, 9(3): 6368-6378. doi: 10.3934/math.2024310

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  • Let pod(n) and ped(n) denote the number of -regular partitions of a positive integer n into distinct odd parts and the number of -regular partitions of a positive integer n into distinct even parts, respectively. Our first goal in this note was to prove two congruence relations for pod(n). Furthermore, we found a formula for the action of the Hecke operator on a class of eta-quotients. As two applications of this result, we obtained two infinite families of congruence relations for pod5(n). We also proved a congruence relation for ped(n). In particular, we established a congruence relation modulo 2 connecting pod(n) and ped(n).



    For convenience, throughout this paper, we use the notation

    fk=n=1(1qnk),k1.

    A partition of a nonnegative integer n is a nonincreasing sequence of positive integers whose sum is n. We denote by pod(n) the number of partitions of n with odd parts distinct (and even parts are unrestricted). The generating function of pod(n) is given by

    n=0pod(n)qn=1ψ(q)=f2f1f4

    where ψ(q):=n=0qn(n+1)/2.

    The congruence properties of pod(n) were first studied by Hirschhorn and Sellers [1] in 2010. They proved that for all α0 and n0,

    pod(32α+3+23×32α+2+18)0(mod3).

    Using modular forms, Radu and Sellers [2] established several congruence relations modulo 5 and 7 for pod(n), such as

    pod(135n+8)pod(135n+107)pod(135n+116)0(mod5),pod(567n+260)pod(567n+449)0(mod7).

    For more details on pod(n), one can refer to [3,4,5].

    Our goal in this paper is to find congruence properties of the function pod(n), which enumerates the partitions of n into non-multiples of in which the odd parts are distinct (and even parts unrestricted). For example pod3(7)=4, where the relevant partitions are 7, 5+2, 4+2+1, 2+2+2+1. The generating function of pod(n) is given by

    n=0pod(n)qn=ψ(q)ψ(q)=f2ff4f1f4f2. (1.1)

    Recently, for each α0, Gireesh, Hirschhorn, and Naika [6] have obtained the generating function for

    n=0pod3(3αn+δα)qn

    where 4δα1(mod3α) if α is even, and 4δα1(mod3α+1) if α is odd. Saika [7] also obtained the congruence properties for pod3(n) and found infnite families of congruences modulo 2 and 3. In addition, Veena and Fathima studied [8] the divisibility properties of pod3(n) by using the theory of modular forms, for example, for k1,

    limX#{nX:pod3(n)0(mod3k)}X=1.

    Similarly, by imposing restrictions on the even parts while the odd parts are unrestricted, we also obtain the -regular partitions with distinct odd parts. Let ped(n) denote the number of -regular partitions of n with even parts distinct. The generating function of ped(n) is given by

    n=0ped(n)qn=f4ff1f4. (1.2)

    Drema and Saikia [9] found some infinite families of congruences modulo 2 and 4 for ped(n) when = 3, 5, 7 and 11. For example, for any prime p5, (6p)=1 and 1rp1, then for any α0, they proved the congruence relation

    ped3(6p2α+1(pn+r)+11p2α+14)0(mod4).

    In [10], Hemanthkumar, Bharadwaj, and Naika established several congruences modulo 16 and 24 for pod9(n). The authors also proved an identity connecting pod9(n) and ped9(n)

    3pod9(2n+1)=ped9(2n+3).

    In this work, we will continue to study the congruence properties of pod(n) and ped(n). The main purpose of this paper is to prove the following results.

    Theorem 1. For any n0, is even, and we have

    2n1i=0pod(2ni)σ1(i)0(mod2)

    where σk(n)=d|ndk is the standard divisor function.

    Theorem 2. Let pi be distinct odd primes. For any m,n0, t>0, we have

    pod2m(AnAs(2m1)8)0(mod2t)

    where A=t(2m1)i=1pi and sZ satisfies 8|As(2m1).

    Theorem 3. For any n0, α0, we have

    n=0pod5(4×152αn+15×(1+152α1)28)qnn=0pod5(4×72αn+7×(1+72α1)24)qnf31(mod2). (1.3)

    Meanwhile, let 1, if 1m<8, m1(mod8), and (m)=1, then we have

    pod5(4×152αn+15×(1+152α1m)28)pod5(4×72αn+7×(1+72α1m)24)0(mod2). (1.4)

    Theorem 4. For any n0, the following statements hold:

    (i)If >0 satisfying 1(mod8) and l is a prime with l|, then

    n=0ped(ln+l218)qnf3lf3/l(mod2). (1.5)

    (ii)If l is a prime satisfying l1(mod8), then

    pedl(ln+l218)podl(n)(mod2). (1.6)

    We begin with some background on modular forms to prove our main results.

    Let f(z)=n=0a(n)qn, if f(z)Mk(Γ0(N),χN) is a modular form. Let p be a prime and the operators Up and Vp are defined by

    f(z)|Up:=n=0a(pn)qn,f(z)|Vp:=n=0a(n)qpn

    which satisfies the following property:

    (f(z)g(z)|Vp)|Up=(f(z)|Up)g(z).

    The Hecke operator Tp is defined by

    Tp:=Up+χN(p)pk1Vp,k1.

    Lemma 1. [12, P. 18], If f(z)=δ|Nη(δz)rδ is an eta-quotient with k=δ|Nrδ/2Z, with the additional that

    δ|Nδrδ0(mod24),δ|NNδrδ0(mod24)

    then f(z) satisfies

    f(az+bcz+d)=χN(d)(cz+d)kf(z),[abcd]Γ0(N).

    Here, the character χN is defined by χN(d):=((1)ksd), where s:=δ|Nδrδ. Moreover, if f(z) is holomorphic (resp. vanishes) at all of the cusps of Γ0(N), then f(z)Mk(Γ0(N),χN) (resp. Sk(Γ0(N),χN).

    Lemma 2. [12, P. 18], Let c, d, and N be positive integers with d|N and gcd(c,d)=1. If f(z) is an eta-quotient satisfying the conditions of Lemma 1 for N, then the order of vanishing of f(z) at the cusp c/d is

    N24δ|Ngcd(d,δ)2rδgcd(d,Nδ)dδ.

    Before proving Theorem 1, we state here the following identity:

    n=1nkqn1qn=n=1σk(n)qn. (3.1)

    Proof of Theorem 1. Taking logarithms of relation (1.1), we find that

    log(n=0pod(n)qn)=n=1log(1q2n)+n=1log(1qn)+n=1log(1q4n)n=1log(1qn)n=1log(1q4n)n=1log(1q2n). (3.2)

    Using the differential operator qddq to (3.2) yields

    (n=0npod(n)qn1)/(n=0pod(n)qn)=2n=1nq4n11q4nn=1nqn11qn4n=1nq4n11q4n+n=1nqn11qn+4n=1nq4n11q4n+2n=1nq2n11q2n (3.3)

    namely,

    n=0npod(n)qn=(n=0pod(n)qn)(2n=1nq4n1q4nn=1nqn1qn4n=1nq4n1q4n+n=1nqn1qn+4n=1nq4n1q4n+2n=1nq2n1q2n).

    Consequently, we can deduce the following congruence:

    n=0npod(n)qn(n=0pod(n)qn)(n=1nqn1qnn=1nqn1qn)=(n=0pod(n)qn)(n=1(σ1(n)σ1(n))qn)(mod2). (3.4)

    By equating the even terms coefficients, we find that

    2npod(2n)=2n1i=0pod(2ni)(σ1(i)σ1(i))0(mod2). (3.5)

    In particular, if is even, we have

    2n1i=0pod(2ni)σ1(i)0(mod2). (3.6)

    This completes the proof Theorem 1.

    Before we prove Theorem 2, we included here the following lemma, which was proved in a letter from Tate to Serre [11]. He proved that the action of the Hecke operators are locally nilpoten of modulo 2. For simplicity, we define Mk:=Mk(SL2Z), Sk:=Sk(SL2Z).

    Lemma 3. If f(z)MkZ[[q]] is a modular form, then there exists a positive integer tdimMk[k12]+1 such that for any collection of distinct odd primes p1,p2,,pt,

    f(z)|Tp1|Tp2||Tpt0(mod2).

    That is, f has some degree of nilpotency that is bounded by [k12]+1, which also bounds the degree of nilpotency of the image of f under any Hecke operator. Based on work of Tate, Mahlburg [13] proved some congruences modulo arbitrary powers of 2 for the coefficients of certain quotients of Eisenstein series. In particular, Boylan [14] gave a corollary of Tate's result, which asserts that for any tj if f(z)S12j(mod2), that is,

    f(z)|Tp1|Tp2||Tpj0(mod2).

    By using the Boylan's result and similar techniques that are used by Mahlburg, we prove here Theorem 2.

    Proof of Theorem 2. Setting =2m in (1.1), we have

    n=0pod2m(n)qn=f2f2mf2m+2f1f4f2m+1f32mf31f3(2m1)1(mod2). (3.7)

    Replacing q by q8 in (3.7) and multiplying both sides by q(2m1), we obtain

    n=0pod2m(n)q8n+(2m1)q(2m1)n=1(1qn)24(2m1)=Δ(z)(2m1)(mod2) (3.8)

    where Δ(z) is the Delta-function, which is the unique cusp form of weight 12 on SL2(Z). Δ(z)(2m1)S12(2m1)(SL2(Z)) is a cusp form of weight 12(2m1). Hence, by using the Boylan's result, for any 2m1 distinct odd primes p1,p2,,p2m1, we have

    Δ(z)(2m1)|Tp1|Tp2||Tp2m10(mod2).

    Furthermore, it is well known that 12Δ(z)(2m1)|Tp1|Tp2||Tp2m1S12(2m1)(SL2(Z)) is also a cusp form of weight 12(2m1). Applying Boylan's corollary once more, we choose any 2m1 distinct odd primes p2m,p2m+1,,p2(2m1) coprime to p1,p2,,p2m1, and we can deduce that

    Δ(z)(2m1)|Tp1|Tp2||Tp2(2m1)0(mod22).

    By iterating the above process, for any t(2m1) distinct odd primes p1,p2,,pt(2m1), we can conclude that

    Δ(z)(2m1)|Tp1|Tp2||Tpt(2m1)0(mod2t). (3.9)

    It follows from (3.8) that

    pod2m(p1p2pt(2m1)n(2m1)8)0(mod2t). (3.10)

    Since (8,pi)=1, setting A=t(2m1)i=1pi, there exists a unique integer s such that 8|As(2m1). Replacing 8n+s by n in (3.10), we obtain

    pod2m(AnAs(2m1)8)0(mod2t).

    This completes the proof of Theorem 2.

    In order to prove the remaining theorems, we first establish an explicit formula for the action of the Hecke operator Tp on eta-quotient η3(z)η3(Nz) for N1(mod8), where p is a prime satisfying p|N.

    Lemma 4. If N>0 with N1(mod8), suppose p is a prime dividing N, then

    η3(z)η3(Nz)|Tp=(1)(p1)/2pη3(pz)η3(Nz/p). (3.11)

    Proof. We write

    η3(8z)=k=1k(4k)qk2.

    Adding the Up operator to η3(8z), we obtain

    η3(8z)|Up=n=1k(4k)qk2/p. (3.12)

    Replacing k by pk in (3.12), we have

    η3(8z)|Up=k=1pk(4pk)qpk2=k=1pk(1p)(4k)qpk2=(1)(p1)/2pη3(8pz). (3.13)

    Since N1(mod8), by Lemmas 1 and 2, we have that η3(8z)η3(8Nz)S3(Γ0(8N),χ2N) is a cusp form of weight 3. Adding the Up operator to η3(8z)η3(8Nz) and employing (3.13), we obtain

    η3(8z)η3(8Nz)|Up=(k=1k(4k)qk2)(k=1k(4k)qNk2)|Up=(k=1pk(4pk)qpk2)(k=1k(4k)qNk2/p)=(1)(p1)/2pη3(8pz)η3(8Nzp).

    Since p|N, then χN(p)=0, and adding the Tp operator to η3(8z)η3(8Nz), we deduce that

    η3(8z)η3(8Nz)|Tp=η3(8z)η3(8Nz)|Up=(1)(p1)/2pη3(8pz)η3(8Nz/p). (3.14)

    Replacing q8 by q in (3.14), we can deduce (3.11).

    To prove Theorem 3, we here need to verify some congruence relations. First, it is easy to check that if f(z)Mk(Γ0(N),χN), then by definitions we have f(z)|Up=f(z)|Tp, for p is a prime satisfying p|N. Second, by using Lemma 4, we can show the following congruences:

    η3(z)η3(15z)|U3=η3(z)η3(15z)|T3=3η3(3z)η3(5z)η3(3z)η3(5z)(mod2), (3.15)
    η3(3z)η3(5z)|U5=η3(3z)η3(5z)|T5=5η3(z)η3(15z)η3(z)η3(15z)(mod2). (3.16)

    Based on the above results, now we are able to prove Theorem 3.

    Proof of Theorem 3. Setting =5 in (1.1), we have

    n=0pod5(n)qn=f2f5f20f1f4f10f1f5f45f1f41f25f35f31(mod2). (3.17)

    From [15, P. 60], Hirschhorn and Sellers proved the following 2-dissection of f5/f1:

    f5f1=f8f220f22f40+qf34f10f40f32f8f20. (3.18)

    Employing (3.18) in (3.17), we obtain

    n=0pod5(n)qn(f8f220f22f40+qf34f10f40f32f8f20)f10f2(mod2). (3.19)

    Extracting those terms involving q2n in (3.19) and replacing q2 by q, we obtain

    n=0pod5(2n)qnf1f5f2f5f1(mod2).

    Applying (3.18) once more, it follows that

    n=0pod5(2n)qnf2(f8f220f22f40+qf34f10f40f32f8f20)(mod2). (3.20)

    Extracting those terms involving q2n in (3.20) and replacing q2 by q, we obtain

    n=0pod5(4n)qnf31(mod2). (3.21)

    Multiplying both sides by q2f315 in (3.21), we have

    (n=0pod5(4n)qn+2)f315q2f31f315=η3(z)η3(15z)(mod2).

    Applying the U3,U5 operators in sequence and employing (3.15) and (3.16), we find that

    [(n=0pod5(4n)qn+2)f315]|U3|U5η3(z)η3(15z)|U3|U5η3(z)η3(15z)|T3|T5η3(z)η3(15z)(mod2)

    which yields

    (n=0pod5(60n8)qn)f31η3(z)η3(15z)(mod2). (3.22)

    Dividing both sides by q2f13 in (3.22) and acting the U15 operator on both sides, we deduce that

    (n=0pod5(900n+112)qn)f31 (mod2).

    By induction, we can deduce that for α0,

    n=0pod5(4×152αn+15×(1+152α1)28)qnf31(mod2) (3.23)

    which is the first part of (1.3). Substituting q by q8 and multiplying both sides by q, we obtain

    n=0pod5(4×152αn+15×(1+152α1)28)q8n+1qf38Δ(z)n=0q(2n+1)2(mod2) (3.24)

    where Δ(z)=n=1(1qn)24. If m1(mod8) and (m)=1, then 8n+m cannot be a square. This implies that the coefficients of q8n+m in the lefthand side of (3.24) must be even. Hence, we have

    pod5(4×152αn+15×(1+152α1m)28)0(mod2)

    which is the first part of (1.4). Similarly as in the preceding discussion, we observe that the eta quotient η3(z)η3(7z)S3(Γ0(7),χ7) is a Hecke eigenform. Hnece, we can conclude that for α0, the following congruence holds:

    n=0pod5(4×72αn+7×(1+72α1)24)qnf31(mod2)

    which is the second part of (1.3). Furthermore, for m1(mod8) and (m)=1, we have

    pod5(4×72αn+7×(1+72α1m)24)0(mod2).

    This completes the proof of Theorem 3.

    As another application of Lemma 4, we are now ready to prove a congruence relation modulo 2 for ped(n).

    Proof of Theorem 4. By (1.2), we have

    n=0ped(n)qn=f4ff1f4f41ff1f4f31f3(mod2).

    Multiplying both sides by q(+1)/8f6, we have

    (n=0ped(n)qn+(+1)/8)f6η3(z)η3(z)(mod2). (3.25)

    Since l|, acting the operator Ul to both sides of (3.25) and using Lemma 4, we have

    (n=0ped(n)qn+(+1)/8)f6|Ulη3(z)η3(z)|Ul=η3(z)η3(z)|Tl=(1)(l1)/2lη3(lz)η3(z/l)η3(lz)η3(z/l)(mod2).

    Consequently,

    n=0ped(ln+18)qn(l2+)/8lf3lf3/l(mod2). (3.26)

    Replacing n(l2+)/8l by n in (3.26), we obtain

    n=0ped(ln+l218)qnf3lf3/l(mod2).

    This proves (1.5).

    In particular, when =l is a prime, we obtain

    n=0pedl(ln+l218)qnf3lf31f2flf4lf1f4f2ln=0podl(n)qn(mod2). (3.27)

    Comparing the coefficients of qn on both sides of (3.27), we obtain

    pedl(ln+l218)podl(n)(mod2).

    We deduce (1.6).

    In this paper, with the help of modular forms, we investigated on some congruence problems for -regular partitions with certain restrictions. In future studies, interested readers may examine whether these methods also can be extended to congruence problems for other types of partition functions.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The author declares that he has no conflict of interest.



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